2017-2018学年江苏省扬州中学高一下学期期中考试 英语
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2017-2018学年江苏省扬州中学高二(下)期中数学试卷(文科)
2017-2018学年江苏省扬州中学高二（下）期中数学试卷（文科）试题数：20，总分：01.（填空题，5分）已知全集U=Z，集合M={x|x2-x-2＜0，x∈Z}，N={-1，0，1，2}，则（∁U M）∩N=___ ．2.（填空题，5分）命题“若x≥1，则x2-4x+2≥-1”的否命题为___ ．3.（填空题，5分）设复数z满足（1+i）z=2i，则|z|=___ ．4.（填空题，5分）设x∈R，则“x＜1”是“x|x|-2＜0”的___ 条件．（填“充分必要”、“充分不必要”、“必要不充分”、“既不充分也不必要”）．5.（填空题，5分）已知函数f（x）= 13x3-x2，a∈R，则曲线y=f（x）在点（3，f（3））处的切线方程为___ ．6.（填空题，5分）已知函数f(x)={x2+2x x≥02x−x2 x＜0若f（2-a2）＞f（a），则实数a的取值范围是___ ．7.（填空题，5分）若方程x2+（k-2）x+2k-1=0有两个实数根，一根在区间（0，1）内，另一根在区间（1，2）内，则实数k的取值范围___ ．8.（填空题，5分）函数f（x）=|x2+x-t|在区间[-1，2]上最大值为4，则实数t=___ ．9.（填空题，5分）已知三角形的三边分别为a，b，c，内切圆的半径为r，则三角形的面积为s= 12（a+b+c）r；四面体的四个面的面积分别为s1，s2，s3，s4，内切球的半径为R．类比三角形的面积可得四面体的体积为___ ．10.（填空题，5分）设函数f′（x）是奇函数f（x）（x∈R）的导函数，f（-1）=0，当x＞0时，xf′（x）-f（x）＞0，则使得f（x）＞0成立的x的取值范围是___ ．11.（填空题，5分）已知a n=log n+1（n+2）（n∈N*），观察下列算式：a1•a2=log23•log34= lg3lg2• lg4lg3=2；a1•a2•a3•a4•a5•a6=log23•log34•…• log78 = lg3lg2• lg4lg3•…• lg8lg7=3…；若a1•a2•a3…a m=2016（m∈N*），则m的值为___ ．12.（填空题，5分）定义区间[x1，x2]长度为x2-x1（x2＞x1），已知函数f（x）= (a2+a)x−1a2x （a∈R，a≠0）的定义域与值域都是[m，n]，则区间[m，n]取最大长度时a的值是___ ．13.（填空题，5分）已知f（x）是以2e为周期的R上的奇函数，当x∈（0，e），f（x）=lnx，若在区间[-e，2e]，关于x的方程f（x）=kx+1恰好有4个不同的解，则k的取值集合是___ ．14.（填空题，5分）已知a为常数，函数f（x）= x(√a−x2+√1−x2)a−1的最大值为1，则a的所有值为___ ．15.（问答题，0分）（1）计算：−3+i2−4i；（2）在复平面内，复数z=（m+2）+（m2-m-2）i对应的点在第一象限，求实数m的取值范围．16.（问答题，0分）已知a∈R，命题p：“∀x∈[1，2]，x2-a≥0”，命题q：“∃x∈R，x2+2ax+2-a=0”．（1）若命题p为真命题，求实数a的取值范围；（2）若命题“p∨q”为真命题，命题“p∧q”为假命题，求实数a的取值范围．17.（问答题，0分）已知函数f（x）=x|x-a|+2x．（1）当a=3时，方程f（x）=m的解的个数；（2）对任意x∈[1，2]时，函数f（x）的图象恒在函数g（x）=2x+1图象的下方，求a的取值范围；（3）f（x）在（-4，2）上单调递增，求a的范围．18.（问答题，0分）一家公司计划生产某种小型产品的月固定成本为1万元，每生产1万件需要再投入2万元，设该公司一个月内生产该小型产品x万件并全部销售完，每万件的销售收入为4-x万元，且每万件国家给予补助2e- 2elnxx - 1x万元．（e为自然对数的底数，e是一个常数）（Ⅰ）写出月利润f（x）（万元）关于月产量x（万件）的函数解析式（Ⅱ）当月产量在[1，2e]万件时，求该公司在生产这种小型产品中所获得的月利润最大值（万元）及此时的月生成量值（万件）．（注：月利润=月销售收入+月国家补助-月总成本）19.（问答题，0分）（1）用分析法证明：当x≥0，y≥0时，√2y≥ √x+2y - √x；（2）证明：对任意x∈R，3|x-1|-x+1，x2+x，-2x-1这3个值至少有一个不小于0．20.（问答题，0分）已知函数f（x）=x2+ax+a+1，g（x）=lnx，（a∈R）．（1）当a=1时，求函数y=f（x）-g（x）的单调区间；（2）若存在与函数f（x），g（x）的图象都相切的直线，求实数a的取值范围．2017-2018学年江苏省扬州中学高二（下）期中数学试卷（文科）参考答案与试题解析试题数：20，总分：01.（填空题，5分）已知全集U=Z，集合M={x|x2-x-2＜0，x∈Z}，N={-1，0，1，2}，则（∁U M）∩N=___ ．【正确答案】：[1]{-1，2}【解析】：先求集合M，再求补集，再求交集．【解答】：解：∵集合M={x|x2-x-2＜0，x∈Z}，∴M={0，1}，∴∁U M={x|x≠0，1，x∈Z}，∴（∁U M）∩N={-1，2}，故答案为：{-1，2}．【点评】：本题考查集合交并补，属于基础题，2.（填空题，5分）命题“若x≥1，则x2-4x+2≥-1”的否命题为___ ．【正确答案】：[1]若x＜1，则x2-4x+2＜-1【解析】：直接利用四种命题的逆否关系，写出结果即可．【解答】：解：命题“若x≥1，则x2-4x+2≥-1”的否命题为：若x＜1，则x2-4x+2＜-1；故答案为：若x＜1，则x2-4x+2＜-1．【点评】：本题考查四种命题的逆否关系的应用，注意命题的否定与否命题的区别，是基础题．3.（填空题，5分）设复数z满足（1+i）z=2i，则|z|=___ ．【正确答案】：[1] √2【解析】：把已知等式变形，然后利用复数代数形式的乘除运算化简，再由复数求模公式计算得答案．【解答】：解：由（1+i）z=2i，得z=2i1+i =2i(1−i)(1+i)(1−i)=1+i，则|z|= √2．故答案为：√2．【点评】：本题考查了复数代数形式的乘除运算，考查了复数模的求法，是基础题．4.（填空题，5分）设x∈R，则“x＜1”是“x|x|-2＜0”的___ 条件．（填“充分必要”、“充分不必要”、“必要不充分”、“既不充分也不必要”）．【正确答案】：[1]充分不必要【解析】：x|x|＜2，对x分类讨论，解出不等式的解集，即可判断出．【解答】：解：x|x|＜2，当x≤0时，化为-x2＜2，恒成立；当x＞0时，化为x2＜2，解得0＜x＜√2，综上可得：x|x|＜2的解集为：{x|x＜√2 }．∴“x＜1”是“x|x|＜2”的充分不必要条件．故答案为：充分不必要．【点评】：本题考查了含绝对值不等式的解法、简易逻辑的判定方法，考查了分类讨论方法、推理能力与计算能力，属于中档题．5.（填空题，5分）已知函数f（x）= 13x3-x2，a∈R，则曲线y=f（x）在点（3，f（3））处的切线方程为___ ．【正确答案】：[1]3x-y-9=0【解析】：先求出导数，然后可得切线斜率，再将切点横坐标代入f（x）求出切点坐标，最后利用点斜式写出切线方程．【解答】：解：f′（x）=x2-2x，所以k=f′（3）=3．又f（3）=0，所以切线方程为：y=3（x-3），即：3x-y-9=0．故答案为：3x-y-9=0．【点评】：本题考查了利用导数求切线方程的基本步骤，抓住切点是关键．属于基础题．6.（填空题，5分）已知函数 f (x )={x 2+2x x ≥02x −x 2 x ＜0若f （2-a 2）＞f （a ），则实数a 的取值范围是___ ．【正确答案】：[1]（-2，1）【解析】：先得到函数 f (x )={x 2+2x x ≥02x −x 2 x ＜0在定义域上是增函数，再由函数单调性定义求解．【解答】：解：易知函数 f (x )={x 2+2x x ≥02x −x 2 x ＜0在定义域上是增函数 ∴f （2-a 2）＞f （a ），可转化为：2-a 2＞a解得：-2＜a ＜1∴实数a 的取值范围是（-2，1）故答案为：（-2，1）【点评】：本题主要考查函数的单调性定义在解不等式中的应用，一般来讲，抽象函数不等式，多数用单调性定义或数形结合法求解．7.（填空题，5分）若方程x 2+（k-2）x+2k-1=0有两个实数根，一根在区间（0，1）内，另一根在区间（1，2）内，则实数k 的取值范围___ ．【正确答案】：[1] 12＜k ＜23【解析】：将方程转化成函数，可知函数有两个零点，根据开口向上的二次函数图象，可以判断函数值，解出即可．【解答】：解：设f （x ）=x 2+（k-2）x+2k-1，为开口向上的二次函数，∵方程x 2+（k-2）x+2k-1=0有两个实数根，一根在区间（0，1）内，另一根在区间（1，2）内，∴f （x ）在区间（0，1）和（1，2）内有零点．∴ {f (0)＞0f (1)＜0f (2)＞0，即 {2k −1＞01+k −2+2k −1＜04+2(k −2)+2k −1＞0 ， 解之得 12＜k ＜23 ．故答案为：12＜k＜23．【点评】：本题考查根与系数的关系，结合函数与零点的问题可以判定，属于中档题．8.（填空题，5分）函数f（x）=|x2+x-t|在区间[-1，2]上最大值为4，则实数t=___ ．【正确答案】：[1]2或154【解析】：根据数f（x）=|x2+x-t|=|（x+ 12）2- 14-t|，在区间[-1，2]上最大值为4，可得4+2-t=4或14+t=4，由此可求t的值．【解答】：解：∵函数f（x）=|x2+x-t|=|（x+ 12）2- 14-t|，在区间[-1，2]上最大值为4，∴4+2-t=4或14+t=4∴t=2或t= 154故答案为：2或154【点评】：本题考查二次函数在闭区间上的最值，考查学生的计算能力，属于基础题．9.（填空题，5分）已知三角形的三边分别为a，b，c，内切圆的半径为r，则三角形的面积为s= 12（a+b+c）r；四面体的四个面的面积分别为s1，s2，s3，s4，内切球的半径为R．类比三角形的面积可得四面体的体积为___ ．【正确答案】：[1]V= 13（s1+s2+s3+s4）R【解析】：根据三角形的边应与四面体中的各个面进行类比，而面积与体积进行类比，进行类比猜想即可．【解答】：解：根据几何体和平面图形的类比关系，三角形的边应与四面体中的各个面进行类比，而面积与体积进行类比：∴△ABC的面积为s= 12（a+b+c）r，对应于四面体的体积为V= 13（s1+s2+s3+s4）R．故答案为：V= 13（s1+s2+s3+s4）R．【点评】：本题考查多面体的体积，考查立体几何和平面几何的类比推理，一般平面图形的边、面积分别于几何体中的面和体积进行类比，是基础题．10.（填空题，5分）设函数f′（x）是奇函数f（x）（x∈R）的导函数，f（-1）=0，当x＞0时，xf′（x）-f（x）＞0，则使得f（x）＞0成立的x的取值范围是___ ．【正确答案】：[1]（-1，0）∪（1，+∞）【解析】：由已知当x＞0时总有xf′（x）-f（x）＞0成立，可判断函数g（x）为增函数，由已知f（x）是定义在R上的奇函数，可证明g（x）为（-∞，0）∪（0，+∞）上的偶函数，根据函数g（x）在（0，+∞）上的单调性和奇偶性，而不等式f（x）＞0等价于xg（x）＞0，分类讨论即可求出【解答】：解：设g（x）= f(x)x ，则g（x）的导数为：g′（x）= xf′(x)−f(x)x2，∵当x＞0时，xf′（x）-f（x）＞0，即当x＞0时，g′（x）恒大于0，∴当x＞0时，函数g（x）为增函数，∵f（x）为奇函数∴函数g（x）为定义域上的偶函数又∵g（-1）= f(−1)−1=0，∵f（x）＞0，∴当x＞0时，f(x)x ＞0，当x＜0时，f(x)x＜0，∴当x＞0时，g（x）＞0=g（1），当x＜0时，g（x）＜0=g（-1），∴x＞1或-1＜x＜0故使得f（x）＞0成立的x的取值范围是（-1，0）∪（1，+∞），故答案为：（-1，0）∪（1，+∞）【点评】：本题主要考查了利用导数判断函数的单调性，并由函数的奇偶性和单调性解不等式，属于综合题．11.（填空题，5分）已知a n=log n+1（n+2）（n∈N*），观察下列算式：a1•a2=log23•log34= lg3lg2• lg4lg3=2；a1•a2•a3•a4•a5•a6=log23•log34•…• log78 = lg3lg2• lg4lg3•…• lg8lg7=3…；若a1•a2•a3…a m=2016（m∈N*），则m的值为___ ．