试题二
PART I 填空题
1．某分组码的最小码距是6，若该码用于纠错，可保证纠正 位错。若用于检错，可保证检出 位错。
2．在多径时变信道中，当多径时延差远远小于符号间隔时 ，当多径时延差同符号间隔可比拟时 。(选择下面所列添入空中，每空只能选一项)
a. 不发生衰落； b 发生阴影衰落；c 发生瑞利衰落；d. 发生频率选择性衰落；
e. 发生非线性失真。
3．某m 序列由n 级移存器组成。将此m 序列延迟一位后同原序列模2相加，所得序列的周期是 ，一个周期中0的个数减1的个数等于 。
4．某信源的速率是1kbps ，用2PSK 调制，其主瓣带宽是 。若将信源序列同一个速率为10k 的m 序列异或后再进行2PSK 调制，则主瓣带宽是 。
PART II 计算题
一、已知(7,3)分组码的生成矩阵为
??????????=001110101001111001110G (1)写出所有许用码组，并求出监督矩阵。
(2)该码的编码效率为多少？
(3)若译码器输入的码组为l001001，请计算其校正子，并指出此接收码组中是否包
含错误。
二、已知某(n ,k )循环码的编码率是2/3，生成多项式是，问
)1)(1()(+++=x x x x g 4
(1)n =? k =?
(2)请写出该编码器的非全0编码结果中次数最低的码多项式()x a 。
(3)已知前问中的所代表的码字a 是非全0码以外的所有编码结果中码重最小
的，问这个循环码的最小码距是多少？
()x a (4)如果该循环码用于检错目的，问错误图样多项式()x e 具有何种特点时不能被收
端检出？
(5)证明该循环码可以检出n 个比特全都发生错误的错误图样()111321++=+++++=???x x x x x x x e n n n n Λ。（提示：设法验证的因式
中只有一个是）
1+n x 1+x (6)请写出信息码组为（1010110110）的编码输出（要求用系统码）。
三、已知某m 序列的特征多项式为35
()1f x x x =++，请：
(1)画出相应的线性反馈移位寄存器序列发生器的结构图。
(2)此m 序列的周期是多少？
(3)若是此m 序列对应的双极性NRZ 信号，请画出()t s ()t s 的自相关函数。 四、某卷积编码器码的结构如下，输出时21,c c 交替输出。
(1)写出该码的生成多项式；
(2)画出该卷积码的格图；
(3)求输入为1100101的输出。
五、某信源的信息速率为9600bit/s ，信源输出通过一个1/2率的卷积编码器后用BPSK 方式传送，BPSK 采用了滚降系数为1的频谱成形。问
(1)BPSK 的符号速率是多少？
(2)BPSK 信号的带宽是多少？
六、请
(1)写出码长为16的Hadamard 矩阵
(2)请验证此矩阵的第9行和第13行是正交的。
试题二参考答案
PART I 填空题
1．某分组码的最小码距是6，若该码用于纠错，可保证纠正 2 位错。若用于检错，可保证检出 5 位错。
2．在多径时变信道中，当多径时延差远远小于符号间隔时 c ，当多径时延差同可比拟时 d 。
a. 不发生衰落； b 发生阴影衰落；c 发生瑞利衰落；d. 发生频率选择性衰落；
e. 发生非线性失真。
3．某m 序列由n 级移存器组成。将此m 序列延迟一位后同原序列模2相加，所得序列的周期是2n ?1，一个周期中0的个数减1的个数等于 -1 。
4．某信源的速率是1kbps ，用2PSK 调制，其主瓣带宽是 2kHz 。若将信源序列同一个速率为10k 的m 序列异或后再进行2PSK 调制，则主瓣带宽是 20kHz 。 PART II 计算题
一. 解：
(1)按对所有信息比特向量u 进行计算得所有需用码字如下表
G =c u u
000 001 010 011 100 101 110 111 c 0000000 0011101 01001110111010100111010100111101001 1110100
监督矩阵为
1011000111010011000100110001H ??????=??????(2)此码的编码效率是3/7。
(3)伴随式为
101011000001110100111100010100
11000110T Hy ????????????????===????????????????s 1??????????????由于s 不是全0，表明接收码字中存在错误。
二、解：
(1)由23k n =及解得：。
5n k ?=15,10n k ==(2)()()()()45411a x g x x x x x x x ==+++=++21+
(3)a =110101，其码重为4，故该码的最小码距是4。
(4)当能被整除时，这样的错误不能被检出。
()e x ()g x (5)()1415011i i x x x =+=+×∑，()140i i x e x ==∑有15项，所以14010
i i x x ==??≠????∑，即1x =不是多项
式14
0i i x =∑的根，即()e x 不含因式1x +。因为()g x 含因式1x +，所以()e x 不可能被()g x 除尽，因此这样的错误可以被检出。
(6)用长除法，1010110110除以110101得余为10001，因此编码输出是101011011010001。
三、解：
(1)序列发生器结构图如下
(2)周期为
5213?=1(3)相关函数如下图示
四、解：
(1)，
()11g x x =+()22g x x x =+(2)格图如下：
(3)输入为1100101时，考虑2bit 的尾比特，则上支路的输出是101011110，下支路的输出是010101111。变成串行后的输出是10 01 10 01 10 11 11 11 01。
五、解：
编码后的速率为19200bit/s,此即BPSK 的符号速率。BPSK 的带宽是Hz 。
()19200138400α+=六、解：
(1)码长为2的Hadarmard 矩阵为
211H ??=??11???
