A-2-1-5-end.2009

2009年普通高校招生统一考试天津卷(英语)第I卷第一部分：英语知识运用（共两节，满分45分）第一节：单项填空（共15小题；每小题1分，满分15分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项。

例：Stand over there ______ you’ll be able to see it better.A、orB、andC、butD、while答案是B。

1、I’m trying to break the _______ of getting up too late.A、traditionB、convenienceC、habitD、leisure2、My parents _____ in Hong Kong、They were born there and have never livedanywhere else.A、liveB、livedC、were livingD、will live3、---- We’re organizing a party next Saturday, and I’d like you to come.---- _______! I have another one that day、Thank you just the same.A、Good luckB、What a pityC、Never do it againD、Welldone4、______ the project in time, the staff were working at weekends.A、CompetingB、Having completedC、To have completedD、To complete5、A person ______ e-mail account is full won’t be able to send or receive anye-mails.A、whoB、whomC、whoseD、whoever6、---- Sorry, I have to ______ now、It’s time for class.---- OK, I’ll call back later.A、hang upB、break upC、give upD、hold up7、It is obvious to the students ______ they should get well prepared for their future.A、asB、whichC、whetherD、that8、Don’t worry if you don’t understand everything.The teacher will ______ the mainpoints at the end.A、recoverB、reviewC、requireD、remember9、_____ by the advances in technology, many farmers have set up wind farms ontheir land.A、Being encouragedB、EncouragingC、EncouragedD、Having encouraged10、The art show was _______ being a failure; it was a great success.A、far fromB、along withC、next toD、regardless of11、---- Putting on a happy face not only helps us make friends but also makes us feelbetter.---- _______.A、I’d love toB、I’m with you on thatC、It’s up to youD、It’s my pleasure12、It was a nice house, but _______ too small for a family of live.A、rarelyB、fairlyC、ratherD、pretty13、I’m not surprised that he became a writer、Even as a child he had a _____imagination.A、clearB、cautiousC、funnyD、vivid14、I travel to the Binhai New Area by light railway every day, _____ do manybusinessmen who live in downtown Tianjin.A、asB、whichC、whenD、though15、This printer is of good quality、If it _______ break down within the first year, wewould repair it at our expense.A、wouldB、shouldC、couldD、might第二节：完形填空（共20小题；每小题1.5分，满分30分）阅读下面短文，掌握其大意，然后从16-35各题所给的A、B、C、D四个选项中，选出最佳选项。

