阶段性测试题16

山西省吕梁市2024-2025学年高三上学期11月期中阶段性测试数学试题一、单选题1．已知集合{}2,1,0,1,2A =--，{}22B x x =<，则A B = （）A ．{}1B ．{}0,1C ．{}0,1,2D ．{}1,0,1-2．已知复数()21i =+z ，则z =（）A ．2BC ．1D ．123．下列函数中，既是奇函数又是减函数的是（）A ．()cos f x x =B ．()1f x x=C ．()13f x x=-D ．()22x xf x -=-4．已知数列{}n a 的各项均不为0，设甲：()2*22,3n n n a a a n n -+=∈≥N ；乙：数列{}n a 是等比数列，则甲是乙的（）A ．充分不必要条件B ．必要不充分条件C ．充要条件D ．既不充分也不必要条件5．已知ABC V 满足AB AC ⊥ ，3144AM AB AC =+ ，且向量BA 在向量BC 上的投影向量为34BC uu ur ，则tan CMA ∠=（）A ．12B ．CD ．26．如图，设矩形()ABCD AB AD <的周长为8cm ，把ACD 沿AC 向ABC V 折叠，AD 折过去后交BC 于点P ，记ABP 的周长为l ，面积为S ，则Sl的最大值为（）A ．3-B ．3+C ．6+D ．6-7．已知函数()f x 是定义在R 上的奇函数，且()1f x +为偶函数，当01x ≤≤时，()2321x f x x =+-，则下列结论中正确的是（）A ．()143f >B ．1633f ⎛⎫< ⎪⎝⎭C ．()ln33f <D ．()2log 183f <8．当[]0,2πx ∈时，曲线()π2sin 03y x ωω⎛⎫=-> ⎪⎝⎭与sin π2x y ⎛⎫=- ⎪⎝⎭的交点个数为4个，则实数ω的取值范围是（）A ．513,36⎛⎫⎪⎝⎭B ．513,36⎫⎡⎪⎢⎣⎭C ．513,36⎛⎤ ⎥⎝⎦D ．138,63⎡⎫⎪⎢⎣⎭二、多选题9．下列命题正确的是（）A ．1sin cos tan 1tan θθθθ⎛⎫+= ⎪⎝⎭B ．(sin 40tan101︒︒-=C ．在等差数列{}n a 中，n a m =，m a n =，()m n ≠，则0m n a +=D ．在等差数列{}n a 中，n S 为其前n 项和，若46S =，810S =，则1618S =10．若实数,x y 满足22223x y xy +-=，则（）A ．223x y +≤B ．32xy ≥C ．x y +≥D ．y x -≤11．已知函数()1ln 1x f x x x +=--，则下列结论正确的是（）A ．若0a b <<，则()()f a f b >B ．()f x 有两个零点C ．()()20232024log 2024log 20230f f +=D ．若()e 1e 1b b f a b +=--，()0,1a ∈，()0,b ∈+∞，则e 1b a =三、填空题12．已知向量()2,3a = ，3,2b m ⎛⎫= ⎪⎝⎭，且()2a b a +//，则m =．13．对于数列{}n a ，定义数列{}1n n a a ++为数列{}n a 的“和数列”，若11a =，数列{}n a 的“和数列”的通项公式为32n ⋅，则数列{}n a 的前21项和21S =．（结果保留指数形式）14．在锐角ABC 中，角A ，B ，C 的对边分别为a ，b ，c ，若22b a ac -=，则ab ba+的取值范围为．四、解答题15．已知函数()()2cos 2cos 10,f x x x x x ωωωω=-+>∈R ，且()f x 的最小正周期为π．(1)将函数()f x 的图象向右平移()0ϕϕ>个单位长度，得到函数()g x 的图象，若()g x 是偶函数，求ϕ的最小值；(2)若()65f θ=，π0,3θ⎡⎤∈⎢⎥⎣⎦，求cos 2θ的值．16．已知函数()()22log 22f x x x =-+．(1)证明：曲线()y f x =是轴对称图形；(2)若函数()()32223f xg x x x a =+-+在[]3,3-上有三个零点，求实数a 的取值范围．17．民族要复兴，乡村需振兴．为响应国家号召，我市城市规划管理局拟将某乡村一三角形区域规划成休闲度假区，通过文旅赋能乡村经济发展．度假区按如图所示规划为三个功能区：PBC △区域规划为露营区，PAB 区域规划为休闲垂钓区，PAC 区域规划为自由活动区．为安全起见，预在鱼塘四周围筑护栏．已知90ABC ∠=︒，AB =，3km BC =，P 为ABC V 内一点，120BPC ∠=︒．(1)当PB =时，求护栏的长度（PAB 的周长）；(2)若120APB ∠=︒，求tan PBA ∠；(3)为了容纳更多的游客，露营区的面积要尽可能大，求露营区面积的最大值．18．已知函数()()()ln f x x x m m =+∈R ．(1)令()()2f x g x mx x x=++，求()g x 的单调区间；(2)若存在()1212,x x x x <使得()()12f x f x =，求证：2212e mx x --<．19．对于无穷数列{}n a ，“若存在()*,,m k a a t m k N m k -=∈>，必有11m k a a t ++-=”，则称数列{}n a 具有()M t 性质．(1)若数列{}n a 满足()()*21,2253,n n n a n n n ⎧=⎪=⎨-≥∈⎪⎩N判断数列{}n a 是否具有()1M 性质？是否具有()4M 性质？(2)把（1）中满足()M t 性质的t 从小到大一一列出，构成新的数列{}n b ，若12121inn b i S ==-∑，求证：2n S <；(3)对于无穷数列{}n a ，设{},j i T x x a a i j ==-<，若数列{}n a 具有()0M 性质，求集合T 中元素个数的最大值．（写出表达式即可，结论不需要证明）。

