当前位置:文档之家› 《Java基础入门》_课后习题答案解析__1~

《Java基础入门》_课后习题答案解析__1~

《Java基础入门》_课后习题答案解析__1~
《Java基础入门》_课后习题答案解析__1~

第1章 Java开发入门

一、填空题

1、Java EE、Java SE、Java ME

2、JRE

3、javac

4、bin

5、path、classpath

二、选择题

1、ABCD

2、C

3、D

4、B

5、B

三、简答题

1、面向对象、跨平台性、健壮性、安全性、可移植性、多线程性、动态性等。

2、JRE(Java Runtime Environment,Java运行时环境),它相当于操作系统部分,提供了Java程

序运行时所需要的基本条件和许多Java基础类,例如,IO类、GUI控件类、网络类等。JRE是提供给普通用户使用的,如果你只想运行别人开发好的Java程序,那么,你的计算机上必须且只需安装JRE。

JDK(Java Development Kit,Java开发工具包),它包含编译工具、解释工具、文档制作工具、打包工具多种与开发相关的工具,是提供给Java开发人员使用的。初学者学习和使用Java语言时,首先必须下载和安装JDK。JDK中已经包含了JRE部分,初学者安装JDK后不必再去下载和安装JRE了。

四、编程题

public class HelloWorld {

public static void main(String[] args) {

System.out.println("这是第一个Java程序!");

}

}

第2章 Java编程基础

一、填空题

1、 class

2、 true和false

3、单行注释、多行注释、文档注释

4、基本数据类型、引用数据类型

5、 1、2、4、8

6、 & && | ||

7、 0

8、 5

9、 34

10、56

二、判断题

1、错

2、对

3、错

4、对

5、错

三、选择题

1、AD

2、AD

3、C

4、ABCD

5、C 6 、A 7、AC 8、A 9、B 10、A

四、程序分析题

1、编译不通过。int值4和b相加时,由于变量b的类型为byte,取值范围没有int类型大,存不下

int类型的值,因此编译不通过。

2、编译不通过。这是因为y是在最里层的代码块中定义的一个变量,只有在那个代码块中才可使用,

在使用y = x;语句时已经超过了y变量的作用域,所以编译无法通过。

3、打印结果为:3。

4、打印结果为:

9

8

7

五、简答题

1、Java语言的八种基本数据类型有:byte字节型,占一个字节。short短整型,占两个字节。int

整型,占4个字节。long长整型,占8个字节。float单精度浮点型,占4个字节。double双精度浮点型,占8个字节。char字符型,占两个字节。boolean型,表示逻辑值,有true和false 两个值,分别占一个字节。

2、如果使用“&”在表达式之间进行连接,那么无论任何情况,“&”两边的表达式都会参与计算。如

果使用“&&”进行连接,当“&&”左边的表达式为false,则不会执行其右边的表达式。例如定义int x = 2,y = 0; boolean b = x < y & x / y> 0表达是会发生被0除异常,因为x / y的表达式执行了。而boolean b = x < y & x / y> 0是不会出现这种异常的,因为x < y为false,表达式x / y不会执行。

3、方法重载指的是在一个类中可以声明多个同名的方法,而方法中参数的个数或者数据类型不一致。

调用这些同名的方法时,JVM会根据实际参数的不同绑定到不同的方法。

六、编程题

1、参考答案

public class Test01 {

public static void main(String[] args) {

int sum = 0;

for (int i = 1; i < 100; i++) {

if (i % 2 != 0)

sum += i;

}

System.out.println(sum);

}

}

2、参考答案

public class Test02 {

public static void main(String args[]) {

int y = function(0);

System.out.println(y);

}

public static int function(int x) {

int y;

if (x > 0) {

y = x + 3;

} else if (x == 0) {

y = 0;

} else {

y = x * x - 1;

}

return y;

}

}

3、参考答案

public class Test03 {

public static void main(String[] args) {

int[] arr = { 25, 24, 12, 76, 101, 96, 28 };

for (int i = 0; i < arr.length - 1; i++) {

// 定义内层循环

for (int j = 0; j < arr.length - i - 1; j++) {

if (arr[j] > arr[j + 1]) { // 比较相邻元素

// 下面的三行代码用于交换两个元素

int temp = arr[j];

arr[j] = arr[j + 1];

arr[j + 1] = temp;

}

}

}

for (int i = 0; i < arr.length; i++) {

System.out.print(arr[i] + " "); // 打印元素和空格}

}

}

第3章面向对象(上)

一、填空题

1、封装、继承、多态

2、new

3、成员变量、局部变量

4、类、类

5、this

6、finalize()

