诺基亚手机测试题
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Nokia试题Senserio: UL Interference TroubleshootingIn wireless network,sometimes we find some uplink interference coming from either interference from BTS or external from uncertain source.(上行干扰 BTS 内部或者外面不确定源)1. pleace calculate Normal Value of PrxNoise. Prxnoise is the noise level in the BTS ,digitalreceiver when there is no load,(thermal noise+noise figure).Thermal noise can be calculated by following formula.Formula: Thermal noise: 10*log10(1000*kTB) where(热噪声) K:1.38E-23T:temperature in Kelvin B:3.84E6Assume T=300Thermal noise: 10*log10(1000*kTB)=10*log10(1000*1.38E-23*300*3.84E6) 2. How impact to the system if interference exists?3. What info element in DT tool can check UL interferecon level? What KPI counter you need tocheck first before on-site visit? 4. After collecting those KPI info,find there is one area having UL interference with 7-? Cellssuffering UL Interference What is your criteria to choose sites with highly potential interference source finging?5. Now you are ready to find the UL interference what kind of tool andinfo need to preparebefore going for troubleshooting6. When on-site visit ,what BTS unit you need to measure?(answer unit) measurement at BTSunit we will need confirm the the interference in not from BTS orDue to budget limitation there is only 50 she can capansion What KPI or count you propose to evaluate whether this site transmission expanseion cadidateAfter Iub expansion,customer want to improve user experience in HSDPA by purchasing 15 code ,code multiplexing and 16QAM feature ,what parameters setting you need to change according to these features?Because of R99 and HSDPA in share carries ,what is possible negative impact you expactAfter you propose to customer with Dual carriers solution to setors the negative impact,HSDPA user is pushing to 2nd carrier these are two options diretedRRC for HSDPA layer and IFHO to 2nd carrier Please explain the advantage of DiretedRRC for HSDPA layer compared to IFHO to 2nd carrierIn order to verify the 14.4M HSDPA Throughput performance you may need to send DT team to verify ,What info can prove this site is having 14.4Mbps per site with 15code inDT log?If you find the DL application throughput is only 2Mbps what in good RF coverage and quality you may ask RAN engineer to use E2K, tool to help What is the purpose in the E2KWhen DT pass by a building entrance during the Drive test ,the call is drop due to UE camp on Indoor cell in idle mode in front of building entrance and call drop in door cell due to RF signaling fading quicklyNote: This indoor site has 3 sectors ,1st Cell serving B3-B1,2nd Cell serving 1F-3F and 3rd cell serving 4F-6F. All three sectors have samesetting :PtxPrimaryCPICH=33dbm,MaxBitRateDLPSNRT=384bps,MinAllowedBitRateDL=64 bps,InitiaBitRateDL=128kbpsa. Please find a solution for above prolemb. Unfortunately,customer complains that there is high drop call when UE close to windowon 3F,youfind