江苏省无锡市普通高中2016年秋学期高三期中基础性检测试卷(WORD 答案)详解
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无锡市第一中学2015-2016学年度上学期高三综合练习英语试卷一、单项填空21. _____ fewer people send letters to one another, the hobby of stamp collecting has steadilybeen in decline.A. BeforeB. AlthoughC. AsD. If22. ---Is there a science museum in your city?---Yes, but it _____ at the moment.A. was builtB. is being builtC. has been builtD. would be built23. ---Is Mary still working in your company?---Not since July. She and her husband ______ to New York as soon as she got a job there.A. movedB. have movedC. had movedD. would move24. _____ the website of the Department of health in your city, and you will learn a lot aboutfirst aid.A. SearchingB. SearchC. To searchD. Having searched25. Shower water is considered _____ and no longer usable until the chemicals and wastes areremoved from it.A. to polluteB. to be pollutingC. to be pollutedD. to have polluted26. ---What shall I do if I get lost in a strange town ?---Ask whoever is available in the street for help, just as you _____ do in your own town.A. shouldB. mustC. mightD. will27. Each year, a set of new words is added to the dictionary, _____ the changing tastes andhabits of a nation.A. to reflectB. reflectingC. having reflectedD. to have reflected28. It remains to be seen _____ the new product will be well accepted on the local market.A. thatB. whatC. whereD. whether29. There have been many occasions _____ I’ve been on a plane and we hit some bad suddenviolent movements.A. whichB. whenC. whereD. as30. Our company’s latest toy product is of the highest quality and it is just _____ your childrenneed.A. whatB. whichC. howD. whose31. What a pity! Considering his ability and experience, he _____ better.A. could have doneB. must have doneC. couldn’t have doneD. needn’t have done32. Jim came back early last night. It was not yet eight o’clock _____ he got home.A. beforeB. thatC. whenD. until33. The father couldn’t figure out _____ made his son spend so much time in preparing for thismatch.A. what it was thatB. that it was whatC. it was what thatD. what was it that34. ---The old store enjoys a good reputation in this area.---I can’t agree more. There are very few, _____, complaints about their services.A. if anythingB. if anyC. if soD. if ever35. ---What do you think it is that matters much at home?---It is the atmosphere _____ you feel relaxed and comfortable.A. whereB. thatC. whichD. what二、完形填空Everyone hates to wait in lines. But it’s not always the length of the wait we find so ___36___. Our behavior when waiting is only ___37___ defined by the length of the wait. “Often the psychology of queuing is more ___38___than the statistics of the wait itself,” said the MIT researcher Richard Larson, an expert on waiting lines.One obvious ___39___of queuing psychology is that we get bored when we wait in line. This issue is ___40___ in many ways, from magazines in hospital waiting rooms to mirrors in elevators ___41___we can check our appearance.We really ___42___ it when we expect a short wait and then get a long one. But studies show that we are much more ___43___when we are given an idea of how long we’ll be waiting. Walt Disney Co knows this ___44___ than anyone else. It posts estimated waiting times for attractions in its theme parks. But according to Larson, these times are ___45___ so that visitors get to the front of the queue more quickly than they expect. It keeps them ___46___.But perhaps the biggest influence on our feelings about waiting in a line has to do with our sense of ___47___. When it comes to queues, the universally acknowledged ___48___ is first come, first served. Any deviation (违反) from this principle is regarded as unfair and can___49___ violent queue rage (大怒).Sometimes however, we are willing to make ___50___. For example, we are fine with the priority given to those with a more critical condition in hospital. ___51___ in most situations, we demand fairness. You’ve probably ___52___ mild queue rage yourself in fast food restaurants, watching people in the other line move faster than you, ___ 53___ yourself for having chosen the “wrong” line.In order to solve this problem, the serpentine (蛇形的) line was ___54___. Slate magazine’s website explains: “The serpentine line isn’t always faster than multi-lines. But it offers important relief: you absolutely ___55___ have to see someone arrive after you and get served before you.”36. A. unchangeable B. uninteresting C. unbearable D. unbelievable37. A. simply B. partly C. naturally D. completely38. A. necessary B. different C. reasonable D. important39. A. reason B. aspect C. disadvantage D. result40. A. solved B. reflected C. explained D. discovered41. A. in case B. as if C. so that D. even if42. A. hate B. imagine C. understand D. consider43. A. careful B. patient C. worried D. polite44. A. less B. longer C. better D. worse45. A. incorrectly estimated B. accurately estimatedC. underestimatedD. overestimated46. A. happy B. relaxed C. busy D. surprised47. A. defeat B. fairness C. achievement D. disappointment48. A. truth B. information C. habit D. standard49. A. lead to B. result from C. relate to D. put forward50. A. differences