7、静态变量

8、内部类

9、javadoc

10、private

二、判断题

1、对

2、对

3、错

4、对

5、错

三、选择题

1、B

2、D

3、B

4、ABC

5、ABCD

6、ACD

7、ABCD

8、ABCD

9、D 10、D

四、程序分析题

1、程序不能编译通过,因为在类A中的成员变量secret用private修饰,所以在类Test1中无法访问。

2、程序不能编译通过,因为在静态方法method()中不能访问非静态成员变量x。

3、程序能够编译通过,运行的结果为“inner”。

五、简答题

1、构造方法是类的一个特殊成员,它会在类实例化对象时被自动调用。而普通方法只有在使用的时

候才会被调用。在定义构造方法时要求方法名与类名相同、在方法名的前面没有返回值类型的声明、在方法中不能使用return语句返回一个值

2、单例模式可以保证在整个程序运行期间针对该类只存在一个实例对象。

六、编程题

1、参考答案

class Student {

private String name;

private double grade;

public Student() {

}

public Student(String name, double grade) {

https://www.doczj.com/doc/4c16865428.html, = name;

this.grade = grade;

}

public String getName() {

return name;

}

public void setName(String name) {

https://www.doczj.com/doc/4c16865428.html, = name;

}

public double getGrade() {

return grade;

}

public void setGrade(double grade) {

this.grade = grade;

}

}

public class Test01 {

public static void main(String[] args) {

Student stu1 = new Student();

stu1.setName("zhangsan");

stu1.setGrade(99);

Student stu2 = new Student("lisi", 100);

}

}

2、参考答案

c lass Father {

private String name = "zhangjun";

class Child {

public void introFather() {

System.out.println("My Father's name is " + name);

}

}

}

public class Test02 {

public static void main(String[] args) {

Father.Child child = new Father().new Child();

child.introFather();

}

}

第4章面向对象(下)

一、填空题

1、继承

2、方法,抽象类

3、import

4、子类、父类、基类

5、Exception

6、final

7、super

8、Object

9、try、catch

10、jar –cvf,java –jar

二、判断题

1、错

2、对

3、错

4、对

5、对

三、选择题

1、B

2、C

3、ABC

4、 ABCD

5、C

6、AC

7、C

8、D

9、A 10、B

四、程序分析题

1、程序编译能通过,这是因为int x = 2 / 0; System.out.println(x);这两条语句使用了try块,

捕获了程序因为除以0而产生的异常情况,之后程序会继续向下执行,输出“进入catch代码块”,“进入finally代码块”。

2、程序编译不通过,这是因为在程序中使用了final关键字修饰Animal类,使得Animal类不能被

继承。shout()方法中同样使用了final关键字,使得该方法不能被重写。

3、程序编译能通过,输出结果为“动物叫!”和“汪汪……”,因为在程序中调用shout()方法时,首

先会通过super.shout()调用父类的方法说出“动物叫!”之后再输出“汪汪……”

4、程序编译不通过,因为接口中定义的方法不能有方法体,所以定义的eat()方法是错误的。接口

中的方法必须在子类中全部实现,由于run()方法在子类中并没有重新实现,所以这也是错误的。

五、简答题

1、在继承关系中,子类的方法与父类的某一方法具有相同的方法名、返回类型和参数列表,则称子

类的该方法重写(覆盖)父类的方法。

2、多态意味着一个对象有着多种形态,可以在特定的情况下,表现不同的状态,从而对应着不同的

属性和方法。简单的说,多态就是使用父类类型的变量引用子类对象,根据被引用子类对象的特性,程序会得到不同的运行效果。

3、在Java中,使用abstract关键字修饰的类称之为抽象类。抽象类是不能被实例化的,通常需要

写一个子类来继承抽象类,同时实例化子类来获得该类的对象。抽象类通常用于表示一种抽象的概念。

接口可以说是一种特殊的抽象类,接口中只能定义常量和抽象方法。由于接口的特殊性,在定义时需要使用interface关键字。

六、编程题

1、参考答案

class Student {

public String name;

public int age;

public Student(String name,int age){

https://www.doczj.com/doc/4c16865428.html,=name;

this.age=age;

}

public void show(){

System.out.println("name: "+name+" age: "+age);

}

}

class UnderGraduate extends Student{

public String degree;

public UnderGraduate(String name,int age,String degree){

super(name, age);

this.degree=degree;

}

public void show(){

System.out.println("name: "+name+" age: "+age+" degree: "+degree);

}

}

public class Test01{

public static void main(String[] args) {

Student student = new Student("zhangsan", 16);

student.show();

UnderGraduate underGraduate = new UnderGraduate("lisi", 20, "bechalor");

underGraduate.show();

}

}

2、参考答案

interface Shape {

double area(double givenValue);

}

class Square implements Shape{

public double area(double sideLength) {

return sideLength*sideLength;

}

}

class Circle implements Shape{

public double area(double r) {

return Math.PI*r*r;

}

}

public class Test02 {

public static void main(String[] args) {

Shape square = new Square();

Shape circle = new Circle();

