电力系统分析第八章讲解
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第八章电力系统不对称故障的分析和计算8-1 简单不对称短路的分析8-2 电压和电流对称分量经变压器后的相位变换8-3 非全相断线的分析8-4 应用节点阻抗矩阵计算不对称故障8-5 复杂故障的计算方法第八章电力系统不对称故障的分析和计算本章主要内容各种简单不对称故障的序分量边界条件复合序网的概念和正序等效定则电压电流对称分量经过变压器后的相位变换利用阻抗矩阵计算不对称故障的原理和方法序网方程(1)(1)(1)fa eq ff fa V E Z I =− (2)(2)(2)fa ff fa V Z I =− (0)(0)(0)fa ff fa V Z I =− (2)fa I (2)ff jX (2)fa V (0)fa I (0)ff jX (0)fa V (1)fa I (1)ff jX (1)fa V (0)fV8-1 简单不对称短路的分析1. 单相(a 相)接地短路—序分量边界条件0, 0(1), 0fa fb fcV I I === 相量表示的边界条件:(1)(2)(0)(1)(2)(0)(1)(2)(0)0002fafa fa fa fb fb fb fb fc fc fc fc V V V V I I I I I I I I =++==++==++= ()对称分量表示的边界条件0faV = fbV fcV faI 0fbI = 0fcI = a bc (1)(2)(0)2(1)(2)(0)2(1)(2)(0)0030fafa fa fa fb fa fa fa fc fa fa fa a V V V VI I I I I I I I αααα=++==++==++= ()以相为参考相(1)(2)(0)(1)(2)(0)0(8-42)fa fa fa fa fa fa V V V I I I ⎫++=⎪⎬==⎪⎭()序分量边界条件:8-1 简单不对称短路的分析1. 单相(a 相)接地短路—联立方程求解0faV = fbV fcV faI 0fbI = 0fcI = a bc (1)(2)(0)(1)(2)(0)0(82)fa fa fa fa fa fa V V V I I I ⎫++=⎪−⎬==⎪⎭ (0)(1)(1)(1)(2)(2)(2)(0)(0)(0) (81) fa f ff fa fa ff fa fa ff fa V V jX I V jX I V jX I ⎫=−⎪⎪=−−⎬⎪=−⎪⎭ (0)(1)(1)(2)(0)(83)()ffa ff ff ff V I j X X X =−++ ()(0)(1)(1)(1)(2)(0)(1)(2)(2)(2)(0)(0)(0) (84)fa f ff fa ff ff fa fa ff fa fa ff fa V V jX I j X X I V jX I V jX I ⎫=−⎪⎪=+⎪−⎬=−⎪⎪=−⎪⎭8-1 简单不对称短路的分析1. 单相(a 相)接地短路—复合序网0faV = fbV fcV faI 0fbI = 0fcI = a bc (1)(2)(0)(1)(2)(0)0(82)fa fa fa fa fa fa V V V I I I ⎫++=⎪−⎬==⎪⎭ (0)(1)(1)(2)(0)(83)()ffa ff ff ff V I j X X X =−++ ()(0)(1)(1)(1)(2)(0)(1)(2)(2)(2)(0)(0)(0) fa f ff fa ff ff fa fa ff fa fa ff fa V V jX I j X X I V jX I V jX I ⎫=−⎪⎪=+⎪⎬=−⎪⎪=−⎪⎭ ——将各序网络在故障端口连接起来所构成的网络(1)fa I (1)ff jX (1)fa V (2)fa I (2)ff jX (2)fa V (0)fa I (0)ff jX (0)fa V (0)fV 8-1 简单不对称短路的分析1. 单相(a 相)接地短路—故障点各相电流电压222(1)(2)(0)(2)(0)(1)22(1)(2)(0)(2)(0)(1)0()(1)()(1)fafb fa fa fa ff ff fa fc fa fa fa ff ff fa V V V V V j X X I V V V V j X X I αααααααααα=⎡⎤=++=−+−⎣⎦⎡⎤=++=−+−⎣⎦ (1)(2)(0)2(1)(2)(0)2(1)(2)(0)fa fa fa fa fb fa fa fa fc fa fa fa I I I I I I I I I I I I αααα=++=++=++ (0)(1)(1)(2)(0)3()0, 0ff faff ff ff fb fcV I I j X X X I I ==++== ()(1)(2)(0)(1)(2)(2)(1)(0)(0)(1), , fa ff ff fa fa ff fa fa ff fa V j X X I V jX I V jX I =+=−=− 8-1 简单不对称短路的分析1. 