there is other RF signaling from outdoor Please find a solution for this problemc. The other issue is that user working in 4F-6F suffering low DL Throughput even no DLthroughput during the office hour,especially from 10:00AM-13:00P, Below chart show this cell is suffering High code blocking Please propose a short term plan to solve this issue(Parameter Tuning)?and long term plan to solve the capacity issue.Show daily KPI of Code Block Hourly KPI of Code Block 两张图After commercial launch for 2 years ,user traffic keep growing lead to congestion in Iub in order to avoid to this service impact and improve user experience Now operator decide to expansion itansmiision capacity in iub with Hbbrid Back Haul Solution The Hybrid use 1*E1 for R99 RT and NRT service and the others using XDSL with 10M/0Mfor HSDPA service We expact user can get theroatical 14.4Mbps in DL if per site.Cluster TuningNow you are in charage of one cluster tuning Before go for analysis you need to send DT team for drive testing according to the route agreed by customer1. Now you are helping to setup DT tool with 3UE’s Scanner and GPS Please explainfunction or purpose of UE Scanner and GPS during the drive test2. After setup tool you need to setup script for each call pattern you may need toconfig AMR short call AMR long call Packet call FTP Download 128M and scanner a. what is the major testing purpose for AMR short call? What singaling messageindicate call setup successful?b. What is the major testing purpose for AMR Long call ?what signaling messageindicate call successful complete?Please also indicate the dutaill “Cause” of this messagec. For Packet call what setting need to config for Qos Negobalion What NASmessage will send this setting to SGSN and request IP Address d. ForScanner setting ,list at least two setting need to be configured3.After DT log collection, you have to process the statistic result ,listat least two tools for port processding.4.Now you have the result for scanner what potential problem from scanner result please list at least 4methodologies to improve this problem andprioritize these method from High to LowScanner Average RSCP of Best Server Average ECNO of Best Server ECNO above-10 sample percentile RSCP above -85 sample percentile Drive result -62.48 -13.5 75% 95% 5.After coverage analysis you may go futther call eventanalysis,you find there Is always a drop call near the corner when UE is moving from point 1 and make a right turn to point2 then straight forwardpoint3(street corner) it was found the serving cell ECNO is drop sharply dueto building shadowing before SHO attempt to next neighbor cell ,in order to prevent this call drop what could be possible solution to optimize parameterin neighbor level without impact other neighbor SHO behaviorPlease choose the most suitable according above requirementa. change addition window from 2.5db to 4db in cell 1wcel objectb. change drop window from 3db to 5db in well 1 wcell objectc. change adjaECNOffsetfrom 