[精品]新疆昌吉市教育共同体2019届高三化学上学期第二次月考(9月)试题(含解析)

2017-201学年度上学期8月月考试题高三化学试卷说明：1、必须使用黑色0.5签字笔答题。

2、试卷满分：100分。

3、只交答题卡，答案书写在答题卡指定区域；答在试卷上无效。

一、选择题（每题只有一个选项正确，每题6分，共42分） 7．化学与生活密切相关，下列说法正确的是()A ．石油分馏、煤的干馏、烟气脱硫、菜籽中提取菜籽油等过程都是物理变化B ．用天燃气代替煤作燃料可减少大气污染C ．高纯度的硅广泛用于制作光导纤维，光导纤维遇强碱会“断路”D ．绚丽缤纷的烟花中添加了含铁、铂、钠、钾、铜等金属化合物 8．设N A 代表阿伏加德罗常数的值，下列说法中正确的是( ) A. 2.3 g 钠由原子变成离子时，失去的电子数为 0.2N A B.28 g 氮气所含的原子数为N AC.0.2N A 个硫酸分子与19.6 g 磷酸含有相同的氧原子数D.N A 个氧分子与N A 个氢分子的质量比为8∶19．常温下，下列各组离子在指定溶液中能大量共存的是( ) A ． 无色透明的溶液中：Fe 3＋、Mg 2＋、SCN －、Cl －B ．＝1×10－12的溶液中：K ＋、Na ＋、CO 、NOC ．c (Fe 2＋)＝1 mol·L －1的溶液中：K ＋、NH 、MnO 、SOD ． 能使甲基橙变红的溶液中：Na ＋、NH 、SO 、HCO 10．下列表示对应化学反应的离子方程式正确的是( ) A ．碘水中通入适量的SO 2：I 2＋SO 2＋2H 2O===2I －＋SO2－4＋4H ＋B ．NH 4HCO 3溶液与足量NaOH 溶液混合后加热：NH ＋4＋OH －=====△NH 3↑＋H 2OC ．将磁性氧化铁溶于稀HNO 3：Fe 3O 4＋8H ＋===2Fe 3＋＋Fe 2＋＋4H 2OD ．向Ca(ClO) 2溶液中通入SO 2：Ca 2＋＋2ClO －＋H 2O ＋SO 2===CaSO 3↓＋2HClO11．下列说法正确的是()A ．失电子越多，还原性越强，得电子越多，氧化性越强B ．已知①Fe ＋Cu 2＋===Fe 2＋＋Cu ；②2Fe 3＋＋Cu===2Fe 2＋＋Cu 2＋，则氧化性强弱顺序为 Fe 3＋>Cu 2＋>Fe 2＋C ．已知还原性：B －>C －>D －，反应2C －＋D 2===2D －＋C 2和反应2C －＋B 2===2B －＋C 2都能发生 D ．具有强氧化性和强还原性的物质放在一起就能发生氧化还原反应12．下图表示了x 、y 、z 事物间的从属关系，下列选项中不符合图中事物间从属关系的是13．把V L 含有硫酸镁和硫酸钾的混合溶液分成两等份，一份加入含a mol 氢氧化钠的溶液，恰好使镁离子完全沉淀为氢氧化镁；另一份加入含b mol 氯化钡的溶液，恰好使硫酸根离子完全沉淀为硫酸钡。

喀什二中2018-2019学年第一学期高三年级9月考试化学试卷满分100分，90分钟可能用到的相对原子质量：H-1 C-12 N-14 O-16 F-19 Na-23 Mg-24 Al-27S-32 Cl-35.5K-39 Ca-40一、单选题（每题3分，共54分）1、关于钠的说法正确的是A．熔点很高 B．在空气中燃烧时产生黄色火焰C．银白色金属，硬度大 D．在空气中燃烧生成氧化钠2、下列实验装置图所示的实验操作，不能．．达到相应的实验目的的是（）3．下列选项中所涉及的两个量一定相等的是( )A．11.2 L Cl2与4.25 g NH3所含有的原子数B．等物质的量的Al分别与足量的盐酸、NaOH溶液反应转移的电子数C．标准状况下36 g H2O与1.204×1024个O2分子所占的体积D．18.0 g重水(D2O)与20 g Ne所含有的电子数4．设N A表示阿伏加德罗常数，下列叙述不正确的是( )A．通常状况下，1 mol SO3含有的分子数为N AB．1 mol OH－参与电解，转移的电子数目为N AC．标准状况下，含N A个氩原子的氩气体积约为22.4 LD．标准状况下，V L水含有的氧原子数约为V22.4N A 5、下列关于实验的叙述正确的是A. 向一定量的稀硫酸中加入除去油污的稍过量的废铁屑，是制备硫酸亚铁溶液的可行方案B. 向煮沸的1 溶液中滴加饱和溶液制备胶体C. 向铝屑与硫酸反应后的溶液中加入氢氧化钠溶液反应，是制备氢氧化铝的最佳方案D. 向某溶液中，依次加入氯水和硫氰化钾溶液，溶液变红，说明溶液中含有6、有一定质量的 Na2O2、Na2O、Na2CO3、NaOH的固体混合物，与400g质量分数为3.65%的盐酸恰好反应，蒸干溶液，最终得固体质量为( )A．16g B．23.4g C．31g D．无法计算7、在由水电离产生的H＋浓度为1×10－13mol·L－1的溶液中，一定能大量共存的离子组是( )①K＋、Cl－、NO－3、S2－②K＋、Fe2＋、I－、SO2－4③Na＋、Cl－、NO－3、SO2－4④Na＋、Ca2＋、Cl－、HCO－3⑤K＋、Ba2＋、Cl－、NO－3A．①③ B．③⑤C．④⑤D．②⑤8、下列离子方程式的书写正确是A．实验室用大理石和稀盐酸制取CO2：2H+ + CO32- ＝ CO2↑+ H2OB．向NaOH溶液中加入铝粉来制备H2：Al＋2OH-+2H2O===AlO2-＋3H2↑C．氢氧化钡溶液与稀H2SO4反应：Ba2++SO42-=BaSO4↓D．铁和稀盐酸反应：Fe + 2H+ ＝ H 2↑+ Fe 2+9、已知：SO2－3＋I2＋H2O===SO2－4＋2H＋＋2I－，某溶液中可能含有I－、NH＋4、Cu2＋、SO2－3，向该无色溶液中加入少量溴水，溶液仍呈无色，下列判断正确的是( )A．肯定不含I－B．肯定不含NH＋4C．可能含有SO2－3 D．可能含有I－10、被称为万能还原剂的NaBH4（NaBH4中H为－1价, ）能溶于水并和水反应，反应式为： NaBH4 + 2H2ONaBO2+4H2↑，下列有关该反应的说法中，正确的是（）A．NaBH4既是氧化剂又是还原剂 B．NaBH4是氧化剂，H2O是还原剂C．硼元素被氧化，氢元素被还原 D．被氧化的元素与被还原的元素质量比为1:111、下列反应与相比较，的作用相同的是A. B. C.D.12、向某NaOH溶液中通人气体后得溶液M，因通入量的不同，溶液M的组成也不同若向M中逐滴加人盐酸，产生的气体体积与加人盐酸的体积的关系有下列图示四种情况，且图中分别有，，，则下列分析与判断一定正确的是不计的溶解A. 图显示M 中只有一种溶质且为B. 图显示M 中有两种溶质且为C. 图显示M 中有两种溶质且为D. 图显示M 中13、用含有少量Mg 的Al 片制取纯净的Al(OH)3，下列操作中最恰当的组合是( ）①加盐酸溶解 ②加NaOH 溶液 ③过滤 ④通入过量CO 2生成Al(OH)3⑤加盐酸生成Al(OH)3⑥加过量氨水生成Al(OH)3A.①⑥③B.①③⑥③C.②③④③D.②③⑤③14、向100mL0.1mol ⋅L −1硫酸铝铵溶液中逐滴滴入0.1mol ⋅L −1Ba(OH)2溶液..随着Ba(OH)2溶液体积V 的变化，沉淀总物质的量n 的变化如图所示..则下列说法中正确的是( )A. a 点的溶液呈中性B. 从开始到b 点发生反应的总的离子方程式是：Al 3++2SO 42−+2Ba 2++3OH −=Al(OH)3↓+2BaSO 4↓C. c 点加入Ba(OH)2溶液的体积为200mLD. c 点溶液呈碱性15、ClO 2是一种杀菌消毒效率高、二次污染小的水处理剂。

