一-武汉市第十四中学

2025届湖北省武汉市第十四中学数学七上期末达标检测模拟试题考生须知：1．全卷分选择题和非选择题两部分，全部在答题纸上作答。

选择题必须用2B 铅笔填涂；非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。

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3．保持卡面清洁，不要折叠，不要弄破、弄皱，在草稿纸、试题卷上答题无效。

一、选择题(每小题3分,共30分) 1．把方程213148x x--=-去分母后，正确的结果是（ ） A ．2x -1=1-（3-x ） B ．2（2x -1）=1-（3-x ） C ．2（2x -1）=8-3+xD ．2（2x -1）=8-3-x2．下列成语中，表示必然事件的是（ ） A ．旭日东升B ．守株待兔C ．水中捞月D ．刻舟求剑3．下列等式变形正确的是（ ） A ．若a ＝b ，则a-3＝3-b B ．若x ＝y ，则x a ＝yaC ．若a ＝b ，则ac ＝bcD ．若ba dc =，则bc ＝ad4．计算|﹣3|的结果是（ ） A ．3B ．13C ．﹣3D ．13-5．如图，数轴上蝴蝶所在点表示的数可能为（ ）A ．3B ．2C ．1D ．－16．已知下列结论：①若0a b +=，则a 、b 互为相反数；②若0ab >，则0a >且0b >；③+=+a b a b ；④绝对值小于10的所有整数之和等于0；⑤3和5是同类项．其中正确的结论的个数为（ ） A ．2B ．3C ．4D ．57．将正偶数按图排成5列：A ．第250行，第1列B ．第250行，第5列C ．第251行，第1列D ．第251行，第5列8．一个几何体的表面展开图如图所示，这个几何体是( )A ．正方体B ．三棱锥C ．四棱锥D ．圆柱9．有理数a 、b 在数轴上的位置如图所示，则化简|a ﹣b |+a 的结果为（ ）A ．bB ．﹣bC ．﹣2a ﹣bD ．2a ﹣b10．已知1639nx y 与41232mx y 的和是单项式，则m n +的值是（ ） A ．5B ．6C ．7D ．8二、填空题(本大题共有6小题，每小题3分，共18分) 11．已知2n x =，则3n x =__________． 12．在（）里填上“＞”、“＜”或“=”．37×45（___）37 25÷78（___）25 56×115（___）43÷113 13．如图，将一张长方形的纸片沿折痕EF 翻折，使点C 、D 分别落在点M 、N 的位置，且∠AEN=13∠DEN ，则∠AEF 的度数为_______．14．如果一个角的补角是11526'︒，那么这个角的余角是__________．15．一家商店某种裤子按成本价提高50%后标价，又以八折优惠卖出，结果每条裤子获利10元，则这条裤子的成本是_________．16．将正偶数按下表排成5列：第一行 2 4 6 8 第二行 16 14 12 10 第三行 18 20 22 24 第四行 32 30 28 26根据上表排列规律，则偶数2020应在第_________列． 三、解下列各题(本大题共8小题，共72分)17．（8分）在如图所示的方格纸中，每个小正方形的边长为1，每个小正方形的顶点都叫做格点．△ABC 的顶点A 、B 、C 都在格点上．(1)过B 作AC 的平行线BD ．(2)作出表示B 到AC 的距离的线段BE ．(3)线段BE 与BC 的大小关系是：BE BC (填“＞”、“＜”、“=”)． (4)△ABC 的面积为 ．18．（8分）把一些图书分给某班学生阅读，如果每人分3本则剩余20本；如果每人分4本，则还缺25本．这个班有多少学生？19．（8分）解方程()()633262x x x --=-+．20．（8分）迪雅服装厂生产一种夹克和T 恤，夹克每件定价100元，T 恤每件定价50元．厂方在开展促销活动期间，向客户提供两种优惠方案：①买一件夹克送一件T 恤；②夹克和T 恤都按定价的80%付款．现某客户要到该服装厂购买夹克30件，T 恤x 件（x ＞30）．（1）若该客户按方案①购买，夹克需付款 元，T 恤需付款 元（用含x 的式子表示）；若该客户按方案②购买，夹克需付款 元，T 恤需付款 元（用含x 的式子表示）； （2）若x=40，通过计算说明按方案①、方案②哪种方案购买较为合算？（3）若两种优惠方案可同时使用，当x=40时，你能给出一种更为省钱的购买方案吗？试写出你的购买方案，并说明理由．（1）如图1，若AB =6cm ，BC =4cm ，D 为线段AC 的中点，求线段DB 的长度； （2）如图2，若BD =14AB =13CD ，E 为线段AB 的中点，EC =12cm ，求线段AC 的长度．22．（10分）如图所示，直线//,AB CD EOF ∠的顶点在,AB CD 之间且090E F ∠=︒，若135∠=︒，求2∠的度数．23．（10分）如图，已知A ，O ，B 三点在同一条直线上，OD 平分∠AOC ，OE 平分∠BOC ．（1）若∠BOC=62°，求∠DOE 的度数； （2）若∠BOC=α，求∠DOE 的度数；（3）通过（1）(2)的计算，你能总结出什么结论,直接简写出来，不用说明理由.24．（12分）如图，点C 在线段AB 上，AC=6cm ，MB=10cm ，点M 、N 分别为AC 、BC 的中点．（1）求线段BC 的长； （2）求线段MN 的长；（3）若C 在线段AB 延长线上，且满足AC ﹣BC=b cm ，M ，N 分别是线段AC ，BC 的中点，你能猜想MN 的长度吗？请写出你的结论（不需要说明理由）参考答案一、选择题(每小题3分,共30分) 1、C【解析】分析：方程两边乘以8去分母得到结果，即可做出判断．详解：方程去分母得：2（2x ﹣1）=8﹣3+x ． 故选C ．点睛：本题考查了解一元一次方程，其步骤为：去分母，去括号，移项合并，将x 系数化为1，即可求出解． 2、A【分析】根据事件发生的可能性大小判断相应事件的类型． 【详解】解：A ，旭日东升是必然事件； B 、守株待兔是随机事件； C 、水中捞月是不可能事件； D 、刻舟求剑是不可能事件； 故选：A ． 【点睛】本题考查的是必然事件、不可能事件、随机事件的概念．必然事件指在一定条件下，一定发生的事件．不可能事件是指在一定条件下，一定不发生的事件，不确定事件即随机事件是指在一定条件下，可能发生也可能不发生的事件． 3、C【分析】根据等式的性质，依次分析各个选项，选出变形正确的选项即可． 【详解】解：A ．若a b =，则33a b -=-，A 项错误，B ．若x y =，当0a =时，x a 和ya无意义，B 项错误， C ．若a b =，则ac bc =，C 项正确，D ．若ba dc =，但bc ＝ad 不一定成立，D 项错误，故选：C ． 【点睛】本题考查了等式的性质，正确掌握等式的性质是解题的关键． 4、A【分析】根据绝对值的性质进行计算. 【详解】解：∵|−1|=1． 故选A ． 【点睛】5、D【分析】直接利用数轴得出结果即可．【详解】解：数轴上蝴蝶所在点表示的数可能为-1，故选D．【点睛】本题考查了有理数与数轴上点的关系，任何一个有理数都可以用数轴上的点表示，在数轴上，原点左边的点表示的是负数，原点右边的点表示的是正数，右边的点表示的数比左边的点表示的数大.6、B【分析】①根据相反数的定义判断；②根据有理数的乘法法则判断；③根据绝对值的定义判断；④根据绝对值的定义判断；⑤根据同类项的定义判断．【详解】解：①若a+b=0，则a、b互为相反数，故①的结论正确；②若ab＞0，则a＞0且b＞0或a＜0且b＜0，故②的结论错误；③当a与b异号时，|a+b|≠|a|+|b|，故③的结论错误；④绝对值小于10的所有整数之和等于0，故④的结论正确；⑤3和5是同类项，故⑤的结论正确．综上所述，正确的有①④⑤共3个．故选：B．【点睛】本题主要考查了相反数的定义，绝对值的定义以及同类项的定义，熟记相关定义是解答本题的关键．7、D【分析】根据偶数的特点求出2008在这列数中的序号是1004，然后根据每一行数都是4个，求出第1004个所在的行数以及是第几个，从而即可得解．【详解】解：∵所在数列是从2开始的偶数数列，∴2008÷2=1004，即2008是第1004个数，∵1004÷4=251，∴第1004个数是第251行的第4个数，观察发现，奇数行是从第2列开始到第5列结束，∴2008应在第251行，第5列．故选：D．本题是对数字变化规律的考查，根据题目信息得出每4个数为1行，奇数行从第2列开始到第5列结束，偶数行从第4列开始到第1列是解题的关键． 8、C【解析】根据几何体的展开图把它利用空间思维复原即可得到答案.【详解】仔细观察几何体的展开图，根据地面正方形的形状可以确定它是四棱锥. 故选C 【点睛】此题重点考察学生对空间立体图形的认识，把握四棱锥的特点是解题的关键. 9、A【解析】根据数轴可知，a ＜0＜b ，且|a|＜|b|，所以原式=b-a +a=b ．故选A. 10、D【分析】根据和是单项式，得到两式为同类项，利用同类项的定义求出m 与n 的值，即可求出所求． 【详解】解：∵1639nx y 与41232mx y 的和是单项式，∴4m=16，3n=12， 解得m=4，n=4， 则m+n=4+4=8， 故选：D ． 【点睛】本题考查了合并同类项，熟练掌握合并同类项法则是解题的关键．二、填空题(本大题共有6小题，每小题3分，共18分) 11、8【解析】∵2n x = , ∴333)28nn xx ===（ ,故答案为8.12、＜ ＞ =【分析】先计算，再比较大小即可．【详解】解：∵37×45＝1235，37＝1535，∴37×45＜37； ∵25÷78＝1635，25＝1435，∴25÷78＞25； ∵56×115＝1，43÷113＝1，∴56×115=43÷113． 故答案为：＜，＞，=．本题考查了有理数的除法和乘法运算，以及有理数的大小比较，熟练掌握运算法则是解答本题的关键． 13、67.5°【分析】根据已知和∠AEN+∠NED=180°，即可得到∠AEN=45°，∠DEN=135°，由折叠可得，∠DEF=∠NEF ，进而得出∠DEF 的度数，最后得到∠AEF 的度数． 【详解】1,1803︒∠=∠∠+∠=AEN DEN AEN NED∴∠AEN=45°，∠DEN=135°， 由折叠可得，∠DEF=∠NEF ，()1360135112.52︒︒︒∴∠=-=DEF ∴∠AEF=180°-∠DEF=67.5°， 故答案为：67.5 【点睛】本题主要考查了平行线的性质以及折叠问题，解题时注意：在折叠中对应角相等． 14、25°26′【分析】先利用补交的定义求出此角，再利用余角的定义求解即可． 【详解】解： 90(18011526)11526902526'''︒-︒-︒=︒-︒=︒ 故答案为：2526'︒． 【点睛】本题考查的知识点是补角以及余角的定义，熟记定义内容是解此题的关键． 15、50元．【分析】设这条裤子的成本是x 元，提高50%后的价钱是（1+50%）x 元，又以八折优惠卖出的价钱是（1+50%）x ×80%，然后再减去成本价就等于10，所以（1+50%）x ×80%减x 等于10元，列出方程即可解答． 【详解】设这条裤子的成本是x 元， （1+50%）x ×80%-x=10 1.5×0.8x-x=10 0.2x=10 x=50答：这条裤子的成本是50元． 故答案为：50元． 【点睛】16、三【分析】根据题意得到每一行是4个偶数，奇数行从第2列往后排，偶数行从第4列往前排，然后用2000除以2得到2000是第1000个偶数，再用1000÷4得250，于是可判断2000在第几行第几列．【详解】∵2020÷2=1010，∴2020是第1010个偶数，而1010÷4=252······2，第1010个偶数是253行第二个数，253为奇数，则从第二列往右数，∴第1010个偶数是253行，第三列，则偶数2020应在第三列，故答案为三.【点睛】本题考查了关于数字的变化规律：先要观察各行各列的数字的特点，得出数字排列的规律，然后确定所给数字的位置．三、解下列各题(本大题共8小题，共72分)17、(1)见解析；(2)见解析；(3) ＜；(4) 1【分析】（1）连接与点B在同一水平线的格点即可得；（2）过点B作AC的垂线，交AC于点E，则BE即为所求；（3）根据垂线段最短即可得；（4）根据三角形的面积公式可得12ABCS AC BE=⋅．【详解】（1）如图BD即为所求；（2）过点B作AC的垂线，交AC于点E，则BE即为所求，如图所示：（3）由垂线段最短得：BE BC<故答案为：<；（4）ABC的面积为1163922ABCS AC BE=⋅=⨯⨯=故答案为：1．本题考查了平行线与垂直的定义、垂线段最短等知识点，掌握理解平行线与相交线的相关概念是解题关键． 18、这个班有 1 名学生．【分析】可设有 x 名学生，根据总本数相等和每人分 3 本，剩余 20 本，每人分 4 本，缺 25 本可列出方程，求解即可．【详解】解：设有 x 名学生，根据书的总量相等可得： 3x+20＝4x-25， 解得：x ＝1．答：这个班有 1 名学生． 【点睛】本题考查了一元一次方程的应用，根据该班人数表示出图书数量得出等式方程是解题关键． 19、x=1【分析】利用解一元一次方程的步骤：去括号、移项合并、化系数为1，即可求解． 【详解】去括号得：26696--=+-x x x ， 移项合并得：1313x =， 化系数为1得：x=1， ∴x=1是原方程的解． 【点睛】本题考查了解一元一次方程，熟练掌握解一元一次方程的步骤是解答的关键．20、（1）3000；50（x ﹣30）；2400；40x ；（2）按方案①购买较为合算；（3）此种购买方案更为省钱．【解析】试题分析：（1）该客户按方案①购买，夹克需付款30×100=3000；T 恤需付款50（x ﹣30）；若该客户按方案②购买，夹克需付款30×100×80%=2400；T 恤需付款50×80%×x ； （2）把x =40分别代入（1）中的代数式中，再求和得到按方案①购买所需费用=30×100+50（40﹣30）=3000+500=3500（元），按方案②购买所需费用=30×100×80%+50×80%×40=2400+1600=4000（元），然后比较大小；（3）可以先按方案①购买夹克30件，再按方案②只需购买T 恤10件，此时总费用为3000+400=3400（元）． 试题解析：解：（1）3000；50（x ﹣30）；2400；40x ；（2）当x =40，按方案①购买所需费用=30×100+50（40﹣30）=3000+500=3500（元）；按方案②购买所需费用=30×100×80%+50×80%×40=2400+1600=4000（元），所以按方案①购买较为合算； （3）先按方案①购买夹克30件，再按方案②购买T 恤10件更为省钱．理由如下：先按方案①购买夹克30件所需费用=3000，按方案②购买T 恤10件的费用=50×80%×10=400，所以总费用为3000+400=3400（元），小于3500元，所以此种购买方案更为省钱．21、（1）1cm；（2）18cm【分析】（1）由线段的中点，线段的和差求出线段DB的长度为1cm；（2）由线段的中点，线段的和差倍分求出AC的长度为18cm．【详解】（1）如图1所示：∵AC=AB+BC，AB=6cm，BC=4cm∴AC=6+4=10cm又∵D为线段AC的中点∴DC=12AC=12×10=5cm∴DB=DC-BC=6-5=1cm （2）如图2所示：设BD=xcm∵BD=14AB=13CD∴AB=4BD=4xcm，CD=3BD=3xcm，又∵DC=DB+BC，∴BC=3x-x=2x，又∵AC=AB+BC，∴AC=4x+2x=6xcm，∵E为线段AB的中点∴BE=12AB=12×4x=2xcm又∵EC=BE+BC，∴EC=2x+2x=4xcm又∵EC=12cm∴4x=12解得：x=3，∴AC=6x=6×3=18cm．本题综合考查了线段的中点，线段的和差倍分等相关知识点，重点掌握直线上两点之间的距离公式计算方法．22、125°【分析】过点O 作//OM AB ，由平行线的性质得出3135∠=∠=︒，根据平行公理得出// OM CD ，然后根据平行线的性质和垂直的定义求得5455∠=∠=︒，从而利用邻补角定义求解．【详解】解:如图，过点O 作//OM AB3135∴∠=∠=︒.//AB CD ，// OM CD ∴，45∴∠=∠.90EOF ∠=︒，3490EOF ∴∠+∠=∠=︒，4903555∴∠=︒-︒=︒，5455∴∠=∠=︒2 8055125∴∠=︒-︒=︒．【点睛】本题考查平行线的判定和性质，垂直和邻补角的定义，掌握性质定理正确推理论证是解题关键．23、（1）90°；（2）90°；（3）∠DOE =90°.【分析】（1）OD 平分∠AOC ，OE 平分∠BOC ，得出∠DOE 12=（∠BOC +∠COA ），代入数据求得问题； （2）利用（1）的结论，把∠BOC =a °，代入数据求得问题；（3）根据（1）（2）即可得出结论．【详解】（1）∵OD 平分∠AOC ，OE 平分∠BOC ，∴∠DOC 12=∠AOC ，∠COE 12=∠BOC ，∴∠DOE =∠DOC +∠COE 12=（∠BOC +∠COA ）12=⨯（62°+180°﹣62°）=90°； （2）∠DOE ═12（∠BOC +∠COA ）12=⨯（a °+180°﹣a °）=90°； （3）由（1）（2）可得：∠DOE =90°．本题考查了角平分线的定义．掌握角平分线的定义是解答本题的关键．24、（1）BC= 7cm ；（2）MN= 6.5cm ；（3）MN=2b 【分析】（1）根据线段中点的性质，可得MC 的长，根据线段的和差，可得BC 的长； （2）根据线段中点的性质，可得MC 、NC 的长，根据线段的和差，可得MN 的长； （3）根据（1）（2）的结论，即可解答．【详解】解：（1）∵AC=6cm ，点M 是AC 的中点，∴12MC AC ==3cm ， ∴BC=MB ﹣MC=10﹣3=7cm ．（2）∵N 是BC 的中点，∴CN=12BC=3.5cm ， ∴MN=MC+CN=3+3.5=6.5cm ．（3）如图，MN=MC ﹣NC=1122AC BC -=12（AC ﹣BC ）=12b ． MN=2b ． 【点睛】本题考查两点间的距离．。

