2019-2020学年四川省成都七中高二上学期期中考试物理试题及答案
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高2021级2021-2022学年度上期半期物理考试考试时间90分钟总分100分命题人:刘志刚审题人:吕小科一.单项选择题(每题4分,共6个小题,24分)1.两个带有等量电荷的铜球,相距较近且位置保持不变,设它们带同种电荷时的静电力为F1,它们带异种电荷时(电荷量确定值相同)的静电力为F2,则F1和F2的大小关系为:()A.F1=F2 B.F1> F2 C.F1< F2 D.无法比较2.某电场中一条直线上有A,B,C三点,且AB=BC,若设A点为零电势点时,一个q=1C的正电荷从B到C做了5J的正功,则当取C点为零电势点时,B点的电势为()A 5VB 10VC -10V D-5V3如图所示,a、b、c是匀强电场中的三个点,a、b、c三点在同一平面上,三点电势分别是10V、2V和6V,下列各图中电场强度的方向表示正确的是( )4.两个电阻R1、R2的电流和电压的关系如图所示,可知两个电阻的阻值大小之比R1∶R2等于()A.1∶3 B.3∶1C.1∶3 D .3∶15.两个固定的等量异种电荷,在他们连线的垂直平分线上有a、b 、c三点,如下图所示,下列说法正确的是()A.a点电势比b点电势高B.a、b两点场强方向相同,a点场强比b点大C.a、b、c三点的电势与无穷远电势相等D.一带电粒子(不计重力),在a点无初速释放,则它将在a、b、c线上运动6.一电池外电路断开时的路端电压为3 V,接上8 Ω的负载后路端电压降为2.4 V,则可以判定电池的电动势E和内电阻r为( )A.E=2.4 V,r=1 Ω B.E=3 V,r=2 ΩC.E=2.4 V,r=2 Ω D.E=3 V,r=1 Ω二.不定项选择题(本题包括6个小题,每小题4分,共24分,多选和错选为零分,漏选为2分)7.在平行板电容器A、B两板上加上如图所示的交变电压,开头B板的电势比A板高,这时两板中间原来静止的电子在电场力作用下开头运动,设电子在运动中不与极板发生碰撞,则下述说法正确的是(不计电子重力)( )A.电子始终向A板运动B.电子始终向B板运动C.电子先向A板运动,然后向B板运动,再返回 A板做周期性来回运动D.电子先向B板运动,然后向A板运动,再返回B板做周期性来回运动8..如图所示,电路中每个电阻的阻值都相同.当电压U上升时,先烧坏的电阻应是()A.R1和R2 B.R3和R4C.R5 D.不能确定9.如图所示电路,G是电流表,R1、 R2是两个可变电阻,调整可变电阻R1,可以转变电流表G的示数,当MN 间的电压为6V时,电流表的指针刚好偏转到最大刻度。
成都七中2019—2020学年度上期高2021届半期考试物理试卷考试时间:100分钟满分:110分第Ⅰ卷选择题(48 分)一、单项选择题(本大题共12 题,每小题2 分,共24 分,其中每题只有一个正确答案)1、下列说法中正确的是()A.摩擦起电的实质是通过外力做功凭空产生了电荷B.电子就是元电荷C.由公式E =kQr2可知,当r→0 时,E→∞,因此可得场强为无穷大的电场D.电场强度的方向就是电势降低最快的方向2、下列四个电场中,a、b 两点电场强度相同的是()3、下列说法中正确的是( )A.把一根均匀导线等分成等长的两段,则每部分的电阻率也变为原来的一半B.电容器所带的带电量越多,说明它的电容越大C.电动势的单位跟电压的单位一样,都是伏特,所以电动势就是电压D.其他电阻不变时,并联电路中其中一个电阻增大,总电阻增大4、如图甲所示电路,小灯泡通电后其两端电压U 随所通过的电流I 变化的图线如图乙所示,P 为图线上一点,PN 为图线的切线,PM 为U 轴的垂线,PQ 为I 轴的垂线,下列说法中正确的是( )A.随着电流的增大,小灯泡电阻逐渐减小B.对应P 点,小灯泡的电阻为R=U1 I2-I1C.在电路中灯泡L 两端的电压为U1 时,电阻R 两端的电压为I1RD.对应P 点,小灯泡的功率为图中四边形PQOM 所围的“面积”10、如图所示,闭合开关S,待电路稳定后,一带正电的粒子(不计重力)沿中线以初速度v 0进入电场中,粒子通过偏转电场打在荧光屏上的P 点,现在欲使得粒子打在荧光屏上的位置下移,则下列做法可行的是()A.增大粒子的比荷B.增大R2 的电阻C.减小粒子进入偏转电场时的初动能D.增大R1 的电阻11、如图所示,a、b、c 为真空中三个带电小球,b 球带正电,且电量为+Q, 用绝缘支架固定,c 小球带负电,a、c 两小球用绝缘细线悬挂,处于平衡状态时三小球球心等高,且a、b 和b、c 间距离相等,悬挂a小球的细线向左倾斜,悬挂c 小球的细线竖直。
2019-2020学年四川省成都七中高二(上)期中物理试卷一、单选题(3×9=27分)1.(3分)下列说法正确的是()A.两个物体只要相互接触就一定会产生弹力B.两个物体间的滑动摩擦力总是与物体运动方向相反C.一本书在桌面上静止,书对桌面有压力是因为书发生了弹性形变D.静止在斜面上的物体对斜面的压力就等于物体受到的重力2.(3分)下列关于加速度的说法中正确的是()A.由a=可知,a与△v成正比,与△t成反比B.加速度是表示物体速度变化快慢的物理量C.物体加速度为零,则物体的速度一定为零D.物体运动速度越大,其加速度一定越大3.(3分)有四个运动的物体A、B、C、D,物体A、B运动的x﹣t图象如图①所示;物体C、D从同一地点沿同一方向运动的v﹣t图象如图②所示.根据图象做出的以下判断中正确的是()A.物体A和B均做匀速直线运动,且A的速度比B更大B.在0~3 s的时间内,物体B运动的位移为10 mC.t=3 s时,物体C追上物体DD.t=3 s时,物体C与物体D之间有最大间距4.(3分)如图,一物块在水平拉力F的作用下沿水平桌面做匀速直线运动。
若保持F的大小不变,而方向与水平面成60°角,物块也恰好做匀速直线运动。
