双语C期末复习资料(2013级)

《国际贸易实务（双语）》三习题库第一章国际贸易简介Chapter 1 A Brief Introduction to International Trade预习题1. What is international trade?2. Why do nations trade?练习题3. What are the differences between international trade and domestic trade?4. P17-20 专业术语、课后练习复习题5. What are the characteristics of international trade？6. What are the forms of international trade？7. Useful certificates for your future job-hunting.第二章进出口交易的一般程序General Procedure of International Trade一、国际贸易的基本流程Basic procedure of international trade预习题：1. Suppose you are an exporter, what will you do before you enter into a business with a trade partner?2.我国某出口公司与香港C公司签订了一笔总值25万美元销售猪肉的合同,FOB青岛,目的港韩国釜山,付款方式为D/A远期120天办理托收。

该出口公司按规定的装运期限装运货物后,通过中国银行办理托收手续。

中国银行委托香港南洋商业银行为代收行向香港C公司收款。

单据到香港后,C公司即承兑赎单,又以原提单向韩国收货人收取了货款。

香港南洋商业银行在汇票到期时向C公司催促付款,但此时该公司已宣告破产。

经查核C公司在当地注册资本仅15万港元,其财产远远不够抵偿该公司的欠款。

生物化学复习资料Amino acid（氨基酸）: All proteins are made up from the same set of 20 standard amino acids. A typical amino acid has a primary amino group, a carboxyl group, a hydrogen atom and a side-chain(R group) attached to a central α-group atom(Cα). Proline（脯氨酸）is the exception to the rule in that it has a secondary amino group.Primary structure（一级结构）: The linear（线状的）sequence of amino acids joined together by peptide bonds is termed（被称为）the primary structure of the protein. The position of covalent disulfide bonds between cysteine（半胱氨酸）residues is also included in the primary structure.Secondary structure（二级结构）: Secondary structure is a protein refers to the regular folding of regions of the polypeptide chain. The two most common types of secondary structure are the αhelix and βpleated sheet（β折叠）.Tertiary structure（三级结构）: Tertiary structure in a protein refers to the three-dimensional（三维的）arrangement of all the amino acids in the polypeptide chain. This biologically active, native conformation（构造；形态）is maintained by multiple（多重的；多样的）noncovalent （非共价的）bonds.Quaternary structure（四级结构）: if a protein is made up of more than one polypeptide chain it is said to have quaternary structure. This refers to the spatial（空间的）arrangement of the polypeptide subunits（亚基；亚单位）and the nature of the interactions between them.Protein stability（蛋白质稳定性）: In addition to the peptide bonds between individual amino acid residues, the three-dimensional structure of a protein is maintained by a combination of noncovalent interactions(electrostatic forces（静电力）, van derWaals forces（范德华力）,hydrogen bonds（氢键）, hydrophobic forces（疏水作用力）) and covalent interactions(disulfide bonds（二硫键）).The Bohr effect(波尔效应): H+, CO2and 2,3-bisphosphoglycerate（2,3-二磷酸甘油酸）are allosteric effectors（变构效应剂）, promoting the release of O2 from hemoglobin（血红蛋白）. H+ and CO2 bind to different parts of the polypeptide chains, while 2,3-bisphosphoglycerate binds in the central cavity（凹穴）between the four subunits.Dialysis（透析）: Proteins can be separated from small molecules by dialysis through asemi-permeable membrane（半透膜）which has pores that allow small molecules to pass through but not proteins.Function and diversity of collagen（胶原蛋白）: Collagen is the name given to a family of structurally related proteins that form strong insoluble（不可溶的）fibers. Collagens consist of three polypeptide chains, the identity and distribution of which vary between collagen types.Gel filtration chromatography(凝胶过滤层析)Ion exchange chromatography(离子交换层析)Affinity chromatography(亲和层析)Enzymes as catalysts（作为催化剂的酶）: Enzymes are catalysts（催化剂）that change the rate of a reaction without being changed themselves. Enzymes are highly specific and their activity can be regulated. Virtually all enzymes are proteins, although some catalytically active RNAs have been identified.Active site（活性位点）: The active site is the region of the enzyme that binds the substrate, to form an enzyme-substrate complex, and transforms it into product. The active site is a three-dimensional entity（实体）, often a cleft（裂口）of crevice（缺口）on the surface of the protein, in which the substrate is bound by multiple weak interactions. Two models have been proposed to explain how an enzyme binds its substrate: the lock-and-key model and the induced-fit model（诱导契合模型）.Enzyme classification（酶的分类）: Enzymes are classified into six major groups on the basis of the type of reaction that they catalyze. Each enzyme has a unique four-digit classification number.Enzyme assays（酶的测定）: An enzyme assay measures the conversion of substrate to product, under conditions of cofactors, pH and temperature at which the enzyme is optimally active（最佳活性的）.Coenzymes（辅酶）and prosthetic group（辅基）: Some enzymes require the presence of cofactors, small nonprotein units, to function. Cofactors may be inorganic ions or complex organic molecules called coenzymes. A cofactor that is covalently attached to the enzyme is called a prosthetic group. A holoenzyme is the catalytically active form of the enzyme with its cofactor, whereas an apoenzyme（脱辅基酶蛋白）is the protein part on its own.Isoenzymes（同工酶）: Isoenzymes are different forms of an enzyme which catalyze the same reaction, but which exhibit different physical of kinetic（动力学的）properties（性质）.Activation energy and transition state: For a biochemical reaction to proceed, the energy barrierneeded to transform the substrate molecules into the transition state has to be overcome. The transition state has the highest free energy in the reaction pathway. The different in free energy between the substrate and the transition state is termed the Gibbs free energy of activation. An enzyme stabilizes the transition state and lowers Gibbs free energy（吉布斯自由能）, thus increasing the rate at which the reaction occurs.Michaelis-Menten equation（米氏方程）: v＝Vmax[S]/ (Km+[S])It describe these observations and predicts a hyperbolic curve（双曲线）of V0 against [S]. The Michaelis constant, Km, is equal to the sum of the rates of breakdown of the enzyme-substrate complex over its rate of formation, and is a measure of the affinity（亲和性）of an enzyme for its substrate.Enzyme inhibition（酶的抑制）: The catalytic rate of an enzyme can be lowered by inhibitor molecules. Many inhibitors exist, including normal body metabolites, foreign drugs and toxins. Enzyme inhibition can be of two main types: irreversible or reversible. Reversible inhibition can be subdivided into competitive and noncompetitive.Irreversible inhibition（不可逆抑制）: An irreversible inhibition binds tightly, often covalently, to amino acid residues at the active site of the enzyme, permanently inactivating the enzyme.Reversible competitive inhibition（可逆竞争抑制）: A competitive inhibitor competes with the substrate molecules for binding to the active site of the enzyme. At high substrate concentration, the effect of a competitive inhibitor can be overcome. the type of the inhibition can increase the Km ,but leave the Vmax unchanged.