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2017年6月福建省普通高中学生学业基础会考试题及参考答案

2017年6月福建省普通高中学生学业基础会考试题及参考答案
2017年6月福建省普通高中学生学业基础会考试题及参考答案

2017年6月福建省普通高中学生学业基础会考

化学试题

(考试时间:90分钟;满分100分)

第I卷(选择题44分)

一、选择题(本大题有22小题,每小题2分,共44分。每小题只有一个选项符合题目要求)

1.2017年5月,我国在南海海域首次成功试开采“可燃冰”。“可燃冰”是天然气的水合物,外形似冰,下列相关说法不正确

...的是( )

A.“可燃冰”的主要可燃成分是甲烷B.“可燃冰”是一种比较洁净的能源

C.“可燃冰”储量大,可无节制开采D.“可燃冰”的开采,有助于解决人类面临的能源危机

2.下列物质属于混合物的是( )

A.氨气B.空气C.二氧化碳D.氢氧化钠

3.危险化学品必须贴有警示标识。乙醇的包装箱应选用的标识是( )

A B C D

4.下列物质所含分子数最少

..的是( )

A.0.8 mol H2O B.0.5N A个H2 (N A为阿伏加德罗常数的值)

C.标准状况下22.4 L O2D.1.7 g NH3 (NH3的摩尔质量是17g/mol)

5.下列物质属于离子化合物的是( )

A.CO2B.Ne C.HCl D.NaCI

6.化学与生活息息相关。下列做法对人体健康不利

..的是( )

A.用硫黄燃烧产生的二氧化硫漂白银耳B.食用含铁丰富的食物,改善缺铁性贫血C.烹调中加料酒和食醋,增加食物的香味

D.用小苏打(NaHCO3)作焙制糕点的膨松剂

7.下列分散系中,分散质微粒直径介于10一9~10一7m(1~100nm)之间并能产生丁达尔效应的是( )

A.Fe(OH)3胶体B.CuSO4溶液C.NaNO3溶液D.KCl溶液

8.实验室配制250 mL0.1 mol/L Na2CO3溶液时,需要用到的仪器是( )

A B C D

9.下列互为同素异形体的是( )

A .O 2与O 3

B .H 2O 与H 2O 2

C .126C 与14

6C D .CH 4与CH 3CH 3

10.在水溶液中能大量共存的离子组是( )

A .Ag +、K +、Cl —

B .Ba 2+、Na +、SO 42—

C .H +、NH 4+、CO 32—

D .Na +、H +、NO 3—

11.下列反应的离子方程式书写正确的是( ) A .铁和氯化铁溶液反应:Fe + Fe 3+ == Fe 2+

B .稀硫酸和氢氧化钠溶液反应:H + + OH —

== H 2O

C .碳酸钙和稀硝酸反应:CO 32—

+ 2H + == H 2O + CO 2↑

D .氯化铜溶液和氢氧化钾溶液反应:CuCl 2 + 2OH —== Cu(OH)2↓+ 2Cl —

12.下列实验操作正确的是( ) A .向燃着的酒精灯添加酒精

B .用量筒量取10.0 mL 浓硫酸并在量筒中稀释

C .用托盘天平称量物品时,左盘放物品右盘放砝码

D .少量浓硫酸沾在皮肤上,立即用浓NaOH 溶液清洗 13.下列有关有机物的叙述错误..的是( ) A .淀粉没有甜味,不属于糖类 B .普通食醋中约含有3%~5%的乙酸 C .动物的肌肉、毛皮、血液中含有蛋白质

D .许多水果有芳香气味,是因为含有酯类化合物 14.下列属于氧化还原反应的是( )

A .SO 3 +H 2O == H 2SO 4

B .2Mg + CO 2 ===点燃

2MgO + C

C .CaCO 3

===高温

CaO + CO 2↑ D .3HCI +Fe(OH)3 ==FeCl 3 +3H 2O

15.下列变化不涉及...

化学反应的是( ) A .钢铁生锈 B .木柴燃烧 C .冰雪融化 D .食品腐败

16.右图是某有机物的球棍模型,其中“●”表示碳原子,“○”表示氢原子,该有机物结构简式是( )

A .CH 3CH 3

B .CH 2=CH 2

C .CH 3CH 2OH

D .CH 3COOH 17.下列属于取代反应的是( )

A .甲烷完全燃烧:CH 4 +2O 2 点燃

????

→CO 2 + 2H 2O B .乙烯通入溴水中:CH 2=CH 2 + Br 2 —→ CH 2BrCH 2Br

C .甲烷与Cl 2光照条件下反应:CH 4 + Cl 2 光照

????

→CH 3CI + HCl D .乙烯在一定条件下生成聚乙烯:nCH 2=CH 2??????

