2019届高考全国卷1冲刺最后一卷
理 科 数 学（一）
注意事项：
1、本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。答题前，考生务必将自己的姓名、考生号填写在答题卡上。
2、回答第Ⅰ卷时，选出每小题的答案后，用铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。写在试卷上无效。
3、回答第Ⅱ卷时，将答案填写在答题卡上，写在试卷上无效。
4、考试结束，将本试卷和答题卡一并交回。
第Ⅰ卷
一、选择题：本大题共12小题，每小题5分，共60分．在每小题给出的四个选项
中，
只有一项是符合题目要求的．
1．已知集合{}2log 2M x x =<，{}1,0,1,2N =-，则M N =（ ）
A ．{}1,0,1,2-
B ．{}1,1,2-
C ．{}0,1,2
D ．{}1,2
2．设1i
2i 1i
z +=+-，则z =（ ） A ．2
B ．3
C ．4
D ．5
3．设等差数列{}n a 的前n 项和为n S ，若44a =，972S =，则10a =（ ） A ．20
B ．23
C ．24
D ．28
4．我国古代数学名著《数学九章》有“米谷粒分”题：粮仓开仓收粮，有人送来米1534石，验得米夹谷，抽样取米一把，数得254粒夹谷28粒，则这批米中，谷约为（ ） A ．134石
B ．169石
C ．338石
D ．454石
5． “1m >”是“方程22
115
y x m m +=--表示焦点在y 轴上的双曲线”的（ ）
A ．充分不必要条件
B ．必要不充分条件
C ．充要条件
D ．既不充分也不必要条件
6．某几何体的三视图如图所示，则该几何体的体积等于（ ）
A ．
19π6 B ．17π6 C ．23π6 D ．10π
3
7．函数()()2sin ππ1
x
f x x x =
-≤≤+的图象可能是（ ） A ． B ．
C ．
D ．
8．若01a b <<<，b x a =，a y b =，log b z a =，则x ，y ，z 大小关系正确的是（ ） A ．y x z <<
B ．x y z <<
C ．z x y <<
D ．z y x <<
9．执行如图所示程序框图，若输出的S 值为20-，在条件框内应填写（ ） A ．3?i >
B ．4?i <
C ．4?i >
D ．5?i <
10．已知抛物线2:8C y x =的焦点为F ，直线)2y x =-与C 交于A ，B （A 在x 轴上方）两点，若AF mFB =，则实数m 的值为（ ）
A B ．3
C ．2
D ．32
11．某几何体的三视图如图所示，该几何体表面上的点P 与点Q 在正视图与侧视图上的对应点分别为A ，B ，则在该几何体表面上，从点P 到点Q 的路径中，最短路径的长度为（ ）
A B C ．D
12．设函数()()sin f x x ω?=+，()()
(){}
00,A x f x f x '=
=，()22,162x y B x y ????=+≤??????
，若
存在实数?，使得集合A B 中恰好有5个元素，则()0ωω>的取值范围是（ ）
A
．?
????
B
．????? C
．????? D
．?
????
第Ⅱ卷
二、填空题：本大题共4小题，每小题5分，共20分．
13．已知向量()3,0=a
，(2+=a b ，则a 与b 的夹角等于_________．
14
．若二项式6
21x x ?
+????的展开式中的常数项为m ，则21
3d m
x x =?
______． 15．数列{}n a 且21
,2πsin ,4n n n n
a n n ???+=?
???为奇数
为偶数
，若n S 为数列{}n a 的前n 项和，则
2018S =______．
16．长沙市为了支援边远山区的教育事业，组织了一支由13名教师组成的队伍下乡支教，记者采访队长时询问这个团队的构成情况，队长回答：“（1）有中学高级教师；（2）中学教师不多于小学教师；（3）小学高级教师少于中学中级教师；（4）小学中级教师少于小学高级教师；（5）支教队伍的职称只有小学中级、小学高级、中学中级、中学高级；（6）无论是否把我计算在内，以上条件都成立．”由队长的叙述可以推测出他的学段及职称分别是____．
三、解答题：本大题共6个大题，共70分．解答应写出文字说明、证明过程或演算步骤．
17．（12分）在ABC △中，内角A ，B ，C 所对的边分别为a ，b ，c ，()2
cos π3
B -=
，1c =
，sin sin a B A ．
（1）求边a 的值；
（2）求cos 23πB ?
?+ ??
?的值．
18．（12分）如图，四棱锥中P ABCD -，四边形ABCD 为菱形，60BAD ∠=?，
PA PD AD ==
，平面PAD ⊥平面ABCD ． （1）求证：AD PB ⊥；
（2）求二面角A PC D --的余弦值．
19．（12分）“回文数”是指从左到右与从右到左读都一样的正整数，如22，121，3553等．显然2位“回文数”共9个：11，22，33，
，99．现从9个不同2位“回文数”中任取1
个乘以4，其结果记为X ；从9个不同2位“回文数”中任取2个相加，其结果记为Y ． （1）求X 为“回文数”的概率；
（2）设随机变量ξ表示X ，Y 两数中“回文数”的个数，求ξ的概率分布和数学期望()E ξ．
20．（12分）已知椭圆()2222:10x y E a b a b +=>>经过点12P ?? ??
