2017高二期中试卷

2017年春高二下学期期中考班级：姓名： 号数： 难度： 成绩：一、选择题：本题共12小题,每小题4分,共48分.在每小题给出的四个选项中,第1～8题只有一项符合题目要求,第9～12题有多项符合题目要求.全部选对的得4分,选对但不全的得2分,有选错的得0分.1、某用电器两端的正弦交变电压的表达式为311sin100u t V π=（）.关于这个交变电压,下列说法中正确的是（ ）A .有效值为311VB .有效值为440VC .最大值为311VD .最大值为440V 2、如图所示,理想变压器原线圈的匝数11000n =匝,副线圈的匝数2200n =匝.原线圈两端所加的电压1220U V =时,副线圈两端的电压2U 为（ ）A .1100VB .44VC .440VD .22V 3、关于下图i t -函数图像,下列说法中正确的是（ ）A .该函数图像表示的是直流电B .该电流的周期是0.01sC .用电流表测量该电流得到的值为5AD .用电流表测量该电流得到的值为 4、关于磁通量,下列说法中正确的是（ ）A .过某一平面的磁通量为零,该处磁感应强度不一定为零B .磁通量不仅有大小,而且有方向,所以是矢量C .磁感应强度越大,磁通量越大D .磁通量即使磁感应强度5、面积是20.50m 的导线环,处于磁感应强度为24.010T -⨯的匀强磁场中,环面的法向量与磁场夹角为30︒,穿过导线环的磁通量等于（ ）A .22.510Wb -⨯B .21.010Wb -⨯C .21.510Wb -⨯D .2410Wb -⨯6、在图甲所示的电路中,理想变压器原线圈两端的正弦交变电压变化规律如图乙所示.已知变压器原、副线圈的匝数比12:10:1n n =,串联在原线圈电路中电流表1A 的示数为1A ,下列说法正确的是（ ）A .电压表V 的示数为2002VB .变压器的输出功率为20WC .100HzD .电流表2A 的示数为10A 7、对于正弦式交流电,下列说法正确的是（ ） A .电流在一周期内方向改变两次,大小随时间变化 B .电流在一周期内方向改变一次,大小随时间变化C .线圈在中性面时穿过线圈的磁通量最大,电动势最大D .线圈在垂直于中性面的位置磁通量为零,电动势为零8、理想变压器在正常工作时,原、副线圈中不一定相同的物理量是（ ） A .交变电流的频率 B .原线圈的磁通量变化率和副线圈的磁通量变化率C .原线圈的输入功率和副线圈的输出功率D .原线圈的感应电动势和副线圈的感应电动势9、将4Ω的电阻接到内阻不计的交流电源上,该电源电动势e 随时间t 变化规律如图所示,下列说法中正确的是（ ）A .电路中交变电流的频率为2.5HzB .2C .电阻消耗的电功率为2WD .10、理想变压器原线圈两端电压不变,当副线圈电路中的电阻减小时,一下说法正确的是（ ） A .输出电流增大,输入电流减小 B .输出电流增大,输入电流增大 C .输出电压保持不变 D .输出功率和输入功率都增大 11、下列关于电磁感应现象的说法中,正确的是（ ）A .磁通量变化率越大感应电动势就越大B .导体相对磁场运动,导体内一定产生感应电流C .感应电动势与匝数无关D .磁通量为零,感应电动势不一定为零 12、如图,当通电直导线MN 中的电流突然增大时（方向未知）,则可确定的是（ ）A .线框中感应电流的方向B .线框各边受磁场力的方向C .线框整体受磁场力的方向D .线框中电流方向、受磁场力的方向皆不可确定二、简答题（共12分,每题6分）1、什么是电磁感应现象？产生感应电流的条件是什么？/B T 2、简述牛顿三大定律的基本内容三、计算题（共40分,每题10分）1、输送4400kW 的电功率,采用110kV 高压输电,输电导线中的电流是多少?如果用110V 电压输电,输电导线中的电流将是多少?若输电线阻值为10Ω,则电功率的损耗分别为多少?你能得出什么结论?2、如图1所示,一个单匝矩形线圈长10.2L m =,宽20.1L m =,匀强磁场垂直线圈平面向里.磁感强度B 随时间t 变化的规律如图2所示.求 1)当1t s =时,穿过矩形线圈中的磁通量; 2)线圈中感应电动势,并画出感应电流方向./t s3、如图所示,MN 、PQ 是两根足够长的光滑平行金属导轨,导轨间距为l ,导轨所在的平面与水平面夹角为 ,M 、P 间接阻值为R 的电阻.匀强磁场的方向与导轨所在平面垂直,磁感应强度大小为B .质量为m 、阻值为r 的金属棒放在两导轨上,在平行于导轨的拉力作用下,以速度v 匀速向上运动.已知金属棒与导轨始终垂直并且保持良好接触,导轨阻值不计,重力加速度为g ,求: 1)金属棒产生的感应电动势E ;2)通过电阻R 的电流I ; 3)拉力F 的大小. 4、如右图所示,质量为m 带电量为q 的粒子在只受电场力的作用下,从A 点静止开始运动,沿直线运动到B 点。

