〖加34套高考模拟卷〗四川省成都市龙泉中学2021届高考仿真模拟英语试卷含解析
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成都龙泉中学2020-2021学年度2021届高三上学期第20周周考试题化学(时间:45分钟满分:100分)一、单项选择题:本题包括10小题,每小题5分,共50分。
1.食品干燥剂应无毒、无味、无腐蚀性及环境友好。
下列说法错误的是()A.硅胶可用作食品干燥剂B.P2O5不可用作食品干燥剂C.六水氯化钙可用作食品干燥剂D.加工后具有吸水性的植物纤维可用作食品干燥剂2.设N A表示阿伏加德罗常数的值,下列说法正确的是()A.80 ℃时,1 L pH=1的硫酸溶液中,含有的OH-数目为10-13N AB.向含有FeI2的溶液中通入适量氯气,当有1 mol Fe2+被氧化时,该反应转移电子数目为3N AC.100 g质量分数为46%的乙醇水溶液中氧原子数为4N AD.以Mg、Al为电极,NaOH溶液为电解质溶液的原电池中,导线上流过N A个电子3.一定条件下,以CH3CH2OH 为原料可以制取CH2===CH2、CH3CHO(乙醛)、CH2===CHCH===CH2(1,3-丁二烯)、(环氧乙烷)及CH3COOC2H5等物质。
下列说法不正确的是()A.与乙酸乙酯互为同分异构体,且能发生水解反应的有机物有2种(不包括乙酸乙酯本身,且不考虑立体异构)B.乙烯和1,3-丁二烯均能被酸性KMnO4溶液氧化C.1,3-丁二烯分子中的所有原子可能处于同一平面D.乙醛与环氧乙烷互为同分异构体4.FeCO3与砂糖混用可以作补血剂,实验室中制备FeCO3的流程如图所示。
下列说法错误的是()A.可利用KSCN溶液检验FeSO4溶液是否变质B.沉淀过程中有CO2气体放出C.过滤操作的常用玻璃仪器有烧杯、漏斗和玻璃棒D.产品FeCO3在空气中高温分解可得到纯净的FeO5.某有机物的结构简式如图所示,下列说法正确的是()A.分子式为C10H12O3B.能使酸性KMnO4溶液褪色C.1 mol该有机物可中和2 mol NaOHD.1 mol该有机物最多可与3 mol H2发生加成反应6.下列图示与对应的叙述相符的是()A.图Ⅰ表示某吸热反应分别在有、无催化剂的情况下反应过程中的能量变化B.图Ⅱ表示常温下,0.100 mol·L-1 NaOH溶液滴定20.00 mL 0.100 mol·L-1 HCl溶液所得到的滴定曲线C.图Ⅲ表示一定质量的冰醋酸加水稀释过程中,醋酸溶液电离程度:c<a<bD.图Ⅳ表示反应4CO(g)+2NO2(g)N2(g)+4CO2(g),在其他条件不变的情况下改变起始物CO的物质的量,平衡时N2的体积分数变化情况,由图可知NO2转化率c>b>a7.下列实验中,对应的现象以及结论都正确且两者具有因果关系的是()选项实验现象结论A 将稀硝酸加入过量铁粉中,充分反应后滴加KSCN溶液有气体生成,溶液呈血红色稀硝酸将Fe氧化为Fe3+B将铜粉加入1.0 mol·L-1Fe2(SO4)3溶液中溶液变蓝,有黑色固体出现金属铁比铜活泼C用坩埚钳夹住一小块用砂纸仔细打磨过的铝箔在酒精灯上加热熔化后的液态铝滴落下来金属铝的熔点较低D将0.1 mol·L-1 MgSO4溶液滴入NaOH溶液至不再有沉淀产生,再滴加0.1 mol·L-1CuSO4溶液先有白色沉淀生成,后变为浅蓝色沉淀Cu(OH)2的溶度积比Mg(OH)2的小8.有四种短周期主族元素z、e、g、h,其最高价氧化物对应水化物溶液(物质的量浓度均为0.01 mol·L-1)的pH与原子序数的关系如图所示。
1.A.She was late for the appointment.B.She often kept other people waiting.C.She ran into the man on her way here.D.She called her friend about the book.2.A.Mike has forgotten his books a million times.B.Mike should give her a dollar each time he lost something.C.Mike was lying about why he didn’t go over his lessons.D.Mike should have taken his notebook home.3. Where does the conversation take place?A.At a fast-food restaurant.B.At a supermarket.C.On a plane.4.A.The man likes the new wallpaper.B.The man is sensitive to bright colors.C.The woman has changed the furniture.D.The woman has just moved into a new building.5. What is the man now?A.An accountant.B.A teacher.C.A musician.二、听力选择题6. 听下面一段较长对话,回答以下小题。
1. What are the speakers mainly talking about?A.The advantages of studying abroad.B.The preparations before going abroad.C.The plans for the trip.2. What did the man do?A.He applied for his student visa.B.He did his homework.C.He got his passport.3. What does the woman have to do now?A.Book an airline ticket.B.Get a medical checkup.C.Get the shots.7. 听下面一段较长对话,回答以下小题。
专题09 四川盆地基础知识1、概况:四川盆地是中国四大盆地之一,位于四川省内紫色盆地,总面积约26万多平方千米,位于亚洲大陆中南部(北纬28“10`和32.25`之间),中国西南部、囊括四川省中东部,由青藏高原、大巴山、华蓥山、云贵高原环绕而成,周围山地海拔多在1000米~3000米之间。
2、地形:四周为海拔2000~3000米的山脉和高原所环绕,北面是大巴山、米仓山、龙门山,西面是青藏高原边缘的邛崃山、大凉山,南面是大娄山,东面是巫山。
四川盆地是我国最大的外流盆地,面积26万多平方千米。
四川盆地内部丘陵、平原交错,地势北高南低。
由于地表形态的不同,以华蓥山、龙泉山为界。
3、气候:受该地形影响(北面秦岭、大巴山的屏障,大大减弱了冬季寒潮、冷空气的入侵程度,也使夏季热量不易扩散),当地的亚热带(季风)气候特征显著,具有冬暖、春旱、夏热的特点。
四川盆地虽日照不足(小于1400小时),但气候温和(年均温16—18℃),热量充裕(全年活动积温可达5000℃),降水丰沛(1000毫米左右)。
4、水文:四川盆地境内有长江(中国第一大河)、岷江、嘉陵江和乌江(贵州省第一大河,又称“黔江”)等主要河流,水资源和水能资源富集(水量丰富,河床纵比降大),不仅为生产生活提供了充足的水源,还为建设水电基地和发展旅游、养殖渔业等提供了良好的条件。
5、资源:该地区矿产种类繁多,资源丰富,天然气、芒硝(中药)等居中国之冠,井(矿)盐分布广泛(自贡是我国最大的井盐生产基地,被誉为“千年盐都”)。
盆地中矿产资源分布相对集中,地域组合好,利于建设大型矿山和工业基地。
其中,攀枝花城就是一座因矿产资源(钢铁、钒钛)而兴起的年轻城市。
四川盆地,复杂多样的自然条件成为了众多野生动植物的家园。
这里有多种国家重点保护的野生植物(如桫椤——蕨类植物之王)和50多种国家重点保护的珍稀动物。
盆地的西缘山地是中国动物保存最好、最集中的地区。
大熊猫(实际上陕甘等地的秦岭山区也有大熊猫,只是没有四川的名气大)、金丝猴、雪豹在这里。
2021年湖北省恩施高中、龙泉中学、宜昌一中高考数学联考试卷(4月份)一、单项选择题(每小题5分).1.命题“∀x∈R,x2≥0”的否定为()A.∀x∉R,x2≥0B.∀x∈R,x2<0C.∃x∈R,x2≥0D.∃x∈R,x2<0 2.已知集合A={1,2},集合B={0,2},设集合C={z|z=xy,x∈A,y∈B},则下列结论中正确的是()A.A∩C=∅B.A∪C=C C.B∩C=B D.A∪B=C3.数列{a n}是各项均为正数的等比数列,3a2是a3与2a4的等差中项,则{a n}的公比等于()A.2B.C.3D.4.已知m,n是两条不同的直线,α,β是两个不同的平面,则下列判断正确的是()A.若α⊥β,m⊂α,n⊂β,则直线m与n一定平行B.若m⊥α,n⊥β,α⊥β,则直线m与n可能相交、平行或异面C.若m⊥α,l∥α,则直线m与n一定垂直D.若m⊂α,n⊂β,α∥β,则直线m与n一定平行5.已知向量,满足||=1,=(1,﹣2),且|+|=2,则cos<,>=()A.B.C.D.6.在△ABC中,角A,B,C所对的边分别为a,b,c,则“b cos A﹣c<0”是“△ABC为锐角三角形”的()A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件7.《算数书》是我国现存最早的系统性数学典籍,其中记载有求“困盖”的术:置如其周,令相乘也,又以高乘之,三十六成一,该术相当于给出了由圆锥的底面周长L与高h,计算其体积V的近似公式V≈L2h.用该术可求得圆率π的近似值.现用该术求得π的近似值,并计算得一个底面直径和母线长相等的圆锥的表面积的近似值为27,则该圆锥体积的近似值为()A.B.3C.3D.98.已知实数a,b满足a=log34+log129,5a+12a=13b,则下列判断正确的是()A.a>b>2B.b>a>2C.2>b>a D.a>2>b二、多项选择题:本题共4小题,每小题5分,共20分.在每小题给出的四个选项中,有多项符合题目要求。