?，且右焦点)
2
F ．
（1）求椭圆E 的方程；
（2）若直线:l y kx =+与椭圆E 交于A ，B 两点，当AB 最大时，求直线l 的方程．
21．（12分）已知()()2e x f x ax a =-∈R ． （1）求函数()f x '的极值；
（2）设()()e x g x x f x =-，若()g x 有两个零点，求a 的取值范围．
请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分． 22．（10分）【选修4-4：坐标系与参数方程】
在直角坐标系xOy 中，曲线1C 的参数方程为22cos 2sin x y ??=+=???，（?为参数）．以原点O 为极
点，x 轴正半轴为极轴建立极坐标系，曲线2C 的极坐标方程为4sin ρθ=． （1）求曲线1C 的普通方程和2C 的直角坐标方程；
（2）已知曲线3C 的极坐标方程为()0π,θααρ=<<∈R ，点A 是曲线3C 与1C 的交点，点
B 是
曲线3C 与2C 的交点，且A ，B 均异于极点O ，且AB =a 的值．
23．（10分）【选修4-5：不等式选讲】 已知函数()241f x x x =-++． （1）解不等式()9f x ≤；
（2）若对于任意()0,3x ∈，不等式()2f x x a <+恒成立，求实数a 的取值范围．
2019届高考全国卷1冲刺最后一卷
理科数学答案（一）
一、选择题． 1．【答案】D
【解析】由题知{}04M x x =<<，故{}1,2M N =．故选D ．
2．【答案】B 【解析】
()()()()1i 1i 1i 2i
i 1i 1i 1i 2
+++===--+，则3i z =，故3z =，故选B ． 3．【答案】D
【解析】由于数列是等差数列，故41913493672a a d S a d =+==+=???，解得18a =-，4d =，
故101983628a a d =+=-+=．故选D ． 4．【答案】B
【解析】由题意可知：这批米内夹谷约为28
1534169254
?≈石，故选B ． 5．【答案】B
【解析】22
115y x m m +=--表示焦点在y 轴上的双曲线1050m m ->???
-
，解得15m <<，故选B ．
6．【答案】A
【解析】由三视图可以看出，该几何体上半部是半个圆锥，下半部是一个圆柱，
从而体积2211119π
π1π13236
V =???+??=?，故选A ．
7．【答案】A 【解析】因为()()
()()()22sin sin ππ1
1
x x
f x f x x x x --=
=-
=--≤≤+-+，可得()f x 是奇函数．排除
C ； 当π
3x =
时，0π3f ??
> ???
，点在x 轴的上方，排除D ； 当3π
x =-时，π103f ??
-<
-< ???
，排除B ；故选A ． 8．【答案】B
【解析】取特殊值，令14
a =
，12b =，
则1
2
1142b x a ??=== ???，14
1122a y b ??==> ???，12
1
log log 24b z a ===，
则
14
1
1222??<< ???
，即x y z <<，可排除A 、C 、D 选项，故答案为B ． 9．【答案】D
【解析】模拟执行程序，可得：1i =，10S =，
满足判断框内的条件，第1次执行循环体，11028S =-=，2i =， 满足判断框内的条件，第2次执行循环体，2824S =-=，3i =， 满足判断框内的条件，第3次执行循环体，3424S =-=-，4i =， 满足判断框内的条件，第4次执行循环体，44220S =--=-，5i =， 此时，应该不满足判断框内的条件，退出循环，输出的S 值为20-， 则条件框内应填写5?i <，故选D ． 10．【答案】B
【解析】设A 、B 在l 上的射影分别是1A 、1B ，过B 作1BM AA ⊥于M ．
由抛物线的定义可得出Rt ABM △中，得60BAE ∠=?，
1111
cos6012
AA BB AM AF BF m AB AF BF AF BF m ---?=
====+++，解得3m =，故选B ． 11．【答案】C
【解析】由题，几何体如图所示
（1）前面和右面组成一面
此时PQ ． （2）前面和上面在一个平面
此时PQ ，故选C ． 12．【答案】A
【解析】()()sin f x x ω?=+的最大值或最小值，一定在直线1y =±上，又在集合B 中．
当1y =±时，22
162
x y +≤，得x ≤
23T T ?≤?∴?
>??
2π22π3ωω
??≤??∴???>??
，ω≤<，故选A ．
二、填空题． 13．【答案】120?
【解析】已知向量()3,0=a
，(2+=a b ，
令(=c ，则(
)(
)(11
1022
=
-=-=-b c a ， 设向量a 、b 的夹角是θ，于是
31031
cos 62
θ?-+?-=
=
=-
a b
a b
，故120θ
=?．
14．【答案】124
【解析】由题意，二项展开式的通项为66212316
61C C r
r
r
r r
r r T x x ---+???=??=?? ??
????
??
，
由1230r -=，得4r =，所以2
46C 5m =?=??，则5
223533
111
3d 3d |51124m x x x x x ===-=??
．
15．【答案】
3028
2019
【解析】数列{}n a 且21
,2πsin ,4
n n n n
a n n ???+=?
???为奇数
为偶数
，
①当n 为奇数时，21111222n a n n n n ??
=
=- ?++??
；
②当n 为偶数时，πsin
4
n n a =， 所以()()201813520172462018S a a a a a a a a =++++++++
+，
()11111110093028
1101012335
2017201920192019
??
=-+-++
-++-++=
+=
???
