通信网基本概念与主体结构答案
- 格式:doc
- 大小:35.50 KB
- 文档页数:4
计算机网络基础练习题库含参考答案一、单选题(共73题,每题1分,共73分)1.在TCP/IP协议簇的层次中,解决计算机之间通信问题是在()A、网络接口层B、网际层C、传输层D、应用层正确答案:B2.哪种网络设备可以屏蔽过量的广播流量?()A、集线器B、路由器C、交换机D、防火墙正确答案:B3.传输层的作用是向源主机与目的主机进程之间提供数据传输。
A、点到点B、端到端C、点到多点D、多端口之间正确答案:B4.在指定单选框时,只有将以下()属性的值指定为相同,才能使它们成为一组。
A、valueB、nameC、typeD、checked正确答案:B5.IP地址可以标识Internet上的每台电脑,但是它很难记忆,为了方便,我们使用()给主机赋予一个用字母代表的名字。
A、DNS域名系统B、WindowsNT系统C、UNIX系统D、数据库系统正确答案:A6.路由器的缺点是()。
A、无法进行流量控制B、无法隔离广播C、成为网络瓶颈D、不能进行局域网联接正确答案:C7.以下属于低层协议的是()。
A、FTPB、IPC、UDPD、TCP正确答案:B8.以下不属于应用层协议的是()A、TELNETB、SNMPC、HTTPD、RIP正确答案:D9.在对OSI参考模型中,自下而上第一个提供端-端服务的层次是。
A、数据链路层B、传输层C、网络层D、物理层正确答案:B10.在TCP/IP协议配置好后,Ipconfig命令显示的结果不包括下列_______。
A、本机IP地址。
B、网关的IP地址C、子网掩码D、DNS服务器地址正确答案:D11."WWW最初是由_____实验室研制的。
A、CERNB、AT&TC、ARPAD、MicrosoftInternetLab"正确答案:C12.关于虚拟局域网特征的描述中,错误的是。
A、虚拟局域网是建立在局域网交换技术基础上的。
B、逻辑工作组的节点组成不受物理位置的限制。
第一章概论通信系统的组成可以把通信系统概括为一个统一的模型。
这一模型包括有:信源、变换器、信道、噪声源、反变换器和信宿六个部分。
通信网的基本概念通信网是由一定数量的节点(包括终端设备和交换设备)和连接节点的传输链路相互有机地组合在一起,以实现两个或多个规定点间信息传输的通信体系。
也就是说,通信网是由相互依存、相互制约的许多要素组成的有机整体,用以完成规定的功能。
通信网的构成要素通信网在硬件设备方面的构成要素是终端设备、传输链路和交换设备。
为了使全网协调合理地工作,还要有各种规定,如信令方案、各种协议、网路结构、路由方案、编号方案、资费制度与质量标准等,这些均属于软件。
终端设备:是用户与通信网之间的接口设备。
传输链路:是信息的传输通道,是连接网路节点的媒介。
交换设备:是构成通信网的核心要素,它的基本功能是完成接入交换节点链路的汇集、转接接续和分配。
通信网的基本结构通信网的基本结构主要有网形、星形、复合形、总线形、环形、树形和线形通信网的质量要求对通信网一般提出三个要求:●接通的任意性与快速性;●信号传输的透明性与传输质量的一致性;●网路的可靠性与经济合理性。
对电话通信网是从以下三个方面提出的要求接续质量:电话通信网的接续质量是指用户通话被接续的速度和难易程度,通常用接续损失(呼损)和接续时延来度量。
传输质量:用户接收到的话音信号的清楚逼真程度,可以用响度、清晰度和逼真度来衡量。
稳定质量:通信网的可靠性,其指标主要有:失效率(设备或系统投入工作后,单位时间发生故障的概率)、平均故障间隔时间、平均修复时间(发生故障时进行修复的平均时长)等等。
现代通信网的构成一个完整的现代通信网,除了有传递各种用户信息的业务网之外,还需要有若干支撑网,以使网络更好地运行。
业务网业务网也就是用户信息网,它是现代通信网的主体,是向用户提供诸如电话、电报、传真、数据、图像等各种电信业务的网络。
业务网按其功能又可分为用户接入网、交换网和传输网三个部分。
1. 什么是通信网?具体功能是什么?概念:为了完成多用户中任意两个用户之间信源与信宿间的通信过程,需要建立一个网络,这个多用户通信系统互连的通信体系称之为通信网。
(课本)概念:通信网是由一定数量的节点(包括终端节点,交换节点)和连接这些节点的传输系统有机结合在一起,按约定的信令或协议完成任意用户间信息交换的通信体系。
可以克服空间时间等障碍,来进行有效信息交换。
(老师总结的答案)功能:信息传输寻址和路由差错控制网络管理2. 通信的概念和功能。
通信就是将带有信息的信号通过某种方式由发送者向接收者的传递或相互之间的交换。
3. 画图说明通信系统的组成并说明其功能。
图(课本第一页,图1-1)(1)信源:是发出信息的基本设施。
(2)信宿:即受信者,是信息传输的终点设施。
(3)信道:即信息的传输介质。
(4)调制发射系统:该系统的任务是将信源产生的基带信号调制成适合在给定信道中传输的信号,然后通过发射系统将信号发射出去。
(5)解调接收系统:将信道传输中带有噪声和干扰的信号解调成基带信号交给信宿。
4. 通信网的硬件组成终端设备传输设备及链路交换设备5. 通信网的分类按功能分:业务网传送网支撑网支撑网:1.信令网:实现网络节点间信令的传输和转接的网络2.同步网:实现数字设备之间的时钟信号同步的网络3.电信管理网:为提高全网质量和充分利用网络设备而设置,以达到在任何情况下,最大限度的利用网络中的一切可以利用的设备,使尽可能多的通信得以实现。
按业务类型划分:电话通信网数据通信网广播通信网电报网传真网按地理位置分:本地网长途网国际网按传输的信号形式分:数字网模拟网按传输介质分:有线通信网无线通信网按网络功能分:业务网传送网支撑网按运营方式分:公用通信网专用通信网6. 通信网体系结构OSI/RM参考模型:物理层,数据链路层,网络层,传输层,会话层,表示层,应用层课本第九页,图1-5TCP/IP参考模型:网络接口层,互联层(网络层),传输层,应用层课本第10页,图1-77. 通信网的基本拓扑结构网形星形复合形总线形环形树形课本13页,14页,图1-13 1-15 1-14 1-10 1-11 1-128. 电话通信网的组成发送和接收电话信号的“用户环路”设备,进行电路交换的节点设备,连接交换设备之间的中继链路。
通信综合试题一、单选题1.在全程全网中,俗称“最后一公里”的是指。
*A.接入网B.传输网C.交换网D.支撑网2.传输网主要实现设备间进行数据传递,目前最常用的传输技术是。
A.HFCB.ATM*C.SDHD.PDHx3. 在数据通信中最基本的同步方式就是A. 帧同步B. 准同步C. 网同步*D. 位同步4.帧同步是通过在信息码流中插入实现的。
A. 同步码B. 准同步码C. 网同步码*D. 帧同步码5.我国数字同步网采用的节点时钟结构中,哪一级是全网的基准时钟源*A. 一级时钟B. 二级时钟C.三级时钟D. 主从时钟6.下面哪个是属于传输媒体?A. 光盘 =存储媒体*B. 光缆C.RAMD. 硬盘7.音频信息处理的关键技术是A. 音频信息的数字化B. 音频信息的抗干扰C.音频信息的传输*D. 音频信息的压缩8.图像压缩的基本目标是A. 提高信息传输速度B. 提高比特率*C.减小数据量D. 增加信道容量9.同步时分复用是指将时间划分为基本时间单位,1帧占用时长为。