鄂南高中黄冈中学黄石二中荆州中学龙泉中学武汉二中孝感高中襄阳四中襄阳五中宜昌一中夷陵中学2021 届高三湖北十一校第二次联考英语试题本试卷共10 页,共72 题。
全卷满分150 分。
考试用时120 分钟。
注意事项:1. 答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2. 回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3. 考试结束后,将本试卷和答题卡一并交回。
第一部分听力(共两节,满分30 分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5 小题;每小题1.5 分,满7.5 分)听下面5 段对话。
每段对话后有一个小题,从题中所给的A、B、C 三个选项中选出最佳选项。
听完每段对话后,你都有10 秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does the man think of the woman’s old a partment?A. Convenient.B. Comfortable.C. Noisy.2. Where did the woman leave her mobile phone?A. In her bag.B. On the table.C. On the chair.3. How did James contact the woman yesterday?A. By postcard.B. By email.C. By phone.4. What are the speakers probably talking about?A. A pet.B. A job.C. An appointment.5. Who is the man most probably going to work with?A. Pre-school kids.B. The disabled.C. Teenagers.第二节(共15 小题;每小题1.5 分,满22.5 分)听下面5 段对话或独白。
专题十氮及其化合物考点1 氮及氮的氧化物1.[新题型][2021广东惠州调研改编][双选]自然界中时刻存在着氮气的转化。
实现氮气按照一定方向转化一直是科学领域研究的重要课题,如图为N2分子在催化剂的作用下发生的一系列转化示意图:下列叙述正确的是( )A.N 2NH3,NH3NO均属于氮的固定B.催化剂a作用下氮原子发生了还原反应C.催化剂a、b表面均发生了极性共价键的断裂D.使用催化剂a、b均可以提高单位时间内生成物的产量2.[2021河北衡水中学期中]如图是某元素的价类二维图,其中A为正盐,X是一种强碱,通常条件下Z是无色液体,E的相对分子质量比D大16,各物质的转化关系如图所示。
下列说法错误的是( )A.A作肥料时不适合与草木灰混合使用B.同主族元素的氢化物中B的沸点最低C.C一般用排水法收集D.D E的反应可用于检验D3.[2021江苏启东中学月考改编]下列实验方案能达到实验目的的是( )选项实验目的实验方案A鉴别NO2、溴蒸气用湿润的淀粉-碘化钾试纸放在集气瓶口,若试纸变蓝则该气体为溴蒸气B验证I-还原性强于Cl-向NaI溶液中依次滴入少量新制氯水和苯,振荡、静置,上层溶液呈紫红色C 检验Fe(NO3)2晶体是否已氧化变质将Fe(NO3)2晶体样品溶于稀硫酸后,滴加KSCN溶液,观察溶液是否变成红色D检验SO2的漂白性将SO2通入酸性高锰酸钾溶液中,观察溶液是否褪色4.实验室可用如图装置制取少量氮气。
下列说法正确的是( )A.②中盛放的是五氧化二磷B.实验开始时先点燃③中的酒精灯,再点燃①中的酒精灯C.③中硬质玻璃管中的反应为2NH3+3CuO N2+3Cu+3H2OD.实验结束时先熄灭①③中的酒精灯,再将导管从水槽中拿出5.[2021四川成都龙泉中学月考,12分]某学校化学学习小组为探究二氧化氮的性质,按如图所示装置进行实验。
请回答下列问题:(1)装置甲中盛放浓硝酸的仪器A的名称是,该装置中发生反应的化学方程式为。
短文填空专题成都嘉祥外国语学校2020-2021学年九年级上10月月考三、短文填空从下面方框中选出10个单词,并将其正确形式填写在答题卡相应题号后,使短文意思正确通顺(每词限用-次)。
(共10小题,每小题1分:计10分)A young man decided to visit a market known for its talented artists. He hoped to find someone to help him release(释放)the great___1____in his heart. When he was walking through the large market, he felt that___ 2____seemed special. Then he followed a large sound of drops of water and came upon an open gate. He saw a young lady ___3___ in an open yard. Around her were all kinds of stone sculptures (雕刻) of wild animals . Just then the young lady stood up and got a little hammer. She walked towards a large stone after careful ___4____ of one small area; she hit itwith little force. The young man felt sorry for her and thought she must be a learner.Suddenly tons of small pieces of stone broke away. He thought she made a mistake and had broken the whole stone into pieces. A moment later, he found she had not broken the stone, instead, she___ 5____ it to look like the beautiful neck of a great swan. He was ____6___What magic was this? He expected to know.“Oh," she laughed,“I'm guessing you have only been there in the last few minutes . Before you began watching me ,I had hundreds of similar small ___7__to the same spot(点) on that stone. You just saw the result of many days of ___8___workmatched with a special kind of quiet consideration."That's how all great things___ 9___sting attention matched with lasting efforts. Then nothing can get in the way of what must be released." the young lady continued. The young man ___10___ seemed to understand something三、1. force 2. nothing 3. sitting 4. examination 5. had shaped 6. shocked 7. hits 8. careful 9. are achieved 10. Suddenly四川省简阳市简城学区2021届九年级上学期第一次月考英语试题三、短文填空。
2021届全国高考物理(全国统考版)评估验收模拟卷(十一)(解析版)(时间:70分钟;满分:110分)第Ⅰ卷二、选择题:本题共8小题,每小题6分,共48分.在每小题给出的四个选项中,第14~18题只有一项符合题目要求,第19~21题有多项符合题目要求.全部选对的得6分,选对但不全的得3分,有选错的得0分.14.拍皮球是大家都喜欢的体育活动,既能强身又能健体.已知皮球质量为0.4 kg,为保证皮球与地面碰撞后自然跳起的最大高度均为1.25 m,小明需每次在球到达最高点时拍球,每次拍球作用距离为0.25 m,使球在离手时获得一个竖直向下4 m/s的初速度.若不计空气阻力及球的形变,g取10 m/s2,则每次拍球()A.手给球的冲量为1.6 kg·m/sB.手给球的冲量为2.0 kg·m/sC.人对球做的功为3.2 JD.人对球做的功为2.2 J15.如图所示,一倾斜的圆筒绕固定轴OO1以恒定的角度ω转动,圆筒的半径r=1.5 m.筒壁内有一小物体与圆筒始终保持相对静止,小物体与圆筒间的动摩擦因数为32(设最大静摩擦力等于滑动摩擦力),转动轴与水平面间的夹角为60°,重力加速度g取10 m/s2.则ω的最小值是()A.1 rad/s B.303rad/sC.10 rad/s D.5 rad/s16.如图所示,竖直平面内有一金属环,半径为a,总电阻为R.磁感应强度为B的匀强磁场垂直穿过环平面,在环的最高点A 用铰链连接长度为2a 、电阻为R2的导体棒AB .AB 由水平位置紧贴环面摆下,当摆到竖直位置时,B 点的线速度 v ,则这时AB 两端的电压大小为( )A .Ba v B.2Ba v 3C.Ba v 3D.Ba v 617.如图为两条平行的光滑绝缘导轨,其中半圆导轨竖直,水平导轨与半圆导轨相切于C 、E 点,整个装置处于竖直向上的匀强磁场中.现将一导体棒垂直导轨放置,开始时位于图中的A 点处,当导体棒中通有如图所示方向的电流时,导体棒由静止开始运动,并能到达与半圆导轨圆心等高的D 点.已知导轨的间距为L =0.5 m ,磁场的磁感应强度大小B =0.5 T ,导体棒的质量为m =0.05 kg 、长度为L ′=0.5 m ,导体棒中的电流大小为I =2 A ,AC =OD =1 m ,重力加速度为g =10 m/s 2.