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国外大学的实验报告 formal report

国外大学的实验报告 formal report
国外大学的实验报告 formal report

Formal Laboratory Report

Group: Mechanical Properties of Materials Date of experiment:

Abstract

For this experiment, the mechanical strength properties of metals, ceramics and polymers are tested by obtaining their tensile strength (the maximum strength they have before they fracture), modulus (stiffness during elastic deformation) and the elongation to failure. Their response characteristics are noted.

Based on the response outputs obtained from the Material Stress Vs Behaviour Curve and the test report generated by the software, values of the tensile strength, modulus and elongation are obtained.

The materials’ responses, strength and ductility are investig ated using their structures and microstructures and used to make comparisons with theory.

Table of Content

1) Objectives & Introduction (4)

2) Theory (5)

3) Equipment (7)

4) Procedure (8)

5) Results (17)

6) Solutions to logsheet questions (19)

7) Discussion (21)

8) Conclusion (22)

9) References (23)

Objectives and Introduction

Objectives

(a) To understand the different mechanical properties of materials.

(b) To learn how different materials are tested in different ways to obtain their mechanical strength properties.

This experiment introduces the study of how different types of materials such as metals, polymers and ceramics can have very different mechanical properties: polymer, ceramics and metallic materials. This is very important as it helps the engineer to correctly choose the right type of material for the right application.

Metals, ceramics and polymers are basically the three broad categories of materials used in engineering application. It is generally known that metals are usually strong and ductile, ceramics are rigid and brittle and polymers have higher elongation and lower strength.

This experiment aims to expose the number of factors can affect the mechanical strengths of materials. These factors include:

? the category of the material (i.e metal, ceramic or polymer)

? the type of material in that category (eg. crosslinked or thermplastics)

? the difference in micros tructure of the same material (crystalline or amorphous)

Theory

Terminology

(i) Tensile Stress

Force acting on unit area of the material

Tensile Stress σ =

A

F

(ii) Tensile Strain

Deformation or distortion experienced by a unit of the material

Tensile Strain ε =

l l

?

(iii) Modulus of Elasticity

The ratio of stress to corresponding strain when the material behaves elastically.

Tensile Modulus E =

ε

σ

where σ is the engineering stress

F is the applied force

ε is the nominal or engineering str ain

l is the length of the material

(iv) Tensile Toughness

The ability of a material to absorb energy up to fracture, i.e. the resistance to fracture. Specimen

Metals

Metals are described as a lattice of positive ions surrounded by a cloud of delocalized electrons.

Metals are tested using circular cylindrical machined specimen with a dumb bell shape which are gripped on either ends. The thinned out middle section is called the gauge length. Such a specimen can easily be gripped and the failure will be restricted to within the gauge length as this is where the cross section area is the smallest, so that the stress is largest.

Polymers

A polymer is a macromolecule composed of repeating structural units connected by covalent chemical bonds.

Polymers are not tested using such a circular shape. This is because polymers are not usually machined, but is produced in sheet or flattened shapes. Thus they are tested by

using a flattened profile, usually with a larger gauge length than for metals. Again, the specimen has a dumb bell shape so that the cross section area with the gauge length is significantly smaller and thus the failure is restricted to within this length.

Ceramics

Ceramic are inorganic non-metallic materials which are formed by the action of heat. Ceramics such as glass are very hard, thus making machining very difficult. The dumb bell shape is not possible for these materials. Also they are very brittle and thus cannot be gripped without either breaking them or causing defects to lower their strengths. As such, a three point bending test is usually done, since the specimen required can be very flat and need not been shaped by machining.

Equipment

The equipment used for testing the mechanical strength properties for the different materials is the Instron Universal Electro-mechanical Tester Series 5560(Figure 1).

Figure 1

The 5560 Series Table Model Systems are ideal for tests requiring less than 50 kN force and where better alignment or a larger test space are required. The twin column design provides better alignment and increased stiffness as compared with single column systems. These systems can be fitted with a wide range of grips and fixtures for tension, compression, bending and component testing. Additional accessories include extensometers for strain measurement and environmental chambers for high or low temperature tests.

Features:

? 250:1 force measurement range (i.e. use the load cell to down to 0.4% of full capacity with no loss of accuracy)

? Load accuracy of +/-0.5% of indicated load

? 500 Hz synchronous data acquisition rate for all channels

? Hardware control panel for operator convenience

? Automatic transducer recognition for load cells and extensometers

?Bluehill? 2 software compatibility

? Extra height and width options available

? Second test space option

? Library of ASTM and ISO test methods

?Full CE compliance

Procedure

Procedure for Metal Tensile Testing

Procedure for Polymer Tensile Testing

Procedure for Ceramics Flexure Testing

Results

Solutions to logsheet questions

1) What is the basic microstructure of

Metals: Combination of metallic elements, where there are positive metallic ions and free electrons forming crystalline structure.