．
故答案为
3028
2019
． 16．【答案】小学中级
【解析】设小学中级、小学高级、中学中级、中学高级人数分别为a ，b ，c ，d ， 则13a b c d +++=，1d ≥，c d a b +≤+，b c <，a b <， 所以()13a b a b -+≤+，7a b ∴+≥，6c d +≤，
若7a b +=，则6c d +=，a b <，3a ∴=，4b =，5c =，1d =，
若8a b +≥，则5c d +≤，1d ≥，4c ∴≤，b c <，3b ∴≤，5a b ≥>，矛盾， 队长为小学中级时，去掉队长则2a =，4b =，5c =，1d =， 满足11d =≥，64c d a b +=≤+=，45b c =<=，24a b =<=；
队长为小学高级时，去掉队长则3a =，3b =，5c =，1d =，不满足a b <； 队长为中学中级时，去掉队长则3a =，4b =，4c =，1d =，不满足b c <； 队长为中学高级时，去掉队长则3a =，3b =，5c =，0d =，不满足1d ≥； 综上可得队长为小学中级．
三、解答题．
17．【答案】（1）53
；（2．
【解析】（1）由()2cos π3B -=
，得2cos 3
B =-，
因为1c =，由sin sin a B A ，得ab =，∴b =， 由余弦定理2222cos b a c ac B =+-，得234150a a +-=，
解得53a =或3a =-（舍），∴5
3
a =．
（2）由2cos 3B =-，得sin B =sin2B =1cos29
B =-，
∴cos 2cos 2cos sin 2sin 333πππB B B ?
?+=- ??
?．
18．【答案】（1）见解析；（2
【解析】（1）证明：取AD 中点O 连结PO ，BO ，
PA PD =，PO AD ∴⊥．
又四边形ABCD 为菱形，60BAD ∠=?，故ABD △是正三角形， 又点O 是AD 的中点，BO AD ∴⊥． 又PO
BO O =，PO 、BO ?平面BOP ，AD ∴⊥平面BOP ，
又PB ?平面BOP ，AD PB ∴⊥．
（2）PA PD =，点O 是AD 的中点，PO AD ∴⊥．
又平面PAD ⊥平面ABCD ，平面PAD
平面ABCD AD =，PO ?平面PAD ，
PO ∴⊥平面ABCD ，
又AO ，BO ?平面ABCD ，PO AO ∴⊥，PO BO ⊥．又AO BO ⊥， 所以OA ，OB ，OP 两两垂直．
以O 为原点，分别以OA ，OB ，OP 的方向为x 轴，y 轴，z 轴的正方向建立空间直角坐标系O xyz -．
设2AB =，则各点的坐标分别为()1,0,0A ，()B ，()
C -，()1,0,0
D -，()0,0,1P ．
故()AC =-，()1,0,1AP =-，()
1PC =--，()1,0,1PD =--， 设()1111,,x y z =n ，()2222,,x y z =n 分别为平面PAC ，平面PCD 的一个法向量，
由1100
AC AP ?????==??n n
，可得1111300x x z -+?=-+=????，令11z =，则11x =
，1y =
()
11=n ．
由220
PC PD ?=??????=n n
，可得22222200x z x z -+-=--=?????，令21z =，则21x =-
，2y =
故21,??
=- ? ???
n ．
(
)
121,cos ,??
?- ? ?=
==n n ．
又由图易知二面角A PC D --是锐二面角， 所以二面角A PC D --
19．【答案】（1）2
9
；（2）随机变量ξ的概率分布为
随机变量ξ的数学期望为()79
E ξ=
． 【解析】（1）记“X 是‘回文数’”为事件A ．
9个不同2位“回文数”乘以4的值依次为44，88，132，176，220，264，308， 352，396．其中“回文数”有44，88．所以，事件A 的概率()2
9
P A =． （2）根据条件知，随机变量ξ的所有可能取值为0，1，2． 由（1）得()29
P A =
． 设“Y 是‘回文数’”为事件B ，则事件A ，B 相互独立． 根据已知条件得，()2
9C 2059
P B =
=． ()()()2528
0119981P P A P B ξ????===--=
???????
；
()()()()()252543
111999981P P A P B P A P B ξ????==+=-+-=
? ?????
； ()()()2510
29981
P P A P B ξ===?=．
所以，随机变量ξ的概率分布为
所以，随机变量ξ的数学期望为()28431070128181819
E ξ=?
+?+?=．
20．【答案】（1）2214x y +=；（2）y =+．
【解析】（1）设椭圆E 的左焦点()
1F ，则12242a PF PF a =+=?=，
又2
2
2
1c b a c ?=-=，所以椭圆E 的方程为2
214
x y +=．
（2）由()
2222144044
y kx k x x y ????=?+++=+=?，设()11,A x y ，()22,B x y ，
由()
2221
128161404Δk k k =-+>?>
，且12214x x k +=-+，122414x x k
=+，
AB ==
设2114t k =+，则10,2t ??∈ ???，AB ==，
当112
t =
，即k =AB ，此时:l y x =
21．【答案】（1）0a ≤时，()f x '没有极值，0a >时，()f x '有极小值22ln2a a a -； （2）()0,+∞．
【解析】（1）()e 2x f x ax ='-，()e 2x f x a '-'=．
①若0a ≤，显然()0f x ''>，所以()f x '在R 上递增，所以()f x '没有极值． ②若0a >，则()0ln2f x x a ?>''，
所以()f x '在(),ln2a -∞上是减函数，在()ln2,a +∞上是增函数． 所以()f x '在ln2x a =处取极小值，极小值为()()ln221ln2f a a a =-'． （2）()()()2e 1e x x g x x f x x ax =-=-+．函数()g x 的定义域为R ， 且()()
2e e 2x x g x x ax x a ='=++．
①若0a >，则()00g x x <'?<；()00g x x >'?>．所以()g x 在(),0-∞上是减函数， 在()0,+∞上是增函数．所以()()min 01g x g ==-．
令()()1e x h x x =-，则()e x h x x '=．显然()00h x x <'?<， 所以()()1e x h x x =-在(),0-∞上是减函数． 又函数2y ax =在(),0-∞上是减函数，取实数0
<，
则()2
0110g h a
??>+?=-+= ??．
又()010g =-<，()10g a =>，()g x 在(),0-∞上是减函数，在()0,+∞上是增函数． 由零点存在性定理，()g x 在
??