目录党、团、行政、班组获得的荣誉·························2～3区及区以上级别先进个人·······························4～5十四中学2007～2008学年优秀共产党员 (6)教师专业化发展情况 (7)十四中学2007～2008学年优秀教师 (8)十四中学2007～2008学年优秀青年教师 (9)十四中学2007～2008学年优班主任 (9)十四中学2007～2008学年优秀教育工作者 (10)十四中学2007~2008学年先进支部、优秀教研组、优秀备课组 (10)特别奉献奖 (11)“十一五”教育科研成果 (11)论文、教案、课件、课题、教学比赛等获奖情况···········12～17竞赛辅导类···········································18～272007~2008学年度各类学科竞赛获奖学生名单·············28～322008年高考考上一类大学的部分学生名单················33～36学校党政工、教研组、班组获得的荣誉区及区以上级别先进个人十四中学2007～2008学年优秀共产党员十四中学教师专业化发展情况：新评选的市优秀青年教师张新强、冯爱龙、周莉莉新评选的区级教学能手李远更、王留、姚红波、周锦华新评上高级职称的教师王建容、张翔、余振、吴继生新评上中级职称的教师彭丽亚、李娟、马涛十四中学2006～2008学年优秀教师十四中学2006～2008学年优秀青年教师十四中学2007～2008学年优秀班主任十四中学2006～2008学年优秀教育工作者十四中学2007~2008学年先进支部（教研组、备课组）学校文化建设特别贡献奖《“三厅”旧址记》作者：张启武等，校长室奖励1000元。

