湖南省邵东县三中2018届高三第一次月考 英语

2024年邵阳市高三第一次联考试题卷英语本试卷8页。

满分150分。

考试时间120分钟。

注意事项：1．答卷前，考生务必将自己的姓名、班级、考号填写在答题卡上。

将条形码横贴在答题卡上“条形码粘贴区”。

2．作答选择题时，选出每小题答案后，用2B铅笔在答题卡上对应题目选项的答案信息点涂黑；如需改动，用橡皮擦干净后，再选涂其他答案。

答案不能答在试卷上。

3．非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新答案；不准使用铅笔和涂改液。

不按以上要求作答无效。

4．保持答题卡的整洁。

考试结束后，只交答题卡，试题卷自行保存。

第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．What is the chair made of?A．Wood.B．Metal.C．Plastic.2．What does the man think of the food in the restaurant?A．Boring.B．Special.C．Great.3．Where does the man come from?A．New York.B．Washington.C．Los Angeles.4．What is the next TV program?A．The news.B．A quiz show.C．A documentary about animals.5．Where are the speakers?A．In a library.B．In a bookstore.C．At a coffee shop.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

邵东一中2019年高一第三次月考英语科试卷本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，满分120分，考试用时120分钟。

第Ⅰ卷第一部分听力（共两节，满分20分）第一节（共5小题；每小题1分，满分5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