→一定条件下

[22n CH CH ]- 18.右图为原电池装置,下列叙述正确的是( )

A .锌片溶解

B .锌片为正极

C .铜片质量减少

D .该装置将电能转化为化学能

19.合金在生产及科研中具有广泛的作用。下列材料属于合金的是( ) A .陶瓷 B .塑料 C .水泥 D .不锈钢

20.氧元素有多种核素,其中188O 常用作 “示踪原子”,该核素的中子数为( ) A .8 B .10 C .18 D .26

21.化学反应常伴有颜色变化。下列实验中观察不到....颜色变化的是( ) A .NO 暴露在空气中 B .往Na 2CO 3溶液中滴加稀盐酸 C .往NaOH 溶液中滴加酚酞试液 D .往FeCl 3溶液中滴加KSCN 溶液 22.在一定条件下,四个体积相同的密闭容器中,发生反应:2SO 2 + O 2 Δ

催化剂

2SO 3,

第Ⅱ卷 (非选择题56分)

二、填空简答题(本大题有6小题,共40分)

23.(4分)完成下列各题。

(1)在实验室,浓硝酸应保存在 (填“棕色”或“无色”)试剂瓶中。

(2)新鲜的蔬菜和水果中含有较多的维生素C 。维生素C 的分子式为C 6H 8O 6,它属于 (填“无机物”或“有机物”)。

24.(6分)从下列六种有机物中选择合适的物质,将其标号填在横线上。 A .甲醛 B .乙烯 C .乙酸 D .油脂 E .葡萄糖 F .蛋白质 (1)蚕丝的主要成分是 ;

(2)可用于生产肥皂的原料是 ; (3)能使紫色石蕊试液变红的是 ;

(4)纤维素在一定条件下最终水解生成 ; (5)用于制造食物保鲜膜的聚乙烯的原料是 ; (6)可用来浸制生物标本的是 的水溶液。 25.(6分)完成下列各题。

(1)氨气(NH 3)接触氯化氢(HCl)产生白烟(NH 4Cl)。写出该反应的化学方程式: 。

(2)铝热反应可用于焊接铁轨。写出铝(Al)与氧化铁(Fe 2O 3)在高温下反应生成铁(Fe)与氧化铝(Al 2O 3)的化学方程式: 。

26.(12分)下表是元素周期表的一部分,根据表中给出的10种元素,按要求作答。

(1)O 的原子结构示意图是 ; (2)非金属性最强的元素是 ;

(3)F 和Cl 中,原子半径较大的是 ;

(4)常用作半导体材料的是 (填“硅”或“金刚石”);

(5)单质的化学性质最不活泼的元素是;

(6)H2CO3和HNO3中,酸性较强的是;

(7)NaOH和Al(OH)3中,属于两性氢氧化物的是;

(8)硫元素最高价氧化物的水化物的化学式是(填“H2SO4”或“H2SO3”);

(9)能与冷水发生剧烈反应的金属单质是;

(10)

结构式为的有机物分子式是,其中碳元素与氢元素的质量比

m(C)∶m(H)= (相对原子质量:H—1 C—12)。

27.(6分)氧化镁是优质的耐高温材料。某兴趣小组利用菱镁矿(主要成分为MgCO3,还含有少量SiO2、Al2O3等杂质)设计制备氧化镁的流程如下:

(1)步骤(Ⅰ)中分离操作的名称是;

(2)步骤(I)分离出的滤渣中主要含有,它属于(填“酸性”或“碱性”)氧化物;

(3)滤液Y中的阴离子除了含OH—、Cl—外还有;

(4)写出步骤(Ⅲ)Mg(OH)2受热分解生成MgO和H2O的化学方程式:

28.(6分)简要回答下列问题。

(1)常温下,可用铝制容器储存浓硫酸的原因是。

(2)室内装潢涂料不宜用苯作溶剂的原因是。

(3)汽车尾气是城市空气的重要污染源。请你就减少汽车尾气污染提出一条合理建议:。

三、实验探究题(本大题有2小题,共16分)

29.(4分)为达到下表中的实验目的,请选择合适的试剂及实验方法,将其标号填入对应的空

供选择的化学试剂及实验方法有:

A.加热升华

B.向溶液中通入足量的CO2气体

C.分别通入品红溶液中,观察现象

D.取样,加盐酸酸化的BaCl2溶液,

观察现象

30.(12分)某兴趣小组用下图所示实验装置(部分夹持仪器已略去)制取并探究Cl2的性质,装

置(Ⅰ)中发生反应的化学方程式为:MnO2 + 4HCl(浓)

===MnCl2 + Cl2↑+ 2H2O。

[实验探究】

(1)装置(Ⅰ)中仪器a的名称是。

(2)装置(Ⅱ)中浓硫酸的作用是。

(3)实验进行一段时间后,装置(Ⅲ)中的实验现象与分析:

①对甲、乙两处红纸花颜色变化的描述正确的是(填标号)。

A.甲不退色,乙退色B.甲退色,乙不退色

②对比甲、乙两处实验现象,可知具有漂白性的物质是(填“Cl2”或“HCIO”)。

③丙处淀粉K I试纸变为(填“蓝色”或“红色”),其中Cl2和K I发生反应,补充完整下面的化学方程式:Cl2 + 2KI==2KCI +

(4)从实验安全和环境保护的角度考虑,该实验存在的一个明显缺陷是

(5)用8.7g MnO2固体与足量浓盐酸反应,可生成Cl2气体体积(标准状况下)理论上最多为

L。(巳知MnO2的摩尔质量为87 g·mol—1)

