湖南省益阳市2017届高三9月调研考试英语试题

2017届高三第七次月考英语试题2016-12-20第Ⅰ卷（选择题，共 115 分）第一部分听力（共 20 小题；每小题 1.5 分，共 30 分）第一节（共 5 小题；每小题 1.5 分，满分 7.5 分）听下面 5 段对话。

每段对话后有一个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．Where are the two speakers?A．In a bookstore．B．In the library．C．In the post office．2．How will the speakers get to their destination?A．By bus．B．By taxi．C．By subway．3．What was the man’s son doing a t the supermarket?A．Working．B．Killing the time． C．Going shopping．4．How much does the man weigh now?A．80 pounds．B．120 pounds．C．160 pounds．5．What caused the car accident?A．Speed driving．B．The bad weather．C．Careless driving．第二节(共15小题；每小题1.5分，满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟：听完后，各小题给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第6、7题。

6．Why are the mall and Alice often together?A．They are in love．B．They are best friends．C．They often study together．7．What’s the most probable relationship between the two speakers?A．Teacher and student． B．Brother and sister．C．Classmates．听第7段材料，回答第8、9题。

秘密★启用前益阳市2021届高三9月调研考试英语注意事项：1. 答素前，考生务必将自己的姓名、考生号等填写在答题卡和试题卷指定位置。

2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上。

写在本试题卷上无效。

3. 考试结束后，将本试卷和答题卡一并交回。

第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍1. What will the man do this weekend?A.See a doctor.B. Walk around the lake.C. Work at the hospital.2. Where are the speakers?A. On the street.B. At home.C. In a car.3. What is the woman worried about?A. Her interview.B. Her trip.C. Her daughter.4. Who speaks Spanish the fastest?A. Sally.B. Ryan.C. Howard.5. What does the woman suggest buying?A. A bookshelf.B. A sofa.C. A table.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟; 听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

益阳市2017 届高三9 月调研考试英语参考答案1-5 BABCC 6-10 ABBCC 11-15 CBCBA 16-20 CBBCA21-23ACB 24-27 CDAB 28-31 CDAB 32-35 BCDC 36-40 FGCBD41-45 CBADC 46-50 CBBDA 51-55 CDABC 56-60 ABDDB61. beneficial 62. has shown 63. less 64. to reduce 65. breaths66. apology 67. who/ that 68. a 69. accepting 70. from短文改错Last winter, I went skiing in Switzerland. One day, I was skiing down a mountain while I saw a girlwhenaged about 15 who had fallen. She was clearly hurt, crying and trying∧get up, and she couldn’t. So I flaggedto butdown someone to get the ski patrol and stayed with her, talking about her. It was getting extreme cold. About half with/ to extremelyan hour late, the ski patrol showed up and took him down the mountain. I stayed with her because she was solater herscaring. She kept saying, “I think there might be something wrong.”I said, “I’ll make sure of that you get the care scared 去掉you need.”Finally the ambulance come and took her to the nearest hospital. I was very happy that day because my camepresence and assistance were significant to someone in need.书面表达：参考范文The city library is recruiting (招募) volunteers among high school students who are supposedto work on weekends.Those who take an interest are expected to be patient, enthusiastic and responsible high school students in our city. It is required that you should spend at least two hours every weekend working in the library.Tasks for a volunteer include sorting out books, helping readers to borrow or return books and doing some cleaning work. It is also your duty to remind readers to keep quiet in reading rooms and put books in place after reading.If you’d like to join us, you’d better fill in the application form online and email it tocitylibrary@ before next Saturday. The application form can be downloaded from the library website. We are looking forward to your participation.。

2017届高三英语上学期第一次调研测试试题第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。

录音结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节（共5小题；每小题l.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来问答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Where does the conversation take place?A. In a hotel.B. In a schoolC. In a supermarket .2. What is the woman doing?A. Buying a handbag.B. Drawing a colorful picture.C. Trying on a piece of clothing.3. When will the man go to the cinema?A. On Sunday morning.B. On Sunday afternoon.C. On Sunday evening.4. What kind of tea does Tina usually drink?A. English tea.B. Japanese tea.C. Chinese tea .5. How much will the man pay?A. $8.B.$32.C.$40.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5 秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第6、7题。

6. What is Jenny doing now?A. Getting up in her roomB. Preparing for party.C. Performing on stage.7. What did the man come for Jenny?A. To bring her a dress.B. To get her some flowers.C. To invite her to a movie.听第7段材料，回答第8、9题。

2017高三英语9月考考试试题（时间：120分钟总分：150分Ⅰ卷交答题卡，Ⅱ卷交答题纸）第一部分：听力（共两节，满分20分）第一节（共5小题；每小题1分，满分5分）请听下面5段对话，选出最佳选项。

1. Who is the woman talking to?A. James.B. Drake.C. Daniel.2. Why was the man arrested?A. He robbed a bank last week.B. He looks very similar to a criminal.C. He broke into his neighbor’s house.3. What does the woman think the man should do?A. Drive a bit faster.B. Keep driving like that.C. Drive 55 miles per hour.4. When should the two speakers hand in the term paper?A. On October 6th.B. On October 16th.C. On October 26th.5. What may prevent the woman from getting the dress?A. The color.B. The price.C. The size.第二节（共15小题；每小题1分，满分15分）请听下面5段对话或独白，选出最佳选项。

请听第6段材料，回答第6、7题。

6. How much should the man pay in total?A. $115.B. $120.C. $125.7. What does the woman advise the man to do?A. Have a professional tailor his pants.B. Use a plastic b ag to put his pants in.C. Think it over before having the pants shortened.请听第7段材料，回答第8、9题。

2017高考英语试卷及答案及英语调研考试卷2017高考英语试卷及答案及英语调研考试卷全面复习：“地毯式轰炸”;查缺补漏：“精确制导”。

祝高考顺利!下面是店铺为大家推荐的2017高考英语试卷，仅供大家参考!英语调研考试卷第一卷第一部分听力第一节(共5小题;每小题1分，满分5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Why did the man get wet?A. He was caught in the rain.B. He fell into water.C. A fountain wetted him.2. How does the man probably feel now?A. Worried.B. Excited.C. Bored.3. What time does the man usually return home on the weekend?A. By 10 pm.B.By 10:30 pm.C. By midnight.4. What did the woman think of rabbits?A. ScaryB.LovelyC.Shy5. How does the man probably learn English now?A. By watching videos.B. By learning at a school.C. By taking online lessons.第二节(共15小题;每小题1分，满分15分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟：听完后，各小题给出5秒钟的做答时间。

2014级高三上学期第一次月考试题参考答案第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）1-3 BCA 4---7 BDBC 8--11 DABA 12--15 CBAB第二节（共5小题，每小题2分，满分10分）16-20 DGAFE第二部分语言知识及应用（共两节，满分45分）第一节完形填空(共20小题；每小题1.5分，满分30分)21-25 CBDCA 26-30 BABCC 31-35 ABACD 36-40 CCADA第二节（共10小题；每小题1.5分，满分15分）41. who/that 42. is welcomed 43. Compared 44. disadvantages 45. reliable46. the 47. It 48. truly 49. with 50. being cheated第三部分词汇与句子结构（共两节，满分30分）第一节词汇基础（共10小题；每小题0.5分，满分5分）51. symptoms 52. fortune 53. departure 54. adopted 55. appointed56. thorough 57.accompanying 58. adapting/adjusting 59. changeable 60. challenging 第二节句型结构（共10小题；每小题1分，满分10分）61. was robbed of 62. be harmful to 63. takes action 64. In addition65. be aware of 66. approve of 67.burst out laughing 68.In case of69.took charge of 70.was bored with第四部分写作（共两节，满分35分）第一节短文改错（共10小题；每小题1分，满分10分）(请在答卷上完成)1. I had noticed that去掉had2. noise改为noisy.3. a train inspector comes to check 中comes改为came4. but became quite upset 中but改为and5. searching后面加for6. a seat several rows from his owner中his改为its/the7. who found a ticket中a改为the 8. previous改为previously9. strangers改为stranger 10. live后面加in.第二节书面表达（满分25分）Dear Sir/Madam,I’m Li Hua, a Chinese student taking summer courses in your university.Everything is going well. I enjoy all the courses here but one offered by Professor Martin Bygate. I have difficulty understanding him in class. He has a very strong accent, which makes it hard for me to follow him in class. I feel worried about this. I was told that I can go to the Learning Center for help. I’m wondering if I could come on Wednesday and Friday afternoon. I have no classes at both times and can manage to come for help and suggestions. Please let me know which time is OK with you either via lihua@ or 12345678.I am looking forward to your reply.Yours,Li Hua共1页。