单相(a 相)接地短路—相量图(1)fa I (1)fb I (1)fc I (2)fa I (2)fc I(2)fb I (0)fa I faI (0)fb I(0)fa I (0)fc I (2)fa I (2)fb I (2)fc I (1)fa I(1)fc I (1)fb I (1)fa I 以为参考相量(1)fa V (1)fb V (1)fc V (2)fa V (2)fc V (1)fa V (2)fa V (0)fa VfcV fbV (2)fb V (0)fa V 0fa V = ()(1)(2)(0)(1)(2)(2)(1)(0)(0)(1)fa ff ff fa fa ff fa fa ff fa V j X X I V jX I V jX I =+=−=− 8-1 简单不对称短路的分析1. 单相(a 相)接地短路—特例分析(I&II)(0)(0(1)(1)(2)(0)(1))(()3)0)1(3Case I >()ff faff ff ff f f f f ff f f V V I j X X X I X jX I X ==⇒=+>+ :(1)(2)(0),ff ff ff X X X ≈:与系统中性点接地情况有关(1)fa V (1)fb V (1)fc V (2)fa V (2)fc V (2)fb V fbV fcV 0fa V = (0)Case II ff X →:短路点靠近中性点直0,接接地点()(1)(2)(0)(1)(2)(2)(1)(1(0)(01)))(0fa ff ff fa f fa a ff fa fa ff fa V j X X I V jX I V V jX I ≈−=−≈=+=− (0)0, 32fa fb fc f V V V V ===(1)(2)(0)2fa ffa V VV ≈≈8-1 简单不对称短路的分析1. 单相(a 相)接地短路—特例分析(III)(1)(2)(0),ff ff ff X X X ≈:与系统中性点接地情况有关(0)faV (0)fbV (0)fcV 0fa V = fbV f cV (0)(0)fa faV V =− 60D(1)fb V(1)fc V (0)Case III ff X →∞:中性点,不接地系统()(1)(2)(0)(1)(2)(2)(1)(0)(0)(1)fa ff ff fa fa ff fa fa ff fa V j X X I V jX I V jX I =+=−=− (0)(0)0, 3fa fb fc f abV V V V V ====(0)(0)(1)(2)(0), 0, fa f fa fa f V V V V V ===− (1)(2)(0)22(1)(2)(0)(1)2(1)(2)(0)(1)=0(1)(1)fa fa fa fa fb fa fa fa fa fc fa fa fa fa V V V V V V V V V V V V V V αααααα=++=++=−=++=− 8-1 简单不对称短路的分析1. 单相(a 相)接地短路—特例分析(IV)(1)(2)(0),ff ff ff X X X ≈:与系统中性点接地情况有关(2)(0)(2)(0)(1)Case IV 12ff ff fa fa fa X X V V V =⇒==− :()(1)(2)(0)(1)(2)(2)(1)(0)(0)(1)fa ff ff fa fa ff fa fa ff fa V j X X I V jX I V jX I =+=−=− (1)fb V (1)fc V (2)fc V (1)fa V (2)fa V (0)fa V fcV fbV (2)fb V 0faV = 120D(0)(1)(1(2)(0))()fff ff ff fa V j X X X I =++ ()(1)(2)(0)(1)(2)(2)(1)(0)(0)(1)(0)(0)(0)231313fa ff ff fa fa ff fa fa ff f fffa V j X X I V jX I V jX I V V V −=+==−==−=− (0)(1)32fb fc fa f V V V V ===8-1 简单不对称短路的分析2. 两相(b 相和c 相)短路—序分量边界条件, 0(1), 0fb fc fa fb fcV V I I I ==+= 相量表示的边界条件:(1)(2)(0)(1)(2)(0)(1)(2)(0)(1)(2)(0)(1)(2)(0)002fb fb fb fc fc fc fa fa fa fb fb fb fc fc fc V V V VV V I I I I I I I I I ++=++++=+++++= ()对称分量表示的边界条件fa V fb fcV V = 0faI = fbI fcI a bc(1)(2)(1)(2)(0)40(8-7)0fa fa fa fa fa V V I I I ⎫=⎪⎪+=⎬⎪=⎪⎭()序分量边界条件:22(1)(2)(1)(2)(0)22(1)(2)(0)()()0()()203fa fa fa fa fa fa fa fa VV I I I I I a I αααααααα−+−=++=++++= ()以相为参考相8-1 简单不对称短路的分析2. 