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2017-2018学年度第二学期第二次月考（全二册）高一年级语文试卷命题人：校对：考试时长：150 分钟分值：150 分I 卷（选择题，共44分）一基础知识单项选择题(本大题共10小题，每小题2分，共20分。
在下列各小题的备选答案中，选择一个正确的答案)1.下列加点的字注音，错误最多的一项是（）A.憎．恶（zèng）岑．寂（cán）流涎．（yán）锱．铢必较（zhī）B.目眦．（zì）攻讦．（jiān）拉纤．（qiàn）一蹴．而就（cù）C.瞋．目（chēng）绮．丽（yǐ）得逞．（chěng）昙．花一现（tán）D.折腾．（teng）帷．幕（weí）露．穷（lù）清沁．肺腑（qìng）2.下列词语中，错别字最多的一项是（）A.不及不离挥豁无度珍羞美味源源不断B.抱残守却诩诩如生转瞬即逝迫在眉睫C.相形见拙烟熏火燎宠然大物屈指可数D.莫名其妙震耳欲聋猝不及防冠冕堂煌3.下列词语中，加点字解释完全正确的一项是（）A．待人接物．（物体）自鸣．得意（表示）无动于衷．（内心）B.疾．言厉色（急速）胡作非．为（不对）灭顶．．之灾（水漫过头顶）C.自顾不暇．（时间）冥思苦．想（用心）一丝不苟．（苟且、马虎）D.小心．．谨慎（留心）纵横交错．(叉开) 有史可稽．（考核、核查）4.依次填入下列句子横线处的关联词，最恰当的是（）也有的播迁他邦，重振雄风；也有的昙花一现，未老而先亡。
————，————它们内容的深浅，作用的大小，时间的久暂，空间的广狭，————它们存在过，————都是传统文化。
A.不过如果只要便B.不过即使如果就C.但是不管只要便D.但是也许如果就5.下列句子中标点使用规范的一项（）A.“你打碎了我的盘子”，她很低沉地说：“我的小儿子没有饭吃了。
”B. 做年夜饭不能拉风箱——呱嗒呱嗒的风箱声会破坏神秘感——因此要烧最好的草、棉花柴或者豆秸。
2017-2018学年第二学期期末教学质量检测高一物理测试时间：90分钟满分：100分第Ⅰ部分选择题（共56分）一、单项选择题(12个小题，每小题3分，共36分；在每小题给出的四个选项中，只有一个正确选项，选对的得3分，选错或不答的得0分)1. 下列说法符合物理学史实的是A．卡文迪许发现了行星的运动规律 B．开普勒发现了万有引力定律C．牛顿发现了万有引力定律 D．牛顿发现了海王星和冥王星2．一质点(用字母O表示)的初速度v0与所受合外力的方向如图所示，质点的运动轨迹用虚线表示，则所画质点的运动轨迹中可能正确的是3. 如图所示是自行车的轮盘与车轴上的飞轮之间的链条传动装置， P是轮盘边缘上的一个点，Q是飞轮边缘上的一个点．关于P、Q两点运动情况，下列说法正确的是A．角速度大小相等 B．周期相同C．线速度大小相等 D．加速度大小相等4. 两个质量均匀的球体相距较远的距离r，它们之间的万有引力为10-8N．若它们的质量、距离都增加为原来的2倍，则它们间的万有引力为A．4×10-8N B．10-8N C．2×10-8N D．10-4N5. 下列有关功率的说法，正确的是A. 做功越多，功率越大B. 由P = W/t 知P与t成反比C. 功率越大，做功越快D. 完成相同的功，所花时间越长，则功率越大6．在下列实例中(不计空气阻力)机械能守恒的是A．物体做平抛运动B．物体沿斜面匀速下滑C．拉着一个物体沿着光滑的斜面匀速上升D．物体在粗糙水平面减速滑行7．如图所示，乘坐游乐园的翻滚过山车时，质量为m的人随车在竖直平面内旋转，下列说法正确的是A. 车在最高点时人处于倒坐状态，全靠保险带拉住，没有保险带，人就会掉下来B. 人在最高点时对座位一定不可能产生压力C．人在最低点时对座位的压力等于mgD．人在最低点时对座位的压力大于mg8. 转笔包含了许多的物理知识，假设某转笔高手能让笔绕其上的某一点O做匀速圆周运动，下列有关该同学转笔中涉及到的物理知识的叙述正确的是A．笔杆上的点离O点越近的，做圆周运动的角速度越大B．笔杆上的点离O点越近的，做圆周运动的线速度越大C．笔杆做圆周运动的向心力是由万有引力提供的D．若该同学使用中性笔，墨汁可能会因笔快速的转动做离心运动被甩出9．关于“亚洲一号”地球同步通讯卫星，下述说法正确的是A．其轨道平面不一定与赤道平面重合B．它的运行速度小于7.9 km/sC．它可以绕过北京的正上方，所以我国能利用其进行电视转播D．已知其质量是1.24吨，若将其质量增为2.84 吨，则同步轨道半径变为原来的2倍10. 在同一高度将质量相等的三个小球以大小相同的速度分别竖直上抛、竖直下抛、水平抛出，不计空气阻力．从抛出到落地过程中，三球A．运动时间相同 B．落地时的动能相同C．重力的平均功率相同 D．同落地时的速度相同11．如图所示，在一张白纸上放置一根直尺，沿直尺的边缘放置一块直角三角板。
2017-2018学年度第二学期期末检测试题高一英语2018.06．本试卷分为第一卷（选择题）和第二卷（非选择题）两部分。
共120分，时间120分钟。
第一卷（三部分，共80分）第一部分听力（共20小题；每题1分, 满分20分）第一节听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What’s the relationship between the speakers?A. Relatives.B. Classmates.C. Colleagues.2. Why is the woman unhappy?A. She quarreled with the man.B. She was charged high.C. The oranges were bad.3. Who is the man’s teacher?A. Miss Pond.B. Mrs. Pond.C. Miss Brown.4. What do the speakers want to buy?A. A shirt.B. A skirt.C. A coat.5. What does the woman mean?A. She likes going out.B. She’d like to watch TV.C. S he wants to go to sleep.第二节（共15小题）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟。
听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话，回答第6和第7题。
6. What is the man going to do during the summer vacation?A. Take a part-time job.B. Find a full-time job.C. Stay at home.7. What did the woman do last summer?A. Worked in a restaurant.B. Worked in a shop.C. Stayed at home. 听下面一段对话，回答第8至第10题。
— 高一调研考试(数学) 第1页(共4页) —2017-2018学年度第二学期高一调研测试数 学注意事项：1．本试卷分选择题、填空题、解答题三部分.2．答题前，考生务必将自己的学校、姓名、准考证号填写在答题卡相应的位置. 3. 全部答案在答题卡上完成，答在本试卷上无效.一、选择题：共12小题，每小题5分，共60分.在每个小题给出的四个选项中，只有一项是符合题目要求的．1．数列11111,2,3,4 (248)16的通项公式可以是 A.12n n + B.12n n + C.122n n + D.122n n +2．已知a b >，则下列关系正确的是A.11a b <B.22a b > 33a b > D.3311a b< 3．某班统计一次数学测验的平均分与方差，计算完毕以后才发现有位同学的卷子还未登分，只好重算一次．已知原平均分和原方差分别为x 、2s ，新平均分和新方差分别为1x 、21s ，若此同学的得分恰好为x ，则A. x =1x ,2s 21s =B. x =1x ,2s <21sC. x 1x =,2s >21sD. x 1x <,2s 21s =4．若实数x 为2与8的等比中项，则x =A.16B.4C.4-D.4±5．某班运动队由足球运动员18人、篮球运动员12人、乒乓 球运动员6人组成（每人只参加一项），现从这些运动员中抽 取一个容量为n 的样本，若分别采用系统抽样法和分层抽样 法，则都不用剔除个体；当抽取样本的容量为1n +时，若采 用系统抽样法，则需要剔除一个个体，则样本容量n =A. 6B. 7C. 12D. 186．执行如图的程序框图. 若输入3A =, 则输出i 的值为A.3B.4C.5D.67．在ABC ∆中，角,,A B C 所对应的边长分别为,,a b c ，若2,3,3a b B π===，则cos A =6 3 C.6± D.3± 8． 已知实数0,0x y >>，32x xy +=，则2x y +的最小值为A.12B.14C.16D.18— 高一调研考试(数学) 第2页(共4页) —oxy P 2第12题图9．已知2a <，则不等式223210x ax a a -++-<的解集是A. (1,21)a a -+B.(21,1)a a +-C.(1,21)a a +-D.(21,1)a a -+ 10．“勾股定理”在西方被称为“华达哥拉斯定理”，三国时期吴国 的数学家赵爽创制了一幅“勾股圆方图”，用数形结合的方法给出 了勾股定理的详细证明.