2020年12月4日安徽省五校(怀远颖上蒙城涡阳淮南)2021届高三毕业班联考文科数学试题及答案
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安徽省怀远、颖上、蒙城、涡、淮南一中2021届高三“五校”联考英语试题答案听力:1 ------ 5 ACACB 6 ------- 10BABCA11 ----- 15CBACC 16 ------20BABBC阅读理解:21----25 CAAAC26----30 DCABD31----35 CDBBD七选五:36 ---- 40CFBED完形填空:41---- 45 AACBC46 ---- 50 BADDB51 ---- 55 ADCAB56 ---- 60 BCDDC语法填空:61.which62. commonly63. to64. an65. handled66.more likely 67. causing68.weakness69. be prevented70. helps短文改错:1.第一句中place改为places2.第二句中here改为there3.第三句中especial改为especially4.第四句中to 与other之间加the5.第四句中take改为taking6.第五句中bit后的of删掉7.第六句中and改为but8.第六句中plan改为planned9.第七句中what改为which10.第七句中relaxed改为relaxing书面表达:Dear Peter,I am so glad to hear that you are planning to study in China. Therefore, I’m writing to tell you what you can do to have an unforgettable experience during your staying in our country.In the first place, your ability to speak Chinese is very important, which enables you to communicate with the people around you easily. In addition, you’d better have a quick adaptation to the new environment so that you can have a deeper understanding of the Chinese culture. In the meanwhile, developing proper hobbies is of great significance as well, because you will find some people who share the same interest with you, making your life more colorful.This is some of my advice, and I hope it will be helpful to you.Yours,Li Hua 听力原文:Text 1M:How was your weekend, Jane?W:Not too bad. I had planned to take a tour of the City Museum but my uncle’s house caughtfire. I spent the two days helping him clean the house.Text 2W:This blouse is a special offer today. You can have it at 10% off the regular price of 50 dollars.M:It’s nice, but still too expensive. Can you give me a 20% discount?W:No. 10% is my last word.Text 3M:Hi! Alice, did you go to the yard sale last week?W:Certainly. I meant to find a used computer for my brother, but there was no proper one. I bought a camera for my father and a smartphone for myself. Text 4W:Good afternoon, madam. How can I help you?M:Well, I am a little out of shape. I think I should get some exercise to keep fit.What kind of service do you offer?W:First of all, we’ll make a workout plan according to your physical conditions and your personal needs.Text 5W:I’m sorry you have waited so long.I forgot to tell you my meeting is over at 7:00.M:Forget it. I have just been here for ten minutes.W:Let’s go to Hanson and invite him to the party.Text 6M:Are you ready to go to the concert?W:Yes. Should we go there by bus so we aren’t late?M:Actually, why don’t we go there by bike? We could get stuck in the traffic if we travel by bus in the rush hour.W:That’s true. Cycling is good for our environment, too. Let me just get my helmet then.M:Is your helmet comfortable?W:Not really, but I liked the design, so I got it.M:Maybe you should think about getting a round helmet; it’s better.W:I’ll think about it.Text 7W:So, how’s your course going? Do you like it?M:I like my professors and the classes, but it’s a lot of work.W:What are you majoring in?M:Right now, I’m doing some research into the languages of different African tribes.W:That sounds really interesting. Can you speak Swahili?M:Yes, I learned how to speak it when I was little.W:Really? How did you do that?M:Well, I grew up in Africa, so I learned quite a few different languages.W:That’s amazing. Are you doing well in your classes?M:I don’t know because I haven’t received my test results yet.W:When did you take your exams?M:About two weeks ago.W:I’m sure you’ll do well.M:Thanks for the vote of confidence!Text 8W:Good morning. This is Doctor Ruth’s office. What can I do for you?M:Yes, I’d like to make an appointment to see the doctor. My name is Randy Horn.W:Let’s see, Mr.Horn... The doctor’s schedule is full today.M:How about tomorrow?W:Sorry, but I have to say he is also occupied on Tuesday. So, will Wednesday be OK for you, Mr.Horn?M:I