重庆市第八中学2018届高考适应性月考(五)英语试题 含答案

重庆市第八中学2025届高考适应性月考卷（二）数学试卷注意事项:1.答题前，考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚。

2.每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

在试题卷上作答无效。

3.考试结束后，请将本试卷和答题卡一并交回。

满分150分，考试用时120分钟。

一、单项选择题(本大题共8小题.每小题5分，共40分.在每小题给出的四个选项中，只有一项符合题目要求的)1.设a b ，是非零向量，则“a b a b -=+ ”是“a b ，共线”的A .充分而不必要条件B .必要而不充分条件C .充分必要条件D .既不充分也不必要条件2.若()11i z +=，则zz=A .1i +B .1i -C .iD .i-3.已知函数()f x 的定义域为R 且导函数为()f x '，函数()()2y x f x =+⋅'的图象如图1，则下列说法正确的是A .函数()f x 的谱区间是()()202∞-+，，，B .函数()f x 的减区间是()()22∞∞--+，，，C .2x =是函数的极大值点D .0x =是函数的极大值点4.已知2sin sin 44ππαα⎛⎫⎛⎫+= ⎪ ⎪⎝⎭⎝⎭，则cos2α的值为A .23B .35C .34D ．455.设等差数列n a 的前n 项和为n S ，已知774721S a =-，则3a =A .-2B .-1C .1D .26.已知函数()()()()0110e x h x x f x x ⎧≤⎪=⎨⎛⎫-->⎪ ⎪⎝⎭⎩，，.将函数()h x 向左平移一个单位，再向上平移一个单位后得函数4y x=-，若()()22f x f x +<，则实数x 的取值范围是A .(-1，2)B .()()12∞∞--⋃+，，C .()21)2∞--⋃+，，D .][()12∞∞--⋃+，，7.如果数列n a 对任意的*211n n n n n a a a a +++∈->-N ，，则称n a 为“速增数列”，若数列na 为“逆增数列”，且任意项12132023n k a a a a ∈===Z ，，，，则正整数k 的最大值为A .62B .63C .64D .658.已知2e 00a b c >>>，，，当0x >时，e 0x b x c x x ⎛⎛⎫+-≥ ⎪⎝⎭⎝恒成立，则3ab c 的最小值为A .3e 27B .127C .3e 9D .19二、多项选择题(本大题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项是符合题目要求的.全部选对的得6分，部分选对的得部分分，有选错的得0分)9.已知点()()0110i i A x i i ≤≤∈N ，，与点()()10110i i B y i i ≤≤∈N ，，关于点(2，5)对称.若1x ，210x x ⋯，，的平均数为a ，中位数为b ，方差为c ，极差为d ，则1210y y y ⋯，，，这组数满足A .平均数为4a -B .中位数为b-C .方差为2c D .极差为d10.若Ox Oy ，是平面内两条相交成120 角的数轴，1e 和2e是x 轴、y 轴正方向上的单位向量，若向量12OP xe ye =+ ，则规定有序数对(x ，y )为向量OP在坐标系xOy 中的坐标，记作()OP x y = ，，设()()()11111OA OB OC t ==-= ，，，，，，则A.OA =B .OA OB⊥ C .若//BC OA，则3t =D .若ABC 构成锐角三角形，则()25t ∈，11.已知函数()()sin 06f x x πωω⎛⎫=+> ⎪⎝⎭的图象在02π⎛⎫ ⎪⎝⎭，上有且仅有两条对称轴，则下列结论正确的有A .ω的取值范围是(4，5)B .若()f x 的图象关于点5018π⎛⎫ ⎪⎝⎭，对称，则()f x 在09π⎛⎫⎪⎝⎭，上单调递增C .()f x 在04π⎡⎤⎢⎥⎣⎦，上的最小值不可能为12D .若()f x 的图象关于直线3x π=对称，函数()()252024g x f x b x b π⎡⎤=+∈⎢⎥⎣⎦，，，是常数，()g x 有奇数个零点()12221n n x x x x n +⋯∈N ，，，，，则()1232212523n n x x x x x π++++⋯++=三、填空题(本大题共3小题，每小题5分，共15分)12.已知双曲线222:14y x C b-=的虚轴长为2，则双曲线C 的渐近线方程是_____.13.设等比数列n a 的前n 项和为211n n n S S m m m -=+++⋯+，.令2n n b S =+，若n b 也是等比数列，则m =_____.14.曲率在数学上是表明曲线在某一点的弯曲程度的数值.对于半径为()0r r >的圆，定义其曲率1K r=，同样的，对于一般曲线在某点处的曲率，我们可通过该点处的密切圆半径计算.其中对于曲线()y f x ≡在点()()00x f x ，处的密切圆半径计算公式为()()()122001f x R f x ⎡⎤+⎥⎦='''⎢⎣，其中()f x '表示()y f x =的导数，()f x ''表示()f x '的导数.已知曲线():ln C g x x =，则曲线C 在点()()11g ，处的曲事为_____；C 上任一点处曲率的最大值为_____.四、解答题(共77分.解答应写出文字说明，证明过程或演算步骤)15.(本小题满分13分)ABC 的内角A B C 、、的对边分别为a b c 、、、已知22cos a b c B -=.(1)求角C ；(2)若3h c CD ==，平分ACB ∠交AB 于点D ，求CD 的长.已知正项数列n a 的前n 项和为n S 、且()112311n n n a a S a +=-=，.(1)求数列n a 的通项公式;(2)若数列n b 的前n 项和为n T ，且()32n n n b a a =+，证明:43n T <.17.(本小题满分15分)在平面直角坐标系中，已运动点()P x y ，到直线43:3l x =的距离与点P 到点)F 的距离的比是233(1)求动点P 的轨迹方程E ；(2)若轨迹E 与x 轴的交点分别为A B 、。