如图所示的“勾股圆方图”中，四个相同的 直角三角形与中间的小正方形拼成一个边长为4的大正方形，若直 角三角形中较小的锐角0=15α，现在向该大正方形区域内随机地投 掷一枚飞镖，飞镖落在图中区域1或区域2内的概率是A.12 B.58 C. 34 D.7811．已知在ABC ∆中， tan 3,3,19A AB BC =-==，则BC 边上的中线AD 的长为5 7 C.7 D. 7212．“贪吃蛇”的游戏中，设定贪吃蛇从原点出发，沿着如图所示的逆时针方向螺旋式前进，不停的吞食沿途的每一个格点（不包括原点）．已知贪吃蛇的初始长为0，并且每吞食一个格点，长度就增 加1个单位，如它头部到达点2(2,2)P ，其长度增 加到12，若当它头部到达点9(9,9)P 时，则它的长 度增加到A.186B.306C.360D.720二、填空题：本大题共4小题，每小题5分,共20分．13．甲、乙两人在相同的条件下各射击10次，它们的 环数方差分别为22=2.1=2.6ss 甲乙，，则射击稳定程度较高的是 __________（填甲或乙）．14．执行如右图的程序框图，若输入的2x =，则输出 的y =__________．15．求和：1092891032323232+⨯+⨯++⨯+=__________．16．如图，已知,,A B C 三点均在一个半径为R 的圆上，如图，B 在A 的正东方向，距离A 处202C 在A 的东偏北α角处， 同时C 也在B 的东偏北β角处(0)2παβ<<<，若sin sin 2cos cos αβαβ=，sin()3cos cos βααβ-=， 则此圆的半径R =________公里.— 高一调研考试(数学) 第3页(共4页) —三、解答题：解答应写出文字说明、证明过程或演算步骤．17．(本小题满分10分) 单调递增的等差数列{}n a 满足11a =，且123,1,2+3a a a +成等比数列. （Ⅰ）求数列{}n a 的通项公式； （Ⅱ）设11n n n b a a +=，求数列{}n b 的前n 项和n S .18．(本小题满分12分) 已知不等式2(1)0x a x a -++<的解集为M ． （Ⅰ）若2M ∈，求实数a 的取值范围； （Ⅱ）当M 为空集时，求不等式12x a<-的解集．19．(本小题满分12分) 2018年3月19日，世界上最后一头雄性北方白犀牛“苏丹”在肯尼亚去世，从此北方白犀牛种群仅剩2头雌性，北方白犀牛种群正式进入灭绝倒计时。
2017学年第二学期教学质量监测试卷高一数学本试卷共4页，22小题，全卷满分150分，考试时间120分钟。
注意事项：1．答卷前，考生务必用黑色字迹的钢笔或签字笔将自己的姓名和考生号、试室号、座位号填写在答题卡上。
2．选择题每小题选出答案后，用2B 铅笔把答题卡上对应题目选项的答案信息点涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案，答案不能答在试卷上。
3．非选择题必须用黑色字迹钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新的答案；不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
4. 本次考试不允许使用计算器。
5．考生必须保持答题卡的整洁．考试结束后，将答题卡交回。
一、选择题：本大题共12小题，每小题5分，共60分，在每小题所给的四个选项中，只有一个是正确的． 1.5sin 3π的值是(﹡).A. 12-B.2 C. 12 D. 2- 2. 不等式220x x --+>的解集是(﹡).A. (1,)+∞B. (,2)-∞-C. (2,1)-D. (,2)(1,)-∞-⋃+∞ 3. 已知角θ的终边经过点(4,3)P - ，则()cos πθ-的值是(﹡).A.45 B.45- C.35 D.35- 4. 在等差数列{}n a 中，22a =，34,a =则10a ＝(﹡).A. 18B. 16C. 14D. 12 5. 若0,2πα⎛⎫∈ ⎪⎝⎭，且21sin cos 24αα+=，则tan α的值等于(﹡).A.2B. C.D.6. 对任意向量,a b ，下列关系式中不恒成立．．．．的是(﹡). A ．||||||a b a b ⋅≤B ．22()||a b a b +=+C ．||||||a b a b -≤-D ．()()22a b a b a b+⋅-=-7. 设123,,A A A 是平面上给定的3个不同点， 则使123MA MA MA ++=0成立的点M 的个数为(﹡).A. 0B. 1C. 2D. 3 8. 要得到函数2sin 2y x =的图象，只要将函数2sin(21)y x =+的图象(﹡).A ．向左平移1个单位B ．向右平移1个单位C ．向左平移12个单位 D ．向右平移12个单位 9. 函数23sin 23y x π⎛⎫=- ⎪⎝⎭(﹡).A ．在区间7,1212ππ⎡⎤⎢⎥⎣⎦上单调递增B ．在区间7,1212ππ⎡⎤⎢⎥⎣⎦上单调递减C ．在区间,63ππ⎡⎤-⎢⎥⎣⎦上单调递减D ．在区间,63ππ⎡⎤-⎢⎥⎣⎦上单调递增10. 已知等比数列{}n a 满足22463,21a a a a +=+=，则468a a a ++=(﹡).A ．21B ．42C ．63D ．8411. 要制作一个容积为34m ，高为1m 的无盖长方体容器.已知该容器的底面造价是每平方米20元，侧面造价是每平方米10元，则该容器的最低总造价是(﹡).A. 80元B. 120元C. 160元D. 240元12. 在ABC ∆中，角A B C 、、所对边的长分别为a b c 、、，若222sin sin 2sin A B C +=，则cos C 的最小值为(﹡). A. 12-B. 12C. 2D.二、填空题：本大题共4小题，每小题5分，满分20分.把答案填在答题卡上. 13. 若向量=a 与(k =b 共线，则k 的值为 ＊ ．14. 已知关于x 的不等式220x ax a -+>在R 上恒成立，则实数a 的取值范围是 ＊ ．15. 设实数,x y 满足2,1,2x y x +⎧⎪⎨⎪⎩≥≤≤y 则z x y =-+的最大值是 ＊ ．16. 函数()sin 1f x x x =-在区间[0,2]π上所有零点的和等于 ＊ ．三、解答题：本大题共6小题，满分70分．解答应写出文字说明，证明过程或演算步骤． 17.（本小题满分10分）已知平面向量a ，b 满足||1=a ，||=b a 与b 的夹角为θ.(Ⅰ)若a ∥b ，求⋅a b ； (Ⅱ)若a -b 与a 垂直，求θ.18. (本小题满分12分)在等差数列{}n a 中，已知35a =，6919a a +=．(Ⅰ)求数列{}n a 的通项公式； (Ⅱ)设23n a n b n -=+，求12310b b b b +++⋅⋅⋅+的值．19. (本小题满分12分)用“五点法”画函数π()sin()(0,||)2f x A x ωϕωϕ=+><在某一个周期内的图象时，列表并填入了部分数据，如下表：(Ⅰ)请将上表数据补充完整，填写在答题卡表中相应位置上．．．．．．．．．．．．．，并直接写出函数()f x 的解 析式；(Ⅱ)求()f x 在0,2π⎡⎤⎢⎥⎣⎦上的最大值和最小值.20. （本小题满分12分）ABC ∆的内角,,A B C 所对的边分别为a ，b ，c,sin cos a B A =． (Ⅰ)求A ；(Ⅱ)若2b =，ABC ∆的面积为2，求a ．21. (本小题满分12分)如图，在ABC ∆中，已知0135,6,BAC AB AC ∠=== (Ⅰ)求cos B ；(Ⅱ)若点D 在BC 边上，且ABD BAD ∠=∠，求CD 的长．BDAC22. （本小题满分12分）数列{}n a 满足111,(1)(1),N n n a na n a n n n *+==+++∈. (Ⅰ)求数列{}n a 的通项公式n a ；(Ⅱ)设2n nb =，求数列{}n b 的前n 项和n S .2017-2018学年第二学期期末教学质量监测高一数学参考答案与评分标准说明：1．参考答案与评分标准给出了一种或几种解法供参考，如果考生的解法与参考答案不同，可根据试题主要考查的知识点和能力对照评分标准给以相应的分数．2．对解答题中的计算题，当考生的解答在某一步出现错误时，如果后继部分的解答未改变该题的内容和难度，可视影响的程度决定后继部分的得分，但所给分数不得超过该部分正确解答应得分数的一半；如果后继部分的解答有较严重的错误，就不再给分．3．解答右端所注分数，表示考生正确做到这一步应得的累加分数． 4．只给整数分数，选择题和填空题不给中间分． 一、选择题二、填空题13. 1 14. (0,1) 15. 2 16.73π 三、解答题：本大题共6小题，满分70分．解答应写出文字说明，证明过程或演算步骤． 17.（本小题满分10分） 解：(1)∵a ∥b ，∴θ＝0°或180°， ………………………2分 ∴cos 1θ=±， ……………………………………………3分 ∴|||cos 1cos θθ==a b =|a b ……………5分(Ⅱ)∵a -b 与a 垂直，∴(a -b )·a ＝0， ………………7分 即2||10θ-⋅-=a a b =， ……………………8分∴cos θ＝22. ………………………………………………9分 又0°≤θ≤180°，∴θ＝45°. ………………………………10分 18. (本小题满分12分)解：(Ⅰ)设等差数列{}n a 的公差为d ,………………………1分由已知得()()11125,5819.a d a d a d +=⎧⎪⎨+++=⎪⎩ ……………………3分解得13,1.a d =⎧⎨=⎩…………………………………………………4分所以()112na a n d n =+-=+. ……………………………5分(Ⅱ)由（I ）可得3nn b n =+, ………………………………6分所以12310b b b b ++++……2310(31)(32)(33)(310)=++++++++…… …………7分()2310(3333)12310=+++⋅⋅⋅⋅⋅⋅+++++⋅⋅⋅⋅⋅⋅+………9分103(13)(110)10132-+⨯=+- …………………………………11分111335522=⨯+-. …………………………………………12分 19. (本小题满分12分)解：(Ⅰ)根据表中已知数据，可得,sin 325362=32A ππωφππωφπ⎧⋅+=⎪⎪⎪⋅+=⎨⎪⎪⎪⎩…………………2分 (没有列以上方程组，但能正确写出π3,2,6A ωϕ===-不扣分.)