Oracle SQL练习题(2)

oracle sql练习题1. 编写一个SQL查询，找出员工表中工资最高的员工的姓名和工资。

```SELECT ename, salFROM empWHERE sal = (SELECT MAX(sal) FROM emp);```2. 编写一个SQL查询，计算出每个部门的平均工资，并按照平均工资降序排列。

```SELECT deptno, AVG(sal) as avg_salaryFROM empGROUP BY deptnoORDER BY avg_salary DESC;```3. 编写一个SQL查询，找出没有任何员工的部门（即部门中没有员工记录的部门）。

```SELECT d.deptno, d.dnameFROM dept dLEFT JOIN emp e ON d.deptno = e.deptnoWHERE e.deptno IS NULL;```4. 编写一个SQL查询，找出在每个部门中薪资排名第二高的员工的姓名和工资。

```SELECT d.dname, e.ename, e.salFROM emp eINNER JOIN dept d ON e.deptno = d.deptnoWHERE e.sal = (SELECT DISTINCT salFROM empWHERE deptno = e.deptnoORDER BY sal DESCOFFSET 1 ROW FETCH FIRST 1 ROW ONLY);```5. 编写一个SQL查询，找出拥有部门管理权限（即至少管理一个部门）且工资不超过5000的员工的姓名。

```SELECT enameFROM empWHERE empno IN (SELECT DISTINCT mgrFROM empWHERE sal <= 5000);```6. 编写一个SQL查询，找出在工资表中有重复记录的员工姓名和工资。

```SELECT ename, salFROM empGROUP BY ename, salHAVING COUNT(*) > 1;```7. 编写一个SQL查询，找出至少在两个部门工作过的员工的姓名。

Oracle的sql语句练习题含答案（二）Oracle_SQL练习题11.选择部门30中的所有员工.2.列出所有办事员(CLERK)的姓名，编号和部门编号.3.找出佣金高于薪金的员工.4.找出佣金高于薪金的60%的员工.5.找出部门10中所有经理(MANAGER)和部门20中所有办事员(CLERK)的详细资料.6.找出部门10中所有经理(MANAGER),部门20中所有办事员(CLERK),既不是经理又不是办事员但其薪金大于或等于2000的所有员工的详细资料.7.找出收取佣金的员工的不同工作.8.找出不收取佣金或收取的佣金低于100的员工.9.找出各月倒数第3天受雇的所有员工.10.找出早于12年前受雇的员工.11.以首字母大写的方式显示所有员工的姓名.12.显示正好为5个字符的员工的姓名.13.显示不带有"R"的员工的姓名.14.显示所有员工姓名的前三个字符.15.显示所有员工的姓名,用a替换所有"A"16.显示满10年服务年限的员工的姓名和受雇日期.17.显示员工的详细资料,按姓名排序.18.显示员工的姓名和受雇日期,根据其服务年限,将最老的员工排在最前面.19.显示所有员工的姓名、工作和薪金,按工作的降序排序,若工作相同则按薪金排序.20.显示所有员工的姓名、加入公司的年份和月份,按受雇日期所在月排序,若月份相同则将最早年份的员工排在最前面.21.显示在一个月为30天的情况所有员工的日薪金,忽略余数.22.找出在(任何年份的)2月受聘的所有员工。