??
?，()0,1上各有一个唯一的零点．所以0a >符合题意．
②若0a =，则()()1e x g x x =-，显然()g x 仅有一个零点1．所以0a =不符合题意．
③若0a <，则()()ln 2e e a
x g x x -'??=-??
．
（i ）若()ln 20a -=，则1
2
a =-．此时()0g x '≥，即()g x 在R 上递增，至多只有一个零
点，
所以1
2
a =-不符合题意．
（ii ）若()ln 20a -<，则1
02
a -<<，函数()g x 在()(),ln 2a -∞-上是增函数，
在()()ln 2,0a -上是减函数，在()0,+∞上是增函数，
所以()g x 在()ln 2x a =-处取得极大值，且极大值()()(){
}
2
ln 2ln 2110g a a a -=--+
所以()g x 最多有一个零点，所以1
02
a -<<不符合题意．
（iii ）若()ln 20a ->，则1
2
a <-，函数()g x 在(),0-∞和()()ln 2,a -+∞上递增，
在()()0,ln 2a -上递减，所以()g x 在0x =处取得极大值，且极大值为()010g =-<，
所以()g x 最多有一个零点，所以1
2
a <-不符合题意．综上所述，a 的取值范围是()0,+∞．
请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分． 22．【答案】（1）()2
21:24C x y -+=，()2
22:24C x y +-=；（2）7π12
α=或11
π12．
【解析】（1）()2
21:24C x y -+=，()2
22:24C x y +-=．
（2）1:4cos C ρθ=，联立极坐标方程θα=，得4cos A ρα=，4sin B ρα=，
π4A B ρρα?
?∴-=-= ??
?sin 4πα??∴-=
??? 0πα<<，∴7π12
α=
或11
π12．
23．【答案】（1）[]2,4-；（2）5a ≥．
【解析】（1）()9f x ≤，可化为2419x x -++≤，
即2339x x >-≤???
或1259x x -≤≤-≤???或1
339x x <--+≤???，
解得24x <≤或12x -≤≤或21x -≤<-；不等式的解集为[]2,4-． （2）2412x x x a -++<+在()0,3x ∈恒成立，
52412124133
a
x x x a x a x x a x a -?-++<+?--+<-<+-?
<<+， 由题意得，()50,3,33a a -??
?+ ???，所以5005335a a a a a -≤≥???≥?+≥≥???
?．
绝密★启封前试卷类型A 2017年普通高等学校招生全国统一考试（全国1卷）
英语 （考试时间：120分钟试卷满分：150分） 第一部分听力(共两节，满分30分) 略 第二部分阅读理解(共两节，满分40分) 第一节 (共15小题；每小题2分，满分30分) 阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项，并在答题卡上将该项涂黑。 A Pacific Science Center Guide ◆Visit Pacific Science Center’s Store Don’t forget to stop by Pacific Science Center’s Store while you are here to pick up a wonderful science activity or remember your visit. The store is located(位于) upstairs in Building 3 right next to the Laster Dome. ◆Hungry Our ex hibits will feed your mind but what about your body? Our café offers a complete menu of lunch and snack options, in addition to seasonal specials. The café is located upstairs in Building 1 and is open daily until one hour before Pacific Science Center closes. ◆Rental Information Lockers are available to store any belongings during your visit. The lockers are located in Building 1 near the Information Desk and in Building 3. Pushchairs and wheelchairs are available to rent at the Information Desk and Denny Way entrance. ID required. ◆S upport Pacific Science Center Since 1962 Pacific Science Center has been inspiring a passion(热情) for discovery and lifelong learning in science, math and technology. Today Pacific Science Center serves more than 1.3 million people a year and beings inquiry-based science education to classrooms and community