重庆市第八中学2016届高考适应性月考卷（五）文科数学参考答案第Ⅰ卷（选择题，共60分）一、选择题（本大题共12小题，每小题5分，共60分）【解析】1．A 为函数y =的定义域，所以[1)A =+∞，，B 为函数2log y x =在A 上的值域，所以[0)B =+∞，，所以[1)A B =+∞ ，，故选A ． 2．OA 所对应的112i z =+，OB 所对应的22i z =+，所以1212i (12i )(2i )2i (2i )(2i )z z ++-==++-222i 4i 2i 43i 43i 4i 555-+-+===+-，故选A ． 3．平行于同一平面的两个平面平行，故选B ．4．该几何体为一个边长为2的正方体紧贴一个边长为1的正方体，表面积为226111523528⨯⨯-+⨯⨯=+=，故选C ．5．因为ABC △为等腰三角形，外心，重心，垂心均在底边BC 的高线上，所以只需求BC 的中垂线方程，BC 中点(32)M ，，12BC k =-，所以2AM k =，故中垂线方程为24y x =-，故选A ．6．依题意，2b a =，2c b =，sin 2sin B bA a ==，222sin 22sin cos 4cos 4sin sin 2B B B a c bB A A ac+-=== 2222413422b b b b +-== ，故选B ．(本题有误) 7．由图可知，A ，B 显然正确；前4天同样多的资金投资乙商品，收益是4.5倍，甲商品是3倍，C 正确；曲线越接近一条直线，则相关系数越大，由图知乙商品的相关系数大于甲商品的相关系数，故选D ．8．作O C a b =+ ，OA a = ，OB b =，则由平行四边形法则，45AOC BCO ∠=∠=︒，90BOC ∠=︒，在OBC △中，由正弦定理得||sin 90sin 45||a b ︒==︒D ． 9．2π12cos 2sin sin )4cos 2(1sin 2),42αααααα⎛⎫=-=-⇒=- ⎪⎝⎭28(1sin 2)1sin 2αα-=-sin 21α⇒=或7sin 28α=-，故选C ．10．方法一：以A 为坐标原点，AB 为x 轴正方向，AC 为y 轴正方向建立直角坐标系，则BC 的方程为168x y +=，设()P a b ，，则168a b +=，00a b >>，，则4868a b ab = 24812682a b ⎛⎫⎪+= ⎪ ⎪ ⎪⎝⎭≤，故选B ．方法二：设()P a b ，，由相似三角形可知，161081010a CP b BP CP ===-，，所以168a b+=，剩下同方法一．11．由定义知函数()f x 的定义域为253x x x x +++⎧⎪⇒∈⎨⎪∈⎩N N≥，≥，且3x ≥，22(2)(1)(1)(2)31()(2)(1)3243(1)(2)2421321x x x x x f x x x x x x x x x ++--⎛⎫==++=++=+- ⎪⨯--⎝⎭⨯⨯⨯ ，又3x ≥且x +∈N ，所以3x =时，min ()20f x =，故选C ．12．在同一坐标系中作出1122xy ⎛⎫=- ⎪⎝⎭和34y x x =-+的图象，分析图象知在[01)[2)m ∈+∞ ，，上时()f x 在R 上有3个零点，故选D ．第Ⅱ卷（非选择题，共90分）二、填空题（本大题共4小题，每小题5分，共20分）【解析】13．依题意知02p F ⎛⎫⎪⎝⎭，，圆心Q 在线段FO 的垂直平分线4p x =上．因为抛物线C 的准线方程为2p x =-，所以3344p =，即1p =，因此抛物线C 的方程为22y x =． 14．程序在执行过程中S k ，的值依次为：1k =，11lg 3S =+；3k =，1311lg lg 1lg355S =++=+；5k =，13511lg lg lg 1lg 3577S =+++=+；7k =，135711lg lg lg lg 1lg 35799S =++++=+10lg 9=，9k =，退出循环，输出10lg 9S =．15．π()()))2sin 3f x f x ϕϕϕ⎫'+=+++=++⎪⎭，再由()()f x f x '+是偶函数πππ32k ϕ⇔+=+，k ∈Z ，即ππ6k ϕ=+，k ∈Z ，又0πϕ<<，所以0k =时π6ϕ=． 16．如图1，连接BD ，则有四边形ABCD 的面积11sin sin 22ABD CDB S S S AB AD A BC CD C =+=+ △△，由180A C +=︒，得sin sin A C =，从而四边形ABCD 的面积4sin S A =．由余弦定理，在ABD △中：2222cos 54cos BD AB AD AB AD A A =+-=- ，在C D B △中：2222cos 1312cos BD CB CD CB CD C C =+-=- ，所以54c o sA -=1312c o C -，及cos cos A C =-，求得1cos 2A =-，120A =︒，所以4sin S A== 三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤） 17．（本小题满分12分）（Ⅰ）解：设等差数列{}n a 的公差为d ，等比数列{}n b 的公比为q ， 由题设得：11253182b q a a a a d b q ++=-==，，因为1112a b ==，， 所以2d q ==，所以212n n n a n b =-=，．……………………………………………（6分） （Ⅱ）证明：2(1)log (22)2(1)n n n c a b n n n n =-=-=- ，11111122(1)21n n c n n n n ⎛⎫==- ⎪--⎝⎭当≥时，，……………………………………（8分）所以23111111111111112223122n c c c n n n ⎛⎫⎛⎫+++=-+-++-=-< ⎪ ⎪-⎝⎭⎝⎭ ．………………………………………………………………………………（12分）18．（本小题满分12分）解：（Ⅰ）222()100(60102010)100= 4.762()()()()7030802021n ad bc K a b c d a c b d -⨯⨯-⨯==≈++++⨯⨯⨯，2( 3.841)0.05P K =≥，所以没有0099的把握认为阅读量的丰富度与性别有关.……………………（7分）图1（Ⅱ）5名理科生里，用12a a ，表示阅读量丰富的学生，123b b b ，，表示阅读量不丰富的学生，从5名理科生中任取3人的一切可能结果所组成的基本事件空间为121122123112113123212={()()()()()()()a a b a a b a a b a b b a b b a b b a b b Ω，，，，，，，，，，，，，，，，，，，，，213223123()()()}a b b a b b b b b ，，，，，，，，，……………………………………（10分）Ω由10个基本事件组成，且这些基本事件出现是等可能的．事件A 表示“3人中至多有1人阅读量丰富”，则112113123212213223123{()()()()()()()}A a b b a b b a b b a b b a b b a b b b b b =，，，，，，，，，，，，，，，，，，，，，……………………………………………………………………………………（11分）7()10P A =∴． ……………………………………………………………………（12分）19．（本小题满分12分）解：（Ⅰ）如图2，若OM ∥平面11A BCD ，则由线面平行的性质定理得，线OM 平行于平面1AA C 与平面11A BCD 的交线1A C ，所以1AMO AAC △△∽， 所以113AM AO AD MA OC BC ===． ……………………………………………………（6分）（Ⅱ）因为正方形11ADD A 垂直于底面ABCD ， 所以1AA ⊥平面ABCD ．