have to attend a conference then.Is Dr. Ruth available on Thursday?W:Yeah, Dr.Ruth will be available the whole day.M:I guess I can survive until then.W:Would you prefer to come in the morning or the afternoon?M:In the morning, if possible.W:The doctor has an opening at 10:30 Thursday. I’ll put you down for then.M:That would be fine.W:Okay, Mr. Horn, see you Thursday at 10:30.Text 9M:Which university did you graduate from?W:I graduated from Northeastern University.M:What subject did you take at university?W:Economics, but I also like English and biology.M:What are your strong points?W:Well, I’m very good with people. I’m honest. I work hard. I work well under pressure. And I’m patient.M:What kind of people do you like to work with?W:I like a person who works hard. I don’t like lazy people.M:What’s your greatest strength?W:Well, this is a challenging question.I suppose I would say that I’m a quick learner.M:So, you’re smart.W:I think so. I think that I am good at what I do.M:What do you consider your weakness?W:I’m not good at speaking in public. I feel uncomfortable when I speak in public.M:That’s not a problem.It’s unnecessary for this position.Text 10Do you like a little cooler temperature? If so, book your vacation for winter (December through March). The downside of winter travel is that tourist season is also at its highest peak (mainly around Christmas ). From March through June is spring.It is a good time to catch a break on airfare.You may also find better hotel deals in spring as this is the time before the busy summer season when many families with schoolage children travel to Hawaii.Summer is hot and sunny from June through September. You’ll find these tropical fruits at every fruit stand—perfect for eating on the beach. Fall can be a bit wet in Hawaii, especially in October. And some years it rains more frequently in November.However, if you plan to spend a lot of time on thebeach and do activities in the water, this is when the sea surface temperature is the warmest. The ocean temperature in September and October is a pleasant 80 °F (26.6℃). During this time, you’ll also be able to find some hotel rate specials as this time is before the busy Christmas season.。
2021届安徽省五校高三上学期英语联考试题怀远一中、颖上一中、蒙城一中、涡阳一中、淮南一中考试时间2020年12月5日第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
ADaxing International AirportRegulations for certificates1. If your name on the passport is English, but on the ticket it is Chinese, you cannot take a domestic flight.2. The name and other information on the boarding pass must be consistent with the information in the boarding document. If not, the security check will not allow the release.3. The identity document held by the passenger must be the same as the identity document used the time of booking. If the ID number is inconsistent, the security check is not allowed.4. Foreign passengers can be released through security check if there is no space or backslash in their surname and first name. It is recommended that passengers and airlines confirm whether boarding passes can be changed.Regulations for shipping luggage1. Domestic flightNormally, 20kg for economy class, 30kg for business class and 40kg for first class passengers with adult or child tickets.2. International flightIn general, the free shipped luggage limit for economy class passengers is 20kg, and 30kg for economy class passengers with student passports. The allowance of free shipped luggage in business class is 30kg and 40kg for first class.Wheelchair service for special passengersYou can ask for wheelchair service in the ground garage, and the personnel will accompany you to enter the terminal.21.What will happen to a foreigner if there is no space in his surname and first name?A. He will not be allowed to board the plane.B. He has to change the information on his boarding pass.C. He can pass the security check.D. He has to provide his ID