（Km变大，Vmax不变）Reversible noncompetitive inhibition（可逆非竞争性抑制）: A noncompetitive inhibitor binds at a site other than the active site of the enzyme and decreases its catalytic rate by causing a conformational change in the three-dimensional shape of the enzyme. The effect of a noncompetitive inhibitor cannot be overcome at high substrate concentrations. This type of the inhibition can decrease Vmax ,but leave the Km unchanged.（Km不变，Vmax变小）Reversible uncompetitive inhibition（可逆反竞争性抑制）: A uncompetitive inhibition binds at a site located in the substrate-enzyme complex. Thus, the type of the inhibition can decrease both the Vmax and the Km.（Km和Vmax都变小）Allosteric enzymes: A plot（绘制成的坐标图）of V0 against [S] for an allosteric enzyme gives a sigmoidal-shaped curve（S形的曲线）. Allosteric enzymes usually have more than one active site which cooperatively bind substrate molecules, such that the binding of substrate at one active site induces a conformational change in the enzyme which alters the affinity of the other active sites for substrate. Allosteric enzymes are often multisubunit proteins(多亚基蛋白质), with an active site on each subunit. Two models have been proposed to explain the allosteric behavior of enzyme, the concerted or the symmetry model（齐变模型）and the sequential model（序变模型）.Reversible covalent modification: The activity of many enzymes is altered by the reversiblemaking and breaking of a covalent bond between the enzyme and a small nonprotein group. The most common such modification is the addition and removal of a phosphate group（磷酸基）; phosphorylation（磷酸化）and dephosphorylation（去磷酸化）, respectively. Phosphorylation is catalyzed by protein kinases（蛋白激酶）, often using A TP as the phosphate donor, whereas dephosphorylation is catalyzed by protein phosphatases.（蛋白磷酸酯酶或蛋白磷酸化酶）Proteolytic activation（酶原激活）: Some enzymes are synthesized as larger inactive precursors （前体）called proenzymes or zymogens（酶原）. These are activated by the irreversible hydrolysis（水解）of one or more peptide bonds.DNA double helix（DNA双螺旋结构）: In a DNA double helix, the two strands（串；条）of DNA are wound round each other with the bases（碱基）on the inside and the sugar-phosphate backbones（磷酸糖主干）on the outside. The two DNA chains are held together by hydrogen bonds between pairs of bases; adenine（A）always pairs with thymine（T）and guanine（G）always pairs with cytosine（C）. In the double helix, the two strands are organized in an antiparallel arrangement（反平行的排布）(one is oriented in the 5’→3’ , the other is in the 3’→5’).Between the sugar-phosphate strand is the gap which could be divided into two types, that is, the wide named major groove（大沟）and the narrow named minor groove（小沟）.Glycogen（糖原）: glycogen is a branched-chained polysaccharide containing glucose residues linked by α-1-4 bonds（α-1,4糖苷键）with α1-6 branchpoints（α-1,6糖苷键分支点）. The branched nature of glycogen makes it more accessible to glycogen phosphorylase（糖原磷酸化酶）during degradation（降解）, since this enzyme degrades the molecule by sequential removal of glucose residues from the nonreducing ends.Starch（淀粉）: Starch is a mixture of unbranched amylase(glucose residues joined by α1-4 bonds) and branched amylopectin(glucose residues joined α1-4 but with some α1-6 branchpoints).Overview of pentose phosphate pathway（磷酸戊糖途径综述）: The two major products of the pathway are nicotinamide adenine dinucleotide and ribose 5-phosphate（核糖-5-磷酸酯）. Ribose 5-phosphate and its derivatives are components of important cellular molecules such as RNA, DNA, NAD+，flavine adenine dinucleotide(FAD), A TP and coenzyme A(CoA). NADPH is required for many biosynthetic pathways and particularly for synthesis of fatty acids and steroids （类固醇）.Four Biological roles of fatty acids（脂肪酸的四个生理功能）:1.They are components of membranes(sphingolipids and glycerophospholipids)2.Several proteins are covalently modified by fatty acids;3.They act as energy stores(triacylglycerols) and fuel molecules;4.Fatty acid derivatives serve as hormones and intracellular second messengers.Role of Citric acid cycle(柠檬酸循环，又名tricarboxylic acid cycle（三羧酸循环），简称TAC): The cycle oxidizes pyruvate(formed during the glycolytic breakdown of glucose) to CO2andH2O,with the concomitant production of energy. Acetyl CoA from fatty acid breakdown and amino acid degradation products are also oxidaized. In addition, the cycle has a role in producing precursors for biosynthetic pathways.Energy yield of Citric acid cycle（柠檬酸循环的能量产出）: For each turn of the cycle,10 ATP molecules are produced, one directly from the cycle and 9 from the re-oxidation of the three NADH and one FADH2 molecules produced by the cycle by oxidative phosphorylation（氧化磷酸化）.20种常见氨基酸的名称和结构式名称英文缩写结构式甘氨酸(α-氨基乙酸)Glycine Gly GCH2COONH3丙氨酸(α-氨基丙酸)Alanine Ala ACH COONH3CH3亮氨酸(γ-甲基-α-氨基戊酸)*Leucine Leu LCHCOONH3(CH3)2CHCH2异亮氨酸(β-甲基-α-氨基戊酸)* Isoleucine Ile ICHCOONH3CH3CH2CHCH3缬氨酸(β-甲基-α-氨基丁酸)*Valine Val VCHCOONH3(CH3)2CH脯氨酸(α-四氢吡咯甲酸)Proline Pro P COONH H苯丙氨酸(β-苯基-α-氨基丙酸)* Phenylalanine Phe FCHCOONH3CH2蛋(甲硫)氨酸(α-氨基-γ-甲硫基戊酸) * Methionine Met MCHCOONH3CH3SCH2CH2色氨酸[α-氨基-β-(3-吲哚基)丙酸]* Tryptophan Trp WNCH2CH COONH3H丝氨酸(α-氨基-β-羟基丙酸)Serine Ser SCHCOONH3HOCH2谷氨酰胺(α-氨基戊酰胺酸)Glutamine Gln Q CH2CH2CHCOONH3H2N CO苏氨酸(α-氨基-β-羟基丁酸)*Threonine Thr TCHCOONH3CH3CHOH半胱氨酸(α-氨基-β-巯基丙酸)Cysteine Cys CCHCOONH3HSCH2天冬酰胺(α-氨基丁酰胺酸)Asparagine Asn N CH2CHCOONH3H2N CO酪氨酸(α-氨基-β-对羟苯基丙酸) Tyrosine Tyr YCHCOONH3CH2HO天冬氨酸(α-氨基丁二酸) Aspartic acid Asp DNH3HOOCCH2CHCOO谷氨酸(α-氨基戊二酸) Glutamic acid Glu ECHCOONH3HOOCCH2CH2赖氨酸(α,ω-二氨基己酸)*Lysine Lys KCHCOONH2CH2CH2CH2CH2NH3精氨酸(α-氨基-δ-胍基戊酸)Arginine Arg RH2N C CHCOONH2NHCH2CH2CH2NH2组氨酸[α-氨基-β-(4-咪唑基)丙酸] Histidine His H NCH2CH COONH3HN* 为必需氨基酸中性脂肪族氨基酸：Gly (Gly也是二十种中唯一不含手性碳原子的氨基酸，不具有旋光性)Ala Val Lue Ile含羟基或者巯基：Ser Thr Cys Met酸性氨基酸及其酰胺：Asp Asn Glu Gln碱性氨基酸和杂环氨基酸：Lys Arg His Pro芳香族氨基酸：Phe Tyr Trp非极性R基氨基酸：Ala V al Leu Ile Pro Phe Trp Met带正电荷(碱性)R基氨基酸：Lys Arg His不带电荷的极性R基氨基酸：Gly Ser Thr Cys Tyr Asn Gln带负电（酸性）的R基氨基酸：Asp Glu在280nm附近有吸收峰的氨基酸是：Phe Tyr Trp ，其中Trp的吸收峰在280nm处最强等电点：在某一pH的溶液中，氨基酸解离成阳离子和阴离子的趋势及程度相等，所带净电荷为零，呈电中性，此时溶液的pH称为该氨基酸的等电点。