A.100μs*B.125μsC.250μsD.25μs10.在整个光交换过程中,信号是以什么形式存在的?*A.光的形式B.电的形式C.光电转换的形式D.电光转换的形式11.下列哪些是无失真图像压缩编码方法A. 量化编码B. 混合编码C.子带编码*D. 游程编码12.电路交换网络中多采用传输。
*A. 恒比特率B. 变比特率C.高比特率D. 低比特率13.为了获得真实临场感,通信网络对语音和图像的传输时延都要*A. 小于0.25sB. 小于0.15msC.小于0.15sD. 小于0.25msx14.下列哪个不是基于网络层的多播A. 使用网络硬件提供的多播能力实现组通信B. 利用一对一进程间的通信机制实现C.使用网络广播机制实现D. 大量节约系统资源实现通信15. 网络使用路由协议建立多播树,其过程中多播源把数据或者广播通知发送给*A. 所有的路由器B. 同一网关路由器C.所有协调器节点D. 同一网关的协调器节点16.在ATM交换机中,广泛应用的交换网络是A.CLOS网络B.TST网络C.DSN网络*D.banyan网络17.下列哪些属于七层网络互联模型?一57 。
对口高考各科网络基础习题库(含参考答案)一、单选题(共67题,每题1分,共67分)1.以下关于TCP和UDP协议的描述中,正确的是()A、TCP是端到端的协议,UDP是点到点的协议B、TCP是点到点的协议,UDP是端到端的协议C、TCP和UDP都是点到点的协议D、TCP和UDP都是端到端的协议正确答案:D2. 防火墙是隔离内部和外部网的一类安全系统。
通常防火墙中使用的技术有过滤和代理两种。
路由器可以根据()进行过滤,以阻挡某些非法访问。
A、用户标识B、网卡地址C、加密方法D、IP地址正确答案:D3. 细同轴电缆传输的距离是()。
A、200米B、100米C、50米D、500米正确答案:A4.IP报文头中固定长度部分为()字节A、30B、10C、20D、40正确答案:C5. 防火墙中地址翻译的主要作用是:()A、隐藏内部网络地址B、进行入侵检测C、防止病毒入侵D、提供应用代理服务正确答案:A6.在IP层中,信息传输的基本单元是。
A、文件B、位串C、数据分组D、记录正确答案:C7.以太网交换机的每一个端口可以看做一个()A、冲突域B、广播域C、管理域正确答案:A8.IP报文头中固定长度部分为()字节A、10B、40C、20D、30正确答案:C9.UDP提供面向( )的传输服务。
A、端口B、地址C、连接D、无连接正确答案:D10.检查网络联通性的命令是()A、pingB、routeC、ipconfigD、telnet正确答案:A11.双绞线有两个具有绝缘保护层的铜导线按一定密度互相绞绕在一起组成,这样可以()A、降低成本B、降低信号干扰的程度C、提高传输速度D、无任何作用正确答案:B12.常用来查看本地主机 IP 地址的命令是()A、telnetB、ipconfigC、routeD、ping正确答案:B13. 以下传输介质性能最好的是( ) 。
A、同轴电缆B、电话线C、双绞线D、光纤正确答案:D14.个人计算机通过电话线拨号方式接入因特网时,应使用的设备是__ ____。
(单选题)1 : 1 9 0. 2 33.27. 13 是()IP 地址。
A: A类B: B类C: C类I): D 类对的答案:(单选题)2:使用距离矢量路由选择协议的路由器通过以下哪种方式获得最佳途径A:通过向相邻路由器发送一次广播以询问最佳途径B:运营最短途径优先(SPF)算法C:将接受到的途径的度量增长1D:测试每条途径对的答案:(单选题)3:下列功能中,属于表达层提供的功能是()。
A:拥塞控制B:透明传输C:死锁解决D:文本压缩对的答案:(单选题)4: Web上每一个页都有一个独立的地址,这些地址称作统一资源定位器,即()。
A:URLWWWC: HTTPD: USL对的答案:(单选题)5:下面四种答案中,哪一种属于网络操作系统()。
A: DOS操作系统B : Wi n dows9 8操作系统C: WindowsNT操作系统D:数据库操作系统对的答案:(单选题)6:一条线路每1/1 6秒采样一次,传输信号共有16种状态,则其传输速率为()。
A:16b p s4 8 bpsC: 64bps(单选题)13:以下哪个应用是基于ICMP协议应用的?A:文献传输B:电子邮件B:P I NG程序I): BBS对的答案:(单选题)14: HTML语言可以用来编写Web文档,这种文档的扩展名是()。
A:dochtm 或 h t m 1C: txtD: xls对的答案:(单选题)15: In t ernet 称为()。
A:国际互联网B:广域网C:局域网D:世界信息网对的答案:(单选题)16:()是实现数字信号和模拟信号转换的设备。
A:网卡B:调制解调器C:网络线D:都不是对的答案:(单选题)17:主机甲与主机乙之间已建立一个TCP连接,主机甲向主机乙发送了两个连续的TCP段,分别包含300字节和500字节的有效载荷,第•个段的序列号为20 0,主机乙对的接受两个段后,发送给主机甲的确认序列号是()。
A: 500B : 700C: 800I): 1000对的答案:D: 256bps对的答案:(单选题)7:接受端不仅能发现差错,并且能拟定差错发生的位置从而加以纠正的差错控制方法为()。
通信网基本概念与主体结构答案每一个抄通信网的学生都是头疼的天使----Laofuzi Communication Networks 2nd Edition Chapter 10 Solutions Solutions to Chapter 10 10.1. Can all traffic in an IntServ router be of guaranteed service type Explain. Solution: All the traffic can be of guaranteed service only if all the flows are shaped and if they strictly comply with the traffic specifications. However in practice the total amount of traffic that can be admitted will have some limit. The reason is that to bound the delay the maximum queue length in the router must be below a certain threshold. If all of the flows are well behaved and without bursts the queue size will always be reasonably small. However if the flows are bursty the queue may grow to levels that can cause large unacceptable delays. To guarantee the delay bounds extra bandwidth should be assigned based to accommodate the burstiness of the flows. This overbooking can sometimes lead to the queue becoming empty and hence result in underutilization of the output link. Thus it is reasonable to fill the output bandwidth during such periods with best effort traffic. So in summary to efficiently utilize the bandwidth and achieve higher throughputs it is necessary to admit best effort traffic alongside guaranteed service traffic. 