精校word版答案全---太原五中2018—2019学年度第二学期阶段性检测高三英语
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山西太原五中2018-2019学年度下学期高二阶段性检测语文月考试题(2019.05)一、现代文阅读(18分)(一)论述类文本阅读(本题共3小题,6分)阅读下面文字,完成1~3题。
从文化民族主义的历史发展看汉服运动20世纪中国文化民族主义理论先后经过了三个阶段:以章太炎为代表的“国粹国光论”是这个理论的首发与开端,以陈寅恪为代表的“文化民族论”则是这个理论的阐发与发展,而以钱穆为代表的“文化本位论”则完成了民族史学理论的完整逻辑架构。
对于汉服运动,我们也应该把它放置到文化民族主义的历史线索中加以考察。
从章太炎到陈寅恪再到钱穆,中国的文化民族主义理论历来强调民族独立、民族自觉。
但是,他们所有的理论诉求都是建立在“文化本位”而不是“种族本位”的基础上的。
即使是以“推翻满清,建立民国”为目的的章太炎,也明确指出,“提倡国粹”不是要人们尊信孔教,而是要爱惜我们“汉种的历史”。
同样,按照陈寅恪的“文化民族论”,在北朝史中,凡关于胡汉之问题,实一胡化、汉化之问题,而非胡、汉种之问题;在“种族”、“文化”和“地域”三个因素当中,文化之教化居于首位,无论其属于什么血统,也无论其居住于何处地域,皆以“教化”即文化,定其“民族”之属性。
钱穆的“文化本位论”更是毋庸赘言。
汉服运动宣扬汉民族种族的纯正性和优越性,它所推崇的“汉民族本位”归根结底是一种“种族本位”理论。
在一个全球化的时代,甚至可以说在一个文化帝国主义的语境之中,产生民族的“认同焦虑”是必然的,其认识论价值和现实意义也是不可忽视的,但是,由此而退回到“种族本位”,则是必须加以警惕的。
汉服运动“汉本位”的民族观、历史观和文化观,表现出一种以二元对立为基础的自我封闭的、排他的、妄自尊大的价值观和思维方式。
它强调汉民族文化的纯正性和优越性,无视汉民族文化本身的发展和演变,鄙薄汉族之外的其他各民族的文化,反对不同民族文化之间的交流和融合。
这一点,在他们对“汉服”和“唐装”的不同态度上,在他们对“汉民族的杰出人物”和“其他民族的杰出人物”的不同态度上,表现得十分清楚。
太原五中2018—2019学年度第二学期阶段性检测高二理科综合(生物)(文)出题人:任俐校对人:李琳时间:2019.4一、单项选择题:(共30题,每题1分,共30分)26.关于细胞的叙述错误的是A.细胞核、核糖体、线粒体和叶绿体中均能发生碱基互补配对B.卵细胞、神经细胞虽没有细胞周期,但化学成分都不断更新C.肺炎双球菌等原核细胞、酵母菌等真核细胞的遗传物质主要是DNAD.蓝藻之所以能够进行光合作用是因为细胞内含有光合色素27.下列关于蛋白质结构和功能的叙述,正确的是A. 质膜中蛋白质比磷脂更容易移动B. 有些膜蛋白起着生物催化剂的作用C. 各种蛋白质都含有C、H、O、N、S等元素D. 蛋白质特定生物学功能决定蛋白质特定空间结构28.下列有关真核细胞细胞核的叙述正确的是A.细胞核内的核仁被破坏,不会影响胰岛素的合成B.DNA主要是在细胞核中合成的C.有丝分裂中期核基因能够发生转录和翻译D.细胞内所需的能量都在线粒体内产生29.用显微镜观察葫芦藓叶的装片时,为使视野内看到的细胞数目最多,应选用A.目镜5×,物镜10× B.目镜10×,物镜15×C.目镜5×,物镜40 D.目镜10×,物镜40×30.下列有关高等植物细胞结构的说法正确的是A.线粒体、叶绿体、核糖体中均含有DNAB.细胞中膜蛋白的形成与内质网无关C.叶绿体产生的ATP可以为细胞提供能量D.吡罗红甲基绿染色剂使细胞中大部分区域染成红色31.下列关于细胞结构和生物体内化合物的叙述正确的是A.抗体、激素、tRNA发挥一次作用后都将失去生物活性B.ATP脱去两个磷酸基团后成为RNA的基本组成单位之一C.蓝藻和绿藻都能进行光合作用,故二者含有的光合色素相同D.细菌代谢速率极快,细胞膜和细胞器膜为其提供了结构基础32.下列哪个选项均属于生命系统范畴①水分子②石头③迁徙中的一群大雁④变形虫⑤病毒⑥生物圈⑦恐龙化石⑧蛋白质⑨跳动的心脏⑩运输营养的筛管A. ①③⑧⑨B. ②④⑥⑦C. ⑤⑦⑧⑩D. ③④⑥⑨33.请找出下列物质中所有的氨基酸,由这些氨基酸经脱水缩合后形成的物质为NH2—CH2—COOH ① NH2—CH(OH)—COOH ②NH2— CH—(CH2)2—COOH ③ CH2—CH—CH2—COOH ④A.氨基酸B.二肽C.三肽D.四肽34.下图表示生物体内的三个生理过程(a,b,c),在此三个过程中,y代表的物质分别为A. 载体、抗体、酶B. 抗体、载体、酶C. 激素、抗体、载体D. 载体、酶、抗体35.一分子CO2从叶肉细胞的线粒体基质中扩散出来,进入一相邻细胞叶绿体基质内,共穿过的生物膜层数是A. 5B. 6C. 7D. 836.水在生物体内是一种良好的溶剂,是各种化学反应的介质。
太原五中2018—2019学年度第二学期阶段性检测高一英语出题人、校题人:郭海涛李星玲王芳(2019.4)(考试时间:90分钟试卷满分:100分)注意事项:1.本试卷由四个部分组成。
其中,第一和第二部分第一节为选择题。
第二部分第二、三、四节和第三部分为非选择题。
2.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
3.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
4.考试结束后,将答题卡交回。
第一部分阅读理解(共两节,满分30分)第一节(共10小题;每小题2分,满分20分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
AAmsterdam, the capital and most populous city in the Netherlands, is one of the most popular travel destinations in the world, famous for its beautiful canals, top art museum, cycling culture, and Red Light District. Here are some of the key points to remember as you plan your trip to Amsterdam.Must-See AttractionsMost visitors begin their Amsterdam adventure in the Old Centre, which is full of traditional architecture, shopping centers, and coffee shops. You’ll also want to check out Amsterdam’s Museum Quarter in the South District, which is great for shopping at the Albert Cuyp Market and having a picnic in the Vondelpark. The top museums to visit are the Rijksmusuem, the Ann Frank House, and the Van Gogh Museum. The Canal Ring is a UNESCO World Heritage Site that was originally built to attract wealthy home owners and is a popular place for celebrity spotting and nightlife today.TransportationTravelers should be aware that Amsterdam Airport Schiphol is one of the busiest airports in the world. This airport is located about 15 kilometers southwest of city center. You can catch a train from Schiphol to Amsterdam Central Station, which has many connecting routes. It’s typically not a good idea to drive a car to the city center because traffic is heavy and parking is difficult to find. Cycling is incredibly popular here, and it’s easy to find cheap bike rentals around town. Amsterdam has a flat terrain(地形) and is a great city to explore on foot. Money Saving TipsUnless you really want to see the tulips(郁金香) blooming, avoid booking between mid-March and mid-May. This is when hotel and flight prices rise.Look for accommodations in Amsterdam’s South Dis trict, where rates are generally cheaper than in the city center.Buy train tickets at the machine instead of the counter to save a bit of money.Instead of hiring a tour guide, hop on a canal boat. They’re inexpensive and will give you a unique point of view of the city.Check out our homepage to view price comparisons for flights, hotels, and rental cars before you book.1.Which attraction was built with the original purpose of drawing the rich?A.Albert Cuyp Market.B. The Ann Frank House.C. The Van Gogh Museum.D. The Canal Ring.2. Which means of transportation is not advisable in Amsterdam according to the passage?A. The plane.B. The train.C. The car.D. The bike.3. Which way can help visitors save money in Amsterdam?A.Seeing the tulips blooming in spring.B. Avoiding accommodating downtown.C. Buying car tickets at the machine.D. Hiring a local tour guide.BAn Arizona woman who was attacked by a zo o’s jaguar(美洲虎) over the weekend has apologized and admitted she crossed a safety barrier(栅栏) to snap a photo.The woman Leanne told CBS News that she leaned over the barrier at Lichfield Park’s Wildlife World Zoo on Saturday, but she refused to admit she climbed over it as the zoo has said.“I never passed the barrier, but I do admit to leaning over the barrier,” she told the news network.The woman had injuries that were not life-threatening to her arm after the big cat caught onto her through a fence. A fellow park goer got the cat to release its painful grasp by distracting the animal with a plastic water bottle.Mickey Ollson, the director of Wildlife World Zoo, told ABC that the jaguar won’t be harmed because of “human behavior”. He added that this wasn’t the first time that the animal has injured a guest who got too close, however. It’s not clear whether the park plans to re-evaluate the barrier around the exhibit, which has been described as a 3-foot wall. Leanne hopes that they will.“I was in the w rong for leaning over the barrier, but I do think the zoo should look into moving their fence back,” she told CBS News. “I’m not the first, and if they don’t move the fence, I’m probably not going to be the last.”Kitty Block, president and CEO of the Humane Society of the United States, also urged the zoo and other parks to be cautious enough when it comes to separating the animals from people.