2017年湖南省普通高中学业水平考试英语本试题卷分听力技能、阅读技能、知识运用、写作技能四个部分，共7页。

时量120分钟。

满分100分。

第一部分听力技能(共两节，满分20分)做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题；每小题1分，满分5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话读两遍。

例：How much is the shirt?A. ￡19.15.B. ￡9.18.C. ￡9.15.答案是C。

听下面一段对话，回答第1小题。

1. What will the woman do this weekend?A. Go camping.B. Go swimming.C. Go fishing.听下面一段对话，回答第2小题。

2. What time did the woman get up?A. At 7:00.B. At 7:20.C. At 7:40.听下面一段对话，回答第3小题。

3. What is the weather like today?A. Sunny.B. Cloudy.C. Rainy.听下面一段对话，回答第4小题。

4. Why does the man look tired?A. He stayed up late.B. He didn’t sleep well.C. He worked too long.听下面一段对话，回答第5小题。

5. Where are the speakers now?A. In a bookshop.B. In a sports shop.C. In a coffee shop.第二节(共15小题；每小题1分，满分15分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

2016-2017学年湖南省益阳市高三（上）9月调研数学试卷（理科）一、选择题：本大题共12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1．若z=（a 2﹣1）+（a ﹣1）i 为纯虚数，其中a ∈R ，则等于（ ）A ．﹣iB ．iC ．1D ．1或i2．设A 、B 是两个集合，则“A ∩B=A ”是“A ⊆B ”的（ ） A ．充分不必要条件 B ．必要不充分条件 C ．充要条件 D ．既不充分也不必要条件3．设a=1.70.3，b=log 30.2，c=0.25，则a ，b ，c 的大小关系是（ ） A ．a ＜b ＜c B ．b ＜a ＜c C ．c ＜b ＜a D ．b ＜c ＜a4．从一个边长为2的等边三角形的中心、各边中点及三个顶点这7个点中任取两个点，则这两点间的距离小于1的概率是（ ）A ．B ．C ．D ．5．在等差数列{a n }中，已知a 5+a 10=12，则3a 7+a 9=（ ） A ．12 B ．18 C ．24 D ．306．已知（ax +1）6的二项展开式中含x 3项的系数为，则a 的值是（ ）A ．B ．C ．D ．27．三角函数y=sin （﹣2x ）+cos2x 的振幅和最小正周期分别为（ ）A ．，B ．，πC ．，D ．，π8．一空间几何体的三视图如图所示，则该几何体的体积为（ ）A ．1B ．3C ．6D ．29．给出一个如图所示的程序框图，若要使输入的x 的值一输出的y 的值相等，则x 的可能值的个数为（ ）A．1个B．2个C．3个D．4个10．已知F1，F2分别是椭圆的左，右焦点，现以F2为圆心作一个圆恰好经过椭圆中心并且交椭圆于点M，N，若过F1的直线MF1是圆F2的切线，则椭圆的离心率为（）A．﹣1 B．2﹣C．D．11．设两个向量=（λ+2，λ2﹣cos2α）和=（m， +sinα），其中λ，m，α为实数．若=2，则的取值范围是（）A．[﹣1，6] B．[﹣6，1] C．（﹣∞，]D．[4，8]12．定义在（0，）上的函数f（x），f′（x）是它的导函数，且恒有f′（x）＞f（x）•tanx 成立．则（）A．f（）＜f（）B．f（1）＜2cos1•f（）C．f（）＞2f（）D．f（）＞f（）二、填空题：本大题共4小题，每小题5分.13．若过点（0，2）的直线l与圆（x﹣2）2+（y﹣2）2=1有公共点，则直线l的斜率的取值范围是．14．已知变量x，y满足约束条件，则z=x+2y的最大值是9．15．已知数列{a n}的前n项和为S n，且S n=n﹣5a n+23，n∈N*，则数列{a n}的通项公式是a n=1+．16．已知三棱锥P﹣ABC的所有顶点都在球O的球面上，△ABC是边长为2的正三角形，PC为球O的直径，且PC=4，则此三棱锥的体积为．三、解答题：解答应写出文字说明、证明过程或演算步骤.）17．已知△ABC是半径为2的圆的内接三角形，内角A，B，C的对边分别为a、b、c，且2acosA=ccosB+bcosC．（Ⅰ）求A；（Ⅱ）若b2+c2=18，求△ABC的面积．18．某班50位学生期中考试数学成绩的频率直方分布图如图所示，其中成绩分组区间是：[40，50），[50，60），[60，70），[70，80），[80，90），[90，100]．（1）求图中x的值；（2）从成绩不低于80分的学生中随机选取2人，该2人中成绩在90分以上（含90分）的人数记为ξ，求ξ的数学期望．19．如图，在直二面角E﹣AB﹣C中，四边形ABEF是矩形，AB=2，AF=2，△ABC是以A为直角顶点的等腰直角三角形，点P是线段BF上的一点，PF=3．（Ⅰ）证明：BF⊥面PAC；（Ⅱ）求二面角A﹣BC﹣P的余弦值．20．已知抛物线C：y2=4x，过其焦点F作两条相互垂直且不平行于坐标轴的直线，它们分别交抛物线C于点P1、P2和点P3、P4，线段P1P2、P3P4的中点分别为M1、M2．（Ⅰ）求线段P1P2的中点M1的轨迹方程；（Ⅱ）求△FM1M2面积的最小值；（Ⅲ）过M1、M2的直线l是否过定点？若是，求出定点坐标，若不是，请说明理由．21．设函数f（x）=x2+lnx﹣mx（m＞0）．（I）求f（x）的单调区间；（Ⅱ）求f（x）的零点个数；（Ⅲ）证明：曲线y=f（x）上没有经过原点的切线．请考生在22、23、24三题中任选一题作答.注意：只能做所选定的题目.如果多做，则按所做的第一个题目记分，作答时请用2B铅笔在答题卡上将所选题号后的方框涂黑.[选修4-1：几何证明选讲]22．如图所示，BC是半圆O的直径，AD⊥BC，垂足为D，，BF与AD、AO分别交于点E、G．（1）证明：∠DAO=∠FBC；（2）证明：AE=BE．[选修4-4：坐标系与参数方程]23．在平面直角坐标系xOy中，以坐标原点O为极点，x轴正半轴为极轴建立极坐标系，曲线C的极坐标方程为ρ=2sinθ，θ∈[0，2π）．（1）求曲线C的直角坐标方程；（2）若点D在曲线C上，求它到直线l：（t为参数，t∈R）的最短距离．[选修4-5：不等式选讲]24．设函数f（x）=|x﹣a|+5x．（1）当a=﹣1时，求不等式f（x）≤5x+3的解集；（2）若x≥﹣1时有f（x）≥0，求a的取值范围．