高中化学离子方程式大全及练习(绝对精品)

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无机化学部分非金属单质(F2 , Cl2 , O2 , S, N2 , P , C , Si)1.氧化性:F2 + H 2 === 2HF2F2 +2H 2O===4HF+O 2占弊Cl£ +Hg--2HC1 占烬…—Pg 占烬=^PC153C12 +2Fe占燃-CuCl; Cl 2 +2FeCI 2 ===2FeCI 3 2CI2+2NaBr===2NaCI+Br2 CI2 +2NaI ===2NaCI+I2 CI2+SO2 +2H2O===H2SO4 +2HCI (2004 北京咼考)占燃20i +3Fe J,.Fe304—H^SS + Fe 乙FeS S + 2Cu =£= Cu2S N 4- JR;•咼恳咼压-2NH3 催化剂d ■ irx ail_—血訓ES + 02 J'_ so a S+6HNO 3(浓)===H 2SO4+6NO 2 t +2H 2O 3S+4 HNO 3(稀)===3SO 2+4NO t +2H 2O4P + 50£山x …占撚(X2表示F2, CI2, Br2)占燃2C ■+ 少重)…2C0 C + 0"足量)J,co2 PX 3+X 2===PX 5 C+CO 2===2CO(生成水煤气)a—■ I 曰(制得粗硅)啦(粉)+ 02 Si0£Si+2NaOH+H 2O===Na 2SQ3+2H 21 3.(碱中)歧化CI 2+H 2O===HCI+HCIO(加酸抑制歧化,加碱或光照促进歧化)CI2+2NaOH===NaCI+NaCIO+H 2O2CI 2+2Ca(OH)2===CaCI 2+Ca(CIO)2+2H2O金属单质(Na, Mg , Al, Fe )的还原性4Na+O 2===2Na 2O占琳2Na£0 + J, ' 2Na£O2占燃2Na + 02Ng2Na+S===Na 2S (爆炸)2Na+2H 2O===2NaOH+H 21Mg+H 2SO4===MgSO 4+H 212Mg + 02「2HlgO2A1 + 3Cli =^= 2A1C134A1 + 302…2A12O32AI+6HCI===2AICI 3+3H 2 t2AI+3H 2SO4===AI 2(SO4)3+3H2t2AI+6H 2SO4(浓、热)===AI 2(SO4)3+3SO2t +6H2O(AI,Fe在冷,浓的H2SO4,HNO 3中钝化)AI+4HNO 3(稀)===AI(NO 3)3+NO t +2H 2O2AI+2NaOH+2H 2O===2NaAIO 2+3H 21 2A1 +C“(h 二+2Cr言•■曰4A1 + SMnOa ,m2AI2O3 + 3Mn有,回2A1 + F S203' m AlzOs + 2Fe3Fe + 4H20 Cg)=^= Fe^04 + 4H时Fe+2HCI===FeCI 2+H21Fe+CuCI 2 ===FeCI 2+Cu非金属氢化物(HF,HCI,H2O,H2S,NH3)1•还原性:4HC1 (浓)+ MnO? =^= MnClj + 3时+ 2H£016HCI+2KMnO==2KCI+2MnCl2+5CI 21 +8H2O (实验室常用2H z S+SO===3SJ +2H z O2H 述 + 02CJ> 量)2S + 2H202H2S 亠302 (足重)=—=2S0^ + 2H2O2NH+3CI 2===N2+6HCI8NH+3CI 2===N Z+6NHCI4NH J+3Q(纯氧)===2N2+6H2O2NHs + 3CuO 3Cu + N2+ 3HR4NH3 + 5O24N0 + 6H20△4NHj+6NO===5N+6HaO(用氨清除NO)2.酸性:4HF+SiQ===SiF4+2HO (HF保存在塑料瓶的原因,此反应广泛应用于测定矿样或钢样中SiO2的含量)HS+CuC2===CuSj +2HCIHS+FeCl2===(不反应)3.