number.22. If a couple want to fly to Hawaii from Daxing International Airport, they can take _____ luggage for free at most.A. 80kgB. 60kgC. 40kgD. 70kg23. How long will it take from Beijing to Changsha?A. About two hours.B. About three hours.C. About four hours.D. About three and a half hours.BDays after Argentina canceled all international passenger flights to protect the country from the new coronavirus, Juan Manuel Ballestero began his journey home the only way possible: He stepped aboard his small sailboat for what turned out to be an 85-day odyssey across the Atlantic.The 47-year-old sailor could have stayed put on the tiny Portuguese island of Porto Santo, but the idea of spending what he thought could be “the end of the world” away from his fami ly, especially his father who was soon to turn 90, was unbearable. So he loaded his 29-foot sailboat with canned fish, fruit and rice and set sail in mid-March.“I didn’t want to stay like a coward (懦夫) on an island where there were no cases,” Mr. Balleste ro said. “I wanted to do everything possible to return home. The most important thing for me was to be with my family.”Friends tried to dissuade Mr. Ballestero from starting the perilous journey, and the authorities in Portugal warned him he might not be allowed to re-enter if he ran into trouble and had to turn back. But he was determined, “I bought myself a one-way ticket and there was no going back,” he said.Sailing can be a lonely passion, and it was particularly so on this voyage for Mr. Ballestero, who each night tuned into the news on a radio for 30 minutes to assess how the virus was spreading across the globe. “I kept thinking about whether this would be my last trip,” he said.When he made it to his native Mar del Plata, on June 17, he was surprised by the hero’s welcome he received. “Entering my port where my father had his sailboat, where he taught me so many things and where I learned how to sail, gave me the taste of a mission accomplished,” he said. A medical professional administered a test for Covid-19 on the dock. Within 72 hours, after the test came back negative, he wasallowed to set foot on Argentine soil.While he didn’t get to celebrate his father’s 90th birthday in May, he did make it home in time for Father’s Day.24. Why did Juan Manuel Ballestero start his journey?A. To be reunited with his family.B. To avoid being infected by the coronavirus.C. To realize his dream of sailing.D. To prove his bravery.25. What do we know about Juan Manuel Ballestero?A. He was forbidden to enter Mar del Plata port.B. He didn’t receive any information about the outside world during the journey.C. He failed to celebrate his father’s birthday.D. He was not allowed to leave Porto Santo by the authorities in Portugal.26. Wh at does the underlined word “per i lous” in paragraph 4 mean?A. distantB. tiringC. boringD. adventurous27. What can we infer from the text?A. The man was born in Porto Santo in Argentina.B. His friends encouraged him to start his journey.C. A test for Covid-19 was given to him the moment he arrived.D. The man was not worried at all during the trip.CA robot navigates through the strawberries, detecting ripe ones, picking without bruising and placing them in its basket. It sounds futuristic but it is possible now thanks to Rubion, the picking robot for strawberries. This piece of Belgian innovation is not only an answer to the labor shortage in the agricultural industry, but also allows growers to increase the quality of its produce –which in the end benefits the consumer.Demographic (人口结构的) and socio-economic numbers show that the labor shortage in the agricultural industry is a fact. But for Octinion the focus is clearly on addi ng quality. “Thanks to robotics, we have so many possibilities, much more than a human could ever do. Harvest prediction, picking according to market needs, simply picking when the berries are