福州市---学年第一学期九年级期末质量检测(word版含答案)

2019-2020学年度第一学期福州市九年级期末质量抽测英语试卷Ⅱ. 选择填空(共15小题；每小题1分，满分15分)从每小题所给的A、B、C三个选项中，选出可以填入空白处的正确答案。

21.- Have you finished your project?- Not yet. But we are making _______ .A.peaceB. noiseC. progress22. Don’t worry! If you can’t complete the work _______ your own, I will give you a hand.A. InB. onC. at23.- How much difficulty did you have solving this problem?- _______. It’s quite easy.A. NobodyB. NowhereC. None24.--Kate, don’t sing here! I'm busy preparing for tomorrows math test.-Sorry, I didn’t _______ it.A. mentionB. realizeC. manage25.-What a fine day today!Yes. It’s ______ to stay indoors. Why not go out for a picnic?A. sillyB. naturalC. excellent26. Thomas and Martin climbed the higher mountain, ____they enjoyed a better view1A. butB. soC. or27. The style of my dress ______ that of Mary’s, but hers is a little longer.A. is similar toB. is pleased withC. is short of28.-How’s Mrs. Black?-She ______ her medicine and is resting now.A. takesB. is takingC. has taken29.-_____ have you been in the sports club?- Since the first month I came to this school.A. How longB. How soonC. How often30. We ______ respect the disabled and be kind to them.A. dare toB. orC. have to31.- Why can’t Karl enter the bar?- Only those _____ are above eighteen years old are allowed to enter.A. whoB. whichC. when32. My cat was lying under the shelf on the wall. So when the shelf fell, she _____ right on the head.A. hitB. was hitC. was hitting33. Jane and her friends ______ themselves when they saw one another’s costumesA. laughed atB. turned toC. named after34. The doctor did what he could ______ the girl who was badly injured in the accident.2A. saveB. savingC. to save35. Steve is free tomorrow. Let's ask him ________ .A. where he has goneB. when did he go to the Great WallC. whether he wants to go to the ball game with usCBCBA BACAB ABACCⅢ. 完形填空(共10小题；每小题1.5分，满分15分)阅读下面短文，从每小题所给的A、B、C三个选项中，选出可以填入空白处的最佳答案。

福州市2012—2013学年第一学期九年级期末质量检查数学试卷参考答案及评分标准一、选择题（每小题 分，共 分）．✌ ． ． ． ． ． ． ．．✌ ． 二、填空题（每小题 分，共 分）．相交 ． 或15等 ． π ．三 ．932m -<<-三、解答题（满分 分） ．（每小题 分，共 分）（ ）解：原式1+，  分134+-， 分  分 （ ）如图，M 即为所求；  分 （圆心 位置标注正确 分，画图正确 分） BC 所对的圆心角的度数为 度．  分（注：未用水笔描图扣一分） ．（每小题 分，共 分）（ ）解：()22(1)32x x +=+，  分 ()132x x +=±+，  分132x x ∴+=+或1(32)x x +=-+， 分 1242,3x x ∴=-=-．  分（）1,AB BC =解：，3728AC BC∴⋅===分分．分．（满分 分）解：当1a=，1b=时，1)42ab==-；当1a=，1b=时，1)2ab==；当1a=，1b=时，1)42=+>；当1a=，1b=时，1)2=；  分（ ）♋、b可能出现的结果有 种，它们出现的可能性相等，其中满足2ab≤的有 种． 分∴(2)34abP≤＝．  分．（满分 分）解：连接✌，………………………………… 分AC OB⊥，且 为 中点，✌垂直平分 ， ✌＝ ，✌＝✌．………………………………… 分又 ✌＝ ，✌是等边三角形，  分＝ ，✌＝ ，  分在 ♦✌中，AC=，设 ＝⌧，则 ✌＝ x，  分由勾股定理得：222(2)x x+=，解得：11x=，21x=-（不合题意，舍去）．  分✌第题✌＝ ，    ，阴影部分的面积260212136023OAB AOC S S S π⨯-⨯π扇形△＝＝－＝．  分（注：不同解法可参照评分标准给分）．（满分 分）解： ＝ ＜ ， 李先生购买的数量超过 条． 分 设李先生一共购买了x 条棉被，依题意，得：  分 [1200.5(60)]8800x x --=  分 解得：180x = ，2220x =．  分 当180x =时，1200.5(60)110100x --=>，符合题意，  分 当2220x =时，1200.5(60)40100x --=<，不符合题意．  分 答：李先生一共购买了 条棉被．  分．（满分 分）解：（ ）∠ ✈＝ °；………………………………………… 分（ ）如图 ，过✈点作✈☞⊥ 于点☞，连接 ✈，……………………………… 分 ∵✌⊥ ，∴✈☞∥✌，……………………………………………………………… 分 ∵四边形 ☟✈是菱形， ∴ ☜⊥ ☟，又∵ ⊥ ☟，∴ ☜∥ ，∴四边形 ☜✈☞是矩形，又∵☜＝☜✈，∴四边形 ☜✈☞是正方形，………………………… 分 ∴✈☜＝✈☞，即点✈在∠✌的平分线上………………∵在菱形 ☟✈中，∠ ✈＝ °， ∴△ ✈和△ ☟✈都是等边三角形，∴✈＝✈☟，………………………………………… 分 又∵ ☜∥ ，☟✈∥ ， ∴四边形 ✈☟是菱形， ∴ ✈平分∠✌，∴点✈为Rt ABC △的内心；…………………………………… 分图☟☞（ ）∵E 与菱形MPHQ 关于直线PE 对称， ∴E 与直线HQ 、直线MQ 同时相切；或与直线PM 、直线PH 同时相切，……………… 分分两种情况考虑：♊如图 ，设E 与直线HQ 相切于点☠，直线HQ 交✌于点 ，连接☜☠．则☜☠⊥ ☟，四边形CHOE 是矩形． 设E 的半径为❒，则 ☟  ☟ ❒， 由（ ）得： ☟ ✌，☟✈ ✌， ∴四边形✌☟是平行四边形， ∴✌ ☟ ❒，在 ♦ ☜☠中，∠☜☠ ✌ ，  ☜ ☜☠ ❒，✌ ✌ ☜ ☜ ❒，……………………………… 分 又∵在Rt ABC △中， 90C ∠=o ，30A ∠=o ，✌＝ ， ∴ ＝12✌ ，∴AC ==，∴rMH 分∵在 ♦△ ☟中，∠ ☟＝ ，∠ ☟＝∠✌ °， ∴222112()225BM BM MH -==，∴45BM =，…………………………………………… 分 ②如图 ，设E 与直线AB 相切于点☝，连接☜☝， ∴☜☝⊥✌，又30A ∠=o ， ∴✌☜ ☜☠ ❒， ∵3AC AE EC r =+=，3r =r =∴MH =，…………………………………………… 分∴22214()23BM BM MH -==，∴43BM =，☟图图综上所述 当E 与菱形MPHQ 边所在的直线相切时 的值为45或43 …… 分（注：各题不同解法可参照评分标准给分，但，凡用相似证明或解题者，统一在总分中扣 分，不重复扣分．）．解：（ ） 抛物线2=+y ax b 的图像经过点✌（ ， 16+=4=4a b b ⎧⎨-⎩，解得：1=2=4a b ⎧⎪⎨⎪-⎩， 抛物线的解析式为：21=42y x -；………… 分（ ）过点✌作✌☜ ⌧轴于☜，连接✌交⌧轴于点☜，＝✌☜＝ ， ＝ ✌☜＝ ， ＝ ✌☜，  ☹☜✌，…………………………………………… 分 MB MA =，  ☜ 122OE =，…………………………… 分以 为圆心， 为半径的 ，即为以✌为直径的圆．……………… 分 由勾股定理得 MB ==，…………………… 分 点 的坐标为(2-，．………………………………… 分 （ ）如图 ，当点 在点（ ， ）的右侧时， 作✌☜ ⌧轴于☜， ☞ ⌧轴于☞， ✌为等腰直角三角形，✌＝ ， ✌＝ ，即 ✌☞＋ ☞＋ ☞＝ ， ✌☞＝ ☞， 又 ☞＝ ✌☜＝ ， ☞☹ ☜✌，…………………………… 分 ☜＝ ☞，☞＝✌☜，✌（ ， ）， ✌☜＝ ☜＝ ， ☞＝ ☜，即 ☞＋☜☞＝ ☜＋☜☞，☞＝ ☜， ☞＝ ☞，………………………… 分 当点 与点（ ， ）的重合时，点 与原点重合；… 分当点 在点（ ， ）的左侧时（如图 ），同理可得⌧图⌧图✌ 综上所述，点 在直线y x =-的图像上． 设点 的坐标为（❍， ），则点 的坐标为（❍－ ， －❍），  分 又 点 在抛物线21=42y x -的图像上，()214442m m -=--，解得：12=0=6m m ，，当点 的坐标为（ ， ）或（ ， ）时，点 落在抛物线21=42y x -的图像上．  分（注：各题不同解法可参照评分标准给分，但，凡用相似证明或解题者，统一在总分中扣 分，不重复扣分．）。

2022~2023学年第一学期期末九年级质量监测英语试题(考试时间：120分钟满分150分）注意：请把所有答案填涂或书写到答题卡上！请不要错位、越界答题！在本试题上答题无效。

Ⅰ.听力(共三节，20小题，每小题1.5分，满分30分)第一节听句子听下面五个句子，从每小题所给的三幅图中选出与其内容相符的选项。

(每个句子读两遍)1. A. B. C.2. A. B. C.3. A. B. C.4. A. B. C.5. A. B. C.第二节听对话听下面七段对话，从每小题所给的A、B、C三个选项中选出正确答案。

(每段对话读两遍)听第1段对话，回答第6小题。

6. What’s Frank’s favourite subject?A. Chinese.B. History.C. Maths.听第2段对话，回答第7小题。

7. How many times has the man been to New York?A. Once.B. Twice.C. Three times.听第3段对话，回答第8小题。

8. What is the advice to Yang Hui?A. To make friends.B. To get pens.C. To write more.听第4段对话，回答第9小题。

9. When is the movie going to start?A. At 3:10.B. At 3:30.C. At 3:50.听第5段对话，回答第10、11小题。

10. What are they talking about?A. Protecting rainforests.B. Planting trees.C. Protecting wildlife.11. What does the woman suggest doing to raise money?A. Selling books.B. Having a concert.C. Selling some old clothes. 听第6段对话，回答第12、13小题。

