当前位置:文档之家› 2017年杭州师范大学考研试题841数学教育学

2017年杭州师范大学考研试题841数学教育学

2017年杭州师范大学考研试题841数学教育学
2017年杭州师范大学考研试题841数学教育学

杭州师范大学硕士研究生入学考试命题纸2017年考试科目代码841考试科目名称数学教育学(本考试科目共5页,第1页)杭州师范大学

2017年招收攻读硕士研究生入学考试题

考试科目代码:841

考试科目名称:数学教育学

说明:考生答题时一律写在答题纸上,否则漏批责任自负。

一、简答题(每题10分,共60分)

1.简述数学教育基本功能.

2.简述类比推理,并说明它在数学学习中的作用.

3.简述数学概念学习.

4.简述“自学-辅导式”教学模式的含义及操作程序.

5.简述《义务教育数学课程标准(2011版)》对使用信息技术提出的要求.

6.弗赖登塔尔认为数学教育方法的核心是学生的“再创造”,谈谈你对“再创造”的理解.

二、计算题(每题10分,共20分)

1.解关于x 的不等式:2(1)10ax a x -++<.

2.求0ln sin lim ln sin x mx nx

→.三、论述题(每题15分,共30分)

1.《义务教育数学课程标准(2011版)》的课程总目标中明确提出发展学生的“四基”,培养学生“四能”,谈谈你对从“双基”到“四基”、从“双能”到“四能”改变的认识.

2017年考研数学二真题解析

2017年全国硕士研究生入学统一考试数学二试题解析 一、选择题:1~8小题,每小题4分,共32分,下列每小题给出的四个选项中,只有一项符合题目要求的,请将所选项前的字母填在答题纸... 指定位置上. (1) )若函数0(),0x f x b x >=?≤? 在0x =处连续,则( ) (A)12 ab = (B)12 ab =- (C)0ab = (D)2ab = 【答案】A 【解析】00112lim lim ,()2x x x f x ax a ++→→==Q 在0x =处连续11.22b ab a ∴=?=选A. (2)设二阶可导函数()f x 满足(1)(1)1,(0)1f f f =-==-且'' ()0f x >,则( ) ()()1 1 110 1 1 1 10()()0 ()0()()()()()A f x dx B f x dx C f x dx f x dx D f x dx f x dx ----><>

2017考研英语一真题与答案解析

2017年考研英语一真题原文及答案解析完整版 2017年全国硕士研究生入学统一考试英语(一) Section I Use of English Directions: Read the following text. Choose the best word (s) for each numbered blank and mark A, B, C or D on the ANSWER SHEET. (10 points) Could a hug a day keep the doctor away? The answer may be a resounding “yes!” 1 helping you feel close and 2 to people you care about, it turns out that hugs can bring a 3 of health benefits to your body and mind. Believe it or not, a warm embrace might even help you 4 getting sick this winter. In a recent study 5 over 400 health adults, researchers from Carnegie Mellon University in Pennsylvania examined the effects of perceived social support and the receipt of hugs 6 the participants’ susceptibility to developing the common cold after being 7 to the virus .People who perceived greater social support were less likely to come 8 with a cold ,and the researchers 9 that the stress-reducing effects of hugging 10 about 32 percent of that beneficial effect. 11 among those who got a cold, the ones who felt greater social support and received more frequent hugs had less severe 12 . “Hugging protects people who are under stress from the 13 risk for colds that’s usually 14 with stress,” notes Sheld on Cohen, a professor of psychology at Carnegie. Hugging “is a

