FORTRAN习题答案
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第四章1.program main implicit none write(*,*) "Have a good time." write(*,*) "That's not bad." write(*,*) '"Mary" isn''t my name.' end program2.program main real, parameter :: PI=3 implicit none.14159 real radius write(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积='f8. 3)") radius*radius*PI end program3.program main implicit none real grades write(*,*) "请输入成绩" read(*,*) grades write(*,"(' 调整后成绩为'f8.3)") SQRT(grades)*10.0 end program4.integer a,b real ra,rb a=2 b=3 ra=2.0 rb=3.0 write(*,*) b/a ! 输出1, 因为使用整数计算, 小数部分会无条件舍去write(*,*) rb/ra ! 输出1.55.p rogram main implicit none type distance real meter, inch, cm end type type(distance) :: d write(*,*) "请输入长度:" read(*,*) d%meter d%cm = d%meter*100 d%inch = d%cm/2.54 write(*,"(f8.3'米='f8.3'厘米='f8.3'英寸')") d%meter, d%cm, d%inch end program第五章1.program main implicit none integer money real tax write(*,*) "请输入月收入" read(*,*) money if ( money<1000 ) then tax = 0.03 else if ( money<5000) then tax = 0.1 else tax = 0.15 end if write(*,"(' 税金为'I8)") nint(money*tax) end program2.program main implicit none integer day character(len=20) :: tv write(*,*) "请输入星期几" read(*,*) day select case(day) case(1,4) tv = "新闻" case(2,5) tv = "电视剧" case(3,6) tv = "卡通" case(7) tv = "电影" case default write(*,*) "错误的输入" stop end select write(*,*) tv end program3.program main implicit none integer age, money real tax write(*,*) "请输入年龄" read(*,*) age write(*,*) "请输入月收入" read(*,*) money if ( age<50 ) then if ( money<1000 ) then tax = 0.03 else if ( money<5000 )then tax = 0.10 else tax = 0.15 end if else if ( money<1000 ) then tax = 0.5 else if ( money<5000 )then tax = 0.7 else tax = 0.10 end if end if write(*,"(' 税金为'I8)") nint(money*tax) end program4.program main implicit none integer year, days logical mod_4, mod_100, mod_400 write(*,*) "请输入年份" read(*,*) year mod_4 = ( MOD(year,4) == 0 ) mod_100 = ( MOD(year,100) == 0 ) mod_400 = ( MOD(year,400) == 0 ) if ( (mod_4 .NEQV. mod_100) .or. mod_400 ) then days = 366 else days = 365 end if write(*,"('这一年有'I3'天')") days stop end program第六章1.program main implicit none integer i do i=1,5 write(*,*) "Fortran" end do stop end program2.program main implicit none integer i,sum sum = 0 do i=1,99,2 sum = sum+i end do write(*,*) sum stop end program3.program main implicit none integer, parameter :: answer = 45 integer, parameter :: max = 5 integer weight, i do i=1,max write(*,*) "请输入体重" read(*,*) weight if ( weight==answer ) exit end do if ( i<=max ) then write(*,*) "猜对了" else write(*,*) "猜错了" end if stop end program4.program main implicit none integer, parameter :: max=10 integer i real item real ans ans = 1.0 item = 1.0 do i=2,max item = item/real(i) ans = ans+itemend do write(*,*) ans stop end program5.program main implicit none integer, parameter :: length = 79 character(len=length) :: input, output integer i,j write(*,*) "请输入一个字串" read(*,"(A79)") input j=1 do i=1, len_trim(input) if ( input(i:i) /= ' ' ) then output(j:j)=input(i:i) j=j+1 end if end do write(*,"(A79)") output stop end program第七章1.program main implicit none integer, parameter :: max = 10 integer i integer :: a(max) = (/ (2*i, i=1,10) /) integer :: t ! sum()是fortran库函数write(*,*) real(sum(a))/real(max) stop end program2.integer a(5,5) ! 5*5=25 integer b(2,3,4) ! 2*3*4=24 integer c(3,4,5,6) ! 3*4*5*6=360 integer d(-5:5) ! 11 integer e(-3:3, -3:3) ! 7*7=493.program main implicit none integer, parameter :: max=10 integer f(max) integer i f(1)=0 f(2)=1 do i=3,max f(i)=f(i-1)+f(i-2) end do write(*,"(10I4)") f stop end program4.program main implicit none integer, parameter :: size=10 integer :: a(size) = (/ 5,3,6,4,8,7,1,9,2,10 /) integer :: i,j integer :: t do i=1, size-1 do j=i+1, size if ( a(i) < a(j) ) then ! a(i)跟a(j)交换t=a(i) a(i)=a(j) a(j)=t end if end do end do write(*,"(10I4)") a stop end5.a(2,2) ! 1+(2-1)+(2-1)*(5) = 7 a(3,3) ! 1+(3-1)+(3-1)*(5) = 13第八章1.program main implicit none real radius, area write(*,*) "请输入半径长" read(*,*) radius call CircleArea(radius, area) write(*,"(' 面积= 'F8.3)") area stop end program subroutine CircleArea(radius, area) implicit none real, parameter :: PI=3.14159 real radius, area area = radius*radius*PI return end subroutine2.program main implicit none real radius real, external :: CircleArea write(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积= 'F8.3)") CircleArea(radius) stop end program real function CircleArea(radius) implicit none real, parameter :: PI=3.14159 real radius CircleArea = radius*radius*PI return end function3.program main implicit none call bar(3) call bar(10) stop end program subroutine bar(length) implicit none integer, intent(in) :: length integer i character(len=79) :: string string=" " do i=1,length string(i:i)='*' end do write(*,"(A79)") string return end subroutine4.p rogram main implicit none integer, external :: add write(*,*) add(100) end program recursive integer function add(n) result(sum) implicit none integer, intent(in) :: n if ( n<0 ) then sum=0 return else if ( n<=1 ) then sum=n return end if sum = n + add(n-1) return end function5.program main implicit none integer, external :: gcd write(*,*) gcd(18,12) end program integer function gcd(A,B) implicit none integer A,B,BIG,SMALL,TEMP BIG=max(A,B) SMALL=min(A,B) do while( SMALL /= 1 ) TEMP=mod(BIG,SMALL) if ( TEMP==0 ) exit BIG=SMALL SMALL=TEMP end do gcd=SMALL return end function6.program main use TextGraphLib implicit none integer, parameter :: maxx=60, maxy=20 real, parameter :: StartX=0.0, EndX=3.14159*2.0 real, parameter :: xinc = (EndX-StartX)/(maxx-1) real x integer i,px,py call SetScreen(60,20) call SetCurrentChar('*') x=StartX do px=1,maxx py = (maxy/2)*sin(x)+maxy/2+1 callPutChar(px,py) x=x+xinc end docall UpdateScreen() stop end program第九章1.program main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer count integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old") count = 0 do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) buffer if ( status/=0 ) exit ! 没有资料就跳出循环write(*,"(A79)") buffer count = count+1 if ( count==24 ) then pause count = 0 end if end do else write(*,*) TRIM(filename)," doesn't exist." end if stop end2.p rogram main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer i integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old") do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) buffer if ( status/=0 ) exit ! 没有资料就跳出循环do i=1, len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-3 ) end do write(*,"(A70)") buffer end do else write(*,*) TRIM(filename)," doesn't exist." end if stop end3.program main implicit none type student integer chinese, english, math, science, social, total end type type(student) :: s, total integer, parameter :: students=20, subjects=5 integer i open(10,file="grades.bin",access="direct",recl=1) write(*,"(7A10)") "座号","中文","英文","数学","自然","社会","总分" total = student(0,0,0,0,0,0) do i=1, students read(10,rec=(i-1)*subjects+1) s%chinese read(10,rec=(i-1)*subjects+2) s%english read(10,rec=(i-1)*subjects+3) s%math read(10,rec=(i-1)*subjects+4) s%science read(10,rec=(i-1)*subjects+5) s%social s%total = s%chinese+s%english+s%math+s%science+s%social total%chinese = total%chinese+s%chinese total%english = total%english+s%english total%math = total%math+s%math total%science = total%science+s%science total%social = total%social+s%social total%total = total%total+s%total write(*,"(7I10)") i, s end do write(*,"(A10,6F10.3)") "平均", & real(total%chinese)/real(students),& real(total%english)/real(students),& real(total%math)/real(students),& real(total%science)/real(students),& real(total%social)/real(students),& real(total%total)/real(students) stop end4.program main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer i integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old") do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) buffer if ( status/=0 ) exit ! 没有数据就跳出循环do i=1, len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-(mod(i-1,3)+1) ) end do write(*,"(A70)") buffer end do else write(*,*) TRIM(filename)," doesn't exist." end if stop end5.module typedef type student integer :: num integer :: Chinese, English, Math, Natural, Social integer :: total integer :: rank end type end module program main use typedef implicit none integer, parameter :: fileid=10 integer, parameter :: students=20 character(len=80) :: tempstr type(student) :: s(students) ! 储存学生成绩type(student) ::total ! 计算平均分数用integer i, num, error open(fileid, file="grades.txt",status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open grades.txt fail." stop end if read(fileid, "(A80)") tempstr ! 读入第一行文字total=student(0,0,0,0,0,0,0,0) ! 用循环读入每位学生的成绩do i=1,students read(fileid,*) s(i)%num, s(i)%Chinese, s(i)%English, & s(i)%Math, s(i)%Natural, s(i)%Social ! 计算总分s(i)%Total = s(i)%Chinese + s(i)%English + & s(i)%Math + s(i)%Natural + s(i)%Social ! 累加上各科的分数, 计算各科平均时使用total%Chinese = total%Chinese + s(i)%Chinese total%English = total%English + s(i)%English total%Math = total%Math + s(i)%Math total%Natural = total%Natural + s(i)%Natural total%Social = total%Social + s(i)%Social total%Total = total%Total + s(i)%Total end do call sort(s,students) ! 重新输出每位学生成绩write(*,"(8A7)") "座号","中文","英文","数学","自然","社会","总分","名次" do i=1,students write(*,"(8I7)") s(i) end do ! 