System.out.println(square.area(2));

System.out.println(circle.area(3));

}

}

3、参考答案

class NoThisSongException extends Exception{

public NoThisSongException(){

super();

}

public NoThisSongException(String message){

super(message);

}

}

class Player{

public void play(int index)throws NoThisSongException{ if(index>10){

throw new NoThisSongException("您播放的歌曲不存在");

}

System.out.println("正在播放歌曲");

}

}

public class Test03 {

public static void main(String[] args) {

Player player = new Player();

try {

player.play(13);

} catch (NoThisSongException e) {

System.out.println("异常信息为: "+e.getMessage());

}

}

}

第5章多线程

第6章 JavaAPI

一、填空题

1、String、StringBuffer

2、Date、Calendar、DateFormat

3、getRuntime()

4、sqrt()

5、DateFormat

6、π、e

7、Random、java.util

8、length()

9、静态

10、edcba

二、判断题

1、错

2、错

3、对

4、错

5、对

三、选择题

1、C

2、C

3、D

4、C

5、C

6、B

7、C

8、A

9、A 10、B

四、程序分析题

1、程序编译能通过,输出结果如下

5

7.0

-8.0

-5

8.1

-6.1

2、程序编译能通过,输出结果如下

str.length():15

str.charAt(0):d

lastIndexOf(m):10

substring(2,4):fe

indexOf(g):5

五、简答题

1、String类是不可变类,即字符串值一旦初始化后就不可能改变。StringBuffer是可变字符串类,

类似String的缓冲区,可以修改字符串的值。

2、Date类用来表示某个特定的瞬间,能够精确到毫秒。而在实际应用中,往往需要把一个日期中的

年、月、日等信息单独返回进行显示或处理,这个类中的大部分方法都已被标记过时。Calender 类基本取代了Date类,该类中定义了一系列用于完成日期和时间字段操作的方法。

Calendar的getTime()方法,getTime()返回一个表示Calendar时间值的Date对象,同时Calendar有一个setTime(Date date)方法,setTime()方法接收一个Date对象,将Date对象表示的时间值设置给Calendar对象,通过这两个方法就可以完成Date和Calendar对象之间的转换。

六、编程题

1、参考答案

public class Test01 {

public static void main(String[] args) {

String str = "HelloWorld";

// 字符串转成char数组

char[] ch = str.toCharArray();

StringBuffer buffer = new StringBuffer();

for (int i = str.length() - 1; i >= 0; i--) {

if (ch[i] >= 'A' && ch[i] <= 'Z') {

buffer.append(String.valueOf(ch[i]).toLowerCase());

} else if (ch[i] >= 'a' && ch[i] <= 'z') {

buffer.append(String.valueOf(ch[i]).toUpperCase());

}

}

System.out.println(buffer.toString());

}

}

2、参考答案

import java.text.DateFormat;

import java.util.Calendar;

import java.util.Date;

public class Test02 {

public static void main(String[] args) {

Calendar calendar = Calendar.getInstance();

calendar.add(Calendar.DATE, 100);

Date date = calendar.getTime();

DateFormat format = DateFormat.getDateInstance(DateFormat.FULL);

String string = format.format(date);

System.out.println(string);

}

}

3、参考答案

import java.util.Random;

public class Test03 {

public static void main(String[] args) {

Random rand = new Random();

int[] num = new int[5];

for (int i = 0; i < num.length; i++) {

num[i] = 20 + rand.nextInt(31);

System.out.println(num[i]);

}

}

}

高中数学解析几何测试题答案版(供参考)

解析几何练习题 一、选择题:(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中, 只有一项是符合题目要求的.) 1.过点(1,0)且与直线x-2y-2=0平行的直线方程是( ) A.x-2y-1=0 B.x-2y+1=0 C.2x+y-2=0 D.x+2y-1=0 2.若直线210ay -=与直线(31)10a x y -+-=平行,则实数a 等于( ) A 、12 B 、12 - C 、13 D 、13 - 3.若直线,直线与关于直线对称,则直线的斜率为 ( ) A . B . C . D . 4.在等腰三角形AOB 中,AO =AB ,点O(0,0),A(1,3),点B 在x 轴的正半轴上,则直线AB 的方程为( ) A .y -1=3(x -3) B .y -1=-3(x -3) C .y -3=3(x -1) D .y -3=-3(x -1) 5.直线对称的直线方程是 ( ) A . B . C . D . 6.若直线与直线关于点对称,则直线恒过定点( ) 32:1+=x y l 2l 1l x y -=2l 2 1 2 1-22-02032=+-=+-y x y x 关于直线032=+-y x 032=--y x 210x y ++=210x y +-=()1:4l y k x =-2l )1,2(2l

