高二英语月考试题及答案-湛江市第一中学2015-2016学年高二下学期月考试卷

2015～2016学年上学期汉铁高中高二10月月考英语试题第一部分：听力(分两节，共20小题，每小题1.5分，满分30分)第一节听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What does the woman suggest doing?Repairing the telephone. Surfing the Internet. Cooking at home.2.What did the man do?He bought a computer. Surfing the Internet. He hunted for a new job.3.What are the speakers talking about?A fire. A flood. An earthquake.4.How many people will be expected to the party?15. 135. 150.5.Why does the woman mention her dinner guests?To ask the man to join them. Surfing the Internet. To invite the man to have another drink.第二节听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听下面一段对话，回答第6和第7两个小题。

6.How much wil l the man pay for the CD player?$30. $70. $100.7.What is the man concerned about?Return policy. After-sale repairin g. Exchange of of goods.听下面一段对话，回答第8和第9两个小题。

2015年天津卷高考真题英语试卷-学生用卷一、单项选择1、【来源】 2015年高考真题天津卷第1题2020~2021学年天津和平区天津市第二南开学校高一上学期期中第22题0.5分2017~2018学年天津高一期末联考第9题1分2018~2019学年天津静海区天津市静海区第一中学高二上学期期中第16题1分—Sorry, Liz. I think I was a bit rude to you.—______, but don't do that again!A. Go aheadB. Forget itC. It dependsD. With pleasure2、【来源】 2015年高考真题天津卷第2题The quality of education in this small school is better than ______ in some larger schools.A. thatB. oneC. itD. this3、【来源】 2015年高考真题天津卷第3题2016~2017学年广东广州高二上学期期中五校联考第17题1分2018~2019学年吉林长春朝阳区吉林省实验中学高二下学期期末第30题1分Only when Lily walked into the office that she had left the contract at home.A. she realizedB. has she realizedC. she has realizedD. did she realize4、【来源】 2015年高考真题天津卷第4题—Jack, you seem excited.—______? I won the first prize.A. Guess whatB. So whatC. Pardon meD. Who cares5、【来源】 2015年高考真题天津卷第5题2018~2019学年10月广东深圳福田区深圳市高级中学高中部高二月考第47题1分2019~2020学年广东深圳罗湖区深圳市翠园中学高二上学期期中第6题1分2019~2020学年陕西西安长安区西安交通大学附属中学航天学校高三上学期段考（四诊）第22题1分2017~2018学年北京海淀区北京市十一学校高二上学期期末第49题0.5分in painting, John didn't notice evening approaching.A. To absorbB. To be absorbedC. AbsorbedD. Absorbing6、【来源】 2015年高考真题天津卷第6题2016~2017学年天津高一下学期期末第22题0.5分2017~2018学年天津和平区天津市第一中学高一下学期期末第25题1分2019~2020学年陕西西安长安区西安交通大学附属中学航天学校高三上学期段考（四诊）第23题1分2016~2017学年北京海淀区北京一零一中学高二下学期期中第22题1分Jane can't attend the meeting at 3 o'clock this afternoon because she a class at that time.A. will teachB. would teachC. has taughtD. will be teaching7、【来源】 2015年高考真题天津卷第7题2019~2020学年3月天津河西区高三下学期月考第14题1分I ______ have worried before I came to the new school, for my classmates here are very friendly to me.A. mightn'tB. mustn'tC. needn'tD. couldn't8、【来源】 2015年高考真题天津卷第8题2018~2019学年10月天津和平区天津市双菱中学高二上学期月考第26题1分2018~2019学年10月广东深圳福田区深圳市高级中学高中部高二月考第48题1分2019~2020学年3月天津河西区高三下学期月考第11题1分2019~2020学年广东深圳福田区深圳市高级中学高中部高一下学期期中第15题1.5分______ for two days, Steve managed to finish his report on schedule.A. To workB. WorkedC. To be workingD. Having worked9、【来源】 2015年高考真题天津卷第9题2019~2020学年12月江苏南京玄武区南京市第九中学高一上学期月考第63题1分2018~2019学年陕西西安未央区西安中学高一上学期期末第26题1分2017~2018学年北京东城区北京汇文中学高二上学期期中第35题1分2017~2018学年广东深圳福田区深圳市高级中学高中部高一下学期期中第53题1分Despite the previous rounds of talks, no agreement so far by the two sides.A. has been reachedB. was reachedC. will reachD. will have reached10、【来源】 2015年高考真题天津卷第10题2019~2020学年陕西西安长安区西安交通大学附属中学航天学校高三上学期段考（四诊）第25题1分Tom had to the invitation to the party last weekend because he was too busy.A. turn inB. turn downC. turn overD. turn to11、【来源】 2015年高考真题天津卷第11题2019~2020学年天津南开区高三上学期期末第6题1分If you have any doubts about your health, you'd better______ your doctor at once.A. convinceB. consultC. avoidD. affect12、【来源】 2015年高考真题天津卷第12题We need to get to the root of the problem we can solve it.A. whileB. afterC. beforeD. as13、【来源】 2015年高考真题天津卷第13题2015~2016学年北京西城区北京师范大学第二附属中学高二上学期期中第5题I wish I ______ at my sister's wedding last Tuesday, but I was on a business trip in New York then.A. will beB. would beC. have beenD. had been14、【来源】 2015年高考真题天津卷(部分区联考)第14题2016~2017学年天津高一下学期期末第13题1分See, your computer has broken down again! It doesn't ______ sense to buy the cheapest brand of computer just to save a few dollars.A. haveB. makeC. displayD. bring15、【来源】 2015年高考真题天津卷第15题2018~2019学年广东深圳宝安区宝安第一外国语学校高二下学期期中第62题1分2017~2018学年天津和平区天津市第一中学高二上学期期末第16题1分The boss of the company is trying to create an easy atmosphere his employees enjoy their work.A. whereB. whichC. whenD. who二、完型填空16、【来源】 2015年高考真题天津卷第16题2017~2018学年12月河南洛阳洛龙区洛阳市第一高级中学高二上学期月考第36~55题20分2019~2020学年高一下学期单元测试第30~49题2017~2018学年黑龙江大庆红岗区大庆市铁人中学高二上学期期中第41~60题30分My fiance （未婚夫） and I were excited about shopping for our first home. But our fundswere1, and none of the houses in our price range seemed satisfactory.One agent2 a house in particular. Although her description sounded wonderful, the price was3our range, so we declined. But she kept urging us to have a look4.We finally did and it was5at first sight. It was Our Home, small and charming, overlooking a quiet lake. Walking through the rooms and talking with the owners, a nice elderly couple, we felt the warmth and6of the marriage within that home. As perfect as it was, the price remained too high for us. But every day, we would sit by the lake, looking at the house and dreaming of7it would be like to live there.Days later, we made a(n)8—far below the asking price. Surprisingly, they didn't9us. They renewed their offer10. It was also much more than we could afford, but far11than the original asking price.The next day, we got a12message that another buyer had offered a much higher price. Even so, we decided to talk with the13directly. We made our final offer, which14was thousands of dollars less than the other buyer's bid. We knew it,15we had to try.“Sold!” said the owner. Then he16: He'd seen us sitting by the lake all those times; he knew how much we loved the place and that we'd17the years of work they had put into their home; he realized he would take a18by selling it to us, but it was worthwhile; we were the people they wanted to live there. He told us to consider the19in the price “an early wedding present.”That's how we found our home and how I learned that when peopleare20they are not strangers, only friends we haven't yet met.A. neededB. limitedC. enoughD. largeA. recommendedB. decoratedC. soldD. rentedA. belowB. withinC. beyondD. betweenA. at leastB. at mostC. at timesD. at handA. reliefB. concernC. loveD. curiosityA. prideB. happinessC. challengeD. desireA. whichB. whyC. thatD. whatA. effortB. offerC. promiseD. profitA. come acrossB. look afterC. depend onD. laugh atA. insteadB. indeedC. asideD. apartA. worseB. betterC. lessD. higherA. relaxingB. disappointingC. pleasantD. regularA. agentsB. buyersC. managersD. ownersA. alreadyB. stillC. generallyD. everA. soB. orC. forD. butA. apologizedB. complainedC. criticizedD. explainedA. checkB. analyzeC. appreciateD. ignoreA. lossB. riskC. chanceD. leadA. increaseB. differenceC. interestD. averageA. kindB. politeC. smartD. energetic三、阅读理解17、【来源】 2015年高考真题天津卷（A篇）第17题University Room RegulationsApproved and Prohibited ItemsThe following items are approved for use in residential （住宿的） rooms: electric blankets, hair dryers, personal computers, radios, televisions and DVD players. Items that are not allowed in student rooms include: candles, ceiling fans, fireworks, waterbeds, sun lamps and wireless routers. Please note that any prohibited items will be taken away by the Office of Residence Life.Access to Residential RoomsStudents are provided with a combination （组合密码） for their room door locks upon check-in. Do not share your room door lock combination with anyone. The Office of Residence Life may change the door lock combination at any time at the expense of the resident if it is found that the student has shared the combination with others. The fee is $25 to change a room combination.Cooking PolicyStudents living in buildings that have kitchens are only permitted to cook in the kitchen. Students must clean up after cooking. This is not the responsibility of housekeeping staff. Kitchens that are not kept clean may be closed for use. With the exception of using a small microwave oven （微波炉） to heat food, students are not permitted to cook in their rooms.Pet PolicyNo pets except fish are permitted in student rooms. Students who are found with pets, whether visiting or owned by the student, are subject to an initial fine of ＄100 and a continuing fine of ＄50 a day per pet. Students receive written notice when the fine goes into effect. If, one week from the date of written notice, the pet is not removed, the student is referred to the Student Court.Quiet HoursResidential buildings must maintain an atmosphere that supports the academic mission of the University. Minimum quiet hours in all campus residences are 11:00 pm to 8:00 am Sunday through Thursday. Quiet hours on Friday and Saturday nights are 1:00 am to 8:00 am. Students who violate quiet hours are subject to a fine of $25.(1) Which of the following items are allowed in student rooms?A. Ceiling fans and waterbeds.B. Wireless routers and radios.C. Hair dryers and candles.D. TVs and electric blankets.(2) What if a student is found to have told his combination to others?A. The combination should be changed.B. The Office should be charged.C. He should replace the door lock.D. He should check out of the room.(3) What do we know about the cooking policy?A. A microwave oven can be used.B. Cooking in student rooms is permitted.C. A housekeeper is to clean up the kitchen.D. Students are to close kitchen doors after cooking.(4) If a student has kept a cat in his room for a week since the warning, he will face _____.A. parent visitsB. a fine of $100C. the Student CourtD. a written notice(5) When can students enjoy a party in residences?A. 7:00 am, Sunday.B. 7:30 am, Thursday.C. 11:30 pm, Monday.D. 00:30 am, Saturday.18、【来源】 2015年高考真题天津卷第18题Whether in the home or the workplace, social robots are going to become a lot more common in the next few years. Social robots are about to bring technology to the everyday world in a more humanized way, said Cynthia Breazeal, chief scientist at the robot company Jibo.While household robots today do the normal housework, social robots will be much more like companions than mere tools. For example, these robots will be able to distinguish when someone is happy or sad. This allows them to respond more appropriately to the user.The Jibo robot, arranged to ship later this year, is designed to be a personalized assistant. You can talk to the robot, ask it questions, and make requests for it to perform different tasks. The robot doesn't just deliver general answers to questions; it responds based on what it learns about each individual in the household. It can do things such as reminding an elderly family member to take medicine or taking family photos.Social robots are not just finding their way into the home. They have potential applications in everything from education to health care and are already finding their way into some of these spaces.Fellow Robots is one company bringing social robots to the market. The company's "Oshbot" robot is built to assist customers in a store, which can help the customers find items and help guide them to the product's location in the store. It can also speak different languages and make recommendations for different items based on what the customer is shopping for.The more interaction the robot has with humans, the more it learns. But Oshbot, like other social robots, is not intended to replace workers, but to work alongside other employees. "We have technologies to train social robots to do things not for us, but with us, " said Breazeal.(1) How are social robots different from household robots?A. They can control their emotions.B. They are more like humans.C. They do the normal housework.D. They respond to users more slowly.(2) What can a Jibo robot do according to Paragraph 3?A. Communicate with you and perform operations.B. Answer your questions and make requests.C. Take your family pictures and deliver milk.D. Obey your orders and remind you to take pills.(3) What can Oshbot work as?A. A language teacher.B. A tour guide.C. A shop assistant.D. A private nurse.(4) We can learn from the last paragraph that social robots will.A. train employeesB. be our workmatesC. improve technologiesD. take the place of workers(5) What does the passage mainly present?A. A new design idea of household robots.B. Marketing strategies for social robots.C. Information on household robots.D. An introduction to social robots.19、【来源】 2015年高考真题天津卷第19题2017~2018学年12月河南洛阳洛龙区洛阳市第一高级中学高二上学期月考第21~25题10分2017~2018学年陕西西安雁塔区陕西师范大学附属中学高三上学期开学考试第24~28题10分One day when I was 12, my mother gave me an order: I was to walk to the public library, and borrow at least one book for the summer. This was one more weapon for her to defeat my strange problem—inability to read.In the library, I found my way into the "Children's Room."I sat down on the floor and pulled a few books off the shelf at random. The cover of a book caught my eye. It presented a picture of a beagle. I had recently had a beagle, the first and only animal companion I ever had as a child. He was my secret sharer, but one morning, he was gone, given away to someone who had the space and the money to care for him. I never forgot my beagle.There on the book's cover was a beagle which looked identical to my dog. I ran my fingers over the picture of the dog on the cover. My eyes ran across the title, Amos, the Beagle with a Plan. Unknowingly, I had read the title. Without opening the book, I borrowed it from the library for the summer.Under the shade of a bush, I started to read about Amos. I read very, very slowly with difficulty. Though pages were turned slowly, I got the main idea of the story about a dog who, like mine, had been separated from his family and who finally found his way back home. That dog was my dog, and I was the little boy in the book. At the end of the story, my mind continued the final scene of reunion, on and on, until my own lost dog and I were, in my mind, running together.My mother's call returned me to the real world. I suddenly realized something: I had read a book, and I had loved reading that book. Everyone knew I could not read. But I had read it. Books could be incredibly wonderful and I was going to read them.I never told my mother about my "miraculous"（奇迹般地）experience that summer, but she sawa slow but remarkable improvement in my classroom performance during the next year. And years later, she was proud that her son had read thousands of books, was awarded a PhD in literature, and authored his own books, articles, poetry and fiction. The power of the words has held.(1) The author's mother told him to borrow a book in order to.A. encourage him to do more walkingB. let him spend a meaningful summerC. help cure him of his reading problemD. make him learn more about weapons(2) The book caught the author's eye because.A. it contained pretty pictures of animalsB. it reminded him of his own dogC. he found its title easy to understandD. he liked children's stories very much(3) Why could the author manage to read the book throughA. He was forced by his mother to read it.B. He identified with the story in the book.C. The book told the story of his pet dog.D. The happy ending of the story attracted him.(4) What can be inferred from the last paragraph?A. The author has become a successful writer.B. The author's mother read the same book.C. The author's mother rewarded him with books.D. The author has had happy summers ever since.(5) Which one could be the best title of the passage?A. The Charm of a BookB. Mum's Strict OrderC. Reunion with My BeagleD. My Passion for Reading20、【来源】 2015年高考真题天津卷第20题DOnce when I was facing a decision that involved high risk, I went to a friend. He looked at me for a moment, and then wrote a sentence containing the best advice I've ever had: Be bold and brave — and mighty (强大的) forces will come to your aid.Those words made me see clearly that when I had fallen short in the past, it was seldom because I had tried and failed. It was usually because I had let fear of failure stop me from trying at all. On the other hand, whenever I had plunged into deep water, forced by courage or circumstance, I had always been able to swim until I got my feet on the ground again.Boldness means a decision tobite off more than you can eat. And there is nothing mysterious about the mighty forces. They are potential powers we possess: energy, skill, sound judgment, creative ideas —even physical strength greater than most of us realize.Admittedly, those mighty forces are spiritual ones. But they are more important than physical ones. A college classmate of mine, Tim, was an excellent football player, even though he weighed much less than the average player. “In one game I suddenly found myself confronting a huge player, who had nothing but me between him and our goal line,” said Tim. “I was so frightened that I closed my eyes and desperately threw myself at that guy like a bullet — and stopped him cold.”Boldness — a willingness to extend yourself to the extreme—is not one that can be acquired overnight. But it can be taught to children and developed in adults. Confidence builds up. Surely, there will be setbacks (挫折) and disappointments in life; boldness in itself is no guarantee of success. But the person who tries to do something and fails is a lot better off than the person who tries to do nothing and succeeds.So, always try to live a little bit beyond your abilities—and you'll find your abilities are greater than you ever dreamed.(6) Why was the author sometimes unable to reach his goal in the past?A. He faced huge risks.B. He lacked mighty forces.C. Fear prevented him from trying.D. Failure blocked his way to success.(7) What is the implied meaning of the underlined part?A. Swallow more than you can digest.B. Act slightly above your abilities.C. Develop more mysterious powers.D. Learn to make creative decisions.(8) What was especially important for Tim’s successful defense in the football game?A. His physical strength.B. His basic skill.C. His real fear.D. His spiritual force.(9) What can be learned from Paragraph 5?A. Confidence grows more rapidly in adults.B. Trying without success is meaningless.C. Repeated failure creates a better life.D. Boldness can be gained little by little.(10) What is the author’s purpose in writing this passage?A. To encourage people to be courageous.B. To advise people to build up physical power.C. To tell people the ways to guarantee success.D. To recommend people to develop more abilities.四、任务型阅读21、【来源】 2015年高考真题天津卷第21题Six days a week, up and down the red hills of northeast Georgia, my grandfather brought the mail to the folks there. At age 68, he retired from the post office, but he never stopped serving the community.On his 80th birthday, I sent him a letter, noting the things we all should be thankful for — good health, good friends and good outcomes. By most measurements he was a happy man. Then I suggested it was time for him to slow down. At long last, in a comfortable home, with a generous pension, he should learn to take things easy.“Thank you for your nice words,” he wrote in his letter back, “and I know what you meant, but slowing down scares me. Life isn't having it made; it's getting it made.”“The finest and happiest years of our lives were not when all the debts were paid, and all difficult experiences had passed, and we had settled into a comfortable home. No. I go back years ago, when we lived in a three-room house, when we got up before daylight and worked till after dark to make ends meet.I rarely had more than four hours of sleep. But what I still can't figure out is why I never got tired, never felt better in my life. I guess the answer is, we were fighting for survival, protecting and providing for those we loved. What matters are not the great moments, but the partial victories, the waiting, and even the defeats. It's the journey, not the arrival, that counts.”The letter ended with a personal request: “Boy, on my next birthday, just tell me to wake up and get going, because I will have one less year to do things — and there are ten million things waiting to be done.”Christina Rossetti, an English poet, once said: “Does the road wind uphill all the way? Yes, to the very end.” Today, at 96, my grandfather is still on that long road, climbing.(6) What was the author’s grandfather before he retired? (no more than 5 words)(7) What did the author advise his grandfather to do in his letter? (no more than 10 words)(8) What is the grandfather’s view on life according to his letter back? (no more than 10 words)(9) How do you understand the underlined sentence in the last paragraph? (no more than 10 words)(10) Do you agree with the grandfather’s view on life? Give reasons in your own words, (no more than 20 words)五、书面表达22、【来源】 2015年高考真题天津卷第22题假设你是晨光中学学生会主席李津，你校拟向美国友好交流学校的中文班捐赠一批图书。