计算并输出平圴分数write(*,"(A7,6F7.1)") "平均", & real(total%Chinese)/real(students),& real(total%English)/real(students),& real(total%Math) /real(students),& real(total%Natural)/real(students),& real(total%Social) /real(students),& real(total%Total) /real(students) stop end program subroutine sort(s,n) use typedef implicit none integer n type(student) :: s(n), t integer i,j do i=1,n-1 do j=i+1,n if ( s(i)%total < s(j)%total ) then t = s(i) s(i)=s(j) s(j) = t end if end do end do forall(i=1:n) s(i)%rank = i end forall end subroutine第十章1.integer(kind=4) :: a ! 4 bytes real(kind=4) :: b ! 4 bytes real(kind=8) :: c ! 8 bytes character(len=10) :: str ! 10 bytes integer(kind=4), pointer :: pa ! 4 bytes real(kind=4), pointer :: pb ! 4 bytes real(kind=8), pointer :: pc ! 4 bytes character(len=10), pointer :: pstr ! 4 bytes type student integer Chinese, English, Math end type type(student) :: s ! 12 bytes type(student), pointer :: ps ! 4 bytes2.integer, target :: a = 1 integer, target :: b = 2 integer, target :: c = 3 integer, pointer :: p p=>a write(*,*) p ! 1 p=>b write(*,*) p ! 2 p=>c p=5 write(*,*) c ! 53.module linklist type student integer :: num integer :: Chinese, English, Math, Science, Social end type type datalink type(student) :: item type(datalink), pointer :: next end type contains function SearchList(num, head) implicit none integer :: num type(datalink), pointer :: head, p type(datalink), pointer :: SearchList p=>head nullify(SearchList) do while( associated(p) ) if ( p%item%num==num ) then SearchList => p return end if p=>p%next end do return end function end module linklist program ex1016 use linklist implicit none character(len=20) :: filename character(len=80) :: tempstr type(datalink), pointer :: head type(datalink), pointer :: p type(student), allocatable :: s(:) integer i,error,size write(*,*) "filename:" read(*,*) filename open(10, file=filename, status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open file fail!" stop end if allocate(head) nullify(head%next) p=>head size=0 read(10, "(A80)") tempstr ! 读入第一行字符串, 不需要处理它! 读入每一位学生的成绩do while(.true.) read(10,fmt=*, iostat=error) p%item if ( error/=0 ) exit size=size+1 allocate(p%next, stat=error) ! 新增下一个数据if ( error/=0 ) then write(*,*) "Out of memory!" stop end if p=>p%next ! 移动到链表的下一个数据nullify(p%next) end do write(*,"('总共有',I3,'位学生')") size allocate( s(size) ) p=>head do i=1,size s(i)=p%item p=>p%next end do do while(.true.)write(*,*) "要查询几号同学的成绩?" read (*,*) i if ( i<1 .or. i>size ) exit ! 输入不合理的座号write(*,"(5(A6,I3))") "中文",s(i)%Chinese,& "英文",s(i)%English,& "数学",s(i)%Math,& "自然",s(i)%Science,& "社会",s(i)%Social end do write(*,"('座号',I3,'不存在, 程序结束.')") i stop end program4.module typedef implicit none type :: datalink integer :: i type(datalink), pointer :: next end type datalink end module typedef program ex1012 use typedef implicit none type(datalink) , pointer :: p, head, next integer :: i,n,err write(*,*) 'Input N:' read(*,*) n allocate( head ) head%i=1 nullify(head%next) p=>head do i=2,n allocate( p%next, stat=err ) if ( err /= 0 ) then write(*,*) 'Out of memory!' stop end if p=>p%next p%i=i end do nullify(p%next) p=>head do while(associated(p)) write(*, "(i5)" ) p%i p=>p%next end do ! 释放链表的存储空间p=>head do while(associated(p)) next => p%next deallocate(p) p=>next end do stop end program第十一章1.module utility implicit none interface area module procedure CircleArea module procedure RectArea end interface contains real function CircleArea(r) real, parameter :: PI=3.14159 real r CircleArea = r*r*PI return end function real function RectArea(a,b) real a,b RectArea = a*b return end function end module program main use UTILITY implicit none write(*,*) area(1.0) write(*,*) area(2.0,3.0) stop end program2.module time_utility implicit none type :: time integer :: hour,minute,second end type time interface operator(+) module procedure add_time_time end interface contains function add_time_time( a, b ) implicit none type(time) :: add_time_time type(time), intent(in) :: a,b integer :: seconds,minutes,carry seconds=a%second+b%second carry=seconds/60 minutes=a%minute+b%minute+carry carry=minutes/60 add_time_time%second=mod(seconds,60) add_time_time%minute=mod(minutes,60) add_time_time%hour=a%hour+b%hour+carry return end function add_time_time subroutine input( a ) implicit none type(time), intent(out) :: a write(*,*) " Input hours:" read (*,*) a%hour write(*,*) " Input minutes:" read (*,*) a%minute write(*,*) " Input seconds:" read (*,*) a%second return end subroutine input subroutine output( a ) implicit none type(time), intent(in) :: a write(*, "(I3,' hours',I3,' minutes',I3,' seconds')" ) a%hour,a%minute,a%second return end subroutine output end module time_utility program main use time_utility implicit none type(time) :: a,b,c call input(a) call input(b) c=a+b call output(c) stop end program main3.module rational_utility implicit none private public :: rational, & operator(+), operator(-), operator(*),& operator(/), assignment(=),operator(>),& operator(<), operator(==), operator(/=),& output, input type :: rational integer :: num, denom end type rational interface operator(+) module procedure rat__rat_plus_rat end interface interface operator(-) module procedure rat__rat_minus_rat end interface interface operator(*) module procedure rat__rat_times_rat end interface interface operator(/) module procedurerat__rat_div_rat end interface interface assignment(=) module procedure rat_eq_rat module procedure int_eq_rat module procedure real_eq_rat end interface interface operator(>) module procedure rat_gt_rat end interface interface operator(<) module procedure rat_lt_rat end interface interface operator(==) module procedure rat_compare_rat end interface interface operator(/=) module procedure rat_ne_rat end interface contains function rat_gt_rat(a,b) implicit none logical :: rat_gt_rat type(rational), intent(in) :: a,b real :: fa,fb fa=real(a%num)/real(a%denom) fb=real(b%num)/real(b%denom) if ( fa > fb ) then rat_gt_rat=.true. else rat_gt_rat=.false. end if return end function rat_gt_rat function rat_lt_rat(a,b) implicit none logical :: rat_lt_rat type(rational), intent(in) :: a,b real :: fa,fb fa=real(a%num)/real(a%denom) fb=real(b%num)/real(b%denom) if ( fb > fa ) then rat_lt_rat=.true. else rat_lt_rat=.false. end if return end function rat_lt_rat function rat_compare_rat(a,b) implicit none logical :: rat_compare_rat type(rational), intent(in) :: a,b type(rational) :: c c=a-b if ( c%num == 0 ) then rat_compare_rat=.true. else rat_compare_rat=.false. end if return end function rat_compare_rat function rat_ne_rat(a,b) implicit none logical :: rat_ne_rat type(rational), intent(in) :: a,b type(rational) :: c c=a-b if ( c%num==0 ) then rat_ne_rat=.false. else rat_ne_rat=.true. end if return end function rat_ne_rat subroutine rat_eq_rat( rat1, rat2 ) implicit none type(rational), intent(out):: rat1 type(rational), intent(in) :: rat2 rat1%num = rat2%num rat1%denom = rat2%denom return end subroutine rat_eq_rat subroutine int_eq_rat( int, rat ) implicit none integer, intent(out):: int type(rational), intent(in) :: rat int = rat%num / rat%denom return end subroutine int_eq_rat subroutine real_eq_rat( float, rat ) implicit none real, intent(out) :: float type(rational), intent(in) :: rat float = real(rat%num) / real(rat%denom) return end subroutine real_eq_rat function reduse( a ) implicit none type(rational), intent(in) :: a integer :: b type(rational) :: reduse b=gcv_interface(a%num,a%denom) reduse%num = a%num/b reduse%denom = a%denom/b return end function reduse function gcv_interface(a,b) implicit none integer, intent(in) :: a,b integer :: gcv_interface if ( min(a,b) .eq. 0 ) then gcv_interface=1 return end if if (a==b) then gcv_interface=a return else if ( a>b ) then gcv_interface=gcv(a,b) else if ( a<b ) then gcv_interface=gcv(b,a) end if return end function gcv_interface recursive function gcv(a,b) result(ans) implicit none integer, intent(in) :: a,b integer :: m integer :: ans m=mod(a,b) select case(m) case(0) ans=b return case(1) ans=1 return case default ans=gcv(b,m) end select return end function gcv function rat__rat_plus_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_plus_rat type(rational), intent(in) :: rat1,rat2 type(rational) :: act act%denom= rat1%denom * rat2%denom act%num = rat1%num*rat2%denom + rat2%num*rat1%denom rat__rat_plus_rat = reduse(act) return end function rat__rat_plus_rat function rat__rat_minus_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_minus_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom*rat2%denom temp%num =rat1%num*rat2%denom -rat2%num*rat1%denom rat__rat_minus_rat = reduse( temp ) return end function rat__rat_minus_rat function rat__rat_times_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_times_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom* rat2%denom temp%num = rat1%num * rat2%num rat__rat_times_rat = reduse(temp) return end function rat__rat_times_rat function rat__rat_div_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_div_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom* rat2%num temp%num = rat1%num * rat2%denom rat__rat_div_rat = reduse(temp) return end function rat__rat_div_rat subroutine input(a) implicit none type(rational), intent(out) :: a write(*,*) "分子:" read(*,*) a%num write(*,*) "分母:" read(*,*) a%denom return end