【正确答案】：[1]22016-2【解析】：根据已知中的等式，结合对数的运算性质，可得a 1•a 2•a 3•…• a 2n −2 =n （n≥2），进而得到答案．【解答】：解：∵a n =log n+1（n+2）（n∈N *），∴a 1•a 2=log 23•log 34= lg3lg2 • lg4lg3 =2；a 1•a 2•a 3•a 4•a 5•a 6=log 23•log 34•…• log 78 = lg3lg2 • lg4lg3 •…• lg8lg7 =3；…归纳可得：a 1•a 2•a 3•…• a 2n −2 =n （n≥2），若a 1•a 2•a 3•…•a m =2016，则m=22016-2，故答案为：22016-2【点评】：归纳推理的一般步骤是：（1）通过观察个别情况发现某些相同性质；（2）从已知的相同性质中推出一个明确表达的一般性命题（猜想）．12.（填空题，5分）定义区间[x 1，x 2]长度为x 2-x 1（x 2＞x 1），已知函数f （x ）= (a 2+a)x−1a 2x （a∈R ，a≠0）的定义域与值域都是[m ，n]，则区间[m ，n]取最大长度时a 的值是___ ．【正确答案】：[1]3【解析】：化简f （x ），首先考虑f （x ）的单调性，由题意： {f (m )=m f (n )=n，故m ，n 是方程f （x ）的同号的相异实数根．利用韦达定理和判别式，求出m ，n 的关系．在求最大值．【解答】：解：函数f （x ）=(a 2+a)x−1a 2x （a∈R ，a≠0）的定义域是{x|x≠0}，则[m ，n]是其定义域的子集，∴[m ，n]⊆（-∞，0）或（0，+∞）．f （x ）= (a 2+a)x−1a 2x = a+1a −1a 2x 在区间[m ，n]上时增函数，则有： {f (m )=m f (n )=n， 故m ，n 是方程f （x ）= a+1a −1a 2x =x 的同号相异的实数根， 即m ，n 是方程（ax ）2-（a 2+a ）x+1=0同号相异的实数根．那么mn= 1a 2 ，m+n= a+1a，只需要△＞0， 即（a 2+a ）2-4a 2＞0，解得：a ＞1或a ＜-3．那么：n-m= √(m +n )2−4mn = √−3(1a −13)2+43 ， 故n-m 的最大值为 2√33 ，此时 1a =13 ，解得：a=3．即在区间[m，n]的最大长度为2√33，此时a的值等于3．故答案为3．【点评】：本题考查了函数性质的方程的运用，有一点综合性，利用函数关系，构造新的函数解题．属于中档题，分类讨论思想的运用，增加了本题的难度，解题时注意．13.（填空题，5分）已知f（x）是以2e为周期的R上的奇函数，当x∈（0，e），f（x）=lnx，若在区间[-e，2e]，关于x的方程f（x）=kx+1恰好有4个不同的解，则k的取值集合是___ ．【正确答案】：[1] {−1e ，−12e}【解析】：由题意可得f（0）=0，f（e）=0，f（-e）=0，画出f（x）在[-e，2e]上的图象，计算直线y=kx+1过（e，0），（2e，0），时，k的值，结合图象可得k取值的集合．【解答】：解：f（x）是R上的奇函数，可得f（0）=0，又因为f（x）的周期为2e，所以f（x）=f（x+2e），得f（-e）=f（e），因为f（e）=-f（-e），所以f（e）=f（-e）=0，当x∈（0，e）时，f（x）=lnx，且f（0）=0，f（e）=0，作出函数f（x）在[-e，2e]上的图象，由在区间[-e，2e]上关于x的方程f（x）=kx+1有4个不同的解，则直线y=kx+1经过点（e，0）或（2e，0），则k=- 1e 或- 12e所以k的取值集合为：{- 1e ，- 12e}．故答案为：{- 1e ，- 12e}．【点评】：本题考查方程和函数的转化思想，考查函数的奇偶性和数形结合思想方法，以及运算能力，属于中档题．14.（填空题，5分）已知a 为常数，函数f （x ）= x(√a−x 2+√1−x 2)a−1的最大值为1，则a 的所有值为___ ． 【正确答案】：[1]3±√52【解析】：首先根据解析式可知a≠1，a=0以及a ＜0时不合题意，舍去，再讨论0＜a ＜1和a ＞1时的情况，利用导数得到单调区间，判断出最大值，解出相应的a 即可【解答】：解：由条件可知a≠1，当a=0时，函数的定义域为0，则f （0）=0不合题意，舍去； 当a ＜0时，函数的定义域为∅，不合题意，舍去； 当0＜a ＜1时，函数的定义域为[- √a ， √a ]， 令f′（x ）=(√a−x 2+√1+x 2)−(x 2√a−x 2+x 2√1−x 2)a−1=(√a−x 2+√1−x 2)(1−x 2√a−x 2√1−x 2)a−1=0，解得x=± √aa+1 ，当- √a ＜x ＜- √aa+1 ， √aa+1 ＜x ＜ √a 时，f′（x ）＞0， 当- √aa+1 ＜x ＜ √a a+1 时，f′（x ）＜0，则函数在（- √a ，- √aa+1 ），（ √aa+1 ， √a ）上单调地增，在（- √aa+1 ， √aa+1 ）上单调递减， 当x=- √aa+1 时，f （- √aa+1 ）= √a1−a ， 当x= √a 时，f （ √a ）=- √a1−a ＜0，则f（x）的最大值为f（- √aa+1）= √a1−a=1，解得a= 3−√52（a= 3+√52＞1舍去），当a＞1时，函数的定义域为[-1，1]，当-1＜x＜- √aa+1，√aa+1＜x＜1时，f′（x）＜0，当- √aa+1＜x＜√aa+1时，f′（x）＞0，则函数在（-1，- √aa+1），（√aa+1，1）上单调递减，在（- √aa+1，√aa+1）上单调地增，当x=-1时，f（-1）=- √a−1＜0，当x= √aa+1时，f（√aa+1）= √aa−1，则f（x）的最大值为f（√aa+1）= √aa−1=1，解得a= 3+√52（a= 3−√52＜舍去），综上：a的所有值为3+√52，3−√52．故答案为3±√52．【点评】：本题考查利用函数最大值求参数，考查分类讨论思想，利用导数求函数最值，属于中档偏难题．15.（问答题，0分）（1）计算：−3+i2−4i；（2）在复平面内，复数z=（m+2）+（m2-m-2）i对应的点在第一象限，求实数m的取值范围．【正确答案】：【解析】：（1）利用复数的除法的运算法则化简求解即可．（2）利用复数的对应点所在象限列出不等式组，求解即可．【解答】：解：（1）−3+i2−4i = (−3+i)(2+4i)(2−4i)(2+4i)= −10−10i20= −12−12i…（6分）（2）复数z=（m+2）+（m2-m-2）i对应的点在第一象限，可得：{m+2＞0m2−m−2＞0，解得：m∈（-2，-1）∪（2，+∞）…（14分）【点评】：本题考查复数的代数形式混合运算，复数的几何意义，考查计算能力．16.（问答题，0分）已知a∈R ，命题p ：“∀x∈[1，2]，x 2-a≥0”，命题q ：“∃x∈R ，x 2+2ax+2-a=0”．（1）若命题p 为真命题，求实数a 的取值范围；（2）若命题“p∨q”为真命题，命题“p∧q”为假命题，求实数a 的取值范围．【正确答案】：【解析】：（1）由于命题p ：“∀x∈[1，2]，x 2-a≥0”，令f （x ）=x 2-a ，只要x∈[1，2]时，f （x ）min ≥0即可；（2）由（1）可知，当命题p 为真命题时，a≤1，命题q 为真命题时，△=4a 2-4（2-a ）≥0，解得a 的取值范围．由于命题“p∨q”为真命题，命题“p∧q”为假命题，可知：命题p 与命题q 必然一真一假，解出即可．【解答】：解：（1）∵命题p ：“∀x∈[1，2]，x 2-a≥0”，令f （x ）=x 2-a ， 根据题意，只要x∈[1，2]时，f （x ）min ≥0即可， 也就是1-a≥0，解得a≤1， ∴实数a 的取值范围是（-∞，1]；（2）由（1）可知，当命题p 为真命题时，a≤1，命题q 为真命题时，△=4a 2-4（2-a ）≥0，解得a≤-2或a≥1． ∵命题“p∨q”为真命题，命题“p∧q”为假命题， ∴命题p 与命题q 必然一真一假，当命题p 为真，命题q 为假时， {a ≤1−2＜a ＜1⇒−2＜a ＜1 ，当命题p 为假，命题q 为真时， {a ＞1a ≤−2或a ≥1⇒a ＞1 ，综上：a ＞1或-2＜a ＜1．【点评】：本题考查了简易逻辑的有关知识、函数的性质、方程的解、不等式组等基础知识与基本技能方法，考查了分类讨论的思想方法，考查了推理能力和计算能力，属于中档题．17.（问答题，0分）已知函数f（x）=x|x-a|+2x．（1）当a=3时，方程f（x）=m的解的个数；（2）对任意x∈[1，2]时，函数f（x）的图象恒在函数g（x）=2x+1图象的下方，求a的取值范围；（3）f（x）在（-4，2）上单调递增，求a的范围．【正确答案】：【解析】：（1）当a=3时，f(x)={x2−x，x≥35x−x2，x＜3，分类讨论可得不同情况下方程f（x）=m的解的个数；（2）对任意x∈[1，2]时，函数f（x）的图象恒在函数g（x）=2x+1图象的下方，即x|x-a|＜1在x∈[1，2]上恒成立，解得a的取值范围；（3）f（x）在（-4，2）上单调递增，结合二次函数的图象和性质分段讨论满足条件的a值，可得答案．【解答】：解：（1）当a=3时，f(x)={x2−x，x≥35x−x2，x＜3，当m=6或254时，方程有两个解；当m＜6或m＞254时，方程一个解；当6＜m＜254时，方程有三个解．--------------------------------------------------------------（3分）（2）由题意知f（x）＜g（x）恒成立，即x|x-a|＜1在x∈[1，2]上恒成立，即|x−a|＜1x在x∈[1，2]上恒成立，即x−1x ＜a＜x+1x在x∈[1，2]上恒成立，∴ 32＜a＜2 -----------------------------------------（9分）（3）f(x)={x2+(2−a)x，x≥a −x2+(a+2)x，x＜a① a−22≤a且a+22≥a，即-2≤a≤2时，f（x）在R单调递增，满足题意；② a−22＞a且a+22≥a，即a＜-2时，f（x）在（-∞，a）和（a−22，+∞）单调递增，∵f（x）在（-4，2）上单调递增，∴a≥2或-4，∴a≤-6；③ a−22＞a且a+22＜a，即a＜-2且a＞2时，不存在满足条件的a值；④ a−22＜a且a+22＜a，即a＞2时，f（x）在（-∞，a+22）和（a，+∞）上单调递增，∵f（x）在（-4，2）上单调递增，∴ a+22≥2或a≤-4，∴a＞2综上：a≤-6或a≥-2-----------------------------------------------------（16分）【点评】：本题考查的知识点是分段函数的应用，分类讨论思想，二次函数的图象和性质，难度中档．18.（问答题，0分）一家公司计划生产某种小型产品的月固定成本为1万元，每生产1万件需要再投入2万元，设该公司一个月内生产该小型产品x万件并全部销售完，每万件的销售收入为4-x万元，且每万件国家给予补助2e- 2elnxx - 1x万元．（e为自然对数的底数，e是一个常数）（Ⅰ）写出月利润f（x）（万元）关于月产量x（万件）的函数解析式（Ⅱ）当月产量在[1，2e]万件时，求该公司在生产这种小型产品中所获得的月利润最大值（万元）及此时的月生成量值（万件）．（注：月利润=月销售收入+月国家补助-月总成本）【正确答案】：【解析】：（Ⅰ）由月利润=月销售收入+月国家补助-月总成本，即可列出函数关系式；（2）利用导数判断函数的单调性，进而求出函数的最大值．【解答】：解：（Ⅰ）由于：月利润=月销售收入+月国家补助-月总成本，可得 f (x )=x (4−x +2e −2elnxx −1x −2)−1=−x 2+2(e +1)x −2elnx −2(x ＞0)（Ⅱ）f （x ）=-x 2+2（e+1）x-2elnx-2的定义域为[1，2e]， 且 f′(x )=−2x +2(e +1)−2e x =−2(x−1)(x−e )x(x ＞0) 列表如下：且f （e ）=e 2-2．即：月生产量在[1，2e]万件时，该公司在生产这种小型产品中所获得的月利润最大值为f （e ）=e 2-2，此时的月生产量值为e （万件）．【点评】：本题主要考查利用导数研究函数的单调性、求函数的最值等知识，考查学生利用导数解决实际问题的能力及运算求解能力，属于难题．19.（问答题，0分）（1）用分析法证明：当x≥0，y≥0时， √2y ≥ √x +2y - √x ； （2）证明：对任意x∈R ，3|x-1|-x+1，x 2+x ，-2x-1这3个值至少有一个不小于0．【正确答案】：【解析】：（1）利用分析法的证明方法，推出使命题成立的充分条件 √2xy ≥0 ，即可． （2）利用反证法，假设3|x-1|-x+1，x 2+x ，-2x-1这个3值都小于0，推出3|x-1|+x 2-2x ＜0，得到矛盾的结论，即可证明命题成立．