下列说法中正确的是( )A .导体棒在A 点的加速度大小为8 m/s 2B .导体棒在D 点的速度大小为5 m/sC .导体棒在D 点的向心加速度大小为10 5 m/s 2D .导体棒在D 点时,一条半圆导轨对导体棒的作用力大小为0.75 N18.如图所示,重为10 N 的小球套在与水平面成37°角的硬杆上,现用一垂直于杆向上、大小为20 N 的力F 拉小球,使小球处于静止状态(已知sin 37°=0.6,cos 37°=0.8).则( )A .小球不一定受摩擦力的作用B .小球受摩擦力的方向一定沿杆向上,大小为6 NC .杆对小球的弹力方向垂直于杆向下,大小为4.8 ND .杆对小球的弹力方向垂直于杆向上,大小为12 N19.如图(a)所示,点电荷M 、N 固定于光滑绝缘水平桌面上,其连线的中垂线上有A 、B 、C 三点.一电荷量为+q 的小球自A 点由静止释放,其运动的v -t 图象如图(b)所示,运动到B 、C 点的时刻分别为t B 、t C 速度大小分别为v B 、v C ,且t B 时刻图线切线斜率最大.则下列说法正确的是( )A .A 、B 、C 三点中,B 点的电场强度最大 B .由A 到C 的过程中小球的电势能先减小后变大 C .由A 到C 的过程中,电势逐渐升高D .B 、C 两点之间的电势差U BC =m (v 2C -v 2B )2q20.如图所示,虚线OL 与y 轴的夹角为60°,在此角范围内有垂直于xOy 平面向外的匀强磁场.一带正电荷的粒子从y 轴上的M 点沿平行于x 轴的方向射入磁场,粒子离开磁场后的运动轨迹与x 轴交于P 点(图中未画出).已知OP 之间的距离与粒子在磁场中运动的轨道半径相同,不计粒子的重力.则下列说法正确的是( )A .粒子离开磁场时的速度方向可能垂直虚线OLB .粒子经过x 轴时的速度方向可能垂直x 轴C .粒子离开磁场时的速度方向可能和虚线OL 成30°夹角D .粒子经过x 轴时的速度方向可能与x 轴正方向成30°夹角21.在空间竖直平面内,存在如图甲所示的Ⅰ、Ⅱ、Ⅲ、Ⅳ四个区域,其中区域Ⅱ内和区域Ⅲ内存在方向不同的匀强电场,一电荷量为q 、质量为m 的带正电小球(可视为质点)在0~15 s 内竖直向上运动,其加速度随时间变化的图象(a -t 图象)如图乙所示,若取竖直向下为正方向,重力加速度g 取10 m/s 2,则下列说法正确的是( )A .区域Ⅱ内电场的场强E =mg5q,方向竖直向下 B .在0~5 s 内小球的动能减小 C .在10~15 s 内小球的机械能一直增加D.t=15 s时小球的机械能大于t=5 s时小球的机械能题号1415161718192021答案第Ⅱ卷三、非选择题:共62分.第22~25题为必考题,每个试题考生都必须作答.第33~34题为选考题,考生根据要求作答.(一)必考题:共47分.22.(5分)在“验证力的平行四边形定则”实验中.(1)某次实验中两弹簧测力计的读数分别为F1=1.92 N,F2=3.84 N,如图甲所示,F1和F2的合力大小F合=________N(保留三位有效数字).现保持F2方向不变,减小F1和F2的夹角,为了使橡皮条的结点拉到同样的位置O点,下列说法正确的是________.A.F1一定减小B.F1一定增大C.F2一定减小D.F2一定增大(2)某同学想知道弹簧测力计中弹簧的劲度系数,于是,他将刻度尺与弹簧测力计平行放置,如图乙所示,他根据图中信息得出了弹簧的劲度系数k=________N/m(保留两位有效数字).乙23.(10分)某物理研究小组尝试利用一个电流计准确地测量一节干电池的电动势和内阻.已知干电池的电动势约为1.5 V,内阻几欧姆,可利用的仪器有:A.电流计G(量程I g=30 mA,内阻R g未知)B.电阻箱R(0~99.99 Ω)C.定值电阻箱R0(R0=30 Ω)D.开关E.导线若干回答下列问题:(1)该小组首先设计如图甲所示的电路图.闭合开关S,将电阻的阻值调到17.00 Ω时,电流计恰好满偏;将电阻的阻值调到42.00 Ω时,电流计指针指在如图乙所示位置,则电流计的示数为________mA.由以上数据可得到干电池电动势E =________V.(2)该小组发现图甲所示电路无法测量电源的内阻,原因是_________________.于是他们又设计一个电路测量干电池的内阻,如图丙所示.(3)闭合开关S ,改变电阻箱的阻值R ,读出对应的电流计的读数I ,然后在图丁的1I -1R 坐标系中描出相应的点,并根据所描点的规律作出1I -1R的图线.(4)结合两个实验电路图的数据,可求出电流计电阻R g =________Ω,干电池内阻r =________Ω. 24.(12分)如图所示,物块A 和B 静置在粗糙的水平桌面上,A 、B 之间有一根长为L =2 m 的拉直的轻绳,轻绳能承受的最大拉力为30 N ,A 的质量为m 1=5 kg ,B 的质量为m 2=5 kg ,A 、B 与水平桌面间的动摩擦因数均为μ=0.2.A 受到向左的恒力F 0=10 N 的作用,B 受到向右逐渐增大的水平力F 的作用,从某时刻起A 、B 一起向右运动,当F 增大到某一值时,轻绳刚好被拉断,已知重力加速度为g =10 m/s 2.(1)求轻绳刚被拉断时F 的大小.(2)若轻绳刚被拉断时,A 、B 的速度为8 m/s ,此后保持F 大小不变,当A 停止运动时,A 、B 间的距离为多大?25.(20分)如图所示,有一足够长的光滑平行金属导轨间距为L ,折成倾斜和水平两部分,倾斜部分导轨的倾角与水平面的夹角为θ=30°,水平和倾斜部分均处在磁感应强度为B 的匀强磁场中,水平部分磁场方向竖直向下,倾斜部分垂直斜面向下(图中未画出),两个磁场区互不叠加.将两根金属棒a 、b 垂直放置在导轨上,并将b 用轻绳通过定滑轮和小物体c 连接.已知两棒的长度均为L ,电阻均为R ,质量均为m ,小物块c 的质量也为m ,不考虑其他电阻,不计一切摩擦,运动过程中棒与导轨保持接触良好,且b 始终不会碰到滑轮,重力加速度大小为g.(1)求锁定a,释放b的最终速度v m;(2)使a、b同时由静止释放,同时在a上施加一沿斜面向上的恒力F=1.5mg,求达到稳定状态时a、b 的速度;(3)若(2)中系统从由静止开始经时间t达到稳定状态,求过程中系统产生的焦耳热.(二)选考题:共15分.请考生从2道题中任选一题作答,如果多做,则按所做的第一题计分.33.[物理——选修3-3](15分)(1)(5分)下列说法中正确的是________.(填正确答案标号.选对1个得2分,选对2个得4分,选对3个得5分.每选错1个扣3分,最低得分为0分)A.一定质量的理想气体,在等温变化时,内能不变B.把玻璃管的裂口在火焰上烧熔,它的尖端会变钝,这是玻璃表面分子间作用力表现为斥力使其表面扩张引起的C.每个分子的内能等于它的势能和动能的总和D.浸润与不浸润均是分子力作用的表现E.分子间作用力表现为斥力时,随分子间距离增大,分子势能减小(2)(10分)如图所示,一横截面积为S=500 cm2的汽缸固定在水平面上,在汽缸口附近的位置有一销钉.已知销钉与汽缸左端的距离为L=24 cm,一厚度忽略不计的活塞初始时在距离汽缸左端L0=16 cm处,密封了一定质量的理想气体.汽缸导热性良好,汽缸与活塞间的摩擦不计,外界大气压强恒为p0=1.0×105 Pa,环境温度为T0=300 K,现将环境温度缓慢地升高.求:①当活塞刚到销钉处时,气体对外界做的功以及此时的环境温度;②当环境温度升高到T2=600 K时,汽缸内封闭气体的压强.34.[物理——选修3-4](15分)(1)(5分)如图所示,某均匀介质中有两列简谐横波A和B同时沿x轴正方向传播足够长的时间,在t =0时刻两列波的波峰正好在x=0处重合,则下列说法中正确的是________.(填正确答案标号.选对1个得2分,选对2个得4分,选对3个得5分.每选错1个扣3分,最低得分为0分)A.t=0时刻x=0处质点的振动位移为20 cmB.两列波的频率之比为f A∶f B=5∶3C.t=0时刻一定存在振动位移为-30 cm的质点D.t=0时刻x轴正半轴上到原点最近的另一波峰重合处的横坐标为x=7.5 mE.t=0时刻x轴正半轴上到原点最近的波谷重合处的横坐标为x=7.5 m(2)(10分)单色细光束射到一半径为R的透明球表面,光线在过球心的平面内,入射角i=45°,经折射进入球内后又经内表面反射一次,再经球表面折射后射出,已知真空中光速为c,入射光线与出射光线反向延长线之间的夹角α=30°,如图所示(图上已画出入射光线和出射光线).①在图上画出光线在球内的路径和方向(简单说明画图步骤); ②求透明球对该单色光的折射率和光在透明球中传播的时间.高考仿真模拟卷(十一)14.解析:选D.根据题述,使球在离手时获得一个竖直向下4 m/s 的初速度,根据动量定理,合外力给皮球的冲量为I =m v =0.4×4 kg ·m/s =1.6 kg ·m/s ,选项A 错误;手给球的冲量与重力冲量之和等于合外力冲量,手给球的冲量小于1.6 kg·m/s ,选项B 错误;设人对球做的功为W ,由动能定理,W +mgh =12m v 2,解得W =2.2 J ,选项D 正确,C 错误.15.解析:选C.由于小物体在圆筒内随圆筒做圆周运动,其向心力由小物体受到的指向圆心(转动轴)的合力提供.在小物体转到最上面时最容易与圆筒脱离,根据牛顿第二定律,沿半径方向F N +mg cos 60°=m ω2r ,又沿筒壁方向mg sin 60°≤μF N ,解得ω≥10 rad/s ,要使小物体与圆筒始终保持相对静止,则ω的最小值是10 rad/s ,选项C 正确.16.解析:选C.当摆到竖直位置时,导体棒产生的感应电动势为 E =B ·2a v =2Ba ·0+v2=Ba v ;金属环并联的电阻为R 并=12·12R =14R .AB 两端的电压是路端电压,大小为 U =R 并R 并+12R E =14R 14R +12RBa v =Ba v3,选项C 正确.17.解析:选D.