2016-2017学年山东省菏泽市高二（下）期中数学试卷（理科）一、选择题：本大题共12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1．（5分）下列求导运算正确的是（）A．（x）′=1B．（x2cosx）′=﹣2xsinxC．（3x）′=3x log3e D．（log2x）′=2．（5分）用反证法证明命题“设a，b为实数，则方程x3+ax+b=0至少有一个实根”时，要做的假设是（）A．方程x3+ax+b=0没有实根B．方程x3+ax+b=0至多有一个实根C．方程x3+ax+b=0至多有两个实根D．方程x3+ax+b=0恰好有两个实根3．（5分）复数的实部与虚部分别为（）A．7，﹣3 B．7，﹣3i C．﹣7，3 D．﹣7，3i4．（5分）设f（x）=xlnx，若f′（x0）=2，则x0等于（）A．e2B．e C． D．ln25．（5分）函数f（x）=e x﹣x（e为自然对数的底数）在区间[0，1]上的最大值是（）A．1+B．1 C．e+1 D．e﹣16．（5分）已知积分，则实数k=（）A．2 B．﹣2 C．1 D．﹣17．（5分）在用数学归纳法证明不等式++…+≥（n≥2）的过程中，当由n=k推到n=k+1时，不等式左边应（）A．增加了B．增加了+C．增加了+，但减少了D．以上都不对8．（5分）设曲线y=x2+1在其任一点（x，y）处切线斜率为g（x），则函数y=g （x）cosx的部分图象可以为（）A．B．C．D．9．（5分）直线y=2x+3与抛物线y=x2所围成的弓形面积是（）A．20 B．C．D．10．（5分）函数f（x）=﹣（a＜b＜1），则（）A．f（a）=f（b）B．f（a）＜f（b）C．f（a）＞f（b）D．f（a），f（b）大小关系不能确定11．（5分）已知函数f（x）=x2+，若函数f（x）在x∈[2，+∞]上是单调递增的，则实数a的取值范围为（）A．a＜8 B．a≤16 C．a＜﹣8或a＞8 D．a≤﹣16或a≥1612．（5分）设f（x）是定义在R上的可导函数，且满足f′（x）＞f（x），对任意的正数a，下面不等式恒成立的是（）A．f（a）＜e a f（0）B．f（a）＞e a f（0）C．D．二、填空题（每题5分，满分20分，将答案填在答题纸上）13．（5分）已知函数f（x）=x3﹣4x2+5x﹣4．求曲线f（x）在点（2，f（2））处的切线方程．14．（5分）观察下列等式：（1+1）=2×1（2+1）（2+2）=22×1×3（3+1）（3+2）（3+3）=23×1×3×5…照此规律，第n个等式可为．15．（5分）在Rt△ABC中，三边长分别为a，b，c，则c2=a2+b2，则在同一顶点引出的三条两两垂直的三棱锥V﹣ABC中，则有．16．（5分）已知函数f（x）的定义域为[﹣1，5]，部分对应值如下表，f（x）的导函数y=f'（x）的图象如图所示．下列关于f（x）的命题：①函数f（x）的极大值点为0，4；②函数f（x）在[0，2]上是减函数；③如果当x∈[﹣1，t]时，f（x）的最大值是2，那么t的最大值为4；④当1＜a＜2时，函数y=f（x）﹣a有4个零点．其中正确命题的序号是．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．（10分）已知复数z=1+i（i为虚数单位）．（1）设ω=z2+3﹣4，求|ω|；（2）若=2﹣i，求实数a的值．18．（12分）在如图所示的几何体中，四边形ABCD为矩形，直线AF⊥平面ABCD，EF∥AB，AD=2，AB=AF=2EF=1，点P在棱DF上．（1）求证：AD⊥BF；（2）若P是DF的中点，求异面直线BE与CP所成角的余弦值；（3）若，求二面角D﹣AP﹣C的余弦值．19．（12分）某商场销售某种商品的经验表明，该商品每日的销售量y（单位：千克）与销售价格x（单位：元/千克）满足关系式y=+10（x﹣6）2，其中3＜x＜6，a为常数．已知销售价格为5元/千克时，每日可售出该商品11千克．（Ⅰ）求a的值；（Ⅱ）若该商品的成品为3元/千克，试确定销售价格x的值，使商场每日销售该商品所获得的利润最大．20．（12分）已知数列{a n}满足S n+a n=2n+1．（1）写出a1，a2，a3并推出的a n表达式；（2）用数学归纳法证明所得的结论．21．（12分）已知函数f（x）=x3+ax2+bx+c在x=﹣与x=1时都取得极值．（1）求a、b的值与函数f（x）的单调区间；（2）若对x∈[﹣1，2]，不等式f（x）＜c2恒成立，求c的取值范围．22．（12分）已知函数f（x）=x﹣alnx（a∈R）．（1）当a=2时，求曲线f（x）在x=1处的切线方程；（2）设函数h（x）=f（x）+，求函数h（x）的单调区间．2016-2017学年山东省菏泽市高二（下）期中数学试卷（理科）参考答案与试题解析一、选择题：本大题共12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1．（5分）下列求导运算正确的是（）A．（x）′=1B．（x2cosx）′=﹣2xsinxC．（3x）′=3x log3e D．（log2x）′=【解答】解：A．（x+）′=1﹣，∴A错误．B．（x2cosx）′=﹣2xsinx﹣x2sinx，∴B错误．C．（3x）′=3x ln3，∴C错误．D．（log2x）′=，正确．故选：D．2．（5分）用反证法证明命题“设a，b为实数，则方程x3+ax+b=0至少有一个实根”时，要做的假设是（）A．方程x3+ax+b=0没有实根B．方程x3+ax+b=0至多有一个实根C．方程x3+ax+b=0至多有两个实根D．方程x3+ax+b=0恰好有两个实根【解答】解：反证法证明问题时，反设实际是命题的否定，∴用反证法证明命题“设a，b为实数，则方程x3+ax+b=0至少有一个实根”时，要做的假设是：方程x3+ax+b=0没有实根．故选：A．3．（5分）复数的实部与虚部分别为（）A．7，﹣3 B．7，﹣3i C．﹣7，3 D．﹣7，3i【解答】解：=，∴z的实部与虚部分别为7，﹣3．故选：A．4．（5分）设f（x）=xlnx，若f′（x0）=2，则x0等于（）A．e2B．e C． D．ln2【解答】解：∵f（x）=xlnx，∴f′（x）=lnx+1，由f′（x0）=2，得lnx0+1=2，即lnx0=1，则x0=e，故选：B．5．（5分）函数f（x）=e x﹣x（e为自然对数的底数）在区间[0，1]上的最大值是（）A．1+B．1 C．e+1 D．e﹣1【解答】解：求导函数，可得f′（x）=e x﹣1∵x∈[0，1]，∴f′（x）≥0，f（x）在[0，1]单调递增，∴f（x）max=f（1）=e﹣1，∴函数f（x）=e x﹣x在区间[0，1]上的最大值是e﹣1，故选：D．6．（5分）已知积分，则实数k=（）A．2 B．﹣2 C．1 D．﹣1【解答】解：∵，∴=k∴∴k=2故选：A．7．（5分）在用数学归纳法证明不等式++…+≥（n≥2）的过程中，当由n=k推到n=k+1时，不等式左边应（）A．增加了B．增加了+C．增加了+，但减少了D．以上都不对【解答】解：当n=k时，左侧式子为+++…+，当n=k+1时，左侧式子为++…+++，∴当由n=k推到n=k+1时，不等式左边减少了，增加了+．故选：C．8．（5分）设曲线y=x2+1在其任一点（x，y）处切线斜率为g（x），则函数y=g （x）cosx的部分图象可以为（）A．B．C．D．【解答】解：g（x）=2x，g（x）•cosx=2x•cosx，g（﹣x）=﹣g（x），cos（﹣x）=cosx，∴y=g（x）cosx为奇函数，排除B、D．令x=0.1＞0．故选：A．9．（5分）直线y=2x+3与抛物线y=x2所围成的弓形面积是（）A．20 B．C．D．【解答】解：解得直线y=2x+3与抛物线y=x2的交点坐标为：（﹣1，1）（3，9）∴直线y=2x+3与抛物线y=x2所围成的弓形面积S=∫（2x+3﹣x2）dx=（x2+3x ﹣）|=（9+9﹣9）﹣（1﹣3+）=故选：C．10．（5分）函数f（x）=﹣（a＜b＜1），则（）A．f（a）=f（b）B．f（a）＜f（b）C．f（a）＞f（b）D．f（a），f（b）大小关系不能确定【解答】解：∵，f′（x）=﹣=∴当x＜1时，f'（x）＜0，即f（x）在区间（﹣∞，1）上单调递减，又∵a＜b＜1，∴f（a）＞f（b）故选：C．11．（5分）已知函数f（x）=x2+，若函数f（x）在x∈[2，+∞]上是单调递增的，则实数a的取值范围为（）A．a＜8 B．a≤16 C．a＜﹣8或a＞8 D．a≤﹣16或a≥16【解答】解：∵函数f（x）=x2+在x∈[2，+∞）上单调递增，∴f′（x）=2x﹣=≥0在x∈[2，+∞）上恒成立；∴2x3﹣a≥0，∴a≤2x3在x∈[2，+∞）上恒成立，∴a≤2×23=16∴实数a的取值范围为a≤16．