江苏省南京市金陵中学2020-2021学年高二下学期期末英语试题

第一部分: 听力技能(共两节，满分20分)Section A（共15小题，每小题1分，满分15分）Directions: In this section, you’ll hear six conversations between two speakers. For each conversation there are several questions and each question is followed by three choices marked A, B and C. Listen carefully and then choose the best answer for each question.You will hear each conversation twice.Conversation 11. When does the conversation take place?A. At 6:30B. At 6:00C. At 5:302. How will the speakers go to the concert?A. On footB. By subwayC. By taxiConversation 23. Why can’t Jessica get a student ID?A. She hasn’t registered yet.B. She didn’t take her ID card.C. She went into the wrong room.4. What will she do next?A .Fill in a form. B. Go upstairs. C. Sign her name.Conversation 35. What does the man suggest doing?A. Going for a walk.B. Having a cup of tea.C. Mailing a letter6. What is the woman doing?A. Writing a letterB. Cooking dinnerC. ExercisingConversation 47. What is the date today?A. October 22nd.B. October 23rd.C. October 24th.8. What is special about tomorrow?A. It’s the United Nations Day.B. There will be an International Dress Parade.C. It’s the International Food Festival.9. How old is the United Nations in 2010?A. 70 years.B. 65 years.C.60 years.Conversation 510. What are the speakers talking about?A. FriendsB. PicturesC. Stories.11. What does the man think is the most stressful?A. Being lateB. Having an exam.C. Moving to a new place.12. What does the woman think of interviews?A. They are challengingB. They are stressful.C. They are terrible.Conversation 613. Who is Thomson?A. Linda’s husband.B. The man’s cousin.C. A chef.（主厨,大师傅）14. How many years have the speakers got married?A. 40.B. 50.C.60.15. What do we know about Linda?A. She won’t be invited to the party.B. She doesn’t eat chicken.C. She is a good cook. Section B （共5小题，每小题1分，共5分）Directions: In this section, you’ll hear a short passage. Listen carefully and fill in the numbered blanks with the information you have heard. Fill in each blank with NO MORETHAN THREE WORDS.You will hear the short passage TIWICE.London Marathon第二部分知识运用(共两节，满分20分)第一节单项填空（共10小题；每小题1分，满分10分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。

1一、单项选择题：本小题共8小题，每小题5分，共计40分．在每小题给出的四个选项中，2020-2021学年江苏省南京市鼓楼区金陵中学高二（下）期末数学试卷只有一项是符合题目要求的，请把答案填涂在答题卡相应位置上．．（5分）已知a ∈R ，（1+ai ）i ＝3+i （i 为虚数单位），则a ＝（ ） A ．﹣1B ．1C ．﹣3D ．32．（5分）在等比数列{a n }中，“a 2＜a 3”是“a 4＜a 5”的（ ）条件 A ．充要 B ．充分不必要 C ．必要不充分D ．既不充分也不必要3．（5分）已知抛物线x 2＝2py （p ＞0）上一点M （m ，1）到焦点的距离为，则其焦点坐标为（ ） A ．B ．C ．D ．4．（5分）已知函数f （x ）的图象如图所示，则f （x ）的解析式可能是（ ）A ．f （x ）＝x 2+cos xB ．f （x ）＝x 2+sin xC ．f （x ）＝2x +cos xD ．f （x ）＝2x +sin x5．（5分）在（1+x ）6（1+y ）4的展开式中，记x m y n 项的系数为f （m ，n ），则f （3，0）+f （1，2）＝（ ） A ．24B ．80C ．56D ．1206．（5分）设0＜a ＜，若随机变量X 的分布列是： X 0 a 1 P则当a 在（0，）内增大时（ ） A ．V （X ）增大 B ．V （X ）先增大后减小 C ．V （X ）减小D ．V （X ）先减小后增大7．（5分）设椭圆C：+y2＝1（a＞1），已知点A（0，1），点P为曲线C上的点，若|AP|的最大值为2，则a的取值范围为（ ）A．（1，]B．（1，2]C．[，2）D．（，2]8．（5分）已知a，b∈R且ab≠0，若对任意的x≤0均有（x﹣a）（x﹣b）（x﹣2a﹣b）≤0，则（ ）A．a＜0B．a＞0C．b＜0D．b＞0二、多项选择题本大题共4小题，每小题5分，共20分．在每小题给出的四个选项中，有多项符合题目要求，请把答案填涂在答题卡相应位置上，全部选对得5分，部分选对得2分，不选或有错选的得0分．9．（5分）若直线y＝3a与函数y＝|a x﹣1|（a＞0，且a≠1）的图象有两个公共点，则a可以是（ ）A．2B．C．D．10．（5分）已知双曲线＝1（a＞0）的左，右焦点分别为F1，F2，一条渐近线方程为y＝，P为C上一点，则以下说法正确的是（ ）A．C的实轴长为8B．C的离心率为C．|PF1|﹣|PF2|＝8D．C的焦距为1011．（5分）为庆祝建党100周年，讴歌中华民族实现伟大复兴的奋斗历程，增进全体党员干部职工对党史知识的了解，某单位组织开展党史知识竞赛活动，以支部为单位参加比赛，某支部在5道党史题中（有3道选择题和2道填空题），不放回地依次随机抽取2道题作答，设事件A为“第1次抽到选择题”，事件B为“第2次抽到选择题”，则下列结论中正确的是（ ）A．B．C．D．12．（5分）已知定义在R上的函数y＝f（x）满足f（﹣x）＝﹣f（x），函数y＝f（x+1）为偶函数，且当x∈[0，1]时，f（x）＝log2（x+a），则下列结论正确的是（ ）A．函数y＝f（x）是周期为4的周期函数B．f（2020）+f（2021）＝1C．当x∈（1，2]时，f（x）＝log2（x+1）D．不等式的解集为三、填空题：本大题共4小题，每小题5分，共20分，请把答案填写在答题卡相应位置上．13．（5分）若a＝log45，则2a+2﹣a＝ ．14．（5分）已知{a n}是公差为d的等差数列，{b n}是公比为q的等比数列．若数列{a n+b n}的前n项和S n＝2n2﹣n+2n﹣1（n∈N*），则d+q的值为．15．（5分）设x＞0，y＞0，则x+4y+的最小值为．16．（5分）已知函数f（x）是定义在R上的奇函数，当x≥0时，f（x）＝|x﹣a|+|x﹣2a|﹣3a．若对任意的x∈R，都有f（x﹣）≤f（x），则实数a的取值范围为．四、解答题：本大题共6小题，共70分．请在答题卡指定区域内作答，解答时应写出必要的文字说明，证明过程或演算步骤．17．（10分）设数列{a n}的前n项和为S n，已知S2＝4，a n+1＝2S n+1，n∈N*．（1）求数列{a n}通项公式；（2）求数列{a n﹣2n+1}的前n项和．18．（12分）在1，2，3…，9，这9个自然数中，任取3个数．（Ⅰ）求这3个数中，恰有一个是偶数的概率；（Ⅱ）记ξ为这三个数中两数相邻的组数，（例如：若取出的数1、2、3，则有两组相邻的数1、2和2、3，此时ξ的值是2）．求随机变量ξ的分布列及其数学期望Eξ．19．（12分）已知函数f（x）＝2x3﹣3（a+1）x2+6ax+b，其中a，b为实数．（1）若函数f（x）的图象与x轴相切于点（2，0），求a，b的值；（2）若a≥1，且f（x）在区间（﹣2，2）上取到最大值，求a的取值范围．20．