第二部分阅读理解第一部分（共15小题：每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该项涂黑。

AA woman came out of her house and saw three old men sitting in her front yard. She said, “I don’t think I know you, but you must be hungry. Please come in and have something to eat.”“Is the man of the house home?” they asked. “No,” she replied, “He’s out.” “Then we cannot come in,” they replied.In the evening when her husband came home, she told him what had happened. “Go tell them I am home and invite them in!” The woman went out and invited the men in. “We do not go into a house together,” they replied. “Why is that?” she asked.One of the old men explained that their names were Wealth, Success and Love. Then he added, “Now go in and discuss with your husband which one of us you want in your home.”The woman went in and told her husband what was said. Her husband was overjoyed and he suggested inviting Wealth to fill their home with wealth. And his wife wanted to invite Success; but their daughter-in-law suggested they should invite Love so that their home would be filled with love. At last the husband said to his wife. “Go out and invite Love to be our guest.”The woman went out and asked the three old men, “Which one of you is Love? Please come inand be our guest.”Love got up and started walking toward the house.The other two also got up and followed him. Surprised, the lady asked Wealth and Success: “I only invited Love. Why are you coming in?”The old men replied together: “If you had invited Wealth or Success, the other two of us would have stayed out, but since you invited Love, wherever he goes, we go with him. Wherever there is Love, there is also Wealth and Success!”21. The woman asked the three men to come in and have something to eat because .A. she was a warm-hearted woman.B. they were her neighbours.C. they asked her to do so.D. they were her friends.22. Who does the underlined words “the man” in the second paragraph refer to?A. The woman’s son.B. The woman’s father.C. The woman’s son-in-law.D. The woman’s husband.23. It can be inferred from the passage that .A. The three old men are brothers and they can’t be separated.B. The husband will refuse them in.C. If a person has love, he will own everything.D. The wife will be scolded by the husband.BIs there anything more important than health? I don’t think so. “Health is the greatest wealth,” wise people say. You can’t be good at your studies or work well when yo u are ill.If you have a headache, toothache, backache, earache or bad pain in the stomach, if you complain of a bad cough, if you run a high temperature and have a bad cold, or if you suffer from high or low blood pressure, I think you should go to the doctor.The doctor will examine your throat, feel your pulse, test your blood pressure, take your temperature, sound your heart and lungs, test your eyes, check your teeth or have your chest X-rayed. After that he will advise some treatment, or some medicine. The only thing you have to do is to follow his advice.Speaking about doctor’s advice, I can’t help telling you a funny story.An old gentleman came to see the doctor about his weakness, memory loss and seriousproblems with his heart and lungs. The doctor examined him and said there was no medicine for his disease.He told his patients to go to a quiet place for a month and have a good rest. He also advised him to eat a lot of meat, drink two glasses of red wine every day and take long walks. In other wo rds, the doctor advised him to follow the rule: “Eat at pleasure, drink with measure and enjoy life as it is.” The doctor also said that if the man wanted to be well again, he shouldn’t smoke more than one cigarette a day.A month later the gentleman came to the doctor’s office. He looked cheerful and happy. He thanked the doctor and said that he had never felt a healthier man.“But you know, doctor,” he said, “it’s not easy to begin smoking at my age.”24. The writer thinks that .A. health is the greatest wealthB. work is as important as studiesC. medicine is more important than pleasureD. nothing is more important than pleasure25. The doctor usually tells his patient what to do .A. without examining the patientB. after he has examined the patientC. if the patient doesn’t take medicineD. unless the patient feels pain26. The underlined part means “ ”.A. he was feeling better than everB. he wasn’t a healthier manC. he was feeling worse than beforeD. he will be well again27. From the last sentence of the passage, we learn the man before the doctor told himnot to smoke more than one cigarette a day.A. was a heavy smokerB. didn’t smoke so muchC. didn’t smokeD. began to learn to smokeCHave you ever noticed what happens to an idea once you express it? Just talking about it or writing it down causes you to make it clear in your own mind. How can you use this to increase your brain power? Start writing.By putting thoughts into words, you are telling yourself the logic(逻辑) behind what you think, feel, or only partly understand. Often, explaining a thought is the process of understanding. In other words, you increase your brain power by exercising your “explaining power”.Try this experiment. Explain how you’ll increase your brain power, even if you have no idea how right now. Just start with anything, and create an explanation. For example, start with “I'll learn chess.” or “I’ll read an article on the mind every week.” Explain how that will help. You’ll be surprised how often this becomes a workable plan, and if you actually do this, you'll have a better understanding of your brain from now on.Another benefit of writing is that it helps you remember what you have learnt. Many, if not most, highly productive people are always taking notes. You can try keeping it all in your head, but if you keep a journal of your ideas the next time you're working on a big project, you'll probably have more success.Want to understand a topic? Write a book about it. That's an extreme example, but if you are learning something new, write a letter to a friend about it, and you will understand it better. Want to invent something? Write an explanation of the problem, why you want to solve it, and why it is worth solving, and you’re halfway there.Writers don't always write because they clearly understand something beforehand. Often, they write about something because they want to understand it. You can do the same. Writing will help you to understand it. Give it a try.28. What would be the best title for the text?A. A Way on How to WriteB. Increase Your Brain Power through WritingC. Brain Power Helps Improve Your WritingD. How to Start Your Writing29. According to the text, writing can help you a lot in the following ways EXCEPT __________.A. the increase of your brain powerB. the ability to rememberC. the development of your interest in studyD. the better understanding of a topic30. If a writer writes something, it means that he or she ________.A. has understood it very wellB. needs to understand it betterC. wants to remember it in his or her mindD. is exercising his or her “explaining power”31. What’s the main purpose of the text?A. To advise readers to start their writing.B. To explain the importance of writing.C. To persuade readers to become writers.D. To increase readers’ brain power.DPerhaps you want to kno w how to avoid losing your hearing due to noise. Or maybe you’re already hard of hearing, and want to keep from losing even more hearing.Every year, the Sight and Hearing Association tests selected noise-making toys to see how loud they are. They publish two lists, one of "noisy" toys and an "ear-friendly" list of safe ones. According to the association’s site, noise levels above 90 decibels (分贝) can produce hearing damage in just a short time.No noise-level limits are set for toys by the federal (联邦) government, but 90 decibels is generally seen as the highest acceptable level. A similar group in Canada also tests toys and publishes a report, and both the organizations recommend parents that they should listen to toys before buying them. A car eful parent will limit a child’s time with a noisy toy.Teenagers are just as much at risk, since their activities often expose (暴露) them to loud sounds. Listening to loud music has long been known as one of the risks. Sounds in concerts and even cinemas are known to be loud, and teenagers should always bring along emergency hearing protection such as ear plugs. Another possibility is for them to wear ear moulds (模具) made specially for the purpose of protecting hearing.Adults are mainly exposed to unsafe noise levels while they are at work. The federal government has published several papers on noise control at work, such as Noise Control and Industrial Noise Control Guide.32. According to the Sight and Hearing Association, when choosing a toy for a child, a parent should _______.A. test its quality before buying itB. compare the prices of various toysC. choose a toy from a list of "noisy" toysD. choose a toy with a noise level below 90 decibels33. What are ear moulds made for?A. To prevent emergencies.B. To make the ears look beautiful.C. To reduce hearing damage.D. To cure deafness.34. The government has published papers connected with _____.A. the sources of work noiseB. the unsafe noise levelsC. protecting the hearing of workersD. preventing noise at work35. What do we learn from this passage?A. "Noisy" toys are cheaper than "ear-friendly" ones.B. Toys without sound are best for children.C. Chi ldren should not spend a long time on toys.D. Loud music can damage one’s hearing.第二节(共5小题,每小题2分,满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

2017年上学期高三年级第一次月考历史试卷时量；90分钟，分值：100分命题人：申晓军一．选择题(每小题2分,共60分)1．在传统四合院中，北房南向是正房，房屋的开间进深都较大，台基较高，多为长辈居住，东西厢房开间进深较小，台基也较矮，常为晚辈居住。

这一建筑特点主要反映了( ) A．天人合一的思想B．长尊幼卑的观念C．敬天法祖的传统D．阴阳流转的理念2.《史记·周本纪》载：武王封“帝尧之后于蓟”。

蓟国都在蓟城，在今北京市区西南广安门一带，约公元前7世纪为燕国所并。

蓟国与周天子的关系不包括（）A.定期朝见周天子B.按期向周天子缴纳贡赋C.当地长官由周王任免，不得世袭D.周天子承认蓟国国君在国内的世袭统治权3.据史书记载，官员□□□□“掌邦国刑宪、典章之政令，以肃正朝列……”文中□□□□处缺失的官员身份应是（）A.御史大夫B.刑部尚书C.平章政事D.太尉4.司马迁在《史记》中有一段叙述：“诸侯稍微，大国不过十余城，小侯不过数十里，上足以奉供职，下足以供养祭祀，以蕃辅京师……强本干，弱枝叶之势，尊卑明而万事各得其所。