解得π3,2,6A ωϕ===-. ………………………………………………3分函数表达式为π()3sin(2)6f x x =-.………………………………………3分数据补全如下表：(填对表中 (Ⅱ)02x π≤≤，52666x πππ∴-≤-≤.…………………………8分 由正弦函数的性质， 当262x ππ-=，即3x π=时，()f x 取得最大值3. …………………9分当266x ππ-=-，即0x =时，3(0)2f =-，………………………10分当5266x ππ-=，即2x π=时，3()22f π=， ………………………11分()f x ∴的最小值为32-. ………………………………………………12分因此，()f x 在02π⎡⎤⎢⎥⎣⎦， 上最大值是3，最小值是32-.………………12分 20.（本小题满分12分）解：（Ⅰ）因为sin cos a B A =，所以由正弦定理，得sin sin cos A B B A =，………………………………2分又sin 0B ≠，从而tan A =……………………………4分由于0A π<<，所以3A π=.…………………………………6分（Ⅱ）因为2b =，ABC ∆所以12sin 232c π⨯⋅=， …………………………………8分 所以3c =. ……………………………………………………9分由余弦定理，得2222cos 7a b c bc A =+-=，……………11分所以a =…………………………………………………12分21. (本小题满分12分)解:由余弦定理得，中2222cos BC AC AB AC AB BAC =+-⋅∠, ……………1分220626cos1351836(36)90,=+-⨯⨯=+--= ………………2分所以BC =……………………………………………………………………3分又由正弦定理得,sin sin10AC BAC B BC ∠=== ………………………5分由题设知00045,B <<cos 10B ∴=== ……………7分 解法一：在ABD ∆中，ABD BAD ∠=∠，01802ADB B ∴∠=-， …………8分 由正弦定理得，sin sin sin =sin sin(2)sin 2AB B AB B AB BAD ADB B Bπ==∠-……………………10分6sin 32sin cos cos B B B B=== ……………………………………………………11分所以CD BC BD BC AD =-=-== ………………………12分 解法二：在ACD ∆中，ABD BAD ∠=∠，2ADC B ∴∠=，…………………8分 由正弦定理得，()0sin 45sin =sin sin 2AC B AC ACD AD ADC B-∠=∠ ……………………10分 ()00sin 45cos cos 45sin sin 2AC B B B-=……………………………………………11分22+==12分22.（本小题满分12分）解：(Ⅰ) 解法一：由已知得()111,n n n a a n n N n*++=++∈⋅⋅⋅⋅⋅⋅* 把2n =代入()*式，得2122a a =+，而11,a =所以24a =，………1分 把3n =代入()*式，得39a =，…………………………………………2分 把4n =代入()*式，得416a =， ………………………………………3分……………猜想：()211n a n -=-. ……………………………………………………4分把1n a -代入()*式，得2n a n =. …………………………………………6分（本题猜想之后应用数学归纳法证明.把()211n a n -=-代入()*式，得2n a n =这一步等价于数学归纳法证明中的“递推”，没有“递推”这一步，第(Ⅰ)问最多给4分） 解法二：由已知可得111n na a n n+=++， …………………………………2分 即111+-=+n na a n n，………………………………………………………3分 所以⎧⎫⎨⎬⎩⎭n a n 是以111=a 为首项，1为公差的等差数列.…………………4分(Ⅱ)由(Ⅰ)得，()111=+-⋅=na n n n，………………………………5分所以2=n a n ， …………………………………………………………6分 从而2nn b n =⋅. ………………………………………………………7分1231222322n n S n =⋅+⋅+⋅++⋅ ①………8分()23412122232122n n n S n n +=⋅+⋅+⋅++-+⋅. ②………9分①—②得，2341222222n n n S n +-=+++++-⋅………………10分()111212222212n n n n n n +++-=-⋅=-⋅--. …………………………11分所以()111222122n n n nS n n +++=⋅-+=-+. ……………………12分。
2017—2018学年度第二学期教学质量检查 高一数学参考答案及评分标准二、填空题(每小题5分,满分20分)13.52 14．7； 15．0.95； 16．5三、解答题 17．（本小题满分10分）解:（1） 与2+a b 垂直，得2+0a a b ⋅=（） 即22+=0a a b ……………………2分即10120k -+= ……………………3分解得92k =-． ……………………4分 （2）依题意，10102521||||cos =⨯+-==b a b a θ， ……………………6分因为[0,]θπ∈ s i n 10θ∴==……………………7分 sin tan 3cos θθθ∴== ……………………8分 54110121cos 22cos 2-=-⨯=-=∴θθ ……………………10分18．（本小题满分l2分）解: (1)由题意：第2组的人数：7050.07n =⨯⨯，得到：=200n ， 故该组织有200人.……………………3分(2)第3组的人数为0.3200=60⨯， 第4组的人数为0.2200=40⨯，第5组的人数为0.1200=20⨯. ∵第3，4，5组共有120名志愿者，∴利用分层抽样的方法在120名志愿者中抽取6名志愿者，每组抽取的人数分别为：第3组：606=3120⨯；第4组：406=2120⨯；第5组：206=1120⨯. ……………………5分 记第3组的3名志愿者为1A ，2A ，3A ，第4组的2名志愿者为1B ，2B ， 第5组的1名志愿者为C .则从6名志愿者中抽取2名志愿者有：()12A A ，，()13A A ，，()11A B ，，()12A B ，，()1A C ，，()23A A ，，()21A B ，,()22A B ，,()2A C ，,()31A B ，,()32A B ，,()3A C ，,()12B B ，,()1B C ，,()2B C ，， 共有15种.……………………8分其中第3组的3名志愿者为1A ，2A ，3A ，至少有一名志愿者被抽中的有：()12A A ，，()13A A ，，()11A B ，，()12A B ，，()1A C ，，()23A A ，，()21A B ，,()22A B ，,()2A C ，,()31A B ，,()32A B ，,()3A C ， 共有12种.……………………10分则第3组的为至少有一名志愿者被抽中的概率为541512==P . ……………………12分 [用间接法求解亦可以给满分] 19. （本小题满分l2分） 解：（1）66880838490+++++=q y ，又80y =，75=∴q . ……………………3分（2）4567891362x +++++==， ……………………4分2133050680241327162b ∧-⨯⨯∴==-⎛⎫- ⎪⎝⎭……………………6分 ()138041062a ∧∴=--⨯= ……………………7分 4106y x ∧∴=-+ ……………………8分（3）4106y x ∧=-+1111410690,909001y x y y ∧∧∴=-+=-=-=<，所以()()11,4,90x y =是“理想数据”；2222410686,=868421y x y y ∧∧=-+=--=>，所以()()22,5,84x y =不是“理想数据”;3333410682,838211y x y y ∧∧=-+=-=-==，所以()()33,6,83x y =是“理想数据”.所以所求的“理想数据”为)90,4( ，)83,6(. ……………………12分20. （本小题满分l2分）解: （1）()2ππ2sin 1cos 242f x x x x x ⎛⎫⎛⎫=+-=-+⎪ ⎪⎝⎭⎝⎭π1sin22sin 213x x x ⎛⎫=+=-+ ⎪⎝⎭， ……………………4分∴函数()f x 最小正周期为22T ππ== ……………………5分 (2)ππ,42x ⎡⎤∈⎢⎥⎣⎦∴ππ2π2,363x ⎡⎤-∈⎢⎥⎣⎦， ……………………7分∴π1sin 2[,1]32x ⎛⎫-∈ ⎪⎝⎭ ∴π2sin 2[1,2]3x ⎛⎫-∈ ⎪⎝⎭ ……………………10分 ∴()[2,3]f x ∈……………………11分 ∴函数()f x 的值域是[2,3]……………………12分21. （本小题满分l2分）（1）解：设点(),Q x y 、()00,P x y .