4%石灰土试验段总结
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全新版大学英语综合教程4课后翻译Unit 11. Mr. Doherty and his family are currently engaged in getting the autumn harvest in on the farm.多尔蒂先生和他的家人目前正在农场忙于秋收。
2. We must not underestimate the enemy. They are equipped with the most sophisticatedweapons.我们不能低估敌人,他们装备了最先进的武器。
3. Having been cut of a job/Not having had a job for 3months, Phil is getting increasinglydesperate.菲尔已经三个月没有找到工作了,正在变得越来越绝望。
4. Sam, as the project manager, is decisive, efficient, and accurate in his judgment.作为项目经理,山姆办事果断,工作效率高,且判断准确。
5. Since the chemical plant was identified as the source of solution, the village neighborhoodcommittee decided to close it down at the cost of 100 jobs.既然已经证实这家化工厂是污染源,村委会决定将其关闭,为此损失了一百个工作岗位。
Unit 21.There was an unusual quietness in the air, except for the sound of artillery in the distance.空气有一种不寻常的寂静,只有远处响着大炮的声音。
2. The expansion of urban areas in some African countries has been causing a significant fall inliving standards and an increase in social problems.在某些非洲国家城市的扩展已经引起生活水平相当大的下降和社会问题的增多。
Unit 4. Translation Techniques of Words and Expressions 词法翻译(2)Outline of this unit1. Addition 增词法2. Omission 省词法1. Addition 增词法增补翻译是在原文的基础上,增加一些词语,使译文的语法结构、修辞方式及语言表达符合汉语的行文要求。
要点:增词不增义,增加原文中已省略但汉语表达所需要的词语,不能随心所欲地增加。
增词法的主要类型:语法方面:动词、量词、时态词、名词修辞方面:名词复数、语气词逻辑方面:表示概括性、承上启下、逻辑关联的词语语法方面:动词、量词、时态词、名词上述这些词汇在英语语法中省略了,但在汉语中不可或缺,译文中要增加。
动词:英语动词呈显性;汉语动词在句中是表意的重心,不可少,并且汉语动词不受形态的约束,运用极为灵活,在汉语中备受青睐。
I fell madly in love with her, and she with me.Histories make men wise, poets witty, the mathematics subtle, natural philosophy deep, moral grave, logic and rhetoric able to contend.After the football match, he’s got an important meeting.He dismissed the meeting without a closing speech.练习:I am looking forward to the holidays.We won’t retreat, we never have and never will.Reading makes a full man; conference a ready man; and writing an exact man.The world needn’t be afraid of a possible shortage of coal, oil, natural gas or other sources of fuel for the future.接下来看增加量词的情况。
为了帮助大家高效备考托福,为大家带来托福TPO34口语Task4阅读文本+听力文本+题目+满分范文,希望对大家备考有所帮助。
托福TPO34口语Task4阅读文本: The Familiarity Principle People tend to develop a preference for this they have previously encountered, things they are familiar with. Social psychologists refer to this tendency as the familiarity principle. Given a choice between two similar items, one they have experienced before and another that is new, most people will choose the familiar item. This principle operates even when people are not conscious of their previous experience with an item. Once people have been exposed to an item – even if they do not recall having been exposed to it – they will tend to prefer that item over other items to which they have not been previously exposed. 托福TPO34口语Task4听力文本: Professor:Some researchers did an experiment related to this. What they did was they assembled a group of subjects, a group of students, and they showed these students a series of geometrical shapes. These were very distinctive shapes, a little unusual, not the kind of shapes students often see. But they only showed the students the shapes for a very short period of time, about a second. They also lowered the light in the room to make it even more difficult for the students to see the shapes. So the shapes were there for a split second in dim light and then they were gone.In the next step of the experiment, the researchers again showed the students some shapes, but this time they gave the students a longer time to look at them. And this time they showed the images in pairs, two at a time. In each pair, one shape was a shape the students had already seen for just a split second in dim light. And the other was some other shape that hadn't been shown to them before. After presenting each pair, the researchers asked the students to say which of the two shapes they liked better. Most of the time, the students preferred the shape they’d already seen earlier in the experiment. Now, if you asked them if they’d already seen that shape, they probably wouldn’t know for sure. But that didn’t matter. They still tended to prefer the shapes they’d already seen. 