C语言源代码

＃include 〈stdio.h〉void print_star（void)｛printf（"*＊＊***＊＊*＊*＊*****\n"）; ｝void print_welcome(void）{printf（”C language，welcome!\n")；｝void main（)｛print_star(）;print_welcome（);print_star(）;getchar();｝演示2＃include "stdio。

h"int sum（int i，int j)｛return(i + j);}void main（)｛int n1，n2;printf（"input 2 numbers：\n”);scanf("％d％d”，&n1，＆n2）；printf（"the sum = %d\n",sum(n1,n2）)；getchar(）；}演示3#include "stdio。

h"int maxnum（int,int,int）;main(){int a,b,c；printf("Please enter 3 numbers:\n"）;scanf（”％d，%d，%d”，&a,&b,&c）；printf(”Maxnum is %d\n",maxnum(a，b,c)）；}int maxnum(int x，int y,int z)｛int max=x；if(y>max)max = y;if（z>max）max = z；return max；｝演示4＃include 〈stdio。

h〉int s1(int n）｛int j,s;s=0；for（j=1；j<=n；j++)s=s+j；return s;}int sum（int n)｛int i，s=0；for(i=1;i<=n；i++）s=s+s1（i);return s;｝void main（）｛int n;printf(”n:”）;scanf（”％d"，＆n）；printf（"s=%d\n”,sum（n））；｝演示5#include <stdio.h〉void func(int n）{int i；for(i=n-1;i〉=1;i--）n=n+i；printf("n=％d\n"，n）；｝void main(）｛int n；printf("Input n:"）；scanf（"%d”，＆n）;func（n)；printf(”n=％d\n",n);}演示6＃include <stdio。

人工智能c语言源代码人工智能是一个广泛的领域，涉及多种算法和技术。

在C语言中，可以实现一些基本的人工智能功能。

下面是一个简单的示例，展示了如何使用C语言编写一个简单的决策树算法：c.#include <stdio.h>。

// 定义决策树节点结构。

typedef struct DecisionTreeNode {。

char question;struct DecisionTreeNode yesNode;struct DecisionTreeNode noNode;} DecisionTreeNode;// 创建决策树节点。

DecisionTreeNode createNode(char question) {。

DecisionTreeNode node = (DecisionTreeNode)malloc(sizeof(DecisionTreeNode));node->question = question;node->yesNode = NULL;node->noNode = NULL;return node;}。

// 决策树算法。

void decisionTree() {。

DecisionTreeNode root = createNode("Is it a mammal?");root->yesNode = createNode("Does it have fur?");root->yesNode->yesNode = createNode("It's amammal!");root->yesNode->noNode = createNode("It's not a mammal!");root->noNode = createNode("Does it have feathers?");root->noNode->yesNode = createNode("It's a bird!");root->noNode->noNode = createNode("It's not abird!");printf("%s\n", root->question);char answer;scanf(" %c", &answer);DecisionTreeNode currentNode = root;while (currentNode != NULL) {。