0db to 2db in cell 1->cell2 adjs objectAs we know no matter service call (AMR.NRT PS) or signaling message (Location update GPRS attach ) the first step is setup RRC connection betweenUE and RNC ,Below is the part of RRC connection setup message ,please help to complete it fill-out missing part1-4Please list some example for DT KPI and network statistic KPI for acceptance before network claim cominercial insearth At least 3 for each and include res KPI target EXSHO successful rate>95%1.WCDMA Chip rate is 3.84 Mcps, frequency band width is 5 MHz2.Processing gain of PS384(DL) is 10log(3.84E6/384K) db(note:Gp(db)=W/R3.Frame synchronization is achieved with the P-SCH channel,Slot synchronization is actue with the S-SCH channel4.during random access ,the P-FACH channel is sent by the nodeB to tell the UE,that the NodeB is acquired the preamble transmission of the random access5.regarding 16QAM modulation 4 data bits are modulation to one symbol 6 InE-DPCCH, 10 bit indicating whether the UE needs more resources or not7.In WCDMA R99,the retransmission is Acknowledgment lodgment in layeristerminated at RNC,In HSOPA, the retransmission is acknowledgment inlayer is terminated at BTS,therefore it can save Iub bandwidth.8.In HSDPA UE Category ,with 15 code and 16QAM modulation UE can get the theoretical 14.4,Mbps throughput1.There are down link primary scrambling codes A 32 B64 C128 D5122.Scrambling code is used to separate in uplink A.cells ers C.channel D,service3.CPICH is one kind of channel A.Physical B Logical C.TransportD.Synchronisa (同步) 4.With temperature rising,thermal noise desityA.gets higherB.get lowerC.keep constant D is selected to the type on NodeB 5.Which function following can not be used to improve the cell coverage A MHA B 6-sectors C Extended cellD.Add carrier 6.Which is UL channelamong following transport channel? A.BCH B PCH C FACH D RACH7.When UE send measurement report with event 4A to RNC,it means: A Report SHO measurementB RLC buffer absolute payload exceeds define Threshold in UE(RLC缓存绝对值超出门限)C Trigger one of five ISHO reasonD Trigger one of five IFHO reason8.The frequency of Power control command for WCDMA is A 1000HZ B 1500HZC 500HZD 2hz9.Iur is the logical interface betweenA BTS and RNCB MS and BTSC RNC and RNCD RNC and MSC 10.Following which channel is used for carrier user data in Ul for HSUPA A E-AGCH B E-DPCCH C E-DPDCH D E-HICH11 In optimization,we use Mapinfo to display the RF coverage info in geographily What function in Mapinfo we can use to display the RSCP or ECNO with pre-define legendA Thematic Map(专题地图)B Prism MapC GeocodeD Crystal Report12 what parameter can increase the minimum power per RL Note: kind of try to reduce the PC operation window E CPICHtoRefRABoffset from 0 to -2dbThe parameter defines the offset of the primary CPICH transmission power, and the maximum DL transmission power of the reference service channel in DL power allocation. The maximumtransmission power of the reference service is calculated (in dBm) by subtracting the value of the parameter from the transmission power of the primary CPICH.F PCRangeDL form 20 to 15db感谢您的阅读,祝您生活愉快。