2009 AMC10美国数学竞赛A 卷1. One can holds 12 ounces of soda. What is the minimum number of cans needed to provide a gallon (128 ounces) of soda? (A) 7 (B) 8 (C) 9 (D) 10 (E) 112. Four coins are picked out of a piggy bank that contains a collection of pennies, nickels, dimes and quarters. Which of the following could not be the total value of the four coins, in cents? (A) 15 (B) 25 (C) 35 (D) 45 (E) 553. Which of the following is equal to 111111+++?(A) 54(B)32(C)53(D) 2 (E) 34. Eric plans to compete in a triathlon. He can average 2 miles per hour in the 1/4-mile swim and 6 miles per hour in the 3-mile run. His goal is to finish the triathlon in 2 hours. To accomplish his goal what must his average speed in miles per hour, be for the 15-mile bicycle ride? (A) 12011(B) 11 (C)565(D)454(E) 125. What is the sum of the digits of the square of 111,111,111? (A) 18 (B) 27(C) 45(D) 63(E) 816. A circle of radius 2 is inscribed in a semicircle, as shown. The area inside the semicircle but outside the circle is shaded. What fraction of the semicircle’s area is shaded?(A) 12 (B)6π(C) 2π(D) 23(E) 3π7. A carton contains milk that is 2% fat, an amount that is 40% less fat than the amount contained in a carton of whole milk. What is the percentage of fat in whole milk?(A) 125(B) 3 (C) 103(D) 38 (E) 428. Three Generations of the Wen family are going to the movies, two from each generation. The two members of the youngest generation receive a 50% discount as children. The two members of the middle generation receive no discount. Grandfather Wen, whose senior ticket costs $6.00, is paying for everyone. How many dollars must he pay?(A) 34 (B) 36 (C) 42 (D) 46 (E) 489. Positive integers a, b and 2009, with 2009a b<<, from a gometric sequence with an integer ratio. What is a?(A) 7 (B) 41 (C) 49 (D) 289 (E) 200910. Triangle ABC has a right angle at B. Point D is the foot of the altitude from B, AD=3, and DC=4. What is the area of △ABC?43DCBA(A)(B)(C) 21(D) 1 (E) 4211. One dimension of a cube is increased by 1, another is decreased by 1, and the third is left unchanged. The volume of the new rectangular solid is 5 less than that of the cube. What was the volume of the cube? (A) 8 (B) 27 (C) 64 (D) 125 (E) 21612. In quadrilateral ABCD, AB=5, BC=17, CD=5, DA =9, and BD is an integer. What is BD?(A) 11 (B) 12 (C) 13 (D) 14 (E) 1513. Suppose that P=2m and Q=3n . Which of the following is equal to 12mn for every pair of integers (m,n)? (A) P 2Q(B) P n Q m(C) P n Q 2m(D) P 2m Q n (E) P 2n Q m14. Four congruent rectangles are placed as shown. The area of the outer square is 4times that of the inner square. What is the ratio of the length of the longer side ofBeach rectangle to the length of its shorter side? (A) 3 (B)(C)2+(D)(E) 415. The figures F 1, F 2, F 3, and F4 shown are the first in a sequence of figures. For3n ≥. F n is constructed from F n-1 by surrounding is with a square and placing onemore diamond on each side of the new square than F n-1 had on each side of its outside square. For example, figure F 3 has 13 diamonds. How many diamonds are there in figure F 20? (A) 401 (B) 485 (C) 585(D) 626(E) 76116. Let a, b, c, and d be real numbers with 2a b -=,3b c -= and4c d -=. What isthe sum of all possible values of a d-.?(A) 9 (B) 12(C) 15(D) 18 (E) 2417. Rectangle ABCD has AB=4 and BC=3. Segment EF is constructed through B so that BF is perpendicular to DB, and A and C lie on DE and DF, respectively. What is EF? (A) 9(B) 10(C) 125/12(D) 103/9(E) 12F4F3F2F118. At Jefferson Summer Camp, 60% of the children play soccer, 30% of the children swim, and 40% of the soccer players swim. To the nearest whole percent, what percent of the non-swimmers play soccer?(A) 30% (B) 40% (C) 49% (D) 51% (E) 70%19. Circle A has radius 100. Circle B has an integer radius r<100 and remains internally tangent to circle A as it rolls once around the circumference of circle A. The two circles have the same points of tangency at the beginning and end of circle B’s trip. How many possible values can r have?(A) 4 (B) 8 (C) 9 (D) 50 (E) 9020. Andrea and Lauren are 20 kilometers apart. They bike toward one another with Andrea traveling three times as fast as Lauren, and the distance between them decreasing at a rate of 1 kilometer per minute. After 5minites, Andrea stops biking because of a flat tire and waits for Lauren. After how many minutes from the time they started to bike does Lauren reach Andrea?(A) 20 (B) 30 (C) 55 (D) 65 (E) 8021. Many Gothic cathedrals have windows with portions containing a ring of congruent circles that are circumscribed by a larger circle. In the figure shown, the number of smaller circles is four. What is the ratio of the sum of the areas of the foursmaller circles to the area of the larger circle? (A)3- (B)2-(C)43-（ (D)132-（ (E)2-22. Two cubical dice each have removable numbers 1 through 6. The twelve numbers on the two dice are removed, put into a bag, then drawn one at a time and randomly reattached to the faces of the cubes, one number to each face. The dice are then rolled and the numbers on the two top faces are added. What is the probability that the sum is 7? (A) 19 (B)18(C)16(D)211(E)1523. Convex quadrilateral ABCD has AB=9 and CD=12. Diagonals AC and BD intersect at E, AC=14, and △ABD and △BEC have equal areas. What is AE? (A) 92 (B)5011(C)214(D)173(E) 624. Three distinct vertices of a cube are chosen at random. What is the probability that the plane determined by these three vertices contains points inside the cube? (A) 14 (B)38(C)47(D)57(E)3425. For k>0, let I k =10…064, where there are k zeros between the 1 and the 6. Let N(k) be the number of factors of 2 in the prime factorization of I k . What is the maximum value of N(k)? (A) 6(B) 7(C) 8(D) 9 (E) 10。

第十五届全国青少年信息学奥林匹克联赛初赛试题（提高组 Pascal语言二小时完成）●●全部试题答案均要求写在答卷纸上，写在试卷纸上一律无效●●一．单项选择题（共10题，每题1.5分，共计15分。

