2015-2016商丘市一高高一期中考试试卷
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河南省商丘市高一上学期期中数学试卷姓名:________ 班级:________ 成绩:________一、填空题 (共14题;共17分)1. (1分)已知集合U={1,2,3},A={1,3},B={1,3,4},则=________ .2. (1分)(2020·宝山模拟) 不等式的解集是________3. (1分) (2016高一上·南充期中) 函数y=ax﹣4+1(a>0,a≠1)的图象恒过定点P,P在幂函数f(x)的图象上,则f(x)=________.4. (2分) (2016高一上·西湖期中) 函数f(x)= 的定义域是________;值域是________.5. (2分) (2016高三上·嵊州期末) 已知函数,g(x)=2x﹣1,则f(g(2))=________,f[g(x)]的值域为________.6. (1分)已知a=, b=,,则a,b,c的大小关系为________7. (1分) (2016高一上·普宁期中) 化简(log43+log83)(log32+log92)=________.8. (1分) (2016高一下·太康开学考) 函数的单调增区间是________.9. (1分) (2017高一上·扬州期中) 若函数f(x)=﹣x2+2ax与函数g(x)= 在区间[1,2]上都是减函数,则实数a的取值范围是________.10. (1分) (2017高二下·淮安期末) 若f(x)= ,则f(f())=________.11. (1分)定义运算则函数f(x)=1*2x的最大值为________12. (1分) (2015高一下·仁怀开学考) 已知函数f(x)= ,若f[f(0)]=4a,则实数a等于________.13. (2分) (2016高三上·湖州期末) 已知函数f(x)=sin2x+2cos2x(x∈R),则f()=________,函数f(x)的最大值是________.14. (1分) (2016高一上·浦东期末) 不等式的解集为________.二、解答题 (共6题;共40分)15. (5分)设全集U=R,集合A={x|﹣1≤x<3},B={x|2x﹣4≥x﹣2}.(1)求∁U(A∩B);(2)若集合C={x|2x+a>0},满足B∪C=C,求实数a的取值范围.16. (10分) (2016高一上·清远期末) 计算下列各式的值.(1);(2).17. (5分) (2017高三上·襄阳开学考) 已知函数f(x)=loga(﹣mx)在R上为奇函数,a>1,m>0.(Ⅰ)求实数m的值;(Ⅱ)指出函数f(x)的单调性.(不需要证明)(Ⅲ)设对任意x∈R,都有f( cosx+2t+5)+f( sinx﹣t2)≤0;是否存在a的值,使g(t)=a﹣2t+1最小值为﹣.18. (10分) (2016高一上·海安期中) 小张在淘宝网上开一家商店,他以10元每条的价格购进某品牌积压围巾2000条.定价前,小张先搜索了淘宝网上的其它网店,发现:A商店以30元每条的价格销售,平均每日销售量为10条;B商店以25元每条的价格销售,平均每日销售量为20条.假定这种围巾的销售量t(条)是售价x(元)(x∈Z+)的一次函数,且各个商店间的售价、销售量等方面不会互相影响.(1)试写出围巾销售每日的毛利润y(元)关于售价x(元)(x∈Z+)的函数关系式(不必写出定义域),并帮助小张定价,使得每日的毛利润最高(每日的毛利润为每日卖出商品的进货价与销售价之间的差价);(2)考虑到这批围巾的管理、仓储等费用为200元/天(只要围巾没有售完,均须支付200元/天,管理、仓储等费用与围巾数量无关),试问小张应该如何定价,使这批围巾的总利润最高(总利润=总毛利润﹣总管理、仓储等费用)?19. (5分)已知函数f(x)=log4(4x+1)+kx(k∈R)是偶函数.(1)求k的值;(2)设g(x)=log4(a•2x﹣a)(a<100),若函数f(x)与g(x)的图象只有一个公共点,求整数a的个数.20. (5分) (2018高二下·长春期末) 已知函数 .若在上的值域为区间,试问是否存在常数,使得区间的长度为?若存在,求出所有的值;若不存在,请说明理由(注:区间的长度为).参考答案一、填空题 (共14题;共17分)1-1、2-1、3-1、4-1、5-1、6-1、7-1、8-1、9-1、10-1、11-1、12-1、13-1、14-1、二、解答题 (共6题;共40分)15-1、16-1、16-2、17-1、18-1、18-2、19-1、20-1、。
商丘一高2015~16学年第二学期期中考试高一语文试卷命题人:张宏亮审题人:卞洪建注意事项:1.本试卷分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分,时间150分钟,满分150分。
答卷前,考生务必将自己的班级、姓名、准考证号填写在本试卷和答题纸相应位置上,并在答题卷上张贴自己的条形码2.作答时,将答案写在答题纸上。
写在本试卷上无效。
第Ⅰ卷阅读题甲必考题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1~3题。
家风是核心价值观的微观体现①“家风”是一个家族开展教育的起点。
在传统中国,社会教育不发达,人的成长往往依赖家庭教育。
许多大的家族组织,承担着对本家族成员的社会保障的任务。
家族成员之间通过礼仪性的活动取得联系,同时也接受家族的集体约束。
在这一层面,家风家训好比家族“纲领”,指导和规训着每一位家族成员的生活和行为。
②“家风”还是家族的共识性的道德观念。
无锡《锦树堂钱氏宗谱》所记载钱氏《家训》,可以概括为“孝、悌、忠、信、礼、义、廉、耻”八字。
在传统社会,家风往往是儒家核心价值观念的具体展开,因族群的生活环境及文化传统不同,侧重会略有不同,但无外乎是教人向善、积极进取、勤劳节俭。
③在每一个具体的家族中,家风不仅仅是道德教化的口号,还是家族精神的体现,通过代代家族成员具体的行为而践行和传承。
有的历史人物,可能和这个家族并无直接的血缘关系,但是因为姓氏相同往往也被说成是本族的祖先。
用祖先的荣耀和事迹,增强自身的荣誉感和尊严感,凝聚家族成员,使他们对于姓氏家族本身产生认同。
家风实际是一种经过历史积累而形成的精神尺度。
④中共中央办公厅印发的《关于培养和践行社会主义核心价值观的意见》,为积极培育和践行社会主义核心价值观指明了方向:国家层面倡导富强、民主、文明、和谐,社会层面倡导自由、平等、公正、法治,公民层面倡导爱国、敬业、诚信、友善。
这是对社会主义核心价值观的高度概括,反映了现阶段全国人民价值观的“最大公约数”。
商丘一高2015-2016学年第二学期期中考试高一物理试卷命题人:李建设审题人:李新林一、选择题:(本大题共12小题,每小题4分,共48分,1-8小题在每小题给出的四个选项中,仅有一项符合要求;9-12小题有多项正确。
部分对2分,有错选零分)1、如图所示,质量为m的物体置于倾角为θ的斜面上,物体与斜面间的动摩擦因数为μ,在外力作用下,斜面体以加速度a沿水平方向向左做匀加速运动,运动中物体m与斜面体相对静止。
则关于斜面对m的支持力和摩擦力的下列说法中错误..的是()A.支持力一定做正功B.摩擦力一定做正功C.摩擦力可能不做功D.摩擦力可能做负功2、如图,蹦床是青少年喜欢的一种体育活动,蹦床边框用弹簧固定有弹性网角,运动员从最高点落下直至最低点的过程中,空气阻力大小恒定,则运动员()A.机械能一直减少B.刚接触网面时,动能最大C.重力做功等于克服空气阻力做功D.重力势能的减少量等于弹性势能的增加量3、光盘驱动器在读取内圈数据时,以恒定线速度方式读取。
而在读取外圈数据时,以恒定角速度的方式读取。
设内圈内边缘半径为R1,内圈外边缘半径为R2,外圈外边缘半径为R3。
A、B、C分别为内圈内边缘、内圈外边缘和外圈外边缘上的点。
则读取内圈上A点时A点的向心加速度大小和读取外圈上C点时C点的向心加速度大小之比为()A.B.C. D.4、近地卫星线速度为7.9 km/s ,已知月球质量是地球质量的,地球半径是月球半径的3.8倍,则在月球上发射“近月卫星”的环绕速度约为()A .B .C .D .5、如图所示,有两个同样的球,其中a 球放在不导热的水平面上,b 球用细线悬挂起来,现供给a 、b 两球相同的热量,则两球升高的温度 ( )A .>B . =C .<D .无法比较.6、物体m 用线通过光滑的水平板间小孔与砝码M 相连,并且正在做匀速圆周运动,如图所示.如果减少M 的重量,则物体m 的轨道半径r ,角速度ω,线速度v 的大小变化情况是()2132R R R 2231R R R 3221R R R 3122R R R 811s km /0.1s km /5.1s km /7.1s km /0.2a t ∆b t ∆a t ∆b t ∆a t ∆b t ∆A .r 减小,ω不变B .r 不变,v 变小C .r 减小,v 不变D . r 增大,ω减小7、美国航空航天局2009年6月发射了“月球勘测轨道器”(LRO),LRO 每天在离月球表面50 km 的高度穿越月球两极上空10次。
高一语文试卷注意事项:1.本试卷分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分,时间150分钟,满分150分。
答卷前,考生务必将自己的班级、姓名、准考证号填写在本试卷和答题纸相应位置上,并在答题卷上张贴自己的条形码2.作答时,将答案写在答题纸上。
写在本试卷上无效。
第Ⅰ卷阅读题甲必考题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1~3题。
家风是核心价值观的微观体现①“家风”是一个家族开展教育的起点。
在传统中国,社会教育不发达,人的成长往往依赖家庭教育。
许多大的家族组织,承担着对本家族成员的社会保障的任务。
家族成员之间通过礼仪性的活动取得联系,同时也接受家族的集体约束。
在这一层面,家风家训好比家族“纲领”,指导和规训着每一位家族成员的生活和行为。
②“家风”还是家族的共识性的道德观念。
无锡《锦树堂钱氏宗谱》所记载钱氏《家训》,可以概括为“孝、悌、忠、信、礼、义、廉、耻”八字。
在传统社会,家风往往是儒家核心价值观念的具体展开,因族群的生活环境及文化传统不同,侧重会略有不同,但无外乎是教人向善、积极进取、勤劳节俭。
③在每一个具体的家族中,家风不仅仅是道德教化的口号,还是家族精神的体现,通过代代家族成员具体的行为而践行和传承。
有的历史人物,可能和这个家族并无直接的血缘关系,但是因为姓氏相同往往也被说成是本族的祖先。
用祖先的荣耀和事迹,增强自身的荣誉感和尊严感,凝聚家族成员,使他们对于姓氏家族本身产生认同。
家风实际是一种经过历史积累而形成的精神尺度。
④中共中央办公厅印发的《关于培养和践行社会主义核心价值观的意见》,为积极培育和践行社会主义核心价值观指明了方向:国家层面倡导富强、民主、文明、和谐,社会层面倡导自由、平等、公正、法治,公民层面倡导爱国、敬业、诚信、友善。
这是对社会主义核心价值观的高度概括,反映了现阶段全国人民价值观的“最大公约数”。
⑤从家风到社会主义核心价值观,一个具体现实,另一个宏观抽象,二者其实存在深刻的内在联系。
河南省商丘第一中学高一2015届语文下学期期中(文科)试卷语文5.4本试卷,150分。
考试时长120分钟。
考生务必将答案答在答题卡上,在试卷上作答无效。
考试结束后,将本试卷和答题卡一并交回。