2017年考研数学一真题与解析汇总

2017年考研数学一真题 一、选择题 1—8小题.每小题4分,共32分. 1.若函数0(),0x f x b x >=?≤? 在0x =处连续,则 (A )12ab = (B )1 2 ab =-(C )0ab =(D )2ab = 【详解 】0001112lim ()lim lim 2x x x x f x ax ax a +++→→→-===,0lim ()(0)x f x b f -→==,要使函数在0x =处连续,必须满足11 22 b ab a =?=.所以应该选(A ) 2.设函数()f x 是可导函数,且满足()()0f x f x '>,则 (A )(1)(1)f f >- (B )11()()f f <- (C )11()()f f >- (D )11()()f f <- 【详解】设2()(())g x f x =,则()2()()0g x f x f x ''=>,也就是()2 ()f x 是单调增加函数.也就得到 () ()2 2 (1)(1)(1)(1)f f f f >-?>-,所以应该选(C ) 3.函数22(,,)f x y z x y z =+在点(1,2,0)处沿向量(1,2,2)n =的方向导数为 (A )12 (B )6 (C )4 (D )2 【详解】 22,,2f f f xy x z x y z ???===???,所以函数在点(1,2,0)处的梯度为()4,1,0gradf =,所以 22(,,)f x y z x y z =+在点(1,2,0)处沿向量(1,2,2)n =的方向导数为 ()01 4,1,0(1,2,2)23f gradf n n ?=?=?=?应该选(D ) 4.甲、乙两人赛跑,计时开始时,甲在乙前方10(单位:米)处,如图中,实线表示甲的速度曲线1()v v t =(单位:米/秒),虚线表示乙的速度曲线2()v v t =(单位:米/秒),三块阴影部分的面积分别为10,20,3,计时开始后乙追上甲的时刻为0t ,则( ) (A )010t = (B )01520t << (C )025t = (D )025t > 【详解】由定积分的物理意义:当曲线表示变速直线

2020年考研英语一真题及答案解析

2020年研究生入学统一考试试题(英语一) Section I Use of English Directions: Read the following text. Choose the best word (s) for each numbered blank and mark A, B, C or D on the ANSWER SHEET. (10 points) Even if families are less likely to sit down to eat together than was once the case, millions of Britons will none the less have partaken this weekend of one of the nation's great traditions: the Sunday roast. __1__ a cold winter's day, few culinary pleasures can __2__it. Yet as we report now, the food police are determined that this __3__ should be rendered yet another guilty pleasure __4__ to damage our health. The Food Standards Authority (FSA) has __5__ a public warning about the risks of a compound called acrylamide that forms in some foods cooked __6__ high temperatures.This means that people should __7__ crisping their roast potatoes, spurn thin-crust pizzas and only __8__ toast their bread. But where is the evidence to support such alarmist advice? __9__ studies have shown that acrylamide can cause neurological damage in mice, there is no __10__ evidence that it causes cancer in humans. Scientists say the compound is "__11__ to be carcinogenic" but have no hard scientific proof. __12__ the precautionary principle, it could be argued that it is __13__ to follow the FSA advice. __14__, it was rumored that smoking caused cancer for years before the evidence was found to prove a __15__. Doubtless a piece of boiled beef can always be __16__ up on Sunday alongside some steamed vegetables,without the Yorkshire pudding and no wine. But would life be worth living? __17__, the FSA says it is not telling people to cut out roast foods __18__, but to reduce their lifetime intake. However, their __19__ risks coming across as exhortation and nannying. Constant health scares just __20__ with no one listening. 1. A In B Towards C On D Till 2. A match B express C satisfy D influence 3. A patience B enjoyment C surprise D concern 4. A intensified B privileged C compelled D guaranteed 5. A issued B received C ignored D canceled 6. A under B at C for D by 7. A forget B regret C finish D avoid 8. A partially B regularly C easily D initially 9. A Unless B Since C If D While 10. A secondary B external C inconclusive D negative 11. A insufficient B bound C likely D slow 12. A On the basis of B At the cost of C In addition to D In contrast to 13. A interesting B advisable C urgent D fortunate 14. A As usual B In particular C By definition D After all 15. A resemblance B combination C connection D pattern 16. A made B served C saved D used 17. A To be fair B For instance C To be brief D in general 18. A reluctantly B entirely C gradually D carefully 19. A promise B experience C campaign D competition 20. A follow up B pick up C open up D end up 解析:

2017年考研数学(二)考试大纲(原文)