碱性:NH+HCI===NHCINH+HNO===NHNO2NH+HSQ===(NH)2SO NH+NaCI+H2O+CG>==NaHC9Nh l CI(此反应用于工业制备小苏打,苏打)4.不稳定性:2H2Q===2HO+Ot非金属氧化物1•低价态的还原性:△2SO2+O2+2H2O===2H 2SO4(这是SO2在大气中缓慢发生的环境化学反应)SO2+Cl2+2H2O===H2SO4+2HCI2NO+O2===2NO22CO+O2===2CO2CO + CuO Cu + CO^CO + H20 同帰CO 2 + Hz 3C0 + Fe205=^= 2Fe +3C0a2.氧化性:NO2+2KI+H 2O===NO+I 2 J +2KOH(不能用淀粉.KI溶液鉴别溴蒸气和NO2)2Mg + C02=^= 2fflg0 + C(CO不能用于扑灭由Mg,Ca,Ba,Na,K等燃烧的火灾)3.与水的作用:)SO2+H2O===H 2SO3SO3+H2O===H 2SO43NO2+H2O===2HNO 3+NON2O5+H2O===2HNO 3P2O5+H2O (冷)===2HPO3P2O5+3H2O (热)===2H 3PO4(P2O5极易吸水,可作气体干燥剂)4.与碱性物质的作用:SO2+(NH 4)2SO3+H2O= = = 2NH 4HSO3(这是硫酸厂回收SO2的反应.先用氨水吸收SO2,再用H2SO4 处理:2NH4HSO3+H2SO4= = = (NH4)2SO4 + 2H2O+ 2SO2生成的硫酸铵作化肥,SO2循环作原料气)SO2+Ca(OH)2===CaSO3+H2O(不能用澄清石灰水鉴别SO2和CO2.可用品红鉴别)SO3+Ca(OH)2===CaSO4+H2OCO2+2NaOH(过量)===Na 2CO3+H2OCO2(过量)+NaOH===NaHCO 3CO2+Ca(OH)2(过量)===CaCO 3 J +H2O2CO2(过量)+Ca(OH)2===Ca(HCO 3)2CO2+2NaAIO 2+3H2O===2AI(OH) 3 J +Na2CO3CO2+C6H5ONa+H2O===C6H5OH J +NaHCO3S1O2 + C^O m CaSiOjSiO2+2NaOH===Na 2SQ3+H2O (强碱缓慢腐蚀玻璃)声]曰5101+ CaCO3m CaSiO3+ CSf5102+ Na2C03m NazSiOa + CO 汕金属氧化物1•低价态的还原性:FeO+4HNO 3===Fe(NO 3)3+NO21 +2H2O2。

氧化性:MgO , AI2O3几乎没有氧化性,很难被还原为Mg ,Al.,一般通过电解制Mg和AI.: (制还原铁粉)Fe304 + 4H2血3Fe + 4H203•与水的作用:Na2O+H2O===2NaOH 2Na2O2+2H2O===4NaOH+O 214.与酸性物质的作用:Na2O+CO 2===Na 2CO32Na2O2+2CO2===2Na 2CO3+O2Na2O2+H2SO4(冷,稀)===Na2SO4+H2O2MgO+SO 3===MgSO 4MgO+H 2SO4===MgSO 4+H 2OAl2O3+3H2SO4===AI 2(SO4)3+3H2OAl2O3+2NaOH===2NaAIO 2+H2O (Al 2O3 是两性氧化物)FeO+2HCI===FeCI 2+3H2OFe2O3+6HCI===2FeCI 3+3H2OFe3O4+8HCI===FeCI 2+2FeCI 3+4H2O含氧酸3C12 +2PC12 +PC13占燃=^^2FeCl3Cla +2NaS + HiN2 + 3Hg =2.还原性点燃—FeS1.