B. changes C. exceptions D. preparations51. A. Then B. But C. So D. As52. A. experienced B. noticed C. prevented D. performed53. A. warning B. reminding C. excusing D. blaming54. A. changed B. replaced C. invented D. forbidden55. A. never B. often C. even D. still三、阅读理解ADid you ever wish that you had eyes in the back of your head? Some animals look like they do! However, these “eyes” aren’t for seeing---in fact, they can’t see at all and are called false eyes or eyespots.It’s easy to be fooled by eyespots---after all, they look a lot like eyes. Yet despite their strong resemblance to real eyes, eyespots are just designs, or patterns, found on different parts of an animal’s body. They’ve also been spied on fish, owls and all kinds of insects.You might wonder: if eyespots can’t help an animal see, why do they exist at all? Scientists believe one reason is that eyespots can create a strong reaction in other animals.In the world of the peacock, eyespots can make a male really stand out from the crowd. Peacocks have long, beautiful tails, often decorated with dozens of eyespots. The female peacock has only a short, unattractive brown tail, with no eyespots at all. During the mating season, males fan out their tails for display while females sit back and watch. Studies show that the male with the most eyespots will have the most opportunities to mate.Eyespots can also send an entirely different message, acting as a way for an animal to frighten its enemies away. The peacock butterfly has two sets of eyespots on its wings. At rest, the butterfly folds its wings above its body, displaying a dark underside. This helps the butterfly look less like tasty food to hungry birds. At times, a sharp-eyed enemy will see right through the disguise and dive down to catch it. The butterfly waits until the last possible moment before the bird closes in to open its wings. Out flash its eyespots, as large as the eyes of an owl. This scary display often frightens the bird into flying off.The four-eyed frog of South American uses a similar approach to defend itself. When an enemy approaches, the frog will turn around, bend over, and lift up its rear end to expose the big, black eyespots. Often, that’s enough to make its enemy run away.56. Which of the following is TRUE about peacocks?A. The female has fewer eyespots than the male.B. Males with the most eyespots are most popular.C. The male has a short and unattractive tail.D. Females open their tails to attract males.57. How many functions of animals’ eyespots are mentioned?A. 2.B. 3.C. 4.D. 5.BIt isn’t the first time I have picked tomatoes with Grandma. It is, however, the first time I realize why she requests my help.For as long as I can remember, Grandma’s plentiful tomato garden has been a sign of summer’s end. Each September, just as the decreased heat of the sun hints at cooler days, Grandma requests my help in her tomato garden. She pats my head and assures me she cannot pick tomatoes without my youthful eyes and quick mind. She says we need to examine each tomato and agree on its readiness for picking. While Grandma’s request for my help in the tomato garden is always the same, her desire for my help seems to increase each year.Grandma has eyes for finding even the tomatoes hidden by undergrowth and other tomatoes. I, however, just turn circles looking for the ones I think Grandma will like. I spot what looks like a ripe tomato, head in its direction, and then move to another that appears to be equally ripe. I usually end up watching Grandma and trying to stay out of her way, which seems the only way my eyes and mind are useful. While Grandma says we need to agree on which tomatoes are ready to be picked, my participation does not seem very important. Grandma knows which tomatoes are ready. It is as if she has been in the garden earlier that day, deciding which tomatoes will be picked. I often feel more of a hindrance(妨碍) than a help.It is not until today that I realize it is my company she cannot do without.There we are, lost in the tomato vines. As always, Grandma is walking from vine to vine, thanking me for my willingness to assist. I have to stand to spot the edge of Grandma’s hat amongst the plants. I try to stay near her so I can hear her comments and directions.Grandma’s eyes are always making good judgments, and they are no different in the vegetable garden. From afar she spots what looks like a ripe tomato. As she walks toward the garden, she evaluates the tomato a second time, but from a different angle. If it passes such inspection, I already know it will end up in the basket with the mound of others Grandma has carefully chosen. However, Grandma acts as if she needs a final look to be sure. She calls me to her side, kneels beside the vine while enjoying the warmth of the fading sunlight on her face, and holds the tomato in her hand. She turns each round, red ball toward the sunlight before disconnecting it from the vine with a half-hearted smile.She then looks at me. I nod my head and smile. Grandma assumes I smile in agreement with her tomato selection. I know I smile, instead, at her.58. We can infer from the passage that as a tomato picker, the author