道路勘测设计习题及答案

求临界速度

超高半径

试计算该圆曲线的几何要素及曲线主点桩的桩号？

133013.5

'=13.5

271.015()

m =141.372()m =13.5

2(sec 1) 4.188(⨯-=141.3720.658(m -=

133013.5

'=2(sec 1)E R α=-=2

tan 312.611(T

α

==160-40=12042

2tan R α

2

sec 1

E α-16

2(sec R α24R ()

2(q m α+()

R m 2)β-

66.667()

m

p

250 925027.778250()

R m =-=

4920 230

'+

60

⨯=

120

14.324()

=

7530

2

120 1.24729.938123.817(

'

++=

180

7530298.127(

π

'-⨯⨯

的平曲线形式、半径

8.361()

4920229.979'

+18049202205.585'-⨯4s L =5205.585=125.103242.9917.215(-=8.594()

3830237.472'+)180383028.594π'-⨯275242.991()

m ⨯172423000.222300'

+-