d 2i R di i To solve 2 0, two initial conditions are needed. dt L dt LC One possible choice is i (0) and di (0) / dt. Here i(0) I 0 , and di(0) / dt can be got by i(0), v(0) and ( a).
Take v as the variable dv iC ( a ) becomes dt d 2v R dv v 0 2 dt L dt LC
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Chap 08 Second-Order Circuits
The Source-Free Series RLC Circuit (cont.)
vR (0 ) vo (0 ) vC (0 ) 20 0 vR (0 ) vo (0 ) (b)
vR (0 ) vo (0 ) 3 2 4
(a )
Substituting (b) into (a ) vR (0 ) vo (0 ) 4V
Chap 08 Second-Order Circuits 14
1. The i is continuous (inductor current). 2. The v is continuous (capacitor voltage)
12 i (0 ) 2A, 42 i (0 ) i (0 ) 2A,
Chap 08 Second-Order Circuits
The inductor is treated as a short circuit.
Ch8 Second-Order Circuits
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