2017年考研数学(二)考试大纲(原文) 2017数学二考试大纲 考试科目:高等数学、线性代数 考试形式和试卷结构 一、试卷满分及考试试卷 试卷满分为150分,考试试卷为180分钟 二、答题方式 答题方式为闭卷、笔试。 三、试卷内容结构 高等数学约78% 线性代数约22% 四、试卷题型结构 单项选择题 8小题,每小题4分,共32分 填空题 6小题,每小题4分,共24分 解答题(包括证明题) 9小题,共94分 高等数学 一、函数、极限、连续 考试内容 函数的概念及表示法函数的有界性、单调性、周期性和奇偶性复合函数、反函数、分段函数和隐函数基本初等函数的性质及图形初等函数函数关系的建立数列极限与函数极限的定义及其性质函数的左极限于右极限无穷小量和无穷大量的概念及其关系无穷小量及无穷小量的比较极限的四则运算极限存在的两个准则:单调有界准则和夹逼准则两个重要极限: , 函数连续的概念函数间断点的类型初等函数的连续性闭区间上连续函数的性质 考试要求 1.理解函数的概念,掌握函数的表示法,会建立应用问题的函数关系. 2.了解函数的有界性、单调性、周期性和奇偶性. 3.理解复合函数及分段函数的概念,了解反函数及隐函数的概念. 4.掌握基本初等函数的性质及其图形,了解初等函数的概念. 5.理解极限的概念,理解函数左极限与右极限的概念以及函数极限存在与左极限、右极限之间的关系. 6.掌握极限的性质及四则运算法则. 7.掌握极限存在的两个准则,并会利用它们求极限,掌握利用两个重要极限求极限的方法. 8.理解无穷小量、无穷大量的概念,掌握无穷小量的比较方法,会用等价无穷小量求极限. 9.理解函数连续性的概念(含左连续与右连续),会判别函数间断点的类型. 10.了解连续函数的性质和初等函数的连续性,理解闭区间上连续函数的性质(有界性、最大值和最小值定理、介值定理),并会应用这些性质. 二、一元函数微分学 考试内容 导数和微分的概念导数的几何意义和物理意义函数的可导性与连续性之间的关系平面曲线的切线和法线导数和微分的四则运算基本初等函数的导数复合函数、反函数、隐函数以及参数方程所确定的函数的微分法高阶导数一阶微分形式的不变性微分中值定理洛

2016-2017年考研数学二真题及答案

2016考研数学二真题及答案 一、选择题 1—8小题.每小题4分,共32分. 1.当+→0x 时,若)(ln x 21+α ,α 1 1)cos (x -均是比x 高阶的无穷小,则α的可能取值 范围是( ) (A )),(+∞2 (B )),(21 (C )),(121 (D )),(2 10 【详解】α ααx x 221~)(ln +,是α阶无穷小,αα α2 1 1 2 1 1x x ~ )cos (-是 α 2 阶无穷小,由题意可知??? ??>>121α α 所以α的可能取值范围是),(21,应该选(B ). 2.下列曲线有渐近线的是 (A )x x y sin += (B )x x y sin +=2 (C )x x y 1sin += (D )x x y 12 sin += 【详解】对于x x y 1sin +=,可知1=∞→x y x lim 且01 ==-∞→∞→x x y x x sin lim )(lim ,所以有斜渐 近线x y = 应该选(C ) 3.设函数)(x f 具有二阶导数,x f x f x g )())(()(110+-=,则在],[10上( ) (A )当0≥)('x f 时,)()(x g x f ≥ (B )当0≥)('x f 时,)()(x g x f ≤ (C )当0≥'')(x f 时,)()(x g x f ≥ (D )当0≥'')(x f 时,)()(x g x f ≤ 【分析】此题考查的曲线的凹凸性的定义及判断方法. 【详解1】如果对曲线在区间],[b a 上凹凸的定义比较熟悉的话,可以直接做出判断. 显然x f x f x g )())(()(110+-=就是联接))(,()),(,(1100f f 两点的直线方程.故当0≥'')(x f 时,曲线是凹的,也就是)()(x g x f ≤,应该选(D )

