期末复习试题二

期末复习检测（二）一、选择题1.（）A. B. C. D.2.把千克糖平均分成3份，每份是（）千克。

A. B. C. D.3.（）A. B. C. 14 D.4.有两根绳子，第一根长20米，第二根比第一根长，第二根绳长（）A.4米B.16米C.25米D.24米5.贝贝正在读一本科普书，第一周读了48页，还剩下这本书的没有读。

这本科普书一共（）页。

A. 18B. 80C. 1126.把10克药放入100克水中，药和水的比是（）。

A. 10：100B. 1：10C. 1：11D. 11：17.一个比的前项是30，如果前项增加60，要使比值不变，后项应（）。

A. 增加60B. 减少60C. 乘3D. 除以38.在观看马戏表演的时候，人们一般都会围成圆形。

这是应用了圆特征中（）A. 圆心决定园的位置B. 半径决定圆的大小C. 同圆中的半径都相等D. 同圆中直径是半径的2倍9.一个环形，外圆直径是40厘米，环的宽度是10厘米，它的内圆半径是（）A. 10厘米B. 20厘米C. 30厘米D. 50厘米10.书店以50元卖出两套不同的书，一套赚10%，一套亏本10%，书店是（）。

A. 亏本B. 赚钱C. 不亏也不赚D. 无法确定11.甲数比乙数多25%，则乙数是甲数的（）A. 75%B. 80%C. 125%12.食堂原有15千克味精，第一周用去了，第二周用去了剩下的，要买进（）千克味精，才比原有味精多2千克．A.3B.5C.7D.9二、判断题13. 一条绳长3米，剪去了，还剩米．14.动物园在学校东偏南30°方向5千米处，则学校在动物园西偏北30°方向5千米处。

15.要录入一份稿件，王兰要用6小时，黎明每小时可以录入．王兰比黎明录入的快．16.甲乙两个足球队的比赛结果是3：1，这个比的前项是3后项是0．17.圆的半径增加2cm，周长就增加12.56cm。

三、填空题18.小明家到香山的路程有36千米，小明骑自行车从家出发，第一小时走了全程的，第二小时行了全程的，还剩下全程的________，是________千米．19.在横线上填上“<”、“>”、或“=”：×24________ 5÷8________62.5%36÷ ________36 ________20.一桶水，当冰化成水时，它的体积减少了；那么当水结成冰时，它的体积增加了________。

小学数学二年级下册期末复习试题班级：姓名：得分：一、口算：（14分）36＋42= 760－40＝ 640＋60＝ 93－26=600＋170＝ 2000＋6000＝ 580－570＝ 180－90＝350－200＝ 7000－5000＝ 50＋130= 90＋280＝4×8＋6 = 15－6×2=二、填空。

（14分）1、写出下面各数：三百四十八（）六千零八（）四千零五十（）2、4075是由4个（）、（）个十、5个（）组成的。

读作（）。

（2分）3、小明7：50到校，11：50放学，他上午在校（）小时。

4、按要求的顺序排列下面各数。

（2分）5607 5067 5760 4506 4056( )＜（）＜（）＜（）＜( )5、在 = 。

2克 200分小时 3000千克1分秒 6克千克 15角元6、甲数是125，比乙数多18，乙数是（）。

三、选择题。

（把正确的答案填在括号里，8分）1、5个2分币大约重（）。

① 5克② 5千克③ 5米2、一支铅笔长（）① 20米② 20厘米③ 20克3、一个零也不读的数是（）。

①3051 ②3105 ③ 31504、在没有括号的算式里，有除法和加、减法，要先算（）。

①依次计算②除法③加减法四、判断题：（对的打“√”，错的打“×”，4分）1、1千克棉花和1000克铁一样重。

（）2、笔算加法是从个位加起。

（）3、最大的四位数是9000。

（）4、时、分、秒都是时间单位。

（）2619－634 = 3795 + 537= 88＋97＋105 =验验算算4103－ 279 = 43÷8= 247＋968＋8293＝2、混合运算。

（12分）47－12＋5 60－6×3 （60—18）÷614＋21÷7 4×9÷6 4×（14－8）六、列式计算：（8分）1、比5463多2507的数是多少？2、甲数是723，比乙数少48，乙数是多少？3、一个数减去89，得56，这个数4、295比387少多少？是多少？七、应用题：（26分）1、一张桌子150元，比一把椅子多60元，一把椅子多少元？2、商店里有4盒皮球，每盒6个，卖出20个，还剩多少个？3、学校开运动会，二年级男生得25分，女生得18分，二年级得分比一年级多10分。

一、 选择题（请在正确答案处打√，2×11分）1．根据黑体辐射维恩位移定律，最大辐射强度波长M λ,72.89810M T λ=⨯ Å·K ,那么人体(300K)时辐射最大M λ属于:(A) 可见光 (B)近红外 (C) √远红外光2.已知自发发射系数21A 与受激发射系数21B 之比32121/8/A B h πλ=,那么对于较短波长激光，例如紫外、X 射线激光器相对于长波长激光器产生激光输出将(A) √更难 (B)更易 (C)与波长无关3．激光腔的Q 因子越大，该腔的输出单色性越高，即(A) √输出光谱带宽越小 (B)输出光谱带宽越大 (C)光子寿命越小4．电光调Q 激光器的调制电压波形一般为(A) √方波 (B)正弦波 (C)余弦波5．Nd +3:YAG 和Ti +3:sapphire(掺钛蓝宝石)激光器中产生激光的物质分别是√(A) Nd 和Ti 离子 (B)YAG 和Sapphire (C)Nd 和Ti 原子6．电光调制器半波电压产生的相位差是(A) 90度 (B)45度 (C) √180度7．一般情况下谐振腔的稳定条件是（22111,1R L J R L J -=-=）： (A) √1021≤≤J J ， (B)1021<<J J (C)101<<J ，102<<J8．在下列哪一种情况下激光上下能级布居数最容易实现反转(A) 二能级系统 (B)三能级系统 (C) √四能级系统9．精密干涉测量，全息照相，高分辨光谱等要求单色性、相干性高的 光源。

(A) √单纵模 (B)单横模 (C)多纵模10．假如各纵模振幅不同，则锁模脉冲的时间和光谱带宽积(A)等于1 (B) √315.0≥ (C)011．锁模与调Q 激光器中，饱和吸收体的受激态寿命锁模t 、Q 调t （驰豫时间）与激光器可能产生的极限脉冲宽度p t 关系是(A)锁模t 和Q 调t >p t ， (B)锁模t 和Q 调t <p t (C) √锁模t <p t ，Q 调t >p t二、 填空题(3×12分)1. 激光光源与普通光源相比，具有哪三方面的优点：（1） 单色性高 （2） 方向性好 （3）相干性高（或者亮度高）2. 辐射能量交换的三个基本过程是：（1） 受激吸收 （2） 受激发射 （3） 自发发射3. 激光器的三个基本组成部分是：（1） 工作物质 （2） 谐振腔 （3） 驱动源4. 声光调制器的四个组成部分是：（1） 声光介质 （2） 换能器 （3） 驱动电源 （4）吸声和声反射材料5. 试举出常见的四大类锁模的方法：（1）主动锁模 （2） 被动锁模 （3）同步泵浦锁模 （4）自锁模6. 假设光场能态密度是)(v ρ，粒子从较低能态1ϕ（能量E 1）过渡到较高能态2ϕ（能量E 2）的受激吸收几率是（1）)(12v B ρ；粒子从较高能态2ϕ（能量E 2）过渡到较低能态1ϕ（能量E 1）的受激发射和自发发射几率分别是（2）)(21v B ρ和21A 。

