Ch10_Testbank
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第10章密钥管理Distribution of Public Keys•can be considered as using one of:–public announcement–publicly available directory–public-key authority–public-key certificatesPublicly Available Directory •can obtain greater security by registering keys with a public directory•directory must be trusted with properties:–contains {contains {name,public name,public name,public-key} entries-key} entries –participants register securely with directory –participants can replace key at any time –directory is periodically published–directory can be accessed electronically •still vulnerable to tampering or forgeryPublic-Key Authority •improve security by tightening control over distribution of keys from directory•has properties of directory•and requires users to know public key for the directory•then users interact with directory to obtain any desired public key securely–does require real-time access to directory when keys are neededPublic-Key AuthorityPublic-Key Certificates •certificates allow key exchange withoutpublic-key authority real-time access toreal-time access to public-key authority •a certificate binds identity to public key –usually with other info such as period ofvalidity, rights of use etc•with all contents signed by a trusted Public-Key or Certificate Authority (CA)•can be verified by anyone who knows the public-key authorities public-keyPublic-Key CertificatesPublic-Key Distribution of SecretKeys•use previous methods to obtain public-can use for secrecy or authentication key, , can use for•but public-key algorithms are slow•so usually want to use private-key encryption to protect message contents, , encryption to protect message contents hence need a session key•have several alternatives for negotiating a suitable sessionSimple Secret Key Distribution•proposed by Merkle in 1979–A generates a new temporary public key pair –A sends B the public key and their identity–B generates a session key K sends it to Aencrypted using the supplied public key–A decrypts the session key and both use •problem is that an opponent can intercept and impersonate both halves of protocolPublic-Key Distribution of SecretKeys•if have securely exchanged public-keys:Hybrid Key Distribution•retain use of private-key KDC–shares secret master key with each user–distributes session key using master key–public-key used to distribute master keys •especially useful with widely distributed users •rationale–performance–backward compatibilityDiffie-Hellman Key Exchange •first public-key type scheme proposed by Diffie & Hellman in 1976 along with the exposition of public key concepts–note: now know that Williamson (UK CESG)secretly proposed the concept in 1970•is a practical method for public exchange of a secret key–used in a number of commercial productsDiffie-Hellman Setup•all users agree on global parameters:–large prime integer or polynomial q–a being a primitive root mod q. A) generates their key •each user (each user (eg eg eg. A) generates their key –chooses a secret key (number): x A < q–compute their public key: y A = a x A mod q •each user makes public that key y ADiffie-Hellman Key Exchange •shared session key for users A & B is K AB: K AB = a x A.x B mod q= y A x B mod q (which B can compute)= y B x A mod q (which A can compute)•K AB is used as session key in private-key encryption scheme between Alice and Bob –if Alice and Bob subsequently communicate, they will have the same key as before, unless theychoose new public-keys•attacker needs an x, must solve discrete logDiffie-Hellman Example•users Alice & Bob who wish to swap keys:–agree on prime q=353 and a=3–select random secret keys:•A chooses x A=97, B chooses x B=233–compute respective public keys:•y A=397 mod 353 = 40(Alice)•y B=3233 mod 353 = 248(Bob)–compute shared session key as:•K AB= = y y B x A mod 353 =24897 = 160(Alice)mod 353 = 248•K AB= = y y A x B mod 353 =mod 353 = 4040233 = 160(Bob)Key Exchange Protocols •users could create random private/public D-H keys each time they communicate •users could create a known private/public D-H key and publish in a directory, then consulted and used to securely communicate with them•both of these are vulnerable to a meet-in-the-Middle Attack•authentication of the keys is neededSummary•have considered:–distribution of public keys–public-key distribution of secret keys -Hellman key exchangeDiffie-Hellman key exchange–Diffie。
自然拼读的字母组合和常见规则详解(附精美图片和练习)1.辅音字母1:2.辅音字母2:3.元音字母发短音1: a, e, i4.元音字母发短语2: o, u5.元音字母发长音1-a辅e, e辅e6.元音字母发长音2- i辅e,7.元音字母发长音3-o辅e8.元音字母发长音4-u辅e9.元音字母发长音5两元相遇110.元音字母发长音6两元相遇211.元音字母发长音7单元结尾112.辅音字母c13.辅音字母g14.辅音字母y15.辅音组合L系列16.辅音组合R系列17.辅音字母S系列18.辅音字母H系列19.辅音字母G系列20.辅音字母哑音系列c 字母c 后面接a ,o ,u 的时候,c 的发音与字母k 发音相同,叫做“hard c sound”cat, cap, call, coat, cup当字母c 后面接e ,i ,或y 的时候,通常c 的发音与字母s 发音相同,叫做“soft c sound” city, ice, rice, face, cell, cent, voice, pencil, juice有时在e 或i 前面,c 会发/sh/音 ocean, racial, socialg字母g后面接a,o,u的时候,所发的音叫做“hard g sound” girl, gas, get, give, go当字母g后面接e,i,或y的时候,有时g的发音与字母j的发音相同,叫做“软g音” age, change, ginger, Egypt, gentle, giraffe, badge特例:forget, give, girl中的g发hard soundy y在单词起始位置时发音为辅音yes, you, yard, year, yelly在单词或音节中间或结尾时被当做元音y在结尾,单词只有一个音节时y发长/i/音,y在结尾,单词有两个或以上音节时y发长/e/音y在单词或音节中间时,发短/i/音小测试:my, cry, fly, sky辅音字母组合辅音字母组合的发音很简单,就是把每个辅音字母的发音连在一起就可以了。