2021年武汉市第十四中学高三英语下学期期末考试试题及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AAre you looking for some new and exciting places to take your kids to? Try some of these places.★Visit art museums.They offer a variety of activities to excite your kids' interest. Many offer workshops for making hand-made pieces, traveling exhibits, book signings by children's favorite writer, and even musical performances and other arts.★Head to a natural history museum.This is where kids can discover the past from dinosaur(恐龙) models to rock collections and pictures of stars in the sky. Also, ask what kind of workshops and educational programs are prepared for kids and any special events that are coming up.★Go to a Youtheater.Look for one in your area offering plays for child and family visitors.Pre-show play shops are conducted by area artists and educators where kids can discover the secret about performing arts Puppet(木偶)making and stage make-up are just a couple of the special offerings you might find.★Tryhands-on science.Visit one of the many hands-on science museums aroundthe country.These science play-lands are great fun for kids and grown-ups alike. They'll keep your child mentally and physically active the whole day through while pushing buttons, experimenting, and building. When everyone is tired, enjoy a fun family science show, commonly found in these museums.1.If a child is interested in the universe, he probably will visit _____.A.a YoutheaterB.an art museumC.a hands-on science museumD.a natural history museum2.What does "hands-on science" mean in the last paragraph?A.Science games designed by kids.B.Learning science by doing things.C.A show of kids' science work.D.Reading science books.3.Where does this text probably come from?A.A museum guide.B.A tourist map.C.A science textbook.D.A news report.BEach year, the women of Olney and Liberal compete in an unusual footrace. Dressed in aprons (围裙) andheadscarves, they wait at both towns’starting lines. Each woman holds a frying pan with one pancake inside. At the signal, the women flip (轻抛) pancakes and they’re off!This “pancake racing” tradition is said to have started on Shrove Tuesday, 1445, in Olney. Shrove Tuesday is the day beforethe Christian season of Lent (大斋戒) begins. During Lent, many people decide to give up sugary or fatty foods.Legend says that in 1445, an Olney woman was making pancakes to use up some of her sugar and cooking fats before Lent. She lost track of time and suddenly heard the church bells ring, signaling the beginning of the Shrove Tuesday service. Realizing that she was going to be late for church, she raced out the door still wearing her apron and headscarf and holding her frying pan with a pancake in it. In the following years, the woman’s neighbors imitated her dash to church, and pancake racing was born.The rules are simple. Racers must wear the traditional headscarf and apron. They must flip their pancakes twice - once before starting and once after crossing the finish line. After the race, there are Shrove Tuesday church services. Then Liberal and Olney connect through a video call to compare race times and declare a winner.In both towns, the races have grown into larger festivals. Olney’s festival is an all-day event starting with a big pancake breakfast. Liberal’s festival lasts four days and includes a parade, a talent show, and contests that feature eating and flipping pancakes. Although the women’s race is still the main event, both towns now hold additional races for boys and girls of all ages.4. How did pancake racing start?A. A woman in Olney created it.B. Women made pancakes before Lent.C. A woman dashed to church with a pancake.D. People followed the suit of an interesting incident.5. What should racers obey during the race?A. They can wear fashionable headscarves and aprons.B. They must flip their pancakes once in the race.C. They must flip their pancakes at the beginning of the race.D. They can flip their pancakes in the middle of the race.6. What can we learn about the race from the last paragraph?A. People can show their talent in Olney festival.B. People can enjoy a one-day holiday in Liberal.C. The race is not only intended for women now.D. People can have a big pancake breakfast in both towns.7. What is the text mainly about?A. The origin of pancake racing.B. The history of pancake racing.C. The development of pancake racing.D. The introduction to pancake racing.CKids often admire well-known celebrities, putting posters of their favorite musicians, movie stars and athletes on their bedroom walls. But rarely does a young person get to meet or talk to their idol. Yet for one young tennis player - Coco Gauff - her chance to do just that happened in an amazing way!Coco was born on March 13, 2004. At the age of 4, she developed an interest in tennis after watching Venus Williams win the Australian Open on TV. Coco began playing at 7 and showed a real talent for the sport. When young Coco turned 10, she began training at a tennis centre run by Venus's coach, Patrick Mouratoglou. He still remembers the first time he met Coco. He says, “She impressed me with her determination and fighting spirit. ” Convinced of her talent, Mouratoglou sponsored（资助）Coco to attend his academy in France. While she was preparing to go to the academy in 2019, she received a call that would change her plans and her life!Wimbledon（温布尔顿网球比赛）organizers called and offered Gauff entry to the tournament（联赛）as a wildcard（外卡选手）.This madeher one of the youngest players to ever qualify. Before she knew it she was on her way to London. After arriving, she received another surprise. For her Wimbledon debut（首次登场），she would be playing her lifelong hero, Venus Williams! The tennis legend is 24years older than Gauff.The world watched with amazement as young Gauff beat Venus in two straight sets! Afterwards, Gauff shook Venus's hand, thanked her and said, “I wouldn't be here if it wasn't for you. " After the match, Venus said of Gauff, “I think the sky is the limit；it really is. " Venus said, “I feel honored that I was on her wall [as a poster] at some point in her life. Soon she will be on other girls' walls. It's nice because it will keep going from the next generation to the next generation. "8. What can we learn about Coco from the text?A. She took up tennis as career at the age of 4.B. She went to academy at the age of 7.C. She had played against William before 10.D. She beat William at the age of 159. Which of the following can best describe Coco?A. Talented and modest.B. Lucky and responsible.C. Proud and hard-working.D. Respectful and cheerful.10. What can we infer from Venus's words?A. Coco had reached her limits.B. Coco would rise to fame after the match.C. Coco's poster would be passed on.D. Coco had once visited her home.11. What can be a suitable title for the text ?A. Coco Gauff：Tennis's Next Superstar.B. Coco Gauff：A Poster on the Wall.C. What Posters Mean to a Young Girl.D. The Significance of Admiring an Idol.DSmart speakers have proven to be handy devices in hospitals, allowing patients to control independently . And now, researchers from theUniversityofWashingtonhave developed an artificial intelligence system that enables these devices to monitor heartbeats.Using technology to remotely monitor heart rates isn't new. These days most smartwatches and fitness trackers are capable of it. The good thing here is that researchers have figured out a way to use the microphones in smart speakers to do it without requiring physical contact.In a study published inCommunications Biology, the researchers had the smart speakers send out signals that couldn't be heard which were then reflected off a person's body. They then analyzed these signals to identify small chest wall motions related to heartbeats, as well as separate those signals from surrounding noise and breathing.For this particular proof — of — concept setup, the researchers tested this smart speaker on 26 healthy participants and 24 hospitalized patients with various heart conditions, including atrial fibrillation（心房颤动）and heart failure. In both cases, the smart speaker was within 28 -30 milliseconds of an ECG（心电图）,the gold standard used in hospitals to discover arrhythmia（心律不齐）.Like smartwatches with advanced heart features, using smart speakers in this way opens up the possibility for passive, remote heart monitoring. ECGs, while highly accurate, require a visit to the doctor and several electrodes （电极）to be placed on the body. They,re not capable of continuous monitoring so you're limited to what it picks up at that exact moment in time ——one reason why heart arrhythmia can be so hard to discover.Smartwatches are capable of passive, remote, continuous monitoring, but they require you to wear the device at all times to be effective. It's not something that's comfortable for everyone, especially when it comes tosleep and for those with highly sensitive skin. Another issue is that these advanced smartwatches are expensive, while smart speakers are much cheaper.“If you have a device like this, you can monitor a patient on an extended basis and then develop corresponding care plans that satisfy the patient' s needs,“ said Dr. Arun Sridhar, co — senior author on the study. "And the beauty of using this kind of devices is that they are already in people's homes.”12. What does the author focus on in Paragraph 3?A. How the smart speaker works.B. Why the smart speaker is useful.C. The advantages of smart speakers.D. The importance of the study.13. Why is heart arrhythmia difficult to find?A. ECGs are not highly accurate.B. ECGs can't monitor continuously.C. Doctors know little about heart arrhythmia.D. An ECG test is hard to operate and expensive.14. Which statement best explains the characteristics of smartwatches?A. They are comfortable to wear.B. They are friendly to sensitive skin.C. They are effective and cheap.D. They are able to monitor remotely.15. What can we infer from the last paragraph?A. We need to invent more smart devices.B. Care plans are vital to patients with heart failure.C. Smart speakers could be contactless heart monitors.D. Different devices are needed to meet patients,demands.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

感谢母校塑造了我的灵魂金瑞华（1955届毕业生中国农业大学教授）我自幼体弱多病，患有较严重的心脏病及过敏性鼻炎等多种疾病。

经常患病，不仅严重影响学习，还给身心带来很大痛苦。

那时我十分失望，曾不止一次地出现过轻生的念头。

父母为我心疼，除疼爱外，也积极为我求医治病，希望我能活下来，至于我的学习以及以后的工作，父母从不抱过高的希望。

1950年夏，我考入母校（指“省高”，十四中学前身。

编者注。

）后，在母校老师和同学的关怀与帮助下，我逐步树立了革命人生观，懂得了人活在世，不能只考虑个人得失，而应为国家为人民作出贡献。

记得在我的人生转折过程中，有几件事起到了关键性的作用。

首先是伟大的抗美援朝运动，使我受到了强烈的爱国主义教育。

当时如火如荼的爱国浪潮，席卷了全校师生。

我与其他同学一样，积极投身到这一爱国激流之中，经风雨，受锻炼。

记得当时我将节省下的一点点早餐费捐出，支援国家购买抗美援朝的一枪一弹。

1951年武汉市团代会召开时，母校推荐我为特邀代表与会，使我进一步受到革命教育。

次年一月，我被正式吸收为新民主主义青年团团员，入团介绍人是李淦林和吕道根两位同学。

在此，我衷心感谢母校党团组织和同学们的真诚帮助！第二件事是母校组织学生阅读《钢铁是怎样炼成的》一书。

我被保尔·科察金不畏身残带来的巨大痛苦，坚持为革命奋斗的精神深深地打动，我决心学习保尔，战胜疾病，完成学业，做一个对国家对人民有用的人。

在我休学治病期间，母校党团组织及同学们还常来看望我，鼓励我积极治疗、加强锻炼、早日康复，尽快回校继续学习。

当时，夏国康、李淦林、陆德懋、贾振球、吴人杰等诸多同学都来看过我。

复学后，许多老师如教代数的吴老师、教几何的鲍老师、教化学的张惟聪老师、教生物的陈端本老师（尤其是陈端本老师对我上北京农业大学念昆虫学影响很大）等等都曾热心地为我补课。

这一切使我深感母校的温暖，我终生难忘！由于在母校打下了较好的思想基础、较扎实的学习基础和初步康复的身体基础，1955年夏，我考入北京农业大学（由北大、清华、华大三校农学院合并而成立）后，在大一上学期就被院团委任命为系临时团总支书记。

2021届武汉市第十四中学高三语文月考试题及参考答案一、现代文阅读（36分）(一)现代文阅读I(9分)阅读下面的文字，完成下面小题。

火眼金睛候发山大高是河洛地区远近闻名的杂技演员。

一般杂技演员都有绝招，否则，难以在这个行当里混，“一招鲜，吃遍天”嘛。

可能大家都看过“口中喷火”的杂技，演员嘴里能喷出长长的火龙，或一团一团的火球。

大高早就不玩这个了，按他的说法，这个是初级的，他玩的是“眼中喷火”，两股火苗从眼睛里喷出，像两条火蛇一样，而且，不是直线飞射，而是带拐弯的，像是舞蹈着的火龙，想想就很精彩、刺激。