ripe instead of when workers are available –these are just a few examples of what is possible now for a grower,” says Tom Coen, CEO of the Octinion Technology Group. “The consumer will also notice the difference, as strawberries will be fresher and show less bruising.”Introducing robots in an industry where almost everything gets done by hand is more of a revolution than an evolution. It calls for close cooperation with all stakeholders (利益相关者). Tom Coen: “not only have we been working together with growers and test centers across the world for the past couple of years, breeders have also been keen on being part of the technological developments. ”In 2014 a team of Belgian engineers started the development of the robot. In the meanwhile, Octinion wasn’t the only company presenting a concept. Product Manager Laura Guillaume says it’s not a surprise that the company from Leuven is the first to actually present a commercial product: “by developing the robot from the beginning, we are able to make it practical in greenhouses or tunnels.” Octinion plans on launching harvesting robots for other crops in the upcoming years.28. What can we know about the robot?A. It can help solve the problem of labor shortage.B. It makes little difference to the quality of the fruits.C. It is developed by a group of Belgian engineers independently.D. It has been put into use around the globe.29. What is paragraph 2 mainly about?A. The good news of the robotic picking.B. The advantages of the robotic picking.C. How the robotic picking works.D. Different attitudes to the robotic picking.30. What can we infer from the last paragraph?A. The robot was introduced to the market in 2014.B. Octinion is the only company to put forward the idea of the robot.C. The robot can be used in any situation.D. Various harvesting robots are on the way.31. What can be the best title for the text?A. How robots pick strawberries.B. Fruits will be picked by Robots.C. Strawberry-picking robots are presented.D. A new robot was invented.DEveryone has an anecdote to share about how stress affects their body, particularly in their skin and hair----the only tissues we can see from the outside. Recently, a team from Harvard University provides scientific evidence to support the idea that stres s can cause a person’s hair to turn gray in a study published in the journal Nature. Ya-Chieh Hsu, a professor in this team said in a statement that the study was the first to confirm the common belief that stress can cause gray hair.Most people have about 100,000 hair follicles (毛囊) on their head. The follicles are responsible for making melanocytes (黑素细胞), the cells that give hair its color. As people age, melanocyte production is reduced. This causes a person’s hair to begin turning gray naturally.The team used experiments with mice to look at how stress affects stem cells in hair follicles. At first, the researchers suspected that an immune attack caused by a stressful event might be targeting the melanocyte stem cells. That theory, however, turned out to be false. The team also thought the hormonecortisol (皮质醇), which always increases in the body during times of stress, might be a likely cause. However, when researchers removed the glands (腺体) that produce the cortisol hormones, the hair of mice still turned gray.The scientists then centered their experiments on the body’s sympathetic nervous system ---- a system that is made up of a collection of nerves that extend through the body and controls "fight-or-flight" reactions in dangerous situations. When the mice were subjected to short-term pain or placed in stressful laboratory conditions, these nerves released a chemical called norepinephrine (去甲肾上腺素). When the norepinephrine was released, all the melanocyte stem cells in the hair follicles were highly activated and changed into cells producing pigment (色素). This overproduction process resulted