2015-2016学年福建省福建师大附中高二下学期期末考试英语(解析版)

2015―2016学年高二年级下学期英语期末试卷（本试卷共120分，考试时间100分钟）注意事项：1答题前，考生务必将自己的姓名、准考证号填写在答题卡相应的位置并涂号。

2.全部答案在答题卡上完成，答在本试卷上无效。

3.用黑色笔迹的签字笔将答案写在答题卡上，写在本试卷上无效。

第I卷第二部分、阅读理解(共两节，满分40分)第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项(A, B, C和D)中，选出最佳选项.并且在答题卡上将该项涂黑。

AMoscow Sheremetyevo International AirportIf You’ve Lost Personal Belongings●On Board —Contact the airline’s representatives●At the Airport —Contact:—Sheremetyevo Police Department ……+7(495)578-22-55—Unclaimed luggage storage room in Terminal C ……+7(495)578-23-26—Unclaimed luggage storage room in Terminal D……+7(499)500-65-52(domestic flights)……+7(495)753-86-41(international flights) When collecting Lost and Found items, you shall have an identification document, a boarding pass or a ticket, and also indicate the place where the items were lost and prove they are yours.If Your Luggage Is Lost or DamagedBefore leaving the arrival area, please turn to the Lost and Found counter to file a report. The written claim shall be submitted to the airline company not later than seven days from the time when the luggage was to be collected.If your luggage is not found within twenty-one days of the time when the claim was filed, youhave the right to claim damages in the amount of not more than 600 rubles per kilogram. Amount refunded(退款) for the hand luggage lost through the fault of an airline is not more than 11, 000 rubles regardless of its weight. Amount refunded for damaged luggage is calculated based on the same tariffs(关税).Keep your flight documents (a ticket, boarding pass, luggage tag, and delayed luggage report filed at the airport) until the end of the procedure for searching for your luggage.Current information on luggage-tracing results ……+7(495)578-76-65Lost and Found service of Aeroflot Russian Airlines……+7(495)544-33-25(from 9:00- 20:00)+7(495)753-86-41(24 hours)For further information please contact the airline.1.What should you do if you find your personal possessions lost on board?A.Submit a claim to the company.B.Go to the Lost and Found counter.C.Contact the airline’s representatives.D.Contact the unclaimed luggage storage room2.How much money can you claim if your 20-kilomgram hand luggage is lost?A.600 rubles.B.11,000 rubles at most.C.12,000 rubles at least.D.12,000 rubles at most.3.Which number will you probably dial to see whether your lost luggage has been found?A.7(495)578-76-65B.7(495)544-33-25C.7(499)500-65-52D.7(495)753-86-41BThe loneliest chimp(黑猩猩) in the world just got the best surprise---a hug from a new friend. Ponso has been by himself for nearly three years, finding himself alone after his wife and children died on the island where they were abandoned by a medical testing company many years ago.For years a nearby villager named Germain has been Ponso’s only company, visiting him so often to bring bananas and bread---the chimp’s only source of food on the tiny island. It was clear how much Ponso missed companionship when he was recently visited by Chimpanzee Conservation Centre Director Estelle Raballand. The chimp immediately embraced Estelle Raballand in a huge hug and laughed as she reached out for him, with his smile from ear to ear.For those who know Ponso’s backstory, his immediate ease and trust in humans might be surprising. Ponso was one of 20 chimps, all between the ages of 7 to 11 years old, relocated to an island off the Ivory Coast after being used for testing. After the tests were completed in 2005, the lab reportedly transferred the chimps to a string of islands, occasionally dropping off food and water because there was none in the chimps’ new homes.Disease and hunger soon left only Ponso, his mate and their two children standing. But at the end of 2013 they died within days and Ponso is now completely alone.A group called SOS PONSO is trying to raise money for the poor lonely chimp, already achieving its goal of $20,000 ----all of which will be used for Ponso’s care.4.What do we know about the chimp Ponso?A.He was deserted by his family.B.He found many sources of food.C.He came to the island for a test.D.He suffers from loneliness greatly.5.How did Ponso feel about the visit of Estelle Raballand?A.Excited.B.Frightened.C.Embarrassed.D.Confused.6.What is Paragraph 3 mainly about?A.The chimps’ new settlements.B.How Ponso came to the island.C.Why Ponso was used for a test.D.The medical test about chimps.7.What can be inferred from the text?A.Germain won’t visit Ponso anymore.B. A new lab will be built on the island.C.Many people show concern for Ponso.D.More chimps will be brought to the island.CIt was December 25, 1914, only 5 months into World War I. German, British, and French soldiers, already sick and tired of the senseless killing, disobeyed their superiors and started socializing with “the enemy” along two-thirds of the Western Front.German troops held up Christmas trees with signs “Merry Christmas”. Thousands of troops ran across the battlefields covered with dead bodies. They sang Christmas songs, exchanged photographs of loved ones back home, shared food and even played football. Soldiers hugged men they had been trying to kill a few short hours before. They agreed to warn each other if their officers forced them to fire their weapons, and to aim high.Fear ran through the military leaders on both sides. They felt that their power was being challenged: soldiers declaring their brotherhood with each other and refusing to fight. Generals declared this unexpected peacemaking illegal and said that participating soldiers would face a military court. Those found guilty would be imprisoned or even shot. By March 1915 the socializing movement had been destroyed and the killing machine was back in full operation. Over the next three years more than fifteen million people died in the war.Not many people have heard the story of the Christmas Truce(休战). On Christmas Day, 1988, a local radio host in Boston played “ Christmas in the Trenches”, a song about the Christmas Truce, several times and was stunned by his listeners’ response. Thousands of people called in, praising the song, with many moved to tears by the amazing events it describes.You can probably guess why the callers were in tears. The Christmas Truce story goes against most of what we have been taught about people. It lets us see the world as it can be and says, “This really happened once.” It shows us the potential we have as humans, and contradicts all of those TV and newspaper stories that tell us how mean and heartless people are. It is like hearing that our deepest wishes really are true: the world really can be different.8.The soldiers began socializing with the enemy because ______.A.they couldn’t bear the meaningless killing.B.it was the best way to avoid being killed.C.they feared that they would be caught.D.their enemies were from similar backgrounds.9.How did the generals finally put an end to the soldiers’ socializing?A.They sent the soldiers’ loved ones to prison.B.They moved the two groups of soldiers further apart.C.They increased the number of officers to control the soldiers.D.They warned the soldiers that they would face severe punishment.10.The underlined word “stunned” in Paragraph 4 most probably means “____”.A.satisfiedB. shockedC. amusedD. confused11.The author uses the story of the soldiers to imply that human beings ____.A.are not trustworthy under stress.B.are naturally aggressive and warlikeC.are basically caring and kind-heartedD.will always do what is in their own self-interestDThose accustomed to browsing through thousands of books in large bookstores may find Japan’s Morioka Shoten a little strange. That’s because this tiny bookstore that is located in Ginza, Tokyo sells only a single book at a time.Opened in May 2015, Morioka Shoten is the brainchild of Yoshiyuki Morioka. He began his career as a bookstore clerk in Tokyo’s Kanda district before branching out to open his own store. It was here while organizing book reading and signing that he realized that customers usually came into the store with one title in mind. Morioka began to wonder if a store could exist by selling multiple copies of just one single book. In November 2014, he partnered with Masamichi Toyama to establish a unique bookstore with the philosophy of “A Single Room with a Single Book”.The selections that are picked by Morioka change weekly and vary widely to attract customers with different interests. Recent choices include The True Deceiver, an award-winning Swedish novel by Tove Jansson, Hans Anderse n’s Fairy Tales, and a collection of Karl Blossfeldt’s photography of plants. Morioka has also selected books written by a famous Japanese author Mimei Ogawa.To highlight his only offering, Morioka often uses clever tricks. For example, when selling a book about flowers, the storekeeper decorated his shop with the ones that had been mentioned in the book. He also encourages authors to hold talks and discussions so they can connect with customers. Morioka says his goal is for the customers to experience being inside a book, not just a bookstore.Risky as the idea might seem, things appear to be going well. The storekeeper says he has sold over 2,100 books. Things can get better given that his bookstore is becoming increasingly popular not just among the locals but also visitors form other countries.12.What inspired Morioka to open such a bookstore?A. A Swedish novel.B.His present partner.C. A bookstore clerk.D.His working experience.13.Why is Morioka Shoten unique?A.It is popular with foreigners.B.It sells books of different topics.C.It is decorated with colorful flowers.D.It sells various copies of a book in a week.14.Why does Morioka encourage authors to hold talks?A.To introduce his bookstore.B.To advocate his philosophy.C.To make books better understood.D.To help readers make more friends.15.What’s the author’s opinion about the bookstore’s future?A.Risky.B. Promising.C. Unpredictable.D. Hopeless.第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，并在答题卡上将该项涂黑。

福建省福建师大附中2015-2016学年高一下学期期中考试英语试题（满分：150分时间：120分钟）第Ⅰ卷(共79分)第一部分：听力（共20题；每小题1分, 满分20分）第一节（共5小题；每小题1分, 满分5分）听下面10段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Where does the man probably work?A. At a store.B. At a restaurant.C. At a club.2. What is the woman going to do next week?A. Meet Rich’s mother.B. Buy her mother a present.C. Introduce Rich to her mother.3. What are the speakers talking about?A. A computer.B. A television.C. A radio.4. What will the boy do first?A. Do his homework.B. Clean his room.C. Watch TV.5. Where are the speakers?A. At a bus stop.B. On a bus.C. In the man’s home.第二节（共15小题；每小题1分, 满分15分）听下面5段对话。

每段对话后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话读两遍。

听第6段材料，回答第6、7题。

6. Why does the woman refuse to help the man?A. It is against the rules.B. His instrument is too heavy.C. She doesn’t know where to make a call.7. Where will the man go?A. To the reception.B. To the dining room.C. To the bag office.听第7段材料，回答第8、9题。

