当前位置:文档之家› 赫尔《期权、期货及其他衍生产品》(第9版)笔记和课后习题详解答案

赫尔《期权、期货及其他衍生产品》(第9版)笔记和课后习题详解答案

赫尔《期权、期货及其他衍生产品》(第9版)笔记和课后习题详解答案
赫尔《期权、期货及其他衍生产品》(第9版)笔记和课后习题详解答案

赫尔《期权、期货及其他衍生产品》(第9版)笔记和课后习题详解完整版>精研学习?>无偿试用20%资料

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第1章引言

1.1复习笔记

1.2课后习题详解

第2章期货市场的运作机制

2.1复习笔记

2.2课后习题详解

第3章利用期货的对冲策略

3.1复习笔记

3.2课后习题详解

第4章利率

4.1复习笔记

4.2课后习题详解

第5章如何确定远期和期货价格

5.1复习笔记

5.2课后习题详解

第6章利率期货

6.1复习笔记

6.2课后习题详解

第7章互换

7.1复习笔记

7.2课后习题详解

第8章证券化与2007年信用危机

8.1复习笔记

8.2课后习题详解

第9章OIS贴现、信用以及资金费用

9.1复习笔记

9.2课后习题详解

第10章期权市场机制

10.1复习笔记

10.2课后习题详解

第11章股票期权的性质

11.1复习笔记

11.2课后习题详解

第12章期权交易策略

12.1复习笔记

12.2课后习题详解

第13章二叉树

13.1复习笔记

13.2课后习题详解

第14章维纳过程和伊藤引理14.1复习笔记

14.2课后习题详解

第15章布莱克-斯科尔斯-默顿模型15.1复习笔记

15.2课后习题详解

第16章雇员股票期权

16.1复习笔记

16.2课后习题详解

第17章股指期权与货币期权17.1复习笔记

17.2课后习题详解

第18章期货期权

18.1复习笔记

18.2课后习题详解

第19章希腊值

19.1复习笔记

19.2课后习题详解

第20章波动率微笑

20.1复习笔记

20.2课后习题详解

第21章基本数值方法

21.1复习笔记

21.2课后习题详解

第22章风险价值度

22.1复习笔记

22.2课后习题详解

第23章估计波动率和相关系数23.1复习笔记

23.2课后习题详解

第24章信用风险

24.1复习笔记

24.2课后习题详解

第25章信用衍生产品

25.1复习笔记

25.2课后习题详解

第26章特种期权

26.1复习笔记

26.2课后习题详解

第27章再谈模型和数值算法

27.1复习笔记

27.2课后习题详解

第28章鞅与测度

28.1复习笔记

28.2课后习题详解

第29章利率衍生产品:标准市场模型29.1复习笔记

29.2课后习题详解

第30章曲率、时间与Quanto调整

30.1复习笔记

30.2课后习题详解

第31章利率衍生产品:短期利率模型31.1复习笔记

31.2课后习题详解

第32章HJM,LMM模型以及多种零息曲线32.1复习笔记

32.2课后习题详解

第33章再谈互换

33.1复习笔记

33.2课后习题详解

第34章能源与商品衍生产品

34.1复习笔记

34.2课后习题详解

第35章章实物期权

35.1复习笔记

35.2课后习题详解

第36章重大金融损失与借鉴

36.1复习笔记

36.2课后习题详解

结构力学习题及答案(武汉大学)

结构力学习题 第2章平面体系的几何组成分析2-1~2-6 试确定图示体系的计算自由度。 题2-1图题2-2图 题2-3图题2-4图 题2-5图题2-6图 2-7~2-15 试对图示体系进行几何组成分析。若是具有多余约束的几何不变体系,则需指明多余约束的数目。

题2-7图 题2-8图题2-9图 题2-10图题2-11图 题2-12图题2-13图 题2-14图题2-15图

题2-16图题2-17图 题2-18图题2-19图 题2-20图题2-21图2-1 1 W = 2-1 9 W - = 2-3 3 W - = 2-4 2 W = - 2-5 1 = W - 2-6 4 = W - 2-7、2-8、2-12、2-16、2-17无多余约束的几何不变体系 2-9、2-10、2-15具有一个多余约束的几何不变体系 2-11具有六个多余约束的几何不变体系 2-13、2-14几何可变体系为