2016-2017学年湖南省益阳市高三（上）9月调研数学试卷（理科）参考答案与试题解析一、选择题：本大题共12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1．若z=（a2﹣1）+（a﹣1）i为纯虚数，其中a∈R，则等于（）A．﹣i B．i C．1 D．1或i【考点】复数代数形式的乘除运算．【分析】由纯虚数的定义得a=﹣1，从而=，由此利用复数代数形式的运算法则能求出的值．【解答】解：∵z=（a2﹣1）+（a﹣1）i为纯虚数，其中a∈R，∴，解得a=﹣1，∴====i．故选：B．2．设A、B是两个集合，则“A∩B=A”是“A⊆B”的（）A．充分不必要条件B．必要不充分条件C．充要条件 D．既不充分也不必要条件【考点】必要条件、充分条件与充要条件的判断．【分析】直接利用两个集合的交集，判断两个集合的关系，判断充要条件即可．【解答】解：A、B是两个集合，则“A∩B=A”可得“A⊆B”，“A⊆B”，可得“A∩B=A”．所以A、B是两个集合，则“A∩B=A”是“A⊆B”的充要条件．故选：C．3．设a=1.70.3，b=log30.2，c=0.25，则a，b，c的大小关系是（）A．a＜b＜c B．b＜a＜c C．c＜b＜a D．b＜c＜a【考点】对数值大小的比较．【分析】化简成底数相同，如果底数无法化成同底数，则利用中间值，再利用对数函数和指数函数的性质求解．【解答】解：由指数函数的性质可知，底数大于1时，是增函数，指数越大，函数值越大．∵a=1.70.3＞1.70=1，∴a＞1．由对数函数的性质可知，底数大于1时，是增函数，真数越大，函数值越大．∵b=log30.2，∴b＜0．c=0.25=，∴0＜c＜1．所以：b＜c＜a故选：D4．从一个边长为2的等边三角形的中心、各边中点及三个顶点这7个点中任取两个点，则这两点间的距离小于1的概率是（）A．B．C．D．【考点】几何概型．【分析】根据等边三角形的性质，分别求出任取两个点间的距离，然后求出这7个点中任取两个点的所有种数，找到满足两点间的距离小于1的种数，根据概率公式计算即可．【解答】解：如图，△ABC为等边三角形，D，E，F分别为BC，AC，AB上中点，交点为O，∴AB=BC=AC=2，AD=BE=CF=，EF=DE=DF=1，AE=CE=AF=BF=BD=CD=1，A0=BO=CO=，OD=OE=OF=，由这7个点中任取两个点共有C72=21种，其中这两点间的距离小于1只能是OD，OE，OF 共三种，故这两点间的距离小于1的概率是=，故选：A．5．在等差数列{a n}中，已知a5+a10=12，则3a7+a9=（）A．12 B．18 C．24 D．30【考点】等差数列的通项公式．【分析】由等差数列的通项公式得2a1+13d=12，由此能求出3a7+a9的值．【解答】解：∵在等差数列{a n}中，a5+a10=12，∴2a1+13d=12，3a7+a9=3（a1+6d）+a1+8d=4a1+26d=2（a1+13d）=2×12=24．故选：C．6．已知（ax+1）6的二项展开式中含x3项的系数为，则a的值是（）A．B．C．D．2【考点】二项式系数的性质．【分析】先求得二项式展开式的通项公式，再令x的幂指数等于3，求得r的值，即可求得含x3项的系数，于是可是得到关于a的方程解得即可．=C6r•a r•x r，【解答】解：二项式的展开式的通项公式为T r+1令r=3，故开式中含x3项系数为C63•a3=，解得a=，故选：C．7．三角函数y=sin（﹣2x）+cos2x的振幅和最小正周期分别为（）A．，B．，πC．，D．，π【考点】y=Asin（ωx+φ）中参数的物理意义．【分析】直接利用特殊角的三角函数值以及两角和的正弦函数公式、余弦函数公式化简函数解析式为y=cos（2x+），然后求解最小正周期和振幅．【解答】解：∵y=sin（﹣2x）+cos2x=cos2x﹣sin2x+cos2x=cos2x﹣sin2x=cos（2x+），∴三角函数y=sin（﹣2x）+cos2x的振幅和最小正周期分别为：，π．故选：B．8．一空间几何体的三视图如图所示，则该几何体的体积为（）A．1 B．3 C．6 D．2【考点】由三视图求面积、体积．【分析】几何体是一个四棱锥，四棱锥的底面是一个直角梯形，直角梯形的上底是1，下底是2，垂直于底边的腰是2，一条侧棱与底面垂直，这条侧棱长是2，【解答】解：由三视图知，几何体是一个四棱锥，四棱锥的底面是一个直角梯形，直角梯形的上底是1，下底是2，垂直于底边的腰是2，一条侧棱与底面垂直，这条侧棱长是2，∴四棱锥的体积是=2，故选D．9．给出一个如图所示的程序框图，若要使输入的x的值一输出的y的值相等，则x的可能值的个数为（）A．1个B．2个C．3个D．4个【考点】选择结构．【分析】由已知的程序框图，我们可得该程序的功能是计算并输出分段函数y=的值，结合输入的x值与输出的y值相等，我们分类讨论后，即可得到结论．【解答】解：分析程序中各变量、各语句的作用，再根据流程图所示的顺序，可知：该程序的作用是计算并输出分段函数y=的值又∵输入的x值与输出的y值相等当x≤2时，x=x2，解得x=0，或x=1当2＜x≤5时，x=2x﹣3，解得x=3，当x＞5时，x=，解得x=±1（舍去）故满足条件的x值共有3个故选C．10．已知F1，F2分别是椭圆的左，右焦点，现以F2为圆心作一个圆恰好经过椭圆中心并且交椭圆于点M，N，若过F1的直线MF1是圆F2的切线，则椭圆的离心率为（）A．﹣1 B．2﹣C．D．【考点】椭圆的简单性质．【分析】由已知条件推导出|MF2|=c，|F1F2|=2c，∠F1MF2=90°，从而得到|MF1|=，由此能求出椭圆的离心率．【解答】解：∵F1，F2分别是椭圆的左，右焦点，现以F2为圆心作一个圆恰好经过椭圆中心并且交椭圆于点M，N，过F1的直线MF1是圆F2的切线，∴|MF2|=c，|F1F2|=2c，∠F1MF2=90°，∴|MF1|==，∴2a=，∴椭圆的离心率e===．故选：A．11．设两个向量=（λ+2，λ2﹣cos2α）和=（m， +sinα），其中λ，m，α为实数．若=2，则的取值范围是（）A．[﹣1，6] B．[﹣6，1] C．（﹣∞，]D．[4，8]【考点】平面向量数量积的运算．【分析】根据向量相等的概念，向量相等，即向量的横纵坐标相等，可哪λ用m表示，所以可化简为2﹣，所以只需求的范围即可，再利用向量相等得到的关系式，把m用α的三角函数表示，根据三角函数的有界性，求出m的范围，就可得到的范围．【解答】解：∵=2，∴λ+2=2m，①λ2﹣cox2α=m+2sinα．②∴λ=2m﹣2代入②得，4m2﹣9m+4=cox2α+2sinα=1﹣sin2α+2sinα=2﹣（sinα﹣1）2∵﹣1≤sinα≤1，∴0≤（sinα﹣1）2≤4，﹣4≤﹣（sinα﹣1）2≤0∴﹣2≤2﹣（sinα﹣1）2≤2∴﹣2≤4m2﹣9m+4≤2分别解4m2﹣9m+4≥﹣2，与4m2﹣9m+4≤2得，≤m≤2∴≤≤4∴==2﹣∴﹣6≤2﹣≤1∴的取值范围是[﹣6，1]故选：B12．