每题有且仅有一个正确答案。

）1、关于图灵机下面的说法哪个是正确的：A)图灵机是世界上最早的电子计算机。

B)由于大量使用磁带操作，图灵机运行速度很慢。

C)图灵机只是一个理论上的计算模型。

D)图灵机是英国人图灵发明的，在二战中为破译德军的密码发挥了重要作用。

2、关于BIOS下面的说法哪个是正确的：A)BIOS是计算机基本输入输出系统软件的简称。

B)BIOS里包含了键盘、鼠标、声卡、图形界面显器等常用输入输出设备的驱动程序。

C)BIOS一般由操作系统厂商来开发完成。

D)BIOS能提供各种文件拷贝、复制、删除以及目录维护等文件管理功能。

3、已知大写字母A的ASCII编码为65（十进制），则大写字母J的十六进制ASCII编码为：A) 48 B) 49 C) 50 D) 以上都不是4、在字长为16位的系统环境下，一个16位带符号整数的二进制补码为1111111111101101。

其对应的十进制整数应该是：A)19 B) -19 C) 18 D) -185、一个包含n个分支结点（非叶结点）的非空满k叉树，k>=1，它的叶结点数目为：A) nk + 1 B) nk-1 C) (k+1)n-1 D. (k-1)n+16. 表达式a*(b+c)-d的后缀表达式是：A) abcd*+-B) abc+*d-C) abc*+d-D) -+*abcd7、最优前缀编码，也称Huffman编码。

这种编码组合的特点是对于较频繁使用的元素给与较短的唯一编码，以提高通讯的效率。

下面编码组合哪一组不是合法的前缀编码。

A)（00，01，10，11）B)（0，1，00，11）C)（0，10，110，111）D)（1，01，000，001）8、快速排序平均情况和最坏情况下的算法时间复杂度分别为：A) 平均情况O(nlog2n)，最坏情况O(n2)B) 平均情况O(n)，最坏情况O(n2)C) 平均情况O(n)，最坏情况O(nlog2n)D) 平均情况O(log2n)，最坏情况O(n2)9、左图给出了一个加权无向图，从顶点V0开始用prim算法求最小生成树。