两相(b 相和c 相)短路—联立方程求解(0)(1)(1)(1)(2)(2)(2)(0)(0)(0) (81) fa f ff fa fa ff fa fa ff fa V V jX I V jX I V jX I ⎫=−⎪⎪=−−⎬⎪=−⎪⎭(0)(1)(1)(2)(88)()ffa ff ff V I j X X =−+ (2)(1)(1)(2)(2)(2)(2)(1)(0)(0)(0)(89)0fa fa fa fa ff fa ff fa fa ff fa I I V V jX I jX I V jX I ⎫=−⎪⎪==−=−⎬⎪=−=⎪⎭(1)(2)(1)(2)(0),0(87)0fa fa fa fa fa V V I I I ⎫=⎪⎪+=−⎬⎪=⎪⎭ fa V fb fcV V = 0faI = fbI fcI a bc8-1 简单不对称短路的分析2. 两相(b 相和c 相)短路—复合序网(0)(1)(1)(2)(88)()ffa ff ff V I j X X =−+ fa V fb fcV V = 0faI = fbI fcI a bc(1)(2)(1)(2)(0),0(87)0fa fa fa fa fa V V I I I ⎫=⎪⎪+=−⎬⎪=⎪⎭ (2)(1)(1)(2)(2)(1)(0)(0)(0)(89)0fa fa fa fa ff fa fa ff fa I I V V jX I V jX I ⎫=−⎪⎪==−⎬⎪=−=⎪⎭(1)fa I (1)ff jX (1)fa V (2)fa I (2)ff jX (2)fa V (0)fa I (0)ff jX (0)fa V (0)fV 8-1 简单不对称短路的分析2. 两相(b 相和c 相)短路—故障点各相电流电压(1)(2)(0)(1)(2)(1)2(1)(2)(0)(1)2(1)(2)(0)(1)2222fa fa fa fa fa ff fa fb fa fa fa fa fa fc fa fa fa fa faV V V V V j X I V V V V V V V V V V V V αααα=++===++=−=−=++=−=− (1)(2)(0)22(1)(2)(0)(1)(1)(1)+ 0+ ()33fa fa fa fa fb fa fa fa fa fa fc fb fa I I I I I I I I I j I I I j I αααα=+==+=−=−=−= (2)(1)(0)(1)(2)(2)(1)(0), 0, , 0fa fa fa fa fa ff fa fa I I I V V jX I V =−==== fa V fb fcV V = 0faI = fbI fcI a bc8-1 简单不对称短路的分析2. 两相(b 相和c 相)短路—相量图(1)fa I(1)fb I (1)fc I (2)fa I(2)f c I(2)fb I f bI (1)f a V (1)fc V (1)fb Vfc I(2)f b V(2)fc Vf bV f c V f a V(1)fa I以为参考相量(2)fa V (2)(1)(0)(1)(2)(2)(1)(0), 0, , 0fa fa fa fa fa ff fa fa I I I V V jX I V =−==== 8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—序分量边界条件(1)0, 0fb fc faV V I === 相量表示的边界条件:(1)(2)(0)(1)(2)(0)(1)(2)(0)0002fb fb fb fc fc fc fa fa fa V V V V V V I I I ++=++=++= ()对称分量表示的边界条件faV 0fb fc V V == 0faI = fbI fcI a bc(1)(2)(0)(1)(2)(0)(8-13)04fa fa fa fa fa fa V V V I I I ⎫==⎪⎬++=⎪⎭()序分量边界条件:2(1)(2)(0)2(1)(2)(0)(1)(2)(0)0003fa fa fa fa fa fa fa fa fa V V VV V V I I a I αααα++=++=++= ()以相为参考相8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—联立方程求解(0)(1)(1)(1)(2)(2)(2)(0)(0)(0) (81) fa f ff fa fa ff fa fa ff fa V V jX I V jX I V jX I ⎫=−⎪⎪=−−⎬⎪=−⎪⎭(0)(1)(1)(2)(0)(814)(//)ffa ff ff ff