故选：B．12．（5分）设f（x）是定义在R上的可导函数，且满足f′（x）＞f（x），对任意的正数a，下面不等式恒成立的是（）A．f（a）＜e a f（0）B．f（a）＞e a f（0）C．D．【解答】解：∵f（x）是定义在R上的可导函数，∴可以令f（x）=，∴f′（x）==，∵f′（x）＞f（x），e x＞0，∴f′（x）＞0，∴f（x）为增函数，∵正数a＞0，∴f（a）＞f（0），∴＞=f（0），∴f（a）＞e a f（0），故选：B．二、填空题（每题5分，满分20分，将答案填在答题纸上）13．（5分）已知函数f（x）=x3﹣4x2+5x﹣4．求曲线f（x）在点（2，f（2））处的切线方程x﹣y﹣4=0．【解答】解：由f（x）=x3﹣4x2+5x﹣4，得f′（x）=3x2﹣8x+5，∴f′（2）=1，又f（2）=﹣2．∴曲线f（x）在点（2，f（2））处的切线方程为y+2=1（x﹣2），即x﹣y﹣4=0．故答案为：x﹣y﹣4=0．14．（5分）观察下列等式：（1+1）=2×1（2+1）（2+2）=22×1×3（3+1）（3+2）（3+3）=23×1×3×5照此规律，第n个等式可为（n+1）（n+2）（n+3）…（n+n）=2n•1•3•5…•（2n ﹣1）．【解答】解：题目中给出的前三个等式的特点是第一个等式的左边仅含一项，第二个等式的左边含有两项相乘，第三个等式的左边含有三项相乘，由此归纳第n 个等式的左边含有n项相乘，由括号内数的特点归纳第n个等式的左边应为：（n+1）（n+2）（n+3）…（n+n），每个等式的右边都是2的几次幂乘以从1开始几个相邻奇数乘积的形式，且2的指数与奇数的个数等于左边的括号数，由此可知第n个等式的右边为2n•1•3•5…（2n﹣1）．所以第n个等式可为（n+1）（n+2）（n+3）…（n+n）=2n•1•3•5…（2n﹣1）．故答案为（n+1）（n+2）（n+3）…（n+n）=2n•1•3•5…（2n﹣1）．15．（5分）在Rt△ABC中，三边长分别为a，b，c，则c2=a2+b2，则在同一顶点引出的三条两两垂直的三棱锥V﹣ABC中，则有．【解答】解：由a，b，c为直角三角形的三边，其中c为斜边，则a2+b2=c2，类比到空间中：在四面体V﹣ABC中，∠AVB=∠BVC=∠CVA=90°，则．故答案为16．（5分）已知函数f（x）的定义域为[﹣1，5]，部分对应值如下表，f（x）的导函数y=f'（x）的图象如图所示．下列关于f（x）的命题：①函数f（x）的极大值点为0，4；②函数f（x）在[0，2]上是减函数；③如果当x∈[﹣1，t]时，f（x）的最大值是2，那么t的最大值为4；④当1＜a＜2时，函数y=f（x）﹣a有4个零点．其中正确命题的序号是①②．【解答】由导函数的图象可知：当x∈（﹣1，0），（2，4）时，f′（x）＞0，函数f（x）增区间为（﹣1，0），（2，4）；当x∈（0，2），（4，5）时，f′（x）＜0，函数f（x）减区间为（0，2），（4，5）．由此可知函数f（x）的极大值点为0，4，命题①正确；∵函数在x=0，2处有意义，∴函数f（x）在[0，2]上是减函数，命题②正确；当x∈[﹣1，t]时，f（x）的最大值是2，那么t的最大值为5，命题③不正确；2是函数的极小值点，若f（2）＞1，则函数y=f（x）﹣a不一定有4个零点，命题④不正确．∴正确命题的序号是①②．故答案为：①②．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．（10分）已知复数z=1+i（i为虚数单位）．（1）设ω=z2+3﹣4，求|ω|；（2）若=2﹣i，求实数a的值．【解答】解：（1）由复数z=1+i，得．则ω=z2+3﹣4=（1+i）2+3（1﹣i）﹣4=1+2i﹣1+3﹣3i﹣4=﹣1﹣i，故|ω|=；（2）====2﹣i，由复数相等的充要条件得：，解得a=3．18．（12分）在如图所示的几何体中，四边形ABCD为矩形，直线AF⊥平面ABCD，EF∥AB，AD=2，AB=AF=2EF=1，点P在棱DF上．（1）求证：AD⊥BF；（2）若P是DF的中点，求异面直线BE与CP所成角的余弦值；（3）若，求二面角D﹣AP﹣C的余弦值．【解答】证明：（1）∵AF⊥平面ABCD，∴AF⊥AD，又AD⊥AB，AB∩AF=A，AD⊥平面ABEF，又BF⊂平面ABEF，∴AD⊥BF．（2）解：∵直线AF⊥平面ABCD，AB⊂平面ABCD，∴AF⊥AB，由（1）得AD⊥AF，AD⊥AB，∴以A为原点，AB，AD，AF所在直线为x，y，z轴，建立空间直角坐标系，则B（1，0，0），E（，0，1），P（0，1，），C（1，2，0），∴=（﹣），=（﹣1，﹣1，），设异面直线BE与CP所成角为θ，则cosθ==，∴异面直线BE与CP所成角的余弦值为．（3）解：∵AB⊥平面ADF，∴平面ADF的一个法向量．由知P为FD的三等分点，且此时．在平面APC中，，．∴平面APC的一个法向量．…（10分）∴，又∵二面角D﹣AP﹣C的大小为锐角，∴该二面角的余弦值为．…（12分）19．（12分）某商场销售某种商品的经验表明，该商品每日的销售量y（单位：千克）与销售价格x（单位：元/千克）满足关系式y=+10（x﹣6）2，其中3＜x＜6，a为常数．已知销售价格为5元/千克时，每日可售出该商品11千克．（Ⅰ）求a的值；（Ⅱ）若该商品的成品为3元/千克，试确定销售价格x的值，使商场每日销售该商品所获得的利润最大．【解答】解：（Ⅰ）因为x=5时，y=11，所以+10=11，故a=2（Ⅱ）由（Ⅰ）可知，该商品每日的销售量y=所以商场每日销售该商品所获得的利润为从而，f′（x）=10[（x﹣6）2+2（x﹣3）（x﹣6）]=30（x﹣6）（x﹣4）于是，当x变化时，f（x）、f′（x）的变化情况如下表：由上表可得，x=4是函数f（x）在区间（3，6）内的极大值点，也是最大值点．所以，当x=4时，函数f（x）取得最大值，且最大值等于42答：当销售价格为4元/千克时，商场每日销售该商品所获得的利润最大．20．（12分）已知数列{a n}满足S n+a n=2n+1．（1）写出a1，a2，a3并推出的a n表达式；（2）用数学归纳法证明所得的结论．【解答】解：（1）当n=1时，S1+a1=2a1=3，∴，当n=2时，S2+a2=a1+a2+a2=5，∴，同样令n=3，则可求出，∴，，，猜测．（2）证明：①由（1）已得当n=1时，命题成立；②假设n=k时，命题成立，即，=2（k+1）+1，当n=k+1时，a1+a2+…+a k+2a k+1且a1+a2+…+a k=2k+1﹣a k，=2（k+1）+1=2k+3，∴2k+1﹣a k+2a k+1∴，即，即当n=k+1时，命题成立．根据①②得n∈N+，都成立．21．（12分）已知函数f（x）=x3+ax2+bx+c在x=﹣与x=1时都取得极值．（1）求a、b的值与函数f（x）的单调区间；（2）若对x∈[﹣1，2]，不等式f（x）＜c2恒成立，求c的取值范围．【解答】解；（1）f（x）=x3+ax2+bx+c，f'（x）=3x2+2ax+b由解得，f'（x）=3x2﹣x﹣2=（3x+2）（x﹣1），函数f（x）的单调区间如下表：所以函数f（x）的递增区间是（﹣∞，﹣）和（1，+∞），递减区间是（﹣，1）．（2），当x=﹣时，f（x）=+c为极大值，而f（2）=2+c，所以f（2）=2+c为最大值．要使f（x）＜c2对x∈[﹣1，2]恒成立，须且只需c2＞f（2）=2+c．解得c＜﹣1或c＞2．22．（12分）已知函数f（x）=x﹣alnx（a∈R）．（1）当a=2时，求曲线f（x）在x=1处的切线方程；（2）设函数h（x）=f（x）+，求函数h（x）的单调区间．【解答】解：（1）∵当a=2时，f（x）=x﹣2lnx（a∈R），∴f′（x）=1﹣，∴f′（1）=﹣1，∵f（1）=1，∴曲线f（x）在x=1处的切线方程为y﹣1=﹣（x﹣1），即x+y﹣2=0；（2）∵h（x）=f（x）+，∴h′（x）=，∴a＞﹣2时，h′（x）＞0，可得x＜﹣1或x＞1+a，h′（x）＜0，可得﹣1＜x＜1+a，∴函数的单调增区间是（﹣∞，﹣1），（1+a，+∞）；单调减区间是（﹣1，1+a）；a=﹣2时，h′（x）≥0，∴函数的单调增区间是（0，+∞）；a＜﹣2时，h′（x）＞0，可得x＜1+a或x＞﹣1，h′（x）＜0，可得1+a＜x＜﹣1，∴函数的单调增区间是（0，1+a），（﹣1，+∞）；单调减区间是（1+a，﹣1）．赠送：初中数学几何模型举例【模型四】几何最值模型：图形特征：l运用举例：1. △ABC中，AB=6，AC=8，BC=10，P为边BC上一动点，PE⊥AB于E，PF⊥AC于F，M为AP的中点，则MF的最小值为EM FB2.如图，在边长为6的菱形ABCD中，∠BAD＝60°，E为AB的中点，F为AC上一动点，则EF+BF的最小值为_________。