当初，这个杂技没名字，传得久了，大家就叫它“火眼金睛”。

大高有个徒弟叫阿三，说是徒弟，其实就是个跟班打杂的，跑跑腿，搬搬道具。

阿三一直想学习“火眼金睛”。

这也是他当初拜大高为师的原因，大高没有答应。

问的次数多了，大高就告诉阿三，说眼里喷火是所有火术表演中最危险的，演员必须具有高超的技艺，竭尽所能去保证自身和周围观众的安全。

因为表演过程需要火焰、易燃物和有毒燃料的参与，一不小心非死即伤。

这话说得语重心长，阿三却不以为然，以为大高自私，跟老辈子那些师傅一样,都要留一手。

“死了张屠夫，不吃混毛猪。

”阿三耳濡目染，加上偷偷观看师傅练习，也学得八九不离十。

私下里，阿三瞒着师傅训练。

阿三练习的时候，没有使用燃科，他倒不是怕危险，而是怕被师傅发现，就用水来替代燃料练习，练习的重点是如何控制喷射的方向和连贯性。

这天，阿三的老父亲老树来看望阿三。

阿三正在配燃料，这个配方大高倒没有隐瞒，每次表演都安排阿三配制。

当晚有一场表演，阿三不敢怠慢。

老树看到地上滚落的空酒叛，顺嘴问道：“用酒代替燃料？咋不用汽油和酒精呢？”阿三说：“师傅说过，汽油和酒精是最危险的，千万不能使用，一不小心就会烧伤演员。

”老树顿了一下，问阿三：“你还没学会‘火眼金睛’？”阿三哀怨地说：“他不教我。

”老树叹口气，好久，才狠狠地说：“当年我送你到这里，就是为了学习这个独门绝技。

湖北省53所重点高中湖北省53所重点高中湖北省的教育事业在长期发展中已经取得了很大的进步。

而在湖北省的53所重点高中，则是湖北省教育事业的重要组成部分，是培养优秀人才的重要基地。

这些重点高中是湖北省最著名的高中之一，以优异的师资力量、完备的教学设备和先进的教学方法为标志，培养了无数优秀的学生。

下面让我们一起走进湖北省的53所重点中学，领略它们的风采和魅力。

1、武汉市八中武汉市第八中学坐落于历史文化名城武汉东湖之滨，是一所以高中生为主体、初中生为辅体的寄宿制全日制普通高级中学。

学校是全国示范高中，是国内一流的名校之一，拥有着全国最长的德育寝室制度。

学校创建于1952年，成绩一直名列全国重点中学行列，是湖北省高层次人才培养重要基地。

学校校风严谨、教学中心、教育教学实力超群，能够帮助每一位学生全面而有深度地认识国家和世界，成为有良知、有品质、有才华、有爱心的复合型人才。

2、武汉市莱茵实验中学武汉市莱茵实验中学，创建于1909年，是一所以高中生为主的寄宿制全日制普通高级中学，是武汉市重点高中和湖北省示范高中。

学校坐落于风景秀丽的东湖之滨，校园占地面积16万平方米，建筑风格独特，设施齐全，环境优美。

学校拥有一支由名牌大学教授、教育专家和优秀教师组成的高质量专业教师队伍，特色办学十分明显且成效显著。

3、湖北师范大学附属中学湖北师范大学附属中学是一所由湖北师范大学直接管理的高中，是湖北省重点高中之一，享有很高的美誉度。

学校具有较好的办学条件和优秀的师资力量，致力于培养德智体全面发展、具有深厚人文素养、岗位适应能力强的高素质人才，努力为推动湖北省的教育事业做出更大的贡献。

4、武汉市第十四中学武汉市第十四中学，是武汉市高中教育中的知名品牌之一。

学校创立于1978年，是武汉历史最长的农村侨民中学，现已发展成为一所全日制、寄宿制、高起点、高水平的普通高中。

学校特色鲜明，办学理念先进，逐步形成了文、史、哲、经典等教育特色，在全国高中名校中具有一定影响力。

平均金额(万元)
￥17.92
同比增长：-37.0%
平均节支率
7.2%
同比增长：166.7%
*平均节支率是指，项目节支金额与预算金额的比值的平均值。（节支金额=项目预算金额-中标金额）
1.2 需求趋势
近 3 月(2023-06~2023-08)：
近 1 年(2022-09~2023-08)：
本报告于 2023 年 08 月 13 日 生成
1.4.1 重点项目
（1）家具用具（8）
重点项目
项目名称
中标单位
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TOP1
武汉市第十四中学接待沙发比价 湖北柏谷文智慧科
成交公告
技有限公司
1.5
2022-11-15
本报告于 2023 年 08 月 13 日 生成
3/19
重点项目
项目名称
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TOP2
目标单位： 报告时间：
武汉市第十四中学 2023-08-13
报告解读：本报告数据来源于各政府采购、公共资源交易中心、企事业单位等网站公开的招标采购 项目信息，基于招标采购大数据挖掘分析整理。报告从目标单位的采购需求、采购效率、采购供应 商、代理机构、信用风险 5 个维度对其招标采购行为分析，为目标单位招标采购管理、采购效率 监测和风险预警提供决策参考；帮助目标单位相关方包括但不限于供应商、中介机构等快速了解目 标单位的采购需求、采购效率、采购竞争和风险水平，以辅助其做出与目标单位相关的决策。 报告声明：本数据报告基于公开数据整理，各数据指标不代表任何权威观点，报告仅供参考！
重点项目
项目名称
中标单位
中标金额（万元） 公告时间

武昌区高中阶梯式排名武昌区高中阶梯式排名中国的高中阶段教育包括：普通高级中学、普通中等专业学校、成人高中、职业高中、中级技工学校、职业中等专业学校、中等师范学校等。

接下来由小编为大家整理出武昌区高中阶梯式排名，希望能够帮助到大家！武昌区高中阶梯式排名我们从武昌区的高考成绩排名上为武昌区的高中做了一个阶梯式的排名：1、第一阶梯：华师一附中、湖北省实验。

2、第二阶梯：武汉中学、十四高、水高。

3、第三阶梯：武汉第十五中学、东湖中学、湖大附中、文华中学。

拓展：（一）华师一附中一、华师一附中绝对是武昌区最好的高中，因为华师一附中是面对全省招生的，所以不仅是武汉各区的学生，只要是达到了分数线都可以报名参加。

华师一去年的成绩应该是最近三年来最好的一次，不仅夺得了省文科状元的学生，北大清华的录取人数更是在60人左右，保送的学生人数就有24人。

二、华师一附中高考成绩数据：1、学科竞赛保送清华北大13人。

2、理科实验班保送清北11人。

3、600分以上的学生有87%。

（二）湖北省实验中学。

一、省实验一直是武汉的超强高中，从最好的.生源武珞路实验中的优质生源，每年高中中达到重点高大学几乎是全校性的。

二、湖北省实验中学高考成绩数据：1、文科平均分为605.2在武汉各区是第一。

2、理科平均分为625.2在武汉排第二（第一是华师一）。

3、600分以上的学生有85%，432人。

（三）武汉中学一、武汉中学在全年的高考中可谓是进步非常大，去年的600分以上的学生超过了100人，对比前年的24人可谓是翻了好多倍，而且去年的成绩在全市各大高中排名第九的位置，可喜可贺看得到进步才是一个学校的希望。

二、武汉中学高考成绩数据：1、上了一本线的人数为384人。

2、分数大于600分的有102人。

（四）其他武昌区重点中学1.武汉市武昌楚才实验中学地址：湖北省武汉市武昌区南湖花园松涛苑电话：027-********简介：湖北省武昌实验中学创办于1920年，是首批全国重点中学之一，武汉市首家“省级示范学校”，武汉市政府确定壮大发展的首批“示范优质高中”。

湖北省武汉市第十四中学2024届物理八年级第二学期期末检测模拟试题注意事项：1．答题前，考生先将自己的姓名、准考证号填写清楚，将条形码准确粘贴在考生信息条形码粘贴区。

2．选择题必须使用2B铅笔填涂；非选择题必须使用0．5毫米黑色字迹的签字笔书写，字体工整、笔迹清楚。

3．请按照题号顺序在各题目的答题区域内作答，超出答题区域书写的答案无效；在草稿纸、试题卷上答题无效。

4．保持卡面清洁，不要折叠，不要弄破、弄皱，不准使用涂改液、修正带、刮纸刀。

一、单选题1．如图所示，在三个相同的容器中装有质量相同的水，将木块A、金属块B按不同的方式放入水中，待A, B静止时，三个容器中水对容器底部的压强相比较，正确的是A．p甲>p乙>p丙B．p甲=p乙>p丙C．p甲<p乙=p丙D．p甲=p乙<p丙2．放在水平桌面的甲、乙两个完全相同的杯子，盛有不同浓度的盐水，将一个鸡蛋分别放入其中，鸡蛋静止时，所处的位置如图所示，此时两杯液面相平。

则（）A．鸡蛋在甲杯里受到的重力较大B．鸡蛋在乙杯中受到的浮力较大C．甲杯底部受到的液体压力较大D．乙杯对水平桌面的压强较大3．装满水的容器侧壁上开有三个孔，水从小孔中流出，图中描述正确的是A．B．C．D．4．在两个相同的薄壁塑料瓶（质量忽略不计）内分别装入体积相等、密度为ρ甲和ρ乙的两种液体后密封，再把它们放入两个装有等质量水的相同容器中，处于如图所示状态，两容器对桌面的压强分别为p1和p1．下列判断正确的是（）A．ρ甲＞ρ乙p1＞p1B．ρ甲=ρ乙p1＞p1C．ρ甲＜ρ乙p1＜p1D．ρ甲=ρ乙p1＜p15．如图所示的事例中，属于防止．．惯性带来不利影响的是A．跳高运动员助跑B．用木棒拍打脚垫C．旅行箱下装有小轮D．司机开车应系好安全带6．两次水平拉动同一物体在同一水平面上做匀速直线运动，两次物体运动的路程（s）一时间（t）图象如下图．根据图象，下列判断正确的是A．两次物体运动的速度：v1＜v2B．两次物体所受的拉力：F1＞F2C．0-8s两次拉力对物体做功的功率：P1＞P2D．0-8s两次拉力对物体所做的功：W1=2W27．下列事实与所对应的物理知识不相符的是A．潜水艇用厚钢板制成﹣﹣﹣液体压强B．三峡船闸﹣﹣﹣﹣连通器C．飞机的升力﹣﹣空气浮力D．抽水机抽水﹣﹣大气压强8．如图所示，A为木块，B铝块，C为铁球，它们的体积相等，把它们都浸没在水中，则A．铁球受到的浮力最大B．铝块受到的浮力最大C．木块受到的浮力最大D．三个物体受到的浮力一样大二、多选题9．2019年4月23日，我国在青岛附近海空域举行了庆祝人民海军成立70周年海上阅兵活动，全面展示人民海军新面貌.建设一支强大海军是实现中国梦的有力保障，潜艇是海军的战略重器.如图所示是我国海军的潜艇在海水中悬浮、上浮、漂浮的训练过程示意图，下列对此潜艇分析正确的是A．悬浮和漂浮时受到的浮力相等B．漂浮时排开的海水的重力最小C．上浮过程中所受浮力逐渐变大D．悬浮时潜艇底部所受海水压强最大10．如图所示，盛有水的圆柱形容器静止在水平桌面上，球M受到竖直向下的重力为G ，水对它竖直向下的压力为1F 、竖直向上的压力为2F ，细绳对它竖直向下的拉力为3F ，水对它的浮力为4F ，球M 在水中静止．下列说法中正确的是A ．412F F F =-B ．F 1>F 2C ．F 3=F 4D ．F 4=G+F 3三、填空题11．在弹簧测力计下悬挂一金属块，示数是8.1N ，当把金属块浸没在水中时，测力计的示数是5.1N ，测金属块浸没在水中时受到的浮力为 ________N ，金属块的密度为 ________kg/m 3 ． 已知水的密度为1.0×103kg/m 3 12．如图1，普通水壶壶嘴的高度不低于壶身的高度，其设计遵循了_____的原理；如图2，用吸管将杯中的饮料吸入口中，是利用了_____的作用．13．如图所示，在20N 的水平拉力F 作用下，使重200N 的物体沿水平地面向左做匀速直线运动，滑轮组的机械效率为80％，则物体与地面间的滑动摩擦力为___________N 。