AS/NZS 4665.1/Amdt 1/2009-02-27STANDARDS AUSTRALIA/STANDARDS NEW ZEALANDAmendment No. 1toAS/NZS 4665.1:2005Performance of external power suppliesPart 1: Test method and energy performance markREVISED TEXTThe 2005 edition of AS/NZS 4665.1 is amended as follows; the amendments should be inserted in the appropriate places.SUMMARY: This Amendment applies to the Preface, Clauses 1.1 and 1.3 and Appendices A, B and C. Published on 27 February 2009.Approved for publication in New Zealand on behalf of the Standards Council of New Zealand on 29 January 2009PrefaceIn the seventh paragraph, delete the second sentence and replace with the following: R egulatory authorities have advised that it is intended to mandate Part 2 of the Standard (AS/NZS 4665.2:2005) in regulations in Australia and New Zealand no earlier than 1 December 2008, except for marking requirements, which are intended to be mandated no earlier than 1 April 2009.Clause 1.1Add a new fourth paragraph as follows:Power supplies within the scope of AS/NZS 4879 or IEC 61347.2.13 are excluded from the scope of this Standard.Clause 1.3.3Replace ‘r.m.s.’ with ‘average’.Clause 1.3.8Add a new Clause 1.3.8 as follows:1.3.8 Family of models—Non user selectable output voltageA range of non user selectable single output models based on common technically equivalent components (typically switchmode), but each model may have a different output voltage. They may be sold under different brand names or model numbers or both. Each member of the family is included on a single test report and has the same energy performance mark, but may have a different output voltage.Clause 1.3.9Add a new Clause 1.3.9 as follows:1.3.9 Multi-switch model—User selectable output voltageA model with a single output that provides a range of user selectable output voltages. They may be sold under different brand names or model numbers or both. Test reports may AMDT No. 1 FEB2009 AMDT No. 1 FEB 2009AMDT No. 1 FEB2009AMDT No. 1 FEB 2009AMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .Clauses 1.3.8 to 1.3.15Renumber Clauses 1.3.8 to 1.3.15 as Clauses 1.3.10 to 1.3.17 respectively.Clause 1.3.18Add a new Clause 1.3.18 as follows: 1.3.18 Single model(s)One or more models using technically equivalent components with identical performance specifications having the same output voltage. They may be sold under different brand names or model numbers or both. Test reports may include one or more models having the same energy performance mark.Clauses 1.3.16 and 1.3.17Renumber Clauses 1.3.16 and 1.3.17 as Clauses 1.3.19 and 1.3.20 respectively.Paragraph A1Add new third and fourth paragraphs as follows:External power supplies, for Mark V only, with an input power greater than or equal to 100 W shall have a true power factor of 0.9 or greater at 100% of rated load when tested at 115 V, 60 Hz.Products tested for compliance with Mark V at both 115 V and 230 V shall meet the power factor requirement when tested at 115 V, but not when tested at 230 V.AMDT No. 1 FEB2009AMDT No. 1 FEB 2009 AMDT No. 1 FEB2009AMDT No. 1 FEB 2009 e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .Table A1Delete the Table and replace with the following:TABLE A1ENERGY PERFORMANCE REQUIREMENTS FOR EACH NUMERALNo load power consumptionrequirementsActive mode efficiency requirementsNameplate output power No load powerNameplate output power Mark(P no ) WW(P no ) WOutput specificationAverage active modeefficiencyI Used if it does not meet any of the following criteria 0 to <1 All ≥0.39 × P noII0 to <10 10 to ≤250 ≤0.75 ≤1.0 1 to <49 All ≥0.107 × L n (P no ) + 0.39 0 to 1All ≥0.490 × P no>1 to 49 All ≥0.090 × L n (P no ) + 0.490 to a maximum of 0.840 III 0 to <10 10 to ≤250≤0.5 ≤0.75>49 to 250 All ≥0.840 0 to 1All ≥0.500 × P no>1 to 51 All ≥0.090 × L n (P no ) + 0.500 to a maximum of 0.850 IV0 to <10 10 to ≤250≤0.5 ≤0.5>51 to 250All≥0.850AC-AC AC-DCOutput voltage<6 V andoutput current ≥0.550 A ≥0.497 × P no + 0.067 0 to 1Other models ≥0.480 × P no + 0.140 Output voltage <6 V andoutput current ≥0.550 A ≥0.0750 × L n (P no ) + 0.561 0 to <50≤0.5 ≤0.3>1 to 49Other models ≥0.0626 × L n (P no ) + 0.622Output voltage <6 V andoutput current ≥0.550 A ≥0.860 V50 to ≤250 ≤0.5 ≤0.5 >49 to 250Other models≥0.870VI – X Reserved for future useLEGEND:P no = nameplate output power of the EUT L n = the natural logarithm (base e)AMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .Paragraph A21 Insert a new Clause heading before the first paragraph as follows:A2.1 General2 Delete the Note and replace with the following:NOTE: Numerals VI to X are reserved for future use.3 Insert the following after Figure A1:A2.2 Single performance mark when tested at 115 V a.c., 230 V a.c. and240 V a.c. or has a single input voltage If the external power supply complies with the requirements of a single performance mark at both 115 V a.c. and 230 V a.c. or has a single input voltage, then the mark can be as shown in Figure A1. If only one mark is applied, then it shall be the lowest mark attained when tested at 115 V a.c. and 230 V a.c. A2.3 Dual markingIf the external power supply meets different energy performance for different a.c. supply voltages, then the external power supply may voluntarily be marked with its performance mark qualified by voltage at which it applies, with the appropriate voltage marked immediately beside the mark. Figure A2 