is ___.A. incompetentB. lazyC. enthusiasticD. skillful59. How does the author “already know” the tomato will “end up in the basket”?A. The author is an expert gardener.B. The author is Grandma’s assistant.C. The author has already inspected the tomato’s ripeness.D. The author has spent a lot of time gardening with Grandma.60. The last two sentences of the passage suggest that the author ___.A. realizes Grandma’s true intentionB. teases Grandma about her choice of tomatoesC. understands that Grandma wants reassuranceD. appreciates Grandma’s skill in finding ripe tomatoesCCredit card rewards programs have traditionally featured airline miles, gift certificates, and cash back for customers who spend enough on their cards to rack up points. But recently, credit card companies have started offering a different kind of gift: They’re handing out lower interest rates, refunding interest payments, and using other strategies to provide incentives for cardholders to pay down their debt and make on-time payments. The deals, however, don’t always work in consumers’ favor.The new Citi Forward card gives cardholders points and reduces their annual interest rate for making on-time payments and for staying under their credit limit. TD Bank’s Simply Flexible card changes customer’s interest rates depending on how much of their balance they pay off. If they pay off 10 percent or more of their balance, then they get the lowest available interest rate; paying between the minimum payment and 5 percent of the balance gets them the highest interest rate. And Discover’s Motiva card gives cardholders one month’s worth of interest back after six consecutive (连续的) on-time payments.Card companies say the idea behind the new rewards is to help customers get on top of their finances. “It’s all about promoting financial fitness and giving customers the choices they need to help them manage their debt,” says Michael Copley, senior vice president of retail lending for TD Bank. He says he thinks the Simply Flexible card motivates cardholders to pay off more of their debt and attributes the company’s relatively low delinquency(拖欠债款) rate to the product.Because of the continuing recession (经济萧条), companies have an incentive to keep their customers from sliding further under water. “This is in response to recognition on the part of issuers that they have to help their cardholders do a better job of managing their money so customers keep those cards for a long time,” says Ron Shevlin, senior analyst at Aite Group, a research and advisory firm. The challenge for companies, he says, is to balance the profitability of consumers who maintain a balance, and therefore pay interest fees each month, against the increased risk that those cardholders pose because they are more likely to default (拖欠) on their debt. Rewards programs that encourage customers to maintain a balance while paying on time, such as the Motiva card, may help them strike that balance.According to consumer advocates and credit card experts, consumers who carry a balance may be better off selecting a card with the lowest interest rate rather than participating in one of these rewards programs, although they can help consumers improve their credit. “In general, I think these cards are great for people who don’t have great credit and regularly carry a balance on their cards,” says Adam Jusko, founder of . “Customers who onlyoccasionally carry a balance, on the other hand, would be better off finding a card with a more appealing rewards program,” he adds.61. The recent credit card rewards programs include ___.A. air milesB. gift certificatesC. cash backD. lower interest rates and interest payment refund62. A cardholder of simply Flexible Card will get the lowest interest rate if he ___.A. makes six successive on-time paymentsB. pays off the balance on time and stay under his credit limitC. pays off 15 percent of his balanceD. pays off 5 percent of his balance63. Michael Copley holds that rewards programs ___.A. don’t always work in customers’ favorB. can help the customers pay off more of their debtC. will help the cardholders manage their financeD. can result in a relative low delinquency rate to the credit card64. The underlined phrase “to keep from sliding further under water” implies that ___.A. the companies aim to help their customers during the recessionB. the companies are going to manage the money of their cardholdersC. the companies help the customers manage their finance better so they keep the cardslongerD. the companies want to give the customers more choices in the recession65. The consumer advocates and credit card experts suggest that ___.A. the lowest interest card is a better choice for those who carry a balanceB. the customers who pay off the balance should not participate in any rewards programC. it is better for those who pay off the balance to select a lower interest cardD. customers who carry a balance should select a card with some rewards programsDOver the last 25 years, British society has changed a great deal---or at least many parts of it have. In some ways, however, very little has changed, particularly where attitudes are concerned. Ideas about social