福建师大附中2015-2016学年高二（上）期中数学试卷（理科）（实验班）一、选择题：本大题有12小题，每小题5分，共60分，在每小题给出的四个选项中，只有一项符合题目要求.1．下列结论正确的是（）A．当x＞0且x≠1时，lgx+≥2 B．当x＞0时，+≥2C．当x≥2时，x+的最小值为2 D．当0＜x≤2时，x﹣无最大值2．关于x的不等式mx2﹣mx﹣1＜0的解集是全体实数，则m应满足的条件是（）A．[﹣4，0]B．（﹣4，0]C．[0，4）D．（﹣4，0）3．已知数列{a n}是首项为1的等比数列，S n是{a n}的前n项和，且，则数列{}的前5项和为（）A．或B．或C．D．4．一辆汽车在一条水平的公路上向正西方向行驶，到A处时测得公路北侧远处一山顶D在西偏北α方向上，行驶a千米后到达B处，此时测得此山顶在西偏北β方向上，仰角为γ，根据这些测量数据计算（其中β＞α），此山的高度是（）A．B．C．D．5．在△ABC中，①若B=60°，a=10，b=7，则该三角形有且仅有两解；②若三角形的三边的比是3：5：7，则此三角形的最大角为钝角；③若△ABC为锐角三角形，且三边长分别为2，3，x，则x的取值范围是．其中正确命题的个数是（）A．0 B．1 C．2 D．36．已知约束条件对应的平面区域D如图所示，其中l1，l2，l3对应的直线方程分别为：y=k1x+b1，y=k2x+b2，y=k3x+b3，若目标函数z=﹣kx+y仅在点A（m，n）处取到最大值，则有（）A．k1＜k＜k2B．k1＜k＜k3C．k1≤k≤k3D．k＜k1或k＞k37．在△ABC中，角A，B，C所对应的边分别为a，b，c，sinC+sin（A﹣B）=3sin2B．若，则=（）A．B．3 C．或3 D．3或8．在△ABC中，内角A、B、C的对边分别是a、b、c，若c2=（a﹣b）2+6，△ABC的面积为，则C=（）A．B．C．D．9．设等差数列{a n}的前n项和为S n，且满足S100＞0，S101＜0，对任意正整数n，都有|a n|≥|a k|，则k 的值为（）A．49 B．50 C．51 D．5210．已知数列{a n}的前n项和为，令，记数列{b n}的前n项为T n，则T2015=（）A．﹣2011 B．﹣2012 C．﹣2013 D．﹣201411．若不等式组的解集不是空集，则实数a的取值范围是（）A．（﹣∞，﹣4]B．[﹣4，+∞）C．[﹣4，20] D．[﹣4，20）12．数列{a n}满足a1=1，=，记S n=a i2a i+12，若S n≤对任意的n（n∈N*）恒成立，则正整数t的最小值为（）A．10 B．9 C．8 D．7二、填空题：本大题有4小题，每小题5分，共20分，把答案填在答卷的相应位置.13．已知x，y满足约束条件，若z=ax+y的最大值为4，则a=．14．设数列{a n}的前n项和为S n，且a1=1，{S n+na n}为常数列，则a n=．15．若数列{a n}满足﹣=0，n∈N*，p为非零常数，则称数列{a n}为“梦想数列”．已知正项数列{}为“梦想数列”，且b1b2b3…b99=299，则b8+b92的最小值是．16．已知点G是斜△ABC的重心，且AG⊥BG，+=，则实数λ的值为．三、解答题：本大题有6题，共70分，解答应写出文字说明、证明过程或演算步骤.17．关于x的不等式ax2+（a﹣2）x﹣2≥0（a∈R）（1）已知不等式的解集为（﹣∞，﹣1]∪[2，+∞），求a的值；（2）解关于x的不等式ax2+（a﹣2）x﹣2≥0．18．设S n是数列[a n}的前n项和，．（1）求{a n}的通项；（2）设b n=，求数列{b n}的前n项和T n．19．如图，C、D是两个小区所在地，C、D到一条公路AB的垂直距离分别为CA=1km，DB=2km，AB两端之间的距离为6km．（1）如图1，某移动公司将在AB之间找一点P，在P处建造一个信号塔，使得P对A、C的张角与P对B、D的张角相等，试确定点P的位置．（2）如图2，环保部门将在AB之间找一点Q，在Q处建造一个垃圾处理厂，使得Q对C、D所张角最大，试确定点Q的位置．20．在△ABC中，已知sinB=cosAsinC（1）判断△ABC的形状（2）若•=9，又△ABC的面积等于6．求△ABC的三边之长；（3）在（2）的条件下，设P是△ABC（含边界）内一点，P到三边AB，BC，CA的距离分别为d1，d2，d3，求d1+d2+d3的取值范围．21．某个公园有个池塘，其形状为直角△ABC，∠C=90°，AB=2百米，BC=1百米．（1）现在准备养一批供游客观赏的鱼，分别在AB、BC、CA上取点D，E，F，如图（1），使得EF‖AB，EF⊥ED，在△DEF喂食，求△DEF面积S△DEF的最大值；（2）现在准备新建造一个荷塘，分别在AB，BC，CA上取点D，E，F，如图（2），建造△DEF连廊（不考虑宽度）供游客休憩，且使△DEF为正三角形，设求△DEF边长的最小值．22．已知函数．（1）若对于任意的x∈R，f（x）＞0恒成立，求实数k的取值范围；（2）若f（x）的最小值为﹣2，求实数k的值；（3）若对任意的x1，x2，x3∈R，均存在以f（x1），f（x2），f（x3）为三边长的三角形，求实数k的取值范围．四、附加题：23．（2015秋•福建校级期中）研究数列{x n}的前n项发现：{x n}的各项互不相同，其前i项（1≤i≤n ﹣1）中的最大者记为a i，最后n﹣i项（i≤i≤n﹣1）中的最小者记为b i，记c i=a i﹣b i，此时c1，c2，…c n ，c n﹣1构成等差数列，且c1＞0，证明：x1，x2，x3，…x n﹣1为等差数列．﹣22015-2016学年福建师大附中高二（上）期中数学试卷（理科）（实验班）参考答案与试题解析一、选择题：本大题有12小题，每小题5分，共60分，在每小题给出的四个选项中，只有一项符合题目要求.1．下列结论正确的是（）A．当x＞0且x≠1时，lgx+≥2 B．当x＞0时，+≥2C．当x≥2时，x+的最小值为2 D．当0＜x≤2时，x﹣无最大值【考点】基本不等式．【分析】本题中各选项都是利用基本不等式求最值，注意验证一正、二定、三相等条件是否满足即可．A中不满足“正数”，C中“=”取不到．【解答】解：A中，当0＜x＜1时，lgx＜0，lgx+≥2不成立；由基本不等式B正确；C中“=”取不到；D中x﹣在0＜x≤2时单调递增，当x=2时取最大值．故选B【点评】本题主要考查利用基本不等式求最值的三个条件，一正、二定、三相等，在解题中要牢记．2．关于x的不等式mx2﹣mx﹣1＜0的解集是全体实数，则m应满足的条件是（）A．[﹣4，0]B．（﹣4，0]C．[0，4）D．（﹣4，0）【考点】二次函数的性质．【专题】函数思想；综合法；不等式的解法及应用．【分析】若m=0．则﹣1＜0恒成立，若m≠0，由不等式的解集是全体实数可知f（x）=mx2﹣mx﹣1开口向下，△＜0，列出不等式解出m的范围．【解答】解：当m=0时，不等式为﹣1＜0，恒成立；当m≠0时，∵不等式mx2﹣mx﹣1＜0的解集是全体实数，∴，解得﹣4＜m＜0．综上，m的取值范围是（﹣4，0]．故选：B．【点评】本题考查了二次不等式与二次函数的关系，对m进行讨论是关键．3．已知数列{a n}是首项为1的等比数列，S n是{a n}的前n项和，且，则数列{}的前5项和为（）A．或B．或C．D．【考点】等比数列的前n项和．【专题】等差数列与等比数列．【分析】由已知式子可得数列{a n}的公比，进而可得等比数列{}的首项为1，公比为±，由求和公式可得．【解答】解：∵，∴S8=17S4，∴=16，∴公比q满足q4=16，∴q=2或q=﹣2，∴等比数列{}的首项为1，公比为±，当公比为时，数列{}的前5项和为=；当公比为﹣时，数列{}的前5项和为=故选：A【点评】本题考查等比数列的求和公式，涉及分类讨论的思想，属中档题．4．一辆汽车在一条水平的公路上向正西方向行驶，到A处时测得公路北侧远处一山顶D在西偏北α方向上，行驶a千米后到达B处，此时测得此山顶在西偏北β方向上，仰角为γ，根据这些测量数据计算（其中β＞α），此山的高度是（）A．B．C．D．【考点】解三角形的实际应用．【专题】应用题；解三角形．【分析】先求出BC，再求出CD即可．【解答】解：在△ABC中，∠ACB=β﹣α，∠ABC=π﹣β，AB=a，∴，∴BC=，∴CD=BCtanγ=．故选：B．【点评】本题主要考查了解三角形的实际应用．考查了运用数学知识，建立数学模型解决实际问题的能力．5．在△ABC中，①若B=60°，a=10，b=7，则该三角形有且仅有两解；②若三角形的三边的比是3：5：7，则此三角形的最大角为钝角；③若△ABC为锐角三角形，且三边长分别为2，3，x，则x的取值范围是．其中正确命题的个数是（）A．0 B．1 C．2 D．3【考点】命题的真假判断与应用．【专题】对应思想；定义法；三角函数的求值．【分析】①根据正弦定理判断得出sinA=＞1不成立；②设边长，根据余弦定理得出最大角cosα==﹣＜0，③设出角度，根据大边对大角，只需判断最大角为锐角即可．【解答】解：在△ABC中，①若B=60°，a=10，b=7，由正弦定理可知，，所以sinA=＞1，故错误；②若三角形的三边的比是3：5：7，根据题意设三角形三边长为3x，5x，7x，最大角为α，由余弦定理得：cosα==﹣，则最大角为120°，故正确；③若△ABC为锐角三角形，且三边长分别为2，3，x，设所对角分别为A，B，C，则最大角为B或C所对的角，∴cosB=＞0，得是＜x，cosC=＞0，得x＜．则x的取值范围是，故正确；故选：C．【点评】考查了正弦定理和余弦定理的应用，根据题意，正确设出边或角．6．已知约束条件对应的平面区域D如图所示，其中l1，l2，l3对应的直线方程分别为：y=k1x+b1，y=k2x+b2，y=k3x+b3，若目标函数z=﹣kx+y仅在点A（m，n）处取到最大值，则有（）A．k1＜k＜k2B．k1＜k＜k3C．k1≤k≤k3D．k＜k1或k＞k3【考点】简单线性规划．【专题】不等式的解法及应用．【分析】根据z的几何意义，结合直线斜率之间的关系，即可得到结论．【解答】解：A是l1与l3的交点，目标函数z=﹣kx+y仅在点A处取到最大值，∴直线y=kx+z的倾斜角比l1的要大，比l3的要小，即有k1＜k＜k3，故选：B．【点评】本题主要考查线性规划的应用以及直线斜率之间的关系，比较基础．7．在△ABC中，角A，B，C所对应的边分别为a，b，c，sinC+sin（A﹣B）=3sin2B．若，则=（）A．B．3 C．或3 D．3或【考点】正弦定理；两角和与差的正弦函数；二倍角的正弦．【专题】计算题；解三角形．【分析】根据三角形内角和定理与诱导公式，可得sinC=sin（A+B）=sinAcosB+cosAsinB，代入题中等式并利用三角恒等变换化简，整理得cosB（sinA﹣3sinB）=0，可得cosB=0或sinA=3sinB．再由正弦定理与直角三角形中三角函数的定义加以计算，可得的值．【解答】解：∵A+B=π﹣C，∴sinC=sin（π﹣C）=sin（A+B）=sinAcosB+cosAsinB，又∵sin（A﹣B）=sinAcosB﹣cosAsinB，∴sinC+sin（A﹣B）=3sin2B，即（sinAcosB+cosAsinB）+（sinAcosB﹣cosAsinB）=6sinBcosB，化简得2sinAcosB=6sinBcosB，即cosB（sinA﹣3sinB）=0解之得cosB=0或sinA=3sinB．①若cosB=0，结合B为三角形的内角，可得B=，∵，∴A==，因此sinA=sin=，由三角函数的定义得sinA==；②若sinA=3sinB，由正弦定理得a=3b，所以=3．综上所述，的值为或3．故选：C【点评】本题给出三角形角的三角函数关系式，求边之间的比值．着重考查了三角形内角和定理与诱导公式、三角恒等变换、三角函数的定义和正余弦定理等知识，属于中档题．8．在△ABC中，内角A、B、C的对边分别是a、b、c，若c2=（a﹣b）2+6，△ABC的面积为，则C=（）A．B．C．D．【考点】余弦定理．【专题】解三角形．【分析】由已知和余弦定理可得ab及cosC的方程，再由面积公式可得ab和sinC的方程，由同角三角函数基本关系可解cosC，可得角C【解答】解：由题意可得c2=（a﹣b）2+6=a2+b2﹣2ab+6，由余弦定理可得c2=a2+b2﹣2abcosC，两式联立可得ab（1﹣cosC）=3，再由面积公式可得S=absinC=，∴ab=，代入ab（1﹣cosC）=3可得sinC=（1﹣cosC），再由sin2C+cos2C=1可得3（1﹣cosC）2+cos2C=1，解得cosC=，或cosC=1（舍去），∵C∈（0，π），∴C=，故选：A．【点评】本题考查余弦定理，涉及三角形的面积公式和三角函数的运算，属中档题．9．设等差数列{a n}的前n项和为S n，且满足S100＞0，S101＜0，对任意正整数n，都有|a n|≥|a k|，则k 的值为（）A．49 B．50 C．51 D．52【考点】等差数列的性质．【专题】函数思想；整体思想；综合法；等差数列与等比数列．【分析】由题意和等差数列的性质可得a50+a51＞0；a51＜0，进而可得a50＞0，且|a50|＞|a51|，可得结论．【解答】解：由题意和等差数列的性质可得S100==50（a1+a100）=50（a50+a51）＞0，∴a50+a51＞0；同理S101===101a51＜0，∴a51＜0；∴a50＞0，且|a50|＞|a51|，∴k=51故选：C．【点评】本题考查等差数列的求和公式和性质，整体得出项的正负是解决问题的关键，属中档题．10．已知数列{a n}的前n项和为，令，记数列{b n}的前n项为T n，则T2015=（）A．﹣2011 B．﹣2012 C．﹣2013 D．﹣2014【考点】数列的求和．【专题】等差数列与等比数列；三角函数的图像与性质．【分析】利用“当n=1时，a1=S1．当n≥2时，a n=S n﹣S n﹣1”可得a n，于是=2（n﹣1）•cos．由于函数y=cos的周期T==4．利用周期性和等差数列的前n项和公式即可得出．【解答】解：由数列{a n}的前n项和S n=n2﹣n，当n=1时，a1=S1=1﹣1=0．当n≥2时，a n=S n﹣S n﹣1=n2﹣n﹣[（n﹣1）2﹣（n﹣1）]=2n﹣2．上式对于n=1时也成立．∴a n=2n﹣2．∴=2（n﹣1）•cos．∵函数y=cos的周期T==4．∴T2015=（b1+b5+…+b2009）+（b2+b6+…+b2010）+（b3+b7+…+b2011）+（b4+b8+…+b2012）+b2013+b2014+b2015=0﹣2（1+5+...+2009）+0+2（3+7+ (2011)+4024•cos+4026•cos+4028•cos=4×503+0﹣4026=﹣2014．故选D．【点评】本题考查了利用“当n=1时，a1=S1．当n≥2时，a n=S n﹣S n﹣1”求a n、余弦函数的周期性、等差数列的通项公式与前n项和公式，考查了推理能力和计算能力，属于难题．11．若不等式组的解集不是空集，则实数a的取值范围是（）A．（﹣∞，﹣4]B．[﹣4，+∞）C．[﹣4，20] D．[﹣4，20）【考点】一元二次不等式的解法．【分析】先解不等式：x2﹣2x﹣3≤0，然后a取特殊值验证即可得到答案．【解答】解：解不等式x2﹣2x﹣3≤0得﹣1≤x≤3；观察选项取a=﹣1解不等式x2+4x﹣（1+a）＜0即x2+4x≤0可得﹣4＜x＜0显然A不正确；令a=31不等式x2+4x﹣（1+a）＜0即x2+4x﹣32≤0解得﹣8≤x≤4，仅有B正确．故选B．【点评】选择题的解法非常灵活，一定要观察题干和选项，特殊值一定要特殊．是中档题．12．数列{a n}满足a1=1，=，记S n=a i2a i+12，若S n≤对任意的n（n∈N*）恒成立，则正整数t的最小值为（）A．10 B．9 C．8 D．7【考点】数列与不等式的综合．【专题】转化思想；分析法；等差数列与等比数列；不等式的解法及应用．【分析】先求出数列{a n2}的通项公式，再求S n，注意运用裂项相消求和，以及不等式的性质，可求正整数t的最小值．【解答】解：∵a1=1，=，∴+4=，∴﹣=4，∴{}是首项为1，公差为4的等差数列，∴=4n﹣3，∴a n2=，a n2•a n+12=•=（﹣），∴S n=a i2a i+12=（1﹣+﹣+…+﹣）=（1﹣）＜S n≤对任意的n（n∈N*）恒成立，即为t≥30•=7.5，而t为正整数，所以，t min=8．故选C．【点评】本题考查利用数列的递推式求通项公式及函数的恒成立问题，学会用不等式处理问题．本题对数学思维的要求比较高，要求学生理解“存在”、“恒成立”，属于中档题．二、填空题：本大题有4小题，每小题5分，共20分，把答案填在答卷的相应位置.13．已知x，y满足约束条件，若z=ax+y的最大值为4，则a=2．【考点】简单线性规划．【专题】计算题；函数思想；数形结合法；不等式的解法及应用．【分析】作出不等式组对应的平面区域，利用目标函数的几何意义，利用数形结合确定z的最大值【解答】解：作出不等式组对应的平面区域如图：（阴影部分）．则A（2，0），B（1，1），若z=ax+y过A时取得最大值为4，则2a=4，解得a=2，此时，目标函数为z=2x+y，即y=﹣2x+z，平移直线y=﹣2x+z，当直线经过A（2，0）时，截距最大，此时z最大为4，满足条件，若z=ax+y过B时取得最大值为4，则a+1=4，解得a=3，此时，目标函数为z=3x+y，即y=﹣3x+z，平移直线y=﹣3x+z，当直线经过A（2，0）时，截距最大，此时z最大为6，不满足条件，故a=2；故答案为：2．【点评】本题主要考查线性规划的应用，结合目标函数的几何意义，利用数形结合的数学思想是解决此类问题的基本方法，确定目标函数的斜率关系是解决本题的关键．14．设数列{a n}的前n项和为S n，且a1=1，{S n+na n}为常数列，则a n=．【考点】数列递推式．【专题】计算题；函数思想；数学模型法；等差数列与等比数列．【分析】由已知求出S1+a1=2，可得S n+na n=2，当n≥2时，（n+1）a n=（n﹣1）a n﹣1，然后利用累积法求得a n．【解答】解：∵数列{a n}的前n项和为S n，且a1=1，∴S1+1×a1=1+1=2，∵{S n+na n}为常数列，∴由题意知，S n+na n=2，当n≥2时，S n﹣1+（n﹣1）a n﹣1=2两式作差得（n+1）a n=（n﹣1）a n﹣1，从而=，∴（n≥2），当n=1时上式成立，∴．故答案为：．【点评】本题考查数列的通项公式的求法，训练了累乘法求数列的通项公式，是中档题．15．若数列{a n}满足﹣=0，n∈N*，p为非零常数，则称数列{a n}为“梦想数列”．已知正项数列{}为“梦想数列”，且b1b2b3…b99=299，则b8+b92的最小值是4．【考点】数列递推式．【专题】计算题；转化思想；整体思想；分析法；点列、递归数列与数学归纳法．【分析】由新定义得到数列{b n}为等比数列，然后由等比数列的性质得到b50=2，再利用基本不等式求得b8+b92的最小值．【解答】解：依题意可得b n+1=qb n，则数列{b n}为等比数列．又b1b2b3…b99=299=．则b50=2．∴b 8+b92≥=2b50=4，当且仅当b8=b92，即该数列为常数列时取等号．故答案为：4．【点评】本题是新定义题，考查了等比数列的性质，训练了利用基本不等式求最值，是中档题．16．已知点G是斜△ABC的重心，且AG⊥BG，+=，则实数λ的值为．【考点】正弦定理；余弦定理．【专题】三角函数的求值．【分析】首先根据三角形的重心性质及直角三角形的斜边的中线等于斜边的一半，得到CD=AB，再应用余弦定理推出AC2+BC2=5AB2，将+=应用三角恒等变换公式化简得λ=，然后运用正弦定理和余弦定理，结合前面的结论，即可求出实数λ的值．【解答】解：如图，连接CG，延长交AB于D，由于G为重心，故D为中点，∵AG⊥BG，∴DG=AB，由重心的性质得，CD=3DG，即CD=AB，由余弦定理得，AC2=AD2+CD2﹣2AD•CD•cos∠ADC，BC2=BD2+CD2﹣2BD•CD•cos∠BDC，∵∠ADC+∠BDC=π，AD=BD，∴AC2+BC2=2AD2+2CD2，∴AC2+BC2=AB2+AB2=5AB2，又∵+=，∴+=，则λ=======．故答案为：【点评】此题考查了正弦、余弦定理，三角形的重心性质，熟练掌握定理及公式是解本题的关键．三、解答题：本大题有6题，共70分，解答应写出文字说明、证明过程或演算步骤.17．关于x的不等式ax2+（a﹣2）x﹣2≥0（a∈R）（1）已知不等式的解集为（﹣∞，﹣1]∪[2，+∞），求a的值；（2）解关于x的不等式ax2+（a﹣2）x﹣2≥0．【考点】一元二次不等式的解法；二次函数的性质．【专题】分类讨论；不等式的解法及应用．【分析】（1）根据一元二次不等式与对应方程的关系，利用根与系数的关系，即可求出a的值；（2）讨论a的取值，求出对应不等式的解集即可．【解答】解：（1）∵关于x的不等式ax2+（a﹣2）x﹣2≥0可变形为（ax﹣2）（x+1）≥0，且该不等式的解集为（﹣∞，﹣1]∪[2，+∞），∴a＞0；又不等式对应方程的两个实数根为﹣1和2；∴=2，解得a=1；（2）①a=0时，不等式可化为﹣2x﹣2≥0，它的解集为{x|x≤﹣1}；②a≠0时，不等式可化为（ax﹣2）（x+1）≥0，当a＞0时，原不等式化为（x﹣）（x+1）≥0，它对应的方程的两个实数根为和﹣1，且＞﹣1，∴不等式的解集为{x|x≥或x≤﹣1}；当a＜0时，不等式化为（x﹣）（x+1）≤0，不等式对应方程的两个实数根为和﹣1，在﹣2＜a＜0时，＜﹣1，∴不等式的解集为{x|≤x≤﹣1}；在a=﹣2时，=﹣1，不等式的解集为{x|x=﹣1}；在a＜﹣2时，＞﹣1，不等式的解集为{x|﹣1≤x≤}．综上，a=0时，不等式的解集为{x|x≤﹣1}，a＞0时，不等式的解集为{x|x≥或x≤﹣1}，﹣2＜a＜0时，不等式的解集为{x|≤x≤﹣1}，a=﹣2时，不等式的解集为{x|x=﹣1}，a＜﹣2时，不等式的解集为{x|﹣1≤x≤}．【点评】本题考查了含有字母系数的不等式的解法与应用问题，解题时应用分类讨论的思想，是中档题目．18．设S n是数列[a n}的前n项和，．（1）求{a n}的通项；（2）设b n=，求数列{b n}的前n项和T n．【考点】数列递推式；数列的求和．【专题】计算题．【分析】（1）由条件可得n≥2时，，整理可得，故数列{}是以2为公差的等差数列，其首项为，由此求得s n．再由求出{a n}的通项公式．（2）由（1）知，，用裂项法求出数列{b n}的前n项和T n．【解答】解：（1）∵，∴n≥2时，，展开化简整理得，S n﹣1﹣S n =2S n﹣1S n，∴，∴数列{}是以2为公差的等差数列，其首项为．∴，．由已知条件可得．（2）由于，∴数列{b n}的前n项和，∴．【点评】本题主要考查根据递推关系求数列的通项公式，等差关系的确定，用裂项法对数列进行求和，属于中档题．19．如图，C、D是两个小区所在地，C、D到一条公路AB的垂直距离分别为CA=1km，DB=2km，AB两端之间的距离为6km．（1）如图1，某移动公司将在AB之间找一点P，在P处建造一个信号塔，使得P对A、C的张角与P对B、D的张角相等，试确定点P的位置．（2）如图2，环保部门将在AB之间找一点Q，在Q处建造一个垃圾处理厂，使得Q对C、D所张角最大，试确定点Q的位置．【考点】解三角形的实际应用．【专题】解三角形．【分析】（1）设出PA的长度x，把∠CPA，∠DPB的正切值用含x的代数式表示，由正切值相等求得x的值，即可确定P点的位置；（2）设出PA的长度x，把∠CQA与∠DQB的正切值用含有x的代数式表示，最后把∠CQD的正切值用含有x的代数式表示，换元后再利用基本不等式求最值，最后得到使Q对C、D所张角最大时的x值，即可确定点Q的位置．【解答】解：（1）设PA=x，∠CPA=α，∠DPB=β．依题意有，．由tanα=tanβ，得，解得x=2，故点P应选在距A点2km处；（2）设PA=x，∠CQA=α，∠DQB=β．依题意有，，tan∠CQD=tan[π﹣（α+β）]=﹣tan（α+β）=，令t=x+6，由0＜x＜6，得6＜t＜12，则=，∵，∴，当时，所张的角为钝角，当，即x=时取得最大角，故点Q应选在距A点km处．【点评】本题考查解三角形的实际应用，考查了利用基本不等式求最值，解答的关键是把实际问题转化为数学问题，是中档题．20．在△ABC中，已知sinB=cosAsinC（1）判断△ABC的形状（2）若•=9，又△ABC的面积等于6．求△ABC的三边之长；（3）在（2）的条件下，设P是△ABC（含边界）内一点，P到三边AB，BC，CA的距离分别为d1，d2，d3，求d1+d2+d3的取值范围．【考点】余弦定理；正弦定理．【专题】数形结合；数形结合法；解三角形；不等式的解法及应用．【分析】（1）由题意和三角形的知识可得cosC=0，可得C=90°，△ABC为直角三角形；（2）由数量积的意义可得•=||2=9，可得AC=3，再由三角形的面积公式可得BC=4，由勾股定理可得AB=5；（3）以C为原点，CA、CB所在直线分别为x、y轴建立直角坐标系，设P的坐标为（x，y），可得d1+d2+d3=，且，令x+2y=m，由线性规划的知识可得．【解答】解：（1）∵在△ABC中sinB=cosAsinC，∴sin（A+C）=cosAsinC，∴sinAcosC+cosAsinC=cosAsinC，∴sinAcosC=0，即cosC=0，C=90°，∴△ABC为直角三角形；（2）∵•=||2=9，解得AC=3，又ABC的面积S=×3×BC=6，∴BC=4，由勾股定理可得AB=5；（3）以C为原点，CA、CB所在直线分别为x、y轴建立直角坐标系，则A（3，0），B（0，4），可得直线AB的方程为+=1，即4x+3y﹣12=0，设P的坐标为（x，y），则d1+d2+d3=x+y+，且，∴d1+d2+d3=x+y﹣=，令x+2y=m，由线性规划的知识可知0≤m≤8∴d1+d2+d3的取值范围为[，4]【点评】本题考查解三角形，涉及向量的知识和简单线性规划，数形结合是解决问题的关键，属中档题．21．某个公园有个池塘，其形状为直角△ABC，∠C=90°，AB=2百米，BC=1百米．（1）现在准备养一批供游客观赏的鱼，分别在AB、BC、CA上取点D，E，F，如图（1），使得EF‖AB，EF⊥ED，在△DEF喂食，求△DEF面积S△DEF的最大值；（2）现在准备新建造一个荷塘，分别在AB，BC，CA上取点D，E，F，如图（2），建造△DEF连廊（不考虑宽度）供游客休憩，且使△DEF为正三角形，设求△DEF边长的最小值．【考点】三角形中的几何计算．【专题】计算题；三角函数的求值；解三角形．【分析】（1）设（0＜λ＜1），利用解直角三角形算出EF=2λ百米，再利用EF∥AB算出点D到EF的距离为h=（1﹣λ）百米，从而得到S△DEF=EF•h表示成关于λ的函数式，利用基本不等式求最值即可算出△DEF面积S△DEF的最大值；（2）设正三角形DEF的边长为a、∠CEF=α且∠EDB=∠1，将CF和AF用a、α表示出，再用α分别分别表示出∠1和∠ADF，然后利用正弦定理表示a并结合辅角公式化简，利用正弦函数的值域即可求得a的最小值．【解答】解：（1）Rt△ABC中，∠C=90°，AB=2百米，BC=1百米．∴cosB=，可得B=60°∵EF∥AB，∴∠CEF=∠B=60°设（0＜λ＜1），则CE=λCB=λ百米，Rt△CEF中，EF=2CE=2λ百米，C到FE的距离d=CE=λ百米，∵C到AB的距离为BC=百米，∴点D到EF的距离为h=﹣λ=（1﹣λ）百米可得S△DEF=EF•h=λ（1﹣λ）百米2∵λ（1﹣λ）≤[λ+（1﹣λ）]2=，当且仅当时等号成立∴当时，即E为AB中点时，S△DEF的最大值为百米2（2）设正△DEF的边长为a，∠CEF=α则CF=a•sinα，AF=﹣a•sinα设∠EDB=∠1，可得∠1=180°﹣∠B﹣∠DEB=120°﹣∠DEB，α=180°﹣60°﹣∠DEB=120°﹣∠DEB∴∠ADF=180°﹣60°﹣∠1=120°﹣α在△ADF中，=即，化简得a[2sin（120°﹣α）+sinα]=∴a===（其中φ是满足tanφ=的锐角）∴△DEF边长最小值为．【点评】本题在特殊直角三角形中求三角形边长和面积的最值，着重考查了解直角三角形、平行线的性质、正弦定理和三角恒等变换等知识，考查了在实际问题中建立三角函数模型能力，属于中档题．22．已知函数．（1）若对于任意的x∈R，f（x）＞0恒成立，求实数k的取值范围；（2）若f（x）的最小值为﹣2，求实数k的值；（3）若对任意的x1，x2，x3∈R，均存在以f（x1），f（x2），f（x3）为三边长的三角形，求实数k的取值范围．【考点】复合函数的单调性．【专题】综合题；函数的性质及应用．【分析】（1）问题等价于4x+k•2x+1＞0恒成立，分离出参数k后转化为求函数的最值问题即可；（2），令，则，分k＞1，k=1，k＜1三种情况进行讨论求出f（x）的最小值，令其为﹣2即可解得k值；（3）由题意，f（x1）+f（x2）＞f（x3）对任意x1，x2，x3∈R恒成立．当k=1时易判断；当k＞1，k＜1时转化为函数的最值问题解决即可，借助（2）问结论易求函数的最值；【解答】解：（1）因为4x+2x+1＞0，所以f（x）＞0恒成立，等价于4x+k•2x+1＞0恒成立，即k＞﹣2x﹣2﹣x恒成立，因为﹣2x﹣2﹣x=﹣（2x+2﹣x）≤﹣2，当且仅当2x=2﹣x即x=0时取等号，所以k＞﹣2；（2），令，则，当k＞1时，无最小值，舍去；当k=1时，y=1最小值不是﹣2，舍去；当k＜1时，，最小值为，综上所述，k=﹣8．（3）由题意，f（x1）+f（x2）＞f（x3）对任意x1，x2，x3∈R恒成立．当k＞1时，因且，故，即1＜k≤4；当k=1时，f（x1）=f（x2）=f（x3）=1，满足条件；当k＜1时，且，故，解得；综上所述，【点评】本题考查复合函数的单调性、函数恒成立、函数最值等问题，考查转化思想，综合性较强，难度较大．四、附加题：23．（2015秋•福建校级期中）研究数列{x n}的前n项发现：{x n}的各项互不相同，其前i项（1≤i≤n ﹣1）中的最大者记为a i，最后n﹣i项（i≤i≤n﹣1）中的最小者记为b i，记c i=a i﹣b i，此时c1，c2，…c n ，c n﹣1构成等差数列，且c1＞0，证明：x1，x2，x3，…x n﹣1为等差数列．﹣2【考点】等差关系的确定．【专题】证明题；转化思想；转化法；等差数列与等比数列．【分析】依题意，0＜c1＜c2＜…＜c n﹣1，可用反证法证明x1，x2，…，x n﹣1是单调递增数列；再证明x m为数列{x n}中的最小项，从而可求得是x k=c k+x m，问题得证【解答】证明：设c为c1，c2，…c n﹣2，c n﹣1的公差，对1≤i≤n﹣2，因为b i≤b i+1，c＞0，所以a i+1=b i+1+c i+1≥b i+c i+c＞b i+c i=a i，又因为a i+1=max{a i，x i+1}，所以x i+1=a i+1＞a i≥x i．从而x1，x2，…，x n﹣1为递增数列．因为a i=x i（i=1，2，…n﹣1），又因为b1=a1﹣c1＜a1，所以b1＜x1＜x2＜…＜x n﹣1，因此x n=b1．所以b1=b2=…=b n﹣1=x n．所以x i=a i=b i+c i=x n+c i，因此对i=1，2，…，n﹣2都有x i+1﹣x i=c i+1﹣c i=c，即x1，x2，…，x n﹣1是等差数列．【点评】本题考查等差数列，突出考查考查推理论证与抽象思维的能力，考查反证法的应用，属于难题．。

绝密★启用前【百强校】2015-2016学年福建师大附中高二下期末考试生物试卷（带解析）试卷副标题考试范围：xxx ；考试时间：33分钟；命题人：xxx学校:___________姓名：___________班级：___________考号：___________注意事项．1．答题前填写好自己的姓名、班级、考号等信息 2．请将答案正确填写在答题卡上第I 卷（选择题）一、选择题（题型注释）1、关于基因控制蛋白质合成的过程，下列叙述正确的是（ ） A ．一个含n 个碱基的DNA 分子，转录的mRNA 分子碱基数是n/2个 B ．细菌的一个基因转录时两条DNA 链可同时作为模板，提高转录效率 C ．DNA 聚合酶和RNA 聚合酶的结合位点分别在DNA 和RNA 上 D ．在细胞周期中，mRNA 的种类和含量均不断发生变化2、现代生物进化理论是在达尔文自然选择学说的基础上发展起来的，对自然选择学说进行了完善和发展，主要表现在（ ） ①变和基因重组产生进化的原材料 ②种群是进化的基本单位 ③自然选择是通过生存斗争实现的 ④自然选择决定生物进化的方向 ⑤生物进化的实质是基因频率的改变⑥隔离导致新物种的形成 ⑦适者生存，不适者被淘汰A ．②④⑤⑥⑦B ．②③④⑥C ．①②⑤⑥D ．①②③⑤⑦3、下图是用集合的方法表示各种概念之间的关系，与图示相符的选项是（ ）4、豌豆花的颜色受两对基因P/p 和Q/q 控制，这两对基因遵循自由组合规律。