转换进制程序C语⾔,C语⾔各进制转换源代码#include#include#includevoid ten_two(int);void ten_eight(int);void ten_sixten(int);void two_ten(int);void two_eight(int);void two_sixten(int);void eight_two(int);void eight_ten(int);void eight_sixten(int);void sixten_two(char r[], int k);void sixten_ten(char r[], int k);void sixten_eight(char r[], int k);int main(void){int i, j, number = 0;int temp;char change[10];printf("=============================================================\n");printf(" 欢 迎 使 ⽤ 进 制 转 换 程 序 \n");printf(" 作 者：李 研 时 间：2009 年7 ⽉5 ⽇ \n");printf("=============================================================\n");do{temp = 0;//fflush(stdin);printf("\n请选择转换前的进制:\n2⼆进制\n8⼋进制\n10⼗进\n16⼗六进制\n0退出\n");printf("转换前的进制是:");scanf("%d", &i);case 2:printf("\n请选择转换后的进制:\n2⼆进制\n8⼋进制\n10⼗进\n16⼗六进制\n0退出\n"); printf("转换后的进制是：");scanf("%d", &j);switch(j){case 2:printf("\n同进制之间不⽤转化！\n");temp = 1;break;case 8:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);two_eight(number);temp = 1;break;case 10:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);two_ten(number);temp = 1;break;case 16:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);two_sixten(number);temp = 1;break;case 0:printf("谢谢使⽤！！");}break;printf("转换后的进制是：");scanf("%d", &j);switch(j){case 8:printf("\n同进制之间不⽤转化！\n");temp = 1;break;case 2:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);eight_two(number);temp = 1;break;case 10:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);eight_ten(number);temp = 1;break;case 16:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);eight_sixten(number);temp = 1;break;case 0:printf("谢谢使⽤！！");}break;case 10:printf("\n请选择转换后的进制:\n2⼆进制\n8⼋进制\n10⼗进\n16⼗六进制\n0退出\n");{case 10:printf("\n同进制之间不⽤转化！\n");temp = 1;break;case 2:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);ten_two(number);temp = 1;break;case 8:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);ten_eight(number);temp = 1;break;case 16:printf("\n请输⼊您想要转化的数：");scanf("%d", &number);ten_sixten(number);temp = 1;break;case 0:printf("谢谢使⽤！！");}break;case 16:printf("\n请选择转换后的进制:\n2⼆进制\n8⼋进制\n10⼗进\n16⼗六进制\n0退出\n"); printf("转换后的进制是：");scanf("%d", &j);printf("\n同进制之间不⽤转化！\n"); temp = 1;break;case 2:printf("\n请输⼊您想要转化的数:"); fflush(stdin);gets(change);for(number = 0;; number++){if(change[number] == '\0') break;}sixten_two(change, number);temp = 1;break;case 8:printf("\n请输⼊您想要转化的数:"); fflush(stdin);gets(change);for(number = 0;; number++){if(change[number] == '\0') break;}sixten_eight(change, number); temp = 1;break;case 10:printf("\n请输⼊您想要转化的数:"); fflush(stdin);gets(change);if(change[number] == '\0')break;}sixten_ten(change, number);temp = 1;break;case 0:printf("谢谢使⽤！！");}break;case 0:printf("\n谢谢使⽤！\n");}}while(temp == 1);return 0;}/*以下为: ⼆进制转换为⼗进制,⼋进制,⼗六进制.*/ void two_ten(int a){int i, s = 0;int result = 0;for(i = 1; a != 0; i *= 2){if(a % 10 > 1){s = 1;break;}else{result += (a % 10) * i;}if(s == 1)printf("您的输⼊有误！请重新输⼊\n"); elseprintf("\n转换后的数为：%d\n", result); }void two_eight(int a){int i, j, k, s = 0;int p[30];int result = 0;for(i = 1; a != 0; i *= 2){if(a % 10 > 1){s = 1;break;}else{result += (a % 10) * i;a = a / 10;}}for(j = 0; result != 0; j++){p[j] = result % 8;result = result / 8;}if(s == 1)printf("It is wrong\n");elsefor(k = j - 1; k >= 0; k--) {printf("%d", p[k]);}printf("\n");}}void two_sixten(int a){int i, j, k, s = 0;char p[30];int result = 0;for(i = 1; a != 0; i *= 2){if(a % 10 > 1){s = 1;break;}else{result += (a % 10) * i;a = a / 10;}}for(j = 0; result != 0; j++) {p[j] = result % 16;result = result / 16;if (p[j] > 10){switch(p[j])p[j] = 'A';break;case 11:p[j] = 'B';break;case 12:p[j] = 'C';break;case 13:p[j] = 'D';break;case 14:p[j] = 'E';break;case 15:p[j] = 'F';break;}}else p[j] += 48;}if(s == 1)printf("It is wrong\n"); else{printf("\n转换后的数为："); for(k = j - 1; k >= 0; k--) {printf("%c", p[k]);}printf("\n");}void eight_two(int a){int i, j, k, s = 0;int result = 0;int p[30];for(i = 1; a != 0; i *= 8){if(a % 10 > 7){s = 1;break;}else{result += (a % 10) * i;a = a / 10;}}for(j = 0; result != 0; j++) {p[j] = result % 2;result = result / 2;}if(s == 1)printf("It is wrong\n"); else{printf("\n转换后的数为："); for(k = j - 1; k >= 0; k--) {printf("%d", p[k]);}}void eight_ten(int a){int i, s = 0;int result = 0;for(i = 1; a != 0; i *= 8){if(a % 10 > 7){s = 1;break;}else{result += (a % 10) * i;a = a / 10;}}if(s == 1)printf("It is wrong\n");else{printf("\n转换后的数为：%d\n", result); }}void eight_sixten(int a){int i, j, k, s = 0;char p[30];int result = 0;for(i = 1; a != 0; i *= 8){}else{result += (a % 10) * i;a = a / 10;}}for(j = 0; result != 0; j++) {p[j] = result % 16;result = result / 16;if(p[j]p[j] += 48;else{switch(p[j]){case 10:p[j] = 'A';break;case 11:p[j] = 'B';break;case 12:p[j] = 'C';break;case 13:p[j] = 'D';break;case 14:}}}if(s == 1)printf("It is wrong\n");else{printf("\n转换后的数为：");for(k = j - 1; k >= 0; k--){printf("%c", p[k]);}printf("\n");}}/*以下为: ⼗六进制转换为⼗进制,⼆进制,⼋进制.*/ void sixten_ten(char a[], int k){int i, j, s = 0;int result = 0;int b[50];for(i = 0; i{if(a[i] <= '9' && a[i] >= '1'){b[i] = a[i] - 48;}else{case 'B': b[i] = 11; break; case 'C': b[i] = 12; break; case 'D': b[i] = 13; break; case 'E': b[i] = 14; break; case 'F': b[i] = 15; break; case 'a': b[i] = 10; break; case 'b': b[i] = 11; break; case 'c': b[i] = 12; break; case 'd': b[i] = 13; break; case 'e': b[i] = 14;s = 1;}}}for(i = 1, j = k - 1; j >= 0; j--, i *= 16) {result += b[j] * i;}if(s == 1)printf("It is wrong\n");else{printf("\n转换后的数为：%d", result); }}void sixten_two(char a[], int k){int i, j, s = 0;int result = 0;int b[50];int p[30];for(i = 0; i{if(a[i] <= '9' && a[i] >= '1')b[i] = a[i] - 48;else{switch(a[i]){break; case 'C': b[i] = 12; break; case 'D': b[i] = 13; break; case 'E': b[i] = 14; break; case 'F': b[i] = 15; break; case 'a': b[i] = 10; break; case 'b': b[i] = 11; break; case 'c': b[i] = 12; break; case 'd': b[i] = 13; break; case 'e': b[i] = 14; break; case 'f':}}}for(j = k - 1, i = 1; j >= 0; j--, i *= 16) {result += b[j] * i;}for(j = 0; result != 0; j++){p[j] = result % 2;result = result / 2;}if(s == 1)printf("It is wrong\n");else{printf("\n转换后的数为：");for(k = j - 1; k >= 0; k--){printf("%d", p[k]);}printf("\n");}}void sixten_eight(char a[], int k){int i, j, s = 0;int result = 0;int b[30];int p[30];if(a[i] <= '9' && a[i] >= '1') b[i] = a[i] - 48;else{switch(a[i]){case 'A':b[i] = 10;break;case 'B':b[i] = 11;break;case 'C':b[i] = 12;break;case 'D':b[i] = 13;break;case 'E':b[i] = 14;break;case 'F':b[i] = 15;break;case 'a':b[i] = 10;break;case 'b':b[i] = 11;break;case 'c':b[i] = 12;b[i] = 13;break;case 'e':b[i] = 14;break;case 'f':b[i] = 15;break;default:s = 1;}}}for(j = k - 1, i = 1; j >= 0; j--, i *= 16) {result += b[j] * i;}for(j = 0; result != 0; j++){p[j] = result % 8;result = result / 8;}if(s == 1)printf("It is wrong\n");else{printf("\n转换后的数为：");for(k = j - 1; k >= 0; k--){printf("%d", p[k]);}printf("\n");/*以下为: ⼗进制转换为⼆进制,⼋进制,⼗六进制.*/ void ten_two(int a){int j, k;int p[30];for(j = 0; a != 0; j++){p[j] = a % 2;a = a / 2;}printf("\n转换后的数为：");for(k = j - 1; k >= 0; k--){printf("%d", p[k]);}printf("\n");}void ten_eight(int a){int j, k;int p[30];for(j = 0; a != 0; j++){p[j] = a % 8;a = a / 8;}printf("\n转换后的数为：");for(k = j - 1; k >= 0; k--){printf("%d", p[k]);}printf("\n");{int j, k;int p[30];for(j = 0; a != 0; j++) {p[j] = a % 16;a = a / 16;if(p[j]p[j] += 48;else{switch(p[j]){case 10:p[j] = 'A';break;case 11:p[j] = 'B';break;case 12:p[j] = 'C';break;case 13:p[j] = 'D';break;case 14:p[j] = 'E';break;case 15:p[j] = 'F';break;}}}printf("\n转换后的数为："); for(k = j - 1; k >= 0; k--) {printf("%c", p[k]);}printf("\n");}。

c语言正弦函数源代码#include <stdio.h>#include <math.h>#define PI 3.14159265int main() {double angle, result;int i;printf("Angle\t\tSin(Angle)\n");printf("------------------------\n");for (i = 0; i <= 360; i += 10) {angle = i * PI / 180;result = sin(angle);printf("%d\t\t%f\n", i, result);}return 0;}这是一个使用C语言编写的正弦函数源代码。