上饶县中学2017届高二下学期第一次月考语文试卷命题人：宫文华审题人：李维军本试卷分第I卷（阅读题）和第II卷（表达题）两部分。

满分150分。

考试时间150分钟。

注意事项：1．本试卷满分150分，考试时间150分钟。

试卷答案一律写在答题卷上。

考试结束，只交答题卷。

2．答题前，考生务必将自己的姓名、考号等信息填写在答题卷上。

3．选择题答案使用2B铅笔填涂，如需改动，用橡皮擦干净后，再选涂其他答案标号；非选择题答案使用0.5毫米的黑色墨水签字笔书写，字体工整，笔迹清楚。

4．请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效。

第Ⅰ卷阅读题（共70分）一、现代文阅读（9分，每小题3分）阅读下面的文字，完成1-3题。

围棋与国家林建超围棋起源于中国，是黄河文明的产物，其形制弈法等都饱含着文明母体的基因和特征。

围棋极可能源自上古时期的结绳而治、河图洛书和周易八卦，因为其形制、内涵与中华文明的源头相符。

围棋的产生和发展，始终与弈者对自然、社会和人生的思考感悟联系在一起。

围棋不仅对个人修身养性，而且对民族社会的群体心理产生深刻影响。

围棋是中华五千年文明的象征，民族文化的瑰宝、高度智慧的结晶，这种地位不是任何人封赐的，也不是带有感情色彩的主观结论，而是人们在反复实践和比较中认识到的，是随着社会和文明的进步而不断深化和升华的。

围棋的价值和地位是在与各种掷彩博累活动的比较中确立起来的。

最早有文献记载的围棋活动是在春秋时期。

从春秋到西汉，社会风气浮躁、趋利，具有运气性和刺激性、宜于赌博的博累棋流行甚广，围棋处于受挤压的位置，但始终保持着顽强的生命力。

东汉中期后，社会风气转变，文明程度提高，思想更为自由，人们不满足于掷彩行棋的非公平的竞智斗巧，围棋更加受到人们的喜爱和重视，而曾经盛极一时的博累棋逐步走向衰弱，到唐代时完全消亡了。

博累棋消亡的原因从根本上说是他们不符合我们民族的思想特征，不能满足人们精神生活的真正需求，而围棋在与它们的比较中表现出了本质上的优势。

川一中2015-2016学年度第二学期高一5月考试英语试卷注意事项：1．选择题部分答案用2B铅笔填涂在答题卡对应题号内，答案不能写在试卷上。

2．非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内。

第一部分听力（共15小题，每小题1分，共15分）每段播放两遍。

各段后有几个小题，各段播放前每小题有5秒钟的阅题时间。

请根据各段播放内容及其相关小题，在5秒钟内从题中所给的A，B,C项中，选出最佳选项。

听第一段对话，回答第1—2题。

1. What did the man do on Saturday?A. He went to the movies.B. He had dinner with his friends.C. He called on some friends.2. Who went to see the film with the woman?A. Her classmates.B. Her friends.C. Her husband.听第二段对话，回答第3—4题。

3. How many times has the shop been robbed?A. Five.B. Six.C. Seven.4. What is the woman’s suggestion to the man?A. Rebuilding the shop.B. Closing the shop.C. Decorating the shop.听第三段对话，回答第5—6题。

5. What is the man doing?A. Ordering food.B. Asking for some advice.C. Complaining.6. What will the woman do for the man?A. Bring him another glass.B. Cook the steak for him.C. Ask him to leave. 听第四段对话，回答第7—9题。