class---whether a person is “working-class” or “middle-class”---are one area in which changes have been extremely slow.In the past, the working-class tended to be paid less than middle-class people, such as teachers and doctors. As a result of this and also of the fact that workers’ jobs were generally much less secure, distinct differences in life-styles and attitudes came into existence. The typical working man would collect his wages on Friday evening and then, it was widely believed, having given his wife her “housekeeping”, would go out and squander the rest on beer and betting.The stereotype of what a middle-class man did with his money was perhaps nearer the truth. He was---still is---inclined to take a longer-term view. Not only did he regard buying a house as a top priority, but he also considered the education of his children as extremely important. Bothof these provided him and his family with security. Only in very few cases did workers have the opportunity (or the education and training) to make such long-term plans.Nowadays, a great deal has changed. In a large number of cases factory workers earn as much, if not more, than their middle-class supervisors. Social security and laws to improve job security, combined with a general rise in the standard of living since the mid-fifties of the 20th century, have made it less necessary than before to worry about “tomorrow”. Working-class people seem slowly to be losing the feeling of inferiority they had in the past. In fact there has been a growing tendency in the past few years for the middle-classes to feel slightly ashamed of their position.The changes in both life-styles and attitudes are probably most easily seen amongst younger people. They generally tend to share very similar tastes in music and clothes, they spend their money in having a good time, and save for holidays or longer-term plans when necessary. There seems to be much less difference than in previous generations. Nevertheless, we still have a wide gap between the well-paid (whatever type of job they may have) and the low-paid. As long as this gap exists, there will always be a possibility that new conflicts and jealousies will emerge, or rather than the old conflicts will reappear, but between different groups.66. Which of the following is seen as the cause of class differences in the past?A. Life-style and occupation.B. Attitude and income.C. Income and job security.D. Job security and hobbies.67. The writer seems to suggest that the description of ___ is closer to truth.A. middle-class ways of spending moneyB. working-class ways of spending the weekendC. working-class drinking habitsD. middle-class attitudes68. According to the passage, which of the following is NOT a typical feature of themiddle-class?A. Desiring for security.B. Making long-term plans.C. Having priorities in life.D. Saving money.69. Working-class people’s sense of security increased as a result of all the following factorsEXCEPT___.A. better social securityB. more job opportunitiesC. higher living standardD. better legal protection70. Which of the following statements is INCORRECT?A. Changes are slowly taking place in all sectors of the British society.B. The gap between working-class and middle-class young people is narrowing.C. Differences in income will remain but those in occupation will disappear.D. Middle-class people may sometimes feel inferior to working-class people.四、单词拼写1.Though the country is a_____ in natural resources, we should also save resources andpromote sustainable development.2.The country finally gained its independence today, and every citizen would remember thish_____ moment forever.3.The two reports c_____ each other, so one of them must be false.4.As is known to all, accidents happen when safety checks are o______.5.What are the c_____ for deciding which films should be included in the Film Festival?6.When the actor was awarded an Oscar, many people sent him their warmest _____ (祝贺)onhis success.7.The article was _____ (最初)published in our school’s newspaper.8.His mum has told him not to play with fire _____ (无数的) times.9.Wearing seat belts in cars are _____ (强制的) by law.10.He _____ (归因于) his success more to luck than to ability.五、句子转换1.The CN Tower, short for the Canadian National Tower, is one of the tallest towers in theworld.The Canadian National Tower, which is _____ the CN Tower _____ _____, _____ among the tallest towers in the world.2.Canada’s border with the USA is the longest border in the world not defended by an armyor the police.Canada’s border with the USA is the longest in the world. No armies or police are there _____ _____ of it.3.There is a real chance that a small percentage of students are able to pass the physicalexams.Students _____ a real _____ of passing the physical exams are _____ the _____.六、完成句子1.我们对展映的影片种类没有限制——只要一部影片的质量符合了我们的标准,不管是谁制作的,我们就会选中它。
无锡市普通高中2014年秋学期高三期中基础性检测考试地理试题一、选择题(共60分)(一)单项选择题:本大题共18小题,每小题2分,共计36分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
图1为“某一日期的太阳光照图”,图中阴影表示夜半球,读图完成1~2题。
1.此时,太阳直射点的地理坐标是A.(0°,115°E) B.(0°,60°W)C.(23.5°N,115°E) D.(23.5°S,65°W)2.图中甲、乙、丙、丁四地自转线速度由大到小的排列顺序是A.甲乙丙丁 B.乙丙丁甲C.丙丁甲乙 D.丁乙甲丙图2为“地球大气受热过程示意图”,读图完成3~4题。