“When various types of exhibitors promote all sorts of close meeting with wildlife, people get the mistaken idea that wild animals are approachable,” she said in a statement. “We urge the zoological community exhibitors to set a higher standard to protect people and to respect wildlife from a safe distance by doing away with public contact opportunities with wildlife of all species.”4.How did Leanne free from the danger of the jaguar?A.The zoo director helped her to get away from it.B.The jaguar was attracted by a bottle and let her go.C.Another park goer hurt the jaguar and it ran away.D.Leanne herself struggled with it and scared it away.5. What can we infer from Paragraph 5?A. Human behavior cannot have any influences on the jaguar in the zoo.B. The jaguar tends to attack the guests unexpectedly however far they stay.C. Leanne is doubtful whether the barrier around the exhibit is safe enough.D. The zoo has ensured the barrier will be evaluated again after the accident.6.What did Kitty Block advise the zoo and parks to do?A.Be very cautious to separate the animals from people.B.Look into moving their fence back and clear the barrier.C.Set a higher standard to build up a zoological community.D.Encourage people to have frequent meetings with wildlife.CRobot vacuum cleaners aren’t a new concept, having been around for more than 15 years, but they have become greatly more helpful since the days of catching on rug hairs, running out of battery mid-clean and forgetting where they were.But the next generation of disc-shaped floor-cleaners could bring some of the most important upgrades yet, including being more autonomous than ever and knowing exactly where they are in your home and where you need them to be.iRobot’s latest Roombas, the i7 and i7+, shown off at a recent event in Tokyo, will be arriving in Australia in the coming months. Their key new feature: persistent mapping of your home. The ability to map not only makes the robot quicker and more efficient, but lets it integrate(融入) more closely with smart homes. Once it’s explored your house a few times, the i7 will present you with a map via its smart phone app, which Angle says tends to be “maybe 80 per cent right”.As the robot travels around cleaning up dust, it draws a floor plan and uses a sensor(传感器) to identify landmarks and objects. Unlike previous models, the i7 remembers this information, meaning it will learn the most efficient paths around your home over time.If you change the layout of your furniture, it will adapt the existing map rather than having to create a whole new one and if you have a multi-storey house, it simply makes multiple maps, and use s its learned landmarks to determine which floor it’s on (you’ll still need to carry it up the stairs).iRobot’s CEO and founder Colin Angle says the i7 class, the company’s 10th generation Roomba, is the robot he’s always wanted to build; capable of keeping a home’s floors clean with virtually no user input needed.“This robot has 30 times the processing power of its former generation,” he says. “So we’re fully into a situation today where we can be running machine learning and visual object recognition technology and very advanced algorithms(演算法; 运算法则)on the robot, to allow it to continue to work on increasingly complicated code.”7.According to the passage the robot cleaners invented 15 years ago could ______.A. catch on the hairs on the rugB.charge the battery mid-cleanC.draw the map of the homeD. know their exact home position8. The underlined word “layout” in Paragraph 5 can be replaced by ______.A.arrangementB. designC. styleD. size9. Which of the following statements about the i7 and i7+ is true?A.i7 remembers the identified landmarks like former models.B.They can enter the room upstairs themselves and clean it.C.They can do better in math than the previous cleaners.D.i7 can present a map exactly via its smart phone app.10.What can be the best title of the passage?A.Technologies in the Cleaner.B. The Future of iRobots.C. The Development of iRobots.D. The Latest Robot Cleaner.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
太原五中2018-2019学年第二学期阶段性测试初三数学(4月3日)一.选择题(共10小题,每小题3分,共30分) 1. 8-的相反数A.-8B.8C.±8D.81- 2.2017年我省粮食总产量是695.2亿斤,其中695.2亿用科学计数法表示为A .6.952×610B .6.952×810C .6.952×1010D .695.2×8103. 下列因式分解正确的是A. ()4x -x x 4x -2+=+B.()y x x x x y x 2+=++C.()()()2y -x x -y y y -x x =+D.()()2-x 2x 4x 4-x 2+=+ 4. 一个由圆柱和圆锥组成的几何体如图水平放置,其主(正)视图为 A. B. C. D.5. 最早引入坐标系,用代数方法研究几何图形的数学家是A. 刘徽B. 祖冲之C. 阿基米德D. 笛卡尔6. 据省统计局发布,2017年我省有效发明专利数比2016年增长22.1%。
假定2018年的年增长率保持不变,2016年和2018年我省有效发明专利分别为a 万件和b 万件,则A. ()a 21.221b ⨯+=%B. ()a 1.221b 2%+= C.()2a 1.221b %+= D. a 21.22b ⨯=%7.若关于x 的一元二次方程()0ax 1x x =++有两个相等的实数根,则实数a 的值为A.-1B.1C.-2或2D.-3或18. 为考察两名实习工人的工作情况,质检部将他们工作第一周每天生产合格产品的个数整理成甲、乙两组数据,如下表:关于以上数据,说法正确的是甲 2 6 7 78 乙 2 3 4 8 8A. 甲、乙的众数相同B. 甲、乙的中位数相同C. 甲的平均数小于乙的平均数D. 甲的方差小于乙的方差9. 在□ABCD 中,E 、F 是对角线BD 上不同的两点,下列条件不能得出四边形AECF 一定为平行四边形的是A.BE=DFB.AE=CFC.AF∥CED.∠BAE=∠DCF10. 如图,直线1l ,2l 都与直线l 垂直,垂足分别为点M ,N ,MN=1,正方形ABCD 的边长为2,对角线AC 在直线l 上,且点C 位于点M 处。
太原五中2018—2019学年度第二学期阶段性检测高三英语(考试时间:120分钟试卷满分:150分)注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在本试卷相应的位置。
2.全部答案在答题卡上完成,答在本试卷上无效。
3.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案用0.5mm 黑色笔迹签字笔写在答题卡上。
4.考试结束后,将答题卡交回。
第一部分听力(共两节)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
第二部分阅读理解(共两节,满分60分)第一节(共15小题;每小题3分,满分45分)阅读下面短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AThe 2019 Beijing Horticultural Expo, the largest of its kind, has chosen the the me “Live Green, Live Better”. The expo, opened on April 29 in Yanqing District of Beijing, is scheduled to last for 162 days until October 7.Tickets available●Standard day ticket●Designated day ticket●Discounted ticket●Group ticketDesignated days●Labor Day holiday (May 1 — 4)●Dragon Boat Festival holiday (June 7 — 9)●Mid-Autumn Festival holiday (Sept 13 — 15)●National Day holiday (Oct 1 — 7)Tickets prices●Standard day ticket 120 yuan●Ordinary designated day ticket 160 yuan●Discounted standard day ticket 80 yuan●Discounted designated day ticket 120 yuanTickets are free for children under the age of six or shorter than 130 centimeters. Discounted tickets are available for those with disabilities, seniors (people aged at 60 or above), children, students and PLA soldiers.Where to buyVisitors can buy or book tickets from two online agents, seven travel agencies, or three event channels — the event WeChat account, the event app or Onsite ticket kiosks.Opening hoursBuying tickets for Expo 2019 Beijing requires real-name registration, and all visitors are required to input information from their ID cards (or valid passports, mainland travel permits for Hong Kong and Macao residents, and mainland travel permits for Taiwan residents) to buy or book tickets online.21. From the passage, what can we learn?A. A resident from Macao can only book his ticket with his mainland travel permits.B. Tickets cannot be booked through the event WeChat account.C. One can be admitted in at any time with an unlimited entry pass.D. Visitors must use their real names to buy tickets.22. If a PLA soldier takes his