NOKIA试题姓名:________地区:________成绩:______1.一.填空题(20分)2.GSM中,邻两频道间隔为200kHz。
每个频道采用时分多址接入(TDMA)方式,分为_8__个信道。
每信道占用带宽为_200k_。
3.RTCC是将天线接收下来的信号分成6路。
4.TRUA提供_3___个2M端口VXTA提供___4___个2M端口5.NOKIA基站用于跳频的总线是____FBUS________6.电源柜中分流器的作用是计算电流7.GSM900MHz的上行频段为:890~915,下行频段为:935~9608.GSM1800MHz的上行频段为:1710~1785,下行频段为:1805~18809.不采用LAPD信令压缩时一条2M的PCM能支持10个载波,而采用LAPD信令压缩,压缩因数为4时,一条2M的PCM能支持12个载波10.NOKIA基站7900告警表示.11.传输环回中,通过人工用尾纤、自环电缆对光口、电口进行环回操作叫__________。
12.在多址技术中,不同的用户分配在时隙相同而频率不同的信道上称为頻分,不同的用户分配不同的无线信道(频率)或同一信道内的不同码称为時分,不同的用户分配在时隙不同、频率相同的信道上称为碼分。
1.如果一个ULTRASITE基站有17个TSGA,则至少需要_____个BB2A,条2M的PCM。
2.二.单选题(30分)3.小区选择C1算法跟以下那个因素有关?a.Rxlev_minb.MS_Txpwr_Maxc.Rxlev_Access_MinBS_Txpwr_Max2。
如果一个网络运营商分别有15MHz的上、下行频宽,那么他可以获得多少个GSM 频点(减去一个保护频点)?a.600b.599c.75d.743.1毫瓦与1瓦约相差多少?除以10为DB—10a.20dBb.30dBc.1000dB100dB4.以下哪个现象不存在模拟网,而只存在于数字无线网中?a.瑞利衰落b.拥塞c.快衰落码间干扰5。
诺基亚试题库考卷(III)一、选择题(每题2分,共20分)A. 15年B. 1871年C. 18年D. 1875年2. 诺基亚公司的总部位于哪个国家?A. 瑞典B. 芬兰C. 丹麦D. 挪威A. 诺基亚3210B. 诺基亚6110C. 诺基亚7650D. 诺基亚N95A. 通信设备B. 家用电器C. 化工产品D. 食品产业A. 诺基亚N8B. 诺基亚E7C. 诺基亚808D. 诺基亚C6A. 1990年代B. 2000年代C. 2010年代D. 2020年代A. 马蒂·莱万宁B. 拉吉夫·苏里C. 约玛·奥利拉D. 斯蒂芬·埃洛普A. 智能手机B. 通信设备C. 网络服务D. 物联网A. 诺基亚Lumia 800B. 诺基亚Lumia 710C. 诺基亚Lumia 610D. 诺基亚Lumia 900A. 中国B. 美国C. 印度D. 巴西二、填空题(每题2分,共20分)1. 诺基亚公司的全称是__________。
2. 诺基亚公司的创始人是__________。
3. 诺基亚公司的第一款手机是__________。
4. 诺基亚公司在2007年被__________公司超越,失去了全球手机市场领导地位。
5. 诺基亚公司在2011年与__________公司合作,推出Windows Phone手机。
6. 诺基亚公司在2013年被__________公司收购。
7. 诺基亚公司的手机业务在2014年被__________公司收购。
8. 诺基亚公司的通信设备业务在2015年与__________公司合并。
9. 诺基亚公司在2017年推出了__________品牌的智能手机。
10. 诺基亚公司的愿景是__________。
三、简答题(每题10分,共30分)1. 简述诺基亚公司的发展历程。
2. 分析诺基亚公司在全球手机市场衰落的原因。
3. 诺基亚公司在战略转型过程中采取了哪些措施?四、案例分析题(20分)【案例】诺基亚手机业务的兴衰1990年代,诺基亚公司凭借其出色的手机产品,成为全球手机市场的领导者。
NOKIA网优考试试题试卷说明:1考试时间:100分钟2试卷满分:100分3考试方式:闭卷姓名:分数:一、 填空:(每空0.5分,共20分)1. SDCCHTCH 信道上的测量报告周期是2.语音编码方式。
3. SCH 信道包含了35bit的信息,其中15bit6bit 4.GPRS三种不同的MM5. GPRS 系统有4 种编码速率,其中CS1EDGE 码速率。
6. GPRSTDMA TDMA 帧。
7.8.在GPRS/GSM9.10. GSM,一个TDMA11. GSMTDMA 帧组成。
12. 对于GSM 个TCH 复帧。
13.MML 命令:创建邻区:查看ET 传输误码:__ZYMO_ ___ 查看计时器参数:__ZEGO_ ___ 开启功率控制:__ZEUG_ ___ 查看当前告警:__ZEOL_ ___ 查看切换信息:查看邻区信息:__ZEAO_ ___14. DT 测试时,可以在Um ASSIGNMENTCOMPLETE 消息,前者是系统通过SDCCH 下发给手机的, 信道上报给系统的。
这是一个给手机分配话音信道的过程。
二、单项选择题:(每题1分,共计20分)1.下面哪个指标对TCH DCR有直接的影响:( C )A.BERB.TCH FERC.SACCH FERD.BLER2.下面哪条消息是在SDCCH信道上进行传送的:( C )A.CHANNEL_REQUESTB.ALERTINGC.CM_SERVICE_REQUESTD.PAGING_REQUEST3.小区选择C1算法跟以下那个因素有关:( C )A.Rxlev_minB.MS_Txpwr_MaxC.Rxlev_Access_MinD.BS_Txpwr_Max4.为避免因过多跨越LAC的小区重选而造成的SDCCH的阻塞,我们将与该小区有切换关系且与之LAC不同的相邻小区的哪个参数提高? :( B )A.T3212B.Cell_Reselect_HysteresisC.Cell_Reselect_offsetD.Rxlev_Access_Min5.在一个小区中同时存在多个用户要进行GPRS上行数据传送,是由哪个参数来控制在一个时间内由哪个手机传送?( A )FB.TFIC.RLCD.TBF6.以下哪项不是EGPRS的关键技术( D )A.Incremental RedundancyB.Link AdaptationC.Dynamic Abis PoolD.Packet Control Unit7.一个小区有3个载频,16个SDCCH/8,如果CDED设为16%,那么该小区最多有多少个GPRS 专用信道?