物块与桌面间的动摩擦因数为()A.2﹣B.C.D.5.(3分)在做“验证力的平行四边形定则”实验中,假如F1的大小及方向固定不变,那么为了使橡皮条仍然伸长到O点,对F2来说,下面几种说法中正确的是()A.F2可以有多个方向B.F2的方向和大小可以有多个值C.F2的方向和大小是惟一确定值D.F2的方向是惟一的,但大小可有多个值6.(3分)汽车在200m长的平直跑道做启动、制动性能测试.汽车从跑道一端由静止开始匀加速运动,离终点还有40m时关闭发动机做匀减速运动,恰好停在跑道另一端,全程运动时间为20s,则下列说法正确的是()A.汽车全程的平均速度是20m/sB.汽车关闭发动机时的速度是10m/sC.汽车匀加速运动的加速度是2.5m/s2D.汽车匀减速运动的加速度大小是5m/s27.(3分)2016年4月2日,沪宁高速上海至无锡方向玉祁段发生重大车祸,现场至少50辆车连环相撞。
四川省成都七中实验学校2019-2020学年高二物理上学期期中试题(含解析)一.选择题1.关于物理学史和力学单位,下列说法正确的是A. 卡文迪许利用扭秤实验测出了静电力常量 k 的数值,结果为 k =9.0×109N.m/C 2B. 电场强度的单位可以是 N/C 和 V/mC. 电功率 P=UI 中 P 的单位可以为 W ,A V ⋅还可以为 N s/m ⋅D. 密立根油滴实验测量了电子电荷量,e =1.60×1019C【答案】B【解析】 【详解】A. 卡文迪许利用扭秤巧妙地测得引力常量G 的数值,而不是静电力常量k 的数值,故A 错误。
B. 根据电场强度的定义式F E q=可知,力的单位是N ,电荷的单位是C ,所以电场强度的单位是N/C ,根据电场强度的公式U E d=可知,电势差的单位为V ,距离的单位为m ,所以V/m 是电场强度的单位,故B 正确。
C.根据功率P Fv = 可知,功率单位可以为N m/s ⋅ ,故C 错误。
D. 密立根油滴实验测量了电子电荷量,e =1.60×10-19C ,故D 错误。
2.将两个分别带有电荷量-2Q 和+5Q 的相同金属小球 A 、B 分别固定在相距为r 的两处(均可视为点电荷),它们之间库仑力的大小为 F .现将第三个与 A 、B 两 小球完全相同的不带电小球 C 先后与 A 、B 两小球相互接触后拿走,A 、B 两小球间距离保持不变,则两小球间库仑力的大小为 A. 14F B. 910F C. 15 F D. 25F 【答案】C【解析】【详解】开始时由库仑定律得:225Q Q F k r ⨯=当小球和A 接触后,A 球带电为-Q ,再和B 球接触时,先中和后总电量为4Q ,故平分后B 球带电为2Q ,因此此时:122Q Q F k r ⨯= 所以 15F F =A. 14F 与计算不符,故A 错误。
B. 910F 与计算不符,故B 错误。
2019-2020学年高二上物理期中模拟试卷含答案1.B 2.A 3.B 4.AC 5.D 6.B 7.C 8.CD 9.ABC 10.B 11.AC 12.CD13.答案:1.240 1.682(1.681-1.685) 14.(1)欧姆(或Ω)(1分),×1 (1分),7(1分)(2)①ACF (3分) ②左(1分) ③1(1分);5(1分) ④增大(1分)15.(1)由闭合电路欧姆定律:r R U U E 111+=,r R UU E 222+=, 联立上式并代入数据解得:E =6V ,r =1Ω.(4分) (2)由电功率表达式:()22E P R R r =+,将上式变形为:()224E P R r rR=-+,由上式可知 R =r =1Ω时,P 有最大值:29W 4nm E P r==(4分)16.(10分)解析:(1)将空间立体图改画为如图所示的侧视图,并对杆进行受力分析,由平衡条件得F -Nsinθ=0,Ncosθ-mg =0, 而d RE BBId F == 由以上三式解得tan Rmg θE Bd=(4分) (2)有两种可能性:一种是E 偏大,I 偏大,F 偏大,导体杆有上滑趋势,摩擦力f 沿斜面向下,选沿斜面向上为正方向,根据平衡条件有Fcosθ-mgsinθ-μ(mgcosθ+Fsinθ)=0(2分) 根据安培力公式有F =d RE B 1以上两式联立解得θμθBd θμθRmg E sin cos cos sin 1-+=(1分)另一种是E 偏小,摩擦力f 沿斜面向上, 同理可得θμθBd θμθRmg E sin cos cos sin 2+-=(1分)综上所述,电池电动势的取值范围是θμθBd θμθRmg E θμθBd θμθRmg sin cos cos sin sin cos cos sin -+≤≤+-(2分)17.(10分)(1)对第1个落到O 点的粒子由:02L v t =(1分) 2122d gt =(1分)得:()m/s 5.220==dgLv (1分) (2)对落到B 点的粒子 由:L =v 0t (1分)2212at d =(1分) mg -Eq =ma (1分) 得:203()1.510(V /m)V mg md L E q-==⨯(1分)(3)由:Q =CEd =6.0×10-4(C ) (1分)得:600==qQN (1分) 落到下极板上粒子总数为N +1=601个 (1分)18.(10分)解答:(1)设质子在磁场Ⅰ和Ⅱ中做圆周运动的轨道半径分别为r 1和r 2,区域Ⅱ中磁感应强度为B ',由牛顿第二定律12r v m qvB =①1分22r v m B qv ='②1分粒子在两区域运动的轨迹如图所示,由几何关系可知,质子从A 点出磁场Ⅰ时的速度方向与OP 的夹角为30°, 故质子在磁场Ⅰ中轨迹的圆心角为 θ=60° 1分 则△O 1OA 为等边三角形 OA =r 1 ③1分 r 2=OA sin30° ④1分由①②③④解得区域Ⅱ中磁感应强度为 B '=2B 2分 (2)Q 点坐标 x =OA cos30°+r 2 1分 故 x 31()2mvqB+=…………2分2019-2020学年高二上物理期中模拟试卷含答案(时间:90分钟 满分:100分)一、单项选择题:(每小题4分,共40分 。