由递推关系
2N N N N N H H H H H ??=?????
可得
2
24221111111111111111H H H H H ??????????==???????????????
4
4844 1 1 1 1 1 1 1 11 -1 1 -1 1 -1 1 -11 1 -1 -1 1 1 -1 -11 -1 -1 1 1 -1 -1 11 1 H H H H H ??==????? 1 1 -1 -1 -1 -11 -1 1 -1 -1 1 -1 11 1 -1 -1 -1 -1 1 11 -1 -1 1 -1 1 1 -1????????????????????
8816881 1 1 1 1 1 1 1 1 1 1 1 1 1 1 11 -1 1 -1 1 -1 1 -1 1 -1 1 -1 1 -1 1 H H H H H ??=?????
= -11 1 -1 -1 1 1 -1 -1 1 1 -1 -1 1 1 -1 -11 -1 -1 1 1 -1 -1 1 1 -1 -1 1 1 -1 -1 11 1 1 1 -1 -1 -1 -1 1 1 1 1 -1 -1 -1 -11 -1 1 -1 -1 1 -1 1 1 -1 1 -1 -1 1 -1 11 1 -1 -1 -1 -1 1 1 1 1 -1 -1 -1 -1 1 11 -1 -1 1 -1 1 1 -1 1 -1 -1 1 -1 1 1 -11 1 1 1 1 1 1 1 -1 -1 -1 -1 -1 -1 -1 -11 -1 1 -1 1 -1 1 -1 -1 1 -1 1 -1 1 -1 11 1 -1 -1 1 1 -1 -1 -1 -1 1 1 -1 -1 1 11 -1 -1 1 1 -1 -1 1 -1 1 1 -1 -1 1 1 -11 1 1 1 -1 -1 -1 -1 -1 -1 -1 -1 1 1 1 11 -1 1 -1 -1 1 -1 1 -1 1 -1 1 1 -1 1 -11 1 -1 -1 -1 -1 1 1 -1 -1 1 1 1 1 -1 -11 -1 -1 1 -1 1 1 -1 -1 1 1 -1 1 -1 -1 1??????????????????????????????????????
(2)H 16的第9行为：
a =(1,1,1,1,1,1,1,1,-1,-1,-1,-1,-1,-1,-1,-1)；
第13行为：
b =(1,1,1,1,-1,-1, -1,-1,-1,-1,-1,-1,1,1,1,1)
向量a 、b 之间的内积为
11111111111111110
T =+++????++++????=ab 表明这两行正交。
一、阅读理解（共1道小题，共25.0分） 1. A pretty, well―dressed young lady stopped a taxi in a big square, and a said to the driver, "Do you see that young man at the other side of the square?" "Yes," said the taxi driver. The young man was standing outside a restaurant and looking impatiently (不耐烦地) at his watch every few seconds. "Take me over there," said the young lady. There were a lot of cars and buses in the square, so the taxi driver asked, "Are you afraid to cross the street?" "Oh, no!" said the young lady. "But I promised that I would meet the young man for lunch at one o' clock, and it is now a quarter to two. If I arrive in a taxi, it will at least seem as if I had tried not to be late." 1.How did the young woman get to the square? A.She arrived in a taxi. B.She drove there in a car. C.She got there by bus. D.The story doesn't tell us. 2.Why did the lady stop the taxi? A.Because she didn't want to be late for her appointment (约会). B.Because she wanted to get out of the taxi. C.Because she wanted to go to the restaurant in it. D.Because she was afraid of walking across the street. 3.The young man at the other side of the square_______. A.had probably been waiting for a long time B.had some problem with his watch C.was probably a waiter of the restaurant D.was someone the young lady didn't want to see 4.The young lady was_______. A.clever at making excuse B.not late at all C.45 minutes earlier D.15 minutes late 5.Had she tried not to be late? A.Yes, she had tried her best. B.No, she was just pretending that she had tried. C.Yes, she had tried but she was still late. D.No, she thought being late was better than being early.