成都七中高二下期化学分层练习题(3)注：每个选择题只有一个．．．．选项符合题意。

1．以下分离提纯操作能达到相应目的是（）2．下列各组离子在溶液中能够大量共存，当溶液中c（H+）=10﹣1 mol•L﹣1时，有气体产生：而当溶液中c（H+）=10﹣13 mol•L﹣1时，又能生成沉淀．则该组离子可能是（）A．Na+、Ba2+、NO3﹣、CO32﹣B．Fe2+、Na+、SO42﹣、NO3﹣C．Mg2+、NH4+、SO42﹣、Cl﹣D．Ba2+、K+、Cl﹣、NO3﹣3．能正确表示下列反应的离子方程式是（）A．Fe2O3溶于过量氢碘酸溶液中：Fe2O3+6H++2I﹣═2Fe2++I2+3H2OB．0.1mol/LNH4Al（SO4）2溶液与0.2mol/LBa（OH）2溶液等体积混合：Al3++2SO42﹣+2Ba2++4OH﹣═2BaSO4↓+AlO2﹣+2H2OC．用浓盐酸酸化的KMnO4溶液与H2O2反应，证明H2O2具有还原性：2MnO4-+6H++5H2O2═2Mn2++5O2↑+8H2OD．向次氯酸钠溶液中通入足量SO2气体：ClO﹣+SO2+H2O═HClO+HSO3﹣4．短周期元素X、Y、Z、W的原子序数依次增大，它们的原子最外层电子数为互不相等的奇数，且X、Y、W原子最外层电子数之和恰好等于Z元素的核电荷数，X与W的最高化合价之和为8，常见金属元素Z的一种核素的质量数为28，中子数比质子数多2．下列说法中正确的是（）A．用“百度”搜索知，Y、Z形成的化合物“室温下强度高，…．导热性好，热膨胀系数小，是良好的耐热冲击材料．”由此可推测该化合物属于离子晶体B．化合物YW3水解产物之一具有强氧化性，由此可知Y在该化合物中的化合价为+3 C．由非金属元素组成的化合物YX5是一种是否存在尚待确证的化合物，假如存在，该物质与水反应必然生成气体X2，同时得到一种弱碱溶液D．因为Z的氧化物熔点很高，不适宜于电解，故工业上常用电解Z与W的化合物的方法制取单质Z5．下列说法正确的是（）A．按系统命名法，化合物的名称为2﹣甲基﹣2﹣乙基丙烷B．用溴水可以鉴别1－己烯、碘化钾溶液、苯三种液体C．碳原子数小于5的烷烃共有4种，他们之间互为同系物D．石油裂解可以得到乙烯，煤干馏得到的煤焦油中可以提取苯，乙烯和苯使溴水褪色的原理相同6．LiOH是制备锂离子电池的材料，可由电解法制备．工业上利用如图装置电解制备LiOH，两电极区电解液分别为LiOH和LiCl溶液，下列说法正确的是（）A．电极每产生22.4 L气体，电路中转移2 mole﹣B．电解过程中Li+迁移入B电极区、OH﹣迁移入A电极区C．电解池中总反应方程式为：2HCl2H2↑+Cl2↑D．B极区电解液为LiOH溶液7．甲、乙、丙、丁是中学常见的物质，其中甲、乙、丙均含有同一种元素，在一定条件下的转化关系见图，下列说法正确的是（）A．若丁为用量最大，用途最广的金属单质，乙的溶液一定为FeCl3B．若通常情况下甲、乙、丙、丁都是气体，且乙和丁为空气的主要成分，则反应①的化学方程式为4NH3+5O24NO+6H2OC．若甲、乙、丙的溶液显碱性，则丙可能可以作为医疗上治疗胃酸过多症的药剂D．若丁为化合物，且为氯碱工业的重要产品，则甲一定为含Al3+的盐8．900℃时，向2.0 L恒容密闭容器中充入0.40 mol乙苯，发生反应：C2H5（g）⇌CH=CH2（g）+H2（g）△H=a kJ．mol﹣1．经一段时间后达到平衡．反应过程中测定的部分数据见下表：下列说法正确的是（）A．反应在前20 min的平均速率为v（H2）=0.002 mol•L﹣1•min﹣1B．保持其他条件不变，升高温度，平衡时，c（乙苯）=0.08 mol•L﹣1，则a＜0C．保持其他条件不变，向容器中充入不参与反应的水蒸气作为稀释剂，则乙苯的转化率为50.0%D．相同温度下，起始时向容器中充入0.10 mol乙苯、0.10 mol苯乙烯和0.30 molH2，达到平衡前v（正）＞v（逆）9．C3H2F5Cl的结构有（不含立体异构）（）A．7种B．8种C．9种D．10种10．常温下，下列有关叙述正确的是（）A．在0.1mol•L﹣1Na2C2O4溶液中：2c（Na+）=c（C2O42﹣）+c（HC2O4﹣）+c（H2C2O4）B．向10mL pH=12的NaOH溶液中滴加等体积pH=2的CH3COOH溶液：c（CH3COO﹣）＞c（Na+）＞c（OH﹣）＞c（H+）C．浓度均为0.1 mol•L﹣1的小苏打溶液与烧碱溶液等体积混合：c（Na+）+c（H+）=c（CO32﹣）+c（OH﹣）+c（HCO3﹣）D．浓度均为0.1 mol•L﹣1的硫酸氢铵溶液与氢氧化钠溶液等体积混合c（SO42﹣）=c（Na+）＞c（NH4+）＞c（H+）＞c（OH﹣）11．常温下，在20.00 mL 0.100 0 mol·L－1 NH3·H2O溶液中逐滴滴加0.100 0 mol·L－1 HCl溶液，溶液pH随滴入HCl溶液体积的变化曲线如右图所示。

2015-2016学年度第一学期武山一中高一第一次月考卷英语试卷命题人：王映平第I卷（选择题）一、阅读理解（30分）第一节：阅读下面短文，掌握其大意，然后从各题所给的四个选项（A、B、C和D）中，选出最佳选项。

（共15小题；每小题2分，共30分）AEddie liked music very much when he was at school, but when he went to the university he decided to study medicine instead of music. When he passed his examinations and became a doctor, he had to work in a hospital for some time. There he discovered that a lot of patients were happier and caused less trouble if pleasant music was played to them When Eddie got an office and began to work for himself, he decided to keep his patients happy by having a tape recorder in his waiting-room play beautiful music for them.But soon after the tape recorder had been put in, Eddie‟s nurse heard a wo man, who was sitting in the crowded waiting-room one morning, complained, “Here we‟re all waiting to see the doctor, and he‟s just playing the violin in his office instead of doing his work.”1．Eddie became a student of medicine at university__________.A．because he had lost interest in musicB．because he thought medicine was more important than musicC．to find out new use of music in hospitalD．for reasons unknown from this passage2．Why did Eddie put a tape recorder in his office?A．He wanted to help patients waiting to see him pass the time easily.B．He discovered that music was of help to his patientsC．He enjoyed listening to music while he workedD．He wanted to attract more patients to his office3．From the passage we can see that__________.A．the woman thought Eddie was an unusual doctorB．the woman didn‟t understand musicC．the woman did not understand what Eddie meantD．the woman hated to be kept waitingBTwo men were sitting together in a plane. They were on a long journey. One of the men was a businessman. The other was a farmer. They sat without talking for a while, then the farmer said, “Let‟s do something to pass the time.”“What do you want to do?” the businessman asked. “We can ask each other riddles.” The farmer said, “You start.” “Let‟s make the rules first,” the businessman said. “That‟s not fair. You are a businessman with much knowledge. You know more things than I do. I am just a farmer.”“That‟s true.” The businessman said. “What do you want we should do?” “If you don‟t know the answer to a riddle, you pay me $100. And if I don‟t know the answer, I‟ll pay you $50.” The farmer said. The businessman thought about this, then he said, “OK. That‟s fair. Who will go first?”“I will,” The farmer said. “Here is my riddle. What has three legs when it walks, but only two legs when it flies?” The business man repeated the riddle, “What has three legs when it walks, but only two legs when it flies? Mm, that‟s a good one. I‟m afraid I don‟t know the answer.” He gave the farmer $100, then said, “Tell me the answer. What has three legs when it walks, but only two legs when it flies?” “I don‟t know.” The farmer said and gave him $50.4．The story happened ____________.A．on a farm B．in a shopC．before a long plane journey D．between two passengers5．What does the word “riddle” mean in this story?A．A difficult question to find the answer to.B．Something to help to make rules.C．Something to win money.D．a kind of game in doing business.6．Why did the businessman agree to give more money if he lost?A．He made much more money than the farmer.B．He thought he knew more than the farmer.C．He was interested in making riddles.D．He was better at playing riddle games.7．The farmer _________.A．enjoyed himself on his long journey.B．didn‟t want to pay even one dollarC．spent all his money on the plane ticket.D．won fifty dollars by playing the riddle gameCDoing homework not only can help children master the knowledge they have learned, but also can train their abilities of finishing the work alone, planning the time and doing the duties. But some children don‟t like to complete the work. Why? There are some reasons.Some children feel it is very difficult to do their homework, because they can‟t understand their teacher clearly, and can‟t follow their teacher‟s teaching process. Maybe there is something wrong with their intelligence.But some children‟s intelligence is normal. They are even cleverer, but they don‟t listen to the teacher carefully. It is hard for them to sit well and pay attention to anything. It needs to carry on the attention centralized（集中注意力）training to help the children.Some children love their teacher and then they like the subject. Their interest depends on the teacher who teaches them. So every teacher should be helpful and kind. It can make children love you and the subject you teach. So they can do their homeworkhappily.8．Doing homework can help children ___________.A．master the knowledge B．train their abilitiesC．lean new lessons D．Both A and B9．Some children find the homework difficult. Which reason is NOT right? A．They can‟t understand their teacher clearly.B．They can‟t follow their teacher‟s teaching process.C．The intelligence of all the students isn‟t normal.D．They don‟t listen to the teache r carefully.10．What‟s the Chinese meaning of the underlined word “intelligence”?A．作业B．智商C．思想D．方式11．According to the last paragraph, the writer thinks ________ is very important. A．a teacher B．a subjectC．attention D．homeworkDThe first day of school, our professor introduced an old lady Rose to us.“Why are you in college at such an age?” I asked her. She replied, “I always dreamed of having a college education and now I‟m getting one!” We became friends quickly. At the end of the term I invi ted Rose to make a speech to our football team. I‟ll never forget what she taught us. She said, “There are some secrets of staying young and being happy. You have to laugh and find humor every day. You must have a dream. When you lose your dreams, you will die. There is a huge difference between growing old and growing up. Anybody can grow older. That doesn‟t need any talent or ability. To grow up, you must always find the opportunity in change. Have no regrets. The people who are afraid of death are those with regrets.”At the end of the year, Rose finished her college. One week after graduation, Rose died peacefully in her sleep. We would always remember the great woman.根据短文内容，选择正确答案。

2015—2016学年湖南省邵阳市邵东三中高二（下）第一次月考物理试卷（理科)（实验班)一、选择题（共12小题，每小题4分。

1—8小题只有一个选项正确;9-12有多个选项正确，全部选对的得4分,选不全的得2分,有选错或不答的得0分．）1．在变电所里，经常要用交流电表去监测电网上的强电流，使用的仪器是电流互感器，下列图中能正确反映其工作原理的是(）A． B．C．D．2．如图所示为一只理想变压器,原、副线圈匝数比是10：1，原线圈接入电压为220V的正弦交流电，一个理想二极管与一个最大阻值为10Ω的滑动变阻器串联后接在副线圈上，滑片P在变阻器的最下端,则下列说法正确的是（）A．1分钟内电阻R上产生的热量为1452JB．电压表的示数为22VC．二极管两端的最大电压为22VD．滑片P向上移动时，电流表A的示数减小3．下列说法中正确的是(）A．汤姆生发现电子，表明原子具有核式结构B．按照波尔理论，氢原子核外电子从半径较小的轨道跃迁到半径较大的轨道时,电子的动能减小,原子总能量增加C．氡的半衰期为3.8天,若有4个氡原子核，经过7。