第1篇情商（Emotional Quotient，EQ）是指一个人识别、理解、管理和运用情绪的能力。

在这个年龄阶段，了解自己的情商对于个人成长和社交互动都非常重要。

以下是一份专为16岁青少年设计的情商测试题，旨在帮助你更好地认识自己的情绪管理能力和社交技巧。

测试说明：请仔细阅读每个问题，根据你的实际情况选择最符合你的答案。

每道题有四个选项，分别代表不同的情绪管理方式或态度。

请选择最贴近你自己的选项。

第一部分：情绪识别1. 当你感到沮丧时，你会：A. 尝试找到原因并解决问题B. 寻找朋友倾诉C. 选择一个人待着，让自己冷静下来D. 压抑情绪，不想让别人知道2. 当你在学校遇到困难时，你会：A. 尝试自己解决问题B. 寻求老师或同学的帮助C. 放弃，认为解决不了D. 将困难藏在心里，不告诉任何人3. 当你的朋友遇到困难时，你会：A. 提供帮助，尽力解决问题B. 给予安慰，让他们感到支持C. 觉得自己无能为力，不采取行动D. 认为他们的困难与自己无关4. 当你在课堂上发言时，有人嘲笑你，你会：A. 保持冷静，忽略嘲笑B. 解释自己的观点，争取理解C. 感到尴尬，不再发言D. 与嘲笑者争吵，引发冲突第二部分：情绪理解5. 当你的朋友突然情绪低落时，你会：A. 假设他们一定遇到了什么问题B. 询问他们发生了什么事，给予关心C. 认为他们只是心情不好，不必太在意D. 觉得他们无理取闹，不愿意理睬6. 当你在比赛中失利时，你会：A. 分析原因，总结经验教训B. 觉得自己不够努力，下次会更加努力C. 认为比赛不公平，感到不公平D. 完全放弃，不再参加类似比赛7. 当你的父母工作压力大时，你会：A. 主动询问他们的需求，提供帮助B. 尽量不给他们添麻烦，以免让他们更累C. 觉得他们应该自己解决问题D. 认为他们不应该把工作带回家8. 当你的朋友向你倾诉烦恼时，你会：A. 仔细聆听，给予建议B. 分享自己的经历，试图让他们感到安慰C. 认为他们的问题不重要，不想听D. 提供解决方案，让他们立即行动第三部分：情绪管理9. 当你感到愤怒时，你会：A. 深呼吸，冷静下来，再思考如何处理B. 找个地方发泄，比如大声喊叫或摔东西C. 压抑情绪，不让别人知道D. 与愤怒的人争吵，试图证明自己是对的10. 当你感到焦虑时，你会：A. 制定计划，逐步解决问题B. 与朋友聊天，分散注意力C. 逃避问题，不愿意面对D. 过度担忧，陷入焦虑的循环11. 当你感到沮丧时，你会：A. 尝试做一些让自己开心的事情B. 找朋友倾诉，寻求支持C. 放弃，认为自己无法改变现状D. 将沮丧情绪压抑在心里，不让别人知道12. 当你遇到挫折时，你会：A. 保持积极态度，相信自己能够克服困难B. 分析原因，寻找改进方法C. 感到绝望，不再努力D. 将挫折归咎于他人，抱怨环境第四部分：社交技巧13. 当你在新的社交场合时，你会：A. 主动与别人打招呼，积极参与B. 观察别人，寻找可以交谈的人C. 选择一个人待着，不主动与人交流D. 感到害羞，不愿意与人交往14. 当你的朋友之间发生争执时，你会：A. 尽力调解，帮助解决问题B. 保持中立，不参与争执C. 觉得自己无能为力，不采取行动D. 偏袒一方，加剧争执15. 当你在团队活动中需要合作时，你会：A. 积极参与，提出建议B. 观察别人，寻找可以合作的人C. 选择一个人工作，不愿意与他人合作D. 认为团队活动不重要，不愿意参与16. 当你在社交场合中遇到尴尬的场面时，你会：A. 保持冷静，化解尴尬B. 感到尴尬，逃避问题C. 与尴尬的人争吵，试图证明自己D. 认为尴尬场面与自己无关，不予理会测试结果分析：请在答题结束后，根据你的选择统计每个部分的得分。

高三地理二轮阶段性测试题（含解析）本卷分为第Ⅰ卷(挑选题)和第Ⅱ卷(综合题)，满分100分，时间90分钟。

第Ⅰ卷(挑选题共50分)一、挑选题(本大题共25小题，每小题2分，共50分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

)林线是垂直自然带谱中一条重要的生态界限，通常是指高海拔处树木(针叶林)生长的上限。

下图示意我国局部区域林线海拔散布。

读图完成1～3题。

1.依图可知，E地与F地的林线海拔相差()A.1 800～2 000米B.800～1 000米C.1 200～1 600米D.1 000～1 200米【答案】 C【解析】根据等值线“大于大的，小于小的”原则可知，F地林线海拔为4 400～4 600米;E地林线海拔为3 000～3 200米，交叉相减得到结论。

2.导致D地林线比E地海拔高的主要影响因素是()A.地势B.纬度位置C.海陆位置D.大气环流【答案】 B【解析】D地纬度低，气温高使其林线较高，所以主要影响因素是纬度位置。

3.G地实际林线较低的原因是()A.纬度低，林线低B.坡度陡，林线低C.降水多，林线低D.降水少，林线低【答案】 D【解析】G地位于滇南，海拔较低，降水较少，导致实际林线较低。

读某国樱花开放日期等值线图，回答4～5题。

4.已知该国同纬度樱花开放日期的不同主要是地势导致的，据图判定该国平原地势主要散布在()A.东部B.西部C.北部D.南部【答案】 B【解析】由图可知，该国的樱花开放日期等值线在西部偏向高纬度地区，这说明西部的温度偏高，即西部的地势较低，故该国的平原最可能散布在西部。

5.影响该国樱花开放日期早晚的主要因素，除了地势外还有()①降水②太阳辐射③洋流④土壤A.②③B.③④C.①④D.②④【答案】 A【解析】由图可知，该国的樱花开放日期整体上自南向北推迟，由于越向北获得的太阳辐射能越少;另外，该岛东部沿海地区易受沿岸暖流的影响，樱花开放日期也比同纬度其他地区偏早。