2013-2014杭州师范大学力学题库

003/03/03/0030 3杭州师范大学理学院2013《力学》试题汇编 错误匀速率一、选择题(每题1分,20分) 1、刚体角动量守恒的充分而必要的条件是( )。 (A)刚体不受外力矩的作用 (B)刚体所受合外力矩为零 (C)刚体所受的合外力和合外力矩均为零 (D)刚体的转动惯量和角速度均保持不变 2、下列说法中的是( )。 (A)牛顿第二定律只适用与惯性系。自然界中,惯性系只有一个 (B)只有保守力才有相应的势能,势能是体系所共有的 (C)在北半球,我们往往会看到河道的右边比左边要冲刷的厉害,这与地球自转产生的科里奥利效应密切相关 (D)刚体作平面平行运动时,可以看成和基点的平动以及绕过基点垂直平面轴的转动,基点的选取是任意的 3、下列说法中正确的是( )。 (A)保守力做的功等于势能的减小 (B)牛顿第二定律既适用与惯性系也适用与非惯性系(C)内力可以改变刚体的动能 (D)合外力对体系不做功,体系的机械能一定守恒4、一质点做圆周运动时,有( )。(A)切向加速度大小改变,法向加速度大小改变(B)切向加速度大小改变,法向加速度大小不变(C)切向加速度大小不变,法向加速度大小改变(D)切向加速度大小不变,法向加速度大小不变 5、花样滑冰运动员绕通过自身的竖直轴转动,开始时两臂伸开,转动惯量为,角速度为 ,然后两臂收回,使其转动惯量变为,则其旋转的角速度为( )。 (A) (B) (C) (D)6、对于一个体系来说,在下列的哪种情况下系统的机械能守恒?( )。(A)合外力为0 (B)外力和非保守内力都不作功 I I w w w w w

2020.08.92 /9.42 /8.92/45.22 /7.142/212 1 2 1 211000/10/340/29/30/31/324.016.01.02 /10(C)合外力不作功(D)外力和保守内力都不作功 7、下列说法中错误的是( )。 (A)位移共振频率一般来说等于振动系统的固有频率 (B)牛顿第二定律只适用与惯性系 (C)内力可以改变体系的动能,但不可以改变体系的动量 (D)质点系的转动惯量与质点系的质量分布以及转轴所在的位置有关 8、如图所示,质量为,半径为的均匀滑轮,可绕光滑的水平轴转动的转动,轮子上绕有轻绳,若有一恒力拉绳子的一端,使得轮子由静止开始转动,忽略轴承与滑轮的摩擦,则滑轮转动的角加速度为( )。(A) (B)(C) (D)9、一个质点作简谐振动,振幅为,在起始时刻质点的位移为,且向轴的正方向运动,代表此简谐振动的旋转矢量图为( )。 (A) (B) (C) (D) 10、两个观察者A和B携带频率为Hz的声源。如果A静止,而B以的速率向A运动,若声速为,那么A听到的拍频是( )。(A) (B) (C) (D)11、关于质点的速度和加速度,下列说法的是( )。(A)质点具有恒定的速度,但仍可能具有变化的速率(B)质点具有恒定的速率,但仍可能具有变化的速度(C)质点加速度方向恒定,但速度方向仍可能在不断变化(D)质点速度方向恒定,但加速度方向仍可能在不断变化 12、质量为的小球从高塔上自由落下后时,质量为的小球从同一点自由落 下。求第二个小球释放后时,这两球质点系的质心速度大小( )。(取) kg M m R N F s rad s rad s rad s rad A A x x o A x A A A o o o A x x x A x A x A x s m s m s s s s kg s kg s s m g ===???=v v v v w w w w 错误

2017年考研数学二试题及详解

2017年考研数学二试题及详解 一、选择题 (1 )设1231),1a x a a =,则( ). A. 123,,a a a B. 231,,a a a C. 213,,a a a D. 321,,a a a 【答案】B 【解析】 2 11513 6 2 2311 01()22ln(11 13 x a x x x x a x x x a x +→=-=-=+== 当时, 所以,从低到高的顺序为a 2,a 3,a 1,选B. (2)已知函数2(1),1 ()ln ,1x x f x x x -