A . B . C . D . 7.已知直线mx+ny+1=0平行于直线4x+3y+5=0,且在y 轴上的截距为3 1,则m ,n 的值分别为 A.4和3 B.-4和3 C.- 4和-3 D.4和-3 8.直线x-y+1=0与圆(x+1)2+y 2=1的位置关系是( ) A 相切 B 直线过圆心 C .直线不过圆心但与圆相交 D .相离 9.圆x 2+y 2-2y -1=0关于直线x -2y -3=0对称的圆方程是( ) A.(x -2)2 +(y+3)2 =1 2 B.(x -2)2+(y+3)2=2 C.(x +2)2 +(y -3)2 =1 2 D.(x +2)2+(y -3)2=2 10.已知点在直线上移动,当取得最小值时,过点引圆的切线,则此切线段的长度为( ) A . B . C . D . 11.经过点(2,3)P -作圆22(1)25x y ++=的弦AB ,使点P 为弦AB 的中点,则 弦AB 所在直线方程为( ) A .50x y --= B .50x y -+= C .50x y ++= D .50x y +-= 0,40,22,44,2(,)P x y 23x y +=24x y +(,)P x y 22111()()242 x y -++ =2 321 22

解析几何经典例题

解析几何经典例题 圆锥曲线的定义是“圆锥曲线方程”这一章的基础,对这些定义我们有必要深刻地理解与把握。这里就探讨一下圆锥曲线定义的深层及其综合运用。 一、椭圆定义的深层运用 例1. 如图1,P为椭圆上一动点,为其两焦点,从 的外角的平分线作垂线,垂足为M,将F2P的延长线于N,求M的轨迹方程。 图1 解析:易知故 在中, 则点M的轨迹方程为。 二、双曲线定义的深层运用 例2. 如图2,为双曲线的两焦点,P为其上一动点,从的平分线作垂线,垂足为M,求M的轨迹方程。 图2 解析:不妨设P点在双曲线的右支上, 延长F1M交PF2的延长线于N, 则, 即 在 故点M的轨迹方程为 三、抛物线定义的深层运用 例3. 如图3,AB为抛物线的一条弦,|AB|=4,F为其焦点,求AB的中点M到直线y=-1的最短距离。

图3 解析:易知抛物线的准线l:, 作AA”⊥l,BB”⊥l,MM”⊥l,垂足分别为A”、B”、M” 则 即M到直线的最短距离为2 故M到直线y=-1的最短距离为。 评注:上述解法中,当且仅当A、B、F共线,即AB为抛物线的一条焦点弦时,距离才取到最小值。一般地, 求抛物线的弦AB的中点到准线的最短距离,只有当(即通径长)时,才能用上述解法。 四、圆与椭圆、圆与双曲线定义的综合运用 例4. ①已知圆,M为圆上任一点,MP的垂直平分线交OM于Q,则Q的轨迹为() 图4 ②已知圆,M为圆上任一点,MP的垂直平分线交OM于Q,则Q的轨迹为() A. 圆 B. 椭圆 C. 双曲线 D. 抛物线 解析:①如图4,由垂直平分线的性质,知|QM|=|QP|, 而|QM|=|OM|-|OQ|=2-|OQ| 即|OQ|+|QP|=2>|OP|= 故Q的轨迹是以O(0,0)、P为焦点 长轴长为2的椭圆。应选B。 ②同理,利用垂直平分线的性质及双曲线的定义,可知点Q的轨迹为双曲线的一支,应选C。 五、椭圆与双曲线定义的综合运用 例5. 如图5,已知三点A(-7,0),B(7,0),C(2,-12)。①若椭圆过A、B两点,且C为其一焦点,求另一焦点P的轨迹方程;②若双曲线的两支分别过A、B两点,且C为其一焦点,求另一焦点Q的轨迹方程。

高英课本课后翻译答案

这是我整理的,希望对大家有用。蓝色部分是重点词汇。 第一课 1、一条蜿蜒的小路隐没在树荫深处。 A winding path loses itself in the shadowy distance of the woods. 2、集市上有许多小摊子,出售的货物应有尽有。 At the bazaar, there are many stalls where goods of every conceivable kind are sold. 3、我真不知道到底是什么事让他如此生气。 I really don’t know what it is that has made him so angry. 4、新出土的铜花瓶造型优美,可有精细、复杂的传统图案。 The newly unearthed bronze vase is pleasing in form and engraved with delicate and intricate traditional designs. … 5、在山的那一边是一望无际的大草原。 Beyond the mountains there is a vast grassland that extends as far as the eye can see. 6、他们决定买那座带有汽车房的房子。 They decided to buy that house with a garage attached. 7、教师们坚持对学生严格要求。 The teachers make a point of be ing strict with the students. 8、这个小女孩很喜欢她的父亲。 The girl is very much attached to her father. 9、为了实现四个现代化,我们认为有必要学习国外的先进科学技术。 To achieve the four modernization, we make a point of learn ing from the advanced science and technology of other countries. | 10、黄昏临近时,天渐渐暗下来了。 As dusk fell, daylight faded away. 11徒工仔细地观察他的师傅,然后照着干。 The apprentice watched his master carefully and then followed suit. 12、吃完饭弗兰克常常帮助洗餐具。 Frank often took a hand in the washing-up after dinner.

