绵阳市高2013级第一次诊断性考试
理科综合能力测试 物理部分参考答案及评分标准
第Ⅰ卷（选择题，共42分）
在每题给出的四个选项中，只有一个选项是最符合题目要求的。共7题，每题6分。
1.C
2.D
3.A
4.B
5.B
6.AC
7.BD
第Ⅱ卷（选择题，共 分）
8.（16分）
（1）①AC （3分）；②A （3分）。
（2）①CD （2分）；②1.56（3分）；能（2分）;
③9.70～9.90都给分（3分）。
9. （15分）
（1）设“嫦娥一号”的质量是m 1，则
()221
214)(T H R m H R Mm G π+=+ ………………(4分) 2
32)(4GT H R M +=π ………………(2分) (2)设月球表面的重力加速度为g ，则
mg R Mm G =2
………………(3分) r m
mg F 2υ=- ············································································································ (4分) 解得r
m T R m H R F 2
2232)(4υπ++= ··············································································· (2分)
10．（17分）
（1）设小滑块上滑的加速度大小是a 1，则
ma 1= mg sin θ＋μmg cos θ ···························································································· (2分) v 0=a 1t ·························································································································· (2分) 解得a 1=7.2 m/s 2，t =2.5 s ·························································································· (2分)
（2）小滑块从斜面底端上滑到最高处的过程中，设沿斜面上滑的距离是x ，根据动能定理有 0－202
1υm =－mgh －μmgx cos θ ·················································································· (2分) h = x sin θ ······················································································································ (2分) 解得h =13.5 m ············································································································ (2分)
另解：2a 1x =20υ ········································································································ (2分)
h = x sin θ ······················································································································ (2分) 解得h =13.5m ··········································································································· (2分)
（3）根据功能关系有△E =2μmgx cos θ ···································································· (3分) 解得△E = 10.8 J ········································································································ (2分)
11.（20分）
解：（1）设小滑块能够运动到C 点，在C 点的速度至少为v c ，则
R
m mg c 2υ= ·················································································································· (2分) mgL mgR m m c μυυ--=-22
121202 ·············································································· (2分) 解得v 0=152m/s ····································································································· (1分)
(2)设传送带运动的速度为v 1，小滑块在传送带上滑动时加速度是a ，滑动时间是t 1，滑动过程中通过的距离是x ，则
v 1=r ω ······················································································································ (1分) ma =μmg ···················································································································· (1分) v 1=at 1 ························································································································ (1分) 212
1at x = ····················································································································· (1分) 解得v 1=2m/s ，a =4m/s 2，t 1=0.5s ，x =0.5m
由于x ＜L ，所以小滑块还将在传送带上与传送带相对静止地向B 点运动，设运动时间为t 2，则
L －x = v 1t 2 ················································································································· (2分) 解得t 2=2.25s
则t = t 1＋t 2=2.75s ······································································································ (2分)
（3）轮子转动的角速度越大，即传送带运动的速度越大，小滑块在传送带上加速的时间越长，达到B 点的速度越大，到C 点时对圆轨道的压力就越大。
小滑块在传送带上一直加速，达到B 点的速度最大，设为v Bm ，对应到达C 点时的速度为v cm ，圆轨道对小滑块的作用力为F ，则
aL Bm 22=υ ·
················································································································ (2分) mgR m m Bm cm 22
12122-=-υυ ························································································ (2分) R
m F m g cm 2υ=+ ········································································································· (1分) F m =F ······················································································································· (1分) 解得F m =5N ·············································································································· (1分)