subroutine input subroutine output(a) implicit none type(rational), intent(in) :: a if ( a%denom/=1 ) then write(*, "(' (',I3,'/',I3,')' )" ) a%num,a%denom else write(*, "(I3)" ) a%num end if return end subroutine output end module rational_utility program main use rational_utility implicit none type(rational) :: a,b,c call input(a) call input(b) c=a+b write(*,*) "a+b=" call output(c) c=a-b write(*,*) "a-b=" call output(c) c=a*b write(*,*) "a*b=" call output(c) c=a/b write(*,*) "a/b=" call output(c) if (a>b) write(*,*) "a>b" if (a<b) write(*,*) "a<b" if (a==b) write(*,*) "a==b" if (a/=b) write(*,*) "a/=b" stop end program main4.module vector_utility implicit none type vector real x,y end type interface operator(+) module procedure vector_add_vector end interface interface operator(-) module procedure vector_sub_vector end interface interface operator(*) module procedure real_mul_vector module procedure vector_mul_real module procedure vector_dot_vector end interface interface operator(.dot.) module procedure vector_dot_vector end interface contains type(vector) function vector_add_vector(a,b) type(vector), intent(in) :: a,b vector_add_vector = vector(a%x+b%x, a%y+b%y) end function type(vector) function vector_sub_vector(a,b) type(vector), intent(in) :: a,b vector_sub_vector = vector(a%x-b%x, a%y-b%y) end function type(vector) function real_mul_vector(a,b) real, intent(in) :: a type(vector), intent(in) :: b real_mul_vector = vector( a*b%x, a*b%y ) end functiontype(vector) function vector_mul_real(a,b) type(vector), intent(in) :: a real, intent(in) :: b vector_mul_real = real_mul_vector(b,a) end function real function vector_dot_vector(a,b) type(vector), intent(in) :: a,b vector_dot_vector = a%x*b%x + a%y*b%y end function subroutine output(vec) type(vector) :: vec write(*,"('('F6.2','F6.2')')") vec end subroutine end module program main use vector_utility implicit none type(vector) a,b,c a=vector(1.0, 2.0) b=vector(2.0, 1.0) c=a+b call output(c) c=a-b call output(c) write(*,*) a*b end program main。
FORTRAN习题答案习题⼆⼀、问答题1. 给出下⾯变量名称,哪些是合法变量?哪些是⾮法变量?说明原因。
Count 、num_2、x&y 、4x+5y 、china-suzhou 、$us 、AbCdE 、Mr.bai 、t5、_another 、school_class_25、#125、2002Y 、π、β、A01/02、alpha 、date(1) 1. 判定下⾯整数,指出哪些是合法整数,哪些是⾮法整数?说明原因。
-0、+ 215、$125、3,245,895、5.3245、5#384、-524_3、#5DFE 、23-345、16#1A2B 、38#ABCD 、8#275_2、+327890、4 #3212. 判定下⾯实数,指出哪些是合法实数,哪些是⾮法实数?说明原因。
-0E2、45.2345E3.5、-5489E25_8、-.2345E-35、$185.45E 、+ 2.753425E24_3、 58D85、+0.E-0、-00000.001E5、5,443,223.44、-12 34E+2、+ 18.5E 18、2.5E42习题三⼀、选择题1.下⾯是V isual Fortran 中正确的表达式是。
(A )A*COS(X)+∣B ∣(B )2*EXP(2*X)/SQRT(16.0)(C )B 2-4AC (D )MOD (24.5,0.5)2.下⾯算术赋值语句中正确的语句是。
(A )M*N=(X-Y)/Z (B )+R=A+B/C(C )X=Y=Z-1.0 (D )Y=A*B/C/D3.算术表达式1/3+2/3的值为。
(A )0 (B ) 1 (C ) 0.99999999 (D )值不确定⼆、问答题1. 将下列代数式⽤Visual Fortran 表达式描述:①②③ 4sin 3A-3sinA+sin3A ④ 2.执⾏下列赋值语句后,变量中的值。
变量的类型遵循I —N 规则。
Fortran95程序设计习题答案第四章 1.program main implicit none write(*,*) "Have a good time." write(*,*) "That's not bad." write(*,*) '"Mary" isn''t my name.' end program 2.program main real, parameter :: PI=3 implicit none.14159real radius write(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积='f8. 3)") radius*radius*PI end program 3.program main implicit none real grades write(*,*) "请输入成绩" read(*,*)grades write(*,"(' 调整后成绩为 'f8.3)") SQRT(grades)*10.0 end program 4.integer a,b real ra,rb a=2 b=3 ra=2.0 rb=3.0 write(*,*) b/a ! 输出1, 因为使用整数计算, 小数部分会无条件舍去 write(*,*) rb/ra ! 输出1.5 5.program main implicit none type distance real meter, inch, cm end type type(distance) :: d write(*,*) "请输入长度:" read(*,*) d%meter d%cm = d%meter*100 d%inch = d%cm/2.54 write(*,"(f8.3'米 ='f8.3'厘米='f8.3'英寸')") d%meter, d%cm, d%inch end program 第五章 1.program main implicit none integer money real tax write(*,*) "请输入月收入" read(*,*) money if ( money<1000 ) then tax = 0.03 else if ( money<5000) then tax = 0.1 else tax = 0.15 end if write(*,"(' 税金为 'I8)") nint(money*tax) end program 2.program main implicit none integer day character(len=20) :: tv write(*,*) "请输入星期几" read(*,*) day select case(day) case(1,4) tv = "新闻" case(2,5) tv = "电视剧" case(3,6) tv = "卡通" case(7) tv = "电影" case default write(*,*) "错误的输入" stop end select write(*,*) tv end program 3.program main implicit none integer age, money real tax write(*,*) "请输入年龄"write(*,*) "请输入月收入" read(*,*) money if ( age<50 ) thenread(*,*) ageif ( money<1000 ) then tax = 0.03 else if ( money<5000 )then tax = 0.10 else tax = 0.15 end if else if ( money<1000 ) then tax = 0.5 else if ( money<5000 )then tax = 0.7 else tax = 0.10 end if end ifwrite(*,"(' 税金为 'I8)") nint(money*tax) end program 4.program main implicit none integer year, days logical mod_4, mod_100, mod_400write(*,*) "请输入年份" read(*,*) year mod_4 = ( MOD(year,4) == 0 ) mod_100 = ( MOD(year,100) == 0 ) mod_400 = ( MOD(year,400) == 0 ) if ( (mod_4 .NEQV. mod_100) .or. mod_400 ) then days = 366 else days = 365 end if write(*,"('这一年有'I3'天')") days stop end program 第六章1.program main implicit none integer i do i=1,5 write(*,*) "Fortran" end do stop end program2.program main implicit none integer i,sum sum = 0 do i=1,99,2 sum = sum+i end do write(*,*) sum stop end program3.program main implicit none integer, parameter :: answer = 45 integer, parameter :: max = 5 integer weight, i do i=1,max write(*,*) "请输入体重" read(*,*) weight if ( weight==answer ) exit end do if ( i<=max ) then write(*,*) "猜对了" else write(*,*) "猜错了" end if stop end program4.program main implicit none integer, parameter :: max=10 integer i real item real ans ans = 1.0 item = 1.0 do i=2,max item = item/real(i) ans = ans+item end do write(*,*) ans stop end program5.program main implicit none integer, parameter :: length = 79 character(len=length) :: input, output integer i,j write(*,*) "请输入一个字串" read(*,"(A79)") input j=1 do i=1, len_trim(input) if( input(i:i) /= ' ' ) then output(j:j)=input(i:i) j=j+1 end if end do write(*,"(A79)") output stop end program 第七章 1.program mainimplicit none integer, parameter :: max = 10 integer i integer ::a(max) = (/ (2*i, i=1,10) /) integer :: t ! sum()是fortran库函数write(*,*) real(sum(a))/real(max) stop end program2.integer a(5,5) ! 5*5=25 integer b(2,3,4) ! 2*3*4=24 integerc(3,4,5,6) ! 3*4*5*6=360 integer d(-5:5) ! 11 integer e(-3:3, -3:3) ! 7*7=49 3.program main implicit none integer, parameter :: max=10integer f(max) integer i f(1)=0 f(2)=1 do i=3,max f(i)=f(i-1)+f(i-2) end do write(*,"(10I4)") f stop end program 4.program main implicit none integer, parameter :: size=10 integer :: a(size) = (/5,3,6,4,8,7,1,9,2,10 /) integer :: i,j integer :: t do i=1, size-1 do j=i+1, size if ( a(i) < a(j) ) then ! a(i)跟a(j)交换 t=a(i)a(i)=a(j) a(j)=t end if end do end do write(*,"(10I4)") a stop end5.a(2,2) ! 1+(2-1)+(2-1)*(5) = 7 a(3,3) ! 1+(3-1)+(3-1)*(5) = 13 第八章1.program main implicit none real radius, area write(*,*) "请输入半径长" read(*,*) radius call CircleArea(radius, area) write(*,"(' 面积 ='F8.3)") area stop end program subroutine CircleArea(radius, area) implicit none real, parameter :: PI=3.14159 real radius, area area = radius*radius*PI return end subroutine 2.program main implicit nonereal radius real, external :: CircleArea write(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积 = 'F8.3)") CircleArea(radius) stop end program real function CircleArea(radius) implicit none real, parameter :: PI=3.14159 real radius CircleArea = radius*radius*PI returnend function 3.program main implicit none call bar(3) call bar(10) stop end program subroutine bar(length) implicit none integer, intent(in) :: length integer i character(len=79) :: string string=" " do i=1,length string(i:i)='*' end do write(*,"(A79)") string return end subroutine 4.program main implicit none integer, external :: add write(*,*)add(100) end program recursive integer function add(n)integer, intent(in) :: n if ( n<0 ) then sum=0 return elseresult(sum) implicit noneif ( n<=1 ) then sum=n return end if sum = n + add(n-1) return end function 5.program main implicit none integer, external :: gcdwrite(*,*) gcd(18,12) end program integer function gcd(A,B) implicit none integer A,B,BIG,SMALL,TEMP BIG=max(A,B) SMALL=min(A,B) dowhile( SMALL /= 1 )TEMP=mod(BIG,SMALL) if ( TEMP==0 ) exit BIG=SMALL SMALL=TEMP enddo gcd=SMALL return end function 6.program main use TextGraphLib implicit none integer, parameter :: maxx=60, maxy=20 real, parameter :: StartX=0.0, EndX=3.14159*2.0 real, parameter :: xinc = (EndX-StartX)/(maxx-1) real x integer i,px,py call SetScreen(60,20) call SetCurrentChar('*') x=StartX do px=1,maxx py = (maxy/2)*sin(x)+maxy/2+1 call PutChar(px,py) x=x+xinc end docall UpdateScreen() stop end program 第九章 1.program main implicitnone character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer count integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filenameinquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old") count = 0 dowhile(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) bufferif ( status/=0 ) exit ! 没有资料就跳出循环 write(*,"(A79)") buffercount = count+1 if ( count==24 ) then pause count = 0 end if end do else write(*,*) TRIM(filename)," doesn't exist." end if stop end2.program main implicit none character(len=79) :: filenamecharacter(len=79) :: buffer integer, parameter :: fileid = 10 integer i integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential",status="old") do while(.true.) read(unit=fileid, fmt="(A79)",iostat=status ) buffer if ( status/=0 )exit ! 