（12分）如图所示，正方形ABCD所在平面与梯形ABMN所在平面垂直，MB∥AN，NA ＝AB＝2，BM＝4，CN＝2．（1）证明：MB⊥平面ABCD；（2）求直线AC与平面CDM所成角的正弦值；（3）在线段CM上是否存在一点E，使得二面角E﹣BN﹣M的余弦值为，若存在求出的值，若不存在，请说明理由．21．（12分）设a，b为实数，且a＞1，函数f（x）＝x﹣b log a x+e2，其中e为自然对数的底数．（1）求函数f（x）的单调区间；（2）若对任意b＞2e2，函数f（x）有两个不同的零点，求a的取值范围．22．（12分）已知△ABP的三个顶点在抛物线C：x2＝4y上，F为抛物线C的焦点，点M 为AB的中点，．（1）若|PF|＝，求点M的坐标；（2）求△ABP面积的最大值．2020-2021学年江苏省南京市鼓楼区金陵中学高二（下）期末数学试卷参考答案与试题解析一、单项选择题：本小题共8小题，每小题5分，共计40分．在每小题给出的四个选项中，只有一项是符合题目要求的，请把答案填涂在答题卡相应位置上．1．（5分）已知a∈R，（1+ai）i＝3+i（i为虚数单位），则a＝（ ）A．﹣1B．1C．﹣3D．3【分析】利用复数相等的定义求解即可．【解答】解：因为（1+ai）i＝3+i，即﹣a+i＝3+i，由复数相等的定义可得，﹣a＝3，即a＝﹣3．故选：C．2．（5分）在等比数列{a n}中，“a2＜a3”是“a4＜a5”的（ ）条件A．充要B．充分不必要C．必要不充分D．既不充分也不必要【分析】利用等比数列的通项公式得到a4＝a2•q2，a5＝a3•q2，由q≠0，结合充要条件的定义即可求解．【解答】解：∵等比数列{a n}，∴q≠0，∵a4＝a2•q2，a5＝a3•q2，∴a2＜a3⇔a4＜a5，∴a2＜a3是a4＜a5充要条件，故选：A．3．（5分）已知抛物线x2＝2py（p＞0）上一点M（m，1）到焦点的距离为，则其焦点坐标为（ ）A．B．C．D．【分析】根据抛物线的定义，可得1+＝，求出p，即可求抛物线C的焦点坐标；【解答】解：∵抛物线C：x2＝2py（p＞0）上的一点M（m，1）到焦点F的距离为，∴1+＝，∴p＝1，∴抛物线的焦点坐标为：（0，）．故选：A．4．（5分）已知函数f（x）的图象如图所示，则f（x）的解析式可能是（ ）A．f（x）＝x2+cos x B．f（x）＝x2+sin xC．f（x）＝2x+cos x D．f（x）＝2x+sin x【分析】根据题意，用排除法分析：由函数的奇偶性排除A，计算f（0）的值，排除BC，即可得答案．【解答】解：根据题意，依次分析选项：对于A，f（x）＝x2+cos x，有f（﹣x）＝x2+cos x＝f（x），则函数f（x）为偶函数，不符合题意；对于B，f（x）＝x2+sin x，有f（0）＝0+0＝0，不符合题意；对于C，f（x）＝2x+cos x，有f（0）＝1+1＝2，不符合题意；故选：D．5．（5分）在（1+x）6（1+y）4的展开式中，记x m y n项的系数为f（m，n），则f（3，0）+f （1，2）＝（ ）A．24B．80C．56D．120【分析】由题意根据形定义、二项展开式的通项公式，求得要求式子的值．【解答】解：∵在（1+x）6（1+y）4的展开式中，记x m y n项的系数为f（m，n），则f（3，0）+f（1，2），即x3y0项的系数加上x1y2项的系数，∴f（3，0）+f（1，2）＝•+•＝20+36＝56，故选：C．6．（5分）设0＜a＜，若随机变量X的分布列是：X0a1P则当a在（0，）内增大时（ ）A．V（X）增大B．V（X）先增大后减小C．V（X）减小D．V（X）先减小后增大【分析】利用数学期望的计算公式先求出E（X），然后利用方差的计算公式表示出V（X），再利用二次函数的性质判断单调性即可．【解答】解：由题意可得，E（X）＝（a+1），所以V（X）＝＝＝，所以当a在（0，）内增大时，V（X）减小．故选：C．7．（5分）设椭圆C：+y2＝1（a＞1），已知点A（0，1），点P为曲线C上的点，若|AP|的最大值为2，则a的取值范围为（ ）A．（1，]B．（1，2]C．[，2）D．（，2]【分析】以A（0，1）为圆心，半径为2的圆的方程为x2+（y﹣1）2＝4，只需x2+（y﹣1）2＝4与+y2＝1的交点不超过一个即可，借助图形和判别式求解．【解答】解：以A（0，1）为圆心，半径为2的圆的方程为x2+（y﹣1）2＝4，联立x2+（y﹣1）2＝4与+y2＝1方程可得：（1﹣a2）y2﹣2y﹣3+a2＝0，又∵A（0，1）是椭圆的一个短轴端点，即短轴刚好为2，当△＝0，即a＝时，|AP|的最大值为2，当a时，x2+（y﹣1）2＝4与+y2＝1的交点不止一个，|AP|的最大值大于2，不合题意，∴1＜a＜．故选：A．8．（5分）已知a，b∈R且ab≠0，若对任意的x≤0均有（x﹣a）（x﹣b）（x﹣2a﹣b）≤0，则（ ）A．a＜0B．a＞0C．b＜0D．b＞0【分析】分析可知a，b不可能同时为负，至少有一个为正，然后分①a＞0，b＞0，②a ＞0，b＜0，③a＜0，b＞0讨论得答案．【解答】解：∵ab≠0，∴b≠ab+b，若使对任意的x≤0均有（x﹣a）（x﹣b）（x﹣2a﹣b）≤0，则ab（2a+b）≥0，∴a，b不可能同时为负，至少有一个为正，①若a＞0，b＞0，显然成立；②若a＞0，b＜0，则2a+b≤0，此时要使（x﹣a）（x﹣b）（x﹣2a﹣b）≤0在（﹣∞，0]上恒成立，则必有b＝2a+b，则a＝0，矛盾；③若a＜0，b＞0，则2a+b≤0，此时要使（x﹣a）（x﹣b）（x﹣2a﹣b）≤0在（﹣∞，0]上恒成立，则必有a＝2a+b，则a+b＝0，符合题意；综上，b＞0．故选：D．二、多项选择题本大题共4小题，每小题5分，共20分．在每小题给出的四个选项中，有多项符合题目要求，请把答案填涂在答题卡相应位置上，全部选对得5分，部分选对得2分，不选或有错选的得0分．9．（5分）若直线y＝3a与函数y＝|a x﹣1|（a＞0，且a≠1）的图象有两个公共点，则a可以是（ ）A．2B．C．D．【分析】分类讨论作出两函数的图象，数形结合可得．【解答】解：当0＜a＜1时，y＝|a x﹣1|的图象如图（1）所示，由已知得0＜3a＜1，∴0＜a＜；当a＞1时，y＝|a x+1﹣1|的图象如图（2）所示，由已知可得0＜3a＜1，∴0＜a＜，结合a＞1可得a∈∅．综上可知a的取值范围为（0，）．故选：CD．10．（5分）已知双曲线＝1（a＞0）的左，右焦点分别为F1，F2，一条渐近线方程为y＝，P为C上一点，则以下说法正确的是（ ）A．C的实轴长为8B．C的离心率为C．|PF1|﹣|PF2|＝8D．C的焦距为10【分析】由双曲线的渐近线方程求得a，再由隐含条件求得c，然后逐一核对四个选项得答案．【解答】解：由双曲线＝1（a＞0），得其一条渐近线方程为y＝，又一条渐近线方程为y＝，∴a＝4，则C的实轴长为2a＝8，故A正确；c＝，C的离心率为，故B错误；P为C上一点，则|PF1|﹣|PF2|＝±8，故C错误；C的焦距为2c＝10，故D正确．故选：AD．11．（5分）为庆祝建党100周年，讴歌中华民族实现伟大复兴的奋斗历程，增进全体党员干部职工对党史知识的了解，某单位组织开展党史知识竞赛活动，以支部为单位参加比赛，某支部在5道党史题中（有3道选择题和2道填空题），不放回地依次随机抽取2道题作答，设事件A为“第1次抽到选择题”，事件B为“第2次抽到选择题”，则下列结论中正确的是（ ）A．B．C．D．【分析】利用古典概型的概率公式以及条件概率的概率公式、互斥事件的概率公式求解即可．【解答】解：由题意，事件A为“第1次抽到选择题”，事件B为“第2次抽到选择题”，对于A，＝,故选项A正确；对于B，,故选项B正确；对于C，，故选项C正确；对于D，,，所以,故选项D错误．故选：ABC．12．（5分）已知定义在R上的函数y＝f（x）满足f（﹣x）＝﹣f（x），函数y＝f（x+1）为偶函数，且当x∈[0，1]时，f（x）＝log2（x+a），则下列结论正确的是（ ）A．函数y＝f（x）是周期为4的周期函数B．f（2020）+f（2021）＝1C．当x∈（1，2]时，f（x）＝log2（x+1）D．不等式的解集为【分析】先根据题意得到函数f（x）为奇函数，且是周期为4的周期函数，进而利用函数的性质对选项逐一判断即可．【解答】解：对于选项A，由函数y＝f（x+1）为偶函数得函数y＝f（x）的对称轴为x＝1，故得f（﹣x）＝f（2+x），又，所以f（x+2）＝﹣f（x），从而得f（4+x）＝f（x），所以函数y＝f（x）是周期为4的周期函数，故选项A正确；对于选项B，又奇函数y＝f（x）当x∈[0，1]时，f（x）＝log2（x+a），故得f（0）＝log2a＝0，解得a＝1，所以当x∈[0，1]时，f（x）＝log2（x+1），所以f（2020）+f（2021）＝f（0）+f（1）＝1，故选项B正确；对于选项C，当x∈（1，2]时，2﹣x∈[0，1），所以f（x）＝f（2﹣x）＝log2[（2﹣x）+1]＝log2（3﹣x），故选项C不正确；对于选项D，根据函数的周期性，只需考虑不等式在一个周期[﹣1，3]上解的情况即可．当x∈[0，1]时，由，解得，故得；当x∈（1，2]时，由，解得，故得，综上可得不等式在一个周期[﹣1，3]上的解集为，所以不等式在定义域上的解集为，故选项D正确．综上ABD正确．故选：ABD．三、填空题：本大题共4小题，每小题5分，共20分，请把答案填写在答题卡相应位置上．13．（5分）若a＝log45，则2a+2﹣a＝ ．【分析】直接利用对数运算法则化简求解即可．【解答】解：a＝log45＝log2，则2a+2﹣a＝＝＝．故答案为：．14．（5分）已知{a n}是公差为d的等差数列，{b n}是公比为q的等比数列．若数列{a n+b n}的前n项和S n＝2n2﹣n+2n﹣1（n∈N*），则d+q的值为6．