共建美丽校园,共享绿色生活——湖北省武汉市第十四中学生
态文明教育纪实
冯爱龙;周莹;李月
【期刊名称】《环境教育》
【年(卷),期】2022()10
【摘要】武汉市第十四中学是湖北省一所历史悠久的重点中学。

其前身为创办于1903年的东路高等小学堂和文普通中学堂,1961年被确定为湖北省18所省属重点中学之一。

学校占地8.1万平方米,建筑面积3.5万平方米,校园环境优美,教学设施齐全。

近年来,学校积极构建生态文明教育体系,深入开展生态环境教育,先后获得“武汉市园林示范学校”“武汉市特色学校”“湖北省园林式学校”“湖北省文明校园”“湖北省绿色学校”“全国生态文明教育特色学校”等荣誉称号。

【总页数】1页(P102-102)
【作者】冯爱龙;周莹;李月
【作者单位】不详
【正文语种】中文
【中图分类】G63
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湖北省武汉市第十四中学2023-2024学年高一上学期10月月考英语试题学校:___________姓名：___________班级：___________考号：___________一、阅读理解Burlington School, LondonBurlington School is located in Parsons Green, 15 minutes by underground from the centre of London. Our standard of teaching is high, with courses in General and Specialist English. The coffee bar is open all day serving freshly-cooked meals, and the school organizes a range of social activities to complement(补充) the classes. Students live either in homestays or in one of our hotels.See Burlington School courses and save 10%.University of Liverpool, English Language CentreYou can have confidence in the University of Liverpool. While studying here, you will benefit from modern English teaching methods in small classes of fewer than 16 students.See University of Liverpool courses and save 12%.Interactive English School, BrightonWe are a small friendly school. Being a small school means we can cater for your individual needs more easily than larger schools can. All of our teachers are native speakers, qualified and experienced. Our prices are very affordable and start from 60 per week for full-time courses of 12 lessons.See Interactive English School courses and save 5%.New School of English, CambridgeThe New School of English is located in the beautiful city of Cambridge. The school is open all year and provides a range of English language courses for adults aged at least 16 from all over the world. These courses cover General English as well as courses for professionals looking to focus on specific topic areas. They have a range of accommodation choices for students.See New School of English courses and save 5%.1．What can we know about Burlington School?A．It is open all year.B．It is located in Parsons Green, London.C．It provides no accommodation.D．It offers no social practice classes.2．Which school can provide more personalized courses?A．Burlington School.B．New School of English.C．University of Liverpool.D．Interactive English School.3．Who could be interested in the schools?A．English professors.B．French speakers.C．Foreign English learners.D．Foreign travel agents.When someone asks me what my goals are for the coming year, I don’t usually know how to reply. Of course I, as most people do, want to see an improvement in my grades. This year, however, I’m hoping for something different.Through the course of my school life, I’ve gradually developed a new understanding of the word “prioritization (优先次序)”. The first thing I wish to get in Senior 1 is the ability to manage my time better. I’ll surely become busier with the coming semester (学期), and proper organization is important. From school clubs to academic competitions, everything should be set up in a way that doesn’t influence my health, which leads me to my second goal.My mother has always told me put my health first, so in the future, I hope to both physically and mentally healthy. A person can’t study without having the energy to do so. In order to stay energetic, they must put their health first, no matter how busy they are, or how much work they have to complete.And finally, I hope that I won’t be discouraged (泄气的) by my failure and never give up on my dreams. I hope that I’ll have the courage to try new activities and clubs. I believe my final goal can apply to every student around the world. We should all respect one another’s likes and dislikes, and concentrate on each other’s advantages, not our disadvantages. Everyone should try to take part in all of life’s opportunities(机会).Albert Einstein once said, “Life is like riding a bicycle. To keep your balance (平衡), you must keep moving.” In my case, it’s the other way around. In order to keep moving, I must keep my balance—the balance between studies and activities, efficiency (效率) and procrastination (拖延症), academics and health, passions and dislikes. The new journey is going to be a hard one, but if I set these goals, I believe I will make it through to the end.4．During this school year, what does the author hopes to do?A．Concentrate on improving her overall grades.B．Join as many school clubs aspossible.C．Learn how to manage her time well.D．Spend more time on outdoor activities. 5．According to the article, which of the following students should do?A．Not be afraid of failing.B．Always put their studies first.C．Only do what they’re good at.D．Make different kinds of friends. 6．What does the underlined word in the last paragraph mean?A．A strong feeling of dislike B．A strong feeling of loveC．A strong feeling of anger D．A strong feeling of joy7．What does the author plan to do?A．Show what she likes about high school life.B．Stress (强调) the importance of health to students.C．Show how to balance our studies and activities.D．Share her goals for the coming high school year.When we’re in trouble, we always turn to our parents for help. But would you like them to hear the conversations you have with your friends on the school playground or lunch queue? Social networking sites have become extensions (延伸) of the school hallways, so would you add your parents as “friends” and allow them to view your online activities and conversations with friends?In the past the generation gap included a technology gap, where children were up to date with the latest technology and parents were left behind, content to continue their day-to-day lives as they always had because they had no need to know more about technology. However, more and more parents are beginning to realize just how important social networks are in their lives. This realization has given many parents the motivation (动机) to educate themselves about social networking sites.These days many people are attracted to social networking sites because they can choose who they have around them, there’s also a certain amount of control over privacy (隐私) that we don’t get in real life. Sometimes we feel that privacy is violated (违背) when we must accept a “friend” request from a parent or family member.It’s a difficult choice whether or not to allow a parent to become a part of our onlinelives. On the one hand we don’t want to “refuse” their request because that might hurt their feelings or make them feel you have something to hide. On the other hand if you do accept, then you could have a sense of being watched and no longer feel free to comment or communicate the way you did before.A recent survey suggested that parents shouldn’t take it personally if their children overlook (忽略) their requests. When a teenager overlooks a parent’s friend request, it doesn’t necessarily mean that he is hiding something, but it could mean that this is one part of his life where he wants to be independent.Perhaps talking with parents and explaining would help soften the blow if you do choose not to add them to your friend list.8．What is the passage mainly about?A．Privacy online.B．Parents’ friend requests.C．The generation gap.D．Social networks.9．What can we infer from Paragraph 2?A．Parents have realized the importance of social networks.B．Parents feel secure about their privacy online.C．Social networks successfully fill the generation gap.D．Social networks offer a chance for parents to communicate.10．What maybe the reason for teenagers to refuse a parent’s friend request?A．Their parents make negative comments on them.B．They hide something from their parents.C．They are unwilling to be watched by parents.D．Their parents tend to fall behind in technology.11．What does the underlined “that” in Paragraph 4 refer to?A．Online lives.B．The difficult choice.C．Parents’ request.D．Teenagers’ refusal.Finding the Real YouPsychometric testing—personality testing—has been very popular nowadays as studies show their results to be three times more accurate in predicting your job performance. These tests are now included in almost all graduate recruitment (招聘) and are widely used in the selection of managers.The most popular of these personality tests is the Myers-Briggs Type Indicator (MBTI). It is based on the theory that we are born with a tendency to one personality type which stays more or less fixed throughout life. You answer 88 questions and are then given your “type”, such as Outgoing or Quiet, Feeling or Thinking.Critics of personality testing raise doubts about “social engineering”. Psychologist Dr. Colin Gill warns that the “popular” personality traits (特性) have their disadvantages. “People who are extremely open to new experiences can be butterflies, going from one idea to the next without mastering any of them.” However, the psychometric test is here to stay, which may be why a whole sub-industry on cheating personality tests has sprung up. “It’s possible to cheat,” admits Gill, “but having to pretend to be the person you are at work will be tiring and unhappy and probably short-lived.”So can we change our personality? “Your basic personality is fixed by the time you’re 21,”says Gill,“ but it can be affected by motivation and intelligence. If you didn’t have the personality type to be a doctor but desperately wanted to be one and were intelligent enough to master the skills, you could still go ahead. But trying to go too much against type for too long requires much energy and is actually to be suffered for long. I think it’s why we’re seeing this trend for downshifting—too many people trying to fit in to a type that they aren’t really suited for.”Our interest in personality now exists in every part of our lives. If you ask an expert for advice on anything, you’ll probably be quizzed about your personality. But if personality tests have any value to us, perhaps it is to free us from the idea that all of us are full of potential, and remind us of what we are. As they say in one test when they ask for your age: pick the one you are, not the one you wish you were.12．The Myers-Briggs Type Indicator is based on the belief that ______.A．certain personality traits are commonB．personality is largely decided from birthC．some personality types are better than othersD．personality traits are various from time to time13．According to Dr. Gill, what is the problem with personality tests?A．Employers often find the results unclear.B．They may have a negative effect on takers.C．People can easily lie about their true abilities.D．The results could be opposite to what employers want.14．In Dr. Gill’s view, how easy is it to change your personality?A．It’s possible in your adult life.B．It’s easy if you have great motivation.C．It’s difficult before the age of 21.D．It’s unlikely because it requires much energy.15．What final conclusion does the author reach about the value of personality tests?A．They are not really worth doing.B．They may encourage greater realism.C．They are of doubtful value to employers.D．They can strengthen the idea we have of our abilities.二、七选五Some students prefer to learn by themselves. They believe that they can learn better in this way because they have more freedom, pressure and independence. There is some truth inmore difficult.Firstly, a teacher could act as a guide to lead you to success. When you learn, you need help and advice. A teacher will give you a hand when you face difficulties. 17 What’s more, a teacher always puts real pressure on you. If you study by yourself, you must be strong - minded enough to keep on. 18 But under the guidance of a teacher, you will feel there is always someone to watch you. The teacher may give you homework to do.You have to complete the homework, or you will not pass the course.Last but not least, studying with a teacher will help you receive the benefit of the teacher’s knowledge. 19 . They teach students how to learn and how to obtain information. They guide all of you in class to discuss the material and provide extra material to broaden the scope of the topic.20 I choose to learn in a big family--my school. Without a teacher, I would feel there would be no fun and no pressure. I could not learn well in such dull and depressing situation.A．Teachers can help you solve all of vour problems.B．In short, I prefer to go to class studying with a teacherC．Without a guide, you would be searching in darkness.D．And you may become inactive for lack of a strong will.E．But they fail to see the advantages of learning with a teacher.F．Additionally, teachers are closely connected with our life.G．In class, teachers do more than just going over the material in the text.三、完形填空A heavy thunder storm hit our area recently. Heavy rains, strong winds, and lots of25．A．gray B．delightful C．common D．bright 26．A．disappeared B．worked C．changed D．advanced 27．A．anywhere B．outdoors C．somewhere D．indoors 28．A．shone B．circled C．swept D．traveled 29．A．bothered B．followed C．preferred D．improved 30．A．result B．movement C．darkness D．fight 31．A．nature B．accident C．design D．experiment 32．A．meanwhile B．therefore C．however D．moreover 33．A．match B．present C．thoughts D．storms 34．A．amazed B．content C．upset D．annoyed 35．A．give B．put C．drive D．take四、用单词的适当形式完成句子around me.(用适当的词填空)37．The programme (design) to help people who have been out of work for a long time.(所给词的适当形式填空)38．It had also given me a choice, either to leave that page blank to keep writing the story with hope. (用适当的词填空)39．As a teenager, I look forward to (explore) different career paths as well as the fascinating world. (用所给词的适当形式填空)40．Adam has to study harder and get used to taking (responsible) for a lot more. (用所给词的适当形式填空)41．The letter wasn’t addressed to me but I opened it out of (curious). (所给词的适当形式填空)42．I do believe I am (suit) for this voluntary work, because I have a good knowledge of English. (用所给词的适当形式填空)43．I strongly believe that this year’s music festival will leave a deep impression you. (用适当的词填空)44．It is more likely that none of us would like to start a conversation with strangers, because it is awkward and (challenge). (所给词的适当形式填空)45．With his attention (focus) on his homework, he forgot all about what I had told him. (所给词的适当形式填空)五、建议信46．假设你李华，你是学校英文报“HEART-TO-HEART”专栏的编辑。