托福TPO34口语Task4题目: Explain how the experiment described by the professor illustrates the familiarity principle. 托福TPO34口语Task4满分范文: Familiarity principle is the tendency that people usually prefer things thatthey're familiar with to new ones, even when they're unconscious of their exposure to the item. And the professor illustrates this with an experiment. In the experiment, a group of students were first shown several geometrical shapes, which were really uncommon, for a very short period of time in dim light so that they hardly perceived the objects consciously. Then the researchers showed the students a pair of shapes, and allowed them longer time to look at those shapes, one of which was the shape they had seen in dim light in a flash, while the other, a new one. After that the researchers asked these groups of students which shape they preferred because of familiarity principle, they tended to prefer the one they had already seen to the one they hadn't seen even though they were uncertain whether they'd seen the shapes. (161 words) 以上是给大家整理的托福TPO34口语Task4阅读文本+听力文本+题目+满分范文,希望对你有所帮助!。
4的数字代表什么意思有什么含义 在中国民间,许多⼈都因“四”与“死”的发⾳相近,⾯对“四”有所忌讳,和西⽅社会对“⼗三”的忌讳是类似的。
那么,你知道4的数字代表什么意思吗?接下来就跟着店铺⼀起去看看数字4的含义吧。
数字4的含义(⼀) 数字4的含义:执⾏数 数字四代表物质的坚固性,也就是物质的组成和建造。
⼀个坚固的物质或实体,是它众多构成体的整体组合,同时它⾃⼰⼜是⼆个新的整体。
绝对的⼀以数字四来定义⾃⼰,因爲他同时是⼀个整体和所有构成体(创造)的组合。
埃及⼈运⽤四个简单的现象(⽕、风、⼟、⽔)来形容构成物质所必需的四元素的作⽤⾓⾊。
⽕是活跃的,凝结的法则;⼟是接收的、格式化的法则,风是细微的、沉思的法则,会影响⼒量的交换;⽔是总和,是⼈、⼟、⽔的组合法则,⽔也是⼀种在它们之上的物质。
数字4总是呈现出苦难的特质,它代表着⽣命中那些让你感觉受限、需要收敛⾃我的⽅⾯。
⾯对种种困难应该采取怎样的解决之道,我们在⾯对逆境的时⼜应当如何规范⾃⼰的⼯作⽣活,都需要极强的组织思维与⾃律性,数字4便是带给我们这样的⼈⽣课题。
数字4的含义(⼆) 关键词:限制、规范、服务 象征符号:四⽅型 属性:计算智商型 对应⾊彩;绿⾊ 五⾏:阴⽕ 星座排⾏:巨蟹 这个数字在形态上就像⼀把三⾓量尺,代表精算,中规中矩,同时每⼀笔都是直挺的,见棱见⾓,象征着死板,不知变通。
四季分春夏秋冬,⽅向分东南西北,物质存在的四元素分为⽕、⽔、风、地,数字4代表了完整的秩序。
数字4的物质平⾯结构就像⼀个正⽅盒⼦,坚固、完善、安全。
数字本质都带有原始的意义,1和2的结合创造了3,当组合成⼀个家庭时,就要靠数字4来稳定⽣存的基本“安全”,4的任务就是实现和显化。
正⾯优势 帮助他⼈,实际,秩序,效率,⾃律,组织⼒,可靠,实⼲,诚恳,有勇⽓,任劳任怨,未⾬绸缪,稳重,做事认真,坚定,忠实,逻辑分明 负⾯挑战 ⼼胸狭隘,情绪紧张,不妥协,过分固执,过于谨慎,约束,拒绝改变,⾃我保护,挑剔,嫉妒⼼,吝啬,⼼胸狭窄,缺乏想象⼒,说教,不变通,⽆趣乏味 恐惧 变化,不稳定,⽣活危机 数字4的含义(三) 起初,⼈们都认为“四”最⼀般的象征含义是四⽅和四时。
模拟人生4常用修改秘籍模拟人生4修改秘籍怎么用2014/9/11 17:23:28来源:pc6游戏网作者:liujie我要评论(0)玩模拟人生4的玩家中总有一批不把人物属性改满就难过的强迫症人群,现在就让小编介绍一些秘籍和修改使用经验。
1、金钱修改不要用motherlode,太累了直接sims.modify_funds 5000000500w直接到位2、人物修改先开启testingcheats true然后cas.fulleditmode再shitf点击人物直接进修改界面就能修改所有人物基因数据了注意cas.fulleditmode后面不要加true (论坛里秘籍那里写的是错的)3、抱负奖励没必要用GM之类的修改,游戏自带的秘籍就行plete_current_milestone马上完成抱负,然后把所有抱负都刷一遍一共能有10w+的点数足够你买光所有特征和药水4、技能点数不建议使用那个多功能补丁,用完了会有人物动作无法停止的bug直接用秘籍把技能全部设置成10级就可以stats.set_skill_levelMajor_Fishing 10 钓鱼stats.set_skill_levelMajor_Mischief 10 恶作剧stats.set_skill_levelMajor_Guitar 10 吉他stats.set_skill_levelMajor_Reaping 10 收割stats.set_skill_levelMajor_Programming 10 程式设计stats.set_skill_levelMajor_Gardening 10 园艺stats.set_skill_levelMajor_GourmetCooking 10 米其林烹饪stats.set_skill_levelMajor_Comedy 10 喜剧stats.set_skill_levelMajor_Charisma 10 魅力stats.set_skill_levelMajor_Writing 10 写作stats.set_skill_levelMajor_VideoGaming 10 电玩游戏stats.set_skill_levelMajor_Violin 10 小提琴stats.set_skill_levelMajor_RocketScience 10 火箭科学stats.set_skill_levelMajor_Painting 10 绘画stats.set_skill_levelMajor_Piano 10 钢琴stats.set_skill_levelMajor_Logic 10 逻辑stats.set_skill_levelMajor_Handiness 10 灵巧stats.set_skill_levelMajor_HomestyleCooking 10 烹饪stats.set_skill_levelMajor_Bartending 10 调酒stats.set_skill_levelSkill_Fitness 10 健身stats.set_skill_levelSkill_Child_Social 10 社交(儿童)stats.set_skill_levelSkill_Child_Motor 10 运动(儿童)stats.set_skill_levelSkill_Child_Creativity 10 创意(儿童)stats.set_skill_levelSkill_Child_Mental 10 心智(儿童)5、职业升级请注意,现在为止职业分支只能2选一,选完了以后就算降级回去还是不能重新选,所以要慎重选择职业建议用随身电话,如果用秘籍会出现同时多职业的bug升职可以用秘籍,一次升一级Careers.promote Culinary 厨艺Careers.promote Painter 画家Careers.promote Writer 写作Careers.promoteSecretAgent特工Careers.promote Criminal 罪犯Careers.promote Astronaut 宇航员Careers.promote Entertain 