一、选择题共8小题,每小题5分,共40分。
在每小题列出的四个选项中,选出符合题目要求的一项。
1.下列各句中,加点的成语使用恰当的一句是A.中国小说史上多续书,但几乎没有一部续书的艺术价值可以与原书相媲美,这是无庸置喙的。
B.每到工作总结、评先进时,这些假话、空话、大话恰好迎合了某些人急功好利的心理。
C.每到安排工作时,年过五十的老曹总爱在年青同志面前指指点点,说这说那,一副老气横秋之态。
D.不管是科学奖,还是人文奖,诺贝尔奖还是第一大奖,许多人视其为殊荣,得主大多受宠若惊,但也有人不以为然,拒绝领奖,德国的斯埃特斯就是一例。
2. 依次填入下列各句横线处的词语,恰当的一组是①由达成共识到制订计划,______欧盟在军事一体化道路上迈出了可喜的一步。
②领导既然这样要求,虽然时间紧,任务重,我们也只能________而为之了。
③实践证明,人的大脑愈用愈发达,不用则会_______________。
A.表明勉励蜕化B.说明勉力蜕化C.说明勉励退化D.表明勉力退化3.下列各项词语中,没有错别字的一项是( )A.股分公司份内份外省份年份一份文件B.反应灵活反映情况反应强烈反映真实C.致命一击致关重要闲情逸致专心致志D.理屈词穷曲突徙薪能曲能伸屈打成招4.下列各组词语中加点字的读音,与所给注音全都相同的一组是A.差(chā) 差错误差差强人意差可告慰B解(jiě) 解决押解浑身解数不求甚解C.塞(sè) 堵塞边塞闭目塞听敷衍塞责D.提(tí) 提炼提防提纲挈领耳提面命5.下列词语没有错别字的一项是A.毕躬毕敬按部就班防患未然雷霆万钧B.不记其数发奋图强和盘托出恍然大悟C.荒谬绝伦琅琅上口滥竽充数死心塌地D.故弄悬虚东拼西凑哄堂大笑破釜沉舟6. 下列各组词语中加点的字的读音,与所给注音全都相同的一组是:A.角jiǎo 号角角落头角群雄角逐B.笼lóng 笼子牢笼笼屉烟笼雾锁C.量liáng 思量打量测量量体裁衣D.削xuē剥削削减瘦削日削月割7. 下列词语中加点的字的注音全都不相同的一组是A坡度被覆偏颇推波助澜披星戴月B枯竭髅蝼估计沽名钓誉怙恶不悛C碑文牌匾裨益沁人心脾纵横捭阖D矩形沮丧狙击踽踽独行前倨后恭8. 下列熟语使用不正确的是()A、目前,全球各主要军事强国对隐形军舰的研发,乐此不疲。
商丘一高2015-2016学年第二学期期中考试高一英语试卷注意事项:1. 本试卷分第I卷(选择题)和第II卷(非选择题)两部分2. 答题前,考生务必将自己的姓名、准考证号填写在本试卷相应的位置。
3. 全部答案在答题卡上完成,答在本试卷上无效。
第I卷第一部分听力(免)第二部分阅读理解(共两节,满分60分)第一节(共15小题;每小题3分,满分45分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。
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The purpose of the first advertisement is to _____ .A. build a bridge between guitar playersB. attract guitar players to attend music classesC. look for teachers for several music schoolsD. help guitar beginners to improve their techniques2. Who will probably contact 510-333-9091?A. A dancer lover.B. A Hip-Hop lover.C. A music lover.D. A Qi Gong lover.3. How much can you save if you pay for eight classes at one time before you join Halanda Studio?A. $12.B. $8.C. $6.D. $3.BBrad closed the door slowly as Sue left home to visit her mother. Expecting a whole day to relax,he was thinking whether to read the newsp aper or watch his favorite TV talk show on his first day off in months. “This will be like a walk in the park,”he’d told his wife. “I’ll look after the kids,and you can go visit your mom.”Things started well,but just after eight o’clock,his three little “good kids”—Mike,Randy,and Alex—came down the stairs in their night clothes and shouted “breakfast,daddy.” When food had not appeared within thirty seconds,Randy began using his spoon on Alex’s head as if it were a drum. Alex started to shout loudly in time to the beat(节拍).Mike chanted “Where’s my toast,where’s my toast” in the background. Brad realized his newspaper would ha ve to wait for a few seconds.Life became worse after breakfast. Mike wore Randy’s underwear on his head. Randy locked himself in the bathroom,while Alex shouted again because he was going to wet his pants. Nobody could find clean socks,although they wer e before their very eyes. Someone named “Not Me” had spilled a whole glass of orange juice into the basket of clean clothes. Brad knew the talk show had already started.By ten o’clock,things were out of control. Alex was wondering why the fish in the jar refused his bread and butter. Mike was trying to show off his talent by decorating the kitchen wall with his color pencils. Randy,thankfully,appeared to be reading quietly in the family room,but closer examination showed that he was eating apple jam straight from the bottle with his hands. Brad realized that the talk show was over and reading would be impossible.At exactly 11∶17,Brad called the daycare centre(日托所).“I suddenly have to go into work and my wife’s away. Can I bring the boys over in a few min utes?”The answer was obviously “yes” because Brad was smiling.4.When his wife left home,Brad expected to________.A. enjoy his first day off workB. watch TV talk show with his childrenC. go out for a walk in the parkD. read the newspaper to his children5.Which of the following did Randy do?A. Drawing on the wall.B. Eating apple jam.C. Feeding the fish.D. Reading in a room.6.Why did Brad ask the daycare centre for help?A. Because he wanted to clean up his house.B. Because he suddenly had to go to his office.C. Because he had to take his wife back home.D. Because he found it hard to manage his boys.7.This text is developed________.A. by spaceB. by timeC. by processD. by comparisonCMy students often tell me that they don't have "enough time" to do all their schoolwork.My repl y is often a brief "You have as much time as the president." I usually carry on a bit about there being twenty-four hours in the day for everyone, and suggest that "not enough time" is not an acceptable explanation of not getting something done.Once in graduate school, I tried to prove to one of my professors by saying that I was working hard. His answer to me was, "That's irrelevant (无关的). What's important is the quality of your work." Since then I have had time to think carefully about the "hard worker" dodge (诀窍), and I have come to some conclusions- all relevant to the problem of how much time we have.If you analyze