2022-2023学年福建省福州市九年级（上）期末数学试卷（一检）1. 地铁标志作为城市地铁的形象和符号，是城市文化的缩影.下列图案分别为北京，上海，深圳，福州四个城市的地铁标志，其中是中心对称图形的是( )A. B.C. D.2. 下列成语所描述的事件属于不可能事件的是( )A. 守株待兔B. 水中捞月C. 水滴石穿D. 百发百中3. 下列图形中，正多边形内接于半径相等的圆，其中正多边形周长最小的是( )A. B. C. D.4. 如图，已知直线，直线AC和DF分别与直线，，交于点A，B，C和点D，E，若，，则DE的长是( )A.B. 3C. 6D. 95. 方程的解是( )A. ，B. ，C. ，D. ，6. 如图，将点M绕点O顺时针旋转得到点N，则点N在( )A. 第一象限B. 第二象限C. 第三象限D. 第四象限7. 将抛物线向左平移1个单位长度，平移后的抛物线的解析式是( )A. B. C.D.8. 2020年教育部印发了《大中小学劳动教育指导纲要试行》，劳动教育已纳入人才培养过程.某中学加大校园农场建设，为学生提供更多的劳动场所.该农场某种作物2020年的年产量为100千克，2022年的年产量为225千克.设该作物年产量的平均增长率为x，则符合题意的方程是( )A.B.C.D.9. 关于x的一元二次方程，若，则该方程必有一个根是( )A. B. C. D.10. 公元前3世纪，古希腊科学家阿基米德发现了“杠杆原理”：杠杆平衡时，阻力阻力臂=动力动力臂.当用撬棍撬动一块石头时，发现阻力和阻力臂分别为1200N和，关于动力F和动力臂l，下列说法错误的是( )A. F与l的积为定值B. F随l的增大而减小C. 当l为时，撬动石头至少需要400N的力D. F关于l的函数图象位于第一、第三象限11. 若反比例函数的图象经过点，则k的值是______ .12. 如图，在中，弦AB长为8，于C且，则的半径是______ .13. 某林业部门要考察某种幼树在一定条件下的移植成活率，在同样条件下，对这种幼树进行大量移植，并完成统计情况，得到一组统计数据：移植总次数n150035007000900014000成活数m133532036335803712628成活的频率估计该种幼树在此条件下移植成活的概率是______ 结果精确到14. 在半径为1的圆中，圆心角所对的弧长是______ .15. 某足球运动员将足球沿与地面成一定角度的方向踢出，如果不考虑空气阻力，足球飞行的高度单位：与足球飞行的时间单位：之间具有二次函数关系，其部分图象如图所示，则足球从踢出到落地所需的时间是______ .16. 如图，已知内接于，I是的内心.若，则的度数是______ .17. 解方程：18. 如图，在平行四边形ABCD中，点E，F分别在边AD，BC上，且，连接AF，求证：四边形AECF是中心对称图形.19. 已知一元二次方程有两个不相等的实数根，求a的取值范围.20. 如图，将绕点A顺时针旋转得到为锐角，点D与点B对应，连接BD，求证：∽21. 为增强学生爱国意识，激发爱国情怀，某校9月开展了“喜迎二十大、永远跟党走、奋进新征程”主题教育活动，活动方式有：主题征文，书法绘画，红歌传唱，经典诵读.为了解最受学生喜爱的活动方式，现随机抽取若干名学生进行调查，并将调查结果绘制成如下两幅不完整的统计图.根据以上信息，解答下列问题：参与此次抽样调查的学生人数是______ ，扇形统计图中A部分圆心角的度数是______ ；学校从1班，2班，3班，4班中随机选取两个班参加“红歌传唱”的活动，求恰好选中2班和3班的概率.22. 如图，P为外一点，M为OP中点.过点P作的一条切线PQ，且Q为切点尺规作图，保留作图痕迹，不写作法；在的条件下，若，求证：点M在上.23. 如图，一块余料ABCDEF，，，，，，且CD和AF之间的距离为以AF所在直线为x轴，AB长为1个单位长度，建立适当的平面直角坐标系，图中曲线DE恰好是该平面直角坐标系中反比例函数图象的一部分.补全该平面直角坐标系，并写出点B，C，D，E的坐标；李师傅想利用该余料截取一块矩形材料POMN，其中边PQ在AF上点P在点Q的右侧，其余两个顶点M与N分别在线段BC与曲线段DE上，求所截取的矩形材料PQMN面积的最大值.24. 在中，，两条高AD，BE交于点H，F是CH的中点，连接AF并延长交边BC于点如图1，若是等边三角形，①求证：；②求CG的长；如图2，若，，求的面积.25. 已知抛物线与x轴的正半轴交于点A，与y轴交于点当时，抛物线最低点的纵坐标为；当时，抛物线最低点的纵坐标为求a，b的关系式用含b的代数式表示；若，求抛物线的解析式；在的条件下，M为抛物线对称轴上一点，过点M的直线交抛物线于C，D两点，E为线段CD的中点，过点E作x轴的垂线，交抛物线于点探究是否存在定点M，使得总成立.若存在，求出点M的坐标；若不存在，请说明理由.答案和解析1.【答案】C【解析】解：A、该图形不是中心对称图形，因为找不到一个点使图形绕该点旋转后能够与自身重合，不符合题意；B、该图形不是中心对称图形，因为找不到一个点使图形绕该点旋转后能够与自身重合，不符合题意；C、该图形是中心对称图形，符合题意；D、该图形不是中心对称图形，因为找不到一个点使图形绕该点旋转后能够与自身重合，不符合题意．故选：根据中心对称图形的概念和各图的特点求解．本题考查了中心对称图形的概念．如果一个图形绕某一点旋转后能够与自身重合，那么这个图形就叫做中心对称图形，这个点叫做对称中心．2.【答案】B【解析】解：A、守株待兔，是随机事件，故本选项不符合题意；B、水中捞月，是不可能事件，故本选项符合题意；C、水滴石穿是必然事件，故本选项不符合题意；D、百发百中，是随机事件，故本选项不符合题意；故选：根据事件发生的可能性大小判断．本题考查的是必然事件、不可能事件、随机事件的概念，必然事件指在一定条件下，一定发生的事件．不可能事件是指在一定条件下，一定不发生的事件，不确定事件即随机事件是指在一定条件下，可能发生也可能不发生的事件．3.【答案】A【解析】解：随着圆内接正多边形边数的增加，它的周长和面积越来越接近圆周长和圆面积．故选：根据圆内接多边形的周长小于圆周长，再利用夹逼法对即可选择答案．此题主要考查了正多边形与圆，关键是知道圆内接多边形的周长小于圆周长．4.【答案】C【解析】解：直线，，，，，解得：，故选：根据平行线分线段成比例定理得出比例式，再把和代入，即可求出答案．本题考查了平行线分线段成比例定理，能正确根据平行线分线段成比例定理得出比例式是解此题的关键．5.【答案】C【解析】解：，或，解得：或，故选：由已知等式知这两个因式的值就都有可能为0，这就能得到两个一元一次方程，再分别求解可得．本题主要考查解一元二次方程的能力，熟练掌握解一元二次方程的几种常用方法：直接开平方法、因式分解法、公式法、配方法，结合方程的特点选择合适、简便的方法是解题的关键6.【答案】C【解析】解：将点M绕点O顺时针旋转得到点N，如图，故将点M绕点O顺时针旋转得到点N，则点N在第三象限，故选：作出旋转后的图形，即可得到结论．本题主要考查了旋转的性质，根据题意画出图形是解题关键．7.【答案】B【解析】解：将抛物线向左平移1个单位长度后的抛物线解析式为：，即故选：直接根据“上加下减，左加右减”的原则进行解答．本题考查的是二次函数的图象与几何变换，熟知函数图象平移的法则是解答此题的关键．8.【答案】B【解析】解：根据题意得故选：利用该农场某种作物2022年的年产量=该农场某种作物2020年的年产量该作物年产量的平均增长率，即可得出关于x的一元二次方程，此题得解．本题考查了由实际问题抽象出一元二次方程，找准等量关系，正确列出一元二次方程是解题的关键．9.【答案】A【解析】解：由题意，一元二次方程满足且，当时，代入方程，有；综上可知，方程必有一根为故选：由满足且，可得：当时，有故问题可求．此题考查了一元二次方程的解，方程的解即为能使方程左右两边相等的未知数的值．10.【答案】D【解析】解：阻力阻力臂=动力动力臂，阻力和阻力臂分别为1200N和，动力F和动力臂l的关系式为：，即F与l的积为定值，故选项A不合题意；，，故F随l的增大而减小，故此选项B不合题意；当l为时，撬动石头至少需要的力，故此选项C不合题意；，关于l的函数图象位于第一象限，故选项D符合题意．故选：根据杠杆平衡条件：动力动力臂=阻力阻力臂，代入有关数据计算即可．此题主要考查了反比例函数的应用，正确得出反比例函数解析式是解题关键．11.【答案】6【解析】解：把代入函数中，得，解得故答案为：将点代入解析式可求出k的值．主要考查了用待定系数法求反比例函数的解析式．先设，再把已知点的坐标代入可求出k 值，即得到反比例函数的解析式．12.【答案】5【解析】解：连接OA，弦AB长为8，，于C且，故答案为：连接OA，即可得直角三角形，根据题意，即可求出OA的长度．本题主要考查了垂径定理、勾股定理，解题的关键在于连接OA，构建直角三角形．13.【答案】【解析】解：幼树移植数14000棵时，幼树移植成活的频率为，估计幼树移植成活的概率为，精确到，即为故答案为：大量重复试验时，事件发生的频率在某个固定位置左右摆动，并且摆动的幅度越来越小，根据这个频率稳定性定理，可以用频率的集中趋势来估计概率，这个固定的近似值就是这个事件的概率．本题考查了用大量试验得到的频率可以估计事件的概率，大量反复试验下频率稳定值即概率．14.【答案】【解析】解：圆心角为，，故答案为：根据弧长公式：计算即可．此题主要考查了扇形的弧长计算公式，正确的代入数据并进行正确的计算是解题的关键．15.【答案】【解析】解：设飞行的高度单位：与足球飞行的时间单位：之间的二次函数关系为，将，代入得：，解得，，在中，令得，解得或，足球从踢出到落地所需的时间是，故答案为：设飞行的高度单位：与足球飞行的时间单位：之间的二次函数关系为，用待定系数法求出，令即可解得答案．本题考查二次函数的应用，解题的关键是读懂题意，求出二次函数的函数关系式．16.【答案】【解析】解：如图所示：为的内心，，，，，，，解得：故答案为：根据三角形内心定义进行角的和差计算即可．本题考查了圆周角定理、三角形的内心、三角形外心，熟练掌握圆周角定理是解题的关键．17.【答案】解：，，；；，，【解析】本题主要考查了解一元二次方程的解法．要会熟练运用公式法求得一元二次方程的解．此法适用于任何一元二次方程．公式法的步骤：①化方程为一般形式；②找出a，b，c；③求；④代入公式18.【答案】证明：四边形ABCD是平行四边形，，，四边形AECF是平行四边形一组对边平行且相等的四边形是平行四边形，四边形AECF是中心对称图形．【解析】由平行四边形的性质得出，根据“一组对边平行且相等的四边形是平行四边形”推出四边形AECF是平行四边形，即可得出结论．本题考查了平行四边形的判定与性质，熟练掌握平行四边形的判定与性质是解题的关键．19.【答案】解：方程是一元二次方程，，一元二次方程有两个不相等的实数，，解得，的取值范围是且【解析】根据根的判别式建立关于a的不等式，注意a的数值不能为0，由此两者结合得出答案即可．本题考查了根的判别式，一元二次方程根的情况与判别式的关系：方程有两个不相等的实数根；方程有两个相等的实数根；方程没有实数根．20.【答案】解：绕点A旋转得到，，，，，∽【解析】由旋转的性质可得，，，即可得结论．本题考查了相似三角形的判定，掌握旋转的性质是解题的关键．21.【答案】【解析】解：参与此次抽样调查的学生人数是：人，A类的人数有：人，扇形统计图中A部分圆心角的度数是：；故答案为：40；将1班，2班，3班，4班分别记为1，2，3，4，根据题意，列表如下：12341234如表，所有可能发生的结果共有12种，并且它们发生的可能性相等，其中恰好选中2班和3班的有2种，恰好选中2班和3班的概率是根据C部分的人数和所占的百分比，求出调查的总人数，再用乘以A部分的人数所占的百分比，即可得出扇形统计图中A部分圆心角的度数；根据题意画出树状图，得出所有等可能的情况数，找出恰好选中2班和3班的情况数，然后根据概率公式即可得出答案．此题考查的是用列表法或树状图法求概率．列表法可以不重复不遗漏的列出所有可能的结果，适合于两步完成的事件；树状图法适合两步或两步以上完成的事件．用到的知识点为：概率=所求情况数与总情况数之比．22.【答案】解：如下图：PQ即为所求；证明：连接OQ，与相切于点，，设，则是OP的中点，，，，，，，，点M在上．【解析】根据直角三角形的判定方法画图；根据到直线的距离等于半径的的点在圆上．本题考查了复杂作图，掌握圆的切线的判定定理是解题的关键．23.【答案】解：如图所示：根据题意，得，，，；设直线BC的解析式为，将，代入，得解得直线BC的解析式为，设，四边形MNPQ是矩形，轴，，，，开口向下，且对称轴为直线，，当时，最大，最大值为13，所截取的矩形材料MNPQ面积的最大值为【解析】由题意可知得，，，；先求出直线BC的解析式，设，根据题意用关于m的二次函数表示出矩形POMN 的面积，再利用二次函数的性质可得答案．本题考查了动点函数的图象，反比例函数以及二次函数的性质，待定系数法求函数解析式等知识，表示出矩形的面积，利用二次函数的性质求最值是解题的关键．24.【答案】①证明：是等边三角形，，，，，，，，，在中，，，；②解：过点H作，交AG于点M，，，是CH的中点，，≌，，，，，，，∽，，，是等边三角形，，，，的长为；解：过点H作，交AG于点N，，，是CH的中点，，≌，，，，，是的中位线，，，，，，，，，，，，，，，，∽，，，解得：或舍去，的面积，的面积为【解析】①利用等边三角形的性质可得，，再利用等腰三角形的三线合一性质可得，从而可得，然后在中，利用含30度角的直角三角形的性质可得，从而利用等量代换即可解答；②过点H作，交AG于点M，利用平行线的性质可得，，再根据线段中点的定义可得，从而可得≌，进而可得，然后证明A字模型相似三角形∽，从而利用相似三角形的性质可得，进而可得，最后根据等腰三角形的三线合一性质可得，从而进行计算即可解答；过点H作，交AG于点N，利用平行线的性质可得，，再根据线段中点的定义可得，从而可得≌，进而可得，然后利用平行线分线段成比例的推论可得，从而可得HN是的中位线，进而可得，再根据等量代换可得，最后求出，，再证明∽，从而利用相似三角形的性质可求出AD的长，进而利用三角形的面积公式，进行计算即可解答．本题考查了全等三角形的判定与性质，相似三角形的判定与性质，等边三角形的性质，根据题目的已知条件并结合图形添加适当的辅助线是解题的关键．25.【答案】解：由题意得，，，；，，，，，，，舍去，，；存在，使得总成立，理由如下：设，，，当时，，设直线CD的解析式为，，，，当时，，，当时，，，，，【解析】可推出，，，进一步得出结果；可得出点，从而得出，结合，从而得出结果；先由逆向探讨出点M的坐标，再反过来得出在该条件下，总成立．设点C和点D的坐标，从而得出CD的函数关系式和中点E的坐标，从而得出点F的坐标，进而表示出EF和CD的长，计算出等于本题是二次函数的综合题，考查了求二次函数的解析式，求一次函数的解析式等知识，解决问题的关键是设点的坐标，表示出有关线段的长．。