演员Careers.promoteTechGuru电脑专家儿童少年职业:Careers.promoteGradeschool上小学Careers.promoteHighschool上中学Careers.promote Babysitter 保姆Careers.promote Barista 咖啡调制Careers.promoteRetailEmployee售货员Careers.promoteFastFoodEmployee快餐员工Careers.promoteManualLaborer体力劳动者6、情绪游戏里是玩家获取某种情绪是最麻烦的,需要房间物品配合,这里可以用秘籍直接实现sims.add_buffConfidentHigh自信sims.add_buffEnergizedHigh能量sims.add_buffFlirtyHigh挑逗sims.add_buffe_Buff_Happy快乐sims.add_buffInspiredHigh受启发sims.add_buffFocusedHigh专注sims.add_buffPlayfulHigh爱玩sims.add_buffSadHigh不快sims.add_buffe_Buff_Angry生气7、人际关系成为好友modifyrelationship [现有角色名字] [现有角色姓] [目标角色名字] [目标角色姓] 90 Friendship_Main成为情侣modifyrelationship [现有角色名字] [现有角色姓] [目标角色名字] [目标角色姓] 90 Romance_Main90为可以控制的数字,可以是负数8、一些特殊用途death.toggle false 角色不会死亡fire.toggle false 屋子不会着火sims.spawnsimple随机加一个小人到你家地块,缺朋友的时候最好用sims.hard_reset重置当前模拟市民,出bug时候必用如果想购买所有职业限定物品,家里放2个人,走不同职业的2个分支就可以了,不过主厨套房一直无法解锁,就算主厨10级也不行,可能是个bug。
《使命召唤4:现代战争》全流程全收集图⽂攻略 情报收集1 打开船舱进⼊后,跟着⼩队下楼。
你会在下层舱室看到⼀个醉⿁敌⼈。
就在醉⿁旁边舱室的桌⾯上。
%{p a g e-b r e a k|情报收集1|p a g e-b r e a k}% 情报收集2 船底⼤货仓。
货仓地⾯的栅格⽹上。
%{p a g e-b r e a k|情报收集2|p a g e-b r e a k}% 情报收集3 跟随队友前进时,遇到有敌⼈的路边棚屋。
消灭掉棚屋内的敌⼈。
情报在桌⾯上。
%{p a g e-b r e a k|情报收集3|p a g e-b r e a k}% 情报收集4 灰⽩⾊⽼旧建筑。
进⼊后带上夜视仪,上楼。
楼上房间,马桶旁的桌⼦上。
%{p a g e-b r e a k|情报收集4|p a g e-b r e a k}% 情报收集5 开始时队友在外警戒的临时基地。
下楼进⼊地下室。
地下室⼤厅旁的⼩房间,有3个拳头海报的桌⼦上。
%{p a g e-b r e a k|情报收集5|p a g e-b r e a k}% 情报收集6 巷战,有⽔塔的街道。
前进经过⽔塔后向右转。
⾓落房间⼆楼的桌⼦上。
%{p a g e-b r e a k|情报收集6|p a g e-b r e a k}% 情报收集7 从刚才的房间出去。
向有多个卫星接收器(锅盖)的建筑⽅向⾛。
从蓝⾊的废弃车辆和有3个拳头海报的楼梯⼜上去。
情报就在露台上的桌⼦上。
%{p a g e-b r e a k|情报收集7|p a g e-b r e a k}% 情报收集8 夜视夜战的⼤楼。
⼆楼时会有⼀个等待队友破门⽽⼊的房间。
进去后会看到强光,取下夜视镜就能发现情报。
%{p a g e-b r e a k|情报收集8|p a g e-b r e a k}% 情报收集9 巷战街道,在有⾃⾏车的⾓落右转。
连续右转前进,知道看到有⾹蕉、⽔果箱⼦在前⾯的建筑。
17CHAPTER 4SOLUTIONS TO PROBLEMS4.2 (i) and (iii) generally cause the t statistics not to have a t distribution under H 0.Homoskedasticity is one of the CLM assumptions. An important omitted variable violates Assumption MLR.3. The CLM assumptions contain no mention of the sample correlations among independent variables, except to rule out the case where the correlation is one.4.3 (i) While the standard error on hrsemp has not changed, the magnitude of the coefficient has increased by half. The t statistic on hrsemp has gone from about –1.47 to –2.21, so now the coefficient is statistically less than zero at the 5% level. (From Table G.2 the 5% critical value with 40 df is –1.684. The 1% critical value is –2.423, so the p -value is between .01 and .05.)(ii) If we add and subtract 2βlog(employ ) from the right-hand-side and collect terms, we havelog(scrap ) = 0β + 1βhrsemp + [2βlog(sales) – 2βlog(employ )] + [2βlog(employ ) + 3βlog(employ )] + u = 0β + 1βhrsemp + 2βlog(sales /employ ) + (2β + 3β)log(employ ) + u ,where the second equality follows from the fact that log(sales /employ ) = log(sales ) – log(employ ). Defining 3θ ≡ 2β + 3β gives the result.(iii) No. We are interested in the coefficient on log(employ ), which has a t statistic of .2, which is very small. Therefore, we conclude that the size of the firm, as measured by employees, does not matter, once we control for training and sales per employee (in a logarithmic functional form).(iv) The null hypothesis in the model from part (ii) is H 0:2β = –1. The t statistic is [–.951 – (–1)]/.37 = (1 – .951)/.37 ≈ .132; this is very small, and we fail to reject whether we specify a one- or two-sided alternative.4.4 (i) In columns (2) and (3), the coefficient on profmarg is actually negative, although its t statistic is only about –1. It appears that, once firm sales and market value have been controlled for, profit margin has no effect on CEO salary.(ii) We use column (3), which controls for the most factors affecting salary. The t statistic on log(mktval ) is about 2.05, which is just significant at the 5% level against a two-sided alternative.18(We can use the standard normal critical value, 1.96.) So log(mktval ) is statistically significant. Because the coefficient is an elasticity, a ceteris paribus 10% increase in market value is predicted to increase salary by 1%. This is not a huge effect, but it is not negligible, either.