部编版小学五年级（上）期末综合复习试题（二）语文（考试时间 90分钟全卷满分 100分）学校:___________姓名：___________班级：___________考号：___________温馨提示：遇难心不慌，遇易心更细；拼一分高一分，一分成就终生！一、选择题1．下面的句子应读出“痛惜”语气的一项是（）A．队长很矛盾，不太情愿地说：“欢迎是欢迎，可您的身体……”《小岛》B．我国这一园林艺术的瑰宝．建筑艺术的精华，就这样化为一片灰烬。

《圆明园的毁灭》C．三百年来梦寐不忘的生母啊！请叫儿的乳名，叫我一声“澳门”！《澳门》D．美哉，我少年中国，与天不老！壮哉，我中国少年，与国无疆！《少年中国说》2．下面加点字的注音，有误的一项是（）A．榆．关（yú）瓷．花盆（cí）聒．噪（guō）B．袅．袅（năo）船桨．（jiăng）凛冽．（liè）C．嫦．娥（cháng）无暇．（xiá）闲逸．（yì）3．下面的词语，书写完全正确的一组是（）A．钉鞋忙碌酷暑炎夏B．脊背龟裂引入技途C．口罩彩排峦峦不舍D．路费酸味满坏信心4．下面的词语书写有错的一项是（）A．平稳称赞B．家尝猪豹C．迷惑坚持D．山洪陆地二、诗词曲鉴赏读句子，完成练习。

风一更．，雪一更，聒．碎乡心梦不成，故园无此声。

5．选出加点字的意思。

更（______）A．改变。

B．经历。

C．旧时一夜分五更。

聒（______）A．声音嘈杂，这里指风雪声。

B．斩断。

C．划伤。

6．用“/”给下面的句子画出朗读停顿。

聒碎乡心梦不成，故园无此声。

7．“故园”指的是哪里？“此声”指的是什么声音？_________________________________________8．这句词表达了戍边将士的______之情。

三、填空题9．小小书法家。

fā shì sā huăng bēng tā yóu yŏng（_______）（__________）（_________）（__________）dīng zhŭ chí yán qī zi hūn shā（_______）（__________）（_________）（__________）10．读课文第五自然段，把雨或雪的的形成过程写在括号里。