没有资料就跳出循环 do i=1, len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-3 ) end do write(*,"(A70)") buffer enddo else write(*,*) TRIM(filename)," doesn't exist." end if stop end3.program main implicit none type student integer chinese, english, math, science, social, total end type type(student) :: s, total integer, parameter :: students=20, subjects=5 integer iopen(10,file="grades.bin",access="direct",recl=1) write(*,"(7A10)") "座号","中文","英文","数学","自然","社会","总分" total =student(0,0,0,0,0,0) do i=1, students read(10,rec=(i-1)*subjects+1)s%chinese read(10,rec=(i-1)*subjects+2) s%english read(10,rec=(i-1)*subjects+3) s%math read(10,rec=(i-1)*subjects+4) s%scienceread(10,rec=(i-1)*subjects+5) s%social s%total =s%chinese+s%english+s%math+s%science+s%social total%chinese =total%chinese+s%chinese total%english = total%english+s%englishtotal%math = total%math+s%math total%science = total%science+s%science total%social = total%social+s%social total%total = total%total+s%total write(*,"(7I10)") i, s end do write(*,"(A10,6F10.3)") "平均", & real(total%chinese)/real(students),&real(total%english)/real(students),&real(total%math)/real(students),&real(total%science)/real(students),&real(total%social)/real(students),& real(total%total)/real(students) stop end 4.program main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer i integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) pen(unit=fileid, file=filename, & access="sequential", if ( alive ) then ostatus="old") do while(.true.) read(unit=fileid, fmt="(A79)",iostat=status ) buffer if ( status/=0 ) exit ! 没有数据就跳出循环 doi=1,len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-(mod(i-1,3)+1) ) end do write(*,"(A70)") buffer end do else write(*,*)TRIM(filename)," doesn't exist." end if stop end 5.module typedef typestudent integer :: num integer :: Chinese, English, Math, Natural, Social integer :: total integer :: rank end type end module program main use typedef implicit none integer, parameter :: fileid=10 integer, parameter :: students=20 character(len=80) :: tempstrtype(student) :: s(students) ! 储存学生成绩 type(student) :: total ! 计算平均分数用 integer i, num, error open(fileid,file="grades.txt",status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open grades.txt fail." stop end if read(fileid, "(A80)") tempstr ! 读入第一行文字 total=student(0,0,0,0,0,0,0,0) ! 用循环读入每位学生的成绩 do i=1,students read(fileid,*) s(i)%num, s(i)%Chinese,s(i)%English, & s(i)%Math, s(i)%Natural, s(i)%Social ! 计算总分s(i)%Total = s(i)%Chinese + s(i)%English + & s(i)%Math + s(i)%Natural + s(i)%Social ! 累加上各科的分数, 计算各科平均时使用 total%Chinese = total%Chinese +s(i)%Chinese total%English = total%English + s(i)%Englishtotal%Math = total%Math + s(i)%Math total%Natural = total%Natural +s(i)%Natural total%Social = total%Social + s(i)%Social total%Total = total%Total + s(i)%Total end do call sort(s,students) ! 重新输出每位学生成绩 write(*,"(8A7)") "座号","中文","英文","数学","自然","社会","总分","名次" do i=1,students write(*,"(8I7)") s(i) end do ! 计算并输出平圴分数 write(*,"(A7,6F7.1)") "平均", &real(total%Chinese)/real(students),&real(total%English)/real(students),&real(total%Math) /real(students),&real(total%Natural)/real(students),& real(total%Social)/real(students),& real(total%Total) /real(students) stop end program subroutine sort(s,n) use typedef implicit none integer ntype(student) :: s(n), t integer i,j do i=1,n-1 do j=i+1,n if( s(i)%total < s(j)%total ) then t = s(i) s(i)=s(j) s(j) = t end if end do end do forall(i=1:n) s(i)%rank = i end forall end subroutine 第十章 1.integer(kind=4) ::4 bytes real(kind=4) :: b ! 4 bytes real(kind=8) :: c ! 8 bytes character(len=10) :: a !str ! 10 bytes integer(kind=4), pointer :: pa ! 4 bytesreal(kind=4), pointer :: pb ! 4 bytes real(kind=8), pointer :: pc ! 4 bytes character(len=10), pointer :: pstr ! 4 bytes type studentinteger Chinese, English, Math end type type(student) :: s ! 12 bytes type(student), pointer :: ps ! 4 bytes 2.integer, target :: a = 1 integer, target :: b = 2 integer, target :: c = 3 integer, pointer :: p p=>a write(*,*) p ! 1 p=>b write(*,*) p ! 2 p=>c p=5 write(*,*) c ! 53.module linklist type student integer :: num integer :: Chinese, English, Math, Science, Social end type type datalink type(student) :: item type(datalink), pointer :: next end type contains function SearchList(num, head) implicit none integer :: num type(datalink), pointer :: head, p type(datalink), pointer :: SearchList p=>headnullify(SearchList) do while( associated(p) ) if ( p%item%num==num ) then SearchList => p return end if p=>p%next end do return end function end module linklist program ex1016 use linklist implicit nonecharacter(len=20) :: filename character(len=80) :: tempstrtype(datalink), pointer :: head type(datalink), pointer :: ptype(student), allocatable :: s(:) integer i,error,size write(*,*) "filename:" read(*,*) filename open(10, file=filename, status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open file fail!" stop end if allocate(head) nullify(head%next) p=>head size=0 read(10,"(A80)") tempstr ! 读入第一行字符串, 不需要处理它 ! 读入每一位学生的成绩do while(.true.) read(10,fmt=*, iostat=error) p%item if ( error/=0 )exit size=size+1 allocate(p%next, stat=error) ! 新增下一个数据 if( error/=0 ) then write(*,*) "Out of memory!" stop end if p=>p%next ! 移动到链表的下一个数据 nullify(p%next) end do write(*,"('总共有',I3,'位学生')") size allocate( s(size) ) p=>head do i=1,size s(i)=p%itemp=>p%next end do do while(.true.) write(*,*) "要查询几号同学的成绩?" read (*,*) i if ( i<1 .or. i>size ) exit ! 输入不合理的座号write(*,"(5(A6,I3))") "中文",s(i)%Chinese,& "英文",s(i)%English,& "数学",s(i)%Math,& "自然",s(i)%Science,& "社会",s(i)%Social end do write(*,"('座号',I3,'不存在, 程序结束.')") i stop end program 4.module typedef implicit none type :: datalink integer :: i type(datalink), pointer :: next end type datalink end module typedef program ex1012 use typedef implicit none type(datalink) , pointer :: p, head, nextinteger :: i,n,err write(*,*) 'Input N:' read(*,*) n allocate( head ) head%i=1 nullify(head%next) p=>head do i=2,n allocate( p%next,stat=err ) if ( err /= 0 ) then write(*,*) 'Out of memory!' stop endif p=>p%next p%i=i end do nullify(p%next) p=>head dowhile(associated(p)) write(*, "(i5)" ) p%i p=>p%next end do ! 释放链表的存储空间 p=>head do while(associated(p)) next => p%nextdeallocate(p) p=>next end do stop end program 第十一章 1.moduleutility implicit none interface area module procedure CircleArea module procedure RectArea end interface contains real function CircleArea(r) real, parameter :: PI=3.14159 real rCircleArea = r*r*PI return end function real function RectArea(a,b) real a,b RectArea = a*b return end function end module program main use UTILITY implicit none write(*,*) area(1.0) write(*,*) area(2.0,3.0)stop end program 2.module time_utility implicit none type :: timeinteger :: hour,minute,second end type time interface operator(+) module procedure add_time_time end interface contains functionadd_time_time( a, b ) implicit none type(time) :: add_time_timetype(time), intent(in) :: a,b integer :: seconds,minutes,carryseconds=a%second+b%second carry=seconds/60minutes=a%minute+b%minute+carry carry=minutes/60add_time_time%second=mod(seconds,60)add_time_time%minute=mod(minutes,60)add_time_time%hour=a%hour+b%hour+carry return end functionadd_time_time subroutine input( a ) implicit none type(time),intent(out) :: a write(*,*) " Input hours:" read (*,*) a%hourwrite(*,*) " Input minutes:" read (*,*) a%minute write(*,*) " Input seconds:" read (*,*) a%second return end subroutine input subroutine output( a ) implicit none type(time), intent(in) :: a write(*, "(I3,'hours',I3,' minutes',I3,' seconds')" ) a%hour,a%minute,a%second return end subroutine output end module time_utility program main usetime_utility implicit none type(time) :: a,b,c call input(a) callinput(b) c=a+b call output(c) stop end program main 3.modulerational_utility implicit none private public :: rational, &operator(+), operator(-), operator(*),& operator(/),assignment(=),operator(>),& operator(<), operator(==), operator(/=),& output, input type :: rational integer :: num, denom end type rational interface operator(+) module procedure rat__rat_plus_rat end interface interface operator(-)module procedure rat__rat_minus_rat end interface interfaceoperator(*) module procedure rat__rat_times_rat end interfaceinterface operator(/) module procedure rat__rat_div_rat end interface interface assignment(=) module procedure rat_eq_rat module procedureint_eq_rat module procedure real_eq_rat end interface interface operator(>) module procedure rat_gt_rat end interface interface operator(<) module procedure rat_lt_rat end interface interface operator(==) module procedure rat_compare_rat end interface interface operator(/=) module procedure rat_ne_rat end interface containsfunction rat_gt_rat(a,b) implicit none logical :: rat_gt_rattype(rational), intent(in) :: a,b real :: fa,fbfa=real(a%num)/real(a%denom)fb=real(b%num)/real(b%denom) if ( fa > fb ) then rat_gt_rat=.true. else rat_gt_rat=.false. end if return end function rat_gt_ratfunction rat_lt_rat(a,b) implicit none logical :: rat_lt_rattype(rational), intent(in) :: a,b real :: fa,fbfa=real(a%num)/real(a%denom) fb=real(b%num)/real(b%denom) if ( fb > fa ) then rat_lt_rat=.true. else rat_lt_rat=.false. end if return end function rat_lt_rat function