假设每一对基因中至少有一个显性基因时，花的颜色为紫色，其他的基因组合则为白色。

依据下列杂交结果，P:紫花×白花→F 1:3/8紫花、5/8白花，推测亲代的基因型应该是（ ） A ．PPQq×ppqq B ．PPqq×Ppqq C ．PpQq×ppqq D ．PpQq×Ppqq5、下图是甲、乙两种生物的体细胞内染色体情况示意图，则甲、乙两种生物体细胞的基因型可依次表示为（ ）A ．甲：AaBb 乙：AAaBbbB ．甲：AaaaBBbb 乙：AaBBC ．甲：AAaaBbbb 乙：AaaBBbD ．甲：AaaBbb 乙：AAaaBbbb6、下列关于生物进化和生物多样性的表述中正确的一项是（ ） A ．一个物种的灭绝，会影响到若干其他物种的进化 B ．物种之间的共同进化都是通过物种之间的生存斗争实现的 C ．生物多样性的形成也就是新的物种不断形成的过程 D ．生物多样性指基因多样性、物种多样性和生物群落多样性7、下列不属于生殖隔离实例的是（ ）A ．雄萤火虫给雌虫发出各自特有的闪光求偶信号，雌虫对异种雄虫发出的信号无反应B ．牛蛙的卵和豹蛙的精子能融合成合子，发育一段时间后死亡C ．玉米的花柱很长，拟蜀属植物的花粉在玉米柱头上能萌发，但不能到达子房D ．特纳氏综合症患者缺少了一条X 染色体，性腺发育不良，没有生育能力8、下列与染色体变异有关的说法中不正确的是（ ） A ．染色体变异包括染色体结构的改变和染色体数目的改变 B ．两条染色体相互交换片段都属于染色体变异C ．猫叫综合征的患者与正常人相比，第5号染色体发生部分缺失D ．染色体结构的改变，会使排列在染色体上的基因的数目或排列顺序发生改变9、下图表示科学家对果蝇一条染色体上的基因测定结果，下列有关该图说法正确的是（ ）A ．控制朱红眼与深红眼的基因是等位基因B ．控制白眼和朱红眼的基因在遗传时遵循基因的分离定律C ．该染色体上的基因在后代中都能表达D ．该染色体上的基因呈线性排列10、用32P 标记的噬菌体侵染大肠杆菌，经培养、搅拌、离心、检测，上清液的放射性占15%，沉淀物的放射性占85%。

绝密★启用前【百强校】2015-2016学年福建师大附中高二下期末数学（理）试卷（带解析）试卷副标题考试范围：xxx ；考试时间：154分钟；命题人：xxx学校:___________姓名：___________班级：___________考号：___________注意事项．1．答题前填写好自己的姓名、班级、考号等信息 2．请将答案正确填写在答题卡上第I 卷（选择题）一、选择题（题型注释）1、若,则（ ）A ．B ．C ．D ．2、如图，电路中共有个电阻与一个电灯，若灯不亮，则因电阻断路的可能性的种数为（ ）A ．B ．C ．D ．3、若多项式，则的值为（ ） A ．B ．C ．D ．4、将位同学分别保送到北京大学，清华大学，浙江大学等三所大学就读，则每所大学至少保送一人的概率为（ ）A ．B ．C ．D ．5、对任意实数恒成立，则实数的取值范围为（ ）A ．B ．C ．D ．6、的展开式中含项的系数为（ ）A ．B ．C ．D ．7、的展开式中和的系数相等，则（ ）A ．B ．C ．D ．8、从中不放回地依次取个数，事件表示“第次取到的是奇数”，事件表示“第次取到的是奇数”，则（ ）A ．B ．C ．D ．9、学校要选派名爱好摄影的同学中的名参加校外摄影小组的期培训（每期只派名），由于时间上的冲突，甲、乙两位同学都不能参加第期培训，则不同的选派方式有（ ）A ．种B ．种C ．种 D ．种10、在4次的独立重复试验中，事件在一次试验中发生的概率为，则事件恰有1次发生的概率是（）A． B． C． D．11、直线的参数方程可以是（）A．（为参数）B．（为参数）C．（为参数）D．（为参数）12、已知随机变量服从正态分布，且，则（）A． B． C． D．○…第II卷（非选择题）二、填空题（题型注释）13、已知（，且），通过变式可以得到：；若将赋给，又可得到；由已知也可得到：.请根据以上材料所蕴含的数学思想方法与结论，计算：.14、在平面直角坐标系中，曲线的参数方程为：（为参数），直线的方程为．已知点为曲线上任意一点，则点到直线的距离的最大值是 .15、设的展开式的二项式系数和为64，则展开式中常数项为 .16、已知随机变量的分布列如下表，且，则的值为 .三、解答题（题型注释）17、为评估设备生产某种零件的性能，从设备生产零件的流水线上随机抽取100件零件做为样本，测量其直径后，整理得到下表：经计算，样本的平均值，标准差，以频率值作为概率的估计值．（Ⅰ）为评判一台设备的性能，从该设备加工的零件中任意抽取一件，记其直径为，并根据以下不等式进行评判（表示相应事件的频率）；①； ②； ③．评判规则为：若同时满足上述三个不等式，则设备等级为甲；仅满足其中两个，则等级为乙，若仅满足其中一个，则等级为丙；若全部不满足，则等级为丁．试判断设备的性能等级．（Ⅱ）将直径小于等于或直径大于的零件认为是次品.（ⅰ）从设备的生产流水线上随意抽取2件零件，计算其中次品个数的数学期望；（ⅱ）从样本中随意抽取2件零件，计算其中次品个数的数学期望．18、已知2件次品和3件正品混放在一起，现需要通过检测将其区分，每次随机检测一件产品，检测后不放回，直到检测出2件次品或者检测出3件正品时检测结束. （Ⅰ）求第一次检测出的是次品且第二次检测出的是正品的概率； （Ⅱ）已知每检测一件产品需要费用100元，设表示直到检测出2件次品或者检测出3件正品时所需要的检测费用（单位：元），求的分布列和数学期望.19、已知曲线的极坐标方程是．以极点为平面直角坐标系的原点,极轴为轴的正半轴,建立平面直角坐标系,直线的参数方程是（为参数）．（Ⅰ）将曲线的极坐标方程化为直角坐标方程；（Ⅱ）若直线与曲线相交于、两点,且,求直线的倾斜角的值．20、已知（Ⅰ）求不等式的解集；（Ⅱ）设为正实数，且，求证：21、近年空气质量逐步恶化，出现雾霾天气的现象增多，大气污染危害加重，大气污染可引起心悸、呼吸困难等心肺疾病.为了解某市心肺疾病是否与性别有关，某医院随机地对入院的50人进行了问卷调查，得到如下的列联表. 已知在全部50人中随机抽取1人，抽到患心肺疾病的人的概率为 （Ⅰ）请将列联表补充完整； （Ⅱ）是否有的把握认为患心肺疾病与性别有关？说明你的理由.附：．（Ⅲ）已知在患心肺疾病的10位女性中，有3位又患有胃病，现从患心肺疾病的10位女性中，选出3位进行胃病检查，求至少有1位患有胃病的概率.22、某种产品的广告费支出与销售额（单位：万元）之间有如下对应数据：（Ⅰ）求关于的线性回归方程；（Ⅱ）据此估计广告费支出为10万元时，所得的销售额.（参考数据：，参考公式：回归直线方程，其中）参考答案1、A2、D3、A4、B5、C6、A7、B8、D9、D10、C11、C12、B13、14、15、16、17、（I）丙；（ⅰ）；（ⅱ）18、（Ⅰ）；（Ⅱ）19、（Ⅰ）；（Ⅱ）或20、（Ⅰ）；（Ⅱ）证明详见解析．21、（Ⅰ）列联表见解析；；（Ⅱ）有%的把握认为患心肺疾病与性别有关；（Ⅲ）分布列见解析，22、（I）；（II）【解析】1、试题分析：对两边求导，可得，取，得.考点：导数的应用.【思路点睛】本体主要考查利用导数以及赋值法解决二项式问题，本题在解答过程中要注意，切不可用二项式定理的公式解决；首先注意到要求的结果，根据，对两边求导数，即可得到要求的形式，然后再利用赋值法即可求出结果.2、试题分析：每个电阻都有断路与通路两种状态，图中从上到下的三条支线路，分别记为支线，支线中至少有一个电阻断路情况都有种；支线中至少有一个电阻断路的情况有种，每条支线至少有一个电阻断路，灯就不亮，因此灯不亮的情况共有种情况.考点：分布计算原理.【思路点睛】每个电阻都有断路与通路两种情况，图中从上到下有3条支线，分别记为a、b、c，支线a、b中，至少有一个电阻断路的情况有3种，c中至少有一个电阻断路的情况有23-1=7种，再根据分步计数原理求得结果．3、试题分析：∵，在的展开式中，含的项为，∴．故选C．考点：二项式定理.4、试题分析：先将个人分成三组,或,分组方法有中,再将三组全排列有种,故总的方法数有种.又将位同学分别保送到北京大学，清华大学，浙江大学等三所大学就读，共有种，所以满足题意的概率为.考点：1.1排列组合；2.古典概型.【方法点晴】平均分成的组,不管它们的顺序如何,都是一种情况,所以分组后一定要除以其中为均分的组数,这是为了避免重复计数.非平均分组问题无分配对象，只要按比例分完，再用乘法计数原理来计算.非平均分组有分配对象，要把组数当作元素个数再做排列.分组问题和分配问题是有区别的，前者组与组之间只要元素个数相同是不区分的；而后者即使组元素个数相同，但因对象不同，仍然是可区分的.对于后者必须先分组后排列.5、试题分析：令，当时，，当时，当时，，所以，所以要使得不等式对任意实数恒成立；只要即可，∴或,故选C.考点：一元二次不等式的应用．6、试题分析：∵，故展开式中含项的系数为．考点：二项式定理的应用．7、试题分析：二项式展开式的通项为∴展开式中和的系数分别是∴，解得.故选B．考点：二项式定理.8、试题分析：由题意，，∴，故选D．考点：条件概率与独立事件．9、试题分析：派学生参加第1期培训的方法有种，派学生参加其余2期培训的方法有种，由分步计数原理可得不同的选派方式有种，故选D．考点：排列、组合及简单计数问题．10、试题分析：独立重复试验的性质可知，事件恰有1次发生的概率是.考点：独立重复试验.11、试题分析：根据题意，由于直线，则可知斜率为2，那么通过，消去参数t，可知选项A中，x，选项B，,选项D, ,可知范围不成立，故可知答案为C.考点：直线的参数方程．12、试题分析：随机变量ξ服从正态分布，∴曲线关于对称，∴，故选：B．考点：正态分布曲线的特点及曲线所表示的意义．13、试题分析：由，得，，所以.考点：1、二项式定理；2、合情与演绎推理．【知识点睛】归纳推理和类比推理是常用的合情推理，从推理形式上看，归纳是由部分到整体、个别到一般的推理；类比是由特殊到特殊的推理；而演绎推理是由一般到特殊的推理．从推理所得的结论来看，合情推理的结论不一定正确，有待进一步证明；演绎推理在大前提、小前提和推理形式都正确的前提下，得到的结论是正确的．14、试题分析：由点到直线的距离公式可得，点到直线的距离为，其中，所以当时，点到直线的距离的最大值是.考点：参数方程.【思路点睛】由点到直线的距离公式可得，点到直线的距离为，然后再根据三角恒等变换，化简可得其中，再根据三角函数的性质，即可求出结果.15、试题分析：由二项式系数的性质，可得，解可得，；的展开式为，令，可得，则展开式中常数项为15．考点：二项式定理.16、试题分析：由表格得到，．考点：离散型随机变量的期望与方差．17、试题分析：（I）利用条件，可得设备的数据仅满足一个不等式，即可得出结论；（II）易已知样本中次品共件，可轨迹设备生产零件的次品率为，（ⅰ）由题意可知，于是；（ⅱ）确定的取值，求出相应的概率，即可求出其中次品个数的数学期望．试题解析：解：（Ⅰ），，，因为设备的数据仅满足一个不等式，故其性能等级为丙；（Ⅱ）易知样本中次品共6件，可估计设备生产零件的次品率为0.06．（ⅰ）由题意可知，于是；（ⅱ）由题意可知的分布列为故．考点：正态分布曲线的特点及曲线所表示的意义．18、试题分析：（1）求古典概型概率，先确定两次检测基本事件个数：，再确定第一次检测出的是次品且第二次检测出的是正品的基本事件个数，从而得所求事件概率为（2）先确定随机变量：最少两次（两次皆为次品），最多四次（前三次两次正品，一次次品），三次情况较多，可利用补集求其概率，列出分布列，最后根据数学期望公式求期望试题解析：解:（Ⅰ）记“第一次检测出的是次品且第二次检测出的是正品”为事件，（Ⅱ）的可能取值为200,300,400（或）故的分布列为考点：1.古典概型概率；2.分布列和数学期望.【方法点睛】（1）求随机变量的分布列的主要步骤：一是明确随机变量的取值，并确定随机变量服从何种概率分布；二是求每一个随机变量取值的概率，三是列成表格；（2）求出分布列后注意运用分布列的两条性质检验所求的分布列是否正确；（3）求解离散随机变量分布列和方差，首先要理解问题的关键，其次要准确无误的找出随机变量的所有可能值，计算出相对应的概率，写成随机变量的分布列，正确运用均值、方差公式进行计算.19、试题分析：（Ⅰ）两边同时成以，再根据，即可将曲线的极坐标方程化为直角坐标方程；（Ⅱ）将直线参数方程代入圆的直角坐标方程中，利用直线参数方程的几何意义求出弦长等于解出即可.试题解析：解：（Ⅰ）由，得.（Ⅱ）将代入圆的方程得，化简得设两点对应的参数分别为，则，∴，∴，，或考点：考点：1、极坐标方程化为直角坐标方程；2、直线参数的几何意义.【方法点睛】1．极坐标方程化直角坐标方程，一般通过两边同时平方，两边同时乘以ρ等方式，构造或凑配，再利用互化公式转化．常见互化公式有等．2．参数方程化普通方程，关键是消参，常见消参方式有：代入法，两式相加、减，两式相乘除，方程两边同时平方等．3．若直线与曲线相交于，直线的斜率为，联立直线与曲线的方程，消去，再利用韦达定理将及的值整体代入弦长公式中即可达到目的，此思路体现了“设而不求”的思想．20、试题分析：本题主要考查绝对值不等式的解法、均值不等式等基础知识，考查学生的分析问题解决问题的能力、转化能力、计算能力．第一问，利用零点分段法去掉绝对值符号，转化为不等式组，解出x的范围；第二问，由，所以，平方得（*），利用均值不等式得、、，相加得：，代入（*）中得到结论．试题解析：（Ⅰ）不等式等价于不等式组或，或，解不等式组，得或或，所以不等式的解集为．（Ⅱ）证明：∵，∴，∵为正实数，∴由均值不等式，得（当且仅当时取等号），（当且仅当时取等号），（当且仅当时取等号），∴（当且仅当时取等号），∴，∴（当且仅当时取等号）．考点：绝对值不等式的解法、均值不等式．21、试题分析：（Ⅰ）根据在全部50人中随机抽取1人抽到患心肺疾病的概率为，可得患心肺疾病的人数，即可得到列联表；（Ⅱ）利用公式求得，与临界值比较，即可得到结论．（Ⅲ）在患心肺疾病的10位女性中，有3位又患有胃病，记选出患胃病的女性人数为，则服从超几何分布，即可得到的分布列、数学期望以及方差．试题解析：解：（Ⅰ）根据在全部50人中随机抽取1人抽到患心肺疾病生的概率为，可得患心肺疾病的为30人，故可得,列联表补充如下（Ⅱ）因为的观测值≈8.333，又P（）=0.005=0.5%，所以，我们有99.5%的把握认为是否患心肺疾病是与性别有关系的．（Ⅲ）从患心肺疾病的10位女性中，选出3位进行胃病检查，至少有1位患有胃病的概率考点：独立性检验的应用．22、试题分析：（I）根据公式求回归方程，要求出的值，代入公式即可；（II）令代入回归直线方程即可求得销售额的值.试题解析：解：（Ⅰ），又已知，于是可得：因此，所求回归直线方程为：（Ⅱ）根据上面求得的回归直线方程，当广告费支出为10万元时，（万元）即这种产品的销售收入大约为82.5万元.考点：回归直线方程.。

绝密★启用前【百强校】2015-2016学年福建师大附中高二下期末文科数学试卷（带解析）试卷副标题考试范围：xxx ；考试时间：149分钟；命题人：xxx学校:___________姓名：___________班级：___________考号：___________注意事项．1．答题前填写好自己的姓名、班级、考号等信息 2．请将答案正确填写在答题卡上第I 卷（选择题）一、选择题（题型注释）1、方程有且仅有两个不同的实数解，则以下结论正确的为 A ． B ．C ．D ．2、若关于的不等式有实数解，则实数的取值范围为A ．B ．C ．D ．3、函数（且）的图象可能为4、已知直线是的切线，则的值是（ ）A ．B ．C ．D ．5、将函数的图象向右平移个单位后得到函数，则函数A ．在区间上单调递减B ．在区间上单调递增C ．在区间上单调递减D ．在区间上单调递增6、在参数方程（,t 为参数）所表示的曲线上有B 、C 两点，它们对应的参数值分别为，则线段BC 的中点M 对应的参数值是A ．B ．C ．D ．7、函数的部分图像如图所示，则A ．B ．C ．D ．8、函数的定义域是A ．B ．C ．D ．A． B． C． D．10、参数方程（t为参数）表示什么曲线A．一条直线 B．一个半圆 C．一条射线 D．一个圆11、若，则下列结论不正确的是A． B． C． D．12、A． B． C． D．第II 卷（非选择题）二、填空题（题型注释）13、已知函数有两个极值点,则实数的取值范围是 ．14、若＝ ．15、在极坐标系中，经过点且与极轴垂直的直线的极坐标方程为 ．16、设，角的终边经过点，则=__________．三、解答题（题型注释）17、已知函数，其中，为自然对数的底数．（Ⅰ）求函数的单调区间；（Ⅱ）当时，，求实数的取值范围．18、设函数（Ⅰ）若，解不等式；（Ⅱ）记函数的值域为，若，求的取值范围．19、某同学在一次研究性学习中发现，以下五个式子的值都等于同一个常数．（Ⅰ）试从上述五个式子中选择一个，求出这个常数；（Ⅱ）根据（Ⅰ）的计算结果，将该同学的发现推广为三角恒等式，并证明你的结论．20、已知．（Ⅰ）求的最小值及此时的取值集合；（Ⅱ）将的图象向左平移个单位后所得图象关于原点对称，求的最小值．21、平面直角坐标系中，曲线．直线经过点，且倾斜角为．为极点，以轴正半轴为极轴，建立极坐标系．（Ⅰ）写出曲线的极坐标方程与直线的参数方程；（Ⅱ）若直线与曲线相交于两点，且，求实数的值．22、已知．（Ⅰ）求的值；（Ⅱ）若，求的值．参考答案1、B2、A3、D4、C5、D6、B7、A8、C9、B10、C11、C12、D13、14、15、16、17、（Ⅰ）详见解析；（Ⅱ）18、（Ⅰ）；（Ⅱ）19、（Ⅰ）；（Ⅱ）20、（Ⅰ）；（Ⅱ）21、（Ⅰ），（为参数）；（Ⅱ）或22、（Ⅰ）；（Ⅱ）【解析】1、试题分析：依题意可知（不能等于0）令，然后分别做出两个函数的图象．因为原方程有且只有两个解，所以与仅有两个交点，而且第二个交点是和相切的点，即点为切点，因为，所以切线的斜率．而且点在切线上．于是将点代入切线方程可得：．故选B．考点：1．正弦函数的图象；2．数形结合．【思路点睛】本题是中档题，考查数形结合的思想，函数图象的交点，就是方程的根，注意：的图象只有轴右半部分和轴上半部分，且原点处没有值（因为不等于）；的图象是过原点的一条直线．由题意构造函数，然后分别做出两个函数的图象，利用图象和导数求出切点的坐标以及斜率，即可得到选项．2、试题分析：∵，∴，由不等式有实数解，知，解得．考点：绝对值不等式．【思路点睛】本题考查绝对值不等式、有关绝对值不等式恒成立的问题．利用大于的最小值，求出实数的取值范围是关键．根据绝对值不等式，求出的最小值等于，从而有大于的最小值，列出不等关系解出实数的取值范围即得．3、试题分析：,且定义域关于原点对称，所以函数为奇函数，又当时，所以图像可能是D．考点：1．函数奇偶性；2．函数图像．4、试题分析：设切点坐标为，∵曲线，∴，∴①，又∵切点在切线上，∴②，由①②，解得，∴实数的值为．故选C．考点：利用导数研究曲线上某点切线方程．5、试题分析：把函数的图象向右平移个单位长度，得到的图象所对应的函数解析式为：．即．当函数递增时，由，得．取，得．∴所得图象对应的函数在区间上单调递增．故选：D．考点：函数的图象变换．6、试题分析：，对于中点有同理∴线段的中点对应的参数值是，故选B．考点：1．圆的参数方程；2．中点坐标公式．【思路点睛】本题考查圆的参数方程和中点的坐标公式，本题解题的关键是已知圆上的点，写出点对应的参数式，根据两个点在圆上，可以写出两个点对应的坐标，根据中点的坐标公式，表示出中点的坐标，得到要求的中点对应的参数值．7、试题分析：由图象可知，，所以，当时，，故选A．考点：函数的图象．8、试题分析：因为，所以选C．考点：1．函数的定义域；2．正切函数的性质．9、试题分析：因为是第二象限角，且，所以．考点：两角和的正切公式．10、试题分析：，其中它表示端点为的一条射线．考点：直线的参数方程．11、试题分析：，所以，故选项C不正确．考点：不等式的性质．12、试题分析：．考点：任意角的三角函数值．13、试题分析：解：．令，∵函数有两个极值点，则在区间上有两个实数根．，当时，，则函数在区间单调递增，因此在区间上不可能有两个实数根，应舍去．当时，令，解得．令，解得，此时函数单调递增；令，解得，此时函数单调递减．∴当时，函数取得极大值．当趋近于与趋近于时，，要使在区间上有两个实数根，则，解得．∴实数的取值范围是．考点：利用导数研究函数的极值．【思路点睛】．令，由于函数有两个极值点在区间上有两个实数根．．当时，直接验证；当时，利用导数研究函数的单调性可得：当时，函数取得极大值，故要使有两个不同解，只需要，解得即可．14、试题分析：因为，所以，又．考点：三角恒等变换．【思路点睛】因为，所以，又，由此代入数据，即可求出结果．15、试题分析：点的直角坐标为，故过此点且垂直于极轴的直线方程的直角坐标方程为，化为极坐标方程为．考点：简单曲线的极坐标方程．16、试题分析：．考点：任意角的三角函数．17、试题分析：（Ⅰ），令，当，，单增，，，单减；（Ⅱ）令，即恒成立，而，利用导数的性质和零点存在定理，即可求出结果．试题解析：（Ⅰ），令，当，，单增，，，单减；（Ⅱ）令，即恒成立，而，令，∵，在上单调递增，，当时，，在上单调递增，，符合题意；当时，在上单调递减，，与题意不合；当时，为一个单调递增的函数，而，，由零点存在性定理，必存在一个零点，使得，当时，，从而在上单调递减，从而，与题意不合，综上所述：的取值范围为．考点：1．导数在函数单调性中的应用；2．函数的零点存在定理．18、试题分析：（Ⅰ）由于，故，分，和两种情况讨论，即可求出结果；（Ⅱ）分和两种情况，就可以求出结果．试题解析：解：（Ⅰ）由于，故当时，由，得，解得；当时，，得，解得综上，不等式的解集为（Ⅱ）当时，，的值域当，得，解得，又，故当时，，的值域当，得，解得，又，故综上，的取值范围为．考点：绝对值不等式．19、试题分析：（Ⅰ）这是一个利用三角函数公式进行变换化简求值的问题，主要是抓住“角”之间的关系，联想借助降幂公式及逆用两角和与差的正余弦公式可求得结果；（Ⅱ）依据式子的结构特点、角之间的关系，可以得到形如“”的规律．然后利用和第（Ⅰ）问类似的思路进行证明．试题解析：解：（Ⅰ）．（Ⅱ）=．左边[来源:学_科_网]考点：1．数学归纳法；2．归纳推理．【方法点睛】归纳推理一般是先根据个别情况所体现出来的某些相同的规律，然后从这些已知的相同性质规律推出一个明确的一般性规律或性质．此题是一个三角函数式，所以重点抓住角之间的关系，式子的结构特点进行归纳，得出一般性结论．20、试题分析：（Ⅰ），由三角函数的性质即可求出最值；（Ⅱ）图象向右平移个单位后所得图象对应的角析式为其为奇函数，那么图象关于原点对称，故：，，由此即可求出结果．试题解析：（Ⅰ）∴的最小值为-2，此时，，∴的取值集合为：（Ⅱ）图象向右平移个单位后所得图象对应的角析式为其为奇函数，那么图象关于原点对称，故：，∴，所以正数的最小值为．考点：1．三角恒等变换；2．三角函数的性质．【方法点睛】三角函数的一般性质研究：1．周期性：根据公式可求得；2．单调性：令，解出不等式，即可求出函数的单调递增区间；令，解出不等式，即可求出函数的单调递减区间；3．令或，即可求出函数取最大或最小值时的取值集合．21、试题分析：（Ⅰ）曲线．展开为：，把代入可得曲线的极坐标方程．直线的参数方程为：，（为参数）．（Ⅱ）设两点对应的参数分别为．把直线的参数方程圆的方程可得：，利用，可得，解得即可得出．试题解析：（Ⅰ）曲线．展开为：，可得，即曲线的极坐标方程为．直线的参数方程为：，（为参数）．（Ⅱ）设两点对应的参数分别为．把直线的参数方程代入，可得：．，解得或．考点：简单曲线的极坐标方程．22、试题分析：（Ⅰ）①，，化简整理即可求出结果；（Ⅱ）由（Ⅰ）得，，又，，可得，由此即可求出结果．试题解析：（Ⅰ）①，，即，（Ⅱ）由（1）得，又，，②．考点：1．同角的基本关系；2．诱导公式．。