福州市第一学期九年级期末质量检测语文考试卷初三语文考试卷与考试题姓名:_____________ 年级:____________ 学号:______________【题目】一、积累运用(40分) 给加点字注音，根据拼音写汉字。

A.诘()难B.咬文嚼()宇C.chī()笑D.kè()尽职守参考答案：A.jiéB.jiáoC.嗤D.恪（本题4分）【题目】阅读下面一段文字，完成(l)——(2)题。

2013年12月14 日晚间，“嫦娥”携带着“玉兔”，安全平稳着陆月面。

古往今来，给无数中国人带来美好情思遐想的广寒宫今夜不再清虚 (娴静 孤僻 寂寥)。

中国人千百年来期盼登月的梦想，终于由“嫦娥”变成现实。

此刻，中国航天人不会忘记，他们迈出的每一步，无论是外部环境还是自身科研能力的修炼，也是在突破层层阻力的背景下换来的。

(1)从括号中选择恰当的词语填在横线上。

(2分)答：(2)文中画线句子有语病，请写出修改意见。

(2分)答：参考答案：1）寂寥（2）“无论……，也……”。

改为“无论……，都……。

”（关联词搭配不当）（本题4分）【题目】下面句中加点词语的解释，完全正确的一项是( )。

”b”:”卒中往往语(常常)王侯将相宁有种乎(难道),将军宜枉驾顾之(屈尊)是以先帝简拔以遗陛下(给予),胡不见我于王(为什么)所识穷乏者得我与(得到),搜于国中三日三夜(国家)子非鱼，安知鱼之乐(怎么)参考答案：2（本题3分）【题目】默写。