”这段话反映了司马迁（）A.否定了西汉的“推恩令”B.赞扬了汉初的郡国并行制C.肯定了西汉的“推恩令”D.否定了汉初的郡国并行制5．清朝时，军机处起草的诏旨密封后往往不经内阁、部院，而直接由驿马传递地方督抚的，称为“廷寄”，直接交中央各部院的，称为“交片”，地方督抚密折奏事也可经军机处直达皇帝。

材料表明清朝政治形态的特点是( )A．中枢机构之间彼此牵制B．地方具有较好的自治性和能动性C．高层政治决策具有封闭性D．军机处代替内阁成为了中央官署6.下图中，从图一到图二中国古代中央机构的变化，最能反映出（）A.中央对地方的控制逐步加B.古代君主专制进一步加强C.中央机构精简取得较大成就D.古代中央官制的重大变革7.有学者认为：“由于私有制进一步发展，人的私有意识大大加强，商品货币经济的深度与广度都已今非昔比。

邵东一中2018年下学期高一年级第三次月考试题英语命题人：审题人：本试题卷分为选择题和非选择题两部分，共7页，时量120分钟，总分120分。

第Ⅰ卷第一部分听力（共两节，满分20分）第一节（共5小题；每小题1分，满分5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What is the man's favorite music?A.Jazz music.B.Folk music.C.Country music.2.What does the woman want to do?A.Watch a performance.B.Get some sleep.C.See a film.3.What size does the woman usually wear?A.Size six and a halfB.Size ten.C.Size fifteen and a half.4.What does the man say about Stephanie?A.She will get well soon.B.She has a very bad cold.C.She is coming to the beach.5.Where does the woman want to go?A.Oxford.B.Liverpool.C.London.第二节（共15小题，每小题1分，满分15分）听下面5段对话或独白。

每段对话后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题给出5秒钟的作答时间。

每段对话读两遍。

听第6段材料，回答第6、7题。

6.How will the woman probably get to the new company?A.By plane.B.By car.C.By train.7.What does the man suggest?A.Making a call.B.Writing an e-mail.C.Checking on the Internet.听第7段材料，回答第8、9题。

邵东三中2017届高三年级第一次月考英语试卷第二部分阅读理解（共两节,满分40分）第一节(共15小题，每小题2分,满分30分）阅读下列短文，从每题所给的四个选项中,选择最佳选项,并在答题卡上将该项涂黑。

AHigh school students are some of the busiest people in the world. To get the most from all you do，you must be in control of your time. Your success in high school depends on your use of time。

Here are some important things to remember。

Begin each term by filling in a master plan。

First fill in things you must do (classes，work，practice，etc. that you can’t change。

) Then find the most effective use for these times.Set a regular time and place for study. This will save your time in the long run. If you have a study hall in your school, use it!Use daylight hours to study whenever possible. For most people for every hour of study done in daylight hours，it will take them one and a half hours to do the same task at night。

邵东三中2016届高三第一次月考英语试题第Ⅰ卷（选择题满分100分）第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10称钟的时间来回答有关小题如阅读下一小题。

每段对话仅读一遍。

1.What does the man want to do?A. Take photos.B. Buy a camera.C. Help the woman.2. What are the speakers talking about?A.A noisy night.B. Their life in town.C.A place of living.3. Where is the man now?A. On his way.B. In a restaurant.C. At home.4. What will Celia do?A. Find a player.B. Watch a game.C. Play basketball.5. What day is it when the conversation takes place?A. Saturday.B. Sunday.C. Monday.第二节（共15小题：每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

每段对话或独白读两遍。

听第6段材料，回答6、7题。

6. What is Sara going to do?A. Buy John a gift.B. Give John a surprise.C. Invite John to France.7. What does the man think of Sara’s plan?A. Funny.B. Exciting.C. Strange.听第7段材料，回答第8、9题。