in the early loss of color-producing cells.Ya-Chieh Hsu said that the results showed the harmful effects are more major than what the researchers had imagin ed. “After just a few days, all of the pigment-reproducing stem cells were lost. Once they’re gone, you can’t re produce pigments anymore. The damage is permanent” .32. What happened to the mice in a stressful environment?A. An immune attack destroyed their melanocyte stem cells.B. The hormone cortisol level dropped in their body.C. Their melanocyte stem cells become less active.D. More color-producing cells were lost.33.What is paragraph 4 mainly about?A. The functions of the sympathetic nervous system.B. The process of hair’s turning gray.C. The harmful effects of stress.D. The importance of norepinephrine.34.Which word best describes the author’s attitude to the study?A. SkepticalB. ObjectiveC. TolerantD. Conservative35.What can we learn from the study?A. It is the first to investigate the connection between stress and gray hair.B. The effects of stress is as great as researchers expected.C. Mice become more active when under stress.D. It is natural for one’s hair to turn gray with aging.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
怀远一中、颍上一中、蒙城一中、涡阳一中、淮南一中2021届高三“五校”联考文科数学试题考试时间: 2020年12月4日考生注意:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分150分,考试时间120分钟。
2.考生作答时,请将答案答在答题卡上。
第Ⅰ卷每小题选出答案后,用2B 铅笔把答题卡对应题目的答案标号涂黑;第Ⅱ卷请用直径0.5毫米的黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区域书写的答案无效,在试题卷、草稿纸上作答无效。
............................ 3.本卷命题范围:集合与常用逻辑用语,函数、导数及其应用,三角函数、解三角形,平面向量,复数,数列,不等式。
第Ⅰ卷(选择题 共60分)一、选择题:本题共12小题,每小题5分,共60分. 在每小题给出的四个选项中,只有一项是符合题目要求的.1.设集合{}24A x x =≤≤,{}2430B x x x =-+<,则AB =A .{}14x x <<B .{}23x x ≤< C .{}23x x << D .{}14x x <≤2.已知复数z 满足i 1i z ⋅=+,其中i 为虚数单位,则z 的共轭复数为 A .1i -- B .1i -+ C .1i - D .1i +3.设:p 11<+x ,:q 22<<-x ,则p 是q 的A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件 4.已知2.02=a ,2.0log 2=b ,0.2log 0.3c =,则a b c ,,的大小关系为 A .a b c << B .b a c << C .c b a << D .a c b <<5.筒车是我国古代发明的一种水利灌溉工具,因其经济又环保,至今还在农业生产中得到 使用.明朝科学家徐光启在《农政全书》中用图画描绘了筒车的工作原理(图1所示).假定 在水流量稳定的情况下,筒车上的每一个盛水筒都做逆时针匀速圆周运动,筒车转轮的中心O 到水面的距离h 为1.5m ,筒车的半径r 为2.5m ,筒车每秒转动πrad 12,如图2所示,盛水桶M 在0P 处距水面的距离为3m ,则2s 后盛水桶M 到水面的距离近似为 A .3.2m B .3.4m C .3.6m D .3.8m图1 图26.在正方形ABCD 中,,M N 分别是,BC CD 的中点,若2AB =,则AM BN += A .2 BC . 4 D.7.函数1()f x =的部分图象可能是A B C D8.若正实数x y ,满足+=1x y ,则下列不等式恒成立的是 A 1≤ B 12≥C .2212x y +≥ D .1114x y +≤9.已知数列{}n a 为单调递增的等差数列,且11=a ,若2a ,31a +,6a 成等比数列,则=20a A .18 B .28 C .38 D .58 10.已知函数()f x 满足(2)()f x f x -=,当1x ≥时,12()221x f x x x -=+-+,则不等式(21)(1)f x f x -<+的解集为A .2(2)3, B .2(1)(12)3,, C .(1)(2)-∞+∞,, D .2()(2)3-∞+∞,,11.ΔABC 中,D 为ΔABC 内一点,120ADC .若2CD ,则BCD =A .15︒B .30︒C .45︒D .60︒ 12.已知正实数a b ,满足a b a b b a ->-ln ln ,下列命题中的真命题是 A .若)ln(|ln ||ln |ab b a =+,则b a > B .若)ln(|ln ||ln |ab b a -=+,则b a > C .若b a b a ln ln |ln ln |=,则b a < D .若b a b a ln ln |ln ln |-=,则b a <第Ⅱ卷(非选择题 共90分)二、填空题:本题共4小题,每小题5分,共20分.13.若x y ,满足约束条件301020x y x y x +-≤⎧⎪--≤⎨⎪+≥⎩,则34z x y =+的最大值为 .14.已知向量(23)a k =,,(41)b k =-,. 若a 与b 方向相同,则k = .15.等差数列{}n a 的前n 项和为n S . 且满足721=+a a ,173(3)m m a a m -+=≥,2020m S =,则m = .16.已知函数π()sin()(0)6f x x ωω=+>,若函数()f x 在(0π),内恰有6个极值点,则ω的取值范围为 .三、解答题:共70分. 解答应写出文字说明、证明过程或演算步骤. 第17题满分为10分,第18~22题每题满分为12分. 17. (10分)已知函数2()e xf x ax =-的图象在点))1(,1(f 处的切线斜率为e 2-. (1)求实数a 的值;(2)已知函数)(x f 的导函数是)(x f ',记()()x x f x g +'=,求()x g 的极小值.18. (12分) 已知函数ππ()4cos()sin() 3.26f x x x =-+- (1)求()f x 的最小正周期;(2)若方程()f x m =在ππ[]43-,有实根,求实数m 的取值范围.19. (12分)设数列{}n a 中41=a ,142n n a a n -=≥(),设n n a b 2log 21=. (1)求数列{}n b 的通项公式;(2)令()n nn nb c ⋅-=1,求1220c c c ++⋅⋅⋅+.20. (12分)ABC △的内角,,A B C 的对边分别是,,a b c .设sin 2sin A Ca b=. (1)判断ΔABC 的形状;(2)若3a ,2c ,B 的平分线交AC 于D ,求ΔBCD 的面积.21. (12分)第二届阜阳花博会于2020年9月28日在颍上八里河开幕,其主题为“花漾水上,花开颍上”.据调研获悉,某花卉基地培育有水生与水陆两生花卉30余种,计划在花博会期间举行展销活动.经分析预算,投入展销费x 万元时,销售量为m 万个单位,且112++=x x m (a x ≤<0,a 为正实数).