记点A 到平面11A BCD 的距离为d ，则11111133A A BC A ABC A BC ABC V V d S AA S --=⇒⨯⨯=⨯⨯△△． ………………………………（8分）又由AD =BC =，对角线AC BD ⊥可知图2111134AO OC AC AA AC AB A B =====，，， 所以6ABC S =△，1A BC S =△……………………………………………（11分）代入111133A BC ABC d S AA S d ⨯⨯=⨯⨯⇒=△△． ………………………………（12分）20．（本小题满分12分）解：（Ⅰ）依题意有22222112433c c a a a c b a b c⎧⎪=⎧=⎪⎪⇒=⇒⎨⎨+=⎪⎪=⎩⎪=+⎩，，，，椭圆C ：22143y x +=．………（5分）（Ⅱ）解法一：由对称性不妨设12(02)(02)A A -，，，， 易知直线21QA QA ，斜率存在，分别设为12k k ，.设点00(,)Q x y ，有2200221y x a b+=，222000122200043y a y a y a a k k x x x b +--===-=- ∴． ……………………………（7分）由114642y N y k x k =⎛⎫⎧⇒⎨ ⎪=-⎩⎝⎭，，， 同理224242y M y k x k =⎛⎫⎧⇒⎨ ⎪=+⎩⎝⎭，，，……………………………………………（9分）则有1212747431624NH MH k k k k k k --===--- ．【或0NH MH = 】 …………（11分）所以以线段MN 为直径的圆过(07)H ，. …………………………………（12分）解法二：由对称性不妨设12(02)(02)A A -，，，. 设点00()Q x y ，，所以2200143y x +=，2200220012123(4)9444x y y y =-=--- ∴， ………（7分）1QA l ∴：0000222(0)42y x y x M x y ⎛⎫--=-⇒ ⎪-⎝⎭，， 2QA l ：0000262(0)42y x y x N x y ⎛⎫++=-⇒ ⎪+⎝⎭，， ………………………………（9分）2000200026124747+99902+24x x x HM HN y y y ⎛⎫⎛⎫=--==-+= ⎪ ⎪--⎝⎭⎝⎭，，∴，………（11分）所以以线段MN 为直径的圆过(07)H ，． …………………………………（12分）21．（本小题满分12分）解：（Ⅰ）由于0a >，0x >，故1()a f x x x+=+≥，当且仅当x 时取等号．由题可知：4=，从而3a =． ……………………………………（3分）于是3()g x x'=，从而(1)3g '=，又(1)0g =， 所以()y g x =在点(1(1))g ，处的切线方程为3(1)y x =-， 即330x y --=.………………………………………………………（5分）（Ⅱ）令1()()()ln a h x f x g x x a x x+=-=+-， 所以221(1)(1)()1a a x x a h x x x x ++--'=--=． （1）当1e a +≥，即e 1a -≥时，()h x 在[1e]，上单调递减， 所以min1()(e)e 0e a h x h a +==+-≤，解得：2e 1e 1a +-≥. （2）当11a +≤，即0a ≤时，()h x 在[1e]，上单调递增， 所以min ()(1)110h x h a ==++≤，则2a -≤． …………………………………（8分）（3）当11e a <+<，即0e 1a <<-时，()h x 在[11]a +，上单调递减，在[1e]a +，上单调递增，所以min ()(1)2ln(1)0h x h a a a a =+=+-+≤，而(1ln(1))2(1lne)22a a a -++>-+=，故上述不等式无解．………………（11分）综上所述，a 的取值范围是2e 1e 1a +-≥或2a -≤．……………………………（12分）22．（本小题满分10分）【选修4−1：几何证明选讲】 （Ⅰ）解：∵弦AC 与EF 交于M ，∴EM MF AM MC = ，又∵4AM =，9MC =，EM M F =，6EM =∴，故12EF =． ………………………………………………………………（3分）∵PA 是圆O 的切线，PEF 为圆O 的割线，∴2PA PE PF = ，∵PA =∴(12)108PE PE += ，故6PE =． ……………………………………………………………………（5分） （Ⅱ）证明：如图3，连接OA ，OB ，OM ，AB ，∵M 为弦EF 的中点，∴OM EF ⊥，∴90PAO PBO PMO ∠=∠=∠=︒，∴P ，A ，M ，O ，B 共圆（PO 为该圆的直径）， ………………………………………（7分） ∴，∵PB 是圆O 的切线，PBA BCA ∠=∠∴，PMA BCA ∠=∠∴，∴BC EF ∥． ……………………………………（10分）23．（本小题满分10分）【选修4−4：坐标系与参数方程】解：（Ⅰ）圆C 的直角坐标方程为22(2)9x y ++=，即22450x y y ++-=． ……………………………………………………（2分）又222x y ρ+=，cos x ρθ=，sin y ρθ=， ……………………………………（4分）∴圆C 的极坐标方程为24sin 50ρρθ+-=．…………………………（5分） （Ⅱ）∵点M 的极坐标为4π3⎛⎫ ⎪⎝⎭，， ∴点M的直角坐标为(3)-，且在圆C 内． 设直线l的参数方程为cos 3sin x t y t θθ⎧=⎪⎨=-+⎪⎩，，（t 为参数）， 代入圆C方程得：22(cos )(1sin )9t t θθ+-+=，整理得：22(sin )50t t θθ--=， ……………………………………（7分）22π4(sin )2016sin 203θθθ⎛⎫∆=++=++ ⎪⎝⎭， PM A PBA ∠=∠图3122(sin )t t θθ+=，125t t =-，12||||AB t t =-= 当π3θ=-时||AB最小，min ||AB = 此时直线l的参数方程为123x t y ⎧=⎪⎪⎨⎪=-+⎪⎩，，（t 为参数）．………………………（10分）【另解】由平几知识知当直线l CM ⊥时，AB 的长度最小，又圆心(02)C -，，∴CM k ==， …………………………………（7分） 故直线l的斜率k =，倾斜角为2π3， ∴直线l的参数方程为123x t y ⎧=⎪⎪⎨⎪=-+⎪⎩，，（t 为参数）． …………………………（10分）【注】直线l的普通方程为60y ++=，其参数方程一般形式为：00x x at y y bt =+⎧⎨=+⎩，，（t 为参数），其中00()x y ，60y ++=上任一点，且b a= 24．（本小题满分10分）【选修4−5：不等式选讲】 解：（Ⅰ）由柯西不等式得：2222()(149)(23)a b c a b c ++++++≥， …………（3分）即141S ≥，114S ∴≥， 即S 的取值范围为114⎡⎫+∞⎪⎢⎣⎭，． …………………………………………（5分）（Ⅱ）231a b c ++=∵，2221a b c ++=，231b c a +=-∴，2221b c a +=-， 由柯西不等式得：222()(49)(23)b c b c +++≥（当且仅当23b c =时取=）， 故2213(1)(1)a a --≥， 即2142120a a --≤，解得617a -≤≤，所以min 6 7a=-．………………………………………………………………（8分）由2312367a b cb ca⎧⎪++=⎪⎪=⎨⎪⎪=-⎪⎩，，，解得2737bc⎧=⎪⎪⎨⎪=⎪⎩，，即a取得最小值时，27b=，c37=．…………………………………………（10分）。