点P 在圆C 上，∴2200(3)(5)4x y -+-=. ① ……………………1分又PA 中点为点Q∴002121x x y y =+⎧⎨=+⎩ ………………… 3分 可得021x x =-，021y y =-代入①得22(2)(3)1x y -+-=∴点Q 的轨迹方程为22(2)(3)1x y -+-= …………………… 4分 （2）假设存在直线l ，使得6=∙OM ，设()11,M x y ，()22,N x y ，由222(2)(3)1y kx x y =+⎧⎨-+-=⎩ 得22(1)(24)40k x k x +-++= …………………… 6分因为直线与Q 的轨迹交于两点所以22=(24)16(1)0k k ∆+-+> 得403k <<② …………………… 7分 且121222244,11k x x x x k k++==++ …………………… 8分又212121212(1)2()4OM ON x x y y k x x k x x +=+∙++=+222424(1)24=1011k k k k k +=+⨯+⨯+++ …………………… 9分∴2410k k +-=解得2k =-± …………………… 10分因为2k =--②， …………………… 11分 所以存在直线l：(22y x =-++，使得=10OM ON ∙ ……………………12分22. （本小题满分l2分）解：（1）当1=a 时，1cos sin cos sin )(-++-=x x x x x f ，令x x t cos sin +=，则]2,2[-∈t ，21cos sin 2-=t x x ，22)1(21121)(--=-+--=t t t t g ， 当1=t 时，0)(max =t g ，当2-=t 时，223)(min --=t g ， 所以)(x f 的值域为]0,223[--……………………4分 （2）1)cos (sin cos sin )(-++-=x x a x x x f ，令sin cos t x x =+，则当3[0,]4x π∈时，t ∈，21sin cos 2t x x -=， 2221111()1()2222t h t at t a a -=-+-=--++， …………………… 5分 )(x f 在3[0,]4π内有且只有一个零点等价于()h t 在[0,1){2}内有且只有一个零点，)2,1[无零点.因为1≥a ， ……………………6分 ∴()h t 在[0,1)内为增函数，①若()h t 在[0,1)内有且只有一个零点，)2,1[无零点，故只需10(1)01(0)0020302a h h h ⎧⎪->⎧>⎪⎪-⎪≤⇒≤⎨⎨⎪⎪>⎩->得423>a ；……………………10分②若2为()h t 的零点，)2,1[内无零点，则0232=-a ，得423=a ， 经检验，423=a 不符合题意. 综上，423>a . ……………………12分。
2017—2018学年下期高中学业质量调研抽测 高一数学试题参考答案及评分意见一、选择题: 1-5 ABBAC 6-10:BC C AA 11-12:AD二、填空题13.5.5 14.0.6 15.112π-三、解答题 17．解：(I)设等差数列{}n a 的公差为d ，则822=+d ，所以3=d ，………………2分故数列{}n a 的通项公式为31=-n a n ，前n 项和为232+=n n n S .…………………5分 (II)22=⋅n n n S b n 312+=n n ， 23471031 (2222)+=++++n n n T ， 01214710312...2222-+=++++n n n T ，.........................................................................................................8分 12143333137 (7122222)-++=++++-=-n n n n n n T ．…………………………………10分 18.解： (I)x ＝17(3＋4＋5＋6＋7＋8＋9)＝6，………………………………………2分 y ＝17(67＋69＋73＋81＋89＋90＋91)=80．…………………………………………4分 (II)设回归方程为=+y bx a ，则 717222173490768065 4.6428076147==--⨯⨯===≈-⨯-∑∑ii i i i x y x y b x x ，………………………………………………….6分 36552.147=-=≈a y bx ，所以所求回归方程为 4.6452.14=+y x ．…………8分 (III)当x ＝10时，y ＝98.54，估计每天销售10件这种服装，可获纯利润98.54元． …………………………………………………………………………………………12分19．解：(I)由正弦定理得222+=a c b .………………………2分 由余弦定理得2222cos =+-b a c ac B ,故cos =B 45=o B ………………5分(II)△ABC的面积为1sin 8,2====S ac B ac , …….7分 由4=b 得22162cos =+-a c ac B ，即2248+=a c ，………………..……………9分解得4==a c，或4==、a c ……………………………………………….12分20.解：(I)A 组学生的平均分为94＋88＋86＋80＋775＝85(分)， ∴B 组学生平均分为86分．………………………………………………………2分设被污损的分数为x ，则91＋93＋83＋x ＋755＝86，解得=x 88，………………4分 ∴B 组学生的分数分别为93,91,88,83,75，其中有3人的分数超过85分．∴在B 组学生随机选1人，其所得分超过85分的概率为35.……………………6分 (II)A 组学生的分数分别是94,88,86,80,77，B 组学生的分数分别是91,93,83,88,75，在A 、B 两组学生中分别随机抽取1名同学，其分数组成的基本事件(,)m n ，有(94,91)，(94,93)，(94,83)，(94,88)，（94，75），(88,91)，(88,93)，(88,83)，（88，88），（88，75），(86,91)，(86,93)，（86，83），（86，88），（86，75），（80，91）（80，93），（80，83），（80，88），(80,75),(77,91)，（77，93）,(77,83),(77,88),(77,75)，共25个．……………………………………8分随机各抽取1名同学的分数、m n 满足-m n 8≥的基本事件有(94,83)，(94,75)，（88，75），(86,75)，(80,91)，（80，93），（80，88），（77，91），（77，93），（77，88），共10个．………………………………………………………………………………10分 ∴-m n 8≥的概率为102255=.……………………………………………………12分 21.解：(I)在△ABC 中，因为12cos 13=A ，3cos 5=C ，∴5sin 13=A ，4sin 5=C . ………………………………………………………………………………………1分 从而sin sin(())sin()π=-+=+B AC A C5312463=sin cos cos sin 13513565A C A C +=⨯+⨯=.......................2分 由正弦定理得sin sin =AB AC C B ， 所以12604sin 104063sin 565=⋅=⨯=AC AB C B ,所以索道AB 的长为1040m .……4分(II)假设乙出发t min 后，甲、乙两游客距离为d ，此时，甲行走了(10050)+t m ，乙距离A 处130tm ，所以由余弦定理得:22212(10050)(130)2130(10050)13=++-⨯⨯+⨯d t t t t 2200(377050)=-+t t ．…………………………………………………………6分 由于10400130≤≤t ,即08≤≤t ， 故当35(min)37=t 时，甲、乙两游客距离最短．…………………………………8分 (III)由正弦定理得sin sin =BC AC A B ， 所以12605sin 500()63sin 1365=⋅=⨯=AC BC A m B ，…………………………………10分 乙从B 出发时，甲已走了50(281)550()⨯++=m ，还需走710m 才能到达C . 设乙步行的速度为/min vm ，由题意得5007102250-≤-≤v ， 解得250025008161≤≤v ， 所以为使两位游客在C 处互相等待的时间不超过2min ，乙步行的速度应控制在25002500[,]8161(单位：/min m )范围内．………………………………………12分 22．解：（I ）211458n n n n S S S S ++-+=+ ，2+11144-4-4n n n n n n S S S S S S +-+∴-+=，2144n n n a a a ++∴+=，2114n n n a a a ++∴=-(2)n ≥，……………………………………….2分 21111111122411222n n n n n n n n a a a a a a a a +++++--∴==--，又3221112122a a a a -=-，且21112a a -= 11{}2n n a a +∴-是以1为首项，公比为12的等比数列．