【分析】由{a n+b n}的前n项和S n＝2n2﹣n+2n﹣1（n∈N*），由{a n}是公差为d的等差数列，设首项为a1；求出等差数列的前n项和的表达式；{b n}是公比为q的等比数列，设首项为b1，讨论当q为1和不为1时的前n项和的表达式，由题意可得q≠1，由对应项的系数相等可得d，q的值，进而求出d+q的值．【解答】解：因为{a n+b n}的前n项和S n＝2n2﹣n+2n﹣1（n∈N*），又因为{a n}是公差为d的等差数列，设首项为a1；{b n}是公比为q的等比数列，设首项为b1，所以{a n}的通项公式a n＝a1+（n﹣1）d，所以其前n项和A n＝na1+n（n﹣1）d＝n2+（a1﹣）n，当{b n}中，当公比q＝1时，其前n项和B n＝nb1，所以{a n+b n}的前n项和S n＝A n+B n＝n2+（a1﹣）n+nb1＝2n2﹣n+2n﹣1，显然没有出现2n，所以q≠1，则{b n}的前n项和为B n＝＝﹣，所以S n＝A n+B n＝n2+（a1﹣）n+﹣＝2n2﹣n+2n﹣1，由两边对应项相等可得＝2，a1﹣＝﹣1，q＝2，＝1，解得d＝4，a1＝1，q＝2，b1＝1，所以d+q＝6．故答案为：6．15．（5分）设x＞0，y＞0，则x+4y+的最小值为4．【分析】由基本不等式得x+4y≥2，4+≥2，注意等号要同时取得即可．【解答】解：x+4y≥2＝4（当且仅当x＝4y时，等号成立），4+≥2＝4（当且仅当4＝时，等号成立），故x+4y+≥4（当且仅当4＝且x＝4y，即x＝1，y＝时，等号成立），故x+4y+的最小值为4，故答案为：4．16．（5分）已知函数f（x）是定义在R上的奇函数，当x≥0时，f（x）＝|x﹣a|+|x﹣2a|﹣3a．若对任意的x∈R，都有f（x﹣）≤f（x），则实数a的取值范围为[0，]．【分析】根据题意，由函数的解析式和奇函数的性质作出函数f（x）的草图，f（x﹣）的图象可以由f（x）的图象向右平移的单位得到，由此可得≥6a，解可得a的取值范围，即可得答案．【解答】解：根据题意，当x≥0时，f（x）＝|x﹣a|+|x﹣2a|﹣3a＝，有f（3a）＝6a﹣6a＝0；又由f（x）为奇函数，其草图如图：其图象与x轴3个交点（﹣3a，0）、（0，0），（3a，0），f（x﹣）的图象可以由f（x）的图象向右平移的单位得到，若对任意的x∈R，都有f（x﹣）≤f（x），则有≥6a，解可得：0≤a≤，即a的取值范围为[0，]；故答案为：[0，]．四、解答题：本大题共6小题，共70分．请在答题卡指定区域内作答，解答时应写出必要的文字说明，证明过程或演算步骤．17．（10分）设数列{a n}的前n项和为S n，已知S2＝4，a n+1＝2S n+1，n∈N*．（1）求数列{a n}通项公式；（2）求数列{a n﹣2n+1}的前n项和．【分析】（1）当n＝1时，根据可计算出a1、a2，再根据a n+1＝2S n+1可得a n＝2S n﹣1+1（n≥2），两式相减可知{a n}是等比数列，最后由等比数列的通项公式即可写出a n．（2）令b n＝a n﹣2n+1，又{a n}是等比数列，所以利用分组求和法即可求出数列{b n}的前n项和．【解答】解：（1）由S2＝4，得a1+a2＝4①；又当n＝1时，a2＝2a1+1②，由①②解得a1＝1、a2＝3．当n≥2时，有a n＝2S n﹣1+1，所以a n+1﹣a n＝2（S n﹣S n﹣1）＝2a n，即a n+1＝3a n，所以数列{a n}是以1为首项，3为公比的等比数列，所以a n＝1×3n﹣1＝3n﹣1．（2）令b n＝a n﹣2n+1，则b n＝3n﹣1﹣2n+1，所以{b n}的前n项和为T n＝b1+b2+…+b n，即T n＝30+31+32+…+3n﹣1+（﹣1）+（﹣3）+…+（﹣2n+1）＝+（﹣1﹣2n+1）＝（3n﹣1）﹣n2．18．（12分）在1，2，3…，9，这9个自然数中，任取3个数．（Ⅰ）求这3个数中，恰有一个是偶数的概率；（Ⅱ）记ξ为这三个数中两数相邻的组数，（例如：若取出的数1、2、3，则有两组相邻的数1、2和2、3，此时ξ的值是2）．求随机变量ξ的分布列及其数学期望Eξ．【分析】（I）由题意知本题是一个古典概型，试验发生包含的所有事件是从9个数字中选3个，而满足条件的事件是3个数恰有一个是偶数，即有一个偶数和两个奇数．根据概率公式得到结果．（2）随机变量ξ为这三个数中两数相邻的组数，则ξ的取值为0，1，2，当变量为0时表示不包含相邻的数，结合变量对应的事件写出概率和分布列，算出期望．【解答】解：（I）由题意知本题是一个古典概型，试验发生包含的所有事件是C93，而满足条件的事件是3个数恰有一个是偶数共有C41C52记“这3个数恰有一个是偶数”为事件A，∴；（II）随机变量ξ为这三个数中两数相邻的组数，则ξ的取值为0，1，2，当变量为0时表示不包含相邻的数P（ξ＝0）＝，P（ξ＝1）＝，P（ξ＝2）＝∴ξ的分布列为ξ012p∴ξ的数学期望为．19．（12分）已知函数f（x）＝2x3﹣3（a+1）x2+6ax+b，其中a，b为实数．（1）若函数f（x）的图象与x轴相切于点（2，0），求a，b的值；（2）若a≥1，且f（x）在区间（﹣2，2）上取到最大值，求a的取值范围．【分析】（1）根据导数的几何意义可得，解方程组可得答案；（2）根据导数符号与函数单调性之间的关系，分类讨论函数的单调性，进而讨论最值在何时取得即可．【解答】解：（1）f′（x）＝6x2﹣6（a+1）x+6a＝6（x﹣1）（x﹣a），因为函数f（x）的图象与x轴相切于点（2，0），所以，即，解得．（2）当a⩾2时，易知函数f（x）在（﹣2，1）上单调递增，在（1，2）上单调递减，则f（1）为f（x）在（﹣2，2）上的最大值，满足题意；当a＝1时，f′（x）⩾0恒成立，所以f（x）在（﹣2，2）上单调递增，因此f（x）在（﹣2，2）上没有最大值，不满足题意；当1＜a＜2时，f（x）在（﹣2，1）上单调递增，在（1，a）上单调递减，在（a，2）上单调递增，若f（x）在（﹣2，2）上取到最大值，则必有f（1）⩾f（2），解得，又1＜a＜2，于是．综上所述，a的取值范围为．20．（12分）如图所示，正方形ABCD所在平面与梯形ABMN所在平面垂直，MB∥AN，NA ＝AB＝2，BM＝4，CN＝2．（1）证明：MB⊥平面ABCD；（2）求直线AC与平面CDM所成角的正弦值；（3）在线段CM上是否存在一点E，使得二面角E﹣BN﹣M的余弦值为，若存在求出的值，若不存在，请说明理由．【分析】（1）由BC⊥AB，平面ABCD⊥平面ABMN，知BC⊥平面ABMN，有BC⊥BM，由勾股定理的逆定理可证MB⊥AB，再根据线面垂直的判定定理，得证；（2）以B为原点建立空间直角坐标系，求得平面CDM的法向量，设直线AC与平面CDM所成角为θ，由sinθ＝|cos＜，＞|，得解；（3）设＝λ，λ∈[0，1]，求得平面向量BEN的法向量，由BC⊥平面ABMN，知平面BMN的一个法向量为＝（0，0，1），再由|cos＜，＞|＝，即可得解．【解答】（1）证明：∵正方形ABCD，∴BC⊥AB，∵平面ABCD⊥平面ABMN，且平面ABCD∩平面ABMN＝AB，∴BC⊥平面ABMN，∴BC⊥BM，BC⊥BN，∴BN＝＝＝2，又NA＝AB＝2，∴NA2+AB2＝BN2，即AN⊥AB，∵MB∥AN，∴MB⊥AB，∵BC∩AB＝B，BC、AB⊂平面ABCD，∴MB⊥平面ABCD．（2）解：以B为原点，BA，BM，BC所在直线分别为x，y，z轴建立如图所示的空间直角坐标系，则B（0，0，0），A（2，0，0），C（0，0，2），D（2，0，2），M（0，4，0），N（2，2，0），∴＝（﹣2，0，2），＝（2，0，0），＝（0，4，﹣2），设平面CDM的法向量为＝（x，y，z），则，即，令z＝2，则x＝0，y＝1，∴＝（0，1，2），设直线AC与平面CDM所成角为θ，则sinθ＝|cos＜，＞|＝||＝||＝，故直线AC与平面CDM所成角的正弦值为．（3）解：设＝λ，λ∈[0，1]，则E（0，4λ，2﹣2λ），∴＝（2，2，0），＝（0，4λ，2﹣2λ），设平面向量BEN的法向量为＝（x1，y1，z1），则，即，令x＝1，则y＝1，z＝，∴＝（1，1，），由（1）知，BC⊥平面ABMN，∴平面BMN的一个法向量为＝（0，0，1），∵二面角E﹣BN﹣M的余弦值为，∴|cos＜，＞|＝||＝，即||＝，化简得，3λ2+2λ﹣1＝0，解得λ＝或﹣1（舍负），∴＝，即＝．21．（12分）设a，b为实数，且a＞1，函数f（x）＝x﹣b log a x+e2，其中e为自然对数的底数．（1）求函数f（x）的单调区间；（2）若对任意b＞2e2，函数f（x）有两个不同的零点，求a的取值范围．【分析】（1）对函数f（x）求导，然后分b≤0及b＞0讨论导函数与0的关系，即可得到单调性情况；（2）分析可知，f（x）min＜0，即b﹣b（lnb﹣ln（lna））+e2lna＜0对任意b＞2e2均成立，令g（b）＝b﹣b（lnb﹣ln（lna））+e2lna，对g（b）求导，再研究其单调性及取值情况即可．【解答】解：（1）函数的定义域为（0，+∞），，当b≤0时，f′（x）＞0，f（x）在（0，+∞）上单调递增；当b＞0时，令f′（x）＜0，解得，令f′（x）＞0，解得，∴f（x）在上单调递减，在上单调递增；综上所述，当b≤0时，f（x）的单调递增区间为（0，+∞）；当b＞0时，f（x）的单调递减区间为，单调递增区间为；（2）由（1）可知，当b＞2e2时，f（x）的单调递减区间为，单调递增区间为，∵函数f（x）有两个不同的零点，∴必有，即，即b﹣b（lnb﹣ln（lna））+e2lna＜0对任意b＞2e2均成立，令g（b）＝b﹣b（lnb﹣ln（lna））+e2lna，则g′（b）＝ln（lna）﹣lnb，∴g（b）在（0，lna）上单调递增，在（lna，+∞）上单调递减，若lna＞2e2，则，不合题意；若lna≤2e2，则g（b）在（2e2，+∞）上单调递减，则g（2e2）＜0，即2e2﹣2e2（2+ln2﹣ln（lna））+e2lna≤0，整理得2ln（lna）+lna≤2ln2+2，又y＝2lnx+x在（0，+∞）上单调递增，∴1＜a≤e2，又当0＜x＜1时，g（x）＞0，且，∴存在x∈（x0，+∞），使得f（x）＞0，由函数的单调性及零点存在性定理可知，当1＜a≤e2时，函数f（x）有两个不同的零点．