模块一复习测试题二一．选择题（共10小题）1．若集合{|15}A x N x =∈,a =则下面结论中正确的是( ) A ．{}a A ⊆B ．a A ⊆C ．{}a A ∈D ．a A ∉2．已知实数1a >,1b >,则4a b +是22log log 1a b ⋅的( ) A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既不充分也不必要条件3．若命题“[0x ∀∈,3],都有220x x m --≠ “是假命题,则实数m 的取值范围是( ) A ．(-∞,3]B ．[1-,)+∞C ．[1-,3]D ．[3,)+∞4．若函数2()44f x x x m =--+在区间[3,5)上有零点,则m 的取值范围是( ) A ．(0,4)B ．[4,9)C ．[1,9)D ．[1,4]5．已知2x >,则12y x x =+-的( ) A ．最小值是2 B ．最小值是4 C ．最大值是2 D ．最大值是46．已知函数12x y +=的图象与函数()y f x =的图象关于直线0x y +=对称,则函数()y f x =的反函数是( )A ．21log ()y x =--B ．2log (1)y x =--C ．12x y -+=-D ．12x y -+=7．已知cos()3παα+=为锐角）,则sin (α= )A B C D8．设函数()sin f x x x =,[0x ∈,2]π,若01a <<,则方程()f x a =的所有根之和为()A ．43π B ．2π C ．83π D ．73π 二．多选题（共4小题）9．若集合M N ⊆,则下列结论正确的是( ) A ．MN N =B ．M N N =C ．()M M N ∈D ．()M N N ⊆10．下列说法中正确的有( )A ．不等式2a b ab +恒成立B ．存在a ,使得不等式12a a+成立 C ．若a ,(0,)b ∈+∞,则2b a a b+ D ．若正实数x ,y 满足21x y +=,则218x y+ 11．已知函数||()1x f x x =+,则( ) A ．()f x 是奇函数B ．()f x 在[0,)+∞上单调递增C ．函数()f x 的值域是(,1)[0-∞-,)+∞D ．方程2()10f x x +-=有两个实数根12．下列选项中,与11sin()6π-的值相等的是( ) A ．22cos 151︒-B ．cos18cos 42sin18sin 42︒︒-︒︒C ．2sin15sin 75︒︒D ．tan30tan151tan30tan15o oo o+-三．填空题（共4小题）13．化简32a b-= （其中0a >,0)b >．14．高斯是德国的著名数学家,近代数学奠基者之一,享有“数学王子”的称号,他和阿基米德、牛顿并列为世界三大数学家,用其名字命名的“高斯函数”为:设x R ∈,用[]x 表示不超过x 的最大整数,则[]y x =称为高斯函数,例如:[ 3.4]4-=-,[2.7]2=．已知函数21()15x x e f x e =-+,则函数[()]y f x =的值域是 ． 15．若1lgx lgy +=,则25x y+的最小值为 ． 16．若42x ππ<<,则函数32tan 2tan y x x =的最大值为 ．四．参考解答题（共8小题） 17．已知0x >,0y >,且440x y +=． （Ⅰ）求xy 的最大值; （Ⅱ）求11x y+的最小值． 18．已知函数2()21f x x ax a =--+,a R ∈．（Ⅰ）若2a =,试求函数()(0)2f x y x x=>的最小值; （Ⅱ）对于任意的[0x ∈,2],不等式()f x a 成立,试求a 的取值范围; （Ⅲ）存在[0a ∈,2],使方程()2f x ax =-成立,试求x 的取值范围． 19．解方程 （1）231981xx-=（2）444log (3)log (21)log (3)x x x -=+++20．设函数33()sin cos 2323x x f x ππ=-． （1）求()f x 的最小正周期;（2）若函数()y g x =与()y f x =的图象关于x 轴对称,求当[0x ∈,3]2时,()y g x =的最大值．21．已知函数()cos()(0,0,||)2f x A x B A πωϕωϕ=++>><的部分图象如图所示．（Ⅰ）求()f x 的详细解析式及对称中心坐标;（Ⅱ）先将()f x 的图象纵坐标缩短到原来的12,再向右平移6π个单位,最后将图象向上平移1个单位后得到()g x 的图象,求函数()y g x =在3[,]124x ππ∈上的单调减区间和最值．22．已知函数2()3sin 2cos 12xf x x =-+． （Ⅰ）若()23()6f παα=+,求tan α的值;（Ⅱ）若函数()f x 图象上所有点的纵坐标保持不变,横坐标变为原来的12倍得函数()g x 的图象,且关于x 的方程()0g x m -=在[0,]2π上有解,求m 的取值范围．模块一复习测试题二参考正确答案与试题详细解析一．选择题（共10小题）1．若集合{|15}A x N x =∈,a =则下面结论中正确的是( ) A ．{}a A ⊆B ．a A ⊆C ．{}a A ∈D ．a A ∉【详细分析】利用元素与集合的关系直接求解．【参考解答】解:集合{|15}{0A x N x =∈=,1,2,3},a =a A ∴∉．故选:D ．【点评】本题考查命题真假的判断,是基础题,解题时要认真审题,注意元素与集合的关系的合理运用．2．已知实数1a >,1b >,则4a b +是22log log 1a b ⋅的( ) A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既不充分也不必要条件【详细分析】根据充分必要条件的定义以及基本不等式的性质判断即可． 【参考解答】解:1a >,1b >, 2log 0a ∴>,2log 0b >,2a b ab +,4a b +,故4ab ,222222222log log log ()log 4log log ()[]()1222a b ab a b +⋅==,反之,取16a =,152b =,则1522224log log log 16log 215a b ⋅=⋅=<, 但4a b +>,故4a b +是22log log 1a b ⋅的充分不必要条件, 故选:A ．【点评】本题考查了充分必要条件,考查基本不等式的性质,是一道基础题．3．若命题“[0x ∀∈,3],都有220x x m --≠ “是假命题,则实数m 的取值范围是( ) A ．(-∞,3]B ．[1-,)+∞C ．[1-,3]D ．[3,)+∞【详细分析】直接利用命题的否定和一元二次方程的解的应用求出结果．【参考解答】解:命题“[0x ∀∈,3],都有220x x m --≠ “是假命题,则命题“[0x ∃∈,3],使得220x x m --= “成立是真命题, 故222(1)1m x x x =-=--． 由于[0x ∈,3],所以[1m ∈-,3]． 故选:C ．【点评】本题考查的知识要点:命题的否定的应用,一元二次方程的根的存在性的应用,主要考查学生的运算能力和转换能力及思维能力,属于基础题型．4．若函数2()44f x x x m =--+在区间[3,5)上有零点,则m 的取值范围是( ) A ．(0,4)B ．[4,9)C ．[1,9)D ．[1,4]【详细分析】判断出在区间[3,5)上单调递增,(3)0(5)0f f ⎧⎨>⎩得出即1090m m -⎧⎨->⎩即可．【参考解答】解:函数2()44f x x x m =--+,对称轴2x =,在区间[3,5)上单调递增 在区间[3,5)上有零点,∴(3)0(5)0f f ⎧⎨>⎩即1090m m -⎧⎨->⎩ 解得:19m <, 故选:C ．【点评】本题考查了二次函数的单调性,零点的求解方法,属于中档题． 5．已知2x >,则12y x x =+-的( ) A ．最小值是2 B ．最小值是4 C ．最大值是2 D ．最大值是4【详细分析】直接利用不等式的基本性质和关系式的恒等变换的应用求出结果． 【参考解答】解:已知2x >,所以20x ->,故11222(2)2422y x x x x x =+=-++-=--（当3x =时,等号成立）． 故选:B ．【点评】本题考查的知识要点:不等式的基本性质,关系式的恒等变换,主要考查学生的运算能力和转换能力及思维能力,属于基础题．6．已知函数12x y +=的图象与函数()y f x =的图象关于直线0x y +=对称,则函数()y f x =的反函数是( )A ．21log ()y x =--B ．2log (1)y x =--C ．12x y -+=-D ．12x y -+=【详细分析】设(,)P x y 为()y f x =的反函数图象上的任意一点,则P 关于y x =的对称点(,)P y x '一点在()y f x =的图象上,(,)P y x '关于直线0x y +=的对称点(,)P x y ''--在函数12x y +=的图象上,代入详细解析式变形可得．【参考解答】解:设(,)P x y 为()y f x =的反函数图象上的任意一点, 则P 关于y x =的对称点(,)P y x '一点在()y f x =的图象上,又函数()y f x =的图象与函数12x y +=的图象关于直线0x y +=对称,(,)P y x ∴'关于直线0x y +=的对称点(,)P x y ''--在函数12x y +=的图象上,∴必有12x y -+-=,即12x y -+=-,()y f x ∴=的反函数为:12x y -+=-;故选:C ．【点评】本题考查反函数的性质和对称性,属中档题7．已知cos()3παα+=为锐角）,则sin (α= )A B C D 【详细分析】由11sin sin[()]33ααππ=+-,结合已知及两角差的正弦公式即可求解．【参考解答】解:cos()3παα+=为锐角）,∴1sin()3απ+=,则11111sin sin[()]sin())33233ααππαπαπ=+-=++,1(2=-,=故选:C ．【点评】本题考查的知识点是两角和与差的余弦公式,诱导公式,难度不大,属于基础题．8．设函数()sin f x x x =,[0x ∈,2]π,若01a <<,则方程()f x a =的所有根之和为( )A ．43π B ．2π C ．83π D ．73π 【详细分析】把已知函数详细解析式利用辅助角公式化积,求得函数值域,再由a 的范围可知方程()f x a =有两根1x ,2x ,然后利用对称性得正确答案．【参考解答】解:1()sin 2(sin )2sin()23f x x x x x x π=+=+=+,[0x ∈,2]π,()[2f x ∴∈-,2],又01a <<,∴方程()f x a =有两根1x ,2x ,由对称性得12()()33322x x πππ+++=,解得1273x x π+=．故选:D ．【点评】本题考查两角和与差的三角函数,考查函数零点的判定及应用,正确理解题意是关键,是基础题．二．多选题（共4小题）9．若集合M N ⊆,则下列结论正确的是( ) A ．MN N =B ．M N N =C ．()M M N ∈D ．()M N N ⊆【详细分析】利用子集、并集、交集的定义直接求解． 【参考解答】解:集合M N ⊆,∴在A 中,M N M =,故A 错误;在B 中,M N N =,故B 正确;在C 中,()M M N ⊆,故C 错误;在D 中,M N N N =⊆,故D 正确．故选:BD ．【点评】本题考查了子集、并集、交集定义等基础知识,考查运算求解能力,属于基础题． 10．下列说法中正确的有( )A ．不等式2a b ab +恒成立B ．存在a ,使得不等式12a a+成立 C ．若a ,(0,)b ∈+∞,则2b a a b+ D ．若正实数x ,y 满足21x y +=,则218x y+ 【详细分析】结合基本不等式的一正,二定三相等的条件检验各选项即可判断．【参考解答】解:不等式2a b ab +恒成立的条件是0a ,0b ,故A 不正确;当a 为负数时,不等式12a a+成立．故B 正确; 由基本不等式可知C 正确;对于212144()(2)4428y x y x x y x y x y x y x y+=++=+++=, 当且仅当4y x x y =,即12x =,14y =时取等号,故D 正确． 故选:BCD ．【点评】本题考查基本不等式的应用,要注意应用条件的检验．11．已知函数||()1x f x x =+,则( ) A ．()f x 是奇函数B ．()f x 在[0,)+∞上单调递增C ．函数()f x 的值域是(,1)[0-∞-,)+∞D ．方程2()10f x x +-=有两个实数根【详细分析】根据函数的奇偶性判断A ,根据函数的单调性判断B ,结合图象判断C ,D 即可．