四川省成都七中2019-2020学年高二上学期期中物理试卷一、单选题(本大题共7小题,共21.0分)1.在投掷铅球的过程中,下列说法正确的是()A. 铅球受到手的弹力是由于手发生形变而引起的B. 铅球落地时对地面向下的压力是由地面发生形变而产生的C. 因为铅球不会发生形变,所以手不受铅球的弹力作用D. 铅球在飞行过程中不受重力作用2.下列说法中,正确的是()A. 质点运动的加速度大,则速度变化大B. 质点运动的加速度大,则速度变化快C. 物体在一条直线上运动,如果在相等的时间里变化的位移相等,则物体的运动就是匀变速直线运动D. 加速度大小不变的运动就是匀变速直线运动3.如图所示,直升机沿着水平方向向前飞行时,旋翼平面与水平方向成θ角,旋翼与空气相互作用产生的作用力F与机翼平面垂直。
以下说法正确的是()A. 飞机的重力G=FB. 飞机的重力G=FsinθC. 飞机水平前进的动力为FsinθD. 飞机水平前进的动力为Ftanθ4.在做“验证力的平行四边形定则”的实验中,以下说法中正确的是()A. 用两只弹簧测力计拉橡皮条时,两细绳之间的夹角必须为90°,以便求出合力的大小B. 用两只弹簧测力计拉橡皮条时,结点的位置必须与用一只弹簧测力计拉时结点的位置重合C. 若用两只弹簧测力计拉时,合力的图示F与用一只弹簧测力计拉时拉力的图示F′不完全重合,说明力的合成的平行四边形定则不一定是普通成立的D. 同一实验过程中,结点O的位置允许变动5.冬以来,全国多地多次发生雾霾天气,能见度不足100m.在这样的恶劣天气中,甲、乙两汽车在一条平直的单行道上,乙在前,甲在后同向行驶.某时刻两车司机同时听到前方有事故发生的警笛提示,同时开始刹车,结果两辆车发生了碰撞.如图所示为两辆车刹车后若恰好不相撞的v−t图象,由此可知()A. 两辆车刹车时相距的距离一定等于112.5mB. 两辆车刹车时相距的距离一定小于90mC. 两辆车一定是在刹车后的20s之内的某时刻发生相撞的D. 两辆车一定是在刹车后的20s以后的某时刻发生相撞的6.某物体做匀变速直线运动,若它运动全程的平均速度是v1,运动到中间时刻的速度是v2,经过全程一半位移时的速度是v3,则下列关系中正确的是()A. v1=v2<v3B. v1<v2=v3C. v1=v2>v3D. v1>v2=v37.在如图所示装置中,两物体质量分别为m1、m2,悬点a、b间的距离远大于滑轮的直径,不计绳重及一切摩擦,整个装置处于静止状态。
四川省成都七中2019—2020学年高二物理上学期期中试题(含解析)一、单项选择题 1.下列说法中正确的是A 。
摩擦起电的实质是通过外力做功凭空产生了电荷B 。
电子就是元电荷C 。
由公式2kQE r =可知,当r →0时,E →∞,因此可得场强为无穷大的电场 D 。
电场强度的方向就是电势降低最快的方向 【答案】D 【解析】【详解】A.电荷既不能被创生,也不能被消灭,摩擦起电还是感应起电,都是电荷的转移,故A 错误;B.元电荷是指电子或质子所带的电荷量,数值为191.6010C e -=⨯,但不能说电子就是元电荷,故B 错误;C.公式2QE kr=只适用点电荷产生的电场,当0r →时,带电体不能看成点电荷,该公式不再成立,所以不能得出“当0r →时,E →∞”的结论,故C 错误; D 。
电场强度的方向就是电势降低最快的方向,故D 正确. 2。
下列四个电场中,a 、b 两点电场强度相同的是A. B 。
C. D.【答案】C 【解析】【详解】A. a 、b 是同一等势面上的两点,场强大小相等,但方向不同,则电场强度不同,故A错误;B。
a点电场线比b点电场线密,则a点场强较大,故B错误;C. a、b是匀强电场中的两点,电场强度相同,故C正确;D。
等量异种电荷连线的中垂线是一条等势线,根据电场线的分布可知a点场强较大,故D错误。
3。
下列说法中正确的是A。
把一根均匀导线等分成等长的两段,则每部分的电阻率也变为原来的一半B。
电容器所带的带电量越多,说明它的电容越大C。
电动势的单位跟电压的单位一样,都是伏特,所以电动势就是电压D。
其他电阻不变时,并联电路中其中一个电阻增大,总电阻增大【答案】D【解析】【详解】A。
根据电阻决定式为LRSρ=,可知把一根均匀导线分成等长的两段,则每部分的电阻变为原来的一半,但电阻率与温度和材料有关,与其他因素无关,故电阻率不变,故A 错误;B。
电容器的电容是表征电容器容纳电荷本领大小的物理量,由电容器本身的特性决定,与两极板间的电压和所带的电荷量无关,故B错误;C。
四川省成都七中2019学年高三上学期期中考试理综试题本试卷分为第I卷(选择题)和第n卷(非选择题)两部分,第I卷1-4页,第n卷5-15页.第I卷(选择题)注意事项:1.答第I卷前,考生务必将自己的姓名、考号、考试科目用铅笔填写在答题卡上.2 .每小题选出答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,在选涂其它答案,不能答在试题卷上.3.本卷共21题,每小题6分,共126分.可能用到的相对原子质量:H— 1 O —16 N —14 C —12 Cl —35.5 Cu —64 Na —23一.选择题(本题包括13小题,每题6分,共78分,每小题只有一个选项符合题意)1.右图是细胞直接与内环境进行物质交换示意图,⑤处的箭头表示血液流动的方向。
下列说法正确的是()A. 若③为组织细胞,其生活的具体内环境中的水可来自于③和①B. 若③为脑细胞,⑤处的氧气浓度低于①处,而CO的浓度相反C. 若③为骨骼肌细胞,饭后五小时⑤处的血糖浓度低于①处D. 若③为胰岛B细胞,饭后半小时⑤处的胰岛素浓度高于①处2 .用植物细胞的必需元素配置成完全培养液,在相同的加盖容器内分别培养水稻和番茄幼苗,一段时间后,测定培养液中各种离子与试验开始时各种离子浓度之比如图所示,该试验的结果可以说明()矿质元素的种奠□水稻|番茄A.植物细胞对离子的吸收和对水吸收成正比B.番茄根细胞吸收Si的载体比水稻多C.植物对离子的吸收与离子的浓度成正比D.实验结果表明植物不仅吸收矿质元素也吸收水3.免疫是机体的一种特殊的保护性生理功能。