昌吉市教育共同体2019届高三年级第二次月考数学（文科）试卷考试时间：120分钟分值: 150分一、选择题（5×12=60）1.已知集合，则= ( )A. 或B. 或3C. 1或D. 1或3【答案】B【解析】【分析】利用子集的定义，得到参数所满足的条件，得到相应的等量关系式，之后应用元素的互异性求得结果.【详解】因为集合，，且，所以或，若，则，满足；若，则或，当时，，满足；当时，集合A中元素不满足互异性，舍去，故选B.【点睛】该题考查的是有关集合中参数的取值范围的问题，在解题的过程中，涉及到的知识点有子集的概念，集合中元素的互异性，注意对参数回代检验.2.函数的导数为（）A. B.C. D.【答案】A【解析】分析：由即可的解.详解：函数，求导得：.故选A.点睛：本题主要考查了两函数乘积的求导运算，属于基础题.3.已知函数,若,则实数的值为( )A. B. C. D.【答案】B【解析】因为，所以 ,选B4.函数的图像大致是（）A. B. C. D.【答案】C【解析】试题分析：[法一]首先看到四个答案支中，是偶函数的图象，是奇函数的图象，因此先判断函数的奇偶性，因为，所以函数是奇函数，排除；又时，，选择是明显的.[法二]化为分段函数，画出图象，选考点：1.函数的奇偶性；2.绝对值的定义；3.画函数图象;5.已知函数在R上是增函数且,则实数的取值范围是( )A. B. C. (-1,0) D.【答案】D【解析】【分析】根据增函数的性质：函数值大，自变量也越大，去掉符号“”，即可求m的取值范围.【详解】因为函数在R上是增函数且,所以，即，解得或，所以实数的取值范围是，故选D.【点睛】该题考查的是有关应用函数单调性，求解不等式的问题，在解题的过程中，需要死扣函数单调性的定义，将函数值的大小关系转化为自变量的大小关系，从而求得对应的结果.6.设函数的导函数为,且,则( )A. B. C. D.【答案】C【解析】【分析】先求出导函数，令导函数中，求出，将代入导函数，令导函数中的求出.【详解】因为，所以，所以，所以，所以，所以，故选C.【点睛】该题考查的是有关函数在某个点处的导数的问题，涉及到的知识点有函数的求导公式，利用赋值法求得函数的解析式，明确函数在某点的导数就是导函数在某点处的函数值.7.函数在区间上的最大值是( )A. 1B.C.D. 1+【答案】C【解析】由,故选C.视频8.设函数则满足的的取值范围是( )A. B. C. D.【答案】D【解析】分析：分两种情况讨论，分别解不等式组，然后求并集即可得结果.详解：由或，所以满足的的取值范围是，故选D.点睛：本题主要考查分段函数的解析式、分段函数解不等式，属于中档题.对于分段函数解析式的考查是命题的动向之一，这类问题的特点是综合性强，对抽象思维能力要求高，因此解决这类题一定要层次清楚，思路清晰.9.已知向量,,若,则( )A. B. C. D.【答案】A【解析】【分析】首先应用向量的坐标，利用向量数量积坐标公式得到关于的关系式，利用同角三角函数关系式求得，最后对于分子分母为关于角的弦的二次齐次式，上下同除以，得到关于的式子，代入求得结果.【详解】因为，由得，整理得，所以，故选A.【点睛】该题考查的是有关角的的弦的二次齐次式的分式形式的式子的求值问题，涉及到的知识点有向量的数量积坐标公式，同角三角函数关系式，正确使用公式是解题的关键.10.已知函数的部分图象如图所示,则( )A. ,B. ,C. ,D. ,【答案】D【解析】分析：通过图象求出函数的周期，再求出ω，由（，1）确定φ，推出选项．解答：解：由图象可知：T=π，∴ω=2；（，1）在图象上，所以2×+φ=，φ=-．故选D．11.已知,则( )A. B. C. D. 的夹角为【答案】C【解析】试题分析：根据题意由于，则可知，而对于，从而说明向量成立，对于D，的夹角为，故错误，对于B，由于向量的坐标不符合共线的公式，故错误，选C.考点：向量的数量积点评：主要是考查了向量的数量积的坐标运算属于基础题12.设函数,则下列结论中正确的是( )A. B.C. D.【答案】D【解析】试题分析：由题意，，即为偶函数。

新疆昌吉市教育共同体2019届高三上学期第二次月考（9月）数学（理）试题考试时间：120分钟 分值: 150分一、选择题：（本大题共12个小题，每小题5分，共60分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