rat_compare_rat(a,b) implicit nonelogical :: rat_compare_rat type(rational), intent(in) :: a,btype(rational) :: c c=a-b if ( c%num == 0 ) thenrat_compare_rat=.true. else rat_compare_rat=.false. end if returnend function rat_compare_rat function rat_ne_rat(a,b) implicit none logical :: rat_ne_rat type(rational), intent(in) :: a,btype(rational) :: c c=a-b if ( c%num==0 ) then rat_ne_rat=.false.else rat_ne_rat=.true. end if return end function rat_ne_ratsubroutine rat_eq_rat( rat1, rat2 ) implicitnone type(rational), intent(out):: rat1 type(rational),intent(in) :: rat2 rat1%num = rat2%num rat1%denom = rat2%denom return end subroutine rat_eq_rat subroutine int_eq_rat( int, rat ) implicit none integer, intent(out):: int type(rational), intent(in) :: rat int = rat%num / rat%denom return end subroutine int_eq_rat subroutinereal_eq_rat( float, rat ) implicit none real, intent(out) :: floattype(rational), intent(in) :: rat float = real(rat%num) /real(rat%denom) return end subroutine real_eq_rat function reduse( a ) implicit none type(rational), intent(in) :: a integer :: btype(rational) :: reduse b=gcv_interface(a%num,a%denom) reduse%num =a%num/b reduse%denom = a%denom/b return end function reduse functiongcv_interface(a,b) implicit none integer, intent(in) :: a,b integer :: gcv_interface if ( min(a,b) .eq. 0 ) then gcv_interface=1 return end if if (a==b) then gcv_interface=a return else if ( a>b ) thengcv_interface=gcv(a,b) else if ( a<b ) then gcv_interface=gcv(b,a)end if return end function gcv_interface recursive function gcv(a,b) result(ans) implicit none integer, intent(in) :: a,b integer :: m integer :: ans m=mod(a,b) select case(m) case(0) ans=b returncase(1) ans=1 return case default ans=gcv(b,m) end select return end function gcv function rat__rat_plus_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_plus_rat type(rational), intent(in) :: rat1,rat2 type(rational) :: act act%denom= rat1%denom * rat2%denom act%num = rat1%num*rat2%denom + rat2%num*rat1%denom rat__rat_plus_rat = reduse(act) return end function rat__rat_plus_rat functionrat__rat_minus_rat( rat1, rat2 ) implicit none type(rational) ::rat__rat_minus_rat type(rational), intent(in) :: rat1, rat2type(rational) :: temp temp%denom = rat1%denom*rat2%denom temp%num =rat1%num*rat2%denom - rat2%num*rat1%denom rat__rat_minus_rat = reduse( temp ) return end function rat__rat_minus_ratfunction rat__rat_times_rat( rat1, rat2 ) implicit nonetype(rational) :: rat__rat_times_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom* rat2%denom temp%num = rat1%num * rat2%num rat__rat_times_rat = reduse(temp)return end function rat__rat_times_rat function rat__rat_div_rat( rat1, rat2 ) implicit none type(rational) :: rat__rat_div_rattype(rational), intent(in) :: rat1, rat2 type(rational) :: temptemp%denom = rat1%denom* rat2%num temp%num = rat1%num * rat2%denomrat__rat_div_rat = reduse(temp) return end function rat__rat_div_rat subroutine input(a) implicit none type(rational), intent(out) :: awrite(*,*) "分子:" read(*,*) a%num write(*,*) "分母:" read(*,*)a%denom return end subroutine input subroutine output(a) implicit none type(rational), intent(in) :: a if ( a%denom/=1 ) then write(*, "(' (',I3,'/',I3,')' )" ) a%num,a%denom else write(*, "(I3)" ) a%num end if return end subroutine output end module rational_utility program main use rational_utility implicit none type(rational) :: a,b,c call input(a) call input(b) c=a+b write(*,*) "a+b=" call output(c) c=a-bwrite(*,*) "a-b=" call output(c) c=a*b write(*,*) "a*b=" call output(c)c=a/b write(*,*) "a/b=" call output(c) if (a>b) write(*,*) "a>b" if(a<b) write(*,*) "a<b" if (a==b) write(*,*) "a==b" if (a/=b) write(*,*) "a/=b" stop end program main 4.module vector_utility implicit none type vector real x,y end type interface operator(+) module procedurevector_add_vector end interface interface operator(-) module procedurevector_sub_vector end interface interface operator(*) module procedure real_mul_vector module procedure vector_mul_real module procedure vector_dot_vector end interface interface operator(.dot.) module procedure vector_dot_vector end interface contains type(vector) functionvector_add_vector(a,b) type(vector), intent(in) :: a,bvector_add_vector = vector(a%x+b%x, a%y+b%y) end function type(vector) functionvector_sub_vector(a,b) type(vector), intent(in) :: a,bvector_sub_vector = vector(a%x-b%x, a%y-b%y) end function type(vector) function real_mul_vector(a,b) real, intent(in) :: a type(vector), intent(in) :: b real_mul_vector= vector( a*b%x, a*b%y ) end functiontype(vector) functionvector_mul_real(a,b) type(vector), intent(in) :: a real, intent(in) :: b vector_mul_real = real_mul_vector(b,a) end function real function vector_dot_vector(a,b) type(vector), intent(in) :: a,bvector_dot_vector = a%x*b%x + a%y*b%y end function subroutineoutput(vec) type(vector) :: vec write(*,"('('F6.2','F6.2')')") vec end subroutine end module program main use vector_utility implicit none type(vector) a,b,c a=vector(1.0, 2.0) b=vector(2.0, 1.0) c=a+b call output(c) c=a-b call output(c) write(*,*) a*b end program main。
module linklisttype studentinteger :: numinteger :: Chinese, English, Math, Science, Social end typetype datalinktype(student) :: itemtype(datalink), pointer :: nextend typecontainsfunction SearchList(num, head)implicit noneinteger :: numtype(datalink), pointer :: head, ptype(datalink), pointer :: SearchListp=>headnullify(SearchList)do while( associated(p) )if ( p%item%num==num ) thenSearchList => preturnend ifp=>p%nextend doreturnend functionend module linklistprogram ex1016use linklistimplicit nonecharacter(len=20) :: filenamecharacter(len=80) :: tempstrtype(datalink), pointer :: headtype(datalink), pointer :: ptype(student), allocatable :: s(:)integer i,error,sizewrite(*,*) "filename:"read(*,*) filenameopen(10, file=filename, status="old", iostat=error)if ( error/=0 ) thenwrite(*,*) "Open file fail!"stopend ifallocate(head)nullify(head%next)p=>headsize=0read(10, "(A80)") tempstr ! 读入第一行字符串, 不需要处理它! 读入每一位学生的成绩do while(.true.)read(10,fmt=*, iostat=error) p%itemif ( error/=0 ) exitsize=size+1allocate(p%next, stat=error) ! 新增下一个数据if ( error/=0 ) thenwrite(*,*) "Out of memory!"stopend ifp=>p%next ! 移动到链表的下一个数据nullify(p%next)end dowrite(*,"('总共有',I3,'位学生')") sizeallocate( s(size) )p=>headdo i=1,sizes(i)=p%itemp=>p%nextend dodo while(.true.)write(*,*) "要查询几号同学的成绩?"read (*,*) iif ( i<1 .or. i>size ) exit ! 输入不合理的座号write(*,"(5(A6,I3))") "中文",s(i)%Chinese,&"英文",s(i)%English,&"数学",s(i)%Math,&"自然",s(i)%Science,&"社会",s(i)%Socialend dowrite(*,"('座号',I3,'不存在, 程序结束.')") istopend program。
fortran课后习题答案Fortran课后习题答案在学习Fortran编程语言时,课后习题是巩固知识、提高编程能力的重要途径。
通过解答课后习题,学生可以加深对Fortran语法和逻辑的理解,提高编程实践能力。
以下是一些Fortran课后习题答案,供大家参考。
1. 编写一个Fortran程序,计算并输出1到100的所有偶数的和。
程序代码如下:```fortranprogram sum_even_numbersimplicit noneinteger :: i, sumsum = 0do i = 2, 100, 2sum = sum + iend doprint *, 'The sum of even numbers from 1 to 100 is:', sumend program sum_even_numbers```2. 编写一个Fortran程序,找出一个整数数组中的最大值和最小值,并输出它们的位置。
程序代码如下:```fortranprogram find_max_minimplicit noneinteger :: i, n, max_val, min_val, max_pos, min_pos integer, dimension(10) :: arr! 初始化数组arr = (/3, 7, 2, 8, 5, 10, 1, 6, 4, 9/)! 初始化最大值和最小值max_val = arr(1)min_val = arr(1)max_pos = 1min_pos = 1! 找出最大值和最小值do i = 2, 10if (arr(i) > max_val) thenmax_val = arr(i)max_pos = iendifif (arr(i) < min_val) thenmin_val = arr(i)min_pos = iendifend doprint *, 'The maximum value is', max_val, 'at position', max_posprint *, 'The minimum value is', min_val, 'at position', min_posend program find_max_min```通过这些课后习题的答案,我们可以看到Fortran语言的一些基本特性和常用语法的运用。
一、判断题(共20分,每题1分,√表示对,×表示错)1.FORTRAN源程序的一条语句无法在一行内写下时,在行末用续行标志“!”,表示下一行是当前行的继续。
2.语句X=X+1的含义是将内存中名为X+1的存储单元的值赋给变量X。
3.如果程序单元中有说明语句PARAMETER(A=2.1),则不允许在该程序单元中改变A的值。
4.主程序和子程序可以储存到不同的文件中。
5.即使编译和连接都正确无误,FORTRAN程序运行时仍可能出错。
6.在数据块子程序中,可以调用另一个数据块子程序。
7.设有如下输入语句READ '(1X, F5.2)' , X若由键盘输入:12.3456789,则变量Y的值为12.34。
8.如果有以下程序段CHARACTER::A=’FORTRAN’则A内存储的实际值是’F’。
9.M=2000,为了在屏幕上输出□□***2000*** (其中□表示空格)。
则应使用的语句为:WRITE(*,100)M100 FORMAT(2X,’***’,I4,’***’)10.模块可用USE引用,也可用CALL调用。
11.语句函数定义语句在程序内的位置是:在程序块开头语句之后,END语句之前。
12.若有以下程序段:INTEGER,POINTER ::P1, P2INTEGER,TARGET::I=20, J=30P1=>I; P2=>J; P1=>P2; P2=>P1运行程序,I、J的值都为20。
13.COMMON语句的功能是给不同程序模块中的若干变量分配同一存储单元。
14.设C是复型变量,A、B是实型变量。
把A 的值赋给C的实部,把B的值赋给C的虚部的赋值语句是C=CMPLX(A,B)。
15.顺序存储结构的存储一定是连续的,链式存储结构的存储空间不一定是连续的。
16.A2B的FORTRAN表达式为A**2*B。
17.程序中说明了变量a具有POINTER属性,若a=>b,则b应具有PARAMETER属性。
FORTRAN90程序设计[麒麟火小组]日期:[2013.7.5]土木工程1309班小组成员:曹阳201302655 裴思杰201302618张健201302601 徐嘉辰201302605作业:一.求一元方程的根1.采用语句函数或函数子程序定义一元方程;2.程序采用以下多种方法求方程的根;牛顿迭代法,二分法,迭代法程序利用控制变量(如nmethod)来选择计算方法。
Program Frist !一个可以选择子程序的主程序integer xuhaoprint*,"请选择方法:1:二分法。
2:迭代法。
3:牛顿迭代法。
"read*,xuhaoif(xuhao==1)then !将3种方法放在不同的子程序中,并用选择结构进行选择。