下列有关的叙述中,正确的有几项:()①受抗原刺激后的淋巴细胞,细胞周期会变长,核糖体活动增强②突破皮肤、黏膜等第一道防线后,机体免疫的第二道防线吞噬细胞、溶酶体会对侵入人体的抗原起作用③能识别抗原的细胞有:吞噬细胞、T细胞、B细胞、效应B细胞、记忆细胞④T淋巴细胞与细胞免疫、体液免疫都有关,B淋巴细胞与体液免疫有关,而与细胞免疫无关⑤尽管特异性免疫针对性强,对抗原的杀伤效果好,但机体最终将抗原清除大多数还是要依赖非特异性if免疫A. —项B .二项 C .三项 D.四项4•下图是下丘脑及其直接或间接支配的有关腺体之间关系示意图( 有关说法不正确的是()"+”表示促进,“-”表示抑制)。
一、单选题四川省成都七中实验学校2019-2020学年高二上学期期中考试物理试题1. 关于物理学史和力学单位,下列说法正确的是A .卡文迪许利用扭秤实验测出了静电力常量k 的数值,结果为 k =9.0×109N.m/C 2B .电场强度的单位可以是 N/C 和 V/mC .电功率P=UI 中 P 的单位可以为 W ,还可以为D .密立根油滴实验测量了电子电荷量,e =1.60×1019C2. 将两个分别带有电荷量−2Q 和+5Q 的相同金属小球 A 、B 分别固定在相距为r 的两处(均可视为点电荷),它们间库仑力的大小为F 。
现将第三个与 A 、B 两小球完全相同的不带电小球 C 先后与A 、 B 相互接触后拿走,A 、B 间距离保持不变,则两球间库仑力的大小为( )A .B .C .D .3. 如图所示,A 、B 为两电阻的电压与电流图像,关于两电阻的描述正确的是C .在两图线交点处,电阻A 的阻值大于电阻B变B .在两图线交点处,电阻A 的阻值等于电阻BA .电阻A 的电阻随电流的增大而减小,电阻B 阻值不D.在两图线交点处,电阻A的阻值小于电阻B4. 小宇同学在探究电表改装时,取了两个满偏电流均为I g=1mA、内阻r g=30Ω的表头,分别改装成量程为 0~3V 的电压表和量程为 0~0.6A 的电流表。
下列操作正确的是A.改装成电压表应该串联一个 2990Ω的定值电阻,改装成电流表应该并联一个 0.15Ω的定值电阻B.改装成电压表应该并联一个 2990Ω的定值电阻,改装成电流表应该串联一个 0.15Ω的定值电阻C.改装成电压表应该串联一个 2970Ω的定值电阻,改装成电流表应该并联一个 0.05Ω的定值电阻D.改装成电压表应该并联一个 2990Ω的定值电阻,改装成电流表应该串联一个 0.05Ω的定值电阻5. 电阻R和电动机M串联接到电路时,如图所示,已知电阻R跟电动机线圈的电阻值相等,电键接通后,电动机正常工作.设电阻R和电动机M两端的电压分别为U1和U2,经过时间t,电流通过电阻R做功为W1,产生热量Q1,电流通过电动机做功为W2,产生热量为Q2,则有()A.U1<U2,Q1=Q2B.U1=U2,Q1=Q2C.W1=W2,Q1>Q2D.W1<W2,Q1<Q2二、多选题6. 两个带电小球A、B(可视为点电荷)的质量分别为 m1和m2,带电荷量分别为q1和 q2,用长度相同的绝缘细线拴住并悬挂于同一点,静止时两悬线与竖直方向的夹角相等.则m1和m2、q1和q2的关系可能是A.q1=q2,m1=m2B.q1> q2,m1> m2C.q1< q2,m1=m2D.q1< q2,m1> m27. 如图(1)是某一点电荷形成的电场中的一条电场线,A、B是电场线上的两点,一负电荷q仅在电场力作用下以初速度v0从A运动到B 过程中的速度图线如图(2)所示,则以下说法中正确的是A.A、B两点的电场强度是E A>E BB.A、B两点的电势差U AB>0C.负电荷q在 A到B过程中电势能增大D.由于电场方向由 A→B,所以此电场是由A点左侧正点电荷形成的8. 在空间 O点固定带正电的点电荷Q,其电场的电场线如图所示,在其电场中的A 点有一个带电粒子q(重力不计)。
2023外研版-高二上册-成都第七中学-(第二次月考模拟试卷)(本试卷不含听力)题号A卷B卷总分得分注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
第一部分阅读[共两节,满分50分]第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项。
A篇This document sets out the display standards for Glasgow Museums. This guide will help exhibition planners provide access to exhibitions in our museums. Glasgow Museums’ aim is to improve access to collections by having as many items as possible on display and without physicalbarriers. We also try our best to protect these objects without limiting access to them.Object Placement*Don’t place objects in such a way that they could present a danger to visitors.