高考仿真模拟卷(一)
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高考仿真模拟试卷(一)(时间:120分钟满分:120分得分:________)第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
A(2025届“皖南八校”高三第一次联考)The Code of Visiting Yellowstone National Park The following regulations have been sorted for your convenience.Emergency Phone: Dial 911Yellowstone is a wilderness filled with natural wonders that also have potential dangers.There is no guarantee of your safety.Regulations are strictly enforced to protect you and the park's resources.WildlifeDo not approach wildlife, no matter how calm they appear.Always obey instructions from park staff on the scene.You must stay at least 100 yards away from bears and wolves and at least 25 yards away from other large animals—bison, elk, bighorn sheep, deer, moose, and coyotes.Do not feed any animal.It harms them and it is illegal.Geothermal (地热的) DangersBoardwalks and trails protect you.You must stay on boardwalks and designated (指定的) trails.Pools may be near or above the boiling temperatures and can cause severe, possibly even deadly burns.●Keep your children close to you at all times; make sure they understand the danger.●Pets are prohibited in thermal areas.●Swimming or bathing in thermal pools or streams is prohibited.Where swimming is allowed, swim at your own risk.●Poisonous gases may exist at dangerous levels.If you feel sick, leave immediately.WeatherYellowstone's weather can change quickly and bring cold temperatures, high winds, rain and falling snow.●Be prepared for changing temperatures, storms, and emergencies.●Carry adequate clothing.Driving●Unless otherwise posted, the top speed throughout the park is 45 mph.●If you see wildlife while driving, do not stop or pause in the roadway.1.What do we know about Yellowstone National Park?A.It allows visitors to feed some animals.B.It gives visitors a free ride in the park.C.It will punish visitors if they bring their pets.D.It not only offers visitors pleasure but also there may be dangers.2.When visiting Yellowstone, what are you advised to do?A.Swim in the designated places.B.Tap those calm animals gently.C.Pull up to take photos of animals.D.Bring some cloths to avoid poisonous gases.3.Why is the text written?A.To explain the facilities of the park.B.To introduce the features of the park.C.To offer some guidance to visit the park.D.To attract more people to visit the park.B(2025届四川省天府名校高三上学期联合质量测评)Imagine a small group of people with a shared passion for the same craft.They all have different skills and approaches, but they come together to share skills, share stories, and share in the joy of making something.Modern maker culture is filling headlines and lab spaces all over the world.The way makers communicate with each other has changed over time.In the past, skills mainly came from personal sitdowns with members of the group.But sometimes a teacher wasn't available, or the one available didn't know how to do the skill others wanted to learn.Today a teacher doesn't even have to be in the same country or occupy the same decade as the students.Thanks to the work of people who take the time to break down and share the details of their craft, an interested individual can learn anything.Guides may range from videos to diagrams and text.Regardless of the media, maker resources are meant to be shared.One of the features of the maker movement is the crossover between different interests.Perhaps a passion for cars and for leathercraft can result in a truly custom interior (定制的内饰).Perhaps a love of knitting (编织) and robotics will result in a tiny—but very mobile—robotic furry cat.And once you have started your creation, finding a community to share with is no longer limited to the people nearby.Modern makers have been sharing videos of their progress online for years, contributing greatly to the rapid spread of the maker movement.As different as the participants might be, they share enthusiasm, support, and a willingness to try.Imagine making a pingpong table together with your makers' team.One group builds the basic frame.Another group takes on the responsibility of painting.You knit the net.There is joy in just giving it a try.It will remind you of childhood creations.Whether you are an experienced programmer or just picking up a hammer for the first time, it is never a bad time to come up with an idea, try something, and share the results.4.How did makers communicate with each other in the past?A.By meeting face to face.B.By asking personal questions.C.By visiting a teacher together.D.By sitting together in a classroom.5.What does the underlined word “crossover” in Paragraph 4 mean?A.Exchange.B.Difference.C.Combination.D.Independence.6.What greatly speeds up the spread of modern maker culture?A.The sharing of videos on the Internet.B.The development of education.C.The increasing willingness to share.D.The increasing number of participants.7.Why does the author mention making a pingpong table in the last paragraph?A.To advise us to start small.B.To inspire some creative ideas.C.To stress the importance of childhood creations.D.To encourage us to join in the maker movement.C(2025届贵州省安顺市高三上学期第一次联考)Holding hands, people jumped into the water, and floated around in Boston's Charles River recently.That is something that would not have been possible years ago because the river was so polluted.In the 1960s, the music group The Standells even sang about the river in their popular song—“Dirty Water”.The swimmers were getting their onceayear chance to cool off from the summer heat in the Charles River.It is called “City Splash”.For a few days each year, the state of Massachusetts allows public swimming on Boston's part of the nearly 130kilometer Charles River.The event is in its fifth year.It is a chance for the nonprofit Charles River Conservancy to show its efforts to build a “swim park”.Their idea is to build floating docks where swimmers can jump safely into the river—without touching the risky bottom.These docks would be in areas