……………………………………….4分 ∴1111()22n n n a a -+-=，11224n n n n a a ++∴-=，422n n n a -∴=…………………..………7分 （II ）由（I ）可知+1421421n n n n a c n a --==+-12121n n +--，………………………………………………………8分112121121222++--<=-- k k k k ，123111......2222∴++++<+++=n n c c c c ，……………9分 又111111(21)21111122212122(21)23222k k k k k k k ++++---==-=----⋅+- ， 1211121232+-∴≥--⋅k k k ……………………………………………………………………………………10分 12321111111......(...)2223222∴++++≥+++-+++n n c c c c 11(1)11112212323322312-=-⋅=-+>-⋅-n n n n n ..................................................................11分 综上，1231 (232)-<++++<n n n c c c c *()n N ∈成立.………………………….…………12分。
高一年级下学期月考试题英语试题2018.6第Ⅰ卷（满分100分）第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）请听下面5段对话，选出最佳选项。
1．What will the woman do next?A．Help the man. B．Finish her homework. C．Watch a program.2．What does the woman mean?A．It’s too cold this winter.B．Cold beer is harmful to health.C．The man should drink less beer.3．How much does the man have to pay?A．$90. B．$162. C．$180.4．Why does the man have so many clocks?A．He has trouble getting up. B．He often forgets about time.C．He likes collecting clocks.5．What can we infer about the speakers?A．They’ve known each other.B．They’re having coffee together.C．They think the coffee shop too small.第二节（共15小题；每小题1.5分，满分22.5分）请听下面1段对话或独白，选出最佳选项，回答第6、7题。
6．What does the woman offer to do for the man?A．Call his boss. B．Prepare for his trip. C．Record the program.7．What will the man do tomorrow?A．Go on a business trip. B．Attend a meeting. C．Take a vacation.请听下面1段对话或独白，选出最佳选项，回答第8、9题。
泉州市2017—2018学年度高中教学质量跟踪监测试卷化学（高一年下学期）参考答案一、选择题（每小题只有一个选项符合题意，本题包括22小题，其中1~10题，每小题2分；11~18题，每小题3分，共44分）题号 1 2 3 4 5 6 7 8 9 10 答案 D A B C B D D C C A 题号 11 12 13 14 15 16 17 18 答案ABCBACDB二、 填空题（本题共5小题，共56分） 19.（9分）（1）④；②；③ （各1分，共3分） （2）②；① （各1分，共2分） （3）①；② （各1分，共2分）③⑤ （各1分，共2分） 20.（8分）（1） ， （或） （各1分，共2分）（2）H 2SO 4、H 2O （各1分，共2分） （3）NH 4NO 3 （2分） （4）2S 2Cl 2+2H 2O=SO 2+3S ↓+4HCl （2分） 21.（13分）（1）CH 2=CH 2 羟基 （2分，1分） （2）CH 3COOH + CH 3CH 2OH CH 3COOC 2H 5 + H 2O （3分）酯化反应或取代反应 （1分） （3）有砖红色沉淀产生； （1分）浓H 2SO 4△．（4）饱和Na2CO3、分液（2分，1分）（5）能、聚乙烯分解需要很长时间，难以降解，污染环境（各1分，共2分）22.（13分）（1）Ca(OH)2+2NH4Cl △===CaCl2+2H2O+2NH3↑（2分）（2）ac （各1分，共2分）（3）a；极易溶于水（各1分，共2分）（4）①出现白烟；NH3+HCl= NH4Cl （1分，2分）②水沿导管倒流入D中（1分）（5）②④⑤（各1分，共3分）23. （13分）（1）分液漏斗（1分）（2）吸收SO2防止污染空气及防倒吸（2分）（3）Cu＋2H2SO4（浓）△===CuSO4＋SO2↑＋2H2O （2分）（4）品红褪色；SO2-4；（各1分，共2分）取少量所得溶液于试管中再加入BaCl2溶液，出现白色沉淀（1分）（5）BaSO4（1分）bc （各1分，共2分）（6）448 （2分）。
2017-2018高一下入学假期反馈测试（满分:100+20 时间：90分钟）Part I. 完形填空（共20小题；每小题1.5分，共30分）The Lady with the Sad EyesIt was early December and I was driving my children over an hour to a distant mall to do some Christmas shopping. We were finally nearing the exit that would take us there. I smiled and 1 quietly along to the song playing on the 2 . Suddenly I 3 a figure holding a 4 at the end of the highway exit. “It is probably someone trying to catch a 5 south,” I thought to myself.When I got close enough to read it, however, I saw that it 6 , “Homeless. Please help. Willing to work for food.” I drove past 7 to stop because of the flow of traffic to the mall. As I went past the person I saw that it was an older woman 8 worn, dirty clothes with an incredible 9 in her eyes.I took my children into the mall, but all the Christmas spirit had 10 my heart. I couldn't stop 11 about the woman by the 12 . Later after we left the mall my children and I stopped at a local convenience store to 13 some snacks for the long drive back home. We got in the car and I pulled out. When I got to the exit that would get us back on the highway, 14 , I found myself driving past it and back to the exit we had driven in on. She was 15 there holding her sign in the December air. I pulled off the side of the road, pulled out the money I had left in my wallet and gave it to my daughter in the seat beside me. She then 16 down her window and gave it to the sad eyed lady. The woman stood there with the money in her hand and 17 us, half not 18 that someone had given her so much. 19 she could finish her sentence my daughter reached out, took her