故实数a的取值范围为（1，e2]．22．（12分）已知△ABP的三个顶点在抛物线C：x2＝4y上，F为抛物线C的焦点，点M 为AB的中点，．（1）若|PF|＝，求点M的坐标；（2）求△ABP面积的最大值．【分析】（1）根据抛物线的定义，利用条件|PF|＝，建立方程关系即可求点M的坐标；（2）设直线AB的方程为y＝kx+m，A（x1，y1），B（x2，y2），联立方程求得AB的中点M的坐标为（2k，2k2+m），由．得（﹣x0，1﹣y0）＝（2k，2k2+m﹣1），由△＞0，k2≥0得﹣1＜m≤2．S△ABP＝2S△ABF＝4|m﹣1|＝＝，利用导数即可求解．【解答】解：（1）由题意知焦点F（0，1），准线方程为y＝﹣1，设P（x0，y0），由抛物线的定义可知|PF|＝y0+1＝，解得y0＝，∵x＝4×＝2，∴x0＝．∴P（，），∵．∴，，∴M（，）．（2）设直线AB的方程为y＝kx+m，A（x1，y1），B（x2，y2），由，得x2﹣4kx﹣4m＝0，于是△＝16k2+16m＞0，x1+x2＝4k，x1x2＝﹣4m，即AB的中点M的坐标为（2k，2k2+m）由．得（﹣x0，1﹣y0）＝（2k，2k2+m﹣1），∴x0＝﹣2k，y0＝2﹣2k2﹣m，∵x＝4y0，∴（﹣2k）2＝4（2﹣2k2﹣m），∴12k2＝8﹣4m≥0，由△＞0，k2≥0得﹣1＜m≤2．又∵|AB|＝4，点F到直线AB的距离d＝∴S△ABP＝2S△ABF＝4|m﹣1|＝＝，设f（m）＝m3﹣m2﹣m+1，（﹣1＜m≤2），则f'（m）＝9m2﹣10m+1＝0，解得m1＝﹣，m2＝1，于是f（m）在（﹣1，﹣）是增函数，在（﹣，1）上是减函数，在（1，2）上是增函数，f（﹣）＝，f（2）＝，所以△ABP面积的最大值为×＝4．。

江苏省金陵中学2020至2021学年第二学期高二期中考试高二英语试卷第一部分听力（共两节20小题，每小题分，满分30分）第一节（共5小题；每小题分，满分分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How will the woman deal with the machine?A. She will repair it herself.B. She will ask the man to repair it.C. She will find a repairman to repair it.2. Where is the man going next?A. To his dormitory.B. To the library.C. To the lecture room.3. How long is the girl’s father’s bus iness trip?A. Five weeks.B. Three weeks.C. Two weeks.4. What did the boy do yesterday evening?A. He watched a tennis match.B. He did his homework.C. He talked on the phone.5. Where are the speakers?A. On the road.B. At a police station.C. In a garage.第二节（共15小题；每小题分，满分分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

英语试题本试卷满分120分第I卷第一部分英语知识运用（百强校英语解析团队专供）（共三节，满分50分）第一节听力理解（共20题，每小题0.5分，满分10分）做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Why is Ann so upset？A. She failed one of her exams.B. She is worrying about other lesson.C. She has no time to do her math homework.2. What type of food does the woman cat？A. Junk food.B. Healthy food.C. Delivered food.3. What will the man probably do to stay warm？A. Use a blanket.B. Turn on the heater.C. Drink some hot chocolate.4. What are the speakers mainly talking about？A. The man’s career.B. The man’s travel plan.C. The man’s plan after graduating.5. What are the s peakers’ opinions about the painting？A. It’s simple.B. It’s colorful.C. It’s complex.听下面5段对话。

每段对话后有几个小题，从题中所给的A、B、C、三个选项中选出最佳选项，并标在试卷的相应位置，听每段对话前，你将有时间阅读各个小题，每小题5秒钟：听完后，各小题给出5秒钟的作答时间。

2020-2021学年⾼⼆下学期期末考试英语试题含答案第I卷第⼀部分：英语知识运⽤(共四节,满分50分)第⼀节语⾳知识(共5⼩题；每⼩题1分, 满分5分) 从每⼩题的A、B、C、D四个选项中,找出其划线部分与所给单词的划线部分读⾳相同的选项,并在答题卡上将该选项涂⿊.1. means A. socialist B. constitutionC. usualD. sometimes2. stable A. absorb B. amazementC. actionD. lantern3 album A. climb B.doubtC. beatD. debt4. abrupt A. pulse B. acuteC. glueD. musical5. expectation A. exactly B. extraC. examinationD. except第⼆节情景对话(共5⼩题；每⼩题l分,满分5分) 根据对话情景和内容,从对话后所给的选项中选出能填⼈每⼀空⽩处的最佳选项,并在答题卡上将该选项涂⿊.选项中有两个为多余选项.Peter: Oh, it’s nine o’clock. 6Monica: 7 We are on holiday.Peter: I have to meet Mary at the airport.Monica: 8Peter: At about ten o’clock.Monica: Just stay a little longer and have another cup of tea. It’s fresh and wonderful.Peter: I am sorry I can’t. Thank you just the same. I would be late if I have it.Monica: 9Peter: I have enjoyed the meal very much. It was delicious.Monica: Thank you. 10A. What a pity that you have to leave so soon.B. Why so soon?C.I’m so happy.D.What time is she arriving?E.I must be off now.F.I’m so glad you like it.G. She is coming with her cousins.第三节语法和词汇知识(共10⼩题；每⼩题l分,满分l0分) 从每⼩题的A、B、C、D四个选项中,选出可以填⼊空⽩处的最佳选项,并在答题卡上将该选项涂⿊.11. Have you ever found ______ flash drive has noenough space? Better replace it for ______ bigger one.A. the; theB. a; aC. a;the D. the; a12. —How I wish I had worked harder before theexaminations.