10.2. Develop a packet-scheduling approach to provide guaranteed service controlled load service and best effort service in a router. Can any mix of these three traffic types be supported Explain. Solution: Separate queues must be provided for the packets from each type of service in order for their packets to be serviced appropriately. The set of queues belonging to guaranteed service should always receive service with a rate R which should be larger than the total guaranteed service traffic. The aggregate rate R is guaranteed and controlled by giving priority to the guaranteed service queues and controlling the service they receive by a leaky bucket shaper with a sustained rate of R. Individual queues within the guaranteed service group are serviced in a round-robin fashion while for each queue its service is controlled by a dedicated leaky bucket shaper with the parameters set based on the requirements of the flow assigned to that queue. The set of controlled load service queues are serviced during the periods that guaranteed service queues are not serviced. The capacity in excess of R is available to controlled load traffic. Flows are assigned to different queues and weighted fair queueing can be used within the group to service the queues depending on their requirements. Best effort traffic is given the lowest priority. The queue is serviced only if the other two sets of queues are empty. 10.3. RSVP signaling is very different from ATM signaling. Discuss the differences and list the advantages and disadvantages of each protocol. Solution: RSVP uses Receiver-Initiated Reservation rather than ATM’s per-hop path request to reserve network resources. RSVP is intended for use with multicasting and is receiver oriented. ATM is designed for unicast traffic and is sender oriented. RSVP receiver-initiated reservation Advantage: interoperates with non-RSVP routers soft state provides robustness with respect to faults requests can be merged reducing the reservation load on the routers. Disadvantage: soft state – requires periodic updates receiver needs to know the path for connection. Leon-Garcia/Widjaja 1每一个抄通信网的学生都是头疼的天使----Laofuzi Communication Networks 2nd Edition Chapter 10 Solutions ATM per-hop path request Advantage: hard state –reserve only once. Disadvantage: Individual VCC is required for each host in multicast application. Source requests the connections so it needs to know the requirements of the receiver. 