1、元件计算4×π×f 4× 3.1416×
504×π×f 4
× 3.1416×
504×
π×f
S 4× 3.1416×
50
0.27
r m 0.133
a 0.0442 2.000
b 0.10122b 0.10122
2、正常运行时，最大工作电流计算
1212
E A
3、水平排列时，单芯电缆金属护套感应电压的计算]
23.59
0.4
=
∠
°V
×
]×
I B
×)-3×
Y1
)-=154.7×[j(+a -0.001)-0.152490.044
=×[
j(-=×[j(-Xm 0.7
3
×0.088]×442.0
L 0.044
+
442.0A ＝
0.044
I B ＝=
=-0.037
Ω/km
Y4
＝
Xm +
a
-+0.044+
0.044
+＝＝
0.139Ω/km 0.066Ω/km Y3＝Xm +a +＝0.044Y2＝Xm +＝0.044+＝a 0.088Ω/km ＝0.044+0.044Y1＝Xm +＝＝0.044
Ω/km
Xm ＝10000×ln ×ln
10000
＝
0.044＝＝
0.10110000
Ω/km ×ln 210000
正常工作时单芯电缆的护套感应电压计算（已作连接）
b ＝×ln 5＝×ln 5
2Ω/km 10000a ＝10000×ln ＝
1212
1a 2210.0442
2
1a 2210.0442
2
×L ×0.7×
)+
3
×0.066]×442.0
=
18.10
∠
-11.2
°V
=154.7×[j(-0.023)+=×[
j(-0.044
+
Y2
3I B
×L 0.11478]
0.7
]×
0.7∠0°V ＝13.76E A
=×[j(-E B ＝j Xm ×I B ×V =Xm +)+××
441.99
×=18.10∠11.2
L ＝j 0.044°]×442.0
154.7×[j(-0.023)+0.11478]
×
0.7
×L =×[
j(-3×
Y2
0.044
+
)-3
×0.066]×
I B
E A
=×[j(-Xm +)-×
0.7
=154.7×[j(-0.001)+]
0.152493
×4、直角三角形排列时，单芯电缆金属护套感 应电压的计算442.0
=
23.59
∠
-0.4
°V
0.088]×=×[
j(-
0.044
+
0.044
)++a )+＝]×
×13.76∠0°V E C
=×[j(-Xm 441.99
I B
×L 3×
Y1
E B ＝j Xm ×I B ＝j 0.044
Xm 20.042
Xm 20.042
1b 2210.1012
2＝13.76∠0°V
×0.7442.0×
×441.99
0.7
×L 0.240
]
37.15
-1.4
°V
0.006)-=
∠
=154.7×[j(V
6、双回路上下排列时，单芯电缆金属护套感应电压的计算×0.139)-
3×
Y3
E A
×[]×442.0
×
0.7
×L =×[
j(-0.044+)-3
]×
I B
= 6.882×(-j +3
)=j(-Xm +=
13.76
∠
30.0
°×L =×(
-j +3)×442.0×
0.7
E C
=×(-j +3I B ×L ＝j E B ＝j Xm ×=13.76∠-30.0= 6.882×(-j -°)×
I B
-3V 0.044))×3E A
=×(-j -3=×(
-j )×
I B
5、正三角形排列时，单芯电缆金属护套感 应电压的计算
a 0.044221
b 2210.1012
21b 2210.1012
2a 0.044221b 2210.1012
2=
10.09
∠
5.3
°V
442.0
×
0.7
154.7×[]
0.065
×0.037=j(0.006)+
=
20.50
+)+]×
3∠
0°V
E C
-0.0443
L =×[
j(×
Y4
]×
I B
×442.0×0.7=×[j(-Xm +)+×=j(0.044+)×L E B =j(+)×I B Xm 0.065
]
°V 0.006)-=10.09∠-5.3=154.7×[j(V
7、双回路上下排列时，单芯电缆金属护套感应电压的计算×0.037)-3×
Y4
=
37.15
]×442.0
×
0.7
×L =×[
j(-0.044+)-3
]×
I B
E A
=×[j(-Xm +∠
1.4
°×
3
×0.139]×442.0
0.7
=154.7×[j(0.006)+
0.240
]
)+=×[
j(-
+0.044
×
Y3
]×
3I B
×L 0°V
442.0×0.7=20.50∠E C
=×[j(=j(0.044-Xm +)++)×E B =j(Xm +I B )××L