(iii) These variables are individually significant at low significance levels, with t ceoten ≈ 3.11 and t comten ≈ –2.79. Other factors fixed, another year as CEO with the company increases salary by about 1.71%. On the other hand, another year with the company, but not as CEO, lowers salary by about .92%. This second finding at first seems surprising, but could be related to the “superstar” effect: firms that hire CEOs from outside the company often go after a small pool of highly regarded candidates, and salaries of these people are bid up. More non-CEO years with a company makes it less likely the person was hired as an outside superstar.4.7 (i) .412 ± 1.96(.094), or about .228 to .596.(ii) No, because the value .4 is well inside the 95% CI.(iii) Yes, because 1 is well outside the 95% CI.4.8 (i) With df = 706 – 4 = 702, we use the standard normal critical value (df = ∞ in Table G.2), which is 1.96 for a two-tailed test at the 5% level. Now t educ = −11.13/5.88 ≈ −1.89, so |t educ | = 1.89 < 1.96, and we fail to reject H 0: educ β = 0 at the 5% level. Also, t age ≈ 1.52, so age is also statistically insignificant at the 5% level.(ii) We need to compute the R -squared form of the F statistic for joint significance. But F = [(.113 − .103)/(1 − .113)](702/2) ≈ 3.96. The 5% critical value in the F 2,702 distribution can be obtained from Table G.3b with denominator df = ∞: cv = 3.00. Therefore, educ and age are jointly significant at the 5% level (3.96 > 3.00). In fact, the p -value is about .019, and so educ and age are jointly significant at the 2% level.(iii) Not really. These variables are jointly significant, but including them only changes the coefficient on totwrk from –.151 to –.148.(iv) The standard t and F statistics that we used assume homoskedasticity, in addition to the other CLM assumptions. If there is heteroskedasticity in the equation, the tests are no longer valid.4.11 (i) Holding profmarg fixed, n rdintensΔ = .321 Δlog(sales ) = (.321/100)[100log()sales ⋅Δ] ≈ .00321(%Δsales ). Therefore, if %Δsales = 10, n rdintens Δ ≈ .032, or only about 3/100 of a percentage point. For such a large percentage increase in sales,this seems like a practically small effect.(ii) H 0:1β = 0 versus H 1:1β > 0, where 1β is the population slope on log(sales ). The t statistic is .321/.216 ≈ 1.486. The 5% critical value for a one-tailed test, with df = 32 – 3 = 29, is obtained from Table G.2 as 1.699; so we cannot reject H 0 at the 5% level. But the 10% criticalvalue is 1.311; since the t statistic is above this value, we reject H0 in favor of H1 at the 10% level.(iii) Not really. Its t statistic is only 1.087, which is well below even the 10% critical value for a one-tailed test.1920SOLUTIONS TO COMPUTER EXERCISESC4.1 (i) Holding other factors fixed,111log()(/100)[100log()](/100)(%),voteA expendA expendA expendA βββΔ=Δ=⋅Δ≈Δwhere we use the fact that 100log()expendA ⋅Δ ≈ %expendA Δ. So 1β/100 is the (ceteris paribus) percentage point change in voteA when expendA increases by one percent.(ii) The null hypothesis is H 0: 2β = –1β, which means a z% increase in expenditure by A and a z% increase in expenditure by B leaves voteA unchanged. We can equivalently write H 0: 1β + 2β = 0.(iii) The estimated equation (with standard errors in parentheses below estimates) isn voteA = 45.08 + 6.083 log(expendA ) – 6.615 log(expendB ) + .152 prtystrA(3.93) (0.382) (0.379) (.062) n = 173, R 2 = .793.The coefficient on log(expendA ) is very significant (t statistic ≈ 15.92), as is the coefficient on log(expendB ) (t statistic ≈ –17.45). The estimates imply that a 10% ceteris paribus increase in spending by candidate A increases the predicted share of the vote going to A by about .61percentage points. [Recall that, holding other factors fixed, n voteAΔ≈(6.083/100)%ΔexpendA ).] Similarly, a 10% ceteris paribus increase in spending by B reduces n voteAby about .66 percentage points. These effects certainly cannot be ignored.While the coefficients on log(expendA ) and log(expendB ) are of similar magnitudes (andopposite in sign, as we expect), we do not have the standard error of 1ˆβ + 2ˆβ, which is what we would need to test the hypothesis from part (ii).