—If you had，you________them already.A. would passB. would have passedC.were to pass D. will have passed13. To our relief, at last the opening ceremony of thesports meeting we had been looking forward to___________on time.A. had startedB. startingC. startedD. being started14. _________her son has passed the driving test makesher very happy.A. ThatB. WhatC.Whether D. Because15. I took a risk to carry out the project. Foutunately, it_________ in the end.A. paid upB. paid outC.paid off D.paid back16. Teachers in senior high schools can’t go out veryoften as their work _________ almost all their time.A. take inB. take upC.take over D.take on17. As far as I see, _______ is no possibility _________ hewill win the tennis match this time.A. it; thatB. there; thatC.it; whether D. there; whether18. When you rewrite the paragraph, I advise you toleave out __________ is thought unnecessary or misleading.A. whatB. thatC. thoseD. which19. It rained heavily in the south,______ serious floodingin several provinces.A. causedB. having causedC. causingD. to cause20. On arriving at the earthquake-stricken area, thevolunteers began to involve themselves in some rescue work _____ the heavy rain.A. even ifB. in case ofC.regardless of D. because of第四节完形填空（共20⼩题；每⼩题1.5分,满分30分）阅读下⾯短⽂,从短⽂后各题的A, B, C, D四个选项中,选出合适填⼊对应空⽩处的最佳选项,并在答题卡上将该选项涂⿊.Years ago, I worked at the Ringling Brothers Barnum & Bailey Circus (马戏团). One day, as I was passing the elephants, I suddenly stopped, 21 by the fact that these huge creatures were being held by only a small rope tied to their front leg. It was 22 that they could, at any time, break free, 23 strangely enough, they didn’t. I asked a trainer the 24 for this.He said, “When they were very young we used the 25 size rope, and it was enough to hold them. As they grow up, theybelieve the rope can 26 hold them, so they never try.”Like the elephants, how many of you believe you cannot do a thing, simply because you 27 once before？Do you often tell 28 “I cannot dance”or “I’m not good at math”？These are 29 of self limiting beliefs.You must realize you’re 30 for them. A limiting belief that saysyou’re poor at math may have 31 as a reaction to the embarrassing experiences related to math, or the remarks made by someone important to you which 32 you.The cool thing is that because you create the 33 you can choose to change it！Here is how:First, 34 it with “I am good at math”. Once you change your 35 , your subconsciousness (潜意识) will make this come true by driving you to 36 . That might be to take a math course or to go online 37 help, etc.Gradually you’ll really see your math skills are 38 .This is such a simple process that you can 39 it today. Don’t be like the poor elephants and make your life 40 at a place because of a limiting belief you developed years ago.21. A.excited B.confusedC.discouragedD.worried22. A.impossible B.doubtfulC.uncertainD.obvious23. A. and B.orC.butD.so24. A result B. reasonC.caseD.choice25. A.smaller B.biggerC.sameD.different26. A.still B.almostC.narrowlyD.hardly27. A.did B.failedC.triedD.succeeded28. A.yourself B.othersC.your teacherD.your partner29. A.causes B.storiesC.resultsD. examples30. A.responsible B.honestC.consciousD.depended31. A.stopped B.originatedC.changedD.referred32. A.interested B.inspiredC .bored D.disappointed33. A.belief B.experienceC.embarrassmentD.remark34. A.represent /doc/c8127e610129bd64783e0912a216147916117ed2.html pareC.mixD.replace35. A.action B.thoughtC.aimD.plan36. A. think B. actC.quitD.win37. A.at B.byC.forD.in38. A.recognized B.judgedC.realizedD. improved39. A.begin B.continueC.keepD.finish40. A.unfinished B.involved C. stuck D.changed第⼆部分：阅读理解(共两节,满分30分)第⼀节(共10⼩题；每⼩题2分,满分20分)阅读下列三篇短⽂,从每⼩题后所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该选项涂⿊.A One of the sailors who sailed with Christopher Columbus on his second voyage to the New World was a man named Juan Ponce de Leon. This voyage changed his life.He decided to stay when Columbus returned. Ponce was named governor of Puerto Rico (then called Boriquien) in 1508. While there, he heard many stories of a magical water source. People called it the Fountain of Youth and said that drinking its water kept you young.For the next few years, Ponce tried to find out where the Fountain of Youth was. He asked permission from Spain's King Charles V to go in search of it. The king consented, as long as Ponce paid for the ships and crew himself.The young explorer did so readily, and they set off. It was March 1513. They sailed for days but didn't see the fountain. On March 27, he came within sight of the Florida coast. On April 2, he landed at what he named St. Augustine. This was the first Spanish settlement on the mainland of North America.He had several adventures along the way. He did not, however, find the Fountain of Youth. He returned to