the matter, you can identify two parts of the problem: There is, of course, t he matter of "time", which we can think of as fixed. Then there is the problem of "work" during that time. But, as my professor suggested, it's not how hard one works but the quality of the product that's important.That led me to a new idea: the quality of the work. That concept is perhaps best explained by a sign I once saw on the wall in someone's office: "Don't work harder. Work smarter." There is a lot of sense in that idea.If you can't get more time, and few of us can, the only solution is to improve the quality of the work. That means thinking of ways to get more out of the same time than we might otherwise get. That should lead us to an analysis of our work habits. Since "work" for students usually means "homework", the expressi on "work habits" should be read as "study habits".Then, as a smart student, you will seek to improve those skills that you use in study, chiefly reading and writing. If you learn to read better and write better, there are big benefits that pay off in all your studies.8. From the passage, we know that the author is probably ______.A. a poetB. an engineerC. a novelistD. an educator9. We can infer from the 2nd paragraph that we students still _____.A. have enough timeB. can meet the presidentC. get everything done wellD. should accept the explanation10. Which of the following is TRUE according to the passage?A. The author's students make good use of their time to do all their homework.B. The author tried to tell the professor that he/she (author) had done a good job.C. You can't improve the quality of the work if you can't get more time.D. You'll try to improve your skills in reading and writing if you're a clever student.11. What's the passage mainly about?A. Students don't have enough time.B. No one can get more time.C. Don't work harder; work smarter.D. Read better and write better.DWhen I was about twelve, I headed to a rest aurant for dinner with my family. It was winter, and on that particular night, the wind was really blowing. As my mom and I headed towards therestaurant from our car, a girl about my age and her mother came up to us. They asked if we had any spare change. My mom immediately asked where they kept their things. They pointed to an old car in a parking across the street. The girl said there were six of them living in that car, which was the same size as my own family.My mom said she had something to do after handing the people a few dollars. She sent me inside the restaurant with my dad and my three siblings. But she didn’t come.Later, I found out she had gone home and practically emptied our cupboards into a few bags. Then, she brought that food over to the car and handed the bags to the family. I wasn’t there when that part happened, but I can only imagine the joy it brought to their faces.A few days later, when I actually found out about what she had done, I asked her why she helped those people. She told me that they were not lucky. I remember the face of that girl who had asked us for change, she was the same age as me, yet we looked so different.Here I stood, dressed in almost new clothes, headed to dine in a restaurant and then back home to the bedroom I shared with my younger sister. I remember thinking that the ot her girl didn’t have any food to eat. and she was heading back to a cold car shared with five other people.After painting this picture in my mind, I understood why my mom had done what she did. I will never forget what she did that night, and how she taught me one of the best lessons I ever learned.12. What can be inferred from the first paragraph?A. The girl’s family lived a hard life.B. The author was happy to go to a restaurant.C. The girl’s family lived in an old house.D. The author’s famil y was the same size as the girl.13. Which of the following best describes the author’s mother?A. Reliable and determined.B. Considerate and enthusiastic.C. Cautious and friendly.D. Unusual and optimistic.14.What might be the author’s purpose in writing the text?A. To tell us to show love to others.B. To seek help for the poor family.C. To give a brief introduction of her mother.D. To complain about some social problems.15.What is the best title of the passage?A. How to support the poor familyB.A friend in need is a friend in deedC. the hard life of a little girl’s familyD.A lesson in kindness from my Mum第二节(共5小题;每小题3分,满分15分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。
河南省商丘市第⼀⾼级中学2015-2016学年⾼⼀⽣物下学期期中试题(新)商丘⼀⾼2015?16学年第⼆学期期中考试⾼⼀⽣物试卷⼀、选择题(每题2分,共60分)1、下列性状中属于相对性状的是A.⼈的⾝⾼和体重B.兔⼦的直⽑和卷⽑C.猫的⽩⽑与蓝眼D.棉花的细绒与长绒2、下列说法中正确的是A.表现型相同的⽣物,基因型⼀定相同B.D和D, D和d,d和d都是等位基因C.纯合⼦⾃交后代中不会发⽣形状分离D.隐形性状是指⽣物体不能表现出来的性状3、下列有关孟德尔遗传定律的说法错误的是A.叶绿体基因控制的性状遗传不遵循孟德尔遗传定律B.受精时雌雄配⼦的结合是随机的,这是得出孟德尔遗传定律的条件之⼀C.孟德尔发现分离定律与⾃由组合定律的过程运⽤了假说-演绎法D.任何基因型为AaBb的⽣物个体⾃交,其后代⼀定有4种表现型和9种基因型4、抗维⽣素D佝偻病为X染⾊体显性遗传病,短指为常染⾊体显性遗传病,红绿⾊盲为X染⾊体隐形遗传病,⽩化病为常染⾊体隐性遗传病。