英语模拟测试卷班级 ______________姓名____________得分____________A .fell asleep…watch B. was falling asleep…watchedC. fell asleep……was watchingD. had fallen asleep…watched2. They _________ in Guangzhou since 2000.A. livedB. had livedC. have livedD. were living3. He ________ to play ________ before he was 11 years old.A. had learned, pianoB. had learned, the pianoC. has learned, the pianoD. learns, piano4. —Kate is in hospital.—I know. I ________ and see her at once.A. will goB. am going to goC. am goingD. will be going5. It was very hot yesterday, but it is_________ today.A. even hotterB. more hotterC. much more hotD. much hot6. The house is _______ small for a family of six.A. much tooB. too muchC. very muchD. so7. An accident ___________on this road last week.A. has been happenedB. was happenedC. is happenedD. happened.8. A lot of things ___________by people to save the little girl now.A. are doingB. are being doneC. has been doneD. will be done9. The earth is our home. It ___________well.A. must be protectedB. should protectC. need protectD. should protected10. Twenty—year—olds should not be allowed ________ in China.A. drivingB. to driveC. droveD. to be driven11. Math is more popular than ____________.A. any other subjectB. all the subjectsC. any subjectD. other subjects12. Tom is too short ________ the leaves on the tree.A. to reachingB. to reachC. reachingD. not to reach13. There is a bookshop on_______ side of the street.A. othersB. otherC. anotherD. the other14. —Who sang the best in your class last term?— Jim ____________.A. didB. wasC. doesD. will be15. — ______do you live from your school?— Ten minutes’ walk.A. How soonB. How longC. How oftenD. How far16. — Whose trousers are these? Are they ______________?—No, they are _____________.A. yours, Jim’sB. Jim’s, myC. yours, my fatherD. Jim’s, me17. There is only __________milk left. We need to buy some more.A. littleB. a littleC. fewD. a few18. He loves reading, so he usually_______ a lot of money for books.A. paysB. costsC. takesD. spends19. I am looking forward to this summer. The_____ FIFA World Cup takes place in Brazil _____June 13to July 14.A. twentieth; inB. twentieth; fromC. twenty; inD. twenty; from20. — Sandy, _______ apple on the table is for you. Have it before you go out.—Thanks, Mum. _____ apple a day keeps the doctor away.A. the; AnB. an; AnC. an; TheD. the; The21. —May I have ________ fruit before supper?—Sorry. There isn’t _______ fruit at home now.A. some; someB. any; anyC. some; anyD. any; some22. I_______ watch Happy Goat and Big Big Wolf because I think it’s so boring.A. oftenB. alwaysC. usuallyD. seldom23. — I sometimes don’t have enough time ______ with my parents.—You will if you spend more time ______ with them at home.A. to chat; to stayB. to chat; stayingC. chatting; to stayD. chatting; staying24. — ________ do you visit your grandparents?— Three or four times a year. Usually at Mid-Autumn festival and Spring Festival.A. How longB. How oftenC. How muchD. How many25. —The price of an i-phone 4s will be more than 5000 yuan.— Yes. Good things always ________ much.A. payB. spendC. takeD. cost26. — Could you join us this afternoon?— Sorry, I ______. I ________ take care of my little sister because my mother is out.A. can’t; mayB. couldn’t; have toC. can’t; have toD. couldn’t; may27. ― ______ big river it is!— Yes. I am afraid I can’t swim ______ it.A. What; throughB. How; pastC. What a; acrossD. How a; over28. — _________ Mr. Zhang ________ Beijing last week?— No, but he ________ Beijing with his son next time.A. Did; visit; visitsB. Did; visit; will visitC. Does; visit; visitsD. Will; visit; will visit29. —Which of the following words has the same sound as the “ed” in the word “danced”?—Let me see. That’s _______.A. neededB. listenedC. chattedD. passed30. — Xiao Fang, we decided ________ a picnic this weekend. Will you join us?— I’m afraid not. I have a lot of homework _______.A. to have; to doB. to have; doingC. having; to doD. having; doing二、完形填空(请将正确答案的选项填写在下列方框中，每题1分，共10分)31Grade 7. Li Jie was one of my classmates. He and I were also neighbors. He always listened to his mother 32 I didn’t like listening to my mother. I didn’t think it was necessary for 33 to teach me anything. Li Jie knew all about that but he said 34 to me.One weekend, he invited me to watch a film. I liked films very much so I went to the 35 with him happily. The film was about the love between a 36 and her son. After watching it, I began to know how great the love of the mother was. I felt 37 that I didn’t listen to my mother before. I decided to think more about my mother than about 38 . After I told that to him, Li Jie smiled and said, “It’s really necessary for you to watch such a film. That was a good choice (选择) for both you and me.”Suddenly, I knew 39 he invited me to watch the film. Just then, I knew a true friend is always 40 .31. A. met B. did C. happened D. told32. A. and B. but C. so D. or33. A. her B. you C. him D. them34. A. something B. anything C. everything D. nothing35. A. park B. cinema C. museum D. zoo36. A. mother B. father C. sister D. brother37. A. happy B. excited C. sorry D. interested38. A. myself B. herself C. himself D. yourself39. A. how B. where C. what D. why40. A. polite B. hard-working C. good D. helpful三、阅读理解阅读下列短文，从每小题后所给出的A、B、C、D 四个选项中，选出最佳答案，并将正确答案APicture ShowThere are 12,000 pictures on show here. You can see the whole Chinese history!Place: City MuseumPrice: ￥30Time: 9:00 a.m.-5:00 p.m. Monday-FridayFilms at the MuseumThere are two European(欧洲的) films on Saturday afternoon at the Museum Theatre. See Broken Window at 2:30. The Workers is at 4:45. For more information, call 84987898.International PicnicAre you tired of eating the same food every day? Come to Central Park on Saturday and enjoy food from all over the world. Delicious and not expensive. Noon to 5:00 p.m.Do You Want to Hear “The Zoo”?“The Zoo”, a popular rock group from Australia, will give their first US concert(音乐会) this Saturday night, at 8 at Rose Hall, City College.The Music Shop’s SaleSale on every record and tape in the shop, Pop, Rock, Jazz, Disco, Folk. Sale starts on Tuesday and ends on Thursday.41. According to the ads(广告), what can you do on Saturday afternoon if you have time?A. I can enjoy the delicious food in Central Park.B. I can see two films and buy some tapes.C. I can go to the City College to watch animals.D. I can see a picture show and listen to music.42. Where can you enjoy a concert after reading the ads above?A. In the Museum Theatre.B. In the City College.C. In the City Museum.D. In the Music Shop.43. What is “The Zoo” in the ads?A. It’s a zoo with many animals in it.B. It’s the first US concert.C. It gives a concert on Sunday night.D. It’s an Australian music group.44. If Lucy would like to buy some cheap records, she cannot go to the Music Shop on _________.A. TuesdayB. WednesdayC. ThursdayD. Saturday45. Which of the followings is True according to the ads?A. People can see the whole European history in the City Museum.B. People can call 84987898 to find more information about food and music.C. People can eat different kinds of food in Central Park.D. People can go to the zoo this Saturday night.BRaisins(葡萄干) in ice cream, in chocolate, and in cookies…Your favorite snacks cannot be without raisins!But do you know how people get raisins from full and juicy grapes? Dry(晒干) them in the sun? Well, that may be one way. But people from Xinjiang have another way.People there build many “blockhouses(碉堡)” out of earth (地面) near a grape garden. It is in these blockhouses that the best raisins are made.People build many “blockhouses” on the hillside. The blockhouses are usually three metres tall and are as big as the size of a classroom.They are quite different from the houses we live in. They have lots of holes in the wall. Inside there are many wooden shelves.After picking the grapes, people put them on the shelves. Because of the hot weather, hot dry wind gets through the holes in the wall and dries the grapes up. 30 to 45 days later, the fruit will turn into soft,sweet raisins!In around the year 535, people in Xinjiang started to send raisins as presents to the emperor(皇帝). This means that 1,500 years ago people began to know how to make raisins!46. This passage is mainly about _____________.A. how to grow grapesB. how to make raisinsC. how to build blockhousesD. how to pick grapes47. Where do people build “blockhouses” in Xinjiang?A. In the classroom.B. In the grape garden.C. On the hillside.D. On wooden shelves.48. What does the underlined word hole mean in Chinese according to the passage?A. 树桩B. 枝条C. 架子D. 洞孔49. Why are the “blockhouses” different from the houses we live in?A. Because they have lots of holes in the wall.B. Because they aren’t as big as the houses we live in.C. Because there aren’t any windows in them.D. Because there’re lots of grapes growing in them.50. Which of the followings is Not true?A. People can find raisins in some ice cream, chocolate and cookies.B. People only dry the full and juicy grapes in the sun to get the raisins.C. The grapes need 30-45 days to turn into raisins in the blockhouses.D. People in Xinjiang began to know how to make raisins 1,500 years ago.CIn Canada you can find dogs, cats, horses etc, in almost every family. These are their pets. People love these pets and pets are their good friends. Before they keep them at their houses, they take them to animal hospitals to give them needles(针) so that they won’t carry disease(疾病). They have special animal food stores, though they can get animal food in almost every store. Some people spend about two hundred Canadian dollars a month on animal food.When you visit people’s homes, they would be very glad to show you their pets.You will also find almost every family has a bird feeder (喂食器) in their garden. All kinds of birds are welcomed to come and have a good meal. They are free to come and go and nobody is allowed (允许) to kill any animals in Canada. They have a law against killing wild(野生的) animals. If you kill an animal, you would be punished(处罚). If an animal happened to get run over by a car, people would be very sad about it.People in Canada have many reasons to like animals. One of them is: When children grow up, they leave their parents and start their own work and life. Then their parents will feel lonely, but pets can help them. They can be good friends and never leave them alone.51. This passage shows that Canadians_________.A. hate animalsB. often kill animalsC. love animalsD. don’t keep their pets inside their houses52. Children leave their parents when they grow up because________.A. they start their own work and lifeB. their parents’ houses are too smallC. they can only find jobs far from their parentsD. they don’t like to live together with their parents any more53. They give their pets needles before keeping them at their houses because _________.A. the pets are sickB. the pets are wildC. the pets are hungryD. they want to stop them from carrying disease54. Why do Canadians like to keep pets at home?A. It is free.B. It is very interesting.C. It can make old parents feel happy.D. It can protect people.55. Which is right according to the passage?A. People buy animal food for their pets only at special animal food stores.B. Any bird can come to the bird feeders to eat.C. Almost every family has a bird cage at his house.D. Pets eat more than people.D(阅读下列文章，根据意思将后面表格内句子补充完整，每空一词。