【解答】：解：（1）要证不等式成立，只需证 √x +√2y ≥√x +2y 成立， 即证： (√x +√2y)2≥(√x +2y)2成立， 即证： x +2y +2√2xy ≥x +2y 成立， 即证： √2xy ≥0 成立，因为x≥0，y≥0，所以 √2xy ≥0 ，所以原不等式成立． （2）假设3|x-1|-x+1，x 2+x ，-2x-1这3个值都小于0，即3|x-1|-x+1＜0，x2+x＜0，-2x-1＜0，则3|x-1|+x2-2x＜0，（*）而3|x-1|+x2-2x=3|x-1|+（x-1）2-1≥1+（x-1）2-1≥（x-1）2≥0．这与（*）矛盾，所以假设不成立，即原命题成立．【点评】：本题考查分析法以及反证法的综合应用，考查分析问题解决问题的能力，是中档题．20.（问答题，0分）已知函数f（x）=x2+ax+a+1，g（x）=lnx，（a∈R）．（1）当a=1时，求函数y=f（x）-g（x）的单调区间；（2）若存在与函数f（x），g（x）的图象都相切的直线，求实数a的取值范围．【正确答案】：【解析】：（1）求得函数h（x）的定义域，以及求导数，讨论单调区间，可得．（2）设函数f（x）上点（x1，f（x1））与函数g（x）上点（x2，f（x2））处切线相同，分别求的切线的斜率，可得设14x2−a2x+lnx−a+a24−2 =0，设F（x）= 14x2−a2x+lnx−a+a24−2，求出导数和单调区间，最值，运用单调性，计算可得a的范围．【解答】：解：（1）因为函数f（x）=x2+ax+a+1，g（x）=lnx，所以a=1时，函数h（x）=f（x）-g（x）=x2+x-lnx+2，定义域为（0，+∞），则h′（x）=2x+1- 1x = (2x−1)(x+1)x，x∈（0，+∞），由h′（x）＜0，即(2x−1)(x+1)x ＜0，解得0＜x＜12，由h′（x）＞0，即(2x−1)(x+1)x ＞0，解得x＞12，所以函数h（x）的增区间为（12，+∞），减区间为（0，12），综上所述，结论时：函数y=f（x）-g（x）的增区间为（12，+∞），减区间为（0，12），（2）假设存在函数f（x），g（x）的图象都相切的直线，设函数f（x）上点（x1，f（x1））与函数g（x）上点（x2，f（x2））处切线相同，由已知有：f′（x）=2x+a，g′（x）= 1x，则f′（x1）=g′（x2）= f(x1)−g(x2)x1−x2，即2x1+a= 1x2 = x12+ax1+a+1−lnx2x1−x2，所以x1= 12x2−a2代入1x2=x12+ax1+a+1−lnx2x1−x2，得：1 4x2−a2x2+lnx2−a+a24−2=0，设F（x）= 14x2−a2x+lnx−a+a24−2，则F′（x）=- 12x3+a2x2+1x= 2x2+ax−12x3，x∈（0，+∞），则方程2x2+ax-1=0有一个正根，记为x0（x0＞0），则2x02+ax0-1=0，即a= 1−2x02x0 = 1x0−2x0，当0＜x＜x0时，F′（x）＜0；当x＞x0时，F′（x）＞0，所以F（x）在区间（0，x0）上单调递减，在区间（x0，+∞）上单调递增，故当x=x0时，函数F（x）min=F（x0）=x02+2x0- 1x0+lnx0-2，设G（x）=x2+2x- 1x+lnx-2，则G′（x）=2x+2+ 1x2 + 1x＞0，在区间（0，+∞）上恒成立，所以G（x）在区间（0，+∞）上时增函数又G（1）=0，所以0＜x≤1时，G（x）≤0，即当0＜x1≤1时，F（x1）≤0，又当x=e a+2时，F（e a+2）= 14e2a+4 - a2e a+2+lne a+2-a+ a24−2 = 14（1e a+2−a）2≥0，所以当0＜x1≤1时，函数F（x）必有零点，即当0＜x1≤1时，必存在x2使得① 成立，即存在x1，x2，使得函数f（x）在点（x1，f（x1））与函数g（x）在点（x2，f（x2））处切线相同，又由y= 1x −2x，得y′=- 1x2−2＜0，所以y= 1x−2x在（0，1]上单调递减，故a= 1x0−2x0∈[-1，+∞），综上所述，结论是：实数a的取值范围为[-1，+∞）．【点评】：本题考查切线的斜率，及导数的综合应用，属于难题．。
江苏省扬州中学2017-2018学年高一英语10月月考试题
江苏省扬州中学2017-2018学年高一英语10月月考试题(考试用时：120分钟满分：120分)第I卷（共 80 分）第一部分听力（共20小题；每小题1分，满分20分）第一节听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
How much does the shirt cost?A. ￡19.15B. ￡9.15C. ￡9.50答案是B。
1. How does the man plan to find a used car?A. Through a car dealer.B. On the Internet.C. From the newspaper.2. Where is the man going?A. To a supermarket.B. To the woman’s.C. To a park.3. What are the speakers mainly talking about?A. A book.B. A writer.C. A bookstore.4. What season is it now?A. Spring.B. Autumn.C. Winter.5. What present has the man bought?A. A book.B. Some flowers.C. A pair of gloves. 第二节听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6. What are the speakers doing?A. Interviewing a champion.B. Reporting a match live.C. Talking about a new world record.7. What do we know about Paul Timmons?A. He breaks a world record.B. He is talented in competing.C. He isn’t in the lead all the time.听第7段材料，回答第8、9题。
江苏省扬州中学20210-2021学年高一下学期5月月考试题 英语
江苏省扬州中学2020-2021学年度第二学期5月阶段测试高一英语2021.05（试卷满分：150分，考试时间：120分钟）注意事项：1. 作答前，请考生务必将自己的姓名、考试证号等写在答题卡上并贴上条形码。
2. 将选择题答案填写在答题卡的指定位置上，非选择题一律在答题卡上作答，在试卷上答题无效。
3. 考试结束后，请将答题卡交监考人员。
第一部分听力（共两节，满分30分）第一节(共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话读一遍。
1. What does the man suggest the woman do?A. Ask for help.B. Buy a new toy.C. Follow the instructions.2. What is the woman going to do tonight?A. To go to a dance party.B. To practise the lines of the play.C. To perform in the drama contest.3. What are the speakers doing?A. Lining up to buy something.B. Complaining to the store owner.C. Waiting to be served in a restaurant.4. What do we know about the woman?A. She is making a joke.B. She is telling a lie.C. She is getting angry.5. When can the man leave his room at the latest?A. 12:00 pm.B. 5:30 pm.C. 2:00 pm.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
江苏省扬州中学2017-2018学年高一上学期期中考试英语试题
江苏省扬州中学2017-2018学年高一上学期期中考试英语试题第Ⅰ卷(选择题共85分)第一部分：听力(共两节,满分20 分)第一节(共5 小题;每小题1分, 满分5分)1. Why does the man like his new room?A. It is near the friends’ flats.B. It is close to the school.C. It is larger than the old one.2. How much will the man pay for two general tickets and two student tickets?A. $30.B. $40.C. $20.3. What do we learn about Jack?A. He worked there as a boss.B. He spoke to the boss.C. He gave orders like a boss.4. What does the woman suggest?A. The radio batteries have been replaced.B. They should get a new radio.C. They don’t really need to hear the radio.5. What do we learn about the woman?A. She should plan for a good dictionary.B. She can’t afford any dictionary.C. She has a better dictionary.第二节(共15 小题;每小题1分, 满分15 分)听第6段材料，回答第6至8题。
6. What kind of color TV was the man going to buy?A. A small one.B. A big one.C. A cheap one.7. What kind of color TV set does the woman suggest the man should buy?A. A cheap one.B. A small one.C. A big one.8. Why does the woman give the man such a suggestion?A. It would be a waste of money.B. He might h ave to change it in a few years’ time.C. His sitting room is not very big.听第7段材料，回答第9至11题。
【高一英语试题精选】江苏省扬州中学2018—2018学年度第二学期期中考试高一英语试卷及答案