hand, and gave her the food she had bought for the trip home.We pulled back out on the highway and made small talk for the rest of the way home. None of us felt proud or even 20 with what we had done. We only wished we could have done more.1. A. walked B. sang C. drove D. moved2. A. radio B. road C. train D. floor3. A. imagined B. noticed C. suspected D. remembered4. A. hat B. book C. sign D. gesture5. A. cold B. thief C. ride D. bus6. A. said B. instructed C. meant D. taught7. A. unable B. ready C. eager D. afraid8. A. on B. for C. by D. in9. A. belief B. gratefulness C. hope D. sadness10. A. attracted B. struck C. left D. broke11. A. doubting B. thinking C. complaining D. mentioning12. A. car B. exit C. store D. door13. A. bake B. make C. return D. buy14. A. however B. otherwise C. therefore D. besides15. A. perhaps B. still C. almost D. even16. A. ran B. fell C. rolled D. broke17. A. offered B. served C. thanked D. checked18. A. believing B. explaining C. supporting D. preferring19. A. Since B. While C. Until D. Before20. A. strange B. angry C. lucky D. happyPart II.阅读理解（共15小题；每小题2分，共30分）AThe Tropical Paradise HolidayWelcome to St Anna, our tropical paradise just off the coast of Latin America. You can spend two weeks in our luxury four-star hotel. The cost of your flight is included in the holiday, and you can be picked up from your home by our special airport bus. On your arriving, our coach will be waiting to take you to the hotel. All flights leave from Heathrow on a Monday morning.The Cowrie Hotel is built right on the beachfront, and many rooms have wonderful ocean views. If swimming and surfing are not enough for you, the hotel also offers horse rides on the island, and a discount membership of the golf club.The Rain Forest Adventure HolidayEvery year Broughton holidays offer twelve days of unforgettable adventure in a tropical rain forest. You may have a choice of Borneo, Malaysia, Indonesia, or even to the greatest rain forest of them all, the mighty Amazonian forest.You will fly to our special base camps at the edge of the forest, where you will be given five days of survival training, and talks on the local wildlife.Then you take a bus into the forest. You will have to walk the final five miles to the camp sites to avoid disturbing the local ecology. All of the camp sites have been carefully built to cause the minimal amount of disturbance to the local wildlife.Remember that these adventure holidays take you deep into the wilderness, and they are not suitable for families with young children. Also remember that no more than two dozen guests can stay at any camp at one time, so if you want to go on one of these very special holidays, you will need to book early!(294 words)21. Choosing the Tropical Paradise Holiday, travelers can enjoy ___________.A. a welcome partyB. beautiful ocean viewsC. different indoor activitiesD. free membership of the golf club22. What can we learn about the rain forest holiday?A. Booking early, travelers will get a discount.B. Travelers will learn to talk with wild animals.C. The holiday will end with survival training.D. Different means of transportation will be used.23. What kind of people will probably choose the rain forest holiday?A. People loving water sports.B. People travelling with children.C. People concerned with environment and wildlife.D. People preferring comfortable hotels.Three-year-old Teddy Lasry was sleeping in his cowboy outfit (套装) yesterday at his family’s Fifth Ave. apartment when he shot up in bed screaming. A 3-foot-long black-and-white snake twisted around his left arm and had just bitten his little finger.