高考英语完形类和阅读类训练（5） 完型填空。阅读下面短文，掌握其大意，然后从以下题所给的A、B、C、D四个选项中，选出最佳选项。 Mr. Green was ill and went to the hospital. A doctor __1__ and said, “Well, Mr. Green, you are going to __2__ some injections, and you’ll feel much better. A nurse will come __3__ give you th e first one this evening, and then you’ll __4__ get another one tomorrow evening.” __5__ a young nurse came to Mr. Green’s bed and said to him, “I am going to give you your __6__ injection now, Mr. Green. Where do you want it?” The old man was __7__. He looked at the nurse for a __8__, then he said, “__9__ has ever let me choose that before. Are you really going to let me choose now?” “Yes, Mr. Green,” the nurse answered. She was in a hurry. “Where do you want it?” “Well, then,” the old man answered __10__ “I want it in your left arm, please.”名师点评 这是一篇笑话，格林先生在医院看病时需要打点滴，当护士让他选择身体的一个部位时，他却借题发挥，选了护士的左臂。 (B)1. A. looked for him B. looked him overC. looked after him D. looked him up 【解析】B。look for sb/sth 意为“寻找……”；look after sb 意为“照料……”；look up sb意为“看望……”；而look over sb意为“检查某人”，最贴近文意，为正确选项。 (A)2. A. get B. give C. make D. hold 【解析】A。医生要对格林先生进行注射，格林先生是动作的接受者，故应选get。 (D)3. A. so B. but C. or D. and 【解析】D。空白部分前面I come 和后面的give形成承接关系，所以应用 and连接。 (D)4. A. must B. can C. had better D. have to 【解析】D。must 不可以用于将来时，根据文章意思，应选have to。 (D)5. A. In the morning B. In the afternoonC. In the endD. In the evening 【解析】D。与上文this evening相对应，In the evening应为正确选项。 (A)6. A. first B. one C. two D. second
2015真题（卷一） A. 伦敦运河博物馆每月脱口秀 除8月以外，我们的脱口秀节目将在每月第一个周四的19:30拉开序幕，持续到21:00左右结束。门票价格合理，无需预定。 11月7日场 运河先驱演讲者：克里斯*路易斯 詹姆斯*布林德利是人们公认的早期大运河的主要工程师之一，同时也是一名培训师，指导别人如何设计和建设大运河。克里斯*路易斯将向听众阐述布林德利是如何在培养早期“土木工程师”过程中做出如此积极贡献的。 12月5日场 都市之冰演讲者：马尔科姆*塔克 在冰箱问世之前，保存食物和餐饮业都需要冰块。马尔科姆*塔克向听众介绍天热冰块的引进史，建设冰井的技术，及伦敦的冰块贸易发展史。 2月6日场 科兹沃尔德丘陵运河的演变演讲者：利兹*佩恩 斯特劳德大运河将在不久后重新开放，而泰晤士河和塞文河还需要更久的时间。我们将对当前的发展进行解说。 3月6日场 河中“小岛”---泰晤士河岛演讲者：米兰达*维克 泰晤士河岛有很多小岛，米兰达对其都有所了解，她将向我们介绍其中最有趣的几个岛屿。在线订票：...... 更多信息..... B 今年冬天，寒冷的东北部实在是不适合过冬，所以当这个周末恰好有机会去佛罗里达的萨拉索塔时，天还没亮，我就迫不及待的收拾好行囊出发了。萨拉索塔是个温暖的地方，十分养人，一路上我都在想象着那里的沙滩和橙子树。当我们到达目的地，看到蔚蓝的天空，感受到温暖的空气时，我心中油然而生一种感激之情。整个周末我们都在游泳，品美酒，观日落（日落时间是在傍晚时分，不是下午四点），但是最和我口味的就是每天早晨7点的蔬菜大抢购，现在我们每天7点起床去萨拉索塔的农贸市场抢购蔬菜，为了这些蔬菜，起得再早也值得。 该农贸市场始建于1979年，每周六从早上七点开放至下午一点，沿着北柠檬街和洲街搭起帐篷，无论严寒酷暑，风雨无阻。市场种蔬菜水果品种繁多，有成筐的水灵灵的红草莓，有Java Dawg的咖啡卡车，车的两侧都刷着红漆，最吸人眼球的就是西红柿，又大又软，圆润红透。 我曾有过很多次买到（卖家）保证是自然成熟的西红柿，但实际却并非如此，失望之极，我已经很多年不在冬天买西红柿了。无论它们在商店里看上去多么诱人，只要一拿回家就会变干变硬，食之无味。但是在Brown’s Grove农场一个特殊的摊位上，全都是新鲜柔软的西红柿，犹如拳头大小，由于过后我还是买了一些。这笔交易还真不赖。在那一刻，我意识到冬天在萨拉索塔最好的经历就是，可以吃到一些回到纽约之后几个月都吃不到的食物。 看着眼前的西红柿，我很高兴，尤其是当我发现Brown’s Grove农场是Jack Dusty 的供应商之一时我更加开心了。Jack Dusty是在萨拉索塔丽嘉登酒店新开的一家餐厅。我也真是幸运，本来那晚我就打算去那里吃饭的。到了那儿我甚至可以不看菜单，就知道直接点和西红柿有关的菜就可以了。 C
绝密★启用前 2019年普通高等学校招生全国统一考试(全国卷I) 英语 注意事项： 1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。 2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。如需改动，用橡皮擦干净后，再选涂其他答案标号。回答非选择题时，将答案写在答题卡上，写在本试卷上无效。 3.考试结束后，将本试卷和答题卡一并交回。 第一部分听力(共两节，满分30分) 做题时，先将答案标在试卷上。录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。 第一节 (共5小题;每小题1.5分，满分7.5分) 听下面5段对话。每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。
例：How much is the shirt? A. ￡19.15. B. B. ￡9.18. C. C. ￡9.15. 答案是C。 1.Where does this conversation take place? A. In a classroom. B. In a hospital. C.In a museum. 2.What does Jack want to do? A. Take fitness classes. B. Buy a pair of gym shoes. C. Change his work schedule. 3.What are the speakers talking about? A. What to drink.