八年级阶段性测试物理试题参考答案一、二、选择题答案 三、非选择题：16.（4分）米 50.0 17.（4分）振动 音调18.（4分）次声波（或次声） 固体 19.（4分）虚 3评分标准：每空2分。

按答案给分，16题第一个空填符号不得分，第二个空“写单位”或填“50”不得分；19题第二个空写单位不得分。

20.（8分，每问3分）已知：t 甲=6:00，t 乙=8:30,s 甲=400km ，s 2=s 乙=150km.v 2=100km/h 求：（1）s 1 （2） v 1 （3）t 2解：（1）s 1=s 甲-s 乙=400km-150km=250km ………………………2分（2）h km h kmt s v /1005.2250111===………………………3分（3）t 1=t 乙-t 甲=8:30-6:00=2.5h由tsv =得， h h km km v s t 5.1/100150222===………………………3分 答：（1）轿车从甲标志牌行驶到乙标志牌的距离为250km;（2）轿车从入口处行驶到乙标志牌的平均速度为100km/h ;（3）在遵守交通法规的前提下，从乙地到青岛最快所用的时间为1.5h 。

评分标准：根据以上标准得分。

不写公式不得分，只写公式不与题目中的数值对应不得分；不带单位或单位错误减1分，不带角标减1分，计算错误扣1分，不写答或代表答的语言减1分。

21.（8分，每空1分）（1）tsv（2）较缓 （3）①0.25 ②1.0 （4）不是 小车下滑过程中速度越来越快 （5）不同 相同 22.（8分，每空2分）（1）声音是由物体振动产生的 转换法（2）真空不能传声（或声音不能在真空中传播）（3）音调23.（10分，每空2分）（1）平面镜 （2）反射光线、入射光线和法线 （3）等于（4）光路是可逆的 （5）法线偏向入射光线一侧（或法线与镜面不垂直）评分标准：根据以上标准得分。