定义在（0，）上的函数f（x），f′（x）是它的导函数，且恒有f′（x）＞f（x）•tanx成立．则（）A．f（）＜f（）B．f（1）＜2cos1•f（）C．f（）＞2f（）D．f（）＞f（）【考点】利用导数研究函数的单调性．【分析】根据条件构造函数g（x）=f（x）cosx，求函数的导数，利用函数的单调性即得到结论．【解答】解：当x∈（0，），cosx＞0，则不等式f′（x）＞f（x）•tanx等价为f′（x）＞f（x）•，即cosxf′（x）﹣sinxf（x）＞0，设g（x）=f（x）cosx，则g′（x）=cosxf′（x）﹣sinxf（x）＞0，即函数g（x）在（0，）单调递增，则g（）＜g（），g（1）＞g（），g（）＜g（），g（）＜g（），即f（）＜f（），cos1f（1）＞f（），f（）＜f（），f（）＜f（），则f（）＜f（），故A正确．2cosf（1）＞f（），故B错误．f（）＜2f（），故C错误．f（）＜f（），故D错误．故选A．二、填空题：本大题共4小题，每小题5分.13．若过点（0，2）的直线l与圆（x﹣2）2+（y﹣2）2=1有公共点，则直线l的斜率的取值范围是．【考点】直线与圆的位置关系．【分析】用代数法，先联立方程，消元后得到一个方程，利用△≥0，即可求得直线l的斜率的取值范围．【解答】解：设直线方程为y=kx+2（k≠0），代入圆（x﹣2）2+（y﹣2）2=1，消去y整理得（1+k2）x2﹣4x+3=0，∵过点（0，2）的直线l与圆（x﹣2）2+（y﹣2）2=1有公共点，∴△≥0，即16﹣12（1+k2）≥0，∴k∈．故答案为：．14．已知变量x，y满足约束条件，则z=x+2y的最大值是9．【考点】简单线性规划．【分析】作出不等式组对应的平面区域，利用z的几何意义，即可求出z的最大值．【解答】解：作出不等式组对应的平面区域如图：由z=x+2y得y=﹣x+z，平移直线y=﹣x+z，由图象可知当直线y=﹣x +z 经过点A ，y=﹣x +z 的截距最大，此时z 最大．由，解得，即A （1，4），代入z=x +2y=1+2×4=9．即目标函数z=x +2y 最大值为9． 故答案为：9．15．已知数列{a n }的前n 项和为S n ，且S n =n ﹣5a n +23，n ∈N *，则数列{a n }的通项公式是a n =1+．【考点】数列递推式．【分析】由S n =n ﹣5a n +23，n ∈N *，可得n=1时，a 1=1+23﹣5a 1，解得a 1．n ≥2时，a n =S n﹣S n ﹣1，变形为：a n ﹣1=（a n ﹣1﹣1），再利用等比数列的通项公式即可得出． 【解答】解：∵S n =n ﹣5a n +23，n ∈N *，∴n=1时，a 1=1+23﹣5a 1，解得a 1=4． n ≥2时，a n =S n ﹣S n ﹣1=n ﹣5a n +23﹣[（n ﹣1）﹣5a n ﹣1+23]=1﹣5a n +5a n ﹣1，变形为：a n ﹣1=（a n ﹣1﹣1），∴数列{a n ﹣1}是等比数列，首项为3，公比为，∴a n ﹣1=，即a n =1+，故答案为：1+．16．已知三棱锥P ﹣ABC 的所有顶点都在球O 的球面上，△ABC 是边长为2的正三角形，PC 为球O 的直径，且PC=4，则此三棱锥的体积为．【考点】棱柱、棱锥、棱台的体积．【分析】根据题意，利用截面圆的性质即可求出点O到平面ABC的距离，进而求出点P到平面ABC的距离，即可计算出三棱锥的体积．【解答】解：因为△ABC是边长为2的正三角形，所以△ABC外接圆的半径r=，所以点O到平面ABC的距离d=，PC为球O的直径，点P到平面ABC的距离为2d=，此棱锥的体积为=，故答案为：．三、解答题：解答应写出文字说明、证明过程或演算步骤.）17．已知△ABC是半径为2的圆的内接三角形，内角A，B，C的对边分别为a、b、c，且2acosA=ccosB+bcosC．（Ⅰ）求A；（Ⅱ）若b2+c2=18，求△ABC的面积．【考点】余弦定理；正弦定理．【分析】（I）利用正弦定理、和差公式、诱导公式即可得出．（II）利用余弦定理、三角形面积计算公式即可得出．【解答】解：（Ⅰ）由正弦定理得：a=4sinA，b=4sinB，c=4sinC，∵2acosA=ccosB+bcosC，∴2sinA•cosA=sinCcosB+sinBcosC，∴2sinA•cosA=sin（B+C），∵A+B+C=π，∴sin（B+C）=sinA，∴2sinA•cosA=sinA，∵0＜A＜π，∴sinA≠0，∴2cosA=1，即cosA=，∵A∈（0，π），∴A=．（II）由（I）可得：sinA=．由（Ⅰ）得．∵a2=b2+c2﹣2bcosA，∴bc=b2+c2﹣a2=18﹣12=6，∴．18．某班50位学生期中考试数学成绩的频率直方分布图如图所示，其中成绩分组区间是：[40，50），[50，60），[60，70），[70，80），[80，90），[90，100]．（1）求图中x的值；（2）从成绩不低于80分的学生中随机选取2人，该2人中成绩在90分以上（含90分）的人数记为ξ，求ξ的数学期望．【考点】离散型随机变量的期望与方差；频率分布直方图；古典概型及其概率计算公式．【分析】（1）根据所以概率的和为1，即所求矩形的面积和为1，建立等式关系，可求出所求；（2）不低于80分的学生有12人，90分以上的学生有3人，则随机变量ξ的可能取值有0，1，2，然后根据古典概型的概率公式求出相应的概率，从而可求出数学期望．【解答】解：（1）由30×0.006+10×0.01+10×0.054+10x=1，得x=0.018（2）由题意知道：不低于80分的学生有12人，90分以上的学生有3人随机变量ξ的可能取值有0，1，2∴19．如图，在直二面角E﹣AB﹣C中，四边形ABEF是矩形，AB=2，AF=2，△ABC是以A为直角顶点的等腰直角三角形，点P是线段BF上的一点，PF=3．（Ⅰ）证明：BF⊥面PAC；（Ⅱ）求二面角A﹣BC﹣P的余弦值．【考点】二面角的平面角及求法；直线与平面垂直的判定．【分析】（Ⅰ）推导出PA⊥BF，从而AC⊥平面ABEF，进而AC⊥BF，由此能证明BF⊥平面PAC．（Ⅱ）以A为原点，方向为x轴的正方向建立空间直角坐标系，利用向量法能求出二面角A﹣BC﹣P的余弦值．【解答】证明：（Ⅰ）由题意知：FB=4，，．∵PA2+PF2=3+9=12=AF2，∴PA⊥BF．∵平面ABEF⊥平面ABC，平面ABEF∩平面ABC=AB，AB⊥AC，AC⊂平面ABC，∴AC⊥平面ABEF．∵BF⊂平面ABEF，∴AC⊥BF．∵PA∩AC=A，∴BF⊥平面PAC．…解：（Ⅱ）由（Ⅰ）知AB、AC、AF两两互相垂直，以A为原点，方向为x轴的正方向建立如图所示空间直角坐标系，则A（0，0，0），B（2，0，0），C（0，2，0），．∵BF=4，PF=3，∴．∴，．设是平面PBC的法向量，则，∴，取y=1得平面PBC的一个法向量，又平面ABC的一个法向量，设二面角A﹣BC﹣P的平面角为θ，由题中条件可知，则，∴二面角A﹣BC﹣P的余弦值为．…20．