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(完整)安徽普高专升本统考《高等数学》试题答案解析

(完整)安徽普高专升本统考《高等数学》试题答案解析
(完整)安徽普高专升本统考《高等数学》试题答案解析

安徽省2012年普通高等学校专升本招生考试

高等数学

注意事项:

1.试卷共8页,请用签字笔答题,答案按要求写在指定的位置。 2.答题前将密封线内的项目填写完整。

一、选择题(下列每小题的选项中,只有一项是符合题意的,请将表示该选项的字母填在题后的括号内。共10小题,每小题3分,共30分)

1.若函数???

??>+≤=0,sin 0,3)(x a x

x x e x f x 在0=x 在处连续,则=a ( C )

A. 0

B. 1

C. 2

D. 3

解:由)0()00()00(f f f =-=+得231=?=+a a ,故选C. 2.当0→x 时,与函数2

)(x x f =是等价无穷小的是( A ) A. )1ln(2

x + B. x sin C.

x tan D. x cos 1-

解:由11ln(lim 1ln()(lim )

22

0)20=+=+→→x x x x f x x ,故选A.

3.设)(x f y =可导,则'-)]([x e f =( D )

A. )(x

e

f -' B. )(x e f -'- C. )(x x e f e --' D. )(x x e f e --'-

解:)()()()]([x

x x x x

e f e e e f e f -----'-='?'='

,故选D. 4.设

x 1是)(x f

的一个原函数,则?=dx x f x )(3

( B ) A.

C x +2

2

1 B. C x +-221 C. C x +331 D. C x x +ln 414

解:因x 1是)(x f

的一个原函数,所以211)(x x x f -='

???

??=,所以

C x xdx dx x f x +-=-=??23

2

1)(故选B. 5.下列级数中收敛的是( C )

A. ∑∞

=-1

374n n

n n B. ∑

=-1

2

31

n n C.

∑∞

=13

2

n n

n D. ∑∞

=1

21

sin n n

解:因121

)1(lim 212

2)1(lim 33313

<=+=+∞→+∞→n n n n n n n n ,所以∑∞=132n n n 收敛,

故选C. 6.交换?

???+=

10

2121

1

21),(),(y y

y

dx y x f dy dx y x f dy I 的积分次序,则下列各项正确的是( B )

A. ??

1

22

),(x x dy y x f dx B.

??

10

22

),(x x

dy y x f dy C.

?

?2

1

22

),(x x dy y x f dx D.

?

?

2

1

22

),(x x dy y x f dx

解:由题意画出积分区域如图:故选B.

7.设向量21,αα是非齐次线性方程组AX =b 的两个解,则下列向量中仍为该方程组解的是( D ) A. 21αα+ B. 21αα- C. 212αα+ D. 212αα- 解:因,2)(2121b b b A A A =+=+=+αααα同理得

,0)(21=-ααA ,3)2(21b A =+αα,)2(21b A =-αα

故选D.

8.已知向量)2,5,4,0(),0,,0,2(),1,1,2,1(321--==-=αααk 线性相关,则=k ( D ) A. -2 B. 2 C. -3 D. 3

解:????? ??+--+--→????? ??---+--→????? ?

?---=????? ??03002240112125402240112

12540002112132

1k k k k ααα 由于123,,ααα线性相关,所以123(,,)2r ααα≤,因此3=k

9.设B A ,为事件,且,2.0)(,4.0)(,6.0)(===AB P B P A P 则=)(B A P ( A ) A.0.2 B. 0. 4 C. 0.6 D. 0.8

解: 2.0)]()()([1)(1)()(=-+-=+-=+=AB P B P A P B A P B A P B A P

10.有两个口袋,甲袋中有3个白球和1个黑球,乙袋中有1个白球和3个黑球.现从甲袋中任取一个球放入乙袋,再从乙袋中任取一个球,则取出白球的概率是( B ) A.

163 B. 207 C. 41 D. 2

1 解: 由全概率公式得20

7

51415243=?+?=

p

二、填空题(本题共10小题,每小题3分,共30分,把答案填在题中横线上。)

11.设函数2161

31arcsin

x

x y --

-=,则函数的定义域为)4,2[-. 解:424442016,131

12<≤-??

??<<-≤≤-?>-≤-≤-x x x x x .

12.设曲线22-+=x x y 在点M 处的切线斜率为3,则点M 的坐标是)0,1(. 解:12+='x y ,由1312=?=+='x x y ,从而0=y ,故填)0,1(.