10.4. Consider the merging of reservations in RSVP. Suppose that there is a single sender and 2n receivers that are reached through a path that consists of a depth n binary tree that has a router located at each node. What is the total number of reservation request messages generated by the receivers Solution: The total number of reservation request messages generated by thereceivers and routers are equivalent to finding the branches of a binary tree with a depth of n. Let Nn be the number of branches in a binary tree with depth n. At level n there 2n new branches and so we have the recursion Nn Nn–1 2n. Draw a picture of a tree to verify this. It is easy to then verify that Nn total number of request messages is 2n1 – 1. 10.5. Suppose RSVP is used to set up a virtual private network to interconnect n users across an Internet. Discuss the appropriateness of the three RSVP reservation styles for this application. RSVP has three reservation styles Wildcard Filter Fixed Filter and Shared Explicit. Wild card filter WF creates a single reservation shared by all senders. It is designed for applications that are unlikely to have multiple senders transmitting simultaneously. It is not appropriate for VPN applications because WF cannot provide the receiver requests if more than one sender is transmitting at the same time. Fixed filter FF creates a distinct reservation for each sender. It is an appropriate solution for VPN requirements. Each sender VPN has its own resource reservation and this resource is shared by number of receivers hosts located in different location belong to the same VPN. Shared explicit SE creates a single reservation shared by a set of explicit senders. It may also be appropriate in VPN applications under certain conditions. The merging of the reservation between senders can result in a more efficient use of network resources. 10.6. Select and justify a choice an RSVP reservation style that is appropriate for the following situations: Solutions follow questions: a A multiuser application where a video stream from each participant must be delivered to every other participant. This situation is a multipoint to multipoint application so the Fixed Filter FF is the appropriate choice. FF creates a distinct reservation for each participant sender and it can merge downstream requests and forward the sum of flow spec upstream. It is an appropriate reservation style because each participant sender will only receive a single reservation request that has been merged by a multiple of other participants. This simplifies the processing overhead for each sender and allows the processing power to focus on accepting multiple video streams for other participants. b An audioconferencing application that is self-limiting in that more than two participants are unlikely to speak simultaneously. This audio conferencing application is best suited with the Wild card Filter WF style. The WF-style is suitable for applications that are unlikely to have multiple senders transmitting simultaneously. In this application the self-limiting feature prevents two participants from speaking simultaneously. Leon-Garcia/Widjaja 2每一个抄通信网的学生都是头疼的天使----Laofuzi Communication Networks 2nd Edition Chapter 10 Solutions c A multiuser application in which each participant must receive explicit permission before transmitting information. The Shared Explicit SE reservation