第一步部分简单程序设计P55.课堂实践（1）#include<stdio.h>main()｛printf(“**********\n”); printf(“**********\n”); printf(“**********\n”);}（2）#include<stdio.h>main<> /*main()*/{printf(“Hello,World.\n);}P95.课堂实践（1）#include<stdio.h>main(){char a=116,b=119,temp;printf(“a=%c,b=%c\n”,a,b); temp=a;a=b;b=temp;printf(“a=%c,b=%c\n”,a,b); }（2）功能：交换x,y的值;#include<stdio.h> main(){ int x,y;x=5; y=10;x=x+y；y=x-y；x=x-y;printf(“%d,%d”,x,y);}（3）c:dec=120,oct=170,hex=78,ASCLL=x 4、输出内容向左靠齐12123.14159260000000000000000000000000 3.14159260000000000000000000000000P115.课堂实践（1）①3.0-(3.0*4)/(4+2)#include<stdio.h>main(){ float x;x=3.0-（3.0*4）/（4+2）;printf(“%f”,x);}②1/2*(2*3+2/(2*2*2))#include<stdio.h>main(){ float x;x=1/2*（2*3+2/(2*2*2));printf(“%f”,x);}（2）%（3）B（4）#include＜stdio. h＞main{x，y，z；/*没有数据类型*/x＋y＝5；/*赋值表达式左边不能是表达式，应为一个变量*/printf("x＋y＝，z＝"，x，y，z)；/*没有输入格式符*/}P135.课堂实践（1）-14（2）(1)x=4,8 (2)8,8（3）#include<stdio.h>mian(){ int x=10;printf(“当x变量的初值为%d时，进行+=运算后的结果为%d”,x,x+=x);printf(“当x变量的初值为%d时，进行-=运算后的结果为%d”,x,x-=x);printf(“当x变量的初值为%d时，进行*=运算后的结果为%d”,x,x*=x);printf(“当x变量的初值为%d时，进行/=运算后的结果为%d”,x,x/=x);}P13习题一、1、C2、C3、A 二、5，-46，12，20P185.课堂实践（1）#include<stdio.h> main(){ int x,y;scanf(“%d%d”,&x,&y); if(x>y)printf(“x>y”); else if(x<y)printf(“x<y”); elseprintf(“x=y”);}（2）#include<stdio.h> main(){ int x,y;scanf(“%d”,&x);if(x>0) y=1;if(x==0) y=0;if(x<0) y= -1;printf(%d”,y);}P215.课堂实践（1）C （2）B （3）B （4）0.500000 （5）不能：#include<stdio.h>main( ){int x,y,z,max;if(z>y){if(z>x)max＝z;else max=x;}else if (y>x)max＝y;else max=x;printf("\nmax＝%d ",max);}P23 略P24习题一、1、D 2、D 3、C 4、D 5、B 6、B 7、B二、1、y%2==0 2、&& || !3、（x>2&&x<3）||(x<-10)4、（ch>=’A’&&ch<=’z’）ch=ch-32;5、1，06、F三、1、#include<stdio.h>main(){int a;scanf("%d",&a);if(a%5==0&&a%7==0)printf("yes");else printf("no");}2、#include<stdio.h>main(){int m;scanf("qingshuru:%d",&m);if((m%4==0&&m%100!=0)||m%400==0)printf("%d shirunnian",m);else printf("%d bushirunnian",m);}3、#include<stdio.h>#include<math.h>main(){ floata,b,c,dise,x1,x2,realpart,imagpart;scanf(“%f%f%f”,&a,&b,&c);printf(“The equation”);if(fabs(a)<=0)printf(“is not a quadratic\n”);else{ dise=b*b-4*a*c;if(dise<=0)printf(“has two aqualroots:%8.4f\n”,-b/(2*a));elseif(dise>0){ x1=(-b+sprt(disc))/(2*a);x2=(-b-sprt(disc))/(2*a);printf(“has distinct real roots:%8.4f and%8.4f\n”,x1,x2);}else{realpart=-b/(2*a);imagpart=sqrt(-disc)/(2*a);printf(“has complex roots:\n”);printf(“%8.4f+%8.4f\n”,realpart,im agpart);printf(“%8.4f-%8.4f\n”,realpart,imagpart);}P285、课堂实践（1）#include<stdio.h>main( ){int key;char ch;printf("*****\n");scanf("%d",&key);printf("????????:\n");while((ch=getchar())!='\n')(ch-key)>122?putchar(ch+122-33-key): ((ch-key)<33?putchar(ch-122-key):putchar (ch-key));}（2）#include<stdio.h>main(){ int i; /*i没有赋值*/int i=1;printf(“output ten numbers：\n”);while(i<=10)printf(“%3d”);/*没有输出参数*/ {printf(“%3d”,i);i++; /*应加｛｝组成复合语句*/ i++;}}P304. 