河北省衡水中学2020届高三英语试题(有答案)
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专题11 语言文字综合运用一(2020届安徽省芜湖市师大附中高三)阅读下面的文字,完成各题。
一提起中国古代的科学发明,人们马上就会想到四大发明——造纸术、印刷术、指南针和火药。
这四大发明无疑极其是伟大的,它们对世界文明的发展曾经有产生过巨大的影响。
但是,我们也应看到,四大发明只是中国科技文化史上很小的一部分。
纵观中国几千年的科技文化史,我们可以自豪地说,中国古代的科学技术成就是极其辉煌的。
英国科学史家贝尔纳说,中国“许多世纪以来,一直是人类文明和科学的巨大中心之一”。
英国著名的中国科技史家李约瑟也指出:“中国在公元3世纪到13世纪之间保持一个西方的科学知识水平。
”单就古代数学而言,古希腊欧几里得的几何学可说是;但是,对于中国古代数学的成就,人们却知之甚少。
其实,中国古代数学以擅长计算,并逐步形成了自具特色的体系。
();这个体系的特点是以解决社会实际问题为主要目的,以算筹为主要计算工具,以十进位值制的计数系统进行运算,其内容包括算术、代数、几何等各个方面。
在自身的发展历程中,它逐步走向高峰,呈现着的局势,结下累累硕果。
17.依次填入文中横线上的词语,全都恰当的一项是()A.望尘莫及家喻户晓著称于世久盛不衰B.望其项背家喻户晓著称于世名噪一时C.望其项背耳熟能详闻名遐迩久盛不衰D.望尘莫及耳熟能详闻名遐迩名噪一时18.下列填入文中括号内的语句,衔接最恰当的一项是()A.成书于公元1世纪中叶的《九章算术》是这个体系形成的重要标志B.《九章算术》成书于公元1世纪中叶,是这个体系形成的重要呢标志C.这个体系形成的重要标志是成书于公元1世纪中叶的《九章算术》D.这个体系形成的重要标志是《九章算术》,它成书于公元1世纪中叶19.文中画横线的句子有语病,下列修改最恰当的一项是()A.这四大发明无疑极其是伟大的,它们对世界文明的发展曾经有过巨大的影响。
B.这四大发明无疑是极其伟大的,它们对世界文明的发展曾经有过巨大的影响。
河北省衡水中学2020届高三物理上学期期中试题本试卷分第I卷(选择题)和第II卷(非选择)两部分。
共110分。
考试时间110分钟。
第I卷(选择题共60分)注意事项:l.答卷I前,考生务必将自己的姓名、考证号、考试科目用铅笔涂写在答题卡上。
2.答卷I时,每小题选出答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其它答案。
一、选择题(每小题分,共60分。
下列每小题给选项至少有一项符合题意,将正确答案的序号填涂在答题卡上,全部选对的得4分,有漏选的得2分,有错选的得0分)1.如图所示,离水平地面一定高处水平固定一内壁光滑的圆筒,筒内固定一轻质弹簧,弹簧处于自然长度。
现将一小球从地面以某一初速度斜向上抛出,刚好能水平进入圆筒中,不计空气阻力。
下列说法中错误的是A.弹簧获得的最大弹性势能小于小球抛出时的动能B.小球斜上抛运动过程中处于失重状态C.小球压缩弹簧的过程中,小球减小的动能等于弹簧增加的势能D.若抛射点向右移动一小段距离,仍使小球水平进入圆筒中,可以增大抛射速度v0,同时增大抛射角θ2.甲、乙两个质点沿同一线运动,其中质点甲以6m/s的速度匀速直线运动,质点乙作初速度为零的匀变速直线运动,它们的位置x随时间t的变化如图所示。
己知t=3s时,甲、乙图线的斜率相等。
下列判断正确的是A.最初的一段时间内,甲、乙的运动方向相反B.t=3s时,乙的位置坐标为-9mC.乙经过原点时的速度大小为25m/sD.t=10s时,两车相遇3.如图所示,倾角为θ的斜面体c置于水平地面上,物块b置于斜面上,通过跨过光滑定滑轮的细绳与小盒a连接,连接b的一段细绳与斜面平行,连接a的一段细绳竖直,a连接在竖直固定在地面的弹簧上。
现向盒内缓慢加入适量砂粒,a、b、c始终处于静止状态。
下列判断正确的是A.c对b的摩擦力可能减小B.地面对c的支持力可能增大C.地面对c的摩擦力可能不变D.弹簧的弹力可能大4.如图所示,物块A、B静止叠放在水平地面上,B受到大小从零开始逐渐增大的水平拉力F 作用。
专题36 运用裂项相消法求和把数列的通项拆成两项之差,在求和时中间的一些项可以相互抵消,从而求得前n 项和.常见的裂项技巧①1n (n +1)=1n -1n +1. ②1n (n +2)=12⎝⎛⎭⎫1n -1n +2.③1(2n -1)(2n +1)=12⎝⎛⎭⎫12n -1-12n +1. ④1n +n +1=n +1-n .⑤1n (n +1)(n +2)=12⎝⎛⎭⎫1n (n +1)-1(n +1)(n +2).一、题型选讲例1、(2020届山东省九校高三上学期联考)已知数列{}1n a +是等比数列,11a =且2a ,32a +,4a 成等差数列.(1)求数列的通项公式; (2)设11n nn n n a a b a a ++-=,求数列的前n 项和n S .例2、(华南师大附中2021届高三综合测试)在①;②63,371==S a ;③n n S n 22+=,这三个条件中任选一个,补充在下面问题中,然后解答补充完整的题目. 已知S n 为等差数列}{n a 的前n 项和,若 . (1)求a n ; (2)令*)(112N n a b n n ∈-=,求数列}{n b 的前n 项和T n .注:如果选择多个条件分别解答,按第一个解答计分.例3、(江苏盐城中学2021届高三年级第三阶段检测数学试题)已知数列的前n 项和n S 满足2(2,)n n =≥∈N ,且14a =.(1)求数列的前n 项和n S 及通项公式n a ; (2) 记,n T 为的前n 项和,求n T .例4、(2020届山东省德州市高三上期末)已知数列的前n 项和为n S ,且0n a >,242n n n S a a =+.(1)求数列的通项公式; (2)若11nn n S S b S S -=⋅,求数列的前n 项和n T .例5、(2020届山东省滨州市三校高三上学期联考)已知数列的前n 项和n S满足2(2,)n n =≥∈N ,且14a =.(1)求数列的前n 项和n S ,及通项公式n a ; (2)记,n T 为的前n 项和,求n T .