【参考解答】解:对于||:()()1x A f x f x x --=≠--+,()f x 不是奇函数,故A 错误; 对于:0B x 时,1()111x f x x x ==-++在[0,)+∞递增,故B 正确; 对于C ,D ,画出函数()f x 和21y x =-的图象,如图示:,显然函数()f x 的值域是(,1)[0-∞-,)+∞,故C 正确,()f x 和21y x =-的图象有3个交点,故D 错误;故选:BC ．【点评】本题考查了函数的单调性,奇偶性问题,考查数形结合思想,转化思想,是一道中档题．12．下列选项中,与11sin()6π-的值相等的是( ) A ．22cos 151︒-B ．cos18cos 42sin18sin 42︒︒-︒︒C ．2sin15sin 75︒︒D ．tan30tan151tan30tan15o oo o+- 【详细分析】求出11sin()6π-的值．利用二倍角的余弦求值判断A ;利用两角和的余弦求值判断B ;利用二倍角的正弦求值判断C ;利用两角和的正切求值判断D ．【参考解答】解:111sin()sin(2)sin 6662ππππ-=-+==． 对于A ,22cos 1531cos30o -=︒=对于B ,1cos18cos42sin18sin 42cos(1842)cos602︒︒-︒︒=︒+︒=︒=; 对于C ,12sin15sin 752sin15cos15sin302︒︒=︒︒=︒=; 对于D ,tan30tan15tan(3015)tan 4511tan30tan15o oo o+=︒+︒=︒=-．∴与11sin()6π-的值相等的是BC ． 故选:BC ．【点评】本题考查三角函数的化简求值,考查诱导公式、倍角公式及两角和的三角函数,是基础题．三．填空题（共4小题）13．化简32a b -= a （其中0a >,0)b >．【详细分析】根据指数幂的运算法则即可求出．【参考解答】解1311132322()b b bb ⨯=== 原式2111()3322a b a ---==,故正确答案为:a ．【点评】本题考查了指数幂的运算,属于基础题．14．高斯是德国的著名数学家,近代数学奠基者之一,享有“数学王子”的称号,他和阿基米德、牛顿并列为世界三大数学家,用其名字命名的“高斯函数”为:设x R ∈,用[]x 表示不超过x 的最大整数,则[]y x =称为高斯函数,例如:[ 3.4]4-=-,[2.7]2=．已知函数21()15x x e f x e =-+,则函数[()]y f x =的值域是 {1-,0,1} ．【详细分析】先利用分离常数法将函数化为92()51x f x e =-+,进而求出()f x 的值域,再根据[]x 的定义可以求出[()]f x 的所有可能的值,进而得到函数的值域．【参考解答】解:212(1)212192()215151551x x x x x x e e f x e e e e+-=-=-=--=-++++, 0x e >,11x e ∴+>,∴2021x e <<+,∴19295515x e -<-<+, 即19()55f x -<<,①当1()05f x -<<时,[()]1f x =-, ②当0()1f x <时,[()]0f x =,③当91()5f x <<时,[()]1f x =, ∴函数[()]y f x =的值域是:{1-,0,1},故正确答案为:{1-,0,1}．【点评】本题主要考查了新定义运算的求解,关键是能通过分离常数的方式求得已知函数的值域,是中档题．15．若1lgx lgy +=,则25x y+的最小值为 2 ． 【详细分析】根据对数的基本运算,结合不等式的解法即可得到结论．【参考解答】解:1lgx lgy +=,1lgxy ∴=,且0x >,0y >,即10xy =, ∴25251022210x y x y +=, 当且仅当25x y =,即2x =,5y =时取等号, 故正确答案为:2【点评】本题主要考查不等式的应用,利用对数的基本运算求出10xy =是解决本题的关键,比较基础．16．若42x ππ<<,则函数32tan 2tan y x x =的最大值为 16- ．【详细分析】直接利用三角函数的性质和关系式的恒等变换的应用及二次函数的性质的应用求出结果．【参考解答】解:若42x ππ<<,则tan (1,)x ∈+∞, 另22tan tan 21tan x x x=-, 设tan x t =,(1)t >, 则422222244416111111()()24t y t t t t ===-----,当且仅当t =时,等号成立．故正确答案为:16-．【点评】本题考查的知识要点:三角函数关系式的变换,关系式的变换和二次函数的性质,主要考查学生的运算能力和转换能力及思维能力,属于中档题．四．参考解答题（共8小题）17．已知0x >,0y >,且440x y +=．（Ⅰ）求xy 的最大值; （Ⅱ）求11x y+的最小值． 【详细分析】（1）由已知得,40424x y xy =+=解不等式可求,（2）由题意得,11111()(4)40x y x y x y +=++,展开后结合基本不等式可求． 【参考解答】解:（1）0x >,0y >,40424x y xy ∴=+=当且仅当4x y =且440x y +=即20x =,5y =时取等号,解得,100xy ,故xy 的最大值100．（2）因为0x >,0y >,且440x y +=．所以111111419()(4)(5)(540404040y x x y x y x y x y +=++=+++=, 当且仅当2x y =且440x y +=即403x =,203y =时取等号, 所以11x y +的最小值940． 【点评】本题考查了基本不等式在求最值中的应用,属于中档题18．已知函数2()21f x x ax a =--+,a R ∈．（Ⅰ）若2a =,试求函数()(0)2f x y x x =>的最小值; （Ⅱ）对于任意的[0x ∈,2],不等式()f x a 成立,试求a 的取值范围;（Ⅲ）存在[0a ∈,2],使方程()2f x ax =-成立,试求x 的取值范围．【详细分析】（Ⅰ）对式子变形后,利用基本不等式即可求得结果;（Ⅱ）先由题设把问题转化为:2210x ax --对于任意的[0x ∈,2]恒成立,构造函数2()21g x x ax =--,[0x ∈,2],利用其最大值求得a 的取值范围;（Ⅲ）由题设把问题转化为:方程21a x =-在[0a ∈,2]有解,解出x 的范围．【参考解答】解:（Ⅰ）当2a =时,2()41111()22212222f x x x y x x x x -+===+-⨯-=-（当且仅当1x =时取“= “),1min y ∴=-;（Ⅱ）由题意知:221x ax a a --+对于任意的[0x ∈,2]恒成立,即2210x ax --对于任意的[0x ∈,2]恒成立,令2()21g x x ax =--,[0x ∈,2],则(0)10(2)340g g a =-⎧⎨=-⎩,解得:34a , a ∴的取值范围为3[4,)+∞; （Ⅲ）由()2f x ax =-可得:210x a -+=,即21a x =-, [0a ∈,2],2012x ∴-,解得:11x -,即x 的取值范围为[1-,1]．【点评】本题主要考查基本不等式的应用、函数的性质及不等式的解法,属于中档题．19．解方程 （1）231981x x -= （2）444log (3)log (21)log (3)x x x -=+++【详细分析】（1）直接利用有理指数幂的运算法则求解方程的解即可．（2）利用对数运算法则,化简求解方程的解即可．【参考解答】解:（1）231981x x -=,可得232x x -=-,（2分） 解得2x =或1x =;（4分）（2）444log (3)log (21)log (3)x x x -=+++,可得44log (3)log (21)(3)x x x -=++,3(21)(3)x x x ∴-=++,（2分）得4x =-或0x =,经检验0x =为所求．（4分）【点评】本题考查函数的零点与方程根的关系,对数方程的解法,考查计算能力．20．设函数3()cos 323x x f x ππ=-． （1）求()f x 的最小正周期;（2）若函数()y g x =与()y f x =的图象关于x 轴对称,求当[0x ∈,3]2时,()y g x =的最大值． 【详细分析】（1）利用辅助角公式化积,再由周期公式求周期;（2）由对称性求得()g x 的详细解析式,再由x 的范围求得函数最值．【参考解答】解:（1）3()cos sin()32333x x f x x ππππ=-=-． ()f x ∴的最小正周期为263T ππ==;（2）函数()y g x =与()y f x =的图象关于x 轴对称,()()3sin()33x g x f x ππ∴=-=-． [0x ∈,3]2,∴[333x πππ-∈-,]6π, sin()[33xππ∴-∈,1]2,()[g x ∈,3]2． ∴当[0x ∈,3]2时,()y g x =的最大值为32． 【点评】本题考查sin()y A x ωϕ=+型函数的图象和性质,考查三角函数最值的求法,是中档题．21．已知函数()cos()(0,0,||)2f x A x B A πωϕωϕ=++>><的部分图象如图所示． （Ⅰ）求()f x 的详细解析式及对称中心坐标;（Ⅱ）先将()f x 的图象纵坐标缩短到原来的12,再向右平移6π个单位,最后将图象向上平移1个单位后得到()g x 的图象,求函数()y g x =在3[,]124x ππ∈上的单调减区间和最值．【详细分析】（Ⅰ）由函数的图象的顶点坐标求出A ,B ,由周期求出ω,由特殊点的坐标求出ϕ的值,可得函数的详细解析式,再根据余弦函数的图象的对称性,得出结论． （Ⅱ）由题意利用函数sin()y A x ωϕ=+的图象变换规律,正弦函数的单调性、定义域和值域,得出结论．【参考解答】解:（Ⅰ）由函数()cos()(0,0,||)2f x A x B A πωϕωϕ=++>><的部分图象知: 1(3)22A --==,1(3)12B +-==-,72212T πππωω-==⇒=, ()2cos(2)1f x x ϕ∴=+-,把点(,1)12π代入得:cos()16πϕ+=, 即26k πϕπ+=,k Z ∈． 又||2πϕ<,∴6πϕ=-,∴()2cos(2)16f x x π=--． 由图可知(,1)3π-是其中一个对称中心, 故所求对称中心坐标为:(,1)32k ππ+-,k Z ∈． （Ⅱ）先将()f x 的图象纵坐标缩短到原来的12,可得1cos(2)62y x π=--的图象,再向右平移6π个单位,可得11cos(2)sin 2222y x x π=--=- 的图象, 最后将图象向上平移1个单位后得到1()sin 22g x x =+的图象． 由22222k x k ππππ-++,k Z ∈,可得增区间是[4k ππ-,]4k ππ+,当3[,]124x ππ∈时,函数的增区间为[,]124ππ． 则32[,]62x ππ∈,当22x π=即,4x π=时,()g x 有最大值为32, 当322x π=,即34x π=时,()g x 有最小值为11122-+=-． 【点评】本题主要考查由函数sin()y A x ωϕ=+的部分图象求详细解析式,由函数的图象的顶点坐标求出A 、B ,由周期求出ω,由特殊点的坐标求出ϕ的值,余弦函数的图象的对称性．函数sin()y A x ωϕ=+的图象变换规律,正弦函数的单调性、定义域和值域,属于中档题．22．已知函数2()2cos 12x f x x =-+．（Ⅰ）若()()6f παα=+,求tan α的值; （Ⅱ）若函数()f x 图象上所有点的纵坐标保持不变,横坐标变为原来的12倍得函数()g x 的图象,且关于x 的方程()0g x m -=在[0,]2π上有解,求m 的取值范围． 【详细分析】（Ⅰ）利用三角恒等变换,化简()f x 的详细解析式,根据条件,求得tan α的值． （Ⅱ）根据函数sin()y A x ωϕ=+的图象变换规律,求得()g x 的详细解析式,再利用正弦函数的定义域和值域,求得()g x 的范围,可得m 的范围．【参考解答】解:（Ⅰ）2()2cos 1cos 2sin()26x f x x x x x π-+-=-,()()6f παα=+,∴sin()6παα-=,∴1cos 2ααα-=,即cos αα-=,∴tan α=（Ⅱ）把()f x 图象上所有点横坐标变为原来的12倍得到函数()g x 的图象, 所以函数()g x 的详细解析式为()(2)2sin(2)6g x f x x π==-, 关于x 的方程()0g x m -=在[0,]2π上有解, 等价于求()g x 在[0,]2π上的值域, 因为02x π,所以52666x πππ--, 所以1()2g x -,故m 的取值范围为[1-,2]．【点评】本题主要考查三角恒等变换,函数sin()y A x ωϕ=+的图象变换规律,正弦函数的定义域和值域,属于中档题．。