style is best suited for this multiuser application. The SE style creates a single reservation shared by a set of explicit senders. In this application only the participant that receives an explicit permission is allowed to join a single reservation. Any participant that does not receive permission is not allowed to use this single reserved resource.10.7. What information needs to be carried by Resv messages in RSVP to set up guaranteed IP service with a specific bandwidth and a given delay-bound requirement How does a router process this information Solution: The information that must be carried by Resv message in RSVP to set up guaranteed IP service with a specific bandwidth and a given delay bound is: the common header SESSION RSVP_HOP TIME_V ALUES STYLE and Fixed Filter flow descriptor along with flow spec and filter spec. When a router receives this Resv message it reserves the necessary resources based on the flow specification which in turn governs the bandwidth and delay-bound requirements. Next the router exams the filter spec to determine the data packets that correspond to the defined flow spec. 10.8. Discuss the interplay between a QoS routing algorithm RSVP andintegrated services IP. Solution: Integrated services IP provides QoS packet delivery between the source and destination pair. The QoS parameters are dependent on the source requirements for example bandwidth requirement and delay-bound requirement. To provide integrated services it is necessary for the routing protocol network layer to provide QoS routing. QoS routing provides for the selection of paths with specific attributes that can support specified QoS requirements. RSVP provides the means for reserving resources along paths identified by QoS routing. 10.9. Explain how the soft-state feature of RSVP allows it to adapt to failures in the network. Solution: The RSVP soft-state approach requires each node to refresh its reservation periodically by using Path and Resv messages. When a state is not refreshed within a certain time-out period the state is deleted. Upon a link failure within the network a PathErr message is sent to the ingress node source node. The ingress node simply defines a new route by refreshing the Path message to a different next hop. The old failure path will eventually tear down after the timer is expired. This approach provides error recovery upon failure however it is necessary for the ingress node to keep updating the status of the link-state topology and determine the next possible route in case of the primary route fails. 10.10. Discuss whether RSVP provides a scalable means to set up connections to a session that consists of the broadcasting of a given TV program. Solution: Broadcasting a TV program is a point to multipoint multicast application. RSVP does provide a scalable means to set up connections to a session in multicast application. RSVP performs the resource reservation for multicast applications adapting dynamically to changing group membership and changing route. Also RSVP requires the receiver to initiate and maintain the resource reservation rather