2017年高二下学期数学（理）期中试卷(成都九校联考含答案)2016～2017 学年度（下期）高201 级期中联考试卷理科数学考试时间共120 分钟，满分10 分试卷分为第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）注意事项：1答题前，考生务必在答题卡上将自己的姓名、班级、准考证号用0 毫米黑色签字笔填写清楚，考生考试条码由监考老师粘贴在答题卡上的“条码粘贴处”。

2选择题使用2B 铅笔填涂在答题卡上对应题目标号的位置上，如需改动，用橡皮擦擦干净后再填涂其它答案；非选择题用0 毫米黑色签字笔在答题卡的对应区域内作答，超出答题区域答题的答案无效；在草稿纸上、试卷上答题无效。

3考试结束后由监考老师将答题卡收回。

第Ⅰ卷选择题（共60 分）一、选择题（本大题共12 小题，每小题分，共60 分，在每小题给出的四个选项中，只有一个是符合题目要求的）→→→→1．三棱柱AB—A1B11 中，若A＝a，B＝b，1＝，则A1B等于() A．a＋b－B．a－b＋．－a＋b＋D．－a＋b－2．函数f ( x) ៕ sin x  ex ，则f ‘(0)的值为()第1 题图A．1B．2．3D．03 已知，n 表示两条不同直线，α表示平面．下列说法正确的是() A．若∥α，n∥α，则∥nB．若⊥α，n⊂α，则⊥n ．若⊥α，⊥n，则n∥αD．若∥α，⊥n，则n⊥αx4．函数f ( x) ៕ 的单调递减区间是()ln xA．(0, e)B．(e,᠐)．(0,1), (1, e)D(᠄᠐, e)．在棱长为2 的正方体ABD ᠄ A1 B11 D1 中，是底面ABD 的中心，E、F 分别是1 、AD 的中点，那么异面直线E 和FD1 所成的角的余弦值等于()A．1B．10．4D．23－π，π6．已知函数f(x)＝x－sin x，若x1，x2∈22 ，且f(x1)＋f(x2)>0，则下列不等式中正确的是()A．x1>x2 B．x1<x2．x1＋x2>0D．x1＋x2<07 某几何体的三视图如图所示，且该几何体的体积是3，则正视图中的x 的值是()A．3 B．92．3D．22第7 题图8．若对任意的x>0，恒有lnx≤px－1(p>0)，则p 的取值范围是()A．(0,1]B．(1，＋∞)．(0,1)D．[1，＋∞)9．甲、乙两人约定在下午4:30  :00 间在某地相见，且他们在4:30  :00 之间到达的时刻是等可能的，约好当其中一人先到后一定要等另一人20 分钟，若另一人仍不到则可以离去，则这两人能相见的概率是()38A．B．49711．D．161210．如图在一个60 的二面角的棱上有两个点A，B，线段分别A、BD 在这个二面角的两个面内，并且都垂直于棱AB，且AB＝A＝a ，BD＝2a ，则D 的长为()A．2a B．aAB．aD．3aD11．已知函数f ( x) ៕ ax3  bx2  x  d 的图象如图所示，则b  1 的取值范围是()a  1第10 题图A．(᠄ 3 , 1 )B．(᠄ 2 ,1)122 2-10x．(᠄ 1 , 3 )D．(᠄ 3 ,1)2 22第11 题图x 2 212．已知F1 ，F2 分别为双曲线：᠄a 2b 2៕ 1 的左、右焦点，若存在过F1 的直分别交双曲线的左、右支于 A ， B 两点，使得BAF2 ៕ BF2 F1 ，则双曲线的离心率e 的取值范围是()A．3,᠐B．1,2   3,2  D．1,3第Ⅱ卷非选择题（共90 分）二、填空题（本大题共4 小题，每小题分，共20 分）13．1 x2dx = ．0第12 题图2 22 214．已知椭圆1 : 2  2ab៕ 1(a ៖ b ៖ 0) 与双曲线2 : x ᠄ ៕4 有相同的右焦点F2 ，点P 是1 和2 的一个公共点，若PF2៕ 2 ，则椭圆1 的离心率等于．1．四棱柱ABD－A1B11D1 中，底面为平行四边形，以顶点A 为端点的三条棱长都相等，且两两夹角为60°则线段A1 与平面AB 所成角的正弦值为ex16．已知函数f  x  ៕ 1 ᠄x2  x  1，若存在唯一的正整数x0 ，使得 f  x0   0 ，则实数的取值范围为．三、解答题（本大题共 6 小题，第17 题满分10 分，18-22 每题满分12 分，共70 分；解答应写出字说明、证明过程或演算步骤）17．如图，在直三棱柱AB ᠄ A1B11 中，A ៶ B ，点D 是AB 的中点，求证：（Ⅰ）A ៶ B1 ；（Ⅱ）A1 // 平面B1D ．18．某校举行汉字听写比赛，为了了解本次比赛成绩情况，从得分不低于0 分的试卷中随机抽取100 名学生的成绩(得分均为整数，满分100 分)进行统计，请根据频率分布表中所提供的数据，解答下列问题：组号分组频数频率第1 组[0，60)00第2 组[60，70)a03第3 组[70，80)30b第4 组[80，90)20020第组[90，100]10010合计100100（Ⅰ）求a、b 的值；（Ⅱ）若从成绩较好的第3、4、组中按分层抽样的方法抽取 6 人参加市汉字听写比赛，并从中选出 2 人做种子选手，求2 人中至少有1 人是第4 组的概率．19．已知函数f(x)＝x2＋2aln x（Ⅰ）若函数f(x)的图象在(2，f(2))处的切线斜率为1，求实数a 的值；（Ⅱ）求函数f(x)的单调区间；2（Ⅲ）若函数g(x)＝＋f(x)在[1,2]上是减函数，求实数a 的取值范围．x20．在四棱锥P -ABD 中，△ PAB 为正三角形，四边形ABD 为矩形，平面PAB ៶ 平面ABD ，AB =2 AD ，,N 分别为PB,P 的中点（Ⅰ）求证：N //平面PAD ；（Ⅱ）求二面角B—A—的大小；（Ⅲ）在B 上是否存在点E ，使得EN ⊥平面AN ？BE若存在，求B的值；若不存在，请说明理由．21．已知椭圆: x៕ 1 a ៖ b ៖ 0  经过点P(1,3 ) ，离心率e ៕ 3ab（Ⅰ）求椭圆的标准方程；22 ．（Ⅱ）设过点E 0 , ᠄ 2  的直线l 与相交于P, Q 两点，求ៜPQ 面积的最大值．22．已知f ( x) ៕1 x2 ，g ( x) ៕ a ln x(a ៖ 0)2（Ⅰ）求函数F ( x) ៕（Ⅱ）若函数G( x) ៕取值范围；f ( x) g ( x) 的极值；f ( x) ᠄g ( x)  (a ᠄ 1) x 在区间(1 , e) 内有两个零点，求的e（Ⅲ）函数h( x) ៕ g  x  ᠄ x 1 ，设x  (0,1) ，x  (1, ᠐) ，若h( x ) ᠄ h( x )x1 2 2 1存在最大值，记为(a) ，则当a  e  1 时，(a) 是否存在最大值？若存在，求出e其最大值；若不存在，请说明理由．2016～2017学年度（下期）高201级期中联考数学（理科）参考答案及评分建议一、选择题：（每小题分，共60分）1D；2B；3B；4；A；6；7A；8D；9B；10A；11D；12；二、填空题（每小题分，共20分）13 ；14 ；1 ；16 ；三、解答题（共70分）17．证明：（1）在直三棱柱中，平面，所以，，又，，所以，平面，所以，………………（分）（2）设与的交点为，连结，为平行四边形，所以为中点，又是的中点，所以是三角形的中位线，，又因为平面，平面，所以平面………（10分）18．(1)a＝100－－30－20－10＝3，b＝1－00－03－020－010＝030 ………（4分）(2)因为第3、4、组共有60名学生，所以利用分层抽样在60名学生中抽取6名学生，每组分别为，第3组：660×30＝3人，第4组：660×20＝2人，第组：660×10＝1人，所以第3、4、组应分别抽取3人、2人、1人．……………（6分）设第3组的3位同学为A1、A2、A3，第4组的2位同学为B1、B2，第组的1位同学为1，则从6位同学中抽2位同学有1种可能，如下：(A1，A2)，(A1，A3)，(A1，B1)，(A1，B2)，(A1，1)，(A2，A3)，(A2，B1)，(A2，B2)，(A2，1)，(A3，B1)，(A3，B2)，(A3，1)，(B1，B2)，(B1，1)，(B2，1)．其中第4组被入选的有9种，所以其中第4组的2位同学至少有1位同学入选的概率为91＝3……………（12分）19 (1)f′(x)＝2x＋2ax＝2x2＋2ax，由已知f′(2)＝1，解得a＝－3 ……… 4分(2)函数f(x)的定义域为(0，＋∞) ……… 分①当a≥0时，f′(x)＞0，f(x)的单调递增区间为(0，＋∞)；……… 6分②当a＜0时，f′(x)＝2(x＋－a)x－－ax当x变化时，f′(x)，f(x)的变化情况如下：x(0，－a)－a(－a，＋∞)f′(x)－0＋极小值由上表可知，函数f(x)的单调递减区间是(0，－a)；单调递增区间是(－a，＋∞) ……… 8分(3)由g(x)＝2x＋x2＋2aln x，得g′(x)＝－2x2＋2x＋2ax，由已知函数g(x)为[1,2]上的单调减函数，则g′(x)≤0在[1,2]上恒成立，即－2x2＋2x＋2ax≤0在[1,2]上恒成立．即a≤1x－x2在[1,2]上恒成立………10分令h(x)＝1x－x2，在[1,2]上h′(x)＝－1x2－2x＝－(1x2＋2x)＜0，所以h(x)在[1,2]上为减函数，h(x)in＝h(2)＝－72，所以a≤－72故实数a的取值范围为{a|a≤－72} ……… 12分20 （Ⅰ）证明：∵，N分别是PB，P中点∴N是△AB的中位线∴N∥B∥AD又∵AD⊂平面PAD，N 平面PAD所以N∥平面PAD ………………4分(Ⅱ)过点P作P垂直于AB，交AB于点，因为平面PAB⊥平面ABD，所以P⊥平面ABD，如图建立空间直角坐标系设AB=2，则A（-1,0，0），（1,1，0）,（,0，）, B（1,0，0），N（, ，），则，设平面A法向量为，由可得，令，则，即平面法向量所以，二面角的余弦值因为二面角是锐二面角，所以二面角等于………………8分（Ⅲ）存在………………9分设，则，由可得，所以在存在点，使得平面，此时………………12分21（Ⅰ）由点在椭圆上得，①②由①②得，故椭圆的标准方程为 (9)22：（1）解：∴………1分由得，由，得∴在上单调递减，在上单调递增，∴，无极大值………3分（2）解：∴又，易得在上单调递减，在上单调递增，要使函数在内有两个零点，需，即，………分∴，∴，即的取值范围是………7分（3）若，∵在上满足，∴在上单调递减，∴∴不存在最大值………8分则∴方程有两个不相等的正实数根，令其为，且不妨设则在上单调递减，在上调递增，在上单调递减，对，有；对，有，∴∴将，代入上式，消去得∵，∴，据在上单调递增，得设，，∴，即在上单调递增∴∴存在最大值为………12分。