假定销售量与基地的培育量相等,已知培育m 万个单位还需要投入成本)12(+m 万元(不含展销费),花卉的销售价为4(11)m+万元/万个单位. (1)写出该花卉基地的销售利润y 万元与展销费x 万元的函数关系; (2)展销费x 为多少万元时,该花卉基地可以获得最大利润? (注:⨯--利润=销售价销售量投入成本展销费)22. (12分) 已知函数ln ()e xxf x a x=+. (1)当0a =时,求函数)(x f 的单调区间; (2)证明:当21ea =-时,()()g x xf x x =+在(0)+∞,有两个零点.2021届高三“五校”联考文数答案2020年12月4日题号 1 2 3 4 5 6 7 8 9 10 11 12 选项 BDADDBACDACA1.B2.D3. A4. D5.D6. 解:以AB ,AD 为坐标轴建立平面直角坐标系,如图:因为AB=2,所以A(0,0),B(2,0),M(2,1),N(1,2)所以AM=(2,1),BN=(-1,2),AM BN (1,3)+=. 则22AM+BN =1+3=10B .7. 解:首先函数为偶函数,排除A ,当10<<x ,()0<x f ;当1>x ,()0>x f ,选C .8.解析: 222()122x y x y ++≥=,故选择C . 9.解析:设公差为d ,2a =1+d ,31a +=2+2d ,6a =1+5d 所以()22+21+1+5d d d =⋅()()解得31d =-或,又因为d >0,所以3d =所以=20a 1+3(20-1)=5810.由题意知()f x 图象关于直线1x =对称,且()f x 在区间(1)+∞,上单调递增22223x x x ∴-<⇒<<.故选择A 11. 解析:在ACD 中,2CD ,3AC ,120ADC ,由正弦定理得,sin sin AC CDADC CAD ,即32sin 32CAD,解得,2sin 2CAD,所以45CAD ,45BCD CAD ,选择C 项.12.解析: 由a b a b b a ->-ln ln ,得a a bb 1ln 1ln +>+, 设x x x f 1ln )(+=,则)()(a f b f >. 由2ln )(xxx f -=',可知)(x f 在)1,0(上单调递增,在),1(+∞上单调递减.故当1≥a 且1≥b 时,a b <;当1≤a 且1≤b 时,a b >.A 选项中由)ln(|ln ||ln |ab b a =+可知1≥a 且1≥b ,可得b a >.故A 选项正确 另解:取e,1a b ==排除CD 选项;取1,1ea b ==排除B 选项.故选A . 13.解析: 由已知可得34z x y =+在点(25)-,处取得最大值14. 14. 解:向量(23)(41)a k b k ==-,,,,a 与b 方向相同,∴2(-1)-43=0k k ⋅⨯且>0k ,解得3k =.3故答案为:.15.解析:8077321211=+=+=+++-)(n n na a a a a a所以()202024011=+==+n a a S a a n n n 又因为解得n =10116. 解:由()0,πx ∈得πππ(,π)666x ωω+∈+,若函数()f x 在()0,π内恰有6个极值点,则11ππ13ππ262ω<+≤,解得161933ω<≤.17. 解析:(1)ax x f x2e )(-='. ............................................... 1分2e 2e )1(-=-='a f ....................................4分解得1=a ...................................5分(2)由(1)知2e )(-='x x f ,,2e )(x x g x+-= .............................. 6分,1e )(-='x x g 令,0)(='x g 得0=x , ................................................ 7分当)0,(-∞∈x 时,,0)(<'x g )(x g 单调递减;当),0(+∞∈x 时,,0)(>'x g )(x g 单调递增; ..................................... 9分故当0=x 时,)(x g 取极小值1)0(-=g .................................................. 10分18. 解:(1)函数231()4sin (sin cos )323sin 2sin cos 322f x x x x x x x =+-=+-π3(1cos 2)sin 232sin(2)3x x x =-+-=-, ................................................... 4分()f x ∴的最小正周期为2ππ2=.(5分)(2)在区间ππ,43⎡⎤-⎢⎥⎣⎦上,π5ππ2,363x ⎡⎤-∈-⎢⎥⎣⎦, .................................................... 6分故当ππ232x -=-时,函数()f x 取得最小值,为-2, .............................................. 8分 当ππ233x -=时,函数()f x 取得最大值,为3,故()f x 的值域为2,3⎡⎤-⎣⎦...........................10分若方程()f x m =在ππ,43⎡⎤-⎢⎥⎣⎦有实根,则实数m 的取值范围为2,3⎡⎤-⎣⎦ .................................................. 12分19. 19. (1)因为41=a ,)(*-∈≥=N n n a a n n ,241 所以数列{}n a 是以4为首项以4为公比的等比数列....................................................2分所以nn n a 4441=⨯=-.....................................................................................................3分n b n n ==⇒4log 212......................................................................................................5分(2)由(1)可知2)1(n c n n ⋅-= ...............................................................7分2222220212019321+-⋅⋅⋅-+-=+⋅⋅⋅++∴c c c)()()(22222219203412-+⋅⋅⋅-+-=..............................................................................9分20321+⋅⋅⋅+++=.............................................................................10分 ()210220201=⋅+= (12)分20. (1)由sin 2sin A C a b =及正弦定理得2sin cos sin sin sin A ACA B,............................1分 即2sin cos sin sin cos cos sin B A C A B A B ,..................................................2分 所以sin cos sin cos B A A B ,即tan tan A B ..........................................................4分 所以A B ,ABC ∆为等腰三角形. .........................................................................5分 (2)因为A B 且3a ,所以3b a ....................................................................6分 由余弦定理得1cos 3B,所以22sin 3B ................................................................8分 1sin 222ABCS ac B ..........................................................................9分 1sin 32212sin 22BCD ABDB BC BD S BC B S AB AB BD , (10)分 所以36255BCDABCSS . ..........................................................................12分 (其他解法酌情给分) 21. 