例6、(2020届山东省潍坊市高三上期末)已知各项均不相等的等差数列{}n a 的前4项和为10,且124,,a a a 是等比数列的前3项.(1)求,n n a b ; (2)设()11n n n n c b a a =++,求的前n 项和n S .例7、(2020届山东省泰安市高三上期末)已知等差数列的前n 项和为. (1)求的通项公式; (2)数列满足141n n n b T S =-,为数列的前n 项和,是否存在正整数m ,,使得?若存在,求出m ,k 的值;若不存在,请说明理由.例8、【2020届河北省衡水中学全国高三期末大联考】在数列中,有. (1)证明:数列为等差数列,并求其通项公式; (2)记,求数列的前n 项和.n T二、达标训练1、【2020届中原金科大联考高三4月质量检测】已知数列{a n }的前n 项和为S n ,且a n >0,4S n =a n 2+2a n .(1)求数列{a n }的通项公式; (2)若b n =S 1−S n S n ⋅S 1,求数列{b n }的前n 项和T n .2、(2020届山东省临沂市高三上期末)设,向量(31,3)AB n =+,(0,32)BC n =-,. (1)试问数列{}1n n a a +-是否为等差数列?为什么? (2)求数列的前n 项和n S .3、(2020届山东省济宁市高三上期末)已知等差数列满足246a a +=,前7项和728S =. (1)求数列的通项公式;(2)设()()122121n n n n a a b +=++,求数列的前n 项和n T .4、(2020届浙江省温州市高三4月二模)已知等差数列和等比数列满足: (I )求数列{}n a 和的通项公式; (II )求数列的前n 项和n S .5、(南通市2021届高三年级期中学情检测)等比数列{}n a 的前n 项和为成等差数列,且2341216a a a ++=. (1)求数列{}n a 的通项公式; (2)若2(2)log n an b n =-+,求数列1{}nb 的前n 项和n T .6、(金陵中学2021届高三年级学情调研测试(一))已知数列{a n }中,a 1=1,当n ≥2时,其前n 项和S n 满足S n 2=a n (S n -12).(1)求S n 的表达式;(2)设b n =S n2n +1,求数列{b n }的前n 项和T n .。
【衡水金卷】河北省衡水中学2020届高考模拟押题卷(一)理科综合能力测试注意事项:1.本试卷分第I卷(选择题)和第Ⅱ卷(非选择题)两部分。
答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答第I卷时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
写在本试卷上无效。
3.回答第Ⅱ卷时,将答案写在答题卡上。
写在本试卷上无效。
4.考试结束后,将本试卷和答题卡一并交回。
可能用到的相对原子质量:H1C12N14O16Si28Fe56第I卷一、选择题:本题共13小题,每小题6分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1.下列关于细胞中某些物质的叙述,错误的是A.组成纤维素、淀粉、糖原的单体是相同的B.RNA可以在细胞核或某些细胞器中合成C.抗体的形成与分泌需要ATP直接提供能量D.激素和神经递质的合成是在核糖体上进行的2.甲乙两种物质在胰岛B细胞内、外的浓度情况如图所示,下列相关叙述正确的是A.甲可以是Na+,胰岛B细胞兴奋时Na+内流会导致细胞内Na+浓度高于细胞外B.甲可以是氧气,其进入细胞后可以在细胞质基质或线粒体参与相关反应C.乙可以是DNA,其运出细胞后可将遗传信息传递给其他细胞D.乙可以是胰岛素,其运出细胞时不需要载体的协助3.如图表示生物体内遗传信息的传递和表达过程,下列叙述不正确的是A.上述过程均需要模板、酶、能量和原料,并且均遵循碱基互补配对原则B.在神经细胞和甲状腺细胞中均能进行2过程,并且形成的RNA也相同C.过程3中涉及到5种碱基和8种核苷酸D.RNA发生改变,通过5过程形成的蛋白质不一定发生改变4.下列关于植物激素、植物生长调节剂的叙述中,不合理的是A.植物激素不直接参与细胞代谢,只传递调节代谢的信息B.用一定浓度的赤霉素处理种子可以促进其萌发C.给去掉尖端的胚芽鞘放置含生长素的琼脂块后仍能生长,说明生长素可促进生长D.生长素和细胞分裂素在促进植株生长方面存在协同关系5.下图是某家族甲病(A-a)和乙病(B-b)的遗传系谱图。
第一编专题一考点4A(2019·天津卷,D) Would you BET on the future of this man?He is 53 years old.Most of his adult life has been a losing struggle against debt and misfortune.A war injury has made his left hand stop functioning,and he has often been in prison.Driven by heaven-knows-what motives,he determines to write a book.The book turns out to be one that has appealed to the world for more than 350 years.That former prisoner was Cervantes,and the book was Don Quixote(《堂吉诃德》).And the story poses an interesting question:why do some people discover new vitality and creativity to the end of their days,while others go to seed long before?We've all known people who run_out_of_steam before they