全国卷高考英语真题 Standardization of sany group #QS8QHH-HHGX8Q8-GNHHJ8-HHMHGN#
绝密★启用前 2017年普通高等学校招生全国统一考试 英语 本试卷共150分，共14页。考试结束后，将本试卷和答题卡一并交回。注意事项： 1.答题前，考生先将自己的姓名、准考证号码填写清楚，将条形码准确粘贴在条形码区域内。 2.选择题必须使用2B铅笔填涂；非选择题必须使用毫米黑字迹的签 字笔书写，字体工整，笔迹清楚。 3.请按照题号顺序在各题目的答题区域内作答，超出答题区域书写的答案无效；在草稿纸、试题卷上答题无效。 4.作图可先用铅笔画出，确定后必须用黑色字迹的签字笔描黑。 5.保持卡面清洁，不要折叠、不要弄破、弄皱，不准使用涂改液、修正带、刮纸刀。 第一部分听力（共两节，满分30分）
做题时，先将答案标在试卷上，录音结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。 第一节（共5小题，每小题分，满分分） 听下面5段对话，每段对话后有一个小题，从题中所给的A、B、C 三个选项中选出最佳答案。听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 例：How much is the shirt A．￡B．￡C．￡ 答案是C。 1．What will the woman do this afternoon A．Do some exercise. B．Go shopping. C． Wash her clothes. 2．Why does the woman call the man A ．To cancel a flight. B． To make an apology. C． To put off a meeting. 3．How much more does David need for the car A．$ 5,000. B．$20,000. C．$25,000.
2019届高考英语三轮复习完形与阅读强化训练21 一、完形填空（本大题共1小题，共30分） 1.The battle was followed by a terrible storm. Therefore, it wasn’t until October 26 that Vice. Admiral(海军中将)Collingwood was 36 to send off his report to Britain 37 the victory and Nelson’s death. He chose 38 the task one of the smallest ships in his flect. Pickle, 39 by Captain Lapenotiere. In spite of 40 winds and rough seas. Pickle made the 41 of more than 1, 000 miles in just over eight days, 42 Falmouth on the morning of November 4. From there. Captain Lapenotiere 43 a fast post chaise(轻便马车)to London, traveling 44 for 37 hours. He reached the Admiralty in Whitehall at 1 a. m. on Wednesday, November 6-less than 11 days after he had 45 Colingwood. Most of the officials had gone to bed 46 , but the secretary was still 47 in the famous Board Room. Lapenotiete hurried in and 48 the report whit the simple words; “Sir, we have gained a great victory. But we have 49 Lord Nelson.” Copies of the report were quickly made and 50 to the prime Minister and King Ceorge 111. A special edition of a 51 was rushed out and delivered all over the country. The atmosphere of public 52 for the victory was weakened by widespread sorrow the 53 of Nelson. As one poet later wrote; “The victory of Trafalgar was 54 ,indeed, with the usual forms of rejoicing(欢庆)， 55 they were without joy.” 36.A.eager B. anxious C. able D. sure 37.A.announcing B. telling C. mentioning D. warning 38.A.with B. from C. for D. among 39.A.seated B. brought C. owned D. led 40.A.stong B. weak C. warm D. light 41.A.distance B. flight C. voyage D. march 42.A.leaving for B. arriving at C. staying in D. sailing for 43.A.made B. took C. kept D. sat 44.A.freely B. aimlessly C. slowly D. continuously 45.A. seen B. found C. told D. left 46.A.long before B. long ago C. before long D. long after 47.A.on leave B. on business C. at work D. at sea 48.A.took over B. handed over C. gave out D. turned out 49.A.defeated B. beaten C. missed D. lost 50.A.sent B. carried C. suggested D. written 51.A.book B. newspaper C. weekly D. magazine 52.A.hope B. search C. desire D. happiness
2011年全国卷I 阅读 A Pet owners are being encouraged to take their animals to work, a move scientists say can be good for productivity, workplace morale (士气), and the well-being of animals. A study found that 25% of Australian women would like to keep an office pet. Sue Chaseling of Petcare Information Service said the practice of keeping office pets was good both for the people and the pets. “On the pets’ side, they are not left on their own and won’t feel lonely and unhappy,” she said. A study of major US companies showed that 73% found office pets beneficial, while 27% experienced a drop in absenteeism (缺勤). Xarni Riggs has two cats walking around her Global Hair Salon in Paddington. “My customers love them. T hey are their favorites,” she said. “They are not troublesome. They know when to go and have a sleep in the sun.” Little black BJ has spent nearly a ll his two years “working” at Punch Gallery in Balmain. Owner Iain Powell said he had had cats at the gallery for 15 years. “BJ often lies in the shop window and people walking past tap on the glas s,” he said. Ms Chaseling said cats were popular in service industries because they enabled a point of conversation. But she said owners had to make sure both their co-workers and the cats were comfortable. 56. The percentage of American companies that are in favor of keeping office pets is ______. A. 73% B. 27% C. 25% D. 15% 57. We know from the text that “BJ” ______. A. works in the Global Hair Salon B. often greets the passers-by C. likes to sleep in the sun D. is a two-year-old cat 58. The best title for this text would be ______. A. Pets Help Attract Customers B. Your Favorite Office Pets C. Pets Join the Workforce D. Busy Life for Pets B MONTREAL (Reuters) --- Crossing the US-Canada border to go to church on a Sunday cost a US citizen ＄10,000 for breaking Washington’s strict new security rules. The expensive trip to church was a surprise for Richard Albert, who lives right on the Canadian border. Like the other half-dozen people of Township 15, crossing the border is a daily occurrence for Albert. The nearby Quebec village of St. Pamphile is where they shop, eat and go to church. There are many such situations in these areas along the largely unguarded 5, 530-mile border between Canada and the US- which in some cases actually runs down the middle of streets or through buildings. As a