解析:(1)由题意得()x m m m y -+-⎪⎭⎫⎝⎛+=12411 ...................................................2分 x m -+=39x x x -+++⋅=31129x x -+⎪⎭⎫ ⎝⎛+-=31129x x -+-=1921, ...................................................4分所以x x y -+-=1921(a x ≤<0,a 为正实数). .........................................5分 (2)由(1)得:x x y -+-=1921()⎥⎦⎤⎢⎣⎡+++-=19122x x , ......................................7分易知20<<x ,函数递增,2>x ,函数递减.又0>a . .........................9分所以当2>a 时,31=+x ,2=x 万元时,函数取得最大值为16万元; 当20≤<a 时,a x =万元时,函数取得最大值为(a a -+-1921)万元............11分 答:(1)函数关系为x x y -+-=1921(a x ≤<0,a 为正实数). (2)所以当2>a 时,31=+x ,2=x 万元时,函数取得最大值为16万元;当20≤<a 时,a x =万元时,函数取得最大值为(a a -+-1921)万元. ......12分22.解析(1)当0a =时ln ()x f x x =,21ln ()=xf x x-' ........................2分 21ln ()=00xf x x e x -'>⇒<< ........................3分 21ln ()=0x f x e x x -'<⇒< ........................4分()f x ∴单调递减区间为(e,)+∞,单调递增区间为(0,e,) .......................5分(2分2x e -=即0201x e x -=易得0(1,2)x ∈ ...........................................................8分()g x 在0(0,)x 上为增函数,在0()x +∞,上为减函数 020000()ln 10x g x x e x x -=-++=> .................................................................... 9分222()10e g e e e-=+-< ..................................................................... 10分........................................................................ 11分 ()g x ∴在(0,)+∞上有两个零点. ........................................................................ 12分(其他解法酌情给分)。
怀远、颖上、蒙城、涡阳、淮南⼀中2021届⾼三“五校”联考英语试题怀远、颖上、蒙城、涡阳、淮南⼀中2021届⾼三“五校”联考英语试题命题学校涡阳⼀中考试时间 2020年12⽉5⽇试题说明:本试题分为第I卷(客观题)和第II卷(主观题)两部分,全卷满分150分,考试时间120分钟。
考试注意事项:1.答题前,考⽣务必⽤0.5毫⽶⿊⾊墨⽔签字笔将⾃⼰的姓名、座位号、准考证号填涂在答题卡和试卷规定的位置上。
2.回答选择题时,选出每⼩题答案后,⽤2B铅笔把答题卡上所对应题⽬答案标号涂⿊;如需改动,⽤橡⽪擦⼲净后,再选涂其他答案标号。
写在本试卷上⽆效。
3.回答⾮选择题时必须⽤0.5毫⽶⿊⾊墨⽔签字笔在答题卡上作答,答案必须写在答题卡各题⽬指定区域内相应的位置,不能写在试卷上;如需改动,先划掉原来的答案,然后再写上新的答案;不能使⽤涂改液、胶带纸、修正带。
不按以上要求作答的答案⽆效。
第I卷第⼀部分听⼒(共两节,满分30分)做题时,先将答案标在试卷上。
录⾳内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第⼀节(共5⼩题;每⼩题1.5分,满分7.5分)请听下⾯5段对话。
每段对话后有⼀个⼩题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关⼩题和阅读下⼀⼩题。
每段对话仅读⼀遍。
1. What did the woman do at weekend?A. She gave a hand to her uncle.B. She went to see her uncle.C. She visited the City Museum.2. How much will the blouse cost the man?A.10 dollars.B. 40 dollars.C. 45 dollars.3. What did Alice buy for his father?A. A camera.B. A computer.C. A smartphone.4. Where does the conversation take place?A. In a restaurant.B. In a store.C. In a fitness center.5. What will the speakers do next?A. Attend a meeting.B. See a friend.C. Hold a party.第⼆节(共15⼩题;每⼩题1.5分,满分22.5分)听下⾯5段对话或独⽩。
绝密★启用前
安徽省五校联考
(淮南一中涡阳一中怀远一中颍上一中蒙城一中)
2021届高三毕业班上学期12月联考质量检测
地理试题参考答案
2020年12月一、选择题(每小题 2 分,共计 50分)
题号 1 2 3 4 5 6 7 8 9 10 11 12 13
选项 D C B A C B C B A B A B B
题号14 15 16 17 18 19 20 21 22 23 24 25
选项 B D D B B C B A B C D C
二、综合题(共计4小题,50分)
26. (14分)
(1)松嫩平原地势低平,松花江、嫩江及其支流构成向心状水系,地表排水不畅;地处半湿润和半干旱过度地区,蒸发强烈;松嫩平原多黏重泥质沉积物,下渗作用微弱;地表径流将盐分带入沼泽,盐分长期积累,形成盐沼。
(每点2分,任答3点即可)
(2)沼泽湿地萎缩,河床、湖床裸露,植被覆盖率低,多沙质沉积物,土质疏松抗侵蚀能力差;地形平坦,冬春季节多大风天气,风力侵蚀作用强。
(每点2分)
(3)沙丘覆盖在古河道沉积物上,地下水丰富;7、8月份降水量丰富,沙地下渗量大;沙质土地,有利于植物根系生长发育。
(每点2分,任答2点即可)
27. (12分)
(1)由甲地至乙地沉积物颗粒逐渐变细。
(2分)
河流流入湖泊时流速降低,所携带的泥沙逐步沉积;泥沙颗粒大的先沉积,因此湖
1。
怀远一中、颍上一中、蒙城一中、涡阳一中、淮南一中2021届高三“五校”联考理科数学试题考试时间: 2020年12月4日考生注意:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分150分,考试时间120分钟。
2.考生作答时,请将答案答在答题卡上。
第Ⅰ卷每小题选出答案后,用2B 铅笔把答题卡对应题目的答案标号涂黑;第Ⅱ卷请用直径0.5毫米的黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区域书写的答案无效,在试题卷、草稿纸上作答无效。
............................3.本卷命题范围:集合与常用逻辑用语,函数、导数及其应用(含定积分),三角函数、解三角形,平面向量,复数,数列。