课堂实践（1）#include<stdio.h>main(){ int a,s=0;do{ scanf(“%d”,&a);s+=a;}while(a!=-1);printf(“%d”,s);}（2）#include<stdio.h>main(){ int a,b,r,t,maxB;scanf(“%d%d”,&a,&b);if(a<b){ t=a;a=b;b=t;}r=a%b;while(r!=0){ a=b;b=r;r=a%b;}maxB=b;printf(“maxB is %d”,maxB);}P336. 课堂实践（1）4（2）①#include<stdio.h>main(){int i,j;printf("**九九乘法表**");for(i=1;i<10;i++){ for(j=1;j<=i;j++)printf("%d*%d=%d\t",j,i,i*j);printf("\n");}}②#include<stdio.h>main() {int i=1,j;while(i<10){ j=1;while(j<=i){ printf("%d*%d=%d\t",j,i,i*j);j++;}printf("\n");i++;}}③#include<stdio.h>main(){int i=1,j;do{ j=1;do{ printf("%d*%d=%d\t",j,i,i*j);j++;}while(j<=i);printf("\n");i++;}while(i<10);}（3）#include<stdio.h>main(){ int x;scanf("%d",&x);while(x>0){ printf("%d",x%10);x/=10;prtntf(" ");}}P33习题【参考答案】一、1、D 2、C 3、A 4、A 5、D 6、C 7、D 8、D 9、C 10、B二、1、36 2、3 4、1 3 5、 i<=10 if(j%6!=0)三、1、#include<stdio.h>main(){int a,sum=0;for(a=1;a<=100;a++)if(a%2==1)sum=sum+a;printf("%d",sum);}2、#include<stdio.h> main(){ int i,j,s;int t;int k[100];for(i=1;i<=1000;i++) {s=0;t=0;for(j=1;j<i;j++)if(i%j==0){s+=j;k[t++]=j;}if(i==s){printf("%d shiwanshou %d=",i,i);for(;t>0;)if(t>1)printf("%d+",k[--t]);else printf("%d",k[--t]);printf("\n");}｝3、#include<stdio.h>main(){ int y,t=0;for(y=1008;y<=2008;y++)if(y%4==0&&y%100!=0||y%400==0) { printf(“%d\t”,y);t++;if(t%5==0)printf(“\n”);}}4、#include<stdio.h>main(){ int t,i,x,max,min;scanf(“%d”,&t);max=min=t;for(i=1;i<10;i++){scanf(“%d”,&x);if(max<=x)max=x;if(min>=x)min=x;}printf(“%d\t%d\n”,max,min);}5、#include<stdio.h>main(){ int i,j,p;for(i=1;i<=4;i++){ for(p=1;p<=i;p++)printf(“”);for(j=7;j>=2*i-1;j--)printf(“*”); printf(“\n”);}}P395．课堂实践（1）float compare (float a,b,c) {float k;if (a>=b){ k=a;if(a>=c)k=a;elsek=c;}else{k=b;if(b<=c)k=c;return k;}}（2）最大公约数：int zxgys (int m,n){int i,j,k;if(m>=n)k=n;elsek=m;for(i=1;i<=k;i++){if(m%i==0&&n%i==0) j=i;}return j;}最小公倍数：int zdgbs (int a,int b) {int x,y,k;if(a>=b)k=a;elsek=b;for(x=a*b;x>=k;x- -){if(x%a==0&&x%b==0)y=x;}return y;}P41 课堂实践（1）#include<stdio.h>float zhouchang (float x) {float l;l=2*3.14*x;return l;} float mianji (float y){float s;s=3.14*y*y;return s;}voide main (){float r;scanf("%f",&r);float m,n;m=zhopuchang (r);n=mianji (r);printf("m=%f\nn=%f\n",m,n); }（2）float add (float x,float y) {Float z;Z=x+y;Return z;}float sub(float h,float k) {float w;w=h-k;return w;}float mul(float m,n){float i;i=m*n;return i;}float div(float e,f) {float g;g=e/f;return g;}void main(){float p,g;scanf("%f%f",&p,&g); char a;lscanf("%c",&a);float j;if(a=='+'){j=add(p,g);}else if(a=='-'){j=sub(p,g)}else if (a=='*'){j=mul(p,g)}else if (a=='/'){j=div(p,g)}printf("'%f",5);}P43习题一．选择1.B 2.D 3.D 4.A 5.C 6.B 7.B 8.B 9.A 10.D 二．填空1.