call bisection()endifif(xuhao==2)thencall diedai()endifif(xuhao==3)thencall niudun()endifendsubroutine bisection() !二分法的子程序real x1,x2,xreal bisect,func1 !对要调用的子程序作说明doprint*,"输入x1,x2的值:"read*,x1,x2if(func1(x1)*func1(x2)<0.0)exitprint*,"不正确的输入!"enddox=bisect(x1,x2)print 10,'x=',x10format(a,f15.7)real function bisect(x1,x2) !二分法结构的函数子程序real x1,x2,x,f1,f2,fxx=(x1+x2)/2.0fx=func1(x)do while(abs(fx)>1e-6)f1=func1(x1)if(f1*fx<0)thenx2=xelsex1=xendifx=(x1+x2)/2.0fx=func1(x)enddobisect=xendreal function func1(x) !二分法的一元方程子程序real xfunc1=x**3-2*x**2+7*x+4endsubroutine diedai() !迭代法的子程序real xinteger mprint*,'请输入x0和最高循环次数的值:'read*,x,mcall iteration(x,m)endsubroutine iteration(x,m) !迭代法结构的函数子程序implicit nonereal x,x1real func2integer i,mi=1x1=func2(x)do while(abs(x-x1)>1e-6.and.i<=m)print 10,i,x1x=x1i=i+1x1=func2(x)if(i<=m)thenprint 20,'x=',x1elseprint 30,'经过',m,'次迭代后仍未收敛'endif10 format('i='i4,6x,'x='f15.7)20 format(a,f15.7)30 format(a,i4,a)endreal function func2(x) !迭代法一元方程的子程序real xfunc2=(-x**3+2*x**2-4)/7endsubroutine niudun() !牛顿迭代法的子程序real xinteger mprint*,'输入初值'read*,xcall newton(x)endsubroutine newton(x) !牛顿迭代法结构的函数子程序implicit nonereal x,x1real func3,dfunc3integer i,mi=1x1=x-func3(x)/dfunc3(x)do while (abs(x-x1)>1e-6)print 10,i,x1x=x1i=i+1x1=x-func3(x)/dfunc3(x)enddoprint 20,'x=',x110 format('i=',i4,6x,'x=',f15.7)20 format(a,f15.7)endreal function func3(x) !牛顿迭代法一元方程的函数子程序func3=x**3-2*x**2+7*x+4endreal function dfunc3(x) !牛顿迭代法一元方程的导数的子程序real xdfunc3=3*x**2-4*x+7end二.求解线性方程组用高斯消去法解线性方程组Ax=B的解,其中A为N*N系数矩阵,x为解向量,B为方程组右端n 维列向量。
课程名称:Fortran语言程序设计;试卷编号:A 卷;考试时间:120分钟学院1.Fortran语言中有:整数型逻辑型字符型实数型复数型五种基本数据类型。
2.Fortran程序的书写格式有两种固定格式自由格式。
3. 字符型常数’this”s’的字符长度为64. 下列程序运行结果为125。
Program mainImplicit noneInteger::floor=5,iDo i=1, floorIf(i==3)cycleIf(i==4)cycleWrite(*,*)iEnd doend5. 下列程序的运行结果为76.0,2.0。
Program mainImplicit noneReal :: a, b, mA=2.0B=76.0If(a<b)thenM=aA=bB=mEnd ifWrite(*,*) “a=”,a “b=”,bend6. 下列程序的运行结果是10302。
Program testImplicit nonesum=0.0do i=1,203,2sum=sum+iend dowrite(*,*) iend7.下列程序的运行结果是12000。
Program testImplicit noneInteger::iInteger::a(5)=(/ (i, i=1,5) /)Integer::b(5)=0Where (a<3)b=aEnd whereWrite(*,”(5(i3,1x))”) bend8.下列程序的运行结果是30。
Program testImplicit noneInteger,parameter:: limit=10Integer counterInteger:: ans=0Counter=2do while(counter<=limit)ans=ans+countercounter=counter+2end doWrte(*,*)ansend9.下列程序的运行结果是2,3。
软件技术基础(FORTRAN)笔试模拟试题(带答案)一.概念选择题(单选题,将正确的答案填入括号内。
每题1分,共15分)1. 已知整型变量L=5,M=13,N=4,表达式L*M/N 、L/N*M 和M/N*L 的值分别是(A )。
A )16 13 15B )16.25 16.25 16.25C )16.0 13.0 15.0D )16 16 162.将数学式)||(ln 215-+e x 改写为FORTRAN 表达式,正确的是( D )。
A) 1/2*(LOG(ABS(X))+E**(-5))B) 1.0/2*(LN(ABS(X))+E**-5)C) 1/2.0*(LN(ABS(X))+E -5)D) 1.0/2*(LOG(ABS(X))+EXP(-5))3. 设A=.TRUE., B=.FALSE., C=.FALSE., 逻辑表达式(A.OR.B).AND.C 与A.OR..NOT.B 的值是( B )。
A) .T. 与 .F. B).F . 与 .T. C) .T. 与 .T. D) .F. 与 .F .4. 数组REAL A (0:5,-1:5)的元素个数是 ( D )。
A )25B )30C )36D )42 5. 下列数组说明符中错误的是( A )。
A )K(3:2,1:2)B ) K(-1:1,2)C )K(-2:2,-1:1)D )K(2:2,5)6. 关于USE 语句的正确说法是( C )。
A)USE 语句是可执行语句 B)用USE 语句可以代替INCLUDE 语句C)USE 语句必须放在程序单元体的开头 D)USE 语句的位置任意7. 语句OPEN (9,FILE=‘DATA.TXT ’)打开的是 ( B ) 文件。
A )无格式顺序B )有格式顺序C )无格式直接D )有格式直接8. 阅读下列FORTRAN 程序, 程序运行时执行循环体的次数是( A )。
X=0DO L=10, 5, 1X=X+1.0ENDDOENDA) 0 B) 1 C) 6 D) 无穷9.结构化程序设计中有三种基本结构,下列不属于三种基本设计结构的是( D )。
第四章1.program main implicit none write(*,*) "Have a good time." write(*,*) "That's not bad." write(*,*) '"Mary" isn''t my name.' end program2.program main real, parameter :: PI=3 implicit none.14159 real radius write(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积='f8. 3)") radius*radius*PI end program3.program main implicit none real grades write(*,*) "请输入成绩" read(*,*) grades write(*,"(' 调整后成绩为 'f8.3)") SQRT(grades)*10.0 end program4.integer a,b real ra,rb a=2 b=3 ra=2.0 rb=3.0 write(*,*) b/a ! 输出1, 因为使用整数计算, 小数部分会无条件舍去 write(*,*) rb/ra ! 输出1.55.p rogram main implicit none type distance real meter, inch, cm end type type(distance) :: d write(*,*) "请输入长度:" read(*,*) d%meter d%cm =d%meter*100 d%inch = d%cm/2.54 write(*,"(f8.3'米 ='f8.3'厘米 ='f8.3'英寸')")d%meter, d%cm, d%inch end program第五章1.program main implicit none integer money real tax write(*,*) "请输入月收入" read(*,*) money if ( money<1000 ) then tax = 0.03 else if( money<5000) then tax = 0.1 else tax = 0.15 end if write(*,"(' 税金为 'I8)") nint(money*tax) end program2.program main implicit none integer day character(len=20) :: tv write(*,*) "请输入星期几" read(*,*) day select case(day) case(1,4) tv= "新闻" case(2,5) tv = "电视剧" case(3,6) tv = "卡通" case(7) tv = "电影" case default write(*,*) "错误的输入" stop end select write(*,*) tv end program3.program main implicit none integer age, money real tax write(*,*) "请输入年龄" read(*,*) age write(*,*) "请输入月收入" read(*,*) money if( age<50 ) then if ( money<1000 ) then tax = 0.03 else if ( money<5000 )then tax = 0.10 else tax = 0.15 end if else if ( money<1000 ) then tax =0.5 else if ( money<5000 )then tax = 0.7 else tax = 0.10 end if end if write(*,"(' 税金为 'I8)") nint(money*tax) end program4.program main implicit none integer year, days logical mod_4, mod_100,mod_400 write(*,*) "请输入年份" read(*,*) year mod_4 = ( MOD(year,4) ==0 ) mod_100 = ( MOD(year,100) == 0 ) mod_400 = ( MOD(year,400) == 0 ) if( (mod_4 .NEQV. mod_100) .or. mod_400 ) then days = 366 else days = 365end if write(*,"('这一年有'I3'天')") days stop end program第六章1.program main implicit none integer i do i=1,5 write(*,*) "Fortran" end do stop end program2.program main implicit none integer i,sum sum = 0 do i=1,99,2 sum =sum+i end do write(*,*) sum stop end program3.program main implicit none integer, parameter :: answer = 45 integer, parameter :: max = 5 integer weight, i do i=1,max write(*,*) "请输入体重" read(*,*) weight if ( weight==answer ) exit end do if ( i<=max ) thenwrite(*,*) "猜对了" else write(*,*) "猜错了" end if stop end program4.program main implicit none integer, parameter :: max=10 integer i realitem real ans ans = 1.0 item = 1.0 do i=2,max item = item/real(i)ans = ans+item end do write(*,*) ans stop end program5.program main implicit none integer, parameter :: length = 79 character(len=length) :: input, output integer i,j write(*,*) "请输入一个字串" read(*,"(A79)") input j=1 do i=1, len_trim(input) if ( input(i:i)/= ' ' ) then output(j:j)=input(i:i) j=j+1 end if end do write(*,"(A79)") output stop end program第七章1.program main implicit none integer, parameter :: max = 10 integer i integer :: a(max) = (/ (2*i, i=1,10) /) integer :: t ! sum()是fortran库函数write(*,*) real(sum(a))/real(max) stop end program2.integer a(5,5) ! 5*5=25 integer b(2,3,4) ! 2*3*4=24 integer c(3,4,5,6) !3*4*5*6=360 integer d(-5:5) ! 11 integer e(-3:3, -3:3) ! 7*7=493.program main implicit none integer, parameter :: max=10 integer f(max) integer i f(1)=0 f(2)=1 do i=3,max f(i)=f(i-1)+f(i-2) end do write(*,"(10I4)") f stop end program4.program main implicit none integer, parameter :: size=10 integer :: a(size)= (/ 5,3,6,4,8,7,1,9,2,10 /) integer :: i,j integer :: t do i=1, size-1do j=i+1, size if ( a(i) < a(j) ) then ! a(i)跟a(j)交换 t=a(i) a(i)=a(j) a(j)=t end if end do end do write(*,"(10I4)") a stop end5.a(2,2) ! 1+(2-1)+(2-1)*(5) = 7 a(3,3) ! 1+(3-1)+(3-1)*(5) = 13第八章1.program main implicit none real radius, area write(*,*) "请输入半径长"read(*,*) radius call CircleArea(radius, area) write(*,"(' 面积 = 'F8.3)")area stop end program subroutine CircleArea(radius, area) implicit nonereal, parameter :: PI=3.14159 real radius, area area = radius*radius*PIreturn end subroutine2.program main implicit none real radius real, external :: CircleAreawrite(*,*) "请输入半径长" read(*,*) radius write(*,"(' 面积= 'F8.3)") CircleArea(radius) stop end program real function CircleArea(radius) implicit none real, parameter :: PI=3.14159 real radius CircleArea =radius*radius*PI return end function3.program main implicit none call bar(3) call bar(10) stop end program subroutine bar(length) implicit none integer, intent(in) :: length integeri character(len=79) :: string string=" " do i=1,length string(i:i)='*'end do write(*,"(A79)") string return end subroutine4.p rogram main implicit none integer, external :: add write(*,*) add(100)end program recursive integer function add(n) result(sum) implicit none integer, intent(in) :: n if ( n<0 ) then sum=0 return else if ( n<=1 )then sum=n return end if sum = n + add(n-1) return end function5.program main implicit none integer, external :: gcd write(*,*) gcd(18,12)end program integer function gcd(A,B) implicit none integerA,B,BIG,SMALL,TEMP BIG=max(A,B) SMALL=min(A,B) do while( SMALL /= 1 ) TEMP=mod(BIG,SMALL) if ( TEMP==0 ) exit BIG=SMALL SMALL=TEMP end dogcd=SMALL return end function 6.program main use TextGraphLib implicit none integer, parameter :: maxx=60, maxy=20 real, parameter :: StartX=0.0,EndX=3.14159*2.0 real, parameter :: xinc = (EndX-StartX)/(maxx-1) real x integer i,px,py call SetScreen(60,20) call SetCurrentChar('*') x=StartXdo px=1,maxx py = (maxy/2)*sin(x)+maxy/2+1 call PutChar(px,py) x=x+xincend docall UpdateScreen() stop end program第九章1.program main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer count integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old")count = 0 do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status )buffer if ( status/=0 ) exit ! 没有资料就跳出循环 write(*,"(A79)")buffer count = count+1 if ( count==24 ) then pause count = 0 endif end do else write(*,*) TRIM(filename)," doesn't exist." end ifstop end2.p rogram main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer iinteger :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)") filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old")do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) bufferif ( status/=0 ) exit ! 