result, Albert says he did not expect any problems three weeks ago when he returned home to the US after attending church in Canada, as usual. The US customs station in this area is closed on Sundays, so he just drove around the locked gate, as he had done every weekend since the gate appeared last May, following a tightening of border security. Two days later, Albert was told to go to the customs office, where an officer told him he had been caught on camera crossing the border illegally. Ottawa has given out special passes to some 300 US citizens in that area so they can enter the country when Canadian customs stations are closed, but the US stopped a similar program last May. That forces the people to a 200-mile detour along hill roads to get home country through another border checkpoint. Albert has requested that the customs office change their decisions on the fine, but he has not attended a Sunday church since. “I feel like I’m living in a prison,” he said. 59. We learn from the text that Richard Albert is ______. A. an American living in Township 15 B. a Canadian living in a Quebec village
高考英语完形填空、阅读理解精练各三篇（附详细解析）纵观近几年高考完形填空题，我们不难发现：1、语境选择项增多；2、选项设计一 般为同一词类，或属同一范畴；3、难选之处前后多有暗示；4、选材多为具有一定故事情节的记叙文或以叙为主的议论文。 根据高考试题的特点和命题的发展趋势，在复习备考中，对记叙文、以叙为主的议 论文及某些具有一定哲理和教育意义的纯议论性短文都要加强练习。笔者精选三篇不同体裁的典型文章进行供同学们练习，并附详细解析，希望能帮助同学们在这一题型上积累经验，有所突破。 （ A ） In 1989 an 8.2 earthquake almost flattened America, killing over 30,000 people in less than four minutes. In the middle of complete damage and disorder, a father rushed to the school where his son was supposed to be, ___1__ that the building was ___2___. After the unforgettably shock, he ___3___ the promise he had made to his son: "No matter ___4___, I'll always be there for you!" And tears began to ___5___ his eyes. As he looked at the pile of ruins, it looked hopeless, but he kept remembering his ___6___ to his son. He rushed there and started ___7___ the ruins. As he was digging, other helpless parents arrived, ___8___: "It's too late! They're all dead! ___9___, face reality, there's nothing you can do!" To each parent he responded with ___10___: "Are you going to help me now?" No one helped. And then he continued to dig for his son, stone by stone. Courageously he went on alone because he needed to know ___11___: "Is my boy ___12____ or is he dead?" He dug for eight hours...12 hours...24 hours...36 hours...then, in ___13____ hour, he pulled back a large stone and heard his son's __14____. He screamed his son's name, "ARMAND!" He heard back, "Dad!?! It's me, Dad! I told the other kids not to worry. I told them that if you were alive, you __15____ me and __16____ you saved me, they'd be saved. You promised, 'No matter what happens, I'll always be there for you!' You did it, Dad!" "What's going on in there? " the father asked. "There are 14 of us __17____ __18____ 33, Dad. We're scared, hungry, thirsty and thankful you're here. When the building collapsed, it made __19____, and it saved us." "Come out, boy!" "No, Dad! Let the other kids out first, __20____ I know you'll get me! No matter what happens, I know you'll always be there for me!" 1. A. only discovering B. only to discover C. only realizing D. only to realize 2. A. as flat as a pancake B. as high as a mountain C. as strong as an ox D. as weak as a kitten 3. A. memorized B. forgot C. kept D. remembered 4. A. what B. what happen C. which D. who 5. A. fill B. fill in C. come D. burst 6. A. picture B. promise C. present D. encourage 7. A. digging B. digging through C. digging out D. digging into 8. A. to say B. said C. and saying D. saying 9. A. Come out B. Come again C. Come on D. Come off 10. A. one word B. one sound C. one row D. one line 11. A. for himself B. of himself C. by himself D. to himself 12. A. live B. living C. alive D. lively
绝密★启用前 2015年普通高等学校招生全国统一考试新课标1 英语 注意事项： 1. 本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。第Ⅰ卷1页至10页，第Ⅱ卷11页至13页。 2. 答题前，考生务必将自己的姓名，准考证号填写在本试卷相应的位置。 3. 全部答案在答题卡上完成，搭载本试卷上无效。 4. 第Ⅰ卷听力部分满分30分，不计入总分，考试成绩录取时提供给高校作参考。 5. 考试结束后，将本试卷和答题卡一并交回。 第Ⅰ卷 第一部分听力（共两节，满分30分）略 做题时，现将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。 第一节（共5小题；每小题1.5分，满分7.5分）（略） 听下面5段对话，每段对话后有一个小题。从题中所给的A,B,C三个选项中选出最佳选项，并标在试卷的相应位置。听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。 例：How much is the shirt? A.￡ 19.15 B.￡ 9.18 C.￡ 9.15 答案是C。 第二部分阅读理解（共两节，满分60分） 第一节（共15小题；每小题3分，满分45分） 阅读下列短文，从每题所给的四个选项（A、B、C、和D）中，选出最佳选项，并在答题卡上将该项涂黑。 A Monthly Talks at London Canal Museum Our monthly talks start at 19:30 on the first Thursday of each month except August. Admission is at normal charges and you don’t need to book. They end around 21:00. November 7th
绝密★启用前 2010年普通高等学校招生全国统一考试 英语 本试卷分第一卷（选择题）和第二卷（非选择题）两部分。第一卷1至14页。第二卷15至16页。考试结束后，将本试卷和答题卡一并交回。 第一卷 注意事项： 1. 答题前?考生在答题卡上务必用直径0 ? 5毫米黑色墨水签字笔将自己的姓名、准 考证号填写清楚，并贴好条形码。请认真核准条形码上的准考证号、姓名和科目。 2. 每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑，如需改动， 用橡皮擦干净后，再选涂其他答案标号，在试题卷上作答无效。 第一部分听力（共两节，满分30分） 做题时，先将答案标在试卷上。录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。 第一节（共5小题；每小题I 5分，满分7. 5分） 听下面5段对话。每段对话后有一个小题，从题中所给的A、B、C三个选项中选出 最佳选项，并标在试卷的相应位置。听完每段对话后，你都有I0秒钟的时间来回答有关 小题和阅读下一小题。每段对话仅读一遍。 例: How much is the shirt? A￡ 19.15 8 ￡ 9.15 C￡ 9.18 答案是B。 1 What will Dorothy do on the weekend? A Go out with her friend B Work on her paper C Make some pla ns 2. What was the no rmal price of the T-shirt? A. $15 B. $30. C. $50.