CHAPTER 11 AND 14 LIABILITIESTrue/False Questions:1.A liability is a probable future payment of assets or services that a company is presently obligatedto make as a result of past transactions or events.Answer: True2.A single liability can be divided between current and noncurrent liabilities.Answer: True3. 6.A liability does not exist if there is any uncertainty about whom to pay, when to pay, or how much topay.Answer: False4.Trade accounts payable are amounts owed to suppliers for products or services purchased on credit.Answer: True5.Unearned revenues is another name for sales.Answer: False6.Sales taxes payable is credited and cash is debited when companies send sales taxes collected fromcustomers to the government.Answer: False7.Known liabilities are obligations set by agreements, contracts, or laws, and are measurable and definitely determinable.Answer: True8.A contingent liability is a potential obligation that depends on a future event arising from a futuretransaction or event.Answer: False9.The full disclosure principle requires the reporting of contingent liabilities that are reasonably possible.Answer: True10.Debt guarantees are not disclosed because the guarantor is not the primary debtor.Answer: False11.Accounting for contingent liabilities covers three categories. (1) The future event is probable and theamount cannot be reasonably estimated. (2) The future event is remote or unlikely to recur.(3) The likelihood of the liability to occur is impossible.Answer: False12.A high value for the times interest earned ratio means that a company is a higher risk borrower.Answer: False13.The times interest earned ratio is calculated by dividing income before interest expense and incometaxes by interest expense.Answer: True14.When the times interest earned ratio declines, the likelihood of default on liabilities increases.Answer: True15.A short-term note payable is a written promise to pay a specified amount on a definite future datewithin one year or the operating cycle, whichever is longer.Answer: True16. A Premium on Bonds Payable reduces the interest expense of the bond over its life.Answer: True17、A bond listed at 103 on a stock exchange is selling at 103% of its par value.Answer: True18.Callable bonds can be exchanged for a fixed number of shares of the issuing corporation's commonstock.Answer: False19.There are two common payment patterns for installment notes: (1) accrued interest plus equal principalpayments and (2) equal payments.Answer: True20、The carrying value of a long-term note is computed as the present value of all remaining futurepayments, discounted using the market rate at the time of issuance.Answer: True21、A basic present value concept is that cash received in the future is worth more value than the sameamount of cash received today.Answer: False22.An annuity is a series of equal payments at equal time intervals.Answer: True23.The present value of an annuity factor for 6 years at 10% is 4.3553. This implies that an annuity of six$2,000 payments at 10% would equal $8,711.Answer: TrueCalculation: $2,000 x 4.3553 = $8,71124、Both interest on bonds and dividends on stock are tax deductible.Answer: False25、Interest payments on bonds are determined by multiplying the par value of the bond by the stated contract rate.Answer: True26、.Return on equity increases when the expected rate of return from the acquired assets is higher than theinterest rate on the debt issued to finance the acquired assets.Answer: True27.Bond interest paid by a corporation is an expense, whereas dividends paid are not an expense of thecorporation.Answer: True28、The debt-to-equity ratio enables financial statement users to assess the risk of a company’s financingstructure.Answer: True29、A company’s debt-to-equity ratio was 1.0 at the end of Year 1. By the end of Year 2, it had increasedto 1.7. Since the ratio increased from Year 1 to Year 2, the degree of risk in the firm’sfinancing structure decreased during Year 2.Answer: False30、The carrying (book) value of a bond payable is the par value of the bonds plus the discount.Answer: FalseMultiple Choice:1、The characteristics of a liability include:A) A past transaction or event.B) A present obligation.C) A future payment of assets or services.D) Both (a) and (b).E) All of the above.Answer: E2. Obligations not expected to be paid within the longer of one year or the company's operating cycleare reported as:A)Current assets.B) Current liabilities.C) Long-term liabilities.D) Operating cycle liabilities.E) Bills.Answer: C3.Amounts received in advance from customers for future products or services:A)Are revenues.B) Increase income.C) Are liabilities.D) Are not allowed under GAAP.E) Require an outlay of cash in the future.Answer: C4.Contingent liabilities must be recorded if:A)The future event is probable and the amount owed can be reasonably estimated.B) The future event is remote.C) The future event is reasonably possible.D) The amount owed cannot be reasonably estimated.E) All of the above.Answer: A5.Debt guarantees:A)Are never disclosed in the financial statements.B) Are considered to be a contingent liability.C) Are a bad business practice.D) Are recorded as a liability even though it is highly unlikely that the original debtor will