reach life's halfway mark.I'm not talking about those who fail to get to the top.We can't all get there.I'm talking about people who have stopped learning on growing because they have adopted the fixed attitudes and opinions that all too often come with passing years.Most of us,in fact,progressively narrow the variety of our lives.We succeed in our field of specialization and then become trapped in it.Nothing surprises us.We lose our sense of wonder.But,if we are willing to learn,the opportunities are everywhere.The things we learn in maturity seldom involve information and skills.We learn to bear with the things we can't change.We learn to avoid self-pity.We learn that however much we try to please,some people are never going to love us—an idea that troubles at first but is eventually relaxing.With high motivation and enthusiasm,we can keep on learning.Then we will know how important it is to have meaning in our life.However,we can achieve meaning only if we have made a commitment to something larger than our own little egos(自我),whether to loved ones,to fellow humans,to work,or to some moral concept.Many of us equate(视……等同于) “commitment” with such “caring” occupations as teaching and nursing.But doing any ordinary job as well as one can is in itself an admirable commitment.People who work toward such excellence—whether they are driving a truck,or running a store—make the world better just by being the kind of people they are.They've learned life's most valuable lesson.文章大意:主题:人与自我(做人与做事);话题:过有意义的成年人生活。
河北省衡水中学2020届高三下学期一调试题一、选择题1.如图所示,一固定的细直杆与水平面的夹角为α=15°,一个质量忽略不计的小轻环C 套在直杆上,一根轻质细线的两端分别固定于直杆上的A 、B 两点,细线依次穿过小环甲、小轻环C 和小环乙,且小环甲和小环乙分居在小轻环C 的两侧.调节A 、B 间细线的长度,当系统处于静止状态时β=45°.不计一切摩擦.设小环甲的质量为m 1,小环乙的质量为m 2,则m 1∶m 2等于( )A. tan 15°B. tan 30°C. tan 60°D. tan 75°【答案】C【解析】 试题分析:小球C 为轻环,重力不计,受两边细线的拉力的合力与杆垂直,C 环与乙环的连线与竖直方向的夹角为600,C 环与甲环的连线与竖直方向的夹角为300,A 点与甲环的连线与竖直方向的夹角为300,乙环与B 点的连线与竖直方向的夹角为600,根据平衡条件,对甲环:,对乙环有:,得,故选C . 【名师点睛】小球C 为轻环,受两边细线的拉力的合力与杆垂直,可以根据平衡条件得到A 段与竖直方向的夹角,然后分别对甲环和乙环进行受力分析,根据平衡条件并结合力的合成和分解列式求解.考点:共点力的平衡条件的应用、弹力.2.在平直公路上行驶的a 车和b 车,其位移--时间图象分别为图中直线a 和曲线b ,已知b 车的加速度恒定且等于22m /s 3s t -=,时,直线a 和曲线b 刚好相切,则( )A. a 车做匀速运动且其速度为8m /s 3a v = B. 0t =时,a 车和b 车的距离09m x =C. 3s t =时,a 车和b 车相遇,但此时速度不等D. 1s t =时,b 车的速度为10m/s【答案】B【解析】【详解】A .a 车图像是倾斜直线,所以该车作匀速直线运动,该车速度为822m/s 3x v t ∆-===∆ 故A 错误;C .3t s =时,直线a 和曲线b 刚好相切,则b 车此时速度为2m/s ,故C 错误; B .由0v v at =+得,b 车的初速度为()02238m/s v v at =-=--⨯=b 车在第一秒内位移为2201181217m 22x v t at =+=⨯-⨯⨯= 则0t =时,a 车和b 车的距离0729m x =+=故B 正确;D .1s t =时,b 车的速度为8216m/s v =-⨯=,故D 错误。
专题05 语法填空新高考八省最新名校联考试题汇编(原卷版)1.【2023届河北省衡水中学高三上学期四调】阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。