13.设函数x x y arctan =,则=

''y 2

2)

1(2

x +. 解:2

1arctan x x x y ++=',222

2222)1(2

)1(2111x x x x x y +=+-+++=''. 14.

=+?dx x

x 2012)1(ln

C x ++2013)1(ln 2013

. 解:

C x x d x dx x x ++=++=+??

2013

)1(ln )1(ln )1(ln )1(ln 20132012

2012. 15.=?∞++-dx xe x 01= e . 解:

e dx xe e dx xe

x x ==?

?

+∞-∞++-0

1

.

16.幂级数∑∞

=-15

)2(n n

n

n x 的收敛域为)7,3[-.

解:由152215lim 5)2(15)2(lim )()(lim 11

1<-=-+=-+-=∞→++∞→+∞→x x n n n

x n x x u x u n n n n n n n

n n .

得73<<-x 级数收敛,

当3-=x 时,级数为∑∞

=-1

)1(n n

n 收敛; 当7=x 时,级数为∑∞

=11n n 发散;

故收敛域为)7,3[-.

17.设A 是n 阶矩阵,E 是n 阶单位矩阵,且,032=--E A A 则=--1

)2(E A E A +.

解:)()

2())(2(031

2

E A E A E E A E A E A A +=-?=+-?=---

18.设????

?

??-=10010

1110A ,记1

-A 表示A 的逆矩阵, *A 表示A 的伴随矩阵,则 =-*

1)(A ????

?

??----100101110.

19.设型随机变量),8,1(~N X 且),()(c X P c X P ≥=<则c = 1.

解:由正态分布的对称性得1==μc .

20.设型随机变量X 在区间]4,2[上服从均匀分布,则方差=

)(X D 3

1

.

解:直接由均匀分布得3

1

12)24()(2=-=X D .

三、计算题:本大题共8小题,其中第21-27题每题7分,第28题11分,共60分。

21.计算极限x x

x x 20tan sin lim

-→.

解:原式= 20sin lim x

x

x x -→ =x

x

x 2cos 1lim

0-→

=2

sin lim 0x

x →=0.

22.求由方程xy y x =确定的隐函数的导数dx

dy

. 解:两边取对数得y x y x ln ln ln +=, 两边求导得y y

x y y x y '+='+

11ln , 从而)

1()

ln 1(--=

x x y x y dx dy .

23.计算定积分

?

-22

2

2

1

1dx x x

解:令t x sec =,则,tan sec tdt t dx =当2=x 时, 4

π

=

t ;当2=x 时, 3

π

=

t .

所以原式= ?3

4

2

tan sec tan sec π

πdt t t t

t = ?34

cos π

πtdt = =|34

sin π

πt =

)23(2

1

-.

24.求微分方程02=--'x e y y 的通解.

解:原方程可整理为x

e y y =-'2

这是一阶线性微分方程,其中x

e x Q x P =-=)(,2)(. 所以原方程的通解为

??

????+??=?-C dx e x Q e y dx x P dx x P )()()( )(22C dx e e e dx

x dx

+??

=?-.

)(2C dx e e x x +=?-)(2C e e x x +-=-

x x Ce e 2+-=

25.计算二重积分

??D

yd x σ2,其中D 是由直线222===xy x y x 和、所围成的区域. 解:区域D 如图阴影部分所示.

??

D

yd x σ2

??=x

x

y y x x 22221

d d ?=

2

12222

d 2

1|

y y x x

x

?-=

214

)d 44(2

1x x |215

)252(x x -=5

210=.

26.设矩阵????

?

??---=320031

10

1A ,,231?????

??=B 且满足X B A B AX +=+2

,求矩阵X .

解:由X B A B AX +=+2可得B E A E A B E A X E A ))(()()(2+-=-=-

因024

2

041

100||≠-=---=-E A ,所以E A -可逆, 因此B E A X )(+=????? ???????

?

?---=23122

0021

102????

?

??-=250

27.设行列式132

1

31213

2

113211)(++++=

x x x x x D ,求)(x D 在0=x 处的导数.

解:132731273

21732171321

31213

2113211)(+++++++=

++++=

x x x x x x x x x x x x D

2

11

10

1110

10001)

7(1

32

1

31213

2

113211)

7(--+=++++=x x x x x x x x

)23)(7()2)(1)(7(22+-+=--+=x x x x x x x x .

故)32)(7()23)(72()(22-+++-+='x x x x x x x D . 从而14)0(='D .