21题第（3）问带单位不得分；23第（2）问反射光线和入射光线写反了不得分；其他答案合理均得分。

山东省山东师范大学附属中学2024-2025学年高一上学期11月期中阶段性测试数学试题一、单选题1．已知集合{}3202A =--，，，，{|12}B x x =-<，则A B = （）A ．{}02，B ．{}20-，C ．{}22，-D ．{}202-，，2．若命题“x ∃∈R ，使得20ax +=”是假命题，则实数a 的范围为（）A ．{}0a a >B ．{}2a a >C ．{}0D ．{}2,0a a a >=或3．已知函数()f x 的图象如图所示，则()1f x +的大致图象是（）A ．B ．C ．D ．4．已知幂函数()2()1mf x m m x =+-的图像与坐标轴没有公共点，则(2)f =（）A ．12B C ．14D ．5．已知函数()2f x +的定义域为()3,4-，则函数()g x =的定义域为（）A ．()4,3-B ．()2,5-C ．1,33⎛⎫ ⎪⎝⎭D ．1,53⎛⎫ ⎪⎝⎭6．函数()()()252,2213,2a x x f x x a x a x ⎧---≥⎪=⎨+--<⎪⎩，若对任意()1212,R x x x x ∈≠，都有()()12120f x f x x x -<-成立，则实数a 的取值范围为（）A ．[]4,1--B ．[]4,2--C ．(]5,1--D ．[]5,4--7．已知正数,x y 满足1211x y+=+，则2x y +的最小值是（）A ．8B ．7C ．6D ．58．已知()f x 是定义在R 上的奇函数，且在(,0)-∞上单调递增，若()20f -=，则()()()()012x f x f x +--<的解集是（）A ．()()2,00,2-⋃B ．()()2,01,2-UC ．()()2,10,2--⋃D ．()()2,11,2--⋃二、多选题9．设全集为U ，集合A ，B 满足()U A B =∅ ð，则（）A ．A B A= B ．A B U ⋃=C ．()U A B U È=ðD ．()U B A U=U ð10．若0a b >>，则下列不等式中不成立的是（）A ．11a b a b+>+B ．11a b a b->-C ．11b b a a +>+D ．22a b aa b b+>+11．取一条长度为1的直线段，将它三等分，去掉中间一段，留剩下两段，再将剩下的两段再分别三等分，各去掉中间一段，剩下更短的四段，……，将这样的操作一直继续下去，直至无穷，由于在不断分割舍弃过程中，所形成的线段数目越来越多，长度越来越小，在极限的情况下，得到一个离散的点集，称为康托尔三分集.某数学小组类比拓扑学中的康托尔三等分集，定义了区间[]0,1上的函数()f x ，规定其具有以下性质：①任意1201x x ≤<≤，()()12f x f x ≤；②()24x f x f ⎛⎫= ⎪⎝⎭；③()()11f x f x +-=，则关于该函数下列说法正确的是（）A ．()f x 在[]0,1上单调递增B ．()f x 的图象关于点11,22⎛⎫⎪⎝⎭对称C ．当116x =时，()14f x =D ．当115,1616x ⎡⎤∈⎢⎥⎣⎦时，()()12f f x =三、填空题12．已知函数()f x 为R 上奇函数，当0x >时，()223f x x x =+-，则0x <时，()f x =.13．已知两个正实数x ，y 满足40x y xy +-=m 恒成立，则实数m 的取值范围是.14．高斯是德国著名数学家，享有“数学王子”的美誉，以“高斯”命名的数学概念、定理、公式有很多，比如我们教材中所学习的“高斯函数[]y x =”其中[]x 表示不超过x 的最大整数，例如[]22=，[]3,73=，[]2.13-=-.现有函数()[]22f x x x t =-+，如果该函数既有最大值也有最小值，则实数t 的取值范围是.四、解答题15．计算化简下列各式(1)化简：123312783125-⎛⎫⨯++⎪⎝⎭(2)若112252x x-+=（其中1x >），分别求出1122x x --与1x x -+的值：(3)16．已知函数()()212f x mx m x m =--+-（m ∈R ）.(1)若不等式()0f x ≥恒成立，求m 的取值范围；(2)解不等式()1f x m ≥-.17．如图，在周长为8的矩形ABCD 中（其中AB AD >），现将ABC V 沿AC 折叠到AB C ' ，设AB '与CD 交于点E ，设AB x =.(1)求证：B EC ' 的周长为定值；(2)试用x 表示B E '的长，并求x 的取值范围；(3)当x 为何值时，B EC ' 的面积S 取得最大值，并求出该最大值.18．已知函数()21x a bf x x ++=-是定义域为()1,a -的奇函数.(1)求出()f x 的解析式；(2)判断()f x 在区间()1,1-上的单调性，并用函数单调性定义证明该结论；(3)解不等式1102t f f t ⎛⎫⎛⎫+-< ⎪ ⎪⎝⎭⎝⎭.19．设,a b R ∈，若函数()f x 定义域内的任意一个x 都满足()()22f x f a x b +-=，则函数()f x 的图象关于点(),a b 对称；反之，若函数()f x 的图象关于点(),a b 对称，则函数()f x 定义域内的任意一个x 都满足()()22f x f a x b +-=.已知函数()531x g x x +=+.（Ⅰ）证明：函数()g x 的图象关于点()1,5-对称；（Ⅱ）已知函数()h x 的图象关于点()1,2对称，当[]0,1x ∈时，()21x m x m h x =-++.若对任意的[]10,2x ∈，总存在22,13x ⎡⎤∈-⎢⎥⎣⎦，使得()()12h x g x =成立，求实数m 的取值范围.。

上海市控江中学2018-2019学年高二英语上学期10月阶段性测试试题（含解析）Part OneI.Cloze (30%)Directions: For each blank in the following passage there are four words or phrases marked A, B,C and D. Fill in each blank with the word or phrase that best fits the context.完形填空（共15小题；每小题2分，满分30分）阅读下面短文，从短文后所给各题的A、B、C、D四个选项中选出能填入相应空白处的最佳选项, 并将答案填写在答题卡标号为1--15的相应位置上。

People think children should play sports. Sports are fun, and children keep healthy while playing with others. However, playing sports can have___1___effects on children. It may produce feelings of poor self-respect or aggressive behavior in some children. According to research on kids and sports,40,000,000 kids play sports in the US. Of these,18,000,000 say they have been___2___at or called names while playing sports. This leaves many children with a bad___3___of sports. They think sports are just too aggressive.Many researchers believe adults, especially parents and coaches, are themain___4___of too much aggression in children’s sports. They believechildren___5___aggressive adult behavior. This behavior is then further strengthened through both positive and negative feedback. Parents and coaches are powerful teachers because children usually look up to them. Often these adults behave aggressively themselves, sending children the message that___6___is everything. Many parents go to children’s sporting events and shout___7___at other players or cheer when their child behaves___8___As well, children are even taught that hurting other players is___9___or are pushed to continue playing even when they are injured.___10___,the media makes violence seem exciting. Children watch adult sports games and see violent behavior replayed over and over on television.As a society, we really need to___11___this problem and do something about it.Parents and coaches___12___should act as better examples for children. They also need to teach children better___13___They should not just cheer when children win or act aggressively. They should teach children to___14___themselves whether they win or not. Besides, children should not be allowed to continue to play when they are injured. If adults allow children to play when injured, this gives the message that___15___is not as important as winning.1. A. restrictive B. negative C. active D. instructive2. A. knocked B. glanced C. smiled D. shouted3. A. impression B. concept C. taste D. expectation4. A. resource B. cause C. course D. consequence5. A. question B. understand C. copy D. neglect6. A. winning B. practising C. fun D. sport7. A. praises B. orders C. remarks D. insults8. A. proudly B. ambitiously C. aggressively D. bravely9. A. acceptable B. impolite C. possible D. accessible10. A. By contrast B. In addition C. As a result D. After all11. A. look up to B. face up to C. make up for D. come up with12. A. in particular B. in all C. in return D. in advance13. A. techniques B. means C. values D. directions14. A. respect B. relax C. forgive D. enjoy15. A. body B. fame C. health D. spirit 【答案】1. B 2. D 3. A 4. B 5. C 6. A 7. D 8. C 9. A 10.B 11. B 12. A 13.C 14.D 15. C【解析】略Part TwoII. Grammar(11%)Section A Directions: After reading the passage below , fill in each blank with the proper forms of the given words to make the passage coherent and grammatically correct.Sports shoes that work out ___16___ their owner has enough exercise to warrant time in front of the television have been devised in the UK. The shoes —named Square Eyes — contain an electronic pressure sensor and a tiny computer chip to record how many steps the wearer has taken in a day. A wireless transmitter passes the information to a receiver ___17___ (connect) to a television, and this decides how much ev ening viewing time the wearer deserves, based on the day’s efforts.The design was inspired by a desire to fight ___18___ the rapidly ballooning waistlines among British teenagers, says Gillian Swan, ___19___ developed Square Eyes as a final year design pr oject at Brunel University to London, UK. “We looked at current issues and childhood overweight really stood out,” she says. “And I wanted to tackle that with my design.” ___20___ a child has used up their daily allowance gained through exercise, the television automatically ___21___ (switch) off. And further time in front of the TV ___22___ only be earned through more steps.Swan calculated how exercise should translate to television time using the recommended daily amounts of ___23___. Health experts suggest that a child take 12,000 steps each day and watch no more than two hours of television. So, every 100 steps recorded by the Square Eyes shoes ___24___ (equal) precisely one minute of TV time.Existing pedometers（计步器）normally clip onto a belt or slip into a pocket and keep count of steps by measuring sudden movement. Swan says these can be easilytricked ___25___ recording steps through shaking. But her shoe has been built to be ___26___ (hard) for lazy teenagers to cheat. “It is possible, but it would be a lot of effort,” she says. “That was one of my main design considerations.”【答案】16. whether17. connected18. against19. who 20. Once21. switches22. can 23. both24. equals 25. into26. harder【解析】【分析】这是一篇说明文。