2017-2018学年湖南省邵阳市邵东三中高三（上）第一次月考数学试卷（文科）一．选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中，只有一项是符合题目要求的.1．设集合A={1，3，5，7}，B={x|2≤x≤5}，则A∩B=（）A．{1，3}B．{3，5}C．{5，7}D．{1，7}2．已知复数z满足（z﹣1）i=1+i，则z=（）A．﹣2﹣i B．﹣2+i C．2﹣i D．2+i3．3名学生排成一排，其中甲、乙两人站在一起的概率是（）A．B．C．D．4．设△ABC的角A，B，C所对的边分别是a，b，c，且a2+c2+ac﹣b2=0，则角B是（）A．B．C． D．5．已知椭圆C的短轴长为6，离心率为，则椭圆C长轴长为（）A．5 B．10 C．4 D．86．将函数y=2sin（2x+）的图象向右平移个周期后，所得图象对应的函数为（）A．y=2sin（2x+）B．y=2sin（2x+）C．y=2sin（2x﹣）D．y=2sin（2x﹣）7．一个几何体的三视图如图所示（单位长度：cm），则此几何体的体积是（）A．112cm3B．cm3 C．96cm3D．224cm38．在下列区间中，函数f（x）=e x+4x﹣3的零点所在的区间为（）A．（，）B．（﹣，0）C．（0，）D．（，）9．如图所示，该程序框图运行后输出的结果为（）A．2 B．4 C．8 D．1610．如图，正方体ABCD﹣A1B1C1D1中，直线BC1与平面A1ACC1所成的角为（）A．B．C．D．11．函数y=2log4（1﹣x）的图象大致是（）A．B．C．D．12．函数f（x）=x2﹣2lnx的单调减区间是（）A．（0，1）B．（1，+∞）C．（﹣∞，1）D．（﹣1，1）二．填空题：本大题共4小题，每小题5分13．已知A（1，3），B（2，4），=（2x﹣1，x2+3x﹣3），且=，则x=．14．不查表求tan105°的值为．15．若直线x﹣y=2被圆（x﹣a）2+y2=4所截得的弦长为2，则实数a的值为．16．铁矿石A和B的含铁率a，冶炼每万吨铁矿石的CO2排放量b及每万吨铁矿石的价格c某冶炼厂至少要生产（万吨）铁，若要求2的排放量不超过（万吨）则购买铁矿石的最少费用为（百万元）三．解答题：解答应写出文字说明，证明过程或演算步骤17．已知等差数列{a n}的前n项和为S n（n∈N*），a3=5，S10=100．（1）求数列{a n}的通项公式；（2）设b n=2+2n求数列{b n}的前n项和T n．18．如图所示的四棱锥P﹣ABCD中，底面ABCD为菱形，PA⊥平面ABCD，E为PC的中点．（1）求证：PA∥平面BDE．（2）设AC=6，BD=4，PA=3，求四棱锥E﹣ABCD的体积．19．某日用品按行业质量标准分成五个等级，等级系数X依次为1，2，3，4，5．现从一批该a、b、c的值；（Ⅱ）在（Ⅰ）的条件下，将等级系数为4的3件日用品记为x1，x2，x3，等级系数为5的2件日用品记为y1，y2，现从x1，x2，x3，y1，y2，这5件日用品中任取两件（假定每件日用品被取出的可能性相同），写出所有可能的结果，并求这两件日用品的等级系数恰好相等的概率．20．如图，已知直线l：y=kx﹣2与抛物线C：x2=﹣2py（p＞0）交于A，B两点，O为坐标原点， +=（﹣4，﹣12）．（1）求直线l和抛物线C的方程；（2）抛物线上一动点P从A到B运动时，求△ABP面积最大值．21．已知函数f（x）=xlnx．（1）求函数f（x）的极值点；（2）设函数g（x）=f（x）﹣2（x﹣1），求函数g（x）在区间[1，e]上的最小值．（其中e为自然对数的底数）．选做题（请考生在第22、23、24题中任选一题作答，如果多做，则按所做的第一题计分）22．如图，E是圆内两弦AB和CD的交点，直线EF∥CB，交AD的延长线于F，FG切圆于G．（1）求证：∠AEF=∠EDF；（2）设EF=6，求FG的长．23．在直角坐标系xOy中，曲线C1的参数方程为（t为参数），以O为极点，Ox正半轴为极轴建立极坐标系，曲线C2的极坐标方程为ρ=4cosθ．（1）求曲线C1的直角坐标方程；（2）设C1与C2相交于A，B两点，求A，B两点的极坐标．24．已知函数f（x）=|x﹣|+|x+|，M为不等式f（x）＜2的解集．（Ⅰ）求M；（Ⅱ）证明：当a，b∈M时，|a+b|＜|1+ab|．2017-2018学年湖南省邵阳市邵东三中高三（上）第一次月考数学试卷（文科）参考答案与试题解析一．选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中，只有一项是符合题目要求的.1．设集合A={1，3，5，7}，B={x|2≤x≤5}，则A∩B=（）A．{1，3}B．{3，5}C．{5，7}D．{1，7}【考点】交集及其运算．【分析】直接利用交集的运算法则化简求解即可．【解答】解：集合A={1，3，5，7}，B={x|2≤x≤5}，则A∩B={3，5}．故选：B．2．已知复数z满足（z﹣1）i=1+i，则z=（）A．﹣2﹣i B．﹣2+i C．2﹣i D．2+i【考点】复数代数形式的乘除运算．