( A )A.3个B.2个C.1个D.4个8.如果 c1=40, REO=20, TEO=30, PET=20, 那么当你停留在该小区15秒和30秒时,C2分别为:(B)A.60 and 30B.30 and 60C.40 and 60D.60 and 409.一个小区有5个空闲的PDCH,只有一个GPRS手机传文件时, 能用几个PDCH, 谁是决定因素? ( C )A.由PCU来决定分配几个时隙B.由BTS来决定分配时隙数C.由手机自身的多时隙能力来决定用几个时隙10.手机在one phase时,资源请求的时候使用哪个信道? (A)A.RACH (PRACH)B.AGCH (PAGCH)C.ACCH (PACCH)D.PDTCH11.一个小区的BSIC为62,则这个小区的NCC和BCC分别为(诺基亚设备):( B )A. 6和2B.7和6C. 6和6D. 10和212.基于以下几种原因的切换优先级排布为( D )1. Downlink quality2. Interference (uplink or downlink)3. Uplink quality4. Uplink level5. MS-BS distance (maximum or minimum)6. Downlink level7. Better cell (Power budget or Umbrella)8. PC due to Lower quality thresholds (uplink and downlink)9. PC due to Upper level thresholds (uplink and downlink).A. 2,3,1,5,6,4,7,8,9B. 2,1,3,4,6,5,7,9,8C. 2,1,3,4,6,5,7,8,9D. 2,3,1,4,6,5,7,8,913.EGPRS规划主要涉及以下接口的规划( C )A.GrB.GsC.AbisD.A-ter14.AG参数的目的是为_____________预留模块:(B)A.寻呼 B、接入 C、测量 D、广播15.寻呼组参数MFR的设置范围从2—9,如果提高MFR的设置,可以产生的作用:_______(B)A.寻呼容量增加,接续时间更短,手机更耗电;B.寻呼容量增加,接续时间变长,手机更省电;C.寻呼容量减少,接续时间更短,手机更省电;D.寻呼容量减少,接续时间变长,手机更耗电;16.通过以下那个参数可以指定话务分配到BCCH载频和非BCCH载频的优先情况:(A)A、TRPB、TXP、C、RXPD、RLT17.TBF建立的过程中不会用到下面那种信道 ( D )A. RACHB. AGCHC.PDTCHD. SDCCH18.如果系统设置周期性位置更新的时间为10小时,那么一个周期性位置更新发生在( D )。
NOKIARNP试题库6(QA)5篇第一篇:NOKIA RNP试题库6(Q&A)TypeUnitOrDepartmentHere TypeYourNameHereDOCUMENTTYPETypeDateHere(6)1.If the Mobile Station is using ARFCN=36, which frequency is it transmitting on? a)455.2 MHz b)734.2 MHz c)897.2 MHz d)1837.2 MHzc)is the correct answer2.if BSIC=43, then NCC and BCC should be equal to: a)NCC=5, BCC=3 b)NCC=3, BCC=5 c)NCC=4, BCC=3 d)NCC=3, BCC=4a)is the correct answer3.if we see from the test mobile that the TA=3, then the distance from the BTS should be nearly: a)1000m b)1650m c)2000m d)500mb)is the correct answer4.One cell has 2 TRXs(14 timeslots used for TCH).How many Erlang can this cell carry if the QoS(blocking rate)is 2%? a)2.7 Erlang b)8.2 Erlang c)16.0 Erlang d)14.0 Erlangb)is the correct answer5.What is the duplex distance in GSM900(distance between Transmit and Receive frequencies)? a)45 kHz b)30 MHz c)45 MHz d)90 MHzc)is the correct answer6.What is the maximum distance between a MS and a BTS(in dedicated mode, without the extended cell option)? a)12 km b)18 km c)35 km Question and answerTypeUnitOrDepartmentHere TypeYourNameHered)70 kmc)is the correct answer7.SMS can transmit in which logical channel of the following:a)BCCH b)SDCCH c)TCH d)FACHb)is the correct answer8.if the BTS transmission Power is 20 W, then it should be equal to a)20 db b)30 db c)33 db d)43 db e)is the correct answer9.in GSM system, how often will the MS report to the BTS in dedicated mode: a)400ms b)480ms c)580ms d)600msb)is the correct answer10.which fading is due to shadowing by terrain structures and large obstacles: a)slow fading b)fast fading c)Rician fadinga)is the correct answer11.if the clutter lose factor is 20 dbm, and 100m away from the BTS's signal is 60dbm, then 1000m away from the BTS's signal should be: a)70 dbm b)80 dbm c)90 dbm d)100 dbmb)is the