大学英语3词汇选择练习题 第一单元选择题 1. It __________that the necklace was made of glass. A. turned out B. made out C. looked out D. took out 解析：该题选A，题目大意是“原来那串项链是用玻璃做的”。 turn out: 结果是；证明是 The party turned out to be very successful. 晚会结果开得很成功。 2. ___________, he can finish the work in a couple of weeks. A. Giving good health B. If give good health C. Given good health D. If he is good given health 解析：该题选C，题目大意是“倘若身体好，他能在一两周内完成这项工作”。given 引导方式状语，意为“倘若，假设，考虑到”。如： 1. Given their inexperience, the y’ve done a good job.考虑到他们缺乏经验，他们 的工作已经做得不错了。 2. Given some more time, I would do the job better.假如时间再多些，我能把工作 做得更好。 3. Given good health, the old lady can look after her grand-daughter for her son.假 如身体好的话，这位老太太能帮她儿子照看孙女。 3. ___________ to speak at the meeting, I couldn’t very well refuse. A. Called up B. Called off C. Called at D. Called on 解析：该题选D，题目大意是“要让我在会上发言，我是不会拒绝的”。 call on sb. to do st h：invite/require sb. to do sth.请/要求某人做某事 1. A teacher can call on individual students to compose similar questions. 老师可以要求每个学生提出类似的问题。 2. The chairman called on his people to organize so that they could be more powerful.主席号召他的民众组织起来，这样才能更有力量。 4. The poor police had never __________ of winning. A. made a chance B. took a chance C. stood a chance D. kept a chance 解析：该题选C，题目大意是“可怜的警察毫无胜诉的机会”。 stand a chanc e：have a prospect (of sth.) 有…希望 1. stand a chance of winning the game有可能赢得这场比赛 2. I think you stand a good chance of being elected president.我认为你极有可能 当选为公司总裁。 3. Weak and lame in one leg, he never stood a chance of getting the job of taxi-driver.由于身体虚弱，并且有一条跛腿，他从未有机会得到出租车司机的工作。 5. If our neighbor continues to refuse to keep his dog under control, we have to take him to ___________. A. solicitor B. brush C. prisoner D. court 解析：该题选D，题目大意是“如果我们的邻居仍然拒绝看管好他的狗，我们就不得不法庭上见了”。 take sb. to court：控告某人，对某人提出诉讼 1. If you don't pay up, I'll take you to court. 如果你不还清欠款, 我就到法院告
1. People have been talking about health for a long time because people know the importance of it. People's understanding of health also becomes deeper with the progress in scientific research. Recently the term "health" has come to have a wider meaning than it used to. It no longer means just the absence of illness. Today, health means the well-being of your body, your mind and your relationship with other people. This new concept of health is closely related to another term----quality of life. Quality of life is the degree of overall satisfaction that a person gets from life. Why has the emphasis of health shifted from the absence of disease to a broader focus on the quality of a person's life？One reason for this has to do with the length and conditions of life that people can now expect. Medical advances have made it possible for people today to live longer, healthier lives. Imagine for a moment that you were born in the year 1900. You could have expected on average to live until about the age of 47. In contrast, if you were born in the year 1999, you could expect to live to the age of 75. 2. 1. ______leads to people's deeper understanding of health. 2. https://www.doczj.com/doc/7c14825833.html,mon knowledge 2.Progress in scientific research 3.Better conditions of living 4.Quality of life 3. According to the passage, to people of today, health means______. 4. 1.absence of illness 2. a long life 3.good conditions of living 4.overall satisfaction with life