*All object displays, cased or otherwise, must be viewable by all, including people who are small in figure or in wheelchairs.Open Display*All objects on open display must be Secure from theft and damage.*All objects identified for potential open display must be viewed and agreed on an object-to-object basis byRecommendations DistanceRecommended distance to place objects out of “casual arm's 700mm length”700mm(taken from the edge of the object to the edge of any proposed form ofbarrier)Cased Objects*All cased displays should fall within the general optimum(最优的)viewing band of 750-2,000mm. Ensure everything is visually accessible from a wheelchair.*Position small objects or those with fine detail in the front part of a case, with larger items behind.*Position small items or those with fine detail no higher than 1,015mm from floor level. Objects placed abovethis height are only seen from below by people in wheelchairs or people who are small in figure.( )1. From this text, we can learn that Glasgow Museums______.A. limit access to exhibitions on a daily basisB. are most well-known for its large collectionC. make generous donations to the disabledD. give weight to the experiences of visitors( )2. According to the guide, objects to be placed on open display must______.A. be equipped with anti-theft systemB. be viewed from a distance of 700mmC. receive approval from the museum firstD. fall within arms' reach of a standing man( )3. A mother and her 10-year-old son are likely to both feel comfortable in front of a diamond placed in a glass case at the height of______.A.1,250mmB.950mmC.650mmD.450mmB篇In mammals, loud calls usually serve as alarm signals that warn fellow species of an enemy or other danger. On the other hand, screams from humans can have very different meanings, as Swiss researchers now report in the journal“PLoS Biology”. Human’s screams are not always only associated with negative emotions such as fear, pain, anger and grief, but also positive emotions such as joy and pleasure.Sascha Frihholz and his colleagues from the University of Zurichstudied how many types of human screams there are, how accurately test subjects can distinguish them, and which brain regions are involved(参与)in processing such sound signals. To do this, they first made sound recordings of different screams. Twelve men and women were to put themselves in situations where they reacted with a brief scream. The predetermined situations included, for example: an attack by an armed stranger, celebration about a sporting victory of their favorite team, the threat of an