correct answer12.if c1=40, REO=20, TEO=30, PET=20, then when you stay in the cell for 15s and 30s , C2 should be: a)60 and 30 b)30 and60 c)40 and 60 d)60 and 40b)is the correct answerDOCUMENTTYPETypeDateHere(6)TypeUnitOrDepartmentHere TypeYourNameHere13.the minimum C/I of co-channel re-use should be more than: a)6db b)7db c)8db d)9dbd)is the correct answer14.during the course of optimization, we can get network performance by: a)drive test b)OMC c)Subscriber's complain d)All the aboved)is the correct answer15.which of the following is not a factor in Network Planning?a)Intended coverage area b)Intended grade of service c)Bit rate of the SS7 signaling links d)cost of the network elementsd)is the correct answer16.radio network Planning process starts with a)Selection of Base station Sites b)Survey of intended sites c)Collection of all relevant information d)Working out the frequency planc)is the correct answer16.Frequency reuse is done in GSM Networks, because a)A financially viable GSM network is not possible with available frequencies without reusing them a)The spacing of 200 Khz between carriers instead of 25 Khz(like in analogue networks)reduces the number of frequencies c)it helps in increasing the number of subscribers d)None of above are quite correcta)is the correct answer17.In a certain PLMN, an average subscriber makes 5 calls during office hours(8 AM-6 PM).It is known that in a certain cell area, there are going be 1000 subscribers, at any given hour, during these office hours.Assuming that a subscriber’s conversation lasts for 100 seconds, how many TRXes are needed in this cell to provide a grade of service of 2%? a.2 b.3 c.4 d.There is not enough information given for an exact answer.b)is the correct answerDOCUMENTTYPETypeDateHere(6)TypeUnitOrDepartmentHere TypeYourNameHere18.which of the following is not a parameter affecting the cell size while planning the network? a)Antenna Height b)MS Power c)BTS Power d)None of the aboveb)is the correct answer19.If in a GSM/DCS network the periodic location update timer is set as 10 hours, then a periodic location update is done a)10 hours after the last periodic location update b)10 hours after the last power on location update c)10 hours after the last generic location update d)10 hours after the last transaction of any kind with the NSSc)is the correct answer20.Initiation of the paging process for a mobile station is done by a)MSC over a location area b)all Base Transceiver Stations in a location area c)a Base Station Controller over one BSC area d)a Base Transceiver Station in one cellb)is the correct answer21.Which of the following task is not performed on the SDCCH channel? a)Assignment of Traffic Channel to the MS b)Transmission of Short Messages c)Adaptive Power Control information from BTS to MS only d)Authenticationc)is the correct answer22.what function can get from Tom : a)trace test b)call generation c)frequency scanning d)all of the aboved)is the correct answer23.Which of the