导体棒在水平方向受到安培力作用,安培力大小F 安=BIL ′=0.5 N ,导体棒开始运动时的加速度大小为a =F 安m =10 m/s 2,A 错误;导体棒从A 点到D 点的运动过程,安培力做功W 安=F 安(AC+OD )=1 J ,重力做功W G =-mg ·OC =-0.5 J ,由动能定理得W 安+W G =12m v 2,解得导体棒运动到D 点时的速度大小为v =2 5 m/s ,B 错误;导体棒运动到D 点时,向心加速度大小为a ′=v 2r =20 m/s 2,C 错误;在D 点时,由牛顿第二定律得F -F 安=m v 2r ,解得半圆导轨对导体棒的作用力F =1.5 N ,一条半圆导轨对导体棒的作用力大小为0.75 N ,D 正确.18.解析:选B.对小球受力分析,把重力沿杆方向和垂直杆方向正交分解如图,由共点力平衡可知,F f =mg sin 37°=10×0.6 N =6 N ,F N =F -mg cos 37°=20 N -8 N =12 N 、方向垂直于杆向下,小球受摩擦力的方向一定沿杆向上,大小为6 N ,杆对小球的弹力方向垂直于杆向下,大小为12 N ,选项B 正确,A 、C 、D 错误.19.解析:选AD.正电荷在B 处速度图象的斜率最大,可知在B 处电荷加速度最大,由电荷在光滑绝缘水平面上,水平方向只受电场力,由a =Eqm 可知B 点场强E 最大,选项A 正确;电荷由A 到C 一直加速运动,动能一直增加,电势能一直减小,B 选项错误;电荷由A 到C 一直加速运动,电场力一直做正功,电势能一直减小,由E p =qφ可知由A 到C 电势逐渐降低,C 错误;由动能定理,qU BC =12m v 2C -12m v 2B ,可得B 、C 两点之间电势差U BC =m (v 2C -v 2B )2q,D 选项正确.20.解析:选BD.如果粒子离开磁场时的速度方向垂直虚线OL ,则圆心为O ,粒子达到x 轴上的距离OP >r ,故A 错误;如果粒子经过x 轴时的速度方向垂直x 轴,则粒子经过OL 时速度方向竖直向下,粒子运动轨迹如图1所示,此时轨迹几何关系可得OP =r ,故B 正确;如果粒子离开磁场时的速度方向和虚线OL 成30°夹角,则速度方向如图2所示,此时OP 距离一定小于r ,故C 错误;粒子经过x 轴时的速度方向可能与x 轴正方向成30°夹角,轨迹如图3所示,如果β=30°,则粒子半径r =CA 有可能等于OP ,故D 正确.21.解析:选BD.结合题述,根据题给的加速度随时间变化的图象(a -t 图象)可知,在5~10 s 内小球的加速度为8 m/s 2,说明小球除受到重力作用外,还受到一个大小为15mg 的向上的电场力作用,由qE =15mg ,解得E =mg5q ,由于小球带正电,所以电场方向竖直向上,A 错误;在0~5 s 内,小球的加速度为10 m/s 2,说明小球做竖直上抛运动,小球的动能减小,B 正确;在10~15 s 内小球的加速度为12 m/s 2,说明小球除受到重力作用外还受到一个大小为15mg 的竖直向下的电场力作用,电场力对小球做负功,小球的机械能减小,C 错误;在5~10 s 内电场力对小球做正功,小球的机械能增加,由于小球一直做减速运动,在5~10 s 内小球的位移大于在10~15 s 内的位移,区域Ⅱ内电场力对小球做的正功大于区域Ⅲ内电场力对小球做的负功,所以在t =15 s 时小球的机械能大于t =5 s 时小球的机械能,D 正确.22.解析:(1)如图所示,由余弦定理可得:F 合=F 21+F 22-2F 1F 2cos 60°≈3.33 N ;现保持F 2方向不变,减小F 1和F 2的夹角,为了使橡皮条的结点拉到同样的位置O 点,如图所示,可知:F 2逐渐减小,F 1先减小后增大.(2)在刻度尺上选取刻度,由胡克定律可知: k = 5.09.00-0.6×102 N/m ≈60 N/m. 答案:(1)3.33(3.20~3.40均对) C (2)60(60±1均对)23.解析:(1)由图乙所示表盘可知,其分度值为1 mA ,示数为:20.0 mA ;根据闭合电路欧姆定律可知:E =I (r +R g +R ),由题意可知:E =30×10-3×(r +R g +17.00),E =20×10-3×(r +R g +42.00), 解得:E =1.5 V ;(2)由闭合电路欧姆定律可以求出:r +R g ,由于不知电流计内阻R g ,所以无法求出电源内阻r ; (4)由图丙所示电路图可知,电源电动势:E =U +Ir =I (R g +R 0)+⎣⎡⎦⎤I (R g +R 0)R +I r , 整理得:1I =(R g +R 0)r E ·1R +r E +R g +R 0E, 由图丁所示1I -1R图象可知: r E +R g +R 0E=42, k =(R g +R 0)r E =72-420.25=120, 解得:r =3 Ω,R g =30 Ω.答案:(1)20.0 1.5 (2)G 表内阻未知 (4)30 324.解析:(1)设轻绳刚要被拉断时A 、B 的加速度大小为a ,根据牛顿第二定律,对A 有F T -F 0-μm 1g =m 1a代入数据得a =2 m/s 2对A 、B 整体有F -F 0-μ(m 1+m 2)g =(m 1+m 2)a代入数据得F =50 N.(2)设轻绳断之后,A 的加速度大小为a 1,B 的加速度大小为a 2则a 1=F 0+μm 1g m 1=4 m/s 2 a 2=F -μm 2g m 2=8 m/s 2 A 停下来的时间为t =v a 1=2 s A 的位移为x 1=v 22a 1=8 m B 的位移为x 2=v t +12a 2t 2=32 m A 停止时,A 、B 间距离为x =x 2+L -x 1=26 m.答案:见解析25.解析:(1)当b 和c 组成的系统做匀速运动时,b 、c 有最大速度,且为最终速度,根据平衡条件:mg =BIL ①I =E 2R② E =BL v m ③(2)对a 棒:F -mg sin θ-BIL =ma 1 ⑤代入F 、θ得:mg -BIL =ma 1对于b 和c 系统:mg -BIL =2ma 2 ⑥所以任意时刻a 1∶a 2=2∶1,由于运动时间相同,所以最终a 、b 的速度之比v 1∶v 2=2∶1 ⑦其中I =BL (v 1+v 2)2R⑧ 当二者加速度为0时,a ,b ,c 达到稳定状态,综上得:a 稳定速度:v 1=4mgR 3B 2L 2 ⑨ b 、c 稳定速度:v 2=2mgR 3B 2L 2. ⑩ (3)设a 棒沿着斜面移动的位移大小为x 1,b 、c 棒的位移大小为x 2,由于运动时间相同,且a 1∶a 2=2∶1,则从静止开始至恰好稳定状态,a 、b 棒的位移大小之比:x 1∶x 2=2∶1 ⑪对于a 、b 、c 系统,由功能关系得:(F -mg sin θ)x 1+mgx 2=12m v 21+12(2m )v 22+Q ⑫ 代入F 、θ及⑨得:Q =3mgx 2-4m 3g 2R 23B 4L 4⑬ [另解:a 棒动能定理:(F -mg sin θ)x 1-W 安1=12m v 21-0 b 、c 动能定理:mgx 2-W 安1=12×2m v 22-0 Q =W 安1+W 安2Q =3mgx 2-4m 3g 2R 23B 4L 4] 以a 为研究对象:从静止开始至达到稳定状态根据动量定理:(F -mg sin θ)t -BILt =m v 1-0 ⑭It =q ⑮解得:q =mgt BL -m v 1BL⑯ 因为E =n ΔΦΔt(n =1) ⑰ I =E 2R ⑱其中ΔΦ=BL (x 1+x 2) ⑳由⑪⑲⑳解得:x 2=2qR 3BL○21 将⑨⑯式代入○21 即得:x 2=2R 3B 2L 2(mgt -4m 2gR 3B 2L 2) ○22 将○22式代入⑬ 解得:Q =2m 2g 2Rt B 2L 2-4m 3g 2R 2B 4L 4. 答案:见解析33.解析:(1)一定质量的理想气体在等温变化时,内能不改变,体积变化,与外界有热交换,A 正确;玻璃管的裂口放在火焰上烧熔后,尖端变钝,是表面张力的作用,玻璃表面分子间作用力表现为引力使表面收缩,B 错误;热力学是对大量分子统计的结果,对单个分子没有意义,C 错误;浸润与不浸润均是分子力作用的表现,D 正确;分子间作用力表现为斥力时,随分子间距离增大,分子力做正功,分子势能减小,E 正确.(2)①气体发生等压变化,气体对外界做的功W =Fx =p 0S (L -L 0)=400 J气体的状态参量:T 0=300 K ,V 0=L 0S ,V 1=LS气体升温时发生等压变化,由盖-吕萨克定律有V 0T 0=V 1T 1代入数据解得T 1=450 K.②气体的状态参量:p 1=p 0=1.0×105 Pa ,T 1=450 K ,T 2=600 K从活塞到销钉处时继续升温,气体发生等容变化,由查理定律有p 1T 1=p 2T 2解得p 2≈1.33×105 Pa.答案:(1)ADE (2)见解析34.解析:(1)两列波叠加,t =0时刻x =0处质点的振动位移为两列波振幅之和,为40 cm ,A 错误;根据波形图,A 波的波长为3 m ,B 波的波长为5 m ,两列波在同一介质中传播,波速相同,由λ=v f可知两列波的频率之比为f A ∶f B =λB ∶λA =5∶3,B 正确;由于质点的振动位移等于同一时刻同一质点分别在两列波中振动位移的和,所以t =0时刻一定存在振动位移为-30 cm 的质点,C 正确;两列波波长最简整数比为3∶5,3和5的最小公倍数是15,所以t =0时刻x 轴正半轴到原点最近的另一波峰重合处的横坐标为x =5λA =15 m ,D 错误;t =0时刻x 轴正半轴到原点最近的波谷重合处的横坐标为x =7.5 m ,E 正确. (2)①连接圆心O 与角α的顶点,交球面于C 点,连接AC 、CB ,ACB 即为光线的路径,如图所示.②由几何关系及对称性有r =α2+(i -r ),解得r =30° 由折射定律有n =sin i sin r = 2 AC =BC =2R cos r =3R光在透明球中的传播路程L =23R传播速度v =c n =2c 2传播时间t =L v =26R c. 答案:(1)BCE (2)见解析。