绝密★启用前【百强校】2015-2016学年福建师大附中高一上学期期末英语试卷（带解析）试卷副标题考试范围：xxx ；考试时间：86分钟；命题人：xxx学校:___________姓名：___________班级：___________考号：___________注意事项．1．答题前填写好自己的姓名、班级、考号等信息 2．请将答案正确填写在答题卡上第I 卷（选择题）一、阅读理解（题型注释）Everyone has good days and bad days.Sometimes, you feel as if you‟re on top of the world. But occasionally you feel horrible, and you lose things and you cannot focus on your schoolwork.For more than 20 years, scientists have suggested that high self-esteem (自尊) is the key to success. Now, new research shows that focusing just on building self-esteem may not be helpful. In some cases, having high self-esteem can bring bad results if it makes you less likeable or more upset when you fail at something.“Forget about self -esteem,” says Jennifer Crocker, a psychologist (心理学家) at the University of Michigan, US. “It‟s not the important thing.” Feeling good[来源:学科网ZXXK]Crocker‟s advice may sound a bit strange because it is good to feel good abou t yourself. Studies show that people with high self-esteem are less likely to be depressed, anxious, shy, or lonely than those with low self-esteem.试卷第2页，共12页But, after reviewing about 18,000 studies on self-esteem, Roy Baumeister, a psychologist at Florida State University, has found that building up your self-esteem will not necessarily make you a better person.He believes that violent and wicked (邪恶的) people often have the highest self-esteem of all. He also said: “There‟s no evidence that kids with high self -es teem do better in school.” ProblemsAll types of people have problems. People with high self-esteem can have big egos (自我) that can make them less likeable to their peers(同龄人), said Kathleen Vohs, a psychology professor at Columbia University.People with high self-esteem tend to think more of themselves, Vohs says. People with low self-esteem are more likely to rely on their friends when they need help. What to doResearchers say it is best to listen to and support other people. Find positive ways to contribute to society. If you fail at something, try to learn from the experience. “The best therapy (药方) is to recognize your faults,” Vohs says. “It‟s OK to say, …I‟m not so good at that,‟ and then move on.”1、The new research comes to the conclusion that high self-esteem ________. A ．is not important at all B ．may not be the key to success C ．has taken on a different meaning D ．does not help you do better at school2、One of the conclusions of the new research is that ________. A ．people with high esteem tend to be proudB ．people with high esteem usually do not seek other‟s helpC ．feeling good about oneself doesn‟t mean you lead a happier lifeD ．people with low esteem are often more popular3、The underlined part “a better person” in the passage probably means a pers on who is ______. A ．helpful and supportive B ．gentle and modest C ．likable and successful D ．friendly and kind4、From the text, we can infer the best therapy mentioned in the last paragraph is mainly for people ________. A ．of all kindsB．with low self-esteemC．with high self-esteeD．who are focusing on building self-esteemHayao Miyazaki, the 72-year-old Japanese master of fantasy animation (奇幻动画), one of the most respected animation directors in the world, announced his retirement on September 6, after the recent release of his new film The Wind Rises.Miyazaki‟s vision(视野) has remained unique throughout his many films over the past thirty years. The worlds he creates—the valley of the wind, the castle in the sky, and so many—are so special, so attractive. Here are some key words about his films.Good and evil (邪恶) Miyazaki rarely tells stories in simple good and evil. The worlds he creates tend to be complex (复杂的) and unclear. The bad figures often don‟t seem so bad once you get to know them. Miyazaki has explained that the lack of clear good and evil is because he sees the 21st century as complex time, in which old ideas need to be re-examined, even in children‟s films.Children The heroes in Miyazaki‟s films are usually children or teens, more often young girls. Sometimes they can see the spirit world; they are curious and friendly, even to strange creatures. The stories often deal with growing up.Sky and water Two of Miyazaki‟s great loves are the sky and water, and he uses them in related ways. Flight is a forever theme—Miyazaki has never done a film without flying of some kind. His imagination seems to fly and leave behind the pull of gravity (重力), a force and control that he feels a bound (束缚) from setting him free. Water is another way for Miyazaki to fight gravity. In his films he likes the unexpected floods with crystal-clear water, and objects floating on the surface seem to be supported by magic.Peace Miyazaki‟s negative view of the war goes far more than surface deep. Violence is usually seen as wrong and painful, and Miyazaki‟s heroes are often peacemakers.5、What can we know about good and evil from Miyazaki‟s films?A．The complex time tends to turn good into evil.B．He uses his films to show good finally defeats evil.C．The figures cannot be simply judged as good or evil.D．Children should learn to clearly tell good from evil.6、Miyazaki‟s love for flight may come from ______.试卷第4页，共12页A ．the relation between sky and waterB ．his hate for gravity since his childhoodC ．his desire to be free from gravityD ．his love for water that can flood the world 7、In Miyazaki‟s films we may NOT see ______. A ．the attractive castle in the sky B ．a world left in ruins in the end C ．objects magically floating on the water D ．children with the problems of growing up 8、The purpose of writing the article is to ______.A ．show the writer‟s sadness for Miyazaki‟s retirement from the animation industryB ．help readers to k now about Miyazaki‟s life and his great achievementsC ．praise Miyazaki‟s contribution to the development of the film industryD ．introduce Miyazaki‟s retirement and the features (特点) of his animation filmsA mother is devastated, crying, yelling all she can in that dark corner. There was nobody tohear her yell and not a soul to calm her, because outside her house is a long winding lonely road.The wind was at rest and the leaves didn't rustle, silence filling the air. Loneliness was alreadykilling her ，but no one knows what made her cry.Losing something you love with all your heart isn't really the pain you can everovercome.Radha lost her baby, her only means to live. She saw her child getting killed and the accidentwas terrible. One lonely night, she was walking down the street to get a breath of fresh air withher child hugged tight in her arms.The whole time she walked with her child in her arms. The only thing that worried her wasAryan's future. She was imagining and feeling every day of the child‟s growt h, and figuringwhat she would have in store for him. But who knows what's in store for us tomorrow? Life canchange in a second.On that deserted road, were a few streetlights barely enough? It was this one light that couldbe seen from a distance, but as it came closer it got brighter and brighter. That lightchangedRadha's life into darkness forever. A speeding car came down that road. The driver came at aspeed of 110 kmph throwing beer bottles out of his half open window. He was definitely drunk,and the speed took everything in its path. Just then, there was a loud cry, andsilence set in again.But the mother wasn‟t hurt. She opened her eyes, unable to focus her eyes, and didn‟t seeAryan. After a few minutes when her sight cleared up she looked all over in a panic for her baby,but alas! ... The child hadn‟t even seen life.Simply, don't drink and drive. You could take a life, but kill a number of people. 9、The word“devastated” in Paragraph 1 would probably mean____________ . A ．worried B ．scaredC ．heart-brokenD ．weather-beaten 10、Which of the following statements is TRUE of Radha? A ．She had expected much of Aryan. B ．She got her eyes injured in the accident. C ．She was hit by one bottle on the arm. D ．She had everything ready for Aryan's future.11、The last sentence underlined implies that __________. A ．drunk driving is absolutely forbidden B ．drunk driving is certain to kill a lot of people C ．the driver killed Aryan and his motherD ．there is more than one victim (受害者) in a car accident 12、What would be the best title for the passage? A ．The Death of a Miserable Child B ．The Price for Another Man's Mistake C ．A Sad Mother on a Windy Night D ．Overspeeding from Drunk Driving二、完形填空（题型注释）完形填空As a hospital volunteer, I call on each assigned AIDS patient at least once a day. I most patients with a gentle hug and a kiss on the cheek.I can usually whether or not a patient is comfortable with this .After my third to Mary, I asked politely. “Would you like a hug and a kiss on your cheek?”试卷第6页，共12页Mary smiled, “Yes, I‟d love one.” I drew back,I noticed a tear working its down one cheek. “What‟s wrong?”I asked.“That‟s the first time anyone has me this way since I was attacked by AIDS. The medical staff (工作人员) touch me, but…” she said between sobs (哭泣). I simply sat beside her ， in silence.A few days later, when I went to see Mary , one of her sons and his wife were visiting. “Good evening, Mary. I see you have , so I‟ll stop back later,”I said, giving her a gentle hug and a kiss. Mary grabbed my right wrist as I turned to . “Wait a minute, Mack. I want you to meet my son, John, and daughter-in-law, Sarah.”During the , her anxious family sat clear across the room Mary‟s bed.Later, when I looked in on her, her visitors were still keeping their distance.The evening, John and Sarah were back again, and the scene itself like a familiar rerun on television. I went in, gave Mary a hug and a kiss, to come back later.When I returned, had changed, John and Sarah were seated in chairs — one on each side of Mary‟s — and they were holding hands.Obviously moved, John said, “I guess nothing to if a stranger can hug and kiss my mother.”13、A ．greet B ．see C ．visit D ．help 14、A ．expect B ．ask C ．sense D ．doubt 15、A ．gesture B ．fashion C ．hope D ．idea 16、A ．greeting B ．apology C ．visit D ．explanation 17、A ．Because B ．Where C ．Although D ．As 18、A ．face B ．eye C ．nose D ．way 19、A ．visited B ．pitied C ．touched D ．eared 20、A ．listening B ．sobbing C ．waiting D ．staring 21、A ．late B ．again C ．last D ．first22、A ．interviews B ．roommates C ．affairs D ．guests 23、A ．speak B ．leave C ．sit D ．stay24、A ．days B ．greetings C ．introductions D ．visits 25、A ．to B ．beside C ．on D ．from26、A ．dangerous B ．near C ．safe D ．different 27、A ．following B ．final C ．previous D ．usual28、A ．expressed B ．discovered C ．searched D ．repeated 29、A ．getting B ．trying C ．promising D ．managing 30、A ．something B ．nothing C ．somebody D ．nobody 31、A ．room B ．bed C ．son D ．daughter-in-law32、A ．take care of B ．be afraid of C ．speak well of D ．be proud of三、单项选择（题型注释）33、 So many floods have cut down on the production of peanuts; _______, the price has gone up a great deal.A ．in other wordsB ．in briefC ．even soD ．as a result34、---Why are you still here? Everybody has gone to attend the lecture by the president. ---Oh, I ___________ about it!A ．wasn‟t informedB ．hadn‟t been informedC ．haven‟t informedD ．didn‟t inform35、 --- Have you heard that Tom was given a good beating by his father last night? --- He ________ it. He was making trouble everywhere all the time. A ．made B ．got C ．deserved D ．gained36、People Who Moved China, hosted by CCTV, honors the people _______ the valuable contributions should be remembered by every Chinese.A ．whoseB ．of whomC ．thatD ．of which37、His son will _________him as chairman of the commission after his retirement. A ．continue B ．succeed C ．follow D ．learn38、Sam _____ some knowledge of the computer just by watching others working on it. A ．picked up B ．looked up C ．brought up D ．set up试卷第8页，共12页39、 I like the music _____ he danced yesterday, which was composed by a famous musician. A ．with which B ．against which C ．to which D ．to that40、The palace caught fire three times in the last century, and little of the original building _____ now.A ．is remainingB ．remainsC ．has been remainedD ．is remained41、Mum pretended ________ what happened yesterday at school, but in fact, she has been told about every detail. A ．not to hear about B ．not to have heard about C ．not to be hearing about D ．to not hear about42、If you miss this chance, it may be years __________ you get another one. A ．after B ．when C ．before D ．since第II卷（非选择题）四、单词拼写（题型注释）根据所给首字母, 写出正确的单词来完成句子。

2018-2019学年福建师大附中高二（上）期末英语试卷第一部分听力（共20 题；每小题 1 分，满分 5 分）第一节听下面 5 段对话．每段对话后有一个小题，从题中所给的 A、 B、 C 三个选项中选出最佳选项，并标在试卷的相应位置．听完每段对话后，你都有10 秒的时间来回答有关小题和阅读下一小题．每段对话仅读一遍．1． Where are the speakers ？A． In a hospital ．B． In a restaurant ．C． In a hotel ．2． What did the man like best about the festival ？A． The rides ．B． Fireworks ．C． Some performers ．3． What did the woman do upstairs ？A． She answered a phone call ．B． She took a rest ．C． She worked on a report ．4． How does the woman feel about the man inviting Mike ？A． Dissatisfied ．B． Pleased ．C． Interested ．5． Why did the woman call her friends ？A． To wake them up ．B． To get help from them ．C． To inform them of a meeting ．第二节听下面 5 段对话或独白．每段对话或独白后有几个小题，从题中所给的A、 B、 C 三个选中选出最佳选项．听每段对话或独白前，你将有时间阅读各个小题，每小题 5 秒钟；听完后各小题将给出 5 秒钟的作答时间．每段对话或独白读两遍．6．（ 1）Why doesn't the man want to go for a picnic？A． The weather is bad．B． It is not fun．C． He is tired．（ 2） Where will the speakers go next？A． To a park．B． To a cinema．C． To a lake．7．（ 1）How many meals does the man usually have on weekends？A． Two．B． Three ．C． Four ．（ 2） What does the man often drink later in the evening？A． Red wine ．B． White wine．C． Beer ．8．（ 1）What does the woman check first ？A． If Flight 721takes off on time ．B． If there is a flight to Alabama on Friday ．C． If there are seats available on Flight 712 ．（ 2） How long does it take to get to Alabama ？A． 2.5hours ．B． 2hours ．C． 1.5hours ．（ 3） What does the man want ？A． A round ﹣ trip ticket．B． A window seat ．C． A first ﹣ class air travel ．9．（ 1）What are the speakers mainly discussing ？A． How to act properly in a lab ．B． Whether to wear safety glasses ．C． What to do before using a lab ．（ 2） Why is the man coming to the lab ？A． To get some protective clothing ．B． To see Professor Kennedy ．C． To do his experiment ．（ 3） What is required according to the woman ？A． Keep gloves clean while in the bathroom ．B． Walk around and check the lab ．C． Wear a lab coat at all times ．（ 4） What could the woman be ？A． A science researcher ．B． A lab technician ．C． A chemistry professor ．10．（ 1） Who is Patrick Millar ？A． A host of Food and Drink Show ．B． A director of the Palace Hotel ．C． A well ﹣ known cook ．（ 2） What did the speaker do first after leaving school ？A． She took a cookery course ．B． She worked in the Palace Hotel ．C． She attended a secretarial college ．（ 3） What is the speaker expected to do for Patrick ？A． Prepare the working lunch ．B． Deal with customers ．C． Collect books ．（ 4） What does the speaker say about her job ？A． She has a lot to do every day ．B． She learns a lot from it ．C． She loves it very much ．第二部分阅读理解（共两节）第一节（共 12 小题；每小题2 分，满分24 分）阅读下列短文，从每题所给的四个选项（A、 B、C、和 D）中，选出最佳选项，并在答题卡上将该项涂黑．On the eve of our daughters' weddings，I gave both of them what I considered to be excellentmarital advice：never leave your husband unsupervised（无人监督的）with pruning shears（修枝剪）．If only I had taken my own advice ． I recently let my guard down． Thirty﹣some years of marriage can do that to a woman． Give a man pruning shears and electric trimmers（电动修剪器）and he will give new meaning to "armed and dangerous．"One day earlier this year，my husband said that the crab apple tree was dead．"Why do you think it is dead？" I asked．"Look at it．There's not a leaf on it．""There's not a leaf on anything．It's March，" I said"It looked sick last fall and with this bitter winter we had，I'm convinced it's dead．"The truth is he's never liked the crabapple．Sure，it has beautiful blooms in the spring，but then it gets a disease，the leaves curl，and it drops those little apples that sit on thedriveway ．Each passing week he pronounced the tree dead．Eventually I began to believe him．Though he agreed it would be a regrettable loss，there was a twinkle in his eye． He armed himself a couple of weeks ago and began trimming ． A branch here ， a branch there ， a small limb ， then a large limb ． I watched and then decided to check the wood on some of the branches closer to the trunk．I broke one off and saw green．The crabapple was not dead．It just hadn't had time to leaf out．The tree was now fallingto one side ， but it was not dead ． I would have told him so， but he had moved on to a maple． Once the man starts，he can't stop．One trim leads to another．"Please ， stop!" I called．He smiled and nodded， but he couldn't hear because he had started the hedge （树篱）trimmers and was getting ready to fix a line of hedges．Zip（飕飕声），zip，zip．"What do you think？" he shouted．"It's supposed to be a privacy hedge；now all that will be private are our ankles．"He started the trimmers again．"Stop!" I called，"Come back!""Why？ " he shouted．"You're in the neighbor's yard ． "1. By saying "If only I had taken my own advice ． " the author means that ．A. she didn't follow her own advice about pruning shears ．B. she feels regretful about her marriage after many years ．C. she shouldn't have kept a close watch on her husband ．D. she shouldn't have given that marital advice to her daughters ．2. We can learn from the article that the author's husband ．A. has a great talent for gardening ．B. nearly ruined their neighbor's garden ．C. mistook their crab apple tree for a maple tree ．D. had never used pruning shears before ．3. What does the article mainly talk about ？A. Why the author's husband insisted on trimming their crabapple tree ．B. Why the author's husband shouldn't have been allowed to trim their crab apple tree ．C. How the author has survived her "thirty ﹣ some" years of marriage ．D. How the author's husband killed their crab apple tree ．4. What is the tone of the article ？A. Anxious ．B. Critical ．C. Serious ．D. Humorous ．【答案】 1.A 2.B 3.B 4.D【解析】本文是一篇记叙文。

2015-2016学年下学期高二年级期末考试（英语）2016.7.11 满分150分；用时120分钟第一部分客观题（满分100分）第一部分：听力（共两节，满30分）第一节（共5小题；每小1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What did the man do last weekend?A. He watched a football match.B. He stayed at home.C. He attended a meeting.2. Why is the man late?A. His car broke down.B. He had his car repaired.C. He missed the bus.3. What kind of journey did Susan make?A. A train journey.B. A ship journey.C. A plane journey.4. What is the man doing now?A. W ashing.B. Reading.C. W atching TV.5. When did the man receive Georgia‘s invitation?A. When the woman told him about the news.B. After he had decided to go to another party.C. After the dinner.第二节（共15小题，每小题1.5分；满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

福建师大二附中2015-2016学年第一学期高一年段期末考英语科试卷班级姓名座号准考证号听力第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面对5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What will the woman do tomorrow?A.Go to a dance partyB.Care for her mother.C.Go to the hospital.2.Where is Jim now?A.In China.B. In the US.C. In France.3.what’s the weather like now?A.CloudyB. Fine.C. Rainy4.What are the two speakers mainly talking about?A.A book.B. The man’s eye.C. The man’s interest5.When will the meeting begin?A.At 2:30pmB. At 3:00pm.C.At 3:30pm第二节（共15小题；每小题1.5分，满分22.5分）听下面对5段对话。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话或独白前，你将有时间阅读各个小题，每题5秒钟；听完后，各小题给出5秒作答时间。