下列关于这四种遗传病遗传特征的叙述,正确的是A.短指的发病率男性⾼于⼥性B.抗维⽣素D佝偻病的发病率男性⾼于⼥性C.⽩化病通常会在⼀个家系的⼏代⼈中连续出现D.红绿⾊盲⼥性患者的⽗亲是该病的患者5、与有丝分裂相⽐,减数分裂过程中染⾊体最显著的变化之⼀是A.染⾊体移向细胞两极B.同源染⾊体联会C.有纺锤体形成D.着丝点分开6、对DNA指纹技术应⽤的理论依据是A.碱基互补配对原则B.遗传性状由基因控制C.DNA分⼦具有多样性D.DNA分⼦具有特异性7、下列关于孟德尔研究遗传规律获得成功原因的叙述,错误的是A.先分析多对相对性状,后分析⼀对相对性状B.科学地设计实验程序,提出假说并进⾏验证C.正确地选⽤豌⾖作为实验材料D.运⽤统计学⽅法分析实验结果8、控制植物果实重量的三对等位基因A—a、B—b和C—c,对果实重量的作⽤相等,分别独⽴遗传。
已知基因型为aabbcc的果实重120克,AABBCC的果实重210克。
商丘市一高2015~2016学年第二学期期中考试高一地理试卷一:单选题(每题1.5分,共40×1.5﹦60分)读“我国珠江三角洲某市人口增长示意图”,完成1~2题。
1.有关该市人口数量变化的说法,正确的是()A.该市人口数量呈下降趋势B.从总体上看,该市人口数量的变化以自然增长为主C.影响该市人口迁移的因素主要是经济因素D.该市人口自然增长率呈上升趋势2.2004年以来该市人口机械增长呈下降趋势,其原因正确的是()A.该市因经济发展速度减缓而出现“民工荒”B.该市生态环境恶化,人口迁入量减少C.农村生存环境已好于城市D.是由于京津唐、长江三角洲地区经济的发展右图示意1990---2011年某城市人口自然增长率和净迁入率变动情况 读图回答3---4题。
3.该城市人口增长最快的年份是()A. 2008年B. 2002年C. 1999年D. 2011年4.该市人口总量最多和最少的年份分别是()A.2011年 1990年 B. 2011年 1993年C.2008年 1990年 D. 2008年 1993年人口的性别结构是指一个国家或地区两性人口数量的比例关系,它通常由性别比这个指标加以度量。
性别比为平均每100名女性所对应的男性人口的数量。
读右图完成5~6题。
5.一般情况下,当曲线①的峰谷出现时会引起( )A .人口老龄化B .人口增长率加快C .人口素质提高D .人口增长率减慢6.若图中曲线①代表珠江三角洲工业区的性别比,造成20世纪80年代性别比较低的原因可能是 ( )A .大量男性劳动力迁入B .当地重男轻女的思想严重C .不同性别的死亡率不同造成的一种自然现象D .大量女性劳动力迁入某学校研究性学习小组的学生通过调查,记录了该地区农事活动的时间表。
分析回答7~8题。
7.该地区可能位于我国的 ( )A .三江平原B .洞庭湖平原C .华北平原D .珠江三角洲8.该地区发展农业生产的主要限制性因素可能是( )A .低温、冻害B .地形、水源C .光照、风沙D .旱涝、盐碱 北海道(如右图所示)是日本重要的农业地区。
2015-2016学年度第一学期期中考试卷九年级物理一、填空题(每空1分,共14分)1、火柴可以擦燃,也可以放在火上点燃,前者是用__________的方法使火柴燃烧,后者是用__________的方法使火柴燃烧,两种方法都可以改变物体的内能。
2、汽油的热值是4.6×107J/kg,完全燃烧210g汽油能放出______________的热量;若这些热量的一半被水吸收,可使_______kg水,从20℃升高到40℃(水的比热容为4.2×107J/(k g·℃)。
3、内燃机的一个工作循环有四个冲程,下图中表示的是其中的________冲程;它将______能转化成机械能。
4、有两只定值电阻,甲标有“15Ω 0.6A”,乙标有“10Ω 1A”,现将它们串联起来接到某电源两端,为了不损坏电阻,该电源电压不能超过______V;若将它们并联起来,在不损坏电阻的情况下,干路上最大电流是_______A。
5、如图所示,电源电压恒定,R1=30Ω,R2=60Ω。
当开关S3闭合,S1、S2都断开时,电流表的示数为0.1A;当开关S1闭合时,S2、S3都断开,电流表的示数______A;当开关S1、S2都闭合时,S3断开,电流表的示数______A。
6、如图甲的电路中,电源电压保持不变。
闭合开关后,滑片P由b端滑到a端,电流表示数I与电压表示数U的变化关系如图乙所示,则可判断电源电压是_______V,定值电阻R0的阻值是________Ω。
7、LED灯具有节能、环保等特点,额定电压为220V、额定功率为4.4W的LED灯泡,灯泡的额定电流是_______A,若它每天正常发光5h,一个月(30天)消耗的电能是________kW·h。
二、单项选择题(每小题2分,共16分)8、下列现象中,能说明分子不停地做无规则运动的是()A、细雨濛濛B、雪花飞舞C、桂花飘香D、树叶飘落9、冬天,我们常用热水袋取暖,这主要是因为水具有()A、较多的热量B、较大的密度C、较高的温度D、较大的比热容10、如图所示,用酒精灯给试管加热,试管口软木塞冲出的过程中,下列说法正确的是()A、水蒸汽对软木塞做功,水蒸汽内能增大B、水蒸汽的内能转化为软木塞的机械能C、能量的转化与热机压缩冲程能量转化相同D、试管口的“白气”是水蒸汽汽化形成的11、要用一只开关同时控制两盏电灯,这两盏灯的连接方式是()A、只能串联B、只能并联C、串联并联都不行D、可以串联或并联12、在如图所示的电路中,当开关S闭合时,灯L1、L2均不亮。
商丘一高2015—2016学年第二学期期中考试高一化学试卷本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)。
满分为100分,考试时间90分钟。
注意事项:1、姓名和坐号写在答题卷的指定位置,选择题答案填在答题卷的答题栏内。
2、 考试结束只交答题卷。
可能用到的相对原子质量: H=1 N=14 O=16 K=39第Ⅰ卷(共54分)一、选择题(本题包括18小题,每小题3分,共54分,每小题只有一个正确答案) 1.下列各项中表达正确的是A .H 、D 、T 表示同一种核素B .用电子式表示HCl 形成过程:C .F -离子结构示意图:D .次氯酸电子式:2.在一定温度下某密闭容器中,加入1moA 、3molB 、2molC 和2molD ,发生反应:m A(g)+n B(g) x C(g)+y D(s),各物质的物质的量随着时间的变化如右图 所示,则当下列条件成立时,能说明反应已经达到平衡状态的是 ①C 的生成速率与C 的消耗速率相等 ②ひ正(A )=2ひ逆(C)③A、B 、C 的浓度不再变化 ④反应物的转化率不再变化⑤混合气体的压强不再变化 ⑥混合气体的物质的量不再变化⑦单位时间内消耗amolA,同时生成 3amolB ⑧A、B 、C 、D 的分子数之比为1:3:2:2A .①②③④⑤⑥⑦ B.①③④⑤⑥⑦ C .①③④⑥⑦ D.①③⑤⑥⑦⑧ 3.下列结构简式代表了几种不同的烷烃A .2种B .3种C .4种D .5种4.我国首创的海洋电池以铝板为负极,铂网为正极,海水为电解质溶液,空气中的氧气与铝反应产生电流。
电池总反应为4Al +3O 2+6H 2O===4Al(OH)3,下列说法不正确的是A .正极反应式为O 2+2H 2O +4e -===4OH -B .电池工作时,电流由铝电极沿导线流向铂电极C .以网状的铂为正极,可增大与氧气的接触面积D .该电池通常只需要换铝板就可以继续使用5.X 、Y 、Z 、WA .1 mol WB .W 、X 、Y 三种元素的最高价氧化物对应水化物的酸性依次增强C .Y 的氢化物与W 的单质反应的产物中可能含有共价键和离子键D .0.3 mol Cu 分别与足量HY O 3和H 2ZO 4的稀溶液反应均产生0.2 mol 气体 6.下列关于化学键说法正确的是A .构成单质分子的微粒中不一定含有化学键B .只含有共价键的物质一定是共价化合物C .NaCl 溶于水破坏了离子键,乙醇溶于水破坏了共价键D .CaCl2 中既有共价键又有离子键7. 如图是部分短周期元素原子(用字母表示)最外层电子数与原子序数的关系图。
商丘一高2015-2016学年第二学期期中考试高一数学(理)试卷考试时间:120分钟 试卷满分:150分本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分.考生作答时,将答案答在答题卡上(答题注意事项见答题卡),在本试卷上答题无效.第Ⅰ卷(选择题,共60分)一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.(1) 化简0sin 2016的结果是( )(A)0sin 36 (B) 0cos36 (C) 0sin 36- (D) 0cos36-(2) 2016年4月5日,“商丘一高数学优质课大赛”在分校报告厅举行,下图是七位评委老师为高一年级王学涛老师打出的分数的茎叶图,去掉一个最高分和一个最低分后,所剩数据的平均数和方差分别为 ( )(A)84,4.84 (B) 84,1.6 (C) 85,4 (D) 85,1.6(3) 已知cos tan 0θθ⋅<,那么角θ是( )(A)第一或第二象限角 (B)第二或第三象限角 (C)第三或第四象限角 (D)第一或第四象限角 (4) 2016 年3月10号,商丘一高高三1班从甲、乙、丙等5名候选学生中选2名作为青年志愿者到商丘“阳光老年公寓”献爱心关爱老人,则甲、乙、丙中有2个被选中的概率为 ( )(A)310 (B) 110 (C) 320 (D) 120 (5) 如图所示算法程序框图中,令a =tan 315°,b =sin 315°,c =cos 315°,则输出结果为( )(A)1 (B)-1 (C)2-(D) 22(6) 在一组样本数据11(,)x y ,22(,)x y …(),n n x y (122,,,n x x ≥…,n x 不全相等)的散点图中,若所有样本点(,)i i x y (1,2,3,i =…,n )都在直线21y x =-+上,则这 组样本数据的样本相关系数为( )(A) 1- (B) 2- (C) 2 (D) 1(7) 先后抛掷2枚质地均匀的骰子,得到的点数分别记为y x ,,则点),(y x 落在直线34=x 与38=x 之间的概率为( ) (A) 361 (B) 61 (C) 92 (D) 154(8)同时具有性质“①最小正周期是π,②图象关于直线3π=x 对称;③在]3,6[ππ-上是增函数”的一个函数是 ( )(A) )62sin(π+=x y (B) )32cos(π+=x y (C))62sin(π-=x y (D) )62cos(π-=x y (9) 一组数据3,4,5,,s t 的平均数是4,这组数据的中位数是m ,对于任意实数,,s t 从3,4,5,,,s t m 这组数据中任取一个,取到数字4的概率的最大值为 ( ) (A) 16 (B) 13 (C)12 (D) 23(10) 为了得到函数y =sin(2x -π6)的图象,可以将函数y =cos 2x 的图象 ( )(A) 向右平移π6个单位长度 (B)向右平移π3个单位长度(C)向左平移π6个单位长度 (D)向左平移π3个单位长度(11) 在区间,22ππ⎡⎤-⎢⎥⎣⎦上随机取一个数x ,cos x 的值介于0到12之间的概率为 ( )(A) 13 (B) 1π(C) 12 (D) 23(12) 定义在R 的奇函数)cos(2)(ϕω+=x x f (其中ω>0,0<ϕ<π),在)4,0(π上单调,则)(x f 的周期不可能...