Boriquien.He continued to govern tile island, and he continued to hear stories of the Fountain of Youth. Finally, in 1521, he set out again.This time, he landed on the Florida coast again. While he and his men were building houses for a new settlement, they were attacked by native tribesmen（部落成员）. Many of his men died, but Ponce escaped, although he was injured. He reached Cuba and entered a hospital, where he died of wounds from the attack in Florida. Juan Ponce de Leon never found the Fountain of Youth. Neither did anyone else, at least as far as we know.41. Ponce's voyage to the New World with Columbus______________.A. affected his future life greatlyB. made him forget the way backC. was supported by Charles V financiallyD. was to find the Fountain of Youth42. The underlined word "consented" in Paragraph 4probably means_____________.A. agreedB. opposedC. doubtedD. succeeded43. According to the passage, Ponce_____________.A. became governor of Boriquien in 1513B. found the Fountain of Youth in 1521C. arrived in Florida twiceD. didn't show much interest in the Fountain of Youth44. According to the last paragraph we can know that______________.A. Ponce managed to escape from native tribesmen's attack without any injuryB. Ponce died in Florida in 1521C. his men weren't well received by native tribesmen in FloridaD. people found the Fountain of Youth after Ponce's deathBThere is plenty for kids and teens to do in the Syracuse area during the summer, including some great educational opportunities. Here are the top four.Rosamond Gifford Zoo CampThe zoo offers separate camps for kids. The camps for kindergarteners run from 9 am to 12:30 pm, and cost $115 for zoo members and $135 for non-members. Kids entering 7th and 8th grades will have half a day from 1 pm to 4:30 pm. The cost is $149 for members and $160 for non-members. All camps feature numerous educational activities and animal encounters. The camps run from August 14 to August 19. Registration starts from July 10 for members and July 15for non-members.Active Learning Services at Christian Brothers AcademyFrom August 1 to August 5, Christian Brothers Academy will host Active Learning Services from USA Chess. Topics of learning will include Chess Camp (age 5-15), and Video Game Creation Program (age 8-15). Chess Camp promises improved chess skills through chess instructors utilizing demo(演⽰) boards and historic games. Half day sessions will cost $280 for the Computer Camps. A full day of Chess costs $400, and a half day of Chess followed by a half day of Computer Camps cost $430.Syracuse University Summer CollegeFrom July 5th to August 12th, Syracuse University will host pre-college programs for high school students. The Summer College will offer a wide variety of programs including architecture, engineering and computer science, public communications, and eco-fashion. The progams are taught by the teachers of Syracuse University and include hands-on activities. The costs range from $2325 to 7624.The Sheldon Institute at SUNY OswegoThe State University of New York will hold two-week educational enrichment programs for students entering grades2-4 from July 25 to August 5. Children will have a set program featuring art, science, technology, cultural appreciation and writing. Tuition for the programs is only $320 and a downloadable application is available.45. If a preschool boy and his 8th-grade brother attend the Zoo Camps, they should pay___________.A. $264B. $275C. $295D. It depends.46. What do we know about the Chess Camp from the passage?A. It will last for two weeks.B. Only children aged 8-15 can attend it.C. Whole day sessions will cost $250 for it.D. Children can learn improved chess skills through it.47. Where can children attend the largest number of programs with low cost?A. Christian Brothers AcademyB. Rosamond Gifford ZooC. The Sheldon InstituteD. Syracuse UniversityCSchools are still free to pass the potato. On Tuesday, the U.S. Senate voted to block a proposal(提议) by the U.S. Department of Agriculture (USDA) would have limited the amount of potatoes and other starchy(富含淀粉的) vegetables served in schools. And those vegetables high in carbohydrates(碳⽔化合物) would also have been banned from school breakfast. The USDA had wanted to make the