wife, his 64-year-old father and five-old-year son to the expo on June 7, how much will he pay for their tickets?A. 360.B. 480.C. 400.D. 520.23. Where is the passage most probably taken from?A. A notice board.B. A report.C. A magazine.D. A book review.BFriends always ask why I, a middle-aged woman with no athletic talent, travel to perilous places — the jungles of Thailand or Borneo, for example, where the water is often unsafe and the food risky; places with infectious diseases, poisonous snakes and the wildest animals; some places where the locals are just a few generations past headhunting.I never know how to answer. My travel decisions assumed a new gravity nine years ago after高三英语第3页(共22页)高三英语第4页(共22页)I suffered a stroke. To prevent another stroke, my doctors told me, I’d have to take dangerously high levels of blood thinner (血液稀释剂) for the rest of my life and any travel would be risky.I had to think about what was important to me: family, of course, and friends. But then what? No matter how many times I thought about it, no bucket list was complete without travel. Then I had to decide how I might manage the risk. I had to decide how lucky I felt.My return to travel after my stroke came in baby steps. The first real test of my travel courage came nine months after my stroke when I joined my husband, Jack, on a business trip to China. After we’d toured the remains of a Tang dynasty temple on a high mountain, Jack wanted to ride down on a toboggan (长雪橇).Before the stroke it would’ve seemed like fun. But now? I hesitated. M y mental klaxon (高音喇叭) screamed warnings about the consequences of a cut, a fall, and a crash. Then, gaining confidence from who knows where, I lowered myself carefully into the toboggan, which marked my adventure travel comeback.In the years since then, I’ve traveled about twenty-five percent of the time. Through it all, my lucks held out — no deadly falls, no car accidents or serious infections. For me, adventure travel is a risk worth taking. Travel broadens my world and keeps me connected to nature. Wh at’s more, saying “yes” to travel keeps me connected to myself.24. What does the underlined word “perilous” in Paragraph 1 probably mean?A. Unique.B. Dangerous.C. Historical.D. Famous.25. What did the doctors advise the author to do?A. Do proper exercise.B. Enjoy the rest of her life.C. Keep away from traveling.D. Spend more time with her family.26. Why did the author mention her travel to China?A. It was her last adventure.B. She recovered her courage through it.C. She liked the beautiful scenery in China.D. It was the most dangerous experience in her life.27. What is the best title for the text?A. A business trip to ChinaB. Unique travel experiencesC. Why I still travel to the wildD. How I overcame the fear of diseaseCThe new president of Harvard University is the son of an Eastern European refugee and Auschwitz (奥斯威辛) survivor —Lawrence S. Bacow. His father worked full time while attending a state college in Detroit at night to earn his degree.Bacow, the former president of Tufts University, has taken over Harvard at a time when higher education is under attack for being financially out of reach to many Americans. But Bacow said his family’s journey had reflected the power of college education to transform generations and the opportunities that have historically been available in the United States.“My parents came to this country with almost nothing,” Bacow said. “I wouldn’t be here if this country had not been open to people like my parents at that time. Nor would I if my father hadn’t had the opportunity to get the college education.”Bacow grew up in Pontiac, Michigan. His father’s family fled anti-Jewish (反犹太的) violence in Minsk, then part of the Soviet Union, before the start of World War II and went to the United States. His mother arrived in Brooklyn at age 19, having survived Auschwitz concentration camp. She was the only Jew from her town to have survived the war. Yet Bacow, who is married with two sons, said that while growing up in Michigan, he had a happy childhood, entering science fairs as a child and building radios like his dad.Bacow has spent most of his professional career at MIT, Harvard and Tufts. He was a professor of environmental studies at MIT, and later a principal at the university. He led Tufts from 2001 to 2011. At Tufts, Bacow earned a reputation for shaking up a sleepy university that was being overshadowed by its peers in Boston. He is also credited with leading it through both 9/11 and the 2008 financial crisis.As the Tufts president, Bacow traveled around the country, reaching out to alumni (校友), and he urged his faculty and deans to do the same, in an effort to boost donations to finance Tufts’ academic ambitions. He raised more than $20 million for faculty recruitment, attracting up-and-coming professors by offering junior faculty perks (福利), such as long academic leaves that they couldn’t get elsewhere.Under Bacow’s leadership, Tufts spent millions on labs and libraries. He also made addresses nationally about the need to make higher education more accessible and affordable to low-income students.28. The reason why Bacow appreciates college education is that .A. college education is out of reach to many AmericansB. his family changed their fate due to college educationC. few opportunities were available when his father came into the countryD. a college degree helped his mother survive Auschwitz29. What can we infer from the passage?A. The fellow townspeople of Bacow were all killed besides his mother.高三英语第7页(共22页)高三英语第8页(共22页)B. Bacow’s mother stimulated his interest in science.C. Bacow’s father was good at working with electronics.D. Bacow’s father came to the U.S. after World War II broke out.30. The underlined word “shaking up” in paragraph 5 probably means .A. reactivatingB. causingC. damagingD. taking over31. What is this passage mainly about?A. How to be admitted to Harvard University.B. The history of Bacow’s family.C. The art of Bacow’s leadership in Tufts.D. Bacow’s way to indivi dual success.DProfessional athletes pay a high price for their pursuit of excellence and glory. Training to the limit tears muscles and wears out joints. Gymnasts often need hip replacements when barely into middle age. Few footballers make it to the end of their careers with their knees intact.But many also run a darker risk: doping —the use of banned athletic performance-enhancing drugs by athletic competitors. The Winter Olympics in Pyeongchang, in South Korea, starts this week in its shadow. Years after whistle-blowers first revealed wholesale (大规模的) doping in Russia, the International Olympic Committee (IOC) at last decided to bar it from taking part. But it has allowed many Russians to compete as individuals. And on the