3 What has the woma n decided to do On Sun day after noon? A To atte nd a weddi ng B To visit an exhibiti on C To meet a friend 4 When does the bank close on Sa turday? A At l: 00 pm B At 3: 00 pm C At 4: 00 pm 5 Where are the speakers? A In a store B In a classroom C At a hotel 第二节（共15小题;每小题1 5分，满分22 .5分） 听下面5段对话或独白。每段对话或独白后有几个小题，从题中所给的A、B、C三 个选项中选出最佳选项，并标在试卷的相应位置。听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题给出5秒钟的作答时间。每段对话或独白读两遍。 听第6段材料，回答第6、7题。 6 What do we know about Nora? A She prefers a room of her own B She likes to work with other girls C She lives near the city center. 7 .What is good about the flat? A It has a large sitting room B It has good furniture C It has a big kitchen 听第7段材料，回答第& 9题。 8 Where has Barbara bee n? A Mila n
2018高考英语全国二卷真题 考 第二部分阅读理解(共两节，满分40分) A Summer Activities Students should read the list with their parents/carers, and select two activities they would like to do. Forms will be available in school and online for them to indicate their choices and return to school. Before choices are finalized, parents/ carer s will be asked to sign to confirm their child’s choices. 21. Which activity will you choose if you want to go camping? A. OUT. B. WBP. C. CRF. D. POT. 22. What will the students do on Tuesday with Mrs. Wilson? A. Travel to London. B. See a parade and fireworks. C. Tour central Paris. D. Visit the WWI battlefields.
23. How long does Potty about Potter last? A. Two days. B. Four days. C. Five days. D. One week. B Many of us love July because it’s the month when nature’s berries and stone fruits are in abundance. These colourful and sweet jewels form British Columbia’s fields are little powerhouses of nutritional protection. Of the common berries, strawberries are highest in vitamin C, although, because of their seeds, raspberries contain a little more protein (蛋白质), iron and zinc (not that fruits have much protein). Blueberries are particularly high in antioxidants (抗氧化物质). The yellow and orange stone fruits such as peaches are high in the carotenoids we turn into vitamin A and which are antioxidants. As for cherries (樱桃), they are so delicious who cares? However, they are rich in vitamin C. When combined with berries of slices of other fruits, frozen bananas make an excellent base for thick, cooling fruit shakes and low fat “ice cream”. For this purpose, select ripe bananas for freezing as they are much sweeter. Remove the skin and place them in plastic bags or containers and freeze. If you like, a squeeze of fresh lemon juice on the bananas will prevent them turning brown. Frozen bananas will last several weeks, depending on their ripeness and the temperature of the freezer. If you have a juicer, you can simply feed in frozen bananas and some berries or sliced fruit. Out comes a “soft-serve” creamy dessert, to be eaten right away. This makes a fun activity for a children’s party; they love feeding the fruit and frozen bananas into the top of the machine and watching the ice cream come out below. 24. What does the author seem to like about cherries? A. They contain protein. B. They are high in vitamin A. C. They have a pleasant taste. D. They are rich in antioxidants. 25. Why is fresh lemon juice used in freezing bananas? A. To make them smell better. B. To keep their colour. C. To speed up their ripening. D. To improve their nutrition. 26. What is “a juicer” in the last paragraph? A. A dessert. B. A drink. C. A container. D. A machine. 27. From which is the text probably taken? A. A biology textbook. B. A health magazine. C. A research paper. D. A travel brochure. C Teens and younger children are reading a lot less for fun, according to a Common Sense Media report published Monday. While the decline over the past decade is steep for teen readers, some data in the report shows that reading remains a big part of many children’s lives, and indicates how parents might help encourage more reading. According to the report’s key findings, “the proportion (比例) who say they ‘hardly ever’ read for fun has gone from 8 percent of 13-year-olds and 9 percent of 17-year-olds in 1984 to 22 percent and 27 percent respectively today.” The report data shows that pleasure reading levels for younger children, ages 2—8, remain largely the same.