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第一部分(共20小题,每小题1.5分,满分30分)1.Bob was trying to ________ that he knew the famous singer who would perform in our city.A.let out B.lay outC.figure out D.make out2._____ at the differences between her culture and theirs, Annie wanted to return home.A.Confusing B.ConfusedC.Having confused D.To confuse3.–What’s that noise?–Oh, I forgot to tell you. The new machine ______.A.was tested B.will be testedC.is being tested D.has been tested4.The famous player tried again and again after each failure. That’s _____ he succeeded at last.A.what B.whenC.whether D.why5.Hard work,along with dedicated revolutionary spirit is the fundamental guarantee of success,which is ________ we should learn from the pioneers participating in the Long March.A.that B.whatC.where D.how6.One hundred and fifteen Chinese companies hit the newly released Fortune 500 list for 2017, ______ an increase for the 14th straight year, domestic website reported on Thursday.A.to realize B.realizedC.realizing D.having realized7.I wish I ______ at my sister’s wedding last Tuesday, but I was on a business trip in New York then. A.will be B.would beC.have been D.had been8.---We want someone to design the new art museum for me.---_____ the young fellow have a try?A.Shall B.May C.Will D.Need9.﹣Mom,I'll stay in to accompany my grandpa this evening.﹣________!A.With pleasure B.Never mindC.Suit yourself D.It depends10.It seems late to say anything. We probably ______ it if we had made an offer sooner.A.would have got B.would getC.had got D.got11.I wanted to major in English at first, but later I ________ my mind and now I am a writer. A.changed B.have changedC.would change D.will change12.— Do you have any problems if you ______ this job?—Well, I’m thinking about the salary….A.offer B.will offer C.are offered D.will be offered13.Scientists have introduced a new model of 3D printer, ______ differs from the existing ones in certain aspects.A.as B.which C.who D.that14.I will be surprised if you can get Calvin, who is a close-fisted man, these donation draw tickets from you.A.buy B.buyingC.buys D.to buy15.___________the effect of culture shock, he is trying to read a lot about it before going to France for further study.A.To reduce B.ReducedC.Reducing D.Having reduced16.Top graduates from universities are ________ by major companies.A.chased B.registeredC.offered D.compromised17._____ here, come and have a cup of tea.A.Passing B.To pass C.Pass D.Having passed18.It is obvious that John is unhappy. _________, it comes as no surprise that she has decided to change her job.A.However B.Otherwise C.Moreover D.Therefore19.He ______ a chance to try it again just now.A.gave B.will give C.is given D.was given20.Mary felt from the outside world, since she lacked an Internet connection and couldn’t receive any e-mail.A.cut down B.cut in C.cut off D.cut out第二部分阅读理解(满分40分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳选项。
21.(6分)An image is worth a thousand kilos? Okay, so maybe not a thousand kilos, exactly, but a study shows how a photo diary can keep dieters motivated, making them more likely to achieve their target weight.Elias Kuzmar Daza, a medical professional from Colombia, studied the motivation levels of patients on weight loss programs at a nutrition clinic.Different measurements were taken of the patients each week, including body mass index (指标) food and exercise diaries, etc. to record their progress. In addition, full-body photographs were taken each week, which proved to be very motivating and a key factor in patients completing the full program.Over the course of the sixteen-week program, a full ninety percent of patients, aged between 16 and 72, saw the treatment through to the end, with seventy percent successfully meeting their weight loss aims. Among those monitored, one measurement proved particularly motivating: waistline.This finding indicates that the majority of the patients who attended the clinic did so motivated by image, rather than any underlying condition. It should be pointed out that eighty percent of them were female.Another useful finding of this study was that patients did not necessarily need to attend the clinic in person for the program to be effective. A support line was set up, which patients could call to submit their measurements. They also took and sent their own full-body photographs to the researcher. Fifty percent of patients completed the program in this way.Summarizing the findings, Kuzmar says: “What patients want is a photo, rather