DES加密算法的实现
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实验课程:网络安全实验项目:DES加密算法的实现实验日期:系:数学与计算机学院班级:网络工程姓名:学号:指导教师:成绩:【实验目的】掌握DES加密算法的基本原理使用编程语言实现DES的加密和解密【实验环境】Windows 系统Java编程环境或者VC++编程环境【实验内容和步骤】第一步:变换明文。
对给定的64位比特的明文x,首先通过一个置换IP表来重新排列x,从而构造出64位比特的x0,x0=IP(x)=L0R0,其中L0表示x0的前32比特,R0表示x0的后32位。
第二步:按照规则迭代。
规则为Li = Ri-1Ri = Li⊕f(Ri-1,Ki) (i=1,2,3…16)经过第一步变换已经得到L0和R0的值,其中符号⊕表示的数学运算是异或,f表示一种置换,由S盒置换构成,Ki是一些由密钥编排函数产生的比特块。
f和Ki将在后面介绍。
第三步:对L16R16利用IP-1作逆置换,就得到了密文y。
代码如下:输入64位比特明文IP置换表LRLi= Ri-1Ri= Li⊕f(Ri-1,Ki)(i=1,2,…16)迭代16次IP逆置换表输出64位比特密文#include "stdio.h"#include "string.h"#define uchar unsigned char/***************明文转换声明部分**************///IP1置换表int IP_1[64]={58, 50, 42, 34, 26, 18, 10, 2,60, 52, 44, 36, 28, 20, 12, 4,62, 54, 46, 38, 30, 22, 14, 6,64, 56, 48, 40, 32, 24, 16, 8,57, 49, 41, 33, 25, 17, 9, 1,59, 51, 43, 35, 27, 19, 11, 3,61, 53, 45, 37, 29, 21, 13, 5,63, 55, 47, 39, 31, 23, 15, 7};//IP2逆置换表int IP_2[64]={40, 8, 48, 16, 56, 24, 64, 32,39, 7, 47, 15, 55, 23, 63, 31,38, 6, 46, 14, 54, 22, 62, 30,37, 5, 45, 13, 53, 21, 61, 29,36, 4, 44, 12, 52, 20, 60, 28,35, 3, 43, 11, 51, 19, 59, 27,34, 2, 42, 10, 50, 18, 58, 26,33, 1, 41, 9, 49, 17, 57, 25};//E扩展置换表int E_case[48]={32, 1, 2, 3, 4, 5,4, 5, 6, 7, 8, 9,8, 9, 10, 11, 12, 13,12, 13, 14, 15, 16, 17,16, 17, 18, 19, 20, 21,20, 21, 22, 23, 24, 25,24, 25, 26, 27, 28, 29,28, 29, 30, 31, 32, 1};//S盒压缩int S1[4][16]={14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13};int S2[4][16]={15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9};int S3[4][16]={10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12}; int S4[4][16]={ 7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14}; int S5[4][16]={ 2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3}; int S6[4][16]={12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13}; int S7[4][16]={ 4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12}; int S8[4][16]={13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11}; //P盒置换int Permute[32]={ 16, 7, 20, 21, 29, 12, 28, 17,1, 15, 23, 26, 5, 18, 31, 10,2, 8, 24, 14, 32, 27, 3, 9,19, 13, 30, 6, 22, 11, 4, 25};/************字节与二进制相互变换部分******************///字节转换成二进制int ByteToBit(char ch,char bit[8]){uchar x;for(x=0;x<8;x++){*(bit+x)=((ch<<x)&0x80)>>7;}return 0;}//字符串转换成二进制位串int Char8ToBit64(char ch[8],char bit[64]){uchar x;for(x=0;x<8;x++){ByteToBit(*(ch+x),bit+(x<<3));}return 0;}//二进制转换成字节int BitToByte(char bit[8],char *ch){uchar x;for(x=0;x<8;x++){*ch|=*(bit+x)<<(7-x);}return 0;}//将二进制串转换成字符串int Bit64ToChar8(char bit[64],char ch[8]){uchar x;memset(ch,0,8); //把ch[8]全部清零。
for(x=0;x<8;x++){BitToByte(bit+(x<<3),ch+x);}return 0;}/***************密钥声明部分*******************/ //密钥PC-1置换表int PC_1[56]={57, 49, 41, 33, 25, 17, 9,1, 58, 50, 42, 34, 26, 18,10, 2, 59, 51, 43, 35, 27,19, 11, 3, 60, 52, 44, 36,63, 55, 47, 39, 31, 23, 15,7, 62, 54, 46, 38, 30, 22,14, 6, 61, 53, 45, 37, 29,21, 13, 5, 28, 20, 12, 4};//密钥PC-2置换表int PC_2[48]={14, 17, 11, 24, 1, 5,3, 28, 15, 6, 21, 10,23, 19, 12, 4, 26, 8,16, 7, 27, 20, 13, 2,41, 52, 31, 37, 47, 55,30, 40, 51, 45, 33, 48,44, 49, 39, 56, 34, 53,46, 42, 50, 36, 29, 32};//密钥每次轮回移位表uchar Left_Move[16]={1, 1, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1};/*************密钥的生成函数部分**************************/ //PC-1置换函数int PC1_permute(char pc1[64],char