没有资料就跳出循环do i=1, len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-3 ) end do write(*,"(A70)") bufferend do else write(*,*) TRIM(filename)," doesn't exist." end if stop end3.program main implicit none type student integer chinese, english, math, science, social, total end type type(student) :: s, total integer, parameter :: students=20, subjects=5 integer i open(10,file="grades.bin",access="direct",recl=1) write(*,"(7A10)") "座号","中文","英文","数学","自然","社会","总分" total = student(0,0,0,0,0,0) do i=1, students read(10,rec=(i-1)*subjects+1) s%chinese read(10,rec=(i-1)*subjects+2) s%english read(10,rec=(i-1)*subjects+3) s%math read(10,rec=(i-1)*subjects+4) s%science read(10,rec=(i-1)*subjects+5)s%social s%total = s%chinese+s%english+s%math+s%science+s%social total%chinese= total%chinese+s%chinese total%english = total%english+s%english total%math =total%math+s%math total%science = total%science+s%science total%social =total%social+s%social total%total = total%total+s%total write(*,"(7I10)") i,s end do write(*,"(A10,6F10.3)") "平均", & real(total%chinese)/real(students),&real(total%english)/real(students),& real(total%math)/real(students),& real(total%science)/real(students),&real(total%social)/real(students),& real(total%total)/real(students)stop end 4.program main implicit none character(len=79) :: filename character(len=79) :: buffer integer, parameter :: fileid = 10 integer i integer :: status = 0 logical alive write(*,*) "Filename:" read (*,"(A79)")filename inquire( file=filename, exist=alive) if ( alive ) then open(unit=fileid, file=filename, & access="sequential", status="old") do while(.true.) read(unit=fileid, fmt="(A79)", iostat=status ) buffer if ( status/=0 ) exit ! 没有数据就跳出循环do i=1, len_trim(buffer) buffer(i:i) = char( ichar(buffer(i:i))-(mod(i-1,3)+1) ) end do write(*,"(A70)") buffer end do else write(*,*) TRIM(filename)," doesn't exist." end if stop end5.module typedef type student integer :: num integer :: Chinese, English, Math, Natural, Social integer :: total integer :: rank end type end module program main use typedef implicit none integer, parameter :: fileid=10 integer, parameter :: students=20 character(len=80) :: tempstr type(student) :: s(students) ! 储存学生成绩 type(student) :: total ! 计算平均分数用integer i, num, error open(fileid,file="grades.txt",status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open grades.txt fail." stop end if read(fileid, "(A80)") tempstr ! 读入第一行文字 total=student(0,0,0,0,0,0,0,0) ! 用循环读入每位学生的成绩do i=1,students read(fileid,*) s(i)%num, s(i)%Chinese,s(i)%English, & s(i)%Math, s(i)%Natural, s(i)%Social ! 计算总分 s(i)%Total = s(i)%Chinese + s(i)%English + & s(i)%Math +s(i)%Natural + s(i)%Social ! 累加上各科的分数, 计算各科平均时使用total%Chinese = total%Chinese + s(i)%Chinese total%English = total%English +s(i)%English total%Math = total%Math + s(i)%Math total%Natural = total%Natural + s(i)%Natural total%Social = total%Social + s(i)%Social total%Total = total%Total + s(i)%Total end do call sort(s,students) ! 重新输出每位学生成绩 write(*,"(8A7)") "座号","中文","英文","数学","自然","社会","总分","名次" do i=1,students write(*,"(8I7)") s(i) end do ! 计算并输出平圴分数write(*,"(A7,6F7.1)") "平均", &real(total%Chinese)/real(students),& real(total%English)/real(students),&real(total%Math) /real(students),& real(total%Natural)/real(students),&real(total%Social) /real(students),& real(total%Total) /real(students) stop end program subroutine sort(s,n) use typedef implicit none integer n type(student) :: s(n), t integer i,j do i=1,n-1 do j=i+1,n if( s(i)%total < s(j)%total ) then t = s(i) s(i)=s(j) s(j) = t end ifend do end do forall(i=1:n) s(i)%rank = i end forall end subroutine第十章1.integer(kind=4) :: a ! 4 bytes real(kind=4) :: b ! 4 bytes real(kind=8) :: c !8 bytes character(len=10) :: str ! 10 bytes integer(kind=4), pointer :: pa !4 bytes real(kind=4), pointer :: pb ! 4 bytes real(kind=8), pointer :: pc !4 bytes character(len=10), pointer :: pstr ! 4 bytes type student integer Chinese, English, Math end type type(student) :: s ! 12 bytes type(student), pointer ::ps ! 4 bytes2.integer, target :: a = 1 integer, target :: b = 2 integer, target :: c = 3 integer, pointer :: p p=>a write(*,*) p ! 1 p=>b write(*,*) p ! 2 p=>c p=5 write(*,*) c !53.module linklist type student integer :: num integer :: Chinese, English,Math, Science, Social end type type datalink type(student) :: item type(datalink), pointer :: next end type contains function SearchList(num, head) implicit none integer :: num type(datalink), pointer :: head, p type(datalink), pointer :: SearchList p=>head nullify(SearchList) do while( associated(p) ) if ( p%item%num==num ) then SearchList => p return end if p=>p%next end do return end function end module linklist programex1016 use linklist implicit none character(len=20) :: filename character(len=80) :: tempstr type(datalink), pointer :: head type(datalink), pointer :: p type(student), allocatable :: s(:) integer i,error,size write(*,*) "filename:" read(*,*) filename open(10, file=filename, status="old", iostat=error) if ( error/=0 ) then write(*,*) "Open file fail!" stop end if allocate(head) nullify(head%next) p=>head size=0 read(10, "(A80)") tempstr ! 读入第一行字符串, 不需要处理它 ! 读入每一位学生的成绩 do while(.true.) read(10,fmt=*, iostat=error) p%item if ( error/=0 )exit size=size+1 allocate(p%next, stat=error) ! 新增下一个数据 if ( error/=0 )then write(*,*) "Out of memory!" stop end if p=>p%next ! 移动到链表的下一个数据 nullify(p%next) end do write(*,"('总共有',I3,'位学生')") size allocate( s(size) ) p=>head do i=1,size s(i)=p%item p=>p%next end do do while(.true.) write(*,*) "要查询几号同学的成绩?" read (*,*) i if( i<1 .or. i>size ) exit ! 输入不合理的座号 write(*,"(5(A6,I3))") "中文",s(i)%Chinese,& "英文",s(i)%English,& "数学",s(i)%Math,& "自然",s(i)%Science,& "社会",s(i)%Social end do write(*,"('座号',I3,'不存在, 程序结束.')") i stopend program4.module typedef implicit none type :: datalink integer :: i type(datalink), pointer :: next end type datalink end module typedef programex1012 use typedef implicit none type(datalink) , pointer :: p, head, next integer :: i,n,err write(*,*) 'Input N:' read(*,*) n allocate( head ) head%i=1 nullify(head%next) p=>head do i=2,n allocate( p%next,stat=err ) if ( err /= 0 ) then write(*,*) 'Out of memory!' stop end if p=>p%next p%i=i end do nullify(p%next) p=>head do while(associated(p)) write(*, "(i5)" ) p%i p=>p%next end do ! 释放链表的存储空间p=>head do while(associated(p)) next => p%next deallocate(p) p=>next end do stop end program第十一章1.module utility implicit none interface area module procedure CircleArea module procedure RectArea end interface contains real function CircleArea(r) real, parameter :: PI=3.14159 real r CircleArea =r*r*PI return end function real function RectArea(a,b) real a,b RectArea = a*b return end function end module program main use UTILITY implicit none write(*,*) area(1.0) write(*,*) area(2.0,3.0) stop end program2.module time_utility implicit none type :: time integer :: hour,minute,second end type time interface operator(+) module procedureadd_time_time end interface contains function add_time_time( a, b ) implicit none type(time) :: add_time_time type(time), intent(in) :: a,binteger :: seconds,minutes,carry seconds=a%second+b%second carry=seconds/60 minutes=a%minute+b%minute+carry carry=minutes/60add_time_time%second=mod(seconds,60) add_time_time%minute=mod(minutes,60)add_time_time%hour=a%hour+b%hour+carry return end function add_time_time subroutine input( a ) implicit none type(time), intent(out) :: a write(*,*) " Input hours:" read (*,*) a%hour write(*,*) " Input minutes:"read (*,*) a%minute write(*,*) " Input seconds:" read (*,*) a%second return end subroutine input subroutine output( a ) implicit nonetype(time), intent(in) :: a write(*, "(I3,' hours',I3,' minutes',I3,'seconds')" ) a%hour,a%minute,a%second return end subroutine output endmodule time_utility program main use time_utility implicit nonetype(time) :: a,b,c call input(a) call input(b) c=a+b call output(c)stop end program main3.module rational_utility implicit none private public :: rational, & operator(+), operator(-), operator(*),& operator(/), assignment(=),operator(>),& operator(<), operator(==),operator(/=),& output, input type :: rational integer :: num,denom end type rational interface operator(+) module procedurerat__rat_plus_rat end interface interface operator(-) module procedurerat__rat_minus_rat end interface interface operator(*) module procedurerat__rat_times_rat end interface interface operator(/) module procedurerat__rat_div_rat end interface interface assignment(=) module procedurerat_eq_rat module procedure int_eq_rat module procedure real_eq_rat endinterface interface operator(>) module procedure rat_gt_rat endinterface interface operator(<) module procedure rat_lt_rat endinterface interface operator(==) module procedure rat_compare_rat endinterface interface operator(/=) module procedure rat_ne_rat endinterface contains function rat_gt_rat(a,b) implicit none logical ::rat_gt_rat type(rational), intent(in) :: a,b real :: fa,fbfa=real(a%num)/real(a%denom) fb=real(b%num)/real(b%denom) if ( fa > fb )then rat_gt_rat=.true. else rat_gt_rat=.false. end if return end function rat_gt_rat function rat_lt_rat(a,b) implicit none logical :: rat_lt_rat type(rational), intent(in) :: a,b real :: fa,fbfa=real(a%num)/real(a%denom) fb=real(b%num)/real(b%denom) if ( fb > fa )then rat_lt_rat=.true. else rat_lt_rat=.false. end if return end function rat_lt_rat function rat_compare_rat(a,b) implicitnone logical :: rat_compare_rat type(rational), intent(in) :: a,btype(rational) :: c c=a-b if ( c%num == 0 ) thenrat_compare_rat=.true. else