河北省武邑中学2020-2021学年高二英语下学期6月期末复习试题2第一部分阅读理解 AI want you all to know that I’ve quit social media, and my life has gotten so much better. I mean, it’s only been 15 minutes but I can already tell I’m a different person. Fifteen minutes ago, I stopped using Facebook and Twitter. Within seconds, I noticed I am happier, less irritable, more contemplative (深思熟虑的) and balanced. I’m spending more time on activities that matter. Just in the past two minutes, I’ve looked at a book on my bo okshelf and briefly pondered opening it.I’m truly changing. This is going to sound crazy, but since quitting social media—now, let’s see, 16 minutes ago—all of my senses are enhanced. My eyesight is clearer. Food tastes better. I just smelled the first tulips of spring. I am jolted by a burst of energy. Every morning I am going to meditate or at least lie in my bed and consider meditating.What purpose does social media serve, anyhow? The academics tell us it’s making us miserable—the constant updates from friends with their expensive vacations and gossips about celebrities. If you think about it, the Internet was really only supposed to be for one thing: ordering socks from J. Crew. Then people started posting photographs of their dogs in Halloween costumes, and we all began sending Happy Birthday wishes to classmates we’d lost touch with since fifth grade, and the whole thing became the nightmare.Social media ruins perfectly good human beings. There are people I lovein real life and hate on social media. Worst still, social media stifles( 抑制) creativity. They’ve studied this in rats, you know. Scientists made rats quit using Facebook, and when they came back in a few hours, all of the rats were writing really solid debut novels.It’s been 17 minutes. I have a feeling that my quitting social media is having a physical effect. All I did was quit looking at my phone 900 times a day. I’ll tell them the secret. Quit social media. All of life’s annoying problems will be over. Your relationships will improve. Y ou’ll never feel down. You’ll never get stuck in traffic.Do I miss it? Thanks for asking. I don’t even know why I thought it was so important. I do not need to see the 800th photo from my co-worker’s trip.I have no idea how a hot topic is going on. And i t’s OK. I can’t imagine going back. I’ve quit social media. It’s only been 18 minutes, but I’m pretty sure I’m going to make it a full twenty.1. What was the Internet originally used to do according to the passage?A. To read digital books.B. To do shopping online.C. To make some new friends.D. To share holiday experience.2. The author keeps counting the time in order to ______.A. show how fantastic it is to quitB. prove it a struggling process to quitC. remind himself of the time in quittingD. make a record for his study of quitting3. What is the tone of this article?A. Official.B. Serious.C. Humorous.D. Plain.4. Which of the following would be the best title for the passage?A. How I Made an Important DecisionB. Why We Can’t Live Without the InternetC. The Influence of Social Media: Pros & ConsD. Quitting Social Media Will Save Your LifeBMost people have been taught that losing weight is a matter of simple math. Cut calories—specifically 3,500 calories, and you’ll lose a pound. But as it turns out, experts are learning that this decades-old strategy is actually pretty misguided. “This idea of ‘a calorie in and a calorie out’ when it comes to weight loss is not only outdated, it’s just wrong,” says Dr. Fa tima Cody Stanford, an obesity specialist at Harvard Medical School. The truth is that even careful calorie calculations don’t always yield(产生) uniform results.How your body burns calories depends on a number of factors. Three factors affect how your body processes calories.Your gut microbiome (肠道微生物). Trillions of organisms live in your gut, and the important types may influence how many calories your body absorbs from food. This may occur because some types of organisms are able to break down and use more calories from certain foods than other types of organisms. Researchers have found that people who are naturally thin have different typesof organisms living inside them than those who are overweight.Your metabolism (新陈代谢). Each body has a “set point” that governs weight, says Dr. Stanford. This set point reflects several factors, including your genes, your environment, and your behaviors. A region at the base of your brain stands guard to keep your body weight from dipping below that set point—which is not really a bonus if you’re trying to lose weight.The type of food you eat. Your food choices may also influence your calorie intake, and not just because of their specific calorie content. One 2019 study published in Cell Metabolism found that eating processed foods seems to spur people to eat more calories compared with eating unprocessed foods.If counting calories isn’t a dependable way to manage your weight, what can you do to shed extra pounds? Dr.Stanford recommends the following.Focus on diet quality. When planning your meals, focus on choosing unprocessed foods, including lean meats, whole grains, and lots of fruits and vegetables in their natural form.Exercise regularly. Aim to get at least 150 minutes of moderate-intensity exercise each week. Moderate exercise is done at a level where you can talk, but not sing.Consult a professional. “A lot of people believe it’s a moral failing if they are unable to lose weight,” says Dr. Stanford. But it’s not. As with other medical conditions, many people will need help from a doctor. Successful weight loss may require more than just diet and exercise. “Only 2% of peoplewho meet the criteria for the use of anti-obesity medications actually get them. This means that 98% of people who could be treated are n’t,” she says, “Don’t be afraid to seek help if you need it.”5. What can we infer from Paragraph 1?A. Old theories actually mislead us.B. Losing weight lies in losing calorie.C. Calorie calculations lead to good results.D. Losing weight by losing calorie is outdated.6. The processing of calories is affected by how you ______.A. choose the types of food you consumeB. focus on the quality of your dietC. adjust your brain to the “set point”D. reduce the organisms living in your gut7. T he underlined word “shed” in Paragraph 6 means “______”.A. weighB. produceC. loseD. cost8. It is implied in the passage that ______.A. cutting calories is essential for weight lossB. losing weight can be double-edgedC. healthy eating keeps you losing weightD. a healthy lifestyle is key to weight loss七选五How to pass an important testWhether it's a first grade science test or College Entrance Exam, all tests have one thing in common: you have to pass. 9 . Stuck in a situationwhere you don't know what to do? This article can help.Tips★Once you get the study guide, make plans right away to study as soon as possible. No excuses! Killing time with friends isn't worth it, since you can always hang out with them any other day.★Get plenty of rest. 10 . If you walk into the classroom sleepily, you'll most likely not finish the test because you are so tired.★Eat a good meal for breakfast. 11 . Some healthy breakfast suggestions are oatmeal (燕麦片), high fibre food, and grapefruit with the fresh fruit salad.★Bring all necessary materials. 12 . Bring pencils, pens, pencil sharpeners, snacks (if allowed), erasers, the calculator (if allowed) and anything else you'll need for the test.★ 13 . Showing up late cuts back the time you'll have to take for the test if it's already testing hours. You'll probably miss any important information needed in completing the test. In some tests, late comers are not allowed to take the test.A. The exam tests vocabulary, reading and maths skills.B. One piece of cheese probably won't last until test time.C. Don't forget to set your alarm clock and show up on the test day on time.D. Studies show that if you get enough sleep, your brain will be much more efficient.E. Showing up without something as simple as a pencil can make a big effecton your test.F. Failing the test won't help you in the long run, so it's important toknow how to prepare to pass that big test.G. This test is a challenging one and every year many students are unableto qualify just because of lack of guidance.二、完形填空When I tried out for the football team during the summer before 9th grade,I never imagined how important this sport would become in my life. Footballis a 1 sport, at times almost painful, and practices really 2 a team’s physical and mental limits. Without trust in my own ability and a strong sense of commitment (投入), I would never have managed to continue after years of hard work as a player, and with countless 3 .In the first year, I played on the defensive line. This was an amazing 4 that gave me a great sense of achievement. But in the last game of the season,I was seriously injured. I was prohibited from any physical activities for six months. After going 5 a series of physical treatments, I returned to the field as a team captain. I practiced harder than ever to make up for my6 time.In September, during my junior year, my name was mentioned in the local newspaper as the key defensive linemen on the team. After playing a fantastic season, I was given the 7 of Most Valuable Player.8 , my skills in football do not magically extend to other sports. During the winter break, I went on a snowboarding trip and seriously injured my right shoulder. I had to have four 9 . Since I could not use my right arm for two months, I had to learn how to write and eat using my left hand.10 life must go on. I knew that my own present efforts would decide m y f u t u r e,s o I11 the strict training program to build strength and improve flexibility in my 12 . After an eight-month recovery, I was back out on the field playing football, the sport I 13 .In this sense, the world of football has taught me an important life lesson: 14and commitment make what seems impossible 15 . This lesson from football is one that I know translates through every part of life.1. A. tough B. popular C. typical D. dynamic2. A. set B. control C. test D. require3. A. mistakes B. adventures C. accidents D. injuries4. A. performance B. position C. moment D. advantage5. A. with B. over C. through D. into6. A. valuable B. lost C. extra D. regular7. A. pride B. choice C. name D. honor8. A. Unfortunately B. Similarly C. Happily D. Gradually9. A. practices B. tryouts C. seasons D.operations10. A. But B. Or C. So D. And11. A. examined B. changed C. provided D. completed12. A. shoulder B. hand C. leg D. foot13. A. explore B. avoid C. love D. support14. A. Knowledge B. Belief C. Experience D. Opinion15. A. enjoyable B. possible C. sensible D. responsible三、应用文写作假定你是李华, 你的美国笔友 Jim 对你校社团的近期活动非常感兴趣。