大学英语第一册课后习题答案

新视野大学英语(第二版)第一册Unit 1 III. 1. rewarding 2. communicate 3. access 4. embarrassing 5. positive 6. commitment 7.virtual 8. benefits 9. minimum 10. opportunities IV. 1. up 2. into 3. from 4. with 5. to 6. up 7. of 8. in 9. for 10.with V. 1.G 2.B 3.E 4.I 5.H 6.K 7.M 8.O 9.F 10.C Sentence Structure VI. 1. Universities in the east are better equipped, while those in the west are relatively poor. 2. Allan Clark kept talking the price up, while Wilkinson kept knocking it down. 3. The husband spent all his money drinking, while his wife saved all hers for the family. 4. Some guests spoke pleasantly and behaved politely, while others wee insulting and impolite. 5. Outwardly Sara was friendly towards all those concerned, while inwardly she was angry. VII. 1. Not only did Mr. Smith learn the Chinese language, but he also bridged the gap between his culture and ours. 2. Not only did we learn the technology through the online course, but we also learned to communicate with friends in English. 3. Not only did we lose all our money, but we also came close to losing our lives. 4. Not only do the workers want a pay increase, but they also want reduced working hours. 5. Not only is the house expensive, but it is also too far away from my company. Translation VIII. 1. Not only can students choose when and where to learn for an online course, but they can also take time to think through answers before making a reply. 2. She is excited by the idea of online learning while be considers it meaningless and useless. 3. Communicating with native English speakers is a very rewarding experience from which we can learn a lot. 4. Today, more and more people have access to the Internet through which they look for the information they need. 5. He wants her to give up working and stay home to look after the children. She feels, however, that this is too much for her. 6. Now that we have finished the course, we shall start doing more revision work. IX. 1. 我永远都不会忘记那位老师,是他告诉我学外语是有趣的、有价值的。如果没有他,我的英语说得不会像现在这样好。

解析几何专题含答案

椭圆专题练习 1.【2017浙江,2】椭圆22 194 x y +=的离心率是 A B C .23 D .5 9 2.【2017课标3,理10】已知椭圆C :22 221x y a b +=,(a >b >0)的左、右顶点分别为A 1,A 2,且以线段A 1A 2为直径的圆与直线20bx ay ab -+=相切,则C 的离心率为 A .3 B .3 C .3 D .13 3.【2016高考浙江理数】已知椭圆C 1:+y 2=1(m >1)与双曲线C 2:–y 2=1(n >0)的焦点重合,e 1, e 2分别为C 1,C 2的离心率,则() A .m >n 且e 1e 2>1 B .m >n 且e 1e 2<1 C .m 1 D .m b >0),四点P 1(1,1),P 2(0,1),P 3(–1, 2),P 4(1,2 )中恰有三点在椭圆C 上. (1)求C 的方程; (2)设直线l 不经过P 2点且与C 相交于A ,B 两点.若直线P 2A 与直线P 2B 的斜率的和为–1,证明:l 过定点. 8.【2017课标II ,理】设O 为坐标原点,动点M 在椭圆C :2 212 x y +=上,过M 作x 轴的垂线, 垂足为N ,点P 满足NP =u u u r u u u r 。

平面解析几何经典题(含答案)

平面解析几何 一、直线的倾斜角与斜率 1、直线的倾斜角与斜率 (1)倾斜角的范围 0 180 (2)经过两点的直线的斜率公式是 (3)每条直线都有倾斜角,但并不是每条直线都有斜率 2.两条直线平行与垂直的判定 (1)两条直线平行 对于两条不重合的直线l1,l2 ,其斜率分别为k1, k2 ,则有 l1 / /l2 k1 k2 。特别地, 当直线 l1,l2 的斜率都不存在时,l1与l2 的关系为平行。 (2)两条直线垂直 如果两条直线l1,l2 斜率存在,设为k1, k2 ,则l1 l2 k1 k2 1 注:两条直线l1 ,l2 垂直的充要条件是斜率之积为-1,这句话不正确;由两直线的斜率 之积为 -1,可以得出两直线垂直,反过来,两直线垂直,斜率之积不一定为-1。如果 l1,l2 中 有一条直线的斜率不存在,另一条直线的斜率为0 时, l1与l2 互相垂直。 二、直线的方程 1、直线方程的几种形式 名称方程的形式已知条件局限性 点斜式 不包括垂直于x 轴的直 线为直线上一定点,k 为斜率 斜截式k 为斜率, b 是直线在y 轴上的截距不包括垂直于x 轴的直线两点式 不包括垂直于x 轴和 y 轴的是直线上两定点 直线 截距式 a 是直线在x 轴上的非零截距, b 是直不包括垂直于x 轴和 y 轴或