国际贸易实务双语教程复习材料一、判断1. When dealing in international trade (exporting and importing), a businessman has to face a variety of conditions which differ from those to which he has grown accustomed in the domestic trade. ( )2. According to the CISG, once the offerer stipulates the validity on the offer ,the offerer can still cancel the offer . （）3. Offer and acceptance are two indispensable links for reaching an agreement and concluding a contract. ( )4. During the negotiation , the offer is made by seller and acceptance is made by buyer . （）5. Enquiry, offer and acceptance are indispensable part of a negotiation . （）6. If an offer remarks \（）7. An advertisement on paper is aneffective offer . （） 8. Same to the offer, acceptance also can be cancel . （） 9. An offer may not indicate the terms of payment.（）10. The price-list and catalogues sent to some companies are also offers with binding effect.（） 11. Price terms are mainly applied to determining the prices of commodities in international trade. （）12. Warsaw-Oxford Rules clearly explain the thirteen kinds of trade terms incurrent use. ( ) 13. As an exporter, you concluded a deal with an American on basis of EXW; then your transaction risk is reduced the minimum degree . （）14. According to the interpretation of the Revised American Foreign Trade Definition, FAS is suitable for all kinds of transportation. （）15. On CIP terms, the seller must pay the freight rate and insurance premium as well as bear all the risks until the goods have arrived at the destination . （）16. The common feature of an FOB contract and an FAS contract is that the seller must load the goods on a named ship. ( )17. According to Incoterms 2021, FCA is suitable for all kinds of transportation . （）18.在国际贸易中，一项合同的有效成立都必须经过询盘、发盘、还盘、接受和签约五个环节。