eve of the competition the Court of Arbitration for Sport (CAS) said that 28 others should receive a more tolerant penalty from the IOC, further muffling the anti-doping message.Russia’s doping is unusual only in its scale and institutional nature. No country or sport is immune. Studies, and an anonymous survey at the World Athletics Championships in 2011, suggest that a third of athletes preparing for big international competitions take banned substances. Yet just 1-2% fail a test each year. Lance Armstrong, a cyclist who won the Tour de France seven times and later admitted to doping all the while, was tested on 250 occasions. The few times he failed, he avoided punishments by claiming he had taken anti-inflammatories (消炎药) for saddle-sores (骑行引起的肌肉酸痛).Doping is more sophisticated than when some states used steroids (类固醇) to bulk up athletes. New drugs are designed to be undetectable in a blood or urine sample. Many athletes “blood dope,” receiving transfusions or taking a drug that stimulates the production of red blood cells to improve their physical strength. Soviet athletes who were fed steroids suffered a host of serious problems in later life. They were more likely to commit suicide, or to miscarry (流产) or have a disabled child. No one knows what risks those taking new “designer” versions are running. Blood-doping can cause heart attacks; more than a dozen cyclists’ deaths have already been linked to it.The agencies that set out to stop doping are hugely outclassed. As the argument over punishments on Russia illustrate, they are divided and weak. Most testing is done by national bodies, which may not try very hard to find evidence that would get their own stars banned. The World Anti-Doping Agency (WADA), which oversees them, is packed with officials fromnational sports federations and the IOC. Their interests are likewise conflicted. Its budget is tiny. The system seems to be designed to look tough but punish only the occasional scapegoat (替罪羊). Honest athletes deserve better.32. The word “muffling” (in paragraph 2) is closest in meaning to “.”A. deafeningB. conveyingC. spreadingD. weakening33. Why did the author cite an instance of Lance Armstrong?A. To illustrate he is a model of Russian athlete.B. To show cycling is very popular in France.C. To indicate doping exists everywhere.D. To suggest doping is an exception for American athletes.34. Which of the following is NOT a side-effect of steroids?A. Giving birth to an unhealthy child.B. Suicidal tendencies.C. Stimulates the production of red blood cells.D. Unintentionally having a pregnancy end early.35. What can be inferred from the passage?A. The CAS should put more severe penalties on Russian athletes.B. The Winter Olympics in Pyeongchang have not been successful due to doping scandals.C. Doping is quite common among athletes in France and Russia.D. W ADA does a good job monitoring doping in the Olympics.第二节(共5小题,每小题3分,满分15分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018——2019学年度第二学期阶段性检测高三理科综合时间:2019.05.23注意事项:1.本试题分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
2.答题前,考生务必将自己的姓名、准考证号填写在本试题相应的位置。
3.全部答案在答题卡上完成,答在本试题上无效。
4.考试结束后,将本试题和答题卡一并交回。
二、选择题:本题共8小题,每小题6分。
在每小题给出的四个选项中,第14~18题只有一项符合题目要求,第19~21题有多项符合题目要求。
全部选对的得6分,选对但不全的得3分,有选错的得0分。
14.下列说法正确的是A .β射线也可能是原子核外电子电离形成的电子流,它具有中等的穿透能力B .按照电离能力来看,放射性元素放出的三种射线由弱到强的排列顺序是α射线、β射线、γ射线C .按照玻尔的氢原子理论,当电子从高能级向低能级跃迁时,氢原子系统的电势能减少量可能大于电子动能的增加量D .在微观物理学中,不确定关系告诉我们不可能准确地知道单个粒子的运动情况,但是可以准确地知道大量粒子运动时的统计规律15.如图所示的电路中,有一自耦变压器,左侧并联一只理想电压表V 1后接在稳定的交流电源上;右侧串联灯泡L 和滑动变阻器R ,R 上并联一只理想电压表V 2 .下列说法中正确的是A .若F 不动,滑片P 向下滑动时,V 1示数变大,V 2示数变大B .若F 不动,滑片P 向下滑动时,灯泡消耗的功率变小C .若P 不动,滑片F 向下移动时,V 1、V 2的示数均变小D .若P 不动,滑片F 向下移动时,灯泡消耗的功率变大16.如图所示是两个横截面分别为圆和正方形但磁感应强度均相同的匀强磁场,圆的直径D 等于正方形的边长,两个电子分别以相同的速度飞入两个磁场区域,速度方向均与磁场方向垂直,进入圆形磁场区域的速度方向对准了圆心,进入正方形磁场区域的方向是沿一边的中点且垂直于边界线,则下列判断正确的是 A .两电子在两磁场中运动时,其轨迹圆对应的圆心角一定不相同B .两电子在两磁场中运动的时间一定不相同C .进入圆形磁场区域的电子一定先飞离磁场D .进入圆形磁场区域的电子一定不会后飞出磁场17.如图所示,匀强电场中的六个点A 、B 、C 、D 、E 、F 为正八面体的六个顶点,已知BE 中点O 的电势为零,A 、B 、C 三点的电势分别为7V 、-1V 、3V ,则E 、F 两点的电势分别为A .2V 、-2VB .1V 、-3VC .1V 、-5VD .2V 、-4V18.小铁块置于薄木板右端,薄木板放在光滑的水平地面上,铁块的质量大于木板的质量。
高一历史(文) 第1页(共8页) 高一历史(文) 第2页(共8页)密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018—2019学年度第二学期阶段性检测高 一 历 史(文)时间:2019.4一、选择题:本题共24个小题,每小题2分,共48分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1.《管子》说:“农之事,必有一耜、一铫、一镰、一 鎒、一椎、一铚,然后成为农。
”反映出A .小农经济对工具要求较高B .铁器应用广泛C .铁农具决定小农经济产生D .铁农具应用普遍2. 韩婴《韩诗外传》说到:“八家相保,出入更守,疾病相忧,患难相救,有无相贷,饮食相召,嫁娶相谋,渔猎分得,仁恩施行,是以其民和亲而相好。
”反映了井田制 A.是土地公有制 B.劳动产品平均分配 C.有农村公社遗存 D.消除了社会矛盾 3.《四民月令》所反映的豪强田庄,从规模上看是一种大地产经营,涉及农、林、牧、副、渔各业。
基本生产者雇农,是农村中的贫弱下户,有自己的家庭和独立的经济。
反映出田庄经济本质是A.小农经济B.自耕农经济C.资本主义萌芽D.商品经济4.唐、宋两代,南方县级的政区设置越来越多。
北方县反而不断合并。
反映了当时 A.经济重心南移 B.商品经济发达 C.海外贸易兴盛 D.政治重心南移5.宋代,每到季风来临,政府都派遣官员主持祈风祭海仪式,由此成为航海活动组织者和管理者。
据此可知宋代A.放弃重农抑商政策B.政府重视海外贸易C.市舶是政府主要收入来源D.经济重心南移完成6.据统计,明代各地织染局生产凋敝,而苏州、杭州、南京城市里民营织机约有15000张,山西潞安最盛时有织机9000多张。
此现象出现的根本原因是A.商品经济发展B.政府鼓励引导C.民营技术领先D.民营居主导地位 7.明朝正统初年(1435年),军官俸禄折合成白银;景泰年间(1449-1457年),文官俸禄折银。
此现象出现是因为A.吏治松懈滋生贪腐之风B.税收以白银征收C .外贸发展美洲白银大量流入 D.土地兼并阻碍谷米收获8.《万历承天府志》记载,湖广地区“地多异省之民,而江右为最,商游工作者,凭田以耕,僦居以住,岁久渐为土著”,围湖垦荒,使该地区成为全国主要粮食生产基地,产生“湖广熟,天下足”的谚语。
太原五中2018—2019学年度第二学期阶段性检测高二地理(文)命题人:秦玲爱校对:杨志杰(2019.04)一、选择题(每小题四个选项中只有一个正确选项,每小题1.5分,共45分)下图为我国部分地区示意图。
读图,完成1~2题。
1.图中序号表示的区域A.①降水稀少,河流均为内流河B.②光照充足,植被类型为荒漠C.③雨热同期,主要为湿润和半湿润区D.④水热充足,主要为热带和暖温带区2.下列叙述正确的是A.①到②地势由第一级阶梯到第二级阶梯B.②到③由畜牧业过渡到种植业为主C.③到④人口密度逐渐递增D.④到⑤的植被变化体现了从沿海向内陆的地域分异规律下图是经纬网图层和中国著名山脉图层的叠加图,图中经纬线间隔度数相等,四个小黑点为中国领土四至点(最东、最西、最北、最南)。
读图,完成3~4题。
3.经纬网的纬线间距为A.3°B.5°C.8°D.10°4.图中山脉是我国两大地形区分界线的有A.①B.①②C.①②③D.①②③④下图为沪昆高铁干线示意图。
读图,完成5~6题。
5.下列铁路干线穿过的省区,从东向西依次是A.沪、浙、湘、赣、鄂、滇B.沪、湘、黔、赣、浙、云C.沪、浙、赣、湘、贵、滇D.浙、赣、湘、黔、滇、沪6.沪昆高铁干线A.途经昆明、武汉等省级行政中心B.横跨地势第一、二、三级阶梯C.跨越热带、亚热带季风气候区D.沿线地区多泥石流、洪涝等灾害下表为我国主要流域水量平衡值(外流域水平衡原理:降水量=径流量+蒸发量),蒸发系数是一定汇水面积地面蒸发量与降水量的比值。
读表完成7~8题。
7.a、b、A.珠江、松花江、雅鲁藏布江、黄河B.雅鲁藏布江、珠江、松花江、黄河C.珠江、雅鲁藏布江、松花江、黄河D.雅鲁藏布江、珠江、黄河、松花江8.b水系蒸发系数最低的主要原因是A.纬度高B.光照弱C.峡谷深D.气温低读我国局部区域图,回答9~10题。
9.读图,分析1月日均最高温与日均最低温差值大于7月的主要原因是A.太阳高度B.昼夜长短C.河流流向D.天气状况10.图中河流A.结冰期短B.汛期长C.流域面积大D.发源于长白山读我国各地红叶最佳观赏期示意图,完成第11~12题。
太原五中2018—2019学年度第二学期阶段性检测高三英语校对:高三英语组(2019.5)(考试时间:120分钟试卷满分:150分)注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在本试卷相应的位置。
2.全部答案在答题卡上完成,答在本试卷上无效。
3.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案用0.5mm 黑色笔迹签字笔写在答题卡上。
4.考试结束后,将答题卡交回。
第一部分听力(共两节)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
例:How much is the shirt?A. £19.15.B. £9.18.C. £9.15.答案是C。
1.What does John find difficult in learning German?A.Pronunciation.B. V ocabulary.C. Grammar.2. What is the probable relationship between the speakers?A. Colleagues.B. Brother and sister.C. Teacher and student.3. Where does the conversation probably take place?A. In a bank.B. At a ticket office.C. On a train.4. What are the speakers talking about?A. A restaurant.B. A street.C. A dish.5. What does the woman think of her interview?A. It was tough.B. It was interesting.C. It was successful.第二节(共15小题)听下面5段对话或独白。