than cold numbers.” These photos serve as visual confirmation that all their hard work is paying off, encouraging them on to further weight loss.1、What is the purpose of the study?A.To show losing weight is very easy.B.To compare several ways to lose weight.C.To prove the effect of images in weight losing.D.To see how many people can lose weight successfully.2、How many patients in the clinic reached their weight-loss goals?A.50%. B.70%.C.80%. D.90%.3、What can give people most motivation when they are trying to lose weight?A.Fri ends’ encouragement. B.Others’ strong muscles.C.Their slimmer waistline. D.Their standard blood pressure.4、What must the patients do to complete the weight-loss program?A.Go to the clinic every week.B.Call to submit their measurements.C.Report to the professional every day.D.Take full-body photographs each week.22.(8分)Living in a culture that is different from your own can be both an exciting and challenging experience. The following are 6 cultural differences between China and the USA to help promoting mutual understanding.MoneyAs is well known, the Chinese are conservative when they are planning to spend money, but far fewer American families are saving money for emergencies and education than their Chinese counterparts (对等的人)..PrivacyChinese people do not have the same concept of privacy as American do. They talk about topic such as ages, income or marital (婚姻的) status, which Americans think is annoying and disturbing.FamilyIn China, elders are traditionally treated with great respect while young are cared for. In America, the goal of the family is to encourage independence, particularly that of the children. Unlike the Chinese, older Americans seldom live with their children.FriendsChinese people have different meanings to define friends. Just hanging out together time to time is not friendship. Friendship means lifelong friends who feel it deeply necessary to give each other whatever help might seem required. Americans always call people they meet friends, so the definition of friends is general and different. There are work friends, playing friends, school friends and drinking friends.EducationChinese people value education and career more than Americans, who in turn attach more great importance to good character and faith, which they think are of great value in their life.________Basically China values the community and the USA values the individual. If you achieve something in the USA, it’s because you are great. While in China, if you achieve something, it’s because the team, or family, or company is great. Everything you do gets owed to the greater whole, while in American individual achievements are celebrated.1、What can be inferred from the passage?A.Americans lay more stress on faith and good personality.B.Americans think much of the individual and the community.C.Americans are mean with money to spend while Chinese are not.D.Americans define friendship almost the same.2、Which of the following can best describe the last difference?A.Achievements B.IndividualC.Team VS Individual D.Teamwork3、What is the purpose of writing the passage?A.To promote friendship between China and the USA.B.To help Chinese live well in the USA.C.To have a complete understanding of the USA.D.To introduce the cultural differences between China and the USA23.(8分)After two years of careful consideration, Robert McCrum has reached a conclusion on his selection of the 100 greatest novels written in English. Take a look at a few in his list:The Pilgrim’s Progress by John Banyan (1678)A sto ry of a man in search of truth told with the simple clarity and beauty of Bunyan’s prose makes this an English classic.Robinson Crusoe by Daniel Defoe (1719)By the end of the 19th century, no book in English literary history had enjoyed more editions and translations. This world-famous novel is a complex literature that one cannot resist.Gulliver’s Travels by Jonathan Swift (1726)A great work that’s been repeatedly printed, Jonathan Swift’s Gulliver’s Travels comes third in our list of the best novels written in English.Clarissa by Samuel Richardson (1748)Clarissa is a tragic heroine, pressured by her dishonorable family to marry a wealthy man she dislikes, in the book that Samuel Johnson described as “the first book in the world that shows the knowled ge about the human heart”.Tom Jones by Henry Fielding (1749)Tom Jones is a classic