）1．设集合{}3213A x x =-≤-≤，集合为函数的定义域，则（ ） A ． B ． C ． D ． 2．函数最小正周期为（ ）A ．B ．C ．D ．3．已知曲线在点处的切线与直线垂直，则的值是（ ） A ． B ．1 C ． D ． 4．下列说法正确的是（ ）A ．若命题都是真命题，则命题“”为真命题B ．命题：“若，则或”的否命题为“若，则或”C ．命题“”的否定是“”D ．“”是“”的必要不充分条件 5．设函数，则下列结论错误的是（ ） A ．是偶函数 B ．是奇函数 C ．是奇函数 D ．是偶函数 6．函数的零点的个数为（ ） A ．0B ．1C ．2D ．37．已知，则（ ）A ．B ．C ．D ．8．已知函数()2,143,1x x f x x x x ⎧≤⎪=⎨+->⎪⎩，则的值域是（ ） A ． B ． C ． D ． 9．三个数6log ,7.0,67.067.0的大小顺序是( )A.7.07.0666log 7.0<< B.6log 67.07.07.06<< C.67.07.07.066log << D.7.067.067.06log <<10．已知是定义在R 上的奇函数，当时，（m 为常数），则的值为（ ） A ．B ．C ．6D ．11．若函数⎪⎩⎪⎨⎧≤+->=1,1)32(1,)(x x a x x ax f 是上的减函数，则实数的取值范围是（ ）A ．B ．C ．D ．12．已知关于的方程()22ln 2x x x k x +=++在上有两解，则实数的取值范围为（ ） A ． B ． C ． D ．二、填空题（每题5分，满分20分，将答案填在答题纸上） 13．若函数()1,0,0,x x f x x ⎧-<⎪=⎨⎪≥⎩，则 ．14．设⎩⎨⎧+∞∈-∞∈=),[,),(,)(2a x x a x x x f ，若，则的取值范围为_____________．15．⎪⎭⎫ ⎝⎛-⋅⋅34tan 65cos 34sinπππ= . 16．直线分别与曲线，交于、两点，则的最小值为 ．三、解答题 （本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．（本题满分10分）已知函数()log (1)log (3)a a f x x x =-++（）．（Ⅰ）求函数的定义域；（Ⅱ）若函数的最小值为，求实数的值．18．（本题满分12分） 已知，且tan α＞0．231(),()23f x x xg x x x m=+=-+（1）由tan α的值； （2）求的值．19．（本题满分12分）已知函数2()sin 22f x x x =-． （1）求函数的解析式及其最小正周期； （2）当时，求函数的值域．20．（本题满分12分）定义在实数集上的函数.⑴求函数的图象在处的切线程;⑵若对任意的恒成立，求实数m 的取值范围.21．（本小题满分12分）已知函数4()log (41)xf x kx =++是偶函数． （Ⅰ）求的值；（Ⅱ）设44()log (2)3xg x a a =⋅-，若函数与的图象有且只有一个公共点， 求实数的取值范围．22.(本小题满分12分) 在平面直角坐标系xOy 中，过点P (2,0)的直线l 的参数方程为⎩⎨⎧x ＝2－3t y ＝t(t 为参数)，圆C 的方程为x 2＋y 2＝9.以坐标原点O 为极点，x 轴的非负半轴为极轴建立极坐标系．(1)求直线l 和圆C 的极坐标方程；(2)设直线l 与圆C 相交于A ，B 两点，求|PA |·|PB |的值．参考答案选择题：填空题：13、14、15、433-16、2解答题：17、解：（Ⅰ）由，得∴定义域为（Ⅱ）函数化为22()log (1)(3)log (23)log (1)4a a a f x x x x x x ⎡⎤=-+=--+=-++⎣⎦，∴ ，2log (1)4log 4a a x ⎡⎤-++≥⎣⎦∴，即由，得，故实数的值为 18、解：（1）由，得，又tan α＞0，则α为第三象限角，所以，∴．（2）．19、（1）利用二倍角公式、两角和公式和辅助角公式将函数化简1()sin(2)62f x x π=-++，； （2）∵，∴， ∴，∴函数的值域是． 20、试题解析：⑴∵,当时， ∵'()21'(1)3f x x f =+⇒=∴所求切线方程为23(1)310y x x y -=-⇒--=. ⑵令321()()()3'()(3)(1)3h x g x f x x x x m h x x x =-=--+⇒=-+ ∴当时，；当时，；当时，；要使恒成立，即.由上知的最大值在或取得. 而52055(1),(4)03333h m h m m m -=+=-⇒+≤⇒≤- ∴实数m 的取值范围.21、 解：（Ⅰ）由函数是偶函数可知：44log (41)log (41)x x kx kx -∴++=+-即对一切恒成立（Ⅱ）函数与的图象有且只有一个公共点 即方程4414log (41)log (2)23xx x a a +-=⋅-有且只有一个实根 化简得：方程有且只有一个实根 令，则方程有且只有一个正根(1)，不合题意； (2)或 若，不合题意；若(3)一个正根与一个负根，即以上结果经过验证均满足（此步没有可不扣分） 综上，实数的取值范围是22、解 (1)直线l 的普通方程为x ＋3y －2＝0， 将⎩⎪⎨⎪⎧x ＝ρcos θy ＝ρsin θ代入得，ρcos θ＋3ρsin θ－2＝0，整理得直线l 的极坐标方程为ρcos(θ－π3)＝1.圆C 的极坐标方程为ρ＝3.(2)直线l 的参数方程为⎩⎨⎧x ＝2－3ty ＝t，将其代入x 2＋y 2＝9得4t 2－43t －5＝0，所以|PA |·|PB |＝|t 1|·|t 2|＝|t 1t 2|＝54.。

新疆昌吉市教育共同体2019届高三上学期第二次月考（9月）数学（理）试题考试时间：120分钟分值: 150分一、选择题：（本大题共12个小题，每小题5分，共60分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