PC1_Buff[56]){uchar x;for(x=0;x<56;x++){PC1_Buff[x]=pc1[PC_1[x]-1];}return 0;}//PC密钥左移int KeyLeftMove(char pcB[56],char Move){uchar x;char Cn[28],Dn[28];char a_buff,b_buff,c_buff,d_buff;//**********PC-1密钥56位分离成左右各28位************** memcpy(Cn,pcB,28);memcpy(Dn,pcB+28,28);//*****************PC密钥左移部分******************* a_buff=Cn[0];b_buff=Dn[0];if(2==Move){c_buff=Cn[1];d_buff=Dn[1];}for(x=0;x<28;x++){if(27==x){if(1==Move){Cn[27]=a_buff;Dn[27]=b_buff;}if(2==Move){Cn[26]=a_buff;Cn[27]=c_buff;Dn[26]=b_buff;Dn[27]=d_buff;}}else{Cn[x]=Cn[x+Move];Dn[x]=Dn[x+Move];}}//******************28bit合成56bit******************** memcpy(pcB,Cn,28);memcpy(pcB+28,Dn,28);return 0;}//PC-2逆置换函数int PC2_permut(char pc2[56],char PC2_Buff[48]){uchar x;for(x=0;x<48;x++){PC2_Buff[x]=pc2[PC_2[x]-1];}return 0;}//产生16轮的子密钥函数int Key16Itera(char key[64],char subKeys[16][48]){uchar x,move;char temp1[56];PC1_permute(key,temp1);//PC1置换,返回值tempfor(x=0;x<16;x++){move=Left_Move[x];KeyLeftMove(temp1,move);//移位,返回值temp,56bitPC2_permut(temp1,subKeys[x]);}return 0;}/***********明文加密函数部分*************///IP置换int IP1_permute(char IP1[64]){uchar x;char IP1Buff[64];for(x=0;x<64;x++){IP1Buff[x]=IP1[IP_1[x]-1];}memcpy(IP1,IP1Buff,64);return 0;}//32bit经E盒扩展成48bitint R_Expand48bit(char R[32],char RE[48]) {uchar x;for(x=0;x<48;x++){RE[x]=R[E_case[x]-1];}return 0;}//IP64逆置换int IP2_permute(char IP2[64]){uchar x;char temp2[64];for(x=0;x<64;x++){temp2[x]=IP2[IP_2[x]-1];}memcpy(IP2,temp2,64);return 0;}//经P盒置换int Pcase(char S8Byte[32]){uchar x;char temp3[32];for(x=0;x<32;x++){temp3[x]=S8Byte[Permute[x]-1];}memcpy(S8Byte,temp3,32);return 0;}//经S盒压缩成32bitint Reduceto32bit(char EKey[48],char S32bit[32]){uchar x,Rank,Line;int out;for(x=0;x<8;x++){Rank=(EKey[1+6*x]<<3)|(EKey[2+6*x]<<2)|(EKey[3+6*x]<<1)|(EKey[4+6*x]);Line=(EKey[6*x]<<1)|(EKey[5+6*x]);//在S盒寻找需要的数if(0==x) { out=S1[Line][Rank];}if(1==x) { out=S2[Line][Rank];}if(2==x) { out=S3[Line][Rank];}if(3==x) { out=S4[Line][Rank];}if(4==x) { out=S5[Line][Rank];}if(5==x) { out=S6[Line][Rank];}if(6==x) { out=S7[Line][Rank];}if(7==x) { out=S8[Line][Rank];}//把一位数拆成数四位数S32bit[4*x+0]=(((char)(out))&0x08)>>3;S32bit[4*x+1]=(((char)(out))&0x04)>>2;S32bit[4*x+2]=(((char)(out))&0x02)>>1;S32bit[4*x+3]=(((char)(out))&0x01);}return 0;}/***************明文16次迭代,加密,*************************************输入值:mw[64]\子密钥:miyue[16][48]***************************返回值:data[64]***********************/int Encryp(char data[64],char Zkey16[16][48]){uchar x,y;char Left[32],Right[32],EKbuff[48];char SE32bit[32];IP1_permute(data);//IP置换memcpy(Left,data,32);//分离32bitmemcpy(Right,data+32,32);for(x=0;x<16;x++){R_Expand48bit(Right,EKbuff);//E盒扩展for(y=0;y<48;y++) //与密钥异或{EKbuff[y]^=Zkey16[x][y];}Reduceto32bit(EKbuff,SE32bit);//经S盒压缩32bit,返回值SE32bitPcase(SE32bit); //经P盒置换,返回值SE32bitfor(y=0;y<32;y++) //与左半部分Left 32bit异或{SE32bit[y]^=Left[y];}memcpy(Left,Right,32);memcpy(Right,SE32bit,32);}memcpy(data,Right,32);//合成64bitmemcpy(data+32,Left,32);IP2_permute(data); //IP逆置换return 0;}/**********************密文输入,解密,16次迭代**************************************************输入值:miwen[64]*******************************************************输出值:mw[64]******************************/ int Decryp(char miwen[64],char D_Zkey16[16][48]){uchar x,y;char D_Left[32],D_Right[32];char D_EKbuff[48],D_SE32bit[32];IP1_permute(miwen); //IP1置换。