3.当前化石燃料的燃烧,排放大量温室气体导致A.①增加 B.②减少C.③增加 D.④减少4.我国西北地区昼夜温差大,是因为A.白天大气辐射强,夜晚①弱B.白天地面吸收强,夜晚②弱C.白天反射作用强,夜晚③弱D.白天太阳辐射强,夜晚④弱美国科罗拉多大峡谷为大自然的沧海桑田提供了证据,被誉为“活的地质教科书”。
人们从谷壁可以观察刭各个时期的地层。
图3为“科罗拉多大峡谷景观照片”,图4为“地壳物质循环示意图”,读图完成5~6题。
5.科罗拉多大峡谷谷壁的岩石对应图4中A.② B.③ C.④ D.⑤6.图3所示景观的形成过程是A.沉积作用一地壳运动一流水侵蚀 B.流水沉积一地壳运动一风力侵蚀C.地壳运动一板块张裂一风力侵蚀 D.泥沙堆积—板块张裂一冰川侵蚀有专家提出水循环可分为自然循环和社会循环两大类,图5为“某城市水循环示意图”,读图完成7~8题。
7.图中③④⑤⑥分别表示A.大气降水、地面蒸发、地表径流、跨流域调水B.人工降水、植物蒸腾、管道输水、地下径流C.人工降水、管道输水、跨流域调水、地表径流D.大气降水、水汽输送、地下径流、管道输水8.关于人类对城市水循环影响的叙述,正确的是A.城市绿地建设,可以减少①B.大量开采地下水,可以增加②C.污水回收利用,可以减少⑥D.用透水材料改造水泥路面,可以增加⑦图6示意我国黄土高原某地林木的分布状况,图中相邻等高线之间高差均为40米。
无锡市2015年秋学期高三期中考试试卷数 学命题单位:江阴市教研室 制卷单位:无锡市教育科学研究院注意事项及说明: 本卷考试时间为120分钟, 全卷满分为160分.一.填空题(本大题共14小题,每小题5分,共计70分.请把答案填写在答题卡相应位......置上...) 1.已知集合{}02M x x =<<,{}1N x x =>,则M N = ▲ . 2.设3i1i+=+a+b i (i 为虚数单位,a ,b ∈R ),则a+b= ▲ . 3.若函数42x xay +=的图象关于原点对称,则实数a 等于 ▲ . 4.已知角α的终边经过点()10,P m ,且4tan 5α=-,则m 的值为 ▲ . 5.某人抛掷质地均匀的骰子,其抛掷两次的数字之和为7的概率是 ▲ .6.执行如图所示的程序框图,则输出的z 的值是 ▲ .7.已知函数2,1,()33,1,x x f x x x -⎧-=⎨+>-⎩… 则满足()4f a …的实数a 的取值范围是 ▲ .8.如图,在△ABC 中,12CD AE DA EB ==,若DE CA CB λμ=+ ,则λμ+= ▲ .9.设,x y 满足约束条件24,1,20,x y x y x +⎧⎪-⎨⎪+⎩………则目标函数2z x y =-的最大值为 ▲ .10.已知数列{}n a 是公差为2的等差数列,若6a 是7a 和8a 的等比中项,则6S =___ ▲ ___. 11.若函数()ln f x x a =- ()R a ∈满足(3)(3)f x f x +=-,且()f x 在(),m -∞单调递减,则实数m 的最大值等于 ▲ . 12.若,2παπ⎛⎫∈⎪⎝⎭,且3cos 2sin()4παα=-,则sin 2α的值为 ▲ .13.定义在R 上的函数()f x 满足2log (3),0,()=(1)(2),0,x x f x f x f x x -⎧⎨--->⎩… 则f (11)= ▲ . 14.已知函数2()2e x f x x =与()3e x g x x a =+的图象有且只有两个交点,则实数()f x 的取值范围是 ▲ .二、解答题:(本大题共6道题,计90分.解答应写出必要的文字说明、证明过程或演算步骤 15.(本小题满分14分)已知函数()()2sin f x x ωϕ=+(0ω>,02πϕ<<)的图象经过点(,且相邻两条对称轴间的距离为2π. (1)求函数()f x 的单调增区间; (2)若将()f x 的图象向左平移4π个单位,得到函数()g x 的图象,求函数()g x 在区间0,2π⎡⎤⎢⎥⎣⎦上的最大值和最小值.B A16.(本小题满分14分)如图,在五面体SABCD中,四边形ABCD为平行四边形,AD⊥平面SAB.(1)若SA=3,AB=4,SB=5,求证:SA⊥AC;(2)若点E是SB的中点,求证:SD∥平面ACE.17.(本小题满分14分)在平面直角坐标系xOy中,已知向量a=(2,0),b=(0,1).设向量()1cosx a bθ=++,2siny ka bθ=-+⋅,其中02πθ<<.(1)若x∥y,且π3θ=,求实数k的值;(2)若x⊥y,求实数k的最大值,并求取最大值时cosθ的值.18.(本小题满分16分)如图,某自行车手从O点出发,沿折线O–A–B–O匀速骑行,其中点A位于点O南偏东45 且与点O相距千米.该车手于上午8点整到达点A,8点20分骑至点C,其中点C位于点O南偏东α︒-(45)(其中sinα=,090α︒︒<<)且与点O相距千米(假设所有路面及观测点都在同一水平面上).(1)求该自行车手的骑行速度;(2)若点O正西方向27.5千米处有个气象观测站E,假定以点E为中心的3.5千米范围内有长时间的持续强降雨.试问:该自行车手会不会进入降雨区,并说明理由.SB19.(本小题满分16分)已知数列{}n a 、{}n b 是正项数列,{}n a 为等差数列,{}n b 为等比数列,{}n b 的前n 项和为n S ()N n *∈,且1122=1,=+1a b a b =,33=a b —2.(1)求数列{}{},n n a b 的通项公式; (2)令11n n n n b c S S ++=⋅,求数列{}n c 的前n 项和n S ;(3)设21n n n a d b +=,若m d n ≤恒成立,求实数m 的取值范围.20.(本小题满分16分)设函数()ln 1nf x x m x =+-,其中n ∈N *,n ≥2,且m ∈R .(1)当2n =,1m =-时,求函数()f x 的单调区间;(2)当2n =时,令()()22g x f x x =-+,若函数()g x 有两个极值点1x ,2x ,且12x x <,求()2g x 的取值范围;(3)当1m =-时,试求函数()f x 的零点个数,并证明你的结论.。
2018届江苏省无锡市普通高中高三上学期期中基础性检测考数学试题一、填空题1.已知集合{}0,1,2A =,集合11,B x ⎧⎫=⎨⎬⎩⎭,且B A ⊆,则实数x =___________. 【答案】12【解析】因为B A ⊆,则12x =, 12x = 2.若复数z a i =+(a 为正实数)的模为2,则a =______________.【解析】由题意,2=,所以a =3.菲波那切数列(Fibonacci,sequence ),又称黄金分割数列,因数学家列昂纳多斐波那契(Leonadoda Fibonacci )以兔子繁殖为例子而引入,故又称为“兔子数列”,指的是这样一个数列:1,2,3,5,8,13,21,…,则该数列的第10项为______________. 【答案】89【解析】按要求,将数列列出来:1,2,3,5,8,13,21,34,55,89,··· 所以第10项为89。
4.若函数()()1,0{ 3,0x x f x f x x -≤=->,则()5f =______________.【答案】2【解析】()()()5212f f f ==-=5.已知函数()22f x x ax =+-的单调递减区间为(),1-∞,则实数a 的值为______________. 【答案】2- 【解析】由题意, 12a-=,则2a =-。
6.若变量,x y 满足2{236 0x y x y x +≤-≤≥,且2x y a +≥恒成立,则a 的最大值为______________. 【答案】4-【解析】所以过()0,2-时, 2x y +的最小值为-4,所以a 的最大值为-4.7.将函数sin2y x =的图象向右平移()0ϕϕ>个单位长度,若所得图象过点1,32π⎛⎫ ⎪⎝⎭,则ϕ的最小值是______________. 【答案】4π 【解析】移动后()()sin2sin 22y x x ϕϕ=-=-,过点1,32π⎛⎫⎪⎝⎭, 则21sin 232πϕ⎛⎫-=⎪⎝⎭,所以22236k ππϕπ-=+或252236k ππϕπ-=+, 所以4k πϕπ=+或12k πϕπ=-+,所以ϕ的最小值为4π。
无锡市普通高中2016年秋学期高三期中基础性检测考试卷语文一、语言文字运用(15分)1.在下面一段话的空缺处依次填入词语,最恰当的一组是(3分)在银行信贷依然快速增长的前提下,现行的楼市调控政策只能是。
因为充盈的流动性正继续吹大楼价泡沫,开发商依然可以从银行那里源源不断地获取资金,这使得他们并无的资金链压力,从而也就有的资源长久与中央政府耗下去。
因此,一道道“限购令”,充其量只是延后了房价的进一步上涨而已。
A.扬汤止沸迫不及待充沛B.扬汤止沸迫在眉睫充足C.推波助澜迫在眉睫充足D.推波助澜迫不及待充沛2.古人喜欢将不同诗人的诗句组合在一起,构成对联,别有意趣。
下面八句诗,组合成四副对联,不恰当的一组是(3分)A.鸟啼碧树闲临水(储嗣宗)B.桃花尽日随流水(张旭)竹映高墙似傍山(薛能)江月何年初照人(张若虚)C.倾壶待客花开后(李中)D.林花经雨香犹在(寇准)出竹吟诗月上初(杜荀鹤)茅檐常扫尽无苔(王安石)3.在下面一段文字横线处填入语句,衔接最恰当的一项是(3分)帕乌斯托夫斯基对大自然的态度平和而优雅。
①文学借此恢复对美和善的感知和表达②也含着一种仁爱的生命意识③因而,他的这种“自然崇拜”的文学主张和写作实践,就同时具有了双重意义④这态度里含着一种成熟的审美意识⑤而这些,恰好又都是他所生活的那个时代所缺乏的,也是那个时代的文学所缺乏的⑥人们借此摆脱紧张、僵硬的“斗争模式”A.④①⑥③⑤②B.④②⑤③⑥①C.④③⑤②①⑥D.④②③⑥①⑤4.对下面两首小诗所描写的事物,理解正确的一项是(3分)[甲]最后只有垃圾留下当音乐与灯光相继离开衣帽间内一片荒凉杯盘还残余着字句和笑脸的渣滓[乙]住在里面的男人努力检阅风霜与阳光住在里面的女人用泪水灌溉青春的枯井老人面对一池皱了的春水A. [甲]夜色[乙]监狱B.[甲]舞会[乙]影子C. [甲]宴会[乙]镜子D.[甲]荒野[乙]窗户5.阅读下面这幅漫画,对它的寓意理解最贴切的一项是(3分)A.在人生的道路上,永远不要轻言放弃,胜利可能就在眼前。
(语文)江苏省无锡市普通高中2016年秋学期高三期中基础性检测考试语文卷解析江苏省无锡市普通高中2016年秋学期高三期中基础性检测考试语文卷一、语言文字运用(15分)1.在下面一段话的空缺处依次填入词语,最恰当的一组是(3分)在银行信贷依然快速增长的前提下,现行的楼市调控政策只能是。
因为充盈的流动性正继续吹大楼价泡沫,开发商依然可以从银行那里源源不断地获取资金,这使得他们并无的资金链压力,从而也就有的资源长久与中央政府耗下去。
因此,一道道“限购令”,充其量只是延后了房价的进一步上涨而已。
A.扬汤止沸迫不及待充沛B.扬汤止沸迫在眉睫充足C.推波助澜迫在眉睫充足D.推波助澜迫不及待充沛2.古人喜欢将不同诗人的诗句组合在一起,构成对联,别有意趣。
下面八句诗,组合成四副对联,不恰当的一组是(3分)A.鸟啼碧树闲临水(储嗣宗)B.桃花尽日随流水(张旭)竹映高墙似傍山(薛能)江月何年初照人(张若虚)C.倾壶待客花开后(李中)D.林花经雨香犹在(寇准)出竹吟诗月上初(杜荀鹤)茅檐常扫尽无苔(王安石)3.在下面一段文字横线处填入语句,衔接最恰当的一项是(3分)帕乌斯托夫斯基对大自然的态度平和而优雅。
①文学借此恢复对美和善的感知和表达②也含着一种仁爱的生命意识③因而,他的这种“自然崇拜”的文学主张和写作实践,就同时具有了双重意义④这态度里含着一种成熟的审美意识⑤而这些,恰好又都是他所生活的那个时代所缺乏的,也是那个时代的文学所缺乏的⑥人们借此摆脱紧张、僵硬的“斗争模式”A.④①⑥③⑤②B.④②⑤③⑥①C.④③⑤②①⑥D.④②③⑥①⑤4.对下面两首小诗所描写的事物,理解正确的一项是(3分)【甲】【乙】最后只有垃圾留下住在里面的当音乐与灯光相继离开男人努力衣帽间内一片荒凉检阅风霜与阳光杯盘还残余着字句和笑脸的渣滓住在里面的女人用泪水灌溉青春的枯井老人面对一池皱了的春水A.【甲】夜色【乙】监狱B.【甲】舞会【乙】影子C.【甲】宴会【乙】镜子D.【甲】荒野【乙】窗户5.阅读下面这幅漫画,对它的寓意理解最贴切的一项是(3分)A.在人生的道路上,永远不要轻言放弃,胜利可能就在眼前。