秘密★启用前重庆市第八中学2023届高考适应性月考卷（二）数学注意事项：1．答题前，考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚．2．每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号.在试题卷上作答无效.3.考试结束后，请将本试卷和答题卡一并交回.满分150分，考试用时120分钟.一、单项选择题（本大题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的）1.设全集U =R ，集合{}=02A x x ≤≤，{}=240x B x -≥，则集合()UA B = ð（）A.()0,2 B.(]0,2 C.[)0,2 D.[]0,22.设x =R ，则“01x <<”是“2230x x --<”的（）A.充分而不必要条件B.必要而不充分条件C.充要条件D.既不充分也不必要条件3.在医学生物学试验中，经常以果蝇作为试验对象，一个关有6只果蝇的笼子里，不慎混入了两只苍蝇（此时笼内共有8只蝇子：6只果蝇和2只苍蝇），只好把笼子打开一个小孔，让蝇子一只一只地往外飞，直到两只苍蝇都飞出，再关闭小孔.记事件k A 表示“第k 只飞出笼的是苍蝇”，1,2,,8k =⋅⋅⋅，则()52|P A A 为（）A.15B.16C.17D.254.定义在R 上的函数()f x 满足()()121f x f x x +=-++，则下列是周期函数的是（）A.()y f x x=+ B.()y f x x=- C.()2y f x x=+ D.()2y f x x=-5.我国古代数学家僧一行应用“九服晷影算法”在《大衍历》中建立了晷影长l 与太阳天顶距θ（0180θ︒≤≤︒）的对应数表，这是世界数学史上较早的一张正切函数表，根据三角学知识可知，晷影长度l 等于表高h 与太阳天顶距θ正切值的乘积，即tan l h θ=.对同一“表高”两次测量，第一次和第二次太阳天顶距分别为α，β，若第一次的“晷影长”是“表高”的2倍，且()1tan 3αβ-=，则第二次的“晷影长”是“表高”的（）倍A.1B.2C.3D.46.已知81log 32a =，0.01b π=，sin1c =，则,,a b c 的大小关系是（）A.c b a <<B.c a b<< C.a b c<< D.a c b<<7.在ABC 中，π3A =，G 为ABC 的重心，若12AG AB AG AC ⋅=⋅= ，则ABC 外接圆的半径为（）A.B.2C.D.8.若函数()32f x ax bx cx d=+++()0a >有极值点1x ，2x ，且()22f x x =，则关于x 的方程()()2320a f x bf x c ++=⎡⎤⎣⎦的不同实数根个数是（）A.3B.4C.5D.6二、多项选择题（本大题共4小题，每小题5分，共20分.在每小题给出的选项中，有多项是符合题目要求的.全部选对的得5分，部分选对的得2分，有选错的得0分）9.已知0a b >>，且1ab =，则下列式子正确的有（）A.22log log 0a b ->B.22log log 1a b +>C.22log log 0a b ⋅< D.224a b +>10.设首项为1的数列{}n a 的前n 项和为n S ，已知121n n S S +=+，则下列结论正确的是（）A.数列{}1n S +为等比数列B.数列{}n a 不是等比数列C.21n n S a =-D.{}n a 中任意三项不能构成等差数列11.已知函数()4f x x πω⎛⎫=+ ⎪⎝⎭()0ω>，则下列说法正确的是（）A.若函数()f x 的最小正周期为π，则其图象关于直线π8=x 对称B.若函数()f x 的最小正周期为2π，则其图象关于点π,04⎛⎫ ⎪⎝⎭对称C.若函数()f x 在区间π0,8⎛⎫⎪⎝⎭上单调递增，则ω的最大值为2D.若函数()f x 在[]0,2π有且仅有4个零点，则ω的取值范围是151988ω≤<12.已知F 为椭圆C ：221168x y +=的左焦点，直线l ：=y kx ()0k ≠与椭圆C 交于A ，B 两点，AE x ⊥轴，垂足为E ，BE 与椭圆C 的另一个交点为P ，则（）A.8AF BF +=B.14AF BF+的最小值为2C.直线BE 的斜率为12k D.PAB ∠为钝角三、填空题（本大题共4小题，每小题5分，共20分）13.复数z 满足：23i z z +=+，则=z ______.14.定义在R 上的函数()f x 满足以下两个性质：①()() f x f x -=，②()()20f x f x +-=，满足①②的一个函数是______.15.已知M 是边长为1的正ABC 的边AC 上的动点，N 为AB 的中点，则BM MN ⋅的最大值是_____.16.已知函数()()2log 41xf x x =+-，数列{}n a 是公差为4的等差数列，若()()()()112233440a f a a f a a f a a f a +++=，则数列{}n a 的前n 项和=n S ______.四、解答题（共70分.解答应写出文字说明，证明过程或演算步骤）17.如图，在棱柱111ABC A B C -中，D 为棱BC 的中点.（1）证明：1//A B 平面1AC D ；（2）若该三棱柱为正三棱柱，且所有棱长均相等，求直线AC 与平面1AC D 所成角的正弦值.18.在ABC中，角A ，B ，C的对边分别为a ，b ，c ，已知()()()2sin sin sin sin sin sin cos cos C A B A B C A C B ----=-+.（1）求B ；（2）已知2a c -=，ABC S =△，求b .19.记n S 为数列{}n a 的前n 项和，已知1=2a ，{}32n n a S -是公差为2的等差数列.（1）求{}n a 的通项公式；（2）证明：121111na a a ++⋅⋅⋅+<.20.核电站某项具有高辐射危险的工作需要工作人员去完成，每次只派一人，每人只派一次，工作时长不超过15分钟，若某人15分钟内不能完成该工作，则撤出，再派下一人，现有小胡、小邱、小邓三人可派，且他们各自完成工作的概率分别为1p ，2p ，3p .假设1p ，2p ，3p 互不相等，且假定三人能否完成工作是相互独立.（1）任务能被完成的概率是否与三个人被派出的先后顺序有关？试说明理由；（2）若按某指定顺序派出，这三人各自能完成任务的概率依次为1q ，2q ，3q ，其中1q ，2q ，3q 是123,,p p p 的一个排列.①求所需派出人员数目X 的分布列和数学期望()E X ；②假定1231>>>p p p ，为使所需派出的人员数目的数学期望达到最小，应以怎么样的顺序派出？21.已知函数()()()ln 3f x x a x =++()a ∈R .（1）若函数()f x 在定义域内单调递增，求a 的取值范围；（2）若=2a ，()f x kx >在()1,x ∈+∞上恒成立，求整数k 的最大值.（参考数据：ln 20.69≈，ln 3 1.1≈）22.已知双曲线E ：22221x y a b-=0a >，0b >）一个顶点为()2,0A -，直线l 过点()3,0Q 交双曲线右支于M ，N 两点，记AMN ，AOM △，AON △的面积分别为S ，1S ，2S .当l 与x 轴垂直时，1S 的值为152.（1）求双曲线E 的标准方程；（2）若l 交y 轴于点P ，PM MQ λ= ，PN NQ μ=，求证：λμ+为定值；（3）在（2）的条件下，若121625S S mS μ=+，当58λ<≤时，求实数m 的取值范围.秘密★启用前重庆市第八中学2023届高考适应性月考卷（二）数学注意事项：1．答题前，考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚．2．每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号.在试题卷上作答无效.3.考试结束后，请将本试卷和答题卡一并交回.满分150分，考试用时120分钟.一、单项选择题（本大题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的）【1题答案】【答案】C【2题答案】【答案】A【3题答案】【答案】C【4题答案】【答案】B【5题答案】【答案】A【6题答案】【答案】D【7题答案】【答案】C【8题答案】【答案】A二、多项选择题（本大题共4小题，每小题5分，共20分.在每小题给出的选项中，有多项是符合题目要求的.全部选对的得5分，部分选对的得2分，有选错的得0分）【9题答案】【答案】ACD 【10题答案】【答案】ACD 【11题答案】【答案】ACD 【12题答案】【答案】AC三、填空题（本大题共4小题，每小题5分，共20分）【13题答案】【答案】1+i ##i+1【14题答案】【答案】()πcos 2f x x =（答案不唯一）【15题答案】【答案】2364-【16题答案】【答案】228n n-四、解答题（共70分.【17题答案】【答案】（1）证明见解析（2）55【18题答案】【答案】（1）3π（2）b =【19题答案】【答案】（1）31nn a =-（2）证明见解析【20题答案】【答案】（1）无关；理由见解析（2）①分布列见解析；期望为121232q q q q --+；②完成任务概率大的人先派出【21题答案】【答案】（1）)5e ,-⎡+∞⎣（2）6【22题答案】【答案】（1）22143x y -=（2）证明见解析（3）1832,55⎛⎤⎥⎝⎦第8页/共8页。