opponent.From the recordings, the researchers finally selected 420 screams. From this, they identified six distinct categories of screams, including three of alarming characters (cries of pain, anger, and fear) and three non-alarming screams ( as expressions of great pleasure, extreme joy, and desperate sadness). Contrary to all expectations, the subjects reacted to non-alarming screams more quickly and recognized the emotion expressed with it more reliably than with alarming screams. This was also confirmed by images of the brain using functional magnetic resonance imaging(FMR).“Until now, researchers assumed that humans also detect and process perceived alarm signals particularly quickly in the form of screams, as this is an important survival mechanism(机制),”says Frihholz. But unlike monkeys and other mammals, non-alarming screams would have become more important for communication.“This changed priority(优先)is probably due to needs that have evolved in the evolution of complex human social relationships."( )4. What does the text mainly talk about?A. Human’s screams expressions.B. An experiment launched in screams.C. Loud calls as a survival mechanism.D. Mammals' loud calls served as alarm signals.( )5. Which expression can be reacted to more quickly?A. Cries of pain.B. Anger.C. Fear.D. Desperate sadness( )6. What does the last paragraph convey?A. Monkeys are not sensitive to non-alarming screams.B. Humans survive because of quick reaction to screams.C. Non-alarming screams gain priority because of human’s revolution.D. Non-alarming screams make human social relationships more complex.( )7. What is the purpose of the text?A. To spread and advocate.B. To argue and discuss.C. To compare and inform.D. To recommend and introduce.C篇Good manners are always good manners. That's what I thought until I married Alexander, who is Russian.When I first met Alexander and he said to me in Russian, “Nalei mnye chai-pour me some tea.” I got angry and answered, “Pour it yourself." Translated into English, without a“please”, it sounded really rude to me. But in Russian it was fine-you don't have to add any polite words.However, when I took Alexander home to meet my parents in the UK, I had to give him a good lesson about pleases and thank-yous, and to teach him to smile, smile, smile.Another thing that Alexander just couldn't understand was why people say things like “Wouldyou mind passing me the salt, please?" He said, “It's only the salt, for God’s sake! What do you say in English if you want a