(1)过尽千帆皆不是， 。

肠断白频洲。

(2) ，西北望，射天狼。

(3) ，载不动许多愁。

(4)万钟则不辩礼义而受之， ！(5)陛下亦宜自谋，以 ， 。

(6)无意苦争春，一任群芳妒。

， 。

(7)辛弃疾在《破阵子·为陈同甫赋壮词以寄之》中以“ ， 。

”表达了他收复河山、建功立业的理想。

(8) 王维《使至塞上》中“大漠孤烟直，长河落日圆”的名句，使我们联想到范仲淹《渔家傲·秋思》中描写边城冷落荒凉景色的句子：“ ，。

2021-2022学年福建省福州市九年级（上）期末数学试卷一、选择题（本大题共10小题，共40.0分）1.下列图形是中心对称图形的是()A. B. C. D.2.在下列事件中，必然事件是()A. 购买一张体育彩票，中奖B. 随意翻到一本书的某页，这页的页码是奇数C. 射击运动员射击一次，命中靶心D. 任意画一个圆的内接四边形，其对角互补3.关于x的一元二次方程x2+2021x+2022=0的根的情况是()A. 没有实数根B. 只有一个实数根C. 有两个相等的实数根D. 有两个不相等的实数根4.已知正多边形的半径与边长相等，那么正多边形的边数是()A. 4B. 5C. 6D. 85.二次函数y=x(x+2)图象的对称轴是()A. x=−1B. x=−2C. x=2D. y轴6.为创建文明城市，某区2020年投入绿化资金800万元，2022年计划投入960万元，设每年投入资金的平均增长率为x，则下列符合题意的方程是()A. 800(1+2x)=960B. 800(1+x)=960C. 800(1+x)2=960D. 800+800(1+x)+800(1+x)2=9607.下列说法正确的是()A. 有一个角等于100°的两个等腰三角形相似B. 两个矩形一定相似C. 有一个角等于45°的两个等腰三角形相似D. 相似三角形一定不是全等三角形8.已知点A(a,y1)，B(a+1,y2)在反比例函数y=a2+1x(a是常数)的图象上，且y1<y2，则a的取值范围是()A. a<0B. a>0C. 0<a<1D. −1<a<09.如图，△ABC内接于⊙O，∠ABC=90°，D是ACB⏜的中点，连接CD，BD交AC于点E，若∠ACD=55°，则∠AED的度数是()A. 80°B. 75°C. 67.5°D. 60°10.已知二次函数y=ax2+bx+c的图象过点A(2,n)，当x>0时，y≥n，当x≤0时，y≥n+1，则a的值是()A. −1B. −14C. 14D. 1二、填空题（本大题共6小题，共24.0分）11.如果两个相似三角形的周长比为2：3，那么这两个相似三角形的面积比为______．12.一个质地均匀的小正方体，6个面分别标有数字1、2、2、3、5、5.若随机投掷一次小正方体，则朝上一面的数字是5的概率为______．13.若m是方程2x2−3x−3=0的一个根，则4m2−6m+2015的值为______．14.用半径为4，圆心角为90°的扇形纸片围成一个圆锥的侧面，则这个圆锥的底面圆半径为______．15.如图，在Rt△AOB中，O为坐标原点，∠AOB=90°，∠BAO=60°，若点A在反比例函数y=−2x的图象上运动，则点B所在的函数解析式为______．16.如图，D是等边三角形ABC内一点，∠ADB=90°，将△ABD绕点A旋转得到△ACE，延长BD交CE于点G，连接ED并延长交BC于点F.则下列结论：①△ADE是等边三角形；②四边形ADGE是轴对称图形；③AC，EF互相平分；④BF=CF.其中正确的有______.(填序号)三、计算题（本大题共1小题，共8.0分）17.解方程：x2+6x−1=0．四、解答题（本大题共8小题，共78.0分）18.如图，在△ABC中，点D、E、F分别在AB、BC、AC边上，DE//AC，∠DEF=∠A.求证：△BDE∽△EFC．19.如图，已知反比例函数y=k图象的一支经过点A(2,3)和点B(点B在点A的右侧)，作xBC⊥y轴，垂足为C，连接AC，AB．(1)求反比例函数的解析式；(2)若△ABC的面积为7，求B点的坐标．20.交通拥堵是城市发展中的顽疾．某市从A地到火车站共有两条道路L1和L2，现准备对其中耗时多的一条道路进行拓宽改造，为此市交通局对从A地到火车站的行驶时间进行调查．现随机抽取驾车从A地到火车站的100人进行调查，调查结果如下：行驶时间(10～2020～3030～4040～5050～60分钟)驾行L1的人51420183数驾行L2的人1416181数(1)抽取行驶时间在50～60分钟到达火车站的人进行座谈，从这4人中随机抽取2人现场填写问卷，请用列表或画树状图法求这2人是选择不同道路到火车站的概率；(2)以A地到达火车站所用时间的平均值作为决策依据，试通过计算说明，从A地到火车站应选择哪条道路进行拓宽改造？21.如图，PA，PB是圆的切线，A，B为切点．(1)求作：这个圆的圆心O(用尺规作图，保留作图痕迹，不写作法和证明)；(2)在(1)的条件下，延长AO交射线PB于C点，若AC=4，PA=3，请补全图形，并求⊙O的半径．22.为预防新冠病毒，口罩成了生活必需品，某药店销售一种口罩，每包进价为6元，日均销售量y(包)与每包售价x(元)满足y=−5x+80，且10≤x≤16．(1)每包售价定为多少元时，药店的日均利润最大？最大为多少元？(2)当进价提高了a元，且每包售价为13元时，日均利润达到最大，求a的值．23.如图，将矩形ABCD绕点A顺时针旋转，使点E落在BD上，得到矩形AEFG，EF与AD相交于点H，连接AF．(1)求证：BD//AF；(2)若AB=1，BC=2，求AH的长．24.如图，△ABC内接于⊙O，弦BD⊥AC，垂足为E，点D，点F关于AC对称，连接AF并延长交⊙O于点G．(1)连接OB，求证：∠ABD=∠OBC；(2)求证：点F，点G关于BC对称；(3)若BF=OB=2，求△ABC面积的最大值．x2．25.已知直线y1=kx+1(k>0)与抛物线y2=14(1)当−4≤x≤3时，函数y1与y2的最大值相等，求k的值；x2交于A，B两点，与y轴交于F点，点(2)如图①，直线y1=kx+1与抛物线y2=14C与点F关于原点对称，求证：S△ACF：S△BCF=AC：BC；x2先向上平移1个单位，再沿直线y1=kx+1的方向移动，使向(3)将抛物线y2=14右平行移动的距离为t个单位，如图②所示，直线y1=kx+1分别交x轴，y轴于E，F两点，交新抛物线于M，N两点，D是新抛物线与y轴的交点，当△OEF∽△DNF时，试探究t与k的关系．答案和解析1.【答案】B【解析】解：A.不是中心对称图形，故本选项不符合题意；B.是中心对称图形，故本选项符合题意；C.不是中心对称图形，故本选项不符合题意；D.不是中心对称图形，故本选项不符合题意．故选：B．根据中心对称图形的定义进行判断，即可得出答案．本题考查了中心对称图形的概念，判断中心对称图形是要寻找对称中心，旋转180度后与原图重合．2.【答案】D【解析】解：A.购买一张体育彩票，中奖，这是随机事件，故A不符合题意；B.随意翻到一本书的某页，这页的页码是奇数，这是随机事件，故B不符合题意；C.射击运动员射击一次，命中靶心，这是随机事件，故C不符合题意；D.任意画一个圆的内接四边形，其对角互补．这是必然事件，故D符合题意；故选：D．根据随机事件，必然事件，不可能事件的特点判断即可．本题考查了随机事件，熟练掌握随机事件，必然事件，不可能事件的特点是解题的关键．3.【答案】D【解析】解：关于x的一元二次方程x2+2021x+2022=0，∵b2−4ac=20212−4×1×2022=4084441−8088=4076353>0，∴方程有两个不相等的实数根．故选：D．求出方程根的判别式的值，判断方程解的情况即可．此题考查了根的判别式，熟练掌握一元二次方程根的判别式与方程解的情况之间的关系是解本题的关键．4.【答案】C【解析】解：∵正多边形的半径与边长相等，∴正多边形的相邻的两条半径与一条边围成一个正三角形，∴正多边形的中心角为60°∵正多边形所有中心角的和为360°，∴360°÷60°=6，∴正多边形的边数为6，故选：C．根据正多边形的半径与边长相等，可知正多边形的相邻的两条半径与一条边围成一个正三角形，由此求出其中心角的度数，进而求出正多边形的边数．本题考查了正多边形的计算，解决此题的关键是正确的理解正多边形的有关概念，并组成直角三角形求有关线段的长或角的度数，体现了转化思想．5.【答案】A【解析】解：∵二次函数的解析式为：y=x(x+2)，∴此抛物线与x轴的交点为(0,0)，(−2,0)，=−1．∴抛物线的对称轴为直线x=0−22故选：A．先根据二次函数的解析式求出函数图象与x轴的交点，再根据两交点关于对称轴对称即可得出结论．本题考查的是二次函数的性质，熟知二次函数的交点式是解答此题的关键．6.【答案】C【解析】解：每年投入资金的平均增长率为x，根据题意得，800(1+x)2=960，故选：C．根据题意得到关系式为：2020年绿化投入的资金×(1+年平均增长率)2=2022年绿化投入的资金，把相关数值代入求得合适的解即可．本题考查了一元二次方程的应用；得到2年后所需资金的关系式是解决本题的关键．7.【答案】A【解析】解：A、有一个角等于100°的两个等腰三角形相似，因为100°只能是等腰三角形的顶角，所以这两个等腰三角形相似，正确，本选项符合题意；B、两个矩形一定相似，错误，边不一定成比例，本选项不符合题意；C、有一个角等于45°的两个等腰三角形相似，错误，45°角不一定是对应角，本选项不符合题意；D、相似三角形一定不是全等三角形，相似比为1时，是全等三角形，本选项不符合题意．故选：A．根据相似图形的定义一一判断即可．本题考查相似图形，全等三角形的判定等知识，解题的关键是理解相似图形的定义，属于中考常考题型．8.【答案】D【解析】解：∵k=a2+1>0，∴反比例函数y=a2+1(a是常数)的图象在一、三象限，在每个象限，y随x的增大而减小，x①当A(a,y1)，B(a+1,y2)在同一象限，∵y1<y2，∴a>a+1，此不等式无解；②当点A(a,y1)、B(a+1,y2)在不同象限，∵y1<y2，∴a<0，a+1>0，解得：−1<a<0，故选：D．根据反比例函数的性质分两种情况进行讨论，①当点A(a,y1)，B(a+1,y2)在同一象限时，②当点A(a,y1)，B(a+1,y2)在不同象限时．此题主要考查了反比例函数图象上点的坐标特征，分类讨论是解题的关键．9.【答案】B【解析】解：连接AD，⏜的中点，∵D是ACB∴AD⏜=BD⏜，∴AD=BD，∴∠DAB=∠ABD=55°，∴∠ADB=180°−2∠ABD=70°，∵∠ABC=90°，∴∠DBC=90°−∠ABD=35°，∴∠DAC=35°，∴∠AED=180°−∠ADE−∠DAE=180°−70°−35°=75°．故选：B．连接AD，由等腰三角形的性质求出∠DAB=∠ABD=55°，求出∠DAC=35°，由三角形内角和定理可得出答案．此题考查了圆周角定理，圆心角、弧、弦之间的关系以及等腰三角形的性质．正确作出辅助线是解题的关键．10.【答案】C【解析】解：将(2,n)代入y=ax2+bx+c得n=4a+2b+c，∵x>0时，y≥n，∴抛物线开口向上，∵x≤0时，y≥n+1，∴x=0时，y=c=n+1，把c=n+1代入n=4a+2b+c得n=4a+2b+n+1，整理得4a+2b=−1，∵x>0时，y≥n，∴抛物线顶点纵坐标为y=n，把x=−b2a 代入y=ax2+bx+n+1得y=b24a−b22a+n+1=n，∴b24a=1，即b2=4a，∴4a+2b=b2+2b=−1，解得b=−1，∴a=b24=14．故选：C．将(2,n)代入求出a，b，c与n的关系，由当x>0时，y≥n，当x≤0时，y≥n+1可得抛物线开口向上，顶点纵坐标为n，c=n+1，进而求解．本题考查二次函数的性质，解题关键是掌握二次函数与方程及不等式的关系．11.【答案】4：9【解析】解：因为两个相似三角形的周长比为2：3，所以这两个相似三角形的相似比为2：3，所以这两个相似三角形的面积比为4：9；故答案为：4：9．根据相似三角形周长的比等于相似比，相似三角形面积的比等于相似比的平方解答．本题考查的是相似三角形的性质，相似三角形周长的比等于相似比；相似三角形面积的比等于相似比的平方．12.【答案】13【解析】解：∵一个质地均匀的小正方体有6个面，其中标有数字5的有2个，∴随机投掷一次小正方体，则朝上一面的数字是5的概率=26=13．故答案为：1．3先求出5的总数，再根据概率公式即可得出结论．本题考查的是概率公式，熟知随机事件A的概率P(A)=事件A可能出现的结果数与所有可能出现的结果数的商是解答此题的关键．13.【答案】2021【解析】解：∵m是方程2x2−3x−3=0的一个根，∴2m2−3m−3=0，即2m2−3m=3，∴4m2−6m+2015=2(2m2−3m)+2015=2×3+2015=2021．故答案为：2021．先根据一元二次方程解得定义得到2m2−3m=3，再把4m2−6m+2015变形为2(2m2−3m)+2015，然后利用整体代入的方法计算．本题考查了一元二次方程的解：能使一元二次方程左右两边相等的未知数的值是一元二次方程的解．14.【答案】1【解析】解：设这个圆锥的底面圆半径为r，，根据题意得2πr=90⋅π⋅4180解得r=1，所以这个圆锥的底面圆半径为1．故答案为1．设这个圆锥的底面圆半径为r，利用弧长公式得到2πr=90⋅π⋅4，然后解关于r的方程即可．180本题考查了圆锥的计算：圆锥的侧面展开图为一扇形，这个扇形的弧长等于圆锥底面的周长，扇形的半径等于圆锥的母线长．