氧化性:HCIO+H 2SO3===H2SO4+HCIHCIO+H 2°2===HCI+H 2O+O2(氧化性:HCIO>HCIO 2>HCIO 3>HCIO4, 但浓,热的HCIO4氧化性很强) 2H2SO4 CS) + c =£= coaf + 2SOat + 四刃H2SO4+Fe(AI)室温下钝化A 6H?S04(^) + 2Fe Fe?(S04^3+ 3S0?f + 6H2O 2H2SO4 CS) + Cu CUSO4 + SOaf + 2H£0 H2SO4(浓)+2HBr===SO 2 f +B「2 f +2H2O H2SO4(稀)+Fe===FeSO4+H2 4HNO 3(浓)+C===CO 2 f +4NO2 f +2H2O 6HNO 3(浓)+S===H 2SO4+6NO 2 f +2H2O 5HNO 3(浓)+P===H 3PO4+5NO2 f +H2O 6HNO3 (浓、热)+Fe===Fe(NO 3)3+3NO2f +3出0 4HNO 3(稀)+Fe (不足)===Fe(NO 3)3+NO f +2H2O 8HNO3(稀)+3Fe (过量)===3Fe(NO 3)2+2NO f +4H 2O 2•还原性:H2SO3+X2+H2O===H 2SO4+2HX (X 表示Cl2,B「2,l2)2H2SO3+O2===2H2SO4H2SO3 + H2O2===H 2SO4+H2OH2SO3+2FeCl3+H2O===H2SO4+2FeCl2+2HCI3.酸性:H2SO4(浓)+CaF2===CaSO4+2HF fH2SO4(浓)+NaCI===NaHSO 4+HCI fH2SO4(浓)+2NaCI===Na 2SO4+2HCI fH2SO4(浓)+NaNO 3===NaHSO 4+HNO 32HNO 3+CaCO3===Ca(NO 3)2+H2O+CO2 f (用HNO3 和浓H2SO4不能制H2S, HI , HBr, SO2等还原性气体)4H3PO4+Ca3 ( PO4) 2===3Ca(H 2PO4)2 (重钙)3.不稳定性:2HCIO===2HCI+O 2f4HN0a 4N02f 亠ST 十阳刃碱1.低价态的还原性:4Fe ( OH) 2+O2+2H2O===4Fe(OH) 32.与酸性物质的作用:2NaOH+SO2 (少量)===Na 2SO3+H2ONaOH+SO 2 (足量)===NaHSO 32NaOH+SiO 2===Na2SiO3+H2O2NaOH+AI 2O3===2NaAIO 2+H2ONaOH+HCI===NaCI+H 2O NaOH+H 2S (足量)===NaHS+H 2O 2NaOH+H 2S (少量)===Na2S+2H2O 3NaOH+AICI3===AI (OH ) 3 J +3NaCI NaOH+AI(OH) 3===NaAIO2+2H2O NaOH+NH 4CI===NaCI+NH 3f +H2O Mg(OH)2+2NH4CI===MgCI 2+2NH 3 • H2O AI(OH) 3+NH4CI(或NH3 • H2O 不溶解) 3 .不稳定性:△Mg (OH) 2 MgO +A2A1 (OH) , - + 3H?0A2Fe(0H)3 Fe203 + 3H2O匚U (OH)屯=== CuO + H^O盐1.氧化性:2FeCl3+Fe===3FeCl22FeCl3+Cu===2FeCI 2+CuCI 2 (用于雕刻铜线路版)2FeCl3+H 2S===2FeCI 2+2HCI+S J2FeCl3+2KI===2FeCI 2+2KCI+I 2 JFeCl2+Mg===Fe+MgCI 22.还原性:2FeCl2+CI 2===2FeCI 33Na2S+8HNO 3(稀)===6NaNO 3+2NO f +3S J +4H2O3Na2SO3+2HNO 3(稀)===3Na 2SO4+2NO f +H2O2Na2SO3+O 2===2Na 2SO43.