where the water quality would be tested repeatedly.Boston is one of the cities hoping to follow the model of Copenhagen, Denmark.That city opened the first of its three floating harbor baths in the early 2000s.On sunny days, people swim in the harbor baths surrounded by tall buildings and cars on the highways.At night, the area is filled with people enjoying music and food.Just recently Paris opened public swimmin g in a oncepolluted canal.New York, London, Berlin and other cities are planning similar features for their waterways.In Boston, the Charles River Conservancy still needs to raise several million dollars.It also needs to get approvals from city, state and federal agencies.The groups spokeswoman S.J.Port, said the__biggest__problem has already been taken care of: The Charles is now one of the cleanest city rivers in America.The U.S.Environmental Protection Agency announced this month that the riverearned a “B” grade for water quality last year—an “A” being the best grade.It means the Charles River met the requirement for swimming 55 percent of the time.8.What is the function of floating docks?A.They are places for swimmers to rest.B.They let swimmers get into the river safely.C.They surround swimmers in a safe area of the river.D.They are used to test the water quality repeatedly.9.Which of the following has set a good example for others in offering floating harbor baths?A.Paris.B.Boston.C.Copenhagen.D.Berlin.10.What does the underlined part “the biggest problem” refer to?A.The pollution of Charles River.B.Lack of money to treat pollution.C.Getting approvals from governments.D.Meeting the requirement of “A” grade.11.What can be inferred from the text?A.The water in Charles River reaches drinking standard.B.People can swim in Charles River at any time.C.This summer is the hottest in Boston.D.Charles River flows through Boston.D(2024年安徽省合肥市巢湖市高考英语模拟试卷)Angel Garcia Crespo is a computer engineer at Carlos Ⅲ University of Madrid in Spain.His group has invented a new way for deafblind people to “watch” TV.The idea for the technology grew out of previous work by his group.The team had already worked on making audiovisual (视听的) materials accessible to people with either vision or hearing disabilities.But the group wanted to help people with both challenges.So they asked some deafblind people what would help.In addition to relying on their sense of touch to communicate, deafblind people can also get and send information with a Braille line.The Braille system uses patterns of raised dots to stand for letters and numbers.A Braille line is an electronic machine with a changeable Braille display.Dots rise up or drop down based on the information sent to the machine.Now the new system changes TV signals to data a Braille line can use.“The key to the system is the possibility of using subtitles (字幕) to collect TV information,”Garcia Crespo explains.“Subtitles travel with the image (影像) and the audio in electromagnetic waves we don't see.But an electronic system can keep those waves.”First,a computer program,or app,pulls out the subtitles and visual descriptions from the broadcast signal.The system then combines the information and changes both into data for Braille.Now another app gets to work, which sends the data out to people's Braille lineson demand.“This is done in real time,in less than a second,” Garcia Crespo says.This lets a deafblind person “watch” TV as it's broadcast.The system will work with various Braille lines,as long as there's a bluetooth connection available.Now,the system is only used in Europe,and it should soon be available in the US.12.What inspired Garcia Crespo's group to work on the new technology?A.Deafblind people's poor life.B.Their pity on the disabled people.C.The challenges they face in work.D.Their group's previous research.13.Why can the electronic system collect TV information?A.It can combine all kinds of broadcast signals.B.It can keep the waves with subtitles travelling.C.It can work together with a variety of Braille lines.D.It can pull out the subtitles and visual descriptions.14.What does the author think of the future of the new technology?A.Challenging. B.Bright.C.Rewarding. D.Hopeless.15.What should be a suitable title for the text?A.New Technology Is Improving Deafblind People's LifeB.A New Braille Line Is Applied to Disabled People's LifeC.A Spanish Group Makes TV Accessible to Blind PeopleD.New Technology Helps Deafblind People “Watch” TV其次节(共5小题;每小题2分,满分10分)依据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
2023年新高考卷仿真模拟卷语文试题含参考答案一、现代文阅读(35分)(一)现代文阅读Ⅰ(本题共5小题,17分)阅读下面的文字,完成1~5题。
材料一:古籍今译是一项在现实生活中发挥广泛作用的工作,近百年来,成果丰硕。
从宏观上讲,它在一定程度上制约或影响上层建筑,使其对经济基础产生反作用,从而调节或改变人的现实生存条件,间接地参与对经济基础的巩固或变革;从细节上看,它以其认识功能影响人的意识,进而影响人的行为,达到影响社会生活的目的。
这类工作不可能像衣食住行那样来得直接,也不具有强制性,它就像杜甫说的春雨那样“随风潜入夜,润物细无声”,潜移默化地浸润人们心田,陶冶情操。
它虽不能与国计民生活动并驾齐驱,但从生存发展的意义上讲,社会是受益于它的。
在翻译方式方法的探索上,清末思想家严复提出的“信、达、雅”的标准,受到人们的推崇。
我们现在沿用“信、达、雅”三个词,并赋予它们以新的含义。
“信”是指忠实地反映原作的内容,包括思想、风格、精神等。
“达”是译文要畅达明白,用现代汉语将原作的内容准确地表达出来。
“雅”是规范、典雅。
雅是有条件的,原作雅,译文才能雅。
“信、达、雅”之间,信是基础,是第一位的,达与雅是第二位的。
没有信,达与雅就失去了基础。
达是信的翅膀,没有达,信也就失去了凭借。
雅是达的发展,没有达,不可能有雅。
今译的过程是一个矛盾运动的过程,这里存在古今汉语表达形式之间的矛盾,原作的思想内容与译者的理解之间的矛盾等。
当译者将原作的内容用规范的现代汉语忠实地、准确地表达出来,达到了信达雅的统一,上述这些矛盾基本上解决了,今译也就完成了。
翻译界历来有直译和意译之说,有人主张直译,有人主张意译,双方进行了长期的争论。
主张直译的人批评意译随意胡译、乱译。
主张意译的人批评直译逐字呆译、死译。
实践证明,直译、意译都是行之有效的今译方法。
直译与意译具有共同性,亦有差异性。
共同性是都要求忠实于原作。
差异性主要表现在方法上,前者强调按原文的结构、语序翻译。
一、现代文阅读(共25分)1. 答案:D解析:根据原文第三段“尽管如此,这种尝试并未得到广泛认可”,可知作者对这种尝试持保留态度。
2. 答案:C解析:根据原文第二段“这些作品在表现手法上往往较为新颖,但内容却相对简单”,可知C选项符合原文描述。
3. 答案:B解析:根据原文第四段“这种小说常常以独特的视角、丰富的想象力吸引读者”,可知B选项正确。
二、古代诗文阅读(共35分)4. 答案:(1)D(2)A解析:根据原文“愿乘长风破万里浪,直挂云帆济沧海”可知,D选项正确;根据原文“遥知兄弟登高处,遍插茱萸少一人”可知,A选项正确。
5. 答案:(1)C(2)B解析:根据原文“文章以‘梦’为线索,通过梦境的描绘,反映了作者对人生的感悟”,可知C选项正确;根据原文“诗中通过‘望岳’、‘归隐’等意象,表达了作者对人生、理想的思考”,可知B选项正确。
三、语言文字运用(共20分)6. 答案:A解析:根据题意,选项A符合语境。
7. 答案:C解析:根据题意,选项C符合语法规则。
8. 答案:D解析:根据题意,选项D符合修辞手法。
四、作文(共60分)题目:青春,我们共同书写答案:青春,是人生中最美好的时光。
在这个阶段,我们拥有无尽的梦想、激情和活力。
正是这些特质,让我们在青春的道路上,不断追求、不断进步。
青春,是我们共同书写的历史。
从校园生活到社会实践,我们携手前行,共同经历了许多难忘的瞬间。
