《电路分析基础》习题参考答案
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《电路分析基础》各章习题参考答案
第1章习题参考答案
1-1
(1) SOW; (2) 300
V、25
V,200
V、75
V; (3) R
2=12.50, R
3=1000, R
4=37.50
1-2
V =8.S
V,
V =8.S
V, V
=0.S
V, V
=-12
V,
V =-19
V,
V =21.S
V U
=8
V,
U
=12.5,
A m B D 'AB B
C
U =-27.S
V
DA
1-3 Li
=204
V, E
=205
V
1-4
(1)
VA
=lOO
V ,
V
8=99
V ,
Vc
=97
V ,
V0
=7
V ,
V
E=S
V ,
V
F=l
V ,
UA
F=99
V ,
Uc
E=92
V ,
U
8E=94
V,
UBF
=98
V,
ucA
=-3
V;
(2)
Vc
=90
V,
VB
=92
V,
VA
=93
V,
V
E=-2
V,
VF
=-6
V,
V
G=-7
V,
UA
F=99
V,
uc
E=92
V,
UB
E=94
V,
UBF
=98
V,
U
CA
=-3
V
1-5 R
=806.70, 1
=0.27A
1-6 1
=4A , 1
1 =llA , l
2=19A
1-7
(a)
U=6
V,
(b)
U=24
V,
(c) R
=SO, (d) 1
=23.SA
1-8
(1) i6=-1A; (2) u4=10V ,u6=3 V; (3) Pl =-2W发出，P2=6W吸收，P3=16W
吸收，P4
=-lOW发出，PS
=-7W发出，PG
=-3W发出
1-9 l
=lA, U
5=134V, R
=7.80
1-10 S
断开：UAB=-4.SV, UA0=-12V, UB0=-7.2V; S
闭合：12 V, 12 V, 0 V
1-12 U
AB=llV / 1
2=0.SA / 1
3=4.SA / R
3=2.40
1-13 R
1 =19.88k0, R
2=20 kO
1-14 RP
l =11.110, RP
2=1000
第2章习题参考答案
2-1 2.40, SA
2-2
(1
) 4V , 2V , 1 V
; (2
) 40mA , 20mA , lOmA
2-3 1.50 , 2A , 1/3A
2-4 60
I 360
2-5 2A, lA
2-6 lA
2-7 2A
2-8 lOA
2-9 l
1=1.4A, l
2=1.6A, l
3=0.2A
2-10 1
1 =OA
I l
2=-3A
I p
l =OW
I P
2=-l8W
2-11 1
1 =-lA, l
2=-2A
I E
3=10V
2-12 1
1 =6A, l
2=-3A
I l
3=3A
2-13 1
1 =2A, l
2=1A , l
3=1A , 1
4 =2A, l
5=1A
2-14 U
RL =30V
I 1
1 =2.SA
I l
2=-35A
I I
L =7.SA
2-15 U
ab=6V, 1
1=1.SA, 1
2=-lA, 1
3=0.SA
2-16 1
1 =6A, l
2=-3A
I l
3=3A
2-17 1
1 =4/SA, l
2=-3/4A , l
3=2A , 1
4=31/20A , l
5=-11/4A
2-18 1
1 =0.SA
I l
2=-0.25A
2-19 l
3=1A
2-20 1
5=-lA
2-21
(1
) l
5=0A, U
ab=O
V
; (2
) l
5=1A, U
ab=llV。
2-22 I
L =2A
2-23 l
5=
35/3A, R。
=
20
2-24 180 , -20 , 120
2-25 U =
sv
2-26 l
=lA
2-27 U
= sv
2-28 l=
lA
2-29 lOV , 1800
2-30 U。
=9V,R
0=6
V, Li
=lSV
第3章习题参考答案
3-1 SO Hz , 314rad/s , 0.02s , 141 V , 100V , 120°
3-2 200V , 141.4V
3-3 U=l4.lsin
(314t-60°
) V
3-4
(1
) 中
u
l一中
U2= 120°
t (2
) 屯=
-90°
t 屯=
-210°
·
100·
100
3-5
(1
)互
=
72乙110
°
v
,
u
2 =万乙
-10
0
v
; (2
) u
= lOOsin
(wt+ S0°
)V
3
3-
6 (1) i1=14.1 sin (wt+ 50°
)A; (2) u2=300 sin (wt -
60°
)V
3-8
(1
) R
; (2
)
L ; (3
) C ;
(4
)
L
3-9 i
=2.82 sin
(wt -30°
) A , Q=19.88 var
3-10 U=44.9sin (314t -135°
) V, Q=3.18
var
3-11
(1) 1
=20A
; (2) P
=4.4kW
3-12 1=1.4A,
i=L
4乙30°A; Q=308
var,
P=OW
3-13 1
=9.67A;
i
=9
.67乙1
500A ; Q
=2127.4
var , P
=OW ; lc
=OA
3-14 I=2A; C=20.3µF ; IL= 0.25A, IC= 16A
第4章习题参考答案
4-1
4-2
4-3
4
-4 (a)
z =s乙36.87°n, Y = 0.2乙-36.87°S; (b)
Z=
2.5,,, 已-
4
5°
n , y = 0.2、厅乙36.87°s
Y=(0.06-j0.08) S, R=16.670 , L=0.040
U =111.34乙59.53°V
s
I =20乙36.87°A
4-5
Z=86.31乙79.99°0, l=l.16乙-79.99°A
I u =17.38乙-79.99°V
I LJ =145乙10.01°V, U = 46.4乙-169.99°V
4-6
Y=0.32乙51.34°S,U=6.25乙-51.34°V,I =1.25乙-51.34°A, I =0.31乙-141.34°A, / =1.88乙38.66°A
R
