选修课考试作业
1001 Sum Problem ............................................................................................ 错误!未定义书签。1089 A+B for Input-Output Practice (I) .......................................................... 错误!未定义书签。1090 A+B for Input-Output Practice (II) ......................................................... 错误!未定义书签。1091 A+B for Input-Output Practice (III) ........................................................ 错误!未定义书签。1092 A+B for Input-Output Practice (IV) ........................................................... 错误!未定义书签。1093 A+B for Input-Output Practice (V) ......................................................... 错误!未定义书签。1094 A+B for Input-Output Practice (VI) ........................................................ 错误!未定义书签。1095 A+B for Input-Output Practice (VII) .......................................................... 错误!未定义书签。1096 A+B for Input-Output Practice (VIII) ...................................................... 错误!未定义书签。'
2000 ASCII码排序 ............................................................................................ 错误!未定义书签。2001计算两点间的距离.................................................................................. 错误!未定义书签。2002计算球体积 ............................................................................................. 错误!未定义书签。2003求绝对值 ................................................................................................. 错误!未定义书签。2004成绩转换 ................................................................................................. 错误!未定义书签。2005第几天 ..................................................................................................... 错误!未定义书签。2006求奇数的乘积 ......................................................................................... 错误!未定义书签。2007平方和与立方和...................................................................................... 错误!未定义书签。2008数值统计 ................................................................................................. 错误!未定义书签。2009求数列的和 ............................................................................................. 错误!未定义书签。~
2010水仙花数 ................................................................................................. 错误!未定义书签。2011多项式求和 ............................................................................................. 错误!未定义书签。2012素数判定 ................................................................................................. 错误!未定义书签。2014青年歌手大奖赛_评委会打分................................................................ 错误!未定义书签。2015偶数求和 ................................................................................................. 错误!未定义书签。2016数据的交换输出...................................................................................... 错误!未定义书签。2017字符串统计 ............................................................................................. 错误!未定义书签。2019数列有序! ................................................................................................ 错误!未定义书签。2020绝对值排序.............................................................................................. 错误!未定义书签。2021发工资咯：）............................................................................................ 错误!未定义书签。:
2033人见人爱A+B .......................................................................................... 错误!未定义书签。2039三角形 ..................................................................................................... 错误!未定义书签。2040亲和数 ..................................................................................................... 错误!未定义书签。
姓名：郑春杰
班级：电商1001
学号：34
1001 Sum Problem
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
Author
DOOM III
解答：
#include<>
main()
{
int n,i,sum;
sum=0;
while((scanf("%d",&n)!=-1))
{
sum=0;
for(i=0;i<=n;i++)
sum+=i;
printf("%d\n\n",sum);
}
}
1089 A+B for Input-Output Practice (I)
Problem Description
Your task is to Calculate a + b.
Too easy! Of course! I specially designed the problem for acm beginners.
You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.
Input
The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
1 5
10 20
Sample Output
6
30
Author
lcy
Recommend
JGShining
解答：
#include<>
main()
{
int a,b;
while(scanf("%d%d",&a,&b)!=EOF) printf("%d\n",a+b);
}
1090 A+B for Input-Output Practice (II)
Problem Description
Your task is to Calculate a + b.