《广告概论》考试试卷一 单项选择题。

在每小题列出的四个选项中只有一个是符合题目要求的，请将正确选 项前的字母填在题后的括号内。

多选、少选、漏选、错选，均无分。

（本大题共20小题，每 小题1分，共20分） 北京路上有些商店的售货员站在门口击掌引起路人注意，并高声邀请路人入店属于（） 广告形式。

A. 口头广告 B.实物广告 广告的作用不包括（）。

A.指导消费 B.促进销售香烟广告不准进入电视反映了A.生产观念B.推销观念1. 2. 3. 4. C.标记广告 D.招牌广告 C.塑造形象 ）。

C.营销观念D.增加宣传成本 有很多女性会受打折影响而购买了并不需要的东西，A.情绪化心理B.情感丰富 “味道好极了！”这句广告语体现了 A.品名定位B.品质定位“孔府家酒，叫人想家”是属于（ A.理性诉求广告 B.企业广告 C.感性诉求广告 D.形象广告第一部《中华人民共和国广告法》于（）年施行。

A.1985B.2001C.1992D.1995理发店的门口常常挂着三色柱，这是（）广告形式。

A. 口头广告 B.实物广告 C.标记广告 D.招牌广告 产品引入期的广告多采用（）。

A.报道式广告B.劝导式广告 5. 6. 7. 9.）。

A.商品广告B.企业广告 11. 下列媒体可信度最好的是（）。

A.江苏卫视 B.安徽卫视12. 广告创意的出发点和基础是（ A.广告口号 B.广告标语 ）。

C.爱炫耀的心理 （）。

C.价格定位 ）。

D.社会营销观念 反映了女性的（）o D.爱美的心理 C.提醒式广告 C.品牌广告 C.浙江卫视 C.广告主题 D.功效定位D.竞争式广告D.观念广告 D. CCTV-1 D.广告文案13. 广告语言对（）、市场营销和社会文化起着重要作用。