6天就只剩下1个D．太阳辐射的能量主要来自太阳内部的核裂变反应4．如图所示，在光滑水平面上质量分别为m A=3kg、m B=2kg，速率分别为v A=5m/s、v B=3m/s 的A、B两小球沿同一直线相向运动，下列说法中正确的是(）A．它们碰撞前的总动量大小是21 kgm/s,方向水平向左B．它们碰撞后的总动量大小是21 kgm/s，方向水平向右C．它们碰撞前的总动量大小是9 kgm/s，方向水平向左D．它们碰撞后的总动量大小是9 kgm/s，方向水平向右5．某金属的逸出功为2。

6eV，这意味着（)A．这种金属内部的电子克服原子核引力做2。

6 eV的功即可脱离该金属表面B．这种金属内部的电子只要获得2。

6eV的能量即可脱离该金属表面C．要使这种金属有电子逸出，入射光子的能量必须大于2.6 eVD．这种金属受到光照时若有电子逸出，则电子离开金属表面时的动能至少等于2。

都匀一中2015—2016学年高一年级第二学期开学质检考试英语本试卷分第I卷（选择题）和第II卷（非选择题）。

第I卷第1页至第10页，第II卷第10页至第12页。

考试结束，将本试卷的答题卡交回。

注意事项：1、答题前，考生务必将自己的姓名、准考证号填写在答题卡上，认真核对条形码上的姓名、准考证号，并将条形码粘贴在答题卡的指定位置上。

2、选择题答案使用2B铅笔填涂，如需改动，用橡皮擦干净后，再选涂其它答案标号；非选择题答案使用0.5毫米的黑色中性（签字）笔或碳素笔书写，字体工整、笔迹清楚。

3、请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效。

4、保持卡面清洁，不折叠，不破损。

第Ⅰ卷第一部分:听力(共两节,满分20分)第一节(共5小题; 每小题1分, 满分5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Why can’t the woman go to the party?A. Because she doesn’t want to.B. Because she has to work.C. Because she wants to eat in a restaurant.2. What’s the relationship between the two speakers?A. Teacher and student.B. Waiter and customer.C. Patient and doctor.3. What time is it?A. 8:45.B. 8:15.C. 9:15.4. What does the man want to learn?A. Russian.B. Spanish.C. English.5. What does the man believe?A. There must be many thieves around.B. He was wrong to have placed his wallet on the desk.C. His wallet was stolen during the past hour.第二节(共15小题; 每小题1分, 满分15分)听下面5段对话或独白。

吉安一中2015-2016学年度上学期第二次月考高一英语试卷第一部分：听力（共两节，满分30分）第一节（共5小题；每小题1.5分；满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What is the probable relationship between the two speakers?A. Doctor and patientB. Father and daughter.C. Teacher and student.2. What is the woman doing?A. Listening to musicB. Fixing the radio.C. Doing her homework.3. Where does the man plan to do this Sunday?A. Read a novel.B. Play football.C. Watch TV.4. How many women workers are there in the man’s factory?A. 120.B. 180.C. 300.5. Who will help the woman do the cleaning?A. Tim.B. TonyC. Lily.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第6至7题。

6. Where does this conversation take place?A. In a bank.B. In a restaurant.C. In a shop.7. How much is the iPad without a discount?A. 5,850 yuan.B. 5,600 yuanC. 6,500 yuan.听第7段材料，回答第8至9题。

荥阳高中2011---2012学年下学期三月月考第I 卷（共115分）第一部分：英语知识运用（共两节，满分75分）第一节：单项填空（共30题；每小题1.5分，满分45分）1.He studied hard, _______ the exam.A. aim at passingB. aiming at passingC. aiming passingD. aimed to pass2. ---Would you please give me an example to show how useful a computer is?--- Sure. _________ people get _________ information from it every day.A. The number of, a lot ofB. A huge number of, plenty ofC. Many a, a great deal ofD. Lots of, a lot3. In the dark forests ______, some of which are large enough to hold several small towns.A. are lying many lakesB. do many lakes lieC. many lakes lieD. lie many lakes4. ______ is known to us all is that the economy of China is getting better and better.A. ItB. WhatC. AsD. Which5. Our monitor is the first one ________ at the classroom in our class every morning.A. arriveB. arrivesC. to arriveD. arriving6. ---Pity you missed the lecture on nuclear pollution.--- I ________ it, but I was busy preparing for a job interview.A. attendedB. had attendedC. would attendD. would have attended7. The doctor recommended that you ______ swim after eating a large meal.A. wouldn‟tB. couldn‟tC. needn‟tD. shouldn‟t8. China has got a good _______ for fighting against the flu with its careful and smooth organization.A. reputationB. influenceC. impressionD. knowledge9. It is a pity that I missed the chance to get the signature of my favorite sports star, Liu Xiang, __________.A. in the fleshB. in placeC. in fleshD. in addition10. ---I am afraid I can‟t return the book to you before Friday.---_________.A. Don‟t be afraidB. Be carefulC. Not at allD. Take your time11. ---Does this dress fit Mary? ---Anything is OK. She is _________ about what she wears.A. especialB. particularC. casualD. general12. Is this reason _________ at the meeting for his carelessness in his work?A. he explainedB. what he explainedC. how he explainedD. why he explained.13. Look at the terrible situation I am in! If only I ________ your advice.A. followB. would followC. had followedD. have followed14. ---How I wish I had studied harder when I was in senior school!--- If you had, you ________ a university student now.A. areB. wereC. shouldD. would be15. It is illegal for a public official to ask people for gifts or money ______ favors to them.A. in preference toB. in place ofC. in agreement withD. in exchange for16. Why not _______ that suit to see if it matches with your shirt?A. try outB. try onC. to try onD. to try out17. ---He says that my new car is a _______ of money.---Don‟t you think those words are just sour grapes?A. lackB. loadC. questionD. waste18. Studies show that people are more _________ to suffer from back problems if they always sit before computerscreens for long hours.A. likelyB. possibleC. probableD. sure19. _______ the drought in Southwest China, millions of people had to carry water from faraway places.A. Apart fromB. In case ofC. Due toD. In spite of20. ---They are quiet, aren‟t they?--- Yes. They are accustomed _________ over meals.A. to talkB. to not talkC. to talkingD. to not talking21. ________ for the chance to go to university, the young man devoted himself to study.A. DesperateB. DesperatelyC. Being desperateD. Be desperate.22. Isn‟t it time you _______ down to _______ something useful?A. got; learningB. get; learnC. to get; learningD. got; learn23. As is known to all, the 2012 Olympic Games will _________ in London.A. come aboutB. break outC. take placeD. be happened24. People in China_______ to overorder food, for they will find it embarrassing if all the food is consumed.A. usedB. turnC. tendD. intend25. Jenny nearly missed the flight________ doing too much shopping.A. as a result ofB. on top ofC. in front ofD. in need of26. The prices of the dresses in our store_______ from 100 dollars to 300 dollars.A. increaseB. costC. rangeD. develop27. Is this farm_______ you visited last week?A. whereB. the oneC. on whichD. /28. The old couple have two children, _______ able to come to see them when they feel lonely, however.A. both of them areB. none of them areC. both of whom areD. neither of whom is29. Do you ______ her optimistic view of the state of the economy_______ the financial crisis had little effect onChina?A. agree to, whatB. agree, whichC. subscribe to, thatD. subscribe with, whether30. He spoke in such a low voice that it was impossible to make out exactly________ he was trying to say.A. it was what thatB. what was it thatC. that what it wasD. what it was that第二节完形填空（共20小题：每小题1．5分，满分30分）阅读下面的短文，从短文后各题所给的四个选项（A、B、C和D）中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。