）1.设集合，集合为函数的定义域，则（）A. B. C. D.【答案】D【解析】【分析】求出两个集合后可求它们的交集.【详解】，，故，选D.【点睛】本题考查集合的基本运算，属于基础题.2.函数最小正周期为A. B. C. D.【答案】C【解析】因为，所以其最小正周期，故选C．【名师点睛】求三角函数最小正周期的方法：①利用周期函数的定义；②利用公式：y=A sin(ωx＋φ)和y=A cos(ωx＋φ)的最小正周期为，y=tan(ωx＋φ)的最小正周期为；③对于形如的函数，一般先把其化为的形式再求周期．3.已知曲线在点处的切线与直线垂直，则的值是A. -1B. 1C.D.【答案】C【解析】由y=x3知y'=3x2，故切线斜率k=y'|x=1=3.又切线与直线ax+y+1=0垂直，故－3a=－1，得a=.选C.点睛：利用导数的几何意义解题，主要是利用导数、切点坐标、切线斜率之间的关系来进行转化.以平行、垂直直线斜率间的关系为载体求参数的值，则要求掌握平行、垂直与斜率之间的关系，进而和导数联系起来求解.4.下列说法正确的是（）A. 若命题都是真命题，则命题“”为真命题B. 命题：“若，则或”的否命题为“若，则或”C. 命题“”的否定是“”D. “”是“”的必要不充分条件【答案】C【解析】试题分析：对于选项，因为命题，都是真命题，所以命题为假命题，所以命题“”为假命题，即选项不正确；对于选项，命题“若，则或”的否命题为“若，则且”，即选项不正确；对于选项，由全称命题的否定为特称命题可知，命题“，”的否定是“，”，即选项是正确的；对于选项，因为“”可得，所以“”是“”的充分条件，反过来显然不成立，所以“”是“”的充分不必要条件，即选项是不正确的．故应选．考点：１、命题及其关系；2、充分条件；3、必要条件．5.设函数，则下列结论错误的是（）A. 是偶函数B. 是奇函数C. 是奇函数D. 是偶函数【答案】D【解析】，所以函数是奇函数，，所以函数，函数是偶函数，就是奇函数，奇偶=奇函数，是偶函数，所以偶奇=奇函数，所以错的是D，故选D.6.函数的零点的个数为（）A. 0B. 1C. 2D. 3【答案】B【解析】【分析】先判断函数为单调增函数，再计算，借助零点存在定理可判断函数零点的个数.【详解】为上的单调增函数，又，，所以在上有一个零点，选B.【点睛】函数零点个数的判断，需利用函数的单调性和零点存在定理来判断，选择怎样的点来计算其函数值且函数值异号是关键，可根据解析式的特点选点，如对于对数等，应选或等，对于指数，应选等形式的数来计算.7.已知，则（）A. B. C. D.【答案】D【解析】，所以，，故选D.8.已知函数，则的值域是（）A. B. C. D.【答案】B【解析】时，，时，，当且仅当时取等号，综上有，故选B．9.三个数的大小顺序是（）A.B.C.D.【答案】D【解析】试题分析：根据题意，由于三个数，那么可知其大小关系为，考点：指数函数与对数函数.10.已知是定义在上的奇函数，当时，（为常数），则的值为（）A. 4B.C.D.【答案】B【解析】由题意，是定义在上的奇函数，当时，（为常数），，，，故有时故选B【dj 】本题考查函数奇偶性质，解题的关键是利用求出参数的值，再利用性质转化求值．11.若函数是上的减函数，则实数的取值范围是（）A. B. C. D.【答案】C【解析】【详解】因为是上的减函数，故，故，选C.【点睛】在上单调的分段函数应该满足在每段上是单调的，除此之外还应考虑函数在分段点处对应的值的大小关系.12.已知关于的方程在上有两解，则实数的取值范围为（）A. B. C. D.【答案】B【解析】，所以问题转化为关于的方程在上有两个不相等的实数根，令函数，则，令函数，则在上有，故在上单调递增，因为，所以当时，有，即，此时单调递减，当时，有，即，此时单调递增，因为，所以实数的取值范围是，故选B.【点睛】已知函数有零点求参数取值范围常用的方法和思路(1)直接法：直接根据题设条件构建关于参数的不等式，再通过解不等式确定参数范围；(2)分离参数法：先将参数分离，转化成求函数值域问题加以解决；(3)数形结合法：先对解析式变形，在同一平面直角坐标系中，画出函数的图象，然后数形结合求解．二、填空题（每题5分，满分20分，将答案填在答题纸上）13.若函数，则__________．【答案】【解析】，，故填：.14.设，若，则的取值范围为_____________．【答案】【解析】【分析】分或分类讨论即可．【详解】若，则，若，则，舎，故，填．【点睛】本题考查分段函数．一般地，分段函数应该根据自变量不同的范围分类讨论．本题题设中的两段上的函数的解析式是确定的，但两段的范围是随的变化而变化的，故应该根据与的大小关系来分类讨论．15. _________.【答案】【解析】【分析】利用诱导公式和特殊角的三角函数值进行计算.【详解】原式.【点睛】一般地，我们可以利用诱导公式把任意的角的三角函数值转化为上的角的三角函数值.诱导公式应用过程中注意“奇变偶不变，符号看象限” .16.直线分别与曲线，交于，，则的最小值为__________．【答案】【解析】当是，由题意可得：，令，则：，当时，，函数单调递增，当时，，函数单调递减，函数的最大值为，据此可知的最小值为2.三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17.已知函数（）（1）求函数的定义域；（2）若函数的最小值为，求的值.【答案】（1）；（2）．【解析】试题分析：（1）要使函数有意义，则有解之得函数的定义域；（2）整理可得，则由复合函数的单调性可得的最小值为，由此可解得a的值．试题解析;；（1）要使函数有意义，则有解之得，所以函数的定义域为．（2）．，，．由，得，．18.已知，且.（1）由的值；（2）求的值.【答案】（1）（2）【解析】【解析】试题分析：（1）先根据诱导公式得,再根据同角三角函数关系求的值；（2）先根据诱导公式化简得,再利用同角三角函数关系化切:,最后将(1)的数值代入化简得结果.试题解析：解：（1）由，得，又，则为第三象限角，所以，所以.（2）方法一：，则方法二：.19.已知函数．（1）求函数的解析式及其最小正周期；（2）当时，求函数的值域．【答案】（1），；（2）.【解析】【分析】（1）把化为可求其最小正周期．（2）先求出的范围，再利用正弦函数求对应的值域．【详解】（1），故．（2）因为，所以，，故函数的值域是．【点睛】形如的函数，可以利用降幂公式和辅助角公式将其化为的形式，再根据复合函数的讨论方法求该函数的单调区间、对称轴方程、值域和对称中心等．20.定义在实数集上的函数.⑴求函数的图象在处的切线方程;⑵若对任意的恒成立，求实数m的取值范围.【答案】（1）；（2） .【解析】【分析】（1）计算后可得到切线的斜率，利用点斜式可得到切线方程.（2）令，利用导数求后解不等式可得实数的取值范围.【详解】（1）∵，当时，，∵，故，∴所求切线方程为.⑵令，故.∴当时，；当时，；当时，；要使恒成立，即.由上知的最大值在或取得.，故，故实数的取值范围.【点睛】解决曲线的切线问题，核心是切点的横坐标，因为函数在横坐标处的导数就是切线的斜率.函数不等式的恒成立问题，可通过构建新函数把恒成立问题归结为新函数的最值来处理.21.已知函数是偶函数．（Ⅰ）求的值；（Ⅱ）设，若函数与的图象有且只有一个公共点，求实数的取值范围．【答案】（1）；（2） .【解析】【分析】（1）利用计算的值即可.（2）函数图像有一个交点等价于方程有且只有一个实根，换元后即为有且只有一个正根，分讨论即可.【详解】（Ⅰ）由函数是偶函数可知：，所以，即对一切恒成立，所以．（Ⅱ）函数与的图象有且只有一个公共点即方程有且只有一个实根，化简得：方程有且只有一个实根．令，则方程有且只有一个正根．(1)，则，不合题意；(2)时，若有两个相等的实数根，则，故或，若，，不合题意；若，，符合题意．若一个正根与一个负根，即，故．综上，实数的取值范围是．【点睛】含参数的奇函数或偶函数，可利用定义求参数的大小，也可以利用特殊值求参数的值（注意检验）．对数方程的解可利用对数的运算性质、换元法等将其转化为一元二次方程在一定范围上的解的问题，从而利用根分布或参变分离求参数的取值范围．22.在平面直角坐标系中，过点的直线的参数方程为为参数)，圆的方程为，以坐标原点为极点，轴的非负半轴为极轴建立极坐标系．(1)求直线和圆的极坐标方程；(2)设直线与圆相交于两点，求的值．【答案】（1）；（2） .【解析】【分析】（1）先求出直线的普通方程，再根据得到相应的极坐标方程．（2）设直线的参数方程为，利用的几何意义可计算．【详解】(1)直线普通方程为，将代入得，，整理得直线的极坐标方程为.圆的极坐标方程为.(2)直线的参数方程为（为参数）将其代入得，所以.【点睛】（1）直角坐标转化为极坐标，关键是，而极坐标转化为直角坐标，关键是．（1）若直线的参数为（参数，为直线的倾斜角），则是之间的距离，我们常利用这个几何意义计算线段的乘积、线段的和或线段的差等．。