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(c) 习题3-2图 3-3~3-9 试作图示静定刚架的力图。 习题3-3图习题3-4图 习题3-5图习题3-6图 习题3-7图习题3-8图

习题3-9图 3-10 试判断图示静定结构的弯矩图是否正确。 (a) (b) (c) (d) 部分习题答案 3-1 (a )m kN M B ?=80(上侧受拉),kN F R QB 60=,kN F L QB 60-= (b )m kN M A ?=20(上侧受拉),m kN M B ?=40(上侧受拉),kN F R QA 5.32=, kN F L QA 20-=,kN F L QB 5.47-=,kN F R QB 20=

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Unit 9 Vocabulary 1(P215) Into Chinese 1.有力的工具 2.时髦的字眼 3.资金流 4.债券融资 5.产权投资 6.跨国兼并与收购 7.往来账目赤字8.收支盈余 9.裙带资本主义 10.规模经济 11.零部件生产 12.吓人的前景 13.有道理的假设 14.强有力的反对 15.转基因作物 16.缺少共同的议事日程 17.腐蚀当地文化 18.声请加入 19.极力夸大某人的势力 20.推广技术 Into English 1.a double-edged sword 2.national sovereignty 3.a daunting question 4.trade negotiation 5.economic unification 6.ever-declining costs 7.consumer confidence 8.economic forecast 9.economic entities 10.multilateral institutions 11.ensuing financial crisis 12.after adjusting for inflation 13.a full-scale economic downturn 14.lopsided trade flows 15.boom-bust cycle 16.management skill 17.product design 18.unpredictable consequence 19.high-cost industries 20.the OECD 2.(P216) 1.propel/push/ spur 2.The amount we benefit;neutralized;heighten/intensify 3.inspire/rouse/stimulate/stire/give rise to/lead to 4.expected/estimated/projected/forecast;help to improve/contribute to improving/favor a rise in 5.shield/defend/preserve;reduce/lower;phase out/lift/eliminate 6.championed/advocated/stood for/fought for/supported;trade liberalization;engage with/integrate with/link up with/participate in 7.develop into/snowball until it becomes/grow into/escalate into;slump/recession/depression/crisis 8.disregard/ignore 9.dwarfed/exceeded

《结构力学习题集》(含答案)

第三章 静定结构的位移计算 一、判断题: 1、虚位移原理等价于变形谐调条件,可用于求体系的位移。 2、按虚力原理所建立的虚功方程等价于几何方程。 3、在非荷载因素(支座移动、温度变化、材料收缩等)作用下,静定结构不产生内力,但会有位移且位移只与杆件相对刚度有关。 4、求图示梁铰C 左侧截面的转角时,其虚拟状态应取: A. ; ; B. D. C. =1 =1 5、功的互等、位移互等、反力互等和位移反力互等的四个定理仅适用于线性变形体系。 6、已知M p 、M k 图,用图乘法求位移的结果为:()/()ωω1122y y EI +。 M k M p 2 1 y 1 y 2 * * ωω ( a ) M =1 7、图a 、b 两种状态中,粱的转角?与竖向位移δ间的关系为:δ=? 。 8、图示桁架各杆E A 相同,结点A 和结点B 的竖向位移均为零。 A a a 9、图示桁架各杆EA =常数,由于荷载P 是反对称性质的,故结点B 的竖向位移等于零。 二、计算题: 10、求图示结构铰A 两侧截面的相对转角?A ,EI = 常数。 q l l l /2 11、求图示静定梁D 端的竖向位移 ?DV 。 EI = 常数 ,a = 2m 。 a a a 10kN/m 12、求图示结构E 点的竖向位移。 EI = 常数 。 l l l /3 /3 q