2015-2016学年四川省绵阳市科学城一中高二（下）第一次月考化学试卷一、选择题（本题包括25小题，每小题2分，共50分，每小题只有一个选项符合题意）1．某浓度的氨水中存在下列平衡：NH3•H2O⇌NH4++OH﹣，如想增大NH4+的浓度，而不增大OH﹣的浓度，应采取的措施是（）A．适当升高温度 B．加入NH4Cl固体C．通入NH3 D．加入少量盐酸2．一定量的稀硫酸与足量的铝粉反应时，为了减缓反应速率，且不影响生成氢气的总量，应向稀硫酸中加入适量的（）A．NaOH（固体）B．CH3COOH C．NaCl（固体） D．CH3COONa（固体）3．0.02mol•L﹣1的HCN溶液与0.02mol•L﹣1 NaCN溶液等体积混合，已知混合溶液中pH＞7，则下列关系中，正确的是（）A．c（Na+）＞c（CN﹣）＞c（H+）＞c（OH﹣）B．c（HCN）+c（CN﹣）=0.04 mol•L﹣1 C．c（Na+）+c（H+）=c（CN﹣）+c（OH﹣）D．c（CN﹣）＞c（HCN）4．将Al片和Cu片用导线相连，一组插入浓盐酸中，一组插入稀氢氧化钠溶液中，分别形成原电池，则在这两原电池中，正极分别为（）A．Cu片、Cu片B．Cu片、Al片C．Al片、Al片D．Al片、Cu片5．关于C（CH3）3CH2CH3说法中错误的是（）A．它的名称是2，2﹣二甲基丁烷B．它的核磁共振氢谱有3个峰C．它的分子式为C6H14D．若它由烯烃与H2加成而来，则烯烃有两种6．为了探究金属腐蚀的条件和快慢，某课外学习小组用不同的细金属丝将三根大小相同的普通铁钉分别固定在如图所示的三个装置内，并将这些装置在相同的环境中放置相同的一段时间，下列对实验结果的描述不正确的是（）A．实验结束时，装置Ⅰ左侧的液面一定会下降B．实验结束时，装置Ⅰ左侧的液面一定比装置Ⅱ的低C．实验结束时，铁钉b腐蚀最严重D．实验结束时，铁钉c几乎没有被腐蚀7．在含有酚酞的0.1mol/L氨水中加入少量的NH4Cl晶体，则溶液颜色（）A．变蓝色B．变深 C．变浅 D．不变8．铜锌原电池（如图）工作时，下列叙述正确的是（）A．正极反应为：Zn﹣2e﹣═Zn2+B．电池反应为：Zn+Cu2+═Zn2++CuC．在外电路中，电子从正极流向负极D．盐桥中的K+移向ZnSO4溶液9．下列关于电解质溶液的正确判断是（）A．在pH=11的溶液中，K+、Cl﹣、HSO3﹣、Na+可以大量共存B．在pH=0的溶液中，Na+、NO3﹣、Fe2+、K+可以大量共存C．常温下，由0.1 mol•L﹣1一元碱BOH溶液的pH=10，可知BOH溶液中存在BOH⇌B++OH ﹣D．常温下，由0.1 mol•L﹣1一元酸HA溶液的pH=3，可推知NaA溶液中存在A﹣+H2O=HA+OH ﹣10．25℃时，pH=3的盐酸a L分别与下列三种溶液充分混合后，溶液均呈中性：①c（NH3•H2O）=1×10﹣3 mol•L﹣1的氨水b L，②c（OH﹣）=1×10﹣3 mol•L﹣1的氨水c L，③c（OH﹣）=1×10﹣3 mol•L﹣1的Ba（OH）2溶液d L．试判断a、b、c、d的数量大小关系为（）A．a=b＞c＞d B．b＞a=d＞c C．b＞a＞d＞c D．c＞a=d＞b11．关于浓度均为0.1mol•L﹣1的三种溶液：①氨水、②盐酸、③氯化铵溶液，下列说法不正确的是（）A．c（NH4+）：③＞①B．水电离出的c（H+）：②＞①C．①和②等体积混合后的溶液：c（H+）=c（OH﹣）+c（NH3•H2O）D．①和③等体积混合后的溶液：c（NH4+）＞c（Cl﹣）＞c（OH﹣）＞c（H+）12．下列说法不正确的是（）A．K sp只与难溶电解质的性质和温度有关B．由于K sp（ZnS）＞K sp（CuS），所以ZnS沉淀在一定条件下可转化为CuS沉淀C．其他条件不变，离子浓度改变时，K sp不变D．两种难溶电解质，K sp小的，溶解度一定小13．下列有关说法正确的是（）A．若2，2，3，3﹣四甲基戊烷由烯烃加成而来，则该烯烃的名称是2，2，3，3﹣四甲基﹣1﹣﹣戊烯B．在氯化银的沉淀溶解平衡体系中，加入蒸馏水，氯化银的K sp增大C．在氯化银的沉淀溶解平衡体系中，加入碘化钾固体，氯化银沉淀可转化为碘化银沉淀D．在碳酸钙的沉淀溶解平衡体系中，加入稀盐酸，溶解平衡不移动14．25℃时，在25mL 0.1mol•L﹣1的NaOH溶液中，逐滴加入0.2mol•L ﹣1的CH3COOH溶液，溶液的pH与醋酸体积关系如图所示，下列分析不正确的是（）A．B点的横坐标a＞12.5B．C点时溶液中有：c（CH3COO﹣）＞c（Na+）＞c（H+）＞c（OH﹣）C．D点时溶液中有：c（CH3COO﹣）+c（CH3COOH）=2c（Na+）D．曲线上A、B间的任意一点，溶液中都有：c（CH3COO﹣）＞c（Na+）＞c（OH﹣）＞c （H+）15．下列关于实验现象的描述不正确的是（）A．把铜片和铁片紧靠在一起浸入稀硫酸中，铜片表面出现气泡B．用锌片做阳极，铁片做阴极，电解氯化锌溶液，铁片表面出现一层锌C．把铜片插入三氯化铁溶液中，在铜片表面出现一层铁D．把锌粒放入盛有盐酸的试管中，加入几滴氯化铜溶液，气泡放出速率加快16．下列事实能说明醋酸是弱电解质的是（）①醋酸与水以任意比例互溶②醋酸溶液能导电③醋酸溶液中存在醋酸分子④0.1mol•L﹣1醋酸的pH比盐酸pH大⑤在漂白剂溶液中滴加醋酸能增强漂白效果⑥0.1mol•L﹣1醋酸溶液的pH=2 ⑦大小相同的锌粒与相同物质的量浓度的盐酸和醋酸反应，醋酸产生氢气速率慢⑧CH3COOK溶液能使酚酞试液变红色．A．②④⑥⑧B．③④⑥⑦C．④⑤⑥⑧D．③④⑥⑦⑧17．Li﹣Al/FeS电池是一种正在开发的车载电池，该电池中正极的电极反应式为：2Li++FeS+2e ﹣=Li2S+Fe．有关该电池的下列说法中，正确的是（）A．Li﹣Al在电池中作为负极材料，该材料中Li的化合价为+1价B．该电池的电池反应式为：2Li+FeS=Li2S+FeC．负极的电极反应式为Al﹣3e﹣=Al3+D．充电时，阴极发生的电极反应式为：Li2S+Fe﹣2e﹣=2Li++FeS18．下列有机物的命名中错误的是（）A．3，4﹣二甲基﹣4﹣乙基庚烷B．3，5﹣二甲基﹣3﹣庚烯C．3﹣乙基﹣1﹣辛烯 D．2，4，4﹣三甲基戊烷19．用阳极X和阴极Y电解Z的水溶液，电解一段时间后，再加入W，能使溶液恢复到电20．下列说法不正确的是（）A．0.2 mol•L﹣1的NaHCO3溶液中：c（Na+）＞c（HCO3﹣）＞c（OH﹣）＞c（H+）B．向氨水中逐滴滴入盐酸至溶液的pH=7，则混合液中：c（NH4+）=c（Cl﹣）C．CH3CH3的二溴代烷有2种，则CH3CH3的四溴代烷也是2种D．用﹣C3H7取代甲苯苯环上的1个氢原子，所得芳香烃的数目是三种21．下列各组离子在指定条件下，一定能大量共存的是（）A．能使蓝色石蕊试纸变红色的溶液中：K+、Na+、CO32﹣、NO3﹣B．c（H+）=1×10﹣1mol•L﹣1的溶液中：Cu2+、A13+、SO42﹣、NO3﹣C．能使碘化钾淀粉试纸变蓝的溶液中：Na+、NH4+、S2﹣、Br﹣D．水电离出的c（H+）为1×10﹣12 mol•L﹣1的溶液中：Na+、Mg2+、Cl﹣、SO42﹣22．下列说法错误的是（）A．0.1mol/LCH3COOH溶液中：c（CH3COO﹣）+c（CH3COOH）=0.1mol/LB．Na2S溶液中：c（OH﹣）=c（H+）+c（HS﹣）+2c（H2S）C．配制FeCl3溶液，应加少量盐酸D．将Al2（SO4）3溶液蒸干，灼烧得Al2O323．下列说法错误的是（）A．同浓度的下列溶液，c（NH4+）大小顺序：（NH4）2SO4＞NH4HSO4＞NH4Cl＞NH4HCO3 B．同浓度的下列溶液，pH值大小顺序：Na2CO3＞NaClO＞NaHCO3＞CH3COONaC．用水冲洗BaSO4比用稀硫酸冲洗损失大D．用惰性电极电解某溶液，两极分别产生H2和O2，pH值一定升高24．有关甲、乙、丙、丁四个图示的叙述不正确的是（）A．甲中负极反应式为Zn﹣2e﹣═Zn2+B．乙中阳极反应式为Ag﹣e﹣═Ag+C．丙中H+向碳棒方向移动D．丁中电解开始时阳极产生黄绿色气体25．2，3﹣二甲基丁烷可生成多少种不同沸点的一溴代物（）A．1种B．2种C．3种D．4种二、非选择题（本题包括6小题，共50分）26．（1）体积相同，PH值均为2的盐酸和CH3COOH溶液，若分别加水稀释10倍，溶液的pH分别变成m和n，则m与n的关系为．若分别加水稀释m倍、n倍，溶液的pH 都变成3，则m与n的关系为．（2）CH3OH﹣﹣﹣O2﹣﹣﹣KOH电池（惰性电极）的负极反应式（3）电解饱和KI溶液的离子方程式．27．为测定某有机物A的结构，设计了如下实验：①将4.6g该有机物完全燃烧，生成了0.2mol CO2和5.4g H2O；②用质谱仪实验得质谱图；③用核磁共振仪处理该化合物得核磁共振氢谱图，图中三个峰的面积比为1：2：3．试回答下列问题：（C﹣12，H﹣1，O﹣16）（1）有机物A的相对分子质量为．（2）有机物A的实验式为．（3）A的分子式为，结构简式为．28．锌银电池广泛用作各种电子仪器的电源，它的充电、放电过程可表示为2Ag+Zn（OH）2Ag2O+Zn+H2O回答下列有关问题：（1）电池的放电过程是（填“①”或“②”）．（2）该电池属于（填“酸”、“碱”或“中”）性电池．（3）写出充电时的电极反应式：阳极：．阴极：．（4）充电时，电池的正极应接电源的极．（5）试简述回收该种废电池的意义．．29．（1）将等体积等物质的量浓度的盐酸和氨水混合后，溶液呈性（填“酸”、“中”或“碱”），溶液中c（NH4+）c（Cl﹣）（“＞”“=”“＜”）．（2）pH=3盐酸和pH=11氨水等体积混合后溶液呈性（填“酸”、“中”或“碱”），溶液中c （NH4+）c（Cl﹣）（“＞”“=”“＜”）．（3）写出NaHCO3水溶液呈碱性的水解离子方程式；⇌Ag+（aq）（4）含有足量AgCl固体的饱和溶液，氯化银在水中存在沉淀溶解平衡：AgCl（S）+Cl﹣（aq）在25℃时，氯化银的K sp=1.8×10﹣10mol2•L﹣2．现将足量氯化银分别放入：①100mL蒸馏水中；②100mL 0.1mol•L﹣1氯化镁溶液中；③100mL 0.1mol•L﹣1氯化铝溶液中；④100mL0.1mol•L﹣1盐酸溶液中．充分搅拌后，相同温度下银离子浓度由大到小的顺序是（填写序号）．30．如图所示装置中，甲、乙、丙三个烧杯依次分别盛放足量的NaCl溶液、AgNO3溶液、x溶液，a、b、c、d电极均为石墨电极．接通电源，经过一段时间后，乙中c电极质量增加．据此回答问题：（1）电源的N端为极；（2）电极d上发生的电极反应式为；（3）当电路中有0.04mol电子通过时，a、b、c、d电极上产生的气体或固体的物质的量之比是；（4）若利用丙池实现铁上镀铜，则“e﹣f﹣x溶液”是；（要求e、f、x用具体物质回答，下同）．若利用丙池实现电解精炼铜，则“e﹣f﹣x溶液”是．31．回答下列问题：（1）有一种酸性溶液，含有Na+、SO42﹣和Cl﹣，测得三种离子的浓度分别是0.01mol•L﹣1、0.0035mol•L﹣1和0.004mol•L﹣1，该溶液的pH为．（2）AlCl3溶液显酸性，试用离子方程式表示这一原理．（3）液氨的电离类似于水，试写出液氨的电离方程式；在液氨中加入NH4Cl，平衡将向移动．（4）写出3，5﹣二甲基﹣3﹣庚烯的结构简式．32．下列有关实验的叙述中错误的是（）A．在蒸馏装置中，温度计水银球的位置在蒸馏烧瓶的支管口处．B．“苯甲酸的重结晶”实验步骤是：加热溶解﹣﹣﹣趁热过滤﹣﹣﹣冷却结晶﹣﹣﹣滤出晶体C．在萃取实验中，溶质在萃取剂中的溶解度小于在原溶剂中的溶解度D．在过滤实验中，应做到“一贴，二低，三靠”33．已知25℃时，K sp（FeS）=8.1×10﹣17，试求FeS的溶解度（要求有计算过程Fe﹣56，S﹣32）．2015-2016学年四川省绵阳市科学城一中高二（下）第一次月考化学试卷参考答案与试题解析一、选择题（本题包括25小题，每小题2分，共50分，每小题只有一个选项符合题意）1．某浓度的氨水中存在下列平衡：NH3•H2O⇌NH4++OH﹣，如想增大NH4+的浓度，而不增大OH﹣的浓度，应采取的措施是（）A．适当升高温度 B．加入NH4Cl固体C．通入NH3 D．加入少量盐酸【考点】弱电解质在水溶液中的电离平衡．【分析】氨水存在电离平衡NH3•H2O⇌NH+OH﹣，要想增大NH的浓度，而不增大OH﹣的浓度，则加入的物质必须含有铵根离子或含有能和氢氧根离子反应的离子，据此分析解答．【解答】解：A．适当升高温度，平衡正向移动，c（NH4+）增大，c（OH﹣）增大，故A错误；B．加入氯化铵固体，c（NH4+）增大，平衡逆向移动，c（OH﹣）减小，故B正确；C．向氨水中通入氨气，c（NH4+）增大，c（OH﹣）增大，故C错误；D．加入少量盐酸，盐酸和氢氧根离子反应生成水，促进氨水电离，c（NH4+）增大，c（OH ﹣）减小，故D正确；故选BD．2．一定量的稀硫酸与足量的铝粉反应时，为了减缓反应速率，且不影响生成氢气的总量，应向稀硫酸中加入适量的（）A．NaOH（固体）B．CH3COOH C．NaCl（固体） D．CH3COONa（固体）【考点】化学反应速率的影响因素．【分析】减缓反应速率，可降低氢离子浓度，或降低反应温度，不影响生成氢气的总量，则所加入物质与氢离子不反应，以此解答该题．【解答】解：A．NaOH固体能与硫酸反应，减小生成氢气的总量，故A错误；B．加入醋酸，生成氢气的量增多，故B错误；C．加入氯化钠固体，溶液浓度不变，反应速率不变，故C错误；D．加入CH3COONa（固体），生成醋酸，醋酸为弱酸，溶液氢离子浓度减小，反应速率减小，但不影响生成氢气的总量，故D正确．故选D．3．0.02mol•L﹣1的HCN溶液与0.02mol•L﹣1 NaCN溶液等体积混合，已知混合溶液中pH＞7，则下列关系中，正确的是（）A．c（Na+）＞c（CN﹣）＞c（H+）＞c（OH﹣）B．c（HCN）+c（CN﹣）=0.04 mol•L﹣1 C．c（Na+）+c（H+）=c（CN﹣）+c（OH﹣）D．c（CN﹣）＞c（HCN）【考点】离子浓度大小的比较．【分析】0.02mol•L﹣1的HCN溶液与0.02mol•L﹣1 NaCN溶液等体积混合，混合溶液中pH ＞7，溶液呈碱性，说明NaCN水解程度大于HCN电离程度，溶液中存在电荷守恒和物料守恒，据此判断．【解答】解：0.02mol•L﹣1的HCN溶液与0.02mol•L﹣1 NaCN溶液等体积混合，混合溶液中pH＞7，溶液呈碱性，说明NaCN水解程度大于HCN电离程度，A．溶液呈碱性，则c（H+）＜c（OH﹣），结合电荷守恒得c（Na+）＞c（CN﹣），离子浓度大小顺序是c（Na+）＞c（CN﹣）＞c（OH﹣）＞c（H+），故A错误；B．溶液中存在物料守恒，根据物料守恒得c（HCN）+c（CN﹣）=0.02mol•L﹣1，故B错误；C．溶液中存在电荷守恒，根据电荷守恒得c（Na+）+c（H+）=c（CN﹣）+c（OH﹣），故C 正确；D．混合溶液中pH＞7，溶液呈碱性，说明NaCN水解程度大于HCN电离程度，则c（CN ﹣）＜c（HCN），故D错误；故选C．4．将Al片和Cu片用导线相连，一组插入浓盐酸中，一组插入稀氢氧化钠溶液中，分别形成原电池，则在这两原电池中，正极分别为（）A．Cu片、Cu片B．Cu片、Al片C．Al片、Al片D．Al片、Cu片【考点】原电池和电解池的工作原理．【分析】Al可与盐酸或氢氧化钠溶液反应，铜为不活泼金属，形成原电池时，较活泼金属为负极，不活泼金属为正极，以此解答．