一、单项选择题（共10道小题，共100.0分） 1.Water __________ through the pipes. A.flashed B.fused C.flushed D.fluttered 知识点: 阶段作业二 学生答案: [C;] 标准答 案: C 得分: [10] 试题分 值: 10.0 提示: 2.Mary _________ with embarrassment when she couldn’t answer the question. A.shivered B.worried C.flushed D.scattered 知识点: 阶段作业二 学生答案: [C;] 标准答 案: C 得分: [10] 试题分 值: 10.0 提示: 3.If you think you can do the job, don’t hesitate, just __________. A.go away B.go over C.go ahead D.go off 知识点: 阶段作业二 学生答案: [C;] 标准答 案: C 得分: [10] 试题分10.0
值: 提示: 4.All persons and places mentioned in this book are __________. A.indexed B.indirected C.indisposed D.induced 知识点: 阶段作业二 学生答案: [A;] 标准答 案: A 得分: [10] 试题分 值: 10.0 提示: 5.They waved to one another till the train was __________. A.out of stock B.out of order C.out of sight D.out of action 知识点: 阶段作业二 学生答案: [C;] 标准答 案: C 得分: [10] 试题分 值: 10.0 提示: 6.(错误) Jane is __________ with cold so that her teeth are chattering. A.shaking B.shivering C.quaking D.shocking 知识点: 阶段作业二
一、阅读理解（共1道小题，共50.0分） 1.Robert Bruce was a famous Scottish general. In the early 14th century he tried to drive the English out of Scotland, but he was not successful because the English were too strong. Finally, Bruce had to run away and hide in a cave. One day, he lay in his cave thinking of the sad state of Scotland. A spider began to make a web above his head. Simply to pass the time, Bruce broke the web. Immediately the spider began to make a new one. Six times Bruce broke the web and six times the spider immediately made a new one. Bruce was surprised at this. He told himself that he would break the web a 7th time. If the spider made a new one, it would be a good lesson to him, for like the spider, he had been defeated six times. Bruce then broke the web. Again the spider made a new one. From this simple fact, Bruce became encouraged. He again got an army together. This time he was successful and drove the English out of Scotland. 1. Who was Robert Bruce? A. He was an English general. B. He was a Scottish general. C. He was a spider researcher D. He was a biologist from Scotland. 2. Why did Bruce hide in a cave? A. Because he was defeated by the English. B. Because he was afraid of the English army. C. Because he was looking for spiders D. Because he was badly injured in the battle. 3. In the beginning he broke the spider web just because______.
计算机与信息技术学院实验报告 专业：通信工程 年级/班级：2009级 2011—2012学年第一学期 课程名称 光纤通信 指导教师 李新源 本组成员 学号姓名 XXXXXX 实验地点 计算机楼501 实验时间 2012年4月6 日 项目名称 自动光功率控制电路 实验类型 硬件实验 一、 实验目的 1.掌握自动功率控制电路的工作原理 二、实验内容： 1.学习自动功率控制电路的工作原理 2.测量相关特征测试点的参数 三、实验仪器： 1.示波器。 2.光纤通信实验系统。 3.光功率计。 4.万用表。 5.FC/PC 型光纤跳线2根。 四、实验原理： 激光器输出光功率与温度和老化效应密切相关。保持激光器输出光功率稳定，可以用光反馈来自动调整偏置电流，电路如下图所示： 1 A 3 A 2 A B I