real favour?”He also watched in amazement when, at a dinner party in England, we swallowed some really disgusting food and I said, “Mmmm... delicious." In Russia, people are much more direct. The first time Alexander's mother came to our house for dinner, she told me that my soup needed more flavouring. Afterwards, when we argued about it, my husband said, “Do you prefer your dinner guests to lie?"Alexander complained that in England he felt like an idiot because in Russia if you smile all the time people think you are mad. In fact, this is exactly what my husband's friends thought of me the first time I went to Russia because I smiled at everyone.At home we now have an agreement. If we're speaking Russian, he can say “Pour me some tea”. But when we're speaking English, he has to add a “please”, a “thank you”, and a smile.( )8.What can we know from what Alexander said?A. He didn't think politeness was necessary.B. He didn't like the writer's politeness.C. He wasn't used to the English politeness.D. He wasn’t willing to have good manners.( )9. What did Alexander's friends think of the author when they first met her?A.She was noble.B. She was strange.C. She was lovely.D. She was impolite.( )10. What can we learn from their agreement?A. They respect each other.B. They change a lot for each other.C. They learn from each other.D. They fail to fit in with each other.( )ll. What topic is the text mainly about?A. Good manners.B. Human relations.C. Culture shock.D. Mixed marriages.D篇What fisherman Moul Thun from a remote island in the Mekong River, in northern Cambodia, didn't know was that stingray(黄貂鱼) he hooked would eventually be named the largest recorded freshwater fish. For Zeb Hogan, who’s been documenting large freshwater fishes for almost two decades, the discovery of the stingray, which was released alive back into the river, filled him with hope. "It proves these underwater big fish, which are in critical danger, still exist," says Hogan.Hogan's pursuit for big fish, called the Megafishes Project and supported by National Geographic Society, began in 2005 when fishermen in northern Thailand pulled a 646 pound catfish out of the Mekong River. The species is known that it was the largest, that is, the heaviest-ever caught in the area.Arriving at the island, the team found Thun's fish, a female that appeared to be in good health. It was more than 13 feet from nose to tail. The researchers were shocked to see her weight at 661 pounds. She set a new world record. The original aim of