重庆市第八中学2024-2025学年高二上学期第一次月考英语试题一、阅读理解Notice on the orderly opening of the National Museum of China The National Museum of China (NMC) has limited the daily visitor arrivals with a new timetable and adopted an online booking system. We hereby inform you of the following regulations: * The NMC is open from 9:00 to 17:00 (last admission at 16:00) and closes on Monday.* Visitors must make appointments 1-7 days in advance. Group reservations and on-site reservations are not accepted.* Visitors can make online appointments through our official website or official social media platform account.* On the day of the visit, please enter the museum with Chinese ID cards. For other documents holders, please bring the copies of the original documents used at the time of reservation.* Visitors must enter the museum during their reserved time period to avoid crowding. If visitors miss their reserved time period, they will be refused. If visitors cannot make it on time, please apply for a cancellation in the reservation system before 15:00 on the day of the visit. Reservations cannot be cancelled after the reserved date, and the system will automatically record one’s account as “absent”. For anyone whose account contains three times of absence, the visitor will not be able to make new reservations within 90 days.* Staff-guided tours are cancelled temporarily. Visitors must be in an orderly manner throughout the visit.The NMC will take measures to ensure orderly and safe visits. Thanks for your support and cooperation.National Museum of China 1．When can visitors enter the NMC?A．At 11:00, Monday.B．At 10:30, Sunday.C．At 17:00, Thursday. D．At 16:30, Friday.2．What do we know about the NMC reservation?A．It should be made on site.B．It can be made in groups.C．It must be made a week ahead.D．It can be made through official website.3．What if a visitor misses the reserved time period?A．He should reserve in three months.B．He must reserve again before 15:00.C．He will be refused to enter the museum.D．His account can be recorded as “absent”.Two years ago, Holmes participated in Back to School Bash. He was holding down two jobs at the time — one with the city’s public works department, the other as a barber. Saturday was his busiest hair-cutting day, but he chose to donate his time and give free haircuts to unfortunate kids so they’d look neat on that first day of classes. But then he had a light bulb moment: “The kids should earn their free haircut by having to read a book to me,” Holmes said.The idea was so popular that he continued it the first Tuesday of every month for the next two years. Boys from five to ten years old would grab a favorite book, settle into the barber chair, and read aloud while Holmes was doing their hair. If they were puzzled over a word, Holmes was there to help. After the haircut, they’d review he book, from the characters and vocabulary to the themes — just like in school, only more fun. Holmes, who is married and has two sons, ages three and four, recognizes that not every parent has the time to read with their kids.Holmes admits he, too, benefits from the process. “There was this seven-year-old who struggled through his book, stuttering over words even though he didn’t have a stutter (口吃),” said Holmes. He had the boy take the book home and practice. When the child came back a few days later, “He read it with no problems. That inspires me.”Holmes and his family have recently moved to a Chicago suburb. When they get settled, he plans to take up his role as the Story-book Barber. “The way the world is today with guns and violence,” he says, “it’s a safe heaven for the kids, to come to the barbershop and read books.”4．What do we know about Holmes two years ago?A．He had only one job.B．He earned a lot as a barber.C．He offered free haircuts to the poor kids.D．He was the organizer of Back to School Bash.5．The example in Paragrap3 mainly proves that _______.A．Holmes is very strict with the kidsB．Holmes also learns a lot from the kidsC．being a fluent reader needs plenty of practiceD．many kids have trouble in reading a storybook6．What can we learn from the last Paragraph?A．Holmes is dissatisfied with the world today.B．Holmes’ barbershop will have some changes.C．Holmes’ barbershop has won great popularity.D．Holmes will continue to be a storybook barber.7．What is the best title for the text?A．The Storybook BarberB．Back to School BashC．Reading Counts A LotD．Care About the KidsAny schoolchild knows that a whale breathes through its blowhole. Fewer know that a blowhole is a nostril (鼻孔) slightly changed by evolution into a form more useful for a mammal that spends its life at sea. And only a dedicated expert would know that while toothed whales, such as sperm whales, have one hole, baleen (鲸须) whales, such as humpback and Rice whales, have two.Even among the baleen whales, the placing of those nostrils differs. In some species they are close together. In others, they are much further apart. In a paper published in Biology Letters Conor Ryan, a marine biologist at the Scottish Association for Marine Science, suggests why that might be. Having two nostrils, he argues, helps whales smell in stereo (立体空间).Many types of baleen whales eat tiny animals known as zooplankton (浮游动物), whichthey catch by filtering (过滤) them from seawater using the sheets of fibrous baleen that have replaced teeth in their mouths. But to eat something you first have to find it. Toothed whales do not hunt by scent. In fact, the olfactory bulb—the part of the brain that processes smell—is absent in such creatures. But baleen whales still have olfactory bulbs, which suggests smell remains important. And scent can indeed give zooplankton away. Zooplankton like to eat other tiny creatures called phytoplankton (浮游植物). When these are under attack, they release a special gas called dimethyl sulphide, which in turn attracts baleen whales.Most animals have stereoscopic senses. Having two eyes, for instance, allows an animal to compare the images from each in order to perceive depth. Having two ears lets them locate the direction from which a sound is coming. Dr Ryan theorized that paired blowholes might bring baleen whales the same sorts of benefits.The farther apart the sensory organs are, the more information can be extracted by the animal that bears them. The researchers used drones to photograph the nostrils of 143 whales belonging to 14 different species. Sure enough, baleen whales that often eat zooplankton, such as the North Atlantic right whale, have nostrils that are farther apart than do those, such as humpback whales, that eat zooplankton occasionally. Besides allowing them to breathe, it seems that some whales use their blowholes to determine in which direction dinner lies.8．What do we know about whales’ nostrils according to the first two paragraphs?A．They are adapted ones.B．They are developed merely for smell.C．They are not easy to detect.D．They are fixed universally in numbers. 9．What plays a role when baleen whales hunt zooplankton?A．The teeth that baleen whales have.B．The smell that phytoplankton send.C．The sound waves that zooplankton create.D．The chemical signals that zooplankton give off.10．How is the concept of stereoscopic senses explained in paragraph 4?A．By quoting a theory.B．By using examples.C．By making contrast.D．By making inferences.11．What is the position of nostrils related to according to the last paragraph?A．The sense of smell.B．The possibility to attract food.C．The ability to locate food.D．