已知抛物线C：y2=4x，过其焦点F作两条相互垂直且不平行于坐标轴的直线，它们分别交抛物线C于点P1、P2和点P3、P4，线段P1P2、P3P4的中点分别为M1、M2．（Ⅰ）求线段P1P2的中点M1的轨迹方程；（Ⅱ）求△FM1M2面积的最小值；（Ⅲ）过M1、M2的直线l是否过定点？若是，求出定点坐标，若不是，请说明理由．【考点】轨迹方程．【分析】（Ⅰ）确定线段M1M2的中点P坐标，消去参数，即可得到线段P1P2的中点M1的轨迹方程；（Ⅱ）利用，即可求△FM1M2面积的最小值；（Ⅲ）分类讨论，利用yk2+（x﹣3）k﹣y=0，即可得出结论．【解答】解：（Ⅰ）由题设条件得焦点坐标为F（1，0），设直线P1P2的方程为y=k（x﹣1），k≠0．联立，得k2x2﹣2（2+k2）x+k2=0．△=[﹣2（2+k2）]2﹣4k2k2=16（1+k2）＞0．设P1（x1，y1），P2（x2，y2），则，，∴．∴线段P1P2的中点M1的轨迹方程为：y2=2（x﹣1）（x＞1）．…（Ⅱ）由（Ⅰ）知：．同理，设，则．∴，，因此．当且仅当，即k=±1时，取到最小值4．…（Ⅲ）当k≠±1时，由（Ⅱ）知直线l的斜率为：，所以直线l的方程为：，即yk2+（x﹣3）k﹣y=0，（*）当x=3，y=0时方程（*）对任意的k（k≠±1）均成立，即直线l过点（3，0）．当k=±1时，直线l的方程为：x=3，也过点（3，0）．所以直线l恒过定点（3，0）．…21．设函数f（x）=x2+lnx﹣mx（m＞0）．（I）求f（x）的单调区间；（Ⅱ）求f（x）的零点个数；（Ⅲ）证明：曲线y=f（x）上没有经过原点的切线．【考点】利用导数研究函数的单调性；利用导数研究曲线上某点切线方程．【分析】（I）通过对函数f（x）求导，并令导数为零，分两种情况解方程即得结论；（Ⅱ）通过（I）可知，当0＜m≤2时函数f（x）有一个零点；当m＞2时，通过令极大值为g（m）并对其求导可知g′（m）＜0，进而可得结论；（Ⅲ）通过设通过原点的切线为y=kx，切点横坐标为x0，通过求导可将k=f′（x0）、切点纵坐标y0代入切线方程，通过对g（x）=x2﹣lnx+1求导即得结论．【解答】（I）解：依题意，函数f（x）的定义域为：（0，+∞），且f′（x）=x+﹣m，令f′（x）=0，即x+﹣m=0，即x2﹣mx+1=0，则△=m2﹣4，当△＜0即0＜m＜2时，方程f′（x）=0无根；当△=0即m=2时，方程f′（x）=0有唯一根x=1；当△＞0即m＞2时，方程f′（x）=0有两根x=；故当0＜x＜或x＞时，函数f（x）单调递增，当＜x＜时，函数f（x）单调递减；综上所述，当0＜m≤2时，函数f（x）在（0，+∞）上单调递增；当m＞2时，函数f（x）的递增区间为：（0，）、（，+∞），递减区间为：（，）；（Ⅱ）解：由（I）可知，当0＜m≤2时，函数f（x）有一个零点；当m＞2时，为函数f（x）的极大值点，令g（m）=f（）=•+ln﹣m•，其中m＞2，则g′（m）=•[2m﹣﹣]+••[1﹣•]﹣﹣•[1﹣•]=﹣＜0，故g（m）＜g（2）=0.5﹣2=﹣1.5，∴函数f（x）有一个零点；综上所述，函数f（x）的零点个数为1；（Ⅲ）证明：设通过原点的切线为y=kx （极值点的切线平行x轴，且极值小于0，均不过原点，故k≠0），切点横坐标为x0，则由导数的几何意义可知k=f′（x0）=，切点纵坐标y0=y₀=+lnx0﹣mx0，代入切线方程：+lnx0﹣mx0=﹣mx0+1，即﹣lnx0+1=0 （*）令g（x0）=﹣lnx0+1，则g′（x）=x﹣，故驻点x=1为极小值点，∴g（x0）≥g（1）=1.5＞0，即方程（*）无解，∴曲线y=f（x）上没有经过原点的切线．请考生在22、23、24三题中任选一题作答.注意：只能做所选定的题目.如果多做，则按所做的第一个题目记分，作答时请用2B铅笔在答题卡上将所选题号后的方框涂黑.[选修4-1：几何证明选讲]22．如图所示，BC是半圆O的直径，AD⊥BC，垂足为D，，BF与AD、AO分别交于点E、G．（1）证明：∠DAO=∠FBC；（2）证明：AE=BE．【考点】与圆有关的比例线段；圆周角定理．【分析】（Ⅰ）连接FC，OF，利用，说明OB=OF，然后证明∠AOB=∠FCB，推出∠DAO=∠FBC．（Ⅱ）证明△OAD≌△OBG，推出OD=OG．然后证明△AGE≌△BDE，即可证明AE=BE．【解答】证明：（Ⅰ）连接FC，OF，∵，OB=OF，∴点G是BF的中点，OG⊥BF．因为BC是⊙O的直径，所以CF⊥BF．∴OG∥CF．∴∠AOB=∠FCB，…∴∠DAO=90°﹣∠AOB，∠FBC=90°﹣∠FCB，∴∠DAO=∠FBC．…（Ⅱ）在Rt△OAD与Rt△OBG中，由（Ⅰ）知∠DAO=∠GBO，又OA=OB，所以，△OAD≌△OBG，于是OD=OG．∴AG=OA﹣OG=OB﹣OD=BD．…在Rt△AGE与Rt△BDE中，由于∠DAO=∠FBC，AG=BD，所以，△AGE≌△BDE，因此，AE=BE．…[选修4-4：坐标系与参数方程]23．在平面直角坐标系xOy中，以坐标原点O为极点，x轴正半轴为极轴建立极坐标系，曲线C的极坐标方程为ρ=2sinθ，θ∈[0，2π）．（1）求曲线C的直角坐标方程；（2）若点D在曲线C上，求它到直线l：（t为参数，t∈R）的最短距离．【考点】简单曲线的极坐标方程；参数方程化成普通方程．【分析】（1）把已知极坐标方程两边同时乘以ρ，结合得答案；（2）化直线的参数方程为普通方程，化圆的方程为标准方程，求出圆心坐标和半径，结合点到直线的距离公式求得答案．【解答】解：（1）由ρ=2sinθ，θ∈[0，2π）．得ρ2=2ρsinθ，即x2+y2﹣2y=0；（2）由直线l：，得．化圆x2+y2﹣2y=0为x2+（y﹣1）2=1，则圆心坐标为（0，1），圆心到直线的距离为d=．∴D到直线的最短距离为1．[选修4-5：不等式选讲]24．设函数f（x）=|x﹣a|+5x．（1）当a=﹣1时，求不等式f（x）≤5x+3的解集；（2）若x≥﹣1时有f（x）≥0，求a的取值范围．【考点】其他不等式的解法．【分析】（1）当a=﹣1时，|x+1|+5x≤5x+3，从而解得；（2）当x≥0时，f（x）=|x﹣a|+5x≥0恒成立，从而转化为故只需使当﹣1≤x＜0时，f（x）=|x﹣a|+5x≥0，从而化简可得（4x+a）（6x﹣a）≤0，从而分类讨论解得．【解答】解：（1）当a=﹣1时，|x+1|+5x≤5x+3，故|x+1|≤3，故﹣4≤x≤2，故不等式f（x）≤5x+3的解集为[﹣4，2]；（2）当x≥0时，f（x）=|x﹣a|+5x≥0恒成立，故只需使当﹣1≤x＜0时，f（x）=|x﹣a|+5x≥0，即|x﹣a|≥﹣5x，即（x﹣a）2≥25x2，即（x﹣a﹣5x）（x﹣a+5x）≥0，即（4x+a）（6x﹣a）≤0，当a=0时，解4x×6x≤0得x=0，不成立；当a＞0时，解（4x+a）（6x﹣a）≤0得，﹣≤x≤，故只需使﹣≤﹣1，解得，a≥4；当a＜0时，解（4x+a）（6x﹣a）≤0得，≤x≤﹣，故只需使≤﹣1，解得，a≤﹣6；综上所述，a的取值范围为a≥4或a≤﹣6．2016年10月10日。