在学习中,我们相互鼓励、共同进步;在活动中,我们团结协作、共同成长。
这些经历,让我们更加坚定信念,勇往直前。
青春,是我们奋斗的舞台。
在这个舞台上,我们挥洒汗水,追求卓越。
无论是学业、事业,还是兴趣爱好,我们都在努力拼搏,追求更高的目标。
正是这种拼搏精神,让我们在青春的道路上,不断超越自我,成就非凡。
青春,是我们感悟人生的起点。
在这个阶段,我们开始思考人生的意义,探索生活的真谛。
我们懂得了珍惜、懂得了付出,懂得了感恩。
这些感悟,让我们在青春的道路上,更加坚定地走向成熟。
2023年新高考卷仿真模拟卷语文试题及参考答案解析一、现代文阅读(35分)(一)现代文阅读一(本题共5小题,19分)阅读下面的文字,完成1至5题。
材料一:中国文学在从古典向现代发生转型变化之际,就在创作中显示了自身的特色。
近代发生的文学变革,虽然以“文界革命”、“诗界革命”和“小说界革命”相标榜,但其创作带有很深的传统文学印记。
五四文学革命,结束了这种新旧杂糅的状态,但新文学最初的创作尝试,仍免不了要经历一个“小脚放大”的蜕变过程。
这期间,所谓中国特色在创作中的最初表现,是从中国文学的母体中带出来的鲜明胎记。
五四文学革命之后,中国文学受外来影响渐多,取法于外渐成一时风气,但新文学并未就此泯灭中国特色。
只要祛除阐释的遮蔽,就不难看出,在这些新式的外衣下,各体文学创作,仍然具有中国文学的特质。
以鲁迅的小说创作为例,笔者曾把鲁迅的小说分为以下几类:承袭古人“发愤”著书的传统,如“忧愤深广”的《狂人日记》;以古仁人之心,关切民痰,悲天惘人,而以写实笔法出之的《祝福》等;直接继承清代讽刺小说的传统,因“哀其不幸,怒其不争”而“冷嘲热讽”的《孔乙己》和《阿Q正传》等;受“诗骚传统”和古代散文影响,如“诗化”“散文化”的《故乡》和《伤逝》等;化用笔记文体,而以“油滑”之笔出之的《故事新编》等。
这些都留有很深的中国文化和中国文学的传统印记。
二十世纪三十年代以后,因为有“革命文学”的提倡和左翼作家的实践,成长期的现代中国文学,在接受传统浸润的同时,又自觉地开发民间资源,汲取民间滋养,逐渐在民族化、民间化的方向上,凝聚自身特色。
到四十年代的根据地、解放区文学,“为中国老百姓所喜闻乐见的中国作风和中国气派”,就成了这期间及此后一个相当长的时期里,文学追求中国特色的主要方向。
李季等人的长篇叙事诗创作、赵树理等人的小说创作,提供了榜样。
他们的作品在改造民间曲艺方面所取得的宝贵经验,是这期间的文学锻造中国特色的主要表现。
同样缘起于根据地、解放区时期,在新中国成立后得到长足发展的“革命历史演义”和“新英雄传奇”创作,是中国特色创作追求的又一重要成果。
2023年新高考卷仿真模拟卷语文试题及参考答案解析一、现代文阅读(35分)(一)现代文阅读一(本题共5小题,19分)阅读下面的文字,完成1至5题。
材料一:从东汉末年到魏晋,意识形态领域内的新思潮即所谓新的世界观人生观和反映在文艺、美学上的同一思潮的基本特征,是什么呢?简单说来,这就是人的觉醒。
它恰好成为从两汉时代逐渐脱身出来的一种历史前进的音响。
在人的活动和观念完全屈从于神学目的论和谶纬宿命论支配控制下的两汉时代,是不可能有这种觉醒的。
文艺和审美心理比起其他领域,反映得更为敏感、直接和清晰一些。
《古诗十九首》以及风格与之极为接近的苏李诗(东汉无名氏文人假托李陵所作的三首抒情诗,及假托苏武所作的四首诗,被人们合称为苏李诗),无论从形式到内容,都开一代先声。
它们在对日常时世、人事、节候、名利、享乐等等咏叹中,直抒胸臆,深发感喟。
在这种感叹抒发中,突出的是一种性命短促、人生无常的悲伤。
这种对生死存亡的重视、哀伤,对人生短促的感慨、喟叹,从建安直到晋宋,从中下层直到皇家贵族,在相当一段时间中和空间内弥漫开来,成为整个时代的典型音调。
他们唱出的都是同一哀伤,同一感叹,同一种思绪,同一种音调。
可见这个问题在当时社会心理和意识形态上具有重要的位置,是他们的世界观人生观的一个核心部分。
这个核心便是在怀疑论哲学思潮下对人生的执着。
在表面看来似乎是如此颓废、悲观、消极的感叹中,深藏着的恰恰是它的反面,是对人生、生命、命运、生活的强烈的欲求和留恋。
而它们正是在对原来占据统治地位的意识形态——从经术到宿命,从鬼神迷信到道德节操的怀疑和否定基础上产生出来的。
正是对外在权威的怀疑和否定,才有内在人格的觉醒和追求。
也就是说,以前所宣传和相信的那套伦理道德、鬼神迷信、谶纬宿命、烦琐经术等等规范、标准、价值,都是虚假的或值得怀疑的,它们并不可信或无价值。
只有人必然要死才是真的,只有短促的人生中总充满那么多的生离死别哀伤不幸才是真的。
2023年普通高等学校招生全国统一考试新高考仿真模拟卷数学(一)一、单选题1.已知集合{}24xA x =<,{}1B =≤,则A B =( )A .()0,2B .[)1,2C .[]1,2D .()0,12.已知复数z 满足()()()1i 12i 1z z +=+-,则复数z 的实部与虚部的和为( ) A .1B .1-C .15D .15-3.()()51223x x -+的展开式中,x 的系数为( ) A .154B .162C .176D .1804.已知1tan 5α=,则2cos 2sin sin 2ααα=-( ) A .83-B .83C .38-D .385.何尊是我国西周早期的青铜礼器,其造形浑厚,工艺精美,尊内底铸铭文中的“宅兹中国”为“中国”一词的最早文字记载.何尊的形状可以近似地看作是圆台与圆柱的组合体,高约为40cm ,上口直径约为28cm ,下端圆柱的直径约为18cm .经测量知圆柱的高约为24cm ,则估计该何尊可以装酒(不计何尊的厚度,403π1266≈,1944π6107≈)( )A .312750cmB .312800cmC .312850cmD .312900cm6.已知()f x 是定义域为R 的奇函数,满足()()2f x f x =-,则()2022f =( ) A .2B .1C .1-D .07.在四棱锥P ABCD -中,ABCD 是边长为2的正方形,AP PD ==PAD ⊥平面ABCD ,则四棱锥P ABCD -外接球的表面积为( )A .4πB .8πC .136π9D .68π38.已知抛物线C :24y x =,O 为坐标原点,A ,B 是抛物线C 上两点,记直线OA ,OB 的斜率分别为1k ,2k ,且1212k k =-,直线AB 与x 轴的交点为P ,直线OA 、OB 与抛物线C 的准线分别交于点M ,N ,则△PMN 的面积的最小值为( )A B C D二、多选题9.已知函数()()1cos 02f x x x ωωω=>的图像关于直线6x π=对称,则ω的取值可以为( ) A .2B .4C .6D .810.在菱形ABCD 中,2AB =,60DAB ∠=,点E 为线段CD 的中点,AC 和BD 交于点O ,则( ) A .0AC BD ⋅= B .2AB AD ⋅= C .14OE BA ⋅=-D .52OE AE ⋅=11.一袋中有3个红球,4个白球,这些球除颜色外,其他完全相同,现从袋中任取3个球,事件A “这3个球都是红球”,事件B “这3个球中至少有1个红球”,事件C “这3个球中至多有1个红球”,则下列判断错误的是( )A .事件A 发生的概率为15B .事件B 发生的概率为310C .事件C 发生的概率为335D .1(|)31P A B =12.对于函数()()32,f x x x cx d c d =+++∈R ,下列说法正确的是( )A .若0d =,则函数()f x 为奇函数B .函数()f x 有极值的充要条件是13c <C .若函数f (x )有两个极值点1x ,2x ,则4412281x x +>D .若2c d ==-,则过点()20,作曲线()y f x =的切线有且仅有3条三、填空题13.已知样本数据1-,1-,2,2,3,若该样本的方差为2s ,极差为t ,则2s t=______. 14.已知圆O :221x y +=与直线l :=1x -,写出一个半径为1,且与圆O 及直线都相切的圆的方程:______.15.已知椭圆()222210x y a b a b+=>>的左顶点为A ,左焦点为F ,过F 作x 轴的垂线在x轴上方交椭圆于点B ,若直线AB 的斜率为32,则该椭圆的离心率为______.16.已知f (x )是偶函数,当0x ≥时,()()2log 1f x x =+,则满足()2f x x >的实数x 的取值范围是______.四、解答题17.已知数列{}n a 是等差数列,1324,,a a a a +成等比数列,56a =. (1)求数列{}n a 的通项公式;(2)设数列11n n a a +⎧⎫⎨⎬⎩⎭的前n 项和为n S ,求证:()221n n S n +<+.18.在ABC 中,内角A ,B ,C 所对的边分别为a ,b ,c ,cos sin cos c B a A b C =-. (1)判断ABC 的形状; (2)若3ab ,D 在BC 边上,2BD CD =,求cos ADB ∠的值.19.如图,在直三棱柱111ABC A B C 中,D 、E 分别是AB 、1BB 的中点,12AA AC CB ==,AB =.(1)求证:1//BC 平面1A CD ;(2)若1BC =,求四棱锥1C A DBE -的体积; (3)求直线1BC 与平面1ACE 所成角的正弦值.20.新高考模式下,数学试卷不分文理卷,学生想得高分比较困难.为了调动学生学习数学的积极性,提高学生的学习成绩,张老师对自己的教学方法进行改革,经过一学期的教学实验,张老师所教的80名学生,参加一次测试,数学学科成绩都在[]50,100内,按区间分组为[)50,60,[)60,70,[)70,80,[)80,90,[]90,100,绘制成如下频率分布直方图,规定不低于80分(百分制)为优秀.(1)求这80名学生的平均成绩(同一区间的数据用该区间中点值作代表);(2)按优秀与非优秀用分层抽样方法随机抽取10名学生座谈,再在这10名学生中,选3名学生发言,记优秀学生发言的人数为随机变量X ,求X 的分布列和期望.21.已知12,F F 分别为双曲线()222210,0x ya b a b-=>>左、右焦点,(P 在双曲线上,且124PF PF ⋅=. (1)求此双曲线的方程;(2)若双曲线的虚轴端点分别为12,B B (2B 在y 轴正半轴上),点,A B 在双曲线上,且()22B A B B μμ=∈R ,11B A B B ⊥,试求直线AB 的方程.22.已知函数()()211e 12x f x a x a x ax a =---+++,()R a ∈.(1)当1a =时,求f (x )的单调区间;(2)当310,e a ⎛⎫∈ ⎪⎝⎭时,求证:函数f (x )有3个零点.参考答案:1.B【分析】化简集合A 和B ,即可得出A B ⋂的取值范围. 【详解】解:由题意在{}24xA x =<,{}1B =≤中,{}2A x x =<,{}12B x x =≤≤ ∴{}12A B x x ⋂=≤< 故选:B. 2.D【分析】根据复数的运算法则求出复数43i 55z -+=,则得到答案.【详解】(1i)(2i 1)(2i 1)z z +=-+-(2i)2i 1z -=-,2i 1(2i 1)(2i)43i 43i 2i 5555z --+-+====-+-, 故实部与虚部的和为431555-+=-,故选:D. 3.C【分析】根据二项式定理可求得()523x +展开式通项,由此可确定12,T T ,结合多项式乘法运算进行整理即可确定x 的系数. 【详解】()523x +展开式的通项公式为:()55155C 2323C rr r r r r rr T x x --+=⋅⋅=⋅; 当1r =时,412523C 240T x x =⨯=;当0r =时,51232T ==;x ∴的系数为24023224064176-⨯=-=.故选:C. 4.A【分析】利用二倍角公式化简为正、余弦的齐次分式,分式上下同除2cos α,代入1tan 5α=可得答案.【详解】2222cos 2cos sin sin sin 2sin 2sin cos αααααααα-=--22111tan 825123tan 2tan 255ααα--===---, 故选:A. 5.C【分析】根据圆柱和圆台的体积公式计算可得结果. 【详解】下端圆柱的体积为:224π91944π⋅=6107≈3cm ,上端圆台的体积为:()22116π1414993⨯+⨯+16π4033=⨯1612663≈⨯6752=3cm , 所以该何尊的体积估计为61076752+=128593cm . 因为12850最接近12859,所以估计该何尊可以装酒128503cm . 故选:C 6.D【分析】根据函数()f x 是定义域为R 的奇函数,且()()2f x f x =-得出函数()f x 是周期为4的周期函数,进而求解.【详解】因为函数()f x 是定义域为R 的奇函数,且()()2f x f x =-, 所以(2)()()f x f x f x +=-=-,所以(4)()f x f x +=, 即函数()f x 是周期为4的周期函数,因为函数()f x 是定义域为R 的奇函数,所以(0)0f =, 因为()()2f x f x =-,所以(2)(0)0f f ==, 又因为202245052=⨯+,所以(2022)(2)0f f ==, 故选:D . 7.C【分析】将该四棱锥的外接球放在一个长方体内,画出图形,利用已知条件找出球心,建立相应的关系式,求出外接球的半径,利用球体表面积公式计算即可. 【详解】由题意将该四棱锥放在一个长方体的中, 如图∴所示:取AD 的中点H ,连接PH ,连接,AC BD 交于1O ,由AP PD =则在等腰PAD 中有:PH AD ⊥,又平面PAD ⊥平面ABCD ,且平面PAD ⋂平面ABCD=AD , 则PH ⊥平面ABCD , 又112AH AD ==, 所以在Rt PAH △中,3PH ===,由底面为正方形ABCD ,所以它的外接圆的圆心为对角线的交点1O , 连接1O H ,则1PH O H ⊥,PAD 外接圆的圆心为2O ,且在PH 上,过点1O ,2O 分别作平面ABCD 与平面PAD 的垂线,则两垂线必交于点O ,点O 即为四棱锥P ABCD -外接球的球心, 且1OO ⊥平面ABCD ,又PH ⊥平面ABCD ,即2O H ⊥平面ABCD , 所以1OO ∥PH ,所以四边形12OO HO 为矩形. 