【分析】由已知等式变形，然后利用复数代数形式的乘除运算化简求得z﹣1，进一步求得z．【解答】解：由（z﹣1）i=1+i，得z﹣1=，∴z=2﹣i．故选：C．3．3名学生排成一排，其中甲、乙两人站在一起的概率是（）A．B．C．D．【考点】等可能事件的概率．【分析】根据甲、乙两人站在一起的站法有A22•A22=4 种，所有的站法有A33=6种，由此求得甲、乙两人站在一起的概率．【解答】解：甲、乙两人站在一起的站法有A22•A22=4 种，所有的站法有A33=6种，故其中甲、乙两人站在一起的概率是=，故选：A．4．设△ABC的角A，B，C所对的边分别是a，b，c，且a2+c2+ac﹣b2=0，则角B是（）A．B．C． D．【考点】余弦定理．【分析】利用余弦定理即可得出．【解答】解：∵a2+c2+ac﹣b2=0，由余弦定理可得：cosB===﹣，B∈（0，π），解得B=．故选：C．5．已知椭圆C的短轴长为6，离心率为，则椭圆C长轴长为（）A．5 B．10 C．4 D．8【考点】椭圆的简单性质．【分析】由2b=6，得b=3，椭圆的离心率e====，即可求得a的值，求得椭圆C长轴长．【解答】解：可知：2b=6，b=3，e====，∴a=5，椭圆C长轴长为2a=10，故选：B．6．将函数y=2sin（2x+）的图象向右平移个周期后，所得图象对应的函数为（）A．y=2sin（2x+）B．y=2sin（2x+）C．y=2sin（2x﹣）D．y=2sin（2x﹣）【考点】函数y=Asin（ωx+φ）的图象变换．【分析】求得函数y的最小正周期，即有所对的函数式为y=2sin[2（x﹣）+]，化简整理即可得到所求函数式．【解答】解：函数y=2sin（2x+）的周期为T==π，由题意即为函数y=2sin（2x+）的图象向右平移个单位，可得图象对应的函数为y=2sin[2（x﹣）+]，即有y=2sin（2x﹣）．故选：D．7．一个几何体的三视图如图所示（单位长度：cm），则此几何体的体积是（）A．112cm3B．cm3 C．96cm3D．224cm3【考点】由三视图求面积、体积．【分析】几何体是一个简单的组合体，上面是一个正四棱锥，底面的边长是4，棱锥的高是2，下面是一个正四棱柱，底面是边长为4的正方形，侧棱长是4，根据棱锥的体积公式和棱柱的体积公式得到结果．【解答】解：由题意知几何体是一个简单的组合体，上面是一个正四棱锥，底面的边长是4，棱锥的高是2，下面是一个正四棱柱，底面是边长为4的正方形，侧棱长是4，∴几何体的体积是=（cm3）故选B．8．在下列区间中，函数f（x）=e x+4x﹣3的零点所在的区间为（）A．（，）B．（﹣，0）C．（0，）D．（，）【考点】函数零点的判定定理．【分析】根据导函数判断函数f（x）=e x+4x﹣3单调递增，运用零点判定定理，判定区间．【解答】解：∵函数f（x）=e x+4x﹣3∴f′（x）=e x+4当x＞0时，f′（x）=e x+4＞0∴函数f（x）=e x+4x﹣3在（﹣∞，+∞）上为f（0）=e0﹣3=﹣2＜0f（）=﹣1＞0f（）=﹣2=﹣＜0∵f（）•f（）＜0，∴函数f（x）=e x+4x﹣3的零点所在的区间为（，）故选：A9．如图所示，该程序框图运行后输出的结果为（）A．2 B．4 C．8 D．16【考点】程序框图．【分析】执行程序框图，依次写出每次循环得到的a，b的值，当a=4时，不满足a≤3，退出循环，输出b的值为8．【解答】解：执行程序框图，有a=1，b=1满足a≤3，b=2，a=2满足a≤3，b=4，a=3满足a≤3，b=8，a=4不满足a≤3，退出循环，输出b的值为8．故选：C．10．如图，正方体ABCD﹣A1B1C1D1中，直线BC1与平面A1ACC1所成的角为（）A．B．C．D．【考点】直线与平面所成的角．【分析】连接BD，BD∩AC=0，连接OC1，确定∠BC1O为直线BC1与平面A1ACC1所成的角，从而可得结论．【解答】解：连接BD，BD∩AC=0，连接OC1，由正方体的性质可得BO⊥AC，BO⊥AA1且AA1∩AC=A∴BO⊥平面AA1C1C∴∠BC1O为直线BC1与平面A1ACC1所成的角设正方体的棱长为a，则OB=a，BC1= a在Rt△BC1O中，sin∠BC1O===∴∠BC1O=故选D．11．函数y=2log4（1﹣x）的图象大致是（）A．B．C．D．【考点】函数的图象．【分析】利用函数的定义域以及函数的单调性判断函数的图象即可．【解答】解：由题意可知函数的定义域为：x＜1，函数是减函数．故选：C．12．函数f（x）=x2﹣2lnx的单调减区间是（）A．（0，1）B．（1，+∞）C．（﹣∞，1）D．（﹣1，1）【考点】函数的单调性及单调区间．【分析】求出函数的导数，令导数小于0，注意函数的定义域，解不等式即可得到单调减区间．【解答】解：函数f（x）=x2﹣2lnx（x＞0）的导数为f′（x）=2x﹣，令f′（x）＜0，解得0＜x＜1．即有单调减区间为（0，1）．故选A．二．填空题：本大题共4小题，每小题5分13．已知A（1，3），B（2，4），=（2x﹣1，x2+3x﹣3），且=，则x=1．【考点】平面向量的坐标运算．【分析】求出，利用向量相等，列出方程，求解即可．