人教版2022-2023学年第一学期九年级数学第三次阶段性综合测试题（附答案）一、单项选择题（共18分）1．中秋节是中国的传统节日，有“团圆”、“丰收”的寓意．月饼是首选传统食品，不仅美味，而且设计多样．下列月饼图案中，为中心对称图形的是（）A．B．C．D．2．方程x2+6x﹣5＝0的左边配成完全平方后所得方程为（）A．（x+3）2＝14B．（x﹣3）2＝14C．（x+3）2＝4D．（x﹣3）2＝4 3．若气象部门预报明天下雪的概率是85%，下列说法正确的是（）A．明天下雪的可能性比较大B．明天一定不会下雪C．明天一定会下雪D．明天下雪的可能性比较小4．如图，AB为⊙O的直径，C，D为⊙O上的两点，若∠ABD＝54°，则∠C的度数为（）A．34°B．36°C．46°D．54°5．二次函数y＝ax2+bx+c的部分图象如图所示，由图象可知方程ax2+bx+c＝0的根是（）A．x1＝﹣1，x2＝5B．x1＝﹣2，x2＝4C．x1＝﹣1，x2＝2D．x1＝﹣5，x2＝56．截止到2021年3月15日，返乡入乡创业就业规模扩大，全国当年各类返乡入乡创业创新人员由2018年的320万人增加到2020年的1010万人．设我国从2018年到2020年返乡入乡创业创新人员的平均增长率为x，则可列方程为（）A．320（1+2x）＝1010B．320×2（1+x）＝1010C．320（1+x）2＝1010D．320+320（1+x）+320（1+x）2＝1010二、填空题（共24分）7．一元二次方程x2＝﹣x的根是．8．在平面直角坐标系中，点M（﹣2，4）关于原点对称的点的坐标是．9．抛物线y＝（x+2）2﹣2的顶点是．10．已知抛物线y＝﹣（x+3）2﹣5，当x时，y随x的增大而增大．11．如图，矩形ABCD中，AB＝3，AC＝5．以点A为中心，将矩形ABCD旋转得到矩形AB′C′D′，使得点B′落在边AD上，此时DB′的长为．12．如图，已知四边形ABCD内接于⊙O，∠ABC＝68°，则∠ADC的度数是．13．如图，⊙O的内接正六边形ABCDEF边长为cm，则该正六边形的面积为cm2．14．如图，半径为10的扇形AOB中，∠AOB＝90°，C为弧AB上一点，CD⊥OA，CE⊥OB，垂足分别为D，E．若∠CDE＝40°，则图中阴影部分的面积为（结果保留π）．三、解答题（共78分）15．解一元二次方程：x2﹣x﹣1＝0．16．已知关于x的方程x2+4x+3﹣a＝0有两个不相等的实数根，求a的取值范围．17．已知抛物线y＝x2﹣kx﹣3k与x轴的一个交点为（﹣2，0）（1）求k的值；（2）求抛物线与x轴的另一个交点坐标．18．红红和丁丁玩纸牌游戏，如图是同一副扑克中的4张牌的正面，将它们正面洗匀后放在桌面上．（1）红红从4张牌中抽取一张，这张牌的数字为大于7的概率是．（2）红红先从中抽取一张，丁丁从剩余的3张牌中也抽出一张，比较两人抽取的牌面上的数字，数字大者获胜，请用树状图或列表法求出红红获胜的概率．19．如图，在7×8的正方形网格中，每个小正方形的边长均为1，点A，B，C均在小正方形的顶点上．（1）将线段AB绕点C逆时针旋转90°得到线段DE（点A，B的对应点分别为点D，E），请画出线段DE．（2）以AD为对角线作▱AEDF，画出▱AEDF，并直接写出▱AEDF的面积．20．如图，在等腰△ABC中，AB＝AC，以AC为直径作⊙O交BC于点D，过点D作DE ⊥AB，垂足为E．（1）求证：DE是⊙O的切线．（2）若DE＝，∠C＝30°，求的长．21．如图，在正方形ABCD中，AD＝2，将边BC绕点B逆时针旋转30°得到线段BP，连接AP并延长交CD于点E，连接PC．（1）判断△ABP的形状，并说明理由．（2）求CE的长．22．某商场购进一批单价为4元的日用品．若按每件5元的价格销售，每月能卖出3万件；若按每件6元的价格销售，每月能卖出2万件，假定每月销售件数y（件）与价格x（元/件）之间满足一次函数关系．（1）试求y与x之间的函数关系式；（2）当销售价格定为多少时，才能使每月的利润最大？每月的最大利润是多少？23．小明进行铅球训练，他尝试利用数学模型来研究铅球的运动情况．他以水平方向为x 轴方向，1m为单位长度，建立了如图所示的平面直角坐标系，铅球从y轴上的A点出手，运动路径可看作抛物线，在B点处达到最高位置，落在x轴上的点C处．小明某次试投时的数据如图所示．（1）在图中画出铅球运动路径的示意图；（2）根据图中信息，求出铅球路径所在抛物线的表达式；（3）若铅球投掷距离（铅球落地点C与出手点A的水平距离OC的长度）不小于10m，成绩为优秀．请通过计算，判断小明此次试投的成绩是否能达到优秀．24．如图，△ABC中，AB＝AC，∠BAC＝120°，将△ABC绕点A逆时针旋转一个角度α（0＜α＜120°）得到△ADE，DE交BC于点F，连接AF，在旋转过程中，有下列对某些四边形状的判断．甲：四边形AFCE可能是矩形；乙：四边形ADCE可能是菱形；丙：四边形ABFE可能是菱形．解答下列问题：（1）上述判断正确的是．（2）请选择一个你认为正确的判断，画出相应的图形，求出此时旋转角a的度数，并给予证明．25．如图，△ABC中，AB＝AC＝8cm，∠BAC＝120°．动点P从点A出发，在AB边上以每秒1cm的速度向终点B匀速运动（点P不与点A，B重合），同时动点Q从点B出发，沿BC边以每秒cm的速度向终点C匀速运动，连接PQ．设运动时间为x（s），△BPQ 的面积为y（cm2）．（1）BP＝cm，点Q到AB的距离为cm．（用含x的代数式表示）（2）求y关于x的函数解析式，并写出自变量x的取值范围．