如图∴连接2AO ,则22AO PO =,在2Rt AO H 中,22223O H PH PO PH AO AO =-=-=-,所以()2222222213AO AH HO AO =+=+-,解得253AO =,所以254333O H =-=,所以1243OO O H ==, 在图∴中连接OB ,由112O B BD =所以在1Rt OO B 中,OB ==即四棱锥P ABCD -外接球的半径为R OB ==, 所以四棱锥P ABCD -外接球的表面积为: 221364πR 4ππ9S ==⨯=⎝⎭,故选:C. 8.D【分析】设出A 、B 的坐标,由1212k k =-解得12y y 的值,再分别求出点M 、点N 的坐标,求得||MN 的式子,研究AB l 恒过x 轴上的定点可得点P 的坐标,进而用方法1基本不等式或方法2函数思想求得三角形面积的最小值.【详解】设211(,)4y A y ,222(,)4y B y ,则114k y =,224k y =, ∴12121612k k y y ==- ∴1232y y =-, ∴设OA l :14y x y =,令=1x -得:14y y =-,∴14(1,)M y --,同理:24(1,)N y -- ∴12121212||44||||4||8y y y y MN y y y y --=-+==, 设AB l :x my t =+,221044x my t y my t y x=+⎧⇒--=⎨=⎩ 20m t ∆=+>,124y y m +=,124y y t ,又∴1232y y =-,∴432t -=-,解得:8t =, ∴AB l :8x my =+恒过点(8,0),∴AB l 与x 轴交点P 的坐标为(8,0),即:(8,0)P , ∴点P 到准线=1x -的距离为8+1=9. 方法1:1211||1321||||888y y MN y y -==+≥⨯=1||y =.∴19||9||22PMN S MN MN =⨯=≥△, ∴∴PMN的面积的最小值为2. 方法2:12||||8y y MN -==∴20m ≥∴||MN ≥m =0时取得最小值.∴19||9||22PMN S MN MN =⨯=≥△, ∴∴PMN故选:D. 9.AD【分析】首先将函数()f x 化成一个三角函数,然后根据对称轴公式求得ω的表达式,对整数k 赋值求得结果.【详解】()()1cos sin 26f x x x x ωωωπ=+=+,因为函数()f x 的图象关于直线6x π=对称,所以662k ωπππ+=+π,k ∈Z ,解得26k ω=+,因为0ω>,所以当0k =时,2ω=;所以当1k =时,8ω=. 故选:AD. 10.ABD【分析】以O 为坐标原点可建立平面直角坐标系,利用平面向量数量积的坐标运算依次验证各个选项即可.【详解】四边形ABCD 为菱形,AC BD ∴⊥,则以O 为坐标原点,,OC OD 正方向为,x y 轴,可建立如图所示平面直角坐标系,2AB AD ==,60DAB ∠=,2BD ∴=,OA OC ===()0,0O ∴,()A ,()0,1B -,()0,1D ,12E ⎫⎪⎪⎝⎭,对于A ,ACBD ,0AC BD ∴⋅=,A 正确;对于B ,()3,1AB =-,()3,1AD =,312AB AD ∴⋅=-=,B 正确;对于C ,3122OE ⎛⎫= ⎪ ⎪⎝⎭,()BA =-,31122OE BA ∴⋅=-+=-,C 错误; 对于D ,3122OE ⎛⎫= ⎪ ⎪⎝⎭,3122AE ⎛⎫= ⎪ ⎪⎝⎭,915442OE AE ∴⋅=+=,D 正确. 故选:ABD. 11.ABC【分析】根据题意求出基本事件总数、满足条件的基本事件数,利用古典概型概率公式及条件概率公式求解即可.【详解】由题意7个球中任取3个球的基本事件总数为:37C 35=这3个球都是红球的基本事件数为:33C 1=,所以事件A 发生的概率为:1()35P A =,故A 错误, 这3个球中至少有1个红球的基本事件数为:1221334343C C C C +C 1812131⋅+⋅=++=,所以事件B 发生的概率为:31()35P B =,故B 错误, 这3个球中至多有1个红球的基本事件数为:123344C C C 18422⋅+=+=,事件C 发生的概率为22()35P C =,故C 错误, 因为1()()35P AB P A ==, 所以由条件概率公式得:1()135(|)31()3135P AB P A B P B ===, 故D 正确, 故选:ABC. 12.BCD【分析】对于A :利用奇偶性的定义直接判断;对于B :利用极值的计算方法直接求解;对于C :先求出13c <,表示出244122161692781c x x c +=-+,即可求出;对于D :设切点()00,x y ,由导数的几何意义得到3200025460x x x --+=.设()322546g x x x x =--+,利用导数判断出函数()g x 有三个零点,即可求解.【详解】对于A :当0d =时,()32f x x x cx =++定义域为R .因为()()()()()3232f x x x c x x x cx f x -=-+-+-=-+-≠-, 所以函数()f x 不是奇函数.故A 错误;对于B :函数()f x 有极值⇔ ()f x 在R 上不单调.由()32f x x x cx d =+++求导得:()232f x x x c =++'.()f x 在R 上不单调⇔()f x '在R 上有正有负⇔4430c ∆=-⨯>⇔13c <.故B 正确.对于C :若函数f (x )有两个极值点1x ,2x ,必满足0∆>,即13c <.此时1x ,2x 为2320x x c ++=的两根,所以1212233x x c x x ⎧+=-⎪⎪⎨⎪=⎪⎩. 所以()22212121242293c x x x x x x +=+-=-.所以()()222244222212121242216162293992781cc c x x x xx x c +=+-=--=-+ 对称轴164272329c -=-=⨯,所以当13c <时,()224412216162116116292781932738181c x x c +=-+>⨯-⨯+=. 即4412281x x +>.故C 正确;对于D :若2c d ==-时,()3222f x x x x =+--.所以()2322f x x x '=+-.设切点()00,x y ,则有:()3200002000002203222y x x x y f x x x x ⎧=+--⎪-⎨=+-=⎪-⎩', 消去0y ,整理得:3200025460x x x --+=不妨设()322546g x x x x =--+,则()26104g x x x '=--.令()0g x '>,解得:2x >或13x <-;令()0g x '<,解得: 123x -<<.所以()g x 在1,3⎛⎫-∞- ⎪⎝⎭,()2,+∞上单调递增,在1,23⎛⎫- ⎪⎝⎭上单调递减.所以()()()()()32111119254660333327g x g =-=-----+=>极大值, ()()322225242660g x g ==⨯-⨯-⨯+=-<极小值.所以作出的图像如图所示:因为函数()g x 有三个零点,所以方程3200025460x x x --+=有三个根,所以过点()20,作曲线()y f x =的切线有且仅有3条.故D 正确. 故选:BCD. 13.710##0.7 【分析】根据极差的定义可得()314t =--=,先求出平均数,再从方差,从而可求2s t.【详解】极差()314t =--=,平均数为()()1122315-+-+++=,故方差()()()()()222222114111*********s ⎡⎤=--+--+-+-+-=⎣⎦. 所以21475410s t ==.故答案为:710. 14.()2221x y +-=(答案不唯一)【分析】根据圆的圆心和半径,结合直线和圆的位置关系及两个圆的位置关系计算即可. 【详解】设圆心C 为()00,x y ,由已知圆C 与直线l :=1x -相切, 圆C 与圆O :221x y +=相切,可得0112x ⎧--=,即得0002x y =⎧⎨=⎩或0002x y =⎧⎨=-⎩或0020x y =-⎧⎨=⎩, 且已知半径为1,所以圆的方程可以为: ()2221x y +-=或()2221x y ++=或2221x y故答案为: ()2221x y +-=(答案不唯一) 15.12##0.5【分析】由题意设(),0A a -,2,b B c a ⎛⎫- ⎪⎝⎭,再由232AB b a k c a -==-+结合222a b c =+,即可得出答案.【详解】由题意可得,(),0A a -,(),0F c -,令椭圆()222210x y a b a b +=>>中x c =-,解得:2b y a=±,所以2,b B c a ⎛⎫- ⎪⎝⎭,而2032AB b a k c a -==-+,则2232a c a c a c a a -+==-+, 解得:12e =. 故答案为:12. 16.()(),01,-∞⋃+∞【分析】利用奇偶性和函数的单调性解不等式.【详解】当0x ≥时,()()2log 1f x x +,函数在[)0,∞+上单调递增,∴()(0)0f x f ≥=,又()f x 是偶函数,所以()f x 的值域为[)0,∞+.当0x ≥时,()()2log 1f x x +,不等式()2f x x >()22log 1x x +>,即()22log 10x x+->,设()22()log 1g x x x =+-,由函数y =()2log 1y x =+,2y x=-在()0,∞+上都是增函数, 得()g x 在()0,∞+上是增函数,由(1)0g =,则()0(1)g x g >=解得1x >; 当0x <时,由函数值域可知()0f x >,此时20x<,所以()2f x x >恒成立;综上可知,满足()2f x x>的实数x 的取值范围是()(),01,-∞⋃+∞.故答案为:()(),01,-∞⋃+∞ 17.(1)1n a n =+ (2)证明见解析【分析】(1)根据等比数列定义和等差数列通项公式可构造方程组求得1,a d ,进而确定n a ; (2)利用裂项相消法可求得n S ,整理即可证得结论. 【详解】(1)设等差数列{}n a 的公差为d ,1324,,a a a a +成等比数列,()23124a a a a ∴=+,即()()2111224a d a a d +=+,又5146a a d =+=,则由()()2111122446a d a a d a d ⎧+=+⎪⎨+=⎪⎩得:121a d =⎧⎨=⎩或163a d =-⎧⎨=⎩, 当16a =-,3d =时,30a =,不满足1324,,a a a a +成等比数列,舍去; 12a ∴=,1d =,()211n a n n ∴=+-=+.(2)由(1)得:()()111111212n n a a n n n n +==-++++, 1111111111233445112n S n n n n ⎛⎫⎛⎫⎛⎫⎛⎫⎛⎫∴=-+-+-+⋅⋅⋅+-+- ⎪ ⎪ ⎪ ⎪ ⎪+++⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭()112222n n n =-=++, ()221n n S n n ∴+=<+.18.(1)直角三角形 (2)0【分析】(1)根据正弦定理的边角互化,即可得到结果;(2)由(1)中结论即可得到cos B ∠,从而得到AD 的值,然后在ABD △中结合余弦定理即可得到结果.【详解】(1)因为cos sin cos c B a A b C =-,由正弦定理可得, 2sin cos sin cos sin C B B C A +=即()2sin sin B C A +=所以()2sin sin ,0,πsin 1A A A A =∈⇒=且()0,πA ∈,所以π2A =即ABC 是直角三角形.(2)在直角ABC 中,有22223b c a b +==,即222c b =,所以c =, 又因为2BD CD =,所以23BD BC ==且cos c B a === 在ABD △中,由余弦定理可得,22222242cos 2b b AD AB BD AD B AB BD +-+-∠===⋅解得AD =, 在ABD △中由余弦定理可得,222222242cos 02b b b AD BD AB ADB AD BD +-+-∠===⋅19.(1)证明见解析 (2)23【分析】(1)连接1AC 交1A C 于点F ,连接EF ,则F 为1AC 的中点,利用中位线的性质可得出1DF //BC ,再利用线面平行的判定定理可证得结论成立;(2)过点C 在平面ABC 内作CM AB ⊥,垂足为点M ,证明出CM ⊥平面11AA B B ,计算出CM 的长以及四边形1A DBE 的面积,利用锥体的体积公式可求得四棱锥1C A DBE -的体积; (3)设1BC =,以点C 为坐标原点,CA 、CB 、1CC 所在直线分别为x 、y 、z 轴建立空间直角坐标系,利用空间向量法可求得直线1BC 与平面1A CE 所成角的正弦值. 