2013 NationalEnglish ContestforCollegeStudents(LevelC - Final)参考答案及作文评分标准PartIListening Com prehension (30 marks)Section A (5 marks)1—5 ACBBCSection B (10 marks)6—10 CCABA11—15 BCBCASection C (5 marks)16—20 ACBACSection D (10 marks)21.prescription22.drugaddiction23.lenientapproach24.distinguished between25.arelicensed to 26.singletransaction27.Proponents28.legitimate29.campaigns30.therebyPartIIVocabulary and Structure(15 marks)31—35 DBBCB36—40 CABAD41—45 ABACAPartIIICloze(10 marks)46.height47.both48.surprising49.mistakenly50.through51.hungry52.scientific53.Sleepiness54.connection55.evilPartIV Reading Com prehension (40 marks)Section A (10 marks)56.risks57.innocentrmation59.gang60.requestingSection B (10 marks)61.F62.T63.F64.Itprovidesstudentswith an onlinelearningenvironment.65.Theyreceivetheindividualsupportandadvicetheyneedtosucceed in theirstudy.Section C (10 marks)66.enduring 67.starved68.moredramatically69.D70.CSection D (10 marks)71.BecausetheEgyptiansworshipedcatsasholyanimalsandtherewerelawsprotectingthem.72.TheDarkAgesin Europe.1--73.About10 percent.74.猫惯有“巫师的助手”之称。