江苏省扬州中学2018—2018学年度第二学期期中考试高一英语试卷及答案江苏省扬州中学--Go for a piic this weekend, OK?--- ________ I love getting close to natureA I couldn’t agree more BI afraid notC I believe notD I don’t think so23 --- What do you think of teaching, Bob？--- I find it fun and challenging It is a job ______ you are doing something seriousbut interestingA whereB whichC whenD that24 --- _______Mary e and play puter games?--- No, _______she has finished her homeworkA Will, whenB Shall, onceC Would, ifD Shall, unless25 I would have gone to visit him in the hospital if it had been at all possible, but I ________ fully occupied the whole of last weekA wereB had beenC have beenD was26 ________ I like most about her is ________ care-free attitudeA What; herB What; that herC How; for herD How; a27 --- Do you regret paying 500 dollars for your necklace?--- No, I would gladly pay _________ for itA two times as muchB twice as manyC twice as muchD as twice as much28 --- Hoas Robert’s co oking?--- Oh, pretty good I was quiteA admiredB interestedC impressedD inspired29 As senior 3 students, it is the most important to ___a。
江苏省扬州中学2017-2018学年高二下学期期中考试物理有答案
江苏省扬州中学2017-2018学年度第二学期期中考试高二物理试卷考试时间：120分钟试卷满分120分一、单项选择题：本题共6小题，每小题3分，共18分。
在每小题给出的四个选项中，只有一个选项符合题意。
1．在以下家用电器中使用温度传感器的是（）A．空调机 B．家电遥控器 C．消毒柜 D．自动门2．变压器副线圈两端电压为零时，原线圈两端的电压随时间的变化可能为（）A. B. C. D.3．如图表示一交流电的变化的图像，此交流电的有效值为( )A. B. C. D.4．如图所示，三只完全相同的灯泡a、b、c分别与盒子Ⅰ、Ⅱ、Ⅲ中的三种元件串联，再将三者并联，接在正弦交变电路中，三只灯泡亮度相同．若保持电路两端电压有效值不变，将交变电流的频率增大，观察到灯a变暗、灯b变亮、灯c亮度不变．则三个盒子中的元件可能是（）A. Ⅰ为电阻，Ⅱ为电容器，Ⅲ为电感器B. Ⅰ为电感器，Ⅱ为电阻，Ⅲ为电容器C. Ⅰ为电感器，Ⅱ为电容器，Ⅲ为电阻D. Ⅰ为电容器，Ⅱ为电感器，Ⅲ为电阻5．自行车的尾灯采用了全反射棱镜的原理，它虽然本身不发光，但在夜间骑行时，从后面开来的汽车发出的强光照到尾灯后，会有较强的光被反射回去，使汽车司机注意到前面有自行车．尾灯的构造如图所示。
下面说法正确的是（）A．汽车灯光应从左面射过来，在尾灯的左表面发生全反射B．汽车灯光应从左面射过来，在尾灯的右表面发生全反射C．汽车灯光应从右面射过来，在尾灯的左表面发生全反射D．汽车灯光应从右面射过来，在尾灯的右表面发生全反射6．远距离输电中，当输送的电功率为P，输送电压为U时，输电线上损失的电功率为△P，若输送的电功率增加为2P，而输电线中损失的电功率减为△P/4,（输电线电阻不变）那么输电电压应增为（）A. 32UB. 16UC. 8UD. 4U二、多项选择题（本小题共6小题，每小题4分，共24分。
每小题四个选项中至少有两个选项符合题意，全部选对得4分，漏选的得2分，错选的得0分）7.下列关于传感器说法中正确的是（）A. 话筒是一种常用的声传感器，其作用是将电信号转换为声信号B. 电子秤所使用的测力装置是力传感器，它是把力信号转化为电压信号C. 电熨斗能自动控制温度的原因是它装有双金属片，这种双金属片的作用是控制电路的通断D. 光敏电阻能够把光照强弱这个光学量转换为电阻这个电学量8.如图为某质点做简谐运动的图象，则由图线可知（）A. t=2.5s时，质点的速度与加速度同向B. t=1.5s时，质点的速度与t=0.5s时速度等大反向C. t=3.5s时，质点正处在动能向势能转化的过程之中D. t=0.1s 和t=2.1s 时质点受到相同的回复力9.一列简谐横波沿x 轴传播，图甲为在1t s =时刻的波形图象，P 、Q 为介质中2x m =和3x m =处的两质点，图乙为某质点的振动图象，由图象可知，下列说法中正确的是（ ）A. 该简谐横波一定沿x 轴正向传播，速度大小为lm/sB. 图乙不可能是质点P 的振动图象C. 2t s =时刻，质点P 的速度一定最大，且一定沿y 轴负方向D. 3t s =时刻，质点Q 的速度一定最大，且一定沿y 轴负方向10.如图1所示，在匀强磁场中，一矩形金属线圈绕与磁感线垂直的轴匀速转动。
精品解析：江苏省扬州市广陵区扬州中学2023-2024学年高一下学期5月月考英语试题(原卷版)
2023-2024 学年度第二学期阶段练习高一英语（本试卷满分150 分，考试时间120 分钟）第一部分听力（共两节，每小题1.5 分，满分30 分）第一节(共5小题;每小题1.5分，满分7.5分)听下面5段对话。
每段对话后有一个小题，从题中所给的A 、B 、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Who keeps the pen now?A. Louise.B. Julie.C. Mark.2. When do the speakers usually play tennis?A. On Monday.B. On TuesdayC. On Friday.3. How does the woman probably feel?A. Frightened.B. Relaxed.C. Amused.4. What does the woman suggest the man do?A. Order a taxi.B. Take a different train.C. Reschedule the interview.5. How many times did the woman call the man?A. Five.B. Four.C. Three.第二节(共15小题;每小题1.5分，满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A 、B 、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟;听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话，回答以下小题。
6. What is the main idea of the conversation?A. Recalling a meeting.B. Discussing a show.C. Mistaking identity.7. How does the man know of the woman?A. From TV.B. From a party.C. From school.听下面一段对话，回答以下小题。
江苏省扬州市2017-2019年三年中考英语试卷分类汇编：单项选择(含解析)
单项选择2019一、单项选择（共15小题；每小题1分，计15分）1. —Look at _____ boy over there. He looks excited.—Yeah, he has won _____ first prize in the school English Reading & Writing Competition.A. a ; theB. the; aC. the ; theD. a ; a答案：C解析：第一空，在那边的那个男孩，特指，用the；第二空，序数词前用the。
2. —Annie, _____ books are all over the place.—Sorry, mum. I’ll put them away.A. youB. yourC. yoursD. yourself答案：B解析：根据句意是“你的书”，用形容词性物主代词your。
3. The 2021 International Horticultural Expo _____ in Yangzhou.A. holdsB. will holdC. is heldD. will be held答案：D解析：根据句意“2021年国际园艺博览会在扬州举办”，2021年还未到，用一般将来时，国际园艺博览是被举办，用被动语态。
4. —I’m not sure what to write about The Secret Garden in the report.—You should read some _____ about the book before writing.A. reviewsB. reasonsC. resultsD. rewards答案：A解析：根据句意“你应该在写之前读一些评论”。
5. —My feelings for you have not changed.—But you have changed. You are not as you _____.A. areB. wereC. will beD. have been答案：B解析：根据句意“你不像你以前那样”，用一般过去时。
江苏省扬州中学2017-2018学年高一下学期期中生物试卷Word版含解析.pdf
）
A．是次级精母细胞，处于减数分裂第二次分裂后期 B ．含同源染色体 2 对、DNA
分子 4 个、染色单体 0 个 C ．正在进行等位基因分离、 非等位基因自由组合 D．是
次级卵母细胞，形成的每个子细胞中含有 2 条染色体，仅 1 个具有生殖功能
16．下列说法正确的是（
）
A．生物的性状和性别都是由性染色体上的基因控制的 B ．人类色盲基因 b 位于
18．在香水玫瑰的花色遗传中，红花、白花为一对相对性状，受一对等位基因的
控制（用 R、r 表示）．从下面的杂交实验中可以得出的正确结论是（
）
杂交组合
后代性状
一 红花 A×白花 B
全为红花
二 红花 C×红花 D
红花与白花之比约为 3：1
A．红花为显性性状 B ．红花 A 的基因型为 Rr C．红花 C 与红花 D 的基因型不同
胞分裂和细ቤተ መጻሕፍቲ ባይዱ分化
9．精子形成过程中出现联会现象时， 细胞中核 DNA分子数与染色体之比是 （ ）
A．1：1 B ． 1： 2 C． 2： 1 D．4：1
10．同源染色体指（
）
A．一条染色体复制形成的两条染色体 B ．分别来自父亲和母亲的两条染色体
C．形态特征大体相同的两条染色体 D．减数分裂过程中联会的两条染色体
27．根据基因的自由组合定律，在正常情况下，基因型为 YyRr 的豌豆不能产生
的配子是（
）
A．YR B．Yr C ．yR D．YY
28．基因型为 YyRr 的个体与基因型为 YYRr的个体杂交，按自由组合定律遗传，
子代的基因型有（
）
A．6 种 B ．4 种 C．2 种 D ．8 种
29．孟德尔用纯种黄色圆粒豌豆和纯种绿色皱粒豌豆进行杂交实验，产生的
江苏省扬州中学2018-2019学年高一下学期期中考试英语试题(含答案)
江苏省扬州中学2018-2019学年第二学期期中试卷高一英语试题2019.04 本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分150分，考试时间120分钟。
第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Which place does the woman want to visit?A. A bank.B. Wall Street.C. A shopping mall.2. What’s the weather like now?A. Cloudy.B. Sunny.C. Windy.3. According to the woman, what does the man need urgently now?A. A good rest in hospital.B. Relaxing travel by air.C. Further medical treatment.4. What is the probable relationship between the speakers?A. Lifeguard and swimmer.B. Brother and sister.C. Friends.5. How will the man pay probably?A. With a card.B. By check.C. In cash.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；1听完后，各小题将给出5秒钟的作答时间。
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2017-2018学年江苏省扬州中学高一下学期期中考试英语本试卷分六部分。