太原五中2018—2019学年度第二学期阶段性检测高三数学(理)一、选择题(本大题共12小题,每小题5分,共60分,每小题有且只有一个正确选项)1. 若复数满足(为虚数单位),则A. B. C. D.2. 若集合,,则下列结论中正确的是A. B. C. D.3. 某中学的高中女生体重(单位:)与身高(单位:)具有线性相关关系,根据一组样本数据,用最小二乘法近似得到回归直线方程为,则下列结论中不正确的是A. 与具有正线性相关关系B. 回归直线过样本的中心点C. 若该中学某高中女生身高为,则可断定其体重必为D. 若该中学某高中女生身高增加,则其体重约增加4. 在中,,,,则A. B. 或 C. D. 或5. 在等比数列中,若,,则的值是A.4B.8C.16D. 326. 已知平面向量,满足,,则的值是A. B. 7 C. D. 10高三数学(理) 第3页(共28页) 高三数学(理) 第4页(共28页)7. 一个几何体的三视图如图所示,其中正视图是一个正三角形,则该几何体的外接球的体积为A.B.C.D.8.小明在花店定了一束鲜花,花店承诺将在第二天早上7:30~8:30之间将鲜花送到 小明家.若小明第二天离开家去公司上班的时间在早上8:00~9:00之间,则小明在离开家之前收到这束鲜花的概率是( )A.18B.14C.34D.789. 已知函数,其图象相邻两条对称轴之间的距离为是偶函数,下列判断正确的是A. 对称函数 的最小正周期为B. 函数在上单调递增C. 函数 的图象关于直线D. 函数 的图象关于点对称10. 在平面直角坐标系 中,双曲线的右支与焦点为的抛物线交于 , 两点,若,则该双曲线的渐近线方程为A. y =B. 2y x =±C. y x =D. 12y x =±11.已知 ,不等式 的解集为A.B. C. D.12.如图,在四面体ABCD 中,3,2====BD AC CD AB ,5==BC AD ,E 、F 分别是,AD BC 中点.若用一个与直线EF 垂直,且与四面体的每个面都相交的平面α去截该 四面体,由此得到一个多边形截面,则该多边形截面面积最 大值为ABC .52D .54二、填空题(本大题共4小题,每小题5分,共20分)13.若不等式组20510080x y x y x y -+≥⎧⎪-+≤⎨⎪+-≤⎩,所表示的平面区域存在点00(,)x y ,使00+20x ay +≤成立,则实数a 的取值范围是___________. 14. 已知,,则. 15. 已知直线 : 与圆相交于, 两点, 是线段中点,则到直线的距离的最大值为 .16.等边ABC ∆的边长为1,点P 在其外接圆劣弧AB 上,则PAB PBC S S ∆∆+的最大值 为 .三、解答题(本大题5小题,共60分,解答应写出文字说明、证明过程或演算步骤) 17.(12分)已知数列{}n a 中, 11a =, ()*14nn n a a n N a +=∈+.高三数学(理) 第7页(共28页) 高三数学(理) 第8页(共28页)(1)求证: 113n a ⎧⎫+⎨⎬⎩⎭是等比数列,并求{}n a 的通项公式; (2)数列{}n b 满足()1413n n n n n b a +=-⋅⋅,求数列{}n b 的前n 项和n T . 18.(12分)如图,在棱长为2的正方体1111ABCD A B C D -中,E ,F ,M ,N 分 别是棱AB ,AD ,11A B ,11A D 的中点,点P ,Q 分别在棱1DD ,1BB 上移动,且(02)DP BQ λλ==<<.(1)当1λ=时,证明:直线1//BC 平面EFPQ ;(2)是否存在λ,使面EFPQ 与面PQMN 所成的二面角为直二面角?若存在,求出λ的值;若不存在,说明理由.19.(12分)第四届世界互联网大会在浙江乌镇隆重召开,人工智能技术深受全世界人民的关注,不同年龄段的人群关注人工智能技术应用与发展的侧重点有明显的不同,某中等发达城市的市场咨询与投资民调机构在该市对市民关注人工智能技术应用与发展的侧重方向进行调查,随机抽取1 000名市民,将他们的年龄分成6段:[20,30),[30,40),[40,50),[50,60),[60,70),[70,80],并绘制了如图所示的频率分布直方图.(1)求这1 000名市民年龄的平均数和中位数(同一组中的数据用该组区间的中点值作代表);(2)调查发现年龄在[20,40)的市民侧重关注人工智能技术在学习与工作方面的应用与发展,其中关注智能办公的共有100人,将样本的频率视为总体的频率,从该市年龄在[20,40)的市民中随机抽取300人,请估计这300人中关注智能办公的人数;(3)用样本的频率代替概率,现从该市随机抽取20名市民调查关注人工智能技术在养老服务方面的应用与发展的情况,其中有k 名市民的年龄在[60,80]的概率为P (X =k ),其中k =0,1,2,…,20,当P (X =k )最大时,求k 的值.20.(12分)已知(2,0)A -,(2,0)B ,点C 是动点,且直线AC 和直线BC 的斜率之积为34-. (1)求动点C 的轨迹方程;(2)设直线l 与(Ⅰ)中轨迹相切于点P ,与直线4x =相交于点Q ,且(1,0)F , 求证:90PFQ ∠=.21.(12分)已知函数()b ax x xe x f x+++=2,曲线()x f y =在点()()0,0f 处的切线方程为 0324=--y x ( 1 ) 求b a ,的值; ( 2 ) 证明: ()x x f ln >.说明:请在22、23题中任选一题做答,写清题号.如果多做,则按所做第一题记分. 22.(10分)已知曲线的参数方程是( 是参数),以坐标原 点为极点, 轴的正半轴为极轴建立极坐标系,曲线 的极坐标方程是.(1)写出 的极坐标方程和 的直角坐标方程;(2)已知点 ,的极坐标分别为和 ,直线 与曲线相交于两点 ,,射线与曲线 相交于点,射线与曲线相交于点 ,求的值.23.(10分)已知函数,.(1)当 时,解不等式 ;(2)若存在满足,求 的取值范围.高三数学(理) 第11页(共28页) 高三数学(理) 第12页(共28页)数学答案(理)选择题DCCDA C A D B C A B 填空题13.(],1-∞-14.34- 15.416.1217. 1.【答案】(1)答案见解析;(2)11525443n n n T -+=-⋅.(2)()1413n n n n n b a +=-⋅⋅,341n n a =-113n n n b -+=12n n T b b b =+++ ∴01212313333n n n n n T --+=++++①121123133333n n n n n T -+=++++② ①-②得12121111233333n n n n T -+=++++-111311313nn n -+=+--53112233n n n +=-⋅-∴11525443n n n T -+=-⋅.18.(1)见解析;(2)12λ=±.高三数学(理) 第15页(共28页) 高三数学(理) 第16页(共28页)(2)设平面EFPQ 的一个法向量为(),,n x y z =,则由0{0FE n FP n ⋅=⋅=,得0{0.x y x z λ+=-+=,于是可取(),,1n λλ=-.设平面M N P Q 的一个法向量为()',','m x y z =,由0{N M m N P m ⋅=⋅=,得()''0{'2'0x y x z λ+=-+-=,于是可取()2,2,1m λλ=--. 若存在λ,使面EFPQ 与面P Q M N 所成的二面角为直二面角,则()()2,2,1,,10m n λλλλ⋅=--⋅-=,即()()2210λλλλ---+=,解得12λ=±,显然满足02λ<<.故存在12λ=±,使面EFPQ 与面PQMN 所成的二面角为直二面角.19.解:(1)由频率分布直方图可知,抽取的1 000名市民年龄的平均数x -=25×0.05+35×0.1+45×0.2+55×0.3+65×0.25+75×0.1=54(岁).设1 000名市民年龄的中位数为x ,则0.05+0.1+0.2+0.03×(x -50)=0.5,解得x =55,所以这1 000名市民年龄的平均数为54,中位数为55.(2)由频率分布直方图可知,这1 000名市民中年龄在[20,40)的市民共有(0.05+0.10)×1 000=150人,所以关注智能办公的频率为100150=23, 则从该市年龄在[20,40)的市民中随机抽取300人,这300人中关注智能办公的人数为300×23=200.故估计这300人中关注智能办公的人数为200.(3)设在抽取的20名市民中,年龄在[60,80]的人数为X ,X 服从二项分布, 由频率分布直方图可知,年龄在[60,80]的频率为(0.025+0.010)×10=0.35,所以X ~B (20,0.35),所以P (X =k )=C k 200.35k (1-0.35)20-k ,k =0,1,2, (20)设t =P X =k P X =k -=C k 200.35k 0.6520-kC k -1200.35k -10.6521-k =-k 13k,k =1,2, (20)若t >1,则k <7.35,P (X =k -1)<P (X =k ); 若t <1,则k >7.35,P (X =k -1)>P (X =k ). 所以当k =7时,P (X =k )最大, 即当P (X =k )最大时,k 的值为7.20.解:(1)设(,)C x y ,则依题意得34AC BC k k ⋅=-,又(2,0)A -,(2,0)B ,所以有 3(0)224y y y x x ⋅=-≠+-, 整理得221(0)43x y y +=≠,即为所求轨迹方程. ┄┄┄┄┄┄5分高三数学(理) 第19页(共28页) 高三数学(理) 第20页(共28页)(2)设直线l :y kx m =+,与223412x y +=联立得2234()12x kx m ++=,即222(34)84120k x kmx m +++-=,依题意222(8)4(34)(412)0km k m ∆=-+-=,即2234k m +=, ┄┄┄┄┄┄8分∴122834km x x k -+=+,得122434kmx x k -==+, ∴2243(,)3434km m P k k -++,而2234k m +=,得43(,)k P m m-,又(4,4)Q k m +, ┄┄┄┄┄┄10分 又(1,0)F ,则43(1,)(3,4)0k FP FQ k m m m⋅=--⋅+=.知FP FQ ⊥, 即90PFQ ∠=.21.(1)解:()()a x e x x f x+++='21,由题意有()()⎪⎩⎪⎨⎧-===+='230210b f a f ,解得23,1-==b a ┄┄┄┄┄┄4分 (2)证明:(方法一)由(1)知,()232-++=x x xe x f x.设()x x x xe x h x ln 2-++= 则只需证明()23>x h ()()x x e x x h x 1121-+++='()⎪⎭⎫ ⎝⎛-++=x e x x 121,设()x e x g x 12-+=则()012>+='x e x g x ,()x g ∴在()+∞,0上单调递增 0424141<-+=⎪⎭⎫ ⎝⎛e g ,0323131>-+=⎪⎭⎫⎝⎛e g⎪⎭⎫⎝⎛∈∃∴31,410x ,使得0x 001g (x )e 20x =+-= ┄┄┄┄┄┄7分且当()0,0x x ∈时,()0<x g ,当()+∞∈,0x x 时,()0>x g∴当()0,0x x ∈时,()0<'x h ,()x h 单调递减当()+∞∈,0x x 时,()0>'x h ,()x h 单调递增 ┄┄┄┄┄┄8分()()==∴0min x h x h 0020ln 0x x x e x x -++,由01200=-+x e x ,得210-=x e x , ()+⎪⎪⎭⎫ ⎝⎛-=∴21000x x x h 0020ln x x x -+0020ln 1x x x -+-=, ┄┄┄┄┄┄10分设()x x x x ln 12-+-=ϕ,⎪⎭⎫ ⎝⎛∈31,41x ,()x x x 112--='ϕ()()xx x 112-+= ∴当⎪⎭⎫ ⎝⎛∈31,41x 时,()0<'x ϕ,()x ϕ在⎪⎭⎫⎝⎛31,41单调递减,∴()()>=00x x h ϕ23131⎪⎭⎫ ⎝⎛=⎪⎭⎫ ⎝⎛ϕ⎪⎭⎫ ⎝⎛-+-31ln 131233ln 97>+=,因此()23>x h ┄┄┄┄┄┄12分(方法二)先证当0≥x 时,()232-++=x x xe x f x232-≥x ,即证02≥-+x x xe x设()x x xe x g x-+=2,0≥x 则()()121-++='x e x x g x,且()00='g()()022>++='x e x x g ,()x g '∴在[)+∞,0单调递增,()()00='≥'g x g ()x g '∴在[)+∞,0单调递增,则当0≥x 时,()()002=≥-+=g x x xe x g x┄┄┄┄┄┄8分(也可直接分析232232-≥-++x x x xe x⇔02≥-+x x xe x ⇔01≥-+x e x 显然成立) 再证x x ln 232≥-设()x x x h ln 232--=,则()x x x x h 1212-=-=',令()0='x h ,得21=x高三数学(理) 第23页(共28页) 高三数学(理) 第24页(共28页)且当⎪⎭⎫ ⎝⎛∈21,0x 时,()0<'x h ,()x h 单调递减;当⎪⎭⎫ ⎝⎛+∞∈,21x 时,()0>'x h ,()x h 单调递增.∴()x x x h ln 232--=02ln 2121>+-=⎪⎭⎫⎝⎛≥h ,即x x ln 232>-又()232232-≥-++=x x x xe x f x,()x x f ln >∴┄┄┄┄┄┄12分 法三:要证不等式等价于xln x 3e x 1x 2x++>+ 令xF (x)e x 1=++,ln x 3G (x)x 2x=+,分别求最值. 22.(1)由题得曲线的普通方程为,化成极坐标方程为.曲线 的直角坐标方程为.(2) 易知在直角坐标系下,,,则线段 是圆 的一条直径,所以,由,得.由于, 是椭圆上的两点,在极坐标下,设 ,.分别代入中,得所以即所以23(1)当时,,由得.当时,不等式等价于,解得,所以;当时,不等式等价于,即,所以此时不等式无解;当时,不等式等价于,解得,所以.所以原不等式的解集为.(2)因为原命题等价于,所以,所以为所求实数的取值范围.高三数学(理) 第27页(共28页) 高三数学(理) 第28页(共28页)。
密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018—2019学年度第二学期阶段性检测高 一 化 学(理)时间:2019.04.02相对原子质量: H 1 C 12 N 14 O 16 S 32 Mg 24 Ca 40一、选择题(每小题只有一项符合题意,1-10题每小题2分,11-20题每小题3分,共50分)1.据报道,科学家最近发现了一种新的粒子,这种粒子由3个1H 原子核和2个电子构成。
下列关于这种粒子的说法中,正确的是( ) A .它是氢的一种新同位素 B .这种新元素的核电荷数是3 C .它是H 2的一种新同素异形体D .它比一个普通氢分子多一个氢原子核2.右图为元素周期表中元素X 的信息。