函数首部和函数体2.void add; float add;3.1,1,14. 1,2,3;5. break; scanf(“%c”,&ch);6. x=4 y=9 z=57.first:14 ,4 ,12second:26 ,4 ,12third:26 ,3 ,68. a+b=99. 810. 125三．1．#include<stdio.h>#include<math.h>fun (int x,int y){int m;m=x-y;m=abs(m);return m;}2． void deb (int x){int i;for(i=2;i<=x;i++){if(x%i==0)break;}if(i>=x)printf("%d is su shu\n",x);}3. 略第二部分程序设计算法示例P676.(1)#include<stdio.h>main(){int b,m,l;for(b=1;b<20;b++){for(m=1;m<33;m++){l=100-m-b;if(5*b+3*m+l/3==100)printf("%d%d%d\n",b,m,l)}}}(2) #include<stdio.h> main(){int a,b,c,d;for(a=1;a<10;a++){for(b=1;b<20;b++){ for(c=1;c<50;c++){d=40-a-b-c;if(10*a+5*b+2*c+d==100) printf("%d,%d,%d,%d\n",a,b,c,d);}}}}P705.(1)#include<stdio.h>main(){int a,b,c;c=2;for(a=2;a<=3;a++){if(a==c)continue;b=6-a-c;if(b==c)continue;if(a==3)printf("a与z是对手\n");if(b==1)printf("b与x是对手\n");printf("c与y是对手\n");}}5.(2)#include<stdio.h>main (){int d=5;int a,b,c,e,f,g;for(a=1;a<=7;a++){if(a==d)continue;for(b=1;b<=7;b++){if(b==a||b==d)continue;for(c=1;c<=7;c++) {if(c==a||c==b||c==d)continue;for(e=1;e<=7;e++){if(e==a||e==b||e==c||e==d)continue;for(f=1;f<=7;f++){ if(f==e||f==d||f==c||f==b||f==a) continue;g=(23-a-b-c-e-f);if(g==f||g==e||g==d||g==c||g==b||g==a) continue;}}}}}printf("a=%d\nb=%d\nc=%d\nd=%d\ne=%d \nf=%d\ng=%d\n",a,b,c,d,e,f,g);}5.(3) 略P71习题一、1. B2. D3. C4.C,D二．1.2*x+4*y==90;2.14三．1.#include<stdio.h>main (){int a,b,c;for(a=1;a<=9;a++){for(b=0;b<=9;b++){for(c=0;c<=9;c++){if(a*a*a+b*b*b+c*c*c==100*a+10*b+c) printf("%d%d%d\n",a,b,c)；}}}}2#include<stdio.h>main (){int bh,mh,lh;for(bh=1;bh<=40;bh++){for(mh=1;mh<=50;mh++){lh=100-bh-mh;if(3*bh+2*mh+lh/2) printf("bh=%d\nmh=%d\nlh=%d\n");}}}P755.#include<stdio.h>main (){float x1,x2;x1=1.5;x2=(x1+1/x1)/2;while(x1=x2){x1=x2;x2=(x1+1/x1)/2;}printf("%f",x2);}P765.（1）略5.（2）#include<stdio.h>main (){int day=1;int x1=0,x=0;float j;while(x1<100){x=day*2;day++;x1+=x;}j=x1*0.8/(day-=1);printf("%f",j);}P76习题一1.（1）B（2）D2. （1）C （2）A二1.（1）x1==0(2) x/0.5-22.sum%4==0三略P80.5、课堂实践#include <stdio.h>void main(){ long int f1,f2;int i;f1=1; f2=1;for(i=1;i<=20;i++){printf(“%4ld %4ld”,f1,f2); if(i%2==0) printf(“\n”);f1=f1+f2; f2=f2+f1;} }P81.5、课堂实践#include <stdio.h>#include <math.h>int s(int a,int b){ int g;if( b= =0)g=1;elseg=pow(a,b);return(g);}main(){ int x,y,m;Scanf(“%d,%d”,&x,&y);m=s(x,y);printf(“%d”,m);}P81.习题一、1、(1) age(n-1)+2 (2)age(n)2、计算Fibonacci数列第7项元素 k=13二、略P85.略P93.5、课堂实践(1) D (2) C (3) C (4)D(5)#include <stdio.h>main(){ int a[5],s[5];int i;for(i=0;i<5;i++)scanf(“%d”,&a[i]);for(i=0;i<5;i++){ s[i]=a[i]+5;printf(“%d”,s[i]);}}P96.5、课堂实践（1）#include <stdio.h>void main(){ inta[10]={265,301,751,129,937,863,742,694,7 6,438};int i,j,t;for(j=0;j<9;j++)for(i=0;i<9-j;i++)if(a[i]>a[i+1]){ t=a[i];a[i]=a[i+1];a[i+1]=t;}for(i=0;i<10;i++)printf(“%d ”,a[i]);}（2）.补充直接插入排序原理。