2017高考英语试卷及答案及英语调研考试卷2017高考英语试卷及答案及英语调研考试卷第三部分：英语知识运用第一节：完形填空 ( 共 20 小题 ; 每小题 1分，满分 20 分 )阅读下面短文，掌握其大意，然后从21～40各题所给的四个选项(A、B、C和D)中，选出最佳选项。

For many 36 in the US, earning some money gives them a sense of 37 . By making their own money they can buy whatever they want. It also develops a sense of responsibility and independence.Most teens I know have a small sum of money. Their 38 give them an allowance . For some, an allowance is given every week; for 39 , every month or so. Usually they can get 10 to 30 dollars a month from their parents. An allowance is typically based on the 40 of chores , such as washing the dishes, cleaning up one’s room, taking out the trash, and 41 the floor. 42 to younger siblings (兄弟姐妹)is also regarded as worthy of extra cash, 43 some cases.Many teens also work to get 44 . Since most of my peers are not 45 for a formal job, many choose part-time positions. These require relatively 46 time and basically no training. They can have these jobs like babysitting; 47 younger students, offered by most schools 48 a small fee; 49 bagging groceries at local supermarkets.50 spending habits, most teens spend their money in a relatively carefree (无忧的) style. Often, a month’s allowance can be spent in just a few hours. I’m not saying that teens in US are 51 saving money. Indeed, in many situations, teens can be quite level-headed(清醒的) in 52 money towards college or other 53plans. The way teens manage their money should not be seen asa 54 . It may just be a defining characteristic of their carefree 55 .36. A. adults B. teens C. babies D. elders37. A. freedom B. pride C. happiness D. excitement38. A. parents B. teachers C. friends D. schools39. A. the others B. another C. the other D. others40. A. completion B. performance C. end D. success41. A. watering B. washing C. sweeping D. removing42. A. Cruelty B. Coldness C. Usefulness D. Kindness43. A. in B. on C. by D. for44. A. dollars B. money C. cash D. fees45. A. satisfied B. ready C. qualified D. allowed46. A. little B. much C. more D. no47. A. helping B. training C. tutoring D. informing48. A. in need of B. in return for C. with the purpose of D. asa result of49. A. and B. but C. so D. yet50. A. As for B. Because of C. In spite of D. But for51. A. used to B. expert at C. looking forward to D. incapable of52. A. spending B. earning C. saving D. collecting53. A. future B. present C. past D. last54. A. characteristic B. weakness C. merit D. symbol55. A. lifestyle B. attitude C. habit D. thinking第二节英语知识运用(共10小题;每小题1分，满分10分)阅读下面材料，在空白处填入适当的内容(1个单词)或括号内单词的正确形式。