首先，我们包含了stdio.h和math.h头文件，分别用于输入输出和数学计算。

然后，我们定义了一个常量PI，其值为3.14159265，用于将角度转换为弧度。

在main函数中，我们声明了两个变量angle和result，分别用于存储角度和正弦值。

我们还声明了一个整型变量i，用于控制循环。

接下来，我们使用printf函数打印表头，包括角度和正弦值的标题。

然后，我们使用for循环从0度到360度，每次增加10度。

在循环中，我们将角度转换为弧度，并使用sin函数计算正弦值。

最后，我们使用printf函数打印角度和对应的正弦值。

最后，我们返回0，表示程序正常结束。

这段代码可以生成一个角度从0度到360度，每隔10度的正弦函数表。

通过运行这段代码，我们可以得到正弦函数在这些角度下的值，从而更好地理解正弦函数的性质。

------------------------------------------------------------------------摘自宋鲁生程序设计大赛乘法口诀表#include <stdio.h>#include <conio.h>void main(void){int i,j,x,y;clrscr();printf("\n\n * * * 乘法口诀表* * * \n\n");x=9;y=5;for(i=1;i<=9;i++){gotoxy(x,y);printf("%2d ",i);x+=3;}x=7;y=6;for(i=1;i<=9;i++){gotoxy(x,y);printf("%2d ",i);y++;}x=9;y= 6;for(i=1;i<=9;i++){for(j=1;j<=9;j++){gotoxy(x,y);printf("%2d ",i*j);y++;}y-=9;x+=3;}printf("\n\n");}用一维数组统计学生成绩#include <stdio.h>void main(){char SelectKey,CreditMoney,DebitMoney;while(1){do{clrscr();puts("=========================");puts("| Please select key: |");puts("| 1. Quary |");puts("| 2. Credit |");puts("| 3. Debit |");puts("| 4. Return |");puts("=========================");SelectKey = getch();}while( SelectKey!='1' && SelectKey!='2' && SelectKey!='3' &&SelectKey!='4' );switch(SelectKey){case '1':clrscr();puts("================================");puts("| Your balance is $1000. |");puts("| Press any key to return... |");puts("================================");getch();break;case '2':do{clrscr();puts("==================================");puts("| Please select Credit money: |");puts("| 1. $50 |");puts("| 2. $100 |");puts("| 3. Return |");puts("==================================");CreditMoney = getch();}while( CreditMoney!='1' && CreditMoney!='2' && CreditMoney!='3' );switch(CreditMoney){case '1':clrscr();puts("=========================================");puts("| Your Credit money is $50,Thank you! |");puts("| Press any key to return... |");puts("=========================================");getch();break;case '2':clrscr();puts("==========================================");puts("| Your Credit money is $100,Thank you! |");puts("| Press any key to return... |");puts("==========================================");getch();break;case '3':break;}break;case '3':do{clrscr();puts("====================================");puts("| Please select Debit money: |");puts("| 1. $50 |");puts("| 2. $100 |");puts("| 3. $500 |");puts("| 4. $1000 |");puts("| 5. Return |");puts("====================================");DebitMoney = getch();}while( DebitMoney!='1' && DebitMoney!='2' && DebitMoney!='3' &&DebitMoney!='4' && DebitMoney!='5' );switch(DebitMoney){case '1':clrscr();puts("===========================================");puts("| Your Debit money is $50,Thank you! |");puts("| Press any key to return... |");puts("===========================================");getch();break;case '2':clrscr();puts("===========================================");puts("| Your Debit money is $100,Thank you! |");puts("| Press any key to return... |");puts("===========================================");getch();break;case '3':clrscr();puts("===========================================");puts("| Your Debit money is $500,Thank you! |");puts("| Press any key to return... |");puts("===========================================");getch();break;case '4':clrscr();puts("===========================================");puts("| Your Debit money is $1000,Thank you! |");puts("| Press any key to return... |");puts("===========================================");getch();break;case '5':break;}break;case '4':clrscr();puts("================================");puts("| Thank you for your using! |");puts("| Good bye! |");puts("================================");return;}}模拟ATM（自动柜员机）界面#include <stdio.h> void main(){int Password=0,Number=0,price=58,i=0;while( Password != 1234 ){if( i >= 3 )return;i++;puts("Please input Password: ");scanf("%d",&Password);}i=0;while( Number!=price ){do{puts("Please input a number between 1 and 100: ");scanf("%d",&Number);printf("Your input number is %d\n",Number);}while( !(Number>=1 && Number<=100) );if( Number >= 90 ){printf("Too Bigger! Press any key to try again!\n");}else if( Number >= 70 && Number < 90 ){printf("Bigger!\n");}else if( Number >= 1 && Number <= 30 ){printf("Too Small! Press any key to try again!\n");}else if( Number > 30 && Number <= 50 ){printf("Small! Press any key to try again!\n");}else{if( Number == price ){printf("OK! You are right! Bye Bye!\n");}else if( Number < price ){printf("Sorry,Only a little smaller! Press any key to try again!\n");}else if( Number > price ){printf(" Sorry, Only a little bigger! Press any key to try again!\n");}getch();}}用二维数组实现矩阵转置/* 用二维数组实现矩阵的转置*/#include <stdio.h>#define ROW 3#define COL 4main(){int matrixA[ROW][COL],matrixB[COL][ROW];int i,j; clrscr();printf("Enter elements of the matrixA,");printf("%d*%d:\n",ROW,COL);for( i=0; i<ROW; i++ ){for( j=0; j<COL; j++ ){scanf("%d",&matrixA[i][j]);}}for( i=0; i<ROW; i++ ){for( j=0; j<COL; j++ ){matrixB[j][i] = matrixA[i][j];}}printf("MatrixB,");printf("%d*%d:\n",COL,ROW);for( i=0; i<COL; i++ ){for( j=0; j<ROW; j++ ){printf("%8d",matrixB[i][j]);}printf("\n");}printf("\n Press Any Key to Quit... \n");getch();}求解二维数组的最大/最小元素#define MAXN 20int a[MAXN][MAXN];main(){int min, /* 存储最小值*/max; /* 存储最大值*/int row,col,n;clrscr();printf("Please input the order of the matrix:\n");/* 输入方阵的阶次*/ scanf("%d",&n);printf("Please input the elements of the matrix,\n from a[0][0] to a[%d][%d]:\n",n-1,n-1);for(row=0;row<n;row++)for(col=0;col<n;col++)scanf("%d",&a[row][col]);for(min=a[0][0],row=0;row<n;row++){/* 从每行选出最大数*/for(max=a[row][0],col=1;col<n;col++)/*从row行选出最大数*/if(max<a[row][col])max=a[row][col];if(min>max)/* 保存至row行的最小数*/min=max;}printf("The minimum of maximum number is %d\n",min);for(max=a[0][0],row=0;row<n;row++){/* 每行选出最小数*/for(min=a[row][0],col=1;col<n;col++)/* 从row行选出最小数*/ if(min>a[row][col])min=a[row][col];if(max<min)/*保存至row行的最大数*/max=min;}printf("The maximum of minimum numbers is %d\n",max);printf("\nPress any key to quit...\n");getch();}利用数组求前n个质数#define N 50main(){int primes[N];int pc,m,k; clrscr();printf("\n The first %d prime numbers are:\n",N);primes[0]=2;/*2是第一个质数*/pc =1;/*已有第一个质数*/m =3;/*被测试的数从3开始*/while(pc<N){/*调整m使它为下一个质数*/k=0;while(primes[k]*primes[k]<=m)if(m%primes[k]==0){/*m是合数*/m+=2;/*让m取下一个奇数*/k=1;/*不必用primes[0]=2去测试m，所以k从一开始*/}elsek++;/*继续用下一个质数去测试*/primes[pc++]=m;m+=2;/*除2外，其余质数均是奇数*/}/*输出primes[0]至primes[pc-1]*/for(k=0;k<pc;k++)printf("%4d",primes[k]);printf("\n\n Press any key to quit...\n ");getch();}编制万年历#include "stdio.h"long int f(int year,int month){/*f(年，月)＝年－1，如月<3;否则，f(年，月)＝年*/if(month<3) return year-1;else return year;} long int g(int month){/*g(月)＝月＋13，如月<3;否则，g(月)＝月＋1*/if(month<3) return month+13;else return month+1;} long int n(int year,int month,int day){/*N=1461*f(年、月)/4+153*g(月)/5+日*/return 1461L*f(year,month)/4+153L*g(month)/5+day;} int w(int year,int month,int day){/*w=(N-621049)%7(0<=w<7)*/return(int)((n(year,month,day)%7-621049L%7+7)%7);} int date[12][6][7];int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};main(){int sw,leap,i,j,k,wd,day;int year;/*年*/char title[]="SUN MON TUE WED THU FRI SAT";clrscr();printf("Please input the year whose calendar you want to know: ");/*输入年*/scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/sw=w(year,1,1);leap=year%4==0&&year%100||year%400==0;/*判闰年*/for(i=0;i<12;i++)for(j=0;j<6;j++)for(k=0;k<7;k++)date[i][j][k]=0;/*日期表置0*/for(i=0;i<12;i++)/*一年十二个月*/for(wd=0,day=1;day<=day_tbl[leap][i];day++){/*将第i＋1月的日期填入日期表*/date[i][wd][sw]=day;sw=++sw%7;/*每星期七天，以0至6计数*/if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/} printf("\n|==================The Calendar of Year %d=====================|\n|",year);for(i=0;i<6;i++){/*先测算第i+1月和第i+7月的最大星期数*/for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/wd+=date[i][5][k]+date[i+6][5][k];wd=wd?6:5;printf("%2d %s %2d %s |\n|",i+1,title,i+7,title);for(j=0;j<wd;j++){printf(" ");/*输出四个空白符*//*左栏为第i+1月，右栏为第i+7月*/for(k=0;k<7;k++)if(date[i][j][k])printf("%4d",date[i][j][k]);else printf(" ");printf(" ");/*输出十个空白符*/for(k=0;k<7;k++)if(date[i+6][j][k])printf("%4d",date[i+6][j][k]);else printf(" ");printf(" |\n|");}/*scanf("%*c");/*键入回车输出下一个月的日历*/}puts("=================================================================|") ;puts("\n Press any key to quit...");getch();}对数组元素排序rest(int a[], int n){int i,low,high,t; for(i=0,low=0,high=n-1;i<=high;) {if(a[i]>0){/*a[i]与a[high]交换，随之high减1*/t=a[i];a[i]=a[high];a[high]=t;high--;}else if(a[i]==0)i++; /* 掠过该元素*/else{/*a[i]与a[low]交换，随之low增1, i增1*/t=a[i];a[i]=a[low];a[low]=t;low++;i++;}}}int s[]={8,4,0,-1,6,0,-5};main(){int i;clrscr();printf("\n The arry before rest is:\n");for(i=0;i<sizeof(s)/sizeof(s[0]);i++)printf("%4d",s[i]);rest(s,sizeof(s)/sizeof(s[0]));printf("\n The arry after rest is:\n");for(i=0;i<sizeof(s)/sizeof(s[0]);i++)printf("%4d",s[i]);printf("\n Press any key to quit...