A.市场运作B.市场环境C.市场活动D.市场经济 14. “农夫山泉，有点甜”体现了广告语言创作的（）原则。

A.生动形象、煽动性强 B.新颖贴切、个性鲜明 C.通俗易懂、便于记忆 D.真实可信、科学准确 15. 利用思考的连锁反应引发新创意是（）的特点。

2022-2023学年北京市中国人民大学附属中学高二上学期期末复习（二）数学试题一、单选题1．设复数，是z 的共轭复数，则（ ）3i1i z +=-z z z ⋅=A ．-3B ．-1C ．3D ．5【答案】D【分析】先利用复数的除法化简，进而得到共轭复数，再利用复数的乘法运算求解.【详解】解：∵，()()()()3i 1i 3i 12i 1i 1i 1i z +++===++-+∴，．12i z =-()()2212i 12i 125z z ⋅=+-=+=故选：D ．2．已知向量，，且，则实数的值为（ ）．(),2,1a m =()1,0,4b =-a b ⊥m A ．4B ．C ．2D ．4-2-【答案】A【分析】依题意可得，根据数量积的坐标表示得到方程，解得即可.0a b ⋅=【详解】解：因为，，且，(),2,1a m =()1,0,4b =-a b ⊥ 所以，解得.40a b m ⋅=-+=4m =故选：A3．抛物线的准线方程是（ ）22y x =A ．B ．C ．D ．12x =12x =-18y =18y =-【答案】D【分析】先将抛物线方程化为标准形式，再根据抛物线的性质求出其准线方程.【详解】抛物线的方程可化为x 2y12=故128p =其准线方程为y 18=-故选：D4．已知双曲线C ：有相等的焦距，则22221x y a b -=2215x y +=C 的方程为（ ）A ．B ．2213x y -=2213y x -=C ．D ．22193x y -=22139x y -=【答案】B【分析】根据椭圆的焦距可得双曲线C ：的焦距，根据双曲线C ：2215x y +=22221x y a b -=2c求得，即可得出答案.22221x y a b -=ba =222c ab =+22,a b【详解】解：因为双曲线C ：22221x y a b -=所以，ba =b =椭圆的焦距为，2215x y +=4所以双曲线C ：的焦距，即，22221x y a b -=24c =2c =又因，解得，所以，2222234c a b a a =+=+=21a =23b =所以C 的方程为.2213y x -=故选：B.5．如图是抛物线形拱桥，当水面在l 时，拱顶离水面2米，水面宽4米，水位下降1米后，水面宽（ ）米．A ．B ．C ．D ．【答案】B【分析】通过建立直角坐标系，设出抛物线方程，将A 点代入抛物线方程求得m ，得到抛物线方程，再把B （x 0，﹣3）代入抛物线方程求得x 0进而得到答案．【详解】如图建立直角坐标系，设抛物线方程为x 2＝my ，将A （2，﹣2）代入x 2＝my ，得m ＝﹣2∴x 2＝﹣2y ，B （x 0，﹣3）代入方程得x 0，=故水面宽为．故选：B ．6．如图，已知正方形所在平面与正方形所在平面构成的二面角，则异面直线ABCD ABEF 60︒与所成角的余弦值为（ ）．AC BFA ．B ．CD 1412【答案】A【分析】根据题目条件可知，即为平面与平面构成二面角的平面角，将异面直EBC ∠ABCD ABEF 线与所成角的余弦值转化成直线方向向量夹角余弦值的绝对值即可.AC BF 【详解】根据题意可知，即为平面与平面构成二面角的平面角，所以EBC ∠ABCD ABEF ，60EBC ∠= 设正方形边长为1，异面直线与所成的角为，AC BF θ，，AC AB BC =+ BF BE EF =+EF BA ==- 所以()))(()(BF BE E AC AB BC AB BC F BE AB +==++- 即210(1)11cos 6002BF BE B AC AB AB BC BC E AB =-+-=+-+⨯⨯-=-所以；4c os 1,A A BF BF B C AC C F==-= 即，1cos cos ,4F AC B θ==所以，异面直线与所成角的余弦值为.AC BF 14故选：A.7．对于直线：（），现有下列说法：l 10ax ay a +-=0a ≠①无论如何变化，直线l 的倾斜角大小不变；a ②无论如何变化，直线l 一定不经过第三象限；a ③无论如何变化，直线l 必经过第一、二、三象限；a ④当取不同数值时，可得到一组平行直线．a 其中正确的个数是（ ）A ．B ．C ．D ．1234【答案】C【分析】将直线化为斜截式方程，得出直线的斜率与倾斜角，可判断①正确，④正确；由直线的纵截距为正，可判断②正确，③错误．【详解】直线：（），可化简为：，即，则直线的斜率l 10ax ay a +-=0a ≠210x y a +-=21y x a =-+为，倾斜角为，故①正确；直线在轴上的截距为，可得直线经过一二四象限，故1-135︒y 210a >②正确，③错误；当取不同数值时，可得到一组斜率为的平行直线，故④正确；a 1-故选：C8．已知是椭圆的两个焦点，若椭圆上存在点满足，则的12F F ，22:18x y C m +=C P 1290F PF ∠=︒m 取值范围是（ ）A ．B ．(][)0,216,+∞ (][)0,416,+∞ C ．D ．(][)0,28,+∞ (][)0,48,+∞ 【答案】B【分析】利用圆的直径所对圆周角为，将椭圆上存在点满足，转化为以90︒C P 1290F PF ∠=︒为直径的圆与椭圆有交点，即可求解.12F F 【详解】解：若椭圆上存在点满足，只需满足以为直径的圆与椭圆有交点，C P 1290F PF ∠=︒12F F即,即，122F F b c ≤=22b c ≤当时,椭圆的焦点在轴上,此时，则，解得：，8m <x 2228,,8a b m c m ===-8m m ≤-4m ≤当时，椭圆的焦点在轴上，此时，则，解得：.8m >y 222,8,8a m b c m ===-88m ≤-16m ≥综上，.(][)0,416,m ∈+∞ 故选：B【点睛】本题考查椭圆的基本性质，属于较易题。