following parameters have an impact of the handset's power consumption in Idle Mode? a)dtx_mode b)no_of_m_frames_between_paging(Number of Multiframes between Paging Groups)c)timer_periodic_update_ms d)dr_in_use(Directed Retry in Use)b)and c)is the correct answer24.On which logical channels can a Handover Command be sent from the BTS to the MS? a)SDCCHDOCUMENTTYPETypeDateHere(6)TypeUnitOrDepartmentHere TypeYourNameHereb)SACCH c)FACCH d)BCCHa)and c)is the correct answer25.which measure can lower the interference?a)power control b)frequency hopping c)DTX d)antenna diversitya), b), c), d)are all the correct answer26.the advantage of Power Control including: a)lower the interference b)save power consumption c)increase capacity d)increase coveragea)and b)is the correct answer27.in the dedicated mode, the MS will measure: a)serving cell's RXLEV b)serving cell's quality c)neighbour's RXLEX d)analyze the BSICa), b), c)and d)are the correct answer28.The handover is considered radio resource if the cause is which of the following reasons :a)Level(uplink / downlin b)Quality(uplink / downlink)c)Interference(uplink / downlink)d)Power budgeta),b),c)and d)are all correct answer29.which of the following logical channel is in downlink direction: a)FACCH b)PCH c)AGCH d)RACHa),b)and c)is the correct answer30.which of the following description is the feature of BB hopping:DOCUMENTTYPETypeDateHere(6)TypeUnitOrDepartmentHere TypeYourNameHerea)TRX use fixed frequency b)TRX use hopping frequencyexcept BCCH c)in dedicated mode,MS hopping in different TRX d)In dedicated mode, MS hopping in different frequency but in fixed TRXa)and c)is the correct answerDOCUMENTTYPETypeDateHere(6)第二篇:面试Q&A面试问题面试官的问题:“你好!欢迎参加启德公益成就学院的面试,我是启德成就学院的XXX,今天将会与你做接近十分钟的面谈,让我们更加了解彼此,以下我们可以开始了吗?”1、请您做一分钟的自我介绍。
诺基亚手机测试题(四)班级姓名得分一、填空题(每空0.5分,共计30分)1、诺基亚GSM手机主要可分为、、三大系列,DCT4系列手机主要可分为、、、、五大系列,其中1600属于系列;BB5可以分为、、、四大类,其中,N70属于系列,5200属于系列。
2、诺基亚UPP8M系列手机的CPU型号主要有、、、、、、、、、。
3、诺基亚DCT4系列手机的电源IC主要可分为、、三大类4、诺基亚DCT4系列手机的射频IC(中频IC)主要包括、、、、五大类,其中1600手机采用,型号为。
5、诺基亚WD2系列手机的CPU型号主要有、、、。
6、诺基亚TIKU系列手机的CPU主要分为、两大类。
7、诺基亚BB5系列手机的主电源IC主要分为、两大类,其中诺基亚N70的主电源IC型号为;诺基亚BB5系列手机的副电源IC主要分为、两大类,其中诺基亚N70的副电源IC型号为。
8、诺基亚DCT4系列手机电源IC内部集成、、。
9、诺基亚手机常见的收音机IC型号有、、、,其中5200手机的收音机IC型号为。
10、诺基亚手机恢复出厂设置的保密码是,查看软件版本指令是,恢复出厂设置指令是,诺基亚S60系统软格指令是,诺基亚S60系统硬格指令是。
二、不定项选择题(漏选无分,每题2分,共计10分)1、以下哪些信号不正常会导致1600手机不开机()A.VIOB.VCOREC.PWRONXD.VFLASH1E.PURXF. SLEEPXG.RFCLKH.FLSCLK2、以下哪些元件损坏会导致1600手机加电即大电流,同时拆掉可以开机A、收音机ICB、电源ICC、音频放大器D、功放E、中频ICF、背光升压ICG、照相机供电管H、充电IC3、以下哪些信号不正常会导致N70手机不开机()A.VIOB.VCOREC.PWRONXD.VFLASH1E.PURXF. VREFG.VDRAMH.SLEEPX4、诺基亚5200手机的哪些IC可与N70手机通用A.主CPUB.主电源ICC.38.4MHz晶振D.篮牙模块E.功放F.音频放大器G.背光升压IC5、以下哪些元件损坏会导致N70手机加电即大电流,同时拆掉可以开机A、蓝牙收音机模块B、电源ICC、音频放大器D、功放E、接收中频ICF、背光升压ICG、驱动接口ICH、多媒体卡处理器三、英译汉,不正常造成什么故障(每题1分,共计20分)1、PWRONX2、UEMINT3、PURX4、LPRFCLK5、VMMC6、RFBUSENX17、I2C_SCL8、MMCCMD9、EXTCLK10、TXP11、SDRCLK12、RETUINT13、FLSRSTX14、EXTRDX15、VCHAR16、TAHVOINT17、BTFM_WAKEUP18、VCAMDIG19、MMICLK20、VPUMP四、看图分析题(共计4题,共计40分)1、1600手机的送受话电路原理分析(10分)(1)画出1600手机的本机受话电路。