下列关于X 的说法正确的是( ) A . 属于过渡元素 B . 质量数为74.92 C . 处于第4周期第IIIA 族 D . 非金属性比氮弱 3.下列叙述中错误的是( ) A .酸性:HClO 4>H 3PO 4>H 2SiO 3 B .还原性:Na >Mg >Al C .稳定性:HF >HCl >HBr D .原子半径:Cl >S >O 4.下列说法正确的是( ) A .乙烯分子的电子式为B .甲烷分子的球棍模型为C .用电子式表示Na 2O 的形成过程为D .含6个质子和8个中子的碳元素的核素符号:12C 5.下列物质中,含有非极性键的共价化合物是( )A .N 2B .Na 2O 2C .CO 2D .CH 3CH 36.下列关于卤族元素由上到下性质递变的叙述,正确的是( )①单质的氧化性增强 ②单质的颜色加深 ③气态氢化物的稳定性增强 ④单质的沸点升高 ⑤简单阴离子的还原性增强A .①②③B .②③④C .②④⑤D .①③⑤ 7.下列叙述正确的是( )A .共价键只存在于共价化合物中B .碳酸氢铵是典型离子化合物,其受热分解过程中,不仅破坏离子键还破坏了共价键C .ⅠA 族与ⅦA 族元素间只能形成离子化合物D .共价化合物中各原子最外层都一定满足8电子结构8.某元素X 最高价氧化物对应的水化物的化学式为H n XO 2n-2,则在其气态氢化物中X 元素的化合价为( )A .3n-10B .3n-12C .12-3nD .3n-4 9.能证明乙烯分子中含有一个碳碳双键的事实是( ) A .乙烯分子中碳、氢原子的个数比为1∶2B .乙烯完全燃烧生成的CO 2和H 2O 的物质的量相等C .乙烯易与溴水发生加成反应,且1 mol 乙烯完全加成需消耗1 mol 溴单质D .乙烯能使酸性KMnO 4溶液褪色11.下列说法错误的是( )A .烷烃的通式为C n H 2n +2,随n 的增大,碳元素的质量分数逐渐增大B .1 mol CH 2==CH 2先与HCl 发生加成反应,再与Cl 2发生取代反应,最多消耗Cl 2 5 molC .相同质量的乙烯和甲烷完全燃烧后生成水的质量相同D .乙烯的化学性质比乙烷的化学性质活泼12.A 、B 分别为第三、四周期同一主族的不同元素的原子,它们原子核内的质子数等于中子数。
太原五中 2018— 2019 学年度第二学期阶段性检测高 三 数学(文)一、选择题 (本大题共 12 小题,每题 5 分,共 60 分,每题有且只有一个正确选项 )1.已知会合 A 2, 1,0,1,2 , B{ x | x 2 4} ,则以下图中暗影部分所表示的会合为()A. 2, 1,0,1B. 0C.1,0D.1,0,12.下边对于复数z2 的四个命题:1 ip 1 : z 2p 2 : z 的共轭复数 z 在复平面内对应的点的坐标为 1, 1p 3 : z 的虚部为 -1p 4 : z 22i此中的真命题是( )A. p 2 , p 3B. p 1 , p 2C. p 2 , p 4D. p 3, p 43.阅读以下图的程序框图,若输入的k 9 ,则该算法的功能是( )A. 计算数列 2n 1 的前 10 项和B. 计算数列2n 1 的前 9 项和 C. 计算数列 2n 1D. 计算数列2n 1的前 10 项和 的前 9项和4.若新高考方案正式实行,甲、乙两名同学要从政治、历史、物理、化学四门功课中分别选用两门功课学习,则他们选择的两门功课都不同样的概率为( )A.1 1 C.1 D.2 B.32365.已知点 ( m,8) 在幂函数 f (x) (m 1) x n的图象上,设 a f ( 3) , bf (ln ) ,3cf (2),则a 、b 、c 的大小关系为()2A . ac bB . ab cC . bcaD .ba c6.如图,网格纸上小正方形的边长为1,粗线画出的是某三棱锥的三视图,则该三棱锥的外接球的表面积是()A. 25B.254C.29D.294x y 37.若变量 x , y 知足拘束条件x y1,且 z ax 3 y 最小值为 7,2xy 3则 a 的值为( )A. 1B. 2C.-2D.-18.已知函数 f ( x)ln x ln( 2x) ,则()A. f (x) 在 ( 0,2) 单一递加B. f ( x) 在 (0,2) 单一递减C. yf ( x) 的图像对于直线x1对称D. y f ( x) 的图象对于点 (1,0) 对称9.函数 f ( x) (2 1)cos x 图象的大概形状是()e x1A .B .C .D .x 2 y 2 1( a0, b0) 上存在一点 P 知足以 OP 为边长的正方形的面10.若双曲线b 2a 2积等于 2ab (此中 O 为坐标原点),则双曲线的离心率的取值范围是( )A. (1, 5]B. (1,7 ] C.[5, )D. [7, )222211.已知函数 fxAsinx( A 0,0,) 的2象如 所示,令g x fx f ' x ,以下对于函数 g x 的 法中不正确的选项是()A.函数 g x象的 称 方程 xk12 k ZB. 函数 g x 的最大 2 2C. 函数 g x 的 象上存在点 P ,使得在 P 点 的切 与直l : y 3x 1平行D. 方程 gx2 的两个不一样的解分x 1 , x 2, x 1 x 2 最小212.已知函数 f (x)(2a)( x 1)2 ln x ,若函数 f ( x) 在 (0, 1) 上无零点, ()2A.a [2 4 ln 2,) B. a (2 4 ln 2, ) C. a[1 2 ln 2,)D.a(1 2 ln 2,)二、填空 (本大 共 4 小 ,每小 5 分,共 20 分,把答案填在 中的横 上 )13.已知 e 1、 e 2 是相互垂直的 位向量,若e 1- 3e 2 与 e 1+ λe 2 角 30o ,λ的.14.埃及数学家 了一个独到 象:除2用一个 独的符号表示之外,其余形如23n ( n =5,2117, 9,⋯ ) 的分数都可写成若干个 分数(分子1 的分数 )和的形式,比如 5= 3+15.我 能够理解:假设有2 个面包,要均匀分5 人,假如每人得 1,不 分,每人得1,余1,再将1分2333成 5 份,每人得111 215, 每人分得 3+15.故我 能够得出形如n (n = 5, 7, 9,11,⋯ )的分数的分解: 2=1+ 1 ,2= 1+ 1 ,2= 1+ 1,⋯,按此 律2= ________.53 15 74 28 95 451115.若 的内切球和外接球的球心重合,且内切球的半径1,的体.16.各 均 正数的数列a n 和b n 足: a n , b n , a n 1 成等差数列, b n , a n 1 , b n 1成等比数列,且 a 11, a 2 3, 数列 a n 的通 公式 __________ .三、解答题(本大题 5 小题,共60 分,解答应写出文字说明、证明过程或演算步骤)17.( 12 分)如图,在ABC 中,内角 A ,B , C 的对边分别为 a ,b, c ,已知 c 且 BD 4 , bCD ,2 , 2ccosC b , D , E 分别为线段BAE CAE .BC 上的点,(1)求线段AD的长;(2)求ADE的面积.18.(12 分)在四棱锥P ABCD中,底面ABCD为平行四边形,AB3, AD 2 2 ,ABC45 , P 点在底面 ABCD 内的射影 E 在线段 AB 上,且 PE2, BE 2EA, M 在线段 CD 上,且CM 2CD .3( 1)证明:CE平面PAB;( 2)在线段AD上确立一点F,使平面PMF平面 PAB ,并求三棱锥 P AFM 的体积.19.( 12 分)某城市为鼓舞人们绿色出行,乘坐地铁,地铁企业决定依照乘客经过地铁站的数目实行分段优惠政策,不超出9 站的地铁票价以下表:乘坐站数 x0 x3 3 x 6 6 x9票价(元)123现有甲、乙两位乘客同时从起点乘坐同一辆地铁,已知他们乘坐地铁都不超出9 站,且他们各自在每个站下车的可能性是同样的.(1)若甲、乙两人共付费2元,则甲、乙下车方案共有多少种?(2)若甲、乙两人共付费4元,求甲比乙先抵达目的地的概率.20.( 12 分)已知抛物线 y 24x ,直线 l : y1 x b 与抛物线交于 A , B 两点.2( 1)若以 AB 为直径的圆与 x 轴相切,求该圆的方程;( 2)若直线 l 与 y 轴负半轴订交,求AOB ( O 为坐标原点 )面积的最大值.21.( 12 分)已知函数 f (x) x 2 (ln xln a)(a 0) .( 1)当 a1 时,设函数 g( x)f ( x),求函数 g( x) 的单一区间和极值;x( 2)设 f ( x) 是 f ( x) 的导函数,若f (x)1 对随意的 x0恒成立,求 a 的取值范围;x2( 3)若 x 1 , x 2 (1,1) , x 1x 2 1,求证: x 1 x 2 ( x 1 x 2 ) 4 .e说明:请在 22、 23 题中任选一题做答,写清题号.假如多做,则按所做第一题记分.22.( 10 分)选修 4-4:坐标系与参数方程在直角坐标系 xOy 中,曲线 M 的参数方程为x sincosy( 为参数),sin 2若以该直角坐标系的原点 O 为极点, x 轴的正半轴为极轴成立极坐标系,曲线 N 的极坐标方程为:sin2t (此中 t 为常数) .42( 1)若曲线 N 与曲线 M 有两个不一样的公共点,求t 的取值范围;( 2)当 t2 时,求曲线 M 上的点与曲线 N 上点的最小距离 .23.( 10 分)选修 4-5:不等式选讲设函数 f (x)2x a 2a .( 1)若不等式 f ( x)6 的解集为 x 6 x 4 ,务实数 a 的值;( 2)在( 1)的条件下,若不等式f ( x) (k 2 1)x 5 的解集非空,务实数 k 的取值范围 .答案1.已知会合A2, 1,0,1,2 , B { x | x24} ,则以下图中暗影部分所表示的会合为()A.2, 1,0,1B.0C.1,0D.1,0,1【答案】 D【分析】求解二次不等式可得:B x | x 2或x2,则e R B x | 2 x 2 ,由 Venn 图可知图中暗影部分为:A e R B1,0,1.此题选择 D 选项.2.下边对于复数2的四个命题:z1ip1 : z2p2 : z的共轭复数 z 在复平面内对应的点的坐标为1,1 p3 : z 的虚部为-1p4 : z22i此中的真命题是()A. p2, p3B. p1, p2C. p2, p4D. p3, p4【答案】 C【分析】由题意可得:z22 1 i 2 2i,则:1 i 1 i1i1 i2z1212 2 ,命题p1为假命题;z 1 i ,其在复平面内对应的点的坐标为1,1命题 p2为真命题;z 的虚部为1,命题 p3为假命题;z21i 22i i 22i ,命题 p4为真命题;1上可得:真命 是p 2 , p 4 .本 C.3. 如 所示的程序框 ,若 入的k 9 , 算法的功能是()A. 算数列 2n 1的前 10 和 B. 算数列 2n 1的前 9 和C. 算数列 2n1 的前 10 和D. 算数列2n 1 的前 9 和【答案】 B【分析】框 第一 累加 量S 和循 量 i ,S=0, i=1 ;判断 i > 9 不行立, 行 S=1+2× 0=1 ,i=1+1=2 ;判断 i > 9 不行立, 行 S=1+2× 1=1+2, i=2+1=3 ;判断 i > 9 不行立, 行 S=1+2×( 1+2) =1+2+2 2, i=3+1=4 ;⋯判断 i > 9 不行立, 行 S=1+2+2 2+⋯ +2 8, i=9+1=10 ;28判断 i > 9 成立, 出S=1+2+2 +⋯ +2 .故 : B4.若新高考方案正式 施,甲、乙两名同学要从政治、 史、物理、化学四 功 中分 取两 功学 , 他 的两 功 都不同样的概率 ()A.1 1 1 D.2 B.3C.362答案: A5.已知点 ( m,8) 在 函数 f (x)(m1) x n 的 象上, a f ( 3) , bf (ln ) ,3c f (2),则a 、b、 c 的大小关系为(A)2A .a c b B.a b c C.b c a D.b a c答案: A6.如图,网格纸上小正方形的边长为1,粗线画出的是某三棱锥的三视图,则该三棱锥的外接球的表面积是A. B. C. D.【答案】 D【分析】由已知中的三视图可得:该几何体是一个以俯视图为底面的三棱锥,其外接球相当于以俯视图为底面侧棱长为 1 的直三棱柱的外接球,再由正弦定理易得底面三角形的外接圆半径,球心究竟面的距离,故球半径,故球的表面积,应选 D.x y37.若变量x,y知足拘束条件x y1,且z ax 3 y 的最小值为7,则a的值为()2x y3A.1B.2C. 2D. -17.【答案】 B【分析】作出不等式组对应的平面地区如图:由{xy1得: A4,5 ;由{x y3得:B 2,1;由{xy1得 C 1,2,2x y32x y3x y3由 z ax 3 y ,得 y a x z,则直线的截距最小,z 也最小,33∵目标函数 z ax 3 y 的最小值为7,8.已知函数f ( x)ln x ln( 2x) ,则()A. f (x)在(0,2)单一递加B. f ( x)在(0,2)单一递减C. y f ( x) 的图像对于直线x1 对称D. y f ( x)的图象对于点(1,0) 对称8.答案: C分析:由题意知 ,,因此的图象对于直线对称,C正确 ,D 错误;又,在上单一递加 ,在上单一递减 ,A,B 错误 ,应选 C.9.21)cos x图象的大概形状是 ()函数 f ( x) (1 e x1exx1 ,则 f (1)【分析】 f ( x)x cos x ,f (x) 为奇函数,令0,选 B .1ex2y 21( a0, b0)上存在一点 P 知足以 OP 为边长的正方形的面10.若双曲线b2a 2积等于 2ab (此中 O 为坐标原点),则双曲线的离心率的取值范围是()A. (1,5] B. (1,7 ] C. [ 5 ,) D. [7 ,) 2222答案 C分析此题主要考察圆锥曲线。
密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018—2019学年度第二学期阶段性检测高 二 物 理(理)出题人:齐丽虹 校对人:吴柴乐 时间:2019.5一、选择题(本题包含12小题,其中1—8小题为单选,9—12小题为多选,每小题4分,共48分)1.黑体辐射的强度与波长关系如图所示,由图可知下列说法错误的...是( ) A. 黑体辐射的强度随着温度的升高,各种波长的辐射强度都增加 B. 随着温度的升高,辐射强度的极大值向着波长较短的方向移动 C. 任何温度下,黑体都会辐射各种波长的电磁波D. 不同温度下,黑体只会辐射相对应的某些波长的电磁波2.根据爱因斯坦的“光子说”可知( )A. “光子说”本质就是牛顿的“微粒说”B.光的波长越大,光子的能量越小C.一束单色光的能量可以连续变化D.只有光子数很多时,光才具有粒子性3.关于光的波粒二象性下列说法正确的是( ) A.光子说完全否定了波动说 B.光波频率越高,波动性越明显C.个别光子易表现出粒子性,大量光子易表现出波动性D.光的波粒二象性是指光和经典的波和微粒都很相似4.现用电子显微镜观测线度为d 的某生物大分子的结构。
为满足测量要求,将显微镜工作时电子的德布罗意波长设定为1,>n nd其中。
已知普朗克常量h 、电子质量m 和电子电荷量e ,电子的初速度不计,则显微镜工作时电子的加速电压应为( )A .222med h n B .313222)(en h mdC .2222men h d D .2222medh n 5. 下列能揭示原子具有核式结构的实验是( )A. 光电效应实验B. 康普顿效应实验C. α粒子散射实验D. 氢原子光谱的发现 6.关于经典电磁理论与氢原子光谱之间的关系,下列说法正确的是( ) A.经典电磁理论很容易解释原子的稳定性B.据经典电磁理论,电子绕原子核转动时,电子会不断释放能量,最后被吸附到原子核上C.根据经典电磁理论,原子光谱应该是不连续的D.氢原子光谱彻底否定了经典电磁理论7.“约瑟夫森结”由超导体和绝缘体制成.若在结两端加恒定电压U ,则它会辐射频率为v 的电磁波,且v 与U 成正比,即v=kU 。