【解答】解：铝比铜活泼，插入盐酸溶液中，铝为负极，铜为正极，插入稀NaOH溶液中，金属铜和氢氧化钠不反应，金属铝能和氢氧化钠溶液发生自发的氧化还原反应，此时金属铝是负极，金属铜是正极．故选A．5．关于C（CH3）3CH2CH3说法中错误的是（）A．它的名称是2，2﹣二甲基丁烷B．它的核磁共振氢谱有3个峰C．它的分子式为C6H14D．若它由烯烃与H2加成而来，则烯烃有两种【考点】常见有机化合物的结构．【分析】A．该有机物为烷烃，根据烷烃的命名原则对该有机物进行命名；B．根据有机物分子中含有等效氢原子的数目进行判断；C．根据结构式确定分子式；D．该有机物的结构中，只有﹣CH2CH3中的碳原子之间可以补充双键．【解答】解：A．C（CH3）3CH2CH3分子中，最长碳链含有4个C，主链为丁烷，在2号C 上含有2个甲基，该有机物命名为：2，2﹣二甲基丁烷，故A正确；B．C（CH3）3CH2CH3分子中，同一个碳原子上的三个甲基等效，亚甲基和另外一个甲基的氢不同，故含有3种氢原子，核磁共振氢谱有3个峰，故B正确；C．根据结构式确定分子式为C6H14，故C正确；D．该有机物的结构中，只有﹣CH2CH3中的碳原子之间可以补充碳碳双键，连接3个甲基上的碳已满足碳的4键，不能再补充双键，则该烯烃有1种，故D错误．故选D．6．为了探究金属腐蚀的条件和快慢，某课外学习小组用不同的细金属丝将三根大小相同的普通铁钉分别固定在如图所示的三个装置内，并将这些装置在相同的环境中放置相同的一段时间，下列对实验结果的描述不正确的是（）A．实验结束时，装置Ⅰ左侧的液面一定会下降B．实验结束时，装置Ⅰ左侧的液面一定比装置Ⅱ的低C．实验结束时，铁钉b腐蚀最严重D．实验结束时，铁钉c几乎没有被腐蚀【考点】金属的电化学腐蚀与防护．【分析】（1）中，因盐酸易挥发，则铁与盐酸反应生成氢气；（2）中，铁、铜形成原电池反应，发生析氢腐蚀；（3）中，浓硫酸具有吸水性，铁钉不易腐蚀，以此解答该题．【解答】解：A．装置I中，因盐酸易挥发，则铁与盐酸反应生成氢气，则压强增大，左侧的液面一定会下降，故A正确；B．装置II中，铁、铜形成原电池反应，发生析氢腐蚀，生成氢气的速率比I大，生成的氢气体积大，则装置II中左侧的液面比装置Ⅰ左侧的液面低，故B错误；C．装置II中发生电化学腐蚀，腐蚀速率快，所以铁钉b腐蚀最严重，故C正确；D．装置III中，浓硫酸具有吸水性，铁钉不易腐蚀，故D正确．故选B．7．在含有酚酞的0.1mol/L氨水中加入少量的NH4Cl晶体，则溶液颜色（）A．变蓝色B．变深 C．变浅 D．不变【考点】弱电解质在水溶液中的电离平衡．【分析】从加入少量的NH4Cl晶体后氨水的电离平衡移动方向进行判断．【解答】解：因氨水电离生成氢氧根离子，则酚酞遇碱变红，当加入少量的NH4Cl晶体后，NH4+离子浓度增大，根据同离子效应，加入NH4Cl后，氨水的电离平衡向逆方向移动，抑制氨水电离，从而c（OH﹣）变小，颜色变浅．故选：C．8．铜锌原电池（如图）工作时，下列叙述正确的是（）A．正极反应为：Zn﹣2e﹣═Zn2+B．电池反应为：Zn+Cu2+═Zn2++CuC．在外电路中，电子从正极流向负极D．盐桥中的K+移向ZnSO4溶液【考点】原电池和电解池的工作原理．【分析】根据原电池原理分析．正极得电子，负极失去电子；电池反应为氧化还原反应；盐桥的作用就是使电荷守恒，形成闭合回路，阳离子向正极移动，阴离子向负极移动．【解答】解：A，正极上铜离子得电子，发生还原反应，故错误；B，电池反应原理为锌与硫酸铜溶液反应置换铜，故正确；C，外电路中，电子从负极流向正极，故错误；D，盐桥中阳离子流向正极，阴离子流向负极，即盐桥中的K+移向CuSO4溶液，故错误；故选B．9．下列关于电解质溶液的正确判断是（）A．在pH=11的溶液中，K+、Cl﹣、HSO3﹣、Na+可以大量共存B．在pH=0的溶液中，Na+、NO3﹣、Fe2+、K+可以大量共存C．常温下，由0.1 mol•L﹣1一元碱BOH溶液的pH=10，可知BOH溶液中存在BOH⇌B++OH ﹣D．常温下，由0.1 mol•L﹣1一元酸HA溶液的pH=3，可推知NaA溶液中存在A﹣+H2O=HA+OH ﹣【考点】离子共存问题．【分析】A．p=11的溶液呈碱性，亚硫酸氢根离子与氢氧根离子反应；B．酸性条件下硝酸根离子能够氧化亚铁离子；C．常温下，由0.1 mol•L﹣1一元碱BOH溶液的pH=10，氢氧根离子浓度为0.0001mol/L，说明BOH在溶液中不能完全电离；D．常温下，由0.1 mol•L﹣1一元酸HA溶液的pH=3，说明HA为弱电解质，则A﹣的水解反应应该用可逆号．【解答】解：A．该溶液呈碱性，溶液中存在大量氢氧根离子，HSO3﹣与氢氧根离子反应，在溶液中不能大量共存，故A错误；B．pH=0的溶液为酸性溶液，NO3﹣、Fe2+在酸性条件下能够发生氧化还原反应，在溶液中不能大量共存，故B错误；C．常温下，由0.1 mol•L﹣1一元碱BOH溶液的pH=10＜13，说明BOH为弱电解质，在溶液中部分电离出氢氧根离子，其电离方程式为：BOH⇌B++OH﹣，故C正确；D．常温下，由0.1 mol•L﹣1一元酸HA溶液的pH=3＞1，说明HA为弱酸，A﹣的水解反应为可逆反应，应该用可逆号，NaA正确的水解反应为：A﹣+H2O⇌HA+OH﹣，故D错误；故选C．10．25℃时，pH=3的盐酸a L分别与下列三种溶液充分混合后，溶液均呈中性：①c（NH3•H2O）=1×10﹣3 mol•L﹣1的氨水b L，②c（OH﹣）=1×10﹣3 mol•L﹣1的氨水c L，③c（OH﹣）=1×10﹣3 mol•L﹣1的Ba（OH）2溶液d L．试判断a、b、c、d的数量大小关系为（）A．a=b＞c＞d B．b＞a=d＞c C．b＞a＞d＞c D．c＞a=d＞b【考点】弱电解质在水溶液中的电离平衡．【分析】HCl是强电解质，所以pH=3的盐酸溶液中c（H+）=1×10﹣3 mol•L﹣1，要中和等物质的量的HCl溶液，碱都是一元碱时，碱的浓度越大，需要的碱体积越小，据此分析解答．【解答】解：HCl是强电解质，所以pH=3的盐酸溶液中c（H+）=1×10﹣3 mol•L﹣1，要中和等物质的量的HCl溶液，碱都是一元碱时，碱的浓度越大，需要的碱体积越小，Ba（OH）2是强碱，且酸中氢离子浓度等于碱中氢氧根离子浓度，所以酸碱的体积相等，即a=d；由于HCl与NH3•H2O的中和产物NH4Cl可水解呈酸性，则要使混合溶液呈中性，NH3•H2O 必需过量，则b＞a；由于NH3•H2O是一种很弱的碱，只有少部分电离，则②中的c一定小于a，即d＞c，通过以上分析知，这几种溶液体积大小顺序是b＞a=d＞c，故选B．11．关于浓度均为0.1mol•L﹣1的三种溶液：①氨水、②盐酸、③氯化铵溶液，下列说法不正确的是（）A．c（NH4+）：③＞①B．水电离出的c（H+）：②＞①C．①和②等体积混合后的溶液：c（H+）=c（OH﹣）+c（NH3•H2O）D．①和③等体积混合后的溶液：c（NH4+）＞c（Cl﹣）＞c（OH﹣）＞c（H+）【考点】离子浓度大小的比较．【分析】A．NH3•H2O是弱电解质，部分电离，NH4Cl是强电解质完全电离，NH4Cl中NH4+水解但程度较小；B．酸或碱抑制水电离，酸中c（H+）越大或碱中c（OH﹣）越大越抑制水电离；C．NH3•H2O是弱电解质、HCl是强电解质，①和②等体积混合后，二者恰好反应生成NH4Cl，溶液中存在质子守恒，根据质子守恒判断；D．①和③等体积混合后，NH3•H2O电离程度大于NH4+水解程度导致溶液呈碱性，再结合电荷守恒判断．【解答】解：A．NH3•H2O是弱电解质，部分电离，NH4Cl是强电解质完全电离，NH4Cl 中NH4+水解但程度较小，所以c（NH4+）：③＞①，故A正确；B．酸或碱抑制水电离，酸中c（H+）越大或碱中c（OH﹣）越大越抑制水电离，①中c（OH ﹣）小于②中；c（H+），所以①抑制水电离程度小于②，则水电离出的c（H+）：②＜①，故B错误；C．NH3•H2O是弱电解质、HCl是强电解质，①和②等体积混合后，二者恰好反应生成NH4Cl，溶液中存在质子守恒，根据质子守恒得c（H+）=c（OH﹣）+c（NH3•H2O），故C 正确；D．①和③等体积混合后，NH3•H2O电离程度大于NH4+水解程度导致溶液呈碱性，再结合电荷守恒得c（NH4+）＞c（Cl﹣），NH3•H2O电离程度、NH4+水解程度都较小，所以离子浓度大小顺序是c（NH4+）＞c（Cl﹣）＞c（OH﹣）＞c（H+），故D正确；故选B．12．下列说法不正确的是（）A．K sp只与难溶电解质的性质和温度有关B．由于K sp（ZnS）＞K sp（CuS），所以ZnS沉淀在一定条件下可转化为CuS沉淀C．其他条件不变，离子浓度改变时，K sp不变D．两种难溶电解质，K sp小的，溶解度一定小【考点】难溶电解质的溶解平衡及沉淀转化的本质．【分析】A．化学反应平衡常数只与反应本身的性质和温度有关，与溶液中离子浓度无关；B．从难溶电解质的溶解平衡的角度分析；C．K sp只受温度的影响；D．K sp小的，溶解度不一定小．【解答】解：A．化学反应平衡常数只与反应本身的性质和温度有关，当难溶物确定时就只和温度有关了，故A正确；B．由于K sp（ZnS）＞K sp（CuS），在ZnS饱和溶液中加入Cu2+溶液，可生成CuS沉淀，故B正确；C．K sp只受温度的影响，与浓度无关，故C正确；D．对于阴、阳离子的个数比相同即同一类型的难溶电解质，K sp的数值越大，难溶电解质在水中的溶解能力越强即溶解度越大．对于阴、阳离子的个数比不同的难溶电解质，不能直接用K sp的大小比较它们的溶解能力，必须通过计算进行比较，故D错误．故选D．13．下列有关说法正确的是（）A．若2，2，3，3﹣四甲基戊烷由烯烃加成而来，则该烯烃的名称是2，2，3，3﹣四甲基﹣1﹣﹣戊烯B．在氯化银的沉淀溶解平衡体系中，加入蒸馏水，氯化银的K sp增大C．在氯化银的沉淀溶解平衡体系中，加入碘化钾固体，氯化银沉淀可转化为碘化银沉淀D．在碳酸钙的沉淀溶解平衡体系中，加入稀盐酸，溶解平衡不移动【考点】难溶电解质的溶解平衡及沉淀转化的本质．【分析】A．碳碳双键只能在戊烷的4、5号上，则命名烯烃时双键在1、2号C上；B．Ksp只与温度有关；C．AgI比AgCl更难溶；D．盐酸与碳酸根离子反应，促进碳酸钙的溶解．【解答】解：A．若2，2，3，3﹣四甲基戊烷由烯烃加成而来，则该烯烃的名称是3，3，4，4﹣四甲基﹣1﹣﹣戊烯，故A错误；B．在氯化银的沉淀溶解平衡体系中，加入蒸馏水，氯化银的K sp不变，故B错误；C．在氯化银的沉淀溶解平衡体系中，加入碘化钾固体，因AgI比AgCl更难溶，则氯化银沉淀可转化为碘化银沉淀，故C正确；D．在碳酸钙的沉淀溶解平衡体系中，加入稀盐酸，盐酸与碳酸根离子反应，促进碳酸钙的溶解，溶解平衡正向移动，故D错误；故选C．14．25℃时，在25mL 0.1mol•L﹣1的NaOH溶液中，逐滴加入0.2mol•L ﹣1的CH3COOH溶液，溶液的pH与醋酸体积关系如图所示，下列分析不正确的是（）A．B点的横坐标a＞12.5B．C点时溶液中有：c（CH3COO﹣）＞c（Na+）＞c（H+）＞c（OH﹣）C．D点时溶液中有：c（CH3COO﹣）+c（CH3COOH）=2c（Na+）D．曲线上A、B间的任意一点，溶液中都有：c（CH3COO﹣）＞c（Na+）＞c（OH﹣）＞c （H+）【考点】酸碱混合时的定性判断及有关ph的计算．【分析】A．醋酸钠是强碱弱酸盐，其水溶液呈碱性，要使混合溶液呈中性，则醋酸应该稍微过量；B．C点溶液呈酸性，则c（H+）＞c（OH﹣），且溶液中溶质为醋酸和醋酸钠，醋酸电离程度大于醋酸根离子水解程度而导致溶液呈酸性，根据电荷守恒判断；C．D点溶液中溶质为等物质的量浓度的醋酸钠和醋酸，溶液中存在物料守恒；D．溶液呈碱性，则c（OH﹣）＞c（H+），根据电荷守恒判断．【解答】解：A．醋酸钠是强碱弱酸盐，其水溶液呈碱性，要使混合溶液呈中性，则醋酸应该稍微过量，所以B点的横坐标a＞12.5，故A正确；B．C点溶液呈酸性，则c（H+）＞c（OH﹣），且溶液中溶质为醋酸和醋酸钠，醋酸电离程度大于醋酸根离子水解程度而导致溶液呈酸性，根据电荷守恒得c（CH3COO﹣）＞c（Na+），醋酸电离程度较小，所以c（CH3COO﹣）＞c（Na+）＞c（H+）＞c（OH﹣），故B正确；C．D点溶液中溶质为等物质的量浓度的醋酸钠和醋酸，溶液中存在物料守恒，根据物料守恒得c（CH3COO﹣）+c（CH3COOH）=2c（Na+），故C正确；D．溶液呈碱性，则c（OH﹣）＞c（H+），根据电荷守恒得c（CH3COO﹣）＜c（Na+），如果醋酸浓度很小，还存在c（CH3COO﹣）＜c（OH﹣），故D错误；故选D．15．下列关于实验现象的描述不正确的是（）A．把铜片和铁片紧靠在一起浸入稀硫酸中，铜片表面出现气泡B．用锌片做阳极，铁片做阴极，电解氯化锌溶液，铁片表面出现一层锌C．把铜片插入三氯化铁溶液中，在铜片表面出现一层铁D．把锌粒放入盛有盐酸的试管中，加入几滴氯化铜溶液，气泡放出速率加快【考点】常见金属元素的单质及其化合物的综合应用．【分析】A．铜片和铁片和稀硫酸构成原电池，铜作正极；B．阳极是活性金属锌，所以阳极金属锌失去电子发生氧化反应，阴极上溶液中的阳离子即锌离子得到电子变成锌，在铁极上析出；C．铜的金属活动性不及铁，不能置换金属铁；D．构成原电池反应，可以加速反应的速率；【解答】解：A．把铜片和铁片紧靠在一起浸入稀硫酸中，形成铜、铁、稀硫酸原电池，正极是金属铜，该极上电子和溶液中的氢离子结合产生氢气，故A正确；B．用锌片做阳极，铁片做做阴极，电解氯化锌溶液，这是一个电镀池，镀层金属锌作阳极，待镀件铁作阴极，镀层金属盐氯化锌溶液作电解质，发生反应：阳极：Zn﹣2e﹣=Zn2+；阴极：Zn2++2e﹣=Zn，故B正确；C．把铜片插入三氯化铁溶液中，铜和氯化铁反应生成氯化铜和氯化亚铁，铜的金属活动性不及铁，铜不能置换出铁，故C错误；D．把锌片放入盛盐酸的试管中，加入几滴氯化铜溶液，锌置换出铜，所以形成了铜、锌、稀盐酸原电池，原电池反应可以加速反应的速率，故D正确；故选C．16．下列事实能说明醋酸是弱电解质的是（）①醋酸与水以任意比例互溶②醋酸溶液能导电③醋酸溶液中存在醋酸分子④0.1mol•L﹣1醋酸的pH比盐酸pH大⑤在漂白剂溶液中滴加醋酸能增强漂白效果⑥0.1mol•L﹣1醋酸溶液的pH=2 ⑦大小相同的锌粒与相同物质的量浓度的盐酸和醋酸反应，醋酸产生氢气速率慢⑧CH3COOK溶液能使酚酞试液变红色．A．②④⑥⑧B．③④⑥⑦C．④⑤⑥⑧D．③④⑥⑦⑧【考点】强电解质和弱电解质的概念．【分析】不完全电离的电解质为弱电解质，可以根据醋酸的电离程度及醋酸钠溶液的酸碱性判断醋酸的强弱．【解答】解：①醋酸的溶解度与其酸性无关，故①错误；②醋酸溶液能导电，说明醋酸在水溶液里能电离出阴阳离子，为电解质，而不能证明醋酸的电离程度，所以不能证明醋酸为弱酸，故②错误；③醋酸稀溶液中存在醋酸分子，说明醋酸存在电离平衡，能证明醋酸是弱酸，故③正确；④常温下，0.1mol/L醋酸的pH比0.1mol/L盐酸的pH大，说明醋酸不完全电离，能证明醋酸是弱酸，故④正确；⑤醋酸能和漂白剂反应生成HClO，说明醋酸酸性比次氯酸强，但不能说明醋酸的电离程度，所以不能证明醋酸是弱酸，故⑤错误；⑥0.1mol/L醋酸溶液pH=2，能说明醋酸是弱酸，故⑥正确；⑦大小相同的锌粒与同物质的量浓度的盐酸和醋酸反应，醋酸产生H2速率慢，说明醋酸中氢离子浓度小于盐酸中氢离子浓度，则证明醋酸是弱酸，故⑦正确．⑧CH3COOK溶液能使酚酞试液变红色，说明醋酸是弱酸，故⑧正确；。