湖南省益阳市2022届高三上学期9月调研考试英语试题(3)一、听力选择题1. What will the woman do?A．Go to the coffee shop.B．Return some books.C．Talk to Mary.2. Who will the mango shopping with?A．The woman.B．Alice.C．His family.3.A．Manager and clerk.B．Doctor and patient.C．Teacher and student.D．Waitress and customer.4.A．The movie is good except the bad ending.B．The movie won an award.C．She agrees with the man’s comments.D．She doesn’t like the special effects.5. What is the man doing?A．Planning a vacation.B．Keeping a secret.C．Telling good news.二、听力选择题6. 听下面一段较长对话，回答以下小题。

1. What is Frank usually responsible for at home?A．Doing the washing.B．Cleaning the house.C．Preparing the food.2. What does Frank think Karen should do?A．Relax more.B．Study harder.C．Do some chores.7. 听下面一段较长对话，回答以下小题。

1. What is the probable relationship between the speakers?A．A couple.B．Colleagues.C．Schoolmates.2. Who supports the woman to study?A．Her family.B．Her friend.C．Her government.3. What does the woman think of changing foreign money into dollars?A．Greatly encouraging.B．Terribly disappointing.C．A bit satisfying.8. 听下面一段较长对话，回答以下小题。

第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1。

若2(1)(1)z a a i =-+-为纯虚数，其中a R ∈，则21a iai++等于（ )A ．i -B ．iC ．1D ．1或i 【答案】B 【解析】试题分析：由题意21010a a ⎧-=⎨-≠⎩，解得1a =-，21a i ai ++21(1)21(1)(1)2i i ii i i i ++====--+．故选B ．考点：复数的概念，复数的运算． 2. 设A ，B 是两个集合，则“AB A =”是“A B ⊆”的（ ）A ．充分不必要条件 B.必要不充分条件 C ．充分必要条件 D ．既不充分又不必要条件 【答案】C 【解析】考点：充分必要条件． 3。

设0.31.7a =，3log 0.2b =，50.2c =，则a ，b ，c 的大小关系是（ ）A ．a b c <<B ．b a c <<C ．c b a <<D ．b c a << 【答案】D 【解析】 试题分析：因为0.31.71>，3log 0.20<,500.21<<，所以a c b >>．故选D ．考点：指数函数与对数函数的性质．4。

从一个边长为2的等边三角形的中心、各边中点及三个顶点这7个点中任取两个点，则这两点间的距离小于1的概率是（ ） A ．17 B ．37 C ．47 D ．67【答案】A 【解析】试题分析:这7个点中只有中心到三边中点的距离小于1，因此所求概率为27317P C ==．故选A ．考点:古典概型．5. 在等差数列{}n a 中，已知51012a a +=,则793a a +=（ ） A ．12 B ．18 C ．24 D ．30 【答案】C考点：等差数列的通项公式．6. 已知6(1)ax +的二项展开式中含3x 项的系数为52,则a 的值是（ ) A ．18 B ．14 C ．12D ．2 【答案】C 【解析】试题分析：6(1)ax +6(1)ax =+，含3x 的项为336()C ax 3336C a x =，因此33652C a =，12a =．故选C ．考点:二项式定理的应用． 7. 三角函数()sin(2)cos 26f x x x π=-+的振幅和最小正周期分别是（ ）A2π Bπ C2πDπ 【答案】D 【解析】 试题分析：()sin(2)cos 26f x x x π=-+sin cos 2cos sin 2cos 266ππx x x =-+3cos 222x x =)3πx =-周期为22πT π==．故选D ．考点：三角函数()sin()f x A ωx φ=+的性质．【名师点睛】简谐运动的图象对应的函数解析式：()sin()f x A ωx φ=+（[0,),0,0x A ω∈+∞>>为常数)．其中物理意义如下:A 是振幅，ωx φ+为相位，φ为初相,周期2πT ω=，频率为12ωf T π==． 8。