2017学年度第一学期高二语文期中考试试题卷一、现代文阅读（35分）（一）论述类文本阅读（共9分）阅读下面的文字，完成1～3题。

（每小题3分）“示众”有悠远的历史，在文明史上，“示众”担当的功能主要是惩罚，其次是教育，“杀鸡给猴看”、“以儆效尤”。

我们看示众现象，多半发生在战争、政治、司法、教育领域，它的威慑力、它唤起“示众的材料”和“看客”的羞耻心，都起到了“杀一儆百”的作用。

关于示众的起源没有人提供答案，政治学家、教育学家、心理学家难以肯定它究竟是政治人物发明，还是教育者创造，抑或是父母总结出来的。

如果按照《易经》提供的线索，我们大概能够猜想，示众在中国，是统治者们的杰作。

无论是谈论市场经济的“噬嗑卦”，还是谈论教育的“蒙卦”，先人都系辞以“示众”一类的字样。

“噬嗑卦”的系辞是，亨，利用狱。

蒙卦的系辞是，“利用刑人，用说桎梏。

”可以说，无论起源，东西方人是不约而同地发现了“示众”的功能，它利用人性深处的羞耻心，使人“浪子回头”、“知错认错”，使围观者引以为耻引以为戒，不越雷池一步。

示众有过巨大的历史意义。

当代学者汤一介曾说文明会经历三阶段：“专制为体，教化为用”的阶段；“自由为体，民主为用”的阶段；“和谐为体，中庸为用”的阶段。

可以说，示众正是文明第一阶段的应有之义；或者说，凡是示众文化盛行的地方，不过仍处在第一阶段而已。

在这个层面上，西方走在人类的前头。

早在18世纪末，一位名叫本杰明·鲁思的西方学者就把示众柱等刑罚史上的物品视为野蛮时代和野蛮国家的标记，视为理性对人们心灵影响微弱的证据。

我们今天看到，示众现象在发达国家是越来越少了，在我国也遭到大众的抵制和不安，因为示众冒犯人的尊严。

当专制不用教化的时代，示众就失去了意义。

示众只是权势者的游戏，这种游戏只能培育冷血的看客。

当一个文明体不再能以专制为本体的时代，示众也会失去意义。

革命者不怕示众，甚至以示众相标榜。

陈毅有诗为证：断头今日意如何？创业艰难百战多。

伊宁县第二中学2016—2017学年第二学期期中考试高二年级数学考试时间：120分钟总分：150分命题人：谢红英第Ⅰ卷一．选择题（每题5分，共60分）1.若函数32()21f x x x=+-，则(1)f'-=（）A.7-B.C. 1-D.72若曲线y=x4的一条切线l与直线x+4y﹣8=0垂直，则l的方程是（）A．4x﹣y﹣3=0 B．x+4y﹣5=0 C．4x﹣y+3=0 D．x+4y+3=03.双曲线4y2﹣25x2=100的焦点坐标是（）A．（﹣5，0），（5，0）B．（0，﹣5），（0，5）C．， D．，4.双曲线x2﹣=1的离心率是（）A．B． C． D．25.抛物线x2=4y的准线方程是（）A．y=﹣1 B．y=﹣2 C．x=﹣1 D．x=﹣26.已知a＝(－3,2,5)，b＝(1，x，－1)且a·b＝2，则x的值是()A．3 B．4 C．5 D．67.如下图是函数y=f(x)的导函数y=f′(x)的图象,则下面判断正确的是（）A.在区间(－2,1)内f(x)是增函数B.在(1,3)内f(x)是减函数C.在(4,5)内f(x)是增函数D.在x=2时,f(x)取到极小值8.已知△ABC的顶点B，C在椭圆+y2=1上，顶点A是椭圆的一个焦点，且椭圆的另外一个焦点在BC边上，则△ABC的周长是（）A． B．6 C． D．129.已知函数f（x）=sinx+lnx，则f′（1）的值为（）A．1﹣cos1 B．1+cos1 C．cos1﹣1 D．﹣1﹣cos110.曲线y=x2上的点P处的切线的倾斜角为4π，则点P的坐标为（）A．（0，0） B．（2，4）C．（，） D．（，）11.已知()2,5,1A-，()2,2,4B-，()1,4,1C-，则AC与AB的夹角为（）A．30︒ B．45︒ C．60︒ D．90︒12.过抛物线24y x=焦点F的直线交抛物线于A、B两点，交其准线于点C，且A、C位于x轴同侧，若2AC AF=，则BF等于A．2 B．3 C．4 D．5二．填空题（每小题5分，共20分）13.已知函数()f x的导数为2'()f x x x=-，则当x=时，函数()f x取得极大值14. 函数sin xy x=的导数为________________ 15.设抛物线y 2=﹣12x 上一点P 到y 轴的距离是1，则点P 到该抛物线焦点的距离是 ．16.椭圆：x 216＋y 24＝1内有一点P(2,1)，则经过P 并且以P 为中点的弦所在直线方程为____________． 16．x ＋2y －4＝0解析 设弦的两个端点为M (x 1，y 1)，N (x 2，y 2)，则⎩⎪⎨⎪⎧x 2116＋y 214＝1x 2216＋y 224＝1，两式相减，得(x 1＋x 2)(x 1－x 2)16＋(y 1＋y 2)(y 1－y 2)4＝0. 又x 1＋x 2＝4，y 1＋y 2＝2，k MN ＝y 1－y 2x 1－x 2，∴k MN ＝－12，由点斜式可得弦所在直线的方程为y ＝－12(x －2)＋1，即x ＋2y －4＝0.三．解答题（共60分，写出必要的计算、证明或者说明）17（10分）求下列函数的单调区间和极值（需写出必要的文字说明及表格）32()267f x x x =-+；18.（12分）已知函数y=xlnx （1）求这个函数的导数；（2）求这个函数的图象在点x=1处的切线方程．19（12分）如图，在正方体ABCD —A 1B 1C 1D 1中，E 、F 分别是BB 1、D 1B 1的中点，求证： EF ⊥平面B 1AC.20（12分）已知椭圆的焦点是F 1(－1,0)、F 2(1,0)，P 是椭圆上的一点，若|F 1F 2|是|PF 1|和|PF 2|的等差中项，求该椭圆的方程 答案] x 24＋y 23＝1解析] 由题意得2|F 1F 2|＝|PF 1|＋|PF 2|， ∴4c ＝2a ，∵c ＝1，∴a ＝2. ∴b 2＝a 2－c 2＝3， 故椭圆方程为x 24＋y 23＝1.21（12分）在四棱锥P －ABCD 中，底面是边长为∠BAD ＝120°，且P A ⊥平面ABCD ，P A＝，M ，N 分别为PB ，PD 的中点．(1)证明：MN ∥平面ABCD ；(2)过点A 作AQ ⊥PC ，垂足为点Q ，求二面角A －MN －Q 的平面角的余弦值．22．（12分）设函数32()2338f x x ax bx c =+++在1x =及2x =时取得极值．（1）求a 、b 的值；（2）若对于任意的[03]x ∈，，都有2()f x c <成立，求c 的取值范围．22．解：（1）2()663f x x ax b '=++，因为函数()f x 在1x =及2x =取得极值，则有(1)0f '=，(2)0f '=． 即6630241230a b a b ++=⎧⎨++=⎩，．解得3a =-，4b =．（2）由（Ⅰ）可知，32()29128f x x x x c =-++，2()618126(1)(2)f x x x x x '=-+=--．当(01)x ∈，时，()0f x '>； 当(12)x ∈，时，()0f x '<； 当(23)x ∈，时，()0f x '>． 所以，当1x =时，()f x 取得极大值(1)58f c =+，又(0)8f c =，(3)98f c =+． 则当[]03x ∈，时，()f x 的最大值为(3)98f c =+． 因为对于任意的[]03x ∈，，有2()f x c <恒成立， 所以 298c c +<， 解得 1c <-或9c >，因此c 的取值范围为(1)(9)-∞-+∞ ，，．。