与碱性物质的作用:MgCI 2+2NH3 • H2O===Mg(OH) 2 J +NH4CIAICI 3+3NH 3 •H2O===AI(OH) 3 J +3NH4CIFeCl3+3NH 3 •H2O===Fe(OH) 3 J+3NH4CI4.与酸性物质的作用:Na2CO3+HCI===NaHCO 3+NaCINaHCO 3+HCI===NaCI+H 2O+CO2 f3Na2CO3+2AICI 3+3H2O==2AI(OH) 3 J +3CO2f +6NaCI3Na2CO3+2FeCI 3+3H2O==2Fe(OH) 3 J +3CO2 f +6NaCI3NaHCO 3+AICI3===AI(OH) 3 J +3CO2f + 3NaCI 3NaHCO3+FeCl3===Fe(OH) 3 J+3CO2f + 3NaCI3Na?S+Al2(SO4)3+SH20=2Al (OH)3I+3H2S t + 3Ma2S043NaAIO 2+AICI3+6H2O===4AI(OH) 3J + 3 NaCI5.不稳定性:Na2S2O3+H2SO4===Na2SO4+S J +SO2f +H2ONEjCl =^= NH3t + HClfANH4HCO? --- NH3f + HsOt + COifCH-CH+ 班2 一B rCltCHBr催化剂n 匚H2=CHC1△ —Br2+ HBrH2—CH2CH3I 浓H2SO4+ 3HONO2 - -2C G鹿+ 15O2兰卷12CO2 + 6H202CH3CH2OH+2Na 2CH 3CH2ONa+H 2 f△C2H 5- -OH + H- -Br C2H 5Br + H2OC2H5OH(液)+ 3O2(气)- 2CO2 (气)+ 3H2O (液)催化剂2CH3CH2OH + O2 2CH3CHO + 2H2O△浓H2SO4C H---O.H +-H- -O —C H C H—O —C H+ H O• CH3CH2OH確化剂\ CH3COOHH4 + 2AgJ + 3NH3+ H2CH3CHO + 2Ag (WsOHA△CH3CHO + 2C U(OH)2CH3COOH + CU2O J + 2H2O催化剂2CH 3CHO + O2OH2CH3COOHONa+H2OOH+ NaHCO3CH3CH?S0H+ HOOCCHs ■= CH3CO ie OC2H S + 氐0ACH3COOC£H5 + H20 r.叫-=CHaCH^OH + CH3COOHAC17 H33C - O — CH2 OI C17H33C O — CH0 IC17H33C _ O — CH 23H2催化剂加热,加压J + 3HBr2C U CNO3)3 2CuO + + 0汕A2KC1O S=—2KC1 +Na^COa + H2Of + CO时Ca(HC03)2 =^= CaCO3+ H20 +ACaCOg 匚aO + CO;f MgCO3=^= MgO + CO 汀有机化学部分占烬CH4 + 202 ・C02 + 2H20匚田+ C12 ——・CH^Cl + HC1CH3CI + Cl£—* CH^Cli + HC1Ahl匚H2CI2 + C12―* CHC13 + HC1 CHC13 + Cl2——・CC14 + HC1 CEi 同温* 2H£ + C浓硫酸 e …… ,丄口a CH3CH2OH ------- *CHpCHg f + HjO 17012:占烬CH2=CH2 + 302 > 2CO2 + 2H2O CH2-CH2+ f CH2ErCH2ErCH2=CH2+ ------ >CH3CH20H n CH2=CH2-催化剂aCaC2 + 2H z0 —C2H2t + Ca(0H)a 占堺C2H2+ 502 > 4C02 + 2H2OBrCH^CHBr + Br^ ―k CHBraCHBrz催化叫CH2=CHCi* fCH2-CH(Cl)^n浓硝酸一_ + HO —NO2 NO2+ H2O 催化剂+ Br 2催化剂------ *△Q CH 2、/CCH3 H2 N。