第Ⅰ卷(选择题 共60分)一、选择题:本题共12小题,每小题5分,共60分. 在每小题给出的四个选项中,只有一项是符合题目要求的.1.设集合{}24,A x x =≤≤{}2430B x x x =-+<,则AB = A .{}14x x << B .{}23x x ≤<C .{}23x x <<D .{}14x x <≤2.已知复数z 满足i 1i z ⋅=+,其中i 为虚数单位,则z 的共轭复数为A .1i -+B .1i --C .1i +D .1i -3.设: |1|1p x +<,:22q x -<<,则p 是q 的A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件4.已知点A B ,是圆O 上两点,2π3AOB ∠=,AOB ∠的平分线交圆O 于点C ,则OC =A .1122OA OB + B .322OA OB + C .2233OA OB + D .OA OB + 5.筒车是我国古代发明的一种水利灌溉工具,因其经济又环保,至今还在农业生产中得到使用.明朝科学家徐光启在《农政全书》中用图画描绘了筒车的工作原理(图1所示).假定在水流量稳定的情况下,筒车上的每一个盛水筒都做逆时针匀速圆周运动,筒车转轮的中心O到水面的距离h为1.5m,筒车的半径r为2.5m,筒车转动的角速度ω为πrad/s12,如图2所示,盛水桶M在0P处距水面的距离为3m,则2s后盛水桶M到水面的距离近似为A.3.2m B.3.4m C.3.6m D.3.8m图1 图26.记n S是等差数列{}n a的前n项和,已知30S=,68a=,则10a=A.12 B.14 C.16 D.187.函数21()log||f xx=的部分图象可能是A B C D8.已知2.02=a,2.0log2=b,2log2.0=c,则,,a b c的大小关系为A.a b c<< B.b a c<< C.c b a<< D.acb<<9.已知ABC△是边长为3的等边三角形,点D为ABC△内一点,且120ADC∠=︒,1AD=,则BD=xyO xyO xyxyOA .12B . C. 1 D 10.已知函数22()log |1|21f x x x x =-+-+,则不等式(21)(1)f x f x -<+的解集为A .2(,1)(1,2)3B .2(2,0)(0,)3- C .2(,2)3 D .2(,2)(,)3-∞-+∞ 11.已知函数π()sin(),(0,||)2f x x ωϕωϕ=+>≤,π4x =-是()f x 的零点,直线π4x =是()f x 图象的对称轴,且()f x 在ππ()42,上单调,则ω的最大值为A .1B .2C .3D .4 12.若关于x 的不等式2e (ln )x a x x x ≥-对任意(0,+)x ∈∞恒成立,则实数a 的取值范围为A .2(,e ]-∞B .(,e]-∞C .(,1]-∞D .1(,]e-∞ 第Ⅱ卷(非选择题 共90分)二、填空题:本题共4小题,每小题5分,共20分.13.已知向量,a b 为单位向量,其夹角为π3,则|2|+=a b . 14.函数2()23ln f x x x x =--的极小值为 .15.已知复数12,z z 满足1||1z =,234i z =+,其中i 为虚数单位,则12||z z -的最大值为 . 16.已知n S 是等比数列{}n a 的前n 项和,q 为{}n a 的公比且43ln S S =.若11>S ,则下列命题中所有正确的序号是 .①10q -<<;②40a >;③321S S S >+;④321S S S <+.三、解答题:共70分. 解答应写出文字说明、证明过程或演算步骤. 第17题满分为10分,第18~22题每题满分为12分.17.(10分)已知函数122()(1)f x x ax -=-+.(1)若函数()f x 的定义域为R ,求实数a 的取值范围;(2)若1[,2]2x ∀∈,都有()12f x ≤成立,求实数a 的取值范围.18.(12分)已知向量a =(cos ,sin )x x ,b 33(cos sin ,cos sin )=+-x x x x ,设函数()=f x ⋅a b .(1)求函数()f x 的最小正周期及单调递增区间;(2)若关于x 的方程()0f x m -=在π[0,]2上有两个不同的实数解,求实数m 的取值范围.19.(12分)设数列{}n a 满足13a =,1233n n a a n +=-+.(1)计算2a ,3a ,猜想{}n a 的通项公式并加以证明;(2)求数列1{}3nn a +的前n 项和n S .20.(12分)ABC △的内角,,A B C 的对边分别是,,a b c .设sin 2sin A C a b=. (1)判断ABC △的形状; (2)若ABC △的外接圆半径为1,求ABC △周长的最大值.21.(12分)第二届阜阳花博会2020年9月28日在颍上八里河开幕,其主题为“花漾水上,花开颍上”.据调研获悉,某花卉基地培育有水生与水陆两生花卉30余种,计划在花博会期间举行展销活动.经分析预算,投入展销费x 万元时,销售量为m 万个单位,且112++=x x m (a a x -≤<20,a 为正实数).假定销售量与基地的培育量相等,已知该基地每培育m 万个单位还需要投入成本(21)m +万元(不含展销费),花卉的销售价定为4(11)m+万元/万个单位. (1)写出该花卉基地的销售利润y 万元与展销费x 万元的函数关系;(2)展销费x 为多少万元时,该花卉基地可以获得最大利润?(注:⨯--利润=销售价销售量投入成本展销费)22.(12分) 已知函数ln ()e x x f x a x=+,()()g x xf x x =+. (1)若曲线()y f x =在点(1,(1))f 处的切线过点(2,1),求实数a 的值;(2)当21ea =-时,证明:()2g x <.。
绝密★启用前
安徽省五校联考
(淮南一中涡阳一中怀远一中颍上一中蒙城一中)
2021届高三毕业班上学期12月联考质量检测
政治试题参考答案
2020年12月
一、选择题
1.D
2.C
3.B
4.C
5.B
6.D
7.A
8.A
9.C 10.D
11.A 12.A 13.C 14.B 15.C
16.D 17.C 18.B 19.A 20.B
21.A 22.B 23.D 24.C
二、非选择题
25.①优化产业结构,发展特色产业,发展优质高效农业,增加农民收入。
(4分)
②农业科技专家深入产业扶贫一线,长线帮扶,聚焦科技力量提质增效。
(3分)
③种养加结合,发展乡村旅游,促进农村一二三产业融合发展,带动贫困户脱贫。
(4分)
④重视市场营销,完善营销网络,线上线下共助农产品销售,实现产品价值。
(3分)
26.①稳定经济,促进就业,增加居民收入,提高消费能力。
(3分)
②完善社会保障制度,改善消费预期,增强居民消费信心。
(3分)
③强化市场监管,规范消费市场,优化消费环境,居民放心消费。
(3分)
④推进供给侧结构改革,培育新消费热点,创新消费模式,加快消费转型升级,满足消费需求。
(3分)
27.①坚持党的领导,发挥党总揽全局、协调各方的领导核心作用。
(3分)
1。
绝密★启用前
安徽省五校联考
(怀远一中 颖上一中 蒙城一中 涡阳一中 淮南一中)
2021届高三毕业班联考质量监测
数学(文)试题
2020年12月4日
考生注意:
1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分150分,考试时间120分钟。
2.考生作答时,请将答案答在答题卡上。
第Ⅰ卷每小题选出答案后,用2B 铅笔把答题卡对应题目的答案标号涂黑;第Ⅱ卷请用直径0.5毫米的黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区域书写的答案无效,在试题卷、...................草稿纸上作答无效。
.........
3.本卷命题范围:集合与常用逻辑用语,函数、导数及其应用,三角函数、解三角形,平面向量,复数,数列,不等式。
第Ⅰ卷(选择题 共60分)
一、选择题:本题共12小题,每小题5分,共60分. 在每小题给出的四个选项
中,只有一项是符合题目要求的.
1.设集合
{}24A x x =≤≤,{}2430B x x x =-+<,则A B = A.{}14x x << B.{}23x x ≤< C.{}23x x << D.{}14x x <≤
2.已知复数z 满足i 1i z ⋅=+,其中i 为虚数单位,则z 的共轭复数为
A.1i --
B.1i -+
C.1i -
D.1i +
3.设:p 11<+x ,:q 22<<-x ,则p 是q 的
A.充分不必要条件
B.必要不充分条件
C.充要条件
D.既不充分也不必要条件
4.已知2.02=a ,2.0log 2=b ,0.2log 0.3c =,则a b c ,,的大小关系为
A.a b c <<
B.b a c <<
C.c b a <<
D.a c b <<
5.筒车是我国古代发明的一种水利灌溉工具,因其经济又环保,至今还在农业生产中得到使用.明朝科学家徐光启在《农政全书》中用图画描绘了筒车的工作原理(图1所示).假定在水流量稳定的情况下,筒车上的每一个盛水筒都做逆时针匀速圆周运动,筒车转轮的中心O 到水面的距离h 为1.5m ,筒车的半径r 为
2.5m ,筒车每秒转动πrad 12,如图2所示,盛水桶
M
在0P 处距水面的距离为3m ,
则2s 后盛水桶M 到水面的距离近似为
图1 图2
A.3.2m
B.3.4m
C.3.6m
D.3.8m
6.在正方形ABCD 中,,M N 分别是,BC CD 的中点,若2AB =,则AM BN +=
A.2
B.10
C. 4
D.25
7.函数21()log ||f x x =
的部分图象可能是
A B C D x y O x y O O x
y
O x y。