Input
Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
2
1 5
10 20
Sample Output
6
30
Author
lcy
Recommend
JGShining
解答：
#include<>
#define M 1000
void main()
{
int a,b,n,j[M],i;
Input
Input contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 terminates the input and this test case is not to be processed.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
1 5
10 20
0 0
Sample Output
6
30
Author
lcy
Recommend
JGShining
解答：
#include<>
main()
{
int a,b;
scanf("%d %d",&a,&b);
while(!(a==0&&b==0))
{
printf("%d\n",a+b);
scanf("%d %d",&a,&b);
}
}
1092A+B for Input-Output Practice (IV)
Problem Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
Sample Output
10
15
Author
lcy
Recommend
JGShining
解答：
#include <>
int main()
{
int n,sum,i,t;
while(scanf("%d",&n)!=EOF&&n!=0)
{
sum=0;
for(i=0;i { scanf("%d",&t); sum=sum+t; } printf("%d\n",sum); } } 1093 A+B for Input-Output Practice (V) Problem Description Your task is to calculate the sum of some integers. Input Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. Output For each group of input integers you should output their sum in one line, and with one line of output for each line in input. Sample Input 2 4 1 2 3 4 5 1 2 3 4 5 Sample Output 10 15 Author lcy 解答： #include<> main() { int n,a,b,i,j,sum; sum=0; while(scanf("%d\n",&n)!=-1) { for(i=0;i { scanf("%d",&b); for(j=0;j { scanf("%d",&a); sum+=a; } printf("%d\n",sum); sum=0; } } } 1094 A+B for Input-Output Practice (VI) Problem Description Your task is to calculate the sum of some integers. Input Input contains multiple test cases, and one case one line. Each case starts with an integer N, and then N integers follow in the same line. Output For each test case you should output the sum of N integers in one line, and with one line of output for each line in input. Sample Input 4 1 2 3 4 5 1 2 3 4 5 Sample Output 10 15 Author lcy Recommend JGShining 解答： #include<> main() { int n,a,b,i,j,sum; sum=0; while(scanf("%d\n",&n)!=-1) { for(j=0;j { scanf("%d",&a); sum+=a; } printf("%d\n",sum); sum=0; } } [ Copy to Clipboard ][ Save to File] 1095A+B for Input-Output Practice (VII) Problem Description Your task is to Calculate a + b. Input The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line. Output For each pair of input integers a and b you should output the sum of a and b, and followed by a blank line. Sample Input 1 5 10 20 Sample Output 6 30 Author lcy Recommend JGShining 解答： #include<> main() { int a,b; while(scanf("%d%d",&a,&b)!=EOF) printf("%d\n\n",a+b); } 1096 A+B for Input-Output Practice (VIII) Problem Description Your task is to calculate the sum of some integers. Input Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line. Output For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs. Sample Input 3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3 Sample Output 10 15 6 Author lcy Recommend JGShining 解答： int main() { int a,b,i,j,l[1000],k; scanf("%d",&i); getchar(); for(j=1;j<=i;j++) l[j]=0; for(j=1;j<=i;j++) { scanf("%d",&a); getchar(); for(k=1;k<=a;k++) { scanf("%d",&b); getchar(); l[j]+=b; } } for(j=1;j<=i-1;j++) printf("%d\n\n",l[j]); printf("%d\n",l[i]); } 2000 ASCII码排序Problem Description 输入三个字符后，按各字符的ASCII码从小到大的顺序输出这三个字符。 Input 输入数据有多组，每组占一行，有三个字符组成，之间无空格。 Output 对于每组输入数据，输出一行，字符中间用一个空格分开。 Sample Input qwe asd zxc Sample Output e q w a d s c x z Author lcy Source C语言程序设计练习（一） Recommend JGShining 解答： #include<> main() { char a,b,c,d; while(scanf("%c %c %c",&a,&b,&c)!=EOF) { getchar(); if(a>=b) { if(c>=a) printf("%c %c %c\n",b,a,c); else if(b>=c) printf("%c %c %c\n",c,b,a); else if(b printf("%c %c %c\n",b,c,a); } else { if(c>=b) printf("%c %c %c\n",a,b,c); else if(c>=a) printf("%c %c %c\n",a,c,b); else if(a>c) printf("%c %c %c\n",c,a,b); } } } 2001计算两点间的距离 Problem Description 输入两点坐标（X1,Y1）,（X2,Y2）,计算并输出两点间的距离。 Input 输入数据有多组，每组占一行，由4个实数组成，分别表示x1,y1,x2,y2,数据之间用空格隔开。 Output 对于每组输入数据，输出一行，结果保留两位小数。 Sample Input 0 0 0 1 0 1 1 0 Sample Output Author lcy Source C语言程序设计练习（一） Recommend JGShining 解答： #include<> #include<> main() { double a,b,c,d,s; while(scanf("%lf %lf %lf %lf",&a,&b,&c,&d)!=EOF) { s=sqrt((a-c)*(a-c)+(b-d)*(b-d)); printf("%.2lf\n",s); }
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