The ability to communicate.In a world where everyone has their own opinions on just about everything, it’s common for people to be critical of each other’s mistakes and imperfections without noticing their own. Some individuals mistakenly think it’s their responsibility to make you into a better person. They do this by first pointing out your shortcomings directly and then providing advice on how you can improve.So what is the possible solution to criticism? If you are the one forcing others to feel ashamed of themselves, please stop. Make a conscious decision rather than highlight the negative aspect of a person’s performance or attitudes. You are more likely to offer helpful suggestions from the beginning. If you are on the receiving end of criticism, the “OK” response is a perfect solution. When someone comments negatively on a task you are doing or a personality issue of yours, a natural response is to defend and attack. However, this approach is rarely effective as it puts both parties on the defensive. Instead, simply reply with “OK”. This brief one-word response acknowledges the other person’s comment without agreeing with it or feeling necessary to engage in a debate about it.It’s crucial to stay connected to what the other person is talking about, and listen without getting upset, to be an objective observer. In fact, there is much that one can learn from a negative review. You can ask yourself: Did I make a mistake? Could I have done better? Did I give 100% of myself to the task at hand? If so, how can I improve myself? As for chronic criticizers: It is important to set strict boundary with them. Remove yourself from their presence when necessary.In any case, one can learn to be “OK” with criticism and not allow it to negatively impact your life or relationship with the other party.12．What might the author think of people who like to judge others?A．Self-centered.B．Responsible.C．Talkative.D．Warm-hearted. 13．What does a person mean by saying “OK” according to Paragraph 3?A．He thinks the advice is helpful.B．He completely agrees with the comments.C．He wants to avoid unnecessary arguments.D．He defends himself with the response. 14．What is the recommended action for dealing with chronic criticizers?A．Embrace their views.B．Criticize them in return.C．Avoid interaction if needed.D．Engage with them regularly.15．What is the most suitable title for the text?A．The Art of Giving Criticism B．Mastering Self-Defense against Criticism C．Dealing with Personal Relationships Flexibly D．The Path to Self-Improvement through CriticismLessons that are Learned from the OlympicsThe Olympic Games are enjoyed by everyone. Here are some tips about how to bring the deeper meaning of the Olympics into your life.◆Excellence comes with hard work and practice.Learning about the training schedules of Olympic athletes reminds us that success doesn’t come easily. Repetition is the servant (仆人) of success. Set long-term goals as well as realistic ones. 16 And remember the most important competitor you have is actually you.◆ 17There are hundreds of events at the Olympics, each standing for a specific activity that athletes have chosen to follow. You can recognize the creativity and excitement and form strong feelings about it, which will help you to achieve your dreams.◆Expect to fail sometimes.Every athlete who has made it into Olympic competition has suffered injury and disappointment along the way, but that has not been the end of their dream. 18 You can treat your setbacks (挫折) as a teaching tool.◆Enjoy your success.Observe the Olympic athletes when they stand on the winners’ platform with their medals, listening to their national anthems (国歌). Their pride is obvious. Enjoy the feelings of power that come from your achievement. 19◆Enjoy other cultures.With its symbol of the five-ring Olympic flag, the Olympics celebrate the unity of the games while honoring individual nationality. 20A．You deserve it.B．Have confidence in yourselves.C．Work hard for your personal best.D．Find your strong feelings and develop it.E．Enough practice will make you successful.F．Athletes show respect to those from other countries.G．They know that they can learn more from failure than success.二、完形填空When my sister Diane began playing the violin, she was seven. How did she sound? Terrible. But she didn’t 21 . At twelve, she asked our parents if she could 22 a full-time music school. They said no. Actually, everyone agreed that my sister lacked talent.I was better at my 23 . My teacher had told my parents that I had great potential. So my parents found the best piano teacher in the area to 24 me. But the only time he was available was Saturday afternoons at 3 pm. Back then, I was 25 by the British TV show The Avengers, which was 26 every Saturday at 3 pm. I let nothing take up my The Avengers hour. So I 27 this amazing opportunity. Today,I don’t even have a 28 in my house.My sister became an engineer, but she 29 stopped making music. When she was in her 40s, she changed her career. She went back to college, got a 30 in music education, and became a music teacher. She starts kids out on their first instrument and gives them all the encouragement and support she never 31 .Recently, she and a pianist pal put on a recital. A big crowd of friends and family 32 for her. As she played, I looked around at the 33 . Everyone was obviously enjoying the music. It occurred to me that I was the only person who remembered that 7-year-old kid making those perfectly 34 sounds and knew how far she had come, despite 35 .Talent is important. But enthusiasm (热情) is even more important.21．A．admit B．advance C．quit D．improve 22．A．attend B．join C．leave D．visit 23．A．major B．project C．composition D．instrument 24．A．examine B．train C．correct D．challenge25．A．surprised B．serious C．fascinated D．particular 26．A．aired B．filmed C．designed D．commented 27．A．jumped at B．opened up C．waited for D．turned down 28．A．tutor B．musician C．piano D．violin 29．A．already B．even C．never D．once 30．A．degree B．chance C．scholarship D．praise 31．A．expected B．provided C．imagined D．received 32．A．paid off B．showed off C．stayed up D．turned up 33．A．audience B．students C．spotlights D．platform 34．A．sweet B．bad C．powerful D．pleasing 35．A．everybody B．everything C．something D．somebody三、单词拼写36．The course on cultural d was designed to broaden students’ understanding of different societies. (根据首字母单词拼写)37．The customer’s c for a refund was denied due to the store’s policy on used items. (根据首字母单词拼写)38．In the pursuit of knowledge, scientists s truth through experimentation and analysis, striving to uncover the principles that govern the natural world. (根据首字母单词拼写) 39．The hospital’s dedicated (全体职员) worked tirelessly throughout the night to ensure that all patients received the necessary care and attention. (根据汉语提示单词拼写) 40．Despite the early hour, the students (精力充沛地) read aloud the textbook and other materials every morning. (根据汉语提示单词拼写)41．The artist used a series of vibrant colors to (给书或文章加插图) the depth and complexity of the emotions experienced by the characters in the novel. (根据汉语提示单词拼写) 42．The company’s f work hours policy has significantly improved employee satisfaction and productivity.(根据首字母单词拼写)43．Striving for success without hard work is like trying to h where you haven’t planted. （根据首字母单词拼写）44．The dense fog (笼罩) the city, creating an atmosphere that made the streets seem mysterious and almost deserted. (根据汉语提示单词拼写)45．(诚然), the process of learning a new language can be challenging, but the rewards of communication and understanding are well worth the effort. (根据汉语提示单词拼写)四、语法填空语法填空A CCTV journalist succeeded in arousing a heated discussion among citizens. The discussion was about 46 (ask) people if they were happy. There are a 47 (vary) of responses to the question, even some quite funny ones included. Although people played jokes on the answers, it did not take long 48 they begin to figure out the true meanings of happiness.It is certain that people’s views on happiness 49 (affect) greatly by their own life experiences. Unfortunately, too many people refer to being rich as happiness and there is no sign of 50 decrease in the number of those who are voluntarily at the mercy of wealth. Some people whose intention is 51 (make) big money appreciate being given any chance to multiply their income, believing that is 52 their happiness lies. Some are eager to inherit (继承) their parent’s property, especially those who are known 53 silver-spoon kids (富二代). Even worse, some would rather break the law to satisfy their financial desire or seek their fortune 54 (illegal).In my opinion, happiness is not about pursuing wealth merely but about admiring the beautiful things in life. Therefore, live 55 (you) life to the fullest and be happy.五、书信写作56．假定你是李华，上周末你们班在当地的助老中心参加了志愿者活动。