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相对原子质量：Zn 65 Cu 64第I卷（选择题)一、单选题1.下列能量的转化过程中，由化学能转化为电能的是( )A B C D铅蓄电池放电风力发电水力发电太阳能发电A. A B. B C. C D. D 2．已知：CH4(g) + 2O2(g) = CO2(g) + 2H2O(l) ΔH = －Q12H2(g) + O2(g) = 2H2O(g) ΔH = －Q2；2H2(g) + O2(g) = 2H2O(l) ΔH = －Q3常温下，取甲烷和氢气体积比为4:1的混合气体11.2L（已折合成标准状况），完全燃烧后恢复至室温，则放出的热量为（）A．0.4Q 1 + 0.05Q 2C．0.4Q 1 + 0.1Q 2B．0.4Q 1 + 0.05Q 3 D．0.4Q1 + 0.1Q 33．50mL0.50mol·L-1盐酸与50mL0.55 mol·L -1NaOH 溶液进行中和反应，通过测定反应过程中所放出的热量可计算中和热，下列说法正确的是A．在测定中和热的实验中，至少需要测定并记录的温度是3次B．大烧杯上如不盖硬纸板，测得的中和热数值会偏小C．用相同浓度和体积的氨水代替NaOH 溶液进行上述实验，测得中和热的数值会偏大D．从实验装置上看，除了缺少环形玻璃搅拌棒外没有其他问题4．下图表示某可逆反应在使用和未使用催化剂时，反应过程和能量的对应关系。