湖北省武汉市第十四中学2024届中考英语四模试卷含答案注意事项1．考生要认真填写考场号和座位序号。

2．试题所有答案必须填涂或书写在答题卡上，在试卷上作答无效。

第一部分必须用2B 铅笔作答；第二部分必须用黑色字迹的签字笔作答。

3．考试结束后，考生须将试卷和答题卡放在桌面上，待监考员收回。

Ⅰ. 单项选择1、Our history teacher is very ________. She never plays jokes with us.A．serious B．funny C．nervous D．patient2、It is said that e-schoolbags are going to be brought into use in Chinese middle schools soon. In fact. It is a small computer that is __________ than a usual schoolbag but holds all the things for study, such as a _________，an exercise book and so on．A．much smaller, testbook B．even smaller, textbookC．far smaller, comic book3、—Must I go there right now, mum?—No, you ____. You can go there tomorrow.A．shouldn’t B．can’t C．mustn’t D．needn’t4、The number of the students in our class is _______than _______in yours.A．bigger, that B．more, those C．smaller, the ones D．larger, it5、---Eric, _____ can you have your poster been ready?---I'm not sure. We are still waiting for the final design.A．how long B．how soon C．how often D．how far6、— Fath er’s day is coming. Have you prepared any presents for your father?—Not yet, but I’m sure I ______ one for him.A．bought B．buy C．have bought D．will buy7、In 2000, we ____ to the Great Wall and had a good time there.A．go B．went C．will go D．have gone8、People usually like the TV channels with funnier programmes but ________advertisements.A．few B．littleC．fewer D．less9、—Do you know ________? I’m going to visit him.—Sorry, I don’t know.A．where does Mr Li live B．where did Mr Li liveC．where Mr Li lives D．where Mr Li lived10、Never ____ till tomorrow what may be done today. In this way, you can get most and learn best.A．put on B．put down C．put offⅡ. 完形填空11、Mr Brown was a rich shopkeeper. He 1 a lot of money to his son Jim when he was dying. The young man often 2 his friends to dinner and several years later he spent all the money on the 3 food. Now he got into trouble and nobody came to him. It made him 4 and he went to ask a clever old man for advice.“My money has 5 and my friends have gone,” said the young man. “What will happen to me now?”“Don,t 6 , young man,” answered the old man. “Everything will soon be all right again.7 and you will soon feel much happier.”8 this, the young man was very glad. He asked, “Am I going to be9 again if I don’t like working?”“No,”said the old man.“I 10 you will soon get used to being poor and having no friends.”1．A．lent B．left C．borrowed D．got2．A．made B．hoped C．asked D．pulled3．A．common B．cheap C．terrible D．delicious4．A．sad B．happy C．polite D．careful5．A．begun B．been used up C．hurried D．flown6．A．worry B．say C．smile D．sing7．A．Stand B．Study C．Work D．Wait8．A．Seeing B．Touching C．Hearing D．Feeling9．A．safe B．dangerous C．rich D．poor10．A．think B．wish C．understand D．surpriseⅢ. 语法填空12、(B) Complete the passage with the proper forms of given words.Zengzi was a famous thinker in Chinese history. His 1．(teach) was Confucius (孔子).One day, Zengzi’s wife was going to the market to sell something for money without their son. The boy kept 2．(cry) and shouting. She said to her son, “When I come back, I’ll kill our pig to make a meal for you.”But she didn’t do as she said. “How can you cheat a child?” Zengzi said 3．(serious) “The small child only 4．(follow) the example of his parents. If you cheat him, he may cheat 5．(other) like you.” Having said this, Zengzi raised the knife and killed the pig.Ⅳ. 阅读理解A13、A little young boy loved football with his all heart. But being half the size of the other boys, at all the games, the young boy sat on the bench and hardly ever had chances to play. His father was always standing there with cheering. He never missed a game.This young boy was still the smallest of the class when he entered high school. But his father continued to encourage him but also made it very clear that he did not have to play football if he didn’t want to. But the boy loved football and decided to_______All though high school he never missed any practice or a game but remained a bench-warmer all four years. His faithful father was always standing there with words of encouragement for him.When the young son went to college, he became a member of the football team. This young athlete never missed practice during his four years at college, but he never got to play in a game. It was the end of his last football season, and as he began to practice, bad news came by telegram. His father died that morning.After three days, it was time for the last game. The young man went to the coach and said, “Coach, please let me play. I’ve just got to play today.” Feeling sorry for the kid, the coach agreed finally. Before long, the coach, the players and everyone in the stands could not believe their eyes. This little unknown athlete, who had never played before, was doing everything right. Nobody could stop him. He ran, he passed, and at last, he won! He was really like a star.He looked at the coach, with tears in his eyes, and said, “Well, you knew my dad died, but did you know that my dad was blind?” he continued, “Dad came to all my games, but today was the first time he could see me play, and I wanted to show him I could do it!”1．Why did the boy always sit on the bench?A．Because he liked watching football games.B．Because he didn’t practice hard enough.C．Because he had to stay with his father.D．Because he was not big and strong enough.2．What does the phrase “hang in there” in paragraph 2?A．在那逗留B．坚持到底C．挂在那里D．忍耐一下3．When was the son on a football team?A．Before he went to school.B．When he was at the primary school.C．When he was at the high school.D．When he as at college.4．Which of the following is TRUE?A．The son was the smallest in his school.B．The son was good at playing football.C．The father saw all the son’s games.D．The coach believed the son so much.5．What’s the best title of this passage?A．What a football player! B．He could see me play!C．I think I can! D．Let me play!B14、How can we keep the environment? One way is to remember the Four Rs: Reduce, Reuse, Recycle, and Rebuy. ReduceWe need to use reusable materials and products. We also need to reduce the packaging that is used for new goods in shops. It is important that we improve our use of paper, cardboard, glass, metal, plastic, and other materials.ReuseVery often we throw away items that still could be used. For example, we sometimes throw away clothes when they no longer fit us, or we buy some new furniture and throw away something that could be repaired. Other people could make use of these items. We need to change our bad habits.RecyclingBy recycling, we can make something new from something old. This saves natural resources(资源). It also helps to offer jobs.RebuyingIf we buy recycled goods, we help to save resources and avoid waste. The money we spend also supports the recycling process. Remember the Four Rs!Of course, there are many other ways to improve our environment, we know. Let’s try them.根据材料内容选择最佳答案，将其标号填入题前括号内。