23.对于每个员工,显示其加入公司的天数.24.显示姓名字段的任何位置包含"A"的所有员工的姓名.25.以年月日的方式显示所有员工的服务年限.答案：1.select ename,job,mgr,hiredate,sal,comm,deptno from emp where deptno=30;2.select ename,empno,deptno from emp where job='CLERK';3.select*from emp where comm>sal;4.select*from empwhere comm>sal*0.6;5.select empno,ename,job,hiredate,sal,comm,deptnofrom empwhere(job='MANAGER'and deptno=10)or(job='CLERK'and deptno=20);6.select empno,ename,job,hiredate,sal,deptnofrom empwhere(job='MANAGER'and deptno=10)or(job='CLERK'and deptno=20)or((job<>'MANAGER'and job<>'CLERK')and sal>=2000);7.select distinct ename,job,commfrom empwhere NVL(comm,0)>0;注意如果像上面这样写，就job ename comm3个同时不同的都列出来正确的是：select distinct jobfrom empwhere NVL(comm,0)>0;8.select ename,comm.from emp where NVL(comm,0)=0or NVL(comm,0)<100;如果按上面的写法就重复了，直接可以写成select ename,commfrom empwhere NVL(comm,0)<100;9select ename,job,last_day(hiredate)-3from emp;select ename,job,hiredatefrom empwhere hiredate=last_day(hiredate)-2;10.select ename，jobfrom empwhere months_between(sysdate,hiredate)/12>1211.select initcap(ename)name,job,hiredatefrom emp;12.select ename,job,hiredate from emp where length(ename)=5;13select ename,job from emp where ename not like'%R%';14.select substr(ename,1,3)name,job,hiredate from emp；15select replace(ename,'A','a')name,job,hiredate from emp;16select ename,job,hiredate from empwhere months_between(sysdate,hiredate)/12>=10;17.select*from emp order by ename;18.select ename,hiredate from emp order by hiredate desc;19.select ename,job,sal from emp order by job desc,sal asc;20.select ename,to_char(hiredate,'yyyy')year,to_char(hiredate,'mm')monthsfrom emporder by months,year asc;21.select ename,sal/30dailysalfrom emp;22.select ename,hiredatefrom empwhere to_char(hiredate,'mm')='02';23.select ename,sysdate-hiredate天数from emp;24.select ename from emp where instr(ename,'A',1)>0;25.select ename,to_char(hiredate,'yyyy/mm/dd')from emp；--26.列出至少有一个员工的所有部门.select dname from emp,dept where emp.deptno=dept.deptno group by dname;select distinct dname from emp,dept where emp.deptno=dept.deptno;--说明：（1）select中出现的字段一定要出现在group by中;--（2）如果select中出现的字段不出现在group by中，则一定要出现在select的聚合函数中，对于想出现的字段，可用max()或min()。

oracle的sql练习题1. 编写SQL查询语句，从员工表（EMPLOYEES）中选择工资（SALARY）大于5000的员工信息，按照工资的降序排列。

```sqlSELECT * FROM EMPLOYEES WHERE SALARY > 5000 ORDER BY SALARY DESC;```2. 编写SQL查询语句，从部门表（DEPARTMENTS）中选择部门名称（DEPARTMENT_NAME）、部门位置（LOCATION_ID）以及该部门员工的数量，按照员工数量的升序排列。