全国大学生英语竞赛C类考试2013年决赛试题及详解[视频讲解]Part ⅠListening Comprehension (30 marks)Section A (5 marks)In this section, you will hear five short conversations. Each conversation will be read only once. At the end of each conversation, there will be a twenty-second pause. During the pause, read the question and the three choices marked A, B and C, and decide which is the best answer. Then mark the corresponding letter on the answer sheet with a single line through the centre.1. Why does the man want an early appointment?A. Because he mustn’t eat before he goes for the appointment.B. Because he doesn’t feel like eating breakfast that morning.C. Because he wants to see the doctor without taking time off work.【答案】A【解析】男士说早上和医生有预约，而且做检查前12小时不能吃东西，提到Then I can have a snack and not miss too much time at work.所以他要早一些去。

【录音原文】M: I have to have an appointment first thing in the morning. The doctor wants to do me tests and I mustn’t eat for twelve hours before that. I’m right, aren’t I?W: Yes. She said the best way is to go without breakfast and come in early.M: Yeah. Then I can have a snack and not miss too much time at work.2. Why is the man dissatisfied with the college?A. He’s got problems in study last term and it further affects him this term.B. His professor changes the timetable of lectures very often.C. He’s unhappy with the time arrangement of the lectures.【答案】C【解析】由男士的话…three lectures on a Friday. I wish they wouldn’t change the timetable every term可知，男士对课程的时间安排不满意。

2013 National English Contest for College Students (Level C - Preliminary)Part I Listening Comprehension (30 marks)Section A (5 marks) 1—5 ABCCBSection B (10 marks) 6—10 ABBCB 11—15 CABABSection C (5 marks) 16—20 CACBBSection D (10 marks) 21. yearn for 22. flush out 23. tends to recommend 24. compensate for 25. lack of evidence 26. separated into 27. assessed 28. medication 29. contradictory 30. wrinklesPart II Vocabulary and Structure (15 marks) 31—35 CDCCB 36—40 BADCA 41—45 ADBCAPart III Cloze (10 marks) 46. hiding 47. surprising 48. pressure 49. presidency 50. existence 51. with 52. place 53. gravity 54. Additionally55. afternoonPart IV Reading Comprehension (40 marks) Section A (10 marks) 56. money 57. comparing 58. unique 59. altered 60. privacySection B (10 marks) 61. F 62. F 63. T 64. Pansies are more hardy than busy lizzies. 65. Potentillas.Section C (10 marks) 66. extreme lengths / great lengths 67. compatible with 68. on condition 69. C 70. B Section D (10 marks) 71. Glaciers and forests. 72. 24 cubic miles of ice. 73. They have increased in numbers. 74. 阿拉斯加的大部分土地曾经是常年冰冻，或是一年中多数时间都保持冰冻状态，以此保持它的完整。