“The babysitter (a person taking care of children while their parents are away for a short time) was frightened to death,” said Teddy’s father, David Lasry, who, along with his wife, Evelyn, was at work w hen the snake appeared about 4:00 pm.The horrified babysitter called 911 and the building’s doorman. The doorman and two cable TV workers helped take the snake off the boy’s arm and put it in a garbage bag. Police rushed Teddy to Mount Sinai Medical Center, where he spent two hours attached to a heart monitor as a precaution in case the snake was poisonous. It wasn’t. Experts at the snakebite treatment center at Jacobi Medical Center in the Bronx, where policemen took the snake, found out it was a non-poisonous California king snake.But how did it end up in Teddy’s bed?A little detective work determined that the snake had escaped two weeks ago from its cage in the apartment of a doctor whose family lives four floors below the Lasrys. The apologetic owner said his son’s pet snake likely traveled up the water pipes and into his neighbor’s apartment. “It’s a very gentle, very harmless snake,” he said. “It’s handled by our family all the time.”David Lasry believed the pet was simply hungry after two weeks of wandering. Evelyn said her son seems to have overcome his fright by thinking of himself as a hero cowboy as he rode in the back of the police car to the hospital.“I told Teddy he’s a pretty snake, a nice pet snake who got out of his cage,” Evelyn said. “B ut he asked, ‘Why did he bite my finger, Mamma?’ And I said, ‘Because he saw that you are a big boy, Teddy, in your cowboy outfit and he got scared.’”(341 words)24. What did the babysitter do after Teddy was bitten by a snake?A. She made an emergency call.B. She called the TV company.C. She ran out of the apartment.D. She took the snake off Teddy’s arm.25. We can learn from the passage that the snake _______.A. was poisonousB. was deserted by its ownerC. was kept in a cage by its ownerD. escaped to the apartment downstairs26. From the passage, we know _______.A. the snake was used to being touchedB. Teddy was awake when the snake arrivedC. Teddy’s mother was at home when the snake turned upD. Teddy needed a heart machine to stay alive for two hours27. Teddy probably believed he was attacked because _______.A. his parents weren’t at home C. he was asleepB. the snake was scared of him D. the snake was hungryPeople in the United States honor their parents with two special days: Mother’s Day, on the second Sunday in May, and Father’s Day, on the third Sunday in June. These days are set aside to show love and respect for parents. They raise their children and educate them to be responsible citizens. They give love and care. These two days offer an opportunity to think about the changing roles of mothers and fathers. More mothers now work outside the home. More fathers must help with child-care.These two special days are celebrated in many different ways. On Mother’s D ay people wear carnations. A red one symbolizes a living mother. A white one shows that the mother is dead. Many people attend religious services to honor parents. It is also a day when people whose parents are dead visit the cemetery. On these days, famil ies get together at home, as well as in restaurants. They often have outdoor barbecues for Father’s Day. These are days of fun and good feelings and memories.Another tradition is to give cards and gifts. Children make them in school. Many people make their own presents. These are valued more than the ones bought in stores. It is not the value of the gift that is important, but it is “the thought” that counts. Greeting card stores, florists, candy makers, bakeries, telephone companies, and other stores do a lot of business during these holidays. (238 words)28. Which is NOT a reason for children to show love and respect for parents?A. Parents bring up children.B. Parents give love and care to children.C. Parents pass away before children grow up.D. Parents educate children to be good persons.29. What do you know from the passage?A. Fewer women worked outside the home in the past.B. Mother’s Day and Father’s Day are both in May.C. Fathers are not as important as mothers at home.D. Not all the children respect their parents.30. Which do you think is right about “carnation”?A. It only has two kinds of color.B. It’s kind of flower showing love and best wishes.C. People can wear carnations only on the second Sunday in May.D. It ref ers to the special clothes people wear on Mother’s Day or Father’s Day.31. What do you think “florists” do?A. They sell flowers.B. They make bread or pastry.C. They offer enough room for