15.【答案】y=6x【解析】解：分别过A、B作AC⊥y轴于C，BD⊥y轴于D.设A(a,b)．∵点A在反比例函数y=−2的图象上，x∴ab=2．在△OAC与△BOD中，∠AOC=90°−∠BOD=∠OBD，∠OCA=∠BDO=90°，∴△OAC∽△BOD，∴OC：BD=AC：OD=OA：OB，在Rt△AOB中，∠AOB=90°，∠BAO=60°，∴∠ABO=30°，∴OA：OB=1：√3，∴b：BD=a：OD=1：√3，∴BD=√3b，OD=√3a，∴BD⋅OD=3ab=6，又∵点B在第一象限，∴k=6．∴点B所在的函数解析式为y=6，x．故答案为：y=6x如图分别过A、B作AC⊥y轴于C，BD⊥y轴于D.设A(a,b)，则ab=1.根据两角对应相等的两三角形相似，得出△OAC∽△BOD，由相似三角形的对应边成比例，则BD、OD都可用含a、b的代数式表示，从而求出BD⋅OD的积，进而得出结果．本题考查了反比例函数图象上点的坐标特征，待定系数法求函数的解析式，相似三角形的判定和性质，正确的作出辅助线构造相似三角形是解题的关键．16.【答案】①②④【解析】解：∵△ABD绕点A旋转得到△ACE，∴AD=AE，∠BAD=∠CAE，∠ADB=∠AEC=90°，∴∠BAD+∠DAC=∠CAE+∠DAC，即∠BAC=∠DAE=60°，∴△ADE是等边三角形，故结论①正确；如图，连接AG，∵△ADE是等边三角形，∴AD=AE，∵∠ADG=∠AEG=90°，AG=AG，∴Rt△ADG≌Rt△AEG(HL)，∴GD=GE，∠DAG=∠EAG，∵△ADE是等边三角形，∴直线AG垂直平分DE，∴四边形ADGE是一个轴对称图形，故结论②正确；连接AF，∵∠DAC+∠EAC=60°=∠ACB，∴∠EAC≠∠ACB，∴AE与FC一定不平行，∴四边形AFCE一定不是平行四边形，∴AC，EF一定不互相平分，故结论③错误；∵△ADE是等边三角形，∠ADG=90°，∴∠EDG=∠BDF=30°，∴∠ADF=120°，∴∠ADF+∠ABC=180°，∴A，B，F，D四点共圆，∴∠ADG=∠AFB=90°，根据三线合一，得BF=CF，故结论④正确．故答案为：①②④．根据旋转的性质得到AD=AE，∠BAD=∠CAE，得证∠DAE=60°，判断结论①正确；连接AG，利用HL判断结论②；连接AF，证明四边形AFCE一定不是平行四边形；利用四点共圆，证明∠AFB=90°，根据三线合一，得BF=CF．本题考查了旋转的性质，全等三角形的判定与性质，线段的垂直平分线的性质，四点共圆，等腰三角形的三线合一，熟练掌握旋转的性质是解题的关键．17.【答案】解：方程变形得：x2+6x=1，配方得：x2+6x+9=10，即(x+3)2=10，开方得：x+3=±√10，解得：x1=−3+√10，x2=−3−√10．【解析】方程常数项移到右边，两边加上9，利用完全平方公式变形后，开方即可求出解．此题考查了解一元二次方程−配方法，熟练掌握完全平方公式是解本题的关键．18.【答案】证明：∵DE//AC，∴∠BDE=∠A，∠DEB=∠C，∠EFC=∠DEF，∵∠DEF=∠A，∴∠BDE=∠EFC，∴△BDE∽△EFC．【解析】由平行线的性质可得∠BDE=∠A，∠DEB=∠C，∠EFC=∠DEF，可证∠BDE=∠EFC，可得结论．本题考查了相似三角形的判定，掌握相似三角形的判定方法是解题的关键．19.【答案】解：(1)由题意得，k=xy=2×3=6∴反比例函数的解析式为：y=6．x(2)设B点坐标为(a,b)，如图，作AD⊥BC于D，则D(2,b)，∵反比例函数y=6的图象经过点B(a,b)x∴b=6a∴AD=3−6．a∴S△ABC=12BC⋅AD=12a(3−6a)=7，解得a=203，∴b=6203=910∴B(203,910).【解析】(1)把A的坐标代入反比例函数的解析式即可求得；(2)作AD⊥BC于D，则D(2,b)，即可利用a表示出AD的长，然后利用三角形的面积公式即可得到一个关于b的方程求得b的值，进而求得a的值．本题考查了待定系数法求反比例函数的解析式，反比例函数的性质，熟练掌握待定系数法求函数的解析式是解题的关键．20.【答案】解：(1)用列表法表示所有可能出现的结果如下：共有12种可能出现的结果情况，其中两人选择不同路线的有6种，所以这2人是选择不同道路到火车站的概率为612=12；(2)驾行L1的所有人用时的平均数为15×560+25×1460+35×2060+45×1860+55×360=35(分)，驾行L2的所有人用时的平均数为15×140+25×440+35×1640+45×1840+55×140=38.5(分)，∵35<38.5，∴从A地到火车站应选择驾行L2的道路进行拓宽改造．【解析】(1)用列表法表示从驾行L1的3人和驾行L2的1人中任意选择2人，得出所有可能出现的结果，进而求出选择不同道路到火车站的概率；(2)根据加权平均数的计算方法计算出驾行L1、驾行L2的所有人用时的平均数，比较得本题考查列表法或树状图法求简单随机事件发生的概率，列举出所有可能出现的结果情况是解决问题的关键．21.【答案】解：(1)如图，圆心O即为所求；(2)由(1)知：CA⊥PA，∴∠CAP=90°，∵AC=4，PA=3，∴PC=√AC2+PA2=5，∵PA=PB=3，∴BC=PC−PB=2，∵OC=AC−OA=4−OA=4−OB，在Rt△OBC中，根据勾股定理，得OC2=OB2+BC2，∴(4−OB)2=OB2+22，解得OB=3．2∴⊙O的半径为3．2【解析】(1)分别过切点A，B作PA和PB的垂线，交于点O即可；(2)根据勾股定理即可求出⊙O的半径．本题考查作图−复杂作图，切线的性质，等腰三角形的性质等知识，解题的关键是灵活运用所学知识解决问题，属于中考常考题型．22.【答案】解：(1)设药店的日均利润为w元，由题意得：w=(x−6)y=(x−6)(−5x+80)=−5x2+110x−480=−5(x−11)2+∵−5<0，10≤x≤16，∴当x=11时，w有最大值，最大值为125，∴每包售价定为11元时，药店的日均利润最大，最大为125元；(2)由题意得：w=(x−6−a)(−5x+80)=−5x2+(110+5a)x−480−80a，对称轴为x=−110+80a2×(−5)=11+12a，∴11+12a=13，解得：a=4．【解析】(1)设日均毛利润为w，根据日均利润=每包利润×销售量列出函数解析式，再利用二次函数的性质求解即可；(2)根据日均利润=每包利润×销售量列出函数解析式，由日均利润达到最大时每包售价应定为13元得出11+12a=13，解之即可．本题主要考查二次函数的应用，解题的关键是理解题意，从中找到题目蕴含的相等关系，并熟练掌握二次函数的性质．23.【答案】(1)证明：∵将矩形ABCD绕点A顺时针旋转，使点E落在BD上，得到矩形AEFG，∵AE=AB，∴∠AEB=∠ABE，∵∠ABD=∠EAF，∴∠AEB=∠EAF，∴AF//BD；(2)解：∵BD//AF，∴∠DEF=∠AFE，∵∠ADE=∠AFE，∴∠DEF=∠ADE，∴EH=DH，设EH=x，则DH=x，AH=2−x，∵∠HEA=90°，∴x2+12=(2−x)2，解得：x=34，∴AH=2−34=54．【解析】(1)由旋转知AE=AB，得∠AEB=∠ABE，由∠ABD=∠EAF，得∠AEB=∠EAF，从而得出结论AF//BD；(2)由平行线的性质可证EH=DH，设EH=x，则DH=x，AH=2−x，在Rt△AEH中，利用勾股定理即可列出方程解决问题．本题主要考查了矩形的性质，旋转的性质，平行线的判定与性质，勾股定理等知识，利用勾股定理列方程是解题的关键．24.【答案】(1)证明：连接OC，∵BD⊥AC，∴∠AEB=90°，∴∠EAB+∠ABE=90°，∵BC⏜=BC⏜，∴∠BOC=2∠BAC，∵OB=OC，∴∠OBC=∠OCB，∵∠OBC+∠OCB+∠BOC=180°，∴2∠OBC+2∠BAC=180°，∴∠OBC+∠BAC=90°，∴∠OBC=∠ABE，即∠OBC=∠ABD，(2)证明：连接BG，AD，GC，AG交BC于点H，∵点D，F关于AC对称，∴EF=ED，∵BD⊥AC，∴∠AEF=∠AED=90°，又∵AE=AE，∴△AEF≌△AED(SAS)，∴∠EAF=∠EAD，∠AFE=∠ADE，即∠GAC=∠DAC，∵OC⏜=OC⏜，∴∠DAC=∠DBC，∵GC⏜=GC⏜，∴∠GAC=∠GBC，∴∠DBC=∠GBC，⏜∵AB⏜=AB,∴∠ADB=∠BGA，∵∠AFD=∠BFG，∴∠BFG=∠AGB，∴△BHF≌△BHG(AAS)，∴FH=GH，∠BHF=∠BHG=90°，∴点F，点G关于BC对称；(3)解：连接OG，由(2)得△BHF≌△BHG，∴BF=BG，∵BF=OB=2，∴BG=OB=2，∴OB=OG=BG，∴△OBG为等边三角形，∠BOG=30°，∴∠BOG=60°，∠BAC=12第21页，共24页当AG垂直平分BC时，AH最长，此时S△ABC最大，∠BAC=60°，∴△ABC为等边三角形，作OM⊥BC，∴OM=12OB=1，BM=√22−12=√3，∴BC=2√3，∴S△ABC=12×BC×AH=12×2√3×(2+1)=3√3，∴S△ABC最大值为3√3．【解析】(1)连接OC，由∠OBC+∠OCB+∠BOC=180°，得2∠OBC+2∠BAC=180°，由圆周角定理知∠BOC=2∠BAC，从而得到∠OBC+∠BAC=90°，即可证明结论；(2)连接BG，AD，GC，AG交BC于点H，首先利用SAS证明△AEF≌△AED，得∠EAF=∠EAD，∠AFE=∠ADE，再利用AAS证明△BHF≌△BHG，得FH=GH，∠BHF=∠BHG= 90°；(3)首先可知△OBG为等边三角形，得∠BOG=60°，∠BAC=12∠BOG=30°，当AG垂直平分BC时，AH最长，此时S△ABC最大，∠BAC=60°，从而解决问题．本题是圆的综合题，主要考查了圆周角定理，轴对称的性质，全等三角形的判定与性质，等边三角形的判定与性质等知识，综合性较强，要求学生有较强的识图能力，证明△BHF≌△BHG是解题问题的关键．25.【答案】解：(1)∵抛物线y2=14x2的对称轴为y轴，又−4≤x≤3，∴当x=−4时，函数y2有最大值，y2=14x2=14×(−4)2=4．∵k>0，∴函数y1=kx+1随x的增大而增大，∴当x=3时，函数y1的最大值也是4．将x=3，y=4代入y1=kx+1，得4=3k+1．∴k=1；(2)将x=0代入y1=kx+1得y1=1，∴F(0,1)，∵C点与F点关于原点对称，第22页，共24页第23页，共24页 ∴C(0,−1)．依题意设A 点坐标为(m,14m 2)，代入直线y 1=kx +1的解析式，得14m 2=mk +1，解得k =14m −1m ． ∴y 1=(14m −1m )x +1，由{y =(14m −1m )x +1y =14x 2得mx 2−(m 2−4)x −4m =0． 又由x 1+x 2=m −4m ，x 1=m ，得x 2=−4m ， ∴y 2=4m 2．∴B(−4m ,4m 2).分别过A ，B 两点作y 轴的垂线AP 与BQ ，垂足分别为P ，Q ．可得AP =−m ，PC =14m 2+1+1，BQ =−4m ，QC =4m 2+1．∴APBQ=−m −4m =m 24，CP CQ =14m 2+14m 2+1=m 24， ∴AP BQ =CPCQ ．又∠APC =∠BQC =90°，∴△APC∽△BQC ，∴AC BC =AP BQ ，∵S △ACF =12FC ⋅AP ，S △BCF =12FC ⋅BQ ，∴S △ACF ：S △BCF =AC ：BC ；(3)抛物线y 2=14x 2向上平移1个单位后为y 2=14x 2+1，再沿直线y 1=kx +1的方向，向右平移t 个单位，相当于再向上移动了kt 个单位，平移后的抛物线为y =14(x −t)2+第24页，共24页 (1+kt)……①，则点D 的坐标为(0,14t 2+kt +1)，M 点的坐标为(t,1+kt)．∴直线y =kx +1……②，将①②联立并整理，得x 2−2xt −4kx +t 2+4kt =0，∴x 1+x 2=2t +4k ．依题意，得x 1=x M =t ，∴x 2=x N =t +4k ，则点N 的坐标为(t +4k,kt +4k 2+1)．∵△OEF∽△DNF ，∴∠NDF =∠EOF =90°，∴DN ⊥y 轴，∴y D =y N ，∴14t 2+kt +1=kt +4k 2+1．解得t =4k(t =−4k 不合题意，舍去)，即t 与k 的关系式为t =4k ．【解析】(1)当x =−4时，函数y 2有最大值，y 2=14x 2=14×(−4)2=4.当x =3时，函数y 1的最大值也是4.将x =3，y =4代入y 1=kx +1，得4=3k +1，则可得出答案；(2)求出C(0,−1).依题意设A 点坐标为(m,14m 2)，求出点B 的坐标为(−4m ,4m 2).分别过A ，B 两点作y 轴的垂线AP 与BQ ，垂足分别为P ，Q.证明△APC∽△BQC ，由相似三角形的性质得出AC BC =AP BQ ，则得出结论；(3)证明∠NDF =∠EOF =90°，得出DN ⊥y 轴，可证出y D =y N ，则14t 2+kt +1=kt +4k 2+1.整理可得出结论．本题是二次函数综合题，考查了二次函数的图象与性质，一次函数的图象与性质，待定系数法，相似三角形的判定与性质等知识点，熟练掌握相似三角形的判定与性质是解题的关键．。