首先，PIN管监测背向光功率，经检出的光电流由A1放大，送入比较器A3的反向输入端，输入的数字信号和直流参考信号经A2比较放大，接到的A3同相输入端。A3和VT3组成恒流源，给激光器加上偏置电流IB的大小，其中信号参考电压是防止控制电路在无输入信号或长连“0”时，使偏流自动上升。这种电路在10°C～50°C温度范围内功率不稳定度ΔP/P可小于5%。 五、实验步骤： 1.关闭系统电源。按以下方式用连信号连接导线连接： 数字信号模块（数字信号输出一）P300—P100 1310数字光发模块 （数字光发信号输 入） 2.用光纤跳线连接1310nm光发模块和光功率计。 3.将1310nm光发模块的J100，两位都调到ON状态。 4.将1310nm光发模块的J101设置为“数字”。 5.打开系统电源，将数字信源模块第一路的拨码开关U311全拨到OFF状态。这时输入到1310nm数字光发模块的信号始终为“1”。 6.用万用表测量R124两端的电压。测量方法：先将万用表打到20V直流电 压档。然后，将红表笔插入1310nm数字发光模块的台阶插座TP101黑表笔插入TP102。读出万用表的读数U1，代入公式I1= U1/ R124（R124=51Ω）可得此时 自动光功率控制所补偿的电流。观察此时光功率计的读数P1。然后，将1310nm 的拨码开关的右边一位拨到OFF状态，记下光功率计的读数P2。 7.调整手调电位器RP100改变光功率的大小，再重复实验步骤5，将测的实 验数据填入下表。 8.关闭系统电源，拆除实验导线。将各实验仪器摆放整齐。 六、实验结果和心得： 1 2 3 4 5 6 7 16.31dB 16.17dB 11.90dB 7.62dB 6.62dB 4.59dB 3.40dB 37.31dB 25.58dB 11.88dB 7.62dB 6.63dB 4.59dB 3.42dB 3.14mA 5.88mA 8.43mA 12.75mA 1 4.51mA 19.80mA 24.12mA
北邮大学英语3第二次阶段作业 一、完形填空（共1道小题，共50.0分） 1.Many years ago there was a poor man. He had an orange tree 1 his garden. On the tree there were many fine oranges. 2 he found one 3 his oranges was much bigger 4 the others. It was as 5 as a football. Nobody had ever seen 6 orange. The poor man took the orange to the king. The king was so happy ___7 __he gave the man a lot of money for it. When a rich man heard of it, he said to hi mself, “It's only an orange. Why has the king given so much money 8__ it? I'II take my gold cup to the king. He'll give me 9 money.” The next day when the king received the gold cup, he said to the rich man, 'What a beautiful cup! I'll show you __10__ , please take this great orange." a. A.on B.in C.over D.with 学生答案: B; 标准答 案: B b. A.One day B.Yesterday C.When D.This morning 学生答案: A; 标准答 案: A c. A.for B.in
光通信技术实验报告 实验一光通讯系统WDM系统设计 实验目的 1.熟悉Optisystem实验环境，练习使用元件库中的常用元件组建光纤通信系统。 2.使用OptiSystem模拟仿真WDM系统的各项性能参数，并进行分析。 实验原理 光波分复用系统简介 光波分复用是指将两种或多种各自携带有大量信息的不同波长的光载波信号，在发射端经复用器汇合，并将其耦合到同一根光纤中进行传输，在接收端通过解复用器对各种波长的光载波信号进行分离，然后由光接收机做进一步的处理，使原信号复原，这种复用技术不仅适用于单模或多模光纤通信系统，同时也适用于单向或双向传输。 波分复用系统的工作波长可以从0.8μm到1.7μm，由此可见，它可以适用于所有低衰减、低色散窗口，这样可以充分利用现有的光纤通信线路，提高通信能力，满足急剧增长的业务需求。 WDM光通信结构组成 1)滤波器：在WDM系统中进行信道选择，只让特定波长的光通过，并组织其他光波长 通过。可调谐光滤波器能从众多的波长中选出某个波长让其通过。在WDM系统的光接收机中，为了选择所需的波长，一般都需依赖于其前端的可调谐滤波器。要求其有宽的谱宽以传输需要的全部信号谱成分，且带宽要窄以减小信道间隔。 2)复用器/解复用器（MUX/DEMUX）：将多个光波长信号耦合到一路信道中，或使混合 的信号分离成单个波长供光接收机处理。一般，复用/解复用器都可以进行互易，其结构基本是相同的。实际上即是一种波长路由器，使某个波长从指定的输入端口到一个指定的输出端口。 实验软件介绍 OptiSystem是一款创新的光通讯系统模拟软件包，它集设计、测试和优化各种类型宽带光网络物理层的虚拟光连接等功能于一身，从长距离通讯系统到LANS和MANS都使用。一个基于实际光纤通讯系统模型的系统级模拟器，OptiSystem具有强大的模拟环境和真实的
北邮大学英语2答案 【精选】
一、完形填空（共1道小题，共50.0分） 1.(错误) I first saw the baby panda when she was only 10 days old. She looked like a white mouse. We ____1___her Xi Wang. It means “hope”. When Xi Wang was born, she weighed____2___100 grams. Xi Wang drank her mothe r’s milk for as much as 14 hours a day. When she was six months old, she started to eat bamboo shoots (嫩芽) and ____3____. Eight months later, she was not a small baby any more. She grew into a____4___young panda and weighed 35 kilos. When Xi Wang was 20 months old, she had to look after herself _____5___ her mother had another baby. ____6_____, it is very difficult for pandas to live in the wild. Here are some of the _____7____that pandas like Xi Wang may have