（3）当y＝S△ABC时，求x的值．（4）在点P，Q的运动过程中，以PQ为直径作⊙O，⊙O能与AB或BC相切吗？若能，请直接写出x的值；若不能，请说明理由．26．如图，抛物线y＝x2+bx+c与x轴交于A，B两点（点A在点B左侧），与y轴交于点C （0，3）．（1）若抛物线的对称轴是直线x＝﹣2．①求抛物线的解析式．②点P在对称轴上，若△PBC的面积是6，求点P的坐标．（2）当b≤0，﹣2≤x≤0时，函数y的最大值满足3≤y max≤16，求b的取值范围．参考答案一、单项选择题（共18分）1．解：选项A、C、D不能找到这样的一个点，使图形绕某一点旋转180°后与原图重合，所以不是中心对称图形；选项C能找到这样的一个点，使图形绕某一点旋转180°后与原图重合，所以是中心对称图形；故选：B．2．解：移项得：x2+6x＝5，配方可得：x2+6x+9＝5+9，即（x+3）2＝14，故选：A．3．解：若气象部门预报明天下雪的概率是85%，说明明天下雪的可能性比较大，故选：A．4．解：连接AD，如图，∵AB为⊙O的直径，∴∠ADB＝90°，∴∠A＝90°﹣∠ABD＝90°﹣54°＝36°，∴∠C＝∠A＝36°．故选：B．5．解：由图象可知对称轴x＝2，与x轴的一个交点横坐标是5，它到直线x＝2的距离是3个单位长度，所以另外一个交点横坐标是﹣1．所以x1＝﹣1，x2＝5．故选：A．6．解：依题意得：320（1+x）2＝1010．故选：C．二、填空题（共24分）7．解：∵x2＝﹣x，∴x2+x＝0，则x（x+1）＝0，∴x＝0或x+1＝0，解得x1＝0，x2＝﹣1．故答案为：x1＝0，x2＝﹣1．8．解：点（﹣2，4）关于原点对称的点的坐标为（2，﹣4）．故答案为：（2，﹣4）．9．解：∵y＝（x+2）2﹣2是抛物线解析式的顶点式，∴根据顶点式的坐标特点可知，顶点坐标为（﹣2，﹣2）．故答案为：（﹣2，﹣2）．10．解：∵抛物线y＝﹣（x+3）2﹣5，∴抛物线开口向下，对称轴为直线x＝﹣3；∵x＜﹣3时，y随x的增大而增大，故答案为：＜﹣3．11．解：∵四边形ABCD是矩形，∴∠BAD＝∠B＝90°，AD＝BC，∵AB＝3，AC＝5，∴BC＝＝＝4，∴AD＝4，由旋转的性质可知，AB＝AB′＝3，∴DB′＝AD﹣AB′＝4﹣3＝1，故答案为：1．12．解：∵四边形ABCD内接于⊙O，∠ABC＝68°，∴∠ADC＝180°﹣∠ABC＝180°﹣68°＝112°，故答案为：112°．13．解：过点O作OH⊥AB于点H，连接OA，OB，∵⊙O的内接正六边形ABCDEF边长为cm，∴OA＝OB＝AB＝2cm，∴OH＝OA•cos30°＝2×＝3（cm），∴S正六边形ABCDEF＝6S△OAB＝6××＝18（cm）2．故答案为：18．14．解：如图，连接OC，∵∠AOB＝90°，CD⊥OA，CE⊥OB，∴四边形CDOE是矩形，∴OD＝CE，DE＝OC，CD∥OE，∵∠CDE＝40°，∴∠DEO＝∠CDE＝40°，在△DOE和△CEO中，，∴△DOE≌△CEO（SSS），∴∠COB＝∠DEO＝40°，∴图中阴影部分的面积＝扇形OBC的面积，∵S扇形OBC＝＝，故答案为：．三、解答题（共78分）15．解：∵a＝1，b＝﹣1，c＝﹣1，∴Δ＝（﹣1）2﹣4×1×（﹣1）＝5＞0，则x＝＝，∴x1＝，x2＝．16．解：∵方程x2+4x+3﹣a＝0有两个不相等的实数根，∴Δ＝42﹣4×1×（3﹣a）＝4+4a＞0，解得：a＞﹣1．17．解：（1）根据题意得，4+2k﹣3k＝0，所以k＝4；得抛物线的解析式为y＝x2﹣4x﹣12；（2）∵x2﹣4x﹣12＝0，解得x1＝﹣2，x2＝6，∴抛物线与x轴的另一个交点坐标（6，0）．18．解：（1）从4张牌中抽取一张，这张牌的数字为大于7的概率是＝，故答案为：；（2）根据题意画树状图如下：共有12种等可能的结果数，其中红红获胜的结果有6个，∴红红获胜的概率为＝．19．解：（1）如图，线段DE即为所求；（2）如图，平行四边形AEDF即为所求．四边形AEDF的面积＝2×4＝8．20．（1）证明：连接OD；∵OD＝OC，∴∠C＝∠ODC，∵AB＝AC，∴∠B＝∠C，∴∠B＝∠ODC，∴OD∥AB，∴∠ODE＝∠DEB；∵DE⊥AB，∴∠DEB＝90°，∴∠ODE＝90°，即DE⊥OD，∴DE是⊙O的切线．（2）解：连接AD，∵AC是直径，∴∠ADC＝90°，∵AB＝AC，∠C＝30°，∴∠B＝∠C＝30°，BD＝CD，∴∠OAD＝60°，∵OA＝OD，∴△AOD是等边三角形，∴∠AOD＝60°，∵DE＝，∠B＝30°，∠BED＝90°，∴CD＝BD＝2DE＝2，∴OD＝AD＝tan30°•CD＝×2＝2，∴的长为：＝．21．解：（1）△ABP是等边三角形．理由：∵四边形ABCD是正方形，∴∠ABC＝∠BAD＝∠D＝90°，∵把边BC绕点B逆时针旋转30°得到线段BP，∴PB＝BC＝AB，∠PBC＝30°，∴∠ABP＝60°，∴△ABP是等边三角形；（2）∵△ABP是等边三角形，∴∠BAP＝60°，∴∠DAE＝30°，∵AD＝2，∴DE＝AD•tan30°＝2，∴CE＝2﹣2．22．解：（1）由题意，可设y＝kx+b（k≠0），把（5，30000），（6，20000）代入得：，解得：，所以y与x之间的关系式为：y＝﹣10000x+80000；（2）设利润为W元，则W＝（x﹣4）（﹣10000x+80000）＝﹣10000（x﹣4）（x﹣8）＝﹣10000（x2﹣12x+32）＝﹣10000[（x﹣6）2﹣4]＝﹣10000（x﹣6）2+40000所以当x＝6时，W取得最大值，最大值为40000元．