每段对话或独白读两遍。

听第6段材料，回答6，7题6.what does the man most probably want to do?A.Eat at a restaurant.B. Watch a movieC. Go to a hotel.7.How far is it from the hotel to the white building?A. A five-minute walkB. A ten-minute walkC. A fifteen-minute walk听第7段材料，回答8，9题8.How often does the newspaper come out?A. Every day.B. Once a weekC. Twice a week9.What kind of movies does the man like watching the most?A.Horror moviesB. Funny moviesC. Science fictions听第8段材料，回答10至12题10.How does the woman go to work now?A. By busB. By subwayC. By bike11.What does the man think of cares?A. ConvenientB. UnnecessaryC. Bad for environment12.How does the man r eact to the woman’s advice?A.He wants to follow itB.He is very disappointedC.He is really surprised.听第9段材料，回答13至16题13.Why does the woman to to Bath?A. To visit relatives.B. To do sightseeingC. To learn about history14.What do we know about the Jane Austen Centre?A.Jane Austen once lived there.B.It’s the most famous place in BathC.Two of Jane Austen’s books were set there.15.Why has the woman booked tickets?A. To save time.B. To save money.C. To avoid ticket shortage.16.What’s the man’s plan for the summer?A.To travel to Oxford.B. To go with the woman.C. To visit tea houses. 听第10段材料，回答17至20题17.Wehn may they enter the Forbidden City on October 10th?A. At 7:00am.B. At 7:30am.C. At 7:45am.18.What will they do on the night of October11th?A. Watch showsB. Go shoppingC. Walk around the city19.What will they do next?A.Go to their hotel.B. Go to a restaurantC. Go to Tian’anmen Square.20.Who is the speaker speaking to?A.Some Chinese touristsB.Some American touristsC.Some Chinese students.第二部分: 阅读理解(30%)AOne evening after dinner, Mr. and Mrs. Tisich called a family meeting. “We’ve had to make a difficult decision,” Mr. Tisich announced. “You see, your mother has been offered a post as co-director of a television station in Chicago. Unfortunately, the station is not here. After thinking long and hard about it, we’ve concluded that t he right decision is to move to Chicago.”Marc looked shocked, while his sister Rachel breathlessly started asking when they’d be moving. “It’s surprising, but exciting!” she said. Marc simply said, “We can’t go—I can’t leave all my friends. I’d rather stay here and live with Tommy Lyons!”The Tisichs hoped that by the time they moved in August, Marc would grow more accustomed to the idea of leaving. However, he showed no signs of accepting the news, refusing to pack his belongings.When the morning of the move arrived, Marc was nowhere to be found. His parents called Tommy Lyons’ house, but Mrs. Lyons said she hadn’t seen Marc. Mrs. Tisich became increasingly concerned, while her husband felt angry with their son for behaving so irresponsibly. What they did n’t know was that Marc had started walking over to Tommy’s house, with a faint idea of hiding in Lyons’ attic(阁楼) for a few days. But something happened on the way as Marc walked past all the familiar landscape of the neighborhood: the fence that he and his mother painted, the tree that he and his sister used to climb, the park where he and his father often took evening walks together. How much would these m ean without his family, who make them special in the first place? Marc didn’t take the time to answe r that question but instead hurried back to his house, wondering if there were any moving cartons(纸板箱)the right size to hold his record collection.21. The conflict in this story was caused by___________.A. Marc and Rachel’s different tempersB. a quarrel between Tommy Lyons and MarcC. Marc’s disagreement with his parents about their moveD. Mr. and Mrs. Tisich’s remark of Marc’s irresponsibility22. Marc and Rachel’s reactions to the move were similar in the way that both were____________A. surprisedB. angry and upsetC. anxious for more detailsD. worried about packing23. The reason for Marc’s going home was that _________________.A. he did not want to be left behindB. he realized his family was essential to himC. he hoped to reach an agreement with his parentsD. he wished to be a more responsible person24. What would most likely happen next?A. Marc would bring his records over to the Lyons’s house.B. Mr. and Mrs. Tisich would call the police.C. Marc would join his family for house moving.D. Mr. and Mrs. Tisich would start searching for MarcBStudents in many countries are learning English. Some of these students are small children. Others are teenagers. Many are adults. Some learn at school, others learn by themselves.A few learn English over the radio, on TV, or in film. One must work hard to learn another language.Why do all these people want to learn English? It is difficult to answer this question. Many boys and girls learn English at school because it is one of their subjects r equired for study. They study their own language and maths and English. Some people learn it because it is useful for their work. Many people learn English for their higher studies, because at college or university some of their books are in English. Other people learn Englishbecause they want to read newspaper or magazines in English.25.People learn English _________.A．at school B．over the radio C．on TV D．not all in the same way26.Different kinds of people want to learn English __________.A．together with other subjects B．for different reasonsC．for their work D．for higher studies at college27.From this passage we know that _________.A．we can learn English easilyB．English is very difficult to learnC．English is learned by most people in the worldD．English is a useful language but one must work hard to learn28.Which of the following is right?A．we don’t need to learn any foreign languages.B．we can do well in all our work without English.C．English is the most important subject in school.D．we should learn English because we need to face the world.CThe US company iRobot made a new kind of sub-marine (潜水艇), called the Seaglider, last week.The robotic submarine was developed by re-searchers at the University of Washington. It is about 1.8 meters long and weighs about 52 kilograms. It moves through water at a speed of up to 20-25 kilo-meters a day and can stay at sea for up to six months before needing a battery recharged. This special character results from its special propulsion system (动力系统). Unlike a traditional submarine, the Seaglider does not have a propeller (螺旋桨). It has an air tank that is emptied and filled to adjust (调整) depth, as well as a pair of wings that help to guide and lead the submarine.A traditional submarine, on the other hand, “puts water inside tanks to make it heavier, or it will expel (排出) the water to make it lighter,” explained Frederick, a professor at the University of Washington.Each time the Seaglider comes to the surface, it sends the data which it collects toits controllers by satellite. Operators can also send the submarine new information. For example, they can change its course in their office through giving the computer orders.Seagliders are already being used for scientific re-search, such as environmental studies. iRobot also hopes to sell the submarine to the military (军队). At $100,000 each, the Seaglider is a cheap way to keep an eye on the ocean.“These things can go out there and monitor (监控) large areas of ocean because they’re very persistent. They can go for thousands of miles on their own. At the same time, you can tell them to stay in one place and they can circle,” says Helen Greiner, chairwoman of iRobot. “This is science fiction stuff in many ways, but it’s really o ut there and working.”29. Unlike a traditional submarine, the Seaglider _____.A. is only 1.8 meters long and weighs 52 kilogramsB. has an air tank to adjust depth instead of a propellerC. can travel at a speed of 150 kilometers a dayD. can be used to do environmental research30. When the Seaglider comes to the surface, it will _____.A. change its batteryB. force out a lot of waterC. send the data to its controllersD. stay in one place31. Nowadays, the Seaglider is being used only _____.A. by the militaryB. in scientific researchC. by the governmentD. in science fiction32. It can be inferred from the passage that the Seaglider _____.A. is not driven by a human beingB. doesn’t need a battery rechargedC. doesn’t have a long lifeD. can change its course itselfD“I don’t like my parents. They always tell me I should do this, and should not do that. It sometimes makes me angry,” said Li Ping, a m iddle school student in Hunan. Do you have the same problem? Perhaps your parents had the same problem when they were your age long ago. Why does it seem that some parents are not so friendly in their children’s eyes?One of the biggest things is when someone becomes a parent, he / she likes worrying things. They worry about everything about you, from the time you were born. They do a lot for you, though something would make you angry, because they care about you and worry about you. They worry about your choice of friends, the food you eat, your work at school, how much sleep you get, etc. All these things are part of your life. They want you to grow up healthily and happily.So how can you make things easier on yourself? It’s easier than you think. Just m ake sure your parents know what you’re doing. Get them to know your friends. Phone if you stay somewhere else so that your parents don’t call every hospital in the phone book looking for your body. Say sorry to them when you make mistakes. Take responsibility (责任) for what you have done. Talk about your ideas with them. They may talk about theirs with you.Most of all, try to think about why your parents do this or do that. They are still practicing being parents and need help you can give them. Someday, when you become a parent, they may be able to help you know how to get on with your children.33. What does the writer think we should do if we go back home later than usual? We should ________.A. tell our friendsB. tell the teacherC. say sorry to our parentsD. make a telephone call to our parents34. The writer thinks ________.A. it’s wrong of parents to worry about their children too muchB. some parents are unfriendly, which makes their children angryC. children should do everything as their parents sayD. parents love their children very much and the children should understand them35. Which do you think is the best title for the passage?A. Parents’ ResponsibilityB. How to Get on with ParentsC. Zhang Hua’s ProblemD. What Are Parents Worrying about .第三部分：完形填空(30%)The day before Father’s Day, Mrs. Berry asked her students to make a card for theirfathers. She passed out paper and pieces of cloth.Elizabeth looked for a while at the blue cloth and began to cut it. Then she 36 her paper in half and began writing. When Elizabeth finally looked at the message the teacher gave on the paper, she noticed something else. She felt her 37 grow hot —she hadn’t heard that anyone who didn’t have a father could make one for a grandfather or an uncle.As her teacher walked to her, E lizabeth tried 38 her card with her arm, but Mrs. Berry gently 39 it so that she could read it. Elizabeth sat 40, waiting for her to say something, but she saw a 41 roll down Mrs. Berry’s face. She had never made Mrs. Berry so ups et.When school was over, Elizabeth 42 until all the other kids left so that she could 43 . “I’m sorry for not listening. I’ll make another card 44 you want. I’ll do it 45 and bring it tomorrow.”“ 46 are you talking about?” asked Mrs. Berry.“My Father’s Day card. I know you’re upset be-cause I didn’t do it 47 .”“Elizabeth, that was the 48 card in the whole class. It was so 49 that it made me cry.”Elizabeth was so 50 that she ran out of the class-room.When her mom came home from work that night, Elizabeth 51 to give her the card early.On the front of the card was a 52 of Elizabeth’s mom, with a blue piece of cloth cut like her hair. In-side the card she had written:Dear Mom,I know you work really hard to be both a mommy and a(n) 53 . I want to thank you and54 you a happy Father’s Day!Love,ElizabethWhen her mom read the card she started 55 , just like Mrs. Berry did.36. A. cut B. tore C. spread D. folded37. A. heart B. face C. hands D. body38. A. covering B. holding C. doing D. making39. A. caught B. left C. lifted D. placed40. A. alone B. still C. up D. down41. A. tear B. smile C. hair D. sweat42. A. worked B. waited C. stood D. sat43. A. apologize B. stop C. understand D. stay44. A. because B. until C. unless D. if45. A. just here B. at once C. at home D. at school46. A. Who B. Whose C. Which D. What47. A. carefully B. quickly C. wrong D. right48. A. worst B. best C. favorite D. simplest49. A. wild B. useful C. sweet D. hard50. A. happy B. regretful C. brave D. rude51. A. seemed B. decided C. refused D. promised52. A. recording B. discovery C. drawing D. writing53. A. teacher B. sister C. daddy D. aunt54. A. wish B. hope C. want D. congratulate55. A. laughing B. joking C. worrying D. crying第四部分:阅读七选五（10%）How to Recognize a True FriendBe able to trust your friends. You should be able to trust true friends and they should return this trust. Does your friend tell you secrets that no one else knows? Ask you for advice? 56_ However, if your friend hides things from you and acts secretively, then this is a sign that they may not trust you,57 Think about it. How comfortable are your friends when they are around you? Watch them, are they being themselves around you? Are they acting fake... perhaps hiding something? True friendships can take a while to develop, but if your friends are true they should feel comfortable around you, and vice versa (You with them).Thi nk about loyalty. 58 If you are in need of a helping hand, your true friends should be there to offer it to you. True friends do not try to get one another into trouble. A t rue friend will always be loyal to you and will not reveal your secrets, Think about nicknames. A lot of true friends love to give each other nicknames! If your friend is giving you nicknames, then this is a great sign. Think of the nickname yourfriend has given you, does it suit you well? 59Look at how you fight. Nearly all best friends fight. 60 True friends will find their way through a fight, no matter what the size is. True friends will remain 'faithful' to each other even during a fight. They still care about each other.A. Choose your friend carefully.B Consider comfort.D. True friends are always there for one another.C. Both are sure signs that your friend trusts you.E. If so, this shows your friend must know you quite wellF. An inside joke shows that you share a special connection with your friend.G. So if you and your friend have a little argument, don’t worry!第五部分：完成句子（15%）61.这是在两国交战的时期。