线在 y 轴上的非零截距过原点的直线 一般式 A ,B,C 为系数无限制,可表示任何位置的 直线 三、直线的交点坐标与距离公式 三、直线的交点坐标与距离公式 1.两条直线的交点 设两条直线的方程是,两条 直线的交点坐标就是方程组的解,若方程组有唯一解,则这两条 直线相交,此解就是交点的坐标;若方程组无解,则两条直线无公共点,此时两条直线平 行;反之,亦成立。 2.几种距离 (1 )两点间的距离平面上的两点间的距离公式 (2)点到直线的距离 点到直线的距离; (3)两条平行线间的距离 两条平行线间的距离 注:(1)求点到直线的距离时,直线方程要化为一般式; (2)求两条平行线间的距离时,必须将两直线方程化为系数相同的一般形式后,才能套用 公式计算 (二)直线的斜率及应用 利用斜率证明三点共线的方法: 已知A(x , y ), B(x , y ), C (x , y ), 若 x 1 x 2 x3或k AB k AC ,则有 A 、B、 C 三点共 1 1 2 2 3 3 线。

高级英语第三版第一册课后答案

高英课内考点:第一课:Paraphrase 1、we’re elevated 23 feet. Our house is 23 feet above sea level. 2、The place has been here since 1915,and no hurricane has ever bothered it. The house was built in 1915,and since then no hurricane has done any damage to it. 3、We can batten down and ride it out. We can make the necessary preparation and survive the hurricane without much damage. 4、The generator was doused,and the lights went out. Water got into the generator,it stopped working.As a result all lights were put out. 5、Everybody out the back door to the cars! Everyone go out through the back door and get into the cars! 6、The electrical systems had been killed by water.

The electrical systems in the cars had been destroyed by water. 7、John watched the water lap at the steps,and felt a crushing guilt. As John watched the water inch its way up the steps,he felt a strong sense of guilt because he blamed himself for endangering the family by making the wrong decision not to flee inland. 8、Get us through this mess,will You? Oh,God,please help us to get through this dangerous situation. 9、She carried on alone for a few bars;then her voice trailed away. She sang a few words alone and then her voice gradually grew dimmer and stopped. 10、Janis had just one delayed reaction. Janis didn’t show any fear on the spot during the storm,but she revealed her feelings caused by the storm a few nights after the hurricane by getting up in the middle of the night and crying softly. 英译汉: 1、But,like thousands of others in the coastal communities,John was reluctant to abandon his home unless the family----his wife,Janis,and their seven children,aged 3 to 11---was clearly endangered.

大学英语精读第一册课后练习部分答案

大学英语精读第一册课后练习部分答案 Unit 1 Cloze (A) 1. aware 2. performance 3. average 4. adequate 5. set aside 6. mentions 7. look over 8. commit (B) 1. if/once 2. about 3. it 4. know 5. up 6. as 7. from 8. words 9. into 10. other 11. for 12. when Translation 1、他这次考试的失败使他意识到定期复习功课的重要。 His failure in the exam has made him aware of the importance of reviewing his lessons regularly. 2、请一定不要忘记离家前你父母对你说过的话。 Be sure not to forget what your parents said to you before you left home. 3、我确信她的英语知识对这项工作来说是足够的了。 I'm sure her knowledge of English is adequate for the job. 4、这篇文章的目的是告诉学生怎样培养良好的学习习惯。 The purpose of this article is to tell the students how to develop good study habits. 5、在当今时代,人们越来越多地依靠计算机(computers)来解决各种各样的问题。In our age, people depend more and more on computers to solve various kinds of difficult problems. 6、略读不仅可以帮助你对将要阅读的东西有所了解,还可以帮助你读得快些,提高你的阅读理解力。 Skimming not only helps you get some idea of what you are going to read but also helps you read faster and improve your comprehension. 7、有些人以为男孩子比女孩子聪明。然而,事实未必如此。 Some people believe that boys are cleverer than girls. This is not necessarily the case, however. 8、即使智力一般的学生也可以通过改进学习习惯习惯而成为优等生。 Even students of average intelligence can become top students by improving their study habits.