rat_compare_rat=.false. end if return end function rat_compare_rat function rat_ne_rat(a,b) implicitnone logical :: rat_ne_rat type(rational), intent(in) :: a,btype(rational) :: c c=a-b if ( c%num==0 ) then rat_ne_rat=.false.else rat_ne_rat=.true. end if return end function rat_ne_rat subroutine rat_eq_rat( rat1, rat2 ) implicit none type(rational),intent(out):: rat1 type(rational), intent(in) :: rat2 rat1%num =rat2%num rat1%denom = rat2%denom return end subroutine rat_eq_ratsubroutine int_eq_rat( int, rat ) implicit none integer, intent(out):: inttype(rational), intent(in) :: rat int = rat%num / rat%denom return end subroutine int_eq_rat subroutine real_eq_rat( float, rat ) implicit none real, intent(out) :: float type(rational), intent(in) :: rat float =real(rat%num) / real(rat%denom) return end subroutine real_eq_rat function reduse( a ) implicit none type(rational), intent(in) :: a integer :: b type(rational) :: reduse b=gcv_interface(a%num,a%denom) reduse%num = a%num/b reduse%denom = a%denom/b return end function reduse function gcv_interface(a,b) implicit none integer, intent(in) ::a,b integer :: gcv_interface if ( min(a,b) .eq. 0 ) then gcv_interface=1 return end if if (a==b) then gcv_interface=a return else if ( a>b ) then gcv_interface=gcv(a,b) else if ( a<b ) then gcv_interface=gcv(b,a) end if return end function gcv_interface recursive function gcv(a,b) result(ans) implicitnone integer, intent(in) :: a,b integer :: m integer :: ans m=mod(a,b) select case(m) case(0) ans=b return case(1) ans=1 return case default ans=gcv(b,m) end select return end function gcv function rat__rat_plus_rat( rat1, rat2 ) implicitnone type(rational) :: rat__rat_plus_rat type(rational), intent(in) ::rat1,rat2 type(rational) :: act act%denom= rat1%denom * rat2%denom act%num = rat1%num*rat2%denom + rat2%num*rat1%denom rat__rat_plus_rat = reduse(act) return end function rat__rat_plus_rat functionrat__rat_minus_rat( rat1, rat2 ) implicit none type(rational) ::rat__rat_minus_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom*rat2%denom temp%num =rat1%num*rat2%denom - rat2%num*rat1%denom rat__rat_minus_rat = reduse( temp ) return end function rat__rat_minus_rat function rat__rat_times_rat( rat1,rat2 ) implicit none type(rational) :: rat__rat_times_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom* rat2%denom temp%num = rat1%num * rat2%num rat__rat_times_rat = reduse(temp) return end function rat__rat_times_rat function rat__rat_div_rat( rat1, rat2 ) implicit none type(rational) ::rat__rat_div_rat type(rational), intent(in) :: rat1, rat2 type(rational) :: temp temp%denom = rat1%denom* rat2%num temp%num =rat1%num * rat2%denom rat__rat_div_rat = reduse(temp) return end function rat__rat_div_rat subroutine input(a) implicit none type(rational), intent(out) :: a write(*,*) "分子:" read(*,*) a%num write(*,*) "分母:" read(*,*) a%denom return end subroutine input subroutine output(a) implicit none type(rational), intent(in) :: a if ( a%denom/=1 ) then write(*, "(' (',I3,'/',I3,')' )" ) a%num,a%denom else write(*, "(I3)" ) a%num end if return end subroutine outputend module rational_utility program main use rational_utility implicit none type(rational) :: a,b,c call input(a) call input(b) c=a+b write(*,*)"a+b=" call output(c) c=a-b write(*,*) "a-b=" call output(c) c=a*b write(*,*) "a*b=" call output(c) c=a/b write(*,*) "a/b=" call output(c)if (a>b) write(*,*) "a>b" if (a<b) write(*,*) "a<b" if (a==b) write(*,*) "a==b"if (a/=b) write(*,*) "a/=b" stop end program main4.module vector_utility implicit none type vector real x,y end type interface operator(+) module procedure vector_add_vector end interface interface operator(-) module procedure vector_sub_vector end interface interface operator(*) module procedure real_mul_vector module procedure vector_mul_real module procedure vector_dot_vector end interface interface operator(.dot.) module procedure vector_dot_vector end interface contains type(vector) function vector_add_vector(a,b) type(vector), intent(in) :: a,b vector_add_vector = vector(a%x+b%x, a%y+b%y) end function type(vector) function vector_sub_vector(a,b) type(vector), intent(in) :: a,b vector_sub_vector = vector(a%x-b%x, a%y-b%y) end function type(vector) function real_mul_vector(a,b) real, intent(in) :: a type(vector), intent(in) :: b real_mul_vector = vector( a*b%x, a*b%y ) end functiontype(vector) function vector_mul_real(a,b) type(vector), intent(in) :: a real, intent(in) :: b vector_mul_real = real_mul_vector(b,a) end function real function vector_dot_vector(a,b) type(vector), intent(in) :: a,b vector_dot_vector = a%x*b%x + a%y*b%y end function subroutine output(vec) type(vector) :: vec write(*,"('('F6.2','F6.2')')") vec end subroutine end module program main use vector_utility implicit none type(vector) a,b,ca=vector(1.0, 2.0) b=vector(2.0, 1.0) c=a+b call output(c) c=a-b call output(c) write(*,*) a*b end program main。
习题二一、问答题1. 给出下面变量名称,哪些是合法变量?哪些是非法变量?说明原因。
Count 、num_2、x&y 、4x+5y 、china-suzhou 、$us 、AbCdE 、Mr.bai 、t5、 _another 、school_class_25、#125、2002Y 、π、β、A01/02、alpha 、date(1) 1. 判定下面整数,指出哪些是合法整数,哪些是非法整数?说明原因。
-0、+ 215、$125、3,245,895、5.3245、5#384、-524_3、#5DFE 、 23-345、16#1A2B 、38#ABCD 、8#275_2、+327890、4 #321 2. 判定下面实数,指出哪些是合法实数,哪些是非法实数?说明原因。
-0E2、45.2345E3.5、-5489E25_8、-.2345E-35、$185.45E 、+ 2.753425E24_3、 58D85、+0.E-0、-00000.001E5、5,443,223.44、-12 34E+2、+ 18.5E 18、2.5E42习题三一、选择题1.下面是V isual Fortran 中正确的表达式是 。
(A )A*COS(X)+∣B ∣ (B )2*EXP(2*X)/SQRT(16.0) (C )B 2-4AC (D )MOD (24.5,0.5) 2.下面算术赋值语句中正确的语句是 。
(A )M*N=(X-Y)/Z (B )+R=A+B/C (C )X=Y=Z-1.0 (D )Y=A*B/C/D 3.算术表达式1/3+2/3的值为 。
(A ) 0 (B ) 1 (C ) 0.99999999 (D )值不确定二、问答题1. 将下列代数式用Visual Fortran 表达式描述:① ②③ 4sin 3A-3sinA+sin3A ④2.执行下列赋值语句后,变量中的值。
变量的类型遵循I —N 规则。
设I=6,K=2,N=-3,T=7.5,Y=1.5①L=T/Y/2.0 2 ②M=I/K*Y+1.5 6 ③Z=I*K+Y 13.5 ④A=I**K/N+T/Y -7.0习题四一、运行程序题2200BA CBy Ax +++z sin e 21y -psin )c p sin()b p sin()a p sin(---1. 判断下列输入输出语句是否正确?(1) PRINT*, ´X=´, X, ´X*Y**2=´, X*Y**2(2) WRITE ( * , * ) A, B, NO, ´Y=´, Y(3) READ*, N, M, 5.0K(4) WRITE ( *,22 ) A, B, I, K, C22 FORMA T ( 4X, 2F5.0, 2I5 )(5) WRITE ( 8,33 ), X, Y, M, Z, N,33 FORMA T ( 4X, 2F5.0 2I5 )(6) READ ( *,44 ) NF, G, H, I, J44 FORMA T ( 4X, I5, 2 ( F6.2, I5 ) )2. 已知整型变量i、j、k、l、m、n,执行下面表控输入语句:READ*, i,jREAD*, k,l,mREAD*, n按以下格式输入8个数据:2526 50 45 57 4327 28输入语句执行后,每个变量取何值?i=25、j=26、k=27、l=28、m=0、n=03. 写出输出结果,设I=56,J=1274,K=5126WRITE ( *,100 ) I, J, K(1) 100 FORMA T ( 1X, I4 )(2) 100 FORMA T ( 1X, 2I5 )56 12745126(3) 100 FORMA T ( 1X, 2 ( I5,2X ) / )56 127451264. 写出输出结果,设I=512,J=612,A=18.34,B=-21.4,C=112.463,D=-2174.573WRITE ( *,100 ) I,J,A,B,C,D(1) 100 FORMA T ( 1X,I5,2X,2 ( F10.2,2X ),F12.1 )512 0.00E+00 18.34 -2.14112.46 -2174.57(2) 100 FORMA T ( 3X,2 ( I4,2X ),2 ( F10.2,2X ),´NEW´)512 0.00E+00 18.34 -2.14 NEW112.46 -2174.57 NEW5. 有读入语句:READ ( *,100 ) I,J,B设输入的值为:I=63,A=76.5,J=122,B=156.783。
如用下面的FORMA T语句应如何输入数据。
(1) 100 FORMA T ( I4,F6.2,I5,F8.2 )(2) 100 FORMA T ( I4,2X,F6.2,I5,F8.2 )(3) 100 FORMA T ( 1X,2 ( I4,2X,F10.2 ) )(4) 100 FORMA T ( I4,F6.2/I5,F8.2 )(5) 100 FORMA T ( I4/F6.2/I5/F8.2 )(6) 100 FORMA T ( I5,F8.1 )6.IMPLICIT NONEINTEGER::I,J,KREAD *,I,JK=I/JPRINT *,‟K=‟,KEND当输入9,2时,输出结果为K=4 。
7.IMPLICIT NONEREAL::I,J,KREAD(*,*)I,JK=I/JWRITE(*,*)‟K=‟,KEND当输入9,2时,输出结果为K=4.500000。
8.下面是一些非法的输入输出语句和格式说明语句。
说明其非法原因。
READ * i,j,kREAD 10 i,j,kREAD *,…i=‟,i,…j=‟,jREAD(*,10) i,j,125READ(*,…(“i=”,I3,“j=”,I3)‟) i,jREAD(…(I3,I3)‟,*) i,j10 FORMA T(1X,I3,:,I3,:,I3)PRINT * i,j,kPRINT 10 i,j,kWRITE *,…i=‟,i,…j=‟,jWRITE(20,*) i,j,125PRINT(*,…(“i=”,I3,“j=”,I3)‟) i,jWRITE(…(I3,I3)‟,*) i,j20 FORMA T(1X,I3,I3 I3)9.给定下面READ和FORMA T语句:READ 100,i,j,k,m,n100 FORMA T(I2,I3,2X,I2,1X,I4.1,I3)执行READ语句,输入以下5组数据:12345678901234567890↙1 322 43 565 768 78↙12,3 43 7 ,2 3455↙1232;45A18 93 215↙1 23;324;445;555;777↙READ语句执行后,每组i,j,k,m,n的值分别是多少?10.给定下面READ和FORMA T语句:READ 100,a,b,c100 FORMA T(F5.2,F5.1,E8.3)执行READ语句,输入以下5组数据:12345678901234567890↙123,456789012,345890↙1 322 43 565 E+ 28↙123E2343 7 2 3455↙1.23245.E3.1893 215↙READ语句执行后,每组a,b,c的值分别是多少?11.已知:i=25,j=-125,k=-4725,m=-31500,a=48.57,x=-1.5E+11,y=158.895E-11。
给定输出语句:WRITE(*,100)i,a,j,b,k,m,x,y对下面不同的FORMA T语句,写出输出结果:①100 FORMA T(1X,I3,1X,F5.2,1X,I4,1X,F9.2,I5,I6,E12.3,E12.3E3)②100 FORMA T(3X,I4,1X,F9.2,1X,I4,1X,F9.2,2I5,2E12.3)③100 FORMA T(… i=‟,I3,…a=‟,F5.2,…j=‟,I4,…b=‟,F9.2,…k=‟,I5,…m=‟,I6,…x=‟,E12.3,…y=‟,E12.3E3)④100 FORMA T(2(2X,I4,2X,F9.2),2I5,2E12.3)⑤100 FORMA T(1X,I3,1X,F5.2/1X,I4,1X,F9.2/I5,I6,E12.3,E12.3E3)12.已知:i=315,j=512,a=43.57,b=-15.9,c=123.456,d=-5231.573。
给定输出语句:WRITE(*,100)i,j,a,b,c,d对下面不同的FORMA T语句,写出输出结果:①100 FORMA T(1X,I4,2X,I5,2X,2(F7.2,2X),F10.1)②100 FORMA T(1X,2(I4,2X),2(F7.2,2X),…OLD‟)13.给定下面程序:READ 10,i,j,k,m,n10 FORMA T(1X,I3, T5,I3,I4,TL8,I2,TR5,I3)PRINT *,i,j,k,m,nEND程序执行时,输入数据:1234567890987654321↙程序执行后,变量i,j,k,m,n的值是什么?二、填空题下面程序是求任意两个整型数M、N的和,要求输出形式为:M+N=和,如M=3,N=8,则输出形式为:M+N= 11。
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IMPLICIT NONEINTEGER::M,N,SREAD*,M,NS=M+NPRINT *,…M+N=‟ ,SEND习题五一、选择题1、已知:A=4.9,B=5.5,C=8.0,L=.FALSE.,则其值为’假’的表达式是。
A) A<B.OR..NOT.B<CB) L.OR.A<C.NEQV.LC) 13>C.EQV..NOT.LD)L.EQV.A<B+C2、以下不合法的Visual Fortran表达式是。
A)A<B<C<DB) .NOT.(X<0.0)C)A>=B.EQV.C>DD)A.AND.B.AND.C3、以下能表示条件“X、Y中至少有一个大于0且小于等于10”的逻辑表达式是。
A)(0<X<=10).OR.(0<Y<=10)B)(0<X.AND.X<=10).AND.(0<Y.AND.Y<=10)C)(0<X.AND.X<=10).OR.(0<Y.AND.Y<=10)D)0< (X.OR.Y)<= 104、以下能表示条件“X、Y中至少有一个大于等于10或小于5”的逻辑表达式是。