满分120分。
考试时间120分钟。
第I卷(三部分共85分)第一部分：听力 (共两节，满分20分)第一节（共5小题；每小题1分，满分5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Where are the two speakers?A. On a busy street.B. In a Beijing Hotel.C. At a station.2. How does the man like the book?A. Humorous.B. Scientific.C. Popular.3. Why is Peter leaving?A. To visit his parents.B. To attend college.C. To have a holiday.4. What time is it now?A. Seven o’clock.B. Seven-thirty.C. Eight o’clock.5. How much does the man need to pay?A. 35 dollars.B. 115 dollars.C. 150 dollars.第二节（共15小题；每小题1分，满分15分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话，回答第6和第7两个小题。
6. Where are the speakers?A. At a meeting.B. At a party.C. At a wedding.7. What does the man say about Anne?A. She is humorous.B. She is very intelligent.C. She is easy to get to know.听下面一段对话，回答第8和第9两个小题。
8. Why did Mr. Miller get up late?A. He watched a football match live last night.B. He watched a football match on TV late last night.C. He couldn’t fall asleep after watching a football match.9. What happened to Mr. Miller on his way to work?A. He had a car accident.B. He was stopped by the police.C. He was stuck in a traffic jam.听下面一段对话,回答第10至第12三个小题。
10. Where does the man want to go?A. To New York.B. To New Jersey.C. To Hawaii.11. When will the man leave?A. In the morning.B. In the afternoon.C. In the evening.12. How much does one ticket cost?A. $310.B. $325.C. $620.听下面一段对话，回答第13至第16四个小题。
13. How many customers have just come to the restaurant?A. Three.B. Four.C. Five.14. Where will they sit eating?A. In the center.B. Near the window.C. In the back.15. Which style of Chinese food is not served in this restaurant?A. Hunan food.B. Sichuan food.C. Guangdong food.16. What food will the customers eat?A. Hunan food.B. Zhejiang food.C. Sichuan food.听下面一段对话，回答第17至第20四个小题。
17. What is the woman’s major?A. Painting.B. English.C. Japanese.18. When did the woman last see Lily?A. Three days ago.B. One week ago.C. Three years ago.19. What is Lily’s problem?A. She lacks chances to speak Chinese.B. She finds it difficult to write Chinese words.C. She doesn’t know how to remember Chinese words.20. Where does the woman plan to further her study?A. In China.B. In Italy.C. In England.第二部分：英语知识运用（共两节，满分35分）第一节：单项填空（共 15 小题；每小题 1 分，满分 15 分）21.I will be on an exchange program this summer, _______ I’ve desired for a long time.A. oneB. the oneC. thatD. when22. The film Wolf Warrior II ______ a rescue operation in Africa, led by a former Special Forces soldier Leng Feng.A. focuses onB. insist onC. comments onD. relies on23. Hannah Taylor began to host the “Big Bosses Lunches” program, ______ she would try to persuade local business leaders to contribute to the cause.A. whenB. whereC. thatD. which24. The discovery of new evidence led to ________.A. the thief having caughtB. catch the thiefC. the thief being caughtD. the thief to be caught25. The manager has decided to put ________ he thinks is energetic and cleverin the position of the leadership of the company.A.whoeverB. anyoneC. whomeverD. those26.After he graduated from college, he _______ his father’s business.A.took inB. took upC. took overD. took on27.Imagination is more important than knowledge, for knowledge is limited,imagination is about all there ever will be to know and understand.A. orB. whileC. thoughD. so28. You can try the convenience store, but it _______ well be closed. It’s too late now.A. canB. mayC. mustD. should29. I once had a chance to experience what romance was but somehow away _______.A.it goesB. went itC. did it goD. it went30. As a result of the serious flood, twothirds of the buildings in the area_____.A. need repairingB. needs to repairC. needs repairingD. need to repair31. No man knows what potential he has till he very hard to be good.A. triedB. will tryC. is tryingD. has tried32. Anyone who has spent some time with children must become ______ of the difference in the way boys and girls react to similar situations.A. innocentB. interestedC. awareD. concerned33. The Chinese football fans don't know when, , their beloved national team will make it to the World Cup finals.A. if soB. if anyC. if everD. if not34. in his novel, he ran into the car in front of the building.A. CoveredB. BuriedC. AppliedD. Busy35. —Dad, look, I can ride the bike!—! I knew you'd get the hang of it eventually!A. You name itB. You are asking for itC. It’s up to youD. There you go第二节完形填空 (共20小题，每小题1分，满分20分)I made up my mind to drive to South Carolina to meet my friends in my used car. Though I had been there once 36 and did not know the way very well, I was on the 37 after I had made some inquiries.At Ashvelle, there was a crossroad. I could go on along the main road or I could take a short cut. The short cut was to 38 several hills and was dangerous. I hesitated for a 39 while and then chose the main road, for I wanted to be __40__.Something happened after I drove a long way and found it was not the correct road that I wanted to __41___ but the hilly road I decided to avoid. I realized that it was at the __42___ that I had made the __43___ mistake. “What shall I do?”I asked myself. If I went back to take that road again, it would be very late__44___ the time I got to Columbia. Thinking it _45__, I decided to go on. “If __46___ people can go along this road, why can’t I?”I __47___ myself.The short cut, to my surprise, was not that __48___; in fact, it was only a very peaceful country road, __49___ up and down two low hills. There was __50___ traffic. On both sides of the road, you could see trees, wild flowers, and __51___ with cows and horses. My fear was__52___ with the wind. Listening to the beautiful country music over my car stereo(立体声), I drove on and _53___ the scenery which was so quiet and so natural. Even my used car forgot to give me __54___. It was just in this lightheartedness that I arrived at my destination. My friends,after they heard what had happened to me, __55___ said it sounded like an adventure.36. A. before B. ago C. already D. still37. A. train B. car C. highway D. way38. A. have B. go C. ride D. cross39. A. few B. little C. long D. lot40. A. safe B. dangerous C. fast D. slow41. A. go B. leave C. take D. drive42. A. crossroad B. comer C. station D. beginning43. A. direction B. road C. disappointed D. interesting44. A. to B. from C. at D. by45. A. about B. over C. of D. up46. A. another B. the other C. other D. other47. A. asked B. forced C. encouraged D. told48. A. far B. safe C. dangerous D. dirty49. A. going B. coming C. driving D. walking50. A. heavy B. little C. few D. light51. A. farms B. trucks C. houses D. villages52. A. together B. gone C. cover D. coming53. A. looked B. liked C. enjoyed D. found54. A. happy B. scenery C. joys D. problems55. A. all B. they C. which D. who第三部分：阅读理解（共15小题；每小题2分，满分30分）AHave you noticed that every time you have an exam at your doctor, your prescription glasses （验配眼镜）always get higher and higher? You then get a new pair of glasses, and you move on with your life. And then comes your next exam the next year, and your prescription goes higher again. When will it stop? Will you be living your life with vision that gets poorer and poorer?There are many other choices for you, such as eye surgeries and laser therapies（激光治疗）, but do you really want to go through with these dangerous and expensive operation? Are the risks worth it? For many, it’s not.Introducing an amazing breakthrough in eye care and considered to be the very solution to eyesight improvement—Quantum Vision System.What is this amazing Breakthrough?The System promises to recover your vision at the speed oflight, or more exactly in at least 7 days. It is an e-book that can bedownloaded onto any electronic equipment such as a personalcomputer or a smartphone, so you get access to the guide fromanywhere and at any time you wish.The e-book is created by Dr. William Kemp, who completelytransformed his clinic and practice when he discovered this scientific breakthrough.Inside the e-book are several step-by-step instructions, guides, and videos, explaining the very causes of poor eyesight and what you can do to recover yourself. The program uses 100% all-natural methods to help you achieve a perfect 20/20 vision in a matter of days.The program costs only $37, which you can buy online from their official website. Once you pay for the program, you get instant access to all the information you need to move from one prescription point to another in just 10 minutes, and achieve 20/20 vision in just 7 days.The program comes with a 60-day 100% money back guarantee so if you don’t see any results or if you think it doesn’t work, you get your full money back without question.56. Quantum Vision System is intended for those who ______.A. have eyesight problemsB. receive eye surgeriesC. suffer from mental disorderD. suffer from blindness57. The system can be purchased ______.A. at the clinicB. on the App storeC. on the websiteD. on the phone58. The passage is meant to ______.A. recommend a doctor who transformed his clinic and practiceB. advocate an eye operation that helps people regain their eye visionC. introduce a scientific discovery which will greatly improve people’s livesD. advertise an e-book which can recover your vision naturally in a short timeBIt all started in 2013, when Shea Stollenwerk, then eight years old, asked for a new hand for Christmas. Shea was born with a partial right hand, which restricts her ability to do things that other kids take for granted.“My mom went online”, says Shea, who lives in Muknowango, Wisconsin. Shea’s mother, Ranee, soon learned about a community of artists, designers, and scientists who are making big breakthroughs with artificial hands.Frankie Flood, a professor at the University of Wisconsin in Milwaukee, was among the designers who saw Ranee’s online request. Flood obtained help from fellow professor Adeam Blair and their students, who were learning how to make designs using a 3-D printer. “We made a mold(模子) of Shea’s hand out of plaster(石膏), and then we 3-D scanned her hand,” Flood says.While being fitted in Flood’s laboratory, Shea got to choose the color of her new hand. She went with bright pink. She now has a pink hand, a purple hand, and a purple and pink one, and can do things that she couldn’t do before, like peeling potatoes, picking up objects, and catching a ball.Flood and his team have since built hands for six other local children. Indirectly, they have helped dozens more by posting their designs online so that people around the world can print them out. Flood is also working on artificial legs for military soldiers who were injured on the battlefield. “Without a covering, the artificial leg is kind of ugly and plain,” Flood says. “Soldiers wa nt something that will restore the shape of their legs and make them look cooler when they’re playing sports.”As for Shea, the aspiring musician can now play her violin with the help from an adaptive device that Flood’s team created. “Nothing