昌吉市教育共同体2019届高三上学期第二次月考（9月）英语试卷考试时间：100分钟分值: 150分第一卷（选择题）一．单项选择（每小题1.5分，共30分）1.Washington, a state in the United States, was named _______one of the greatest American presidents.A. in honor ofB. by means ofC. instead ofD. in remembering of2.. She _______Mr White for two years.A. marriedB. has been married toC. married withD. has bee marrying3. Cell phones are now widely used, _______possible for us to talk to anyone from almost anywhere.A. make itB. to make itC. makingD. making it4. The Chinese people have made great contributions ___the world peace.A. ofB. toC. onD. for5. ______was known to all, he had broken his promise ____he would give us a rise.A. As; whichB. As; thatC. It; thatD. It ; which6. Your composition is good but your handwriting requires _______.A. to improveB. improvedC. being improvedD. improving7. The matter ________your fate cannot be taken for granted.A. relating toB. related toC. relate toD. to related to8. Tom kept quiet about the accident_______ lose his job.A. so not as toB. so as not toC. so as to notD. not so as to9. _________, we’ll support you.A. No matter what happensB. No matter what will happenC. No matter what will be happenedD. No matter what is happened10. He always goes to see his grandmother ___________.A. every other daysB. every few dayC. each few daysD. every few days11. It is high time you ____ your homework.A. doB. have doneC. will doD. did12.. China is separated _____Japan ___the East China Sea.A. of; inB. of; toC. from; toD. from; by13. It was the very place _________ the soldiers fought over sixty years ago.A. thatB. whichC. whereD. there14. Hardly ______ when the bus suddenly pulled away.A. they had got to the bus stopB. they got to the bus stopC. did they get to the bus stopD. had they got to the bus stop15. After the new technique was introduced, the factory produced______ tractors in 1998 as the year before.A. as many twiceB. as twice as manyC. twice as manyD. twice as many as16. The reason __________ more and more young people dream of becoming a famous singer or musicianis __________ they can be millionaires overnight.A. that; thatB. why; becauseC. that; whetherD. why; that17. We, teenagers, have already had the ability to take care of our daily life __________.A. humorouslyB. exhaustedlyC. energeticallyD. independently18. Young people who have got jobs may realize university lessons can’t be the only preparati on for all ofthe situations ________ appear in the working world.A. whereB. whenC. thatD. what19. When Horace finished telling his joke, all the schoolmates __________ at him for 10 seconds or so and then burst into laughter.A. glaredB. staredC. fixedD. spied20. Nowadays the name, Harry Potter, will be _________ to many young readers.A. sensitiveB. familiarC. devotedD. grateful二．完形填空（每小题1.5分，满分30分）You are travelling on an ocean ship when suddenly a giant wave causes the ship to overturn. Hundredsof people die21,but you and several others22in the ballroom. Would you stay there and23for help? Or would you try,24the danger, to find your way out of the ship?This is the25faced by th e characters in the film “Poseidon”.Trapped in the ballroom of the overturned ship, the26orders the surviving guests to wait for help.A small group of people27to accept this fate. They try to escape, knowing that there will be no way back28the captain locks the doors behind them.At the time of the disaster, each of the characters is trying to overcome personal problems in their own lives. All must face their29and make life and death decisions.Architect Richard Nelson is preparing to kill himself when the wave hits. He feels depressed over the 30of his relationship with his partner. But he is forced to fight31his life, and learns to want to live again. He realizes he must32the past and not think too much about the bad.Robert Ramsey, a fireman, decides to33his own life so that his daughter, Jen,34live. He swims to the ship’s control room35he must press a switch to change the direction of the ship.He knows he will likely36in the process, but just as surely, he knows that it’s the only way his friends can escape. His actions give the others a chance to reach37.They escape from the ship just before it38,killing all those waiting inside and Jen’s father as well. All the characters who survive feel 39to be alive, but they are also aware that their own40,bravery and determination saved their own lives.21. A. gradually B. individually C. finally D. immediately22. A. stay B. dance C. survive D. live23. A. ask B. wait C. cry D. demand24. A. despite B. in C. with D. except25. A.position B. scene C.danger D. dilemma26. A. director B. captain C. sailor D. passenger27. A. refuse B. agree C. hesitate D. dislike28. A. unless B. until C. once D. when29. A. death B. survival C. courage D. fears30. A. end B. departure C. failure D. difficulty31. A. against B. for C. with D. over32. A. let alone B. let go of C. let out D. let down33. A. give up B. give away C. give in D. give out34. A. might B. can C. would D. must35. A. which B. there C. where D. then36. A .succeed B. fail C. survive D. drown37. A. safety B. home C. success D. destination38. A. breaks B. explodes C. sinks D. overturns39 .A. relieved B. relaxed C. lucky D. happy40.A. calmness B. choices C. fortune D. confidence三、阅读理解（共15小题；每小题2分，满分40分）（一）篇章阅读ADriving In AmericaKeep RightThe traffic follows the “keep right rule”. While driving, drive on the right side of the road. On one-way, multiple lanes(车道) road, the right-most lane would be slowest and left-most lane is fastest.Hand SignalsThough indicators(车的指示灯) are used for the purpose of showing which direction you are going, knowing some hand signals is very important and are usually always asked in a driving test. When you want to turn right, you can put your left hand out of the window and point upward. When you want to make a left turn, you can reach your left arm out of the window and point to the left. If you want to slow down or stop, you can just point downward.School BusesYellow school buses have flashing red lights and stop signs that reach out from the driver’s side. The drivers use these warning signals when letting pupils on and off. No matter which side of the road you are traveling on, if you come upon a school bus with its lights flashing and a stop sign used, you must stop. It’s the law. Remain stopped until the lights stop flashing or the stop sign is removed.Using the HornUsing horns is not common in America. Actually they are very rarely used. You may use your horn to warn walkers or other drivers of possible trouble or to avoid accidents. Do not use your horn to express anger or co mplain about other drivers’ mistakes or to try to get a slow driver to move faster.41. If Freddy is asked to go to Florida in the shortest time from Missouri, on which lane in the picture belowshould he drive his car according to Paragraph 1?①②③④A. Lane ①.B. Lane ②.C. Lane ③.D. Lane ④.42. What could a driver do in America when turning left?A. Place left hand out of the window pointing upward.B. Put left hand out of the window pointing downward.C. Reach left arm out of the window pointing to the left.D. Place left hand out of the window pointing backward.43. According to the passage, which of the following is possibly accepted in America?A. Use horns sometimes to warn passers-by of danger.B. Drive on before the stop sign on a school bus is removed.C. Use hand signals instead of indicators to show which direction you are going.D. Do not use warning signals in the school bus until all the pupils get on the bus.44. Who is the passage most probably written for?A. Passers-by.B. Pupils.C. Policemen.D. Drivers.BWhat will power your house in the future? Nuclear, wind, or solar power? According to scientists at the Massachusetts Institute of Technology (MIT) in the US, it might be leaves – but man-made ones.Natural leaves are able to change sunlight and water into energy. It is known as photosynthesis (光合作用). Now researchers have found a way to copy this seemingly simple process.The man-made leaf developed by Daniel Nocera and his partners at MIT can be seen as a special chip with catalysts (催化剂). Similar to natural leaves, it can split water into hydrogen and oxygen when put into a bucket of water. The hydrogen and oxygen gases are then stored in a fuel cell (电池), which uses those two materials to produce electricity.A man-made leaf is not a new idea. The first man-made leaf was invented in 1997 but was too expensive and changeable for practical use. The new leaf, on the contrary, is made of cheap materials, easy to use and highly stable. In laboratory studies, Nocera showed that a man-made leaf prototype (原型) could operate continuously for at least 45 hours without a drop in activity.The wonderful improvements come from Nocera’s recent discovery of several powerful, new, inexpensive catalysts. These catalysts make the energy change inside the leaf more efficient with water and sunlight. Right now, the new leaf is about 10 times more efficient at carrying out photosynthesis than a natural one. Besides, the machine can run in whatever water is available; t hat is, it doesn’t need pure water. This is important for some countries that don’t have enough pure water.With the goal to “make each home its own power station” and “giving energy to the poor”, scientists believe that the new machine could be widely used in developing countries, especially in India and rural China.45. What will give power to our house in the future, according to MIT?A. Man-made leaves.B. Nuclear.C. Solar power.D. Wind.46. Which of the following orders correctly shows how the man-made leaf is used to produce electricity?a. man-made leaves split water into hydrogen and oxygenb. the hydrogen and oxygen gases are stored in a fuel cellc. the man-made leaves are put in waterd. the fuel cell uses hydrogen and oxygen to produce electricityA. cbad.B. bcad.C. cabd.D. cadb.47. What does the underlined “stable” in the 4th paragraph mean?A. Secure.B. Powerful.C. Unnatural.D. Unchangeable.48. The aim of the scientists at MIT in developing the new man-made leaves is to .A. build up more power stations in the worldB. provide cheaper energy for developing countriesC. offer people in developing countries access to pure waterD. gain a deeper understanding of the photosynthesis processCThe elephant was lying heavily on its side, fast asleep. A few dogs started barking at it. The elephant woke up in a terrible anger: it chased the dogs into the village where they ran for safety.That didn't stop the elephant. It destroyed a dozen houses and injured several people. The villagers were scared and angry. Then someone suggested calling Parbati, the elephant princess.Parbati Barua's father was a hunter of tigers and an elephant tamer. He taught Parbati to ride an elephant before she could even walk. He also taught her the dangerous art of the elephant round-up -- how to catch wild elephants.Parbati hasn't always lived in the jungle. After a happy childhood hunting with her father, she was sent to boarding school in the city. But Parbati never got used to being there and many years later she went back to her old life. "Life in the city is too dull. Catching elephants is an adventure and the excitement lasts for days after the chase," she says.But Parbati doesn't catch elephants just for fun. "My work," she says, "is to save man from the elephants, and to keep the elephants safe from man." And this is exactly what Parbati has been doing for many years. Increasingly, the Indian elephant is angry: for many years, illegal hunters have attacked it and its home in the jungle has been reduced to small pieces of land. It is now fighting back. Whenever wild elephants enter a tea garden or a village, Parbati is called to guide the animals back to the jungle before they can kill.The work of an elephant tamer also involves love and devotion. A good elephant tamer will spend hours a day singing love songs to a newly captured elephant. "Eventually they grow to love their tamers and never forget them. They are also more loyal than humans," she said, as she climbed up one of her elephants and sat on the giant, happy animal. An elephant princess indeed!49. For Parbati, catching elephants is mainly to .A. get long lasting excitementB. keep both man and elephants safeC. send them back to the jungleD. make the angry elephants tame50. Before Parbati studied in a boarding school, .A. she spent her time hunting with her fatherB. she learned how to sing love songsC. she had already been called an elephant princessD. she was taught how to hunt tigers51. Indian elephants are getting increasingly angry and they fight back because __________.A. they are caught and sent for heavy workB. illegal hunters capture them and kill themC. they are attacked and their land gets limitedD. dogs often bark at them and chase them52. The passage starts with an elephant story in order to explain that in India _________.A. people easily fall victim to elephants' attacksB. the man-elephant relationship is getting worseC. elephant tamers are in short supplyD. dogs are as powerful as elephantsDShe turned up at the doorstep of my house in Cornwall. No way could I have sent her away. No way, not me anyway. Maybe someone had kicked her out of their car the night before. "We're moving house.” "No space for her any more with the baby coming." "We never really wanted her, but what could we have done? She was a present." People find all sorts of excuses for abandoning an animal. And she was one of the most beautiful dogs I had ever seen.I called her Goldie. If I had known what was going to happen I would have given her a more creative name. She was so unsettled during those first few days. She hardly ate anything and had such an air of sadness about her. There was nothing I could do to make her happy, it seemed. Heaven knows what had happened to her at her former owner's. But eventually at the end of the first week she calmed down. Always by my side, whether we were out on one of our long walks or sitting by the fire.That's why it was such a shock when she pulled away from me one day when we were out for a walk. We were a long way from home, when she started barking and getting very restless. Eventually I couldn't hold her any longer and she raced off down the road towards a farmhouse in the distance as fast as she could.By the time I reached the farm I was very tired and upset with Goldie. But when I saw her licking (舔) the four puppies (幼犬) I started to feel sympathy towards them. "We didn't know what had happened to her," said the woman at the door. "I took her for a walk one day, soon after the puppies were born, and she just disappeared." "She must have tried to come back to them and got lost," added a boy from behind her.I must admit I do miss Goldie, but I've got Nugget now, and she looks just like her mother. And I've learnt a good lesson: not to judge people.53. In her first few days at the author's house, Goldie .A. felt worriedB. was angryC. ate a littleD. sat by the fire54. Goldie rushed off to a farmhouse one day because she .A. saw her puppiesB. heard familiar barkingC. wanted to leave the authorD. found her way to her old home55. The passage is organized in order of .A. timeB. effectivenessC. importanceD. complexity（二）七选五Everyone knows that fish is good for health. 56. But it seems that many people don’t cook fish at home. Americans eat only about fifteen pounds of fish per person per year, but we eat twice as much fish in restaurants as at home. Buying, storing, and cooking fish isn’t difficult.57 This text is about how to buy and cook fish in an easy way.58 F resh fish should smell sweet: you should feel that you’re standing at the ocean’s edge. Any fishy or strong smell means the fish isn’t fresh.59 When you have bought a fish and arrive home, you’d better store the fish in the refrigerator if you don’t cook it immediately, but fresh fish should be stored in your fridge for only a day or two. Frozen fi sh isn’t as tasty as the fresh one.There are many common methods used to cook fish. 60 First, clean it and season it withyour choice of spices(调料). Put the whole fish on a plate and steam it in a steam pot for 8 to 10minutes if it weighs about one pound. (A larger one will take more time.) Then, it’s ready to serve.A. Do not buy it.B. The easiest is to steam it.C. This is how you can do it.D. It just requires a little knowledge.E. The fish will go bad within hours.F. When buying fish, you should first smell it.G. The fats in fish are thought to help prevent heart disease.第二卷（非选择题）四．语法填空（每小题1.5分，共15分）阅读下面材料，在空白处填入适当的内容（不多于3个单词）或括号内单词的正确形式。