\n");getch();}任意进制数的转换/* 函数trans将无符号整数n翻译成d（2<＝d<＝16）进制表示的字符串s */ #define M sizeof(unsigned int)*8int trans(unsigned n, int d, char s[]){static char digits[] ="0123456789ABCDEF"; /* 十六进制数字的字符*/char buf[M+1];int j, i = M;if(d<2||d>16){s[0]='\0'; /* 不合理的进制，置s为空字符串*/return 0; /* 不合理的进制，函数返回0 */}buf[i]='\0';do{buf[--i]=digits[n%d]; /*译出最低位，对应字符存入对应工作数组中*/n/=d;}while(n);/* 将译出在工作数组中的字符串复制到s */for(j=0;(s[j]=buf[i])!='\0';j++,i++);/* 其中控制条件可简写成s[j]=buf[i] */return j;}/* 主函数用于测试函数trans() */main(){unsigned int num = 253;int scale[]={2,3,10,16,1};char str[33];int i;clrscr();for(i=0;i<sizeof(scale)/sizeof(scale[0]);i++){if(trans(num,scale[i],str))printf("%5d = %s(%d)\n",num,str,scale[i]);elseprintf("%5d => (%d) Error! \n",num,scale[i]);}printf("\n Press any key to quit...\n");getch();}判断回文数/* 函数circle用于判断正整数n的d进制数表示形式是否是回文数*/ int circle(int n, int d){int s=0,m=n;while(m){s=s*d+m%d;m/=d;}return s==n;}/* main函数用于测试circle函数*/int num[]={232,27,851};int scale[]={2,10,16};main(){int i,j;clrscr();for(i=0;i<sizeof(num)/sizeof(num[0]);i++)for(j=0;j<sizeof(scale)/sizeof(scale[0]);j++)if(circle(num[i],scale[j]))printf("%d -> (%d) is a Circle Number!\n",num[i],scale[j]);elseprintf("%d -> (%d) is not a Circle Number!\n",num[i],scale[j]);printf("\n Press any key to quit...\n");getch();}求解钢材切割的最佳订单#include <stdio.h>#define N 20#define DELTA 2int bestlen;int bestsele[N];int sele[N];int n;int orderlen[N];int total;main(){int i;clrscr();printf("\n Please enter total length of the steel:\n");/* 输入钢材总长*/scanf("%d",&total);printf("\n Please enter number of order:\n"); /* 输入定单数*/ scanf("%d",&n);printf("\n Please enter the orders:\n"); /* 输入各定单*/for(i=0;i<n;i++)scanf("%d",&orderlen[i]);bestlen=0; /*最佳解用料的初值*/for(i=0;i<n;i++)sele[i]=bestsele[i]=0; /*置当前选择和最佳选择初值*/try(); /* 调用函数求解*/for(i=0;i<n;i++) /* 输出结果*/if(bestsele[i])printf("order %d length = %d\n",i+1,orderlen[i]);printf("\n Press any key to quit...");getch();}try(){int i,len;for(len=i=0;i<n;i++) /* 求当前选中的用料量*/if(sele[i])len+=orderlen[i]+DELTA;if(len-DELTA<=total) /* 注意最后一段可能不需要切割*/{if(bestlen < len){/* 找到一个更好的解*/bestlen = len;for(i=0;i<n;i++)bestsele[i]=sele[i];}for(i=0;i<n;i++) /* 对所有未选定单逐一作选中尝试循环*/if(!sele[i]){sele[i]=1; /* 做选中尝试*/try();sele[i]=0;}}}指向数组的指针main(){int x,y,z; /* 定义三个int型变量*/int *xp = &x, /* 定义指针变量xp,并赋值为x的地址，使xp指向x */ *yp = &y, /* 定义指针变量yp,并赋值为y的地址，使yp指向y */*zp = &z; /* 定义指针变量zp,并赋值为z的地址，使zp指向z */int t;printf("\nPlease input x,y,z:\n");scanf("%d%d%d",xp,yp,zp); /* 通过变量的指针，为变量输入值*/ if(*xp>*yp) /* 通过指向变量的指针引用变量的值*/{t=*xp; /* 通过指向变量的指针引用变量的值*/*xp=*yp;/* 通过指向变量x的指针xp,引用变量x的值*/*yp=t; /* 通过指向变量y的指针yp,引用变量y的值*/}if(*xp>*zp) /* 通过指向变量的指针,引用变量的值*/{t=*xp; /* 通过指向变量x的指针xp,引用变量x的值*/*xp=*zp;/* 通过指向变量x的指针xp,引用变量x的值*/*zp=t; /* 通过指向变量z的指针zp,引用变量z的值*/}if(*yp>*zp) /* 通过指向变量的指针,引用变量的值*/{t=*yp; /* 通过指向变量的指针,引用变量的值*/*yp=*zp;/* 通过指向变量y的指针yp,引用变量y的值*/*zp=t;/* 通过指向变量z的指针zp,引用变量z的值*/}printf("x = %d\ty = %d\tz = %d\n",x,y,z);printf("\nPress any key to quit...\n");getch();}阿拉伯数字转换为罗马数字#include <stdio.h>#define ROWS 4#define COLS 4int nums[ROWS][COLS]={{1000,1000,1000,1000},{900,500,400,100},{90,50,40,10},{9,5,4,1}};char *roms[ROWS][COLS]={{"m","m","m","m"}, {"cm","d","cd","c"},{"xc","l","xl","x"},{"ix","v","iv","i"}}; main(int argc,char *argv[ ]){int low,high;char roman[25]; if(argc<2){ printf("Usage:roman decimal_number\n");/*运行程序需带整数参数*/}high=low=atoi(argv[1]);/*将第一个参数转换成整数*/checknum(low);if(argc>2){/*带两个参数*/high=atoi(argv[2]);checknum(high);if(low>high){low=high;high=atoi(argv[1]);}}elselow=1;for(;low<=high;low++){to_roman(low,roman);printf("%d\t%s\n",low,roman);}} checknum(int val)/*检查参数合理性*/{if(val<1||val>9999){printf("The number must be in range 1..9999.\n");exit(0);}}to_roman(int decimal,char roman[ ])/*将整数转换成罗马数字表示*/ {int power,index;roman[0]='\0';for(power=0;power<ROWS;power++)for(index=0;index<COLS;index++)while(decimal>=nums[power][index]){strcat(roman,roms[power][index]);decimal-=nums[power][index];}}通讯录的输入输出#include <stdio.h>#define ZIPLEN 10#define PHONLEN 15/*struct addr类型定义*/ struct addr{char *name;/*姓名*/char *address;/*地址*/char zip[ZIPLEN];/*邮政编码*/char phone[PHONLEN];/*电话号码*/}; main()/*本主函数示意上述输入输出函数的用法*/{struct addr p[100];int i,j;clrscr();for(i=0;readaddr(p+i);i++);for(j=0;j<i;j++) writeaddr(p+j);puts("\n Press any key to quit...");getch();} /* 函数readaddr用于输入一个通信录函数*/int readaddr(struct addr *dpt){int len;char buf[120];/*输入字符串的缓冲区*/ printf("\nPlease input theName:\n");/*输入姓名*/if(scanf("%s",buf)==1){len=strlen(buf);dpt->name=(char *)malloc(len+1);/*申请存贮姓名的空间*/ strcpy(dpt->name,buf);}else return 0;/*Ctrl+Z结束输入*/printf("Please input the Address:\n");/*输入地址*/if(scanf("%s",buf)==1){len=strlen(buf);dpt->address=(char *)malloc(len+1);/*申请存贮地址的空间*/ strcpy(dpt->address,buf);}else{/*Ctrl+Z结束输入*/free(dpt->name);/*释放存贮姓名的空间*/return 0;}printf("Please input the Zip code:\n");/*输入邮编*/if(scanf("%s",buf)==1)strncpy(dpt->zip,buf,ZIPLEN-1);else{free(dpt->name);/*释放存贮姓名的空间*/free(dpt->address);/*释放存贮地址的空间*/return 0;/*Ctrl+Z结束输入*/}printf("Please input the Phone number:\n");/*输入电话号码*/ if(scanf("%s",buf)==1)strncpy(dpt->phone,buf,PHONLEN-1);else{free(dpt->name);free(dpt->address);return 0;/*Ctrl+Z结束输入*/}return 1;} /* 函数writeaddr用于输出通讯录*/int writeaddr(struct addr*dpt){printf("Name : %s\n", dpt->name);/*输出姓名*/printf("Address : %s\n", dpt->address);/*输出地址*/printf("Zip : %s\n", dpt->zip);/*输出邮编*/printf("Phone : %s\n\n", dpt->phone);/*输出电话号码*/}扑克牌的结构表示enum suits{CLUBS,DIAMONDS,HEARTS,SPADES}; struct card{enum suits suit;char value[3];};struct card deck[52];char cardval[][3]= {"A","2","3","4","5","6","7","8","9","10","J","Q","K"};char suitsname[][9]={"CLUBS","DIAMONDS","HEARTS","SPADES"}; main() {int i,j;enum suits s;clrscr();for(i=0;i<=12;i++)for(s=CLUBS;s<=SPADES;s++){j=i*4+s;deck[j].suit=s;strcpy(deck[j].value,cardval[i]);}for(j=0;j<52;j++)printf("(%s%3s)%c",suitsname[deck[j].suit],deck[j].value,j%4==3?'\n':'\t');puts("\nPress any key to quit...");getch();}用“结构”统计学生成绩#include <stdio.h>#define N 200#define SCORES 5#define NUMLEN 10struct std_type{char no[NUMLEN];/*学号*/char *name;/*名字符串指针*/int scores[SCORES];/*五门功课的成绩*/};struct std_type students[N];int order[N];int total[N]; /*[函数]输入一个学生信息函数*/int readastu(struct std_type *spt){int len,j;char buf[120];/*输入字符串的缓冲区*/ printf("\nNumber : ");/*输入学号*/if(scanf("%s",buf)==1)strncpy(spt->no,buf,NUMLEN-1);elsereturn 0;/*Ctrl+Z结束输入*/printf("Name : ");/*输入姓名*/if(scanf("%s",buf)==1){len=strlen(buf);spt->name=(char *)malloc(len+1);/*申请存贮姓名的空间*/ strcpy(spt->name,buf);}else return 0;/*Ctrl+Z结束输入*/printf("Scores : ");/*输入成绩*/for(j=0;j<SCORES;j++)if(scanf("%d",spt->scores+j)!=1)break;if(j==0)/*一个成绩也未输入*/{free(spt->name);/*释放存贮姓名的空间*/return 0;}for(;j<SCORES;j++)/*少数未输入的成绩用0分代之*/ spt->scores[j]=0;return 1;} /*[函数]输出一个学生信息的函数*/int writeastu(struct std_type *spt){int i; printf("Number : %s\n",spt->no);/*输出学号*/printf("Name : %s\n",spt->name);/*输出姓名*/printf("Scores : ");/*输出成绩*/for(i=0;i<SCORES;i++)printf("%4d",spt->scores[i]);printf("\n\n");} main(){int n,i,j,t; clrscr();for(n=0;readastu(students+n);n++);/*采用冒泡法对学生信息数组排序*/for(i=0;i<n;i++){order[i]=i;/*预置第i个输入的学生*/for(t=0,j=0;j<SCORES;j++)/*求第i个学生的总分*/t+=students[i].scores[j];total[i]=t;}/*冒泡排序*/for(i=0;i<n-1;i++)/*共扫视n-1遍*/for(j=0;j<n-1-i;j++)if(total[order[j]]<total[order[j+1]]){/*交换名次*/t=order[j];order[j]=order[j+1];order[j+1]=t;}for(j=0;j<n;j++)/*输出*/writeastu(students+order[j]);printf("\n Press any key to quit...\n");getch();}报数游戏#include <stdio.h>struct ele{int no;struct ele *link;}main(){int n,m,i;struct ele *h,*u,*p;clrscr();printf("Please input n&m:\n");scanf("%d%d",&n,&m);/*输入n和m*/h=u=(struct ele *)malloc(sizeof(struct ele));/*形成首表元*/ h->no=1;for(i=2;i<=n;i++)/*形成其余的n-1个表元*/{u->link=(struct ele *)malloc(sizeof(struct ele));u=u->link;u->no=i;/*第i个表元置编号i*/}u->link=h;/*末表元后继首表元，形成环*/puts("\nThe numbers of who will quit the cycle in turn are:"); while(n){for(i=1;i<m;i++)/*掠过m－1个表元*/u=u->link;p=u->link;/*p指向第m个表元*/u->link=p->link;/*第m个表元从环中脱钩*/printf("%4d",p->no);free(p);/*释放第m个表元占用的空间*/n--;}printf("\n\n Press any key to quit...\n");getch();}学生成绩管理程序/*学生成绩管理程序编制一个统计学生考试分数的管理程序。