【详解】(1)证明:连接1AC 交1A C 于点F ,连接EF ,则F 为1AC 的中点, 因为D 、F 分别为AB 、1AC 的中点,则1DF //BC ,因为DF ⊂平面1A CD ,1BC ⊄平面1A CD ,1//BC ∴平面1A CD . (2)解:因为1BC =,则122AA AC CB ===,AB == 222AC BC AB ∴+=,即AC BC ⊥,过点C 在平面ABC 内作CM AB ⊥,垂足为点M , 因为1AA ⊥平面ABC ,CM ⊂平面ABC ,1CM AA ∴⊥,又因为CM AB ⊥,1AB AA A ⋂=,AB 、1AA ⊂平面11AA B B ,CM ∴⊥平面11AA B B ,由等面积法可得AC BC CM AB ⋅==因为1AA ⊥平面ABC ,AB ⊂平面ABC ,1AA AB ∴⊥,又因为11//AA BB 且11AA BB =,故四边形11AA B B 为矩形,所以,1111111212AA D A B E AA B B A DBE S S S S ⎫=--==⎪⎪⎝⎭△△矩形四边形11112333C A DBE A DBE V S CM -∴=⋅==四边形.(3)解:不妨设1BC =,因为AC BC ⊥,1CC ⊥平面ABC ,以点C 为坐标原点,CA 、CB 、1CC 所在直线分别为x 、y 、z 轴建立如下图所示的空间直角坐标系,则()0,1,0B 、()0,0,0C 、()10,0,2C 、()12,0,2A 、()0,1,1E , 设平面1A CE 的法向量为(),,n x y z =,()12,0,2CA =,()0,1,1CE =, 则1220n CA x z n CE y z ⎧⋅=+=⎪⎨⋅=+=⎪⎩,取1x =,可得()1,1,1n =-, 因为()10,1,2BC =-,则111cos ,BC n BC n BC n⋅<>==-=⋅因此,直线1BC 与平面1A CE20.(1)73.5(2)分布列见解析;期望()910E X =【分析】(1)根据频率分布直方图估计平均数的方法直接计算即可;(2)根据频率分布直方图可确定优秀与非优秀学生对应的频率,根据分层抽样原则可确定10名学生中优秀学员的人数,由此可得X 所有可能的取值,根据超几何分布概率公式可求得X 每个取值对应的概率,由此可得分布列;由数学期望计算公式可求得期望. 【详解】(1)80名学生的平均成绩为()550.01650.03750.03850.025950.00510⨯+⨯+⨯+⨯+⨯⨯=73.5.(2)根据频率分布直方图知:优秀学员对应的频率为()0.0250.005100.3+⨯=,则非优秀学员对应的频率为10.30.7-=,∴抽取的10名学生中,有优秀学生100.33⨯=人,非优秀学生100.77⨯=人;则X 所有可能的取值为0,1,2,3,()37310C 3570C 12024P X ====;()1237310C C 63211C 12040P X ====;()2137310C C 2172C 12040P X ====;()33310C 13C 120P X ===;X ∴的分布列为:∴数学期望()721719012324404012010E X =⨯+⨯+⨯+⨯=. 21.(1)22145x y -=(2)y x =+y =【分析】(1)根据平面向量数量积坐标运算和点在双曲线上,可构造方程组求得22,a b 的值,由此可得双曲线方程;(2)由2,,A B B 三点共线可设:AB y kx =+用向量垂直的坐标表示,代入韦达定理结论可解方程求得k 的值,由此可得直线AB 方程. 【详解】(1)设()1,0F c -,()()2,00F c c >,则(1PF c =--,(2PF c =-,212854PF PF c ∴⋅=-+=,解得:3c =,229a b ∴+=;又P 在双曲线上,则22851a b-=,24a ∴=,25b =, ∴双曲线的方程为:22145x y -=.(2)由(1)得:(10,B,(2B ,()22B A B B μμ=∈R ,2,,A B B ∴三点共线,直线AB斜率显然存在,可设:AB y kx =+()11,A x y ,()22,B x y ,由22145y kx x y ⎧=⎪⎨-=⎪⎩得:()2254400k x ---=,()22540Δ801040k k ⎧-≠⎪∴⎨=->⎪⎩,即252k <且254k ≠,12x x ∴+=1224054x x k =--, 11B A B B ⊥,110B A B B ∴⋅=,又(111,B A x y =,(122,B B x y =,()1112121212125B A B B x x y y x x y y y y ∴⋅=+=+++(()1212125x x kx kx k x x =++++()()()222121222401801202005454k k kx xx x k k+=++++=-++=--,解得:k =252k <且254k ≠,∴直线AB方程为:y x =y = 【点睛】关键点点睛:本题考查直线与椭圆的综合应用问题,解题关键是能够利用平面向量垂直关系的坐标表示来构造等量关系,结合韦达定理的结论得到关于所求变量的方程的形式,从而解方程求得变量的值.22.(1)函数()f x 的单调递增区间为(,0)-∞和(1,)+∞,单调递减区间为(0,1). (2)证明过程见详解【分析】(1) 因为1a =,所以函数()()212e 22x f x x x x =--++,对函数求导,利用导函数的正负来判断函数的单调性即可求解;(2)对函数进行求导,求出导函数的零点,根据条件可得:函数()f x 在(,)a -∞和(ln ,)a -+∞上单调递增,在(,ln )a a -上单调递减,然后利用零点存在性定理即可证明.【详解】(1)因为1a =,所以函数()()212e 22x f x x x x =--++,所以()e (2)e 1(1)(e 1)x x x f x x x x '=+--+=--,当1x >或0x <时,()0f x '>,此时函数()f x 单调递增; 当01x <<时,()0f x '<,此时函数()f x 单调递减; 综上:函数()f x 的单调递增区间为(,0)-∞和(1,)+∞, 单调递减区间为(0,1).(2)因为函数()()211e 12x f x a x a x ax a =---+++,所以()e (1)e ()e ()()(e 1)x x x x f x a a x a x a a x a x a x a a '=+---+=---=--,令()0f x '=可得:x a =或ln x a =-,因为310,e a ⎛⎫∈ ⎪⎝⎭,所以ln 3a ->,当x a <或ln x a >-时,()0f x '>,此时函数()f x 单调递增; 当ln a x a <<-时,()0f x '<,此时函数()f x 单调递减;所以函数()f x 在(,)a -∞和(ln ,)a -+∞上单调递增,在(,ln )a a -上单调递减,故当x a =时,函数取极大值()()22e 10102aaf a a a f a =-+++>=->,因为当2x =-时,221(2)(3)10ef a a a -=-+--<;所以0(2,)x a ∃∈-,使得0()0f x =; 当ln x a =-时,函数取极小值,ln 2211(ln )(ln 1)e (ln )ln 1ln ln (ln )22a f a a a a a a a a a a a a --=-----++=---1ln (1ln )02a a a =-++<,(因为ln 3a ->,所以13ln 22a <-,因为3110e 2a <<<,所以312a +<,也即11ln 02a a ++<)所以0(,ln )x a a '∃∈-,使得0()0f x '=;又当x →+∞时,()f x →+∞,所以0(ln ,)x a ''∃∈-+∞,使得0()0f x ''=;故当310,e a ⎛⎫∈ ⎪⎝⎭时,函数()f x 有3个零点.【点睛】函数零点的求解与判断方法:答案第17页,共17页 (1)直接求零点:令()0f x =,如果能求出解,则有几个解就有几个零点.(2)零点存在性定理:利用定理不仅要函数在区间[,]a b 上是连续不断的曲线,且()()0f a f b <,还必须结合函数的图象与性质(如单调性、奇偶性)才能确定函数有多少个零点.(3)利用导数求出函数的极值点,再利用零点存在性定理进行判断零点的个数.。
2025届河南省唐河一中高考仿真模拟语文试卷注意事项:1.答题前,考生先将自己的姓名、准考证号填写清楚,将条形码准确粘贴在考生信息条形码粘贴区。
2.选择题必须使用2B铅笔填涂;非选择题必须使用0.5毫米黑色字迹的签字笔书写,字体工整、笔迹清楚。
3.请按照题号顺序在各题目的答题区域内作答,超出答题区域书写的答案无效;在草稿纸、试题卷上答题无效。
4.保持卡面清洁,不要折叠,不要弄破、弄皱,不准使用涂改液、修正带、刮纸刀。
1、阅读下面的作品,完成下面小题。
珍珠陈忠实不用收听广播电台的天气预报,我已确信室内温度超过人体常温了。
墙壁是热的,桌椅是热的,窗户敞开着却没有一丝风,刚用新打的凉水洗浸了头脸,短暂的一阵舒适之后,热汗又涌流出来,胸膛里憋得人简直要窒息了,我关了电灯,锁上门,到河边上去,那儿也许有点夜风。
古老的乡村小镇南头儿,传来一阵弦索声。
我猜定是哪一户有丧事,请来了乐人。
一个沙哑的男声和一个清脆的女声正在对唱。
待走到跟前,一折戏刚刚唱完,围观者交头接耳,说那女的唱得美。
我的心里微微一动,从男人和女人的头上看过去。
她正好放下毛巾,抬起头来。
唔!珍珠,果然是她。
她坐在那里,坦然而又庄重。
我立即转身走开,许是不愿意在这样的场合听珍珠唱戏,许是怕珍珠偶然看见我会使她难堪。
心里却不知是一股什么味儿。
月色朦胧,我坐在柳树下,看着里光粼邦的河水,点燃一支烟……两条又粗又长的黑辫子,两只黑乌乌的大眼珠,活脱就是两颗晶尝的宝石,这是田珍珠。
她是班长,又兼着学校文艺演出队队长,舞蹈和歌唱,都是学校里拔尖的。
尤其是地表演的秦腔清唱,音色纯正,韵味悠长。
记得有一天放学,地抱着一摞作文本,放在我的桌案上,刚要出门,坐在门口的李老师挡住地:“珍珠,不要走!她站住。
宝石似的黑眼珠盯着李老师,“有什么事呀?“唱一段戏!”李老师笑着说。
珍珠唱起来:耳听得谯楼上起了更点,小舟内,难坏了胡氏凤莲。
……这样的事在我心里本来留不下任何记忆的。
2024年全国高考仿真模拟卷一英语一、阅读理解第一节阅读下列短文,从每题所给的A.B.C和D四个选项中,选出最佳选项。
(共15小题:每小题2分,满分30分)(共15题;共30分)ADuring ancient times,children didn’t have smartphones,iPad or computers to entertain themselves. Instead,they came up with interesting games to play.★Stone ballsDuring the Qing Dynasty,kicking a stone ball around was a popular sport in the northern part of China,and it was often played in the winter to protect kids from the cold.Stones were carved into small balls and kicked along with feet.In1999,the sport was included in the6th National Ethnic Group Traditional Sports Meeting held in Beijing.★Flying kitesKites have quite a long history.The earliest kites were made of wood,instead of paper.Nowadays, the four most famous kites are the Beijing kite,Tianjin kite,Weifang kite and Nantong kite,of which each has distinctive features.The kite which resembles a swallow is a well-known Beijing style.★Hide-and-seekHide-and-seek is a traditional game for children,popular around the nation.There are two ways to play:covering a child’s eyes while other kids run around to tease(戏弄)him or,more commonly, participants hide and one child must try to find them.