default.E) All of the above.Answer: B6.The times interest earned ratio reflects:A) A company's ability to pay its operating expenses on time.B) A company's ability to pay interest even if sales decline.C) A company's profitability.D) The relation between income and debt.E) The relation between assets and liabilities.Answer: B7.If the times interest ratio:A)Increases, then risk increases.B) Increases, then risk decreases.C) Is greater than 1.5, then the company is in default.D) Is less than 1.5, the company is carrying too little debt.E) Is greater than 1.5, the company is likely carrying too much debt.Answer: B8. The times interest earned computation is:A)(Net income + Interest expense + Income taxes)/Interest expense.B) (Net income + Interest expense - Income taxes)/Interest expense.C) (Net income - Interest expense - Income taxes)/Interest expense.D) (Net income - Interest expense + Income taxes)/Interest expense.E) Interest expense/(Net income + Interest expense + Income taxes expense).Answer: A9. Short-term notes payable:A)Can replace an account payable.B) Can be issued in return for money borrowed from a bank.C) Are negotiable.D) Are an unconditional promise to pay.E) All of the above.Answer: E10. On December 1, Martin Company signed a $5,000 3-month 6% note payable, with the principleplus interest due on March 1 of the following year. What amount of interest expense is accrued at December 31 on the note?A)$0B) $25C) $50D) $75E) $300Answer: B$5,000 x 0.06 x 1/12 = $2511. On November 1, Carter Company signed a $9,000 4-month 10% note payable, with the principle plusinterest due on March 1 of the following year. What is the adjusting entry for the accrued interest at December 31 on the note?A)Debit interest expense, $0; credit interest payable, $0.B)Debit interest expense, $100; credit interest payable, $100.C)Debit interest expense, $150; credit interest payable, $150.D)Debit interest expense, $200; credit interest payable, $200.E)Debit interest expense, $300; credit interest payable, $300.Answer: CCalculation: $9,000 x .10 x 2/12 = $15012. The employer should record payroll deductions as:A)Employee receivables.B) Payroll taxes.C) Current liabilities.D) Wages payable.E) Employee payables.Answer: C13.An estimated liability:A)Is an unknown liability of a certain amount.B) Is a known obligation of an uncertain amount that can be reasonably estimated.C) Is a liability that may occur if a future event occurs.D) Can be the result of a lawsuit.E) Is not recorded until the amount is known for certain.Answer: B14. Employee vacation benefits:A)Are estimated liabilities.B) Are contingent liabilities.C) Are recorded as an expense when the employee takes a vacation.D) Are recorded as an expense when the employee retires.E) Increase net income.Answer: A15.Bonds that have an option exercisable by the issuer to retire them at a stated dollar amount prior tomaturity are known as:A) Convertible bonds.B) Sinking fund bonds.C) Callable bonds.D) Serial bonds.E) Junk bonds.Answer: C16、A bond traded at 102½ means that:A) The bond pays 2.5% interest.B) The bond traded at $1,025 per $1,000 bond.C) The market rate of interest is 2.5%.D) The bonds were retired at $1,025 each.E) The market rate of interest is 2 ½ % above the contract rate.Answer: B17、Promissory notes that require the issuer to make a series of payments consisting of both interest andprincipal are:A) Debentures.B) Discounted notes.C) Installment notes.D) Indentures.E) Investment notes.Answer: C18、An advantage of bond financing is:A) Bonds do not affect owners' control.B) Interest on bonds is tax deductible.C) Bonds can increase return on equity.D) It allows firms to trade on the equity.E) All of the above.Answer: E19、Which of the following statements is true?A) Interest on bonds is tax deductible.B) Interest on bonds is not tax deductible.C) Dividends to stockholders are tax deductible.D) Bonds do not have to be repaid.E) Bonds always decrease return on equity.Answer: A20、A disadvantage of bonds is:A) Bonds require payment of periodic interest.B) Bonds require payment of principal.C) Bonds can decrease return on equity.D) Bond payments can be burdensome when income and cash flow are low.E) All of the above.Answer: E21、The debt-to-equity ratio:A) Is calculated by dividing book value of secured liabilities by book value of pledged assets.B) Is a means of assessing the risk of a company’s financing structure.C) Is not relevant to secured creditors.D) Can always be calculated from information provided in a company’s income statement.E) Must be calculated from the market values of assets and liabilities.Answer: B22、When a bond sells at a premium:A) The contract rate is above the market rate.B) The contract rate is equal to the market rate.C) The contract rate is below the market rate.D) It means that the bond is a zero coupon bond.E) The bond pays no interest.Answer: A23、Amortizing a bond discount:A) Allocates a part of the total discount to each interest period.B) Increases the market value of the Bonds Payable.C) Decreases the Bonds Payable account.D) Decreases interest expense each period.E) Increases cash flows from the bond.Answer: A24、The effective interest amortization method:A) Allocates bond interest expense using a changing interest rate.B) Allocates