in the future. If hunters catch a panda, they will kill it for its fur. If farmers____8____trees and forests, pandas will have no place to live in. When mothers leave baby pandas alone, people will often take them away. People think that the baby pandas need ____9_____. If pandas are in danger, we should try our best to protect them. If we do____10_____, soon there will be no more pandas in the world!?? a. A.made B.called C.told D.kept 学生答案: B; 标准答 案: B b. A.quite
一、完形填空（共1道小题，共50.0分） 1. Alfred Adler, a famous doctor, had experience_3__ illustrates this. When he was a small boy he was poor at arithmetic. His teacher got the idea that he had no ability in arithmetic, and told his parents what she thought in order that they would not expect_4__ much of him. __5_ this way, they too developed the idea, “Isn?t it too bad that Alfred can?t do arithmetic?” He accepted their mistaken estimate of his ability, felt that it was __6_ to try, and was very poor at arithmetic, just as they expected. One day Adler succeeded in solving a problem which _7__of the other students had been able to solve. This gave him confidence. He _8___ the idea that he couldn?t do arithmetic and was determined to show them that he could. His new __9__ confidence stimulated him to go at arithmetic problems with a new spirit. He now worked with interest, __10_, and purpose, and he soon became extraordinarily good at arithmetic. a. A. well B. necessary C. in D. good b. A. possible B. possibly C. likely D. like c. A. to B. when C. what D. which d. A. too B. very C. so
武汉大学电工电子信息学院实验报告 电子信息学院通信工程专业2015年 9 月17日 实验名称光纤通信的光传输指导教师易本顺 姓名徐佑宇年级2012级学号2012301200003成绩 一、预习部分 1.实验目的 2.实验基本原理 3.主要仪器设备(含必要的元器件、工具) 一、实验目的 1、通过光传输系统课程设计使学生熟悉常见的几种传输网络的特点及应用场 合； 2、了解ZXMP S325的具体硬件结构，加深对于光传输的理解； 3、掌握 ZXMP S325 的组网过程以及网管工具的使用，培养学生在传输组网工 程方面的实际应用技能。 二、实验设备 1、SDH设备：ZXMP S325； 2、实验用维护终端 三、实验原理 SDH技术是目前通信网络的主流技术，它以其突出的技术优势为网络提供优质、高效、可靠的通信业务，能够满足带宽数据及图像视频等多业务的传输需求，自愈功能强。 1、光传输原理及优势 SDH 全称同步数字体系（Synchronous Digital Hierarchy）， SDH 规范了数字信号的帧结构、复用方式、传输速率等级、接口码型特性，提供了一个国际支持框架，在此基础上发展并建成了一种灵活、可靠、便于管理的世界电信传输网。这种传输网易于扩展，适于新电信业务的开展，并且使不同厂家生产的设备互通成为可能，这正是网络建设者长期以来追求的目标。 其优势主要体现在以下几个方面： （1）接口方面 ·电接口：STM-1是SDH的第一个等级，又叫基本传输模块，比特率为155.520Mb/s，STM-N是SDH第N个等级的同步传送模块，比特率是STM-1的N倍（N=4n=1,4,16...）·光接口：仅对电信号扰码，光口信号码型是加扰的NRZ码，采用世界统一的7级扰码。 （2）复用方式 低速SDH信号以字节间插方式复用进高速SDH帧结构中，位置均匀、有规律，是可预见的
A . anyone else B . anything C . some of the things D . anything else A . more larger, all B . much larger, that C . very larger, both D . larger, those
A . flooded B . were flooded C . was flooded D . flood √4. A . being B . C . having D . having A . happened to see B . was happened to see C . happened to be seen D . was happened to be seen
A . rather B . enough C . quite a D . fairly A . the much best B . much the most best C . the very best D . very the best A . will put off
B . will be put off C . will be put D . has put off A . When B . What time C . How often D . How long A . take good care of B . has taken good care of C . took good care of D . are taken good care of