经典 C 语言源代码1、(1)某年某月某日是星期几#include<stdio.h>int main(){int year, month, day;while (scanf_s("%d%d%d", &year, &month, &day) != EOF){if (month == 1 || month == 2)// 判断month 是否为1 或2 {year--;month += 12;}int c = year / 100;int y = year - c * 100;int week = (c / 4) - 2 * c + (y + y / 4) + (13 * (month + 1) / 5) day - 1;while (week<0) { week += 7; }week %= 7;switch (week){case 1:printf("Monday\n"); break;case 2:printf("Tuesday\n"); break;case 3:printf("Wednesday\n"); break;case 4:printf("Thursday\n"); break;case 5:printf("Friday\n"); break;case 6:printf("Saturday\n"); break;case 0:printf("Sunday\n"); break;}}return 0;}1、(2)某年某月某日是第几天(一维数组)#include "stdio.h" void main() {int i, flag, year, month, day, dayth;int month_day[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };printf(" 请输入年/月/日：\n");scanf_s("%d/%d/%d", &year, &month, &day);dayth = day;flag = (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0);if (flag)month_day[2] = 29;for (i = 1; i < month; i++)dayth = dayth + month_day[i];Prin tf("%d∕%d∕%d 是第％d 天\n", year, mon th, day, dayth);}2、30 个数中找最小的数及其位置#include "stdio.h"# define SIZE 30void main() {int i;float data[SIZE];int min;Printf("请输入%d个浮点数：∖n",SIZE);for (i = 0; i < SIZE; i++) {//scan f_s("%f", & data[i]); data[i] = rand() % 30 + 1;Printf("%f、", data[i]);}min = 0;for (i = 1; i < SIZE; i++) { if(data[i] < data[min])min = i;}Printf("最小值是％5.2f位置是％5d∖n", data[min], min); }3、30 个数从小到大排序(1)#include "stdio.h"# define SIZE 30void main() {int i,j;float data[SIZE],temP;int min;Printf("请输入%d个整型数：∖n",SIZE);for (i = 0; i < SIZE; i++) {scanf_s("%f", &data[i]);}for (i = 0; i < SIZE; i++) { min = i;for (j = i + 1; j < SIZE; j++)if (data[j] < data[min])temp = data[min];min = j;data[min] = data[i]; data[i] = temp;}printf("\n 排序后的结果是：\n");for (i = 0; i < SIZE; i++) printf("%5.2f", data[i]);}(2)模块化程序(数组名作为函数参数) #include "stdio.h"# define SIZE 5void accept_array(float a[], int size); void sort(float a[], int size); void show_array(float a[], int size);void main() {float score[SIZE]; accept_array(score, SIZE);printf(" 排序前："); show_array(score, SIZE);sort(score, SIZE);printf(" 排序后："); show_array(score, SIZE); }void accept_array(float a[], int size) {int i;printf(" 请输入%d 个分数：", size);for (i = 0; i < size; i++) scanf_s("%f", &a[i]);}void show_array(float a[], int size) {int i;for (i = 0; i < size; i++)printf(" %5.2f", a[i]);printf("\n");}void sort(float a[],int size) {int i, min, j;float temp;for (i = 0; i < SIZE; i++) {min = i;for (j = i + 1; j < SIZE; j++)if (a[j] < a[min])min = j;}temp = a[min]; a[min] = a[i]; a[i] = temp;}}4、( 1)指针加减：#include "stdio.h"#define SIZE 10 void main() {int a[SIZE] = { 1,2,3,4,5,6,7,8,9,10 }; int *pa, i;pa = &a[0];//pa=a; printf("\n");for (i = 0; i < SIZE; i++) { printf(" %d", *pa);//printf(" %d", *(pa+1)); pa++;(2)指针比较：#include "stdio.h"#define SIZE 10void main() {int a[SIZE] = { 1,2,3,4,5,6,7,8,9,10 };int *pa, i;int *qa;pa = qa = &a[0];printf(" 请输入%d 整型数：",SIZE); for (; pa < qa + SIZE;pa++) scanf_s("%d", pa);for (pa--; qa <= pa; pa--)printf(" %d", *pa);}5、两字符串相连：#include "stdio.h"#include "string.h"void str_cat(char str1[], char str2[]); void main() {int i, j;char str1[160];char str2[80];printf(" 请输入第一个字符串："); gets(str1);printf(" 请输入第二个字符串："); gets(str2);str_cat(str1, str2);puts(str1);}void str_cat(char str1[], char str2[]) { int i, j;i = 0;while (str1[i] != '\0')i++;j = 0;while (str2[j] != '\0') {str1[i] = str2[j]; i++; j++;}str1[i] = '\0';6、二维数组( a，b 转置) #include "stdio.h" void main() {int i, j, b[2][3];int a[3][2] = { {1,2},{3,4},{5,6} };for (i = 0; i < 2; i++) {}for (j = 0; j < 3; j++)b[i][j] = a[j][i];}printf("\na:\n");for (i = 0; i < 3; i++) { for (j = 0; j < 2; j++) printf("%5d", a[i][j]);printf("\n");}printf("\nb:\n");for(i = 0; i < 2; i++) { for (j = 0; j < 3; j++) printf("%5d", b[i][j]);printf("\n");}7、输入一个二维数组并输出(指针)#include "stdio.h"void main() {int x[2][3];int i, j;for (i = 0; i < 2; i++)for (j = 0; j < 3; j++)scanf_s("%d", *(x + i) + j); putchar('\n');for (i = 0; i < 2; i++){for (j = 0; j < 3; j++)printf("%d ", *(*(x + i) + j));putchar('\n');}}8、冒泡法排序一个数组#include "stdio.h"#define size 10 void maopao(int a[]); void main() { int a[10];int i;printf(" 请输入10 个整数：\n"); for (i = 0; i < 10; i++) scanf_s("%d", &a[i]); maopao(a);}void maopao(int a[]) {int i, j, temp;for (i = 0; i < 9; i++) {// 进行9 轮排序for (j = 0; j < 9 - i; j++)// 每轮进行9-i 次交换{if (a[j] > a[j + 1]){ temp = a[j];a[j] = a[j + 1];// 大的沉底，小的上浮a[j + 1] = temp;}}}printf(" 排序结果：\n"); for (i = 0; i < 10; i++) printf("%4d", a[i]); }9、两数组A，B，要求A<B,如A ：4，7，9B ：1，3，5，8，9变换后A ：1，3，5B ：4，7，8，9，9#include <stdio.h>VOid ReArranger(int* A, int* B, int m, int n) //A 和B是各有m 个和n 个整数的非降序数组，本算法将B 数组元素逐个插入到A 中，使A 中各元素均不大于B 中各元素，且两数组仍保持非降序排列。