是( ) (A)2π(B) π (C) π2(D) π4第Ⅱ卷 (非选择题,共90分)二、填空题:本大题共4小题,每小题5分,共20分. (13) 已知3sin(3)2sin()2παπα+=+,则sin 4cos ____5sin 2cos αααα-=+ .(14) 假设你妈妈网购了一件衣服,快递员可能在早上6:30~7:30之间把快递送到你家,你妈妈离开家去工作的时间在早上7:00~8:00之间,则你妈妈在离开家前能得到快递的概率是____. (15) 已知扇形的周长为10cm ,面积为42cm ,圆心角为)20(παα<<,则α等于____. (16) 有下列命题:①用“除k 取余法”将十进制数89转化为二进制数是(2)1011001. ②互斥事件不一定是对立事件,对立事件一定是互斥事件.③事件A ,B 同时发生的概率一定比A,B 中恰有一个发生的概率小. ④()()()1P A B P A P B ⋃=+=则事件A B 与的关系是互斥且对立.⑤在等腰直角三角形ABC 中,直角顶点为C,在ACB ∠的内部,以C 为端点任作一条射线CM 与线段AB 交于点M ,则AM AC <的概率是2. 上述五个命题正确的是 ________(把你认为正确的命题的序号都写上)三、解答题:本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤. (17) (本题满分10分)已知31)125cos(=+απ,且2παπ-<<-,求)12cos(απ-的值. (18) (本题满分12分)(Ⅰ)用更相减损术求91与35的最大公约数.(Ⅱ)已知一个5次多项式为5432()42322500441f x x x x x x =++--+,用秦九韶算法求这个多项式当5=x 时的值.(19) (本题满分12分)已知11cos()cos()cos()sin(2)22()9sin()sin()sin(3)cos()2f ππααπαπααπαπαπαπα-++-=+----. (Ⅰ)化简)(αf ;(Ⅱ)若α是第三象限角,且322)23cos(=-πα,求)(αf 的值.(20) (本题满分12分)商丘市民权县某乡镇2009年至2015年农村居民家庭人均纯收入y (单位:千元)的数据如下表:(Ⅰ)求y 关于t 的线性回归方程;(Ⅱ)利用(Ⅰ)中的回归方程,分析2009年至2015年该乡镇农村居民家庭人均纯收入的变化情况,并预测该乡镇2017年农村居民家庭人均纯收入.附:回归直线的斜率和截距的最小二乘估计公式分别为:121()()ˆˆˆ,()nii i nii tt y y bay bt t t ==--==--∑∑.(21) (本题满分12分)商丘市睢县不仅是美丽的“中原水城”也是在国家工商标局正式注册的“中原鞋都”,质检人员从 量指标值分8(Ⅰ)在表格中作出这些数据的频率分布直方图;(Ⅱ)估计这种产品质量指标的平均数及方差(同一组中的数据用该组区间的中点值作代表);(Ⅲ)根据以上抽样调查数据,能否认为该企业生产的这种产品符合“质量指标值不低于95的产品至少要占全部产品80%”的规定?(22) (本题满分12分)商丘市第一高级中学高三宏志班男同学有45名,女同学有15名,老师按照分层抽样的方法组建了一个4人的课外兴趣小组.(Ⅰ)求某同学被抽到的概率及课外兴趣小组中男、女同学的人数;(Ⅱ)经过一个月的学习、讨论,这个兴趣小组决定选出两名同学做某项实验,方法是先从小组里选出1名同学做实验,该同学做完后,再从小组内剩下的同学中选一名同学做实验,求选出的两名同学中恰有一名女同学的概率;(Ⅲ)试验结束后,第一次做试验的同学得到的试验数据为68,70,71,72,74,第二次做试验的同学得到的试验数据为69,70,70,72,74,请问哪位同学的实验更稳定?并说明理由.商丘市一高2015~2016学年度第二学期期中考试高一数学(理)参考答案一.选择题(每小题5分,共60分) 1-4CDCA 5-8DABC 9-12 DBAA 二.填空题(每小题5分,共20分) (13)61-. (14)87. (15)21. (16)① ②三.解答题(17)(本题满分10分) 解:2παπ-<<- ,12125127παππ-<+<-∴. 31)125cos(=+απ ,απ+∴125是第四象限角.…………………………………………..5分 .322)31(1)125(cos 1)125sin(22-=--=+--=+∴απαπ .322)125sin()]125(2cos[)12cos(-=+=+-=-∴απαππαπ……………………………..10分(18)(本题满分12分)(Ⅰ)解:91-35=56 56-35=21 35-21=14 21-14=7 14-7=7所以,91与35的最大公约数是7.…………………………………………..6分 (Ⅱ)解:根据秦九韶算法,把多项式改写成如下形式:()((((42)3)2)2500)441.f x x x x x x =++--+按照从内到外的顺序,依次计算一次多项式当5=x 时的值: 4×5+2=2222×5+3=113 113×5-2=563 563×5-2500=315 315×5+441=2016所以,当5=x 时,)(x f 的值等于2016.…………………………………………..12分(19)(本题满分12分)解:(Ⅰ) )]2(4sin[)]sin()[sin()cos ()]2(5cos[)sin )(cos )(sin ()(αππαπαπααππαααα+++----+---=f)2sin()]sin ([sin )cos ()]2cos([cos sin 2απααααπαα+------=αααααααcos sin sin )cos (sin cos sin 2-=.tan cos sin ααα-=-= …………………………………………..6分(Ⅱ) ααπαππαππαsin )2cos()]2(cos[)23cos()23cos(-=--=-+=-=-, .322sin -=∴α 又α为第三象限角,31981sin 1cos 2-=--=--=∴αα, .2231322cos sin )(-=---=-=∴αααf …………………………………………..12分(20)(本题满分12分)解:(Ⅰ)由题意,=×(1+2+3+4+5+6+7)=4,=×(2.9+3.3+3.6+4.4+4.8+5.2+5.9)=4.3, ∴===0.5,=﹣=4.3﹣0.5×4=2.3.∴y 关于t 的线性回归方程为=0.5t+2.3;…………………………………………..6分(Ⅱ)由(Ⅰ)知,b=0.5>0,故2007年至2013年该地区农村居民家庭人均纯收入逐年增加,平均每年增加0.5千元. 将2015年的年份代号t=9代入=0.5t+2.3,得:=0.5×9+2.3=6.8,故预测该地区2017年农村居民家庭人均纯收入为6.8千元.…………………………………………..12分(21)(本题满分12分) 解:(1)频率分布直方图如图所示:(2)质量指标的样本平均数为=80×0.06+90×0.26+100×0.38+110×0.22+120×0.08=100,质量指标的样本的方差为S 2=(﹣20)2×0.06+(﹣10)2×0.26+0×0.38+102×0.22+202×0.08=104, 这种产品质量指标的平均数的估计值为100,方差的估计值为104.(3)质量指标值不低于95的产品所占比例的估计值为0.38+0.22+0.08=0.68,由于该估计值小于0.8,故不能认为该企业生产的这种产品符合“质量指标值不低于95的产品至少要占全部产品80%”的规定. (22)(本题满分12分)解(Ⅰ)P =n m =460=115,∴某同学被抽到的概率为115.设有x 名男同学,则4560=x4,∴x =3,∴男、女同学的人数分别为3,1. ………………4分(Ⅱ)把3名男同学和1名女同学记为a 1,a 2,a 3,b ,则选取两名同学的基本事件有:(a 1,a 2),(a 1,a 3),(a 1,b ),(a 2,a 1),(a 2,a 3),(a 2,b ),(a 3,a 1),(a 3,a 2),(a 3,b ),(b ,a 1),(b ,a 2),(b ,a 3)共12种,其中有一名女同学的有6种.∴选出的两名同学中恰有一名女同学的概率为P =612=12.………………8分(Ⅲ)x 1=68+70+71+72+745=71,x 2=69+70+70+72+745=71,s 21=-2+…+-25=4,s 22=-2+…+-25=3.2∴第二次做实验的同学的实验更稳定.………………12分。
2015级高一第一学期期中检测语文学科考试时间:150分钟满分:150分本试卷分第Ⅰ卷(阅读题)和第Ⅱ(表达题)两部分。
满分150分,考试时间150分钟。
第Ⅰ卷阅读题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1~3题。
周代,尽管关于食品安全事件的记载不多,但我们还是看到,由于食品安全关系重大,统治者对此非常重视并作出了特别规定。
周代的食品交易是以直接收获采摘的初级农产品为主,所以对农产品的成熟度十分关注。
据《礼记》记栽,周代对食品交易的规定有:“五谷不时,果实未熟,不鬻于市。
”这是我国历史上最早的关于食品安全管理的记录。
汉唐时期,食品交易活动非常频繁,交易品种十分丰富。
为杜绝有毒有害食品流入市场,国家在法律上作出了相应的规定。
汉朝《二年律令》规定:“诸食脯肉,脯肉毒杀、伤、病人者,亟尽孰燔其余……当燔弗燔,及吏主者,皆坐脯肉赃,与盗同法。
”即肉类因腐坏等因素可能导致中毒者,应尽快焚毁,否则将处罚当事人及相关官员。
唐朝《唐律》规定:“脯肉有毒,曾经病人,有余者速焚之,违者杖九十。
若故与人食并出卖,令人病者,徒一年;以故致死者,绞。
即人自食致死者,从过失杀人法。
”从《唐律》中可以看到,在唐代,知脯肉有毒不速焚而构成的刑事犯罪分为两种情况,处罚各不相同:一是得知脯肉有毒时,食品的所有者应当立刻焚毁所剩有毒食品,以绝后患,否则杖九十;二是明知脯肉有毒而不立刻焚毁,致人中毒,则视情节及后果以科罚。
宋代,饮食市场空前繁荣。
孟元老在《东京梦华录》中,追述了北宋都城开封府的城市风貌,并且以大量笔墨写到饮食业的昌盛,书中共提到一百多家店铺以及相关行会。
商品市场的繁荣,不可避免地带来一些问题,一些商贩“以物市于人,敝恶之物,饰为新奇;假伪之物,饰为真实。
如绢帛之用胶糊,米麦之增温润,肉食之灌以水,药材之易以他物”(《袁氏世范》)。
有的不法分子甚至采用鸡塞沙,鹅羊吹气、卖盐杂以灰之类伎俩谋取利润。
为了加强对食品掺假,以次充好现象的监督和管理,宋代规定从业者必须加入行会,而行会必须对商品质量负责。
商丘一高2014-2015学年第一学期期中考试高一物理试题卷一.选择题(本题包括12小题,共48分。