无锡市普通高中2016年秋学期高三期中基础性检测考试卷数学一、填空题(本大题共14小题,每题5分,满分70分.)1.命题“若ln ln a b >,则a b >”是____________命题(填“真”或“假”).【答案】真考点:命题真假的判定.2.某工厂生产甲、乙、丙、丁4类产品共计1200件,已知甲、乙、丙、丁4类产品的数量之比为1:2:4:5,现要用分层抽样在方法从中抽取60件,则乙类产品抽取的件数为_____________.【答案】10【解析】试题分析:由题设乙类产品抽取的件数为106054212=⨯+++,故应填答案10. 考点:分层抽样的计算.3.函数y =的定义域为___________.【答案】[]12,【解析】试题分析:由题设可得210201≤≤⇒⎩⎨⎧≥-≥-x x x ,故应填答案[]12,. 考点:函数的定义域及不等式的解法.4.已知集合{}{}1,2,,a A B a b ==,若12A B ⎧⎫=⎨⎬⎩⎭,则A B =____________. 【答案】1112⎧⎫-⎨⎬⎩⎭,, 【解析】试题分析:由题设212=a ,则1-=a ,又B ∈21,则21=b ,故A B =1112⎧⎫-⎨⎬⎩⎭,,,故应填答案1112⎧⎫-⎨⎬⎩⎭,,. 考点:集合的交集并集运算.5.执行如图所示的流程图,则输出M 的应为____________.【答案】2考点:算法流程图的识读和理解.6.若复数()()()1120,x y i i x y R -+++=∈⎡⎤⎣⎦,则x y +=_____________.【答案】0【解析】试题分析:因为02≠+i ,所以0)1(1=++-i y x ,故1,1-==y x ,则0=+y x ,故应填答案0.考点:复数的概念及运用.7.已知盒中有3张分别标有1,2,3的卡片,从中随机地抽取一张,记下数字后再放回,再随机地抽取一张,记下数字,则两次抽得的数字之和为3的倍数的概率为___________.【答案】13【解析】试题分析:抽取的所有能有)2,3(),1,3(),3,3(),3,2(),1,2(),2,2(),3,1(),2,1(),1,1(共九种,其中)3,3(),1,2(),2,1(的数字之和都是3的倍数,所以两次抽得的数字之和为3的倍数的概率为3193==P ,故应填答案13. 考点:古典概型公式及运用.8.已知向量,a b 满足2,1,223a b a b ==-=,则a 与b 的夹角为____________.【答案】0120【解析】试题分析:因为12)2(2=-,即12444=+⋅-b a ,也即21cos ->=⋅<,所以a 与b 的夹角为0120,故应填答案0120.考点:向量的数量积公式及运用. 9.已知,x y 满足2y x x y x a ≥⎧⎪+≤⎨⎪≥⎩,若3z x y =+的最大值为M ,最小值为m ,且0M m +=,则实数a 的值为_____________.【答案】1-y=-3x+z考点:线性规划的知识及运用.10.已知()cos 24x f x π⎛⎫=-⎪⎝⎭,若()13f α=,则sin α=____________. 【答案】79-【解析】试题分析:由题设可得31)42cos(=-πα,即322sin 2cos =-αα,也即97)32(12sin 2cos 22=-=-αα.97sin -=α,故应填答案79-. 考点:二倍角的正弦及同角平方关系的运用.【易错点晴】三角变换公式及诱导公式是中学数学中的重要内容和工具,也高考和各级各类考试的重要内容和考点.本题以函数的解析式()cos 24x f x π⎛⎫=- ⎪⎝⎭和()13f α=为背景,考查的是三角变换的公式及转化化归的数学思想等有关知识和方法的综合运用.解答本题时要充分利用题设中提供的条件信息求出31)(=αf 建立方程322sin 2cos =-αα,然后运用两边平方及正弦二倍角公式求出97sin -=α,从而使得问题获解. 11.若函数2,0ln ,0x a x y x a x x ⎧-≤=⎨-+>⎩,在区间()2,2-上有两个零点,则实数a 的取值范围为__________.【答案】[)0,2ln 2+考点:函数的图象及零点的确定.【易错点晴】本题设置了一道以分段函数的解析式2,0ln ,0x a x y x a x x ⎧-≤=⎨-+>⎩背景的零点个数的综合应用问题.其的目的意在考查在数形结合的意识及运用所学知识去分析问题解决问题的能力.解答本题时要充分运用题设中提供的条件信息和图形信息,将问题等价转化为两个函数a x y -=2与函数x a x y ln +-=在给定的区间]0,2(-和区间)2,0(内分别有一个零点的问题.然后数形结合建立不等式组⎪⎩⎪⎨⎧>+->-≤-02ln 2040a a a ,通过解不等式组从而获得答案.12.设数列{}n a 的前n 项和为n S ,已知()2*427n n S a n n n N =-+∈,则11a =______________.【答案】2-【解析】试题分析:由题设()2*427n n S a n n n N =-+∈可得)1(7)1(24211-+--=--n n a S n n ,将以上两式两边相减可得7122241++--=-n a a a n n n ,即41+--=-n a a n n ,所以41+-=+-n a a n n ,又因为31=a ,所以14232-=+--=a ,故34213=+-=a ,依次可推得211-=a ,应填答案2-.考点:数列的递推式及运用.【易错点晴】数列的前n 项和与数列的通项公式之间的关系等有关知识是高中数学中的重要内容和解答数学问题的重要工具之一.本题设置的目的意在考查数列的通项n a 与其前n 项和n S 的关系)1(1>-=-n S S a n n n 及数列中的列举法归纳法等有关知识的灵活运用.求解时先依据题设条件()2*427n n S a n n n N =-+∈,进而得到()2*427n n S a n n n N =-+∈,然后逐一验证探求得到211-=a ,从而使得问题巧妙获解.13.已知正实数,a b 满足37a b +=,则1412a b+++的最小值为___________.【解析】试题分析: 因为1412a b +++11413(2)4(1)[(1)3(2)]()[13]14121412b a a b a b a b++=++++=++++++1313+≥,故应填答案1314+. 考点:基本不等式及灵活运用.【易错点晴】基本不等式是高中数学中的重要内容和解答数学问题的重要工具之一.本题设置的目的是考查基本不等式的灵活运用和灵活运用所学知识去分析问题解决问题的能力.求解时先将已知变形为1412a b+++133413]2)1(41)2(313[141)2411)](2(3)1[(141+≥++++++=++++++=b a a b b a b a ,然后再运用基本不等式最后达到获解之目的.14.已知正实数,x y 满足22ln ln 2x y x y +-=+,则y x =___________.考点:函数方程思想及基本不等式的运用条件.【易错点晴】基本不等式是高中数学中的重要内容和解答数学问题的重要工具之一.本题设置的目的是考查基本不等式的灵活运用和灵活运用所学知识去分析问题解决问题的能力.求解时先将已知22ln ln 2x y x y +-=+变形为222ln -+=y x xy ,然后再运用基本不等式得到22ln -≥xy xy ,再用取得等号时的条件⎪⎩⎪⎨⎧==⇒⎪⎩⎪⎨⎧-==21222ln 4y x xy xy y x ,使得问题获解. 二、解答题(本大题共6小题,共90分.解答应写出文字说明、证明过程或演算步骤.)15.(本题满分14分)已知三点()()()1,1,3,0,2,1,A B C P -,为平面ABC 上的一点,AP AB AC λμ=+且 0,3AP AB AP AC ==.(1)求AB AC ;(2)求λμ+的值.【答案】(1)4;(2)13λμ+=. (2)因为0AP AB =,所以AP AB ⊥,因为()2,1AB =,设(),2AP a a =-,................6分因为3AP AC =,所以()(),21,23,43,1a a a a a -=-==-,...........8分()1,2AP =-,因为()1,2AC =,所以()()()1,22,11,2λμ-=+,..........10分 所以1222λμλμ-=+⎧⎨=+⎩,则13λμ+=..............14分 考点:向量的数量积公式及坐标形式的运算公式等有关知识的综合运用.16.(本题满分14分)如图,在正方体1111ABCD A B C D -中,E 为棱1DD 的中点.求证:(1)1//BD 平面EAC ;(2)平面EAC ⊥平面1AB C .【答案】(1)证明见解析;(2)证明见解析.(2)因为1,AC BD DD ⊥⊥平面ABCD ,所以11,DD AC BD DD ⊥于D ,所以AC ⊥平面1BDD ,所以1AC BD ⊥,.................8分同理可证11AB BD ⊥,..................9分又1AC AB 于A ,所以1BD ⊥平面1AB C ,..................11分因为1//EO BD ,所以EO ⊥平面1AB C ,又EO ⊂平面EAC ,所以平面EAC ⊥平面1AB C ......................14分考点:线面平行的判定定理及面面垂直的判定定理等有关知识的综合运用.17.(本题满分14分)在ABC ∆中,角,,A B C 所对的边分别为,,a b c ,已知sin cosB b A =.(1)求B ;(2)若1cos sin 4A C =,求A . 【答案】(1)3B π=;(2)125π. 【解析】试题分析:(1)借助题设条件运用正弦定理建立方程求解;(2)借助题设运用三角变换公式建立方程探求.试题解析:(1)因为sin sin a b A B=,所以sin sinB b A a =,又sin cos b A B =cos sin B a B =,..........3分即tan B =3B π=.................6分考点:正弦定理及三角变换的公式等有关知识的综合运用.18.(本题满分16分)某工厂第一季度某产品月生产量依次为10万件,12万件,13万件,为了预测以后每个月的产量,以这3个月的产量为依据,用一个函数模拟该产品的月产量y(单位:万件)与月份x的关系. 模拟函数1:by ax cx=++;模拟函数2:sy m n s=+.(1)已知4月份的产量为万件,问选用哪个函数作为模拟函数好?(2)受工厂设备的影响,全年的每月产量都不超过15万件,请选用合适的模拟函数预测6月份的产量.【答案】(1)by ax cx=++;(2)13.875.【解析】试题分析:(1)借助题设条件运用已知建立方程组分析探求;(2)借助题设运用函数的思想分析探求.试题解析:(1)若用模拟函数1:by ax cx=++,则有1012221333a b c b a c b a c ⎧⎪=++⎪⎪=++⎨⎪⎪=++⎪⎩,解得125,3,22a b c ==-=,.................3分 即32522x y x =-+,当4x =时,13.75y =..............5分 若用模拟函数2:xy m n s =+,则有23101213mn smn s mn s=+⎧⎪=+⎨⎪=+⎩,解得18,,142m n s =-==,.................8分 即3142xy -=-,当4x =时,13.5y =....................10分所以选用模拟函数1好...................11分考点:函数思想、函数求值及分析探求思想等有关知识的综合运用.19.