c语言入门源代码C语言作为一种非常流行和广泛应用的编程语言，在计算机科学领域发挥了重要作用。

掌握C语言编程的基本知识和技能是初学者的首要任务。

本文将为你提供一些C语言入门的源代码示例，帮助你更好地理解和掌握C语言编程。

代码示例一：Hello World#include <stdio.h>int main() {printf("Hello World!\n");return 0;}这是一个经典的C语言程序，用于向屏幕输出"Hello World!"。

在C 语言中，使用printf函数来实现输出操作。

其中，"\n"表示换行符，用于使输出在新的一行显示。

代码示例二：求和#include <stdio.h>int main() {int num1, num2, sum;printf("请输入两个整数：\n");scanf("%d%d", &num1, &num2);sum = num1 + num2;printf("两个数的和为：%d\n", sum);return 0;}这段代码演示了如何实现两个整数的求和。

首先，使用printf函数提示用户输入两个整数。

接下来，使用scanf函数从用户处获取输入的整数值，并将它们分别赋给num1和num2变量。

然后，将num1和num2变量相加得到sum变量的值，并使用printf函数输出结果。

代码示例三：判断奇偶数#include <stdio.h>int main() {int num;printf("请输入一个整数：\n");scanf("%d", &num);if(num % 2 == 0) {printf("%d是偶数。