13、图示结构,EI=常数 ,M =?90kN m , P = 30kN 。求D 点的竖向位移。 P 3m 3m 3m 14、求图示刚架B 端的竖向位移。 q 15、求图示刚架结点C 的转角和水平位移,EI = 常数 。 q 16、求图示刚架中D点的竖向位移。EI = 常数 。 l/2 17、求图示刚架横梁中D点的竖向位移。 EI = 常数 。 18、求图示刚架中D 点的竖向位移。 E I = 常数 。 q l l/2 19、求图示结构A、B两截面的相对转角,EI = 常数 。 l/3 l/3 20、求图示结构A 、B 两点的相对水平位移,E I = 常数。

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大学英语精读第三版(上海外语教育出版社董亚芬主编) 第三册Book3 Unit1~Unit10 翻译答案 ? Unit1 翻译 1) 发言人(spokesman)明确表示总统在任何情况下都不会取消(cancel)这次旅行。 The spokesman made it clear that the President would not cancel the trip under any circumstances. 2) 杰克对书架上那些书一本也不了解,所以他的选择是很随意的。 Jack didn't know anything about any of the books on the bookshelf, so his choice was quite arbitrary. 3) 随后发生的那些事件再次证明了我的猜疑(suspicions)是对的。(confirm) The subsequent events confirmed my suspicions once again. 4) 我认为我们应该鼓励中学生在暑假找临时工作。 I think we should encourage high school students to find temporary jobs / employment during their summer holidays. 5) 令我们吃惊的是,这位常被赞为十分正直的州长(governor)竟然是个贪官(corrupt official)。 To our surprise, the governor who had often been praised for his honesty turned out to be a corrupt official. 6) 少数工人得到提升(be promoted),与此同时却有数百名工人被解雇。 A few workers were promoted, but meanwhile hundreds of workers were dismissed. 7) 如果有机会,约翰也许已成为一位杰出的画家了。(given) Given the chance, John might have become an outstanding painter. 8) 数小时后,有人看见那个男孩在林子里瞎转。 Several hours later, the boy was found wandering around in the woods. ? Unit2 翻译 迅速方便地获得信息是很重要,但学会以新的方式看信息甚至更为重要。医学上一次重大突破也许能说明这一观点。科学家本想寻找一种治天花的特效药,但他们没有成功。英国医生爱德华·詹纳放弃寻找特效药,而是通过找到一种预防天花的办法征服了这一疾病。显然,是创造性思维使他的工作获得巨大收获。总之,记住下面这句话肯定大有裨益:有多种方法可以用来看待你下载的大量资料。 It is important to have easy and quick access to information, but it is even more important to learn to look at / view information in new ways. A major medical breakthrough may illustrate the point. Scientists had intended to find a cure for smallpox, but they got nowhere. Edward Jenner, a British physician, abandoned the quest for a cure and conquered the disease by finding a way to prevent it. Obviously, it was creative thinking that led to his fruitful work. In short, it definitely pays to keep this in mind: there is more than one way to look at / view volumes of data you download. ? Unit3 翻译 1) 许多美国大学生申请政府贷款交付学费。 Many American students apply for government loans to pay for their education / tuition. 2) 除阅读材料外,使用电影和多媒体(multimedia)会激发学生学习的兴趣。 Besides reading materials, the use of films and multimedia can stimulate students' interest in a

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习题 7-1 试确定图示结构的位移法基本未知量数目,并绘出基本结构。 (a) (b) (c) 1个角位移3个角位移,1个线位移4个角位移,3个线位移 (d) (e) (f) 3个角位移,1个线位移2个线位移3个角位移,2个线位移 (g) (h) (i) 一个角位移,一个线位移一个角位移,一个线位移三个角位移,一个线位移7-2 试回答:位移法基本未知量选取的原则是什么?为何将这些基本未知位移称为关键位移?是否可以将静定部分的结点位移也选作位移法未知量? 7-3 试说出位移法方程的物理意义,并说明位移法中是如何运用变形协调条件的。 7-4 试回答:若考虑刚架杆件的轴向变形,位移法基本未知量的数目有无变化?如何变化? 7-5 试用位移法计算图示结构,并绘出其内力图。 (a) 解:(1)确定基本未知量和基本结构 有一个角位移未知量,基本结构见图。 l 7- 32