2019学年七年级英语下学期期末复习（二）试题一、选择题1．— Would you like . —No, thanks. I’m full.A．something else B．else something C．anything else D．else anything2．--______was your school trip? --It was great!A．How B．Where C．When D．Why.3．---What did she do yesterday? ----She_______ at home.A．stayed B．staying C．staied D．stays4．—Your hair is very beautiful. — __________A．No, it isn’t B．Thank youC．Not at all D．You’re welcome5．Those are my twin sisters. _______ of them are interested in soap operas. A．Each B．All C．Both D．One6．- Are you happy to have the two-month summer holiday?-Sure. We can relax ourselves and do many things we like.A．two months B．two month C．two months’D．two month’s7．_____do you want to see them? _____ they’re interesting.A．Why , so B．Why, Because C．Because, So D．So, Why8．________late for school again.A．Not B．Not be C．Don’t be D．Aren’t9．The Internet is really ________ to us. We can download a lot of things from it.A. usefulB. difficultC. different10．It usually takes him 10 minutes ________ to school.A. walksB. to walkC. walk11．—What does your sister do on Sunday evening?—She usually books but now she TV.A. read, watchB. reads, is watchingC. is reading, watches 12．—Where is Vickers now?—He ________ in the reading room.A. readB. readingC. is reading13．She is in Canada vacation now.A．in B．on C．at D．to14．Her mother goes to work ________ bus every morning.A. byB. atC. on15．My father is a policeman. He is ________ help with my lessons.A．enough busy to B．busy enough toC．too busy to D．very busy to16．— Could you teach me how to use the computer?—___________.A．Never mind B．Not at allC．No problem D．That’s all right17．There are about _______________ students in our school.A．four thousand B．four thousands ofC．four thousand of D．thousand of18．—the weather ?—It’s rainingA. How’s, likeB. What’s, likeC. what’s, /19．film Alice Through the Looking Glass（爱丽丝镜中奇遇记）was shown on 27 May.It is __________wonderful film.A．A; a B．An; a C．The; a D．The; an20．— Look at my new watch!— How beautiful!____________, where did you buy it?A．On the way B．In the wayC．By the way D．In this way二、完型填空In Australia, different people have different ways to enjoy themselves. They also have their own ideas about ______ to pass time.______ children, about 80%, work hard in school because they have to take lots of exams. ______ school, they don’t want to stay at home reading books any more. Instead, they put aside their school bags and go out to play.Some old people ______ early in the morning. Then they go to park to ______. It helps them know what is happening around the world. In the evening, they would prefer to stay at home ______ rather than do anything else.Young people enjoy having ______ trips on weekends. They go to mountains to have a picnic or ______to the forest to camp. They usually start on Friday and spend one or two days outside. Then on ______ evening, they start their way backhome. Nobody seems to be in a hurry, although a busy week is waiting for ___ again.21．A. what B. how C. when22．A. Some B. Most C. All23．A. In B. At C. After24．A. get up B. come up C. stay up25．A. read newspapers B. do sports C. enjoy themselves26．A. climbing hills B. watching TV C. going shopping27．A. boring B. busy C. relaxing28．A. go B. goes C. went29．A. Friday B. Sunday C. Tuesday30．A. they B. them C. their三、阅读单选Studying in groups is becoming more and more popular in class. It has many advantages. For example, we can not only save time but also encourage each other when we study in groups. I still remember when I was in Grade 8, my physics was very poor, I had a really hard time with it. Once in class, the teachers asked us to discuss it with each other, but I was very shy, I could not do it like what they told me. My physics teacher encouraged me to face others and talk with someone else bravely, then I studied with some classmates together. When I did not understand any questions, they could give me some advice, I could quickly find out the ways to deal with the problems. After that, I felt very relaxed and asked my classmates a lot of questions about physics. I did not feel stressed out at all. At last, I finished my homework by myself for the first time. How excited I was!Because of studying in groups, I am not worried about physics any more. With my classmates’ help, I get more confidence. It also gives me more chances to improve myself in many ways. So let’s study more in groups.Choose the best choice from A, B or C according to what you read.31．What subject was poor for the writer in Grade 8?A. English.B. Physics.C. Math.32．we can __________each other when we study in groups.A. save timeB. encourage each otherC.A和B33．________encouraged me to face others and talk with someone else bravely.A. My motherB. My physics teacherC. No one34．Which of the following is WRONG in this article?A.I felt relaxed after studying in groups.B. With my classmates’ help, I get more confidence.C. I am still worrying about physics because of studying with my classmates. 35．What is the best title of the article?A.To study in groups.B. To do homework in groups.C. To study alone.Love is the most (最) important thing in the world (世界). We need love in our life and the world also needs love to get better.When I was a little girl, I thought that my father didn’t love me. He let me do everything by myself. I was afraid of darkness (黑暗), but he let me walk home alone. When I did well in my study, he only said, “Be better.” I couldn’t understand (明白) him. Where was his love?But one day, I understood his love. It was a rainy day. School was over. At first I was not happy because I didn’t ha ve an umbrella.But then I saw that my father with a big umbrella walking in the rain. He kept me away from the rain with the umbrella and we ran home together. He was all wet. On that day, I knew my father loved me very much. I understand what love is. 36．The writer thinks the most important thing in the world is _________.A. moneyB. timeC. love37．The girl was not happy on a rainy day because________.A. she didn’t see her fatherB. she was afraidC. she didn’t have an umbrella38．The underlined (划线的) word “wet” means “_______” in Chinese.A. 累的B. 湿的C. 干的39．Which is TRUE (正确的)?A. The girl’s father didn’t love her.B. The girl’s father often let her walk home alone.C. The girl’s father took an umbrella to school every day.40．Which is the best title (标题) for the passage (短文)?A. Father’ s LoveB. An UmbrellaC. My FatherOn Christmas Eve—the night before Christmas, children are very happy. They put their stockings at the end of their beds before they go to bed. They want Santa Claus to give them some presents.Mr. Green tells his children that Santa Claus is a very kind man. He comes on Christmas Eve. He lands on (降落) the top of each house and comes down the chimney (烟囱) into the fireplace (壁炉) and brings them a lot of presents.Christmas Day always begins before breakfast. The children wake up very early. They can’t wait (等待) to open the presents in their stockings. Then they wake up their parents and shout "Merry Christmas!"Do you know what Christmas means? Christmas Day is the birthday of Jesus Christ. When Christ was born, many people gave him presents. So today, people still do the same thing to each other.41．Christmas Eve is ____________.A．the night before December 24 B．the night after December 25C．the night of December 24 D．the night of December 2542．Santa Claus often puts the presents __________.A．into Children’s hats B．into children’s stockingsC．under children’s beds D．into children’s shoes43．Santa Claus comes into the house through(通过) the ________.A．window B．doorC．chimney D．fireplace44．On the morning of Christmas Day, children say "________ " to their parents. A．Good morning! B．Thank you!C．Good luck! D．Merry Christmas!45．On Christmas Day, people often give_______ to each other.A．presents B．lucky moneyC．Christmas trees D．stockingsLeopards ( 豹 ) live in many parts of the world , from Siberia to Africa .They have a very beautiful yellow skin with large black spots. They live for about 15 years and eat small mammals (哺乳动物) such as zebras, monkeys, and antelopes ( 羚羊) .They sleep for about 12 hours a day . Leopards are very solitary（独居的）animals. They spend most of their time alone in trees , where they wait until a small animal passes . they jump on the animal and then drag it up into the tree, where they eat it. Like many animals ,leopards are disappearing because people hunt them. They kill them for their beautiful coats. The Sinai leopard , for example , from Egypt, is now probably extinct（绝种的）.46．How long does a leopard usually live?A．Fifty weeks B．Fifteen months C．Twelve days D．Fifteen years47．Leopards_______________ .A．live in family groups B．live aloneC．live together D．live with other animals 48．Leopards spend much time in tree because they want to_____________ .A．sleep B．jump C．wait and catchsmall mammals D．rest49．Which is not true ?A．Leopards have beautiful furB．Leopards eat animals and plantsC．Leopards sleep 12 hours a dayD．The Sinai leopard probably extinct50．Why do people hunt leopards ? Because .A．they kill them for their meat B．they attack people all the time C．they are dangerous D．they kill them for their coats四、从所给句子中选择恰当的句子完成下面的对话。

专项一字词与句子一、给下列加点字的正确读音打“√”。

投掷．(zhèng zhì) 缭．乱( liáo niáo) 咖．啡(jiā kā) 旭．日(xǜ xù) 暸．望( liáo liào) 选择．( zé zhé) 脊．梁(jǐ jí) 崇．高(chóng cóng) 醋．酸( cù còu) 二、看拼音,写词语。

xiān xì lián peng tíng zhǐào mànfēi yuè chéng xiàn jiàn zào cháng tú三、给下列多音字组词。

杆gān ( ) 禁 jīn ( ) 都dōu( )gǎn ( ) jìn ( ) dū( )和hé ( ) 嚷 rāng( ) 折zhé ( )huò ( ) rǎng ( ) zhé ( )四、给下列字加偏旁组成新字,再组词。

占______( ) 寸______( ) 扁______( ) ______( ) ______( ) ______( ) 弗______( ) 土______( ) 包______( ) ______( ) ______( ) ______( ) 五、将下列词语补充完整。

没( )打( ) ( )( )并论兴( )采( )争( )斗( ) 窃窃( )( ) 人山( )( )善( )甘( ) 奔流( )( ) 双( )戏( )六、照样子,写词语。

金灿灿(ABB式)______________ ______________ ______________波光粼粼(ABCC式)______________ ______________ ______________无忧无虑(无×无×式)______________ ______________ ______________走南闯北(含方位词的)______________ ______________ ______________七、写出下列词语的近义词或反义词。