双语中学2013—2014年学年度上学期期末考试高二物理试卷时间 90分钟 满分100分选择题 （共12小题每题4分，共48分，每个小题只有一个答案是正确的） 1．有关电场强度的理解，下列叙述正确的是( ) A ．由FE q=可知，电场强度E 跟试探电荷所受电场力F 成正比，跟其带电量成反比 B ．电场强度是反映电场自身特性的物理量，与是否存在试探电荷无关C ．由2KQE r =可知，在离点电荷Q 很近的地方即r →0，场强E 可达无穷大 D ．公式UE d=对任何电场都适用2、真空中两个相同的带等量异种电荷的小球A 和B ，分别固定在两处，两球间静电力为F 。

用不带电的同样小球C 先和A 接触，再与B 接触，然后移去C ，则A 、B 间的静电力应为（ ） A ．F/2 B ．F/4 C ．F/8 D ．3F/83、如图所示的情况中，a 、b 两点的电势相同，而电场强度也相同的是 （ ）A ．甲图：带电平行金属板两板间边缘附近处的a 、b 两点B ．乙图：离点电荷等距的a 、b 两点C ．丙图：两个等量异种点电荷连线的中垂线上，与连线中点等距的a 、b 两点D ．丁图：两个等量异种点电荷连线上，与连线中点等距的a 、b 两点4、如图所示为一匀强电场，实线为电场线，一个带电粒子射入该电场后，留下一条虚线所示的轨迹，途经a ，b 两点，由a 运动到b ，且不计粒子的重力。

则下面判断正确的是( ) A ．b 点的电势高于 a 点的电势B ．粒子在a 点的动能大于在b 点的动能C ．粒子在a 点的电势能大于b 点的电势能D ．粒子带正电5、用图5所示的实验装置研究平行板电容器的电容与哪些因素有关，下面哪些说法符合实验结果（ ）A.把M 板向左平移，静电计指针示数变大B.把M 板向右平移，静电计指针示数变大C.把M 板向上平移，静电计指针示数变小D.保持两板不动，在M 、N 之间插入一块云母板， 静电计指针示 数变大6、在如图所示的点电荷的电场中，一试探电荷从A 点分别移动到B 、C 、D 、E 各点，B 、C 、D 、E 在以Q 为圆心的圆周上，则电场力做功A ．从A 到B 做功最大 B ．从A 到C 做功最大 C ．从A 到E 做功最大D ．做功一样大7、如图所示电路中，三只灯泡原来都正常发光，当滑动变阻器的滑动触头P 向左移动时，下面判断正确的是A 、L 1和L 3变亮，L 2变暗B 、L I 变暗，L 2变亮，L 3亮度不变C 、L 1和L 2变亮，L 3变暗D 、L I 变亮，L 2变暗，L 3亮度不变8、如图所示，A 、B 、C 三点都在匀强电场中，已知AC ⊥BC ，∠ABC=60°，BC=20cm ，把一个电量为10-5c 的正电荷从A 移到B ，电场力做功为零，从B 移到C ，电场力做功-1.73×10-3J ，则该匀强电场的电场强度大小和方向 A.865V/m,垂直AC 向左 B. 865V/m,垂直AC 向右C. 1000V/m,垂直AB 斜向上D. 1000V/m,垂直AB 斜向下9、如图5所示为用直流电动机提升重物的装置，重物的重量为500N ，电源电动势为110V ，不计电源内阻及各处摩擦，当电动机以0.90m/s 的恒定速度向上提升重物时，电路中的电流为5.0A ，可以判断错误的是：（ ） A 、电动机消耗的总功率为550W B 、提升重物消耗的功率为450W C 、电动机线圈的电阻为22Ω D 、电动机线圈的电阻为4Ω10、如图所示，将两不带电的绝缘导体AB 、CD 放在带负电的导体Q 的附近，达到静电平衡状态后，下列说法正确的是A ．用导线连接A 、B 两端，连通瞬间有电流通过导线，方向由A 到BB ．用导线连接A 、C 两端，连通瞬间没有电流通过导线C ．用导线连接A 、D 两端，连通瞬间有电流通过导线，方向由A 到D D ．用导线连接B 、C 两端，连通瞬间有电流通过导线，方向由C 到B11、如图所示，三个等势面上有a、b、c、d四点，若将一正电荷由c经a移到d点，电场力做正功W1；若由c经b移到d点，电场力做正功W2．则W1与W2，c、d两点电势ϕc、ϕd关系为A．W1＞W2，ϕc＞ϕ d B．W1＜W2，ϕc＜ϕdC．W1＝W2，ϕc＜ϕd D．W1＝W2，ϕc＞ϕd12、粗细均匀的金属环上A、B、C、D四点把其周长分成四等分，如右图所示。