28.已知离散型随机变量X 的密度函数为?????

????≥<≤<≤<=.2,1,21,

21,10,,0,0)(x

x x a x x F 且数学期望34)(=X E .

求: (1) a 的值; (2) X 的分布列;(3)方差D (X ).

解:(1) 由分布函数的性质知,随机变量X 的可能取值为0、1、2,且

2

1)2(,21)1(,)0(==-=

===X P a X P a X P

图5-7

因3

423212)21(10)(=-=?+-?+?=a a a X E 所以6

1

=

a . (2) 由(1)即得

(3) 3

223160)(2

222=?+?+?=X E ,

四、证明题与应用题:本大题

共3小题,每小题10分,共30分。

29.设)(2y

x f xy u =,其中)(t f 可微,u y

z

y x z x

3:=??+??证明. 证明:因为

y

y x f xy y x f y x u 1

)()(22?'+=?? ),()(2

y

x f xy y x

f y '+=

???

? ??-?'+=??22)()(2y x y x f xy y x xyf y u )()(22y

x f x y x xyf '-=,

故)()(2)()(2222y

x

f y x y x f xy y x f y x y x f xy y u y x u x

'-+'+=??+?? )(32

y

x

f xy =u 3=. ????(9分)

30.设D 是由曲线e x x y ==,ln 及x 轴所围成的的平面区域

求: (1) 平面区域D 的面积S ; (2) D 绕y 轴旋转一周所成的旋转体的体积V . 解:区域D 如图阴影部分所示。曲线x y ln =与x 轴及 e x =的交点坐标分别为)1,(),0,1(e (1)平面区域D 的面积

1)ln (d ln |1

1

=-==?e

e x x x x x S .

(2)D 绕y 轴旋转一周所成的旋转体的体积V

).

1(2

2

d d )(121

221

221

22

|+=

-

==-=-??=??e e e y e e y

e e V y y y π

π

πππππ

31.证明不等式:当e b a >>时,

)71828.2(ln ln ≈<

a a

b a b . 证明: 设),(,ln )(+∞∈=e x x x x f ,则),(,0ln 1)(+∞∈>+='e x x x f , 所以),(ln )(+∞∈=e x x x x f 在上单调递增,从而当当e b a >>时,有

)()(b f a f >,即b b a a ln ln >,即

b

a

a b

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安徽省普通高等学校专升本考试2012年真题 注意事项: 1.试卷共8页,请用黑色签字笔答题,答案写在答题纸上,写在试卷上无效。 2.答题前请将答题纸上密封线内的项目填写完整。 PartI Vocabulary and Structure(1 point each;30 point in all) Directions:There are 30 incomplete sentences. You are required to complete each one by deciding on the most appropriate word or words from the four choices marked A,B,C and D,and then write the write the corresponding letter on the Answer sheet. 1.—Hello, ____ Kate? —Yes, speaking. A. is this B. is that C. are you D. is it 2. By the time I got home, my mother ____ to bed. A. went B. was getting C. had gone D. has gone 3 ____ everything ____ ,it was not a bad holiday. A. brining--into effects B. learning--by heart C. petting--into practice D. taking--into account 4. When waiting at a bus stop for a long time, most people often look ____ and asleep. A. bored B. surprised C. excited D. amused 5. ____ the effective method , I answered all the questions correctly. A. Thanks to B. In case of C. As well as D.Apart from 6. If you are like most people , your intelligence ____ from season to season. A. turns B. change C. varies D. ranges 7. No cream hot me, thanks. I am ____ a diet. A. in B. on C. from D. off 8. ____ really worries George is that his parents expect too much of him. A. What B. This C. Whichever D. It 9.Mary loves Jazz, and she has played ____ for years. A. piano B. a piano C. one piano D. the piano 10.Ted made up has mind soon and accepted the invitation ____ . A. without hesitation B. without doubt C.without understanding D. without exception 11.It is good manners ____ help to others when they are in need. A. to obtain B. obtaining C. to offer D. offering 12. ____ you've grown your favorite flowers, the following job is to take care. A. Although B. Before C. While D. 13. Huangshan Mountain is really a magnificent place for an enjoyable and ____ vacation. A.dull B. annual C. relaxing D. noisy https://www.doczj.com/doc/dc7593114.html,ura ____ her parents travel abroad once a year. A. and B. together with C. as well as D. accompanied by 15.—Who broke the window ? —Not me—It must have been ____ else.

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