(iv) Write 1θ = 1β +2β, or 1β = 1θ– 2β. Plugging this into the original equation, and rearranging, givesn voteA = 0β + 1θlog(expendA ) + 2β[log(expendB ) – log(expendA )] +3βprtystrA + u ,When we estimate this equation we obtain 1θ≈ –.532 and se( 1θ)≈ .533. The t statistic for the hypothesis in part (ii) is –.532/.533 ≈ –1. Therefore, we fail to reject H 0: 2β = –1β.21C4.3 (i) The estimated model isn log()price = 11.67 + .000379 sqrft + .0289 bdrms (0.10) (.000043) (.0296)n = 88, R 2 = .588.Therefore, 1ˆθ= 150(.000379) + .0289 = .0858, which means that an additional 150 square foot bedroom increases the predicted price by about 8.6%.(ii) 2β= 1θ – 1501β, and solog(price ) = 0β+ 1βsqrft + (1θ – 1501β)bdrms + u= 0β+ 1β(sqrft – 150 bdrms ) + 1θbdrms + u .(iii) From part (ii), we run the regressionlog(price ) on (sqrft – 150 bdrms ), bdrms ,and obtain the standard error on bdrms . We already know that 1ˆθ= .0858; now we also getse(1ˆθ) = .0268. The 95% confidence interval reported by my software package is .0326 to .1390(or about 3.3% to 13.9%).C4.5 (i) If we drop rbisyr the estimated equation becomesn log()salary = 11.02 + .0677 years + .0158 gamesyr (0.27) (.0121) (.0016)+ .0014 bavg + .0359 hrunsyr (.0011) (.0072)n = 353, R 2= .625.Now hrunsyr is very statistically significant (t statistic ≈ 4.99), and its coefficient has increased by about two and one-half times.(ii) The equation with runsyr , fldperc , and sbasesyr added is22n log()salary = 10.41 + .0700 years + .0079 gamesyr(2.00) (.0120) (.0027)+ .00053 bavg + .0232 hrunsyr (.00110) (.0086)+ .0174 runsyr + .0010 fldperc – .0064 sbasesyr (.0051) (.0020) (.0052) n = 353, R 2 = .639.Of the three additional independent variables, only runsyr is statistically significant (t statistic = .0174/.0051 ≈ 3.41). The estimate implies that one more run per year, other factors fixed,increases predicted salary by about 1.74%, a substantial increase. The stolen bases variable even has the “wrong” sign with a t statistic of about –1.23, while fldperc has a t statistic of only .5. Most major league baseball players are pretty good fielders; in fact, the smallest fldperc is 800 (which means .800). With relatively little variation in fldperc , it is perhaps not surprising that its effect is hard to estimate.(iii) From their t statistics, bavg , fldperc , and sbasesyr are individually insignificant. The F statistic for their joint significance (with 3 and 345 df ) is about .69 with p -value ≈ .56. Therefore, these variables are jointly very insignificant.C4.7 (i) The minimum value is 0, the maximum is 99, and the average is about 56.16. (ii) When phsrank is added to (4.26), we get the following:n log() wage = 1.459 − .0093 jc + .0755 totcoll + .0049 exper + .00030 phsrank (0.024) (.0070) (.0026) (.0002) (.00024)n = 6,763, R 2 = .223So phsrank has a t statistic equal to only 1.25; it is not statistically significant. If we increase phsrank by 10, log(wage ) is predicted to increase by (.0003)10 = .003. This implies a .3% increase in wage , which seems a modest increase given a 10 percentage point increase in phsrank . (However, the sample standard deviation of phsrank is about 24.)(iii) Adding phsrank makes the t statistic on jc even smaller in absolute value, about 1.33, but the coefficient magnitude is similar to (4.26). Therefore, the base point remains unchanged: the return to a junior college is estimated to be somewhat smaller, but the difference is not significant and standard significant levels.