每小题给出的四个选项中,有的只有一个选项正确,有的有多个选项正确,全部选对的得4分,选对但不全的得2分,有选错的得0分1.对于参考系,下列说法正确的是( )A.研究地面上物体的运动,参考系必须选择地面B.可以选择任意物体为参考系,不论选择谁为参考系,对同一物体运动的描述是一样的C.选择不同的参考系,物体的运动情况可能不同D.研究物体的运动,必须选定参考系v做匀速直线运动,当它经过某处的同时,该处有一汽车开2.一摩托车沿着平直的公路以速度t始做初速度为零的匀加速直线运动去追赶,根据已知条件可以求出( )A.汽车追上摩托车时汽车的路程 B.汽车追上摩托车时汽车的速度C.汽车从开始起动到追上摩托车时所用的时间 D.汽车追上摩托车前二者之间的最大距离3.一个做匀变速直线运动的物体,某时刻t速度的大小为20m/s,已知该物体2s前速度大小为2m/s,在t时刻之前1s内该物体的()A.位移的大小可能小于14mB.位移的大小可能大于15mm/s D.加速度的大小可能大于10m/2sC.加速度的大小可能小于824.一同学从商丘火车站到郑州大学新校区大门口,可以乘火车,再换乘62路公交,也可以先乘大巴到郑州东站,再换乘出租车,当然还可以坐家用轿车直达;这几种情况下:①他的运动轨迹不一样②他走过的路程相同③他的位置变化是不同的④他的位移是相同的以上说法正确的是( )A.①②B.③④ C.①④ D.②③5.右边的四组图象中,能够反映同一直线运动的是()6.一辆汽车以速度v行驶了全程的一半,然后匀减速行驶了全程的另一半,恰好停止,则全程的平均速度为()A 、2v B 、32v C 、23v D 、3v 7. 一根轻绳的两端分别拴两个小球,一人用手拿住上端的一个球将它们从六楼阳台上由静止释放,两球先后落地的时间差为△t 1;若将它们从四楼阳台上由静止释放,则它们落地的时间差为△t 2.不计空气阻力,则△t 1、△t 2满足( )A .△t 1 = △t 2B .△t 1 > △t 2C .△t 1 < △t 2D .以上都有可能8.小李骑自行车在一条平直公路上行进,图中详细记录了自行车开始一段时间内的t v -图象,某同学为了简化计算,用虚线作近似处理,下列说法正确的是 ( ) A .在1t 时刻,虚线反映的加速度比实际的大B .在0~1t 时间内,由虚线计算出的平均速度比实际的大C .在1t ~2t 时间内,由虚线计算出的平均速度比实际的大D .在3t ~4t 时间内,虚线反映的是匀速运动 9.一木块沿粗糙斜面下滑,木块受的力是 ( )A .重力、木块对斜面的压力、沿斜面的下滑力B .重力、斜面给的支持力、滑动摩擦力C .重力、斜面受的压力、滑动摩擦力D .重力、对斜面的压力、斜面给的支持力、下滑力、滑动摩擦力 10.关于摩擦力与弹力,下列说法中正确的是( )A .粗糙 的两个接触面之间有弹力一定有摩擦力B .弹力的方向一定跟对应的接触面垂直C .有摩擦力一定有弹力D .摩擦力一定是阻碍物体的运动作用力11.如两个共点力1F 2F 合力大小为F , 1F ' 2F '合力大小为F ';并且满足1F 2F 夹角与1F ' 2F '的夹角相同,1F >1F '、2F >2F '.则以下说法错误....的有:( ) A .F 一定大于F ' B. F '一定大于F C. F '可能等于F D. F 可能小于F '12.如图所示,把一质量分布均匀的光滑球放在竖直墙ab 与板cd 之间静止,cd 与ab 夹角为α。
商丘一高2014-2015学年第一学期期中考试高一英语试题注意:1.本试卷分第I卷和第II卷两部分,共150分;考试时间100分钟;2.第I卷的答案请用2B铅笔涂在答题卷上;第II卷请用0.5毫米黑色签字笔写在指定位置上;3.交卷时只交答题卷。
第I卷(共100分)第二部分阅读理解(共两节 20小题;每小题3分,满分60分)第一节(共15小题;每小题3分,满分45分)阅读下列短文, 从每题所给的四个选项(A、B、C和D)中, 选出最佳选项,并在答题卷上将该项涂黑。
AIt happened to be a beautiful summer afternoon, and Mr. Phillip was taking a walk in the downtown area of Paris, capital of France.When he turned to a street corner, he heard the voice of a lovely French singer coming from a nearby restaurant. The sweet music attracted him, so he went into the restaurant to hear it better. Mr. Phillip sat down quietly at a table near the door. Noticing the waiter come over, he ordered a glass of French wine.The waiter returned with the glass of wine and put it on the table. Mr. Phillip started drinking the wine slowly and watching other people in the restaurant. There were three customers sitting at a table near him. He could tell by their accents that one of them was an American, one an Englishman and the third man was a funny-looking stranger. The polite waiter served each of the three men a glass of beer. By chance, each glass had a fly in it.Out of curiosity, Mr. Phillip watched carefully what they were going to do. To his amusement, he found that each of them took a quite different attitude. The American picked up his glass, took a hard look at the fly, and then poured the fly and half of his beer on the floor. The Englishman looked into the glass, noticed the fly and reached for a spoon, with which he took the fly out of the beer and drank the rest of it. And the stranger noticed the fly in the beer, picked it with his fingers, squeezed (挤压) it carefully in order to save every drop of beer, then drank it up.21. Mr. Phillip went into the restaurant to _____.A. have something to eat after the walkB. wait for a friend thereC. enjoy the pleasant musicD. meet his three friends there22. The restaurant where Mr. Phillip had a drink must be _____.A. a first-class oneB. a rather dirty placeC. expensive and comfortableD. a place where only beer was served23. Of all the three customers at the table, _____.A. the American liked the beer bestB. the Englishman wasted half of his beerC. the stranger was the cleverestD. the stranger drank the most from the glassBDick was a twenty-year-old man. His father was a teacher and taught chemistry in a middle school and his mother worked in a shop. They live a happy life until his parentsdied one night when suddenly an earthquake broke out. Luckily his sister took him to see their aunt in the city and they did not stay at home. Everything was destroyed in the earthquake and the two children got into trouble. Thanks to their aunt who was not rich enough, they grew up but they lived a hard life. His sister was so sad that she becamea nun(修女). After he finished middle school, he was introduced to an owner of a hotel and began to work there.One day the young man fell to the ground while he was cleaning a window on the second floor. He was sent to the hospital and t he doctor looked him over. One of his legs was broken and he had to be in hospital. He said to the nurse. “I’m a poor man, madam. Arrange a third-class ward(安排一个三等病房) for me, please.”“Can’t anybody help you?”“No, madam,” answered Dick. “I have only a sister. She’s a nun and she’s poor, too.”“I don’t think so,” the nurse said angrily. “Nuns usually marry God. And God is the richest in the world, you know!”