2013-2０14 真题第一节单项选择。

(共１5小题，每小题1分，满分15分)２1. —Whｅｒe is yｏuｒ motheｒ?一She tｈe ｓupermａrket. She’ｌl ｂe bacｋ in hａlf an ｈｏｕｒ.Ａ. ｇoes tｏ B. haｓ goｎe tｏ C． haｓｂｅen ｔo２2. —Mr. Lｉn. of us finisheｄthe work by noｗ.—Weｌl doｎe, ｃhildrｅn.Ａ. Twｏ－three；ｈas B. Two－third; hａve Ｃ． Twｏ-tｈiｒd s；ｈａve 23．—Hoｗ beautiful yｏur schｏoｌ is!—Yeｓ, it haｓ chaｎged ａｌot I cａme heｒe．Ａ. ｓiｎcｅﻩB． until C. although24.—Musｔ I aｎswｅr tｈe ｑuesｔioｎｉn Engｌish?—No, yoｕ. Yｏu can ａnswer ｉt ｉｎ Chinｅsｅ.A. caｎ’tB. neeｄn’ｔ C． mustn’ｔ25．—Why do you ｌiｋe ｔhis stｏｒy?—Ｂeｃauｓｅ it is so moving ｔhat it ｍakeｓme ﻩ．A. cryﻩB. crｙinｇ C． tｏcｒy26.—Mｉｋe’s going toｈａｖｅ a picnic tｈiｓｗeekend.—Ｙes，Ａ. ｓo ｈａve Ｉﻩ B． so am I C. so do I27.一Ｗhat do ｙｏu thiｎk of the tｒａffic in ｏｕr ciｔy?—Iｔ’ｓﻩtｈan it uｓed ｔo ｂe, buｔｔheｒe’s stｉｌｌ a long wａy ｔo ｇｏ.Ａ. ｇood Ｂ. better C. ｂest２8.—Which ｄo ｙou likｅbｅtter, ｔｅa or cｏffee?—tuB .ﻩI pｒefer tea.A. AｌlB. NeitｈerﻩC. Bｏｔh2９.ﻩ—You shoulｄｙｏur tｅachｅr’s aｄviｃｅif ｙou ｗant to impｒｏve your Ｅngｌisｈ.—Ｔhaｔ sounｄｓ greaｔ.A. hear B． catｃh C．ｆollow30. —is tｈe popｕｌａtion of the U．Ｓ. Ａ?一 I onｌy knoｗ thａt it’s ｔhan Chｉna’s.Ａ．What; ｌessﻩ B． What; ｓmalｌer C. Hoｗ mｕch; ｓmaｌler３１.—Did the tｅaｃｈer ｔeｌl you thｉs afterｎoｏn?—Yes. Wｅ’lｌｇｏ to visｉｔ the Sｃｉeｎce Museuｍ.A. hoｗ to doﻩB. ｗheｒe to ｇoﻩ Ｃ. ｗhａt ｔｏ dｏ32.—Hｏw muｃh difficultｙｄid you hａve thiｓpｒｏblem?—s’tI .ﻩｑuite easy.A. ｓolviｎg; None Ｂ．ｓｏlvｉnｇ；ＡnythiｎｇＣ．to ｓｏlve ； Noｔhing33.一Do ｙoｕｂeｌievｅtheｒe are aliens?—I’m afraid ｎoｔ． I dｏn’t thｉｎk alｉens in space.A. can fｉｎｄB. caｎbe foｕｎｄﻩC． cａn’ｔ bｅfouｎd34.—Ｗhaｔｄid Bob ask yoｕ jｕsｔｎｏw?—He wantｅｄ tｏ know ｈｏw ｌonｇ nehwﻩＩｒeached the cｉnema.A. tｈe film ｈad started B． the ｆiｌm ｗｉll fiｎish C．the fiｌm had been on35.—Did Mr. Ｂrｏwn tell yｏuﻩ?—Ye ｓ. H ｅ ｓaid he w ｅｎｔ th ｅre in ２0１2.A. wh ｅre he spe ｎt h ｉs vacationＢ． ｗh ｅn he traveled to Xi ａｍenC ． how he went to Ta ｉw ａｎ I ｓla ｎd第二节补全对话。

福州市2010—2011学年第一学期期末九年级质量检查数学试卷参考答案及评分标准一、选择题1-5 ABAAB 6-10 DCBBC二、填空题：11. 直线x=7 12. 2 13. ①② 14. 1或3 15.3三、解答题()16.1:4(5 410(7 10÷==解分)分) ())(()16.2:3212224433(4(5(7a b c d====-=--=解，，，依题意得:a+c-bd=3分)分) +1-分) ()()22212171:x420x4420(3 22(52(62(72(8xxxxxx-+=-+-=-=-=∴==解分)分)分)原方程的解是分)分)()()()()()2212117.21231233123445312362743x x x x x x x x x x x x -=-∴-=±-∴-=-=-=--=-∴=解:(分)(分)(分)(分)(分)原方程的解是或228=-(分)18. （1）证明：3604ABCDEF OAB OCD OA OC OAH OCK ∴=∴∠=∠=是正六边形和是等边三角形,(分)(分)由旋转性质可得AOH COK ∠=∠…………………………………………………（5分）()AOH COK ASA ∴∆≅∆…………………………………………………………（6分）（2）由（1）得AOH COK S S ∆∆=………………………………………………………（8分）∴正六边形ABCDEF 与扇形OMN 重叠部分的面积=S 四边形ABCO =2183AOB S ∆=…（10分）19.解：（1）31. ………………………………（5分） （2）方法一：画树状图如下：…………………………（10分）所有可能出现的结果共有9种，其中满足条件的结果有5种。

所以P （所指的两数的绝对值相等）=95……………………………………………（12分） 方法二：列表格如下：1-0 1 1-（1-，1-） （1-，0） （1-，1） 0 （0，1-） （0，0） （0，1） 1（1，1-）（1，0）（1，1）…………………………………（10分）所有可能出现的结果共有9种，其中满足条件的结果有5种. 所以P （所指的两数的绝对值相等）=95……………………………………………（12分） 20.解：设这个相同的百分数是x,依题意可得：………………………………………（1分） 15+15（1+x ）+15（1+x ）（1－x ）=47.4………………………………………………（6分） 整理得x 2－x+0.16=0……………………………………………………………………（7分） 解得：x 1=0.8=80%, x 2=0.2=20%………………………………………………………（10分） 经检验， 80%, 20%均符合题意.答：这个相同的百分数是80%或20%…………………………………………………（12分） 21. （1）证明：当t =2s 时，AD =2OA =5t=10㎝，BE =t=2㎝ ∴AD ＋BE =12㎝=AB ····················（1分） ∴点D 、E 重合，即点E 在⊙O 上···········（2分） 又EF ⊥AD∴⊙O 与EF 相切·························（3分） （2）解：由已知可得△AEF 是等腰Rt △， ∴ EF=AE =12t -，∴DE=DA-EA=5t-（12-t ）=6t-12.第二 次第 一 次在Rt △DEF 中,由三角形面积公式可得,6-12(12)48t t -=1（）2………………………（5分） 解得：124,10t t ==，………………………（6分）答：∴当t=4和10时，△DEF 的面积为48cm 2………………………………（7分）图21-（1） 图21-（2） （3）解：设DEF ∆的面积为S cm 2，①当0<t ≤2时，如图21-（1） DE =126t -，EF=AE =12t -, ∴1S=2(126)(12)t t --=23(7)75t --,…………………………………（8分） ∵二次项系数为3>0，抛物线开口向上. ∴当t<7时, S 随t 的增大而减小, 又∵0<t ≤2,∴ S<72. ………………………………………………………………………（9分） (或写成“当0<t ≤2时，不存在最大值”,也可得分) ②当2<t ≤12时，如图21-（2） DE =612t -，EF=AE =12t -， ∴1S=2(612)(12)t t --=23(7)75t --+，……………………………（10分） ∴当t =7秒时，S 有最大值为75，………（11分） ∵75>72，∴综上所述，当t =7秒时，DEF ∆面积最大，最大值为752cm .…………（12分）22. 解：（1）解法（一）： 由已知可得A 点坐标为（1，0）． ∵对称轴为直线4=x ，∴B 点坐标为（7，0）．……………………………………………………………（1分）由⎪⎪⎩⎪⎪⎨⎧==++=++,37,0749,0c c b a c b a 解得⎪⎪⎪⎩⎪⎪⎪⎨⎧=-==,37,38,31c b a ∴抛物线的解析式为3738312+-=x x y ．………………………………………（3分） 解法（二）：由已知可得A 点坐标为（1，0）． 设抛物线的解析式为k x a y +-=2)4（由⎪⎩⎪⎨⎧=+=+,3716,09k a k a 解得⎪⎩⎪⎨⎧==.3,31b a ∴抛物线的解析式为3)4312--=x y （=3738312+-x x ．………（3分）（2）由3)43137383122--=+-=x x x y （，可得顶点M 的坐标为（4，－3）． ………………………………………………………………………………………（4分） 在Rt △OMN 中，ON =4，MN =3，由勾股定理得OM =5． …………………（5分） （图中确定P 点位置）．…………………………………………………………（6分） ①当圆心在P 1点时，设⊙P 1交y 轴于Q 1点，连接P 1Q 1，过P 1点作P 1D ⊥y 轴， 则P 1C =2CD ， ∵P 1C =5，P 1D =4， 在Rt △P 1CD 中， 由勾股定理得CD =3． ∴CQ 1 =2CD =6， OQ 1 =6－73=311， ∴此时Q 点坐标为（0，－311）．……（8分） ②当圆心在P 2点时，设⊙P 2交y 轴于Q 2点，连接P 2Q 2， 同理可得CQ 2=6， OQ 2 =6+73=325， ∴此时Q 点坐标为（0，325）．…………………………………………………（9分）（3）存在.①当P 1点在∠MON 的平分线上时，过P 1点作P 1E ⊥OM ，设⊙P 1 的半径长P 1N =1r ，则P 1E =1r ，P 1M =3－1r ，根据切线长定理ON =OE =4，∴EM =OM －OE = 5－4=1．在Rt △P 1EM 中， 由勾股定理得：132121+=-r r ）（，解得341=r ．………（10分） P 1点坐标为（4，43-）……………………………………………………………（11分） ②当P 2点在∠MON 邻补角的平分线上时，过P 2点作P 2F ⊥OM ，设⊙P 2的半径长P 2N =2r ，则P 2F =2r ，P 2M =3+2r ，根据切线长定理ON =OF =4， ∴FM =OM +OF = 5+4=9．在Rt △P 2F M 中， 由勾股定理得：2222293+=+r r ）（，解得122=r ．……………………………………（13分） P 2点坐标为（4，12）……………………………（14分）。