高级英语第一册Unit12 课后练习题答案

THE LOONS 课后习题答案/answer I . 1)The Tonnerres were poor The basis of their dwelling was a small square cabin made of poles and mud, which had been built some fifty years before. As the Tonnerres had increased in number, their settlement had been added, until thc clearing at the foot of the town hill was a chaos of lean-tos, wooden packing cases, warped lumber, discarded car tyres, ramshackle chicken coops, tangled strands of barbed wire and rusty tin cans. 2)Sometimes, one of them would get involved in a fight on Main Street and be put for the night in the barred cell underneath the Court House. 3)Because she had had tuberculosis of the bone, and should have a couple of months rest to get better. 4)Her mother first objected to take Piquette along because she was afraid that the girl would spread the disease to her children and she believed that the girl was not hygienic. She then agreed to do so because she preferred Piquette to the narrator's grandmother, who promised not to go along with the family and decided to stay in the city if the girl was taken along. 5)The cottage was called Macleod, their family name. The scenery there was quite beautiful with all kinds of plants and animals at the lakeside. 6)The narrator knew that maybe Piquette was an Indian descendant who knew the woods quite well, so she tried to ask Piquette to go and play in the wood and tell her stories about woods. 7)Because Piquette thought the narrator was scorning and showing contempt for her Indian ancestors, which was just opposite to her original intention. 8)Because the narrator felt somewhat guilty. Piquette stayed most of the time in the cottage and hardly played with the narrator. At the same time, she felt there was in Piquette something strange and unknown and unfathomable. 9)That was the very rare chance she was unguarded and unmasked, so that the author could perceive her inner world. 10)Her full name is Vanessa Macleod. 11)Just as the narrator's father predicted, the loons would go away when more cottages were built at the lake with more people moving in. The loons disappeared as nature was ruined by civilization. In a similar way, Piquette and her people failed to find their position in modern society. Ⅱ. 1)who looked deadly serious, never laughed 2)Sometimes old Jules, or his son Lazarus, would get involved in a rough, noisy quarrel or fight on a Saturday night after much drinking of liquor. 3)She often missed her classes and had little interest in schoolwork. 4)I only knew her as a person who would make other people feel ill at ease. 5)She lived and moved somewhere within my range of sight (Although I saw her, I paid little attention to her). 6)If my mother had to make a choice between Grandmother Macleod and

第一册新概念 课后习题答案

新概念英语第一册习题 Lesson 1 A About you Copy this dialogue. Add your own name at the end. 抄写这段对话,. 在结尾处加上你的名字。 Sue: Excuse me. ______ John: Yes? ______ Sue: What's your name? ______ John: Pardon? ______ Sue: What's your name? ______ John: My name is John. ______ Sue: What's your name? ______ You: My name is...... ______ B Vocabulary Write the correct words in the questions.. 用正确的词完成以下问句。 book car coat dress house√. pen pencil shirt wathc 1 Is this your h______? 6 Is this your c______? 2 Is this your w______? 7 Is this your c______? 3 Is this your sh ______? 8 Is this your d______? 4 Is this your b______? 9 Is this your p______? 5 Is this your p______? 10 Is this your s ______? C Numbers Write the numbers in figures.. 用阿拉伯数字表示以下数词。 three 3 ten______ one______ four______ six______ five______ eight_________ seven______ two______ nine______ Lesson 1 B 2 watch 3 shirt 4 book 5 pen 6 coat 7 car 8 dress 9 pencil 10 skirt C 10,1,4,6,5,8,7,2,9 新概念英语第一册习题Lesson 2 Lesson 2 Is this your....?这是你的....吗? A Structure Write questions with the words.用所给的词写出问句。 Handbag Is this your handbag? 1 book ______ 2 car ______ 3 coat ______ 4 dress ______ 5 house ______ 6 pen ______ 7 pencil ______ 8 shirt ______ 9 skirt ______ 10 watch ______ B Situations Look at the situations. Which expression do you use for each?针对所 给情景选择你应该说的话。

解析几何解答题专练

解析几何解答题专练

19.(本小题14分) 已知椭圆G 的中心在坐标原点,焦点在x 轴上,且经过点)20 P ,和点 212Q ?-- ?? ,. (Ⅰ)求椭圆G 的标准方程; (Ⅱ)如图,以椭圆G 的长轴为直径作圆O ,过直线2-=x 上的动点T 作圆O 的两条切线,设切点分别为A ,B ,若直线AB 与椭圆G 交于不同的两点C ,D ,求CD AB 的取值范围. 解:(Ⅰ)设椭圆G 的标准方程为22 221x y a b +=(0a b >>), 将点)20 P ,和点21Q ? - ? ? , 代入,得 22 2 2 11 12a a b ?=??+=??,解得 2221 a b ?=??=??. 故椭圆G 的标准方程为2 212 x y +=. (Ⅱ)圆2 C 的标准方程为2 22 x y +=, 设()1 1 ,A x y ,()2 2 ,B x y , 则直线AT 的方程为1 1 2x x y y +=,直线BT 的方程为2 2 2x x y y +=, 再设直线2-=x 上的动点()2,T t -(t R ∈),由点()2,T t -在直线AT 和BT 上,得

设1s m =(1 04s <≤) ,则AB CD = 设()3 1632f s s s =+-,则()()2 269661160 f s s s '=-=-≥, 故()f s 在10,4 ?? ?? ? 上为增函数, 于是()f s 的值域为(]1,2,CD AB 的取值范围是(. 19.(本小题满分14分) 已知椭圆C : 22 22 1(0)x y a b a b +=>> 离心率2 e = ,短轴长为. (Ⅰ)求椭圆C 的标准方程; (Ⅱ) 如图,椭圆左顶点为A , 过原 点O 的直线(与坐标 轴不重合)与椭圆C 交于P ,Q 两点,直线PA ,QA 分别 与y 轴 交于M ,N 两点.试问以MN 为直径的圆是否经过 定点(与直线PQ 的斜率无关)?请证明你的结论.