[知识应用]

Cl2常用于饮用水消毒。Cl2溶于水得到氯水,氯水中HClO的浓度越大杀菌能力越强。(6)已知25℃时,氯水中Cl2(溶于水的氯气分子)、HClO、ClO—三种微粒所占百分数与pH的关系如右图。则用Cl2处理饮用水时,溶液的pH最佳控制范围是(填标号)。

A.3~5.5 B.5.5~7.5

201 7年6月福建省普通高中学生学业基础会考

化学试题

参考答案与评分标准

说明:化学方程式未配平、反应条件未注明、产物状态标错的扣0.5分。

第Ⅰ卷(选择题44分)

一、选择题(本大题有22小题,每小题2分,共44分。每小题只有一

二、填空简答题(本大题有6小题,共40分)

23.(1)棕色…………………………………………………………………(2分)

(2)有机物………………………………………………………………(2分) 24.(1)F (2)D (3)C (4)E (5)B (6)A

(若写相应具体物质名称也给分)…………………………(每空1分,共6分) 25.(1)NH3 + HCl =NH4Cl…………………………………………(3分)

高温

(2)2Al + Fe2O3 ==2Fe + Al2O3…………………………………(3分) 26.(1)………………………………………………………………(1分)

(2)F(或氟)………………………………………………………………(1分)

(3)Cl……………………………………………………………………… (1分)

(4)硅………………………………………………………………………(1分)

(5)Ar(或氩)……………………………………………………………(1分)

(6)HNO3………………………………………………………………… (1分)

(7) Al(OH)3 ………………………………………………………(1分)

(8)H2SO4………………………………………………………………(1分)

(9)Na…………………………………………………………………(1分) (10)C6H6…………………………………………………………………(1分) 12:1…………………………………………………………………(2分) 27.(1)过滤…………………………………………………………………(1分)

(2)SiO2(或二氧化硅) 酸性……………………………(每空1分,共2分)

(3)[Al(OH)4]-……………………………………………………………(1分)

(4)Mg(OH)2==MgO+H2O………………………………………………(2分)

28.(1)常温下,氯和浓硫酸反应生成致密的氧化膜阻止了进一步反应(发生钝化)(其它合理答案也给分)…………………………………………………(2分)

(2)苯易挥发且苯是有毒物质(其它合理答案也给分)…………………(2分)

(3)少开私家车或坐公交车、骑自行车、步行、植树造林等

(其它合理答案也给分)…………………………………………………(2分)

三、实验探究题(本大题有2小题,共l6分)

29. C A D B………………………………………(每空1分,共4分) 30.(1)分液漏斗……………………………………………………………(1分)

(2)干燥氯气(或者吸收氯气中的水)……………………………… (1分)

(3)①A

②HClO

………………………………………………(每空1分,共4分)

③蓝 I

2

(4)缺少尾气处理装置……………………………………………………(2分)

Cl2 + 2K I == I2 + 2KCl………………………………………………(2分)

(5)2.24…………………………………………………………………(2分)

(6)A………………………………………………………………………(2分)

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2018年高中英语会考真题+模拟训练试题(共两套含答案) 高中英语会考真题 注意事项: 1.本试卷分选择题和非选择题两部分,共36小题,考试时间150分钟,满分150分。 2.答卷前,考生务必用黑色字迹的钢笔或签字笔将自己的姓名、准考证号填写在答题卡上。 将条形码横贴在答题卡“考生条形码区”。 3.每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦 干净后,再选涂其他答案,答案不能答在试卷上。 4.考生必须保持答题卡的整洁。考试结束后,将试卷和答题卡一并交回。 第Ⅰ卷 第一部分、阅读理解(共两节,满分60分) 第一节、(共10小题;每小题4分,满分40分) 阅读下列短文,然后从各题所给的四个选项(A、B、C和D)中,选出最佳选项并在答题卡上将该选项涂黑。 A There was a man .He had four sons. He wanted his sons to learn how to judge things,so he let them go and look at a pear tree that was far away. The first son went in winter, the second in the spring, the third in the summer , the youngest son in the fall.When they had all gone and come back, he called them together to describe what they had seen. The first son said the tree was ugly,bent and weak. The second son said no--it was covered smelt so sweet and looked so beautiful. The last son disagreed with all of them, he said it was ripe and full of fruit, life and fulfillment(成就). The man then said to his sons that they were all right, because they each had seen but only one season in the tree’s life. He told them that you cannot judge a tree or a person by only one season, and that essence of who they are — the pleasure,the joy and love from that — can only be measured at the end, when all the seasons are up. If you give up when it’s winter, you’ll miss the hope of your spring, the beauty of your summer, the fulfillment of your fall. Don’t let the pain of one season destro y the joy of all the rest.

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