(iv) The variable id is just a worker identification number, which should be randomly assigned (at least roughly). Therefore, id should not be correlated with any variable in the regression equation. It should be insignificant when added to (4.17) or (4.26). In fact, its t statistic is about .54.23C4.9 (i) The results from the OLS regression, with standard errors in parentheses, aren log() psoda =−1.46 + .073 prpblck + .137 log(income ) + .380 prppov (0.29) (.031) (.027) (.133)n = 401, R 2 = .087The p -value for testing H 0: 10β= against the two-sided alternative is about .018, so that we reject H 0 at the 5% level but not at the 1% level.(ii) The correlation is about −.84, indicating a strong degree of multicollinearity. Yet eachcoefficient is very statistically significant: the t statistic for log()ˆincome β is about 5.1 and that forˆprppovβ is about 2.86 (two-sided p -value = .004).(iii) The OLS regression results when log(hseval ) is added aren log() psoda =−.84 + .098 prpblck − .053 log(income ) (.29) (.029) (.038) + .052 prppov + .121 log(hseval ) (.134) (.018)n = 401, R 2 = .184The coefficient on log(hseval ) is an elasticity: a one percent increase in housing value, holding the other variables fixed, increases the predicted price by about .12 percent. The two-sided p -value is zero to three decimal places.(iv) Adding log(hseval ) makes log(income ) and prppov individually insignificant (at even the 15% significance level against a two-sided alternative for log(income ), and prppov is does not have a t statistic even close to one in absolute value). Nevertheless, they are jointly significant at the 5% level because the outcome of the F 2,396 statistic is about 3.52 with p -value = .030. All of the control variables – log(income ), prppov , and log(hseval ) – are highly correlated, so it is not surprising that some are individually insignificant.(v) Because the regression in (iii) contains the most controls, log(hseval ) is individually significant, and log(income ) and prppov are jointly significant, (iii) seems the most reliable. It holds fixed three measure of income and affluence. Therefore, a reasonable estimate is that if the proportion of blacks increases by .10, psoda is estimated to increase by 1%, other factors held fixed.。
数字4的风水含义是什么
【数字4的风水含义】
1、阴阳平衡:数字4可以把阴阳的力量平衡起来,表示着阴与阳的不
断变化和互相补充,象征和谐、长寿、统一。
2、造型象征:数字4有“方正”之美,比喻调和之美,可以应用到建筑、装饰、摆设等方面,给人以宽广、充满、安全的感觉。
3、古德耆境:数字4与中国传统哲学的“道德耆境”有着巨大的关联,
反映了四季的到来,以及极乐世界和宇宙的起源、互动和演化。
4、五行关联:数字4有着与五行关联的含义,阳有着土、金、水、火,而阴有木,这五者是相互结合、彼此促进的,象征着新的生命和宁静。
5、四象传承:数字4和“四象”有着深刻的联系,象征着永恒不变、四
季之秀、平和宽容,在整个宇宙体系里具有根本的纽带作用。
6、吉祥意义:数字4代表吉祥、繁荣、和平,可以用在室内、家居装
饰上,把不同的物质与精神元素完美结合,给人以喜乐,祝愿团圆,
家庭团聚。
7、合圆卦象:数字4与家庭组织的卦象有着重要的相关性,象征着图
腾的复合性和社会的维系。
可以把它用在书画、香梯、摆件等上,预
示着一家人和睦、完满相处。
我的四个心理花瓶每个人的心中都会有这样四个空花瓶,它们的形状各不相同,代表着各种不同的含义,随着我们的成长,我们在渐渐地往我们的花瓶中注水,或多或少,我们用它们来衡量自我,分析自我。
一、我的四个心理花瓶二、关于四个花瓶的分析1.花瓶1:课业、工作前景这是一个普通花瓶,瓶身较细,它的水位大概在三分之二左右。
花瓶中三分之二的水位,其一,它代表了我并没有在学业中投入饱和的百分百的精力,这也导致了我对所取得的既有成绩并不十分满意;其二,它代表了我对所学专业的工作前景已经有一定的了解,但并不是非常的充分,所以,我对未来工作方面的规划只有一个大致的方向,并未做出一个较为详细的规划。
花瓶的瓶身较细,随着不断地注水,水位的上升也比较快,意在告诉自己,关于课业、事业方面,只要付出足够的努力,所能得到的回报就会很明显。
2.花瓶2:人际关系这个花瓶是一个肚大颈小的瓶子,它的水位是全满,但花瓶的底部有一个小缺口。
花瓶中的全满水位,其一,它代表了我们家庭成员关系比较和谐,这主要得益于我的家庭是一个相对比较民主的家庭,家庭氛围非常融洽,家人们也都是比较开朗乐观的人;其二,它代表了我对自己的除亲属外的人际关系的满意,开朗外向的性格使我在交友方面更加得心应手。
这个花瓶肚大颈小的形状代表了我对自我人际关系总体感到很圆满,但,花瓶底部有一个小缺口,这说明了,如果没有持续地注水,有可能会导致人际关系的流失。
这个小缺口旨在提醒自我,对于人际关系这一块,我还有一些方面有待补缺补漏。
3.花瓶3:躯体健康和体力精力这是一个上宽下窄的花瓶,它的水位也是全满。
现在的我正步入青年期,一个精力旺盛的时期。
处于这个时期的我,身体可以说是很健康,比较少生病,也有很多精力去参与各种各样有趣的活动,也能经常去参与一些体育锻炼。
全满水位代表了,我自我感觉这个时期的我精力无限。
但,随着时间的快速流逝,我的精力也将会随之流逝。
所以这个上宽下窄的花瓶形状,说明了,水量的减少,水位会先缓慢下降再慢慢加快,也代表了精力会慢慢下降。
随着,我国信息技术的不断蓬勃发展,近年来我国医院的信息化建设取得了很大进展,各层级医疗机构相比从前都面临着激烈的市场竞争,需要为病患者提供更人性化、更合理的服务。
近年来我国医药卫生体制改革不断深化,人民健康状况和基本医疗卫生服务的公平性可及性持续改善。
自从2019年经历了一场突如其来的新冠肺炎疫情,医药卫生体系经受住了考验,为打赢新冠肺炎疫情防控阻击战发挥了重要作用。
坚持以习近平新时代中国特色社会主义思想为指导,以人民为中心的发展思想,坚持保基本、强基层、建机制,统筹推进深化医改与新冠肺炎疫情防治相关工作,把预防为主摆在更加突出位置,推动把以治病为中心转变为以人民健康为中心,继续着力解决看病难、看病贵问题,为打赢疫情防控的人民战争、总体战、阻击战,保障人民生命安全和身体健康提供有力支撑,抗击新冠肺炎的阻击战之所以可以取得成功医疗信息化建设在其中发挥了至关重要的作用。