【解答】解：A（1，3），B（2，4），=（2x﹣1，x2+3x﹣3），=（1，1），=，可得：（2x﹣1，x2+3x﹣3）=（1，1），即，解得x=1．故答案为：1．14．不查表求tan105°的值为﹣2﹣．【考点】两角和与差的正切函数．【分析】根据tan105°=tan（60°+45°），利用两角和的正切公式求得它的值．【解答】解：tan105°=tan（60°+45°）===﹣2﹣，故答案为：﹣2﹣．15．若直线x﹣y=2被圆（x﹣a）2+y2=4所截得的弦长为2，则实数a的值为0或4．【考点】直线与圆相交的性质．【分析】由已知得圆心（a，0）到直线x﹣y=2的距离d==，由此利用点到直线的距离公式能求出实数a的值．【解答】解：∵直线x﹣y=2被圆（x﹣a）2+y2=4所截得的弦长为2，∴圆心（a，0）到直线x﹣y=2的距离d==，∴，解得a=0或a=4，故答案为：0或4．16．铁矿石A和B的含铁率a，冶炼每万吨铁矿石的CO2排放量b及每万吨铁矿石的价格c某冶炼厂至少要生产（万吨）铁，若要求2的排放量不超过（万吨）则购买铁矿石的最少费用为15（百万元）【考点】简单线性规划的应用．【分析】本题考查的知识点是简单线性规划的应用，由已知条件中，铁矿石A和B的含铁率a，冶炼每万吨铁矿石的CO2排放量b及每万吨铁矿石的价格c，对应的表格，再根据生产量不少于1.9（万吨）铁，及CO2的排放量不超过2（万吨）我们可以构造出约束条件，并画出可行域，利用角点法求出购买铁矿石的最少费用．【解答】解：设购买铁矿石A和B各x，y万吨，则购买铁矿石的费用z=3x+6yx，y满足约束条件表示平面区域如图，则当直线z=3x+6y过点B（1，2）时，购买铁矿石的最少费用z=15故答案为：15三．解答题：解答应写出文字说明，证明过程或演算步骤17．已知等差数列{a n}的前n项和为S n（n∈N*），a3=5，S10=100．（1）求数列{a n}的通项公式；（2）设b n=2+2n求数列{b n}的前n项和T n．【考点】数列的求和；等差数列的通项公式．【分析】（1）设等差数列{a n}的公差为d，由a3=5，S10=100．可得，解出即可得出；（2）b n=2+2n=22n﹣1+2n，利用等比数列与等差数列的前n项和公式即可得出．【解答】解：（1）设等差数列{a n}的公差为d，∵a3=5，S10=100．∴，解得，∴a n=2n﹣1．（n∈N*）．（2）b n=2+2n=22n﹣1+2n，∴数列{b n}的前n项和T n==．18．如图所示的四棱锥P﹣ABCD中，底面ABCD为菱形，PA⊥平面ABCD，E为PC的中点．（1）求证：PA∥平面BDE．（2）设AC=6，BD=4，PA=3，求四棱锥E﹣ABCD的体积．【考点】棱柱、棱锥、棱台的体积；直线与平面平行的判定． 【分析】（1）连接AC 交BD 于点O ，连接OE ，由中位线定理得出PA ∥OE ，故结论成立；（2）V E ﹣ABCD =V P ﹣ABCD ，代入体积公式计算即可． 【解答】证明：（1）连接AC 交BD 于点O ，连接OE ． ∵四边形ABCD 是菱形，∴O 为AC 的中点，又E 为PC 的中点， ∴EO ∥PA ．∵PA ⊄平面BDE ，EO ⊂平面BDE ， ∴PA ∥平面BDE ．（2）S 菱形ABCD ==12，V P ﹣ABCD =S 菱形ABCD •PA==12．∵E 为PC 的中点，∴V E ﹣ABCD =V P ﹣ABCD =6．19．某日用品按行业质量标准分成五个等级，等级系数X 依次为1，2，3，4，5．现从一批该20a 、b 、c 的值；（Ⅱ）在（Ⅰ）的条件下，将等级系数为4的3件日用品记为x 1，x 2，x 3，等级系数为5的2件日用品记为y 1，y 2，现从x 1，x 2，x 3，y 1，y 2，这5件日用品中任取两件（假定每件日用品被取出的可能性相同），写出所有可能的结果，并求这两件日用品的等级系数恰好相等的概率．【考点】概率的应用． 【分析】（I ）通过频率分布表得推出a +b +c=0.35．利用等级系数为4的恰有3件，等级系数为5的恰有2件，分别求出b ，c ，然后求出a ．（II ）根据条件列出满足条件所有的基本事件总数，“从x 1，x 2，x 3，y 1，y 2，这5件日用品中任取两件，等级系数相等”的事件数，求解即可．【解答】解：（I）由频率分布表得a+0.2+0.45+b+c=1，即a+b+c=0.35．因为抽取的20件日用品中，等级系数为4的恰有3件，所以b==0.15等级系数为5的恰有2件，所以c==0.1从而a=0.35﹣0.1﹣0.15=0.1所以a=0.1，b=0.15，c=0.1．（II）从x1，x2，x3，y1，y2，这5件日用品中任取两件，所有可能的结果为：{x1，x2}，{x1，x3}，{x1，y1}，{x1，y2}，{x2，x3}，{x2，y1}，{x2，y2}，{x3，y1}，{x3，y2}，{y1，y2}设事件A表示“从x1，x2，x3，y1，y2，这5件日用品中任取两件，等级系数相等”，则A包含的基本事件为：{x1，x2}，{x1，x3}，{x2，x3}，{y1，y2}共4个，又基本事件的总数为：10故所求的概率P（A）==0.420．如图，已知直线l：y=kx﹣2与抛物线C：x2=﹣2py（p＞0）交于A，B两点，O为坐标原点， +=（﹣4，﹣12）．