一、单项选择题（共20道小题，共100.0分）1Her brother ______ to leave her in the dark room alone when she disobeyed his order. 1declared 1threatened 1warned 1exclaimed 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0提示:2It is certain that he will ______ his business to his son when he gets old.1take over 1think over 1hand over 1go over 知识点:Vocabulary 学生答案:[C;]标准答案:C 得分:[5]试题分值: 5.0提示:3The president spoke at the business meeting for nearly an hour without ______ his notes. 1bringing up 1referring to 1looking for 1trying on 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0 提示: 4 With oil prices keeping ______, people are hesitating whether to buy a car or not.1 rising 1 arising 1raising 、管路敷设技术通过管线敷设技术不仅可以解决吊顶层配置不规范高中资料试卷问题，而且可保障各类管路习题到位。在管路敷设过程中，要加强看护关于管路高中资料试卷连接管口处理高中资料试卷弯扁度固定盒位置保护层防腐跨接地线弯曲半径标高等，要求技术交底。管线敷设技术中包含线槽、管架等多项式，为解决高中语文电气课件中管壁薄、接口不严等问题，合理利用管线敷设技术。线缆敷设原则：在分线盒处，当不同电压回路交叉时，应采用金属隔板进行隔开处理；同一线槽内，强电回路须同时切断习题电源，线缆敷设完毕，要进行检查和检测处理。、电气课件中调试对全部高中资料试卷电气设备，在安装过程中以及安装结束后进行高中资料试卷调整试验；通电检查所有设备高中资料试卷相互作用与相互关系，根据生产工艺高中资料试卷要求，对电气设备进行空载与带负荷下高中资料试卷调控试验；对设备进行调整使其在正常工况下与过度工作下都可以正常工作；对于继电保护进行整核对定值，审核与校对图纸，编写复杂设备与装置高中资料试卷调试方案，编写重要设备高中资料试卷试验方案以及系统启动方案；对整套启动过程中高中资料试卷电气设备进行调试工作并且进行过关运行高中资料试卷技术指导。对于调试过程中高中资料试卷技术问题，作为调试人员，需要在事前掌握图纸资料、设备制造厂家出具高中资料试卷试验报告与相关技术资料，并且了解现场设备高中资料试卷布置情况与有关高中资料试卷电气系统接线等情况，然后根据规范与规程规定，制定设备调试高中资料试卷方案。、电气设备调试高中资料试卷技术电力保护装置调试技术，电力保护高中资料试卷配置技术是指机组在进行继电保护高中资料试卷总体配置时，需要在最大限度内来确保机组高中资料试卷安全，并且尽可能地缩小故障高中资料试卷破坏范围，或者对某些异常高中资料试卷工况进行自动处理，尤其要避免错误高中资料试卷保护装置动作，并且拒绝动作，来避免不必要高中资料试卷突然停机。因此，电力高中资料试卷保护装置调试技术，要求电力保护装置做到准确灵活。对于差动保护装置高中资料试卷调试技术是指发电机一变压器组在发生内部故障时，需要进行外部电源高中资料试卷切除从而采用高中资料试卷主要保护装置。
南京工程学院 通信工程学院 实验报告 课程名称光纤通信_________ 实验项目名称光纤通信实验_______ 实验学生班级通信（卓越）131_____ 实验学生姓名吴振飞_____ _____ 实验学生学号 208130429_________ 实验时间2016.6.15___ 实验地点信息楼C413_______ 实验成绩评定 ______________________ 指导教师签字 ______________________ 2016年 6月 19日
目录 实验一半导体激光器P-I特性测试实验 (1) 一、实验目的 (1) 二、实验仪器 (1) 三、实验原理 (1) 四、实验内容 (2) 五、实验步骤 (2) 六、注意事项 (2) 七、思考题 (3) 实验二光电探测器特性测试实验 (3) 一、实验目的 (3) 二、实验仪器 (3) 三、实验原理 (3) 四、实验内容 (4) 五、实验步骤 (4) 六、注意事项 (4) 实验三电话光纤传输系统实验 (4) 一、实验目的 (4) 二、实验内容 (5) 三、预备知识 (5) 四、实验仪器 (5) 五、实验原理 (5) 六、注意事项 (6) 七、实验步骤 (6) 九、思考题 (6)
实验一半导体激光器P-I特性测试实验 一、实验目的 学习半导体激光器发光原理和光纤通信中激光光源工作原理；了解半导体激光器平均输出光功率与注入驱动电流的关系；掌握半导体激光器 P(平均发送光功率) -I(注入电流) 曲线的测试方法。 二、实验仪器 1、ZYE4301G 型光纤通信原理实验箱 1 台 2、光功率计1 台 3、FC/PC-FC/PC 单模光跳线 1 根 4、万用表(自带) 1 台 5、连接导线 20 根 三、实验原理 半导体激光二极管(LD) 或简称半导体激光器，它通过受激辐射发光，(处于高能级E2的电子在光场的感应下发射一个和感应光子一模一样的光子，而跃迁到低能级E1，这个过程称为光的受激辐射，所谓一模一样，是指发射光子和感应光子不仅频率相同，而且相位、偏振方向和传播方向都相同，它和感应光子是相干的。) 是一种阈值器件。由于受激辐射与自发辐射的本质不同，导致了半导体激光器不仅能产生高功率(≥10mW) 辐射，而且输出光发散角窄(垂直发散角为 30~50°，水平发散角为 0~30° )，与单模光纤的耦合效率高(约 30%~50%)，辐射光谱线窄(Δλ =0.1~1.0nm)，适用于高比特工作，载流子复合寿命短，能进行高速信号(>20GHz) 直接调制，非常适合于作高速长距离光纤通信系统的光源。 对于线性度良好的半导体激光器，其输出功率可以表示为ηω (1-1) Pe=)(2thDIIq ?η其中intintaaamirmirD+=ηη，这里的量子效率ηint，表征注入电子通过受激辐射转化为光子的比例。在高于阈值区域，大多数半导体激光器的ηint接近于 1。 1-1 式表明，激光输出功率决定于内量子效率和光腔损耗，并随着电流而增大，当注入电流I>Ith时，输出功率与I成线性关系。其增大的速率即P-I曲线的斜率，称为斜率效率 dPη2DeqdIηω= (1-2) P-I特性是选择半导体激光器的重要依据。在选择时，应选阈值电流Ith尽可能小， Ith对应P值小，而且没有扭折点的半导体激光器，这样的激光器工作电流小，工作稳定性高，而且不易产生光信号失真。并且要求P-I曲线的斜率适当。斜率太小，则要求驱动信号太大，给驱动电路带来麻烦; 斜率太大，则会出现光反射噪声及使自动光功率控制环路调整困难。半导体激光器具有高功率密度和极高量子效率的特点，微小的电流变化会导致光功率输出变化，是光纤通信中最重要的一种光源，半导体激光器可以看作为一种光学振荡器，要形成光的振荡，就必须要有光放大机制，也即激活介质处于粒子数反转分布，而且产生的增益足以抵消所有的损耗。将开始出现净增益的条件称为阈值条件。一般用注入电流值来标定阈值条件，也即阈值电流Ith，当输入电流小于Ith时，其输出光为非相干的荧光，类似于LED发出的光，当电流大于Ith