因此选择D. (3)反常函数①1 21x e dx x -∞?,②1 201x e dx x +∞?的敛散性为( ). A. ①收敛,②收敛 B. ①收敛,②发散 C. ①发散,②收敛 D. ①发散,②发散 【答案】B 【解析】①11 11 02011[lim lim ](01)1x x x x x x e dx e d e e x x --∞-∞→∞→=-=--=--=??收敛。 ② 1 1 1 110 20 00 11 [lim lim ]x x x x x x x e dx e d e e e x x + ∞ +∞+∞→∞ →=-=-=--=+∞? ?发散。 所以,选B. (4)设函数()f x 在(,)-∞+∞内连续,其导函数的图形如图所示,则( ). A. 函数()f x 有2个极值点,曲线()y f x =有2个拐点 B. 函数()f x 有2个极值点,曲线()y f x =有3个拐点 C. 函数()f x 有3个极值点,曲线()y f x =有1个拐点 D. 函数()f x 有3个极值点,曲线()y f x =有2个拐点 【答案】B 【解析】根据图像可知导数为零的点有3个,但是最右边的点左右两侧导数均为正值,因此不是极值点,故有2个极值点,而拐点是一阶导数的极值点或者是不可导点,在这个图像上,一阶导数的极值点有2个,不可导点有1个,因此有3个拐点 .

2017年考研英语一真题-高清版含答案

2017年考研英语一真题-高清版含答案 Section I Use of English Directions: Read the following text.Choose the best word(s)for each numbered blank and mark A,B,C or D on the ANSWER SHEET.(10points) Could a hug a day keep the doctor away?The answer may be a resounding “yes!”1helping you feel close and2to people you care about,it turns out that hugs can bring a3of health benefits to your body and mind. Believe it or not,a warm embrace might even help you4getting sick this winter. In a recent study5over400healthy adults,researchers from Carnegie Mellon University in Pennsylvania examined the effects of perceived social support and the receipt of hugs6the participants’susceptibility to developing the common cold after being7to the virus.People who perceived greater social support were less likely to come8with a cold,and the researchers9that the stress-reducing effects of hugging10about 32percent of that beneficial effect.11among those who got a cold,the ones who felt greater social support and received more frequent hugs had less severe 12. “Hugging protects people who are under stress from the13risk for colds that’s usually14with stress,”notes Sheldon Cohen,a professor of psychology at Carnegie.Hugging“is a marker of intimacy and helps15the feeling that others are there to help16difficulty.” Some experts17the stress-reducing,health-related benefits of hugging to the release of oxytocin,often called“the bonding hormone”18it promotes attachment in relationships,including that between mothers and their newborn babies.Oxytocin is made primarily in the central lower part of the brain, and some of it is released into the bloodstream.But some of it19in the brain,where it20mood,behavior and physiology.

杭州师范大学题库:高等数学A卷(期末样卷)

一、填空(共20分,每空格4分) 1.设(sin )1cos2f x x =+,则()f x =222x -; 2.函数()f x 在点0x 可导(可微)是()f x 在点0x 连续的 充分 条件(充分、必要、充分必要); 3.设函数()y f x =在区间I 内二阶可导,如果()f x '' >0 ,曲线()y f x =在I 内是凹的; 4.设2x e 是()f x 的一个原函数,则 (sin )cos f x xdx ?=?2sin x e C +; 5 . 0=? 1 。 二、单项选择题(共20分,每小题4分) 1. arcsin arccos x x += ( C ) A.2π B. π C. 2 π D. 0 2.由2,12t x y t ==-确定的方程,二阶导数22d y dx = ( C ) A. 1 t B. 21t C. 31t D. 41t 3.函数()2f x x =+在点0x =处 ( A ) A. 连续但不可导 B. 连续且可导 C. 不连续故不可导 D. 具有连续的导数 4. 设()f x 在[],a b 上连续,且()()0f a f b <,则至少存在一点(,)a b ξ∈使( A )成立 A. ()0f ξ= B. '()0f ξ= C. ''()0f ξ= D. ()()'()()f b f a f b a ξ-=- 5. 已知? ??≥<=,1,ln ,1,e )(x x x x f x 则()x f 在1=x 处的导数( D ). A. 等于0 B. 等于1 C. 等于e D. 不存在 三、计算题(共48分,每题8分)

2017年考研数学一真题及答案(全)