(本题满分16分)已知正项数列{}n a 为等比数列,等差数列{}n b 的前n 项和为()*n S n N∈,且满足:139********,41,,S S S a b a b =-===.(1)求数列{}n a ,{}n b 的通项公式; (2)设()*1122n n n T a b a b a b n N =+++∈,求n T ;(3)设,,n n n a n c b n ⎧=⎨⎩为奇数为偶数,问是否存在正整数m ,使得()121283m m m m m m c c c c c c +++++=++.【答案】(1)()1*2n n a n N -=∈;(2)()()*3828n n T n n N =-⨯+∈;(3)2m =.(2)()111222112352n n n n T a b a b a b n -=+++=-⨯+⨯++-⨯,.........① 则()222212352n n T n =-⨯+⨯++-⨯,..............② 将①—②得:()()()()()212322235232235228328n nn nnnT n n n --=-+⨯+++--⨯=⨯---⨯-=-⨯-所以()()*3828nn T n n N=-⨯+∈...................8分 (3)因为12,35,n n n n c n -⎧=⎨-⎩为奇数为偶数,当1m =时,()1231238114812,318c c c c c c +=+=++=,不等,...........9分 当2m =时,2348147836c c c +=+=,()()2343314736c c c ++=++=成立,...............10分当3m ≥且为奇数时,2,m m c c +为偶数,1m c +为奇数,所以128m m m c c c +++为偶数,()123m m m c c c ++++为奇数,不成立,.............12分 当4m ≥,且m 为偶数时,若()121283m m m m m m c c c c c c +++++=++,即()()()352318335231m m m m m m -++=-+++,..................13分 得()2912821820m m m m --=-.............(*)因为()()24912823612821820m m m m m m --≥-->-,所以(*)不成立.......15分 综上得2m =............................16分考点:等差数列的有关知识及错位相减法求和等有关知识的综合运用.【易错点晴】本题以等差数列等比数列的前n 项和与通项的关系式为背景,考查的是运用数列、不等式等有关知识进行推理论证的思维能力及综合运用所学知识去分析问题和解决问题的能力.第一问求解时充分借助题设条件中的有效信息利用等差数列的通项公式及前n 项和之间的关系建立方程组进行求解.第二问则运用错位相减法求和法进行求解;第三问分类整合的思想进行分析推证探求,从而使得问题获解. 20.(本题满分16分) 已知函数()sin x xf x e=的定义域为[]()0,2,g x π为()f x 的导函数. (1)求方程()0g x =的解集; (2)求函数()g x 的最大值与最小值;(3)若函数()()F x f x ax =-在定义域上恰有2个极值点,求实数a 的取值范围. 【答案】(1)4x π=或54x π=;(2)最大值为()01g =,最小值为212g e ππ⎛⎫=- ⎪⎝⎭;(3)22ea e ππ---<<或32a eπ-=.(2)因为()cos sin sin cos cos 2x x x x xx x x x xg x e e e e e '=--+-=-,...........4分 令()0g x '=,解得x π=或3x π=,...........................5分所以()g x 的最大值为()01g =,所以()g x 的最小值为212g e ππ⎛⎫=- ⎪⎝⎭.........7分 (3)因为()()sin cos x x x xF x a g x a e e'=-+-=-, 所以函数()()F x f x ax =-在定义域上恰有2个极值点,等价于()0g x a -=在定义域上恰有2个零点且在零点处异号,即()y g x =与y a =的图象恰有两个交点................... 9分由(2)知()()2001,22F g a a F g a e a πππ-⎛⎫⎛⎫''=-=-=-=-- ⎪ ⎪⎝⎭⎝⎭,()()32233,2222a F g a e F g a e a ππππππ---⎛⎫⎛⎫''=-==-=- ⎪ ⎪⎝⎭⎝⎭, 若02F π⎛⎫'≥⎪⎝⎭,则3022F F ππ⎛⎫⎛⎫''>> ⎪ ⎪⎝⎭⎝⎭,所以()0F x '=至多只有1个零点,不成立,...............10分所以只有02F π⎛⎫'<⎪⎝⎭;..................11分 若302F π⎛⎫'<⎪⎝⎭,则()20F π'<,所以()0F x '=只有1个零点,不成立,..........12分 所以302F π⎛⎫'≥⎪⎝⎭................13分 若302F π⎛⎫'=⎪⎝⎭,即32a e π-=,在32x π=处同号,不成立; 若()20F π'≤,则()0F x '=有3个零点,不成立,....................14分 所以只有()20F π'>.所以满足的条件为:()()22022220F g a e a F g a e a ππππππ--⎧⎛⎫⎛⎫'=-=--<⎪ ⎪ ⎪⎝⎭⎝⎭⎨⎪'=-=->⎩, 解得22e a eππ---<<或32a eπ-=....................16分注:利用图像直接得出22e a e ππ---<<或32a eπ-=扣4分.考点:导数的知识及分析推证法等有关知识的综合运用.【易错点晴】导数是研究函数的单调性和极值最值问题的重要而有效的工具.本题就是以函数解析式()sin xxf x e =为背景,考查的是导数知识在研究函数单调性和最值等方面的综合运用和分析问题解决问题的能力.第一问求解时直接运用导数的求导法则建立求出4x π=或54x π=;第二问求解时,直接运用导数和函数的单调性之间的关系求出其最值;第三问则是运用函数的零点之间的关系建立等式,然后分析推证的方法求出参数a 的取值范围是22ea eππ---<<或32a eπ-=.。
无锡市一般高中2021年秋学期高三期中根基性检测试卷数 学命题单位:宜兴市教师展开中心制卷单位:无锡市教育科学研究院本卷须知及说明:本卷考试时间为 120分钟,全卷总分值为160 分.一.填空题〔本大题共 14小题,每题 5分,合计 70分.请把答案填写在答题卡相应地点.......上.〕. 1.命题“假定lna lnb ,那么a b 〞是 ▲ 命题〔填“真〞或“假〞〕. 2.某工厂生产甲、乙、丙、丁 4类产品合计1200 件,甲、乙、丙、丁 4类产品的数目 之比为1:2:4:5,现要用分层抽样的方法从中抽取 30件,那么乙类产品抽取的件数为▲.3.函数y x 1 2 x 的定义域为 ▲ .4.会合Aa,Ba,b ,假定AB1,1,2 2那么AB ▲ .5.履行以下列图的流程图,那么输出的M 应为▲ .6.假定复数[x 1(y 1)i ]( 2 i)(x0,y R ),那么xy▲ .7.盒中有3张分别标有 1,2,3的卡片,从中随机地抽取一张,记下数字后再放回,再随机地抽取一张,记下数字,那么两次抽得的数字之和为 3的倍数的概率为▲.8.a2,b1,a 2b 23,那么a 与b 的夹角为▲ .y ⋯x,yx, z3xym Mm09 知足 xy , 2, 假定 的最大值为M,最小值为,且 ,那么.⋯x a,实数a 的值为▲.10.f(x) x),假定 f() 1 ▲. cos( ,那么sin 2 4 311.假定函数y x 2a, x 0,在区间( 2,2)上有两个零点,那么实数 a 的范围为▲.,xa lnx,x0,12.设数列a n 的前n项和为S n,4S n2a n n27n(nN),那么a11▲.13.正实数a,b知足a3b7,那么14的最小值为▲.14.正实数x,y知足x1a2b2y2lnx lny,那么x y▲.2二、解答题:〔本大题共6道题,计90分.解允许写出必需的文字说明、证明过程或演算步骤〕15.〔本题总分值14分〕三点A(1,1),B(3,0),C(2,1),P为平面ABC上的一点,AP ABAC,且AP AB0,APAC 3.1〕求ABAC;2〕求的值.16.〔本题总分值14分〕如图,在正方体ABCD-A1B1C1D1中,E为棱DD1的中点,求证:1〕BD1∥平面EAC;(2〕平面EAC⊥平面AB1C.17.〔本题总分值14分〕在ABC中,角A,B,C所对的边分别为a,b,c,bsinA3acosB.〔1〕求角B的值;31〔2〕假定cosAsinC,求角A的值.418.〔本题总分值16分〕某工厂第一季度某产品月生产量分别为10万件,12万件,13万件,为了展望此后每个月的产量,以这3个月的产量为依照,用一个函数模拟该产品的月产量y〔单位:万件〕与月份x 的关系.模拟函数1:y ax b c;模拟函数2:ymn x s.x〔1〕4月份的产量为万件,问采用哪个函数作为模拟函数好?〔2〕受工厂设施的影响,整年的每个月产量都不超出15万件,请采用适合的模拟函数展望6月份的产量.19.〔本题总分值16分〕数列a n为等比数列,等差数列b n的前n项和为S n〔n N〕,且知足:S13208,S9S741,a1b2,a3b3.〔1〕求数列a n,b n的通项公式;〔2〕设T n a1b1a2b2a n b n〔n N〕,求T n;a n,n,〔3〕设c n为奇数问能否存在正整数m,使得c m c m1c m28为偶数b n,n,3(c m c m1c m2).20.〔本题总分值16分〕函数f(x)sinx,定义域为[0,2],g(x)为f(x)的导函数.e x〔1〕求方程g(x)0的解集;〔2〕求函数g(x)的最大值与最小值;〔3〕假定函数F(x)f(x) ax在定义域上恰有2个极值点,务实数a的取值范围.精选文档11。
无锡市普通高中2016年秋学期高三期中考试试卷英语参考答案听力测试(20分)1~5 ACCBB 6~10 CCACC 11~15 ACCCA 16~20 BCCBA单项填空(15分)21~25 CBAAC 26~30CADBC 31~35 DBACC完形填空(20分)36~40 CDDBA 41~45 ABBCC 46~50 DADCC 51~55BBCDC阅读理解(30分)56~57 DB 58~60 DBA 61~64 DACD 65~70 BACADA任务型阅读(10分)71. unexpected / amazing / surprising/ astonishing 72.fairness 73. serve74. living 75. long-term 76. ahead/beforehand77. instincts / heart 78. clearly 79. point / meaning / sense80. patient/calm书面表达(25分)Nowadays, a beautiful face plays an important part in helping people achieve fame and fortune. Some people even improve their appearance through undesirable plastic surgery. However, success comes from perseverance. (30 words)Personally, I think it’s unfair to offer fewer chances to those with average appearance. What really counts in one’s life is one’s ability but not the appearance. As we all know, appearance is given by parents, and we shouldn’t change it at will. Meanwhile, plastic surgery will also add to the economic burden of a family. We shouldn’t expect success overnight through beautiful image. We can only build confidence and succeed by working hard and learning more relevant knowledge.In conclusion, we must take a proper attitude to image. Virtue is more important than appearance. It is necessary for us to do what we can to improve our inner qualities to fit in with the society and achieve our goals. (120 words)书面表达得分要点和评分标准一、评分细则1.本题总分为25分,按5个档次给分。