2017学年度第一学期高二年级英语学科期中考试（考试时间：120分钟满分：150分）第I卷 (共110分)I. Listening Comprehension（25分）Section A (10×1=10分)Directions: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a qu estion will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a c onversation and the question about it, read the four possible a nswers on your paper, and decide which one is the best answ er to the question you have heard.1. A. All day.B. Only in the morning.C. Only in the afternoon.D. The same as weekdays.2. A. Doctor and patient.B. Customer and salesgirl.C. Man and wife.D. Customer and waitress.3. A. The woman changed the reservation.B. The woman made no reservation.C. The woman made the reservation for the 9:30 flight.D. The woman misunderstood the man.4. A. Stay in the garden.B. Join the man.C. Watch TV.D. Do some housework.5. A. About seven or eight days.B. Four or five days.C. Exactly one week.D. More tha n ten days.6. A. Britain. B. Italy. C. Spain.D. France.7. A. On a boat trip. B. In a cin ema.C. At the beach.D. In a restaurant.8. A. At 10:05. B. At 5:10.C. At 10:40.D. At 5:20.9. A. Travel agency clerk.B. Office secretary.C. Head nurse.D. Hotel receptionist.10.A. 12 years. B. 24 years. C. 6 years.D. 18 years.Section B(10×1.5=15分)Directions: In Section B, you will hear several longer conversa tion(s) and short passage(s), and you will be asked several qu estions on each of the conversation(s) and the passage(s). Th e conversation(s) and the passage(s) will be read twice, but th e questions will be spoken only once. When you hear a questi on, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. Having no children gives a couple more freedom.B. Having children in youth brings a couple plenty of joy.C. A couple will enjoy life with their children.D. A couple think of children as a nuisance(讨厌的人).12. A. The desire for a job.B. The desire for a free lifestyle.C. The desire for further education.D. The desire for beauty.13. A. To build a career in communication.B. To have a baby soon.C. To enjoy life better.D. To have a large circle of friends.Questions 14 through 16 are based on the following passage.14. A. People from Holland.B. People from Britain.C. People from Germany.D. The Puerto Ricans.15. A. Asians. B. Irishmen.C. Eastern Europeans.D. Italians.16. A. For adventure.B. For religious freedom.C. For a better life.D. For independence.Questions 17 through 18 are based on the following conversa tion.17. A. They had difficulty understanding their professor.B. They got stuck in the beginning.C. They had no talent for writing.D. They didn’t like detective stories.18. A. To go shopping.B. To get herself relaxed.C. To look for inspiration for her story.D. To meet Prof. Wilson.Questions 19 through 20 are based on the following conversa tion.19. A. She has trouble learning English.B. She is often late for class.C. She has won a scholarship.D. She is absent-minded in class.20. A. She is doing well in study.B. She has to deliver milk every morning to earn her school fees.C. Her parents fell ill two months ago.D. She has behaved well in school.II. Grammar and VocabularySection A (10×2=20分)Directions: Read the following passage. Fill in the blanks to make the passage coherent. For the blanks with a given word, fi ll in each blank with the proper form of the given word. For the other blanks, fill in each blank with one proper word. Make su re that your answers are grammatically correct.Stress：Good or Bad?Stress used to be an almost unknown word, but now that we are used to talking about it, I have found that people are begin ning to get stressed about being stressed.In recent years，stress（21）（regard） as a cause of a whole range of medi cal problems, from high blood pressure to mental illness. But l ike so many other things, it is only too much stress（22） does you harm. It is time you（23）________(consider) that if there were no stress in your life, yo u would achieve a little. If you are stuck at home with no stres s, then your level of performance will be low. Up to a certain p oint, the more stress you are under, the（24）_______（good） your performance will be. Beyond a certain point, th ough, further stress will only lead to exhaustion, illness and fin ally a breakdown. You can tell when you are over the top and on the downward slope, by asking yourself （25） num ber of questions. Do you, for instance, feel that too much is be ing expected of you, and yet find（26） impossible to say no？Do you find yourself getting impatient or（27）（annoy）with people over unimportant things？…If the answer to all th ose questions is yes, you had better（28）（control）your stress, as you probably are under more stress than is go od for you.To some extent, you can control the amount of stress in your l ife. Doctors have worked out a chart showing how much stres s is involved（29）_______various events. Getting married is 50, pregnancy 40, moving house 20, Christmas 12, etc. If the total stress in your life is over 150, you are twice as likely（30）（get）ill.Section B (10分)Directions: Complete the following passage by using the word s in the box. Each word can only be used once. Note that ther e is one word more than you need.In a society, such as the United States or Canada, which has many national, religious, and cultural differences, people___3 1___ value individualism——the differences among people. Teachers place a lot of importa nce on the____32___ that make each student special. The ed ucational systems in these countries show these values. Stud ents do not memorize information. Instead, they work ____33_ ___and find answers themselves. There is often discussion in the classroom. At an early age, students learn to form their o wn ideas and opinions.In most Asian societies, on the contrary, people have the sam e language, history, and culture. Perhaps for this reason, the educational system in much of the Orient ___34____ society’s belief in group goals and purposes rather than individualism. Children in China, Japan, and Korea often work together and help one another on assignments. In the classroom, the teach ing __35____ are often very formal. The teacher lectures, and the students listen. There is not much discussion. Instead, the students recite rules or information that they have memorized .There are advantages and disadvantages to both of these____36___ of education. For example, one advantage to the syst em in Japan is that students there learn much more math and science than American students learn by the end of high sch ool. They also study more hours each day and more days eac h year than North Americans do. The system is difficult, but it ___37___students for a society that values discipline and self-control. There is, however, a disadvantage. Memorization is a n____38_____ learning method in Japanese schools, yet man y students say that after an exam, they forget much of the info rmation they have memorized.The advantage of the educational system in North America, o n the other hand, is that students learn to think for themselves . The system prepares them for a society that values ___39__ __ ideas. There is, however, a disadvantage. When students graduate from high school, they haven't ___40____as many b asic rules and facts as students in other countries have.III． Reading ComprehensionSection A (15分)Directions: For each blank in the following passage there are f our words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Just as the stock market rises and falls in response to what people are willing to put their money behind, we have inside ou rselves an inner economy that rises and falls in response to o ur beliefs about what is possible．Sometimes the degree to w hich we are willing to （41）our belief systems determi nes the success of our inner economy．For example, imagine that your family of origin had a belief that musical talent was not something they（42）. As a member of that group, you would likely （43） that same belief about yourself. As a result, even i f you had a great desire to create music, you might be （44）to really get behind yourself．Because you might fear th at your （45） would not pay off．Even if you had the c ourage to follow your passion, your inner belief that you are n ot （46） would probably stop your trying．And that wo uld be a major （47） to invest your energy in your dre am．On the other hand，belief isn't anything （48）．If you found a way to （49）_______ that negative belief, a great flood of energy wo uld pour forth, greatly increasing the possibility of your succes s. How much energy we are willing to invest in the various ide as and dreams is like the money people are, or are not, willingto invest in the various products available for trade on the sto ck market．And in both cases, （50） plays a key role in determining how willing we are to get behind something．O ne way to open up the possibility for greater success in our in ner economies is to understand that belief is not the reliable （51） we sometimes think．There are other more reli able things of success that we can put our（52） in, such as passion, feeling, and sense．Some of the most successful investors in the stock market are the o nes that go against the grain, trusting their sense over the （53） opinion held by ordinary people about what will work．In the same way，we can learn to trust our heart's desires and our sense to guid e us,（54）____ any beliefs that stand in the way of our ability to ful ly invest in ourselves. As we take out energy from limiting ide as about what is possible, we（55） the resources that have the power to make our i nner economy prosper．41．A．simplifB．challenge C．eliminate D．maintainy42．A．possessedB．trusted C．objected D．missed 43．A．reject B．preserve C．deny D．share 44．A．willing B．sorry C．reluctant D．ready45．A．succes s B．knowledgeC．professionD．investment46．A．devote d B．talented C．concernedD．interested47．A．obstacleB．excuse C．chance D．principle48．A．import ant B．fixed C．changeableD．stimulating49．A．enhanceB．reserve C．release D．follow 50．A．energy B．hobby C．expense D．belief 51．A．guide B．ability C．goal D．policy 52．A．aim B．faith C．task D．dream53．A．unacce ptable B．strange C．unbelievableD．common54．A．questio ning B．understandingC．interpretingD．believing55．A．stick to B．lead to C．free up D．leave outSection B（11×2=22分）Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. Fo r each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information give n in the passage you have just read.