北邮英语统考题库 a ted Test（1） 第一部分：交际用语（共10 题?；每 题1分?，满分10分?） 部分共 ?10? ， 每 ??部分 4?选项，请从A、B、 C、D 选项?选 ?? 选项?。 1. — How are you, Bob? —___ Ted. A. How are you? you. C. How do you do? D. Nice to meet you. 2. —s for your help. —_ u re. mind. me. 3. —r. —__. A. call my e s e s e s e s me 4. —___? — Oh, r. D. whic is that 5. —with you? —____, and how are you? o n it B. Ahem, not too bad s y fast 6. —you have on! —___ s. I got it ye r day. . C. You can have it. . — r day? — r. e s. e s. e nt. — m e back! Had a nice trip? —____ day. C. By d ays. call. — now?
— __ e r here. r. s g. h op, you know. 10. — n g now. — ____ r ful. ? C. Not at all. D. Good luck! 第二部分：阅读理解（共15 题?；每 题2分?，满分30分?） 部分共 ?3 ，每 ?5 题?。请从每 ?题A、B、C、D 选项?，选 ??选项。 Passa?g e 1 Commu?n ity servi?c e is an impor?t ant compo?n ent of educa?t ion here at our unive?r s ity?.We encou?r age all stude?n ts to volun?t eer for at least? one commu?n ity activ?ity befor?e they gradu?a te. A new commu?n ity progr?a m calle?d“One On One” helps? eleme?n tary?stude?n ts who ve falle?n behin?d. Your educa?t ion major?s might? be espec?ially?inter?e sted?i n it becau?s e it offer?s the oppor?t unit?y to do some teach?ing, that is, tutor?ing in math and Engli?s h. You d have to volun?t eer two hours? a week for one semes?t er. You can choos?e to help a child?with math, Engli?s h, or both. Half-hour lesso?n s are fine, so you could?do a half hour of each subje?ct two days a week. Profe?s sor Dodge?will act as a mento?r（导师）to the tutor?s—he ll be avail?a ble to help you with lesso?n plans? or to offer? sugge?s tion?s for activ?ities?. He has offic?e hours? every? Tuesd?a y and Thurs?d ay after?n oon. You can sign up for the progr?a m with him and begin?the tutor?ing next week. I m sure you ll enjoy?this commu?n ity servi?c e and you ll gain valua?b le exper?ience?at the same time. It looks?good on your resum?e, too, showi?n g that you ve had exper?ience?with child?ren and that you care about?your commu?n ity. If you d like to sign up, or if you have any quest?ions, stop by Profe?s sor Dodge?s offic?e this week. (220wo?r ds) 11. What is the purpo?s e of the talk? _____?B____? A. To expla?in a new requi?r e men?t for gradu?a tion?. B. To inter?e st stude?n ts in a new commu?n ity progr?a m. C. To discu?s s the probl?e ms of eleme?n tary?schoo?l stude?n t s. D. To recru?it eleme?n tary?schoo?l teach?e rs for a speci?a l progr?a m. 12. What is the purpo?s e of the progr?a m that the speak?e r descr?ibes?____C?____ A. To find jobs for gradu?a ting?stude?n ts. B. To help educa?t ion major?s p repa?r e for final? exams?. C. To offer? tutor?ials to eleme?n tary?schoo?l stude?n ts. D. To provi?d e fundi?n g for a commu?n ity servi?c e proje?c t. 13. What does Profe?s sor Dodge?do? _____?__A__? A. He advis?e s stude?n ts to parti?c ipat?e in certa?in progr?a m. B. He teach?e s part-time in an eleme?n tary?schoo?l.