Anyone who has an interest in Dunhuang will have heard of Fan Jinshi. The Chinese archaeologist ___36___ has spent more than half a century researching and preserving the caves at the heart of the ancient Silk Road in Gansu Province ___37___(know) as the “Daughter of Dunhuang” in her field, though “protector” is probably a more fitting ___38___(describe).Fan has been studying the historical site since the early 1960s, first as an archaeology undergraduate from Peking University, then as a conservationist when she ___39___(become) the deputy director of the Dunhuang Research Academy in 1984, which serves to prevent the ancient site ___40___ being destroyed.“It is over a thousand years old. It is an old person, an ___41___(extreme) weak old person. It has___42___(variety) illnesses. If you are a little careless, it could be gone. Gone forever,” Fan says.Today, thanks to the work of great ___43___(archaeologist) such as Fan, Dunhuang is proud of the world’s largest and best-preserved collection of Buddhist relics ___44___(date) from the 15th to the 13th centuries. The main Mogao site is made up of 735 caves spread across a 1,700-metre-wide cliff face, containing 45,000 square metres of murals(壁画) ____45____ more than 2,000 colourful sculptures.2.【2023届吉林省长春吉大附中实验学校高三上学期模拟考试试题】阅读下面短文,在空白处填入1个恰当的单词或括号内单词的正确形式。
第9讲 三角函数中的范围最值问题题型一 与三角函数对称性相关的最值范围问题【例1】若将函数()sin2cos2f x x x =+的图象向左平移ϕ(0ϕ>)个单位,所得的图象关于y 轴对称,则ϕ的最小值是( ) A.4πB.38π C.8πD.58π【答案】C 【玩转跟踪】1、【广州市2020届高三第一学期第一次调研】将函数2sin cos 33y x x ππ⎛⎫⎛⎫=++ ⎪ ⎪⎝⎭⎝⎭的图象向左平移()0ϕϕ>个单位,所得图象对应的函数恰为奇函数,则ϕ的最小值为 A.12π B. 6π C. 4π D. 3π【答案】B【解析】将函数2sin 23y x π⎛⎫=+ ⎪⎝⎭的图象向左平移()0ϕϕ>个单位,所得图象对应的函数:()2sin 23y x πϕ⎡⎤=++⎢⎥⎣⎦,又其为奇函数,∴2sin 203πϕ⎛⎫+= ⎪⎝⎭, ()22k πZ 3k πϕ+=∈,, k π23πϕ=-,()Z k ∈,又0ϕ>当k 1=时, ϕ的最小值为6π,故选:B2、【河南省2020届高三12月联考】若函数()2sin 23f x x π⎛⎫=+ ⎪⎝⎭关于直线x m =(0m <)对称,则m 的最大值为( ) A.4π-B.1112π-C.512π-D.712π-【答案】C【解析】由题意得, ()232m k k Z πππ+=+∈,即()212k m k Z ππ=+∈, 0m <, 1k ∴=-时, m 的最大值为512π-.3、【2020河南省林州市第一中学模拟】定义运算12142334a a a a a a a a =-,将函数()sin (0)cos wxf x w wx=>的图象向左平移23π个单位长度,所得图象对应的函数为偶函数,则w 的最小值是( ) A.14 B. 54 C. 74 D. 34【答案】B4.【2020届湖北省重点中学高三上学期第三次月考】已知函数.(1)若函数)(x f y =的图像关于直线对称,求a 的最小值;(2)若存在使成立,求实数m 的取值范围. 分析:(1)先利用降幂公式进行化简,然后利用辅助角公式将)(x f 化为)32sin(2)(π+=x x f ,最后根据正弦函数的对称性求出对称轴,求出a 的最小值即可; (2) 根据的范围求出320π+x 的范围,再结合正弦函数单调性求出函数f (x 0)的值域,从而可求出m =的取值范围. 答案(1)12π(2)(][)+∞⋃-∞-,12,题型二 与三角函数的单调性相关的最值问题【例2】已知0ω>, ()sin 4f x x πω⎛⎫=+⎪⎝⎭在2ππ⎛⎫⎪⎝⎭,上单调递减,则ω的取值范围是( ) A.15[ 24⎤⎥⎦, B. 13[ 24⎤⎥⎦, C. 102⎛⎫⎪⎝⎭, D. ](0 2, 【答案】A 【玩转跟踪】2()[2sin()sin ]cos 3f x x x x x π=++(0)x a a =>05[0,],12x π∈0()20mf x -=05[0,],12x π∈00021()20()sin(23mf x m f x x π-=⇒==+1、【皖江名校2020届高三12月份大联考】若函数的图象在区间上只有一个极值点,则的取值范围为( )A.B.C. D. 【答案】B【解析】结合题意,函数唯一的极值点只能是,所以有 得。