密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018—2019学年度第二学期阶段性检测高 一 理 科 综 合(文)出题人:秦伟、吕宏斌、程婷 校对人:周子琦、吕宏斌、程婷 时间:2019.4.3一、选择题(1-20题每题1分;21-38题每题3分,共74分。
)1.孟德尔运用假说-演绎法总结出了遗传学的两大规律,以下说法中属于假说的是①F1代全部显现高茎 ②生物性状是由遗传因子决定的 ③F2代既有高茎又有矮茎,性状分离比接近3:1 ④体细胞中遗传因子成对存在 ⑤受精时,雌雄配子随机结合A .①③B .②④⑤C .①②③ D.①②③④⑤ 2.下列性状中属于相对性状的是A.人的身高与体重B.兔的长毛与短毛C.猫的白毛与蓝眼D.棉花的细绒与长绒3.大豆的白花和紫花为一对相对性状。
下列杂交实验中,能判定性状显隐性关系的是①紫花×紫花→紫花 ②紫花×紫花→301紫花+110白花 ③紫花×白花→紫花 ④紫花×白花→98紫花+107白花 A .①和③ B .②和③ C .③和④ D .④和①4.为鉴定一株高茎豌豆和一只黑色豚鼠的纯合与否,应采取的简便遗传方法分别是 A.杂交、杂交 B.杂交、测交 C.自交、自交 D.自交、测交5. 已知水稻高秆(T )对矮秆(t )为显性,抗病(R )对感病(r )为显性,这两对基因在非同源染色体上。
现将一株表现型为高秆、抗病的植株的花粉授给另一株表现型相同的植株,所得后代表现型是高秆∶矮秆=3∶1,抗病∶感病=3∶1。
根据以上实验结果,判断下列叙述错误的是:A.以上后代群体的表现型有4种B.以上后代群体的基因型有9种C.以上两株亲本可以分别通过不同杂交组合获得D.以上两株表现型相同的亲本,基因型不相同 6.下列说法正确的是A .表现型相同的生物,基因型一定相同B .D 和D ,D 和d ,d 和d 都是等位基因C .隐性性状是指生物体不能表现出来的性状D .杂合子一般表现出显性性状7.基因型为AAbbCC 与aaBBcc 的小麦进行杂交,这三对等位基因分别位于非同源染色体上,F 1杂种形成的配子种类数和F 2的基因型种类数分别是A .4和9B .4和27C .8和27D .32和818.下表为3个不同小麦杂交组合及其子代的表现型和植株数目。
2018-2019学年山西省太原市第五中学高一下学期阶段性检测(5月)政治(文)第I卷一、选择题(每小题四个选项中只有一个正确选项,每小题2分,共48分)1. 2019年是实现第一个百年奋斗目标的关键之年,脱贫攻坚也进入到最后的冲刺阶段,将有更多的贫困人口实现脱贫,人民群众有更多更实在的获得感、幸福感、安全感。
让人民群众有更多获得感、幸福感、安全感的根本原因是A.人民民主是最真实的、最管用的民主B.我国是人民民主专政的社会主义国家C.我国公民依法享有更广泛的民主权利D.民主具有鲜明阶级性,人民当家作主2.2018年1月,党中央、国务院决定在全国开展扫黑除恶专项斗争。
聚焦涉黑涉恶问题突出的重点地区、重点行业、重点领域,把打击锋芒始终对准群众反映最强烈、最深恶痛绝的各类黑恶势力违法犯罪,始终保持对各类黑恶势力违法犯罪的严打高压态势。
由此可见①在新时代,打击黑恶势力是现代化建设的根本保证②民主与专政是相辅相成的,专政是民主的基础③政府依法打击违法犯罪行为,切实履行政治职能④只有坚持人民民主专政,才能营造和谐稳定的社会环境A.①② B.①③ C.②④ D.③④3.近年来,我国民主政治建设取得巨大进步。
下列对公民参与政治生活和行使的民主权利的分析,对应不正确的是①作为选民参加直接选举人大代表的活动——公民行使基本的民主权利②对小区物业管理问题提出批评和建议——公民自觉地参与民主决策③找人大代表反映政府食品安全监管不力问题——公民主动参与基层民主管理④参加某区政府举行的民主评议活动——公民对政府工作进行民主监督A.①③ B.①④ C.②③ D.③④4.为培养学生的社会责任感,某地开展面向中小学生的“雏鹰建言行动”。
几年来,学生围绕“环境保护”“中医药文化”等20多个主题开展探究,形成5万余条建言,不少被人大代表、政协委员纳入提案带上两会,交政府相关部门办理。
“雏鹰建言行动”①为政府进行科学决策提供了更丰富的信息资源②是中小学生有序参与社会政治生活的具体表现③是中小学生通过人大代表联系群众制度来参与民主决策④扩大了中小学生的政治权利,利于意见表达和集中民智A.①② B.①③ C.②③ D.③④5.在中国社会主义制度下,有事好商量,众人的事情由众人商量,找到全社会意愿和要求的最大公约数,是人民民主的真谛。
高二物理 第1页,共6页 高二物理 第2页,共6页密学校 班级姓名 学号密 封 线 内 不 得 答 题太原五中2018-2019学年度第二学期阶段性检测高 二 物 理(理)出题、校对:严逸璊、于佳欢 (2019.4)一、选择题(本大题共12个小题,每小题4分,共48分。
其中1-8题只有一个选项符合题意,9-12题有多个选项符合题意,全选对的给4分,选对选不全的给2分,有错选的不给分,请将正确选项填写到答题纸的相应位置) 1.下列说法正确的是A.通电线圈在磁场中转动的现象是电流的磁效应B.感应电流的磁场总是与引起感应电流的磁场方向相反C.线圈放在磁场越强的位置,线圈中产生的感应电动势一定越大D.只要磁场变化,即使没有电路,在空间也将产生感生电场2.如图所示的情况中,金属导体中产生的感应电动势不是Blv 的是A B C D3.如图甲所示,线圈的匝数n =200匝,横截面积S =50 cm 2,线圈总电阻r =10 Ω,沿轴向有匀强磁场,磁场的磁感应强度随时间按如图乙所示规律变化,则 A.若在a 、b 间接一个理想电流表时,第0.4 s 末电流表的示数为0.4 AB.若在a 、b 间接一个理想电流表时,第0.2 s 末和0.6 s 末的电流方向相同C.第1 s 末a 、b 间电压为零D.第0.9 s 末a 、b 间电压比0.2 s 末的小4.光滑曲面与竖直平面的交线是抛物线,如图所示,抛物线的方程为y =x 2,其下半部处在一个水平方向的匀强磁场中,磁场的上边界是y =2m 的直线(如图中的虚线所示)。
一个质量为1kg 的小金属块从抛物线上y =4m 处以速度v=2m/s 沿抛物线下滑,假设曲面足够长,重力加速度g 取10m/s 2,则金属块在曲面上滑动的过程中产生的焦耳热总量为 A.20J B.18J C.22J D.42J5.电磁灶热效率高达90%,炉面无明火,无烟无废气,电磁“火力”强劲,安全可靠.如图所示是描述电磁灶工作原理的示意图,下列说法正确的是A.电磁灶通电线圈加恒定电流仍可正常使用,且电流越大,电磁灶加热效果越好B.电磁灶通电线圈加交流电后,在锅底产生涡流,进而发热工作C.电磁灶的锅不能用陶瓷锅或耐热玻璃锅,主要原因是这些材料的导热性能较差D.在盛有水的锅和电磁灶中间放一纸板,则水无法烧开6.如图所示,虚线两侧有垂直线框平面磁感应强度均为B 的匀强磁场,半径为L 、总电阻为R 的直角扇形导线框OAC 绕垂直于线框平面轴O 以角速度ω匀速转动。
太原五中2018—2019学年度第二学期阶段性检测高三英语(考试时间:120分钟试卷满分:150分)第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第二部分阅读理解(共两节,满分60分)第一节(共15小题;每小题3分,满分45分)阅读下面短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AIt is commonly believed that in medieval France, New Year was celebrated on 1 April. Then in 1562, Pope Gregory introduced a new calendar for the Christian world, changing New Year to 1 January. With no modern communications, news travelled slowly and new ideas were often questioned. Many people did not hear of the change, some merely forgot, and others chose to ignore it. These people were called fools. Invitations to non-existent “New Year” parties were sent and other practical jokes were played. Over time playing tricks on 1 April became a tradition. The custom eventually spread to England and Scotland, and it was later transported across the Atlantic to the American colonies (殖民地) of the English and the French. April Fools’ Day has now developed into an international festival of fun, with differ ent nationalities celebrating the day in special ways.France and ItalyIn France and Italy, if someone plays a trick on you, you are the “fish of April”. By the month of April fish have only just hatched and are therefore easy to catch. Children stick pap er fish to their Friends’ backs and chocolate fish are found in the shops.America and BritainToday, Americans and the British play small tricks on friends and strangers alike on 1 April. A common trick is to point to a friend’s shoe and say “Your shoelac e(鞋带) is untied.” When they lookdown, they are laughed at. Schoolchildren might tell a friend that school has been cancelled. Sometimes the media get involved. Once, a British short film was shown on April Fools’ Day about spaghetti farmers and how they harvest their crop from spaghetti trees!ScotlandIn Scotland, April Fools’ Day lasts for two days! The second day is called “Taily Day” and tricks on this day involve the bottom (or the “tail”, in informal speech). Often a sign saying ‘kick me’ is stuck o nto someone’s back without them knowing.21. In what condition would someone be called “fish of April” in France?A. When one is fooled.B. If one is fond of fish.C. When one fools others.D. If one prefers chocolate.22. What was the purpose of the British short film?A. To help the audience.B. To trick the audience.C. To warn the audience.D. To inform the audience.23. Where does April Fools’ Day last for more than one day?A. Italy.B. France.C. America.D. Scotland.BI have never been a fan of the phrase, “No pains, no gains.” I prefer the alternative version, “No pains, no pains!” When it comes to exercise, for example, I learned years ago that pushing through pain was more likely to lay me up with an aching back than to leave me feeling strong and healthy.But there are times when stressful situations actually do lead to greater happiness. A new study published in the Journal of Happiness Studies found that people who pursue (追求) goals that are tough to achieve feel more stress in the moment, but greater happiness in the aftermath particularly if they feel connected to others along the way.The researchers concluded that happiness increases when people develop greater competence in something and greater competence only comes when people keep on working through the stress-inducing phase of trying, fighting, and trying again to learn and grow. If the psychological needs to be autonomous or self-directed, and to be connected to others are met, the momentary stresses will be less acute, and theresulting happiness will be more lasting.This idea reminds me of another often quoted phrase, which I have heard in reference to challenging tasks, such as exercise —“Fill-in-the-blank-stressful-task