2016年秋学期无锡市普通高中高三数学期末考试试卷一、填空题(本大题共14小题,每小题5分,共70分)1、设集合{}0>=x x A ,{}21≤<-=x x B ,则=B A . 2、已知复数iz -=12,其中i 为虚数单位,则复数z 的共轭复数为 . 3、命题“422≥≥∀x x ,”的否定是 .4、从3男2女共5名学生中任选2名参加座谈会,则选出的2人恰好为1男1女的概率 为 .5、根据如图所示的伪代码可知,输出的结果为 .6、已知向量),(),,(1112-==,若-与m +垂直,则实数m 的值为 .7、设不等式表示⎪⎩⎪⎨⎧≤+≤-≥401y x y x x 表示的平面区域为M ,若直线2-=kx y 存在M 内的点,则实数k 的取值范围为 .8、已知函数⎩⎨⎧<>-=032x x g x x f x ),(,)(是奇函数,则=-))((2g f .9、设公比不为1的等比数列{}n a 满足81321-=a a a ,且342a a a ,,成等差数列,则数列{}n a 的前4项和为 .10、设函数)cos(cos sin )(232π+-=x x x x f ,则函数)(x f 在区间],[20π上的单调增 区间为 .11、已知圆锥的侧面展开图是一个圆心角︒120为且面积为π3的扇形,则该圆锥的体积等 于 .12、设点P 是有公共焦点21F F ,的椭圆1C 与双曲线2C 的一个交点,且21PF PF ⊥,椭圆1C 的离心率为1e ,双曲线2C 的离心率为2e ,若123e e =,则=1e .13、若函数)(x f 在区间)](,[n m n m <上的值域恰好是],[n m ,则称区间为],[n m 函数)(x f 的一个“等值映射区间”.下列函数:①12-=x y ;②x y 22log +=;③12-=xy ;④11-=x y ,其中存在唯一一个“等值映射区间”的函数有 个. 1←i 2-←S While 8<i 2+←i i S i S +←3 End Whlie int Pr S14、已知200>>>c b a ,,,且2=+b a ,则252-+-+c c ab c b ac 的最小值为 . 二、解答题(本大题共6小题,共90分.解答应写出必要的文字说明、证明 或演算步骤)15、在ABC ∆中,角C B A ,,所对的边分别为c b a ,,,且122=++CB A cos sin ,D 为BC 上一点,且AC AB AD 4341+=. (1)求A sin 的值;(2)若524==b a ,,求AD 的长.16、在四棱锥ABCD P -中,底面ABCD 为矩形,⊥AP 平面PCD ,F E ,分别为AB PC , 的中点.(1)求证:平面⊥PAD 平面ABCD ;(2)求证://EF 平面PAD .17、某地拟在一个U 形水面)(︒=∠=∠90B A PABQ 上修一条堤坝EN (E 在AP 上,N 在BQ 上),围出一个封闭区域EABN ,用以种植水生植物.为美观起见,决定从AB上点M 处分别向点N E ,拉2条分隔线MN ME ,将所围区域分成3个部分(如图),每部 分种植不同的水生植物.已知︒=∠==90MEN BM EM a AB ,,,设所拉分隔线总长度 为l .(1)设θ2=∠AME ,求用θ表示l 的函数表达式,并写出定义域;;(2)求l 的最小值.18、已知椭圆13422=+y x ,动直线l 与椭圆交于C B ,两点(点B 在第一象限). (1)若点B 的坐标为),(231,求OBC ∆的面积的最大值;(2)设),(),,(2211y x C y x B ,且0321=+y y ,求当OBC ∆的面积最大时直线l 的方程.19、数列{}n a 的前n 项和为n S ,21=a ,)(r na S n n +=3(R ∈r ,*∈N n ). (1)求r 的值及数列{}n a 的通项公式; (2)设nn a n b =(*∈N n ),记{}n b 的前n 项和为n T . ①当*∈N n 时,n n T T -<2λ恒成立,求实数λ的取值范围; ②求证:存在关于n 的整式)(n g ,使得1111-⋅=+∑-=)()(n g T Tn n i i对一切2≥n ,*∈N n 都成立.20、已知函数)()(R ∈++=m mx x x f 12,x e x g =)(.(1)当],[20∈x 时,)()()(x g x f x F -=为增函数,求实数m 的取值范围; (2)若),(01-∈m ,设函数)()()(x g x f x G =,4541+-=x x H )(,求证:对任意],[,m x x -∈1121,)()(21x H x G ≤恒成立;2016年秋学期无锡市普通高中期末考试试卷高三数学(加试题)说明:解答时,应写出文字说明、证明过程或演算步骤. 21.(本题满分10分)选修4-4:坐标系与参数方程设极坐标系的极点为直角坐标系的原点,极轴为x 轴的正半轴.已知曲线C 的极坐标方程为8sin ρθ=(1)求曲线C 的直角坐标方程; (2)设直线,2,x t y t =⎧⎨=+⎩(t 为参数)与曲线C 交于A,B 两点,求AB 的长.22.(本题满分10分)选修4-2:矩阵与变换 已知变换T 将平面上的点()11,,0,12⎛⎫ ⎪⎝⎭分别变换为点93,2,,442⎛⎫⎛⎫-- ⎪ ⎪⎝⎭⎝⎭.设变换T 对应的矩阵为M.(1)求矩阵M ;(2)求矩阵M 的特征值.23.(本题满分10分)某小区停车场的收费标准为:每车每次停车时间不超过2小时免费,超过2小时的部分每小时收费1元(不足1小时的部分按1小时计算).现有甲乙两人独立来停车场停车(各停车一次),且两人停车时间均不超过5小时.设甲、乙两人停车时间(小时)与取车概率如下表所示.(1)求甲、乙两人所付车费相同的概率;(2)设甲、乙两人所付停车费之和为随机变量ξ,求ξ的分布列和数学期望E ξ.24.(本题满分10分)如图,四棱锥P ABCD -中,PA ⊥平面ABCD ,四边形ABCD 为直角梯形,//,90,1,2,,,AD BC BAD CBA PA AB BC AD E F G ∠=∠=====分别为,,BC PD PC 的中点.(1)求EF 与DG 所成角的余弦值;(2)若M 为EF 上一点,N 为DG 上一点,是否存在MN,使得M N ⊥平面PBC?若存在,求出点M,N 的坐标;若不存在,请说明理由.。
无锡市普通高中2016年秋学期高三期中基础性检测试卷
数 学 2016.11
命题单位:宜兴市教师发展中心 制卷单位:无锡市教育科学研究院
注意事项及说明: 本卷考试时间为120分钟, 全卷满分为160分.
一.填空题(本大题共14小题,每小题5分,共计70分.请把答案填写在答题卡相应位置.......上.
.) 1.命题“若ln ln a b >,则a b >”是 ▲ 命题(填“真”或“假”).
2.某工厂生产甲、乙、丙、丁4类产品共计1200件,已知甲、乙、丙、丁4类产品的数量之比为1:2:4:5,现要用分层抽样的方法从中抽取30件,则乙类产品抽取的件数为 ▲ .
3
.函数y =的定义域为 ▲ .
4.已知集合{}{}1,2,,a A B a b ==,若12A B ⎧⎫=⎨⎬⎩⎭
,则A B = ▲ .
5.执行如图所示的流程图,则输出的M 应为 ▲ .
6.若复数[1(1)i ](
2i )0x y -+++=(,)R x y ∈,则x y += ▲ .
7.已知盒中有3张分别标有1,2,3的卡片,从中随机地抽取一张,记下数字后再放回,再随机地抽取一张,
记下数字,则两次抽得的数字之和为3的倍数的概率为 ▲ . 8.已知2a =,1b =,223a b -=,则a 与b 的夹角为 ▲ .
9.已知,x y 满足,2,,y x x y x a ⎧⎪+⎨⎪⎩
……… 若3z x y =+的最大值为M ,最小值为m ,且0M m +=,则
实数a 的值为 ▲ .
10.已知()cos()24x f x π=-,若1()3
f α=,则sin α= ▲ . 11.若函数2,0,ln ,0,
x a x y x a x x ⎧-=⎨-+>⎩…在区间(2,2)-上有两个零点,则实数a 的范围为▲ .
12.设数列{}n a 的前n 项和为n S ,已知2427()N n n S a n n n *
=-+∈,则
11a = ▲ .
13.已知正实数,a b 满足37a b +=,则
1412a b +++的最小值为 ▲ . 14.已知正实数,x y 满足22ln ln 2
x y x y +-=+,则y x = ▲ . 二、解答题:(本大题共6道题,计90分.解答应写出必要的文字说明、证明过程或演算步骤)
15.(本题满分14分)
已知三点(1,1),(3,0),(2,1)A B C -,P 为平面ABC 上的一点,AP AB AC λμ=+,且0AP AB ⋅=,3AP AC ⋅=.
(1)求AB AC ⋅;
(2)求λμ+的值.
16.(本题满分14分)
如图,在正方体ABCD -A 1B 1C 1D 1中,E 为棱DD 1的中点,求证:
(1)BD 1∥平面EAC ;
(2)平面EAC ⊥平面AB 1C .
在ABC ∆中,角,,A B C 所对的边分别为,,a b c ,已知sin cos b A B =.
(1)求角B 的值;
(2)若cos sin A C =
A 的值.
18.(本题满分16分)
某工厂第一季度某产品月生产量分别为10万件,12万件,13万件,为了预测以后每个月的产量,以这3个月的产量为依据,用一个函数模拟该产品的月产量y (单位:万件)与月份x 的关系.模拟函数1:b y ax c x
=++;模拟函数2:x y m n s =⋅+. (1)已知4月份的产量为13.7万件,问选用哪个函数作为模拟函数好?
(2)受工厂设备的影响,全年的每月产量都不超过15万件,请选用合适的模拟函数预测6月份的产量.
已知数列{}n a 为等比数列,等差数列{}n b 的前n 项和为n S (N n *∈),且满足:1397208,41S S S =-=,1233,a b a b ==.
(1)求数列{}n a ,{}n b 的通项公式;
(2)设1122n n n T a b a b a b =+++(N n *∈),求n T ; (3)设,,,,n n n
a n c
b n ⎧=⎨⎩为奇数为偶数 问是否存在正整数m ,使得128m m m
c c c ++⋅⋅+= 123()m m m c c c ++++.
20.(本题满分16分) 已知函数sin ()x x f x e
=,定义域为[0,2]π,()g x 为()f x 的导函数. (1)求方程()0g x =的解集;
(2)求函数()g x 的最大值与最小值;
(3)若函数()()F x f x ax =-在定义域上恰有2个极值点,求实数a 的取值范围.。