湖北省武汉市第十四中学2024届七年级数学第一学期期末统考模拟试题注意事项1．考生要认真填写考场号和座位序号。

2．试题所有答案必须填涂或书写在答题卡上，在试卷上作答无效。

第一部分必须用2B 铅笔作答；第二部分必须用黑色字迹的签字笔作答。

3．考试结束后，考生须将试卷和答题卡放在桌面上，待监考员收回。

一、选择题(每小题3分,共30分)1．1-2020的相反数是（ ） A ．2020 B ．-2020 C ．12020 D ．1-20202．人类已知最大的恒星是盾牌座UY ,它的规模十分巨大,如果将盾牌座UY 放在太阳系的中心,它的表面将接近土星轨道,半径约等于1.43344937×109km .那么这个数的原数是( )A ．143344937kmB ．1433449370kmC ．14334493700kmD ．1.43344937km 3．在3-，7-，()4--，0中，负数有（ ）． A ．1个 B ．2个 C ．3个 D ．4个4．下列各组中的单项式是同类项的是（ ）A ．22xy 和12-2y xB ．2m np -和2mn -C ．2m -和2m -D ．0.5a 和12b - 5．下列代数式222222615,,,,321xy y x x y x x x x y x y x x π--+--+++中，最简分式的个数有（ ） A ．1个 B ．2个 C ．3个 D ．4个6．当x 分别等于1和-1时，代数式4222x x --的两个值（ ）A ．互为相反数B ．相等C ．互为倒数D ．异号7．下列图形是将正三角形按一定规律排列，则第4个图形中所有正三角形的个数有（ ）A ．160B ．161C ．162D ．1638．若x ＝﹣1关于x 的方程2x +3＝a 的解，则a 的值为（ ）A ．﹣5B ．3C ．1D ．﹣19．借助一副三角尺，你能画出下面那个度数的角( )A ．65︒B ．75︒C ．80︒D ．95︒10．若 2b −5a=0，则的值为（ ）A ．B ．C ．D ．二、填空题(本大题共有6小题，每小题3分，共18分)11．已知一组单项式：﹣x 2，2x 4，﹣3x 6，4x 8，﹣5x 10，…则按此规律排列的第15个单项式是_____．12．元代朱世杰所著的《算学启蒙》里有这样一道题：“良马日行二百四十里，驽马日行一百五十里，驽马先行一十二日，问良马几何追及之？”请你回答：良马_______天可以追上驽马．13．在数轴上，点A 表示-5，从点A 出发，沿数轴移动4个单位长度到达点B ，则点B 表示的数是__________．14．如图，甲、乙两个动点分别从正方形ABCD 的顶点A 、C 同时沿正方形的边开始移动，甲点按顺时针方向环形运动，乙点按逆时针方向环形运动．若甲的速度是乙的速度的3倍．则它们第2019次相遇在边_________上．15．如图，数轴上的两个点A 、B 所表示的数分别是a 、b ，对于以下四个代数式：①a+b ；②a ﹣b ；③ab ；④|a|﹣|b|，其中值为正数的是_____（填番号）．16．圆形钟面上从2点整到4点整，时针和分针成60度角时的时间是__________．三、解下列各题(本大题共8小题，共72分)17．（8分）如图，直线AB,CD 交于点O ，OE 平分COB ∠，OF 是EOD ∠的角平分线．（1）说明: 2AOD COE ∠=∠；（2）若50AOC ∠=︒，求EOF ∠的度数；（3）若15BOF =︒∠，求AOC ∠的度数．18．（8分）如图①，已知线段30cm AB =，4cm CD =，线段CD 在线段AB 上运动，E 、F 分别是AC 、BD 的中点.（1）若8cm AC ，则EF =______cm ；（2）当线段CD 在线段AB 上运动时，试判断EF 的长度是否发生变化？如果不变请求出EF 的长度，如果变化，请说明理由；（3）我们发现角的很多规律和线段一样，如图②已知COD ∠在AOB ∠内部转动，OE 、OF 分别平分AOC ∠和BOD ∠，则EOF ∠、AOB ∠和COD ∠有何数量关系，请直接写出结果不需证明.19．（8分）如图，点A 从原点出发沿数轴向左运动，同时点B 从原点出发沿数轴向右运动，4秒钟后，两点相距16个单位长度，已知点B 的速度是点A 的速度的3倍．（速度单位：单位长度/秒）（1）求出点A 点B 运动的速度．（2）若A 、B 两点从（1）中位置开始，仍以原来的速度同时沿数轴向左运动，几秒时原点恰好处在点A 点B 的正中间?（3）若A 、B 两点从（1）中的位置开始，仍以原来的速度同时沿数轴向左运动时，另一点C 同时从B 点位置出发向A 点运动，当遇到A 点后，立即返回向B 点运动，遇到B 点又立即返回向A 点运动，如此往返，直到B 点追上A 点时，点C 一直以10单位长度/秒的速度运动，那么点C 从开始运动到停止运动，行驶的路程是多少单位长度．20．（8分）如图1，点O 为直线AB 上一点，过点O 作射线OC ，使:2:1AOC BOC ∠∠=将一直角三角板的直角顶点放在点O 处，一边ON 在射线OA 上，另一边OM 在直线AB 的下方．（1）将图1中的三角形板绕点O 按照顺时针方向旋转至图2的位置，使得OM 落在射线OA 上，此时ON 旋转的角度是____°；（2）继续将图2中的三角板绕点O 按顺时针方向旋转至图3的位置，使得OM 在BOC ∠的内部，则BON COM ∠-∠=_____________°；（3）在上述直角板从图1旋转到图3的位置的过程中，若三角板绕点O 按每秒钟15︒的速度旋转，当OM 恰好为BOC ∠的平分线时，此时，三角板绕点O 运动时间为__秒，并说明理由．21．（8分）计算;()123127233⎛⎫-+--- ⎪⎝⎭()21335125+⨯- ()33y 与2x -成正比例，且当4x =时，7y =．求当2y =时,x 的值．22．（10分）先化简,再求值:13x －3(x －12y 2)＋(-43x ＋32y 2),其中x ＝－2,y ＝13. 23．（10分）以下是两张不同类型火车的车票(“DXXXX 次”表示动车，“GXXXX 次”表示高铁):()1根据车票中的信息填空:该列动车和高铁是 向而行(填“相”或“同”)．()2已知该动车和高铁的平均速度分别为200/,300/km h km h ，两列火车的长度不计．经过测算，如果两列火车直达终点(即中途都不停靠任何站点)，高铁比动车将早到2h ．求A B 、两地之间的距离．24．（12分）黄岩岛是我国南沙群岛的一个小岛，渔产丰富．一天某渔船离开港口前往该海域捕鱼．捕捞一段时间后，发现一外国舰艇进入我国水域向黄岩岛驶来，渔船向渔政部门报告，并．立即返航．渔政船接到报告后，立即从该港口出发赶往黄岩岛．下图是渔政船及渔船与港口的距离s 和渔船离开港口的时间t 之间的函数图象．(假设渔船与渔政船沿同一航线航行)(1)直接写出渔船离开港口的距离s 和渔船离开港口的时间t 之间的函数关系式；(2)求渔船与渔政船相遇对，两船与黄岩岛的距离；(3在渔政船驶往黄岩岛的过程中，求渔船从港口 出发经过多长时间与渔政船相距30海里．参考答案一、选择题(每小题3分,共30分)1、C【分析】只有符号不同的两个数是相反数，根据定义解答即可 【题目详解】12020-的相反数是12020， 故选：C.【题目点拨】此题考查相反数的定义，理解好“只有”的含义.2、B【分析】有多少次方就把小数点向后移动多少位就可以了.则把1.43344937×109的小数点向后移动9,即可得到结果. 【题目详解】把1.43344937×109的小数点向后移动9,可得1433449370.故选择B. 【题目点拨】本题考查写出用科学记数法表示的原数，解题的关键是知道将科学记数法表示的数,"还原"成通常表示的数,就是把的小数点向右移动位所得到的数.3、A【分析】先化简，然后根据负数的定义：比0小的数是负数，逐一判断即可．【题目详解】解：在3-，77-=，()44--=，0中，负数有：3-，共1个．故选：A ．【题目点拨】本题考查了负数的定义，掌握负数的定义是解题的关键．4、A【解题分析】根据同类项的的定义：“所含字母相同，且相同字母的指数也相同的项叫做同类项”分析可知，上述四个选项中，只有A 中的两个单项式是同类项，其余三个选项中的单项式都不是同类项.故选A.点睛：两个单项式是同类项需同时满足两个条件：（1）两个单项式中所含字母相同；（2）两个单项式中同一字母的指数相等.5、A【分析】根据最简分式的定义对每项进行判断即可． 【题目详解】623xy y x-=-，不是最简分式； 22y x x y x y-=---，不是最简分式； 22x y x y++，是最简分式； 2211211x x x x x --=+++，不是最简分式； 5xπ，不是分式；∴最简分式的个数有1个故答案为：A ．【题目点拨】本题考查了最简分式的问题，掌握最简分式的定义是解题的关键．6、B【分析】分别将x =1和x =-1代入代数式求出结果即可判断．【题目详解】当x =1时，原代数式4221121=⨯--=-；当x =-1时，原代数式422(1)(1)21=⨯----=-； 所以两个值相等．故选：B ．【题目点拨】本题考查代数式求值，熟练掌握求代数式的值的计算方法是解答本题的关键．7、B【解题分析】试题分析：第一个图形正三角形的个数为5，第二个图形正三角形的个数为5×3+2=17， 第三个图形正三角形的个数为17×3+2=53， 第四个图形正三角形的个数为53×3+2=1， 故答案为1．考点：规律型．8、C【分析】将1x =-代入方程得到一个关于a 的等式，求解即可.【题目详解】由题意，将1x =-代入方程得：23a -+=解得：1a =故选：C.【题目点拨】本题考查了一元一次方程的解定义，理解题意，掌握解定义是解题关键.9、B【分析】根据一副三角尺是含有30角的直角三角形和等腰直角三角形，通过角度计算即可得解.【题目详解】根据一副三角尺是含有30角的直角三角形和等腰直角三角形，可知30+45=75︒︒︒，故选：B.【题目点拨】本题主要考查了三角尺的角度，熟练掌握角度的计算是解决本题的关键.10、C【解题分析】先移项，等式两边都除以2b 即可．【题目详解】∵2b−5a=0，∴5a=2b ，∴将等式两边都除以5b 得=．故选：C ．【题目点拨】本题考查了等式的性质2，应用等式的性质2对等式进行正确的变形是解题的关键．二、填空题(本大题共有6小题，每小题3分，共18分)【解题分析】符号规律：序数是奇数时符号为负，序数为偶数时符号为正；系数即为序数；字母的指数是序数的2倍，据此可得．【题目详解】由题意得，第n个单项式是（﹣1）n•n•x2n，所以第15个单项式是（﹣1）15•15•x2×15＝﹣15x1．故答案为：﹣15x1．【题目点拨】本题主要考查数字的变化类，分别找出单项式的系数和次数的规律是解决此类问题的关键．12、1【解题分析】设良马x日追及之，根据题意得：240x=150（x+12），解得x=1．13、-9或-1【分析】先根据点A所表示的数，再分两种情况进行讨论，当点A沿数轴向右移动和点A沿数轴向左移动时，列出式子，求出点B表示的数．【题目详解】解：∵点A表示-5，∴从点A出发，沿数轴向右移动4个单位长度到达B点，则点B表示的数是-5+4=-1；∴从点A出发，沿数轴向左移动4个单位长度到达B点，则点B表示的数是-5-4=-9；故答案为：-9或-1．【题目点拨】此题考查了数轴，解题的关键根据题意列出式子，再根据有理数的加减法法则进行计算，要考虑两种情况，不要漏掉．14、AB【分析】因为甲的速度是乙的速度的3倍，所以第1次相遇，甲走了正方形周长的133248⨯=；从第2次相遇起，每次甲走了正方形周长的34，4次一个循环，从而不难求得它们第2019次相遇位置.【题目详解】每次相遇的位置依次是：DC、AD、BA、BC，依此循环. 201945043÷=故它们第2019次相遇位置与第三次相同，在AB边上.【题目点拨】本题难度中等，主要考查学生对规律的总结能力，发现规律是解题的关键.15、②【分析】由数轴可以看出a＞b，且a＞1，b＜1，根据|a|＜|b|，据此做题．