“Well, then,” Dick said with a smile. “Please arrange a first-class ward for me and post the bill to my brother-in-law.”24. The sister and brother lived a hard life because ________.A. they had to look after themselvesB. they were too youngC. they were hurt in the earthquakeD. they lost all25. After Dick finished middle school, ________.A. he began to work in the hotelB. he began to look for a jobC. he broke his legD. he stayed at home26. Dick asked the nurse not to arrange a first-class ward for him because _________.A. he h adn’t got enough money to pay for the billB. he wanted to save some money for his sisterC. he liked to stay with the poorD. he used to live in a simple room27. Which of the following is true?A. Dick had a rich brother-in-law.B. The nurse would arrange a first-class ward for Dick.C. The nurse would post Dick’s bill to God.D. The nurse would arrange a third-class ward for Dick.CVENICE, a small, waterside city in northeast Italy, boils with happiness and excitement once every year. Between February 21 and March 4, carnival(狂欢节) hits the streets.For most people, carnival means large parties and feasting(盛宴). But in Venice,it also means traditional masks and clothes.These costumes(服装) were first meant to hide personal identities(身份). Then, different social classes could mix in a sea of happiness.Along the waterways, people greeted each other with: “Good morning, Mrs. Mask!”Today, people in Venice still dress up in the strangest of ways—as armed soldiers, butchers and fishermen, for example.Bars and cafes are filled with partygoers who come to show off their beautiful clothes. Their designs and creations are made by special studios. Ready-made costumes are not acceptable.“In the months before the carnival we work overtime to meet the demand,” said a mask-maker. “Many kilo meters of silk and lace(花边) are made into costumes. For shopkeepers, carnival is the best time of year.”The Venice carnival dates back to the Middle Ages. At that time, the city was one of the wealthiest in Europe.The tradition of celebrating with masks and costumes is thought to have been started by the “Stocking Companies”. These were groups of young men who organized parties and festivals and wore colourful stockings to distinguish(区分) themselves.By the 18th century, the carnival had reached its top. It all came to an end when Napoleon controlled Venice in 1797. But in 1979, local people brought the old traditions back to life.Now the Venice carnival attracts huge crowds from all over the world. This year, about 700, 000 people are taking part. Hotels were fully booked months in advance, and bars and restaurants overflow every day.The city certainly be nefits—a whole industry has been built up around the carnival’s masks and clothes.“The Venice carnival is a magical time! It’s such a great expe rience,” said one French tourist.28. What might you infer from the article?A. People in Venice like to party.B. There used to be strong feelings of social class in Venice.C. Venice was a happy city.D. Venice was a city of silk and lace.29. When was the carnival the biggest?A. In the middle ages.B. In 1979.C. In 1797.D. In the 18th century.30. Who started the tradition of wearing masks and costumes?A. Napoleon.B. The silk and lace makersC. The hotel industry.D. You ng men.31. Why do the shopkeepers like the carnival time?A. Because they can make many different kinds of masks.B. Because they can make a lot of money during this time.C. Because many people from all over the world come to Venice.D. Because the city is a “sea of happiness”.32. What would be the best title for this selection(节选)?A. The story of how the carnival began in Venice.B. How the carnival is celebrated in Venice.C. The history of the carnival in Venice.D. What to see and do during the carnival time in Venice.DParents whose children show a special interest in a particular sport feel very difficult to make a decision about their children’s careers. Should they allow their children to train to become top sports men and women? For many children it means starting school work very young, and going out with friends and other interests have to take a second place. It’s very difficult to explain to a young child why he or she has to train five hours a day, even at the weekend, when most of his or her f riends are playing.Another problem is of course money. In many countries money for training is available from government for the very best young sportsmen and women. If this help can not be given, it means that it is the parents who have to find the time and the money to support their child’s development —sports clothes, transport to competitions, special equipment, etc.