is the worst thing to do, but the greatest thing to have done.” In other words, suffering from the stress of an exercise class that leaves us feeling sweat-drenched shouldn’t lead us to walk away from exercising. And if we can pass those stressful moments with a friend, colleague or family member who is trustworthy and supportive, all will be better.As I travel my positive path, I’m certainly not seeking out stress. But life will offer me plenty of it, whether I ask for it or not. My task is to choose wisely when and how to face it head-on, knowing that happiness awaits on the other side.24. What makes the author prefer “No pains, no pains”?A. His terrible fear of pain.B. His deep love of exercise.C. His great desire for health.D. His past experience of pain.25. What results in people’s happiness according to the new study?A. Their tolerance for stress.B. The connection with others.C. Their ability to deal with stress.D. The achievement of their goals.26. What does the author think of challenging tasks?A. They are acute and lasting.B. They are tiring and boring.C. They are stressful but rewarding.D. They are interesting but unhelpful.27. How does the author treat stress in his life?A. Seek it out purposefully.B. Handle it wisely.C. Ask for help bravely.D. Wait until it disappears.CFashions have a lot of rules. Most of them, however, are just wrong. But there’s one rule that goes beyond tradition and into the field of scientific study of the brain: Black garments are slimming. It all comes down to how your visual system processes the light. The below holes in each square are the same in size, yet the white hole looks bigger than the black hole.In the 1500s, Galileo Galilei noticed that some of the planets looked larger when viewed with the naked eye (肉眼) than they did when viewed through a telescope, making the white light of Venus (金星) appear eight to ten times larger than Jupiter (木星) in the night sky. He knew something strange must be going on with his vision to cause this illusion, but he wasn’t sure what it was. Luckily, scientists never stopped wondering, and in 2014, they figured it out.Our visual system operates via two main channels: “on” neurons (神经元) that are sensitive to light things and “off” neurons that are sensitive to dark things. When it came to the dark “off” neurons, the researchers found that they responded predictably to dark shapes on a light background — the greater the contrast between the two, the more active these neurons were. But the light “on” neurons behaved unpredictably. Even with the same amount of contrast, light objects on a dark background caused a greater response in these neurons.Th is makes some sense, evolutionarily speaking. In the dark of night, you’d want to be able to take in every bit of light you can get, so a visual system that enlarges light objects on a dark background could be very useful. However, it’s not that hard to se e dark objects in the light of day. It has some effects in the colors of your clothes and in the appearance of the planets —the brighter appearance of Venus in the night sky makes it look bigger than the darker Jupiter.28. What did Galileo Galilei believe according to Paragraph 2?A. The neurons led to the difference.B. There was something wrong with his telescope.C. The difference was caused by his visual illusion.D. Things were bigger when seen through telescopes.29. What do we know about the “off” neurons?A. They are sensitive to light objects.B. Their behavior can’t be predicted.C. They behave differently from person to person.D. Their activeness improves with the contrast of colors.30. What does the author think of the phenomenon?A. It makes people feel puzzled.B. It brings great harm to people.C. It is more common among youths.D. It is beneficial to people’s evolution.31. What is the text mainly about?A. Why we look thinner when in black.B. What visual illusions bring to people.C. How we are affected by the fashion rules.D. Whether people’s visual system is different.D“No matter where you are or what time it is there’s something going on at a Hard Rock Cafe. All over the world our cafes not only serve great food, but they serve up great music.” Hard Rock Cafes around the world symbolize the timeless energy, originality and unifying(团结的) spirit that have helped to shape rock music over the last century.Founded by two Americans, the first Hard Rock Cafe (HRC) opened its doors to the public on June 14, 1971, in London. Today, HRC has become a global phenomenon with more than 180 cafes in different countries.HRC has also become the world’s leading collector and exhibitor of rock ‘n’ roll memorabilia. It all started when Eric Clapton, a regular at the first HRC, asked the staff if they could hang his guitar on the wall to mark his favourite stool (凳子) as “his spot”. They did and one week later, a package from Pete Townshend arrived with a guitar and a note with the message, “Mine’s as good as his! Love, Pete.”Ever since then, Hard Rock Cafes have been collecting pieces of rock memorabilia and covering their walls with them. Their collection is rotated from restaurant to restaurant and provides the world’s most comprehensive “visual history” of rock ‘n’ roll. These treasures include an awe-inspiring collection of classic guitars and other instruments, posters, music, etc.Throughout its history, HRC has been governed by a special service philosophy: “Love All — Serve All.” Since it was established, HRC has taken part in a wide variety of humane activities around the world.Following its idea of being more than just a restaurant, HRC tries to connect its business and its passion to make the earth a safer, healthier and better place to live.All in all, Hard Rock Cafe International is an entertainment company that continues to successfully expand the Hard Rock brand through countless music-related activities.32. What is the purpose of the first paragraph?A. To explain why HRC is a success.B. To show the characteristics of HRC.C. To describe the excellent service of HRC.D. To introduce what you can share in a HRC.33. Why did Pete send his guitar to the first HRC in London?A. He wanted to occupy a seat.B. He wanted to pay his bill with it.C. He wanted his guitar to be assessed.D. He wanted his guitar to be put on its wall.34. What do we know about the HRC’s collection?A. It is related to rock ‘n’ roll.B. It is housed in the first HRC.C. It was advocated by Eric Clapton.D. It was financed by regular customers.35. What does the HRC’s service philosophy imply?A. HRC welcomes everyone to the cafe.B. HRC is operated for a charitable purpose.C. HRC offers various activities to its customers.D. HRC provides the best service at the lowest price.第二节(共5小题,每小题3分,满分15分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。