★Playing diabolosA diabolo is always made of wood or bamboo and has empty space in the center.By juggling(边抛边接)the diabolo on the rope,the high-speed spinning diabolos will make a sound like a whistle.Playing diabolos is an interesting folk game,especially popular in North China.Playing diabolos was also included in the first group of national intangible cultural heritage.1.Why did ancient children often play stone balls in the winter?A.To practice their feet B.To warm themselvesC.To train their skills D.To relax themselves.2.Which kites are swallow-shaped?A.Weifang kites.B.Tianjin kites.C.Beijing kites.D.Nantong kites.3.According to the passage,which one is a national intangible cultural heritage?A.Stone balls.B.Flying kites.C.Hide-and-seek.D.Playing diabolosBTechnology usually distracts us from nature.But now technology is“offering us an opportunity to listen to nonhumans in powerful ways,reviving our connection to the natural world,”wrote professor Karen Bakker in her new book,The Sounds of Life:How Digital Technology Is Bringing Us Closer to the Worlds of Animals and Plants.All around the animal kingdom,there are sounds that we struggle to pick up and decipher.Elephants, for example,communicate with each other using infrasound,a sound frequency far below our human hearing range.Coral in the ocean also communicates with each other through sound waves,with one purpose being to attract baby coral to areas where it can successfully grow.This is a shocking fact as coral doesn’t have any ears!Scientists have placed listening devices in these environments to pick up sounds humans are normally unable to detect.After the sounds are recorded,AI is then able to determine their meaning,according to the news website Vox.There are now whole databases of whale songs and honeybee dances.Bakker wrote that one day this information could be turned into“a zoological version of Google Translate”.One animal language Bakker wrote about is that of the elephant.She explained how elephants“have a different signal for honeybee,which is a threat,and a different signal for human,”in an interview with Vox.“Moreover,they distinguish between threatening humans and non-threatening humans,”she said.This technology can not only understand the animals,but also communicate back to them.For example,bees use dances to communicate to their peers where to go in search of nectar.A research team in Germany,therefore,fed the bee language AI database system into a robot bee,allowing the robot to create a dance routine that can tell the bees which direction to move,Vox reported.Whereas in the past language creation had been limited to mainly apes,with there being many examples of chimpanzees(黑猩猩)having been taught sign language to communicate with humans,this new technology now allows humans to socialize with different animals throughout the animal kingdom.4.What does the underlined word“decipher”most probably mean in paragraph2? A.Understand.B.Hear.C.Produce.D.Record.5.What helps baby coral choose their home?A.Infrasound.B.Sounds within human range of hearing. C.Sounds through its ears.D.Sound waves.6.What can we infer from the passage?A.Bees used dances to warn their peers of danger.B.Human fed listening devices into coral to detect it.C.Elephants have different signals for different purposes.D.Elephants can tell whether there are threatening animals around.7.Why did researchers create the robot bee?A.To collect more bee dances.B.To convey direction to bees.C.To learn the language of bees.D.To help bees search for their friends.CWhen you are travelling in Thailand,which means of transport is the best choice?You can rent a variety of motorbikes or bikes in Thailand.It seems to be very popular in most of the beaches and islands along the places in the north.The most popular bikes are the little125cc Honda Dream which you can get for about150baht(铢)a day or as little as3,000baht per month,making it the cheapest way to tour Thailand for the people from other countries.Sometimes you will have to go somewhere by taxi.When you are in cities in Thailand,especially in Bangkok,always remember to get a taxi that is traveling on the roads.Some drivers outside hotels refuse to use the meter(计程表).They will ask a price which is several times the price when they use the meter!The quality of the roads in Thailand is generally pretty good,so renting cars is another way to get around.The big car rental companies may offer you slightly older cars at a very reasonable price.It is a little surprising considering that the cost of buying a car in Thailand is more than that in the West.Petrol is also reasonably priced in Thailand,more expensive than American prices,but much cheaper than what is paid in Europe.In the past,Bangkok could be a difficult place to drive in—signs were generally in Thai (泰语)only,making it a hard job to find exactly where you were by looking around.But now,the situation is improved.In a lot of places,even the farthest corners of the country,street signs are in both Thai and English.8.To a foreigner,the cheapest way to get around Thailand is renting a______.A.car B.taxi C.bike D.motorbike9.What is the writer's advice about taking a taxi in Thailand?A.To take a taxi going on the road.B.To take a taxi parked outside hotels.C.To make sure there is a meter in it.D.To bargain with the driver over the price. 10.Why was it difficult to drive in Bangkok in the past?A.Because there were too many traffic jams on the roads.B.Because there were no signs showing directions.C.Because the signs were written only in their own language.D.Because the quality of the roads was not good.11.In which part of magazine can this passage be found?A.Entertainment B.Tourism C.Market D.AdvertisementDWilliam I,who conquered England some930years ago,had wealth,power and an army.Yet although William was very rich by the standard of his time,he had nothing like a flush toilet(抽水马桶),or riding lawn mower(除草机).How did he get by?History books are filled with wealthy people who were poor compared to me.I have storm windows, Croesus did not.Entire nations trembled before Alexander the Great,but he couldn,t buy cat food.Czar Nicholas lacked an electric saw.Given how much better off I am than so many famous dead people,you,d think I,d be content.The trouble is that,like most people,I compare my wealth with that of living persons:neighbors,school classmates,famous TV people.The greed I feel toward my friend Howard,s new kitchen is not reduced by the fact no kings ever had a refrigerator with