2016-2017学年福建师大附中实验班高二（上）期末英语试卷一、阅读理解（本大题共12小题，共24.0分）AHartley got to Central Station nearly an hour before his train was due to leave．A lifetime in the theatre had given him a healthy-indeed excessive- sense of punctuality；a lifetime of unwanted cups of coffee，constant checking of the time，yet another turn around the block before that all too often pointless，tiresome audition （试镜）．Hartley was 75-pretty fit for his age，legs holding lip，memory still ticking over nicely- though the occasions for punctuality were now rather fewer．But he was a creature of habit and couldn't change now．Hartley was a good actor，although the calls on his talents were now infrequent．But really，he thought he'd had a reasonably good career．Something to be proud of．But he'd never had that break-through part．He headed for his platform．Just as the train was about to pull out a man ran down the platform，jumped aboard as the door slammed shut and sank into the seat next to Hartley．"Cutting it a bit fine"，he said．"Indeed"，Hartley replied．"A close run thing"．The man-fortyish，amiable looking-gave him an amused glance．This brief exchange served as an adequate ice-breaker and they chatted their way through the outer suburbs and into the countryside．Having satisfactorily disposed of the sad state of the railways，country versus city living，his neighbour asked Hartley what he did-or had done-for a living．Hartley hated telling people he was an actor．He was not ashamed of his job．Not in the least，but he had long tired of reactions ranging from "what have I seen you in" to "how do you learn all those lines"．So in situations like this he simply selected an occupation from a former role．Bit risky，of course．You say you're a doctor and find yourself meeting the quizzical（疑问的）gaze of a heart surgeon．But he'd never been caught out and it was harmless enough game，Hartley felt．It amused him，and he'd given some damn good performances too．"I'm a lawyer"，he replied．"Retired several years ago．Property law．Bit of criminal stuff"．The train was slowing down．The man glanced out of the window．"My station．I had you quite wrong then"．He stood and took down his briefcase from the overhead rack．"Yes，I'd have said you were an actor．The voice especially．Still，lawyers are actors in a way，don't you think？Plenty of drama in a courtroom"．The train drew into the station．"I'm a film director．Casting a feature at the moment．You study faces．On the train．Everywhere．Always on the lookout．Anyway，enjoyed our chat．Bye．"1.What did Hartley think of his not telling his occupation？______A. Harmful to his acting career．B. Amusing despite the riskC. Helpful to protect his identityD. Upsetting when caught out．2.What can we learn about Hartley's travel companion from the underlined sentence "I hadyou quite wrong then．"？______A. He assumed Hartley had given another answer．B. He understood Hartley's profession was acting．C. He thought Hartley practiced a different profession．D. He mistook Hartley for another person．3.The use of the word "Bye" at the end of the story ______ ．A. shows the readers how unexpectedly Hartley's career endsB. describes Hanley's shock on finding the man is a directorC. confirms Hartley's lack of luck in spite of his acting skillsD. proves the man will reconsider giving Hartley a chance to act4.Which of the following can be the best title of the story？______A. Acting upB. Employ talentsC. Selecting an occupationD. Casting a feature【答案】【小题1】B 【小题2】C 【小题3】C 【小题4】A【解析】1．B．细节理解题．根据第十段So in situations like this he simply selected an occupation from a former role． Bit risky， of course． You say you're a doctor and find yourself meeting the quizzical（疑问的）gaze of a heart surgeon．可知，哈特利认为没有告诉他自己的职业是什么，尽管存在风险，仍然很有趣．故选B．2．C．句意理解题．根据上下文内容可知，"My station．I had you quite wrong then"．的意思是他认为哈特利从事不同的职业．故选C．3．C．推理判断题．根据最后一段"I'm a film director． Casting a feature at the moment． You study faces． On the train． E verywhere． Always on the lookout． Anyway， enjoyed our chat． Bye．" "我是一名电影导演．此刻投出一个特写．你在研究面孔．在火车上．到处都是．一直在寻找．无论如何，享受我们的聊天．再见．"可知，在故事结尾处使用"再见"这个词证实了哈特利尽管他有表演技巧仍然缺乏运气．故选C．4．A．主旨大意题．阅读全文，根据文章内容可知，本文主要讲述了哈特利在火车上碰到了一个电影导演，互相演戏，隐藏了自己的真实职业，最终错失了一个机会．A．表演．故选A．本文是一篇故事类阅读，主要讲述了哈特利在火车上碰到了一个电影导演，互相演戏，隐藏了自己的真实职业，最终错失了一个机会．阅读理解考察学生的细节理解和推理判断能力，做细节理解题时一定要找到文章中的原句，和题干进行比较，再做出正确的选择．在做推理判断题不要以个人的主观想象代替文章的事实，要根据文章事实进行合乎逻辑的推理判断．BA hospital has been forced to ban Pokemon Go players from the site after a monster hub（妖怪枢纽站）was found in the A&E department．Royal Stoke University Hospital discovered that its casualty unit（急诊室）is on the same spot as a Pokemon Go ‘gym' -where players can train their newly caught Nintendo creatures．The University Hospitals of North Midlands Trust agreed last week that patients can play Pokemon Go on wards because walking around is healthy．But the Trust has been forced to post a warning on its website about public access to A&E．It said if Pokemon Go becomes a major annoyance it would ask Nintendo-which decides on the locations of the virtual gymsaccording using GPS-to have it removed from the premises（道馆）．Kevin Parker，associate chief nurse，said："Members of the public who do not need to be at Royal Stoke should not attempt to enter A&E or any other part of the hospital building to play the game．The A&E department is incredibly busy this summer．We want the public to understand that anybody who visits the hospital solely to play the game will provide an unwanted distraction to the important work of the hospital．I'm also aware of various reports in the media of unsafe areas that the game has been played in．""Royal Stoke University Hospital is a safe area where gamers can enjoy Pokemon Go．" Michelle Harris，the Trust's manager，said the game could still be played by those already in hospital．"We recognise that the Pokemon Go game encourages walking and exercise，which is something that the Trust is equally keen to promote，" she said．There are a number of "walking routes" established throughout the Trust that can be used to combine walking and playing the game．"Walking just 30minutes，five times a week，can help reduce the risk of preventable illnesses such as obesity，diabetes，and heart disease．" There have been several warnings about the game since its UK release．Last week a group of teenagers in Wiltshire were left stranded almost 100ft underground after they got carried away searching for Pokemon Go characters．The four boys，aged 16 and 17，ended up getting lost and had to wait to get a phone signal before they could call for help．Eventually，they contacted Dorset and Wiltshire Fire and Rescue team，who took them to safety．Damien Bence，of the fire and rescue team，said："Pokemon Go is obviously leading people into dangerous situations．"5.It seems that Pokemon Go is a game ______ ．A. designed to help patients in hospital recover soonerB. helping cure such diseases as obesity，diabetes and heart diseaseC. encouraging players to walk and exercise instead of staying indoorsD. warning teenagers of the places easy to get lost or attacked6.The A&E department is incredibly busy because ______ ．A. more patients' arrival increases the workload of the A&E departmentB. doctors' playing the game makes the A&E department less efficientC. players' injury increases the workload of the A&E departmentD. players' arrival disturbs the work of the A&E department7.The underlined word in the last paragraph probably means ______ ．A. hurtB. disturbedC. trappedD. threatened8.The passage is mainly about ______ ．A. the negative effects of Pokemon Go since its UK releaseB. the applications of Pokemon Go in hospitals since its UK releaseC. the popularity of Pokemon Go since its UK releaseD. the establishment of Pokemon Go virtual gyms since its UK release【答案】【小题1】C 【小题2】D 【小题3】C 【小题4】A【解析】1．C．细节理解题．根据文章第二段的句子"The University Hospitals of North Midlands Trust agreed last week that patients can play Pokemon Go on wards because walking around is healthy．"可知，Pokemon Go是一款游戏鼓励玩家四处走动，锻炼而不是待在室内．故选C．2．D．细节理解题．根据文章第三段的句子"Members of the public who do not need to be at Royal Stoke should not attempt to enter A&E or any other part of the hospital building to play the game．The A&E department is incredibly busy this summer．"可知，医院的急诊室特别忙因为玩家的到来打扰了急诊室的工作．故选D．3．C．词义猜测题．根据文章最后一段的句子"Last week a group of teenagers in Wiltshire were left stranded almost 100ft underground after they got carried away searching for Pokemon Go characters．"可知，上周，威尔特郡的一群青少年忘乎所以地寻找"口袋妖怪"游戏精灵以至于被困在地下近100英尺的地方．stranded是"困住"的意思．故选C．4．A．主旨大意题．根据全文和第二段的句子"It said if Pokemon Go becomes a major annoyance it would ask Nintendo"可知，文章主要关于"口袋妖怪"游戏的负面的影响．故选A．文章介绍一款游戏"口袋妖怪"的玩家走火入魔，扰民又害己．"口袋妖怪"玩家在一家医院急诊部创立了妖怪枢纽站，扰乱了医院的正常工作，随后医院不得不发布规定，禁止玩家再入内．阅读理解考察学生的细节理解和推理判断能力，做细节理解题时一定要找到文章中的原句，和题干进行比较，再做出正确的选择．在做推理判断题不要以个人的主观想象代替文章的事实，要根据文章事实进行合乎逻辑的推理判断．CWhat does it say about the future of meat when the country's largest process or of chicken，pork，and beef buys a stake（股份）in a start-up that aims to "perfectly replace animal protein with plant protein"？Tyson Foods announced this week that it purchased a 5percent stake in Beyond Meat，the Southern California-based food-tech start-up that made headlines earlier this year with its veggie burger that reportedly cooks and tastes like real beef．To be sure，Beyond Meat's meatless creations have yet to take the country by storm．Although the 100percent plant-based burgers have achieved plenty of positive press since they appeared for the first time in May，so far they're only available at Whole Foods stores in seven states．Even though the company's "chicken" strips，"beef" pies，and meatless frozen dinners are available nationwide，Beyond Meat is hardly a household name．That may be what makes the news of Tyson's investment all the more noteworthy．While the two companies declined to give details about the deal，it's doubtful that Tyson's 5 percent stakemade much of dent（凹陷）in the meat giant's coffers（金库）．The company posted ﹩41.4 billion in sales last year；prior to the deal with Tyson，Beyond Meathad reportedly raised﹩64million in project capital funding-about what Tyson earns before lunch on any given day．Tyson is doing pretty great．The company reported record third-quarter earnings per share in August and says that it expects overall meat production to increase 2 to 3 percent during the next financial year．But like a big oil company shelling out cash to invest in wind power，Tyson's toe-in-the-water move to team up with a start-up devoted to bringing more plant-based protein to American dinner tables seems to suggest the meat industry is starting to see which way the winds are blowing．Sales of plant-based protein，which totaled an estimated﹩5 billion last year，continue to palecompared with the market for meat in America-but vegetarian alternatives to meat are booming，with sales growing at more than double the rate for food products overall．The steady drumbeat of news about the negative health impacts，environmental problems，and animal welfare concerns associated with meat consumption appears to be sinkingin．According to a survey released in April，more than half of Americans surveyed said they plan to eat more plant-based foods in the coming year．9.Beyond Meat's veggie burger made headlines probably because ______ ．A. it makes perfect use of animal proteinB. it uses high tech in the making processC. it tastes as good as a genuine beef burgerD. it represents the diet trend in South California10.Which of the following statements is TRUE regarding the state of Beyond Meat？______A. It is the creator of the country's first 100 percent plant-based burgers．B. It has been well received as its products are available nationwide．C. It is far from being a match to real food processing giants like Tyson．D. It provides high-quality dining experience in selected Whole Foods stores．11.What can we infer from paragraph 4？______A. The purchase of the stake barely costs a thing for Tyson．B. The 5 percent stake in Beyond Meat means a lot to Tyson．C. Tyson's investment hasn't caught the attention of the media as expected．D. Tyson is relying on this investment to raise more project capital funding．12.What does the passage mainly talk about？______A. Meat will still take over the market in spite of other alternatives．B. A major American meat company is betting on plant-based protein．C. Tyson and Beyond Meat work together to build a global meat giant．D. Plants have been found to contain protein that does more good to human beings．【答案】【小题1】C 【小题2】C 【小题3】A 【小题4】B【解析】CCAB1．C．细节理解题．由第二段的…that made headlines earlier this year with its veggie burger that reportedly cooks and tast es like real beef可知，汉堡的味道像真正的牛肉；故选C．2．C．细节理解题．由第三段的内容以及最后一句Beyond Meat is hardly a household name可知，要想使Tyson成为真正的食品加工巨头，这是很遥远的一场比赛，即还有很长的路要走；故选C．3．A．推理判断题．根据第四段The company posted ﹩41.4 billion in sales last year；prior to the deal with Tyson，Beyond Meathad reportedly raised﹩64million in project capital funding-about what Tyson earns before lunch on any given day可知，购买Tyson股份几乎是没有成本的事；故选A．4．B．文章大意题．整篇文章都围绕未来餐桌上肉类的发展方向是素食食物，这也是大公司选择素食食物的原因，风向标转向这里，所以B项美国主要的食品巨头公司在植物性蛋白质方面押注符合文章的内容概括；故选B．这篇文章是一篇说明文，作者阐述了目前泰森食品的未来方向，把素食食物作为以后代替真正的肉类食品，这成为未来的发展方向．阅读理解考察学生的细节理解和推理判断能力，做细节理解题时一定要找到文章中的原句，和题干进行比较，再做出正确的选择．在做推理判断题不要以个人的主观想象代替文章的事实，要根据文章事实进行合乎逻辑的推理判断．二、阅读七选五（本大题共5小题，共5.0分）As is known to all，many things can be measured in terms of data．Sometimes data can indeed tell the truth．With the help of data we can easily know the price of a can of Coke in the supermarket or the result of a football match．Data can make our life easier and more comfortable．What is more important，data seem to be fairer than words or statements．(1) Nowadays，as lies exist in the world，data are expected to tell the truth．Therefore，many of us would rather believe data．On the other hand，if we judge things only by data from the so-called specific research，aren't we a little too narrow-minded？Many people often treat the so-called specific data unwisely just to make sure that they are making the right decisions．(2) For example，how can you tell that somebody isn't a good student just because he or she doesn't get high marks in the final examination？(3) For example，the degree of your feeling happy in your life，the depth of love between you and your friends，and the faith you have in your country．We can only feel them in our hearts but can never express them in data．There is no doubt that analyzing the exact data is important to assessment of an actual event．But data should be dealt with wisely．We often get wrong data which mislead us．(4) Remember，data have no feeling but we humans have．Data do not mean much to people if we do not have the abilities to analyze the data with the knowledge and confidence to judge whether they are true or false．(5)Data are data after all．Life is much more colourful than the pale data．So give the cold data a warm heart and we'll find that the world is far more wonderful than the pale data can describe．A．We should try our best to be wise thinkers．B．If the data are true，we don't have to worry about being cheated．C．But sometimes we may find that data aren't everything．D．Sometimes our hearts and mind are more sensitive than data．E．Now and then the so-called specific data puzzle us very much．F．The exact data should come from assessment of an actual event．G．There are many things in our life which cannot be measured by data．13. A. A B. B C. C D. D E.E F.F G. G14. A. A B. B C. C D. D E.E F.F G. G15. A. A B. B C. C D. D E.E F.F G. G16. A. A B. B C. C D. D E.E F.F G. G17. A. A B. B C. C D. D E.E F.F G. G【答案】【小题1】B 【小题2】C 【小题3】G 【小题4】D 【小题5】A【解析】BCGDA1．B．联系上文题．前面的句子说With the help of data we can easily know the price of a can of Coke in the supermarket or the result of a football match．看出数据可以使我们的生活更容易，舒服．B项：If the data are true， we don't have to worry about being cheated．如果数据是真的，我们就不用担心被骗了．符合文意，故选B．2．C．理解判断题．从后面举的例子For example，how can you tell that somebody isn't a good student just because he or she doesn't get high marks in the final examination？怎么能仅仅因为一名学生期末考试没考好而说他不是好学生？说明数据不能说明一切（But sometimes we may find that data aren't everything）．故选C．3．G．文章衔接题．从后面举的例子和这句话：We can only feel them in our hearts but can never express them in data．我们只能从内心去感受而不能用数据表达．G项：There are many things in our life which cannot be measured by data．在我们的生活中，有许多东西是无法用数据来衡量的．符合文意，故选G．4．D．理解判断题．从后面的句子：Remember，data have no feeling but we humans have．数据没有情感，可是我们人类有．说明选D项：Sometimes our hearts and mind are more sensitive than data．"有时我们的心比数据敏感．"故选D．5．A．联系上文题．从前面的句子Data do not mean much to people if we do not have the abilities to analyze the data with the knowledge and confidence to judge whether they are true or false．可知如果我们没有能力去判断对错，数据对我们什么都不是．A项：We should try our best to be wise thinkers．"我们要做聪明的思考者"．符合文意，故选A．本文是一篇选句填空，文章主要介绍了人们相信数据是因为它使我们的生活更容易和舒适，而且数据似乎是公平的．如今，由于世界上存在着谎言，人们期望数据能说真话，因此，我们中的许多人宁愿相信数据．"七选五"这样的题型，主要目的在于"考查考生对文章的整体内容和结构以及上下文逻辑意义的理解和掌握．解题时最主要的两个步骤就是1．理清文章的逻辑和结构，2．在所给的原文中找出关键词或者说是线索词．文章的整体思路能帮助你在答案中筛选出符合逻辑的选项，关键词则能帮助你确定更多的细节，排除相近的选项．这些技巧多练练就能孰能生巧．三、完形填空（本大题共20小题，共30.0分）I always walk to my husband's office after work，wait for him and then we drive home together every day．One day，while I was waiting for him，a beautiful Cadillac（凯迪拉克轿车）(18) near me．I was busy (19) the car when I noticed the driver．(20)，she was probably the most(21) woman I had ever seen outside of a movie screen．Her eyes were as blue as the sea，and she had teeth like pearls．Minutes later，a man walked over and they drove off．Sitting there，dressed in jeans and a T-shirt，I wanted to (22)．"Why is it so(23) that some people have it all？" I thought．The next week I saw her again，and after that it almost became my(24) to see her．I would(25) if she and her husband ate out a lot and where they went．I wanted her to get out of the car so that I could see her in (26) length．A few weeks later，this question was (27) for me．I was waiting at my usual spot and the lady's husband came over to their car．He opened the door．The pretty woman(28) walked around to the passenger side-leaning on a walking cane．She(29) one leg with her hands and then the other．She had an artificial limb（假肢）on her left leg and a brace on her right one．As they drove away，I began to cry．When my husband arrived，I told him about what had (30)．He said that he knew her husband and that，when the lady was twelve years old，she had been(31) in a car that got stuck on the railroad tracks．Unfortunately，both her parents were killed．The rail company made a large(32) with her because the crossing hadno(33)．That's (34) she owns such a nice car now．For weeks I have(35) this woman and her way of life，but now I realize how(36) I am．When you meet a person who seems to be much better off than you，don't be fooled by (37)．18. A. drove in B. sped by C. pulled up D. turned away19. A. cleaning B. admiring C. expecting D. taking20. A. Sincerely B. Honestly C. Surprisingly D. Obviously21. A. beautiful B. typical C. peaceful D. patient22. A. discuss B. argue C. cry D. ask23. A. unfair B. unusual C. uneasy D. unbelievable24. A. chance B. routine C. regret D. wonder25. A. wonder B. guess C. imagine D. doubt26. A. great B. equal C. full D. standard27. A. raised B. answered C. presented D. checked28. A. quickly B. firmly C. slowly D. hurriedly29. A. bent B. lifted C. crossed D. spread30. A. happened B. changed C. passed D. hidden31. A. discovered B. protected C. left D. trapped32. A. promise B. exchange C. settlement D. arrangement33. A. signs B. notices C. signals D. lights34. A. when B. why C. because D. where35. A. respected B. observed C. accepted D. envied36. A. selfish B. lucky C. mature D. funny37. A. glance B. beauty C. backgrounds D. appearances【答案】【小题1】C 【小题2】B 【小题3】B 【小题4】A 【小题5】C 【小题6】A 【小题7】B 【小题8】A 【小题9】C 【小题10】B 【小题11】C 【小题12】B 【小题13】A 【小题14】D 【小题15】C 【小题16】C 【小题17】B 【小题18】D 【小题19】B 【小题20】D 【解析】1-20 CBBAC ABACB CBADC CBDBD1．C．短语的辨析，drove in驶入，sped by飞驰而过，pulled up停车，turned away转身离开，我看到一辆凯迪拉克轿车停在我旁边，故答案为C．2．B．动名词的辨析，cleaning清理，admiring欣赏，expecting期待，taking拿走，当我看到司机的时候，我正忙于欣赏这辆车，故答案为B．3．B．副词的辨析，sincerely真诚地，honestly老实地，surprisingly令人惊奇地，obviously 显然，老实说，她可能是除了电视看到的最漂亮的妇女，故答案为B．4．A．形容词的辨析，beautiful美丽的，typical典型的，peaceful和平的，patient耐心的，她可能是除了电视看到的最漂亮的妇女，故答案为A．5．C．动词的辨析，discuss讨论，argue争辩，cry哭，ask问，此处指我和她对比那么大，我坐在那想哭，故答案为C．6．A．形容词的辨析，unfair不公平的，unusual不寻常的，uneasy不自在的，unbelievable 难以置信的，此处指为何有的人就拥有一切，这是不公平的，故答案为A．7．B．名词的辨析，chance机会，routine日常，regret后悔，wonder奇迹，在那之后，好像每天看到她就是常规，故答案为B．8．A．动词的辨析，wonder想知道，guess猜，imagine想象，doubt怀疑，我想知道她和她丈夫经常出去吗，故答案为A．9．C．形容词的辨析，great伟大的，equal平等的，full满的，standard标准的，我很希望她能够走出车来，为了让我看看她完整的身材，故答案为C．10．B．动词的辨析，raised抚养，answered回答，presented呈现，checked检查，几个星期之后，我便知道了答案，故答案为B．11．C．副词的辨析，quickly快地，firmly坚定地，slowly缓慢地，hurriedly匆忙地，根据下文她有假肢有支撑，所以她的动作是很慢的，故答案为C．12．B．动词的辨析，bent弯曲，lifted举起，crossed穿过，spread传播，她用双手提起一条腿，紧接着下一只．在他的左脚有假肢，右脚有支撑．所以是用手提起，故答案为B．13．A．动词的辨析，happened发生，changed改变，passed经过，hidden隐藏，当我丈夫到达时，我告诉他发生了什么，故答案为A．14．D．动词的辨析，discovered发现，protected保护，left离开，trapped困，她被困在了一辆被卡在火车轨道的汽车里，故答案为D．15．C．名词的辨析，promise承诺，exchange交换，settlement处理，arrangement安排，在父母双亡后，铁路公司做出了协议，给了一大笔安抚处理费，因为路口没有给出信号灯，这也就是她为什么拥有那么好的车的原因，故答案为C．16．C．名词的辨析，signs标记，notices告示，signals信号，lights灯光，在父母双亡后，铁路公司做出了协议，给了一大笔安抚处理费，因为路口没有给出信号灯，这也就是她为什么拥有那么好的车的原因，故答案为C．17．B．引导词的辨析，根据语境在父母双亡后，铁路公司做出了协议，给了一大笔安抚处理费，因为路口没有给出信号灯，这也就是她为什么拥有那么好的车的原因，因此使用why，故答案为B．18．D．动词的辨析，respected尊敬，observed观察，accepted接受，envied妒忌，前面那几个星期，我很嫉妒这位女性和他的生活的方式，但是现在我意识到我是多么的幸运，故答案为D．19．B．形容词的辨析，selfish自私的，lucky幸运的，mature成熟的，funny搞笑的，前面那几个星期，我很嫉妒这位女性和他的生活的方式，但是现在我意识到我是多么的幸运，故答案为B．20．D．名词的辨析，glance一瞥，beauty美丽，backgrounds背景，appearances外表，本句话是文章的主旨句，有时候当你遇到条件似乎比你好的人，记住不要被外表所欺骗了，故答案为D．本文讲述我在办公室外等丈夫一起开车回家时，遇到一位开着豪车的美丽妇女，我对这位妇女拥有一切美好的东西而感到不公平．后来有一天，当我发现这位妇女远离身有残疾，并且有很多痛苦的过去时，我才意识到自己是多么幸运．在做完形填空时，首先需要快速的浏览全文，把握文章的主旨大意；其次要学会带着问题到文中相应的地方，通过细节阅读来寻找或概括答案；最后理清作者的写作思路也非常重要；做此类题时，要多注意一些形容词或动词的搭配，在平时多积累一些固定搭配．四、语法填空（本大题共1小题，共10.0分）38.Imagine falling towards the planet Earth at (1) awesome speed of 300kilometers perhour．You start your fall from over four kilometers above the earth．And you have less than one minute before you pull your parachute cord．You are falling (2) fast that just turning your head can send you off (3) a different direction．This is the wild side of a sport that has not found its limit -freeflying．Freeflying (4) （base）on the more traditional skydiving，and (5) of them areeye-catching．However，it is more terrifying to watch freeflyers create formations and movements．Freeflyers，(6) the name suggests，enjoy the more spontaneous thrill of doing their own things．The wildest trip for a freeflyers is falling "head down"．Falling "head first" requires a great deal of control，which means (7) （travel）fast and (8) （steady）．Even the(9) （slight）movement has a great effect on your direction．They wear the amusing jumpsuits，strange helmets and smaller parachutes．Actually，their parachutes are about one quarter the size of the traditional skydiver's parachutes．It is only in the last few years that freeflying has gained any real public (10) （accept）．【答案】【小题1】an【小题2】so【小题3】in【小题4】is based【小题5】both【小题6】as【小题7】travel（l）ing【小题8】steadily【小题9】slightest【小题10】acceptance【解析】1．an 2． so 3． in 4． is based5．both6． as 7．travel（l）ing 8． steadily 9．slightest 10． acceptance1．an，考查冠词，at a speed of为固定搭配，awesome以元音音素开头，所以填an．2．so，考查固定搭配，so…that…为固定句型，意为"如此…以致…"．故填so．3．in，考查介词，direction作"方向"讲时，与介词in搭配．故填in．4．is based，考查语态，be based on为固定搭配，意为"以…为基础"．故填is based．5．both．考查代词的用法．这里指的是Freeflying和traditional skydiving两种运动形式，所以用both，表示"两者都……"．所以填both．6．as，考查非限制性定语从句，指代后面整个句子内容，所以用此处as引导非限制性定语从句，as作主语．故填as．7．travel（l）ing，考查动名词，mean作"意味着"讲时，后跟动词-ing形式做宾语．故填traveling．8．steadily．考查副词，副词修饰动词travel，故填steadily．9．slightest，考查最高级，前面有定冠词the，所以用最高级作定语．故填slightest．10．acceptance．考查名词，形容词修饰名词，公众接受，故填名词acceptance．本文讲述跳伞和自由飞翔的感觉：极限自由飞行的运动有着狂野的一面．很吸引眼球．本题主要考查了用单词或短语的适当形式填空．做本题的关键是在理解短文的基础上，灵活运用所学的基础知识．本题考到的知识点有：固定的短语，词类的转换，名词的复数形式，副词以及祈使句的用法等．因此，这就需要在平时的学习中，牢固掌握各语言点及一些语法知识．五、短文改错（本大题共9小题，共18.0分）39.Travelling on the tube in London can actually be quite lonely． This means that even though you're packed into an enclosed space with hundreds of other people， your morning trip to work can leave you feeling somehow alone．______【答案】alone改为lonely【解析】答案：alone改为lonely考查形容词的形式．因为feel是系动词后应用形容词作表语，alone意为"单独的"，lonely 意为"孤独的"，故把alone改为lonely．在伦敦坐地铁旅行实际上是很孤独的，这意味着即使你和数百人挤在一个封闭的空间里，早晨的工作之旅也会让你感到孤独．本题考查句子改错，解答该类问题时应注意分析句子，观察其中的固定短语或者语法知识是否有误，再结合所学知识，进行纠错．40.The baby animals are cute but they grow fast， and within a few weeks they are too bigto handle with． They'll spend the rest of their lives， sometimes decades， in small and empty cages- or even be killed．______【答案】去掉handle后的with【解析】答案：去掉handle后的with．考查句子改错．handle是及物动词，后接宾语时不需要介词with．这些小动物很可爱，但是它们长得很快，几周后它们就会长大而不能控制．他们将会在小而空的笼子里度过余生，这有时会是几十年抑或它们会被杀掉．考查句子改错．单句改错涉及词汇、语法、句型结构等方面的知识和逻辑情理的推断和综合辨析能力，是一种在较高层次上考查考生对英语知识的掌握和语言综合运用能力的测试题型．它是专门针对考生们平时学习英语过程中，尤其是写作练习中常犯的又是较为普遍的错误而设计的．ers' demand that their devices get thinner has also given producers little choice but tryto put more power into thinner batteries．______【答案】try前加to【解析】答案：try前加to考查句子改错．连词but前没有动词do时，后面的动词应用不定式形式，故在try前加to．用户要求他们的设备变得更薄，这也使得生产商别无选择，只能尝试向更薄的电池提供更多的电力．本题考查句子改错，解答该类问题时应注意分析句子，观察其中的固定短语或者语法知识是否有误，再结合所学知识，进行纠错．42.Paris， my first real friends since childhood， helped me get across my tough teenage years and taught me an amazing thing about making friends．______【答案】across改为through【解析】Paris， my first real friends since childhood， helped me get through my tough teenage years and taught me an amazing thing about making friends．答案：across改为through．考查句子改错．get across意为"横过（马路、河等）"，get through意为"穿过；通过"，此处应是后者．帕瑞斯，自从儿时以来我的第一个真正的朋友，帮助我度过了艰难的青少年时期，教我关于结交朋友一件了不起的事情．考查句子改错．单句改错涉及词汇、语法、句型结构等方面的知识和逻辑情理的推断和综合辨析能力，是一种在较高层次上考查考生对英语知识的掌握和语言综合运用能力的测试题型．它是专门针对考生们平时学习英语过程中，尤其是写作练习中常犯的又是较为普遍的错误而设计的．43."I will be president for all Americans，" Trump told an enthusiastic crowd in New York after his victory was certain． "We wil l rebuild our infrastructure， which will become the second to none．"______【答案】去掉second前the【解析】答案：去掉second前the．考查句子改错．second to none意为"最好的"，是固定搭配．"我将成为所有美国人的总统，"特朗普选举胜利确信后在纽约告诉一群热心的群众，"我们会重建基础设施，它会是最好的．"考查句子改错．单句改错涉及词汇、语法、句型结构等方面的知识和逻辑情理的推断和。

福建师大附中2015-2016学年第二学期期末考试卷高二物理（完卷时间：90分钟；满分：100分）说明：本试卷共三大题，18小题。

请把答案写在答卷上。

考试结束后，只要上交答卷。

第I 卷（选择题 共48分）一、选择题（本大题共12小题，每小题4分。

在每小题给出的四个选项中，第1～6题只有一项是符合题目要求，第7～12题有多项符合题目要求。

全部选对的得4分，选对但不全的得2分。

有选错的得0分。

）1．红外线热像仪通过红外线遥感，可检测出经过它时的发热病人，从而可以有效控制疫情的传播。

关于红外线热像仪，下列说法中正确的是A ．选择红外线进行检测，主要是因为红外线光子能量小，可以节约能量B ．红外线热像仪通过发射红外线照射人体来检测C ．红外线热像仪同时还具有杀菌作用D ．根据物体在不同温度下发射的红外线的频率和强度不同的原理来检测体温2．两束单色光Ⅰ、Ⅱ从水下同一位置同一方向射向水面，只产生两束光线，光路图如图所示，则 A ．两束光在水中传播时，光束Ⅱ的速度大于光束Ⅰ的速度 B ．两束光在水中传播时波长一样C ．两束光线通过同一小孔时，光线Ⅰ的衍射现象更明显D ．光束Ⅰ从水中到空气中频率变大3．图甲是利用砂摆演示简谐运动图象的装置，当盛砂的漏斗下面的薄木板被水平匀速拉出时，做简谐运动的漏斗漏出的砂在板上显示出砂摆的振动位移随时间变化的关系曲线，已知木板被水平拉动的速度为0.15m/s ，图乙所示的一段木板的长度为0.60m ，则这次实验砂摆的摆长大约为A ．0.03 mB ．0.5mC ．1.0 mD ．2.0 m4．如图所示为α粒子散射实验装置，粒子打到荧光屏上都会引起闪烁，若将带有荧光屏的显微镜分别放在图中a 、b 、c 、d 四处位置。

则这四处位置在相等时间内统计的闪烁次数符合实验事实的是A ．1305、25、7、1B ．202、405、625、825C ．1202、1010、723、203D ．1202、1305、723、2035．碘131的半衰期约为8天。