绝密★启用前河北衡水中学2020届全国高三第一次联合考试物理命题单位:河北衡水中学天舟教科院本试卷8页。
满分110分。
考试时间90分钟。
注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上相应的位置。
2.全部答案在答题卡上完成,答在本试卷上无效。
3.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案用0.5mm黑色笔迹签字笔写在答题卡上。
4.考试结束后,将本试卷和答题卡一并交回。
一、单项选择题:本题共6小题,每小题5分,共30分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1.如图所示,小明和弟弟在练习滑雪,他俩从斜坡雪面滑到水平雪面时速度相同,且弟弟在前、小明在后,此时他俩收起滑雪杖向前自由滑行。
已知小明及其装备的总质量大于弟弟及其装备的总质量,他俩的滑雪板与雪面之间的动摩擦因数相同。
若不考虑空气阻力,则两人A.一定相碰B.一定不相碰C.不一定相碰D.无法确定2.高空走钢丝杂技表演中,表演者越接近钢丝末端的时候,钢丝倾斜得越厉害,行走难度也越大,行走也越缓慢。
如图所示是两个人同走一根钢丝的示意图(其位置如图所示),假设两人及其装备的总质量相等,下列说法正确的是A.钢丝对甲的作用力小于对乙的作用力B.甲受到的合外力小于乙受到的合外力C.甲对钢丝的压力大于乙对钢丝的压力D.钢丝对甲的摩擦力大于对乙的摩擦力3.如图所示,在一次冰壶比赛中,冰壶(可看作质点)被释放后,在水平面上做匀减速直线运动,依次经过a 、b 、c 三点,到达c 点时冰壶恰好停止。
已知a 、b 间的距离是b 、c 间距离的3倍。
不计空气阻力,下列说法正确的是A.冰壶通过ab 段所用时间小于通过bc 段所用时间B.冰壶在ab 段所受摩擦力的冲量等于在bc 段所受摩擦力的冲量C.冰壶在ab 段的动量变化量大于在bc 段的动量变化量D.冰壶在ab 段的动能变化量等于在bc 段的动能变化量4.如图所示,abcd 是一个用粗细均匀、同种材料的导线弯折成的长方形线框,线框竖直放置,ab 长度为L ,bc 长度为2L 。
衡水中学高三英语试卷 第I卷(选择题 满分90分) 第一部分 听力(共两节,满分20分) 第一节 (共5小题;每小题1分,满分5分) 听下面5段对话。每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 1.How did Sarah get home last night? A. By train B. By bus C. By car 2. When is the woman getting married? A. In October B. In November C. In December 3. Who is the woman? A. A new worker B. A regular C. A shop manager 4. Where is Mary? A. In the manager’s office B. In the meeting room C. In her office 5. What book did the woman buy? A. Cooking B. History C. Traveling 第二节 听下面5段对话或独白。每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。每段对话或独白读两遍。 听第6段材料,回答第6、7题。 6. Where are the speakers? A. At the man’s home B. At a shop C. In a car 7. What has the woman forgotten to bring with her? A. Her bag B. Some money C. A map 听第7段材料,回答第8、9题。 8.What happened to thy boy in the basketball match? A. He injured his leg B. He quit the match halfway C. He failed to score the key ball 9. What was the boy disappointed at? A. The result of the match B. His performance in the match C. His teammates’ behavior after the match 听第8段材料,回答第10至12题。 10. What does the woman think of the marathon training? A. Fun B. Hard C. Boring 11. What makes the woman feel uncomfortable? A. Running with the man at the college B. Exercising in front of other people C. Attending classes with the man 12. When will the speakers take exercise? A. In the evening B. In the afternoon C. In the morning 听第9段材料,回答第13至16题。 