昌吉市教育共同体2019届高三年级第二次月考数学（文科）试卷考试时间：120分钟 分值: 150分一、选择题（5×12=60）1.已知集合{{},1,,A B m B A ==⊆则m = ( )A.0B.0或3C.1D.1或32.函数2cos y x x =的导数为( )A. 2'2cos sin ?y x x x x =- B. 2'2cos sin y x x x x =+ C. 2'cos 2sin y x x x x =- D. 2'cos sin y x x x x =-3.已知函数()1,0,0x x f x ax x -≤⎧=⎨>⎩,若(1)(1)f f -=,则实数a 的值为( )A. 1B. 2C. 0D. 1-4函数的图像大致是（ ）5.已知函数()y f x =在R 上是增函数且()()2f m f m >-,则实数m 的取值范围是( ) A. (],1-∞- B. ()0,+∞ C.(-1,0) D. (,1)(0,)-∞-⋃+∞6.设函数()f x 的导函数为()'f x ,且()()22'1f x x xf =+,则()'0f = ( )A. 0B. 2C. 4-D. 2-7.函数()2sin cos f x x x x =在区间,42ππ⎡⎤⎢⎥⎣⎦上的最大值是( ) A. 1 B.12+ C. 32D.18.设函数122,1,(){1log ,1x x f x x x -≤=->则满足()2f x ≤的x 的取值范围是( )A. []1,2-B. []0,2C. [)1,+∞D. [)0,+∞9.已知向量()4sin ,cos a αα=-,(1,2)b =-,若2a b ⋅=-,则22sin cos 2sin cos αααα=- ( )A. 1B. 1-C. 27-D. 12- 10.已知函数()sin 0,2y x πωϕωϕ⎛⎫=+><⎪⎝⎭的部分图象如图所示,则( )A. 1ω=,6πϕ= B. 1ω=,6πϕ=-C.2ω=,6πϕ=D. 2ω=,6πϕ=-第10题11.已知,,则( )A. B.C.D.、的夹角为αβ+12.设函数()2xf x =,则下列结论中正确的是( )A.(1)(2)(f f f -<< B.((1)(2)f f f <-< C.(2)((1)f f f <<- D.(1)((2)f f f -<<二、填空题（4×5=20）13.若集合2{|10}x ax x ++=有且只有一个元素,则实数a 的取值集合是___________;14.若非零向量a 、b ,满足a b =,()2a b b +⊥,则a 与b 的夹角为___________; 15在三角形ABC 中，若，则的值是___________;16.下列函数:①232y x x =-+;②(]2,2,2y x x =∈;③3y x =;④1y x =-.其中是偶函数的有___________;三、简答题（17题10分，18-22题每题12分） 17.已知4a =,3b =,()()23261a b a b -⋅+=. 1.求a 与b 的夹角θ; 2.求a b +;18.设全集I R =,已知集合(){}{}2230,6||0M x x N x x x =+≤=+-=1.求()I C M N ⋂2.记集合(),I A C M N =⋂已知集合{}15,|,B x a x a a R =-≤≤-∈若A B A ⋃=,求实数a 的取值范围.19. 已知函数()2sin 2x f x x =- 1.求函数()f x 的最小正周期; 2.求()f x 在区间20,3π⎡⎤⎢⎥⎣⎦上的最小值.20.已知函数()22ln f x x x =-,()2h x x x a =-+.1.求函数()f x 的极值;2. 设函数()()(),k x f x h x =-若函数在[]1,3上恰有两个不同的零点,求实数a 的取值范围.21.已知向量()[],,0,,a cos sin θθθπ=∈向量()3,1.b =-1.若a b ⊥,求θ的值;2.若2a b m -<恒成立,求实数m 的取值范围.22.设ABC ∆的内角,,A B C 的对边分别为,,a b c ,且sin cos b A B =. 1.求角B 的大小;2.若3,sin 2sin b C A ==,求,a c 的值及ABC ∆的周长.参考答案一、选择题1-5 B A B C D 6-10 C C D A D 11-12 C D 1.答案：B 解析：因为,所以或若,则,满足若,解得或①若,则,满足②若,则不满足集合中元素的互异性,舍去 综上,或,故选B2.答案：A解析：函数2cos y x x =,求导得: ()22'2cos sin 2cos sin y x x x x x x x x =+-=-,故选A3.答案：B解析：因为(1)(1)f f -=,所以1(1)a --=,所以2a =,故选B4答案： C解析： [法一]首先看到四个答案支中，A,B 是偶函数的图象，C,D 是奇函数的图象，因此先判断函数的奇偶性，因为 ，所以函数f （x ）是奇函数，排除A 、B ；又x>0时，，选择C 是明显的．[法二]化为分段函数 ，画出图象，选C考点：本题考查函数的图象点评：解决本题的关键是绝对值函数化简为分段函数，或从函数的性质入手，例如奇偶性，周期性，单调性等 5.答案：D 解析： 6.答案：C解析： 7.答案：C 解析：()1cos 212sin 2226x f x x x π-⎛⎫=+=+- ⎪⎝⎭, 因为42x ππ≤≤,所以52366x πππ≤-≤,所以()max 13122f x =+=,故选C. 8.答案：D解析：()112{22x x f x -≤≤⇔≤或21{011log 2x x x >⇔≤≤-≤或1x >,故x 的取值范围是[)0,+∞,故选D 。