(A)Today, we tell about a popular graduate degree known as the MBA. The letters represent the words Master of Business Ad ministration.MBA students learn to deal with all kinds of business situation s. They learn to solve business problems. They develop skills needed by many different kinds of companies.All MBA programs teach students about subjects including ec onomics, the structure of organizations, finance, marketing and policy. Students then do more study in areas that interest th em. It usually takes two years to get an MBA degree if you att end school full-time. Many programs permit students to take classes while th ey work. These programs take longer to complete.Business is one of the most popular areas of study for foreign students in the United States. To be admitted to an MBA prog rams, foreign students must show a clear understanding of En glish by taking the TOEFL test. All students must also take th e Graduate Management Admission Test (GMAT). The score s on this test are used by more than 1,500 graduate programs throughout the world.Studying for an MBA can be costly. The program at the Unive rsity of Virginia, for example, costs more than $22,000 a year. That cost does not include housing and food. Foreign student s can get financial aid for MBA studies after the first year. The Darden School of Business at the University of Virginia today has 120 foreign students studying for an MBA degree.To get information about studying for an MBA, use the compu ter and go to a website called MBA Explorer. The Internet add ress is . Another way is to go to a meeting of th e Graduate Management Admission Council. These meetings are called MBA Forums. They are held in different cities in several areas of the world. At the MBA Forums, representatives of business colleges explain their programs and answer quest ions from people interested in studying business.56. Which of the following is NOT mentioned in the MBA prog ram?A. The structure of organization.B. Policy.C. Economics.D. Mathematics.57. MBA Forums are_____________.A. held in different cities in AmericaB. to help MBA students to learn to deal with all personal prob lemsC. the meeting of the Post-graduate Management Administration CouncilD. the meetings where representatives of business colleges c an explain their programs58. Studying for an MBA degree, all the students______.A. can get financial aid for MBA studies after the first yearB. can get a degree after one year of studyC. develop skills needed by many different kinds of companie sD. who study at the University of Virginia must pay no more th an $22,000 a year excluding housing and food.59. Which of the following statements is NOT true?A. MBA stands for Master of Business Administration.B. To get an MBA degree, you should usually spend two year s in attending school full-time.C. Economics is the most popular area of study in the United States.D. All students applying for an MBA program must take the G MAT.(B)60. How often will an employee generally get paid?A. Every Friday.B. Every two weeks.C. Every week.D. Every other Monday.61. Who has the authority to approve the overtime an employ ee wishes to do?A. Cashier.B. Safety department officer.C. Supervisor.D. Human resources officer.62. Where should employees go if they wish to have the parki ng charge taken off their salary?A. Human Resources.B. Business Of fice.C. Cashier’s Office.D. Safety De partment.（C）Talking to human-like devices can be great fun – just ask Siri to tell you a joke. But it may also lead to problems.A recent study by scientists from the University of Kansas (KU ) in the US found that human-like devices keep people from seeking out normal human inter action when they feel lonely.During a series of experiments, participants were asked to wri te about a time when they felt lonely. They also took part in an online game of “catch” against a computer program that was designed to “throw” the ball to other players more often, but p articipants believed they were playing with real people online. Participants were then introduced to human-like products, including a vacuum cleaner (真空吸尘器) designed to appear as if it were smiling. They were also a sked to think about their phone in human-like terms, considering questions like “how much does it help you?”The results showed that the participants were happy with the comfort they got from the machines and didn’t need to seek o ut normal human interaction.Generally, when people feel socially excluded, they seek out other ways to reduce the feeling of loneliness. Normal ways in clude increasing their number of social media friends or enga ging in behaviors to seek out interaction with other people, ac cording to Jenny Olson, assistant professor of marketing at K U.But it wasn’t all bad news, as the team found that there were li mits to how far this effect would extend.“As soon as we tell people we know that it looks like the [vacuum cleaner] is smiling, they seemed to realize it was a machin e and not a person,” Olson told Daily Mail. “The effect goes a way. This seems to be happening on a very subconscious lev el.”Researchers believe the results are important for consumers t o realize how these types of products could affect their social i nteraction with real people, especially because so many new products feature interactivity.“If someone notices they are talking more to Siri lately, maybe that has something to do with feeling lonely,” Olson said. “Fro m that standpoint, it’s important to be aware of it.”The study could also help companies design products that ca n increase the well-being of people who feel lonely, without sacrificing normal soc ial interaction.“Maybe it is more about improving our current relationships,”Olson said, “such as taking a break from screen time and focu sing on developing your real personal connections.”63. Researchers from the University of Kansas found that____ ____.A. human-like devices may help people interact with others.B. interaction with human-like devices may make people feel lonely.C. lonely people may easily become addicted to human-like devices.D. human-like devices may reduce pe ople’s social interaction in real life.64. During the experiments, participants__________.A. were allowed to talk with human-like devices.B. were shown devices with human features.C. played online games with both machines and real people.D. were encouraged to engage in normal human interaction.65. The underlined phrase “this effect” in Paragraph 7 refers t o the fact that________.A. lonely people are more likely to seek out interaction with ot her people.B. lonely people are content to only interact with human-like machines.C. the feeling of loneliness deepens as people interact more with human-like devices.D. people who are socially excluded would get uninterested in socializing.66. What is the significance of the study according to Jenny Olson?A. It shows people why human-like products make them feel lonely.B. It warns people to stop using human-like devices completely and focus on real social interaction. C. It may help the well-being of people who feel lonely and improve their current relat ionships.D. It points out the effects of human-like devices and could help companies improve their products .Section C （4×2=8分）Directions: Read the following passage. Fill in each blank with a proper sentence given in the box. Each sentence can be us ed only once. Note that there are two more sentences than yo u need.In 2009, the number of hungry people in the world reached on e billion for the first time. It's difficult not to be shocked by the f act that more than one in seven people in the world do not ha ve enough to eat. 67 Hunger kills more people per year t han diseases such as AIDS, malaria（疟疾）and TB (肺结核) combined.The UN estimates that almost two thirds of the world's hungry people are in Asia, which is of course the world's most populo us continent. 68 Although this region has a much lower p opulation than Asia, it has the highest percentage of hungry p eople. Almost all of the rest are in Latin America, North Africa and the Caribbean. In the richest regions of the world there ar e only a tiny number of people who don’t have enough to eat.69 They include wars, droughts, floods, and the ove r-use of farming land. All these factors affect food production. M any people also blame greedy businessmen for pushing up th e prices of basic foods in the global market. But the most imp ortant reason, quite simply, is poverty, which has increased re cently due to the financial crisis of 2008.Although many people make the obvious point that there woul d be less hunger if the global population were smaller, few pe ople would argue that there is not enough food to go around. The basic problem seems to be not a lack of food, but its distri bution. In the last 50 years, global food production has risen e ven more quickly than the global population. There are many areas of the world in which people generally have more than enough food. 70 The answer to world hunger, therefore, may be a balanced food distribution around the whole world. Everyone will have enough to eat, but not overeat.IV. Summary Writing (10分)Directions: Read the following passage. Summarize the main idea and the main points of the passage in no more than 60 w ords. Use your own words as far as possible.Most people want to be happy, but few know how to find happiness. Money and success alone do not bring lasting happine ss. Aristotle, a Greek thinker, said, "Happiness depends upon ourselves." In other words, we make our own happiness. Here are a few suggestions to help you be happier.The first secret of happiness is to enjoy the simple things in lif e. Too often, we spend too much time thinking about the futur e-for example, getting into college or getting a good job-that we fail to enjoy the present. You should enjoy life's simpl e pleasures, such as reading a good book, listening to your fa vorite music, or spending time with close friends. People who have several close friends often live happier and healthier live s.Another secret to living a happy life is to be active. Many peop le go dancing or play sports. People can forget about their pro blems and only think about the activities.Finally, many people find happiness in helping others. Studies show that people feel good when they spend their time helpin g others. If you want to feel happier, do good things for someo ne. You can help a friend with his or her studies, go shopping to buy food for an elderly person, or simply help out around th e house by washing the dishes.第II 卷 (共40分)I. Translation（3+3+4+5=15分）Directions: Translate the following sentences into English, usi ng the words given in the brackets.71. 据说他不久就要被提升为总经理。