provides an example of dual marking, where the external power supply meets performance Mark IV at 115 V a.c.and Mark III at 230 V a.c.FIGURE A2 EXAMPLE OF DUAL MARKINGA2.4 P erformance mark for models capable of multiple input voltages whentested at 230 V a.c. only If the external power supply is capable of multiple input voltages, but is tested and complies with the above requirements at 230 V a.c. only, then the mark shall bequalified with ‘230’ as per the examples in Figure A3.FIGURE A3 EXAMPLES FOR 230 V a.c. COMPLIANCE ONLYAMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .A2.5 P erformance mark for models capable of multiple input voltages whentested at 115 V a.c. only If the external power supply is capable of multiple input voltages, but is tested and complies with the above requirements at 115 V a.c. only, then the mark shall bequalified with ‘115’ as per the examples in Figure A4.FIGURE A4 EXAMPLES FOR 115 V a.c. COMPLIANCE ONLYAMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .Figure B1Delete Figure B1 and replace with the following:Does the EPS convert mains a.c.input voltage into one ELV output of a single voltage or user selectable voltage?Is the EPS in a housing that is separate from the end-use product it is intended to power?Does the EPS charge a battery?YESYESDo the batteries or battery pack physically attach directly to the EPS independently of the end-use product they power and with no interveningdevice?NODoes the EPS have a battery chemistry or type selector switch AND indicator light or state of charge meter?Does NOT meet the definition of an EPSDoes NOT meet the definition of an EPSMeets the definition ofan EPSYESNONOYESYESStar tNONOFIGURE B1 FLOWCHART FOR DEFINITION OF SINGLE OUTPUT EXTERNALPOWER SUPPLYAMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .Appendix CDelete Appendix C and replace with the following:APPENDIX CSAMPLE TEST REPORT(Informative)SINGLE OUTPUT EXTERNAL POWER SUPPLY TEST REPORTNameplate input voltageNameplate output voltageNameplate output currentNameplate output watts/VA230 V a.c. 5.0 1.0 5.0 115 V a.c. 5.0 1.0 5.0LAB INFORMATIONTest laboratory name XYZ Test Centre Test laboratory address 1 South StS ydney, N SW 2000 Country Australia Test technician(s) Joe Bloggs Date measured 14 July 2005 Test Standard used AS/NZS 4665.1:2005TEST INSTRUMENTSMake/Model Measurement Calibration date XYZ Model 1 No Load22 April 2005 ABC Model 2 Active Output 21 April 2005CONNECTIONS OR MODIFICATIONS TO THE INPUT AND/OR OUTPUT CORD a.c. input typeAS/NZS 3112 integrated plug Input cord length (mm) Not applicable—integrated plug Output cord length (mm) 1750Output plug typeSingle pin type Modification to connectors for testing NoneTEST SETUPTest report number 000123Manufacturer name Brand X Model ABC CountryChina Input power switchNot present Product powered (if known) Not known Output type d.c.Design typeNon user selectable output voltageNameplate input specifications 100 V – 240 V 50 Hz – 60 HzNameplate input current0.5 A – 0.3 AAMDT No. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .75%50%25%5%0%25%50%75%100%Actual fraction of output current4567832100%25%50%75%100%Input and output power vs Output current Actual fraction of output currentP o w e r (W )InputOutputInput vs Output power0.01.02.03.04.05.06.07.08.0Output power (W)I n p u t p o w e r (W )NOTE: Repeat the following table for minimum and maximum output voltage if applicable.No loadActive power valuesPercent of nameplate current 0% 25% 50% 75% 100% Average Output current (A) 0 0.248 0.498 0.747 1.001 — Output voltage (V) 5.07 5.024 5.003 4.981 4.959 — Output power (W) 0 1.244 2.492 3.721 4.966 — a.c. input current (A) 0.019 0.048 0.070 0.092 0.115 — a.c. input voltage (V) 114.9 114.9 114.9 114.9 114.9 — a.c. input power (W) 0.839 2.621 4.136 5.708 7.390 — Total harmonic distortion (THD ) 88.75% 86.91% 84.99% 83.29% 81.64% — True power factor 0.394 0.477 0.513 0.539 0.561 0.497 Power consumed by EUT (W) 0.839 1.377 1.644 1.987 2.425 — Efficiency — 47.46% 60.25% 65.19% 67.19% 60.02%FIGURE C1 MEASURED AND CALCULATED DATA AT 115 V 60 HzNo. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .75%50%25%5%0%25%50%75%100%Actual fraction of output current4567832100%25%50%75%100%Input and output power vs Output currentActual fraction of output currentP o w e r (W )InputOutputInput vs Output power0.01.02.03.04.05.06.07.08.0Output power (W)I n p u t p o w e r (W )NOTE: Repeat the following table for minimum and maximum output voltage if applicable.No loadActive power values Percent of nameplate current 0% 25% 50% 75% 100% Average Output current (A) 0 0.248 0.498 0.749 1.000 — Output voltage (V) 5.06 5.021 4.999 4.978 4.957 — Output power (W) 0 1.244 2.487 3.729 4.957 — a.c. input current (A) 0.018 0.041 0.052 0.064 0.076 — a.c. input voltage (V) 229.9 229.9 229.9 229.9 229.9 — a.c. input power (W) 1.360 3.703 4.983 6.395 7.927 — Total harmonic distortion (THD ) 86.49% 89.84% 89.48% 88.94% 88.30% — True power factor 0.324 0.396 0.417 0.435 0.451 0.405 Power consumed by EUT (W) 1.360 2.459 2.459 2.666 2.970 — Efficiency — 33.60% 49.92% 58.31% 62.53% 51.09%FIGURE C2 MEASURED AND CALCULATED DATA AT 230 V 50 HzNo. 1 FEB 2009e d t o M r J o s h u a H u a n g o n 07 M a r 2009. P e r s o n a l u s e l i c e n c e o n l y . S t o r a g e , d i s t r i b u t i o n o r u s e o n n e t w o r k p r o h i b i t e d .。