2017年全国硕士研究生入学统一考试 数学(一)试题 一、选择题:1~8小题,每小题4分,共32分.下列每题给出的四个选项中,只有一个选项是符合题目要求的.请将所选项前的字母填在答题纸... 指定位置上. (1 )若函数0(),0x f x b x >=?≤? 在x 连续,则 (A) 12 ab =. (B) 12 ab =- . (C) 0ab =. (D) 2ab =. 【答案】A 【详解】由0 1 lim 2x b a + →==,得12ab =. (2)设函数()f x 可导,且()'()0f x f x >则 (A) ()()11f f >- . (B) ()()11f f <-. (C) ()()11f f >-. (D) ()()11f f <-. 【答案】C 【详解】2() ()()[]02 f x f x f x ''=>,从而2()f x 单调递增,22(1)(1)f f >-. (3)函数2 2 (,,)f x y z x y z =+在点(1,2,0)处沿着向量(1,2,2)n =的方向导数为 (A) 12. (B) 6. (C) 4. (D)2 . 【答案】D 【详解】方向余弦12cos ,cos cos 33 = ==αβγ,偏导数22,,2x y z f xy f x f z '''===,代入cos cos cos x y z f f f '''++αβγ即可. (4)甲乙两人赛跑,计时开始时,甲在乙前方10(单位:m)处.图中,实线表示甲的速度曲线1()v v t =(单位:m/s),虚线表示乙的速度曲线2()v v t =(单位:m/s),三块阴影部分面积的数值一次为10,20,3,计时开始后乙追上甲的时刻记为(单位:s),则

2021考研英语一真题试卷及答案(完整版)

2017考研真题答案:2017考研英语一真题试卷及答案(完整版)2017年全国硕士研究生入学统一考试英语(一)试题+【答案】 Section I Use of English Directions: Read the following text. Choose the best word (s) for each numbered blank and mark A, B, C or D on the ANSWER SHEET. (10 points) Could a hug a day keep the doctor away? The answer may be health benefits to your body and mind. Believe it or not, a warm from Carnegie Mellon University in Pennsylvania examined the the participants' susceptibility to developing the common cold

who got a cold, the ones who felt greater social support and Cohen, a professor of psychology at Carnegie. Hugging "is a benefits of hugging to the release of oxytocin, often called "the relationships, including that between mother and their newborn babies. Oxytocin is made primarily in the central lower part of the brain , and some of it is released into the bloodstream. But physiology. 1.[A] Unlike [B] Besides [C] Despite [D] Throughout 【答案】[B] Besides 2.[A] connected [B] restricted [C] equal [D] inferior 【答案】[A] connected

杭州师范大学综合英语考研真题试题2020、2019年

杭州师范大学硕士研究生招生考试命题纸 杭州师范大学 2020年招收攻读硕士研究生考试题 考试科目代码:718 考试科目名称:综合英语 说明:考生答题时一律写在答题纸上,否则漏批责任自负。 I. Cloze(每小题1分,共50分) Fill in each of the blanks with a function word, otherwise the first letter is given as a clue. Passage One: Instinct or cleverness? We have been brought up to fear insects. We regard them as unnecessary creatures that do more harm than good. We continually wage war (1) ______ them, for they contaminate our food, carry diseases, or devour our crops. They sting or bite without provocation; they fly uninvited into our rooms on summer nights, or beat against our lighted windows. We live in dread not only of unpleasant insects like spiders or wasps, but of quite harmless ones like moths. Reading about them increases our understanding without dispelling our fears. Knowing that the industrious ant lives in a highly organized society does nothing to prevent us (2) ______ being filled with revulsion when we find hordes of them crawling over a carefully prepared picnic lunch. No matter how much we like honey, or how much we have read about the uncanny sense of direction which bees possess, we have a horror of being (3) s______. Most of our fears are unreasonable, but they are impossible to erase. At the same time, however, insects are strangely fascinating. We enjoy reading about them, especially when we find that, like the praying mantis, they lead perfectly horrible lives. We enjoy staring (4) ______ them, entranced as they go about their business, unaware (we hope) (5) ______ our presence. Who has not stood in awe (6) ______ the sight of a spider pouncing (7) ______ a fly, or a column of ants triumphantly bearing home an enormous dead beetle? Last summer I spent days in the garden watching thousands of ants crawling up the trunk of my prize peach tree. The tree has grown against a warm wall on a sheltered side of the house. I am especially proud (8) ______ it, not only because it has survived several severe winters, but because it occasionally produces luscious peaches. During the summer, I noticed that the leaves of the tree were beginning to wither. Clusters of tiny insects called aphides were to be found on the underside of the leaves. They were visited by a large colony of ants which obtained a sort of honey (9) ______ them. I immediately embarked on an experiment which, 2020年考试科目代码718 考试科目名称综合英语(本考试科目共5页,第1 页)