English novel that gets the spirit of its age and whose characters are well-known since they have come to represent the society at that time.Emma by Jane Austen (1816)Ja ne Austen’s Emma is her most outstanding work, mixing the best parts of her early books with a deep sense of feelings.The Narrative of Arthur Gordon Pym of Nantucket by Edgar Allan Poe (1838)Edgar Allan Poe’s only novel—a classic adventure story with supernatural elements—has fascinated and influenced generations of writers.1、Which English book has got the most translations before the 20th century?A.Robinson Crusoe. B.Gulliver’s Travels.C.Tom Jones. D.Emma.2、What does Samuel Johnson think we can learn about from the book Clarissa?A.A love story. B.Quarrels in a family.C.The human heart. D.The spirits of the lime.3、What makes the characters in Tom Jones famous?A.Their classic lifestyles.B.Their different nationalities.C.Their typical spirits of the age.D.Their representation of the society.24.(8分)Life doe sn’t always turn out the way we’d like. When situations take an unfavorable turn, we become upset, frustrated, or angry. When others don’t agree with us, or act in a manner we find disturbing, anger is a typical response. With the exception of a few extreme circumstances» an angry reaction rarely improves the situation or helps us change our mind. Thoughtful consideration of what feelings and reaction are most helpful actually restores our real power, so consider the following alternatives to anger.Compassion, consisting of both understanding and empathy, can be a perfect solution to anger. Each person has a right to live life according to their beliefs, dreams, needs, etc. If someone is acting improperlyor not living up to our ideals, we need to remove th e “shoulds” and remind ourselves that it is a necessary part of their life’s journey. Choosing this alternative response softens one’s heart and prevents anger from arising.Humor is another powerful tool for lessening anger. We take life and personal offense far too seriously. After all, their behavior is a reflection of their internal environment and has nothing at all to do with us and it is in reality relatively unimportant. Humor puts any serious situation into its proper places. It acts as a protective barrier to emotional pain as we recognize that what is happening has nothing at all to do with us.So when others behave badly, forgive them for their bad behaviors rather than judge them in your heart. When life hands us the exact opposite of what we requested, make light of it, After all, this life is only temporary so why get so bent out of shape when it isn’t in line with your ideals? Rain on your wedding day? Break oat the umbrellas and boots and dance in the puddles!1、What can we infer from the first paragraph?A.Anger makes a person more powerful.B.All the people get annoyed easily.C.Anger often does no good to the situation.D.Anger can do something good in most cases.2、How should we respond to others’ misbehavior according to the second paragr aph?A.Criticize it sharply. B.Complain about it.C.Leave it as it is. D.Understand and accept it.3、What does the underlined phrase mean in the last paragraph?A.Dull. B.Angry.C.Delighted. D.Gifted.4、What’s the best title of the passage?A.Alternative Responses to Anger.B.The Bad Effects of Anger.C.The Causes of Frequent Anger.D.The Risk of Getting Angry.25.(10分)Academic learning is usually in the spotlight at school, but teaching elementary-age students “soft” skills like self-control and how to get along with others might help to keep at-risk kids out of criminal trouble in the future.Once a program called Fast Track was started in the early 1990s for more than 7,600 children of 55 schools in America. They were identified by their teachers and parents to be at high risk for developing aggressive behavioral problems. The students were randomly divided into two groups; half took part in the intervention, which included a teacher-led curriculum, parent training groups, academic tutoring and lessons in self-control and social skills. The program, which lasted from first grade through 10th grade, reduced delinquency(少年犯罪), arrests and use of health and mental health services as the students aged through adolescence and young adulthood.In another latest study, by looking at the data from nearly 900 students in previous findings, researchers found that about