7- 33 Z 1M 图 (2)位移法典型方程 11110 p r Z R += (3)确定系数并解方程 i ql Z ql iZ ql R i r p 24031831 ,82 12 12 111= =-∴-== (4)画M 图 M 图 (b) 解:(1)确定基本未知量 1个角位移未知量,各弯矩图如下 4m 4m 4m

7- 34 1Z =1M 图 3 EI p M 图 (2)位移法典型方程 11110 p r Z R += (3)确定系数并解方程 1115 ,35 2p r EI R ==- 15 3502 EIZ -= 114Z EI = (4)画M 图 () KN m M ?图 (c) 解:(1)确定基本未知量 一个线位移未知量,各种M 图如下 6m 6m 9m

现代大学英语精读1-第九课课后参考答案

现代大学英语精读1-第九课课后参考答案

Preview 3.Read the text again for language and complete the following tasks. 2 Translate the following expressions into Chinese. 1. 臂挽着臂齐步前进 2. 并肩作战 3. 谈心里话 4. 一句一句翻译 5. 一寸一寸地爬 6. 一个月一个月地等 7. 夜以继日地下雪 8. 手拉手一起走 9. 面对面坐着 10. 一步一步走 11. 一页一页读 12. 日复一日辛勤劳动 13. 和某人意见相同 14. 咳嗽了一整天 Vocabulary 1 Become familiar with the rules of word formation. 1.Give the corresponding nouns for the following adjectives. 1. weakness 2. quickness 3. strength 4. width 5. breadth

6. heat 7. anger 8. clarity 9. length 10. silence 11. freedom 12. sadness 13. moderation 14. happiness 2.Point out which of the following adjectives can be used as verbs. Those that can be used as verbs are: slow, clear, narrow, open, quiet, dim, thin, clean, empty, close, dry, wet, cool, near, dirty, loose short---shorten strong---strengthen dark---darken hot---heat bright---brighten sad---sadden red---redden ripe---ripen weak---weaken wide---widen thick---thicken quick---quicken cold---cool low---lower angry---anger hard---harden deep---deepen long---lengthen (long在此作“长的”解,如作动词,意为“盼望”) broad---broaden fat---fatten light---lighten (light这里作“轻的”解,如作动词,

结构力学课后习题答案

习题及参考答案 【习题2】【习题3】【习题4】【习题5】【习题6】【习题8】【习题9】【习题10】【习题11】【习题12】【习题13】【习题14】【参考答案】 习题2 2-1~2-14试对图示体系进行几何组成分析,如果是具有多余联系的几何不变体系,则应指出多余联系的数目。 题2-1图 题2-2图 题2-3图题2-4图题2-5图 题2-6图题2-7图题2-8图 题2-9图题2-10图题2-11图

题2-12图 题2-13图 题2-14图 习题3 3-1 试作图示多跨静定梁的M 及Q 图。 (b) (a) 20kN 40kN 20kN/m 40kN 题3-1图 3-2 试不计算反力而绘出梁的M 图。 (b) 5kN/m 40kN (a) 题3-2图 习题4 4-1 作图示刚架的M 、Q 、N 图。 (c) (b)(a)20kN /m 2kN /m 题4-1图 4-2 作图示刚架的M 图。

P (e) (d) (a) (b) (c) 20k N /m 4kN 题4-2图 4-3 作图示三铰刚架的M 图。 (b) (a) 题4-3图 4-4 作图示刚架的M 图。 (a) 题4-4图 4-5 已知结构的M 图,试绘出荷载。 (b) (a) 题4-5图

4-6 检查下列刚架的M 图,并予以改正。 (e)(g)(h) P (d) (c)(a)(b) (f) 题4-6图 习题5 5-1 图示抛物线三铰拱轴线方程x x l l f y )(42-= ,试求D 截面的力。 题5-1图 5-2 带拉杆拱,拱轴线方程x x l l f y )(42-= ,求截面K 的弯矩。 C 题5-2图 题5-3图 5-3 试求图示带拉杆的半圆三铰拱截面K 的力。 习题 6 6-1 判定图示桁架中的零杆。

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现代大学英语精读3 unit 3课后答案

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