\n", num);}else {printf("%d是奇数。

c语言windows编译过程
在Windows操作系统上，使用C语言进行编译的过程主要包括以下几个步骤：
1. 编写源代码：使用文本编辑器编写C语言源代码文件，扩展名为.c。

2. 预处理：使用预处理器对源代码进行处理，包括宏展开、头文件包含、条件编译等。

预处理器生成的文件通常具有扩展名为.i。

3. 编译：使用编译器将预处理后的源代码翻译成汇编代码。

编译器生成的文件通常具有扩展名为.asm。

4. 汇编：使用汇编器将汇编代码翻译成机器码。

汇编器生成的文件通常具有扩展名为.obj。

5. 链接：使用链接器将多个目标文件（.obj）以及所需的库文件进行链接，生成可执行文件。

链接器生成的文件通常具有扩展名为.exe。

在Windows上，可以使用多种工具进行C语言的编译，最常用的是Microsoft Visual Studio（包含了Visual C++编译器）和MinGW （包含了GCC编译器）。

在使用Visual Studio进行编译时，可以通过IDE界面进行操作，也可以使用命令行工具（如cl.exe）执行编译命令。

在使用MinGW进行编译时，一般使用命令行工具（如gcc.exe）执行编译命令。

编译命令的具体参数可以根据需要进行设置，如指定源代码文件、输出文件名、链接的库文件等。

需要注意的是，编译过程中可能会出现一些错误或警告信息，需要根据编译器的提示进行修改和调试。

经典C语言源代码1、(1)某年某月某日是星期几#include<stdio.h>int main(){int year, month, day;while (scanf_s(%d%d%d, &year, &month, &day) != EOF) {if (month == 1 || month == 2)//判断month是否为1或2 {year--;month += 12;}int c = year / 100;int y = year - c * 100;int week = (c / 4) - 2 * c + (y + y / 4) + (13 * (month + 1) / 5) + day - 1;while (week<0) { week += 7; }week %= 7;switch (week){case 1:printf(Monday\n); break;case 2:printf(Tuesday\n); break;case 3:printf(Wednesday\n); break;case 4:printf(Thursday\n); break;case 5:printf(Friday\n); break;case 6:printf(Saturday\n); break;case 0:printf(Sunday\n); break;}}return 0;}1、(2)某年某月某日是第几天（一维数组）#include stdio.hvoid main() {int i, flag, year, month, day, dayth;int month_day[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 }; 牰湩晴尨请输入年/ 月/日：\n);scanf_s(%d/%d/%d, &year, &month, &day);dayth = day;flag = (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0); if (flag)month_day[2] = 29;for (i = 1; i < month; i++)dayth = dayth + month_day[i];printf(%d/%d/%d是第%d天\n, year, month, day, dayth);}2、30个数中找最小的数及其位置#include stdio.h# define SIZE 30void main() {int i;float data[SIZE];int min;牰湩晴尨请输入%d个浮点数：\n,SIZE);for (i = 0; i < SIZE; i++) {//scanf_s(%f, &data[i]);data[i] = rand() % 30 + 1;, data[i]);、printf(%f}min = 0;for (i = 1; i < SIZE; i++) {if (data[i] < data[min])min = i;}牰湩晴尨最小值是%5.2f,位置是]\n, data[min], min); }3、30个数从小到大排序（1）#include stdio.h# define SIZE 30void main() {int i,j;float data[SIZE],temp;int min;牰湩晴尨请输入%d个整型数：\n,SIZE); for (i = 0; i < SIZE; i++) {scanf_s(%f, &data[i]);}for (i = 0; i < SIZE; i++) {min = i;for (j = i + 1; j < SIZE; j++)if (data[j] < data[min])min = j;temp = data[min];data[min] = data[i];data[i] = temp;}printf(\排序后的结果是：\n);for (i = 0; i < SIZE; i++)printf(%5.2f, data[i]);}（2）模块化程序（数组名作为函数参数）#include stdio.h# define SIZE 5void accept_array(float a[], int size);void sort(float a[], int size);void show_array(float a[], int size);void main() {float score[SIZE];accept_array(score, SIZE);牰湩晴尨排序前：);show_array(score, SIZE);sort(score, SIZE);牰湩晴尨排序后：);show_array(score, SIZE);}void accept_array(float a[], int size) { int i;牰湩晴尨请输入%d个分数：, size); for (i = 0; i < size; i++)scanf_s(%f, &a[i]);}void show_array(float a[], int size) { int i;for (i = 0; i < size; i++)%5.2f, a[i]); printf(printf(\);}void sort(float a[],int size) {int i, min, j;float temp;for (i = 0; i < SIZE; i++) {min = i;for (j = i + 1; j < SIZE; j++)if (a[j] < a[min])min = j;temp = a[min];a[min] = a[i];a[i] = temp;}}4、（1）指针加减：#include stdio.h#define SIZE 10void main() {int a[SIZE] = { 1,2,3,4,5,6,7,8,9,10 };int *pa, i;pa = &a[0];//pa=a;printf(\);for (i = 0; i < SIZE; i++) {printf( %d, *pa);//printf( %d, *(pa+1));pa++;}}（2）指针比较：#include stdio.h#define SIZE 10void main() {int a[SIZE] = { 1,2,3,4,5,6,7,8,9,10 }; int *pa, i;int *qa;pa = qa = &a[0];牰湩晴尨请输入%d整型数：,SIZE); for (; pa < qa + SIZE; pa++)scanf_s(%d, pa);for (pa--; qa <= pa; pa--)%d, *pa);printf(}5、两字符串相连：#include stdio.h #include string.hvoid str_cat(char str1[], char str2[]); void main() {int i, j;char str1[160];char str2[80];牰湩晴尨请输入第一个字符串：); gets(str1);牰湩晴尨请输入第二个字符串：);gets(str2);str_cat(str1, str2);puts(str1);}void str_cat(char str1[], char str2[]) { int i, j;i = 0;while (str1[i] != '\0')i++;j = 0;while (str2[j] != '\0') {str1[i] = str2[j];i++; j++;}str1[i] = '\0';}转置）a，b、二维数组（6#include stdio.h void main() {int i, j, b[2][3];6} };for (i = 0; i < 2; i++) {for (j = 0; j < 3; j++)b[i][j] = a[j][i];}printf(\a:\n);for (i = 0; i < 3; i++) {for (j = 0; j < 2; j++)printf(], a[i][j]);printf(\);}printf(\b:\n);for(i = 0; i < 2; i++) {for (j = 0; j < 3; j++)printf(], b[i][j]);printf(\);}}7、输入一个二维数组并输出（指针）#include stdio.hvoid main() {int x[2][3];int i, j;for (i = 0; i < 2; i++)for (j = 0; j < 3; j++)scanf_s(%d, *(x + i) + j);putchar('\n');for (i = 0; i < 2; i++){for (j = 0; j < 3; j++)printf(%d , *(*(x + i) + j));putchar('\n');}}8、冒泡法排序一个数组#include stdio.h #define size 10void maopao(int a[]);void main() {int a[10];int i;牰湩晴尨请输入10 个整数：\n);for (i = 0; i < 10; i++)scanf_s(%d, &a[i]);maopao(a);}void maopao(int a[]) {int i, j, temp;for (i = 0; i < 9; i++) {//进行9轮排序9-ifor (j = 0; j < 9 - i; j++)//每轮进行次交换{if (a[j] > a[j + 1]){temp = a[j];a[j] = a[j + 1];//大的沉底，小的上浮a[j + 1] = temp;}}}牰湩晴尨排序结果：\n);for (i = 0; i < 10; i++)printf(M, a[i]);}9、两数组A，B，要求A<B，如A：4，7，9B：1，3，5，8，9变换后A：1，3，5B：4，7，8，9，9#include <stdio.h>void ReArranger(int* A, int* B, int m, int n) //A和B是各有m个和n 个整数的非降序数组，本算法将B数组元素逐个插入到A中，使A中各元素均不大于B中各元素，且两数组仍保持非降序排列。