高2023级高二（上）10月月考英语试题（答案在最后）第一部分听力（共两节满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What do the speakers prefer eating now?A.Chicken.B.Salad.C.Soup.2.What’s the main idea of this conversation?A.The time of exercise.B.The order of exercise.C.The effects of exercise.3.How often do the speakers meet now?A.Every day.B.Five times per week.C.Once per week.4.How did the woman learn the traditional dance?A.From her children.B.From her friends.C.From her parents.5.What do we know about the woman?A.She values the meaning of her future work.B.She wants to make more money.C.She has decided to be a doctor.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

重庆市第八中学2024届高考适应性月考卷(五)英语参考答案第一部分听力(共两节，满分30分)1~5CBABC 6~10 CAABB 11~15 ACBCB 16~20 CABCB第二部分阅读(共两节，满分 50分)第一节(共15 小题; 每小题2.5分, 满分 37.5 分)21~25AABDC 26~30 DCCDD 31~35BBCAD第二节(共5 小题; 每小题 2.5分, 满分 12.5 分)36~40 FGBDC第三部分语言运用(共两节，满分 30分)第一节(共15 小题; 每小题1分, 满分 15分)41~45 BACDB 46~50 DACAC 51~55ADDCB第二节(共 10 小题; 每小题1.5 分, 满分 15 分)56. realization 57. in 58. was thrown 59. incredibly 60. whose61. to be seen 62. its 63. has won 64. a 65. closed第四部分写作(共两节，满分40分)第一节(满分 15分)【参考范文】NoticeWith the Arbor Day approaching, all exchange students are invited to join in the upcoming tree planting activity in Peo ple’s Park this Sunday , March 12th . This event aims to promote environmental awareness and to enhance our commitmen t to green living.It starts at 8 : 00 am , with a short briefing on tree planting techniques and safety precautions. Participants will then be divided into groups and given seedlings by the park's staff, and proceed to the designated area in the park. Lunch will be pr ovided at mid-afternoon, followed by a short break before the activity is completed.To ensure a smooth experience, it's highly recommended to wear comfortable clothing suitable for outdoor activities an d bring a water bottle to stay hydrated. Don't forget instruments of labor,say, a spade or a bucket.Look forward to an enjoyable and fulfilling day with you!Student Union第二节(满分 25分)【参考范文】Finally Amy got up from her seat.The bright girl, on the verge of tears, flew to Confucius like a gust of wind.“No!”W e let out a deafening roar in chaos, with a noisy discussion hanging over the classroom. “The rule!” Mr. Williams's warning echoed in Amy's mind repeatedly. “Under no circumstances are you to touch the fish.” Hesitantly, she took a step back. Co nfucius lay on the ground, with its mouth gasping for air and its tail gradually stopping swinging. We all sat frozen in place,and just watched, at a loss what to do in panic. At this critical moment Amy had an idea. She put the plastic bag over her h and swiftly, picked Confucius up like a live grenade and put it back into the tank. Thankfully, the lovely creature came to li fe in the water. It swam merrily, as if to express its gratitude to the sweet angel Amy.Relieved, we turned our eyes to Mr. Williams. Unfortunately, Mr. Williams, with a severe look on his face, told Amy to pack her bags and suspended her from school for two days. “Are you serious?”We were all babbling, wearing a woebegone expression. But Mr. Williams did not show the slightest inclination to change. We flocked to the tank, and pressed our faces up to the glass to watch Confucius, wallowing in our guilt. Just then, Amy raised her heroic hand high, still wrapped inthe plastic bag.“Look!”A confident smile spread across her lips. She didn't touch the fish directly with her fingers. That was not against the rule. Mr. Williams nodded in agreement and went back to lecturing. Delighted and feeling proud of Amy,we all ca st eyes now and then on Amy, who invited us to witness how smart it was to apply rules flexibly without violatingprinciples.【解析】第二部分阅读第一节A【语篇导读】这是一篇应用文,文字介绍了参观 Stonehenge 和 Windsor Castle两处景点的一日游行程安排及注意事项。