is ever going to hold her back,” Shea’s father, Steve, told a local reporter.59.What do we know about Shea from Paragraph 1?A. Her left hand is weak.B. She is eager for many gifts.C. She was born with a disability.D. She comes from a poor family.60.What can Shea do with the help of her new hand?A. She can do simple things easily.B. She can play different kinds of sports.C. She can build hands for other children.D. She can make designs using a 3-D printer.61.What can we infer from the passage?A. Flood made S hea’s new hand alone.B. Shea has hands of different colors now.C. Soldiers like artificial legs though they are ugly.D. Ranee made big breakthroughs with artificial hands.62.What do Steve’s words suggest in the last paragraph?A. Shea is a determined girl.B. Shea has an advanced device.C. Shea is a famous musician now.D. Shea gets much help from her family.CPeer PressurePeople who are at your age, like your classmates, are called peers. When they influence you on your decision or action, it’s called peer pressure. All of us, at some point in our lives, have had to deal with peer pressure. The need to follow the crowd and do what majority of us are doing forces us to take up activities which we wouldn’t otherwise.Recent studies have shown that peer pressure might cause an upside to you. It can make you reflect on your actions and make changes to your ways to become a better one. Observing others working hard to reach their goals will definitely encourage you to make a great effort to achieve something positive. When a teen knows that his teammates are practicing hard to become better players then it will directly affect his own performance. He will put in twice the time and energy to raise the level of his game and ensure he has a place on the team.Having a group that brings positive peer pressure can also help you pick up healthy habits that can shape both your personality and your future. The motivation to do well because of pressure from your peers can actually become inspiration. For example, when a child knows that some of his friends regularly read storybooks, he may get into the habit of reading. Seeing that his friends exercise daily, even he may take up the habit and adopt it in life.Just as some influences can be positive, some can be negative too. Peer pressure sometimes can make a dip in your self-confidence. Some kids give in to peer pressure because they want to be liked, or because they worry that others might make fun of them if they don’t go along with the group. Othe rs go along because they are curious to try something new. The idea that “everyone’s doing it” can influence them to leave their better judgment behind. Besides, peer pressure can distance you from your family and friends. It is common for teenagers to think that nobodyunderstands them and that the whole world is against them. The influence of peer pressure is such that it draws them completely away from their family and friends who mean well. They just shut themselves off and fall into bad company.It’s likely that you’ve experienced the effect of peer pressure in different areas, ranging from the clothes you wear to the music you listen to. Sometimes it can be hard to resist and you may feel forced to do something you’re uncomfortable with. So being a ware of and carefully choosing the influence of peers that will lead to healthy and happy experiences is a lifelong process.63. What does the underlined part in Paragraph 2 probably mean?A. A quick reaction.B. A positive effect.C. A serious challenge.D. A potential conflict.64. According to the author, peer pressure can get teenagers to ______.A. become less self-confidentB. provide a model for teammatesC. identify characteristics of different habitsD. improve relationship with family members65. What does the author think of peer pressure?A. It makes no difference to teens’ judgment.B. It influences teens to fit into various lifestyles.C. It helps teens to relieve the uncomfortable feeling.D. It seems like a common phenomenon among teens.66. Which of the following shows the structure of the passage?A. B. C. D.I: Introduction P: Point Sp: Sub-point (次要点) C: ConclusionDI tried not to be biased, but I had my doubts about hiring Stevie. His social worker assured me that he would be a good, reliable busboy. But I had never had a mentally handicapped employee. He was short, a little fat, with the smooth facial features and thick-ton gued speech of Down’s Syndrome （唐氏综合症）. I thought most of my customers would be uncomfortable around Stevie, so I closely watched him for the first few weeks.I shouldn’t have worried. After the first week, Stevie had my sta ff wrapped around his stubby little finger, and within a month my regular trucker customers had adopted him as their official truck stop mascot. After that, I really didn't care what the rest of the customers thought of him. He was like a 21-year-old in blue jeans and Nikes, eager to laugh and eager to please, but fierce in his attention to his duties. Every salt and pepper shaker was exactly in its place, not a bread crumb or coffee spill was visible when Stevie got done with the table. Our only problem was persuading him to wait to clean a table until after the customers were finished.Over time, we learned that he lived with his mother, a widow who was disabled. Money wastight, and what I paid him was probably the difference between them being able to live together and Stevie being sent to a group home.That’s why the restaurant