changes to the federal school lunch program.The Senate’s amendment(修正案) blocks the USDA from putting any limits on amount of servings of potatoes or othervegetables in school lunches. Senator Susan Collins of Maine, a potato—growing state, supported amendment. “USDA’s proposed rule would have put significant and needless costs on our nation’s school districts at a time when they can least afford it,”Collins said.Those in favor of potato limit say that children getenough potatoes already and should be encouraged to try other vegetables. The centre for science in the Public Interest pushed for the restrictions. “USDA’s proposal was about helping kids to eat a very wide variety of vegetables, and I think that opinion has been lost in all this,”said the Center’s Margo Wootan, “Other vegetables have a hard time competing with potatoes.”The proposed change upset potato growers, who believed potatoes were being unfairly targeted. Some schools have criticized the USDA’s attempt to tell them exactly what foods they can or can’t serve. Critics say the USDA should focus on advising schools on how to prepare the potato instead. Potatoes can be a good source of fiber. Many schools already prepare French fries with less grease(油脂) and serve potatoes in healthier ways.The USDA is expected to release a final list of guidelines for the federal school lunch program next year. Senator Mark Udall of Colorado, another potato—growing state, also supported the amendment that blocked the potato limit. “This amendment seeks to ensure flexibility for schools to provide nutritious and affordable school meals.”he said.48. What is the content of the proposal put forward by the USDA?A. Reducing the amount of starch vegetables served in schools.B. Reducing the amount of vegetables served in schools.C. Supporting serving potatoes in school.D. Stopping serving starchy vegetables in schools.49. One reason for blocking the proposal is that________. .A. the proposal will put needless costs on nation’s school districtsB. children like eating potatoes.C. there aren’t enough other vegetables for childrenD. other vegetables will have a hard time competing with potatoes.50. What’s the main idea of the passage?A. Food supplies in America affect students.B. Potatoes served in school will be limited.C. A project on the students’health is carried out.D.A proposal is blocked by the U.S. Senate.第⼆节(共5⼩题；每⼩题2分,满分l0分)根据短⽂内容,从下框的A～F选项中选出能概括每⼀段主题的最佳选项,并在答题卡上将该选项涂⿊.选项中有⼀项为多余项.China must become more livable to retain top talent51. _______________________China has to transform from an "economic power" to a "livable power" in order to keep its wealth, talent and confidence.The "2011 China Private Wealth Report," released recently by China Merchants Bank, shows that nearly 60 percent of the respondents(调查对象) whose investment exceed (超越）10 million yuan have plans to emigrate (移居外国）by investing.52. _______________________Human migration is not a new phenomenon. From the Euro-Asian Silk Road to Columbus's Discovery of the New World, migrants have brought about cultural communications and economic exchanges across the world. Migration has become an important driving force for social progress.53. _______________________Nowadays, economic globalization has considerably improved the freedom and increased the attractiveness of migration from one country to another.A certain degree of Chinese emigration can not only offer more opportunities in personal life, employment and investment but also boost（促进）the exchange and cooperation between China and other countries.54._______________________However, the factors of the emigration wave should also be figured out.The topic of emigration seems serious because this new wave has to some extent reflected some “unlivable”factors in China. The reasons provided by Chinese emigrants include helping their children to avoid domestic exam-oriented education, obtaining a healthy living environment and sound social security, seeking a sounder investment environment and getting rid of the "anti-rich" atmosphere arising from the inequality in wealth.55. _______________________In order to curb（控制）the wave of emigration, China should further deepen social and economic reforms, improve its educational system to guarantee children'shealth and happiness, as well as strengthen the protection of private wealth through legislation. Furthermore, China shouldalso improve the social security system to increase people's happiness, crack down on corruption and promote social justice and equity so as to uphold the dignity of ordinary citizens. Only in this way can China retain its wealth, talent and confidence and curb the overheated immigration wave.第II卷第三部分：写作(共三节, 满分40分)第⼀节单词拼写(共10⼩题；每⼩题1分，满分10分) 根据下列各句句意和空⽩之后的汉语提⽰词，在答题卡指定区域的横线上写出对应单词的正确、完整形式，每空只写⼀词。