V I j X X X =−+ (0)(2)(1)(2)(0)(2)(0)(1)(2)(0)(815)ff fa fa ff ff ff fa fa ff ff X I I X X X I I X X ⎫=−⎪+⎪−⎬⎪=−⎪+⎭faV 0fb fc V V == 0faI = fbI fcI a bc(1)(2)(0)(1)(2)(0)(8-13)0fa fa fa fa fa fa V V V I I I ⎫==⎪⎬++=⎪⎭(2)(0)(1)(2)(0)(1)(2)(0)ff ff fa fa fa fa ff ff X X V V V j I X X ===+ 8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—复合序网(1)(2)(0)(1)(2)(0)(8-13)0fa fa fa fa fa fa V V V I I I ⎫==⎪⎬++=⎪⎭(0)(1)(1)(2)(0)(//)ffa ff ff ff V I j X X X =+ (2)(0)(1)(2)(0)(1)(2)(0)ff ff fa fa fa fa ff ff X X V V V j I X X ===+ (0)(2)(1)(2)(0)(2)(0)(1)(2)(0)ff fa fa ff ff ff fa fa ff ff X I I X X X I I X X ⎫=−⎪+⎪⎬⎪=−⎪+⎭faV 0fb fc V V == 0faI = fbI fcI a bc(1)fa I (1)ff jX (1)fa V (2)fa I (2)ff jX (2)fa V (0)fa I (0)ff jX (0)fa V (0)fV 8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—故障点各相电流电压(2)(0)(1)(2)(0)(1)(1)(2)(0)30ff ff fa fa fa fa fa fa ff ff fb fcX X V V V V V j I X X V V =++==+== (1)(2)(0)(2)(0)22(1)(2)(0)(1)(2)(0)2(2)(0)2(1)(2)(0)(1)(2)(0)+ 0+ + fa fa fa fa ff ff fb fa fa fa fa ff ff ff ff fc fa fa fa fa ff ff I I I I X X I I I I I X X X X I I I I I X X αααααααα=+=⎛⎞+=+=−⎜⎟⎜⎟+⎝⎠⎛⎞+=+=−⎜⎟⎜⎟+⎝⎠(2)(0)(1)(2)(0)(1)(2)(0)ff ff fa fa fa fa ff ff X X V V V j I X X ===+(0)(1)(1)(2)(0)(//)ffa ff ff ff V I j X X X =+ (0)(2)(1)(2)(0)(2)(0)(1)(2)(0)ff fa fa ff ff ff fa fa ff ff X I I X X X I I X X ⎫=−⎪+⎪⎬⎪=−⎪+⎭8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—相量图(1)fa V (1)fb V (1)fc V (2)fa V (2)fc V (2)fb V (0)fa V faV (1)fa I (2)fa I (0)fa IfcIfbI 0faI = (1)fc I (1)fb I (2)fc I (2)fb I 8-1 简单不对称短路的分析3. 两相(b 相和c 相)短路接地—故障点入地电流(2)(0)(1)(2)(0)(1)(2)(0)ff ff fa fa fa fa ff ff X X V V V j I X X ===+(0)(1)(1)(2)(0)(//)ffa ff ff ff V I j X X X =+ faV 0fb fc V V == 0faI = fbI fcI abceI (2)(0)(1)(2)(0)33ff e fb fc fa fb fc fa fa ff ff X I I I I I I I I X X =+=++==−+ (0)(0)(1)(0)(1)(0)(2)33fe fa ff ff ff ff ff VI I jX X X X X ==++ (0)(2)(1)(2)(0)(2)(0)(1)(2)(0)ff fa fa ff ff ff fa fa ff ff X I I X X X I I X X ⎫=−⎪+⎪⎬⎪=−⎪+⎭8-1 简单不对称短路的分析8-1 简单不对称短路的分析—小结简单不对称短路的分析方法小结¾制定各序网络;根据系统运行方式确定故障口正常电压、各序输入阻抗,建立序网方程;(Chapter 7)¾根据故障情况选取参考相,确定用序分量表示的边界条件;¾由序网方程和序分量边界条件求解故障口电流电压各序分量(复合序网、方程求解等);¾对电流电压各序分量进行综合即可得到故障口的电流和电压相量。