```sqlSELECT DEPARTMENT_NAME, LOCATION_ID, COUNT(*) AS EMPLOYEE_COUNTFROM DEPARTMENTSJOIN EMPLOYEES ON DEPARTMENTS.DEPARTMENT_ID = EMPLOYEES.DEPARTMENT_IDGROUP BY DEPARTMENT_NAME, LOCATION_IDORDER BY EMPLOYEE_COUNT ASC;```3. 编写SQL查询语句，从员工表（EMPLOYEES）中选择员工的姓名（FIRST_NAME）以及所属部门的名称（DEPARTMENT_NAME），要求只选择属于部门名称以"E"开头的员工信息。

```sqlSELECT FIRST_NAME, DEPARTMENT_NAMEFROM EMPLOYEESJOIN DEPARTMENTS ON EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_IDWHERE DEPARTMENT_NAME LIKE 'E%';```4. 编写SQL查询语句，从员工表（EMPLOYEES）中选择员工的姓名（FIRST_NAME）以及所属部门的名称（DEPARTMENT_NAME），要求只选择属于部门名称以"A"结尾的员工信息，且员工的工资（SALARY）在3000到6000之间。

oracle sql 试题及答案在Oracle数据库管理和开发中，SQL（Structured Query Language）是一种标准化的关系型数据库语言。

在这篇文章中，我们将提供一些Oracle SQL试题及其答案，旨在帮助读者巩固和加深对Oracle SQL语言的理解。

请注意，答案中不再重复题目，仅给出相应的解答。

1. 以下SQL语句中，哪一个用于创建一个名为"Employees"的表？CREATE TABLE Employees (EmployeeID INT PRIMARY KEY,LastName VARCHAR2(50),FirstName VARCHAR2(50),DateOfBirth DATE);2. 在一个名为"Employees"的表中，你想要删除LastName为"Smith"的所有行。

你应该使用以下哪个SQL语句？DELETE FROM Employees WHERE LastName = 'Smith';3. 假设你有一个名为"Employees"的表，你想要增加一个名为"Salary"的列，数据类型为NUMBER(10,2)。

你应该使用以下哪个SQL 语句？ALTER TABLE Employees ADD (Salary NUMBER(10,2));4. 以下SQL查询语句将返回哪些列？SELECT LastName, FirstName FROM Employees;答案：该查询将返回"Employees"表中的LastName和FirstName列。

5. 以下SQL语句将返回"Employees"表中有多少条记录？SELECT COUNT(*) FROM Employees;答案：该查询将返回"Employees"表中的记录数。

oracle的sql语句的练习题及答案（员⼯表+部门表）⼀、创建表及初始化数据1、表说明：emp员⼯表(empno员⼯号/ename员⼯姓名/job⼯作/mgr上级编号/hiredate受雇⽇期/sal薪⾦/comm佣⾦/deptno部门编号) dept部门表(deptno部门编号/dname部门名称/loc地点)注意：⼯资 ＝ 薪⾦ ＋ 佣⾦2、创建表create table DEPT(DEPTNO NUMBER(2) not null,DNAME VARCHAR2(14),LOC VARCHAR2(13));alter table DEPT add constraint PK_DEPT primary key (DEPTNO);create table EMP(EMPNO NUMBER(4) not null,ENAME VARCHAR2(10),JOB VARCHAR2(9),MGR NUMBER(4),HIREDATE DATE,SAL NUMBER(7,2),COMM NUMBER(7,2),DEPTNO NUMBER(2));alter table EMP add constraint PK_EMP primary key (EMPNO);3、初始化数据insert into DEPT (DEPTNO, DNAME, LOC)values (10, 'ACCOUNTING', 'NEW YORK');insert into DEPT (DEPTNO, DNAME, LOC)values (20, 'RESEARCH', 'DALLAS');insert into DEPT (DEPTNO, DNAME, LOC)values (30, 'SALES', 'CHICAGO');insert into DEPT (DEPTNO, DNAME, LOC)values (40, 'OPERATIONS', 'BOSTON');commit;insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7369, 'SMITH', 'CLERK', 7902, to_date('17-12-1980', 'dd-mm-yyyy'), 800, null, 20);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7499, 'ALLEN', 'SALESMAN', 7698, to_date('20-02-1981', 'dd-mm-yyyy'), 1600, 300, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7521, 'WARD', 'SALESMAN', 7698, to_date('22-02-1981', 'dd-mm-yyyy'), 1250, 500, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7566, 'JONES', 'MANAGER', 7839, to_date('02-04-1981', 'dd-mm-yyyy'), 2975, null, 20);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7654, 'MARTIN', 'SALESMAN', 7698, to_date('28-09-1981', 'dd-mm-yyyy'), 1250, 1400, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7698, 'BLAKE', 'MANAGER', 7839, to_date('01-05-1981', 'dd-mm-yyyy'), 2850, null, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7782, 'CLARK', 'MANAGER', 7839, to_date('09-06-1981', 'dd-mm-yyyy'), 2450, null, 10);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7788, 'SCOTT', 'ANALYST', 7566, to_date('19-04-1987', 'dd-mm-yyyy'), 3000, null, 20);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7839, 