高二期中考试英语试卷第一部分：听力（共两节，满分30分）第一节(共5小题；每小题l.5分，满分7.5分)听下面5段对话。

每段对话后有一小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷相应位置。

听完每段对话后，你都有10秒钟的时间回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What will the man do?A. Open the window.B. Find another room.C. Go out with the woman.2. What’s the date of the woman’s birthday?A. March 15th.B. March 11th.C. March 7th.3. What does the man mean?A. John has some personal problems.B. The problem is common for young men.C.It’s not common for young men to leave home.4. What will the man most probably do?A. Get some change from Jane.B. Go and look for a payphone.e Jane’s mobile phone.5. What does the man mean?A. It was impossible for him to go to the party.B. Everybody was surprised by his appearance at the party.C. He had expected to go to the party for a long time.第二节（共15小题；每小题1.5分，满分22.5分）请听下面5段对话或独白，选出最佳选项。

2017年广东省广州市岭南中学高二年级第一学期期中考试语文试卷一、古代诗文阅读（37 分）（一）文言文阅读与积累。

（本题共6小题，21分）阅读下面的文字，完成1～4题。

《报任安书》司马迁古者富贵而名摩灭，不可胜．记，唯倜傥非常之人称．焉。

盖文王拘而演《周易》；仲尼厄而作《春秋》；屈原放逐，乃赋《离骚》；左丘失明，厥有《国语》；孙子膑脚，《兵法》修列；不韦迁蜀，世传《吕览》；韩非囚秦，《说难》、《孤愤》；《诗》三百篇，大底圣贤发愤之所为作也。

此人皆意有所郁结，不得通其道，故述往事，思来者。

乃如左丘无目，孙子断足，终不可用，退而论书策，以舒其愤，思垂空文以自见．。

仆窃不逊近自托于无能之辞网罗天下放失旧闻略考．其行事综其终始稽其成败兴坏之纪上计轩辕下至于兹为十表本纪十二书八章世家三十列传七十凡百三十篇。

亦欲以究天人之际，通古今之变，成一家之言。

草创未就，会遭此祸，惜其不成，是以就极刑而无愠色。

仆诚以著此书，藏之名山，传之其人，通邑大都，则仆偿前辱之责，虽万被戮，岂有悔哉！然此可为智者道，难为俗人言也。

1．下列加点字的解释不．正确的一项是（3分）( )A．古者富贵而名摩灭，不可胜．记胜：尽，全B．唯倜傥非常之人称．焉称：称道C．思垂空文以自见．见：看见D．略考．其行事考：考证2．下列语句中加点的词与现代汉语意思相同的一项是（3分）( )A．古者富贵．．而名摩灭B．大底圣贤发愤．．之所为作也C．略考其行事．．之人称焉．．D．唯倜傥非常3．对《报任安书》中的思想与内容解释不．正确的一项是（3分）( )A．作者借给任安回信的机会，阐明自己受刑后隐忍苟活的原因，表达了坚持完成《史记》的决心。

B．司马迁认为古代“圣贤发愤之所为作”，都是作者“有所郁结，不得通其道”，“述往事，思来者”，把苦苦思索得到的知识，著述成文，留给来者去思辨验察。

C．这封书信是司马迁的苦心孤诣之作，写得情真意切；作者“为情而造文”，自始至终表达了悲痛的感情。

期中考试试卷高二数学（文）参考答案一、选择题（每小题4分，共40分）1.B2.C3.A4.D 5、C 6.C 7.B 8.D 9、A 10. D二、填空题（每小题4分，共16分） 11. 12. n 313. 1 14. 3三、解答题（共44分,每题11分）15、证明：（1） ∵222a b ab +≥,222a c ac +≥，222b c bc +≥将此三式相加得 2222()222a b c ab ac bc ++≥++,∴原式成立 …… 5分（2）要证原不等式成立，只需证（6+7）2>（22+5）2即证402422>。

∵上式显然成立, ∴原不等式成立. …… 11分16、解析：(1)由ρ＝2知ρ2＝4，所以x 2＋y 2＝4；因为ρ2－22ρcos ⎝⎛⎭⎫θ－π4＝2， 所以ρ2－22ρ⎝⎛⎭⎫cos θcos π4＋sin θsin π4＝2， 所以x 2＋y 2－2x －2y －2＝0. …………………5分(2)将两圆的直角坐标方程相减，得经过两圆交点的直线方程为x ＋y ＝1，化为极坐标方程为ρcos θ＋ρsin θ＝1，即ρsin ⎝⎛⎭⎫θ＋π4＝22………11分17、（1）根据科成绩在85分以上（含85分），则该科成绩为优秀，结合表格中的数据，即可得2×2列联表；（2）利用列联表中的数据，利用公式求得2K ，再与提供的临界值比较，即可得结论试题解析：（1）……5分（2）根据列联表可以求得 ()2220512128.802 6.635614713k ⨯⨯-⨯==>⨯⨯⨯ 所以,我们有99%的把握认为:学生的数学成绩与物理成绩之间有关系……11分18、解：（Ⅰ） 由2sin cos (0)a a ρθθ=>得22sin cos (0)a a ρθρθ=>. ∴曲线C 的直角坐标方程为2(0)y ax a =>.…………………………2分 直线l 的普通方程为2y x =-. ………………………………………4分（Ⅱ）将直线l 的参数方程代入曲线C 的直角坐标方程2(0)y ax a =>中，得28)4(8)0t a t a +++=.设A B 、两点对应的参数分别为12,t t ,则有12128),4(8).t t a t t a +=+⋅=+………………………………7分 ∵2PA PB AB ⋅=，∴21212()t t t t -=⋅ 即21212()5t t t t +=⋅.……………9分∴2)]20(8),a a +=+解之得：2a =或8a =- (舍去),∴a 的值为2…. 11分。

2016-2017学年第一学期期中试高二数学（理科）试题本试卷题目共4页，请在答题卷上作答，满分150分，考试时间120分数参考公式：1.线性回归方程ˆy=ˆb x +ˆa 中，1221ˆni ii nii x ynx y b xnx ==-=-∑∑， ˆa=y -ˆb x ； 2.方差2222121[()()()]n s x x x x x x n=-+-+⋅⋅⋅+-.一、选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中， 只有一项是符合题目要求的.1.为了了解某校高三级2000名学生某天体育锻炼的时间，从中抽取了80名学 生体育锻炼的时间进行统计分析. 在这个问题中, 80名学生的体育锻炼时间 的全体是A. 总体B.个体C.样本的容量D.样本 2.某中学初中部共有110名教师，高中部共有150名 教师, 其性别比例如图所示, 则该校男教师的人数为 A. 93 B. 123 C. 137 D. 167 3. sin 215°- cos 215°= A.-C. -12D.124. 某市2014年各月的平均气温(°C)数据的茎叶图如右图 则这组数据中的中位数是A. 19B.20C. 21.5D. 235. 设命题p ：∀n ∈N, n 2＞2n ，则⌝p 为A. ∃∉N, n 2≤2nB.∃n ∈N, n 2≤2nC.∀n ∈N, n 2≤2nD.∃n ∈N, n 2＜2n 6.已知变量x 与y 负相关, 且由观测数据算得样本平均数x =3, y =3.5, 则由 观测的数据得线性回归方程可能为A.ˆy=0.4x +2.3 B.ˆy =2x –2.5 C.ˆy = –2x +9.5 D.ˆy = –0.3x +4.3 7. 若将一个质点随机投入如图所示的正方形ABCD 中, 则 质点落在以AB 为半径的扇形内（阴影部分）的概率是A. 2πB.4πC. 6πD. 8π 8. 从1,2,3,4中任取2个不同的数, 则取出的2个数之差的绝对值为1的概率是A.12错误！未找到引用源。