bond interest expense using a constant interest rate.C) Allocates a decreasing amount of interest over the life of a discounted bond.D) Allocates bond interest expense using the current market rate for each period.E) Is not allowed by the FASB.Answer: B25、The Premium on Bonds Payable account is a(n):A) Revenue account.B) Adjunct or accretion liability account.C) Contra revenue account.D) Asset account.E) Contra expense account.Answer: B26、A company received cash proceeds of $206,948 on a bond issue with a par value of $200,000. Thedifference between par value and issue price for this bond is recorded as a:A) Credit to Interest Income.B) Credit to Premium on Bonds Payable.C) Credit to Discount on Bonds Payable.D) Debit to Premium on Bonds Payable.E) Debit to Discount on Bonds Payable.Answer: B27、A company may retire bonds by:A) Exercising a call option.B) The holders converting them to stock.C) Purchasing the bonds on the open market.D) Paying them off at maturity.E) All of the above.Answer: E28、The contract rate of interest is also called the:A) Coupon rate.B) Stated rate.C) Nominal rate.D) Market rate.E) Each of A, B, and C.Answer: E29、The Discount on Bonds Payable account is:A) A liability.B) A contra liability.C) An expense.D) A contra expense.E) A contra equity.Answer: B30、The Premium on Bonds Payable account is a(n):A) Revenue account.B) Adjunct or accretion liability account.C) Contra revenue account.D) Asset account.E) Contra expense account. Answer: B。
银行系统招聘考试英语(中国农业银行)模拟试卷10(题后含答案及解析)题型有:1. 词汇与语法结构 3. 阅读理解词汇与语法结构1.The hotel management trains all its staff members to deal with guest inquires_________.A.courtesyB.courteousC.courteouslyD.more courteous正确答案:C解析:这里应该选择副词用来修饰动词deal with,只有C符合。
2.The ski season is_________over,so many people will head up to the mountains this weekend for one last time.A.graduallyB.nearlyC.severelyD.formerly正确答案:B解析:A指的是“不断地”,B指的是“接近”,C指的是“严重地”,D指的是“以前,原来”。
根据题意,很容易得知应该选择B项。
3.The attorney’_________to the shipping company is to sue the port authorities for causing a loss of profit.A.judgmentB.recommendationC.activityD.progression正确答案:B解析:A指的是“判断,辨别力”,B指的是“建议”,C指的是“行动,活动”,D指的是“前进,连续”。
这里应该是指律师给船运公司的建议,所以选B。
4.Mr.Lyall_________to the waiter at Merci Beaucoup that his steak had been overcooked.A.congratulatedB.complainedC.resistedD.demanded正确答案:B解析:A指的是“恭喜”,B指的是“抱怨”,C指的是“坚持”,D指的是“要求”。
国际结算实验-信用证实验参考答案实验4. 信用证结算业务4.2.1实验目标1、开证申请书填写完整、准确性的审核。
2、根据开证申请书正确缮制信用证。
3、掌握信用证的审证要求。
4、信用证通知、保兑的处理。
5、信用证修改的处理流程。
6、信用证中议付、寄单索偿的处理。
7、跟单信用证处理流程。
8、掌握UCP500对信用证业务处理中的规定。
4.2.2 实验要求1、开证行审核开证申请书。
2、开证行缮制全电证、简电证、SWIFT 格式下信用证。
3、通知行审核信用证、通知信用证。
4、开证行、通知行处理信用证的修改。
5、出口地银行议付、付款的处理。
6、寄单行寄单索偿的处理。
7、开证行通知进口商单到付款的处理。
4.2.3 实验素材一、开证申请书2003年5月10日,CHINA IMP. & EXP. CORP. GUANGDONG向中国银行广东省分行提交下面这张开证申请书申请开证,开证行按所给问题审核开证申请书。
APPLICATION FOR IRREVOCABLEDOCUMENTARY CREDIT致:中国银行广东省分行TO: BANK OF CHINA, GUANGDONG BRANCH日期:DATE: MAY 10, 2003兹请贵行以□信开X 电开按下述项目开立不可撤销信用证Please issue by airmail/cable an irrevocable letter of credit as follows 有效期Expiry Date: July 30, 2003在受益人所在国In the beneficiary’s countryLC NO.230BS-453222申请人APPLICANT(Name & Address)CHINA IMP. & EXP. CORP. GUANGDONG INTERNATIONAL BUILDING, DONGFENGXI RD., GUANGZHOU,P.R. CHINA TEL:89676777 受益人Beneficiary(Name & Address)PHILIPS HONG KONG LIMITEDCS/BUSINESS COMMUNICATION SYSTEM26/F, HOPEWELL CENTRE, 17 KENNEDY RD.HONG KONG TEL:8215888/8215688通知行(如未填写贵行可自选)ADVISING BANK(IF BLANK, AT YOUR OPTION) 金额Amount(in figures and words) USD77,495.79 SAY U.S. DOLLARS SEVENTY SEVEN THOUSAND FOUR HUNDRED NINETY FIVE AND CENTS SEVENTY NINE ONLY本证使用时,汇票由你行选定以本公司或你行代理行为付款人见票天,贵行按 % 的发票金额支用,随附下列单据。
10.1 Multiple-Choice and Bimodal Questions1) A gas at a pressure of 10.0 Pa exerts a force of __________ N on an area of 25.5 m.A) 55B) 0.55C) 5.5D) 1.8E) 18Answer: ADiff: 2Page Ref: Sec. 10.22) A gas at a pressure of 325 torr exerts a force of __________ N on an area of 25.5 m.A)3⨯1.810B) 59C)5⨯2.410D) 0.018E) 2.4Answer: CDiff: 2Page Ref: Sec. 10.23) A pressure of 1.00 atm is the same as a pressure of __________ of mm Hg.A) 193B) 101C) 760.D) 29.9E) 33.0Answer: CDiff: 2Page Ref: Sec. 10.24) The National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. The units the NWS uses for atmospheric pressure are inches of mercury. A barometric pressure of 30.51 inches of mercury corresponds to __________ kPa.A) 77.50B) 775.0C) 1.020D) 103.3E) 16.01Answer: DDiff: 2Page Ref: Sec. 10.25) A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the manometer was 12.2 cm. Atmospheric pressure was 783 mm Hg. The pressure of the argon in the container was __________ mm Hg.A) 122B) 661C) 771D) 795E) 882Answer: ADiff: 2Page Ref: Sec. 10.2density 0.791 g/mL as shown below.The difference in heights of the liquid in the two sides of the manometer is 43.4 cm when the atmospheric pressure is 755 mm Hg. Given that the density of mercury is 13.6 g/mL, the pressure of the enclosed gas is __________ atm.A) 1.03B) 0.960C) 0.993D) 0.990E) 0.987Answer: BDiff: 3Page Ref: Sec. 10.2density 0.993 g/mL as shown below. The difference in heights of the liquid in the two sides of the manometer is 32.3 cm when the atmospheric pressure is 765 mm Hg. Given that the density of mercury is 13.6 g/mL, the pressure of the enclosed gas is __________ atm.A) 1.04B) 1.01C) 0.976D) 0.993E) 1.08Answer: ADiff: 3Page Ref: Sec. 10.28) In a Torricelli barometer, a pressure of one atmosphere supports a 760 mm column of mercury. If the original tube containing the mercury is replaced with a tube having twice the diameter of the original, the height of the mercury column at one atmosphere pressure is __________ mm.A) 380B) 760C)31.5210⨯D)34.7810⨯E) 121Answer: BDiff: 3Page Ref: Sec. 10.29) A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. After the compression, the gas pressure was __________ atm.A) 4.00B) 2.00C) 1.00D) 8.00E) 16.0Answer: EDiff: 2Page Ref: Sec. 10.310) A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is __________ atm.A) 1.5B) 7.5C) 0.67D) 3.3E) 15Answer: CDiff: 2Page Ref: Sec. 10.311) A balloon originally had a volume of 4.39 L at 44 °C and a pressure of 729 torr. The balloon must be cooled to __________°C to reduce its volume to 3.78 L (at constant pressure).A) 38B) 0C) 72.9D) 273E) 546Answer: BDiff: 2Page Ref: Sec. 10.312) If 3.21 mol of a gas occupies 56.2 L at 44 °C and 793 torr, 5.29 mol of this gas occupies __________ L under these conditions.A) 14.7B) 61.7C) 30.9D) 92.6E) 478Answer: DDiff: 2Page Ref: Sec. 10.313) A gas originally at 27 °C and 1.00 atm pressure in a 3.9 L flask is cooled at constant pressure until the temperature is 11 °C. The new volume of the gas is __________ L.A) 0.27B) 3.7C) 3.9D) 4.1E) 0.24Answer: BDiff: 2Page Ref: Sec. 10.314) If 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy__________ L at STP.A) 3.92B) 50.8C) 12.9D) 25.5E) 5.08Answer: DDiff: 2Page Ref: Sec. 10.315) A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.00 atm.A) 0.709B) 41.1C) 81.6D) 1.41E) 57.9Answer: CDiff: 2Page Ref: Sec. 10.316) A sample of 2H gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sampleweighing 9.49 g occupies __________ L at 353 K and 2.00 atm.A) 109B) 68.2C) 54.7D) 147E) 77.3Answer: BDiff: 2Page Ref: Sec. 10.317) A sample of an ideal gas (3.00 L) in a closed container at 25.0 °C and 76.0 torr is heated to 300 °C. The pressure of the gas at this temperature is __________ torr.A) 912B) 146C) 76.5D) 39.5E) 22.5310-⨯Answer: BDiff: 3Page Ref: Sec. 10.318) A sample of a gas (1.50 mol) is contained in a 15.0 L cylinder. The temperature isincreased from 100 °C to 150 °C. The ratio of final pressure to initial pressure 21P []P is __________.A) 1.50B) 0.667C) 0.882D) 1.13E) 1.00Answer: DDiff: 3Page Ref: Sec. 10.319) A sample of a gas originally at 25 °C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 atm and the temperature is 15 °C. The final volume of the gas is __________ L.A) 3.0B) 2.8C) 2.6D) 2.1E) 0.38Answer: BDiff: 3Page Ref: Sec. 10.324243Cl (g)CH (g)HCl (g)CH Cl (g)+→+will produce a total of __________ mL of products if pressure and temperature are kept constant.A) 100B) 50C) 200D) 150E) 250Answer: ADiff: 3Page Ref: Sec. 10.321) The reaction of 50 mL of 2N gas with 150 mL of 2H gas to form ammonia via theequation:223N (g)3H (g)2NH (g)+→will produce __________ mL of ammonia if pressure and temperature are kept constant.A) 250B) 50C) 200D) 150E) 100Answer: EDiff: 3Page Ref: Sec. 10.324224242Cl (g)C H (g)C H Cl (g)+→will produce a total of __________ mL of products if pressure and temperature are kept constant.A) 100B) 50C) 25D) 125E) 150Answer: BDiff: 4Page Ref: Sec. 10.323) The amount of gas that occupies 60.82 L at 31°C and 367 mm Hg is __________ mol.A) 1.18B) 0.850C) 894D) 11.6E) 0.120Answer: ADiff: 2Page Ref: Sec. 10.424) The pressure of a sample of 4CH gas (6.022 g) in a 30.0 L vessel at 402 K is __________ atm.A) 2.42B) 6.62C) 0.413D) 12.4E) 22.4Answer: CDiff: 3Page Ref: Sec. 10.425) At a temperature of __________ °C, 0.444 mol of CO gas occupies 11.8 L at 889 torr.A) 379B) 73C) 14D) 32E) 106Answer: EDiff: 3Page Ref: Sec. 10.426) The volume of 0.25 mol of a gas at 72.7 kPa and 15 °C is __________3m.A)5⨯8.110-B)41.210-⨯C)4⨯4.310-D)3⨯8.210-E)12.210-⨯Answer: DDiff: 3Page Ref: Sec. 10.427) The pressure exerted by 1.3 mol of gas in a 13 L flask at 22 °C is __________ kPa.A) 560B) 250C) 18D) 2.4E) 1.0Answer: BDiff: 3Page Ref: Sec. 10.428) A 0.325 L flask filled with gas at 0.914 atm and 19 °C contains __________ mol of gas.A)2⨯1.2410-B)2⨯1.4810-C) 9.42D) 12.4E) 80.7Answer: ADiff: 2Page Ref: Sec. 10.429) A gas in a 325 mL container has a pressure of 695 torr at 19 °C. There are__________ mol of gas in the flask.A)2⨯1.2410-B)21.4810-⨯C) 9.42D) 12.4E) 80.6Answer: ADiff: 2Page Ref: Sec. 10.430) A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new pressure is 795 mm Hg and the temperature is now 26 °C. There are now __________ mol of gas in the flask.A) 1.6B) 2.1C) 2.9D) 3.5E) 0.28Answer: BDiff: 5Page Ref: Sec. 10.431) A sample of gas (1.3 mol) occupies __________ L at 22 °C and 2.5 atm.A) 0.079B) 0.94C) 13D) 31E) 2⨯3.210-Answer: CDiff: 2Page Ref: Sec. 10.432) The volume of 0.65 mol of an ideal gas at 365 torr and 97 °C is __________ L.A) 0.054B) 9.5C) 11D) 41E) 2⨯2.410-Answer: DDiff: 2Page Ref: Sec. 10.433) The volume occupied by 1.5 mol of gas at 35 °C and 2.0 atm pressure is __________ L.A) 38B) 19C) 2.2D) 0.053E) 0.026Answer: BDiff: 2Page Ref: Sec. 10.434) The mass of nitrogen dioxide contained in a 4.32 L vessel at 48 °C and 141600 Pa is __________ g.A)4⨯5.3510B) 53.5C) 10.5D) 70.5E) 29.4610-⨯Answer: CDiff: 3Page Ref: Sec. 10.435) The