成都外国语学校2017届（高二下）6月月考化学试题命题人：王启卫审题人：林兵考试时间：100分钟总分：100分可能用到的原子量：H—1 N—14 Cu—64 O—16 Mg—24 Al—27第Ⅰ卷选择题(共60 分)一．选择题（每题只有一个选项符合题意，每小题2分，共60 分）1. 右图为雾霾的主要成分示意图。

下列说法不正确的是（）A．重金属离子可导致蛋白质变性B．苯是最简单的芳香烃C．向空气中大量排放SO2和N x O y都能引起酸雨和光化学烟雾D．汽车尾气的大量排放是造成雾霾天气的人为因素之一2．设N A为阿伏加德罗常数的值，则下列说法正确的是（）A．电解精炼铜时，若阳极质量减少6.4 g，则电路中转移电子数为0.2N AB. 向NH4Al(SO4)2稀溶液中逐滴加入过量Ba(OH)2溶液，离子方程式为：NH4+＋Al3++2SO42－+ 2Ba2++ 5OH－=2BaSO4↓+ AlO2－+ 2H2O+NH3•H2OC.常温下由水电离出的H+浓度为10-13mol·L-1的溶液中，Fe2+、Cl－、Na+、NO3－可能大量共存D.葡萄糖(C6H12O6)溶液中：SO42-、MnO4-、K+、H+ 可以大量共存3、下列叙述正确的是（）A．汽油、柴油和植物油都属于烃B．乙醇既能被氧化为乙醛，也能被氧化为乙酸C．苯与溴水在Fe3+催化下发生取代反应生成溴苯D．硫酸铜溶液和硫酸铵溶液均可使蛋白质溶液变性4、下列实验操作正确且能达到预期目的的是( )A．①④⑤ B．②③⑤ C．①②③④⑤⑥ D．①⑤⑥5．最简式相同，但既不是同系物，又不是同分异构体的是()A．辛烯和3—甲基—1—丁烯B．甲苯和乙炔C．1—氯丙烷和2—氯丙烷D．甲基环己烷和己烯6．下列情况能发生消去反应的是()A．1—溴丙烷与NaOH醇溶液共热B．氯乙烷与NaOH的水溶液共热C．乙醇与浓H2SO4共热至140℃D．2,2—二甲基-1-丙醇与浓H2SO4共热至170℃7、某有机物的结构简式为CH2=CH﹣CH2OH，则一定条件下该物质能与下列哪些物质反应：①酸性KMnO4溶液②新制的Cu（OH）2悬浊液③溴水④金属钠⑤金属镁，下列组合中正确的是（）A．①②③ B．①③④ C．②③④ D．③④⑤8．含有一个三键的炔烃、加氢后的产物结构简式为：这种炔烃的名称为()A．5－甲基－3－乙基－1－己炔B．5－甲基－3－乙基－2－己炔C．4－甲基－5－乙基－2－己炔D．2－甲基－4－乙基－5－己炔9．某学生将溴乙烷与NaOH溶液共热几分钟后，冷却，滴入AgNO3溶液，结果未见到浅黄色沉淀生成，其主要原因是()A．加热时间太短B．不应冷却后再加入AgNO3C．加AgNO3溶液前未用稀HNO3酸化D．反应后的溶液中不存在Br－10．将W1g光亮的铜丝在空气中加热一段时间后，迅速插入下列物质中，取出干燥，如此反复几次，最后取出铜丝，用蒸馏水洗涤、干燥，称其质量为W2g，实验时由于所插入的物质不同，铜丝的前后质量变化可能不同，下列所插物质与铜丝的质量关系不正确的是() A．石灰水W1<W2B．CO W1＝W2C．NaHSO4溶液W1>W2D．乙醇W1<W211、2015年10月，中国科学家屠呦呦因为创制了新型抗疟药——青蒿素，获得诺贝尔生理学或医学奖。