（1）求直线l和抛物线C的方程；（2）抛物线上一动点P从A到B运动时，求△ABP面积最大值．【考点】抛物线的简单性质．【分析】（1）把直线与抛物线方程联立，设出A，B的坐标，利用韦达定理表示出x1+x2，进而根据直线方程求得y1+y2的表达式，然后利用+=（﹣4，﹣12）求得p和k，则直线l 和抛物线C的方程可得．（2）设P（x0，y0），依题意，抛物线过P的切线与l平行时，△APB面积最大；对抛物线方程求导，求得x0，代入抛物线方程求得y0，点P的坐标可得，进而利用点到直线的距离求得P到直线l的距离把直线方程与抛物线方程联立，利用弦长公式求得|AB|，最后求得∴△ABP 的面积最大值．【解答】解：（1）由得，x2+2pkx﹣4p=0，设A（x1，y1），B（x2，y2），则x1+x2=﹣2pk，y1+y2=k（x1+x2）﹣4=﹣2pk2﹣4，因为+=（x1+x2，y1+y2）=（﹣2pk，﹣2pk2﹣4）=（﹣4，﹣12），所以，解得，所以直线l的方程为y=2x﹣2，抛物线C的方程为x2=﹣2y；（2）设P（x0，y0），依题意，抛物线过P的切线与l平行时，△APB面积最大，y′=﹣x，所以﹣x0=2⇒x0=﹣2，y0=﹣x02=﹣2，所以P（﹣2，﹣2）．此时P到直线l的距离d==，由得，x2+4x﹣4=0，|AB|==4，∴△ABP的面积最大值为×4×=8．21．已知函数f（x）=xlnx．（1）求函数f（x）的极值点；（2）设函数g（x）=f（x）﹣2（x﹣1），求函数g（x）在区间[1，e]上的最小值．（其中e为自然对数的底数）．【考点】利用导数求闭区间上函数的最值；利用导数研究函数的极值．【分析】（1）先求导，根据导数和函数的极值的关系即可求出极值点；（2）先求导，再判断g（x）在[1，e]上的单调性，根据单调性即可求出最值．【解答】解：（1）f′（x）=lnx+1，x＞0，由f′（x）=0，得x=，所以f（x）在区间（0，）上单调递减，在区间（，+∞）上单调递增．所以，x=是函数f（x0的极小值点，极大值点不存在．（2）g（x）=f（x）﹣2（x﹣1）=xlnx﹣2x+1 则g′（x）=lnx﹣1，由g′（x）=0，得x=e，g（x）在[1，e]上单调递减，所以g（x）的最小值为g（e）=2﹣e．选做题（请考生在第22、23、24题中任选一题作答，如果多做，则按所做的第一题计分）22．如图，E是圆内两弦AB和CD的交点，直线EF∥CB，交AD的延长线于F，FG切圆于G．（1）求证：∠AEF=∠EDF；（2）设EF=6，求FG的长．【考点】与圆有关的比例线段．【分析】（1）利用切割线定理可得FG2=FD•FA，利用EF=FG，可得=，从而可得△EFD∽△AFE，由此能证明∠AEF=∠EDF（2）由△DFE∽△EFA，得EF2=FA•FD．由FG是圆的切线，得FG2=FA•FD．由此能求出FG的长．【解答】证明：（1）∵FG与圆O相切于点G，∴FG2=FD•FA，∵EF=FG，EF2=FD•FA，∴=，∵∠EFD=∠AFE，∴△EFD∽△AFE．∴∠AEF=∠EDF．（2）由（1）知△DFE∽△EFA，∴=，即EF2=FA•FD．∵FG是圆的切线，∴FG2=FA•FD．∴FG2=EF2，∵EF=6，∴FG=EF=6．23．在直角坐标系xOy中，曲线C1的参数方程为（t为参数），以O为极点，Ox正半轴为极轴建立极坐标系，曲线C2的极坐标方程为ρ=4cosθ．（1）求曲线C1的直角坐标方程；（2）设C1与C2相交于A，B两点，求A，B两点的极坐标．【考点】参数方程化成普通方程．【分析】（1）将，消去t，曲线C1的直角坐标方程；（2）由ρ=4cosθ，得ρ2=4ρcosθ，求得曲线C2的方程直角坐标x2+y2﹣4x=0，解方程即可求得其交点坐标，即可求得A，B两点的极坐标．【解答】解：（1）由线C1的参数方程为，消去t得：x+y﹣4=0，∴曲线C1的直角坐标方程x+y﹣4=0；（2）由ρ=4cosθ，得ρ2=4ρcosθ，即x2+y2﹣4x=0，，解得：，，曲线C1与曲线C2交点的坐标为（2，2），（4，0），∴A，B两点的极坐标（2，），（4，0）．24．已知函数f（x）=|x﹣|+|x+|，M为不等式f（x）＜2的解集．（Ⅰ）求M；（Ⅱ）证明：当a，b∈M时，|a+b|＜|1+ab|．【考点】绝对值不等式的解法．【分析】（I）分当x＜时，当≤x≤时，当x＞时三种情况，分别求解不等式，综合可得答案；（Ⅱ）当a，b∈M时，（a2﹣1）（b2﹣1）＞0，即a2b2+1＞a2+b2，配方后，可证得结论．【解答】解：（I）当x＜时，不等式f（x）＜2可化为：﹣x﹣x﹣＜2，解得：x＞﹣1，∴﹣1＜x＜，当≤x≤时，不等式f（x）＜2可化为：﹣x+x+=1＜2，此时不等式恒成立，∴≤x≤，当x＞时，不等式f（x）＜2可化为：﹣+x+x+＜2，解得：x＜1，∴＜x＜1，综上可得：M=（﹣1，1）；证明：（Ⅱ）当a，b∈M时，（a2﹣1）（b2﹣1）＞0，即a2b2+1＞a2+b2，即a2b2+1+2ab＞a2+b2+2ab，即（ab+1）2＞（a+b）2，即|a+b|＜|1+ab|．2016年10月20日。