重庆八中2024—2025学年度（上）高三年级第一次月考语文参考答案1.D2.D3.B4.①作为例证，精准恰当地论证了辛弃疾以四六法为文的特点和善于化用前人成句的做法；②从论证辛弃疾为文的特点巧妙自然地引出对他作词特点的分析。

5.【参考示例】①连续的几个短句贯通，形成长句，从句意和语法上看，不能从长句中抽出其中的短句，如“千古江山，英雄无觅，孙仲谋处”三个短句形成一个长句，构成完整的句意。

②将物象作为长句来处理，形成气脉贯通、纵横捭阖的格局，如“想当年，金戈铁马，气吞万里如虎”中“金戈铁马”物象作为长句处理，表达诗人对历史人物的赞扬，气势豪迈。

6.C7.B8.①警惕性更高，反应迅捷。

瓦西里被狙击枪瞄准时，敏锐感知，并迅速做出反应，逃过一劫；②欺骗手段更高明。

瓦西里用“假手”“假头”都引出了对手，但德国人的“假人”由于“50米距离来说，这个头显得大了点儿”而被识破。

（每点2分，其它答案有理也可给分。

）9.①增强紧张感和悬念。

通过瓦西里的视角来叙述，读者只能了解他所见所感，而无法了解德国人的情况，这种限制使得故事充满未知和紧张感，只能随着瓦西里的行动和感知来逐步了解故事。

②深化人物心理描写。

有限视角使得对瓦西里的心理描写更加深入和细腻，读者能够感受到他的恐惧、疲惫、坚持和求生欲望，这种内心的挣扎和变化通过他的视角被生动地展现出来。

③增加故事的代入感。

读者通过瓦西里的眼睛来观察世界，感受他的情绪和体验，这种代入感使得故事更加引人入胜。

读者仿佛亲身经历了这场生死较量，与瓦西里一同感受每一个惊心动魄的瞬间。

④突出主题。

通过瓦西里的视角，读者能够更深刻地理解战争对人性的考验，以及爱情的力量。

同时，瓦西里和德国狙击手之间的较量也寓意着战争中的残酷和无奈。

（每点2分，共6分，其它答案有理也可给分。

）10.DEI11．D12．C13．（1）去年上天把晋国赐给了秦国，秦国不知道夺取晋国反而卖给了我们粮食。

现在上天把秦国赐给了晋国，晋国难道可以违背天意吗？（2）杀死晋君，与将晋君放逐出晋国，与把他带回秦国，与放他回国恢复他的君位，哪个处理方法对我们秦国更有利？14.①秦缪公体恤百姓，心怀仁爱。

重庆市第八中学2023第一部分（共两节，满分30第二部分（共两节，满分50第一节（共15 2.537.5第二节（共5 2.512.5第三部分（共两节，满分30第一节（共15115第二节（共10 1.515565859616465第四部分（共两节，满分40第一节15especially the new-media-related realm英语参考答案·第1页（共7页）第二节（满分25第二部分第一节21细节理解题。

从第二段第一句“facilities on board and a super-friendly captain222324细节推断题。

根据第一段第一句“英语参考答案·第2页（共7页）25细节理解题。

根据第二段最后一句“26细节推断题。

根据第四段内容，即可得出答案。

2728从第二段中29细节推断题。

从第三段中可以推断出答案。

30细节推断题。

从第四段“313233细节推断题。

从第四段克隆方法和过程的介绍可以得出答案。

34从第五段第一句35第二节3637383940英语参考答案·第3页（共7页）第三部分第一节414243444546474849505152535455第二节56575859606162636465英语参考答案·第4页（共7页）could you get some Post-it notes for me2英语参考答案·第5页（共7页）I need to help those people who have regular check-ups on Sunday英语参考答案·第6页（共7页）Ha-ha英语参考答案·第7页（共7页）。

重庆市第八中学2025届高考适应性月考卷（二）地理试卷注意事项：1．答题前，考生务必用黑色碳素笔将自己的姓名、准考证号、考场号、座位号在答题卡上填写清楚。

2．每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。

在试题卷上作答无效。

3．考试结束后，请将本试卷和答题卡一并交回。

满分150分，考试用时75分钟。

一、选择题：本题共15小题，每小题3分，共45分。

在每小题给出的四个选项中，只有一项A ．持续不断增大B ．先减小后增大C ．先增大后减是符合题目要求的。

2023年10月26日，神舟十七号载人飞船在酒泉卫星发射中心成功发射，我国3名航天员驾乘飞船顺利进驻距离地表约400km 的空间站天和核心舱。

2024年4月30日，航天员安全返回地球。

据此完成1~2题。

1．航天员驻留期间，天和核心舱与地球构成的天体系统绕太阳运动线速度大致是小D ．始终保持不变2．驻留期间，酒泉卫星发射中心发射塔与重庄市区解放碑两地每天正午太阳高度的差值α随时间变化的图象为ABCD城市绿荫工程是重庆市2023年重点民生实事之一，也是创建国家生态园林城市的重要举措。

城市绿荫工程包括行道树补栽补植（如图1）、街头绿地提质和山城绿道建设。

据此完成34~题。

图13．城市绿荫工程可缓解城市热岛效应的主要原因是①净化空气②吸收二氧化碳③绿地较水泥地的比热容大④植物蒸腾作用吸收周围的热量A．①②③B．①③④C．①②④D．②③④4．城市绿荫工程产生的生态效益有A．延长路面寿命B．维护生物多样性C．拓展休闲空间D．减少能源消耗量《宋书·天文志》中有如下描述：百川发源，皆自山出，由高趣下，归注于海。

日为阳精，光耀炎炽，一夜入水，所经燋竭。

百川归注，足于补复。

故旱不为减，浸不为益。

据此完成5~6题。

5．“百川归注，足于补复。

故早不为减，浸不为益。

”体现了A．陆地内循环B．海上内循环C．河流补给湖泊D．海洋水平衡6．文中提到的水循环环节主要是A．径流与蒸发B．降水与水汽输送C．径流与下渗D．蒸腾与地下径流“京杭大运河”是我国著名的世界文化遗产。