a third of the influence on future crime outcomes was due to the social and self-regulation skills the students learned from ages 6 to 11.The academic skills, or hard skills like learning of physics, which were taught as part of Fast Track, turned out to have less of an influence on crime and delinquency rates than did the soft skills, which are associated with emotional(情绪的) intelligence. Soft skills might include teaching kids to work cooperatively in a group or teaching them how to think about the long-term consequences when they make a decision.Researchers drew the conclusion that these soft skills should be emphasized even more in oureducation system and in our system of socializing children. Parents should do all they can to promote these skills with their children as should education policymakers. To the extent we can improve those skills, we can improve outcomes in delinquency.1、Fast Track was intended for children who .A.were randomly chosen from their schoolsB.had some problems with academic learningC.often went against their teachers and parents’ wishesD.were considered to have criminal trouble in the future2、What can be learned about "the intervention" in Paragraph 2?A.It included all the students.B.It focused on social skills.C.It improved health services.D.It had positive outcomes.3、Compared with soft skills, hard skills .A.almost have no influence on studentsB.are more affected by students’ emotionC.are mainly related to academic learningD.offer children greater self-control abilities4、Which is the best title for the passage?A.Soft Social Skills MatterB.Fast Track Helps ChildrenC.How to Prevent DelinquencyD.What to DO for Education第三部分语言知识运用(共两节)第一节(每小题1.5分,满分30分)阅读下面短文,从短文后各题所给的A、B、C和D四个选项中,选出可以填入空白处的最佳选项.26.(30分)Our son Jason was born with cerebral palsy(脑瘫). My wife and I often 1 him as he faced many challengers in his early years.It was 2 to see him chosen last for baseball 3 , but he was happy and well 4 by his peers(同龄人)throughout primary school. His most 5 time came when he began high school. One afternoon, he returned home with 6 . He threw his bag on t he floor, shouting angrily, “I’ll never go to school again!” He was 7 with food other kids had thrown at him on the way home. He didn’t tell us what had happened until later.Several days earlier, he had 8 the school running team. That day, a few older students made fun of his 9 on the track and made him the 10 of their one-sided food fight. I called theheadmaster about the matter and it never happened again. He stayed on the team 11 trouble continued.One day in October, We had snow and freezing rain. As the other kids exercised in the gym, they noticed Jason jogging around the snow-covered 12 . A few weeks later, he told us each month students 13 an “athlete of the month”. The coach would list the top athletes, and students voted for the winner. Jason’s 14 had never been listed. But that day, one of the student said, “I’d like to nominate(提名)Jason for the athlete of the month, sir!” The coach looked 15 .“He works harder than any of us, sir,” the student continued.“But we’ll have to have someone 16 the nomination,” the coach replied.Tears formed in Jason’s eyes as he told us what happened next. “Mom, Dad, everyone in the class17 their hands.”We, also in tears, looked at him as he 18 showed his certificate.Whenever I despair, I think of this story. I 19 myself that challengers are not overcome by force, but by patience, 20 and faith.1、A.comforted B.persuaded C.protected D.instructed2、A.boring B.confusing C.heartbreaking D.challenging3、A.purposely B.regularly C.exactly D.eventually4、A.praised B.admired C.respected D.accepted5、A.merciful B.enjoyable C.difficult D.unforgettable6、A.confidence B.sadness C.courage D.fear7、A.covered B.packed C.faced D.supplied8、A.played for B.voted for C.prepared for D.signed up for9、A.promise B.performance C.goal D.ability10、A.target B.cause C.focus D.role11、A.in case B.as if C.ever since D.even though12、A.street B.camp C.track D.field13、A.trained B.found C.dismissed D.chose14、A.name B.progress C.score D.application15、A.satisfied B.surprised C.excited D.disappointed16、A.invite B.seek C.support D.consider17、A.put up B.put back C.put down D.put out18、A.carefully B.firmly C.eagerly D.proudly19、A.warn B.remind C.inform D.teach20、A.honesty B.knowledge C.determination D.development第二节(每小题1.5分,满分15分)阅读下面材料,在空白处填入1个适当的单词或括号内单词的正确形式。