1 2018-2019年最新湖南邵东县第一中学自主招生考试 英语模拟精品试卷 （第一套）

考试时间：120分钟 总分：150分 第I卷（选择题，共100分） 第一节：单项填空（共25小题，每小题1分，满分25分） 1. —When did the terrible earthquake in YaNan happen? —It happened ________ the morning of April 20, 2013. A. on B. at C. in D. / 2. Our teacher told us ________ too much noise in class. A. to make B. make C. not to make D. not make 3. Here is your hat. Don’t forget______ when you __________. A. to put it on, leave B. to wear it, leave C. to wear it, will leave D. putting it on, will leave 4. The baby is sleeping. You _____ make so much noise. A. won’t B. mustn’t C. may not D. needn’t 5. Since you are _____ trouble, why not ask _________ help? A. in, for B. in, to C. with, for D. with, to 6. It’s about___________kilometers from Nanchong to Chengdu. A. two hundreds B. two hundreds of C. two hundred D. two hundred of 7. It is six years since my dear uncle ________China. A. left B. has left C. is left D. had left 8. —How long _______ you _______ the bicycle? —About two weeks. A. have, had B. have, bought C. did, buy D. have, have 9. The Yellow River is not so ________ as the Yangtze River. A. longer B. long C. longest D. a long 10. Mrs.Green usually goes shopping with ________ umbrella in ________ summer. A. a；the B. an； / C. the； a D. /；/ 2

邵东一中2018年下学期高一第三次月考英语答案第一部分听力（共20题，满分20分）1-5 BCBBA 6-10 CCBAA 11-15 BCACC 16-20 BBACA第二部分阅读理解（共15题，满分30分）21-35 CACDA D A CBA CCDBA第三部分英语知识运用（共两节，满分45分）第一节完形填空(共20小题；每小1.5分，满分30分)36-55 CDBCA DBABC DAACD BABDC第二节语法填空(共10小题；每小题1.5分，满分15分)56. Walking57. with58. tracks59. examined60. ran61. However62. has been found63. existence64. which65. really第四部分写作（满分25分）第一节：单词拼写（满分10分）66. unexplained67. possibility68. confused/puzzled69. insisted70. energetic71. Devoted72. forbade73. challenging74. preparation75. approval第二节：书面表达（满分15分）Dear Sir or Madam,I’m Li Hua, planning to visit Britain with my parents. Would you please give me some advice?As you know, Britain is a country with a long history and so many world-famous attractions. However, I can’t visit them at a time. What we are most eager to visit are Big Ben, Cambridge University, Oxford University, the London Eye and the Buckingham Palace. Can you give me some information on the cost and how much time it will take to visit each place so that I can plan my travel in advance? I would appreciate it if you could recommend an economical and pleasant travelling route.I’m looking forward to your early reply.YoursLi Hua。

英语 (试题卷)注意事项：1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

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第一部分听力(共两节，满分30分)第一节 (共5小题；每小题1.5分，满分7.5分)听下面5段对话，每段对话后有一个小题，从题中所给的A、B、C三个选项中选出佳选项。

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1. When should the man have his ticket checked?A. At 6:45p. m.B. At 7:15p. m.C. At 7:30p. m.2. What does Tom Green do?A. A student.B. A writer. C A doctor.3. What is the probable relationship between the speakers?A. Neighbors.B. Husband and wifeC. Doctor and patient.4. According to the woman, what financial responsibility can Kevin take?A. College fee.B. Living expenses.C. Phone bills.5. Why does the woman want to quit her job?A. To work in a flexible environment.B. To concentrate more on work.C. To find a more challenging job.第二节 (共15小题; 每小题1.5分, 满分22.5分)听下面5段对话或独白。