having family parties.D. They sell special clothes for Mot her’s Day and Father’s Day.Personality types are linked with structural differences in the brain, which could explain why one child grows up to be impulsive（冲动的）and outgoing while another becomes diligent and introspective. Structural differences between the brains of 85 people have been measured and linked with the four main categories of personality types, which were classified as “novelty seeking”, characterized by impulsive actions; “harm avoidance”, marked by pessimism and shyness; “reward dependence”, with an addictive personality; and “persistence”, who are people tending to be diligent, hard-working and perfectionists.The researchers said the brain differences are structural and can be measured in the size of specific regions of the brain that appear to be linked with each of the four personality types. For instance, people defined as novelty-seeking personalities had a structurally bigger area in the brain while people with harm-avoidance personalities had significantly smaller volumes of tissue in brain regions.The fact that characteristics are reflected in specific structural differences is useful to know, for instance, when it comes to understanding a child’s behavior and choosing the right approach so that somebody who is, for example, particularly timid, might be helped through education and development.There is no point shouting at a child who is very shy and telling them off, because it does not come naturally to them to put themselves forward. But actually knowing there is a biological basis for this helps educators or parents to use the right approach to help a child to compensate.People who have a reward-dependence personality could, for example, be helped at an early age because they are at risk of turning to drink, drugs or food if they do not get the family support and encouragement they need.“This study shows that personality characteristics are something you are born with, but their full expression can be adjusted during development with the right approach,” said Professor Ve nneri, who carried out the study with colleagues from the University of Parma in Italy and Washington University in St Louis. If you know it’s not something you do but something you are, you can change the environment to reduce the risk. Knowing that someone has such a predisposition (体质) could help them adopt preventive strategies and avoid situations where they might seek rewards which could be potentially harmful. (388 words)32. Which type of person may turn out to be drug-abusers?A. “Novelty seeking”.B. “Reward dependence”.C. “Harm avoidance”.D. “Persistence”.33. Which of the following is true about shy people?A. They are often shouted at and scolded.B. They can naturally put themselves forward.C. They structurally have a smaller brain region.D. They are too timid to be educated and helped.34. What’s the main idea of the passage?A. People have chances to change their personality types.B. Scientists have identified four different personality types.C. Structural differences in the brain have effects on education.D. Personality types are related to structural differences in the brain.35. The author writes the passage to ____________.A. present a factB. argue a claimC. support a researchD. introduce an approach注意：请把完型和阅读答案填涂到机读卡上！！！班级姓名得分Part III. 词汇(共20题；每题1分，满分20分)1) I hadn’t seen her for ages, but I her immediately when I saw her.2) When the teacher came into the classroom, we the room with colorful balloons and flags.3) He ____________the doctor’s advice and went on with his unhealthy lifestyle.4) He thought of a good way and the problem finally.5) The brave boy ________________with a medal for saving the drowning girl.6) Michael has been working in the marketing department since he____________from Harvard University five years ago.7) He ____________that he broke the glass at last.8) The students __________________to visit the National Museum last Friday.9) They have different personalities and often ______________over any topic.10) The old man slipped down on the icy road and _____________his ankle.2. 根据中文意思，补全句子。