此后,为落实《国务院办公厅关于促进“互联网+医疗健康”发展的意见》(国办发〔2018〕26 号)和卫健委《关于进一步推进以电子病历为核心的医疗机构信息化建设工作的通知》(国卫办医发〔2018〕20 号),持续推进以电子病历为核心的医疗机构信息化建设,在《电子病历系统应用水平分级评价管理办法(试行)及评价标准(试行)》国卫办医函〔2018〕1079 号中,明确提出到 2019 年,所有三级医院要达到分级评价 3 级以上;到2020 年,所有三级医院要达到分级评价 4 级以上,二级医院要达到分级评价 3 级以上。
电子病历系统应用水平评级是全面评估各医疗机构现阶段电子病历系统应用所达到的水平,建立适合我国国情的电子病历系统应用水平评估和持续改进体系。
很多具有一定规模的中大型医院为了通过电子病历4级评审,花费较大精力对医院的信息化现状进行调研后,形成对标需求分析。
经过医院前期的基础医院信息系统的建设,包括数字化 HIS 系统、电子病历 EMR 系统、影像 PACS 系统、心电系统、病理系统、检验 LIS 系统、合理用药系统,以及此次信息化建设对标分析,查找差距,优化改造。
四单元(19-24)19 a dinner date晚餐聚会Would you like to come over for dinner tomorrow? 明天你想要过来吃晚饭吗?I `m going to be the chess club after school 放学后我要去国际象棋俱乐部I have math class es on Fridays 星期五我要上数学课。
I `m not doing well in math classes this year . 今年我数学学的不好We are going to plant trees. 我们打算去植树We are both busy all week. 我们两个整个星期都很忙碌How about coming over for dinner this evening? 今晚过来吃晚饭怎么样?V ery old people can`t take care of themselves. 年事很高的人不能照顾自己。
They can get help there and meet new friends 在哪里她们可以得到帮助认识新朋友20 join our club加入我们的俱乐部Do you want to improve your thinking skills ? 你想提高你的思维技能吗?Do you want to make new friends ? 你想交新朋友吗?Chess challenges you and makes you think hard 国际象棋挑战你是你开动脑筋Y ou will learn and have fun at the same time. 你将在学习的同时玩的快乐Join us after school on Tuesdays and Tuesdays in Room 288.星期二和星期四放学后去288房间加入我们。
1、4P即产品(product)、价格(price)、促销(promoti on)、渠道(place)它的主导是以满足市场需求为目标。
2、4C即消费者(Consume r)、成本(Cost)、便利(Conveni ence)和沟通(Communi cation) 它的主导是以追求顾客满意为目标。
3、4R即关联(Relativ ity)、反应(Reactio n)、关系(Relatio n)和回报(Retribu tion)它的主导是以建立顾客忠诚为目标。
之间的区别从字面上就可以理解了,所追求的达到的目标是不同的,但他们之间有一个逐渐发展的过程,这也是这些大师们从实践中总结出来的,不管是4P、4C还是4R,都是来自于实践,又反过来指导着企业的营销实践。
营销组合(Marketi ng Mix)也称作4P模型,强调了产品、价格、销售渠道和促销手段这四个在销售产品中影响巨大的因素,公司制定产品营销战略时必须对它们加以考虑。
产品 (Product)我的产品与我现有其他产品的关系如何?以确定你的产品之间的协作区域,或发现在哪些方面对各项商业活动有约束。
∙我怎样让自己的产品更出众?个性化(Differe ntiati on)是个大题目,要做到这一点可以通过特点、适宜性、格调、可靠性、包装、服务及品牌命名等方面来体现。
∙产品生命周期对我的计划有什么影响?根据产品在产品生命周期(ProductLife Cycle, PLC)中的不同位置,我们应采取不同的营销策略。
价格 (Price)∙成本定价(Cost Plus):这是最简单的价格策略。
方法是在成本的基础上加上期望的利润。
∙消费者认同价值(Perceiv ed Value to the Consume r):指按照为消费者提供的价值收费。
最终幻想4攻略复刻版剧情流程图文详解主要给大家介绍的是如何按照最终幻想4攻略剧情通关,最终幻想4攻略中每一个剧情的boss也都列出来了,不同的boss有不同的打法,大家还是按步骤来吧。
本作的故事破天荒的在地上、地下和月亮世界三个舞台上展开。
主要讲述了赤翼队长塞西尔对巴隆过以力量压迫奴役他国的做法非常不满,因而将自己的想法转达给国王。
不曾想却遭到追杀。
于是塞西尔决定与巴隆国战斗!在漫长的反抗生涯中,塞西尔经历了友情的背叛、爱情的美好以及自身身份的转变。
作为一个经典的RPG游戏系列,我们这次在IOS版上不但看到了一贯的一些经典系统,但是这一代是改变的一代,为什么这么说呢?因为游戏的系统从四代开始,游戏系统都会发生少许改变和发展。
例如基于三代发展出的技能系统和基于二代发展出的魔法习得系统等,可以看出史克威尔的用心。
最重要的是前三代游戏中的水晶,被赋予了更多元化的设定。
它不在是专为主角所独享,演变成了敌我双方都可使用的新形态。
而且由此展开的剧情也变成了互相争夺,不在是一方守护一方破坏的固定模式了。
其中最有亮点的是ATB(ACTIVE TIME BATTLE)战斗模式!舍弃了传统的回合制,采用了全新的时间槽即时战斗系统,使战斗不在是一成不变。
进入游戏后,首先选择游戏难度,小编选了困难,两个难度的进程什么的都一样,只是怪的伤害和血量不同。
首先是一段剧情介绍,赤翼队长塞西尔奉命去收集水晶,虽然善良的队长很不愿意从无辜的人们那里抢夺水晶,但是塞西尔迫于军人的服从而不得不去做这些违心的任务。
突然飞艇遭到的攻击(进入第一场战斗)。
战斗结束后,我们的主角塞西尔回到了王国,把水晶交给国王后,塞西尔忍不住向王国表示出了质疑,没想到这让他被降职,国王让塞西尔带着爆弹戒指去击败幻兽。
到这里,我们就要开始开始的剧情就结束了。
首先我们对游戏的操作做个简单的介绍,游戏采用的单摇杆的行动控制模式,像所有的RPG一样我们的角色都有装备和角色属性,而关于角色的所有信息都可以点击屏幕右上角的按钮后看到。
Unit4一、课文A sportswriter thinks he's met another crank. Instead, he finds a true winner.一位体育专栏作家以为他碰上了一个怪人。
结果他却发现了一个真正的赢家。
A Fan's NotesBill PlaschkeThe e-mail was in some respects similar to other nasty letters I receive. It took me to task for my comments on the Los Angeles Dodgers and argued that I had got everything wrong. However, the note was different from the others in at least two ways.一位球迷的评论比尔·普拉施基这封电子邮件在某些方面与我收到的其他刻薄的信件相似。
它痛斥我对洛杉矶道奇队的评论,并争辩说我把一切全都搞错了。
然而,这个评论与其他的评论至少有两个方面不同。
This note contained more details than the usual "You're an idiot." It included vital statistics on the team's performance. It was written by someone who knew the Los Angeles Dodgers as well as I thought I did.与通常那些“你是个白痴”的评论不同的是,这一评论含有更多的细节。
它包含了该队比赛表现的关键数据。
写这篇评论的人对洛杉矶道奇队的了解绝不亚于我自认为对它的了解。
And this note was signed. The writer's name was Sarah Morris.而且这一评论是署名的。
任务4 作出正确的决策(课后练习题参考答案)一、单项选择题1、C2、B3、C4、C5、A6、A7、A8、B9、A 10、B二、判断题1、错2、对3、错4、对5、错6、对7、错8、对9、错 10、对三、简答题1.决策在组织中有什么重要作用?随着现代科学技术水平的不断提高,市场竞争日趋激烈,影响组织运行的因素变得十分复杂,因为单凭个人经验或主观判断进行决策,是不能适应激烈多变的竞争环境的,管理者也难以作出正确、科学的判断。