'KING', 'PRESIDENT', null, to_date('17-11-1981', 'dd-mm-yyyy'), 5000, null, 10);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7844, 'TURNER', 'SALESMAN', 7698, to_date('08-09-1981', 'dd-mm-yyyy'), 1500, 0, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7876, 'ADAMS', 'CLERK', 7788, to_date('23-05-1987', 'dd-mm-yyyy'), 1100, null, 20);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7900, 'JAMES', 'CLERK', 7698, to_date('03-12-1981', 'dd-mm-yyyy'), 950, null, 30);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7902, 'FORD', 'ANALYST', 7566, to_date('03-12-1981', 'dd-mm-yyyy'), 3000, null, 20);insert into EMP (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)values (7934, 'MILLER', 'CLERK', 7782, to_date('23-01-1982', 'dd-mm-yyyy'), 1300, null, 10);commit;⼆、题⽬练习1．列出⾄少有⼀个员⼯的所有部门。

oracle数据库sql试题及答案Oracle数据库SQL试题及答案1. 如何查询员工表中所有员工的姓名和工资，要求工资从高到低排序？```sqlSELECT name, salaryFROM employeesORDER BY salary DESC;```2. 如何统计每个部门的员工人数？```sqlSELECT department_id, COUNT(*) AS employee_countFROM employeesGROUP BY department_id;```3. 如何查询工资高于平均值的员工信息？```sqlSELECT *FROM employeesWHERE salary > (SELECT AVG(salary) FROM employees);```4. 如何找出没有直属上司的员工？```sqlSELECT *FROM employees e1WHERE NOT EXISTS (SELECT 1FROM employees e2WHERE e1.manager_id = e2.employee_id);```5. 如何查询工资在3000到5000之间的员工姓名和工资？```sqlSELECT name, salaryFROM employeesWHERE salary BETWEEN 3000 AND 5000;```6. 如何删除员工表中所有工资低于3000的员工记录？```sqlDELETE FROM employeesWHERE salary < 3000;```7. 如何更新员工表中所有部门为10的员工的工资，增加10%？```sqlUPDATE employeesSET salary = salary * 1.1WHERE department_id = 10;```8. 如何查询员工表中每个员工的姓名和他们直属上司的姓名？```sqlSELECT AS employee_name, AS manager_name FROM employees e1JOIN employees e2 ON e1.manager_id = e2.employee_id; ```9. 如何查询员工表中每个部门的平均工资？```sqlSELECT department_id, AVG(salary) AS avg_salary FROM employeesGROUP BY department_id;```10. 如何查询员工表中工资最高的员工信息？```sqlSELECT *FROM employeesWHERE salary = (SELECT MAX(salary) FROM employees); ```。

Oracle SQL&PLSQL Test一、选择题(共30题；每题3分)1.Oracle发出下列select语句：SQL> select e.empno, e.ename, d.loc2 from emp e, dept d3 where e.deptno = d.deptno4 and substr(e.ename, 1, 1) = ‘S’;下列哪个语句是Oracle数据库中可用的ANSI兼容等价语句？A．select empno, ename, loc from emp join dept on emp.deptno = dept.deptno where substr(emp.ename, 1, 1) = ‘S’;B．select empno, ename, loc from emp, dept on emp.deptno = dept.deptno where substr(emp.ename, 1, 1) = ‘S’;C．select empno, ename, loc from emp join dept where emp.deptno = dept.deptno and substr(emp.ename, 1, 1) = ‘S’;D．select empno, ename, loc from emp left join dept on emp.deptno = dept.deptno and substr(emp.ename, 1, 1) = ‘S’;2.用下列代码回答问题：Examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?需要检索出无论雇员是否和部门匹配的记录A. SELECT last_name, department_nameFROM employees , departments(+);B. SELECT last_name, department_nameFROM employees JOIN departments (+);C. SELECT last_name, department_nameFROM employees(+) e JOIN departments dON (e.department_id = d.department_id);D. SELECT last_name, department_nameFROM employees eRIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E. SELECT last_name, department_nameFROM employees(+) , departmentsON (e.department_id = d.department_id);F. SELECT last_name, department_nameFROM employees e LEFT OUTERJOIN departments d ON (e.department_id = d.department_id);3.公司销售数据库包含一个PROFITS表，按产品名、销售地区和季度列出利润信息。