答：当销售价格定为6元时，每月的利润最大，每月的最大利润为40000元．23．解：（1）如图所示．（2）解：依题意，抛物线的顶点B的坐标为（4，3），点A的坐标为（0，2）．设该抛物线的表达式为y＝a（x﹣4）2+3，由抛物线过点A，有16a+3＝2．解得，∴该抛物线的表达式为；（3）解：令y＝0，得．解得，（C在x轴正半轴，故舍去）．∴点C的坐标为（，0）．∴．由，可得．∴小明此次试投的成绩达到优秀．24．解：（1）甲不正确：理由是当AF⊥CF时，DE与BC重合，四边形不存在．乙，丙正确（理由见2中证明）．故答案为：乙，丙；（2）①四边形ADCE可能是菱形．当α＝60°时，四边形ADCE是菱形．理由：如图1中，∵∠BAC＝∠DAE＝120°，∠BAD＝60°，∴∠CAD＝∠CAE＝60°，∵AD＝AC＝AE，∴△ADC，△AEC都是等边三角形，∴AC＝EC＝CD，∴AE＝AD＝CD＝EC，∴四边形ADCE是菱形．②四边形ABFE可能是菱形．当α＝30°时，四边形ABFE是菱形．理由：如图2中，∵AB＝AC，AD＝AE，∠BAC＝∠DAE＝120°，∴∠B＝∠ACB＝∠ADE＝∠AED＝30°∵∠BAD＝∠ADE＝30°，∴AB∥DE，∵∠BAD＝∠CAE＝∠ACB＝30°，∴AE∥CB，∴四边形ABFE是平行四边形，∵AB＝AE，∴四边形ABFE是菱形．25．解：（1）由题意可得AP＝xm，BQ＝xcm，∵AB＝8cm，∴BP＝（8﹣x）cm，过Q点作QH⊥AB交于H，∵AB＝AC，∠BAC＝120°，∴∠B＝30°，在Rt△BQH中，HQ＝BQ＝xcm，故答案为：8﹣x，x；（2）过点A作AG⊥BC交于G，∵BA＝8cm，∠B＝30°，∴AG＝4cm，BG＝4cm，∴BC＝8cm，当Q点从B点运动到C点时，x＝8，当P点从A点运动到B点时，x＝8，∴P、Q点同时到达终点，∴0＜x＜8，由（1）知，BP＝（8﹣x）cm，HQ＝xcm，∴y＝×BP×HQ＝（8﹣x）×x＝﹣x2+2x，∴y＝﹣x2+2x（0≤x≤8）；（3）由（2）知，AG＝4cm，BC＝8cm，∴S△ABC＝×8×4＝16cm2，∵y＝S△ABC，∴﹣x2+2x＝×16，解得x＝4+2或x＝4﹣2；（4）⊙O能与AB或BC相切，理由如下：如图3，当⊙O与AB相切时，P为切点，此时PQ⊥AB，∴8﹣x＝×x，∴x＝；如图4，当⊙O与BC相切时，Q为切点，此时PQ⊥BC，∴x＝（8﹣x），解得x＝；综上所述：x＝或．26．解：（1）①抛物线y＝x2+bx+c的对称轴为直线x＝−＝−2，∴b＝4，又∵抛物线与y轴的交点为（0，3），∴c＝3，∴抛物线的解析式为y＝x2+4x+3；②∵抛物线的解析式为y＝x2+4x+3，令y＝0，则x2+4x+3＝0，解得x＝﹣1或﹣3，∴A（﹣3，0），B（﹣1，0），当点P在直线BC的上方时，∵点P在抛物线的对称轴上，∴设点P的坐标为（﹣2，m），则S△PBC＝S梯形PDOC﹣S△PDB﹣S△COB＝（m+3）×2﹣×1×m﹣×1×3＝6，解得m＝9，∴点P的坐标为（﹣2，9）；当点P在直线m的下方时，设直线BC的解析式为y＝mx+n，∵B（﹣1，0），C（0，3）．∴，解得，∴直线BC的解析式为y＝3x+3，∴直线BC与抛物线的对称轴的交点为（﹣2，﹣3），∴S△PBC＝S△PEC﹣S△PEB＝×2×（﹣3﹣m）﹣×1×（﹣3﹣m）＝6，解得m＝﹣15，∴点P的坐标为（﹣2，﹣15）．综上所述，满足条件的点P的坐标为（﹣2，9）或（﹣2，﹣15）；（2）∵b≤0时，∴−≥0，∴x＝−≥0，∵抛物线开口向上，在对称轴左边，y随x的增大而减小，∴当﹣2≤x≤0时，取x＝﹣2，y有最大值，即y＝4﹣2b+3＝﹣2b+7，∵C（0，3），∴当x＝0时，取x＝0，y有最小值3，∴3≤﹣2b+7≤16，解得：−≤b≤2，又∵b≤0，Δ＝b2﹣12＞0，∴＜﹣2．。

2023—2024学年高三年级阶段性测试(定位)英语考生注意：1.答题前，考生务必将自己的姓名、考生号填写在试卷和答题卡上，并将考生号条形码粘贴在答题卡上的指定位置。

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录音内容结束后，你将有2分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例：How much is the shirt?A.₤19.15B.₤9.18.C.₤9.15答案是C。

1.When will the class meeting begin?A.At 9:10.B.At 9:20.C.At 9:30.2.What is the woman doing?A.Selling coffee.B.Visiting a cafe.C.Asking for directions.3.How does the man feel?A.Impatient.B.Helpless.C.Excited.4.What are the speakers probably talking about?A.A bookB.A film.C.A writer.5.What is the probable relationship between the speakers?A.Boss and secretary.B.Saleswoman and customer.C.Doctor and patient.第二节(共15小题；每小题1.5分，满分22.5分)听下面5段对话或独白。