2023-2024学年福建省福州市时代中学九年级英语第一学期期末考试模拟试题考生须知：1．全卷分选择题和非选择题两部分，全部在答题纸上作答。

选择题必须用2B铅笔填涂；非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。

2．请用黑色字迹的钢笔或答字笔在“答题纸”上先填写姓名和准考证号。

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Ⅰ. 单项选择1、The show was so that I couldn’t stop laughing.A．sad B．terrible C．funny D．serious2、— My aunt said she called you yesterday morning, but there was no answer.— Oh, we were at home. Maybe my husband with my daughter and me __________ my car in the garden.A．washed B．washing C．was washing D．were washing3、—I love my school. It always tries its best to our needs.—How lucky you are!A．satisfy B．realize C．encourage D．get4、—It's ________ to stick your chopsticks into the food while having dinner.—I'm sorry. I won't do that again.A．kind B．polite C．rude5、Each year a large number of tourists are __________ to Qinghai Lake, which is China's largest saltwater lake. A．attracted B．attended C．accepted D．achieved6、- Look, my father bought me a new iPad.- I don’t think we need too many expensive things though our parents can them.A．allow B．expectC．afford D．take7、— Did you watch the movie Amazing China?—Y es. It’s one of most popular films this year.A．a B．an C．the8、Jack is very smart . He can deal with any problem .A．easily B．slowly C．differently9、Zhang Miman is a great woman scientist is 82 years old in 2018 .A．who B．which C．what10、Problems and worries are normal in life. When we have a lot of worries, someone advises us ________ our parents about them because they have more experience.A．talking to B．to talk to C．talk toⅡ. 完形填空11、Jack is 2 English boy．He wants 3 a friend in China．His eating habits 4 healthy．He 5fruits and vegetables． 6 are his favorite vegetables．He often has fruit salad 7 dinner．He doesn't eat hamburger 8 ice﹣cream．He doesn't want to 9 fat．Next to his home is a clothes store．They sell things at very good 10 ．Today Jack wants to 11 a new sweater．He 12 to the clothes store with his mother．The sweaters in all 13 are 35 each．Jack likes blue very much, 14 he takes a blue one．Do you like 15 ？Do you want to be his friend？You can e﹣mail him 16 Jack8118@1．com．2．A．a B．an C．the3．A．to have B．have C．has4．A．be B．are C．is5．A．like B．dislike C．likes6．A．Bananas B．Apples C．Carrots7．A．for B．with C．to8．A．and B．or C．but9．A．am B．is C．be10．A．stores B．prices C．dollars11．A．see B．think C．buy12．A．goes B．go C．come13．A．sizes B．names C．colors14．A．so B．and C．but15．A．he B．his C．him16．A．in B．at C．forⅢ. 语法填空12、根据短文内容及所给提示，补全文中单词或用所给单词的正确形式填空。

福建省福州市鼓楼区福州屏东中学2023-2024学年英语九年级第一学期期末统考试题请考生注意：1．请用2B铅笔将选择题答案涂填在答题纸相应位置上，请用0．5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。