than obtaining the bandwidth requirement from each receiver. This process avoids an implosion problem and minimizes the processing overhead to the sender. Finally the RSVP routers provide different reservation styles and the requests can merge in several ways according to Leon-Garcia/Widjaja 3每一个抄通信网的学生都是头疼的天使----Laofuzi Communication Networks 2nd Edition Chapter 10 Solutions the reservation style. This prevents duplicate resource reservations if multiple downstream receivers belong to the same multicast group. 10.11. Explain what happens if RSVP is used to set up small-bandwidth flows on a large-bandwidth link How well does RSVP scale in this situation Solution: If RSVP is used to set up small-bandwidth flows on a large-bandwidth link the router will have to update the available resource bandwidth every time there are small-bandwidth flow request for resources. Moreover the router needs to keep track of the available resources and reject resource reservation requests when the available bandwidth cannot support a particular requirement. The router has to keep track of every single flow resource usage during the setup and tear down procedure. All of these activities consume a lot of processing power when the link has large bandwidth being shared by large numbers of small-bandwidth flows. 10.12. Obtain a packet capture file for RSVP either in the lab or downloaded from a web site. Examine the details of Path Resv and refresh messages. Solution: The following text shows the details of the first PATH message for MPLS path setup shown in Figure 2.27. The file is obtained by printing the capture data from Ethereal. We highlight in color the main fields and interesting information. In particular note the explicit route identified in the message and the LABEL REQUEST. The TIME V ALUES field is set to 30000 ms that is 30 second refresh period. Frame 1 306 bytes on wire 306 bytes captured Arrival Time: Feb 10 2000 08:49:03.806994000 Time delta from previous packet: 0.000000000 seconds Time relative to first packet: 0.000000000 seconds Frame Number: 1 Packet Length: 306 bytes Capture Length: 306 bytes Ethernet II Src: 00:90:92:9d:94:01 Dst: 00:d0:63:c3:b8:47 Internet Protocol Src Addr:17.3.3.3 17.3.3.3 Dst Addr: 16.2.2.2 16.2.2.2 Resource ReserVation Protocol RSVP: PATH Message. SESSION: IPv4-LSP Destination 16.2.2.2 Tunnel ID 1 Ext ID 11030303. SENDER TEMPLATE: IPv4-LSP Tunnel Source: 17.3.3.3 LSP ID: 1. RSVP Header. PA TH Message. RSVP Version: 1 Flags: 00 Message Type: PATH Message. 1 Message Checksum: 0xdb58 correct Sending TTL: 254 Message length: 264 SESSION: IPv4-LSP Destination 16.2.2.2 Tunnel ID 1 Ext ID 11030303. Length: 16 Class number: 1 - SESSION object C-type: 7 - IPv4 LSP Destination address: 16.2.2.2 16.2.2.2 Tunnel ID: 1 Extended Tunnel ID: 285410051 17.3.3.3 HOP: IPv4 210.0.0.1 Length: 12 Class number: 3 - HOP object C-type: 1 - IPv4 Neighbor address: 210.0.0.1 Leon-Garcia/Widjaja 4每一个抄通信网的学生都是头疼的天使----Laofuzi Communication Networks 2nd Edition Chapter 10 Solutions Logical interface: 0 TIME V ALUES: 30000 ms Length: 8 Class number: 5 - TIME V ALUES object .。