江苏省南京市区中学2020年高二英语下学期期末试题含解析一、选择题1. Don’t worry . I’ll get the computer and get someone it to you tomorrow .A. repaired ; sendB. to repair ; to sendC. repair ; sendD. repaired ; to send参考答案：D46. We should carefully _________ the case, and we cannot declare the matter closed before it is thoroughly settled.A. delayB. claimC. remindD. investigate参考答案：D略12. Even a mighty express train can be held up by signals. Which of the following words can be used to replace “held up”?A. delayedB. slowed upC. haltedD. retarded参考答案：A略4. ---How dare she do that?--- to what you did，whatever she did Was reasonable．What’s more，it is none of your business．Can’t you get down to your lessons?A．Comparing，doing B．Comparing，do C．Compared，doing D．Compared, do 参考答案：C5. —You’d better keep quiet in class.—Sometimes I . yesterday, I was very quiet during my English class.A. wouldB. doC. didD. have参考答案：B6. It will be a long time before you _______ the new circumstances.A. adapt toB. will get used toC. used toD. got accustomed to参考答案：A7. So quickly ____ popular that some people who think his style is vulgar（庸俗的）are worried.A. has Xiao Shengyang becomeB. Xiao Shenyang has becomeC. had Xiao Shengyang becomeD. Xiao Shenyang became参考答案：A8. The Summer Olympics run for about two weeks and the summer athletic events are______ five categories.A. divided intoB. put intoC. cut intoD. broke into参考答案：A9. These questions are difficult for children ______.A. to replyB. replyingC. to be repliedD. to reply to.参考答案：D考查固定搭配和动词的用法。

江苏省南京市2020-2021学年高二下学期六校联考期末英语试卷第一部分阅读理解（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。

ASingapore is a very modern country in Southeast Asia. If you’ve been traveling in its capital city, Singapore, it can be a shock when it comes to accommodation prices. For backpackers they have no choice but to stay outside of the central area. If you are a visitor, I think it’s best to stay in the historic central area to make the most of your time. For first-timers I have put together this list of the best areas to stay in Singapore.ChinatownChinatown is where the original community of Chinese immigrants settled in Singapore. The area is lined with Chinese stores, markets, and great places to eat for all budgets. It lies next to the downtown area and there is a variety of accommodation choices, from hostels (招待所) to 5-star hotels.Little IndiaLittle India is where most of the original Indian migrants made their home. Today it is still famous for temples, markets, and lots of places to eat delicious Indian foods. It’s the most popular spot for backpackers and there are some good mid-range choices here.Kampong GlamA short walk from Little India is the Kampong Glam area. This is where Arab traders set up shops, with street names such as Haji Lane, Baghdad St, and Arab St. The neighborhood is now one of the trendiest in Singapore.Changi AirportWith one of the biggest airports in the region, the chances are you might just be passing without time to stay. Changi Airport is awarded as one of the best in the world, so if you have to do an overnighter at an airport, then you couldn’t have a better experience than at Changi. I didn’tget any sleep but it was an enjoyable stay for an airport.1. What will make backpackers disappointed in Singapore?A. The remote location of the hotels.B. The system of accommodation.C. The high charges of the hotels.D. The accommodation with poor facilities.2. Which area is close to the center of Singapore?A. Chinatown.B. Little India.C. Changi Airport.D. Kampong Glam.3. What do we know about Changi Airport?A. It witnesses a noisy environment.B. It has gained a fairly good reputation.C. It offers passengers worse service.D. It is the biggest airport in Singapore.『答案』1. C 2. A 3. B『分析』这是一篇应用文。