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Ⅰ. 单项选择1、— What do you think of the film Titanic 2?—, but someone thinks it's .A．Good enough; bored B．Enough good; boringC．Good enough; boring D．Enough good; bored2、Don't watch short videos on KuaiShou (快手）APP all the day, it is funny but _______ all your valuable time. Don't you know that the final exams are drawing near（临近）?A．takes after B．takes down C．takes off D．takes up3、—Excuse me, could you tell me ______?—Sorry, sir. I wasn’t there at that time.A．how did the accident happen B．how the accident happenedC．how does the accident happen D．how the accident happens4、―How was your exam the day before yesterday?―Oh, I couldn't feel . I made few mistakes in it.A．worse B．worst C．better D．best5、I love the book ______ has a _______ ending.A．which, surprising B．which, surprised C．that, surprised D．that, surprise6、Now most families have only one child _____ our country’s one-child policy.A．so B．because C．because for D．because of7、We don't know the love of our parents _______ we become parents ourselves one day.A．untilB．afterC．whenD．since8、--- Dad, i t is said that the Chang’e-4 spacecraft landed on the far side of the moon. Could you tell me __________?-- Sorry. Let’s search for the information on the Internet.A．whether it is the first spacecraft to land on the far side of the moonB．when did the amazing thing happenC．if the spacecraft has done experiments or notD．how long the spacecraft has landed on the far side of the moon9、—Has Mr. Green travelled abroad yet?—Not only Mr. and Mrs. Green but also their daughterabroad twice.A．have gone B．have been C．has gone D．has been10、—The plane is leaving right now, but Jim hasn't arrived yet.—Well, he said he _____here on time.A．came B．would comeC．can be D．will beⅡ. 完形填空11、Father and sonThe other day, I was sitting in the study and working on my website, a cup of tea on the table and old songs from my computer. It was a special pleasure to have such a 1 day after weeks of hiking, snowboarding and going crazy.“Hi dad! Want some orange juice, graybeard?” Coyote yelled (叫喊) to me much louder than 2 “No, just bring me some chips!” I shouted back.One time, when I misheard what he said three times in a row, he 3 that I had become too old and started to hear worse. Since then, yelling at me has become a kind of family joke.Pushing everything to the limit was the basis of Coyote's character. On one hand, it helped him to achieve tasks he had to do on his own, and he did great, making me proud of him. On the other hand, this brought him 4 , as he did not know when to stop. At such moments, I would behave super⁃fatherly, and give him advice and warnings that he usually ignored (忽视). When he wore a green haircut, I would try to convince (说服) him to paint it black. When he got a tattoo (纹身), we had a / an 5 . All these surely drove me mad, and the big fights started. It is strange but when I was a teenager, my father would act exactly the same and it took me a long time to understand him.“Dad, let me show you something,” Coyote said as he was getting back. “Don't get too 6 , ok ay?” I sighed (叹气), because I was almost sure of what I was about to see.When he 7 his T-shirt, I saw a new tattoo: some Buddhist symbol, I guess.Coyote has been interested in Asian culture for a long time.“Control yourself, graybeard,” I said to myself, trying not to yell something like,“Why the hell would you needanother tattoo after you already made that huge first one?”The next moment I realized that my yelling would not 8 anything; the tattoo was already on Coyote's skin.And then I thou ght: “Hey, what if I get a tattoo myself?”1．A．busy B．blue C．strange D．peaceful2．A．needed B．expected C．accepted D．imagined3．A．complained B．realized C．joked D．shouted4．A．tiredness B．honors C．happiness D．troubles5．A．agreement B．argument C．decision D．discussion6．A．mad B．curious C．excited D．nervous7．A．hid B．showed C．lifted D．hung8．A．interrupt B．change C．test D．costⅢ. 语法填空12、Henry was an office 1．(work) in a big city. He worked very hard and enjoyed traveling in his holidays.He usually went to the seaside, but one year he saw 2．advertisement in a newspaper. “Enjoy country life. Spend a few weeks at West Hill Farm. Good food, Fresh air, Horse riding, Walking, Fishing, cheap and interesting.” “This 3．(sound) a good idea,” he thought. “I’ll spend a month at West Hill Farm. I think I can enjoy ho rse riding, walking and fishing. They’ll make a change from 4．(sit) by the seaside and swimming.”He wrote to the farmer. In the letter he said that he would like to spend all of July there. Then on the first day of July, he left 5．West Hill Farm.But four days later, he returned home.“What was wrong 6．West Hill Farm?” his best friend, Ed, asked him. “Didn’t you enjoy country life?” “Country life was very good,” Henry said. “But there was another problem.”“Oh. What?”“Well,” he said, “the first day I was there a sheep died, and we had roast mutton for dinner.”“What’s wrong with that?” Ed asked. “Fresh meat is the best.”“I know, but on the 7．(two) day a cow died, and we had roast beef for dinner.”“How 8．(luck) you are!”“You don’t understand,” Henry said. “On the third day a pig died and we had roast pork for dinner.”“A different meat every day,” Ed said 9．(loud), “and what are you complaining!”“Let me finish,” Henry said. “on the fourth day the farmer 10．(dead), and I didn’t dare (敢) stay for dinn er!”Ⅳ. 阅读理解A13、Would it surprise you to learn that, like animals, trees can communicate with each other and pass on their wealth to the next generation---their young trees?Suzanne Simard, forest ecologist(生态学家) at the University of British Columbia, explains how trees are much more complex(复杂的) than most of us ever imagined. Although Charles Darwin(达尔文) thought that trees are competing for survival of the fittest, Simard and her team have made a new discovery and showed just how wrong he was. In fact, the opposite is true: trees survive through their group work and support, passing around necessary nutrition(营养) such as nitrogen(氮) and carbon “depending on who needs it”.Nitrogen(氮) and carbon are shared through miles of underground fungi (真菌) networks.This makes sure that all trees in the forest ecological system give and receive just the right amount to keep them all healthy. This system works in a very similar way to the networks of neurons (神经元) in our brains, and when one tree is destroyed, it influences all.Simard talks about “Mother trees”. These are usually the largest, oldest plants that on which all other trees depend. These “Mother trees” are connected to all the other trees in the forest by this network of fungi, and may manage the resources of the whole trees and plants in the forest. She explains how these trees pass on the wealth to the next generation, transporting important resources to young trees so they may continue to grow. When humans cut down “Mother trees” without paying attention to these highly complex “tree societies” of the networks on which they feed, we are reducing the chances to save the whole forest.“We didn’t take any notice of it,” Simard says sadly. “Mother trees” move nutrition into the young trees before dying, but we never give them chance. If we could put across the message to the forestry industry, we could make a huge difference towards our environmental protection efforts for the future.1．The underlined sentence “the opposite is true” in Paragraph 2 probably means that trees.A．compete for survivalB．protect their own wealthC．depend on each otherD．provide support for dying trees2．“Mother trees”are very important because they.A．look the largest in size in the forestB．pass on nutrition to young treesC．bring more wealth to humansD．know more about the “tree societies”3．The underlined word “it” in the last paragraph refers to(指代) .A．how “tree societies” workB．how trees grow oldC．how forestry industry developsD．how young trees survive4．We can learn from the passage that .A．trees aren’t as complex as we think.B．Charles Darwin had the same opinion as Simard.C．if “Mother trees” are cut down, they won’t make differen ce to young trees.D．trees can share resources with other ones by the underground fungi networks.B14、One day, a raven(渡鸦）happened to fly past a lake. Looking at the lake, he saw the most beautiful animal he had ever seen. It was a swan(天鹅)and its feathers(羽毛）were as white as snow. The swan was playing with other birds happily, talking and dancing. And it seemed that the other birds all liked to stay with____. When he looked at his own feathers, they were as black as coal. The raven was very angry with the swan. “How can the swan have such wonderful feathers?” said the raven. What should he do with his feathers? He thought it over and over.Then, the raven decided that he also wanted to have white feathers like the swan’s. From that day on, the raven began to live like the swan. He moved his home from the woods to the lake. He also started to eat water plants like the swan. He tried his best to talk and dance with the other birds. The most important was that each day, the raven would wash his feathers, hoping that they would turn white. Even he went to the nearby rivers and ponds to wash his feathers because he thought the water in the lakes was not enough for him to wash them. But no matter how hard he washed his feathers, they remained black.As he ate only water plants, he soon grew thinner and thinner. Not many days later, the raven died.1．The underlined word “ it” in Paragraph 1 refers to ___.A．the raven B．the swan C．the feather D．the water2．Why was the raven angry with the swan?A．His own feathers were as white as snow.B．The swan did not have black feathers like himC．The swan had beautiful white feathersD．The swan lived in the lake with other birds3．Where was the raven’s natural home?A．The lakes B．The ponds C．The woods D．The rivers4．Why did the raven want to live like the swan?A．He wanted to make friends with the swanB．He wanted to see the swan’s white feathersC．He wanted to eat water plantsD．He wanted to become a swan5．Why did the raven wash his feathers every day?A．He thought his feathers would turn white.B．He wanted to drive the other birds awayC．He thought his feathers were dirty.D．He wanted to keep his feathers whiteC15、Selecting a proper summer camp for your child is not an easy task. You have to consider too many factors（因素）. Remember, you are sending your kid to a summer camp not just to let him enjoy himself but also to help him become confident. So you should try to select a summer camp for your kid so that after he returns from the camp, the first thing that he asks you is when you will send him again for camping. Let us see how you can pick the best summer camp for your child.Search the InternetIf you browse（浏览）the Internet, you will find a number of websites of summer camps where you can find all the detailed information about the camps. For example, how much the whole camping will cost, where the camps are, what children can do in the camps and what additional facilities (额外的设施) they can provide. Don't forget to read the comments（评论）of parents who have sent their children to those camps and pay attention to how they find those camps.______________Some camp organizers prefer advertisements in newspapers. Some of the organizers even invite famous people to their camps to communicate with kids. You should keep an eye in the summer camp advertisements in newspapers so that you could pick a suitable one for your kid.Ask for advice from your child's school teachersGo to your kid's school and ask his teachers whether they can give you names of some of the summer camps they consider to be the best.Know the interest of your childWhile searching, you will come across different types of camps. They are organized according to the nature and interest of children like a music camp, a sports camp, etc. So it is very important to know what your child is interested in before picking a summer camp.1．Which of the following can be put on the line before Paragraph 3?A．Place advertisements in newspapers.B．Visit the organizers of summer camps.C．Search for advertisements in newspapers.D．Invite famous people to talk with your kid.2．We can know that in the writer's opinion, 'A．finding a proper summer camp for children is not difficultB．the purpose of a summer camp is not only for children to have funC．what other parents think about a camp on the Internet is not believableD．children usually don't have to go again after returning from a summer camp3．According to the last paragraph, before making the final decision, parents should_______.A．consider the interest of their kidB．rethink if camping is necessaryC．know everything about the campD．know the kid's performance at schoolD16、The first Starbucks coffee shop opened in 1971 in downtown Seattle, Washington，in the United States. It was a small coffee shop that roasted its own coffee beans. The coffee shop’s business did well, and by 1981 there were three more Starbucks stores in Seattle.Things really began to change for the company in 1981. That year, Howard Schultz met the three men who ran Starbucks. Schultz worked in New York for a company that made kitchen equipment. He noticed that Starbucks ordered a large number of special coffee makers, and he was curious about the company. Schultz went to Seattle to see what Starbucks did, and he liked what he saw. He wanted to become part of the company. In 1982, the original（原先的）Starbucks owners hired Schu ltz as the company’s head of marketing.In 1983, Schultz travelled to Italy. The unique atmosphere of the coffee bars there caught his eye. To Schultz, it seemedthat Italians spent their daily lives in three places; home, work, and coffee bars. His experience in Italy gave Schultz a new idea for Starbucks back in Seattle.Schultz created an atmosphere for Starbucks coffee shops that was comfortable, and customers everywhere seemed to like it. Between 1987 and 1992, Starbucks opened 150 new stores—and that was only the beginning. In fact, by the year 2000, three new Starbucks stores opened somewhere around the world every day!Today, Starbucks has thousands of stores, including stores in twenty-six countries. One thing that helps make Starbucks succeed in cities outside the United States is the way Starbucks works with local stores and restaurants. By working together with a store already in the city, Starbucks gets an understanding of customers in the city. This understanding helps Starbucks open stores in the right locations for their customers.1．What is the main idea of this passage?A．How Starbucks has grown B．What Starbucks makesC．Starbucks’ customers D．How Starbucks makes its coffee2．Which is true about Starbucks’ first ten years of business?A．It grew very quickly B．It was a small companyC．It made special coffee makers D．It was run by Howard Schultz3．About how many new Starbucks opened in 1999?A．3 B．150 C．300 D．more than 10004．What helps Starbucks succeed in places outside the United States?A．Opening restaurants in just a few locations each yearB．Only selling locally produced coffee beansC．working with other major coffee-making companiesD．Learning about local customersE17、More and more people believe that technologies are great for learning. Today, such teaching tools as iPads are used in a lot of courses, including language, history and science.Many teachers are supporters of using iPads in language learning. They say that students now have much more time for discussion in the classroom. Instead of spending valuable class time listening to texts or watching teaching videos, students can do this on their own and come to class prepared for discussion.The teachers also say that iPads allow students to learn at their own pace. Some students might listen to a dialogue only once and understand it, so they can save time for doing other things. Other students, however, might need to listen to the same dialogue again and again to understand it. Using iPads is especially helpful to students who are learning alanguage at different paces.The students who are using the new tool in some courses are also happy. They believe that using iPads is a more enjoyable way to learn (such as listening to stories and watching movies). The class has become much more interesting and creative.There are other advantages for students. By using iPads, they can pay more attention to the material and learn more. Teaching notes are stored in their iPads and are easy to find. Some students spend more time studying now. “I can listen to my language material or watch teaching videos on the bus, instead of having to wait until I get home,” a student explained.Many adults complain that technologies such as iPads are doing harm to students. They worry that students might use iPads to download teaching notes and use them to cheat during exams. Some believe that iPads may separate students from each other. If a student spends more time watching videos on an iPad, he will have fewer opportunities to have face-to-face communication with others.However, technologies are already a part of most students’ day-to-day lives. As for cheating, teachers can ask students to hand in their iPads when they take exams. Education needs to make changes with the times as technology is playing an important part. We should look forward to a wonderful future when iPads and other technologies can add a lot to the classroom.1．What does the express0ion “at their own pace” in Paragraph 3 probably mean?A．According to their own timetable. B．Without their teachers’ help.C．Because of their wonderful goals. D．Against their parents’ hope.2．From the passage we can learn that____.A．students with iPads have less discussion in classB．students get more fun from learning with iPadsC．iPads help students save time waiting for busesD．iPads prevent students from cheating in exams3．The writer probably agrees that____.A．teachers can take control of students’ learningB．exam results depend a lot on new technologyC．technology in education has a bright futureD．note-taking is as helpful as video-watching4．Which magazine does the passage probably come from?A．National Geography B．Popular ScienceC．Outdoor Photography D．Entertainment Weekly5．What's the best title of this passage?A．New technology changes learning B．The wonderful future of iPadsC．A more enjoyable way to learn D．How to use iPads properlyF18、Our school’s science festival just ended a few days ago. What interested me most was the time we spent making a car. It was made out of corrugated cardboard (瓦楞纸板), but could still hold a person, as well as move.We were excited about this idea, but we found it hard to make the car. It seemed impossible for a cardboard car to carry someone. Our physics teacher showed us a video. There was some corrugated board shaped like “A” or “W” in the video, it could hold more weight. This gave us the idea to make the car after getting the proper materials (材料).Because there was not much time left for us, we had to finish it as quickly as possible, We talked about how the car should be made and how to test it. I was glad that we were able to work closely with each other. Everyone saw the work as an interesting way to relax. When the car was finally finished, we J all wore a smile on our faces and found that all our work had been worth it, even after spending whole afternoons Working on it.We joined the competition after we finished the car. Though we didn’t win any prizes, we found I something more meaningful than success, we learned new things about physics and learned how to get along with each other.1．The car was made out of ________.A．thick stone B．special glassC．strong wood D．corrugated cardboard2．The writer’s ________ teacher showed them a video to help them make the car.A．maths B．history C．physics D．English3．The writer was glad that they were able to ________.A．win the prizes successfully B．work closely with each otherC．joined the competition together D．find an interesting way to relax4．Which of the following sentences is TRUE?A．The car they made could hold a person and move.B．It was not very hard for them to make the car.C．They spent much money getting proper materials.D．There was enough time for them to make the car.Ⅴ.书面表达19、书面表达假定你是李华，最近你们班就低碳生活方式进行了讨论，你的英国朋友Peppa向你来信询问讨论情况。