density of ammonia gas in a 4.32 L container at 837 torr and 45.0 °C is__________ g/L.A) 3.86B) 0.719C) 0.432D) 0.194E) 2⨯4.2210-Answer: BDiff: 3Page Ref: Sec. 10.536) The density ofN O at 1.53 atm and 45.2 °C is __________ g/L.2A) 18.2B) 1.76C) 0.388D) 9.99E) 2.58Answer: EDiff: 3Page Ref: Sec. 10.537) The molecular weight of a gas is __________ g/mol if 3.5 g of the gas occupies 2.1 L at STP.A) 41B) 35.510⨯C) 37D) 24.610⨯E) 22.710-⨯Answer: CDiff: 3Page Ref: Sec. 10.538) The molecular weight of a gas that has a density of 6.70 g/L at STP is __________ g/mol.A) 24.9610⨯B) 21.5010⨯C) 17.3010⨯D) 3.35E) 12.9810-⨯Answer: BDiff: 3Page Ref: Sec. 10.539) The molecular weight of a gas that has a density of 7.10 g/L at 25.0 °C and 1.00 atm pressure is __________ g/mol.A) 174B) 14.6C) 28.0D)35.7510-⨯E)26.8510-⨯Answer: ADiff: 3Page Ref: Sec. 10.540) The molecular weight of a gas that has a density of 5.75 g/L at STP is __________ g/mol.A) 3.90B) 129C) 141D) 578E) 31.7310-⨯Answer: BDiff: 3Page Ref: Sec. 10.541) The density of chlorine 2(Cl ) gas at 25 °C and 60. kPa is __________ g/L.A) 20B) 4.9C) 1.7D) 0.86E) 0.58Answer: CDiff: 4Page Ref: Sec. 10.542) The volume of hydrogen gas at 38.0 °C and 763 torr that can be produced by the reaction of 4.33 g of zinc with excess sulfuric acid is __________ L.A) 1.68B) 42.7110-⨯C) 43.6910⨯D) 2.84E) 0.592Answer: ADiff: 4Page Ref: Sec. 10.543) The volume of HCL gas required to react with excess magnesium metal to produce6.82 L of hydrogen gas at 2.19 atm and 35.0 °C is __________ L.A) 6.82B) 2.19C)13.6D) 4.38E) 3.41Answer: CDiff: 3Page Ref: Sec. 10.544) The volume of fluorine gas required to react with 2.67 g of calcium bromide to form calcium fluoride and bromine at 41.0 °C and 4.31 atm is __________ mL.A) 10.4B) 210C) 420D) 79.9E) 104Answer: DDiff: 4Page Ref: Sec. 10.545) What volume (mL) of sulfur dioxide can be produced by the complete reaction of3.82 g of calcium sulfite with excessHCL(aq), when the final 2SO pressure is 827 torr at 44.0 °C?A) 27.6010⨯B) 41.3910-⨯C) 31.0010-⨯D) 0.106E) 25.7810⨯Answer: ADiff: 4Page Ref: Sec. 10.546) Automobile air bags use the decomposition of sodium azide as their source of gas for rapid inflation:322NaN (s)2Na (s)3N (g)→+.What mass (g) of 3NaN is required to provide 40.0 L of 2N at 25.0 °C and 763 torr?A) 1.64B) 1.09C) 160D) 71.1E) 107Answer: DDiff: 4Page Ref: Sec. 10.547) The Mond process produces pure nickel metal via the thermal decomposition of nickel tetracarbonyl:4Ni(CO) (l)Ni (s)4CO (g)→+.What volume (L) of CO is formed from the complete decomposition of 444 g of4Ni(CO) at 752 torr and 22.0 °C?A) 0.356B) 63.7C) 255D) 20.2E) 11.0Answer: CDiff: 4Page Ref: Sec. 10.548) What volume (L) of 3NH gas at STP is produced by the complete reaction of 7.5 g of2H O acording to the following reaction?32223Mg N (s)6H O (l)3Mg(OH) (aq)2NH (g)+→+A) 3.1B) 9.3C) 19D) 28E) 0.32Answer: ADiff: 4Page Ref: Sec. 10.549) Ammonium nitrite undergoes thermal decomposition to produce only gases:4222NH NO (s)N (g)2H O (g)→+What volume (L) of gas is produced by the decomposition of 35.0 g of 42NH NO (s)at 525 °C and 1.5 atm?A) 47B) 160C) 15D) 72E) 24Answer: DDiff: 4Page Ref: Sec. 10.550) The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.322KClO (s)2KCl (s)3O (g)→+What volume (L) of 2O gas at 25 °C and 1.00 atm pressure is produced by thedecomposition of 7.5 g of 3KClO (s)?A) 4.5B) 7.5C) 2.2D) 3.7E) 11Answer: CDiff: 4Page Ref: Sec. 10.551) Since air is a mixture, it does not have a "molar mass." However, for calculation purposes, it is possible to speak of its "effective molar mass." (An effective molar mass is a weighted average of the molar masses of a mixture's components.) If air at STP has a density of 1.285 g/L, its effective molar mass is __________ g/mol.A) 26.94B) 31.49C) 30.00D) 34.42E) 28.80Answer: EDiff: 4Page Ref: Sec. 10.552) A vessel containedN, Ar, He, and Ne. The total pressure in the vessel was 987 torr.2The partial pressures of nitrogen, argon, and helium were 44.0, 486, and 218 torr, respectively. The partial pressure of neon in the vessel was __________ torr.A) 42.4B) 521C) 19.4D) 239E) 760Answer: DDiff: 2Page Ref: Sec. 10.653) The pressure in a 12.2 L vessel that contains 2.34 g of carbon dioxide, 1.73 g of sulfur dioxide, and 3.33 g of argon, all at 42 °C is __________ mm Hg.A) 263B) 134C) 395D) 116E) 0.347Answer: ADiff: 3Page Ref: Sec. 10.654) A sample of He gas (3.0 L) at 5.6 atm and 25 °C was combined with 4.5 L of Ne gas at 3.6 atm and 25 °C at constant temperature in a 9.0 L flask. The total pressure in the flask was __________ atm. Assume the initial pressure in the flask was 0.00 atm and the temperature upon mixing was 25 °C.A) 2.6B) 9.2C) 1.0D) 3.7E) 24Answer: DDiff: 3Page Ref: Sec. 10.655) A sample of 2H gas (2.0 L) at 3.5 atm was combined with 1.5 L of 2N gas at 2.6 atmpressure at a constant temperature of 25 °C into a 7.0 L flask. The total pressure in the flask is __________ atm. Assume the initial pressure in the flask was 0.00 atm and the temperature upon mixing was 25 °C.A) 0.56B) 2.8C) 1.0D) 1.6E) 24Answer: DDiff: 3Page Ref: Sec. 10.656) In a gas mixture of He, Ne, and Ar with a total pressure of 8.40 atm, the mole fraction of Ar is __________ if the partial pressures of He and Ne are 1.50 and 2.00 