— can all be very expensive.Many parents are worried that it is dangerous to start serious training in a sport at an early age. Some doctors agree that young muscles may be damaged by training before they are properly developed. Professional trainers, however, believe that it is only by training young that you can reach the top as a successful sports person. It is clear that very few people do reach the top, and both parents and children should be prepared for failure even after many years of training.33. This article is most probably taken from _______.A. a letterB. an advertisementC. a personal diaryD. a newspaper article34. According to(根据) the passage, parents whose children show a special interest in sport ______.A. try to get financial support from the government for their children’s trainingB. feel uncertain if they should let their children train to be sports men or women trainingC. have to get medical advice from doctors about training methodsD. prefer their children to be trained as young as possible35. Which of the following statements is NOT true?A. By starting young, you won’t have much time for your school work.B. Early training may damage your muscles.C. It’s very expensive for parents to support their child’s development in sports.D. Most children may become professional sports men after a long period of training.第二节(共5小题;每小题3分,共15分)根据短文内容,从短文后的七个选项中选出能填入空白处的最佳选项。
●设立内阁制,辅助皇帝处理国政 ●罢除丞相,权分六部 ●设置厂卫特务机构●皇权逐步加强,地方自治自主权受到商丘市一高2014-2015学年第一学期期中考试高一历史试题第Ⅰ卷(选择题 共60分)一、单项选择题(40小题,每题1.5分 共60分。
在每小题列出的四个选项中,只有一项是最符合题目要求的。
请将答案涂在答题卡上。
)1.“人道亲亲也,亲亲故尊祖,尊祖故敬宗,敬宗故收族,收族故宗庙严,宗庙严故重社稷,重社稷故爱百姓……”,材料主要反映了A.中国古代的分封制度B.中国古代的宗法观念C.中国古代的礼乐制度D.中国古代的仁爱思想2.《荀子•儒效篇》记载:“(周公)兼制天下,立七十一国……”其中宋国是微子的封地,微子属于受封的A .周天子的亲属B .功臣C .先代的贵族D .归附的部落首领3.阴历一月古时本来又叫“政月”,到了秦朝为了避秦王嬴政的讳,就把“政月”改为“正月”,“正”字的读音也当为“征”了。
这说明皇帝制度的主要特征是A.中央集权B.皇帝拥有最高决策权C.独断性和随意性D.皇权至上,皇帝独裁4.《汉书·地理志》言:“秦并兼四海,以为周制微弱,终为诸侯所丧,故不立尺土之封,分天下为郡县。
”材料表明秦朝采取的措施是A .推广行省制度B .推行三公九卿制C .实施郡县制度D .实行郡国并行制5.汉武帝统治时期,全国划分为十三个州部,每州部设刺史一名。
当时刺史的主要职责是A .监察地方政治B .管理地方行政C .征收地方赋税D .掌管地方军事6.有当代学者评论道:它“具有两重性又长期代表中央分驭各地,所握权力大而不专,七百年来给中国社会带来的影响既深且巨。
”这里的“它”指A . 郡B .封国C .行省D .内阁7.为加强皇权,选用一些亲信侍从如侍中、常侍等参与国家政治中枢的主要决策,下列选项,符合这一特点的是A .秦朝三公B .西汉中朝C .唐朝六部D .元朝行省8.右图所列内容为中国某朝代具有的一些特征。
商丘市一高2015-16学年度第一学期期中考试
高一物理试卷
一、选择题(本题共12小题,每小题4分,共48分。
其中1-8题为单选,9-12题为多选)
1、下列各组物理量中,都是矢量的是( )
A.位移、时间、速度
B.速度、速率、加速度
C.加速度、速度的变化、速度
D.路程、时间、位移
2、如图所示,两个同样的弹簧秤每个自重都是0.1N ,下端挂钩的重力忽略不计,甲“正挂”,乙“倒挂”,在乙的下方挂上重0.2N 的砝码,则甲、乙两弹簧秤的示数分别为( )
第2题图 第3题图 第4题图 第8题图
A.0.3N 0.3N
B.0.3N 0.2N
C.0.2N 0.3N
D.0.4N 0.3N
3、测速仪上装有超声波反射和接收装置,如图所示,B 为固定测速仪,A 为汽车,两者相距670m ,某时刻B 发出超声波,同时A 由静止开始做匀加速直线运动,当B 接收到发射回来的超声波信号时,A 、B 相距710m ,已知声速为340m/s ,则汽车的加速度大小为( )
A.20m/s 2
B. 10m/s 2
C. 5m/s 2
D.无法计算
4、一质点沿X 轴正方向做直线运动,通过坐标原点时开始计时,其t t
x 的图象如图所示,则( )
A.质点做匀加速直线运动,加速度为0.5m/s 2
B.质点在1s 末速度为1.5m/s
C.质点在第1s 内的平均速度为0.75m/s
D.质点做匀速直线运动,速度为0.5m/s
5、在物理学的重大发现中科学家们创造了许多物理学方法,如理想实验法、控制变量法、极限思想法、建立物理模型法、类比法和科学假说法等等。
以下关于所用物理学研究方法的叙述不正确的是( )
A.根据速度定义式t x ∆∆,当t ∆非常非常小时,就可以用t
x ∆∆表示物体在t 时刻的瞬时速度,这是应用了极限思想方法
B.在推导匀变速运动位移公式时,把整个运动过程划分成很多小段,每一小段近似看作匀速直线运动,然后把各小段的位移相加,这里采用了微元法
C.在不需要考虑物体本身大小和形状时,用理想化的质点来代替物体,这里采用了理想实验法
D.玻璃瓶内装满水,用穿有透明细管的橡皮泥封口,手捏玻璃瓶,细管内液面高度变大,说明玻璃瓶发生形变,该实验采用放大的思想
6、物体做匀变速直线运动,已知在时间t 内通过的位移为x ,则以下说法正确的是( )
A.可求出物体在时间t 时的速度
B.可求出物体的加速度
C.可求出物体通过2
x 时的速度 D.可求出物体在这段时间内中间间隔的瞬时速度 7、小球A 从离地面20m 高处做自由落体运动,小球B 从A 下方的地面上以20m/s 的速度做竖直上抛运动,两球同时开始运动,在空中相遇,取g=10m/s 2 ( )
A.两球在离地面10m 高处相遇
B.两球相遇时速率都是10m/s
C.两球在空中相遇两次
D.两球落地的时间差为1s
8、甲、乙两物体在t=0时刻经过同一位置沿x 轴运动,v-t 图象如图所示( )
A.甲、乙在t=0到t=1s 之间沿同一方向运动
B.乙在t=0到t=7s 之间的位移为零
C.甲在t=0到t=4s 之间做往复运动 D 甲、乙在t=0s 时的初速度相同
9、如图所示,一倾角为45°的斜面固定于竖直墙上,为使一光滑的铁球静止,需加一水平力F ,且F 过球心,下列说法正确的是( )
A.球一定受墙的弹力且水平向左
B.球可能受墙的弹力且水平向左
C.球一定受斜面的弹力且垂直斜面向上
D.球可能受斜面的弹力且垂直斜面向上
第9题图
10、如图所示为A 、B 两质点在同一直线上运动的位置——时间(x —t )图象。
A 质点的图象为直线,B 质点的图象为过原点的抛物线,两图象交点C 、D 坐标如图。
下列说法正确的是( )
A.两次相遇的时刻分别为 t 1 、t 2
B.0~ t 1时间段内A 在前B 在后,t 1 ~t 2时间段B 在前A 在后
C.两物体速度相等的时刻一定为t 1 ~t 2时间段的中间时刻
D.A 做匀速运动而B 做匀变速运动
11、如图所示,质量为m 的木块在质量为M 的长木板上向右滑行,木块收到向右的拉力F 的作用,长木板处于静止状态,已知木块与长木板间的动摩擦因数为u 1,木板与地面间的动摩擦因数为 u 2,则( )
A.长木板受到地面的摩擦力的大小一定是u 1mg
B. 长木板受到地面的摩擦力的大小一定是u 2(m+M)g
C.当F> u 2(m+M)g 时,长木板便开始运动
D.无论怎样改变F 的大小,长木板都不可能运动
12、物体以速度v 匀速通过直线上的A 、B 两点间需时为t ,现在物体由A 点静止出发,匀加速(加速度大小为a 1)至某一最大速度v m 后立即做匀减速运动(加速度大小为a 2)至B 点停下,历时仍为t ,则物体的( )
A.V a 只能为2v ,无论a 1 、a 2为何值
B. a 1 、a 2必须满足t
v 2a a a a 2 12 1=+ C. 2 1a a 、值必须是一定的 D. v m 可为许多值,与2 1a a 、的大小有关
二、实验题(本题共2小题,共16分。
把答案填在相应的横线上或按照题目的要求作答)13(4分)某同学利用如图(a)装置做“探究弹簧弹力大小与长度的关系”的实验。
○1在安装刻度尺时,必须使刻度尺保持状态。
○2他通过实验得到如图(b)所示的弹力大小F与弹簧长度x的关系图线,由此图线可得该弹簧的员长x0= cm,劲度系数k= N/m。
○3他又利用本实验原理把弹簧做成一只弹簧秤,当弹簧秤上的示数如图(c)所示时,该弹簧的长度x= cm.
14(12分)某同学在“探究小车速度随时间变化规律”实验中,由打点计时器得到表示小车运动过程的一条清晰纸带如图所示,
(1)已知电火花式打点计时器所用交流电的周期为T,纸带上各计数点的间距如图,其中每相隔两点之间还有4个记录点未画出,计算小车运动加速度的表达式(用X、T表示)为a=
(2)某同学量得X1=7.05cm、X2=7.68cm、X3=8.33cm、X4=8.95cm、X5=9.61cm、X6=10.23cm.已知T=0.02S,由此计算出打点计时器打下B、C、D、F时小车的瞬时速度,则打点计时器打下E点时小车的瞬时速度V E= m/s(小数点后保留三位数字)
(3)以A点为计时起点,在坐标图中合理地选择标度,画出小车V-t图象,并利用该图像求出物体的加速度a= m/s2(结果保留两位有效数字)
三、计算题(本题共3小题,共36分。
解答应写出必要的文字说明、方程式和重要演算步骤。
只写出最后答案的不给分。
有数值计算的题,答案中必须明确写出数值和单位)15、(10分)如图所示,放在长木板上的木块质量为m,当木板与水平方向夹角为α时,木块静止在长木板上,则
(1)此时木块所受的弹力和摩擦力各多大?
(2)当把长木板的倾角增大到θ(θ>α)时,木块刚好沿着长木板匀速运动,木块和长木板之间的动摩擦因数为多少?
16(12分)如图所示,物体从光滑斜面上的A点由静止开始下滑,经过B点进入水平面(设经过B点前后速度大小不变),最后停在C点,每隔0.2s通过速度传感器测量物体的瞬时速度,下表给出了部分测量数据。
(重力加速度g=10m/s2)求:
(1)物体在AB段和在BC段的加速度α1和α2;
(2)物体在斜面上下滑的时间;
(3)物体整个运动过程的总过程(结果保留2位有效数字)
17.(14分)如果公路上有一列汽车车队以10m/s的速度正在匀速行驶,相邻车间距为25m,后面有一辆摩托车以20m/s的速度同向行驶,当它距离车队最后一辆车25m时刹车,以0.5m/s2的加速度做匀减速直线运动,摩托车在车队旁边行驶而过,设车队车辆数足够多,求:(1)摩托车最多与几辆汽车相遇?最多与车队中汽车相遇几次?
(2)摩托车从赶上车队到离开车队,共经历多长时间?参考答案:。