2015学年第一学期八年级阶段性检测英语试题卷满分：100分考试时间：70分钟温馨提示：请沉着应试，认真答题，把答案写在答题卷上。

相信你一定有出色的表现！第一部分：听力部分（20分）一、听小对话，选择正确的答案。

（读一遍）。

（每小题1分，共5分）。

( )1.Which city didn’t David go to?A. BostonB. New York CityC. Washington,D. C.( )2.What are the girl’s favorite TV programs?A.The football programsB.The dance programsC.The basketball programs( )3.What did Linda do last weekend?A. Played basketballB. Played ping-pongC. Played tennis( )4. What does the girl think of her sweater?A. It’s cheaper.B. It’s more expensive.C. It’s not beautiful.( )5. How often does the man go to the gym?A. Once a weekB. Twice a weekC. Three times a week二、第二节、听较长对话，选择正确答案。

(读两遍)。

（每小题1分，共5分）。

听下面一段对话，回答第6和第7两个小题。

( )6. Who is more outgoing?A. LindaB. JaneC. The boy( )7. W hat does the girl look like?A. TallB. ShortC. Heavy听第二段对话，回答第8、9、10三个小题。

( )8. What is Jack busy with these days?A. The math examB. The English examC. The after-school program( )9. When are they going to relax?A. On FridayB. On SaturdayC. On Sunday( )10. Where are they going to relax then?A. In the mountainsB. In the parkC. In town三、听短文，从A, B, C三个选项中选择正确的选项，完成信息记录表。

2015年衡阳市八中高二第一次月考政治试题答案一、选择题（30×2分=60分）1~5：DCBCD 6~10：CCDAD 11~15：BDCCA16~20：AACBD 21~25：BBCCB 26~30：DABCD二、非选择题31.（15分）甲同学说：“我喜欢理工科，从没想过当哲学家，考大学又不考哲学。

所以，没有必要在哲学上浪费时间。

”乙同学说：“哲学对我们很重要，哲学是一种方法论，学好哲学不但可以指导我们的实践，还可以帮助我们更好的理解理工科的知识。

”试分析、评论上述两位同学对哲学的看法。

答：（1）甲同学的观点是完全错误的。

（1分）学习哲学，不仅仅是哲学家的事情，哲学与我们的生活密切相关。

（2分）哲学是对具体科学的概括和总结，是关于世界观的学说，是世界观和方法论的统一。

（2分）学好哲学尤其是学好马克思主义哲学，可以更好的帮助我们树立正确的世界观，指导我们理解具体科学知识，使我们更好地认识世界和改造世界，实现自己的理想。

（3分）所以，无论是学文科还是理工科，当不当哲学家，都要了解和学习哲学。

（2）乙同学认为哲学是一种方法论，他看到了哲学对具体科学和实践的指导作用，是其正确的一面。

（3分）但是，他错误地认为哲学仅是一种方法论，而没有认识到哲学是世界观和方法论的统一。

（3分）因此，乙同学的看法是不全面的。

（1分）32.（10分）有人说：“各门具体科学的总和就是哲学,这就是具体科学和哲学的联系．”请评析这一观点．答:①哲学是对各门具体科学知识的概括和总结,而不是各门具体科学知识的简单相加,因此说各门具体科学的总和就是哲学是错误的（2分）②哲学与具体科学的联系包括以下两个方面:第一、具体科学是哲学的基础,具体科学的进步推动着哲学的发展；（4分）第二、哲学为具体科学提供世界观和方法论的指导（4分）。

因此题中的观点是片面的。

33.（15分）甲认为“万事万物都是由水构成的”；乙认为“自然是绝对理念的外化，社会是绝对精神的体现”（1）甲、乙两人的观点分别属于哪种哲学阵营？这两种哲学阵营的根本分歧是什么？甲乙两人分别属于唯物主义和唯心主义两大阵营。

清远市第一中学实验学校2015-2016学年度第一学期第一次月考高二化学试题1．本试卷共二道大题16道小题，满分100分，考试时间100分钟。

2．所有题目的答案必须全部填入答卷中，否则无效。

3．可能需要的相对原子质量数据：H：1，C：12，N：14，O：16， Cl：35.5，Br：80第一部分选择题（共48分）一、单项选择题(本题包括16小题，每小题3分，共48分。

每小题只有一个选项符合题意) 1．对于放热反应 2H2（g）+O2（g）= 2H2O（l），下列说法正确的是（）A．产物H2O所具有的总能量高于反应物H2和O2所具有的总能量B．反应物H2和O2所具有的总能量高于产物H2O所具有的总能量C．反应物H2和O2所具有的总能量等于产物H2O所具有的总能量D．反应物H2和O2比产物H2O稳定2．在同温同压下，下列各组热化学方程式中△H2>△H1的是A．2H2(g)+O2(g)＝2H2O(g)，△H1；2H2(g)+O2(g)＝2H2O(l)，△H2B．S(s)+O2(g)＝SO2(g)，△H1；S(g)+O2(g)＝SO2(g)，△H2C．C(s)+1/2 O2(g)＝CO(g)，△H1；C(s)+O2(g)＝CO2(g)，△H2D．H2(g)+Cl2(g)＝2HCl(g)，△H1； 1/2H2(g)+1/2 Cl2(g)＝HCl(g)，△H23．下列叙述中正确的是A．在稀溶液中，1mol酸和1mol碱完全反应所放出的热量叫做中和热B．在101kPa时1mol物质燃烧时的反应热叫做该物质的燃烧热C．热化学方程式中，各物质前的化学计量数不表示分子个数D．如果反应物所具有的总能量低于生成物所具有的总能量，则发生的反应是放热反应4．已知充分燃烧a g乙炔气体时生成1mol二氧化碳气体和液态水，并放出热量b kJ，则乙炔燃烧的热化学方程式正确的是A．2C2H2(g)＋5O2(g)＝4CO2(g)＋2H2O(l)；ΔH＝－2b kJ·mol—1B．C2H2(g)＋5/2O2(g)＝2CO2(g)＋H2O(l)；ΔH＝2b kJ·mol—1C．2C2H2(g)＋5O2(g)＝4CO2(g)＋2H2O(l)；ΔH＝－4b kJ·mol—1D．2C2H2(g)＋5O2(g)＝4CO2(g)＋2H2O(l)；ΔH＝b kJ·mol—15．仅改变下列一个条件，通过提高活化分子的百分率来提高反应速率的是A．加热B．加压C．降温D．增大反应物浓度6．下列说法正确的是（1）增加水的量或升高温度，一定可以加快镁跟水的反应速率（2）增大硫酸的浓度，一定可以加快锌与硫酸反应制取氢气的速率（3）对于反应CaCO3(s) CaO(s) + CO2(g)，增加CaCO3的量，可以加快正反应速率，而增加CaO或CO2的浓度，则可以加快逆反应速率（4）对于反应3H2(g) + N2(g) 2NH3(g)，在密闭容器中进行(固定体积)，现充入氦气，由于容器中压强增大，则化学反应速率加快（5）对于反应3H2(g) + N2(g) 2NH3(g)，使用适合催化剂，正逆反应速率同等程度加快A．(1) (2) B．(1) (2) (3) C．(1) (2) (3) (4) D．(5)7．一定温度下反应：A2(g)+3 B2(g) 2 AB3(g)（每生成2 mol AB3放出92.4 kJ的热量），在恒温恒压的密闭容器中进行如下实验：①通入1 mol A2和3 mol B2，达平衡时放出热量为Q1，②通入2 mol A2和6 mol B2，达平衡时放出热量为Q2，则下列关系正确的是A．Q2 = 2 Q1 B．2Q1 < Q2 C．Q1 < Q2 < 92.4 kJ D．Q1 = Q2 < 92.4 kJ 8．可逆反应：3 A(气) 3 B(?)+C(?)；△H＞0，随着温度升高，气体平均相对分子质量变小，则下列判断正确的是A．B和C可能都是固体B．B和C一定都是气体C．若C为固体，则B一定是气体D．B和C可能都是液体9．下列反应属于吸热反应的是酶A．C6H12O6(葡萄糖)+6O2 6CO2+6H2OB．CH3COOK+H2O CH3COOH+KOHC．A+B C+D；△H<0D．破坏生成物全部化学键所需能量小于破坏反应物全部化学键所需能量10．在一密闭容器中，用等物质的量的A和B发生如下反应：A(g)+2B(g)2C(g)，反应达到平衡时，若混合气体A和B的物质的量之和与C的物质的量相等，则这时A的转化率为：( )A．40% B．50% C．60% D．70%11．一定温度下, 向aL的密闭容器中加入2molNO2(g), 发生如下反应：2NO22NO+O2,此反应达到平衡的标志是A．单位时间内生成2nmolNO同时生成2nmolNO2B．混合气体中NO2、NO和O2的物质的量之比为2：2：1C．单位时间内生成2nmolNO同时生成nmolO2D．混合气体的颜色变浅12．.下列热方程式书写正确的是（）A．2SO2+O2=2H2O ⊿H= —196.6 kJ/molB．2H2(g)+O2(g)=2H2O（l）⊿H= —517．6 kJ/molC．H2(g)+ 1/2O2(g)=H2O(l) ⊿H= —285．8 kJD．C(s)+O2(g)=CO2(g) ⊿H= +393．5 kJ/mol13．对于达到平衡的反应：2A(g)+B(g)nC(g)，符合上图所示的结论是A.P1＞P2，n＞3B.P1＞P2，n＜3C.P1＜P2，n＞3D.P1＜P2，n＜314．某温度下，将3molA和3molB充入体积为 1L的密闭容器中，发生如下反应：aA（g）+2B（g）3C（g）+D（g）。