湖南省益阳市、湘潭市2018届高三英语9月调研考试试题第一部分听力（共两节,满分30分)回答听力部分时,请先将答案标在试卷上，听力部分结束前，你将有两分钟的时间将你的答案转涂到答题卡上.第一节（共5小题；每小题1。

5分，满分7。

5分）听下面5段对话，每段对话后有一个小题.从题中所给的A，B，C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt？A。

£ 19.15. B. £ 9。

18.C. £ 9。

15.答案是C.1。

How much will the man’s rent be？A。

＄ 150. B. ＄ 240.C。

$ 600.2。

What is the probable relationship between the speakers?A。

Guest and hostess. B. Customer and waitress。

C。

Boss and clerk.3。

What does the man think of the movie?A. Terrible。

B。

Amazing。

C. Boring.4. What does the man want the woman to do？A。

Buy him a mobile phone。

B. Tell him her phone number。

C。

Go to Hong Kong with him.5. What are the speakers talking about?A. A family party。

B. New friends。

C。

The man's host family。

第二节（共15小题;每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

高中英语真题：某中学2017届高三模底测试英语试题Word版.doc一、阅读理解(共4题)1.Chester City Library offers a range of Library Special Needs Services to people who don’t have access to our library servi ce in the usual way. As long as you live in Chester City, we’ll provide a wide range of library services and resources including:● Large printed and ordinary printed books● Talking books on tape and CD● DVDs and music CDs● Magazines● Referenc e and information requestsHome delivery serviceLet us know what you like to read and we will choose the resources for you. Our staff will deliver the resources to your home for free. We alsoprovide a service where we can choose the resources for you or someone instead of you choose the things from the library. You can also choose the resources you need personally.Talking books and captioned videosThe library can provide talking books for people who are unable to use printed books because of eye diseases. You don’t have to miss out on reading any more when you can borrow talking books from the library. If you have limited hearing which prevents you from enjoying movies, we can provide captioned videos for you at no charge.Languages besides EnglishWe can provide books in a range of languages besides English. If possible, we will request these items from the State Library of NSW, Australia.How to joinContact the Library Special Needs Coordinator to register or discuss if you are eligible（合适的）for any of the services we provide ---Tuesday, Wednesday and Thursday 9am ---5pm on 4297 2522 for more information.21. Library Special Needs Services are meant for_____.A. those who are fond of readingB. people living in Chester City with an illness or disabilityC. only those who have walking disabilitiesD. those who can’t get medical help in Chester City22. What can we learn from the passageA. Few entertaining resources are offered here.B. People with limited hearing have to pay for captioned videos.C. Books with different languages are available.D. People have to choose what they need by themselves.23. To get home delivery service, you must_______.A. only choose printed booksB. have others choose the resources for youC. pay the library ahead of timeD. register ahead of time2.In August 2015, President Obama announced that North America’shighest mountain, Mount McKinley, would be renamed. Its new moniker（名字）, Denali, was actually its original Aleut name, meaning “the high one”. The previous name, on the other hand, only dates back to 1896—the year when it was named in honour of William McKinley（1843—1901）, who was shortly to become President of the United States. Denali is of course not the only mountain with an interesting linguistic history, so let’s travel to Asia, and a cross Europe, to explore the naming of those continents’ most famous peaks and mountain ranges.The Nepalese name Himalaya comes from a Sanskrit word meaning “Abode of Snow”, from hima for “snow” and ālaya for “abode”. In Buddhist sources, Himalaya is k nown by various names such as Himavā and Himavanta.In 1856, Mount Everest was named after Sir George Everest （1790—1866）, who was the superintendent （负责人）of the Trigonometrical Survey of India. Everest himself was initially displeased by the naming, since he feared that local inhabitants might not be able to pronounce it.K2 stands for Karakoram 2, because it was the second peak to be surveyed in the Trigonometrical Survey in the Karakoram system. It was also formerly known as Mount Godwin Austen after Col. H. H. Godwin Austen, who first surveyed it. Another alternative name for the mountain is Chhogori.Annapurna is a household Goddess for Hindus, who guarantees to her worshippers （崇拜者）that food will not fail. The name derives（源出）from a Sa nskrit word meaning “one who gives nourishment”.The Matterhorn’s name derives from the name of the nearby town ofZermatt, the second element of which is apparently Matte “meadow”, and Horn, “horn”. Horn is not an unusual element in German names o f mountains with jutting（突出的）peaks. The mountain is called Mont Cervin in French and Monte Cervino in Italian, from the Italian adjective cervino “deer-like”, which conjures up （使想起）a deer’s antlers.Ben Nevis is the Anglicized form of the Scottish Gaelic name Beinn Nibheis, which means“Mountain by the（River）Nevis”. The name of the river apparently derives from a Celtic root for “water”.24. How many continents’ mountains are mentioned in the passage?A. 2B. 3C. 4D. 525. Himalaya is a mountain also named ________.A. NepaleseB. Abode of SnowC. AlayaD. Himavā26. Which of the following is FALSE according to the passage?A. Everest was unhappy about the name of Mount Everest at first.B. K2 was once called Col. H. H. Godwin.C. Annapurna means “one who offers food”.D. Matterhorn comes from the name of the nearby town of Zermatt.27. The above mountains’ names come from sources other than _________.A. colorB. a Sanskrit wordC. a person’s nameD. geographic name3.Every few years comes a fitness trend that has people scratching their heads in amazement. “Crunning” will probably be one of them. The “c” stands for “crawling”(爬行). This new sport needs two-legged humans running on all fours!The funny idea is the brainchild of Shaun McCarthy. The 34-year-old is convinced that it will revolutionize fitness as we know it. According to the sports enthusiast, “The only thing that crunning’s changed about fitness is that it’s changed everything about fitness.”Mccarthy has no scientific evidence to prove that crunning is more efficient than traditional two-legged running. However, he believes it is amore effective way to exercise because it puts an emphasis on the shoulders and arms, providing a complete body workout. Mccarthy also says crunning seems to tire him out more. He therefore concludes that the unconventional exercise is a bigger calorie burner than normal running.While experts generally agree that crunning may provide a better workout, many are not sure if it is the right exercise for humans. Fitness coach Kevin Dean says we are not built to be on all fours and our wrists are therefore not as strong as our ankles. He believes crunning, which he calls a fad(时尚), could result in bad wrist and shoulder injuries, not to mention broken noses.But McCarthy is not worried. Since the release of his crunning video a few weeks ago, many Melbourne residents have been seen scampering around on all fours. As it turns out they are not the only ones. In the Chinese city of Zhengzhou, crawling, a much slower version of crunning, has been a favorite activity for many years. According to some enthusiasts, the light exercise that is believed to date back two thousand years to the Han Dynasty, is good for curing back and spine ailments.Ready to give crunning try? Then Mccarthy recommends investing in some good shoes, hardy gloves and most important of all, a face mask!28. What can we learn about crawling according to Kevin Dean?A. Our ankles are stronger than our wrists.B. Crawling is an efficient way to work out.C. The city of Zhengzhou is the origin of crawling.D. Crawling can burn more calories than normal running.29. What does the author think of crunning?A. Dangerous.B. Interesting.C. Beneficial.D. Unbelievable.30. Why does McCarthy suggest people wearing a face mask when crunning?A. To amuse other people.B. To avoid being recognized.C. To protect the nose from being injured.D. To prevent sweat dropping on the ground.31. What is the text mainly about?A. A new way of crawling.B. A new trend of exercising.C. A scientific discovery.D. A traditional way to keep fit.4.In 1693 the philosopher John Locke warned that children should not be given too much “unhealthy fruit” to eat. Three centuries later, misguided ideas about child-raising are still popular. Many parents fear that their children will die unless ceaselessly watched. In America the law can be equally paranoid (偏执的). In South Carolina this month Debra Harrell was jailed for letting her 9-year-old daughter play in a park unsupervised (无人监督的).Her severe punishment reflects the rich world’s worry about parenting. By most objective measures, modern parents are far more conscientious (认真的) than previous generations. Dads are more hands-on than their fathers were, and working mothers spend more time nurturing their children than the housewives of the 1960s did. However, there are two problems in this picture, connected to class. One is at the lower end. Even if poor parents spend more time with their children than they once did, they spend less than rich parents do. America is a laggard here: its government spends abundantly on school-age kids but much less than other rich countries on the first two or three years of life. If America did more to help poor parents with young children, it would have huge returns.The second one, occurs at the other end of the income scale, and may even apply to otherwise rational (理性的) Economist readers: well-educated, rich parents try to do too much. Safety is part of it—they fear that if they are not constantly watching their children may break their necks, which is theleast rational. Despite the impression you get from watching crime dramas, children in rich countries are safe, so long as they look both ways before crossing the road. The other popular parental fear—that your children might not get into an Ivy League college—is more rational. Academic success matters more than ever before. But beyond a certain point, parenting makes less difference than many parents imagine. Studies in Minnesota and Sweden, for example, found that identical twins grew up equally intelligent whether they were raised together or apart. A study in Colorado found that children that adopted and raised by brainy parents ended up no brainier than those adopted by average parents.This doesn’t mean that parenting is ir relevant. The families who adopt children are carefully screened, so they tend to be warm, capable and middle-class. But the twin and adoption studies indicate that any child given a loving home and adequate stimulation is likely to fulfill her potential. Put another way, better-off parents can afford to relax a bit. And if you are less stressed, your children will appreciate it, even if you still make them eat their fruit and vegetables.32. Which of the following statements is NOT a misguided idea of parenting mentioned in the passage?A. Children should be protected from any dangers by their parentsB. The more conscientious parents are, the more children will surely benefit from parentingC. Children will die unless ceaselessly watchedD. Children are likely to fulfill their potential with a loving home andadequate stimulation33. The underlined word “laggard” in Paragraph 2 probably means a country that __________.A. is ahead in developmentB. falls slow behind othersC. is free from physical or mental disorderD. moves to a higher position34. Which of the following can we learn from the passage?A. Only warm, capable and middle-class people can adopt a child.B. When it comes to child-raising, Economist readers will become more rational.C. Children in rich countries are in greater danger due to the bad influence of crime dramas.D. Although poor parents spend more time with their kids than they once did, they spend less than rich parents do.35. This passage is mainly written to __________.A. urge American laws concerning parenting to be changedB. advise modern parents to learn from their previous generationsC. persuade stressed parents to learn to relax and give more freedom to their childrenD. call on the government to do more to help poor parents with school-age children二、未分类(共2题)1.Bullying(欺凌行为) is a problem in many schools. Maybe lots of you have ever come across school bullies(小霸王). 36Ignore the bully and walk away. It’s definitely not a coward's response—sometimes it can be harder than losing your temper. Walk tall and hold your head high. 37Hold the anger. Who doesn't get really upset with a bully? 38 Bullies want to know they have control over your emotions. Work out your anger in other ways, such as through exercise or writing it down.39 However you choose to deal with a bully, don't use physical force. Not only are you showing your anger, you can never be sure what the bully will do in response. You are more likely to be hurt and get into trouble if you use violence against a bully. You can stand up for yourself in other ways, such as gaining control of the situation by walking away.Talk about it. It may help to talk to a guidance advisor, teacher, or friend. 40 Talking can be a good outlet for the fears and frustrations that can build when you're being bullied.A. Don’t get physical.B. Take charge of the situation.C. People above can give you the support you need.D. Here are some things you can do to fight bullying.E. Some adults believe that bullying is part of growing up.F. But that’s exactly the response he or she is trying to get.2. Climate change has caused a rise in sea levels. This has increased the amount of salt in fresh water 61 (use)on coastal farms. As a result, farmers are 62 (gradual) unable to use fields close to the sea.However, Marc Van Rijsselberg, a farmer in the Netherlands is now using a 63 (mix)of sea and fresh water 64 (grow) healthy and tasty vegetables.farm 65 eight negated areas. Separate pipes pumped fresh and sea water, and a computer program created water with eight levels of salinity(含盐度).The water levels and the levels of salinity was 66 (control) by computerized measuring devices called “sensors”. Mr. Van Rijsselberg said he was able to harvest vegetables from most of the eight testing areas. He said the vegetables were smaller than 67 grown in fresh water. But he said they also had more sugar and salt, so they tasted much 68 (good).He found that potatoes grew better than the other vegetables in the combination of sea and fresh water. Mr.Van Rijsselberg said four kinds of these potatoes would be sent to Pakistan 69 thousands of hectares of land 70 (damage) by salinization last year.三、完型填空(共1题)1.It amazed me—every time I saw Joe，he was smiling. It didn’t _41___ whether he had to stop at a stop light, or if he were the seventh person in __42__ at the bank, and the service stopped just before he got there. Joe __43_ smiled. It made me wonder why he seemed so __44__ every day.Having observed Joe with other people, I __45__ something else also. Joe asked people how they were doing, and really seemed to listen to their __46__. If someone were hurting, he had __47__ for him and kind words, and offered to __48__ in any way he could.began when I went to the grocery store. I smiled as I went up and down the aisles...and people I didn’t even _50__ smiled back at me. Some even __51__! The little kid in the cart(购物车) who was giving his mother a __52__ time saw me smile and _53___ talking...and, you guessed it. He made a shy little attempt at a smile. The man in the handicapped(残疾的) cart __54__ a person to reach something...I could get that for him. The smile even transferred over to him, and he __55__me.As I drove home, I was smiling. I _56___ what I had just learned，and when someone passed me and gave me a(n) _57___, I smiled at him. He looked puzzled.Now I know a smile is a small thing, but what if we were all to try to smile a few more times each day? I couldn’t believe how _58__ I felt. Nothing in my life had changed, __59__ maybe it had. For what I learned was that such a small thing could __60__ not only my spirits, but those around me as well.41.A.work B. happen C. matter D. last42.A.order B. debt C. hand D. line43.A.always B. eventually C. immediately D. still44.A.naughty B. happy C. active D. humorousnoticed D. considered46.A.answers B. complaints C. excuses D. comments47.A.guidance B. respect C. sympathy D. protection48.A.perform B. attempt C. bother D. help49.A.experiment B. life C. project D. program50.A. meet B. touch C. know D. contact51.A.glared B. greeted C. approached D. escaped52.A.spare B. long C. hard D. great53.A.stopped B. tried C. kept D. enjoyed54.A.persuaded B. accepted C. supported D. needed55.A.thanked B. changed C. encouraged D. invited56.A.worried about B. thought about C. talked over D. looked overcall D. ticket58.A.normal B. great C. reasonable D. complicated59.A.so B. for C. but D. till60.A.release B. admire C. display D. lift四、短文改错(共1题)1.假定英语课上老师要求同桌之间交换修改作文，请你修改你同桌写的以下作文。