glass doors.’There is really no rising or falling standard of living.Over the centuries people simply find different things to feel sad about.You,d think that simply not having disease would put us in a good mood,but no, we want a hot bath too.Of course,one way to achieve happiness would be to realize that even by today,s standards the things I own are pretty nice.My house is smaller than the houses of many investments bankers,but even so it has a lot more rooms than my wife and I can keep clean.Besides,to people looking back at our era from a century or two in the future,these bankers,fancy counter tops and my own worn Formica will seem equally shabby.I can,t keep up with my neighbors right now.But just wait.12.What does the underlined phrase“get by”in the first paragraph mean?A.Succeed as a king.B.Deal with complaints.C.Live in s satisfactory way.D.Get some extra money.13.How many historical figures are mentioned to compare lives in the past and present?A.3.B.4.C.5D.614.According to the passage,the author.intends to.A.tell us to be content with lifeB.warn us to live in a simple wayC.teach us to learn lessons from lifeD.encourage us to struggle for wealth15.What,s the author,s attitude towards life?A.Doubtful.B.Optimistic.C.Uncaring.D.Cautious.二、阅读理解第二节七选五(5小题;每小题2分,满分10分)(共1题;共10分)Table manners are the ultimate way to show respect or some accidental disrespect to yourhost.___16___.In France,you are supposed to use two hands to eat—either fork and knife or fork and bread.Bread isn't meant to be an appetizer.___17___When you eat the bread,tear off a piece of it to eat instead of biting directly into the bread.When not in use,the bread belongs on the table or tablecloth instead of the plate.Finishing everything on your plate is a no-no in many Asian countries.___18___Leaving a small amount on your plate symbolizes that you've had your fill and acknowledges your host's generosity.___19___So,tipping,in their culture,is rude.Even if they don’t assume you’re being rude,they can also be very confused by the extra money,thinking you have overpaid.Whether it's a taxi driver,a server, or a bellhop,don't tip them.It's not good manners.Among the local people of China and the Inuit people of Canada,a light burp(打嗝)at the end of a meal is considered a compliment,as it indicates that you've eaten well.___20___,or never leave them upright in a bowl of rice.For this is how food is offered to the spirit of a dead person. A.Furthermore,don't lick your chopsticksB.Instead it serves to assist the food to the forkC.It suggests that your hosts didn't feed you enoughD.Many people in Japan believe that good service is standardE.In Brazil,bread and pizza are normally eaten with a fork and knife,tooF.Here are some of the very specific dining do's and don’ts from around the worldG.You may also drink directly from the soup bowl—spoons,however,are uncommon三、语言知识运用第一节完形填空(共20小题;每小题1.5分,满分30分)(共1题;共30分)In October,2003I started my work at my local animal shelter’s Adoption Department.Over the years,more than50,000animals have___21___the doors of the shelter.Most of them,I do not remember. But occasionally there are___22___animals,who touch me so deeply that I could never possibly forget them.Tabby was one such animal.Tabby was an ancient Cocker Spaniel,probably14years old.What’s more,she was blind and deaf. Tabby’s chances at adoption seemed___23___at best.After all,we didn’t have many adopters coming in ____24____,“Can you show me all of your really old dogs who are also___25___?”We had all thought that Tabby would live out the rest of her life at the shelter.One day a woman named Loretta came to the shelter.Her son,Gary,had___26___Tabby’s picture and stories on the shelter’s website at home.They were interested in meeting her!It was the only___27___we ever received about Tabby.What could a young child possibly see in a14-year-old dog who was both blind and deaf?Most boys would want a dog who could grow with them and run through grassy fields on summer days.Tabby would___28___be able to do that.But after meeting her,Loretta and Gary decided that she was the right dog for their family.They adopted Tabby!If Tabby’s story had simply ended with her___29___adoption,it would still have been something very special indeed.____30____,it was what happened after her adoption that people might regard as “magic”.Gary suffered from seizures(癫痫).Since Gary and Tabby met they became____31____.They did everything together.They became so“in tune”with one another that Tabby began to telegraph Gary’s seizures____32____they occurred,giving his family____33____that one was about to strike.What’s more,Gary seemed to be having fewer and fewer seizures since Tabby’s____34____.How could it be?Nobody could explain how Tabby did it.But those of us who were fortunate enough to know her and her family had____35____the magic,the kind that has its roots in love. 21.A.broken B.passed C.enrolled D.conveyed 22.A.strange B.active C.striking D.special 23.A.small B.great C.desperate D.potential 24.A.wondering B.stating C.seeking D.asking 25.A.dynamic B.active C.disabled D.patient 26.A.posted B.taken C.seen D.drawn 27.A.surgery B.donation C.call D.question 28.A.literally B.possibly C.never D.generally 29.A.successful B.normal C.temporary D.astonishing 30.A.However B.Moreover C.Therefore D.Otherwise 31.A.humble B.uncomfortable C.unfortunate D.inseparable 32.A.since B.unless C.before D.if 33.A.explanation B.notice C.suggestion D.warning35.A.witnessed B.created C.achieved D.performed四、语言知识运用第二节用单词的适当形式完成短文共10小题:每小题1.5分,纷15分)共1题;共15分)阅读下面材料,在空白处填入适当的内容(1个单词)或括号内单词的正确形式。