#include<stdio.h>main(){float pi=3.14159265,r;printf("enter radius:\n");scanf("%f",&r);printf("r=%.2f,c=%.2f,area=%.2f\n",r,2*pi*r,pi*r*r);system("pause");}#include<stdio.h>main(){int m,n,x,y;printf("inputm,n:\n");scanf("%d%d",&m,&n);if (n%2==1){printf("error!! n bu shi ji shu!\n",n);return;}/*n在这里不能是奇数*/x=(4*m-n)/2;y=(n-2*m)/2;if((x>=0)&&(y>=0))printf("x=%d,y=%d\n",x,y); elseprintf("shu ru cuo wu!\n");getch();}#include<stdio.h>#include<math.h>#include<stdlib.h>main(){float a,b,C;printf("enter 3number(a,b,C):\n"); scanf("%.2f %.2f %.2f",&a,&b,&C); s=0.5*a*b*sinC;printf("s=%.2f\n",s);system("pause");}#include<stdio.h>main(){int ds,nl,yf;char c;printf("shu ru ds;\n");scanf("%d",&ds);if (ds<14||ds>1184){printf("input error!press any end...\n"); scanf("%c",&c);exit(0);}/*输入的数字必须是-14~1184之间*/nl=(ds+115)%100;yf=(ds+115)/100;printf("nl=%d,yf=%d\n",nl,yf);system("pause");}#include<stdio.h>#include<string.h>main(){char s1[100],s2[100],s3[100],s4[100]; printf("input a string:\n");gets(s1);strcpy(s1,s2);strcat(s1,"--------------");strcpy(s3,strcat(s1,"--------------"));strcat(strcpy(s3,strcat(s1,"--------------")),s2);strcpy(s4,strcat(strcpy(s3,strcat(s1,"--------------")),s2)); puts(s4);system("pasue");getch();}#include<stdio.h>#include<math.h>main(){float x1,x2,a,b,c;printf("input 3 number(a,b,c):\n");scanf("%f%f%f",&a,&b,&c);x1=(-b+sqrt(b*b-4*a*c))/(2*a);x2=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x1=%f,X2=%f\n",x1,x2);system("pause");getch();}#include<stdio.h>main(){int a,b,c,t;printf("input 3 number:\n");scanf("%d%d%d",&a,&b,&c);if(a>b){t=a;a=b,b=t;}if(a>c){t=a;a=c;c=t;}if(b>c){t=b;b=c;c=t;}printf("1:%d,2:%d,3:%d\n",a,b,c);system("pause");}#include<stdio.h>#include<stdlib.h>#include<conio.h>main(){float pi=3.14159265,r;textbackground(YELLOW);/* 设置背景色为黄色，注意颜色应该大写，可更改 */ textcolor(RED); /* 设置文件颜色为红色，可更改 */clrscr(); /* 清屏，使设置生效 */printf("enter radius:");scanf("%f",&r);if(r<0)printf("Enter Error!\n");elseprintf("r=%.2f,c=%.2f,area=%.2f\n",r,2*pi*r,pi*r*r); system("pause");/* 暂停，按任一键继续 */#include<stdio.h>#include<math.h>#include<conio.h>main(){float a,b,c,delt,x1,x2,p,q;textcolor(YELLOW);clrscr();printf("Input a b c:\n");scanf("%f%f%f",&a,&b,&c);if(a==0){printf("It's not a quadratic equation!\n");system("pause");return;}delt=b*b-4*a*c;if(delt>=0){x1=(-b+sqrt(delt))/(2*a);x2=(-b-sqrt(delt))/(2*a);printf("x1=%.3f x2=%.4f\n",x1,x2);}else{p=-b/(2*a);q=sqrt(-delt)/(2*a);printf("p=%.4fq=%.4f\n",p,q);}system("pause");getch();}}#include<stdio.h>main(){float pi=3.14159265,r;int k=0;while(k<=3){printf("enter radius:\n");scanf("%f",&r);printf("r=%.2f,c=%.2f,area=%.2f\n",r,2*pi*r,pi*r*r); printf("press any key to continue\npress esc to exit."); k++;}}#include<stdio.h>#include<stdlib.h>#include<time.h>#include<conio.h>main(){int a,b,c,oper;long limit,i=0;char char1;textcolor(GREEN);/*设置字体颜色为绿色*/clrscr(); /*清屏，是设置生效*/while(i<=3){printf("qing xuan ze jia huo jian(1or2,1:+,2:-\n"); scanf("%d",&oper);printf("Enter max (<10000):\n");scanf("%ld",&limit);srand((unsigned long)time(0));a=rand()*limit/RAND_MAX;b=rand()*limit/RAND_MAX;while((a<b)&&(oper==2)){a=rand()*limit/RAND_MAX;b=rand()*limit/RAND_MAX;}char1=(oper==2?'-':'+');printf("%d%c%d\n",a,char1,b);scanf("%d",&c);if((oper==2&&a-b==c)||(oper!=2&&a+b==c)) printf("OK!You are very clever!\n"); elseprintf("The result is not correct!\n"); i++;}getch();}#include<stdio.h>#include<conio.h>main(){int y,i=0;textcolor(YELLOW);/*天下事无难易之分只有做与不做之别*/ textbackground(GREEN);clrscr();/*清屏，是设置生效*/while(i<=3){printf("Input year:\n");scanf("%d",&y);if(y%4==0){if(y%100==0){if(y%400==0)printf("y shi run nian!\n"); elseprintf("y bu shi run nian !\n"); }elseprintf("y shi run nian!\n");}elseprintf("y bu shi run nian!");i++;}getche();}#include<stdio.h>#include<time.h>#include<string.h>main(){int xz,wday1,hour1;struct tm *timeptr;time_t secsnow;char s1[30],s2[30],s3[30];printf("input whom do you say to?:\n"); scanf("%d",&xz);if(xz==1)strcpy(s1,"mother");else if(xz==2)strcpy(s1,"father");elsestrcpy(s1,"");time(&secsnow);timeptr=localtime(&secsnow);wday1=timeptr->tm_wday;if(wday1==6)strcpy(s2,"Happy saturday!");else if(wday1==0)strcpy(s2,"Happy sunday");elsestrcpy(s2,"");hour1=timeptr->tm_hour;if(hour1>=4&&hour1<=10)strcpy(s3,"Good morning!");else if(hour1>=17&&hour1<=22)strcpy(s3,"Good afternoon!");elsestrcpy(s3,"Good evening!");printf("%s%s%s",s1,s2,s3);getch();}#include<stdio.h>#include<conio.h>main(){int day,year,month,i=0;textbackground(BROWN);clrscr();while(i<=3){printf("Input 2 number:\n");scanf("%d%d",&year,&month);switch(month){case 1:case 3:case 5:case 7:case 8:case 10:case 12: day=31;break;case 4:case 6:case 11:day=30;break;case 2:day=28;if((year%4==0&&year%100!=0)||year%400==0)day=29;break;deflault:printf("Invalid month input!\n");return;}printf("There are%d days in %d.%d\n",day,year,month); i++;getch();}}。