新视野大学英语读写教程 第一册 课后习题答案

Unit 1 Section A V ocabulary I.1, rewarding 2, communicate 3, access 4, embarrassing 5, positive 6, commitment 7, virtual 8, benefits 9, minimum 10, opportunities. II.1, up 2, into 3, from 4, with 5, to 6, up 7, of 8, in 9, for 10, with. III.1-5: G B E I H 6-10: K M O E C Translation VIII. 1.Not only can students choose when and where to learn for an online course, but they can also tale time to think through answers before making a reply. 2.She is excited by the idea of online learning while he considers it meaningless and useless. https://www.doczj.com/doc/4c16865428.html,municating with native English speakers is a very rewarding experience from which we can learn a lot. 4.Today, more and more people have access to the Internet through which they look for the information they need. 5.He wants her to give up working and stay home to

《高级英语(第一册)》课后翻译习题及答案

Lesson 1 1) Little donkeys thread their way among the throngs of people. little donkeys went in and out among the people and from one side to another 2) Then as you penetrate deeper into the bazaar, the noise of the entrance fades away, and you come to the muted cloth-market. Then as you pass through a big crowd to go deeper into the market, the noise of the entrance gradually disappear, and you come to the much quieter cloth-market. 3) they narrow down their choice and begin the really serious business of beating the price down they drop some of items that they don't really want and begin to bargain seriously for a low price. 4) he will price the item high, and yield little in the bargaining He will ask for a high price for the item and refuse to cut down the price by any significant amount. 5) As you approach it, a tinkling and banging and clashing begins to impinge on your ear As you get near it, a variety of sounds begin to strike your ear. X.1)一条蜿蜒的小路淹没在树荫深处 A zig-zag path loses itself in the shadowy distance of the woods. 2)集市上有许多小摊子,出售的货物应有尽有 At the bazaar there are many stalls where goods of every conceivable kind are sold. 3) 我真不知道到底是什么事让他如此生气。 I really don't know what it is that has made him so angry. 4)新出土的铜花瓶造型优美,刻有精细、复杂的传统图案。 The newly unearthed bronze vase is pleasing in form and engraved with delicate and intricate traditional designs. 5)在山的那边是一望无际的大草原。 Beyond the mountains there is a vast grassland that extends as far as the eye can see. 6)他们决定买那座带有汽车房的房子。 They decided to buy that house with. a garage attached. 7)教师们坚持对学生严格要求。 The teachers make a point of being strict with the students. 8)这个小女孩非常喜欢他的父亲。 This little girl is very much attached to her father.

高中数学必修1课后习题答案完整版

高中数学必修1课后习题答案 第一章 集合与函数概念 1.1集合 1.1.1集合的含义与表示 练习(第5页) 1.用符号“∈”或“?”填空: (1)设A 为所有亚洲国家组成的集合,则:中国_______A ,美国_______A , 印度_______A ,英国_______A ; (2)若2 {|}A x x x ==,则1-_______A ; (3)若2{|60}B x x x =+-=,则3_______B ; (4)若{|110}C x N x =∈≤≤,则8_______C ,9.1_______C . 1.(1)中国∈A ,美国?A ,印度∈A ,英国?A ; 中国和印度是属于亚洲的国家,美国在北美洲,英国在欧洲. (2)1-?A 2 {|}{0,1}A x x x ===. (3)3?B 2 {|60}{3,2} B x x x =+-==-. (4)8∈ C ,9.1?C 9.1N ?. 2.试选择适当的方法表示下列集合: (1)由方程2 90x -=的所有实数根组成的集合; (2)由小于8的所有素数组成的集合; (3)一次函数3y x =+与26y x =-+的图象的交点组成的集合; (4)不等式453x -<的解集. 2.解:(1)因为方程2 90x -=的实数根为123,3x x =-=, 所以由方程2 90x -=的所有实数根组成的集合为{3,3}-; (2)因为小于8的素数为2,3,5,7, 所以由小于8的所有素数组成的集合为{2,3,5,7}; (3)由326y x y x =+??=-+?,得14x y =??=? , 即一次函数3y x =+与26y x =-+的图象的交点为(1,4),

相关主题
文本预览
相关文档 最新文档