国际经济法学（双语）FX212006——在线考试复习资料2021版一、单选题1.国际项目融资中,产品销售协议是由()订立的。

A.主办人与贷款人B.主办人与项目公司C.项目公司与贷款人D.项目公司与产品购买人答案：D2.不属于国际金融法上的资金融通方式是()。

A.国际贷款B.国际间接投资C.国际直接投资D.国际融资租赁答案：C3.关于国际投资法的调整对象,下列说法正确的是()。

A.国际投资法的调整对象包括国际直接投资关系和国际间接投资关系B.国际间接投资主要是跨国购买股票、债券等C.国际直接投资不以取得东道国企业的控制权和经营权为模式D.国际直接投资法要调整政府之间的投资关系答案：B4.国际项目融资中,产品销售协议是由()订立的。

A.主办人与贷款人B.主办人与项目公司C.项目公司与贷款人D.项目公司与产品购买人答案：D5.关于BOT,下列说法错误的是()。

A.BOT是建设-经营-转让B.BOT涉及一系列合同安排C.BOT的合同安排中最基础的是特许协议D.BOT是主要是私人之间的协议答案：D6.国际货币制度历史发展进程是()。

A.布雷顿森林体系—金本位制度——牙买加体制B.牙买加体制—布雷顿森林体系—金本位制度C.金本位制度—布雷顿森林体系—牙买加制度D.金本位制度—牙买加制度—布雷顿森林体系答案：C7.对知识产权保护水平最高的国际公约是()。

A.《建立世界知识产权组织公约》B.《保护工业产权巴黎公约》C.《世界版权公约》D.《与贸易有关的知识产权协议》答案：D8.属于银行信用的支付方式是()。

A.买方直接汇付B.托收C.信用证D.支票答案：C9.《2010年国际贸易术语解释通则》中,卖方承担义务最小的术语是()。

A.CIFB.CIPC.DDPD.EXW答案：D10.关于BOT,下列说法错误的是()。

A.BOT是建设-经营-转让B.BOT涉及一系列合同安排C.BOT的合同安排中最基础的是特许协议D.BOT是主要是私人之间的协议答案：D11.《汉堡规则》规定的诉讼时效为()。

2013年全国职称英语等级考试综合类C级真题及详解第1部分：词汇选项(第1～15题，每题1分，共15分)下面每个句子中均有1个词或者短语划有底横线，请为每处划线部分确定1个意义最为接近的选项。

1. This was an unexceptionally brutal attack.A. openB. suddenC. cruelD. direct【答案】C【解析】句意：这无疑是一次残忍的攻击。

划线词brutal为形容词，意为“残忍的，野蛮的”。

open公开的，敞开的。

sudden突然的意外的。

cruel残酷的，残忍的。

二者意思相近，符合题意。

direct直接的。

故本题正确答案为C。

2. The frame needs to be strong enough to support the engine.A. bottomB. surfaceC. topD. structure【答案】D【解析】句意：这个框架要足够结实以便支撑引擎。

划线词frame为名词，意为“框架，结构”。

bottom底部。

surface表面。

top顶部，顶端。

structure构造，结构。

二者意思相近，符合题意。

故正确答案为D。

3. Traffic reaches its rush hour between 8:00 and 9:00 in the morning.A. borderB. goalC. levelD. peak【答案】D【解析】句意：早八点至九点是上下班交通高峰期。

划线词组rush hour为名词词组，意为“上下班高峰”。

border边界。

Goal目标。

level水平，级别。

peak高峰。

二者意思相近，符合题意。

故正确答案为D。

4. She came across three children sleeping under a bridge.A. passed byB. found by chanceC. took a notice ofD. woke up【答案】B【解析】句意：她碰到三个睡在桥下的小孩。