2020年考研英语一翻译真题及答案解

析2017年考研英语考试已经结束!出国留学考研网在考后第一时间为大家提供2017年考研英语一翻译真题及答案解析,更多考研资讯请关注我们网站的更新! 2017年考研英语一翻译真题及答案解析 英语1文章明显偏学术,今年考察英语语言发展情况,文章选的英国文化教育协会,是雅思出题组织者。它的主席叫大卫格兰多的一本书,叫《英语下一步》,他讲到整本书意思是英语将走向何处。 很有意思的是主席曾经这本书里说到了中文将以后成为世界语言。 英语1考题作为序言部分作为考题。 今年英语1总体难度和去年相比,刚刚过去2016年考研题稳中有一点点上升,没有任何难句出现,只是长句。我认为稳中上升。 第一句话有一个单词难一点,(英文),英语全球性主导地位。翻译里没有考过。(英文)主导地位考过,但是是阅读里经常出现,翻译都是可以的。这句话基本意思说到了,说英语的人进一步扩大,这是一个(英文)状语从句。后面跟着有迹象表明,是主句,表明的迹象是什么呢?从句,英语全球性主导地位在可预见地位将减弱。 fade(英文)略微有难度。我对考研阅读没有那么熟,但是2000年出现过。 如果按照新东方老师关注的精读方法来学习有很好的效果。 第二句话讲到了大卫这个人分析,会终结一些人的(英文),他们或许会认为英语全球性地位是如此稳定。他们有一次词,是(英语)如此稳定,英国年轻一代不需要额外学习其他的语言能力。但是会终结年轻一代的能力。 但是组织的时候要注意一下,有些人认为英语语言地位如此稳定,英国年轻人没有必要学习什么,但是大卫的观点会终结这些人的想法。语序颠倒一下会更好。48题,正在引入英语,引入小学课程,有一个单词,(英语),这个单

杭州师范大学C语言试题第7套

一、判断题 第1题:C语言是一种结构化程序设计语言。参考答案:对 第2题:函数调用可以作为独立的语句存在参考答案:对 第3题:在C语言中使用位段时,一个位段可以在不同的存储单元中。错 第4题:在switch语句中,case后可不加“{、}”。参考答案:对 第5题:在标准C中,while后表达式只能是逻辑或关系表达式。错 第6题:在C语言中,定义结构体变量时可以省略关健字struct。错 第7题:在标准C中并不区分英文字符的大小写。参考答案:错 第8题:二进制文件打开后可以先读文件的末尾,而顺序文件不可以对 第9题:单目运算符++的运算对象可以是char型变量和int型变量,但不能是float 型变量参考答案:对 第10题:“--”运算符的优先级比“-”运算符的优先级低。参考答案:错 二、单选题选择正确的答案输入 第1题:若有以下说明: int w[3][4]={{0,1},{2,4},{5,8}}; int(*p)[4]=w; 则数值为4的数组元素的表达式是 参考答案:D A、*w[1]+1 B、p++,*(p+1) C、w[2][2] D、p[1][1] 第2题:若有说明:int i,j=7,*p=&i;,则与i=j;等价的语句是 参考答案:B A、i= *p; B、*p=*&j; C、i=&j; D、i=* *p; 第3题:设i是int型变量,f是float型变量,为了把100和765.12分别给i和f,用下面的语句:scanf("i=%d,f=%f",&i,&f);正确的输入是 参考答案:B A、100<空格>765.12<回车> B、i=100,f=765.12<回车> C、100<回车>765.12<回车> D、x=100<回车>,y=765.12<回车> 第4题:若fp是指向某文件的指针,且已读到该文件的末尾,则C语言函数feof(fp)的返回值是 参考答案:B A、EOF B、1 C、非零值 D、NULL 第5题:以下程序的输出结果是 main()

相关主题
文本预览
相关文档 最新文档