was a gloomy place that morning last August, the first morning in three years that Stevie missed work. He was at the Mayo Clinic in Rochester getting a heart surgery. His social worker said that people with Downs Syndrome often had heart problems at an early age and there was a good chance he would come through the surgery in good shape and be back at work in a few months.A ripple of excitement ran through the staff later that morning when word came that he was out of surgery, in recovery, and doing fine. Frannie, my head waitress, did a little dance when she heard the good news. Belle Ringer, one of our regular trucker customers, stared at her and asked, “Okay, Frannie, what was t hat all about?”"We just got word that Stevie is out of surgery and going to be okay.""I was wondering where he was. I had a new joke to tell him. What was the surgery about?"Frannie quickly told Belle Ringer and the other two drivers sitting at his booth about Stevie's surgery, then sighed: "Yeah, I'm glad he is going to be OK," she said. "But I don't know how he and his Mom are going to handle all the bills. From what I hear, they're barely getting by as it is."Belle Ringer nodded thoughtfully, and Frannie hurried off to wait on the rest of her tables.After the morning rush, Frannie walked into my office. She had a couple of paper napkins in her hand."What's up?" I asked.“I cleared off that table where Belle Ringer and his friends were sitting after they left, and I found this. This was folded and tucked under a coffee cup."She handed the napkin to me, and three $20 bills fell onto my desk when I opened it. On the outside, in big, bold letters, was printed "Something For Stevie".After three months, when Stevie was supposed to be back to work, there was already $10,000 in cash and checks collected, all from truckers and trucking companies that heard about his problems.So once again we could see Stevie, with a big, big smile on his face, busy clearing all the cups and dishes from the table in my restaurant.67. Why did the author have doubts about hiring Stevie?A. Because Stevie was not that reliable.B. Because Stevie was mentally disabledC. Because Stevie was too short and fat.D. Because Stevie was bad-tempered68. By saying the underlined sentence in Para 3, the author meant that the money she paid Stevie____.A. could help Stevie out of the troubleB. couldn’t thoroughly solve Stevie’s problemC. could make a great difference to Stevie’s lifeD. could send Stevie to a group home69. Why did Frannie sigh after she got word that Stevie would be OK?A. She was worried that the owner would fire Stevie.B. She was worried about Stevie’s health.C. She was worried about Stevie’s finance problem.D. She was worried that no one would help Stevie.70. Stevie was popular among the staff and customers in the restaurant because of____.A. his special appearance.B. his hard work and optimism.C. his funny speeches and actions.D. his kind-hearted behaviour.第Ⅱ卷（三部分共35 分）第四部分: 任务型阅读(共10小题; 每小题1分, 满分10分)Your life is composed of all the little things we experience everyday, and knowing how to find joy in some of those little things is one of the easiest ways to let happiness slowly fill your cup. In order for that to happen, you need to do two very simple things, put yourself in such situations that you can experience happiness there, and then find a way to enjoy the experience and let it sink into you.To put yourself in the position of experiencing happiness every day, Lahan Catalino, Ph.D, at the University of California, San Francisco, recommends an approach called “prioritizing positivity”—organizing your day-to-day life on purpose so that it contains situations which naturally give rise to positive emotions. It involves both taking time off from your daily routine to do things that you really love and heavily weighing the positive emotional consequences of major life decisions, like taking a new job, and you will regularly find yourself.Then how can we find a way to enjoy the happy experience and let it sink into you? Here is what psychologist Rick Hanson, the author of Buddha’s Brain explains.Let a good fact become a good experience.Often we go through life and some good thing happens—a little thing like we checked off an item on our To-Do list, we survived another day at work, the flowers are blooming, and so forth. Hey, this is an opportunity to feel good. Don’t leave the money lying on the table: recognize that this is an opportunity to let yourself truly feel good.Really enjoy this positive experience.Practice what any school teacher knows: if you want to help people learn something, make it as serious as possible—in this case, as felt in the body as possible—for as long as possible.When sinking into this experience, sense your intention that this experience is sinking into you.Sometimes people do this through imagination, like by sensing a golden light coming into themselves. You might imagine a jewel going into the treasure chest in your heart—or just know that this experience is sinking into you, becoming a resource you can take with you no matter where you go.It might seem a little clichè(陈词滥调) to say “stop and smell the roses”, but it’s moments like those that can be stored in your happiness bank and taken out later. Living a happy life can be as simple as accepting the happiness that’s already around you. If you want more, it’s OK to go o ut and achieve it, but don’t forget where happiness really comes from.第五部分: 根据所给中文提示或者首字母，写出对应的单词，注意形式。