诺基亚试题库考卷(II)(考试时间:90分钟,满分:100分)一、选择题(每题2分,共30分)1. 诺基亚最初是以什么业务起家的?()A. 造纸B. 电力C. 通信D. 交通2. 诺基亚在哪一年推出了其首款手机?()A. 1981年B. 1982年C. 1983年D. 1984年A. 诺基亚3310B. 诺基亚5110C. 诺基亚6110D. 诺基亚11004. 诺基亚在2013年收购了哪家公司的移动设备业务?()A. 摩托罗拉B. 索尼爱立信C. 黑莓D. 阿尔卡特朗讯A. 5G网络设备B. 智能手机C. 软件服务D. 航空航天6. 诺基亚在全球5G专利排名中位于第几位?()A. 第一B. 第二C. 第三D. 第四7. 诺基亚与哪家公司合作推出了OZO虚拟现实相机?()A. 谷歌B. 微软C. FacebookD. 苹果二、判断题(每题1分,共20分)1. 诺基亚是芬兰最大的公司。
()2. 诺基亚在智能手机市场上的份额曾一度超过50%。
()3. 诺基亚是第一家推出GSM手机的制造商。
()4. 诺基亚在2011年与微软合作,推出了基于Windows Phone操作系统的手机。
()5. 诺基亚在5G技术方面处于领先地位。
()6. 诺基亚在功能手机市场上已经完全退出。
()7. 诺基亚的Lumia系列手机使用的是Android操作系统。
()8. 诺基亚贝尔实验室是诺基亚旗下的研究机构。
()9. 诺基亚在物联网市场上没有相关业务。
()10. 诺基亚的成长基金专注于投资通信技术相关的创新企业。
()三、填空题(每空1分,共10分)1. 诺基亚公司的总部位于__________。
2. 诺基亚在__________年推出了其首款智能手机。
3. 诺基亚的5G技术专利数量在全球排名__________。
4. 诺基亚在__________年收购了阿尔卡特朗讯。
5. 诺基亚的经典手机游戏“贪吃蛇”首次出现在__________型号的手机上。
第1篇一、基本信息1. 姓名:2. 性别:3. 年龄:4. 教育背景:5. 专业:6. 工作经验:二、性格测试题1. 以下哪个选项更符合你的性格特点?A. 我喜欢与人交往,善于沟通,乐于助人。
B. 我性格内向,喜欢独立思考,不太善于表达自己。
C. 我性格开朗,善于合作,能够迅速适应新环境。
D. 我性格沉稳,做事有计划,注重细节。
2. 当你遇到以下情况时,你会怎么做?A. 遇到困难,我会积极寻求帮助,与同事共同解决问题。
B. 遇到困难,我会先自己尝试解决,如果不行再寻求帮助。
C. 遇到困难,我会选择逃避,不愿意面对。
D. 遇到困难,我会保持沉默,自己承受。
3. 以下哪种工作环境你更喜欢?A. 团队合作,共同完成任务。
B. 个人独立,自由发挥。
C. 严格的管理,明确的分工。
D. 轻松的氛围,自由的工作方式。
4. 当你遇到以下情况时,你会如何处理?A. 同事犯错,我会耐心指导,帮助他们改正。
B. 同事犯错,我会指出错误,让他们自己改正。
C. 同事犯错,我会选择忽视,不予以理会。
D. 同事犯错,我会指责,让他们感到羞愧。
5. 你认为以下哪种工作态度最重要?A. 严谨认真,追求卓越。
B. 谦虚谨慎,善于学习。
C. 自信乐观,勇于挑战。
D. 责任心强,敢于担当。
6. 当你面对以下情况时,你会如何应对?A. 领导批评,我会虚心接受,认真反思。
B. 领导批评,我会辩解,表达自己的观点。
C. 领导批评,我会逃避,不愿意面对。
D. 领导批评,我会保持沉默,不予以理会。
7. 你认为以下哪种工作方式更适合你?A. 按部就班,遵循规章制度。
B. 主动创新,敢于尝试新事物。
C. 团队协作,共同进步。
D. 独立自主,自我驱动。
8. 当你遇到以下情况时,你会如何处理?A. 项目进度延误,我会积极调整计划,确保项目按时完成。
B. 项目进度延误,我会选择放弃,避免损失。
C. 项目进度延误,我会推卸责任,让同事承担。
D. 项目进度延误,我会保持沉默,不予以理会。
广东机电职业技术学院《手机原理与维修》精品课程测试题
诺基亚手机测试题(二)
一、填空题
1、诺基亚BB5系列手机的主电源IC主要分为、两大类,其
中诺基亚N70的主电源IC型号为;主CPU主要分为、
、三大类,其中诺基亚N70的主CPU型号
为。
2、诺基亚BB5系列手机充电IC集成在内部,音频IC集成在内部。
3、诺基亚N70手机采用了三个存储器,其中主字库型号为,暂存型号
为;采用了两个中频IC,其中接收中频IC型号为,发射
中频IC型号为;采用了两个功放,其中GSM功放型号为,
CDMA功放型号为。
4、诺基亚5200手机CPU型号为,主电源IC型号为,
副电源IC型号为;字库型号为,暂存型号
为,中频IC型号为,功放型号为。
5、诺基亚N70手机的系统时钟频率为,蓝牙时钟频率为。
二、不定项选择题
1、以下元件中,哪些元件损坏可能会导致5200手机不开机,但拆掉也能开机
A、收音机IC
B、蓝牙模块
C、音频放大器
D、功放
E、中频IC
F、背光升压IC
G、驱动接口IC
H、多媒体卡处理器
2、以下哪些信号不正常会导致N70手机不开机()
A.VIO
B.VCORE
C.PWRONX
D.VFLASH1
E.PURX
F. VREF
G.VDRAM
H.SLEEPX
3、以下哪些信号不正常会导致5200手机无信号
A.VRCP1
B.RFBUSCLK
C.VRFC
D.RXRESET
E.VIO
F. AFC
G.VAUX
H.VCORE
4、诺基亚5200手机的哪些IC可与N70手机通用
A.主CPU
B.主电源IC
C.38.4MHz晶振
D.篮牙模块
E.功放
F.音频放大器
G.背光升压IC
5、以下哪些元件损坏会导致N70手机加电即大电流,同时拆掉可以开机
A、蓝牙收音机模块
B、电源IC
C、音频放大器
D、功放
E、接收中频IC
F、背光升压IC
G、驱动接口IC
H、多媒体卡处理器
三、英译汉,不正常造成什么故障
1、VSIM2
2、RETUINT
3、SERCLK
4、VRCP1
5、FLSRST
6、SDRCLK
7、TXC
8、EXTCLK
9、MICB1 10、HOOKDET 11、BTFM_WAKEUP 12、VDRAM 13、SCLK 14、WTXDET 15、SLEEPX
16、LPRFCLK 17、RFCLKP 18、MMCCMD 19、MEMADDA 20、SDRDA
四、看图分析题
1、3250手机的送受话电路原理分析
(1)画出3250手机的本机受话电路。
(2)画出3250手机的本机送话电路。
(3)画出3250手机的耳机受话电路。
(4)画出3250手机的耳机送话电路。
(5)、耳机与本机是如何切换的?) (6)、插入耳机后手机又是如何完成免提的?
2、3250手机的收音机电路原理分析
(1)收音机IC工作须具备哪些条件?详细说明引脚、信号名称、含义及电压或频率。
(2)简要叙述收音的过程。
4、根据3250手机原理图画出其开关机原理方框图
1。