13. What are the speakers talking about? A. How to take notes B. How to prepare for a lecture C. How to catch the lecturers’ words 14. What does the woman suggest the man do? A. Go to the classroom a bit early B. Sit together with his classmates C. Get a seat at the back 15. What will the man do if he misses an important point? A. Write down a question B. Manage to get it later C. Ask other listeners at once 16. How does the man make his listening and note-taking more efficient? A. By doing revision before the lecture B. By paying attention to key words C. By just writing down the main points 听第10段材料,回答第17至20题。 17. Who is the speaker? A. A guide B. An officer C. An announcer 18. How long can a British man stay in Guatemala on a visa? A. Up to 10 days B. Up to 30 days C. Up to 40 days 19. Who can get a tourist card for Guatemala? A. British passport holders B. French passport holders C. Irish passport holders 20. Which place is the best choice for children under five? A. Ireland B. Guatemala C. Spain 第二部分 阅读理解(共25小题;每小题2分,满分50分) 第一节 (共20小题;每小题2分,满分40分) 阅读下列四篇短文,从每题后所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。 A Samuel Osmond is a 19-year-old law student from Cornwall, England. He never studied the piano. However, he can play very difficult musical pieces by musicians such as Chopin and Beethoven just a few minutes after he hears them. He learns a piece of music by listening to it in parts. Then he thinks about the notes in his head. Two years ago, he played his first piece Moonlight Sonata(奏鸣曲)by Beethoven. He surprised everyone around him. Amazed that he remembered this long and difficult piece of music and played it perfectly, his teachers say Samuel is unbelievable .They say his ability is very rare, but Samuel doesn’t even realize that what he can do is special. Samuel wanted to become a lawyer as it was the wish of his parents, but music teachers told him he should study music instead. Now, he studies law and music. Samuel can’t understand why everyone is so surprised. “I grew up with music. My mother played the piano and my father played the guitar. About two years ago, I suddenly decided to start playing the piano, without being able to read music and without having any lessons. It comes easily to me ---I hear the notes and can bear them in mind---each and every note,” says Samuel. Recently, Samuel performed a piece during a special event at his college. The piece had more than a thousand notes. The audience was impressed by his amazing performance. He is now learning a piece that is so difficult that many professional pianists can’t play it. Samuel says confidently,” It’s all about super memory---I guess I have that gift.” However, Samuel’s ability to remember things doesn’t stop with music. His family says that even when he was a young boy, Samuel heard someone read a story, and then he could retell the story word for word.