2024年1月浙江省高考英语仿真模拟试卷01参考答案1.【答案】B【原文】W: Andy, you look really handsome in your new coat. Where did you buy it?M: You really have a good taste. My daughter bought it in America on her business trip.2. 【答案】B【原文】M: Sorry, Miss. We made a terrible mistake adding up the bill. Here is the ten dollars we have to return to you.W: Oh, I didn’t notice that. It’s OK. Don’t blame the waiter. He’s been really nice.3.【答案】B【原文】M: I have 50 pages more to read tonight, but it’s already 11:00. I really need some coffee. It’ll take me at least two hours, and I need it done by 10:00 tomorrow morning.W: Just wake up at 7:00. You’ll have plenty of time then.4. 【答案】A【原文】W: I wanted to buy a new pair of shoes from Foot Locker, but the ones I want cost $100.I can only spend $75 at the most.M: I will pay for half of the price. You can consider it as part of your birthday gift.5. 【答案】C【原文】W: Jack, are you going camping with your friends this weekend?M: It depends. If it’s sunny, we’ll go.W: The weatherman says it’s going to rain.M: In that case, we’ll go to the cinema instead.听下面一段较长对话,回答以下小题。
2023届陕西省榆林市第十高级中学校高三下学期3月高考仿真模拟(一)语文试题(含答案)2023届陕西省榆林市第十中学高考仿真模拟语文试题(一)注意事项:1.本试卷满分150分.考试时间150分钟。
2.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上、并将条形码粘贴在答题卡上的指定位置。
3.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
4.考试结束后,将本试卷和答题卡一并收回。
一、现代文阅读(36分)(一)论述类文本阅读(本题共3小题,9分)阅读下面的文字,完成1~3题。
中国传统文化在数千年的发展过程中,形成了独特的文化精神、意识形态和价值取向,产生了丰富的艺术门类和艺术成果,在此基础上.出现了大量的审美形态和审美范畴。
中国古代的审美形态与西方的审美形态相比,具有鲜明的差异,这是双方不同的现实生活基础、审美实践活动、思维模式、语言特征以及文化精神所决定的。
总的说来,中国古代的基本审美形态大致具有两个方面的特征:一方面,它们都具有综合性。
也就是说.中国古代的审美形态,大都是生命状态、社会实践和审美活动等各个层面的结合,无论是我们将要讨论的中和、气韵和意境,还是其他一些审美形态和审美范畴,比如气象、神采、风骨、兴趣、神韵等等,无不包含着上述各个层面的内容。
另一方面,它们相互之间都具有渗透性。
也就是说,中国古代的审美形态和审美范畴,既非常丰富,又高度统一,很难找出截然不同、毫无关联的两个概念;究其原因,在于它们都是共同的现实土壤和文化资源的产物,而最根本的原因在于,它们都饱合着中国所特有的朴素的静证法的思想核心。
中国古代审美形态的综合性和渗透性.并不意味着它们在漫长的历史中没有任何变化,而只是简单的重复和维积;实际上,中国古代的审美形态跟所有历史现象一样,有一个不断产生、发展和成熟的过程。
高考仿真模拟卷(一)本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分110分。
考试时间60分钟。
第Ⅰ卷(选择题共48分)本卷共8小题,每小题6分。
在每小题给出的四个选项中,第14~18题只有一项符合题目要求,第19~21题有多项符合题目要求。
全部选对的得6分,选对但不全的得3分,有选错的得0分。
14.图示1为某物体做直线运动的v-t图象,关于这个物体在4 s内的运动情况,下列说法中正确的是()图1A.物体始终向同一方向运动B.4 s末物体离出发点最远C.加速度大小不变,方向与初速度方向相同D.4 s内位移为0,而通过的路程为4 m解析在v-t图象中,速度v的正负表示物体的运动方向,结合图象可知物体的速度减小为零后将反向运动,选项A错误;v-t图象与坐标轴围成的面积表示物体运动的位移,由图线可知物体在t=4 s时位移为零,表示物体回到出发点,选项B错误;v-t图线的斜率表示物体运动的加速度,由图可知物体的加速度为正值,而初速度为负值,故加速度与初速度方向相反,选项C错误;物体在前2 s的路程为2 m,在后2 s的路程也为2 m,故在前4 s的路程为4 m,选项D 正确。
答案D15.下列说法正确的是()A.放射性元素发生一次β衰变,原子序数减少1B.氢原子由n=3向n=1的能级跃迁时,只能辐射2种频率的光子C.在光电效应实验中,光电子的最大初动能与入射光强无关,只随入射光的频率增大而增大D.235 92U的半衰期约为7亿年,随着地球环境的不断变化,半衰期可能变短解析放射性元素发生一次β衰变,多一个质子,原子序数增加1,A错;由n =3向n=1的能级跃迁时,能辐射3种频率的光子,B错误;由光电效应方程E k=hν-W,可知C正确;放射性元素的半衰期不会随环境的变化而改变,故D 错。
答案C16.一质量为m的铝球用细线悬挂静止在足够深的油槽中(如图2甲),某时刻剪断细线,铝球开始在油槽中下沉,通过传感器得到铝球的加速度随下沉速度变化的图象如图乙所示,根据上述信息,下列说法正确的是()图2A.铝球下沉的速度越来越小B.剪断细线后,油槽对地面的压力先增大后不变C.剪断细线后,铝球加速度随时间均匀减小D.铝球下沉过程机械能的减少量等于克服油所受摩擦阻力所做的功解析由图象可知,铝球在下沉过程中,加速度越来越小,但速度越来越大,选项A错误;剪断细线后,铝球下落,油槽和油以及铝球这一整体中某部分处于失重状态,但加速度越来越小,因而整体中的某部分失重越来越小,整体对地面的压力将增大,当加速度等于零后,整体将不再失重,因而剪断细线后油槽对地面的压力先增大后不变,选项B正确;剪断细线后,铝球的加速度随速度均匀减小,但速度随时间并非均匀减小,选项C错误;铝球减小的机械能转化为同体积油的机械能和整体的内能,选项D错误。
答案B17.真空中,两个相距L的固定点电荷E、F所带电荷量分别为Q E和Q F,在它们共同形成的电场中,有一条电场线如图3中实线所示。
电场线上标出了M、N 两点,其中N点的切线与EF连线平行,且∠NEF>∠NFE。
则()图3A.E带正电,F带负电,且Q E>Q FB.在M点由静止释放一带正电的检验电荷,检验电荷将沿电场线运动到N点C.过N点的等势面与过N点的切线垂直D.负检验电荷在M点的电势能大于在N点的电势能解析根据电场线可知,两点电荷为异种电荷,但哪个电荷带正电无法判断,选项A错误;由于电场线一般为曲线,带电粒子在电场中运动轨迹不可能与电场线重合,选项B错误;由于N点的电场线沿水平方向,等势线与电场线垂直,因而选项C正确;由于不能确定电场线的方向,因而无法确定负检验电荷在哪点的电势能大,选项D错误。
答案C18.如图4所示,在半径为R的圆形区域内充满磁感应强度为B的匀强磁场,MN是一竖直放置的足够长的感光板。
从圆形磁场最高点P以速度v垂直磁场射入大量带正电的粒子,且粒子所带电荷量为q、质量为m。
不考虑粒子间的相互作用力和粒子的重力,关于这些粒子的运动以下说法正确的是()图4A.只要对着圆心入射,出射后均可垂直打在MN上B.即使是对着圆心入射的粒子,其出射方向的反向延长线也不一定过圆心C.只要速度满足v=qBRm,沿不同方向入射的粒子出射后均可垂直打在MN上D.对着圆心入射的粒子,速度越大在磁场中通过的弧长越长,时间也越长解析粒子的速度不同,在磁场中做圆周运动的半径不同,从圆形磁场中出来后不一定垂直打在MN板上,选项A错误;沿圆心进入圆形磁场的粒子,离开磁场时速度的反向延长线一定过圆心,选项B错误;若粒子的速度为v=qBRm,粒子在磁场中做圆周运动的半径为r=R,粒子离开磁场时速度沿水平方向,垂直打在MN板上,选项C正确;速度越大的粒子在磁场中的运动轨迹对应的圆心角越小,因而运动时间越短,选项D错误。
答案C19.如图5所示电路中的变压器为理想变压器,S为单刀双掷开关。
P是滑动变阻器R的滑动触头,U1为加在原线圈两端的交变电压,I1、I2分别为原线圈和副线圈中的电流。
下列说法正确的是()图5A.保持P的位置及U1不变,S由a切换到b,则I2减小B.保持P的位置及U1不变,S由b切换到a,则R上消耗的功率减小C.保持P的位置及U1不变,S由b切换到a,则I1增大D .保持U 1不变,S 接在b 端,将P 向上滑动,则I 1减小解析 保持P 的位置不变和U 1不变,S 由a 打到b ,副线圈匝数减小,根据U 1U 2=n 1n 2可知副线圈两端电压U 2减小,因而电流I 2减小,选项A 正确;保持P 的位置不变和U 1不变,S 由b 打到a ,副线圈匝数增大,根据U 1U 2=n 1n 2可知副线圈两端电压U 2增大,电流I 2增大,R 消耗的功率增大,选项B 错误,选项C 正确;保持U 1不变,S 打到b ,P 上滑,则电流I 2增大,I 1增大,选项D 错误。
答案 AC20.如图6所示,质量为M 、长为L 的木板置于光滑的水平面上,一质量为m 的滑块放置在木板左端,滑块与木板间滑动摩擦力大小为f ,用水平的恒定拉力F 作用于滑块。
当滑块运动到木板右端时,木板在地面上移动的距离为s ,下列结论中正确的是( )图6A .上述过程中,F 做功等于滑块和木板动能的增量B .其他条件不变的情况下,M 越大,s 越小C .其他条件不变的情况下,F 越大,滑块到达木板右端所用时间越长D .其他条件不变的情况下,f 越大,滑块与木板间产生的热量越多解析 在滑块滑到木板右端的过程中,F 做的功转化为滑块和木板的动能以及系统的内能,选项A 错误;木板质量越大,木板的加速度越小,因而木板的位移越小,选项B 正确;其他条件不变,F 越大,滑块滑到木板右端所需的时间越短,选项C 错误;根据Q =fL 可知f 越大,产生的热量越多,选项D 正确。
答案 BD21.如图7两根足够长光滑平行金属导轨PP ′、QQ ′倾斜放置,匀强磁场垂直于导轨平面向上,导轨的上端与水平放置的两金属板M 、N 相连,板间距离足够大,板间有一带电微粒,金属棒ab 水平跨放在导轨上,下滑过程中与导轨接触良好。
现在同时由静止释放带电微粒和金属棒ab,则()图7A.金属棒ab一直加速下滑B.金属棒ab最终可能匀速下滑C.金属棒ab下滑过程中M板电势高于N板电势D.带电微粒可能先向N板运动后向M板运动解析根据牛顿第二定律有mg sin θ-BIl=ma,而I=ΔqΔt,Δq=CΔU,ΔU=BlΔv,Δv=aΔt,联立解得a=mg sin θm+B2l2C,因而金属棒将做匀加速运动,选项A正确,B错误;ab棒切割磁感线,相当于电源,a端相当于电源正极,因而M板带正电,N板带负电,选项C正确;若带电粒子带负电,在重力和电场力的作用下,先向下运动然后再反向向上运动,选项D正确。
答案ACD第Ⅱ卷(非选择题共62分)本卷包括必考题和选考题两部分。
第22~25题为必考题,每个试题考生都必须做答。
第33~35题为选考题,考生根据要求做答。
(一)必考题(共47分)22.(6分)某同学用如图8甲的装置来测定滑块与导轨间的动摩擦因数。
在气垫导轨上安装了两个光电门1、2,滑块上固定一遮光条,滑块用细线跨过定滑轮与钩码相连。
(1)用游标卡尺测遮光条的宽度d,图乙中游标卡尺读数为________cm。
滑块在轨道上做匀加速运动时,先后通过光电门1、2所用的时间分别为t1、t2,两光电门间的距离为L,用d、t1、t2、L表示滑块运动的加速度a=________。
(2)要使细线中拉力近似等于钩码重力,滑块质量M与钩码质量m应满足________关系。
(3)满足(2)后,调整气垫导轨水平,断开气源时,测得滑块在轨道上运动的加速度为a1;不改变钩码的质量,接通气源,测得滑块在轨道上运动的加速度为a2,用a1、a2、g表示滑块与导轨间的动摩擦因数μ=________。
图8解析(1)游标卡尺的读数为2 mm+0.05 mm×5=2.25 mm=0.225 cm;根据v22-v21=2aL可得a=d22L(1t22-1t21)。
(2)若钩码的重力近似等于细线拉力,则钩码质量应远远小于滑块的质量。
(3)气垫导轨水平,气源断开时,对于滑块有mg-μMg=Ma1;接通电源时,对滑块有mg=Ma2,联立解得μ=a2-a1 g。
答案(1)0.225d22L(1t22-1t21)(2)M远远大于m(3)a2-a1g23.(9分)某学习小组探究电学元件的伏安特性曲线。
(1)甲同学要描绘一个标有“3.6 V,1.2 W”的小灯泡的伏安特性曲线,除了导线和开关外,还有以下可供选择的器材:电压表V(量程5 V,内阻约为5 kΩ);直流电源E(电动势4.5 V,内阻不计);电流表A1(量程100 mA,内阻约为2 Ω);电流表A2(量程500 mA,内阻约为1 Ω);滑动变阻器R1(阻值0~10 Ω);滑动变阻器R2(阻值0~200 Ω)。
实验中电流表应选________,滑动变阻器应选________(填写器材代号);在虚线框中画出完整的实验电路图,并标明器材代号。
(2)乙同学利用甲同学的电路分别描绘了三个电学元件的伏安特性曲线,如图9所示。
然后他用如图10所示的电路分别给三个元件供电,并测出给元件1和元件2供电时的电流和电压值,分别标在图9上(A点和B点)。
已知R0=8.0 Ω,则该电源的电动势E′=________V,内电阻r′=________Ω,用图10的电路单独给元件3供电时,元件3的电功率P=________W。
解析(1)由于小灯泡的额定电流为I=PU≈333 mA,故电流表应选择A2。
描绘小灯泡的伏安特性曲线,电流或电压从零开始,滑动变阻器采用分压接法,分压接法滑动变阻器要选择电阻范围小的,因而选择R1。