新疆昌吉市教育共同体2019届高三生物上学期第二次月考（9月）试题考试时间：80分钟分值: 100分一、单选题（2分，共计50分）1.下列关于乙型肝炎病毒的说法正确的是( )A.能在人体血浆中增殖B.不能寄生在呼吸道黏膜细胞中C.具有细胞结构,但无核膜包裹的细胞核D.能独立完成完整生命活动2.流感病毒是引起流行性感冒的元凶,2018年1月,我国南方及北方大部分城市又爆发了一次大面积的流行性感冒,下面有关流感病毒的说法正确的是( )A.流感病毒结构简单,仅含有核糖体一种细胞器B.用细菌培养基可培养甲型HlNl病毒C.流感病毒侵入人体后,不可以在人体细胞外独立生活D.病毒属于生命系统的最小结构层次3.下列有关实验的说法中,正确的是( )A.在“观察DNA和RNA在细胞中的分布”实验中,加质量分数为0.9%的NaCl溶液(生理盐水)的目的是使DNA与蛋白质分离,便于染色B.在“还原糖的鉴定”和“观察DNA和RNA在细胞中的分布”实验中,需要进行水浴加热或保温C.在“还原糖、蛋白质和脂肪的鉴定”实验中,只有脂肪的鉴定必须用到显微镜D.在“蛋白质鉴定”实验中,向蛋白质溶液中先加入质量浓度为0.1g/mL的NaOH溶液,摇匀,再加入质量浓度为0.5g/mL的CuSO4溶液,出现紫色4.下列关于细胞内的糖类与脂质的叙述,不正确的是( )A.糖类是生物维持生命活动的主要能源物质,也是生物体重要的结构物质B.植物细胞中的多糖主要是淀粉和纤维素,动物细胞中的多糖主要是乳糖和糖原C.脂质中的磷脂是构成细胞膜的重要物质D.脂质在细胞的营养、调节和代谢中具有重要功能5.细胞中各种细胞器的形态、结构不同,在功能上也各有分工。

以下对几种细胞器的说法正确的是( )A.所有真核细胞中都含有图示的五种细胞器B.①与③之间膜成分依靠囊泡进行相互转化C.可以在光学显微镜下观察到的结构有②和⑤D.它们都直接参与咦岛素的合成6.不在内质网上合成或加工的生物分子是( )A.抗体B.胆固醇C.纤维素D.核酸7.下列关于真核细胞生物膜的叙述,正确的是( )A.膜蛋白是生物膜功能的主要承担者B.构成膜的脂质主要是磷脂、脂肪和胆固醇C.细胞膜上的受体也可以是磷脂D.核糖体、内质网、高尔基体三种膜结构共同完成分泌蛋白的合成、加工和运输8.下列关于细胞核各结构和功能的叙述,正确的是( )A.核膜属于生物膜系统B.染色体是遗传物质DNA和RNA的载体C.核仁与蛋白质的合成以及核糖体的形成有关D.核孔有利于DNA和RNA从细胞核进入细胞质9.细胞之间通过信息交流,保证细胞间功能的协调关于细胞间信息交流的说法错误的是( )A.B细胞与C细胞上受体的化学本质都是糖蛋白B.图乙可以表示精子与卵细胞的识别C.若A细胞为胰岛B细胞,则胰岛素通过血液循环最终作用于机体的肝细胞、肌细胞等靶细胞D.细胞膜上的受体是细胞间信息交流所必需的结构10.活细胞中,与酶的合成和分泌直接有关的细胞器是( )A.叶绿体和高尔基体B.核糖体、中心体和高尔基体C.核糖体、内质网和高尔基体D.核糖体、高尔基体和溶酶体11.从细胞膜上提取了某种物质,用一定方法处理后,若加入斐林试剂并加热,出现砖红色沉淀,加入双缩脲试剂则出现紫色,该物质是( )A.蛋白质B.磷脂C.糖蛋白D.糖脂12.下列有关细胞器的说法正确的是( )A.洋葱根尖细胞中的DNA存在于线粒体和细胞核中B.细胞质包括细胞器和叶绿体基质C.内质网与脂质合成无关D.植物细胞中高尔基体与细胞壁的形成无关13.下列有关细胞结构和功能的叙述,正确的是( )A.有内质网的细胞不一定是真核细胞B.有高尔基体的细胞不一定具有分泌功能C.有线粒体的细胞不能进行无氧呼吸D.有核糖体的细胞一定能合成分泌蛋白14.3月24日是世界结核病防治日。