atm, respectively.A) 0.179B) 0.238C) 0.357D) 0.583E) 0.417Answer: DDiff: 3Page Ref: Sec. 10.657) A gas mixture of Ne and Ar has a total pressure of 4.00 atm and contains 16.0 mol of gas. If the partial pressure of Ne is 2.75 atm, how many moles of Ar are in the mixture?A) 11.0B) 5.00C) 6.75D) 9.25E) 12.0Answer: BDiff: 2Page Ref: Sec. 10.658) A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is __________ atm.A) 1.7B) 1.5C) 0.60D) 0.35E) 1.0Answer: CDiff: 2Page Ref: Sec. 10.659) A flask contains a mixture of He and Ne at a total pressure of 2.6 atm. There are 2.0 mol of He and 5.0 mol of Ne in the flask. The partial pressure of He is __________ atm.A) 9.1B) 6.5C) 1.04D) 0.74E) 1.86Answer: DDiff: 2Page Ref: Sec. 10.660) Sodium hydride reacts with excess water to produce aqueous sodium hydroxide and hydrogen gas:22NaH (s)H O (l)NaOH (aq)H (g)+→+A sample of NaH weighing __________ g will produce 982 mL of gas at 28.0 °C and 765 torr, when the hydrogen is collected over water. The vapor pressure of water at this temperature is 28 torr.A) 2.93B) 0.960C) 0.925D) 0.0388E) 925Answer: CDiff: 4Page Ref: Sec. 10.661) 2SO (5.00 g) and 2CO (5.00 g) were placed in a 750.0 mL container at 50.0 °C. Thetotal pressure in the container was __________ atm.A) 0.192B) 4.02C) 2.76D) 6.78E) 1.60Answer: DDiff: 3Page Ref: Sec. 10.622partial pressure of 2SO in the container was __________ atm.A) 2.76B) 4.02C) 6.78D) 0.192E) 1.60Answer: ADiff: 3Page Ref: Sec. 10.663) 2SO (5.00 g) and 2CO (5.00 g) were placed in a 750.0 mL container at 50.0 °C. Thepartial pressure of 2CO in the container was __________ atm.A) 6.78B) 2.76C) 1.60D) 0.192E) 4.02Answer: EDiff: 3Page Ref: Sec. 10.664) CO (5.00 g) and 2CO (5.00 g) were placed in a 750.0 mL container at 50.0 °C. The total pressure in the container was __________ atm.A) 10.3B) 4.02C) 6.31D) 0.292E) 1.60Answer: ADiff: 3Page Ref: Sec. 10.62partial pressure of CO in the container was __________ atm.A) 6.31B) 4.02C) 10.3D) 0.292E) 1.60Answer: ADiff: 3Page Ref: Sec. 10.666) CO (5.00 g) andCO (5.00 g) were placed in a 750.0 mL container at 50.0 °C. The2partial pressure ofCO in the container was __________ atm.2A) 4.02B) 10.3C) 1.60D) 0.292E) 6.31Answer: ADiff: 3Page Ref: Sec. 10.667) The root-mean-square speed of CO at 113 °C is __________ m/s.A) 317B) 58.3C) 586D) 993E) 31.5Answer: CDiff: 3Page Ref: Sec. 10.868) A sample ofN gas (2.0 mmol) effused through a pinhole in 5.5 s. It will take2__________ s for the same amount ofCH to effuse under the same conditions.4A) 7.3B) 5.5C) 3.1D) 4.2E) 9.6Answer: DDiff: 4Page Ref: Sec. 10.869) A sample ofO gas (2.0 mmol) effused through a pinhole in 5.0 s. It will take2__________ s for the same amount ofCO to effuse under the same conditions.2A) 4.3B) 0.23C) 3.6D) 5.9E) 6.9Answer: DDiff: 4Page Ref: Sec. 10.870) A sample of He gas (2.0 mmol) effused through a pinhole in 53 s. The same amount of an unknown gas, under the same conditions, effused through the pinhole in 248 s. The molecular mass of the unknown gas is __________ g/mol.A) 0.19B) 5.5C) 88D) 19E) 350Answer: CDiff: 4Page Ref: Sec. 10.871) Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is __________ atm. (22=-,b 0.0171 L/mola 0.211 L atm/mol=)A) 0.730B) 1.00C) 1.21D) 1.37E) 0.367Answer: DDiff: 5Page Ref: Sec. 10.972) Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.50 mol of chlorine gas at 0.00 °C is __________ atm.(22=-,b 0.0562 L/mola 6.49 L atm/mol=)A) 0.993B) 1.50C) 0.676D) 1.91E) 1.48Answer: EDiff: 5Page Ref: Sec. 10.910.2 Multiple Choice Questions1) Which of the following statements about gases is false?A) Gases are highly compressible.B) Distances between molecules of gas are very large compared to bond distances within molecules.C) Non-reacting gas mixtures are homogeneous.D) Gases expand spontaneously to fill the container they are placed in.E) All gases are colorless and odorless at room temperature.Answer: EDiff: 1Page Ref: Sec. 10.12) Of the following, __________ has a slight odor of bitter almonds and is toxic.A)NH3B)N O2C) COD)CH4E) HCNAnswer: EDiff: 2Page Ref: Sec. 10.13) Of the following, __________ has the odor of rotting eggs.NHA)3H SB)2C) CONOD)2E) HCNAnswer: BDiff: 2Page Ref: Sec. 10.14) One significant difference between gases and liquids is that __________.A) a gas is made up of moleculesB) a gas assumes the volume of its containerC) a gas may consist of both elements and compoundsD) gases are always mixturesE) All of the above answers are correct.Answer: BDiff: 1Page Ref: Sec. 10.15) Molecular compounds of low molecular weight tend to be gases at room temperature. Which of the following is most likely not a gas at room temperature?A)Cl2B) HClC) LiClD)H2E)CH4Answer: CDiff: 1Page Ref: Sec. 10.16) Gaseous mixtures __________.A) can only contain moleculesB) are all heterogeneousC) can only contain isolated atomsD) are all homogeneousE) must contain both isolated atoms and moleculesAnswer: DDiff: 1Page Ref: Sec. 10.17 Which of the following equations shows an incorrect relationship between pressures given in terms of different units?A) 1.20 atm = 122 kPaB) 152 mm Hg = 4⨯2.0310 PaC) 0.760 atm = 578 mm HgD) 1.0 torr = 2.00 mm HgE) 1.00 atm = 760 torrAnswer: DDiff: 2Page Ref: Sec. 10.28) The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid, P = ghd. How high a column