可以说,管理者科学、理性的决策等于成功了一半,可见,决策对企业具有非常重要的作用,其重要性具体体现在:①决策决定了组织的生存和发展决策涉及组织生活的方方面面,大到组织的总体发展目标,小到日常管理工作中出现的问题,任何一个决策的正确与否都会影响到组织的正常运作。
正可谓“一着走错,全盘皆输”。
中外许多企业的沉浮经历,足以成为有力的佐证。
因此,每一个决策者必须清醒认识和估计各种情况,以更好地把握其变化规律,制定出科学、正确的决策,保证组织的持续发展。
②决策是组织各项管理职能部门运行的依据决策是管理的重要职能之一,决策也是各项管理职能部门运行的依据。
决策是一个方案,为各职能部门和全体员工指明努力方向和目标。
没有正确的经营决策,各职能部门就无法正常发挥功能,职能造成组织活动的无序甚至混乱。
③正确的决策是组织可持续发展的保证在科学技术发展迅猛、信息膨胀的今天,各种各样的情况层出不穷,任何组织都需要随时根据实际情况,及时、准确和科学地作出正确的决策,以适应社会,求得发展,否则只能面临被淘汰的命运。
2. 决策有哪些程序?要做出一个正确的决策,管理者需要自觉地遵循以下六个步骤:1. 认识决策需要决策过程的第一步就是要认识决策需要。
一些刺激因素通常会激发起决策需要的意识。
当组织环境中发生的变化带来了新的机遇或者威胁时,这些刺激因素就会显现出来。
除了来自于外部环境中的变化,激发决策需要的刺激因素还可能来自于组织内部管理者的行为。
X029府金线中原大道至G207段改造工程(伊滨区段)
(K1+100~K1+220)
填方路基4%石灰土试验段总结
河南海滨路桥建筑工程有限责任公司
X029府金线改造工程项目部
2015年11月10日
目录一、工程概况
二、试验段施工组织
三、确定施工工艺
3.1施工准备
3.2石灰消解
3.3备料与卸料
3.4拌和
3.5整形
3.6碾压
3.7养生
四、试验段总结
五、小结
4%石灰土试验段施工总结2015年10月31日项目部对选定路基填筑4%石灰土试验段开始备土,11月1日正式施工,在施工过程中,项目部技术人员和驻地办监理人员对现场施工进行了全过程的跟踪和旁站,对施工工艺和方法进行了全程控制。
在施工过程中生石灰的消解闷料、石灰土的拌和、装卸、运输、铺筑、整平、压实和养护等多道工序均按设计及施工技术规范执行。
于2015年11月2日碾压结束,经检测各项指标均满足设计和规范要求。
在项目部的精心组织及驻地办的大力协助下,制定出一套详细的石灰土填筑施工工法,并组织项目部技术人员认真学习、贯彻执行,现将试验段施工取得的有关参数、施工工艺、结果总结如下:
一、工程概况:
试验段施工起讫桩号:K1+100~K1+220,长度:120m,宽度:0.5m+7.5m +7.5m +0.5m+超宽碾压0.5m×2=19m,压实厚度为0.2m,采用路拌法施工;试验段工程量:4%石灰土456m3。
二、试验段的施工组织
2.1 试验段主要人员主要职能分配表
2.2试验段施工机械的配备情况
三、确定施工工艺
3.1施工准备
3.1.1下承层准备:下承层通过整平碾压,其压实度、横坡、纵坡等各项指标均达到要求并通过报验合格。
3.1.2测量放线:下承层的准备工作做好后,各项质量指标符合设计要求后,应进行施工放样,用全站仪恢复路基中线和边线,每隔20米设一桩,边线并用石灰洒出坡脚线,每侧坡脚线比设计宽出50cm,并用钢尺校核路基宽度。
3.1.3试验:施工前对石灰进行了滴定试验,试验结果表明,生石灰的钙镁含量达到Ⅲ级及Ⅲ级以上规范要求,同时对4%石灰土的标准试验,按重型击实标准试验,确定了灰土的最佳含水量1
4.40%与灰土的最大干密度1.758g/cm3。
3.2石灰消解
石灰选在路基两侧宽敞且临近水源的场地集中堆放,按每吨石灰
消解需要用水量500~800kg进行加水焖料,待7~10天生石灰充分消解后方可进行使用。
3.3备料与铺料
3.3.1由试验数据,通过计算,得出土的松铺厚度h1
设计压实厚度0.2*摊铺系数1.3=0.26m
3.3.2取土场取土:清除树根、草根及不合格土层,在取土场按预定深度规定范围内由上而下用挖掘机挖取,然后晾晒降低含水量,对土质变化较大的土场(土的塑指变化在5以上)不能混取,应分层按施工段落挖取,确保同一施工段落土质均匀,现场要做好防水和排水措施。
3.3.3翻拌:石灰土采用挖掘机进行拌合,先将石灰与土翻拌一遍,拌后打堆,每天上、下午各测一次原材料的含水量,调整原材料的进料数量,使混合料的含水量略大于最佳含水量2个百分点左右,试验人员应重点进行灰剂量及含水量的检测。
拌合好的灰土应色泽均匀、无离析、成团块现象。
灰土摊铺至路基时,利用灰土拌合机进行破碎拌合处理,使其达到灰土颗粒大小、拌合均匀度均能满足设计及规范要求。
3.3.4灰土拌制要求:在取土场取土时先进行掺灰拌合,在装车卸车时分别进行了一次简单拌合,施工摊铺时,又进行了一次拌合,经过以上工序基本可以达到灰土拌合的要求。
3.3.5根据算得的每延米用土量及每车20m3的运土量,用石灰粉标出每车的卸土位置(划出方格),直接整齐地卸土于路槽上。
备土
时纵向必须成行,并保证每车的运土量基本准确。
3.3.6铺土、翻晒,先用推土机大致推土进行初步的整平,用旋耕耙对土进行翻晒,在灰土的含水量达到最佳含水量+2%以内时,用平地机整平,清余补缺,达到厚度一致,表面平整的效果,然后再用压路机稳压一遍,使其初步成型。
3.4拌和
拌合、检测:路拌机二次拌和,速度控制在5m/min以内,拌和深度以打入下承层1cm为限,以加强上下层粘结,确保拌和层底部无夹层和不均的死角。
在拌和过程中我们指派专人跟机进行挖验,每间隔20米挖验一处,检查是否有素土夹层。
对于拌和不彻底的段落,及时提醒拌和机司机返回重新拌和。
拌和横向搭接30cm。
在拌和以后保证色泽一致,翻拌均匀。
混合料拌和完成后,混合料表面色泽一致,无灰团和花面现象。
3.4.3拌和完成后,抽取灰剂量,抽取结果见后附《4%灰土中石灰剂量试验记录》,由试验结果表明,拌和效果满足要求。
3.5整型
混合料拌和均匀后,先用平地机初步整平和整型。
试验段所处位置为直线段,平地机由两侧向路中心进行刮平,然后用压路机立即在刚整平的路段上快速碾压一遍,以暴露潜在的不平整,再用平地机如前那样整平一遍,以达到最佳的效果。
3.6碾压
3.6.1整型后,为不错过最佳的碾压时机,由试验人员阶段性的
对灰土的含水量进行检测,在土的含水量达到最佳含水量+2%以内时,进行碾压。
3.6.2碾压采用一台22吨振动压路机和一台26吨振动压路机联合完成。
3.6.3采用的碾压组合:先采用振动压路机静压一遍,轮迹重叠1/2弱振1遍,再强振碾压4遍,紧跟振动压路机低速1/2错轮静压1遍,消除轮迹。
3.6.4为达到最佳的碾压效果,为以后的施工提供可靠的依据,碾压过程中,始终都保持灰土层表面湿润,对局部表面水分蒸发快的地方,及时的进行补洒;对有出现“弹簧”、松散、起皮等现象的地方,进行了及时的翻开并重新拌和、碾压达到质量要求。
3.7 养生
碾压结束后,洒水养护使灰土表面处于湿润状状态。
报验结束后封闭交通。
养生时间自灰土成型后7天内,及时洒水保湿养生并封闭交通,7天后至灰土板结前同样需要适度洒水养生,保持一定湿度,以保证灰土表面不开裂、不起灰。
四、试验段总结:
在4%灰土实验段的施工过程中,由于施工准备充分,各相关部门配合协调、技术指导正确,技术交底细致,项目管理部和现场监理监督规范,从而保证了4%灰土试验段的顺利进行,达到了预期目的。
本试验段工程施工时严格按照上报施工作业指导书进行作业,因该技术成熟,操作人员技术熟练,各施工部门协调配合、技术指导正确,监理监督规范,因而4%灰土底基层施工很顺利,证明该作业指导书合理
有效。
(1)、由试验结果确定碾压组合:首先静压一遍,弱振第一遍平均压实度为87.0%;强振第一遍平均压实度为90.3%;强振第二遍压实度平均为92.5%;强振第三遍压实度平均为94.5%;强振第四遍压实度平均为95.6%;最后压路机低速1/2错轮静压1遍后压实度能够达到95.8%。
(2)、最后根据松铺状态下厚度的平均值H松与达到规定压实度的压实厚度的平均值H实计算得出其松铺系数,计算如下:
松铺系数=H松/H实=26/20=1.3
①.经总结本段4%灰土试验段工程得出施工控制参数如下:
1、施工用料上断面后的最佳含水量为土15.5%。
2、施工用料在虚摊铺后厚度控制为26cm左右。
3、确定最佳的机械组合为:压路机静压1遍、振动压路机强振4遍重叠1/2轮宽,再静压1遍光面。
4、整平碾压前松铺系数为1.3,碾压前含水量控制在15%为最佳。
②.总结本段底基层4%灰土试验段工程需要改进提高:
1、缩短标高挂线的时间,以防表面含水量损失过快;
2、加大土的粉碎遍数确保混合料的颗粒粒径,以减少石灰加入后的翻拌次数;
3、严格控制稳压时的速度,并将稳压时挤推到已稳压好断面上的混合料及时人工清除,减少起皮现象;
及时掌握天气变化,将不良天气影响降低到最小程度。
五、小结
通过试验段的施工,为我们在以后的灰土施工中提供了可靠的施工数据和遵循的依据;在今后的灰土施工中,我们还要不断的摸索与总结,对每个施工段的试验数据、结果进行分析和对比,进而对施工工艺进行不断的完善与改善。
争取做的更好,力求做到最好。
河南海滨路桥建筑工程有限责任公司 X029府金线改造工程项目部
2015年11月10日。