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半导体物理与器件英文版第四版课后练习题含答案Chapter 1: Crystal PropertiesMultiple Choice Questions1.Which of the following statements is correct? A. The latticestructure of a crystal can be described by three crystal axes that are normal to each other. B. For a crystal with a primitive cubic unit cell, the coordination number is 8. C. In a crystal lattice with a face-centered cubic (FCC) unit cell, each atom has only six nearest neighbors. D. The Miller indices of a crystal planeperpendicular to the x-axis and passing through point (1, 2, 3) are (1, 2, 3).Answer: A2.Which of the following statements is correct? A. The crystalstructure of diamond is face-centered cubic (FCC). B. The density of silicon is smaller than that of germanium. C. The coordination number of germanium is 4. D. The Miller indices of a crystal plane parallel to the x-axis and passing through point (1, 2, 3) are (1, 0, 0).Answer: DShort Answer Questions1.What is the difference between a lattice and a unit cell?2.Define the concept of coordination number and give anexample of a coordination number 6 crystal structure.3.Define the concept of a crystal plane and expln how Millerindices are used to describe crystal planes.Answers:1.A lattice is an infinitely repeating arrangement of pointsin space that defines the basic symmetry of a crystal, while aunit cell is the smallest repeating unit of a crystal lattice that can be used to reconstruct the entire crystal by translation.2.Coordination number is the number of nearest neighbors of anatom in a crystal lattice. An example of a coordination number 6 crystal structure is the hexagonal close-packed (HCP) structure.3.A crystal plane is an imaginary flat surface in a crystalthat can be used to define the orientation of the crystal in space.Miller indices are a set of integers that describe the orientation of a crystal plane relative to the crystal axes. The Millerindices of a plane are determined by finding the reciprocals of the intercepts of the plane with the crystal axes and thenreducing these reciprocals to the smallest set of integers that give a unique designation of the plane.。
Solutions To The Problems Of Semiconductor〔Part I〕 Solutions To The Problems Of Chapter 1st&3rd〔CEIE of HBU 席砺莼〕1－1．〔P32〕设晶格常数为a的一维晶格，导带极小值附近能量Ec〔k〕和价带极大值附近能量Ev〔k〕分别为：h2k2h2(k−k1)2h2k23h2k2+和Ev(k)= －； Ec(k)=3m0m06m0m0m0为电子惯性质量，k1＝1/2a；a＝0.314nm。
试求：①禁带宽度；②导带底电子有效质量；③价带顶电子有效质量；④价带顶电子跃迁到导带底时准动量的变化。
[解] ①禁带宽度Eg 22(k−k1)22kdEc(k)根据＝＋＝0；可求出对应导带能量极小值Emin的km03m0dk值：kmin＝k1，由题中EC式可得：Emin＝EC(K)|k=kmin=2k1； 4m034由题中EV式可看出，对应价带能量极大值Emax的k值为：kmax＝0；2k122k12h2；∴Eg＝Emin－Emax＝＝并且Emin＝EV(k)|k=kmax＝12m06m048m0a2(6.62×10−27)2＝0.64eV ＝−28−82−1148×9.1×10×(3.14×10)×1.6×10②导带底电子有效质量mn2d2EC222h28232dEC=+=；∴ m=m0 n＝/223m0m03m08dkdk③价带顶电子有效质量m’2d2EV162'2dEV=−，∴==−m/m0 n6m0dk2dk2④准动量的改变量1－2．〔P33〕晶格常数为0.25nm的一维晶格，当外加102V/m，107V/m的电场时，试分别计算电子自能带底运动到能带顶所需的时间。
133h△k＝(kmin-kmax)= k1= [毕] 48aSolutions To The Problems Of Semiconductor〔Part I〕 [解] 设电场强度为E，∵F=h∴t=∫0dt=∫t12a0hdk=qE〔取绝对值〕∴dt=dtqEdk；E＝107V/m时，t＝8.3×1013当E＝102 V/m时，t＝8.3×108〔s〕〔s〕。