of water (d 1.0 g/mL)= would be supported by a pressure that supports a 713 mm column of mercury (d 13.6 g/mL)=?A) 14 mmB) 52 mmC) 713 mmD) 4⨯1.210 mmE) 3⨯9.710 mmAnswer: EDiff: 3Page Ref: Sec. 10.29) The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid, P = ghd. How high a column of methanol (d 0.79 g/mL)= would be supported by a pressure that supports a 713 mm column of mercury (d 13.6 g/mL)=?A) 713 mmB) 41 mmC) 41.210 mm⨯D) 3⨯9.710 mmE) 17 mmAnswer: CDiff: 3Page Ref: Sec. 10.210) If one was told that their blood pressure was 130/80, their systolic pressure was__________.A) 130 PaB) 130 mm HgC) 80 PaD) 80 mm HgE) 80 psiAnswer: BDiff: 1Page Ref: Sec. 10.211) Which statement about atmospheric pressure is false?A) As air becomes thinner, its density decreases.B) Air actually has weight.C) With an increase in altitude, atmospheric pressure increases as well.D) The warmer the air, the lower the atmospheric pressure.E) Atmospheric pressure prevents water in lakes, rivers, and oceans from boiling away.Answer: CDiff: 1Page Ref: Sec. 10.2, 10.312) In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to __________.--A)110.08206 atm L mol K--B)118.314 J mol K--C)1162.36 L torr mol K--D)111.987 cal mol KE) none of the aboveAnswer: BDiff: 2Page Ref: Sec. 10.2, 10.313) The first person to investigate the relationship between the pressure of a gas and its volume was __________.A) Amadeo AvogadroB) Lord KelvinC) Jacques CharlesD) Robert BoyleE) Joseph Louis Gay-LussacAnswer: DDiff: 1Page Ref: Sec. 10.3A) PV = constantB)P= constant VC)V= constant PD)V= constant TE)n= constant PAnswer: ADiff: 2Page Ref: Sec. 10.315) "Isothermal" means __________.A) at constant pressureB) at constant temperatureC) at variable temperature and pressure conditionsD) at ideal temperature and pressure conditionsE) that ΔH rxn = 0Answer: BDiff: 1Page Ref: Sec. 10.3A)P= constant TB)V= constant TC) PV = constantD) V = constant n⨯E) V = constant P⨯Answer: BDiff: 2Page Ref: Sec. 10.317) Which one of the following is a valid statement of Avogadro's law?A)P= constant TB)V= constant TC) PV = constantD) V = constant n⨯E) V = constant P⨯Answer: DDiff: 2Page Ref: Sec. 10.318) The volume of an ideal gas is zero at __________.A) 0 °CB) –45 °FC) -273 KD) -363 KE) –273 °CAnswer: EDiff: 1Page Ref: Sec. 10.319) Of the following, only __________ is impossible for an ideal gas.A) 1212V V = T T B) 1122VT = V T C) 1122V T = V T D) 2211T V = V T E) 1122V T = = 0V TAnswer: BDiff: 2Page Ref: Sec. 10.320) The molar volume of a gas at STP is __________ L.A) 0.08206B) 62.36C) 1.00D) 22.4E) 14.7Answer: DDiff: 1Page Ref: Sec. 10.421) How many moles of gas are there in a 45.0 L container at 25.0 °C and 500.0 mm Hg?A) 0.630B) 6.11C) 18.4D) 1.21E) 207Answer: DDiff: 3Page Ref: Sec. 10.422) Standard temperature and pressure (STP), in the context of gases, refers to __________.A) 298.15 K and 1 atmB) 273.15 K and 1 atmC) 298.15 K and 1 torrD) 273.15 K and 1 pascalE) 273.15 K and 1 torrAnswer: BDiff: 1Page Ref: Sec. 10.423) The volume of 1.20 mol of gas at 61.3 kPa and 25.0 °C is __________ L.A) 135B) 48.5C) 52.4D) 108E) 55.7Answer: BDiff: 2Page Ref: Sec. 10.424) Sodium bicarbonate is reacted with concentrated hydrochloric acid at 37.0 °C and 1.00 atm. The reaction of 6.00 kg of bicarbonate with excess hydrochloric acid under these conditions will produce __________ L of 2COA)21.0910⨯B)42.8510⨯C)41.8210⨯D)28.7010⨯E)31.8210⨯Answer: EDiff: 5Page Ref: Sec. 10.425) The volume of a sample of gas (2.49 g) was 752 mL at 1.98 atm and 62 °C. The gas is __________.A)SO2B)SO3C)NH3D)NO2E) NeAnswer: DDiff: 4Page Ref: Sec. 10.526) The density of __________ is 0.900 g/L at STP.A)CH4B) NeC) COD)N2E) NOAnswer: BDiff: 4Page Ref: Sec. 10.5NO in a 3.50 L tank at 780.0 torr and 37.0 °C is _________ g/L. 27) The density of2A) 1.64B) 9.30C) 1.86D) 2.92E) 3.27Answer: CDiff: 4Page Ref: Sec. 10.528) The density (in g/L) ofCO at 1140 torr and 60.0 °C is __________.2A) 2.42B) 16.2C) 5.70D) 44.0E) 10.9Answer: ADiff: 4Page Ref: Sec. 10.529) Of the following gases, __________ has density of 2.104 g/L at 303 K and 1.31 atm.A) HeB) NeC) ArD) KrE) XeAnswer: CDiff: 4Page Ref: Sec. 10.530) A 255 mL round-bottom flask is weighed and found to have a mass of 114.85 g. A few milliliters of an easily vaporized liquid are added to the flask and the flask is immersed in a boiling water bath. All of the liquid vaporizes at the boiling temperature of water, filling the flask with vapor. When all of the liquid has vaporized, the flask is removed from the bath, cooled, dried, and reweighed. The new mass of the flask and the condensed vapor is 115.23 g. Which of the following compounds could the liquid be? (Assume the ambient pressure is 1 atm.)A)C H410B)C H OH37C)C H26D)C H OH25E)C H OH49Answer: DDiff: 5Page Ref: Sec. 10.531) A sample of an unknown volatile liquid was injected into a Dumas flask(m= 27.0928 g, V= 0.1040 L)and heated until no visible traces of the liquid flask flaskcould be found. The flask and its contents were then rapidly cooled and reweighed(m= 27.4593 g)The atmospheric pressure and temperature during the flask vaporexperiment were 0.976 atm and 18.0 °C, respectively. The unknown volatile liquid was __________.C HA)612C HB)614C HC)714C HD)716C HE)66Answer: BDiff: 5Page Ref: Sec. 10.5。