一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项 是符合题目要求的.1.角α的终边过点(4,3),(0)P k k k -<，则cos α的值是( ) A ．35B ．45C ．35-D ．－45【答案】B 【解析】 试题分析：()()()0553422<-==+-=k k k k k r ，而5454cos =--==k k r x α，故选B. 考点：三角函数的定义2.sin20°cos10°﹣cos160°sin10°=( ) A ．23-B ．23C ．21-D ．21【答案】D 【解析】试题分析：原式等于()2130sin 1020sin 10sin 20cos 10cos 20sin 0000000==+=+，故选D. 考点：两角和与差的三角函数3.设向量a =(m ,1)，b =(1,2)，且|a +b |2=|a |2+|b |2，则m =( )A ． 1-B ．1C ．2-D ．2 【答案】C考点：向量数量积4.下列函数中，最小正周期为π且图象关于原点对称的函数是( ) A ．y=sin （2x+2π） B ．y=cos （2x+2π） C ．y=sin2x+cos2x D ．y=sinx+cosx【答案】B考点：三角函数的性质5.如图，在△OAB 中，P 为线段AB 上的一点， =x+y，且=3，则( )A ．x=，y=B ．x=，y=C ．x=，y=D ．x=，y=【答案】D 【解析】试题分析：()OP OA OB OP PA BP -=-⇔=33,整理为OP OB OA OP 34+=⇔+=所以43=x ，41=y ，故选D. 考点：平面向量基本定理6.若3cos()45πα-=，则sin 2α=( ) A ．725 B ．725- C ．15- D ．15【答案】B 【解析】 试题分析：()53sin cos 224cos =+=⎪⎭⎫⎝⎛-αααπ，两边平方后得:()2518sin cos 2=+αα25182sin 1=+⇔α,解得2572sin -=α，故选B. 考点：三角函数恒等变形7.将函数y=2sin (2x+6π)的图像向右平移4π个周期后，所得图像对应的函数为( )A ．y=2sin(2x+4π) B ．y=2sin(2x+3π) C ．y=2sin(2x –4π) D ．y=2sin(2x –3π)【答案】D考点：三角函数的变换【易错点睛】本题考查了三角函数的变换，属于基础题型，在三角函数的变换中，容易出错在两个地方，举例，①函数x y 2sin =向左平移6π个单位得到哪个函数，很多同学会写成⎪⎭⎫⎝⎛+=62sin πx y ，谨记“左+右－”指的是x ，所以应是⎪⎭⎫ ⎝⎛+=⎪⎭⎫⎝⎛+=32sin 62sin ππx x y ，②⎪⎭⎫ ⎝⎛+=62sin πx y 上所有点的横坐标伸长到原来的2倍，很多同学会写成⎪⎭⎫ ⎝⎛+=⎪⎭⎫ ⎝⎛+=12sin 6221sinππx x y ，谨记，横坐标伸长或缩短到原来的ω1倍，仅仅是x 前面的系数变了，与ϕ无关，所以应是⎪⎭⎫⎝⎛+=6sin πx y . 8.函数=sin()y A x ωϕ+的部分图像如图所示，则（ ）A ．2sin(2)6y x π=-B ．2sin(2)3y x π=-C ．2sin(2+)6y x π=D ．2sin(2+)3y x π=【答案】A考点：()ϕω+=x A y sin 的图像 9.()()01tan181tan 27++的值是( )A B ．1．2 D ．()002tan18tan 27+ 【答案】C 【解析】试题分析：根据公式()127tan 18tan 127tan 18tan 2718tan 000000=-+=+，所以000027tan 18tan 127tan 18tan -=+，原式等于227tan 18tan 27tan 18tan 10000=+++，故选C.考点：两角和的正切函数10.在ABC ∆+ABC ∆一定是( )A ．钝角三角形B ．锐角三角形C ．直角三角形D ．不能确定 【答案】C 【解析】-+BC BA BC BABC BA BC BA⋅-+=⋅++222222,化简为0=⋅BC BA ,即BC BA ⊥,角B 为直角，所以是直角三角形，故选C. 考点：向量数量积11.设函数()sin()cos()(0,)2f x x x πωϕωϕωϕ=+++><的最小正周期为π，且()()f x f x -=，则( ) A ．()f x 在0,2π⎛⎫⎪⎝⎭单调递减 B ．()f x 在3,44ππ⎛⎫⎪⎝⎭单调递减 C ．()f x 在0,2π⎛⎫⎪⎝⎭单调递增 D ．()f x 在3,44ππ⎛⎫⎪⎝⎭单调递增 【答案】A考点：三角函数的图像和性质【方法点睛】本题考查了()ϕω+=x A y sin ⎪⎭⎫⎝⎛<>>200πϕω，，A 的性质，本题考查了两个问题，一是如何求函数解析式，二是如何判断三角函数的性质，A 是振幅，一般根据函数的最值求解，ωπ2=T ,ω一般根据周期求解，ϕ一般根据“五点法”求解，而象本题给出三角函数后，如何判断所给区间是否具有单调性，首先由x 的区间，代入求ϕω+=x u 的区间，然后判断ϕω+=x u 是否落在u y sin =的单调区间内.12.定义在R 上的偶函数()f x 满足(2)()f x f x +=，且在[-3，-2]上是减函数，若,αβ是锐角三角形的两个内角，则( )A ．()()sin sin f f αβ>B ．()()sin cos f f αβ<C ．()()sin cos f f αβ>D ．()()cos cos f f αβ< 【答案】C考点：函数的性质【思路点睛】本题考查了函数性质与解三角形的综合考察，属于中档题型，本题的难点是如何转化锐角三角形这个条件，即若是锐角三角形，需满足⎪⎪⎪⎩⎪⎪⎪⎨⎧>+<<<<22020πβαπβπα，这样βπα->2，这样根据函数的单调性，两边取三角函数，ββπαcos 2sin sin =⎪⎭⎫⎝⎛->，或是⎪⎭⎫⎝⎛-<βπα2cos cos βsin =，这个难点克服后，就容易想到根据函数的性质，转化为求函数()x f 在区间()1,0的单调性.第Ⅱ卷（共90分）二、填空题（每题4分，满分28分，将答案填在答题纸上） 13.设向量a =(x ，x+1)，b =(1，2)，且a ⊥b ，则x= . 【答案】23- 【解析】试题分析：根据两向量垂直，可得()0211=⨯++⨯x x ，解得32-=x ，故填：32-. 考点：向量数量积14.已知向量()()(),12,4,5,,10OA k OB OC k ===-，且,,A B C 三点共线，则k = .【答案】23-考点：向量共线的充要条件 15.已知,022ππαπβ<<<<，3tan 4α=-，()5cos 13βα-=， 则sin β的值为 . 【答案】6365【解析】试题分析：0-<<-αβπ，又因为()0135cos >=-αβ，所以02<-<-αβπ，()1312sin -=-αβ，因为43tan -=α，所以53sin =α，54cos -=α，而()[]()()6563131********sin cos cos sin sin sin =⎪⎭⎫ ⎝⎛-⨯⎪⎭⎫ ⎝⎛-+⨯=-+-=-+=αβααβααβαβ，故填：6563. 考点：三角函数恒等变形16.函数()sin(2)sin()()66f x x x x ππ=++-∈R 的值域为 .【答案】928⎡⎤-⎢⎥⎣⎦，【解析】 试题分析：设t x =-6π，那么()8941sin 2sin sin 21sin 2cos sin 22sin 22+⎪⎭⎫ ⎝⎛--=+-=+=+⎪⎭⎫ ⎝⎛+=t t t t t t t t f π，因为[]1,1sin -∈t ，所以当41sin =t 时，函数取得最大值89，当1sin -=t 时，函数取得最小值-2，所以函数的值域为⎥⎦⎤⎢⎣⎡-89,2，故填：⎥⎦⎤⎢⎣⎡-89,2. 考点：三角函数的性质17.已知△ABC 是边长为1的等边三角形，点E D ,分别是边BC AB ,的中点，连接DE 并延长到点F ，使得EF DE 2=，则BC AF ⋅的值为 .【答案】81考点：向量数量积18.已知函数5()),6f x x π=+方程()f x m =在区间[0,]2π上有两个不同的实数根，则实数m 的取值范围是 .【答案】(【解析】试题分析：如图，画出函数uy sin3=的图像，当⎥⎦⎤⎢⎣⎡∈2,0πx时，⎥⎦⎤⎢⎣⎡∈+=611,65652πππxu，此时()⎥⎦⎤⎢⎣⎡-∈23,3xf，当2π=x时，23-=y根据图像可得若有两个不同的实根，那么⎥⎦⎤⎝⎛-∈23,3m，故填：⎥⎦⎤⎝⎛23-3-，.考点：三角函数图像的应用【方法点睛】本题考查了三角函数图像的应用，属于基础题型，以复合函数的观点解决函数零点问题，首先设π652+=xu，并且求出u的取值范围，然后画出函数uy sin3=的图像，这问题转化为my=与三角函数图像交点的问题，通过图像很容易求出没有交点，一个交点，以及两个交点的m的取值范围问题，切记，最好不要画⎪⎭⎫⎝⎛+=π652sin3xy的图像，因为画这个图像对很多同学来说比较浪费时间得不偿失，一定画换元后的图像.19.已知函数ππ()sin()(0),24f x x+x，ωϕωϕ=>≤=-为()f x的零点，π4x=为()y f x=图像的对称轴，且()f x在π5π()1836，单调，则ω的最大值为 .【答案】9考点：三角函数的性质【思路点睛】本题考查了三角函数的性质，属于中档题型，本题的难点是如何将这两个条件结合在一起，ω是与周期有关的量，对称轴与零点间的距离也与周期有关，这样根据图像得到244--4kT T +=⎪⎭⎫⎝⎛ππ,即ωππ24124122⋅+=+=k T k ，第二个条件⎪⎭⎫⎝⎛36518ππ，是单调区间的子集，所以其长度小于等于半个周期，这样就得到了ω的一个范围与形式，最后求最大值，只能通过从最大的逐个代起，找到ω的最大值. 三、解答题 （本大题共5小题，共62分.解答应写出文字说明、证明过程或演算步骤.） 20.（本题满分12分）已知||=2，||=3，（2﹣3）•（2+）=3． （1）求与的夹角的余弦值； （2）求|+|；（3）求在+方向上的投影．【答案】（1）127-；（2）6；（3）126.∴cos ＜•＞===﹣；（2）|+|===；（3）在+方向上的投影为===．考点：向量数量积【方法点睛】本题考查了向量数量积，属于基础题型，所涉及的公式包括（1）θcos b a b a=⋅，（2）ba b a⋅=θcos ，（3）22a a =，以及()2ba b a +=+，（4）0=⋅⇔⊥b a b a ，（5）投影公式：向量a在b 方向上的投影为θcos a 或是bb a ⋅，对于这类型的向量问题，要谨记公式，并且熟练运用公式避免计算错误.21.（本题满分16分） （1）已知，求的值．(2) 已知3177cos(),,45124x x πππ+=<<求2sin 22sin 1tan x xx+-的值．【答案】（1）41；（2）7528.∴．原式==，由以上知cosx﹣sinx≠0，考点：三角函数的恒等变形求值22.（本题满分为10分）如图所示，某村积极开展“美丽乡村生态家园”建设，现拟在边长为1千米的正方形地块ABCD上划出一片三角形地块CMN建设美丽乡村生态公园，给村民休闲健身提供去处．点M，N分别在边AB，AD上．由于村建规划及保护生态环境的需要，要求△AMN的周长为2千米，请探究∠MCN是否为定值，若是，求出此定值，若不是，请说明理由．【答案】∠MCN 是定值，且∠MCN=4π． 【解析】试题分析：设∠BCM=α，∠DCN=β，AM=x ，AN=y ，则BM=1﹣x ，DN=1﹣y ，若MCN ∠为定值，那么βα+为定值，即()βα+tan 为定值，根据所设条件，得到()βα+tan ()xyy x y x -++-=2，因为AMN ∆的周长等于222=+++y x y x ，将此式进行化简为()y x y x +-=+222，两边平方得到()22-+=y x xy ，代入正切公式得到定值.试题解析：设∠BCM=α，∠DCN=β，AM=x ，AN=y ，则BM=1﹣x ，DN=1﹣y ，在△CBM 中，tan α=1﹣x ，在△CDN 中，tan β=1﹣y ，所以：tan （α+β）=()()()xyy x y x y x y x -++-=----+-=-+211111tan tan 1tan tan βαβα，（5分） △AMN 的周长为2千米，所以222=+++y x y x ，化简得()22-+=y x xy ，代入（*）式，可得tan （α+β）=()()()[]()()1222222=+-+-=-+-++-=-++-y x y x y x y x y x xy y x y x ， 由于α+β(0,)2π∈，所以α+β=4π，所以∠MCN 是定值，且∠MCN=4π．﹣﹣﹣（10分）考点：三角函数的实际应用 23.（本题满分为12分）已知函数f （x ）=2sin ωxcos ωx+23sin 2ωx ﹣3（ω＞0）的最小正周期为π． （1）求函数f （x ）的单调增区间； （2）将函数f （x ）的图象向左平移6π个单位，再向上平移1个单位，得到函数y=g （x ）的图象，若y=g（x ）在[0，b]（b ＞0）上至少含有10个零点，求b 的最小值．【答案】（1）Z k k k ∈⎥⎦⎤⎢⎣⎡+-,125,12ππππ；（2）1259π.试题解析：（1）由题意得f （x ）=2sin ωxcos ωx+23sin 2ωx ﹣3=sin2ωx ﹣3cos2ωx=2sin （2ωx ﹣3π），由最小正周期为π，得ω=1，所以()⎪⎭⎫⎝⎛-=32sin 2πx x f ， 由Z k k x k ∈+≤-≤-,223222πππππ，整理得k k x k ,12512ππππ+≤≤-Z ∈，[KS5UKS5U] 所以函数f （x ）的单调增区间是Z k k k ∈⎥⎦⎤⎢⎣⎡+-,125,12ππππ．【方法点睛】本题考查了三角函数的恒等变换以及三角函数图像的问题，属于基础题型，重点说说对于（1）所考查到的三角恒等变换的问题，比较常见，所使用的公式包括ααα2sin 21cos sin =，22cos 1sin 2αα-=，22cos 1cos 2αα+=，降幂后采用辅助角公式化简，()ϕ++=+x b a x b x a sin cos sin 22，其中ab=ϕtan ，这样函数就可以化简为()ϕω+=x A y sin .24.（本题满分为12分）已知函数x c x b a x f sin cos )(++=的图像经过点)1,0(A 及)1,2(πB(1)已知)2,0(π∈x 时，2|)(|≤x f 恒成立，求实数a 的取值范围;(2)当a 取上述范围内的最大整数．．．．值时，若有实数φ,,n m ，使得1)()(=-+φx nf x mf 对于 R x ∈恒成立，求φ,,n m 的值.【答案】（1）[]234,2-+；（2）161=m ，161=n ，Z k k ∈+=,2ππφ. 【解析】试题分析：（1）首先根据条件可得a c b -==1，将函数转化为()()a x a x f +⎪⎭⎫ ⎝⎛+-=4sin 12π，根据条件可得⎪⎭⎫⎝⎛+4sin πx 的范围，最终讨论a -1的取值范围后，得到函数的值域，根据条件()2≤x f 得到a 的取值范围；（2）由（1）的结论可得8=a ，代入()()1=-+ϕx nf x mf ，要使上式对R x ∈∀恒成立，则需满足()⎪⎩⎪⎨⎧==+=+0sin 0cos 18φφn n m n m ，得到参数的取值范围.试题解析：由12,1)0(=⎪⎭⎫⎝⎛=πf f ，可得，1,1=+=+c a b a ， 所以a c b -==1，所以()()a x a a x x a x f +⎪⎭⎫ ⎝⎛+-=++-=4sin 12)cos )(sin 1(π，（1）设t x =⎪⎭⎫⎝⎛+4sin π，()a t a y +-=12， 因为⎪⎭⎫⎝⎛∈2,0πx ，所以⎪⎭⎫ ⎝⎛∈+πππ43,44x ，即⎥⎦⎤ ⎝⎛∈1,22t ，(2)可得8=a ，则()⎪⎭⎫⎝⎛+-=4sin 278πx x f 由()()1=-+φx nf x mf ，可得()14sin 274sin 278=⎪⎭⎫⎝⎛-+-⎪⎭⎫ ⎝⎛+-+φππx x m n m ，令X x =+4π得，考点：1.三角函数的性质；2.恒成立问题.。

福建师大附中2015－2016学年第一学期期末模块测试高一英语（完卷时间：120分钟；满分：150分）第Ⅰ卷 (共84分)第一部分：听力（共20题；每小题1分, 满分20分）第一节（共5 小题；每小题1分，满分5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话读一遍。

1. How does the man find the movie last night?A. It is moving.B. It is interesting.C. It is not worth seeing.2. How much does the handkerchief cost?A. $7.B. $9.C. $16.3. Who made the woman's personal website?A. She herself.B. Her friend.C. The man.4. What does the man want to have?A. Chocolate.B. Sweets.C. Ice-cream.5. Which section would the man like to read?A. Sports.B. Business.C. News.第二节 (共15小题；每小题1分，满分15分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的做答时间。

每段对话或独白读两遍。

听第6段材料，回答第6至8题。

6. What did the man begin to work in Courtaulds?A. About 4 years ago.B. About 40 years ago.C. About 44 years ago.7. What does the man say about his present life?A. He is used to it.B. He likes it.C. He gets bored with it.8. Who is Rover?A. The man's workmate.B. The man's dog.C. The man's wife.听第7段材料，回答第9至11题。