【题目详解】根据题意可得b＜1＜a，且|a|＜|b|，a﹣b＞1；ab＜1；|a|﹣|b|＜1．故正数有②．故答案为：②【题目点拨】本题考查数轴、绝对值和有理数的四则运算，解题的关键是掌握数轴上表示有理数、绝对值的计算.16、2点整或2点24011分或3点6011分或3点30011分【分析】根据2点整的时刻，时针与分针正好成60度角；设2点x分的时刻，时针与分针成60度角；设3点x分的时刻，时针与分针成60度角；设3点x分的时刻，时针与分针成60度角列方程即可得到结论．【题目详解】∵分针走一圈（360度）要1小时，即速度为360度/1小时＝360度/60分钟＝6度/分钟，钟面（360度）被平均分成了12等份，∴每份（相邻两个数字之间）是30度，∴设x分钟后，时针走过的角度为0.5x度，分针走过的角度为6x度，（1）显然2点整的时刻，时针与分针正好成60度角；（2）设2点x分的时刻，时针与分针成60度角，则应该是分针在前，有6x−（2×30＋0.5x）＝60，∴5.5x＝120，∴x＝240 11，∴2点24011的时刻，时针与分针成60度角；（3）设3点x分的时刻，时针与分针成60度角（时针可以在前），有3×0＋0.5x−6x＝60，∴5.5x＝30，∴x＝60 11，∴3点6011分的时刻，时针与分针成60度角；（4）设3点x分的时刻，时针与分针成60度角（分针可以在前），有6x−（3×30＋0.5x）＝60，∴5.5x＝150，∴x ＝30011， ∴3点30011分的时刻，时针与分针成60度角． 综上所述，时针和分针成60度角时的时间是2点整或2点24011分或3点6011分或3点30011分， 故答案为：2点整或2点24011分或3点6011分或3点30011分． 【题目点拨】本题考查了钟面角，掌握时针、分针的转动情况列出方程是解题的关键．三、解下列各题(本大题共8小题，共72分)17、（1）见解析；（2）57.5º；（3）40º【分析】（1）根据角平分线的定义可得∠COB=2∠COE ，然后根据对顶角相等可得∠AOD=∠COB ，从而证出结论； （2）根据对顶角相等和平角的定义即可求出∠BOD 和∠COB ，然后根据角平分线的性质即可求出∠EOB ，从而求出∠EOD ，再根据角平分线的定义即可求出∠EOF ；（3）设∠AOC=x °，根据对顶角相等可得∠BOD=∠AOC=x °，利用角的关系和角平分线的定义分别用x 表示出∠DOF 、∠EOF 、∠EOB 、∠COB ，然后利用∠AOC ＋∠COB=180°列方程即可求出∠AOC ．【题目详解】解：（1）∵OE 平分COB ∠，∴∠COB=2∠COE∵∠AOD=∠COB∴∠AOD=2∠COE（2）∵50AOC ∠=︒，∴∠BOD=∠AOC=50°，∠COB=180°－∠AOC=130°∵OE 平分COB ∠，∴∠EOB=12∠COB=65° ∴∠EOD=∠EOB ＋∠BOD=115°∵OF 是EOD ∠的角平分线∴∠EOF=12∠EOD=57.5︒ （3）设∠AOC=x °∴∠BOD=∠AOC=x °∴∠DOF=∠BOD ＋∠BOF=（x ＋15）°∵OF 是EOD ∠的角平分线∴∠EOF=∠DOF= （x ＋15）°∴∠EOB= ∠EOF ＋∠BOF=（x ＋30）°∵OE 平分COB ∠，∴∠COB=2∠EOB=（2x ＋60）°∵∠AOC ＋∠COB=180°∴x ＋（2x ＋60）=180解得x=40∴∠AOC=40°【题目点拨】此题考查的是角的和与差，掌握各角的关系、角平分线的定义和对顶角相等是解决此题的关键．18、（1）17cm EF =；（2）EF 的长度不变，17cm EF =；（3）()12EOF AOB COD ∠=∠+∠. 【分析】（1）根据已知条件求出BD=18cm ，再利用E 、F 分别是AC 、BD 的中点，分别求出AE 、BF 的长度，即可得到EF ；（2）根据中点得到12EC AC =，12DF DB =，由EF EC CD DF =++推导得出EF=()12AB CD +，将AB 、CD 的值代入即可求出结果；（3）由OE 、OF 分别平分AOC ∠和BOD ∠得到12COE AOC ∠=∠， 12DOF BOD ∠=∠，即可列得EOF COE COD DOF ∠=∠+∠+∠，通过推导得出()12EOF AOB COD ∠=∠+∠. 【题目详解】（1）∵30cm AB =，4cm CD =，8cm AC ，∴308418BD AB AC CD =--=--=cm ，∵E 、F 分别是AC 、BD 的中点， ∴142AE AC ==cm ， 192BF BD ==cm ， ∴304917EF AB AE BF =--=--=cm ，故17cm EF =；（2）EF 的长度不变. 17cm EF =∵E 、F 分别是AC 、BD 的中点， ∴12EC AC =，12DF DB = ∴EF EC CD DF =++1122AC CD BD =++1()2AC BD CD =++ ()12AB CD CD =-+ ()117cm 2AB CD =+= （3）∵OE 、OF 分别平分AOC ∠和BOD ∠， ∴12COE AOC ∠=∠， 12DOF BOD ∠=∠， ∴EOF COE COD DOF ∠=∠+∠+∠,1122AOC COD BOD =∠+∠+∠, 1()2AOC BOD COD =∠+∠+∠, 1()2AOB COD COD =∠-∠+∠, ()12AOB COD =∠+∠, ∴()12EOF AOB COD ∠=∠+∠. 【题目点拨】此题考查线段的和差、角的和差计算，解题中会看图形，根据图中线段或角的大小关系得到和差关系，由此即可正确解题.19、（1）A 、B 这动的速度分别为1单位长度/秒，3单位长度/秒；（2）2秒时，原点给好处在点A 点B 正中间；（3）C 行驶的路程是80个单位长度．【分析】（1）设点A 的速度为每秒x 个单位，则点B 的速度为每秒3x 个单位，由甲的路程＋乙的路程＝总路程建立方程求出其解即可；（2）设t 秒时原点恰好在A 、B 的中间，根据两点离原点的距离相等建立方程求出其解即可；（3）先根据追击问题求出A 、B 相遇的时间就可以求出C 行驶的路程．【题目详解】（1）设点A 的速度为每秒x 个单位，则点B 的速度为每秒3x 个单位，由题意，得4x ＋4×3x ＝16，解得：x ＝1，所以点A 的速度为每秒1单位长度/秒，则点B 的速度为3单位长度/秒．（2）设t 秒后原点位于A 、B 点正中间．(4)(123)02t t --+-=480t -+=2t =2∴秒时，原点给好处在点A 点B 正中间．（3）设B 点追上A 点的时间为1t 秒112(4)831t --==-（秒） ∴点C 行驶路程：10880⨯=（单位长度）C ∴行驶的路程是80个单位长度．【题目点拨】本题考查了列一元一次方程解实际问题的运用，数轴的运用，行程问题的相遇问题和追及问题的数量关系的运用，解答时根据行程问题的数量关系建立方程是关键．20、（1）90；（2）30；（3）16．【分析】(1)根据旋转的性质可知,旋转角为∠MON ;(2)如图3,利用平角的定义,结合已知条件:∠AOC :∠BOC =1：2,求得∠AOC =60°,然后由直角的性质、图中角与角的数量关系推知∠AOM -∠NOC =30°;(3)需要分类讨论:当OM 平分∠BOC 时,旋转角是60°;当ON 平分∠AOC 时,旋转角为240°．【题目详解】解:（1）根据旋转的性质可知: 旋转角为∠MON =1°, 故答案为1． （2）如图3,∠AOM -∠NOC =30°,理由如下: ∵∠AOC +∠BOC =180°,∠AOC :∠BOC =1:2, ∴∠AOC +2∠AOC =180°,∴∠AOC =60°，∴∠AON +CON =60°,① ∵∠MON =1°, ∴∠AOM +∠AON =1°,② ②-①,得∠AOM -∠CON =30°．（3）16．理由:如图,因点O 为直线AB 上一点,:2:1AOC BOC ∠∠=,所以120,60AOC BOC ︒︒∠=∠=,当OM 恰好为BOC ∠的平分线时,如图所示: 11603022AOC BOC ︒︒∠=∠=⨯=, 因为OM 旋转的角度9012030240︒︒︒︒=++=,所以此时三角板绕点O 运动的时间为2401615=, 所以当OM 恰好BOC ∠的平分线时,三角板绕点O 的运动时间为16秒．【题目点拨】本题主要考查了旋转的性质和角的计算,解决本题的关键是运用分类讨论思想,以防漏解．21、（1）22233-（231；（1）x =1 【分析】（1）根据实数的性质即可化简求解；（2）根据二次根式的运算法则即可求解；（1）设y+1=k(x-2),把4x =时，7y =代入求出k,即可求解．【题目详解】（1）原式13233=-22233=- （2）原式33123=-31=（1）设y+1=k(x-2),把4x =时，7y =代入得10=k(4-2)得k=5∴513y x =-当2y =时则5x-11=2得x =1．【题目点拨】此题主要考查实数的运算及正比例函数的性质，解题的关键是熟知实数的运算法则及待定系数法的运用．22、-4x+3 y 2；813【分析】根据合并同类项的运算法则，把整式进行同类项合并，然后代入x 、y 值计算即可． 【题目详解】解:13x －3(x －12y 2)＋(-43x ＋32y 2)=-x-3x+32y 2＋32y 2 =-4x+3 y 2 当x ＝－2，y ＝13时， 原式=8+13=813， 故答案为：-4x+3 y 2；813． 【题目点拨】本题考查了合并同类项的运算法则，掌握合并同类项的运算法则是解题的关键．23、（1）同；（2）A B 、两地之间的距离是1200km ．【分析】（1）根据相向而行和同向而行的定义即可得出答案；（2）先设出A 、B 两地之间的距离，再根据“高铁比动车早到2h”列出方程，解方程即可得出答案.【题目详解】解：（1）∵动车和高铁的起始点和目的地均相同∴动车和高铁是同向而行．（2）设A 、B 两地之问的距离为xkm ，根据题意得:2200300x x -=， 解得:1200x =．答：A 、B 两地之间的距离是1200km ．【题目点拨】本题考查的是一元一次方程在实际生活中的应用，比较简单，需要熟练掌握 “路程=速度×时间”这一公式及其变形.24、（1）当0≤t≤2时，s=30t ；当2＜t≤8时，s=120；当8＜t≤13时，s=－30t ＋1；（2）60海里；（3）9.6小时或10.2小时【分析】（1）由图象可得出渔船离港口的距离s 和它离开港口的时间t 的函数关系式，分为三段求函数关系式． （2）由图象可知，当8＜t≤13时，渔船和渔政船相遇，利用待定系数求渔政船的函数关系式，再与这个时间段渔船的函数关系式联立，可求相遇时，离港口的距离，再求两船与黄岩岛的距离．（3）在渔政船驶往黄岩岛的过程中，8＜t≤13，渔船与渔政船相距30海里，有两种可能：①s 渔－s 渔政=30，②s 渔政－s 渔=30，将函数关系式代入，列方程求t ．【题目详解】解：（1）当0≤t≤2时，s=30t ；当2＜t≤8时，s=120；当8＜t≤13时，s=－30t ＋1．（2）设渔政船离港口的距离s 与渔船离开港口的时间t 之间的函数关系式为s=kt+b ，则 8k b 0?{34k b 1503+=+=，解得k 45{?b 360==-． ∴s=42t －360联立545360530390t t =-⎧⎨=-+⎩，解得t 10{s 90== ∴渔船离黄岩岛的距离为120－90=60（海里）．（3）∵s 30t 390s 45t 360=-+=-渔渔政，，∴分两种情况：①－30t ＋1－（42t －360）=30，解得t=9.6；②42t －360－（－30t ＋1）=30，解得t=10.2．∴当渔船离开港口9.6小时或10.2小时时，两船相距30海里．。

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