Polymers: Most are organic compounds with long chain structure.

Ceramics: Compounds of metallic and non-metallic element that has amorphous

structure.

2) How does the microstructure determine the strength and ductility of,

Metals: Metals has high strength as it has a closely packed crystalline structure and

the positive ions and electrons in metals have strong electrostatic forces

between them. A large amount of energy is required to overcome the strong attractive forces.

Metals have high ductility due to the ability of the atom layers to roll over each

other into a new position without breaking the metallic bond.

Polymers: Polymers have low strength and high ductility due to their weak secondary van der waals’ f orces and hence low amount of energy is required to break the bonds. Polymers also have long molecular chains can move around easily

and there is no orderly structure. The random coils and molecular entanglements are responsible for the ductility of polymers.

Ceramics: Ceramics have high strength and low ductility. Ceramic has amorphous

structure where atoms are rigidly held giving it a strong bond. Due to its

amorphous structure, ceramic is brittle and easily broken giving it a low

ductility.

3) Why are steels stronger than aluminium alloys?

Steels have higher carbon content than aluminium alloys. Caron atoms form strong

covalent bonds to each other while holding the atoms of other non-metals strongly. In addition, carbon and other elements in steel prevent dislocations in the iron atom

crystal lattice from sliding past one another since it has a BCC structure compared to aluminium FCC structure. Therefore, steels are stronger than aluminium alloys.

4) Is PS or PE stronger? Why?

PS is stronger. PE has weak van der waals’ forces be tween the long-chained structure compared to PS which has a large benzene ring which causes a reduction in the chain mobility and thus an increase in rigidity. Therefore, PS is stronger than PE.

5) Comment on the testing technique of glass and calculate its Modulus of Elasticity.

A three-point bending test is done. It is to test on the strength of the glass. As glass is very brittle, they cannot be gripped without either breaking them or causing defects to lower their strengths.

Modulus of Elasticity =

3

21 . 67

07

.

67

14

.

70+

+

= 68.14 GPa

6) What materials would you choose for the bumper of your passenger car? What are the criteria that you must consider?

I would choose steel for the bumper of a passenger car. Toughness is the most

important criteria. Metals (steel) have high toughness compared to ceramics and

polymers which have low toughness. A bumper of a passenger car has to withstand large force and energy from accidents. Moreover, steels are also stronger than

aluminium alloys.

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入团申请书内容写法

入团申请书内容写法 入团申请书内容写法 。 正文要从接受的申请书的团组织名称下一行空两格处写起。 申请书的正文部分一般篇幅较长,所以要注意分段。下面我们将详细地分析入团申请书的具体写法 1.介绍个人的现实情况 对个人现实情况的介绍,是为了让团组织对自己现在的身份、情况有一个初步和大致的了解,不用展开来写,简明扼要即可。 个人简历和家庭成员及社会关系的情况 这一部分的内容也要简单,无须多用笔墨,但也必须清楚明白。对个人简历的写法,一般要求从上学时写起,到目前为止,只需依据时间的顺序,一项项地排列出来即可。主要家庭成员及社会关系的情况,在申请书正文中可以简单地介绍一下,也可以不写,要视具体情况而定。有的家庭成员及主要社会关系可附在申请书后。 3.入团动机和理由 入团的动机、理由要重点写。申请的理由比较多,则可以从几个方面、几个阶段来写。 4.对团的认识和决心 对团的认识往往是同个人的成长经历有关的,这在申述自己的入团动机时已有所涉及。这里指的是专门较集中的对团认识的文字。 自己的心情、决心这一部分是抒写自己入团的强烈愿望,表达自己的决心的部分。

结尾和落款 申请书可以有结尾,也可以没有。结尾一般写上恳请团组织批准我的申请和 此致 敬礼!之类表示敬意的话即可。 此致另起一行空两格写,敬礼!再另起一行顶格写。 落款,要署上申请人姓名和成文日期,均写在右下角,注意排列整齐。 附送: 入团申请书初中1200字 入团申请书初中1200字 入团申请书初中1200字篇一 尊敬的团组织: 我志愿加入中国共产主义青年团。 我是xx中学初二1班的xxx,身兼语文课代表、学习委员以及值日班长这些职务。在道德上,我具有文明素质,积极进取,乐观向上,作风端正;在学习上时常与同学一起研讨深究问题,面对难题勇往直前,屡次获得优异的成绩;作为班委,我也毫不懈怠得帮助班长管理班级,检查同学们的仪容仪表,维护班级的名誉,在我和其他值日班长一丝不苟地检查下,我们班级常常获得了分纪评比的高分,亦获得了年段的许。在班级上我与同学友好相处,共同进步,为自己的目标努力奋斗。

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