the Megafishes Project was to find, study, and protect the world's largest freshwater fishes. The project focused on species that could grow to at least the size of a human and that lived only in freshwater.Hogan initially drew up a list of roughly 30 species to focus on.The challenge, as Hogan soon learned, was that many of these fish are hard to find. They live in remote, inaccessible places, and often in deep waters. Early on in the search, there were relatively few scientists studying them.What was clear was that the river giants were shrinking in number, threatened by a host of factors including overfishing, water pollution, and the presence of dams, which block migrating fish from completing their life cycles. As Hogan's work progressed, its focus increasingly turned to conservation. “It was never about just finding the biggest fish,” Hogan says, “but looking for ways to protect these extraordinary animals that, in some cases, have been on Earth for hundreds of millions of years but are now drifting out of entities."( )12. Why was Zeb Hogan full of hope?A. Freshwater fishes weren’t in danger.B. Some large fishes didn’t die out.C. The stingray was put into the river.D. Many large fishes existed in rivers.( )13. What can we know about the 646-pound catfish?A. It was also caught by Moul Thun.B. It's the largest recorded freshwater fish.C. It was injured very seriously.D. It was caught in the Mekong River.( )14. Which of the following is the original goal of the Megafishes Project?A. Finding about 30 species of big fishes.B. Studying fishes smaller than humans.C. Protecting big freshwater fishes.D. Setting new record in finding fishes.( )15. What does the underlined part “drifting out of entities" in the last paragraph mean?A. Dying outB. Getting illC. Being protected.D. Living well.第二节(共5小题;每小题2.5分,满分12.5分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。
绝密★启用前
四川省成都市第七中学
2019~2020学年高二年级上学期期中质量检测
物理试题
2019年11月
考试时间:100分钟满分:110分
第Ⅰ卷选择题(48 分)
一、单项选择题(本大题共12 题,每小题2 分,共24 分,其中每题只有一个正确答案)
1、下列说法中正确的是()
A.摩擦起电的实质是通过外力做功凭空产生了电荷
B.电子就是元电荷
C.由公式E =kQ
r2
可知,当r→0 时,E→∞,因此可得场强为无穷大的电场
D.电场强度的方向就是电势降低最快的方向
2、下列四个电场中,a、b 两点电场强度相同的是()
3、下列说法中正确的是( )
A.把一根均匀导线等分成等长的两段,则每部分的电阻率也变为原来的一半
B.电容器所带的带电量越多,说明它的电容越大
C.电动势的单位跟电压的单位一样,都是伏特,所以电动势就是电压
D.其他电阻不变时,并联电路中其中一个电阻增大,总电阻增大
4、如图甲所示电路,小灯泡通电后其两端电压U 随所通过的电流I 变化的图线如图乙所示,P 为图线上一点,PN 为图线的切线,PM 为U 轴的垂线,PQ 为I 轴的垂线,下列说法中正确的是( )
A.随着电流的增大,小灯泡电阻逐渐减
小
B.对应P 点,小灯泡的电阻为R=
U
1 I
2
-I
1
C.在电路中灯泡L 两端的电压为U1 时,电阻R 两端的电压为I1R
1
D.对应P 点,小灯泡的功率为图中四边形PQOM 所围的“面积”
2。