2015-2016学年福建省莆田二十五中高二（下）期末数学试卷（理科）一．选择题（5*12＝60分）1．（5分）设X是一个离散型随机变量，其分布列如图，则q等于（）A．1B．1±C．1﹣D．1+2．（5分）某次联欢会要安排3个歌舞类节目，2个小品类节目和1个相声类节目的演出顺序，则同类节目不相邻的排法种数是（）A．72B．120C．144D．1683．（5分）某初级中学有学生270人，其中一年级108人，二、三年级各81人，现要利用抽样方法抽取10人参加某项调查，考虑选用简单随机抽样、分层抽样和系统抽样三种方案，使用简单随机抽样和分层抽样时，将学生按一、二、三年级依次统一编号为1，2，…，270；使用系统抽样时，将学生统一随机编号1，2，…，270，并将整个编号依次分为10段．如果抽得号码有下列四种情况：①7，34，61，88，115，142，169，196，223，250；②5，9，100，107，111，121，180，195，200，265；③11，38，65，92，119，146，173，200，227，254；④30，57，84，111，138，165，192，219，246，270；关于上述样本的下列结论中，正确的是（）A．②、③都不能为系统抽样B．②、④都不能为分层抽样C．①、④都可能为系统抽样D．①、③都可能为分层抽样4．（5分）将两个数A＝9，B＝15交换使得A＝15，B＝9下列语句正确的一组是（）A．B．C．D．5．（5分）甲、乙两人独立地解同一问题，甲解决这个问题的概率是p1，乙解决这个问题的概率是p2，那么恰好有1人解决这个问题的概率是（）A．p1p2B．p1（1﹣p2）+p2（1﹣p1）C．1﹣p1p2D．1﹣（1﹣p1）（1﹣p2）6．（5分）设随机变量X的分布列为，则P（1＜X≤3）等于（）A．B．C．D．7．（5分）阅读如图所示的程序框图，运行相应的程序．若输入m的值为2，则输出的结果为i＝（）A．3B．4C．5D．68．（5分）如图，设D是图中边长分别为1和2的矩形区域，E是D内位于函数y＝（x ＞0）图象下方的区域（阴影部分），从D内随机取一个点M，则点M取自E内的概率为（）A．B．C．D．9．（5分）设（+）n展开式的各项系数之和为t，其二项式系数之和为h，若t+h＝272，则展开式的x2项的系数是（）A．B．1C．2D．310．（5分）两位同学一起参加某单位的招聘面试，单位负责人对他们说：“我们要从面试的人中招聘3人，假设每位参加面试的人被招聘的概率相等，你们俩同时被招聘的概率是”．根据这位负责人的话可以推断出这次参加该单位招聘面试的人有（）A．44人B．42人C．22人D．21人11．（5分）某微信群中甲、乙、丙、丁、卯五名成员同时抢4个红包，每人最多抢一个，且红包被全部抢光，4个红包中有两个2元，两个3元（红包中金额相同视为相同的红包），则甲乙两人都抢到红包的情况有（）A．35种B．24种C．18种D．9种12．（5分）已知数列{a n满足a n＝a n﹣1+n﹣1（n≥2，n∈N），一颗质地均匀的正方体骰子，其六个面上的点数分别为1，2，3，4，5，6，将这颗骰子连续抛掷三次，得到的点数分别记为a，b，c，则满足集合{a，b，c}＝{a1，a2，a3}（1≤a i≤6，a i∈N，i＝1，2，3）的概率是（）A．B．C．D．二．填空题（4*5＝20分）13．（5分）一个单位共有职工200人，其中不超过45岁的有120人，超过45岁的有80人．为了调查职工的健康状况，用分层抽样的方法从全体职工中抽取一个容量为25的样本，应抽取超过45岁的职工人．14．（5分）若，则（a0+a2+a4）2﹣（a1+a3）2的值为．15．（5分）已知随机变量X服从正态分布X～N（2，σ2），P（X＜4）＝0.84，则P（X≤0）的值为．16．（5分）事件A，B，C相互独立，如果，，则P（B）＝＝三、解答题17．（12分）某学校课题组为了研究学生的数学成绩和物理成绩之间的关系，随机抽取高二年级20名学生某次考试成绩，列出如下所示2×2列联表：（1）根据题中表格的数据计算，你有多少的把握认为学生的数学成绩与物理成绩之间有关系？（2）若按下面的方法从这20人（序号1，2，3，…，20）中抽取1人来了解有关情况：将一个标有数字1，2，3，4，5，6的正六面体骰子连续投掷两次，记朝上的两个数字的乘积为被抽取人的序号．试求：①抽到12号的概率；②抽到“无效序号（序号大于20）”的概率．参考公式：K2＝，其中n＝a+b+c+d临界值表供参考：18．（12分）某兴趣小组欲研究昼夜温差大小与患感冒人数多少之间的关系，他们分别到气象局与某医院抄录了1至6月份每月10号的昼夜温差情况与因患感冒而就诊的人数，得到如下资料：该兴趣小组确定的研究方案是：先从这六组数据中选取2组，用剩下的4组数据求线性回归方程，再用被选取的2组数据进行检验．（1）求选取的2组数据恰好是相邻两个月的概率；（2）若选取的是1月与6月的两组数据，请根据2至5月份的数据，求出y关于x的线性回归方程y＝bx+a；（3）若由线性回归方程得到的估计数据与所选出的检验数据的误差均不超过2人，则认为得到的线性回归方程是理想的，试问该小组所得线性回归方程是否理想？19．（12分）已知甲箱中装有3个红球、3个黑球，乙箱中装有2个红球、2个黑球，这些球除颜色外完全相同．某商场举行有奖促销活动，设奖规则如下：每次分别从以上两个箱中各随机摸出2个球，共4个球．若摸出4个球都是红球，则获得一等奖；摸出的球中有3个红球，则获得二等奖；摸出的球中有2个红球，则获得三等奖；其他情况不获奖．每次摸球结束后将球放回原箱中．（1）求在1次摸奖中，获得二等奖的概率；（2）若连续摸奖2次，求获奖次数X的分布列及数学期望E（X）．20．（14分）某单位实行休年假制度三年以来，50名职工休年假的次数进行的调查统计结果如表所示：根据上表信息解答以下问题：（1）从该单位任选两名职工，用η表示这两人休年假次数之和，记“函数f（x）＝x2﹣ηx ﹣1在区间（4，6）上有且只有一个零点”为事件A，求事件A发生的概率P；（2）从该单位任选两名职工，用ξ表示这两人休年假次数之差的绝对值，求随机变量ξ的分布列及数学期望Eξ．21．（10分）已知直线l经过点P（1，1），倾斜角α＝，（1）写出直线l的参数方程．（2）设l与圆x2+y2＝4相交于点A、B，求点P到A、B两点的距离之积．22．（10分）在平面直角坐标系xOy中，已知曲线C1：x2+y2＝1，以平面直角坐标系xOy 的原点O为极点，x轴的正半轴为极轴，取相同的单位长度建立极坐标系，已知直线l：ρ（2cosθ﹣sinθ）＝6．（1）将曲线C1上的所有点的横坐标、纵坐标分别伸长为原来的、2倍后得到曲线C2，试写出直线l的直角坐标方程和曲线C2的参数方程；（2）在曲线C2上求一点P，使点P到直线l的距离最大，并求出此最大值．2015-2016学年福建省莆田二十五中高二（下）期末数学试卷（理科）参考答案与试题解析一．选择题（5*12＝60分）1．【解答】解：由分布列的性质得；⇒∴q＝1﹣；．故选：C．2．【解答】解：分2步进行分析：1、先将3个歌舞类节目全排列，有A33＝6种情况，排好后，有4个空位，2、因为3个歌舞类节目不能相邻，则中间2个空位必须安排2个节目，分2种情况讨论：①将中间2个空位安排1个小品类节目和1个相声类节目，有C21A22＝4种情况，排好后，最后1个小品类节目放在2端，有2种情况，此时同类节目不相邻的排法种数是6×4×2＝48种；②将中间2个空位安排2个小品类节目，有A22＝2种情况，排好后，有6个空位，相声类节目有6个空位可选，即有6种情况，此时同类节目不相邻的排法种数是6×2×6＝72种；则同类节目不相邻的排法种数是48+72＝120，故选：B．3．【解答】解：①样本间隔是27．有可能是系统抽样，②样本间隔不相同，不可能是系统抽样③样本间隔相同是27，有可能是系统抽样，④样本间隔是27，但第一组没有号码，故④不是系统抽样，由于一年级108人，二、三年级各81人，则如使用分层抽样对应的人数为108：81：81＝4：3：3，则①③有可能是分层抽样，故选：D．4．【解答】解：先把B的值赋给中间变量C，这样C＝15，再把A的值赋给变量B，这样B＝9，把C的值赋给变量A，这样A＝15故选：D．5．【解答】解：根据题意，恰有一人解决就是甲解决乙没有解决或甲没有解决乙解决，则所求概率是p1（1﹣p2）+p2（1﹣p1），故选：B．6．【解答】解：∵∴P（X＝2）＝P（X＝3）＝，∴P（1＜X≤3）＝故选：B．7．【解答】解：第一次执行循环体后：i＝1，A＝2，B＝1，不满足退出循环的条件；第二次执行循环体后：i＝2，A＝4，B＝2，不满足退出循环的条件；第三次执行循环体后：i＝3，A＝8，B＝6，不满足退出循环的条件；第四次执行循环体后：i＝4，A＝16，B＝24，满足退出循环的条件；故输出的i值为4故选：B．8．【解答】解：本题是几何概型问题，区域E的面积为：S＝2×＝1+＝1﹣ln＝1+ln2∴“该点在E中的概率”事件对应的区域面积为1+ln2，矩形的面积为2由集合概率的求解可得P＝故选：C．9．【解答】解：根据题意，展开式的各项系数之和为t，其二项式系数之和为h∴t＝4n，h＝2n∵t+h＝272，∴4n+2n＝272∴（2n﹣16）（2n+17）＝0∴2n＝16∴n＝4∴展开式的通项为：＝令，则r＝4，∴展开式的x2项的系数是故选：B．10．【解答】解：设这次参加该单位招聘面试的人有x人（x≥3），则俩人同时被招聘的概率是，即，即x（x﹣1）＝420，∴（x﹣21）（x+20）＝0，解得x＝21．故选：D．11．【解答】解：若甲乙抢的是一个2和一个3元的，剩下2个红包，被剩下的3人中的2个人抢走，有A22A32＝12种，若甲乙抢的是两个和2元或两个3元的，剩下2个红包，被剩下的3人中的2个人抢走，有A22C32＝6种，根据分类计数原理可得，共有12+6＝18种，故选：C．12．【解答】解：∵数列{a n}满足a n＝a n﹣1+n﹣1（n≥2，n∈N）．∴a2＝a1+1，a3＝a2+2＝a1+3，将这颗骰子连续抛掷三次，得到的点数分别记为a，b，c，共有6×6×6中不同的结果其中满足{a，b，c}＝{a1，a2，a3}的有{1，2，4}，{1，4，2}，{2，1，4}，{2，4，1}，{4，1，2}，{4，2，1}，{2，3，5}，{2，5，3}，{3，2，5}，{3，5，2}，{5，2，3}，{5，3，2}，{3，4，6}，{3，6，4}，{4，3，6}，{4，6，3}，{6，3，4}，{6，4，3}共18种情况故得到的点数分别记为a，b则满足集合{a，b，c}＝{a1，a2，a3}（1≤a i≤6，a i∈N，i＝1，2）的概率P＝＝故选：D．二．填空题（4*5＝20分）13．【解答】解：本题是一个分层抽样，∵单位共有职工200人，取一个容量为25的样本，∴依题意知抽取超过45岁的职工为．故答案为：10．14．【解答】解：∵，当x＝﹣1时，（﹣2）4＝a0﹣a1+a2﹣a3+a4①当x＝1时，（2）4＝a0+a1+a2+a3+a4②而（a0+a2+a4）2﹣（a1+a3）2＝（a0+a1+a2+a3+a4）（a0﹣a1+a2﹣a3+a4）＝（2）4（﹣2）4＝1∴（a0+a2+a4）2﹣（a1+a3）2＝1，故答案为1．15．【解答】解：∵随机变量X服从正态分布N（2，σ2），μ＝2，∴正态曲线的对称轴x＝2，∴P（X≤0）＝P（X≥4）＝1﹣P（X≤4）＝0.16．故答案为：0.16．16．【解答】解：设P（A）＝x，P（B）＝y，P（C）＝z，根据题意，有，解可得，x＝，y＝，z＝，故P（B）＝y＝，＝（1﹣x）•y＝；故答案为，．三、解答题17．【解答】解：（1）假设学生的数学成绩与物理成绩之间没有关系，由所给的表格可得k2＝≈8.802＞7.879，再根据P（K2≥7.879）≈0.005，∴有0.995的把握认为学生的数学成绩与物理成绩之间有关系．（2）把正六面体骰子连续投掷两次，共有6×6＝36种可能情况，被抽到12号的情况是点数分别为（2，6）、（6，2）、（3，4）、（4，3），共4种情况，故：①抽到12号的概率为＝；抽到“无效序号（序号大于20）”的情况有：（4，6）、（6，4）、（5，5）、（5，6）、（6，5）、（6，6），共计6种情况，故抽到“无效序号（序号大于20）”的概率为＝．18．【解答】解：（Ⅰ）由题意知本题是一个古典概型，设抽到相邻两个月的数据为事件A，试验发生包含的事件是从6组数据中选取2组数据共有C62＝15种情况，每种情况都是等可能出现的其中，满足条件的事件是抽到相邻两个月的数据的情况有5种，∴P（A）＝＝；（Ⅱ）由数据求得＝11，＝24，由公式求得＝＝＝，再由＝﹣b，求得＝﹣，∴y关于x的线性回归方程为＝x﹣，（Ⅲ）当x＝10时，＝，|﹣22|＝＜2，当x＝6时，＝，|﹣12|＝＜2，∴该小组所得线性回归方程是理想的．19．【解答】解：（1）设“在1次摸奖中，获得二等奖”为事件A，则P（A ）＝＝．…（4分）（2）设“在1次摸奖中，获奖”为事件B，则获得一等奖的概率为＝，获得三等奖的概率为P3＝＝，所以P（B ）＝＝．…（8分）由题意可知X的所有可能取值为0，1，2．P（X＝0）＝（1﹣）2＝，P（X＝1）＝＝，P（X＝2）＝（）2＝．所以X的分布列是所以E（X）＝0×+2×＝．…（10分）20．【解答】解：（1）函数f（x ）＝x2﹣ηx﹣1过（0，﹣1）点，在区间（4，6）上有且只有一个零点，则必有，解得：η＜，所以，η＝4或η＝5当η＝4时，，第11页（共13页）第12页（共13页）当η＝5时，，又η＝4与η＝5 为互斥事件，由互斥事件有一个发生的概率公式， 所以；（2）从该单位任选两名职工，用ξ表示这两人休年假次数之差的绝对值，则ξ的可能取值分别是0，1，2，3， 于是＝，，，从而ξ的分布列：ξ的数学期望：．21．【解答】解：（1）因为过点（x 0，y 0），且倾斜角为α的直线的参数方程， 由题意，将x 0＝1，y 0＝1，α＝代入上式得直线l 的参数方程为（t 为参数）．（2）因为A ，B 都在直线l 上，故可设它们对应的参数分别为t 1，t 2，则点A ，B 的坐标分别为A ，B ，将直线l 的参数方程代入圆的方程x 2+y 2＝4中，整理得，则t1，t2是此方程的两根，由韦达定理得t1t2＝﹣2，所以|P A|•|PB|＝|t1t2|＝2．即点P到A、B两点的距离之积为2．22．【解答】解：（1）由题意可知：直线l的直角坐标方程为：2x﹣y﹣6＝0，因为曲线C2的直角坐标方程为：．∴曲线C2的参数方程为：（θ为参数）．（2）设P 的坐标（），则点P到直线l的距离为：＝，∴当sin（60°﹣θ）＝﹣1时，点P （），此时．第13页（共13页）。

福建师大附中2015－2016学年第一学期期末考试卷高一(实验班) 英语（完卷时间：120分钟；满分：150分）第Ⅰ卷 (共84分)第一部分：听力（共20题；每小题1分, 满分20分）第一节（共5 小题；每小题1分, 满分5分）听下面5段对话。

每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How does the man find the movie last night?A. It is moving.B. It is interesting.C. It is not worth seeing2. How much does the handkerchief cost?A. $7.B. $9.C.$16.3. Who made the woman's personal website?A. She herself.B. Her friend.C. The man.4. What does the man want to have?A. Chocolate.B. Sweets.C. Ice-cream.5. Which section would the man like to read?A. Sports.B. Business.C. News.第二节 (共15小题；每小题1分，满分15分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的做答时间。

每段对话或独白读两遍。

听第6段材料，回答第6至8题。

6. What did the man begin to work in Courtaulds?A. About 4 years ago.B. About 40 years ago.C. About 44 years ago.7. What does the man say about his present life?A. He is used to it.B. He likes it.C. He gets bored with it.8. Who is Rover?A. The man's workmate.B. The man's dog.C. The man's wife.听第7段材料，回答第9至11题。

本试卷共4页． 满分150分，考试时间120分钟．注意事项：试卷分第I 卷和第II 卷两部分，将答案填写在答卷纸上，考试结束后只交答案卷.第I 卷 共60分一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项 是符合题目要求的.1.已知a ，R b ∈，下列结论成立的是( )A ．若a b <，则ac bc <B ．若a b <，c d <，则ac bd <C ．若0a b <<，则11a b> D ．若a b <，则错误！未找到引用源。

（n *∈N ，2n ≥） 【答案】C考点：不等式的性质2.下列函数中，最小值为的是( ) A ．=y 32322+++x x B ．xx y 2+= C ．)0(sin 2sin π<<+=x x x y D ．xx y lg 2lg +=0(>x 且)1≠x 【答案】B 【解析】试题分析：A.显然不能取等号，B 正确，C 取等号时，sinx>1与正弦函数定义矛盾，D 显然最小值不是，故选B.考点：均值不等式3.设等比数列{}n a 的前n 项和为n S ，若423S S =，则64S S = ( ) A ．2 B ．73 C ．83D ．3 【答案】B考点：等比数列性质及其前n 项和4.设错误！未找到引用源。

为等差数列{}n a 的前n 项和，已知1596a a a -+=，则9S 的值为( ) A ．54 B ．45 C ．27 D ．18 【答案】A 【解析】试题分析：1595956,6,954a a a a S a -+=∴=∴== ，故选A. 考点：等差数列的性质5.若关于x 方程22(1)20x m x m +-+-=的一个实根小于1-，另一个实根大于1，则实数m 的取值范围是( )A．( B ．(2,0)- C ．(2,1)- D ．(0,1)【答案】D 【解析】试题分析：令2212f x x m x m =+-+-（）（），则由题意利用二次函数的性质求得实数m 的取值范围．令2212f x x m x m =+-+-（）（），则由题意可得()()22,1112000f m m f m m m ⎧⎪∴<<⎨⎪⎩--<+-<＝＝，故选D. 考点：一元二次方程根的分布与系数的关系 6.已知0,0>>b a ，若不等式ba mb a +≥+212恒成立，则实数m 的最大值是( )A ．10B ．9C ．8D ．7 【答案】B考点：基本不等式7.在ABC ∆中，内角,,A B C 所对的边分别为,,a b c ，已知)sin sin sin a A c C b B -=-，则角C 的大小为( )A.34π B.4π C.3πD.2π【答案】B 【解析】试题分析：由题根据正弦定理及余弦定理化简分析计算即可)222sin sin sin ,a A c C b B a b c --+=∴+ ＝,2222222a b c a b c cosC ab +-∴+-∴==,04C C ππ∈∴ （，）＝，故选B.考点：正弦定理；余弦定理8.已知等差数列{}n a 的前n 项和n S 满足65S S <且876S S S >=，则下列结论错误．．的是( ) A ．6S 和7S 均为n S 的最大值 B ．07=aC ．公差0d <D ．59S S > 【答案】D 【解析】试题分析：56678S S S S S =<> ，，则A 正确；6770S S a =∴= ，，∴B 正确；566786780000S S S S S a a a d <>>=∴=∴<< ，，，，， ，C 正确；()6789789520a a a a a a S S +++=+<∴< ， ，D 错误．故选D考点：命题的真假判断，等差数列的前n 项和公式及等差数列的性质9.在ABC ∆中，内角,,A B C 所对的边分别为,,a b c ，若B a A b tan tan 22=，则△ABC 的形状是( ) A. 直角三角形 B. 等腰三角形 C. 等腰直角三角形 D. 等腰或直角三角形 【答案】D考点：三角形的形状判定10.已知实数,x y 满足不等式组2040250x y x y x y -+≥⎧⎪+-≥⎨⎪--≤⎩，若目标函数z y ax =-取得最大值时的唯一最优解是(1,3)，则实数a 的取值范围为( )A. (,1)-∞-B. (0,1)C. (1,)+∞D. [1,)+∞ 【答案】C 【解析】试题分析：画出不等式组不是的可行域，将目标函数变形，数形结合判断出z 最大时，a 的取值范围．不等式 2040250x y x y x y -+≥⎧⎪+-≥⎨⎪--≤⎩的可行域．将目标函数变形得y=ax+z ，当z 最大时，直线的纵截距最大，画出直线y=ax 将a 变化，结合图象得到当a ＞1时，直线经过（1，3）时纵截距最大．故选D ．考点：简单的线性规划【方法点睛】确定二元一次不等式(组)表示的平面区域的方法(1)“直线定界，特殊点定域”，即先作直线，再取特殊点并代入不等式组．若满足不等式组，则不等式(组)表示的平面区域为直线与特殊点同侧的那部分区域；否则就对应与特殊点异侧的平面区域． (2)当不等式中带等号时，边界为实线，不带等号时，边界应画为虚线，特殊点常取原点．11.在ABC ∆中，内角,,A B C 所对的边分别为,,a b c ，已知60A = ，b =a 满足的条件是( )A. 6a <<B. 06a <<C. 0a <<D. a ≥6a = 【答案】A考点：正弦定理；解三角形【名师点睛】本题给出三角形ABC 的角A 和b 的长，求当三角形只有一个时边a 满足的条件．着重考查了利用正余弦定理解三角形的知识，属于中档题．(1)正弦定理是一个连比等式，在运用此定理时，只要知道其比值或等量关系就可以通过约分达到解决问题的目的，在解题时要学会灵活运用． (2)运用余弦定理时，要注意整体思想的运用12.设数列}{n a 是集合{33|0,sts t +≤<且,}s t Z ∈中所有的数从小到大排列成的数列，即a 1＝4，a 2＝10，a 3＝12，a 4＝28，a 5＝30，a 6＝36，…. 将数列}{n a 中各项按照上小下大，左小右大的原则排成如下等腰直角三角形数表，则200a 的值为( )A ．91933+B ．101933+C ． 92033+D ．102033+ 【答案】C故答案为：C 考点：归纳推理【名师点睛】本题考查了一个探究规律型的问题，解题时要认真分析题意，寻找其中的规律，从而解出结果．综合性较强，难度较大；(1)归纳是依据特殊现象推断出一般现象，因而由归纳所得的结论超越了前提所包含的范围．(2)归纳的前提是特殊的情况，所以归纳是立足于观察、经验或试验的基础之上的． (3)归纳推理所得结论未必正确，有待进一步证明，但对数学结论和科学的发现很有用第Ⅱ卷 共90分二、填空题：本大题有4小题，每小题5分，共20分，把答案填在答卷的相应位置.13.已知关于x 的不等式210mx nx +-<的解集为11{|,}32x x x <>或，则m n +等于 . 【答案】-1考点：一元二次不等式的解法14.如图，一辆汽车在一条水平的公路上向正西行驶，到A 处时测得公路北侧一山顶D 在西偏北30O 的方向上，行驶600m 后到达B 处，测得此山顶在西偏北75O 的方向上，仰角为30O ，则此山的高度CD =__________m.【答案】 【解析】考点：解三角形的实际应用15.在ABC ∆中，D 为边BC 的中点，2,1,30AB AC BAD ==∠=,则AD = .【解析】试题分析：延长AD 至E ，使DE=AD ，连接BE ，在△ABE 中，利用正弦定理，即可得到结论．延长AD 至E ，使DE=AD ，连接BE ，则,,1BD CD ADC EDB BDE CDA BE AC =∠=∠∴∆∴== ，≌在△ABE 中，2130AB BE BAD ==∠=︒，，，由正弦定理，得∠AEB=90°，故AE AD =∴=考点：正弦定理的应用【方法点睛】正、余弦定理的应用原则：(1)正弦定理是一个连比等式，在运用此定理时，只要知道其比值或等量关系就可以通过约分达到解决问题的目的，在解题时要学会灵活运用；(2)运用余弦定理时，要注意整体思想的运用．16.已知数列{}n x 满足()21||n n n x n N x x ++=-∈* ，若121,(1,0)x x a a a ==≤≠，且n n x x =+3对于任意正整数n 均成立，则数列{}n x 的前2015项和2015S 的值为 .（用具体的数字表示） 【答案】1344 【解析】试题分析：依题意可求得1a =，于是可求得12345620112012201322,2x x x x x x x x x ++=++=++= ，，，考点：数列求和【名师点睛】本题考查数列的求和，着重考查函数的周期性，得到相邻三项之和为2是关键，属于中档题； 数列与函数的综合一般体现在两个方面：(1)以数列的特征量n ，a n ，S n 等为坐标的点在函数图象上，可以得到数列的递推关系；(2)数列的项或前n 项和可以看作关于n 的函数，然后利用函数的性质求解数列问题．三、解答题：本大题有6题，共70分，解答应写出文字说明、证明过程或演算步骤.17.（本小题满分10分）等差数列{}n a 的前n 项和为n S ，已知37a =，5726a a +=. （Ⅰ）求n a 及n S ； （Ⅱ）令211n n b a =-（n N +∈）,求数列{}n b 的前n 项和n T . 【答案】（Ⅰ）221,2n n a n S n n =+=+ ；（Ⅱ）4(1)n nT n =+【解析】试题分析：（Ⅰ）根据等差数列所给的项和项间的关系，列出关于基本量的方程，解出等差数列的首项和公差，写出数列的通项公式和前n 项和公式．（Ⅱ）根据前面做出的数列构造新数列，把新数列用裂项进行整理变为两部分的差，合并同类项，得到最简结果，本题考查的是数列求和的典型方法--裂项法，注意解题过程中项数不要出错．试题解析：（Ⅰ）设等差数列{a n }的公差为d ，∵37a =，5726a a +=,考点：等差数列的通项公式；等差数列的前n 项和；数列的求和．【易错点睛】利用裂项相消法求和的注意事项：(1)抵消后并不一定只剩下第一项和最后一项，也有可能前面剩两项，后面也剩两项；(2)将通项裂项后，有时需要调整前面的系数，使裂开的两项之差和系数之积与原通项相等.18.（本小题满分10分）在ABC ∆中，角C B A ,,所对的边分别为c b a ,,.已知3=a ，36cos =A ，2π+=A B . （Ⅰ）求b 的值； （Ⅱ）求ABC ∆的面积． 【答案】（Ⅰ）；【解析】试题分析：（Ⅰ）利用cosA 求得sinA ，进而利用A 和B 的关系求得sinB ，最后利用正弦定理求得b 的值． （Ⅱ）利用sinB ，求得cosB 的值，进而根两角和公式求得sinC 的值，最后利用三角形面积公式求得答案． 试题解析：（Ⅰ）∵36cos =A∴sin A == ……… 1分 ∵2π+=A B∴sin sin()cos 2B A A π=+==……… 3分由正弦定理得sin sin a Bb A===……… 5分 （Ⅱ）21sin sin()sin(2)cos 22cos 123C A B A A A π=+=+==-=……… 8分∴111sin 3223ABC S ab C ∆==⨯⨯=……… 10分 考点：正弦定理的应用19.（本小题满分12分）某小型餐馆一天中要购买,A B 两种蔬菜，,A B 蔬菜每公斤的单价分别为2元和3 元．根据需要，A 蔬菜至少要买6公斤，B 蔬菜至少要买4公斤，而且一天中购买这两种蔬菜的总费用不能超过60元．如果这两种蔬菜加工后全部卖出，,A B 两种蔬菜加工后每公斤的利润分别为2元和1元，餐馆如何采购这两种蔬菜使得利润最大，利润最大为多少元？【答案】餐馆应购买A 蔬菜24公斤，B 蔬菜4公斤，加工后利润最大为52元答：餐馆应购买A 蔬菜24公斤， B 蔬菜4公斤，加工后利润最大为52元．……… 12分考点：简单的线性规划的应用20.(本小题满分12分)在∆ABC 中，D 是BC 上的点，AD 平分∠BAC ，∆ABD 面积是∆ADC 面积的2倍. （Ⅰ）求CB ∠∠sin sin ； （Ⅱ）若22,1==DC AD ，求BD 和AC 的长.【答案】（Ⅰ）12；=，解得1x=即1AC=……… 12分考点：三角形面积公式；正弦定理；余弦定理21.(本小题满分12分)某企业为解决困难职工的住房问题，决定分批建设保障性住房供给困难职工，首批计划用100万元购买一块土地，该土地可以建造每层1000平方米的楼房一幢，楼房的每平方米建筑费用与建筑高度有关，楼房每升高一层，整层楼每平方米建筑费用提高20元，已知建筑第1层楼房时，每平方米的建筑费用为920元．为了使该幢楼房每平方米的平均费用最低（费用包括建筑费用和购地费用），应把楼房建成几层？此时平均费用为每平方米多少万元？【答案】10层，此时平均费用为每平方米0.111万元．答：了使该幢楼房每平方米的平均综合费用最低，应把楼房建成10层，此时平均费用为每平方米0.111万元． ……… 12分考点：基本不等式的应用【方法点睛】利用基本不等式求解实际应用题的方法：(1)此类型的题目往往较长，解题时需认真阅读，从中提炼出有用信息，建立数学模型，转化为数学问题求解．(2)当运用基本不等式求最值时，若等号成立的自变量不在定义域内时，就不能使用基本不等式求解，此时可根据变量的范围用对应函数的单调性求解．22.（本小题满分14分）已知数列{}n a ，0n a >，其前n 项和n S 满足122n n n S a +=-,其中*n ∈N ．{}n b 是等差数列； （Ⅱ）设2n n n c b -=⋅，n T 为数列{}n c 的前n 项和，求证：3n T <；（Ⅲ）设14(1)2n bn n n d λ-=+-⋅（λ为非零整数，*n ∈N ），试确定λ的值，使得对任意*n ∈N ，都有n n d d >+1成立．【答案】（Ⅰ）1n b n =+；（Ⅱ）略（Ⅲ）-1考点：数列递推式；数列的通项与求和；恒成立问：。